message stringlengths 2 44.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 276 109k | cluster float64 23 23 | __index_level_0__ int64 552 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DLS and JLS are bored with a Math lesson. In order to entertain themselves, DLS took a sheet of paper and drew n distinct lines, given by equations y = x + p_i for some distinct p_1, p_2, …, p_n... | instruction | 0 | 61,585 | 23 | 123,170 |
No | output | 1 | 61,585 | 23 | 123,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DLS and JLS are bored with a Math lesson. In order to entertain themselves, DLS took a sheet of paper and drew n distinct lines, given by equations y = x + p_i for some distinct p_1, p_2, …, p_n... | instruction | 0 | 61,586 | 23 | 123,172 |
No | output | 1 | 61,586 | 23 | 123,173 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,683 | 23 | 123,366 |
Tags: brute force, dp, implementation
Correct Solution:
```
for _ in range(int(input())):
n,m=map(int,input().split())
inp=[]
out=0
for i in range(n):
inp.append(list(input()))
mat=[[] for i in range(n)]
for i in range(n):
for j in range(m):
k=0
while j-k>... | output | 1 | 61,683 | 23 | 123,367 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,684 | 23 | 123,368 |
Tags: brute force, dp, implementation
Correct Solution:
```
for _ in range(int(input())):
n,m=map(int,input().split())
a=[]
t=[]
for i in range(n):
a.append(input())
x=[]
s=0
for j in a[i]:
if(j=="*"): s+=1
x.append(s)
t.append(x)
a... | output | 1 | 61,684 | 23 | 123,369 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,685 | 23 | 123,370 |
Tags: brute force, dp, implementation
Correct Solution:
```
t=int(input())
for _ in range(t):
n,m=map(int,input().split())
inp=[]
for i in range(n):
s=input()
inp.append(s)
ans=0
R=[]
L=[]
for i in range(n):
low=0
high=0
right=[]
left=[]
... | output | 1 | 61,685 | 23 | 123,371 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,686 | 23 | 123,372 |
Tags: brute force, dp, implementation
Correct Solution:
```
for _ in range(int(input())):
ROW,COL=map(int,input().split())
arr=[]
for _ in range(ROW):
arr.append(list(input()))
sol =[[0 for i in range(COL)] for j in range(ROW)]
for row in range(ROW):
for col in range(COL):
... | output | 1 | 61,686 | 23 | 123,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,687 | 23 | 123,374 |
Tags: brute force, dp, implementation
Correct Solution:
```
import sys
#input = sys.stdin.readline
t = int(input())
for test in range(t):
#n = int(input())
[n, m] = list(map(int, input().split(" ")))
a = []
for i in range(n):
a.append(input())
#a = list(map(int, input().split(" ")))
res = 0
b = []
for i in ... | output | 1 | 61,687 | 23 | 123,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,688 | 23 | 123,376 |
Tags: brute force, dp, implementation
Correct Solution:
```
import sys
import math
def II():
return int(sys.stdin.readline())
def LI():
return list(map(int, sys.stdin.readline().split()))
def MI():
return map(int, sys.stdin.readline().split())
def SI():
return sys.stdin.readline().strip()
def FACT(n, mod):
... | output | 1 | 61,688 | 23 | 123,377 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,689 | 23 | 123,378 |
Tags: brute force, dp, implementation
Correct Solution:
```
t = int(input())
for _ in range(t):
n,k = map(int,input().split())
mat = []
ans = [[0 for i in range(k)]for j in range(n)]
for i in range(n):
temp = input()
mat.append(temp)
for i in range(k):
if mat[n-1][i] == '*':... | output | 1 | 61,689 | 23 | 123,379 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n × m matrix consisting of "*" and ".".
<image>
... | instruction | 0 | 61,690 | 23 | 123,380 |
Tags: brute force, dp, implementation
Correct Solution:
```
import sys
import os
for _ in range(int(input())):
n,m=map(int,input().split())
arr=[]
for i in range(n):
s=input()
arr.append(s)
# == 0 else dp1[i][j - 1] + (1 if arr[i][j] == '*' else 0))
dp=[[0 for _ in range(m)]for _ in range(n)]
for i in ... | output | 1 | 61,690 | 23 | 123,381 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,691 | 23 | 123,382 |
Yes | output | 1 | 61,691 | 23 | 123,383 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,692 | 23 | 123,384 |
Yes | output | 1 | 61,692 | 23 | 123,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,693 | 23 | 123,386 |
Yes | output | 1 | 61,693 | 23 | 123,387 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,694 | 23 | 123,388 |
Yes | output | 1 | 61,694 | 23 | 123,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,695 | 23 | 123,390 |
No | output | 1 | 61,695 | 23 | 123,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,696 | 23 | 123,392 |
No | output | 1 | 61,696 | 23 | 123,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,697 | 23 | 123,394 |
No | output | 1 | 61,697 | 23 | 123,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Holidays are coming up really soon. Rick realized that it's time to think about buying a traditional spruce tree. But Rick doesn't want real trees to get hurt so he decided to find some in an n ... | instruction | 0 | 61,698 | 23 | 123,396 |
No | output | 1 | 61,698 | 23 | 123,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Omkar's most recent follower, Ajit, has entered the Holy Forest. Ajit realizes that Omkar's forest is an n by m grid (1 ≤ n, m ≤ 2000) of some non-negative integers. Since the forest is blessed ... | instruction | 0 | 61,717 | 23 | 123,434 |
Yes | output | 1 | 61,717 | 23 | 123,435 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Omkar's most recent follower, Ajit, has entered the Holy Forest. Ajit realizes that Omkar's forest is an n by m grid (1 ≤ n, m ≤ 2000) of some non-negative integers. Since the forest is blessed ... | instruction | 0 | 61,718 | 23 | 123,436 |
Yes | output | 1 | 61,718 | 23 | 123,437 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Omkar's most recent follower, Ajit, has entered the Holy Forest. Ajit realizes that Omkar's forest is an n by m grid (1 ≤ n, m ≤ 2000) of some non-negative integers. Since the forest is blessed ... | instruction | 0 | 61,719 | 23 | 123,438 |
Yes | output | 1 | 61,719 | 23 | 123,439 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Omkar's most recent follower, Ajit, has entered the Holy Forest. Ajit realizes that Omkar's forest is an n by m grid (1 ≤ n, m ≤ 2000) of some non-negative integers. Since the forest is blessed ... | instruction | 0 | 61,720 | 23 | 123,440 |
Yes | output | 1 | 61,720 | 23 | 123,441 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,173 | 23 | 124,346 |
"Correct Solution:
```
import math
import cmath
def dot(a:complex,b:complex):
return (a.conjugate()*b).real
def cross(a:complex,b:complex):
return (a.conjugate()*b).imag
next=[1,2,0]
try:
while True:
l=list(map(float,input().split()))
p=[complex(l[2*j],l[2*j+1]) for j in range(4)]
flg_ans=True
sgn... | output | 1 | 62,173 | 23 | 124,347 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,174 | 23 | 124,348 |
"Correct Solution:
```
import math
import sys
def get_triangle_area(x1, y1, x2, y2, x3, y3):
l1 = math.sqrt(abs(x1-x2)**2+abs(y1-y2)**2)
l2 = math.sqrt(abs(x2-x3)**2+abs(y2-y3)**2)
l3 = math.sqrt(abs(x3-x1)**2+abs(y3-y1)**2)
s = (l1+l2+l3)/2
return math.sqrt(s*(s-l1)*(s-l2)*(s-l3))
for l in sys.... | output | 1 | 62,174 | 23 | 124,349 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,175 | 23 | 124,350 |
"Correct Solution:
```
# ２点(a, b) (c, d)を通る直線の傾きと切片を返す
def func(a, b, c, d):
k = (d - b) / (c - a)
h = d - k * c
return k, h
# ２点と通る直線のf(x)を返す
def fx(a, b, c, d, x):
k, h = func(a, b, c, d)
return k * x + h
def main():
import sys
for dataset in sys.stdin:
ans = 'NO'
try :... | output | 1 | 62,175 | 23 | 124,351 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,176 | 23 | 124,352 |
"Correct Solution:
```
def getTriangleArea(x1, y1, x2, y2, x3, y3): # returns the area of triangle determined by provided 3 points
ux = x2-x1
uy = y2-y1
vx = x3-x1
vy = y3-y1
return abs(ux*vy-vx*uy)/2
inputs=[]
while True:
try:
inputs.append(list(map(float,input().split())))
except EOFError:
brea... | output | 1 | 62,176 | 23 | 124,353 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,177 | 23 | 124,354 |
"Correct Solution:
```
# coding=utf-8
def direction_vector(p1: list, p2: list)->list:
return [p2[0]-p1[0], p2[1]-p1[1]]
def cross_product(v1: list, v2: list)->float:
return v1[0]*v2[1] - v1[1]*v2[0]
if __name__ == '__main__':
while True:
try:
points_receive = list(map(float, input(... | output | 1 | 62,177 | 23 | 124,355 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,178 | 23 | 124,356 |
"Correct Solution:
```
def r(x1, y1, x2, y2, x3, y3):
return x1*(y2-y3)+x2*(y3-y1)+x3*(y1-y2) > 0
while True:
try:
line = input()
except:
break
x1, y1, x2, y2, x3, y3, xp, yp = map(float, line.strip().split())
abc = r(x1, y1, x2, y2, x3, y3)
pab = r(xp, yp, x1, y1, x2, y2)
... | output | 1 | 62,178 | 23 | 124,357 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,179 | 23 | 124,358 |
"Correct Solution:
```
def cross3(a, b, c):
return (b[0] - a[0])*(c[1] - a[1]) - (b[1] - a[1])*(c[0] - a[0])
for line in open(0).readlines():
x1, y1, x2, y2, x3, y3, xp, yp = map(float, line.split())
p1 = (x1, y1); p2 = (x2, y2); p3 = (x3, y3); pp = (xp, yp)
if cross3(p1, p2, p3) < 0:
p1, p2 = p... | output | 1 | 62,179 | 23 | 124,359 |
Provide a correct Python 3 solution for this coding contest problem.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not.
Constraints
You can assume that:
* $ -100 \leq x_1,... | instruction | 0 | 62,180 | 23 | 124,360 |
"Correct Solution:
```
import sys
for s in sys.stdin:
x1,y1,x2,y2,x3,y3,xp,yp = [ float(x) for x in s.split() ]
v12 = (x2-x1, y2-y1)
v23 = (x3-x2, y3-y2)
v31 = (x1-x3, y1-y3)
v1p = (xp-x1, yp-y1)
v2p = (xp-x2, yp-y2)
v3p = (xp-x3, yp-y3)
cp1 = v12[0]*v1p[1] - v1p[0]*v12[1]
cp2 = ... | output | 1 | 62,180 | 23 | 124,361 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,181 | 23 | 124,362 |
Yes | output | 1 | 62,181 | 23 | 124,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,182 | 23 | 124,364 |
Yes | output | 1 | 62,182 | 23 | 124,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,183 | 23 | 124,366 |
Yes | output | 1 | 62,183 | 23 | 124,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,184 | 23 | 124,368 |
Yes | output | 1 | 62,184 | 23 | 124,369 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,185 | 23 | 124,370 |
No | output | 1 | 62,185 | 23 | 124,371 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,186 | 23 | 124,372 |
No | output | 1 | 62,186 | 23 | 124,373 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,187 | 23 | 124,374 |
No | output | 1 | 62,187 | 23 | 124,375 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a triangle formed by three points $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ on a plain.
Write a program which prints "YES" if a point $P$ $(x_p, y_p)$ is in the triangle and "NO" if not... | instruction | 0 | 62,188 | 23 | 124,376 |
No | output | 1 | 62,188 | 23 | 124,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
F - Point Distance
Problem Statement
You work for invention center as a part time programmer. This center researches movement of protein molecules. It needs how molecules make clusters, so it ... | instruction | 0 | 62,226 | 23 | 124,452 |
No | output | 1 | 62,226 | 23 | 124,453 |
Provide a correct Python 3 solution for this coding contest problem.
Problem
Find the angle between the two given angles θ1 and θ2. Here, the angle between them is defined as "θ1 & plus; t'when t'is the one with the smallest absolute value among the t satisfying θ1 & plus; t = θ2 − t" as shown in the figure below.
A... | instruction | 0 | 62,233 | 23 | 124,466 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time
sys.setrecursionlimit(10**7)
inf = 10**20
mod = 10**9 + 7
def LI(): return list(map(int, input().split()))
def LF(): return list(map(float, input().split()))
def LS(): return input().split()
def I(): return... | output | 1 | 62,233 | 23 | 124,467 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,253 | 23 | 124,506 |
"Correct Solution:
```
input()
a = list(map(int, input().split()))
b = list(map(int, input().split()))
d = lambda a, b, n: sum([abs(x - y) ** n for x, y in zip(a, b)]) ** (1/n)
print(d(a, b, 1))
print(d(a, b, 2))
print(d(a, b, 3))
print(max([abs(x - y) for x, y in zip(a, b)]))
``` | output | 1 | 62,253 | 23 | 124,507 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,254 | 23 | 124,508 |
"Correct Solution:
```
import math
n=int(input())
x=list(map(int, input().split()))
y=list(map(int, input().split()))
print(sum([abs(a-b) for (a,b) in zip(x,y)]))
print(math.sqrt(sum([abs(a-b)**2 for (a,b) in zip(x,y)])))
print(math.pow(sum([abs(a-b)**3 for (a,b) in zip(x,y)]), 1/3))
print((max([abs(a-b) for (a,b) in z... | output | 1 | 62,254 | 23 | 124,509 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,255 | 23 | 124,510 |
"Correct Solution:
```
import math
n = int(input())
x = list(map(float, input().split()))
y = list(map(float, input().split()))
d1 = []
d2 = []
d3 = []
for i, j in zip(x, y):
d1.append(abs(i - j))
d2.append(abs(i - j)**2)
d3.append(abs(i - j)**3)
print(sum(d1))
print(math.sqrt(sum(d2)))
print(sum(d3)**(... | output | 1 | 62,255 | 23 | 124,511 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,256 | 23 | 124,512 |
"Correct Solution:
```
n = int(input())
X = [int(i) for i in input().split(" ")]
Y = [int(i) for i in input().split(" ")]
for p in range(1, 4):
print("{:.6f}".format(sum( [abs(a - b) ** p for a, b in zip(X,Y) ] ) ** (1 / p) ) )
print("{:.6f}".format(max( [ abs(a - b) for a, b in zip(X, Y) ] ) ) )
``` | output | 1 | 62,256 | 23 | 124,513 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,257 | 23 | 124,514 |
"Correct Solution:
```
from math import sqrt
n=int(input())
x=list(map(int,input().split()))
y=list(map(int,input().split()))
p1=0;p2=0;p3=0;p=[]
for i in range(n):
a=abs(x[i]-y[i])
p1+=a
p2+=a**2
p3+=a**3
p.append(a)
print(p1)
print(sqrt(p2))
print(p3**(1/3))
print(max(p))
``` | output | 1 | 62,257 | 23 | 124,515 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,258 | 23 | 124,516 |
"Correct Solution:
```
n=int(input())
x=list(map(float,input().split()))
y=list(map(float,input().split()))
for p in range(1,4):
Dxy=float(0)
for i in range(n):
Dxy+=abs(x[i]-y[i])**p
Dxy=Dxy**(1/p)
print(f'{Dxy:.6f}')
Dxy=float(0)
for i in range(n):
if Dxy<abs(x[i]-y[i]):Dxy=abs(x[i]-y[i])
... | output | 1 | 62,258 | 23 | 124,517 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,259 | 23 | 124,518 |
"Correct Solution:
```
n=int(input())
x=list(map(int,input().split()))
y=list(map(int,input().split()))
p1,p2,p3=0,0,0
Dxy=[0]*(n+1)
for i in range(n):
Dxy[i]=abs(x[i]-y[i])
p1+=Dxy[i]
p2+=Dxy[i]**2
p3+=Dxy[i]**3
p2**=0.5
p3**=(1/3)
print(p1,p2,p3,max(Dxy),sep='\n')
``` | output | 1 | 62,259 | 23 | 124,519 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance... | instruction | 0 | 62,260 | 23 | 124,520 |
"Correct Solution:
```
import math
input()
vx = [int(i) for i in input().split()]
vy = [int(i) for i in input().split()]
Dxy = []
for p in range(1,4):
Dxy.append(sum([abs(vx[i] - vy[i]) ** p for i in range(len(vx))]) ** (1 / p))
Dxy.append(max([abs(vx[i] - vy[i]) for i in range(len(vx))]))
for res in Dxy:
pri... | output | 1 | 62,260 | 23 | 124,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric ... | instruction | 0 | 62,261 | 23 | 124,522 |
Yes | output | 1 | 62,261 | 23 | 124,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric ... | instruction | 0 | 62,262 | 23 | 124,524 |
Yes | output | 1 | 62,262 | 23 | 124,525 |
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