message stringlengths 2 44.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 276 109k | cluster float64 23 23 | __index_level_0__ int64 552 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.
\\[ D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}} \\]
It can be the Manhattan distance
\\[ D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n| \\]
where $p = 1 $.
It can be the Euclidean distance
\\[ D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}} \\]
where $p = 2 $.
Also, it can be the Chebyshev distance
\\[ D_{xy} = max_{i=1}^n (|x_i - y_i|) \\]
where $p = \infty$
Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.
Constraints
* $1 \leq n \leq 100$
* $0 \leq x_i, y_i \leq 1000$
Input
In the first line, an integer $n$ is given. In the second and third line, $x = \\{x_1, x_2, ... x_n\\}$ and $y = \\{y_1, y_2, ... y_n\\}$ are given respectively. The elements in $x$ and $y$ are given in integers.
Output
Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively. The output should not contain an absolute error greater than 10-5.
Example
Input
3
1 2 3
2 0 4
Output
4.000000
2.449490
2.154435
2.000000
Submitted Solution:
```
import math
n=int(input())
x=list(map(int,input().split()))
y=list(map(int,input().split()))
D=[0,0,0,0]
p=[1,2,3]
for k in range(4):
if k==3:
D[k]=max(abs(x[i]-y[i])for i in range(n))
else:
D[k]=math.pow(sum(abs((x[i]-y[i])**p[k])for i in range(n)),1/p[k])
print("{:.6f}".format(D[k]))
``` | instruction | 0 | 62,263 | 23 | 124,526 |
Yes | output | 1 | 62,263 | 23 | 124,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.
\\[ D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}} \\]
It can be the Manhattan distance
\\[ D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n| \\]
where $p = 1 $.
It can be the Euclidean distance
\\[ D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}} \\]
where $p = 2 $.
Also, it can be the Chebyshev distance
\\[ D_{xy} = max_{i=1}^n (|x_i - y_i|) \\]
where $p = \infty$
Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.
Constraints
* $1 \leq n \leq 100$
* $0 \leq x_i, y_i \leq 1000$
Input
In the first line, an integer $n$ is given. In the second and third line, $x = \\{x_1, x_2, ... x_n\\}$ and $y = \\{y_1, y_2, ... y_n\\}$ are given respectively. The elements in $x$ and $y$ are given in integers.
Output
Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively. The output should not contain an absolute error greater than 10-5.
Example
Input
3
1 2 3
2 0 4
Output
4.000000
2.449490
2.154435
2.000000
Submitted Solution:
```
n = int(input())
X = list(map(int, input().split()))
Y = list(map(int, input().split()))
import math
p1 = []
p2 = []
p3 = []
for i in range(n):
p1.append(abs(X[i] - Y[i]))
p2.append(p1[i]**2)
p3.append(p1[i]**3)
print(sum(p1))
print(sum(p2)**(1/2))
print(sum(p3)**(1/3))
print(max(p1))
``` | instruction | 0 | 62,264 | 23 | 124,528 |
Yes | output | 1 | 62,264 | 23 | 124,529 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.
\\[ D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}} \\]
It can be the Manhattan distance
\\[ D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n| \\]
where $p = 1 $.
It can be the Euclidean distance
\\[ D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}} \\]
where $p = 2 $.
Also, it can be the Chebyshev distance
\\[ D_{xy} = max_{i=1}^n (|x_i - y_i|) \\]
where $p = \infty$
Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.
Constraints
* $1 \leq n \leq 100$
* $0 \leq x_i, y_i \leq 1000$
Input
In the first line, an integer $n$ is given. In the second and third line, $x = \\{x_1, x_2, ... x_n\\}$ and $y = \\{y_1, y_2, ... y_n\\}$ are given respectively. The elements in $x$ and $y$ are given in integers.
Output
Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively. The output should not contain an absolute error greater than 10-5.
Example
Input
3
1 2 3
2 0 4
Output
4.000000
2.449490
2.154435
2.000000
Submitted Solution:
```
n=int(input())
s_str=[]
for i in range(2):
s_str.append(input().split())
s_int=[]
for i in s_str:
s_int.append([int(s) for s in i])
manh=0
yu=0
p_3=0
che=[]
for i in range(n):
manh+=abs(s_int[0][i]-s_int[1][i])
yu+=(s_int[0][i]-s_int[1][i])**2
p_3+=(s_int[0][i]-s_int[1][i])**3
che.append(abs(s_int[0][i]-s_int[1][i]))
print(manh)
print(yu**(1/2))
print(p_3**(1/3))
print(max(che))
``` | instruction | 0 | 62,265 | 23 | 124,530 |
No | output | 1 | 62,265 | 23 | 124,531 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.
\\[ D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}} \\]
It can be the Manhattan distance
\\[ D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n| \\]
where $p = 1 $.
It can be the Euclidean distance
\\[ D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}} \\]
where $p = 2 $.
Also, it can be the Chebyshev distance
\\[ D_{xy} = max_{i=1}^n (|x_i - y_i|) \\]
where $p = \infty$
Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.
Constraints
* $1 \leq n \leq 100$
* $0 \leq x_i, y_i \leq 1000$
Input
In the first line, an integer $n$ is given. In the second and third line, $x = \\{x_1, x_2, ... x_n\\}$ and $y = \\{y_1, y_2, ... y_n\\}$ are given respectively. The elements in $x$ and $y$ are given in integers.
Output
Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively. The output should not contain an absolute error greater than 10-5.
Example
Input
3
1 2 3
2 0 4
Output
4.000000
2.449490
2.154435
2.000000
Submitted Solution:
```
#!/usr/bin/env python
import math
chebyshev = []
n = int(input())
x = input().split()
y = input().split()
for i in range(n):
x[i] = int(x[i])
for i in range(n):
y[i] = int(y[i])
for p in range(3):
total = 0
for i in range(n):
total += (math.fabs(x[i]-y[i]))**(p+1)
distance = total**(1/(p+1))
print("%.5f" % distance)
for i in range(n):
chebyshev.append(math.abs(x[i]-y[i]))
print("%.5f" % max(chebyshev))
``` | instruction | 0 | 62,266 | 23 | 124,532 |
No | output | 1 | 62,266 | 23 | 124,533 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.
\\[ D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}} \\]
It can be the Manhattan distance
\\[ D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n| \\]
where $p = 1 $.
It can be the Euclidean distance
\\[ D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}} \\]
where $p = 2 $.
Also, it can be the Chebyshev distance
\\[ D_{xy} = max_{i=1}^n (|x_i - y_i|) \\]
where $p = \infty$
Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.
Constraints
* $1 \leq n \leq 100$
* $0 \leq x_i, y_i \leq 1000$
Input
In the first line, an integer $n$ is given. In the second and third line, $x = \\{x_1, x_2, ... x_n\\}$ and $y = \\{y_1, y_2, ... y_n\\}$ are given respectively. The elements in $x$ and $y$ are given in integers.
Output
Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively. The output should not contain an absolute error greater than 10-5.
Example
Input
3
1 2 3
2 0 4
Output
4.000000
2.449490
2.154435
2.000000
Submitted Solution:
```
import math
def mink(x,y,p):
return (sum([math.fabs(_x - _y)**p for _x, _y in zip(x,y)]))**(1/p)
n = int(input())
x = [int(i) for i in input().split()]
y = [int(i) for i in input().split()]
print(mink(x,y,1))
print(mink(x,y,2))
print(mink(x,y,3))
print(mink(x,y,1000))
``` | instruction | 0 | 62,267 | 23 | 124,534 |
No | output | 1 | 62,267 | 23 | 124,535 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your task is to calculate the distance between two $n$ dimensional vectors $x = \\{x_1, x_2, ..., x_n\\}$ and $y = \\{y_1, y_2, ..., y_n\\}$.
The Minkowski's distance defined below is a metric which is a generalization of both the Manhattan distance and the Euclidean distance.
\\[ D_{xy} = (\sum_{i=1}^n |x_i - y_i|^p)^{\frac{1}{p}} \\]
It can be the Manhattan distance
\\[ D_{xy} = |x_1 - y_1| + |x_2 - y_2| + ... + |x_n - y_n| \\]
where $p = 1 $.
It can be the Euclidean distance
\\[ D_{xy} = \sqrt{(|x_1 - y_1|)^{2} + (|x_2 - y_2|)^{2} + ... + (|x_n - y_n|)^{2}} \\]
where $p = 2 $.
Also, it can be the Chebyshev distance
\\[ D_{xy} = max_{i=1}^n (|x_i - y_i|) \\]
where $p = \infty$
Write a program which reads two $n$ dimensional vectors $x$ and $y$, and calculates Minkowski's distance where $p = 1, 2, 3, \infty$ respectively.
Constraints
* $1 \leq n \leq 100$
* $0 \leq x_i, y_i \leq 1000$
Input
In the first line, an integer $n$ is given. In the second and third line, $x = \\{x_1, x_2, ... x_n\\}$ and $y = \\{y_1, y_2, ... y_n\\}$ are given respectively. The elements in $x$ and $y$ are given in integers.
Output
Print the distance where $p = 1, 2, 3$ and $\infty$ in a line respectively. The output should not contain an absolute error greater than 10-5.
Example
Input
3
1 2 3
2 0 4
Output
4.000000
2.449490
2.154435
2.000000
Submitted Solution:
```
import math
n = int(input())
x = list(map(int, input().split()))
y = list(map(int, input().split()))
for p in range(1, 4):
sum = 0
for i in range(n):
sum += math.fabs(x[i]-y[i])**p
print(sum**(1/p))
a = []
for i in range(n):
a.append(math.fabs(x[i]-y[i]))
a = a.sort()
print(a[n])
``` | instruction | 0 | 62,268 | 23 | 124,536 |
No | output | 1 | 62,268 | 23 | 124,537 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,860 | 23 | 125,720 |
Tags: brute force, greedy, sortings
Correct Solution:
```
l = input().split()
n = int(l[0])
b = int(l[1])
l = input().split()
for i in range(len(l)):
l[i] = int(l[i])
l.sort()
m = []
if len(l) == 1:
print(0)
else:
for i in range(n):
if not i == n-1:
for j in range(i + 1, n):
if l[j] - l[i] <= b:
m.append(i + (n - j) - 1)
if m == []:
print(n-1)
else:
print(min(m))
``` | output | 1 | 62,860 | 23 | 125,721 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,861 | 23 | 125,722 |
Tags: brute force, greedy, sortings
Correct Solution:
```
n , d = map(int,input().split())
point_array = list(map(int,input().split()))
point_array.sort()
max_len = 0
for i in range(0,n):
for j in range(i,n):
if (point_array[j] - point_array[i] <= d):
if (j-i+1 > max_len ):
max_len = j-i+1
if( i== j and max_len == 0):
max_len = 1
print(n-max_len)
``` | output | 1 | 62,861 | 23 | 125,723 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,862 | 23 | 125,724 |
Tags: brute force, greedy, sortings
Correct Solution:
```
n,d = map(int,input().split())
x = list(map(int,input().split()))
x.sort()
z = n
for i in range(n):
y = 0
for j in range(i,n):
if (x[j]-x[i] <= d):
if n - (j -i)-1 < z:
z = n - (j -i)-1
print(z)
``` | output | 1 | 62,862 | 23 | 125,725 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,863 | 23 | 125,726 |
Tags: brute force, greedy, sortings
Correct Solution:
```
# coding=utf-8
n, d = list(map(int, input().split()))
a = list(map(int, input().split()))
a.sort()
best = 100000
for i in range(len(a)):
for j in range(i, len(a)):
if a[j] - a[i] <= d and (n - j + i-1) < best:
best = (n - j + i - 1)
print(best)
``` | output | 1 | 62,863 | 23 | 125,727 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,864 | 23 | 125,728 |
Tags: brute force, greedy, sortings
Correct Solution:
```
n,d=map(int,input().split())
x=sorted(list(map(int,input().split(" "))))
sum=0
list=[]
for i in range(n):
for j in range(i,n):
if x[j]-x[i]<=d:
sum+=1
list.append(sum)
sum=0
print(len(x)-max(list))
``` | output | 1 | 62,864 | 23 | 125,729 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,865 | 23 | 125,730 |
Tags: brute force, greedy, sortings
Correct Solution:
```
n, d = map(int, input().split())
mas = list(map(int, input().split()))
mas.sort()
mas.reverse()
fas = []
for a in range(n):
for b in range(a, n):
if mas[a] - mas[b] <= d:
fas.append(a + n - b - 1)
if len(fas) == 0:
print(0)
else:
print(min(fas))
``` | output | 1 | 62,865 | 23 | 125,731 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,866 | 23 | 125,732 |
Tags: brute force, greedy, sortings
Correct Solution:
```
n, d = [int(i) for i in input().split()]
x = [int(i) for i in input().split()]
# if d == 0:
# print(0)
# exit()
x.sort()
# print(x)
hsh = []
pos = 0
l = len(x)
tmp = -1
for i in range(101):
if x[pos] == i:
for pos1 in range(pos, l):
if x[pos] == x[pos1]:
tmp += 1
else:
break
pos = pos1
hsh.append(tmp)
# if pos != l - 1 and x[pos + 1] <= i:
# pos += 1
#
# if pos > 0 and x[pos] == x[pos - 1]:
# hsh[-1] += 1
# i -= 1
# else:
# hsh.append(pos)
#
# print(i)
# print(hsh)
mx = 0
for i in range(l):
if x[i] + d > 100:
mx = max(mx, l - i)
break
if hsh[x[i] + d] - i + 1 > mx:
mx = hsh[x[i] + d] - i + 1
#print(mx)
print(max(0, l - mx))
``` | output | 1 | 62,866 | 23 | 125,733 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3. | instruction | 0 | 62,867 | 23 | 125,734 |
Tags: brute force, greedy, sortings
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
#from bisect import bisect_left as bl #c++ lowerbound bl(array,element)
#from bisect import bisect_right as br #c++ upperbound br(array,element)
def main():
n,d=map(int,input().split(" "))
a=sorted(list(map(int,input().split(" "))))
ans=n-1
for x in range(n):
for y in range(x+1,n):
if a[y]-a[x]<=d:
ans=min(ans,(n-y-1)+x)
print(ans)
#-----------------------------BOSS-------------------------------------!
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | output | 1 | 62,867 | 23 | 125,735 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
def multi():
inp = input().split(" ")
k, d = int(inp[0]), int(inp[1])
l = list(map(int, input().split(" ")))
result = len(l)
l.sort()
for i in range(0, len(l)):
for j in range(len(l) - 1, i - 1, -1):
diam = abs(l[i] - l[j])
if diam <= d:
subResult = len(l) - (j - i + 1)
if result > subResult:
result = subResult
break
print(result)
return
multi()
``` | instruction | 0 | 62,868 | 23 | 125,736 |
Yes | output | 1 | 62,868 | 23 | 125,737 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
a=input().split()
a[0]=int(a[0])
a[1]=int(a[1])
b=input().split()
counter=0
maxLen=0
for i in range(len(b)):
b[i]=int(b[i])
b.sort()
for i in range(0,len(b)):
for j in range(i,len(b)):
if(abs(b[i]-b[j])<=a[1]):
if(abs(j-i)==0 and i==j and maxLen==0):
maxLen=1
else:
if(abs(j-i)+1>maxLen):
maxLen=abs(j-i)+1
print(len(b)-maxLen)
``` | instruction | 0 | 62,869 | 23 | 125,738 |
Yes | output | 1 | 62,869 | 23 | 125,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
n, d = map(int, input().split())
s1 = input()
s = list(map(int, s1.split()))
s_res = [[] for i in range(n)]
s.sort()
for i in range(len(s)):
for j in range(len(s)):
if abs(int(s[j]) - int(s[i])) <= d and int(s[i]) <= int(s[j]):
s_res[i].append(int(s[j]))
l = -1
for i in range(n):
if len(s_res[i]) > l:
l = len(s_res[i])
print(n - l)
``` | instruction | 0 | 62,870 | 23 | 125,740 |
Yes | output | 1 | 62,870 | 23 | 125,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
nd = input().split(' ')
n, d = int(nd[0]), int(nd[1])
points = input().split(' ')
for p in range(len(points)):
points[p] = int(points[p])
points.sort()
to_remove = []
l = len(points)
for i in range(l):
for j in range(l):
if abs(points[i] - points[j]) <= d:
to_remove.append(l - (i-j+1))
print(min(to_remove))
``` | instruction | 0 | 62,871 | 23 | 125,742 |
Yes | output | 1 | 62,871 | 23 | 125,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
n,item=input().split()
n=int(n)
item=int(item)
list1=[int(x) for x in input().split()]
list1.sort()
counter=0
while(True):
if(list1[-1]-list1[0]>item):
list1.remove(list1[-1])
counter+=1
else:
break
print(counter)
``` | instruction | 0 | 62,872 | 23 | 125,744 |
No | output | 1 | 62,872 | 23 | 125,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
def multi():
inp = input().split(" ")
k, d = int(inp[0]), int(inp[1])
l = list(map(int, input().split(" ")))
result = 0
u = 0
l.sort()
while l[len(l) - 1] - l[0] > d:
u = -1 if u == 0 else 0
l.pop(u)
result += 1
print(result)
return
multi()
``` | instruction | 0 | 62,873 | 23 | 125,746 |
No | output | 1 | 62,873 | 23 | 125,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
str1=input()
str2=input()
a=str1.split(" ")
b=str2.split(" ")
n,d=int(a[0]),int(a[1])
multiset=[]
for i in b:
multiset.append(int(i))
multiset.sort()
maximum=0
for i in range(1,n):
j=i-1
count=1
while (j>=0 and abs(multiset[i]-multiset[j])<=d):
count+=1
j-=1
if (count>maximum):
maximum=count
print(n-maximum)
``` | instruction | 0 | 62,874 | 23 | 125,748 |
No | output | 1 | 62,874 | 23 | 125,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We've got no test cases. A big olympiad is coming up. But the problemsetters' number one priority should be adding another problem to the round.
The diameter of a multiset of points on the line is the largest distance between two points from this set. For example, the diameter of the multiset {1, 3, 2, 1} is 2.
Diameter of multiset consisting of one point is 0.
You are given n points on the line. What is the minimum number of points you have to remove, so that the diameter of the multiset of the remaining points will not exceed d?
Input
The first line contains two integers n and d (1 ≤ n ≤ 100, 0 ≤ d ≤ 100) — the amount of points and the maximum allowed diameter respectively.
The second line contains n space separated integers (1 ≤ xi ≤ 100) — the coordinates of the points.
Output
Output a single integer — the minimum number of points you have to remove.
Examples
Input
3 1
2 1 4
Output
1
Input
3 0
7 7 7
Output
0
Input
6 3
1 3 4 6 9 10
Output
3
Note
In the first test case the optimal strategy is to remove the point with coordinate 4. The remaining points will have coordinates 1 and 2, so the diameter will be equal to 2 - 1 = 1.
In the second test case the diameter is equal to 0, so its is unnecessary to remove any points.
In the third test case the optimal strategy is to remove points with coordinates 1, 9 and 10. The remaining points will have coordinates 3, 4 and 6, so the diameter will be equal to 6 - 3 = 3.
Submitted Solution:
```
nd = input().split(' ')
n, d = int(nd[0]), int(nd[1])
points = input().split(' ')
for p in range(len(points)):
points[p] = int(points[p])
points.sort()
to_remove = 0
if len(points) >= 3:
while abs(points[0] - points[-1]) > d and len(points) >= 2:
if abs(points[0] - points[-2]) > abs(points[1] - points[-1]):
del points[0]
else:
del points[-1]
to_remove += 1
elif len(points) == 2 and abs(points[0] - points[-1]) > d:
to_remove = 1
print(to_remove)
``` | instruction | 0 | 62,875 | 23 | 125,750 |
No | output | 1 | 62,875 | 23 | 125,751 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,049 | 23 | 126,098 |
"Correct Solution:
```
e1, e2, e3, e4 = map(int,input().split())
if e1 == e2 and e3 == e4:
print('yes')
elif e2 == e3 and e4 == e1:
print('yes')
elif e3 == e1 and e2 == e4:
print('yes')
else:
print('no')
``` | output | 1 | 63,049 | 23 | 126,099 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,050 | 23 | 126,100 |
"Correct Solution:
```
print('yes' if len(set(input().split())) <= 2 else 'no')
``` | output | 1 | 63,050 | 23 | 126,101 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,051 | 23 | 126,102 |
"Correct Solution:
```
a,b,c,d=sorted(map(int,input().split()))
print(['no','yes'][a==b and c==d])
``` | output | 1 | 63,051 | 23 | 126,103 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,052 | 23 | 126,104 |
"Correct Solution:
```
e1,e2,e3,e4=input().split()
e1=int(e1)
e2=int(e2)
e3=int(e3)
e4=int(e4)
if e1==e2 and e1==e3 and e1==e4:
print("yes")
elif e1==e2:
if e3==e4:
print("yes")
else:
print("no")
elif e1==e3:
if e2==e4:
print("yes")
else:
print("no")
elif e1==e4:
if e3==e2:
print("yes")
else:
print("no")
elif e3==e2:
if e1==e4:
print("yes")
else:
print("no")
elif e4==e2:
if e3==e1:
print("yes")
else:
print("no")
elif e3==e4:
if e1==e2:
print("yes")
else:
print("no")
else:
print("no")
``` | output | 1 | 63,052 | 23 | 126,105 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,053 | 23 | 126,106 |
"Correct Solution:
```
# coding: utf-8
# Your code here!
x = sorted(map(int,input().split()))
if x[0]==x[1] and x[2]==x[3]:
print("yes")
else:
print("no")
``` | output | 1 | 63,053 | 23 | 126,107 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,054 | 23 | 126,108 |
"Correct Solution:
```
e1,e2,e3,e4=(int(x) for x in input().split())
if 1<=e1<=100 and 1<=e2<=100 and 1<=e3<=100 and 1<=e4<=100:
if e1==e2 and e3==e4 or e1==e3 and e2==e4 or e1==e4 and e2==e3:
print("yes")
else:
print("no")
``` | output | 1 | 63,054 | 23 | 126,109 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,055 | 23 | 126,110 |
"Correct Solution:
```
e1,e2,e3,e4=map(int,input().split())# Your code here=map(int,input().split())
if e1==e2 and e3==e4:
print('yes')
elif e1==e3 and e2==e4:
print('yes')
elif e1==e4 and e2==e3:
print('yes')
else:
print('no')
``` | output | 1 | 63,055 | 23 | 126,111 |
Provide a correct Python 3 solution for this coding contest problem.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no | instruction | 0 | 63,056 | 23 | 126,112 |
"Correct Solution:
```
e = sorted(map(int, input().split()))
print("yes" if e[0] == e[1] and e[2] == e[3] else "no")
``` | output | 1 | 63,056 | 23 | 126,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
e1,e2,e3,e4 = map(int,input().split())
if e1==e2:
if e3==e4:
print("yes")
else:
print("no")
elif e1==e3:
if e2==e4:
print("yes")
else:
print("no")
elif e1==e4:
if e2==e3:
print("yes")
else:
print("no")
else:
print("no")
``` | instruction | 0 | 63,057 | 23 | 126,114 |
Yes | output | 1 | 63,057 | 23 | 126,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
# coding: utf-8
# Your code here!
e1,e2,e3,e4=map(int,input().split())
if e1==e2 and e3==e4:
print('yes')
elif e1==e3 and e2==e4:
print('yes')
elif e1==e4 and e2==e3:
print('yes')
else:
print('no')
``` | instruction | 0 | 63,058 | 23 | 126,116 |
Yes | output | 1 | 63,058 | 23 | 126,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
e1, e2, e3, e4 = map(int,input().split())
if e1 == e2:
if e3 == e4:
print('yes')
else:
print('no')
elif e1 == e3:
if e2 == e4:
print('yes')
else:
print('no')
elif e1 == e4:
if e2 == e3:
print('yes')
else:
print('no')
else:
print('no')
``` | instruction | 0 | 63,059 | 23 | 126,118 |
Yes | output | 1 | 63,059 | 23 | 126,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
e1,e2,e3,e4=map(int,input().split())
if (e1==e2 and e3==e4) or (e1==e3 and e2==e4) or (e1==e4 and e2==e3) :
print('yes')
else :
print('no')
``` | instruction | 0 | 63,060 | 23 | 126,120 |
Yes | output | 1 | 63,060 | 23 | 126,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
e = sorted(map(int, input().split()))
print("yes"*(e[0]==e[1])*(e[2]==e[3])+"no"*((e[0]!=e[1])+(e[2]!=e[3])))
``` | instruction | 0 | 63,061 | 23 | 126,122 |
No | output | 1 | 63,061 | 23 | 126,123 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
e = sorted(map(int, input().split()))
print("yes" if e[0] == e[1] and e[2] == e[3])
``` | instruction | 0 | 63,062 | 23 | 126,124 |
No | output | 1 | 63,062 | 23 | 126,125 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
a, b, c, d = sorted(map(int, input().split())
print("YES" if a == b and c == d else "NO")
``` | instruction | 0 | 63,063 | 23 | 126,126 |
No | output | 1 | 63,063 | 23 | 126,127 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The educational program (AHK Education) of the Aiz Broadcasting Association broadcasts a handicraft program for children, "Play with Tsukuro". Today is the time to make a rectangle with sticks, but I would like to see if I can make a rectangle using the four sticks I prepared. However, the stick must not be cut or broken.
Given the lengths of the four bars, write a program to determine if you can make a rectangle with all of them as sides.
Input
The input is given in the following format.
e1 e2 e3 e4
The input consists of one line and is given the integer ei (1 ≤ ei ≤ 100) representing the length of each bar.
Output
Outputs "yes" if a rectangle can be created, and "no" if it cannot be created. However, since a square is a type of rectangle, "yes" is output even if it is a square.
Examples
Input
1 1 3 4
Output
no
Input
1 1 2 2
Output
yes
Input
2 1 1 2
Output
yes
Input
4 4 4 10
Output
no
Submitted Solution:
```
a = list(map(int, input().split()))
print('yes' if ((a[0] in a) and (a[1] in a) and (a[2] in a) and (a[3] in a)) else 'no')
``` | instruction | 0 | 63,064 | 23 | 126,128 |
No | output | 1 | 63,064 | 23 | 126,129 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,087 | 23 | 126,174 |
"Correct Solution:
```
while True:
d, w = map(int, input().split())
if d == 0:
break
area = []
for _ in range(d):
area.append(list(map(int, input().split())))
a = 0
for dp in range(1, d - 1):
for wp in range(1, w - 1):
for i in range(1, d - dp):
for j in range(1, w - wp):
mawari = min(area[i - 1][j - 1:j + wp + 1] + area[i + dp][j - 1:j + wp + 1])
naka = 0
for ii in range(dp):
mawari = min(mawari, area[i + ii][j - 1], area[i + ii][j + wp])
naka = max([naka] + area[i + ii][j:j + wp])
if mawari > naka:
vn = 0
for ii in range(dp):
for jj in range(wp):
vn += mawari - area[i + ii][j + jj]
a = max(vn, a)
print(a)
``` | output | 1 | 63,087 | 23 | 126,175 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,088 | 23 | 126,176 |
"Correct Solution:
```
def f(l,r,u,d):
global e,no
res = 0
hori = 10
for i in range(u,d+1):
if i==u or i==d:
hori = min(hori,min(e[i][l:r+1]))
else:
hori = min(hori,e[i][l],e[i][r])
if hori==no:
return 0
for i in range(u+1,d):
for j in range(l+1,r):
if hori<=e[i][j]:
return 0
res += abs(hori-e[i][j])
return res
while True:
D,W = map(int,input().split())
if D+W==0:
break
e = [list(map(int,input().split())) for _ in range(D)]
for i in range(D):
no = min(e[0]) if i==0 else min(no,min(e[i]))
#l,r,u,d
ans = 0
for l in range(W-2):
for r in range(l+2,W):
for u in range(D-2):
for d in range(u+2,D):
ans = max(ans,f(l,r,u,d))
print(ans)
``` | output | 1 | 63,088 | 23 | 126,177 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,089 | 23 | 126,178 |
"Correct Solution:
```
import sys
from itertools import permutations, combinations, product
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def LIST(): return list(map(int, input().split()))
def MAP(): return map(int, input().split())
ans = []
while 1:
d, w = MAP()
if d == 0 and w == 0:
break
e = [LIST() for _ in range(d)]
sum_max = 0
for i in combinations(range(d), 2):
if abs(i[0]-i[1]) == 1:
continue
for j in combinations(range(w), 2):
if abs(j[0]-j[1]) == 1:
continue
# 堀の最小値を見つける
min_ = 10
for k in range(i[0], i[1]+1):
if k == i[0] or k == i[1]:
for l in range(j[0], j[1]+1):
min_ = min(min_, e[k][l])
else:
min_ = min(min_, e[k][j[0]])
min_ = min(min_, e[k][j[1]])
# 内側を調べる．内側にmin_以上の値があればだめ．
sum_ = 0
for k in range(i[0]+1, i[1]):
for l in range(j[0]+1, j[1]):
# print(k, l, e[k][l])
if e[k][l] >= min_:
sum_ = 0
break
else:
sum_ += (min_-e[k][l])
if e[k][l] >= min_:
break
sum_max = max(sum_max, sum_)
ans.append(sum_max)
for x in ans:
print(x)
``` | output | 1 | 63,089 | 23 | 126,179 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,090 | 23 | 126,180 |
"Correct Solution:
```
def main():
while True:
d, w = map(int, input().split())
if d == 0: break
garden = []
for i in range(d):
garden.append(list(map(int, input().split())))
pondmax = 0
for tly in range(len(garden)):
for tlx in range(len(garden[0])):
for bry in range(tly + 2, len(garden)):
for brx in range(tlx + 2, len(garden[0])):
# sampling
l_gray = []
d_gray = []
for spy in range(tly, bry + 1):
for spx in range(tlx, brx + 1):
if spy == tly or spy == bry or spx == tlx or spx == brx:
d_gray.append(garden[spy][spx])
else: l_gray.append(garden[spy][spx])
if min(d_gray) > max(l_gray):
pond = 0
for depth in l_gray:
pond += min(d_gray) - depth
if pond > pondmax: pondmax = pond
print(pondmax)
main()
``` | output | 1 | 63,090 | 23 | 126,181 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,091 | 23 | 126,182 |
"Correct Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import itertools
def rdp_connect() -> bool:
global h, w, e
h, w = map(int, input().split())
if h == 0 and w == 0:
return False
e = [list(map(int, input().split())) for _ in range(h)]
return True
def rdp_scan(x1: int, y1: int, x2: int, y2: int) -> int:
edges = []
edges.extend([e[j][x1] for j in range(y1, y2 + 1)])
edges.extend([e[j][x2] for j in range(y1, y2 + 1)])
edges.extend([e[y1][i] for i in range(x1 + 1, x2)])
edges.extend([e[y2][i] for i in range(x1 + 1, x2)])
inner = [e[j][i] for j, i in itertools.product(range(y1 + 1, y2), range(x1 + 1, x2))]
edges_min = min(edges)
if edges_min - max(inner) <= 0:
return 0
return sum(map(lambda e: edges_min - e, inner))
if __name__ == '__main__':
while rdp_connect():
best = 0
for y1, x1 in itertools.product(range(h), range(w)):
for y2, x2 in itertools.product(range(y1 + 2, h), range(x1 + 2, w)):
best = max(best, rdp_scan(x1, y1, x2, y2))
print(best)
``` | output | 1 | 63,091 | 23 | 126,183 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,092 | 23 | 126,184 |
"Correct Solution:
```
while True:
d, w = map(int, input().split())
if d == 0:
break
area = []
for _ in range(d):
area.append(list(map(int, input().split())))
v = 0
for dp in range(1, d - 1):
for wp in range(1, w - 1):
for i in range(1, d - dp):
for j in range(1, w - wp):
mawari = min(area[i - 1][j - 1:j + wp + 1] + area[i + dp][j - 1:j + wp + 1])
naka = 0
for ii in range(dp):
mawari = min(mawari, area[i + ii][j - 1], area[i + ii][j + wp])
naka = max([naka] + area[i + ii][j:j + wp])
if mawari > naka:
vn = 0
for ii in range(dp):
for jj in range(wp):
vn += mawari - area[i + ii][j + jj]
v = max(vn, v)
print(v)
``` | output | 1 | 63,092 | 23 | 126,185 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,093 | 23 | 126,186 |
"Correct Solution:
```
while True:
d,w = map(int,input().split())
if d == 0:
break
e = list(list(map(int,input().split()))for i in range(d))
ans = 0
for sx in range(w-2):
for sy in range(d-2):
for tx in range(sx+2,w):
for ty in range(sy+2,d):
#外周の最大値
max_out = float('inf')
for i in range(sx,tx+1):
max_out = min(e[sy][i],e[ty][i],max_out)
for i in range(sy,ty+1):
max_out = min(e[i][sx],e[i][tx],max_out)
v = 0
for j in range(sx+1,tx):
for i in range(sy+1,ty):
v += max_out-e[i][j]
if max_out - e[i][j] <= 0:
v = -float('inf')
ans = max(v,ans)
print(ans)
``` | output | 1 | 63,093 | 23 | 126,187 |
Provide a correct Python 3 solution for this coding contest problem.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9 | instruction | 0 | 63,094 | 23 | 126,188 |
"Correct Solution:
```
def check(ry, rx, x, y, f):
tmpmin = float("inf")
for yi in range(ry):
tmpmin = min(tmpmin, f[yi + y][x])
for xi in range(rx):
tmpmin = min(tmpmin, f[y][xi + x])
for yi in range(ry):
tmpmin = min(tmpmin, f[yi + y][x + rx - 1])
for xi in range(rx):
tmpmin = min(tmpmin, f[ry - 1 + y][x + xi])
res = 0
for yi in range(y + 1, y + ry - 1):
for xi in range(x + 1, x + rx - 1):
res += tmpmin-f[yi][xi]
if f[yi][xi] >= tmpmin:
return 0
return res
def main(d, w):
field = [list(map(int, input().split())) for i in range(d)]
res = 0
for ry in range(3,d+1):
for rx in range(3,w+1):
for y in range(d - ry + 1):
for x in range(w - rx + 1):
res = max(res, check(ry, rx, x, y, field))
print(res)
while 1:
d, w = map(int, input().split())
if d == w == 0:
break
main(d, w)
``` | output | 1 | 63,094 | 23 | 126,189 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(d,w):
aa = [LI() for _ in range(d)]
r = 0
for i in range(d-2):
for j in range(w-2):
for k in range(i+2,d):
for l in range(j+2,w):
mi = inf
for m in range(i,k+1):
t = aa[m][j]
if mi > t:
mi = t
t = aa[m][l]
if mi > t:
mi = t
for m in range(j,l+1):
t = aa[i][m]
if mi > t:
mi = t
t = aa[k][m]
if mi > t:
mi = t
s = 0
for m in range(i+1,k):
for n in range(j+1,l):
if mi <= aa[m][n]:
s = -inf
break
s += mi - aa[m][n]
if r < s:
r = s
return r
while 1:
n,m = LI()
if n == 0:
break
rr.append(f(n,m))
return '\n'.join(map(str, rr))
print(main())
``` | instruction | 0 | 63,095 | 23 | 126,190 |
Yes | output | 1 | 63,095 | 23 | 126,191 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9
Submitted Solution:
```
import sys
# python template for atcoder1
sys.setrecursionlimit(10**9)
input = sys.stdin.readline
def calcVolume(L, R, T, B, min_wall):
'''
池の体積を計算
'''
ret = 0
for w in range(L, R+1):
for h in range(B, T+1):
ret += (min_wall-garden[h][w])
return ret
def pondsVolume(L, R, T, B):
'''
池の体積をreturn
池を作れないなら-1
'''
# 池の中で一番高い所
max_in_pond = 0
for w in range(L, R+1):
for h in range(B, T+1):
max_in_pond = max(max_in_pond, garden[h][w])
# 周りの壁の一番低い所
min_wall = float('inf')
for w in range(L-1, R+2):
min_wall = min(min_wall, garden[B-1][w], garden[T+1][w])
for h in range(B-1, T+2):
min_wall = min(min_wall, garden[h][L-1], garden[h][R+1])
if min_wall <= max_in_pond:
return -1
else:
return calcVolume(L, R, T, B, min_wall)
while True:
d, w = map(int, input().split())
if d == 0:
break
garden = [list(map(int, input().split())) for _ in range(d)]
ans = 0
wallMin = 0
# 池の範囲を全探索
for L in range(1, w-1):
for B in range(1, d-1):
for R in range(L, w-1):
for T in range(B, d-1):
ans = max(ans, pondsVolume(L, R, T, B))
print(ans)
``` | instruction | 0 | 63,096 | 23 | 126,192 |
Yes | output | 1 | 63,096 | 23 | 126,193 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9
Submitted Solution:
```
from itertools import product
while True:
d, w = map(int, input().split())
if d == 0:
exit()
ans = 0
e = [list(map(int, input().split())) for _ in range(d)]
for si, sj in product(range(1, d - 1), range(1, w - 1)):
for ti, tj in product(range(si + 1, d), range(sj + 1, w)):
mx = 0
for i, j in product(range(si, ti), range(sj, tj)):
mx = max(mx, e[i][j])
mn = 100
for i, j in product([si - 1, ti], range(sj - 1, tj + 1)):
mn = min(mn, e[i][j])
for i, j in product(range(si - 1, ti + 1), [sj - 1, tj]):
mn = min(mn, e[i][j])
if mx >= mn:
continue
tmp = 0
for i, j in product(range(si, ti), range(sj, tj)):
tmp += mn - e[i][j]
ans = max(ans, tmp)
print(ans)
``` | instruction | 0 | 63,097 | 23 | 126,194 |
Yes | output | 1 | 63,097 | 23 | 126,195 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Garden with Ponds
Mr. Gardiner is a modern garden designer who is excellent at utilizing the terrain features. His design method is unique: he first decides the location of ponds and design them with the terrain features intact.
According to his unique design procedure, all of his ponds are rectangular with simple aspect ratios. First, Mr. Gardiner draws a regular grid on the map of the garden site so that the land is divided into cells of unit square, and annotates every cell with its elevation. In his design method, a pond occupies a rectangular area consisting of a number of cells. Each of its outermost cells has to be higher than all of its inner cells. For instance, in the following grid map, in which numbers are elevations of cells, a pond can occupy the shaded area, where the outermost cells are shaded darker and the inner cells are shaded lighter. You can easily see that the elevations of the outermost cells are at least three and those of the inner ones are at most two.
<image>
A rectangular area on which a pond is built must have at least one inner cell. Therefore, both its width and depth are at least three.
When you pour water at an inner cell of a pond, the water can be kept in the pond until its level reaches that of the lowest outermost cells. If you continue pouring, the water inevitably spills over. Mr. Gardiner considers the larger capacity the pond has, the better it is. Here, the capacity of a pond is the maximum amount of water it can keep. For instance, when a pond is built on the shaded area in the above map, its capacity is (3 − 1) + (3 − 0) + (3 − 2) = 6, where 3 is the lowest elevation of the outermost cells and 1, 0, 2 are the elevations of the inner cells. Your mission is to write a computer program that, given a grid map describing the elevation of each unit square cell, calculates the largest possible capacity of a pond built in the site.
Note that neither of the following rectangular areas can be a pond. In the left one, the cell at the bottom right corner is not higher than the inner cell. In the right one, the central cell is as high as the outermost cells.
<image>
Input
The input consists of at most 100 datasets, each in the following format.
d w
e1, 1 ... e1, w
...
ed, 1 ... ed, w
The first line contains d and w, representing the depth and the width, respectively, of the garden site described in the map. They are positive integers between 3 and 10, inclusive. Each of the following d lines contains w integers between 0 and 9, inclusive, separated by a space. The x-th integer in the y-th line of the d lines is the elevation of the unit square cell with coordinates (x, y).
The end of the input is indicated by a line containing two zeros separated by a space.
Output
For each dataset, output a single line containing the largest possible capacity of a pond that can be built in the garden site described in the dataset. If no ponds can be built, output a single line containing a zero.
Sample Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output for the Sample Input
0
3
1
9
Example
Input
3 3
2 3 2
2 1 2
2 3 1
3 5
3 3 4 3 3
3 1 0 2 3
3 3 4 3 2
7 7
1 1 1 1 1 0 0
1 0 0 0 1 0 0
1 0 1 1 1 1 1
1 0 1 0 1 0 1
1 1 1 1 1 0 1
0 0 1 0 0 0 1
0 0 1 1 1 1 1
6 6
1 1 1 1 2 2
1 0 0 2 0 2
1 0 0 2 0 2
3 3 3 9 9 9
3 0 0 9 0 9
3 3 3 9 9 9
0 0
Output
0
3
1
9
Submitted Solution:
```
while True:
d,w = map(int,input().split())
if d+w == 0:break
pond = [list(map(int,input().split())) for _ in range(d)]
ans = 0
for left in range(w-1):
for right in range(w-1,left+1,-1):
for top in range(d-1):
for under in range(d-1,top+1,-1):
outh = 10
outh = min(outh,min(pond[top][left:right+1]))
outh = min(outh,min(pond[under][left:right+1]))
zpond = list(zip(*pond))
outh = min(outh,min(zpond[left][top:under]))
outh = min(outh,min(zpond[right][top:under]))
pondh = 0
for i in range(top+1, under):
pondh = max(pondh,max(pond[i][left+1:right]))
if pondh < outh:
cap = outh*(under-top-1) * (right-left-1) - sum(sum(pond[i][left+1:right]) for i in range(top+1,under))
ans = max(cap,ans)
print(ans)
``` | instruction | 0 | 63,098 | 23 | 126,196 |
Yes | output | 1 | 63,098 | 23 | 126,197 |
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