text stringlengths 1.02k 43.5k | conversation_id int64 853 107k | embedding list | cluster int64 24 24 |
|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a favorite sequence a[1 ... n] consisting of n integers. He wrote it out on the whiteboard as follows:
* he wrote the number a_1 to the left side (at the beginning of the whiteboard);
* he wrote the number a_2 to the right side (at the end of the whiteboard);
* then as far to the left as possible (but to the right from a_1), he wrote the number a_3;
* then as far to the right as possible (but to the left from a_2), he wrote the number a_4;
* Polycarp continued to act as well, until he wrote out the entire sequence on the whiteboard.
<image> The beginning of the result looks like this (of course, if n ≥ 4).
For example, if n=7 and a=[3, 1, 4, 1, 5, 9, 2], then Polycarp will write a sequence on the whiteboard [3, 4, 5, 2, 9, 1, 1].
You saw the sequence written on the whiteboard and now you want to restore Polycarp's favorite sequence.
Input
The first line contains a single positive integer t (1 ≤ t ≤ 300) — the number of test cases in the test. Then t test cases follow.
The first line of each test case contains an integer n (1 ≤ n ≤ 300) — the length of the sequence written on the whiteboard.
The next line contains n integers b_1, b_2,…, b_n (1 ≤ b_i ≤ 10^9) — the sequence written on the whiteboard.
Output
Output t answers to the test cases. Each answer — is a sequence a that Polycarp wrote out on the whiteboard.
Example
Input
6
7
3 4 5 2 9 1 1
4
9 2 7 1
11
8 4 3 1 2 7 8 7 9 4 2
1
42
2
11 7
8
1 1 1 1 1 1 1 1
Output
3 1 4 1 5 9 2
9 1 2 7
8 2 4 4 3 9 1 7 2 8 7
42
11 7
1 1 1 1 1 1 1 1
Note
In the first test case, the sequence a matches the sequence from the statement. The whiteboard states after each step look like this:
[3] ⇒ [3, 1] ⇒ [3, 4, 1] ⇒ [3, 4, 1, 1] ⇒ [3, 4, 5, 1, 1] ⇒ [3, 4, 5, 9, 1, 1] ⇒ [3, 4, 5, 2, 9, 1, 1].
Submitted Solution:
```
try:
for t in range(int(input())):
n=int(input())
arr=[int(x) for x in input().split()]
a=0
b=-1
ans=[]
for i in range(len(arr)):
if i%2==0:
ans.append(arr[a])
a=a+1
else:
ans.append(arr[b])
b=b-1
for i in arr:
print(i,end=' ')
except:
pass
```
No
| 31,964 | [
0.39892578125,
0.056121826171875,
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0.210693359375,
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0.1614990234375,
0.09375,
0.8212890625,
0.56787109375,
0.0643310546875,
0.06475830078125,
-0.82958984375,
-0.5927734375,
-0.419921875,
-0.546875,
-0.513671875,
-0.77... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a favorite sequence a[1 ... n] consisting of n integers. He wrote it out on the whiteboard as follows:
* he wrote the number a_1 to the left side (at the beginning of the whiteboard);
* he wrote the number a_2 to the right side (at the end of the whiteboard);
* then as far to the left as possible (but to the right from a_1), he wrote the number a_3;
* then as far to the right as possible (but to the left from a_2), he wrote the number a_4;
* Polycarp continued to act as well, until he wrote out the entire sequence on the whiteboard.
<image> The beginning of the result looks like this (of course, if n ≥ 4).
For example, if n=7 and a=[3, 1, 4, 1, 5, 9, 2], then Polycarp will write a sequence on the whiteboard [3, 4, 5, 2, 9, 1, 1].
You saw the sequence written on the whiteboard and now you want to restore Polycarp's favorite sequence.
Input
The first line contains a single positive integer t (1 ≤ t ≤ 300) — the number of test cases in the test. Then t test cases follow.
The first line of each test case contains an integer n (1 ≤ n ≤ 300) — the length of the sequence written on the whiteboard.
The next line contains n integers b_1, b_2,…, b_n (1 ≤ b_i ≤ 10^9) — the sequence written on the whiteboard.
Output
Output t answers to the test cases. Each answer — is a sequence a that Polycarp wrote out on the whiteboard.
Example
Input
6
7
3 4 5 2 9 1 1
4
9 2 7 1
11
8 4 3 1 2 7 8 7 9 4 2
1
42
2
11 7
8
1 1 1 1 1 1 1 1
Output
3 1 4 1 5 9 2
9 1 2 7
8 2 4 4 3 9 1 7 2 8 7
42
11 7
1 1 1 1 1 1 1 1
Note
In the first test case, the sequence a matches the sequence from the statement. The whiteboard states after each step look like this:
[3] ⇒ [3, 1] ⇒ [3, 4, 1] ⇒ [3, 4, 1, 1] ⇒ [3, 4, 5, 1, 1] ⇒ [3, 4, 5, 9, 1, 1] ⇒ [3, 4, 5, 2, 9, 1, 1].
Submitted Solution:
```
import math
for i in range(int(input())):
n = int(input())
l = list(map(int,input().split()))
k = [0]*n
for i in range(0,n//2):
k[2*i] = l[i]
#print(k)
k[-1] = l[n//2]
#print(l)
for i in range(0,n//2):
k[2*i + 1] = l[n-1-i]
print(k)
```
No
| 31,965 | [
0.39892578125,
0.056121826171875,
0.231201171875,
0.210693359375,
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0.1614990234375,
0.09375,
0.8212890625,
0.56787109375,
0.0643310546875,
0.06475830078125,
-0.82958984375,
-0.5927734375,
-0.419921875,
-0.546875,
-0.513671875,
-0.77... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a favorite sequence a[1 ... n] consisting of n integers. He wrote it out on the whiteboard as follows:
* he wrote the number a_1 to the left side (at the beginning of the whiteboard);
* he wrote the number a_2 to the right side (at the end of the whiteboard);
* then as far to the left as possible (but to the right from a_1), he wrote the number a_3;
* then as far to the right as possible (but to the left from a_2), he wrote the number a_4;
* Polycarp continued to act as well, until he wrote out the entire sequence on the whiteboard.
<image> The beginning of the result looks like this (of course, if n ≥ 4).
For example, if n=7 and a=[3, 1, 4, 1, 5, 9, 2], then Polycarp will write a sequence on the whiteboard [3, 4, 5, 2, 9, 1, 1].
You saw the sequence written on the whiteboard and now you want to restore Polycarp's favorite sequence.
Input
The first line contains a single positive integer t (1 ≤ t ≤ 300) — the number of test cases in the test. Then t test cases follow.
The first line of each test case contains an integer n (1 ≤ n ≤ 300) — the length of the sequence written on the whiteboard.
The next line contains n integers b_1, b_2,…, b_n (1 ≤ b_i ≤ 10^9) — the sequence written on the whiteboard.
Output
Output t answers to the test cases. Each answer — is a sequence a that Polycarp wrote out on the whiteboard.
Example
Input
6
7
3 4 5 2 9 1 1
4
9 2 7 1
11
8 4 3 1 2 7 8 7 9 4 2
1
42
2
11 7
8
1 1 1 1 1 1 1 1
Output
3 1 4 1 5 9 2
9 1 2 7
8 2 4 4 3 9 1 7 2 8 7
42
11 7
1 1 1 1 1 1 1 1
Note
In the first test case, the sequence a matches the sequence from the statement. The whiteboard states after each step look like this:
[3] ⇒ [3, 1] ⇒ [3, 4, 1] ⇒ [3, 4, 1, 1] ⇒ [3, 4, 5, 1, 1] ⇒ [3, 4, 5, 9, 1, 1] ⇒ [3, 4, 5, 2, 9, 1, 1].
Submitted Solution:
```
ans = []
def solve(arr):
a = ""
index = 0
eq = 0
if len(arr) % 2 == 0:
l = len(arr) // 2
else:
l = len(arr) // 2 + 1
while index != l:
if eq % 2 == 0:
a += str(arr[0 + index]) + " "
else:
a += str(arr[-1 - index]) + " "
index += 1
eq += 1
if len(arr) % 2 != 0 and len(arr) > 4:
return a[0:-2]
return a
if __name__ == '__main__':
k = int(input())
arr = []
for i in range(k):
n = input()
arr.append([int(x) for x in input().split()])
for i in range(len(arr)):
print(solve(arr[i]))
```
No
| 31,966 | [
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0.056121826171875,
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0.1614990234375,
0.09375,
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0.0643310546875,
0.06475830078125,
-0.82958984375,
-0.5927734375,
-0.419921875,
-0.546875,
-0.513671875,
-0.77... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a favorite sequence a[1 ... n] consisting of n integers. He wrote it out on the whiteboard as follows:
* he wrote the number a_1 to the left side (at the beginning of the whiteboard);
* he wrote the number a_2 to the right side (at the end of the whiteboard);
* then as far to the left as possible (but to the right from a_1), he wrote the number a_3;
* then as far to the right as possible (but to the left from a_2), he wrote the number a_4;
* Polycarp continued to act as well, until he wrote out the entire sequence on the whiteboard.
<image> The beginning of the result looks like this (of course, if n ≥ 4).
For example, if n=7 and a=[3, 1, 4, 1, 5, 9, 2], then Polycarp will write a sequence on the whiteboard [3, 4, 5, 2, 9, 1, 1].
You saw the sequence written on the whiteboard and now you want to restore Polycarp's favorite sequence.
Input
The first line contains a single positive integer t (1 ≤ t ≤ 300) — the number of test cases in the test. Then t test cases follow.
The first line of each test case contains an integer n (1 ≤ n ≤ 300) — the length of the sequence written on the whiteboard.
The next line contains n integers b_1, b_2,…, b_n (1 ≤ b_i ≤ 10^9) — the sequence written on the whiteboard.
Output
Output t answers to the test cases. Each answer — is a sequence a that Polycarp wrote out on the whiteboard.
Example
Input
6
7
3 4 5 2 9 1 1
4
9 2 7 1
11
8 4 3 1 2 7 8 7 9 4 2
1
42
2
11 7
8
1 1 1 1 1 1 1 1
Output
3 1 4 1 5 9 2
9 1 2 7
8 2 4 4 3 9 1 7 2 8 7
42
11 7
1 1 1 1 1 1 1 1
Note
In the first test case, the sequence a matches the sequence from the statement. The whiteboard states after each step look like this:
[3] ⇒ [3, 1] ⇒ [3, 4, 1] ⇒ [3, 4, 1, 1] ⇒ [3, 4, 5, 1, 1] ⇒ [3, 4, 5, 9, 1, 1] ⇒ [3, 4, 5, 2, 9, 1, 1].
Submitted Solution:
```
for _ in range(int(input())):
n=int(input())
l=list(map(int,input().split()))
i=1
ui=0
uj=n-1
l1=[]
while(ui<=uj):
if(i):
i=0
l1.append(l[ui])
ui+=1
else:
i=1
l1.append(l[uj])
uj-=1
for i in range(n):
print(l[i],end=" ")
```
No
| 31,967 | [
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0.1614990234375,
0.09375,
0.8212890625,
0.56787109375,
0.0643310546875,
0.06475830078125,
-0.82958984375,
-0.5927734375,
-0.419921875,
-0.546875,
-0.513671875,
-0.77... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
for _ in[0]*int(input()):
s=input();i=0;r=[]
while i<len(s):
if'twone'==s[i:i+5]:r+=i+3,;i+=4
if s[i:i+3]in('one','two'):r+=i+2,
i+=1
print(len(r),*r)
```
| 32,651 | [
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-1.0634765625,
-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
if __name__ == "__main__":
for _ in range(int(input())):
s = input()
twone = []
one = []
two = []
n = len(s)
for i in range(n - 5 + 1):
if s[i : i + 5] == "twone":
twone.append(i)
for i in range(n - 3 + 1):
if s[i : i + 3] == "one":
one.append(i)
for i in range(n - 3 + 1):
if s[i : i + 3] == "two":
two.append(i)
print(len(one) + len(two) - len(twone))
twoneset = set(twone)
for num in one:
if num - 2 not in twoneset:
print(num + 2, end = ' ')
for num in two:
if num not in twoneset:
print(num + 2, end = ' ')
for num in twone:
print(num + 3, end = ' ')
# print(one)
print()
```
| 32,652 | [
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-1.0634765625,
-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
for _ in range(int(input())):
s = input()
c = []
s = s.replace("twone", "tw+ne")
s = s.replace("two", "t+o")
s = s.replace("one", "o+e")
for i in range(len(s)):
if s[i] == '+':
c.append(i+1)
print(len(c))
print(*c)
```
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-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
def find(s, string):
inds = []
for i in range(len(s)):
if i + len(string) > len(s): break
if s[i:i+len(string)] == string: inds.append(i)
return set(inds)
t = int(input())
for i in range(t):
s = input()
ones = find(s, "one")
twos = find(s, "two")
both = find(s, "twone")
inds = []
for item in ones:
if item-2 not in both:
inds.append(item+1)
for item in twos:
if item not in both:
inds.append(item+1)
for item in both:
inds.append(item+2)
print(len(inds))
print(" ".join(str(x+1) for x in inds))
```
| 32,654 | [
0.16650390625,
0.399169921875,
0.400634765625,
0.15625,
-0.73388671875,
-0.303955078125,
-0.266845703125,
0.049041748046875,
0.1688232421875,
0.6904296875,
1.0546875,
0.032623291015625,
-0.017913818359375,
-1.0634765625,
-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
from sys import stdin
from collections import deque
mod = 10**9 + 7
# def rl():
# return [int(w) for w in stdin.readline().split()]
from bisect import bisect_right
from bisect import bisect_left
from collections import defaultdict
from math import sqrt,factorial,gcd,log2,inf,ceil
ok=55
for i in range(100002):
ok=ok+1
t = int(input())
for _ in range(t):
s = input()
ans = set()
for i in range(len(s)-2):
if i+1 not in ans:
if s[i] == 't' and s[i+1] == 'w' and s[i+2] == 'o':
try:
if s[i+3] == 'o':
ans.add(i+2)
else:
try:
if s[i+3] == 'n' and s[i+4] == 'e':
ans.add(i+3)
else:
ans.add(i+2)
except:
ans.add(i+2)
except:
ans.add(i+2)
if s[i] == 'o' and s[i+1] == 'n' and s[i+2] == 'e' and i+2 not in ans and i+3 not in ans:
ans.add(i+2)
print(len(ans))
print(*ans)
```
| 32,655 | [
0.16650390625,
0.399169921875,
0.400634765625,
0.15625,
-0.73388671875,
-0.303955078125,
-0.266845703125,
0.049041748046875,
0.1688232421875,
0.6904296875,
1.0546875,
0.032623291015625,
-0.017913818359375,
-1.0634765625,
-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
t=int(input())
for _ in range(t):
s=input()+" "
i=0
ans=[]
while i<len(s)-3:
if s[i]=='o':
if s[i+1]=='n':
if s[i+2]=='e':
ans.append(i+1)
i+=2
else:
i+=1
elif s[i]=='t':
if s[i+1]=='w':
if s[i+2]=='o':
if s[i+3]=='n':
ans.append(i+2)
i+=3
else:
ans.append(i+1)
i+=2
else:
i+=1
i+=1
if len(ans)==0:
print(0)
print()
else:
print(len(ans))
for i in ans:
print(i+1,end=" ")
print()
```
| 32,656 | [
0.16650390625,
0.399169921875,
0.400634765625,
0.15625,
-0.73388671875,
-0.303955078125,
-0.266845703125,
0.049041748046875,
0.1688232421875,
0.6904296875,
1.0546875,
0.032623291015625,
-0.017913818359375,
-1.0634765625,
-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
t = int(input())
for _ in range(t):
s = input()
i = 0
R = []
while i < len(s):
# print(s[i:i+5])
if i+4<len(s) and s[i:i+5] == "twone":
# print('paso')
R.append(i+2+1)
i+=5
elif i+2<len(s) and (s[i:i+3] == "one" or s[i:i+3] == "two"):
R.append(i+1+1)
i+=3
else: i+=1
print(len(R))
for i in R:
print(i, end=' ')
print()
```
| 32,657 | [
0.16650390625,
0.399169921875,
0.400634765625,
0.15625,
-0.73388671875,
-0.303955078125,
-0.266845703125,
0.049041748046875,
0.1688232421875,
0.6904296875,
1.0546875,
0.032623291015625,
-0.017913818359375,
-1.0634765625,
-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Tags: dp, greedy
Correct Solution:
```
from sys import stdin,stdout
from collections import Counter
for _ in range(int(stdin.readline())):
# n=int(stdin.readline())
# a=list(map(int,stdin.readline().split()))
s=list(input())
n=len(s)
ans=[]
for i in range(n-4):
sub=s[i:i+5]
if sub==list('twone'):
ans+=[i+3]
s[i+2]=' '
for i in range(n-2):
sub=s[i:i+3]
if sub in [list('one'),list('two')]:
ans+=[i+2]
s[i+1]=' '
print(len(ans))
print(*ans)
```
| 32,658 | [
0.16650390625,
0.399169921875,
0.400634765625,
0.15625,
-0.73388671875,
-0.303955078125,
-0.266845703125,
0.049041748046875,
0.1688232421875,
0.6904296875,
1.0546875,
0.032623291015625,
-0.017913818359375,
-1.0634765625,
-0.72509765625,
-0.003589630126953125,
-0.35205078125,
-0.334... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
#Bhargey Mehta (Junior)
#DA-IICT, Gandhinagar
import sys, math
MOD = 10**9+7
#sys.stdin = open('input.txt', 'r')
for _ in range(int(input())):
s = input()+'x'
r = []
for i in range(len(s)):
if s[i:i+3] == 'two':
if s[i:i+5] != 'twone':
r.append(i+2)
else:
r.append(i+3)
elif s[i:i+3] == 'one':
if s[i-2:i+3] != 'twone':
r.append(i+2)
print(len(r))
print(*r)
```
Yes
| 32,659 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
t = int(input())
for _ in range(t):
s = input()
ans=[]
i=2
while (i<len(s)):
if (s[i-2:i+1]=='one'):
ans.append(i)
i+=3
elif (s[i-2:i+1]=='two'):
if (i+1<len(s)) and (s[i+1]=='n'):
ans.append(i+1)
else:
ans.append(i)
i += 3
else:
i+=1
print (len(ans))
print (*ans)
```
Yes
| 32,660 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
# cook your dish here
for _ in [0]*int(input()):
s = input()
i = 0
r = []
while i < len(s):
if 'twone' == s[i:i+5]:
i += 3
r += i,
if s[i:i+3] in ('one', 'two'):
r += i+2,
i += 1
print(len(r))
print(*r)
```
Yes
| 32,661 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
def one_two(s):
ch1="one"
ch2="two"
ch3="twone"
final=""
i=0
count=0
l=[]
while(i<len(s)):
if(s[i:i+5]==ch3):
l.append(i+3)
i=i+5
elif(s[i:i+3:]==ch1 or s[i:i+3:] ==ch2):
l.append(i+2)
i=i+3
else:
i=i+1
print(len(l))
print(*l)
n=int(input())
for i in range(0,n):
s=input()
one_two(s)
```
Yes
| 32,662 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
#########################################################################################################\
#########################################################################################################
###################################The_Apurv_Rathore#####################################################
#########################################################################################################
#########################################################################################################
import sys,os,io
from sys import stdin
from types import GeneratorType
from math import log, gcd, ceil
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop, heapify
from bisect import bisect_left , bisect_right
import math
alphabets = list('abcdefghijklmnopqrstuvwxyz')
#for deep recursion__________________________________________-
def bootstrap(f, stack=[]):
def wrappedfunc(*args, **kwargs):
if stack:
return f(*args, **kwargs)
else:
to = f(*args, **kwargs)
while True:
if type(to) is GeneratorType:
stack.append(to)
to = next(to)
else:
stack.pop()
if not stack:
break
to = stack[-1].send(to)
return to
return wrappedfunc
def ncr(n, r, p):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den,p - 2, p)) % p
def primeFactors(n):
l = []
while n % 2 == 0:
l.append(2)
n = n / 2
for i in range(3,int(math.sqrt(n))+1,2):
while n % i== 0:
l.append(int(i))
n = n / i
if n > 2:
l.append(n)
c = dict(Counter(l))
return list(set(l))
# return c
def power(x, y, p) :
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
#____________________GetPrimeFactors in log(n)________________________________________
def sieveForSmallestPrimeFactor():
MAXN = 100001
spf = [0 for i in range(MAXN)]
spf[1] = 1
for i in range(2, MAXN):
spf[i] = i
for i in range(4, MAXN, 2):
spf[i] = 2
for i in range(3, math.ceil(math.sqrt(MAXN))):
if (spf[i] == i):
for j in range(i * i, MAXN, i):
if (spf[j] == j):
spf[j] = i
return spf
def getPrimeFactorizationLOGN(x):
spf = sieveForSmallestPrimeFactor()
ret = list()
while (x != 1):
ret.append(spf[x])
x = x // spf[x]
return ret
#____________________________________________________________
def SieveOfEratosthenes(n):
#time complexity = nlog(log(n))
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
def si():
return input()
def divideCeil(n,x):
if (n%x==0):
return n//x
return n//x+1
def ii():
return int(input())
def li():
return list(map(int,input().split()))
#__________________________TEMPLATE__________________OVER_______________________________________________________
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
# else:
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def findall(p, s):
'''Yields all the positions of
the pattern p in the string s.'''
i = s.find(p)
while i != -1:
yield i
i = s.find(p, i+1)
def solve():
x = si()
poss = ['two','one','twoone']
ind = [i for i in findall(poss[2], x)]
ans = []
x = list(x)
for i in ind:
x[i+2]='1'
ans.append(i+1+2)
x = ''.join(x)
ind = [i for i in findall(poss[1], x)]
x = list(x)
for i in ind:
x[i]='1'
ans.append(i+1)
x = ''.join(x)
ind = [i for i in findall(poss[0], x)]
x = list(x)
for i in ind:
x[i]='1'
ans.append(i+1)
# print(x)
print(len(ans))
# print(''.join(x))
print(*ans)
t = 1
t = ii()
for _ in range(t):
solve()
```
No
| 32,663 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
if __name__ == "__main__":
for _ in range(int(input())):
s = input()
twone = []
one = []
two = []
n = len(s)
for i in range(n - 4):
if s[i : i + 5] == "twone":
twone.append(i)
for i in range(n - 2):
if s[i : i + 3] == "one":
one.append(i)
for i in range(n - 2):
if s[i : i + 3] == "two":
two.append(i)
print(len(one) + len(two) - len(twone))
twoneset = set(twone)
for num in one:
if num - 2 not in twoneset:
print(num + 1, end = ' ')
for num in two:
if num not in twoneset:
print(num + 1, end = ' ')
for num in twoneset:
print(num + 3, end = ' ')
# print(one)
print()
```
No
| 32,664 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
def one_two(s):
ch1="one"
ch2="two"
ch3="twone"
final=""
i=0
count=0
while(i<len(s)):
if(s[i]=='o'):
p=s[i:i+3:]
if(p==ch1):
final=final+str(i+2)+" "
i=i+3
count=count+1
else:
i=i+1
elif(s[i]=='t'):
p=s[i:i+3:]
p1=s[i:i+5:]
if(p==ch3):
final=final+str(i+3)+" "
i=i+5
count=count+1
elif(p1==ch2):
final=final+str(i+2)+" "
i=i+3
count=count+1
else:
i=i+1
else:
i=i+1
print(count)
print(final)
n=int(input())
for i in range(0,n):
s=input()
one_two(s)
```
No
| 32,665 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-empty string s=s_1s_2... s_n, which consists only of lowercase Latin letters. Polycarp does not like a string if it contains at least one string "one" or at least one string "two" (or both at the same time) as a substring. In other words, Polycarp does not like the string s if there is an integer j (1 ≤ j ≤ n-2), that s_{j}s_{j+1}s_{j+2}="one" or s_{j}s_{j+1}s_{j+2}="two".
For example:
* Polycarp does not like strings "oneee", "ontwow", "twone" and "oneonetwo" (they all have at least one substring "one" or "two"),
* Polycarp likes strings "oonnee", "twwwo" and "twnoe" (they have no substrings "one" and "two").
Polycarp wants to select a certain set of indices (positions) and remove all letters on these positions. All removals are made at the same time.
For example, if the string looks like s="onetwone", then if Polycarp selects two indices 3 and 6, then "onetwone" will be selected and the result is "ontwne".
What is the minimum number of indices (positions) that Polycarp needs to select to make the string liked? What should these positions be?
Input
The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Next, the test cases are given.
Each test case consists of one non-empty string s. Its length does not exceed 1.5⋅10^5. The string s consists only of lowercase Latin letters.
It is guaranteed that the sum of lengths of all lines for all input data in the test does not exceed 1.5⋅10^6.
Output
Print an answer for each test case in the input in order of their appearance.
The first line of each answer should contain r (0 ≤ r ≤ |s|) — the required minimum number of positions to be removed, where |s| is the length of the given line. The second line of each answer should contain r different integers — the indices themselves for removal in any order. Indices are numbered from left to right from 1 to the length of the string. If r=0, then the second line can be skipped (or you can print empty). If there are several answers, print any of them.
Examples
Input
4
onetwone
testme
oneoneone
twotwo
Output
2
6 3
0
3
4 1 7
2
1 4
Input
10
onetwonetwooneooonetwooo
two
one
twooooo
ttttwo
ttwwoo
ooone
onnne
oneeeee
oneeeeeeetwooooo
Output
6
18 11 12 1 6 21
1
1
1
3
1
2
1
6
0
1
4
0
1
1
2
1 11
Note
In the first example, answers are:
* "onetwone",
* "testme" — Polycarp likes it, there is nothing to remove,
* "oneoneone",
* "twotwo".
In the second example, answers are:
* "onetwonetwooneooonetwooo",
* "two",
* "one",
* "twooooo",
* "ttttwo",
* "ttwwoo" — Polycarp likes it, there is nothing to remove,
* "ooone",
* "onnne" — Polycarp likes it, there is nothing to remove,
* "oneeeee",
* "oneeeeeeetwooooo".
Submitted Solution:
```
t = int(input().strip())
# nums = list(map(int, input().strip().split()))
for _ in range(t):
s = input().strip()
l = len(s)
count = 0
ps = []
for i, c in enumerate(s):
if i == 0 or i == l-1:
continue
elif c == 'n' and s[i-1:i+2] == 'one':
if s[i-3:i+2] != 'twone':
ps.append(str(i))
count += 1
elif c == 'w' and s[i-1:i+2] == 'two':
if s[i-3:i+2] != 'twone':
ps.append(str(i))
count += 1
else:
ps.append(str(i+1))
count += 1
print(count)
print(' '.join(ps))
```
No
| 32,666 | [
0.25439453125,
0.388427734375,
0.364990234375,
0.0772705078125,
-0.74267578125,
-0.213623046875,
-0.36474609375,
0.050201416015625,
0.1407470703125,
0.61767578125,
0.92919921875,
0.01436614990234375,
-0.0092010498046875,
-1.01953125,
-0.728515625,
-0.07257080078125,
-0.3046875,
-0.... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarpus is an amateur programmer. Now he is analyzing a friend's program. He has already found there the function rangeIncrement(l, r), that adds 1 to each element of some array a for all indexes in the segment [l, r]. In other words, this function does the following:
function rangeIncrement(l, r)
for i := l .. r do
a[i] = a[i] + 1
Polycarpus knows the state of the array a after a series of function calls. He wants to determine the minimum number of function calls that lead to such state. In addition, he wants to find what function calls are needed in this case. It is guaranteed that the required number of calls does not exceed 105.
Before calls of function rangeIncrement(l, r) all array elements equal zero.
Input
The first input line contains a single integer n (1 ≤ n ≤ 105) — the length of the array a[1... n].
The second line contains its integer space-separated elements, a[1], a[2], ..., a[n] (0 ≤ a[i] ≤ 105) after some series of function calls rangeIncrement(l, r).
It is guaranteed that at least one element of the array is positive. It is guaranteed that the answer contains no more than 105 calls of function rangeIncrement(l, r).
Output
Print on the first line t — the minimum number of calls of function rangeIncrement(l, r), that lead to the array from the input data. It is guaranteed that this number will turn out not more than 105.
Then print t lines — the descriptions of function calls, one per line. Each line should contain two integers li, ri (1 ≤ li ≤ ri ≤ n) — the arguments of the i-th call rangeIncrement(l, r). Calls can be applied in any order.
If there are multiple solutions, you are allowed to print any of them.
Examples
Input
6
1 2 1 1 4 1
Output
5
2 2
5 5
5 5
5 5
1 6
Input
5
1 0 1 0 1
Output
3
1 1
3 3
5 5
Note
The first sample requires a call for the entire array, and four additional calls:
* one for the segment [2,2] (i.e. the second element of the array),
* three for the segment [5,5] (i.e. the fifth element of the array).
Tags: data structures, greedy
Correct Solution:
```
n = int(input())
big = 10 ** 5
last = (big + 1) * [ -1 ]
data = list(map(int, input().split()))
data.insert(0, 0)
data.append(0)
result = []
previous = 0
for pos, current in enumerate(data):
if current > previous:
for x in range(previous + 1, current + 1):
last[x] = pos
elif current < previous:
for x in range(previous, current, -1):
result.append('%d %d' % (last[x], pos - 1))
previous = current
print(len(result))
print('\n'.join(result))
```
| 32,787 | [
0.1885986328125,
0.1209716796875,
-0.0203094482421875,
0.18408203125,
-0.09552001953125,
-0.453369140625,
-0.03985595703125,
0.125244140625,
0.194091796875,
1.0673828125,
0.92529296875,
0.111328125,
0.025177001953125,
-0.93603515625,
-0.59423828125,
0.08465576171875,
-0.63818359375,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarpus is an amateur programmer. Now he is analyzing a friend's program. He has already found there the function rangeIncrement(l, r), that adds 1 to each element of some array a for all indexes in the segment [l, r]. In other words, this function does the following:
function rangeIncrement(l, r)
for i := l .. r do
a[i] = a[i] + 1
Polycarpus knows the state of the array a after a series of function calls. He wants to determine the minimum number of function calls that lead to such state. In addition, he wants to find what function calls are needed in this case. It is guaranteed that the required number of calls does not exceed 105.
Before calls of function rangeIncrement(l, r) all array elements equal zero.
Input
The first input line contains a single integer n (1 ≤ n ≤ 105) — the length of the array a[1... n].
The second line contains its integer space-separated elements, a[1], a[2], ..., a[n] (0 ≤ a[i] ≤ 105) after some series of function calls rangeIncrement(l, r).
It is guaranteed that at least one element of the array is positive. It is guaranteed that the answer contains no more than 105 calls of function rangeIncrement(l, r).
Output
Print on the first line t — the minimum number of calls of function rangeIncrement(l, r), that lead to the array from the input data. It is guaranteed that this number will turn out not more than 105.
Then print t lines — the descriptions of function calls, one per line. Each line should contain two integers li, ri (1 ≤ li ≤ ri ≤ n) — the arguments of the i-th call rangeIncrement(l, r). Calls can be applied in any order.
If there are multiple solutions, you are allowed to print any of them.
Examples
Input
6
1 2 1 1 4 1
Output
5
2 2
5 5
5 5
5 5
1 6
Input
5
1 0 1 0 1
Output
3
1 1
3 3
5 5
Note
The first sample requires a call for the entire array, and four additional calls:
* one for the segment [2,2] (i.e. the second element of the array),
* three for the segment [5,5] (i.e. the fifth element of the array).
Tags: data structures, greedy
Correct Solution:
```
import re
import sys
exit=sys.exit
from bisect import bisect_left as bsl,bisect_right as bsr
from collections import Counter,defaultdict as ddict,deque
from functools import lru_cache
cache=lru_cache(None)
from heapq import *
from itertools import *
from math import inf
from pprint import pprint as pp
enum=enumerate
ri=lambda:int(rln())
ris=lambda:list(map(int,rfs()))
rln=sys.stdin.readline
rl=lambda:rln().rstrip('\n')
rfs=lambda:rln().split()
mod=1000000007
d4=[(0,-1),(1,0),(0,1),(-1,0)]
d8=[(-1,-1),(0,-1),(1,-1),(-1,0),(1,0),(-1,1),(0,1),(1,1)]
########################################################################
n=ri()
a=ris()
a.append(0)
l,r=[],[]
s=0
for i,x in enum(a):
while s<x:
l.append(i+1)
s+=1
while s>x:
r.append(i)
s-=1
print(len(l))
while l:
print(l.pop(),r.pop())
```
| 32,788 | [
0.1885986328125,
0.1209716796875,
-0.0203094482421875,
0.18408203125,
-0.09552001953125,
-0.453369140625,
-0.03985595703125,
0.125244140625,
0.194091796875,
1.0673828125,
0.92529296875,
0.111328125,
0.025177001953125,
-0.93603515625,
-0.59423828125,
0.08465576171875,
-0.63818359375,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarpus is an amateur programmer. Now he is analyzing a friend's program. He has already found there the function rangeIncrement(l, r), that adds 1 to each element of some array a for all indexes in the segment [l, r]. In other words, this function does the following:
function rangeIncrement(l, r)
for i := l .. r do
a[i] = a[i] + 1
Polycarpus knows the state of the array a after a series of function calls. He wants to determine the minimum number of function calls that lead to such state. In addition, he wants to find what function calls are needed in this case. It is guaranteed that the required number of calls does not exceed 105.
Before calls of function rangeIncrement(l, r) all array elements equal zero.
Input
The first input line contains a single integer n (1 ≤ n ≤ 105) — the length of the array a[1... n].
The second line contains its integer space-separated elements, a[1], a[2], ..., a[n] (0 ≤ a[i] ≤ 105) after some series of function calls rangeIncrement(l, r).
It is guaranteed that at least one element of the array is positive. It is guaranteed that the answer contains no more than 105 calls of function rangeIncrement(l, r).
Output
Print on the first line t — the minimum number of calls of function rangeIncrement(l, r), that lead to the array from the input data. It is guaranteed that this number will turn out not more than 105.
Then print t lines — the descriptions of function calls, one per line. Each line should contain two integers li, ri (1 ≤ li ≤ ri ≤ n) — the arguments of the i-th call rangeIncrement(l, r). Calls can be applied in any order.
If there are multiple solutions, you are allowed to print any of them.
Examples
Input
6
1 2 1 1 4 1
Output
5
2 2
5 5
5 5
5 5
1 6
Input
5
1 0 1 0 1
Output
3
1 1
3 3
5 5
Note
The first sample requires a call for the entire array, and four additional calls:
* one for the segment [2,2] (i.e. the second element of the array),
* three for the segment [5,5] (i.e. the fifth element of the array).
Tags: data structures, greedy
Correct Solution:
```
N = 100000
v = []
for i in range(0, N) :
v.append([])
line = input()
n = int(line)
line = input()
lineSplit = line.split()
a = 0
for i in range(0, len(lineSplit)) :
b = int(lineSplit[i])
if b > a :
for j in range(a, b) :
v[j].append([i, -1])
elif b < a :
for j in range(a-1, b-1, -1) :
v[j][-1][1] = i
a = b
if a > 0 :
for j in range(0, a) :
v[j][-1][1] = n
c = 0
for i in range(0, N) :
c += len(v[i])
print(c)
#for i in v :
# print(i)
for i in range(0, N) :
for j in range(0, len(v[i])) :
print(v[i][j][0] + 1, v[i][j][1])
```
| 32,789 | [
0.1885986328125,
0.1209716796875,
-0.0203094482421875,
0.18408203125,
-0.09552001953125,
-0.453369140625,
-0.03985595703125,
0.125244140625,
0.194091796875,
1.0673828125,
0.92529296875,
0.111328125,
0.025177001953125,
-0.93603515625,
-0.59423828125,
0.08465576171875,
-0.63818359375,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarpus is an amateur programmer. Now he is analyzing a friend's program. He has already found there the function rangeIncrement(l, r), that adds 1 to each element of some array a for all indexes in the segment [l, r]. In other words, this function does the following:
function rangeIncrement(l, r)
for i := l .. r do
a[i] = a[i] + 1
Polycarpus knows the state of the array a after a series of function calls. He wants to determine the minimum number of function calls that lead to such state. In addition, he wants to find what function calls are needed in this case. It is guaranteed that the required number of calls does not exceed 105.
Before calls of function rangeIncrement(l, r) all array elements equal zero.
Input
The first input line contains a single integer n (1 ≤ n ≤ 105) — the length of the array a[1... n].
The second line contains its integer space-separated elements, a[1], a[2], ..., a[n] (0 ≤ a[i] ≤ 105) after some series of function calls rangeIncrement(l, r).
It is guaranteed that at least one element of the array is positive. It is guaranteed that the answer contains no more than 105 calls of function rangeIncrement(l, r).
Output
Print on the first line t — the minimum number of calls of function rangeIncrement(l, r), that lead to the array from the input data. It is guaranteed that this number will turn out not more than 105.
Then print t lines — the descriptions of function calls, one per line. Each line should contain two integers li, ri (1 ≤ li ≤ ri ≤ n) — the arguments of the i-th call rangeIncrement(l, r). Calls can be applied in any order.
If there are multiple solutions, you are allowed to print any of them.
Examples
Input
6
1 2 1 1 4 1
Output
5
2 2
5 5
5 5
5 5
1 6
Input
5
1 0 1 0 1
Output
3
1 1
3 3
5 5
Note
The first sample requires a call for the entire array, and four additional calls:
* one for the segment [2,2] (i.e. the second element of the array),
* three for the segment [5,5] (i.e. the fifth element of the array).
Tags: data structures, greedy
Correct Solution:
```
import re
import sys
exit=sys.exit
from bisect import bisect_left as bsl,bisect_right as bsr
from collections import Counter,defaultdict as ddict,deque
from functools import lru_cache
cache=lru_cache(None)
from heapq import *
from itertools import *
from math import inf
from pprint import pprint as pp
enum=enumerate
ri=lambda:int(rln())
ris=lambda:list(map(int,rfs()))
rln=sys.stdin.readline
rl=lambda:rln().rstrip('\n')
rfs=lambda:rln().split()
mod=1000000007
d4=[(0,-1),(1,0),(0,1),(-1,0)]
d8=[(-1,-1),(0,-1),(1,-1),(-1,0),(1,0),(-1,1),(0,1),(1,1)]
########################################################################
n=ri()
a=ris()
a.append(0)
ans=[]
stk=[n]
for i,x in enum(a):
while a[stk[-1]]>x:
j=stk.pop()
k=a[j]-max(a[stk[-1]],x)
for _ in range(k):
ans.append((j+1,i))
if a[stk[-1]]<x:
a[j]=x
stk.append(j)
if a[stk[-1]]!=x:
stk.append(i)
print(len(ans))
for i,j in ans:
print(i,j)
```
| 32,790 | [
0.1885986328125,
0.1209716796875,
-0.0203094482421875,
0.18408203125,
-0.09552001953125,
-0.453369140625,
-0.03985595703125,
0.125244140625,
0.194091796875,
1.0673828125,
0.92529296875,
0.111328125,
0.025177001953125,
-0.93603515625,
-0.59423828125,
0.08465576171875,
-0.63818359375,
... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarpus is an amateur programmer. Now he is analyzing a friend's program. He has already found there the function rangeIncrement(l, r), that adds 1 to each element of some array a for all indexes in the segment [l, r]. In other words, this function does the following:
function rangeIncrement(l, r)
for i := l .. r do
a[i] = a[i] + 1
Polycarpus knows the state of the array a after a series of function calls. He wants to determine the minimum number of function calls that lead to such state. In addition, he wants to find what function calls are needed in this case. It is guaranteed that the required number of calls does not exceed 105.
Before calls of function rangeIncrement(l, r) all array elements equal zero.
Input
The first input line contains a single integer n (1 ≤ n ≤ 105) — the length of the array a[1... n].
The second line contains its integer space-separated elements, a[1], a[2], ..., a[n] (0 ≤ a[i] ≤ 105) after some series of function calls rangeIncrement(l, r).
It is guaranteed that at least one element of the array is positive. It is guaranteed that the answer contains no more than 105 calls of function rangeIncrement(l, r).
Output
Print on the first line t — the minimum number of calls of function rangeIncrement(l, r), that lead to the array from the input data. It is guaranteed that this number will turn out not more than 105.
Then print t lines — the descriptions of function calls, one per line. Each line should contain two integers li, ri (1 ≤ li ≤ ri ≤ n) — the arguments of the i-th call rangeIncrement(l, r). Calls can be applied in any order.
If there are multiple solutions, you are allowed to print any of them.
Examples
Input
6
1 2 1 1 4 1
Output
5
2 2
5 5
5 5
5 5
1 6
Input
5
1 0 1 0 1
Output
3
1 1
3 3
5 5
Note
The first sample requires a call for the entire array, and four additional calls:
* one for the segment [2,2] (i.e. the second element of the array),
* three for the segment [5,5] (i.e. the fifth element of the array).
Submitted Solution:
```
from bisect import bisect_right
from bisect import bisect_left
n=int(input())
b=list(map(int,input().split()))
res=[]
ind=[[] for i in range(10**5+1)]
j=0
while(j<n):
ind[b[j]].append(j)
j+=1
p=[-1]
p+=ind[0]
ans=[]
p.append(n)
j=0
while(j<len(p)-1):
if p[j]==p[j+1]:
pass
else:
if (p[j]+1)<=(p[j+1]-1):
res.append([p[j]+1,p[j+1]-1])
ans.append([p[j]+1,p[j+1]-1])
j+=1
j=1
while(j<=n):
test_list=ind[j]
i=0
newres=[]
while(i<len(res)):
l,r=res[i][0],res[i][1]
lo = bisect_right(test_list, l-1)
hi = bisect_left(test_list, r+1) - 1
if hi>=lo:
p = [l-1]
p += test_list[lo:hi+1]
p.append(r+1)
q = 0
while (q < len(p)-1):
if p[q] == p[q + 1]:
pass
else:
if (p[q] + 1) <= (p[q + 1] - 1):
newres.append([p[q] + 1, p[q + 1] - 1])
q += 1
else:
if b[l]!=j:
newres.append([l,r])
i+=1
res=[]
for m in newres:
res.append(m)
ans.append(m)
j+=1
print(len(ans))
for j in ans:
print(j[0]+1, j[1]+1)
```
No
| 32,791 | [
0.2841796875,
0.09814453125,
-0.019012451171875,
0.196044921875,
-0.1903076171875,
-0.332763671875,
-0.10333251953125,
0.204345703125,
0.17333984375,
1.0302734375,
0.8447265625,
0.08953857421875,
0.013092041015625,
-0.931640625,
-0.5341796875,
0.048797607421875,
-0.564453125,
-0.38... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarpus is an amateur programmer. Now he is analyzing a friend's program. He has already found there the function rangeIncrement(l, r), that adds 1 to each element of some array a for all indexes in the segment [l, r]. In other words, this function does the following:
function rangeIncrement(l, r)
for i := l .. r do
a[i] = a[i] + 1
Polycarpus knows the state of the array a after a series of function calls. He wants to determine the minimum number of function calls that lead to such state. In addition, he wants to find what function calls are needed in this case. It is guaranteed that the required number of calls does not exceed 105.
Before calls of function rangeIncrement(l, r) all array elements equal zero.
Input
The first input line contains a single integer n (1 ≤ n ≤ 105) — the length of the array a[1... n].
The second line contains its integer space-separated elements, a[1], a[2], ..., a[n] (0 ≤ a[i] ≤ 105) after some series of function calls rangeIncrement(l, r).
It is guaranteed that at least one element of the array is positive. It is guaranteed that the answer contains no more than 105 calls of function rangeIncrement(l, r).
Output
Print on the first line t — the minimum number of calls of function rangeIncrement(l, r), that lead to the array from the input data. It is guaranteed that this number will turn out not more than 105.
Then print t lines — the descriptions of function calls, one per line. Each line should contain two integers li, ri (1 ≤ li ≤ ri ≤ n) — the arguments of the i-th call rangeIncrement(l, r). Calls can be applied in any order.
If there are multiple solutions, you are allowed to print any of them.
Examples
Input
6
1 2 1 1 4 1
Output
5
2 2
5 5
5 5
5 5
1 6
Input
5
1 0 1 0 1
Output
3
1 1
3 3
5 5
Note
The first sample requires a call for the entire array, and four additional calls:
* one for the segment [2,2] (i.e. the second element of the array),
* three for the segment [5,5] (i.e. the fifth element of the array).
Submitted Solution:
```
import re
import sys
exit=sys.exit
from bisect import bisect_left as bsl,bisect_right as bsr
from collections import Counter,defaultdict as ddict,deque
from functools import lru_cache
cache=lru_cache(None)
from heapq import *
from itertools import *
from math import inf
from pprint import pprint as pp
enum=enumerate
ri=lambda:int(rln())
ris=lambda:list(map(int,rfs()))
rln=sys.stdin.readline
rl=lambda:rln().rstrip('\n')
rfs=lambda:rln().split()
mod=1000000007
d4=[(0,-1),(1,0),(0,1),(-1,0)]
d8=[(-1,-1),(0,-1),(1,-1),(-1,0),(1,0),(-1,1),(0,1),(1,1)]
########################################################################
n=ri()
a=ris()
a.append(0)
ans=[]
stk=[(n,0)]
for i,x in enum(a):
while a[stk[-1][0]]>x:
j,k=stk.pop()
for _ in range(k):
ans.append((j+1,i))
if a[stk[-1][0]]<x:
stk.append((i,x-a[stk[-1][0]]))
elif a[stk[-1][0]]!=x:
stk.append((i,0))
print(len(ans))
for i,j in ans:
print(i,j)
```
No
| 32,792 | [
0.2841796875,
0.09814453125,
-0.019012451171875,
0.196044921875,
-0.1903076171875,
-0.332763671875,
-0.10333251953125,
0.204345703125,
0.17333984375,
1.0302734375,
0.8447265625,
0.08953857421875,
0.013092041015625,
-0.931640625,
-0.5341796875,
0.048797607421875,
-0.564453125,
-0.38... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
tests = int(input())
for _ in range(tests):
a, b, c, d, k = map(int, input().split(' '))
import math
a = math.ceil(a / c)
b = math.ceil(b / d)
if(a + b) > k:
print(-1)
else:
print(a, b)
```
| 33,436 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
from math import ceil
t = int(input())
for i in range(t):
nLectures, nPractical, nLecturesCap, nPracticalCap, pencilcaseSize = map(int, input().split())
necessaryPens = ceil(nLectures / nLecturesCap)
necessaryPencils = ceil(nPractical / nPracticalCap)
if (necessaryPens + necessaryPencils > pencilcaseSize):
print(-1)
else:
print(necessaryPens, necessaryPencils)
```
| 33,437 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
t=int(input())
for i in range(t):
a,b,c,d,k=map(int,input().split())
if(a%c==0):
x=int(a/c)
else:
x=int((a/c)+1)
if(b%d==0):
y=int(b/d)
else:
y=int((b/d)+1)
if(k>=(x+y)):
print(x,y)
else:
print(-1)
```
| 33,438 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
def main(a, b, c, d, k):
if a < c:
# print('hi')
ac = 1
else:
ac = int(a / c)
if (a % c) != 0:
ac = ac + 1
if b < d:
bd = 1
else:
bd = int(b / d)
if (b % d) != 0:
bd = bd + 1
# print(ac, bd, k)
if (bd + ac) > k:
return -1
else:
return [ac, bd]
if __name__ == '__main__':
t = int(input())
for t_itr in range(t):
z = list(map(int, input().rstrip().split()))
a = z[0]
b = z[1]
c = z[2]
d = z[3]
k = z[4]
res = main(a, b, c, d, k)
if isinstance(res, list):
print(*res)
else:
print(res)
```
| 33,439 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
from math import ceil
t = int(input())
for i in range(t):
a, b, a1, b1, k = [int(i) for i in input().split()]
pen = ceil(a / a1)
pencil = ceil(b / b1)
if pen + pencil > k:
print(-1)
else:
print(pen, pencil)
```
| 33,440 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
# input
t = int(input())
javab_pen = []
javab_pencil = []
for i in range(t):
a, b, c, d, k = [int(x) for x in input().split()]
if a % c != 0:
# print(a//c + 1)
javab_pen.append(a//c + 1)
else:
javab_pen.append(a//c)
if b % d != 0:
javab_pencil.append(b//d + 1)
else:
javab_pencil.append(b//d)
if javab_pen[i]+javab_pencil[i] > k:
javab_pen[i] = (-1)
for i in range(t):
if javab_pen[i] == -1:
print(-1)
continue
print(javab_pen[i], javab_pencil[i])
```
| 33,441 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
def main():
t = int(input())
for i in range(t):
a,b,c,d,k = map(int, input().split())
aa = a//c
if a%c != 0:
aa += 1
bb = b//d
if b%d != 0:
bb +=1
if aa + bb > k:
print("-1")
else:
print("{} {}".format(aa, bb))
if __name__ == "__main__":
main()
```
| 33,442 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Tags: math
Correct Solution:
```
t = (int(input()))
for i in range(t):
a,b,c,d,k = map(int,input().split())
x = -(-a//c)
y = -(-b//d)
if (x + y > k):
print(-1)
else:
print(x,y)
```
| 33,443 | [
0.41552734375,
0.0243988037109375,
0.346923828125,
-0.080322265625,
-0.63037109375,
-0.25048828125,
-0.31494140625,
0.266357421875,
-0.05255126953125,
0.828125,
0.955078125,
-0.11883544921875,
0.310302734375,
-0.5341796875,
-0.45361328125,
0.38720703125,
-0.546875,
-0.365478515625,... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
import math
t=int(input())
while(t):
a,b,c,d,k=map(int,input().split())
x=math.ceil(a/c)
y=math.ceil(b/d)
if((x+y)>k):
print("-1")
else:
print(x,y)
t=t-1
```
Yes
| 33,444 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
t = int(input())
import math
for _ in range(t):
a = list(map(int,input().split()))
k = math.ceil(a[0]/a[2])+math.ceil(a[1]/a[3])
if k<=a[4]:
print(math.ceil(a[0]/a[2]),math.ceil(a[1]/a[3]))
else:
print(-1)
```
Yes
| 33,445 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
def abc(a,b,c,d):
x=(a-1)//c+1
y=(b-1)//d+1
return x,y
for i in range(int(input())):
a,b,c,d,k=map(int,input().split())
x,y=abc(a,b,c,d)
if x+y>k:
print(-1)
else:
print(x,y)
```
Yes
| 33,446 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
from math import ceil
t = int(input())
reult = ''
for i in range(t):
line = input().split(' ')
a = int(line[0])
b = int(line[1])
c = int(line[2])
d = int(line[3])
k = int(line[4])
pen = ceil(a / c)
pencils = ceil(b / d)
if pen + pencils <= k:
result = '{} {}'.format(pen, pencils)
else:
result = '-1'
print(result)
```
Yes
| 33,447 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
t = int(input())
c1 = 0
c2 = 0
for i in range(t):
g = list(input().split())
for j in range(len(g)):
g[j] = int(g[j])
if g[2] % g[0] > 0 :
c1 = (g[0] // g[2]) + 1
else:
c1 = g[0] // g[2]
if g[3] % g[1] > 0 :
c2 = (g[1] // g[3]) + 1
else:
c2 = g[1] // g[2]
if g[4] >= c1 + c2:
print(c1, g[4] - c1)
else:
print(-1)
```
No
| 33,448 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
import math
n=int(input())
mas=list()
for i in range(n):
a,b,c,d,k = map(int, input().split())
r = a//c+1+1+b//d
if r <=k:
mas.append(a//c+1)
mas.append(b//d+1)
else:
mas.append(-1)
mas.append(0)
i=0
while i<=(len(mas)-1):
print(mas[i], end=' ')
if mas[i+1]!=0:
print(mas[i+1])
else:
print()
i+=2
```
No
| 33,449 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
import math
t=int(input())
for i in range(t):
a,b,c,d,k=map(int,input().split())
if(a%c==0):
x=math.ceil(a/c)
if(a%c!=0):
x=math.ceil((a/c)+1)
if(b%d==0):
y=math.ceil(b/d)
if(b%d!=0):
y=math.ceil((b/d)+1)
if((x+y)>k):
print('-1')
elif((x+y)<=k):
x += (k - x - y);
print(x,y)
```
No
| 33,450 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tomorrow is a difficult day for Polycarp: he has to attend a lectures and b practical classes at the university! Since Polycarp is a diligent student, he is going to attend all of them.
While preparing for the university, Polycarp wonders whether he can take enough writing implements to write all of the lectures and draw everything he has to during all of the practical classes. Polycarp writes lectures using a pen (he can't use a pencil to write lectures!); he can write down c lectures using one pen, and after that it runs out of ink. During practical classes Polycarp draws blueprints with a pencil (he can't use a pen to draw blueprints!); one pencil is enough to draw all blueprints during d practical classes, after which it is unusable.
Polycarp's pencilcase can hold no more than k writing implements, so if Polycarp wants to take x pens and y pencils, they will fit in the pencilcase if and only if x + y ≤ k.
Now Polycarp wants to know how many pens and pencils should he take. Help him to determine it, or tell that his pencilcase doesn't have enough room for all the implements he needs tomorrow!
Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then the test cases follow.
Each test case is described by one line containing five integers a, b, c, d and k, separated by spaces (1 ≤ a, b, c, d, k ≤ 100) — the number of lectures Polycarp has to attend, the number of practical classes Polycarp has to attend, the number of lectures which can be written down using one pen, the number of practical classes for which one pencil is enough, and the number of writing implements that can fit into Polycarp's pencilcase, respectively.
In hacks it is allowed to use only one test case in the input, so t = 1 should be satisfied.
Output
For each test case, print the answer as follows:
If the pencilcase can't hold enough writing implements to use them during all lectures and practical classes, print one integer -1. Otherwise, print two non-negative integers x and y — the number of pens and pencils Polycarp should put in his pencilcase. If there are multiple answers, print any of them. Note that you don't have to minimize the number of writing implements (though their total number must not exceed k).
Example
Input
3
7 5 4 5 8
7 5 4 5 2
20 53 45 26 4
Output
7 1
-1
1 3
Note
There are many different answers for the first test case; x = 7, y = 1 is only one of them. For example, x = 3, y = 1 is also correct.
x = 1, y = 3 is the only correct answer for the third test case.
Submitted Solution:
```
try:
t = int(input())
while t:
labcdk = list(map(int, input().split()))
a = labcdk[0]
b = labcdk[1]
c = labcdk[2]
d = labcdk[3]
k = labcdk[4]
x = a/c
if type(x) == float:
x = round(x)
x += 1
else:
pass
y = k-x
if y<0:
print("-1")
else:
print(x," ", y)
t -= 1
except Exception as e:
pass
```
No
| 33,451 | [
0.423583984375,
0.09033203125,
0.29443359375,
-0.127197265625,
-0.69677734375,
-0.160888671875,
-0.33935546875,
0.282470703125,
-0.0380859375,
0.86669921875,
0.859375,
-0.02764892578125,
0.234130859375,
-0.5185546875,
-0.42822265625,
0.326416015625,
-0.5234375,
-0.337646484375,
-... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
import sys
input = sys.stdin.readline
from collections import defaultdict
for T in range(int(input())) :
n = int(input())
arr = []
for i in range(n) :
arr.append(list(input().strip()))
count = 0
for i in range(n):
if arr[i] in arr[i+1 : ] :
count +=1
j = 0
k = 1
while arr[i] in arr[i+1 : ] or arr[i] in arr[:i] :
arr[i][k] = str(j)
if j == 9 :
k +=1
j = (j +1)%10
print(count)
for i in range(n):
print(''.join(arr[i]))
```
| 34,398 | [
0.3359375,
0.300537109375,
0.412841796875,
-0.1685791015625,
-0.40966796875,
-0.513671875,
-0.3994140625,
-0.35888671875,
0.13623046875,
0.72802734375,
0.947265625,
-0.09027099609375,
0.061981201171875,
-0.96044921875,
-0.74755859375,
-0.2449951171875,
-0.333251953125,
-0.457519531... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
import sys
from collections import defaultdict
input = sys.stdin.readline
def main():
t = int(input())
for _ in range(t):
n = int(input())
d = defaultdict(lambda: [])
mk = {}
ans = [0] * n
for i in range(n):
x = input().rstrip()
d[x].append(i)
ans[i] = x
mk[x] = 1
def get_number(x):
for i in range(len(x)):
for d in range(0, 10):
y = x[:i] + str(d) + x[i + 1:]
if y not in mk:
mk[y] = 1
return y
assert(0)
changes = 0
for k, v in d.items():
while len(v) > 1:
changes += 1
p = v.pop()
ans[p] = get_number(k)
ans[v.pop()] = k
print(changes)
print("\n".join(ans))
main()
```
| 34,399 | [
0.318603515625,
0.31689453125,
0.400390625,
-0.173583984375,
-0.39599609375,
-0.498046875,
-0.392333984375,
-0.36572265625,
0.1331787109375,
0.70703125,
0.9736328125,
-0.0938720703125,
0.0258941650390625,
-0.96533203125,
-0.75341796875,
-0.268310546875,
-0.326904296875,
-0.46655273... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
t=int(input())
for i in range(t):
n=int(input())
a=dict()
b=[]
for i in range(n):
c=input()
a[c]=a.get(c,-1)+1
b.append(c)
print(sum(a.values()))
rlb=range(len(b))
for i in rlb:
v=b[i]
if a.get(v,0)==0:
print(v)
else:
v,vo=v[1:],v
for i in range(10):
if not str(i)+v in a:
a[str(i)+v]=0
a[vo]-=1
print(str(i)+v)
break
```
| 34,400 | [
0.3515625,
0.302490234375,
0.38818359375,
-0.1810302734375,
-0.389404296875,
-0.51513671875,
-0.368896484375,
-0.334228515625,
0.1492919921875,
0.740234375,
0.98193359375,
-0.0823974609375,
0.0183258056640625,
-0.96875,
-0.74072265625,
-0.2880859375,
-0.36767578125,
-0.47021484375,... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
import math
from decimal import *
getcontext().prec = 25
from itertools import permutations
MOD = pow(10, 9) + 7
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# n, k = map(int, input().split(" "))
# l = list(map(int, input().split(" ")))
for _ in range(int(input())):
n = int(input())
l = [int(input()) for i in range(n)]
d = {}
for i in l:
d[i] = d.get(i, 0) + 1
r = []
c = 0
for i in range(n):
if d[l[i]] > 1:
val = l[i] // 10 * 10
while True:
if d.get(val, 0) == 0:
break
val += 1
d[val] = d.get(val, 0) + 1
r.append(val)
c += 1
d[l[i]] -= 1
else:
r.append(l[i])
print(c)
for i in r:
print("0"*(4-len(str(i)))+ str(i))
```
| 34,401 | [
0.351318359375,
0.26220703125,
0.330810546875,
-0.134521484375,
-0.461669921875,
-0.56689453125,
-0.373046875,
-0.33349609375,
0.16796875,
0.76220703125,
0.95947265625,
-0.041595458984375,
0.061798095703125,
-0.95458984375,
-0.7275390625,
-0.1878662109375,
-0.323974609375,
-0.48876... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
def solve():
n = int(input())
pins = []
letters = []
for j in range(n):
pin = input()
pins.append(list(pin))
letters.append(pin[0])
res = 0
for a in range(len(pins)):
if pins.count(pins[a]) >= 2:
for j in range(0, 10):
if str(j) not in letters:
letters.append(str(j))
pins[a][0] = str(j)
res += 1
break
print(res)
for pin in pins:
print(*pin, sep='')
t = int(input())
for i in range(t):
solve()
```
| 34,402 | [
0.34130859375,
0.3115234375,
0.40380859375,
-0.1424560546875,
-0.39501953125,
-0.5380859375,
-0.372802734375,
-0.31396484375,
0.157470703125,
0.69873046875,
0.9765625,
-0.0484619140625,
0.0285186767578125,
-0.9697265625,
-0.7138671875,
-0.2476806640625,
-0.357177734375,
-0.47045898... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
for _ in range(int(input())):
n = int(input())
pins= []
for i in range(n):
pins.append(list(map(str,input())))
#print(pins)
reslt = 0
i, j, k = 0, 0, 0
same = False
while i < n:
j = 0
while j < n:
if i != j and pins[i] == pins[j]:
same = True
reslt += 1
break
j += 1
if same:
k = 0
while k <= 9:
j = 0
pins[i][-1] = str(k)
done = True
while j < n:
if i != j and pins[i] == pins[j]:
done = False
break
j += 1
if done:
break
k += 1
i += 1
same = False
print(reslt)
for i in range(n):
j = 1
pinseq = pins[i][0]
while j < 4:
pinseq += pins[i][j]
j += 1
print(pinseq)
del pinseq
```
| 34,403 | [
0.340087890625,
0.294677734375,
0.404541015625,
-0.1627197265625,
-0.396240234375,
-0.52490234375,
-0.3671875,
-0.3349609375,
0.13818359375,
0.7236328125,
0.9921875,
-0.06585693359375,
0.0201263427734375,
-0.97021484375,
-0.708984375,
-0.25048828125,
-0.35986328125,
-0.464599609375... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
def changePins():
n = int(input())
arr, s = [], set()
for i in range(n):
arr.append(str(input()))
s.add(arr[i])
done = [0] * n
res = 0
for i in range(n):
if done[i]:
continue
for j in range(i+1,n):
if arr[i] == arr[j]:
done[j] = 1
res += 1
k = 0
while k < 4 and arr[i] == arr[j]:
for c in ('0','1','2','3','4','5','6','7','8','9'):
newCode = list(arr[j])
newCode[k] = c
newCode = "".join(x for x in newCode)
if newCode not in s:
s.add(newCode)
arr[j] = newCode
break
k += 1
print(res)
for i in arr:
print(i)
if __name__ == "__main__":
t = int(input())
while t:
changePins()
t -= 1
```
| 34,404 | [
0.334228515625,
0.306640625,
0.38671875,
-0.1612548828125,
-0.388427734375,
-0.55908203125,
-0.366455078125,
-0.33642578125,
0.154296875,
0.72314453125,
1.01953125,
-0.0816650390625,
0.02447509765625,
-0.966796875,
-0.7021484375,
-0.273681640625,
-0.38916015625,
-0.49658203125,
-... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Tags: greedy, implementation
Correct Solution:
```
import os, sys
# copy unique numbers to new array
# for each non-unique:
# increment lowest digit (with starting from 0 if neccesary) until number becomes unique
def solve(pins):
new_pins = [ None ] * len(pins)
used_pins = set()
changed_digits = 0
for x in range(len(pins)):
if pins.count(pins[x]) == 1:
new_pins[x] = pins[x]
used_pins.add(pins[x])
for x in range(len(pins)):
if new_pins[x] is None:
old_pin = pins[x]
if old_pin not in used_pins:
used_pins.add(old_pin)
new_pins[x] = old_pin
else:
removed_last_digit_pin = (old_pin // 10) * 10
for addition in range(0, 10):
new_pin = removed_last_digit_pin + addition
if new_pin not in used_pins:
used_pins.add(new_pin)
new_pins[x] = new_pin
changed_digits += 1
break
return changed_digits, [ str(q).zfill(4) for q in new_pins ]
num = int(input().strip())
for x in range(num):
n = int(input().strip())
pins = [
int(input().strip()) for _ in range(n)
]
k, new_pins = solve(pins)
print(k)
for p in new_pins:
print(p)
```
| 34,405 | [
0.33837890625,
0.338134765625,
0.3388671875,
-0.10205078125,
-0.39306640625,
-0.52734375,
-0.406982421875,
-0.2919921875,
0.1962890625,
0.6611328125,
0.9912109375,
-0.04217529296875,
0.05596923828125,
-0.96630859375,
-0.73046875,
-0.1884765625,
-0.302734375,
-0.46337890625,
-0.37... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
import sys
input = lambda: sys.stdin.readline().rstrip()
for _ in range(int(input())):
a = int(input())
mas = []
ans = 0
jk = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
for i in range(a):
s = input()
mas.append(s)
for i in range(a):
if mas[i] in mas[:i] or mas[i] in mas[i + 1::]:
for j in jk:
if str(j) + mas[i][1::] in mas[:i] or str(j) + mas[i][1::] in mas[i + 1::]:
continue
else:
mas[i] = str(j) + mas[i][1::]
ans += 1
break
print(ans)
for row in mas:
print(row)
```
Yes
| 34,406 | [
0.365478515625,
0.33740234375,
0.33544921875,
-0.1712646484375,
-0.5283203125,
-0.449462890625,
-0.44482421875,
-0.2052001953125,
0.1317138671875,
0.70556640625,
0.88037109375,
0.01311492919921875,
0.059356689453125,
-0.94189453125,
-0.7294921875,
-0.301513671875,
-0.28125,
-0.4484... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
import sys
input = lambda:sys.stdin.readline()
int_arr = lambda: list(map(int,input().split()))
str_arr = lambda: list(map(str,input().split()))
get_str = lambda: map(str,input().split())
get_int = lambda: map(int,input().split())
get_flo = lambda: map(float,input().split())
mod = 1000000007
def solve(n,lis):
c = 0
for i in lis:
tmp = 0
for j in range(10):
if lis.count(i) == 1:
break
else:
tmp = 1
i[-1] = str(j)
c += tmp
print(c)
for i in lis:
print(''.join(i))
for _ in range(int(input())):
lis = []
n = int(input())
for i in range(n):
lis.append(list(str(input())[:-1]))
solve(n,lis)
```
Yes
| 34,407 | [
0.348876953125,
0.366943359375,
0.3173828125,
-0.1741943359375,
-0.5390625,
-0.454345703125,
-0.46337890625,
-0.2005615234375,
0.12188720703125,
0.7041015625,
0.8583984375,
-0.0020732879638671875,
0.0570068359375,
-0.94970703125,
-0.73876953125,
-0.33544921875,
-0.282470703125,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
"""
This template is made by Satwik_Tiwari.
python programmers can use this template :)) .
"""
#===============================================================================================
#importing some useful libraries.
import sys
import bisect
import heapq
from math import *
from collections import Counter as counter # Counter(list) return a dict with {key: count}
from itertools import combinations as comb # if a = [1,2,3] then print(list(comb(a,2))) -----> [(1, 2), (1, 3), (2, 3)]
from itertools import permutations as permutate
from bisect import bisect_left as bl #
from bisect import bisect_right as br
from bisect import bisect
#===============================================================================================
#some shortcuts
mod = pow(10, 9) + 7
def inp(): return sys.stdin.readline().strip() #for fast input
def out(var): sys.stdout.write(str(var)) #for fast output, always take string
def lis(): return list(map(int, inp().split()))
def stringlis(): return list(map(str, inp().split()))
def sep(): return map(int, inp().split())
def strsep(): return map(str, inp().split())
def graph(vertex): return [[] for i in range(0,vertex+1)]
def zerolist(n): return [0]*n
def nextline(): out("\n") #as stdout.write always print sring.
def testcase():
for p in range(int(inp())):
solve()
def printlist(a) :
for p in range(0,len(a)):
out(str(a[p]) + ' ')
#===============================================================================================
# code here ;))
def solve():
n = int(inp())
a = []
for i in range(0,n):
a.append(inp())
lastdigit = set([])
for i in range(0,n):
lastdigit.add(a[i][3])
# print(lastdigit,end=' == lastdigit')
# print(a,end=' ==a')
changes = 0
for i in range(0,n):
for j in range(i+1,n):
if(a[i]==a[j]):
changes +=1
for k in range(0,10):
if(str(k) not in lastdigit):
a[j] = a[j][:3] + str(k)
lastdigit.add(str(k))
break
out(changes)
nextline()
for i in range(0,n):
out(a[i])
nextline()
testcase()
```
Yes
| 34,408 | [
0.3271484375,
0.341064453125,
0.297119140625,
-0.167724609375,
-0.5107421875,
-0.48046875,
-0.35400390625,
-0.1641845703125,
0.1484375,
0.7578125,
0.89794921875,
0.0108184814453125,
0.08502197265625,
-0.9091796875,
-0.74267578125,
-0.24755859375,
-0.3046875,
-0.487060546875,
-0.2... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
t = int(input())
for zz in range(t):
n = int(input())
p = []
for i in range(n):
p.append(input())
d = {}
for i in p:
try:
d[i] += 1
except:
d[i] = 1
#print(d)
k = 0
for v in d.values():
k += v - 1
print(k)
s = set(p)
for i in range(len(p)):
if d[p[i]] > 1:
d[p[i]] -= 1
cop = p[i]
while len(cop) <= 3:
cop.insert(0, 0)
po = 0
c = 9
st = True
while st:
p[i] = list(cop)
p[i][po] = str(c)
p[i] = ''.join(p[i])
c -= 1
if p[i] not in s:
st = False
if c == 0:
c = 9
po += 1
s = set(p)
for i in p:
print(i)
```
Yes
| 34,409 | [
0.354736328125,
0.324462890625,
0.352294921875,
-0.194580078125,
-0.529296875,
-0.45458984375,
-0.4296875,
-0.183349609375,
0.1090087890625,
0.728515625,
0.9033203125,
0.015625,
0.05975341796875,
-0.92431640625,
-0.7021484375,
-0.318603515625,
-0.33154296875,
-0.484619140625,
-0.... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
from sys import *
from math import *
t=int(stdin.readline())
for _ in range(t):
n=int(stdin.readline())
m=[]
ans=0
for i in range(n):
m.append(int(input()))
for i in range(n):
c=m[i]
m[i]-=1
if c in m:
m[i]+=1
f=0
v=m[i]%10
k=m[i]-v
for j in range(10):
if k not in m:
m[i]=k
f=1
ans+=1
break
else:
k+=i
if f==0:
if m[i]+10 not in m:
m[i]+=10
f=1
ans+=1
if f==0:
if m[i]+100 not in m:
m[i]+=100
ans+=1
f=1
if f==0:
if m[i]+1000 not in m:
m[i]+=1000
ans+=1
f=1
else:
m[i]+=1
print(ans)
f=[]
for i in range(n):
d=int(log10(m[i]))
x=4-d
a=[]
for j in range(x-1):
a.append(0)
a.append(m[i])
f.append(a)
for i in range(n):
print(*f[i],sep="")
```
No
| 34,410 | [
0.351318359375,
0.343994140625,
0.341552734375,
-0.214111328125,
-0.51220703125,
-0.447509765625,
-0.4384765625,
-0.1976318359375,
0.13671875,
0.71142578125,
0.9111328125,
0.03118896484375,
0.041839599609375,
-0.931640625,
-0.71044921875,
-0.301025390625,
-0.3212890625,
-0.4765625,... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
arr = []
for i in range(n):
arr.append(input())
ar = set(arr)
print(n - len(arr))
new_arr = []
for i in arr:
if i not in new_arr:
new_arr.append(i)
else:
for j in range(10):
val = str(j) + i[1:]
if val not in ar:
ar.add(val)
new_arr.append(val)
break
print("\n".join(new_arr))
```
No
| 34,411 | [
0.347412109375,
0.334228515625,
0.3330078125,
-0.195556640625,
-0.517578125,
-0.45263671875,
-0.42138671875,
-0.1912841796875,
0.1292724609375,
0.708984375,
0.91162109375,
0.01049041748046875,
0.053863525390625,
-0.95703125,
-0.70947265625,
-0.32275390625,
-0.349853515625,
-0.48559... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
for i in range(int(input())):
n,l=int(input()),[]
for i in range(n):
r=input()
if r not in l:l.append(r)
x=0
for j in range(10):
if len(l)==n:break
q=l[0].replace(l[0][0],str(j),1)
if q not in l:
l.append(q);x+=1
print(x)
for i in l:
print(i)
```
No
| 34,412 | [
0.352783203125,
0.3310546875,
0.34033203125,
-0.183349609375,
-0.5146484375,
-0.452392578125,
-0.4169921875,
-0.184326171875,
0.133544921875,
0.712890625,
0.92431640625,
0.02734375,
0.052398681640625,
-0.94189453125,
-0.70849609375,
-0.31396484375,
-0.336669921875,
-0.479248046875,... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A PIN code is a string that consists of exactly 4 digits. Examples of possible PIN codes: 7013, 0000 and 0990. Please note that the PIN code can begin with any digit, even with 0.
Polycarp has n (2 ≤ n ≤ 10) bank cards, the PIN code of the i-th card is p_i.
Polycarp has recently read a recommendation that it is better to set different PIN codes on different cards. Thus he wants to change the minimal number of digits in the PIN codes of his cards so that all n codes would become different.
Formally, in one step, Polycarp picks i-th card (1 ≤ i ≤ n), then in its PIN code p_i selects one position (from 1 to 4), and changes the digit in this position to any other. He needs to change the minimum number of digits so that all PIN codes become different.
Polycarp quickly solved this problem. Can you solve it?
Input
The first line contains integer t (1 ≤ t ≤ 100) — the number of test cases in the input. Then test cases follow.
The first line of each of t test sets contains a single integer n (2 ≤ n ≤ 10) — the number of Polycarp's bank cards. The next n lines contain the PIN codes p_1, p_2, ..., p_n — one per line. The length of each of them is 4. All PIN codes consist of digits only.
Output
Print the answers to t test sets. The answer to each set should consist of a n + 1 lines
In the first line print k — the least number of changes to make all PIN codes different. In the next n lines output the changed PIN codes in the order corresponding to their appearance in the input. If there are several optimal answers, print any of them.
Example
Input
3
2
1234
0600
2
1337
1337
4
3139
3139
3139
3139
Output
0
1234
0600
1
1337
1237
3
3139
3138
3939
6139
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
arr = []
for i in range(n):
arr.append(input())
print(n - len(set(arr)))
new_arr = []
for i in arr:
if i not in new_arr:
new_arr.append(i)
else:
for j in range(10):
val = str(j) + i[1:]
if val not in new_arr:
new_arr.append(val)
break
print("\n".join(new_arr))
```
No
| 34,413 | [
0.353759765625,
0.341796875,
0.332763671875,
-0.1983642578125,
-0.51220703125,
-0.44091796875,
-0.4296875,
-0.1898193359375,
0.1234130859375,
0.71533203125,
0.9072265625,
0.003826141357421875,
0.05291748046875,
-0.95458984375,
-0.7080078125,
-0.32958984375,
-0.351806640625,
-0.4873... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
import sys
for _ in range(int(input())):
n, m, x = map(int, sys.stdin.readline().split())
c, r = divmod(x-1, n)
print(m*r+c+1)
```
| 34,508 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
import sys, math, itertools, random, bisect
from collections import defaultdict
INF = 10**18
def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_array(): return list(map(int, sys.stdin.readline().strip().split()))
def input(): return sys.stdin.readline().strip()
mod = 10**9 + 7
# MAX = 100001
# def sieve():
# isPrime = [True]*(MAX)
# isPrime[0] = False
# isPrime[1] = False
# for i in range(2,MAX):
# if isPrime[i]:
# for j in range(i*i, MAX, i):
# isPrime[j] = False
# primes = [2]
# for i in range(3,MAX,2):
# if isPrime[i]: primes.append(i)
# return primes
for _ in range(int(input())):
n,m,x = get_ints()
row = (x-1)%n + 1
col = math.ceil(x/n)
# print(row,col)
print(m*(row-1) + col)
```
| 34,509 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Codeforces Round #710 (Div. 3)
Problem A. Strange Table
:author: Kitchen Tong
:mail: kctong529@gmail.com
Please feel free to contact me if you have any question
regarding the implementation below.
"""
__version__ = '0.1'
__date__ = '2021-03-25'
import sys
def solve(n, m, x) -> int:
col = (x - 1) // n + 1
row = x % n
if row == 0:
row = n
row -= 1
return m * row + col
def main(argv=None):
t = int(input())
for _ in range(t):
n, m, x = map(int, input().split())
print(solve(n, m, x))
return 0
if __name__ == "__main__":
STATUS = main()
sys.exit(STATUS)
```
| 34,510 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
t = int(input())
for i in range(t):
n, m, x = map(int, input().split())
# print((x + n - 1) // n, x % n)
print(((x + n - 1) // n - 1) + ((x % n - 1) % n) * m + 1)
```
| 34,511 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
for _ in range(int(input())):
n, m, x = map(int, input().split())
x -= 1
r, q = divmod(x, n)
res = q*m + r + 1
print(res)
```
| 34,512 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
for _ in [0]*int(input()):
n,m,x = map(int,input().split())
x-=1
i,j = x//n, x%n
print(i+j*m+1)
```
| 34,513 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
for i in range(int(input())):
n,m,x = map(int,input().split())
c=n
a=x//n
if x%n!=0:
a+=1
c=x%n
print(m*(c-1)+a)
```
| 34,514 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Tags: math
Correct Solution:
```
t = int(input())
for case in range(t):
n, m, x = map(int, input().split())
a = (x - 1) // n
b = (x - 1) % n
print(((b * m) + a) + 1)
```
| 34,515 | [
0.54931640625,
-0.0914306640625,
0.021942138671875,
-0.133056640625,
-0.374755859375,
-0.364501953125,
-0.197265625,
-0.021270751953125,
0.1448974609375,
0.451171875,
1.1025390625,
-0.00751495361328125,
-0.1661376953125,
-0.5732421875,
-0.5830078125,
0.0880126953125,
-0.4013671875,
... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
n = int(input())
ans = list()
for i in range(n):
inp = input().split(" ")
modulus = int(inp[2])%int(inp[0])
division = int(int(inp[2])/int(inp[0]))
if(modulus == 0):
modulus = int(inp[0])
division -= 1
ans.append(int(inp[1])*(modulus-1)+(division+1))
for i in ans:
print(i,end = "\n")
```
Yes
| 34,516 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
test = int(input())
for i in range(test,0,-1):
arr = input().split(" ")
n =int(arr[0])
m =int(arr[1])
t =int(arr[2])
answer = (t-1)//n + 1
if t%n==0:
answer +=(n-1)*m
else:
answer+=(t%n-1)*m
print(answer)
```
Yes
| 34,517 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
def zip_sorted(a,b):
# sorted by a
a,b = zip(*sorted(zip(a,b)))
# sorted by b
sorted(zip(a, b), key=lambda x: x[1])
return a,b
def number_to_list(a):
b = []
while a>=1:
c = a%10
a = int(a/10)
b.append(c)
return list(reversed(b))
def str_list_to_int_list(a):
a = list(map(int,a))
return a
def make_1d_array(n,inti= 0):
a = [inti for _ in range(n)]
return a
def make_2d_array(n,m,inti= 0):
a = [[inti for _ in range(m)] for _ in range(n)]
return a
def make_3d_array(n,m,k,inti= 0):
a = [[[inti for _ in range(k)] for _ in range(m)] for _ in range(n)]
return a
def gcd(a,b):
if(b==0):
return a
else:
return gcd(b,a%b);
import sys
input = sys.stdin.readline
I = lambda : list(map(int,input().split()))
S = lambda : list(map(str,input()))
t,=I()
for t1 in range(t):
n,m,x = I()
x1,y1 = x//n,x%n
if y1==0:
y1 = n
x1 = x1-1
print((y1-1)*m+x1+1)
```
Yes
| 34,518 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
from sys import stdin, stdout
def main():
t = int(stdin.readline())
for t in range(t):
nmx = [int(x) for x in stdin.readline().split()]
idash = nmx[-1]%nmx[0]
if idash==0:
idash = nmx[0]
jdash = ((nmx[-1] - idash)/nmx[0]) + 1
y = (nmx[1]*(idash-1)) + jdash
print(int(y))
if __name__ == "__main__":
main()
```
Yes
| 34,519 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
for _ in range(int(input())):
n,m,x = map(int, input().split())
print(((x-1)%n)*m + (x//n) + 1)
```
No
| 34,520 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
#THIS CODE IS MADE BY "harshest2020"
from sys import *
from math import floor,ceil,sqrt
ws=lambda:map(int,stdin.readline().strip().split())
li=lambda:list(map(int,stdin.readline().strip().split()))
mod=1000000007
def ncr(n, r, p):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den, p - 2, p)) % p
def gcd(a,b):
if (b == 0):
return a
return gcd(b, a%b)
def prod(l):
ans=1
for i in range(len(l)):
ans=ans*l[i]
return ans
def sortindex(l,a):
c=[]
if(a==-1):
rev=True
else:
rev=False
for i in range(len(l)):
c.append([l[i],i])
x=sorted(c,reverse=rev)
print(x)
c=[]
for i in range(len(l)):
c.append(x[i][1])
return c
for _ in range(int(input())):
n,m,x=ws()
f=x//n
g=x%n
print(m*(g-1)+f+1)
```
No
| 34,521 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
import math
t = int(input())
def get_answer(n, m, x):
if x == m * n:
return x
c = x // n
r = x % n
return (r - 1) * m + c + 1
for _ in range(t):
n, m, x = list(map(int, input().split()))
print(get_answer(n, m, x))
```
No
| 34,522 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp found a rectangular table consisting of n rows and m columns. He noticed that each cell of the table has its number, obtained by the following algorithm "by columns":
* cells are numbered starting from one;
* cells are numbered from left to right by columns, and inside each column from top to bottom;
* number of each cell is an integer one greater than in the previous cell.
For example, if n = 3 and m = 5, the table will be numbered as follows:
$$$ \begin{matrix} 1 & 4 & 7 & 10 & 13 \\\ 2 & 5 & 8 & 11 & 14 \\\ 3 & 6 & 9 & 12 & 15 \\\ \end{matrix} $$$
However, Polycarp considers such numbering inconvenient. He likes the numbering "by rows":
* cells are numbered starting from one;
* cells are numbered from top to bottom by rows, and inside each row from left to right;
* number of each cell is an integer one greater than the number of the previous cell.
For example, if n = 3 and m = 5, then Polycarp likes the following table numbering: $$$ \begin{matrix} 1 & 2 & 3 & 4 & 5 \\\ 6 & 7 & 8 & 9 & 10 \\\ 11 & 12 & 13 & 14 & 15 \\\ \end{matrix} $$$
Polycarp doesn't have much time, so he asks you to find out what would be the cell number in the numbering "by rows", if in the numbering "by columns" the cell has the number x?
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4). Then t test cases follow.
Each test case consists of a single line containing three integers n, m, x (1 ≤ n, m ≤ 10^6, 1 ≤ x ≤ n ⋅ m), where n and m are the number of rows and columns in the table, and x is the cell number.
Note that the numbers in some test cases do not fit into the 32-bit integer type, so you must use at least the 64-bit integer type of your programming language.
Output
For each test case, output the cell number in the numbering "by rows".
Example
Input
5
1 1 1
2 2 3
3 5 11
100 100 7312
1000000 1000000 1000000000000
Output
1
2
9
1174
1000000000000
Submitted Solution:
```
def func():
n, m, x = [int(x) for x in input().split()]
if(n == 1 and m == 1):
return 1
a = (x - 1)%n
b = (x + 1)//n
c = a*m + b
return c
n = int(input())
for i in range(n):
print(func())
```
No
| 34,523 | [
0.591796875,
-0.0692138671875,
0.053619384765625,
-0.1314697265625,
-0.5263671875,
-0.259033203125,
-0.252685546875,
0.049468994140625,
0.1546630859375,
0.458251953125,
0.91748046875,
0.01059722900390625,
-0.2332763671875,
-0.488037109375,
-0.57470703125,
0.01042938232421875,
-0.3430... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
arr = list()
for i in range(n):
l, r = map(int, input().split())
arr.append((l, r))
e1, e2 = -1, -1
arr.sort()
ans = 'YES'
for i in arr:
if i[0] > e1:
e1 = i[1]
elif i[0] > e2:
e2 = i[1]
else:
ans = 'NO'
print(ans)
```
| 36,589 | [
0.281982421875,
0.06683349609375,
0.1268310546875,
0.29736328125,
-0.2880859375,
-0.52734375,
-0.446044921875,
0.236083984375,
0.4794921875,
0.72802734375,
0.470947265625,
-0.1727294921875,
0.443115234375,
-0.54736328125,
-0.52294921875,
-0.031219482421875,
-0.66455078125,
-0.55859... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
segment = []
for _ in range(n):
segment.append(list(map(int, input().split())))
segment.sort(key = lambda x: x[0])
start1 = 0
end1 = -float('inf')
start2 = 0
end2 = -float('inf')
for x in segment:
start = x[0]
end = x[1]
if start > end1:
start1 = start
end1 = end
elif start > end2:
start2 = start
end2 = end
else:
print("NO")
exit()
print("YES")
```
| 36,590 | [
0.26123046875,
0.0782470703125,
0.07818603515625,
0.345703125,
-0.27294921875,
-0.505859375,
-0.40283203125,
0.292236328125,
0.472412109375,
0.73046875,
0.475830078125,
-0.1236572265625,
0.4677734375,
-0.62158203125,
-0.44970703125,
0.003997802734375,
-0.68994140625,
-0.6171875,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
n=int(input())
a=-1
b=-1
c=[]
for _ in range(n):
c.append(list(map(int,input().split())))
c.sort()
for i in range(n):
if a<c[i][0]:
a=c[i][1]
elif b<c[i][0]:
b=c[i][1]
else:
print("NO")
exit(0)
print("YES")
```
| 36,591 | [
0.25537109375,
0.048736572265625,
0.08587646484375,
0.294921875,
-0.297119140625,
-0.50732421875,
-0.44384765625,
0.306396484375,
0.4892578125,
0.72900390625,
0.44580078125,
-0.1356201171875,
0.446533203125,
-0.56640625,
-0.4970703125,
-0.054107666015625,
-0.6982421875,
-0.57910156... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
def lol(a):
c = 0
for x in a:
if x[1]==1:
c+=1
else:
c-=1
if c>=3:
return 0
return 1
n = int(input())
a = []
for _ in range(n):
x,y = map(int,input().split())
a.append([x,1])
a.append([y,2])
a = sorted(a)
print("YES" if lol(a) else "NO")
```
| 36,592 | [
0.30029296875,
0.044158935546875,
0.10992431640625,
0.2734375,
-0.309326171875,
-0.54833984375,
-0.39697265625,
0.277587890625,
0.4208984375,
0.7509765625,
0.46875,
-0.136474609375,
0.460693359375,
-0.60009765625,
-0.50830078125,
-0.0250091552734375,
-0.6962890625,
-0.63427734375,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
pair = list()
pair1 = list()
pair2= list()
for i in range(n):
x,y = map(int,input().split())
pair.append((x,y))
pair.sort()
f = True
for i in range (n):
x = pair[i][0]
y = pair[i][1]
len1 = len(pair1)
len2 = len(pair2)
if(len1==0 or x>pair1[len1-1][1]):
pair1.append((x,y))
elif(len2==0 or x>pair2[len2-1][1]):
pair2.append((x,y))
else:
f=False
break
if(f):
print('YES')
else:
print('NO')
```
| 36,593 | [
0.31640625,
0.123291015625,
0.1168212890625,
0.2469482421875,
-0.33154296875,
-0.480224609375,
-0.4580078125,
0.2269287109375,
0.54833984375,
0.751953125,
0.45556640625,
-0.2044677734375,
0.442138671875,
-0.5654296875,
-0.50341796875,
-0.051513671875,
-0.775390625,
-0.650390625,
... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
def main():
n = int(input())
events = []
for _ in range(n):
l, r = (int(x) for x in input().split())
events.append((l, 1))
events.append((r + 1, -1))
cur = 0
for _, event in sorted(events):
cur += event
if cur > 2:
print("NO")
break
else:
print("YES")
if __name__ == "__main__":
main()
```
| 36,594 | [
0.22314453125,
0.039306640625,
0.1259765625,
0.292236328125,
-0.2900390625,
-0.5078125,
-0.471923828125,
0.2481689453125,
0.462890625,
0.70166015625,
0.44384765625,
-0.1697998046875,
0.41259765625,
-0.587890625,
-0.5302734375,
-0.042694091796875,
-0.7490234375,
-0.6904296875,
-0.... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
n = int(input())
shows = []
for i in range(n):
start, end = [int(c) for c in input().split(" ")]
shows.append((start, end))
shows.sort(key=lambda tup: tup[0])
last_show_tv1 = None
last_show_tv2 = None
can_watch = True
for show in shows:
if last_show_tv1 == None:
last_show_tv1 = show
elif last_show_tv2 == None:
last_show_tv2 = show
elif not show[0] <= last_show_tv1[1]:
last_show_tv1 = show
elif not show[0] <= last_show_tv2[1]:
last_show_tv2 = show
else:
can_watch = False
break
if can_watch:
print("YES")
else:
print("NO")
```
| 36,595 | [
0.335693359375,
0.040008544921875,
0.0509033203125,
0.3251953125,
-0.1966552734375,
-0.552734375,
-0.468017578125,
0.26806640625,
0.469970703125,
0.73046875,
0.490478515625,
-0.206787109375,
0.53759765625,
-0.61376953125,
-0.57470703125,
-0.04351806640625,
-0.798828125,
-0.54541015... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Tags: data structures, greedy, sortings
Correct Solution:
```
# import os
import sys
# from io import BytesIO, IOBase
# _str = str
# str = lambda x=b"": x if type(x) is bytes else _str(x).encode()
# BUFSIZE = 8192
# class FastIO(IOBase):
# newlines = 0
# def __init__(self, file):
# self._fd = file.fileno()
# self.buffer = BytesIO()
# self.writable = "x" in file.mode or "r" not in file.mode
# self.write = self.buffer.write if self.writable else None
# def read(self):
# while True:
# b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
# if not b:
# break
# ptr = self.buffer.tell()
# self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
# self.newlines = 0
# return self.buffer.read()
# def readline(self):
# while self.newlines == 0:
# b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
# self.newlines = b.count(b"\n") + (not b)
# ptr = self.buffer.tell()
# self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
# self.newlines -= 1
# return self.buffer.readline()
# def flush(self):
# if self.writable:
# os.write(self._fd, self.buffer.getvalue())
# self.buffer.truncate(0), self.buffer.seek(0)
# class IOWrapper(IOBase):
# def __init__(self, file):
# self.buffer = FastIO(file)
# self.flush = self.buffer.flush
# self.writable = self.buffer.writable
# self.write = lambda s: self.buffer.write(s.encode("ascii"))
# self.read = lambda: self.buffer.read().decode("ascii")
# self.readline = lambda: self.buffer.readline().decode("ascii")
input = lambda: sys.stdin.readline().rstrip("\r\n")
import time
start = time.time()
from collections import deque
shows = []
for i in range(int(input())):
shows.append([int(i) for i in input().split()])
shows.sort()
shows = deque(shows)
workers = [-1, -1]
enough_tvs = True
while shows and enough_tvs:
show = shows.popleft()
if workers[0] < show[0]:
workers[0] = show[1]
if workers[1] < show[0]:
workers[1] = -1
elif workers[1] < show[0]:
workers[1] = show[1]
else:
enough_tvs = False
if enough_tvs:
print("YES")
else:
print("NO")
# print(time.time()-start)
# with open('input.txt', 'w') as file:
# for i in range(100000):
# file.writelines(f'{i} {i+1}\n')
# from collections import defaultdict
# def main():
# conflict_found = False
# times = defaultdict(int)
# for _ in range(int(input())):
# if conflict_found:
# break
# a, b = map(int, input().split())
# if not conflict_found:
# for j in range(a, b + 1):
# times[j] += 1
# if times[j] > 2:
# conflict_found = True
# break
# if conflict_found:
# return 'NO'
# else:
# return 'YES'
# print(main())
```
| 36,596 | [
0.2305908203125,
-0.01056671142578125,
0.1693115234375,
0.398193359375,
-0.341552734375,
-0.5302734375,
-0.37939453125,
0.255126953125,
0.46875,
0.77978515625,
0.396728515625,
-0.1502685546875,
0.56201171875,
-0.5146484375,
-0.4560546875,
-0.03277587890625,
-0.64892578125,
-0.65039... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
d = []
for i in range(n):
a, b = map(int, input().split())
d.append((a, -1))
d.append((b, 1))
d.sort()
t = 0
for a, b in d:
t -= b
if t > 2:
print("NO")
exit(0)
print("YES")
```
Yes
| 36,597 | [
0.398193359375,
0.1607666015625,
0.10870361328125,
0.208984375,
-0.499755859375,
-0.350341796875,
-0.61865234375,
0.456787109375,
0.287841796875,
0.81982421875,
0.49462890625,
-0.15771484375,
0.417236328125,
-0.5634765625,
-0.478515625,
-0.09051513671875,
-0.591796875,
-0.53125,
... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
from collections import defaultdict
n = int(input())
times = defaultdict(lambda: 0)
for _ in range(n):
start, end = map(int, input().split(' '))
times[start] += 1
times[end + 1] -= 1
cur_time = 0
for time in sorted(times.keys()):
cur_time += times[time]
if cur_time > 2:
print('NO')
break
else:
print('YES')
```
Yes
| 36,598 | [
0.366455078125,
0.12176513671875,
0.01473236083984375,
0.237060546875,
-0.414794921875,
-0.312744140625,
-0.61279296875,
0.384033203125,
0.347900390625,
0.86328125,
0.49658203125,
-0.2509765625,
0.434326171875,
-0.57421875,
-0.50732421875,
-0.06390380859375,
-0.646484375,
-0.529785... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n=int(input())
shows=[]
for i in range(n):
temp = [int(j) for j in input().split(" ")]
temp[1]+=1
shows.append(temp[::])
shows.sort()
if n>1:
tv1=shows[0][1]
tv2=shows[1][1]
flag1,flag2=0,0
c=0
shows.append([1000000001,1000000001])
for i in range(2,n,1):
if tv1 <= shows[i][0] and flag1==0:
tv1=shows[i][1]
if (shows[i+1][0]>=tv1):
flag1=0
else:
flag1=1
if (shows[i + 1][0] >= tv2):
flag2 = 0
else:
flag2 = 1
elif tv2 <= shows[i][0] and flag2==0:
tv2=shows[i][1]
if (shows[i+1][0]>=tv1):
flag1=0
else:
flag1=1
if (shows[i + 1][0] >= tv2):
flag2 = 0
else:
flag2 = 1
else:
c=-1
if c==0:
print ("YES")
else:
print("NO")
else:
print("YES")
```
Yes
| 36,599 | [
0.3701171875,
0.0831298828125,
0.07476806640625,
0.25537109375,
-0.421630859375,
-0.37646484375,
-0.61865234375,
0.409912109375,
0.32568359375,
0.8505859375,
0.60400390625,
-0.174072265625,
0.499755859375,
-0.66064453125,
-0.384765625,
-0.109375,
-0.5986328125,
-0.55908203125,
-0... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
shows = []
for i in range(n):
l, r = map(int, input().split())
shows.append((l,r))
shows.sort()
a_endtime, b_endtime = -1, -1
for show in shows:
if show[0] <= a_endtime:
print('NO')
break
else:
a_endtime = show[1]
if a_endtime > b_endtime:
a_endtime, b_endtime = b_endtime, a_endtime
else:
print('YES')
```
Yes
| 36,600 | [
0.331298828125,
0.15576171875,
-0.06866455078125,
0.1982421875,
-0.439697265625,
-0.489501953125,
-0.73193359375,
0.45947265625,
0.2281494140625,
0.85986328125,
0.462890625,
-0.10931396484375,
0.47265625,
-0.63037109375,
-0.5537109375,
-0.0946044921875,
-0.6689453125,
-0.5654296875... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
def conflicts(a, b):
return a[1] >= b[0]
shows = []
for i in range(n):
x, y = map(int, input().split())
shows.append((x, y))
shows.sort(key=lambda x: x[0])
ok = True
tv1 = [(-1, -1)]
tv2 = [(-1, -1)]
for s in shows:
if not conflicts(tv1[-1], s):
tv1.append(s)
elif not conflicts(tv2[-1], s):
tv1.append(s)
else:
ok = False
break
if ok:
print('YES')
else:
print('NO')
```
No
| 36,601 | [
0.330078125,
0.145263671875,
0.08172607421875,
0.31005859375,
-0.5439453125,
-0.45556640625,
-0.64013671875,
0.492431640625,
0.384765625,
0.8349609375,
0.46484375,
-0.147216796875,
0.51611328125,
-0.6640625,
-0.49951171875,
-0.1190185546875,
-0.7197265625,
-0.55419921875,
-0.6904... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
shows = []
for i in range(n):
shows.append([int(x) for x in input().split()])
def fit(show, tv):
if show[1]<tv[0] or show[0]>tv[1]:
return True
return False
def main():
if n<2:
print("YES")
return
tv1 = shows[0]
tv2 = shows[1]
for show in shows[2:]:
if fit(show, tv1):
tv1 = [min(show[0],tv1[0]), max(show[1], tv1[1])]
elif fit(show, tv2):
tv2 = [min(show[0],tv2[0]), max(show[1], tv2[1])]
else:
print("NO")
return
print("YES")
return
main()
```
No
| 36,602 | [
0.54150390625,
0.1768798828125,
0.1124267578125,
0.255859375,
-0.482421875,
-0.353515625,
-0.68017578125,
0.41357421875,
0.339111328125,
0.74365234375,
0.64599609375,
-0.2294921875,
0.460205078125,
-0.650390625,
-0.441650390625,
0.025360107421875,
-0.56591796875,
-0.5068359375,
-... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
tv1 = set()
tv2 = set()
can_watch = True
for i in range(n):
start, end = input().split(" ")
if not start in tv1 and not end in tv1:
tv1.add(start)
tv1.add(end)
elif not start in tv2 and not end in tv2:
tv2.add(start)
tv2.add(end)
else:
can_watch = False
print(can_watch)
```
No
| 36,603 | [
0.3515625,
0.12139892578125,
0.0430908203125,
0.28515625,
-0.404296875,
-0.43310546875,
-0.60205078125,
0.425048828125,
0.375244140625,
0.81640625,
0.56201171875,
-0.14697265625,
0.52734375,
-0.5869140625,
-0.53076171875,
-0.070068359375,
-0.64453125,
-0.55224609375,
-0.692382812... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is a great fan of television.
He wrote down all the TV programs he is interested in for today. His list contains n shows, i-th of them starts at moment li and ends at moment ri.
Polycarp owns two TVs. He can watch two different shows simultaneously with two TVs but he can only watch one show at any given moment on a single TV. If one show ends at the same moment some other show starts then you can't watch them on a single TV.
Polycarp wants to check out all n shows. Are two TVs enough to do so?
Input
The first line contains one integer n (1 ≤ n ≤ 2·105) — the number of shows.
Each of the next n lines contains two integers li and ri (0 ≤ li < ri ≤ 109) — starting and ending time of i-th show.
Output
If Polycarp is able to check out all the shows using only two TVs then print "YES" (without quotes). Otherwise, print "NO" (without quotes).
Examples
Input
3
1 2
2 3
4 5
Output
YES
Input
4
1 2
2 3
2 3
1 2
Output
NO
Submitted Solution:
```
n = int(input())
def conflicts(a, b):
return a[1] >= b[0]
shows = []
for i in range(n):
x, y = map(int, input().split())
shows.append((x, y))
shows.sort(key=lambda x: x[0])
ok = True
i = 2
while i < n:
if conflicts(shows[i - 1], shows[i]) and conflicts(shows[i - 2], shows[i - 1]):
ok = False
break
i += 1
if ok:
print('YES')
else:
print('NO')
```
No
| 36,604 | [
0.33251953125,
0.1236572265625,
0.076416015625,
0.279052734375,
-0.515625,
-0.450927734375,
-0.62890625,
0.5078125,
0.3623046875,
0.830078125,
0.468994140625,
-0.1387939453125,
0.5048828125,
-0.66796875,
-0.4755859375,
-0.140625,
-0.7041015625,
-0.53271484375,
-0.68505859375,
0... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
for _ in range(int(input())):
s = list(input())
s.sort()
m = int(input())
a = list(map(int, input().split()))
while a.count(0):
qani = []
for i in range(m):
if a[i] == 0:
qani.append(i)
while s.count(s[-1]) < len(qani):
while len(s) > 1 and s[-1] == s[-2]:
s.pop()
s.pop()
now = s[-1]
while len(s) and s[-1] == now:
s.pop()
for i in qani:
a[i] = now
for i in range(m):
for x in qani:
try:
a[i] -= abs(i-x)
except:
pass
print(''.join(a))
```
| 36,979 | [
0.2744140625,
0.2734375,
0.43994140625,
-0.12103271484375,
-0.427001953125,
-0.35205078125,
-0.306396484375,
-0.148681640625,
0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
-0.11724853515625,
-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
n = int(input())
for _ in range(n):
s = sorted(input())
m = len(s)
input()
b = list(map(int, input().split()))
res = ["" for _ in range(len(b))]
found = 0
while found < len(b):
for i in range(len(b)):
if b[i] != -1:
min_v = b[i]
min_i = i
break
for i, x in enumerate(b):
if x < min_v and x != -1:
min_i = i
min_v = x
min_indices = []
for i in range(len(b)):
if b[i] == min_v:
min_indices.append(i)
b[i] = -1
c = 1
prev = s.pop()
while s and c < len(min_indices):
x = s.pop()
if x != prev:
c = 0
c += 1
prev = x
while s and s[-1] == prev:
s.pop()
found += len(min_indices)
for j in min_indices:
res[j] = prev
for i in range(len(b)):
if b[i] != -1:
b[i] -= abs(i - j)
print("".join(res))
```
| 36,980 | [
0.2744140625,
0.2734375,
0.43994140625,
-0.12103271484375,
-0.427001953125,
-0.35205078125,
-0.306396484375,
-0.148681640625,
0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
-0.11724853515625,
-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
t = int(input())
def process_array(b):
partial_sum = [0 for i in range(len(b))]
placement = [0 for i in range(len(b))]
for i in range(len(b)):
matches = [j for j in range(len(b)) if b[j]==partial_sum[j]]
if len(matches)==0:
break
for m in matches:
partial_sum[m] = -1
placement[m] = i
for j in range(len(b)):
if partial_sum[j]>=0:
for m in matches:
partial_sum[j] += abs(j-m)
return placement
for i in range(t):
s = input()
m = int(input())
b = [int(x) for x in input().split(" ")]
placement = process_array(b)
#print("placement",placement)
dic = {}
for ss in range(len(s)):
if s[ss] not in dic:
dic[s[ss]]=1
else:
dic[s[ss]]+=1
#print("dic",dic)
d_k = list(dic.keys())
d_k = sorted(d_k, reverse=True)
b_d = {}
for bb in placement:
if bb not in b_d:
b_d[bb]=1
else:
b_d[bb]+=1
#print("b_d",b_d)
b_k = list(b_d.keys())
b_k = sorted(b_k)
count_list = [b_d[x] for x in b_k]
#print("count_list",count_list)
ans_k = []
d_iter = 0
for c in count_list:
while dic[d_k[d_iter]]<c:
d_iter+=1
ans_k.append(d_k[d_iter])
d_iter+=1
ans = [0 for j in range(len(placement))]
for j in range(len(ans)):
ans[j] = ans_k[placement[j]]
print("".join(ans))
```
| 36,981 | [
0.2744140625,
0.2734375,
0.43994140625,
-0.12103271484375,
-0.427001953125,
-0.35205078125,
-0.306396484375,
-0.148681640625,
0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
-0.11724853515625,
-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
def works(c, i, prob, btgt, m):
val = 0
for j in range(m):
if prob[j] != ' ' and c < prob[j]:
val += abs(i-j)
return val == btgt
def solve0(prob, s, slack, b, m, depth):
# print(' ' * depth + '|' + prob + '|')
if prob.find(' ') == -1:
return prob, True
c = s.pop()
for i in range(m):
if prob[i] != ' ':
continue
if works(c, i, prob, b[i], m):
ans, ok = solve0( prob[:i] + c + prob[i+1:], s.copy(), slack, b, m, depth+1)
if ok:
return ans, True
if slack > 0:
ans, ok = solve0( prob, s, slack-1, b, m, depth+1)
if ok:
return ans, True
return '', False
def solve(s, m, b):
s = sorted(s)
slack = len(s) - m
ans, correct = solve0(' ' * m, s, slack, b, m, 0)
return ans
cases = int(input().strip())
for _ in range(cases):
s = input().strip()
m = int(input().strip())
b = list(map(int, input().strip().split()))
print(solve(s, m, b))
```
| 36,982 | [
0.2744140625,
0.2734375,
0.43994140625,
-0.12103271484375,
-0.427001953125,
-0.35205078125,
-0.306396484375,
-0.148681640625,
0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
-0.11724853515625,
-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
t = int(input())
for _ in range(t):
freq = {}
a = input()
for ax in a:
freq[ax] = freq.get(ax, 0) + 1
a = sorted(set(a), reverse=True)
bl = int(input())
b = list(map(int, input().split()))
l = []
li = 0
while li < bl:
sm = []
for bi in range(bl):
if b[bi] == 0:
sm.append(bi)
b[bi] = -1
for bi in range(bl):
if b[bi] != -1:
dis = 0
for x in sm:
dis += abs(bi - x)
b[bi] -= dis
l.append(sm)
li += len(sm)
ans = ['a' for _ in range(bl)]
ai = 0
for lx in l:
while freq[a[ai]] < len(lx):
ai += 1
for ii in lx:
ans[ii] = a[ai]
ai += 1
print("".join(ans))
```
| 36,983 | [
0.2744140625,
0.2734375,
0.43994140625,
-0.12103271484375,
-0.427001953125,
-0.35205078125,
-0.306396484375,
-0.148681640625,
0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
-0.11724853515625,
-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
import sys
q=int(sys.stdin.readline())
ans_arr=[]
for i in range(q):
s=sys.stdin.readline().strip()
m=int(sys.stdin.readline())
b=[int(j) for j in sys.stdin.readline().split()]
arr=[]
freq=[0]*26
for g in range(len(s)):
arr.append(s[g])
freq[ord(s[g])-97]+=1
arr.sort()
ans=[]
for g in range(m):
ans.append("a")
ptr=len(arr)-1
d_idx={}
d_ch={}
for sol in range(m):
ind=-2
ctr=0
for e in range(m):
if(b[e]==0 and (e not in d_idx)):
if(ind==-2):
ind=e
ctr+=1
num=ord(arr[ptr])-97
while(freq[num]<ctr):
for g in range(freq[num]):
ptr-=1
num=ord(arr[ptr])-97
d_idx[ind]=1
ans[ind]=arr[ptr]
if(arr[ptr] not in d_ch):
d_ch[arr[ptr]]=1
else:
d_ch[arr[ptr]]+=1
if(ctr==1 and freq[num]-d_ch[arr[ptr]]>0):
for g in range(freq[num]-d_ch[arr[ptr]]):
ptr-=1
ptr-=1
for g in range(m):
if(b[g]!=0):
b[g]=b[g]-abs(g-ind)
answer=""
for h in range(m):
answer+=ans[h]
ans_arr.append(answer)
print("\n".join(ans_arr))
```
| 36,984 | [
0.2744140625,
0.2734375,
0.43994140625,
-0.12103271484375,
-0.427001953125,
-0.35205078125,
-0.306396484375,
-0.148681640625,
0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
-0.11724853515625,
-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
T = int(input())
for _ in range(T):
S = input()
M = int(input())
B = list(map(int, input().split()))
Alpha = {}
for elt in S:
try:
Alpha[elt] += 1
except KeyError:
Alpha[elt] = 1
Alpha = list(Alpha.items())
Alpha.sort(key = lambda x: x[0])
ans = [None]*M
Done = 0
while Done < M:
Zeros = []
Count = 0
for i, elt in enumerate(B):
if elt == 0:
Zeros += i,
Count += 1
toRemove = 0
for letter, count in Alpha[::-1]:
toRemove -= 1
if count >= Count:
for i in Zeros:
ans[i] = letter
Done += Count
break
del Alpha[toRemove:]
for elt in Zeros:
for i in range(len(B)):
if i == elt:
B[i] = -1
else:
B[i] -= abs(i-elt)
print("".join(ans))
```
| 36,985 | [
0.2744140625,
0.2734375,
0.43994140625,
-0.12103271484375,
-0.427001953125,
-0.35205078125,
-0.306396484375,
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0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
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-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Tags: constructive algorithms, greedy, implementation, sortings
Correct Solution:
```
q=int(input())
for i in range(q):
s=input()
m=int(input())
b=list(map(int, input().split()))
d={}
l=sorted(list(set(s)), reverse=True)
for alphabet in l:
d[alphabet]=s.count(alphabet)
ret='0'*m
l0=-1
while 1:
bcopy=b.copy()
n=b.count(0)
if n==0:
break
for j in range(1,30):
if d[l[l0+j]]>=n:
l0+=j
alphabet=l[l0]
break
for j in range(m):
if b[j]==0:
ret=ret[0:j]+alphabet+ret[j+1:]
for k in range(m):
if b[k]!=0:
bcopy[k]-=abs(k-j)
bcopy[j]=-1
b=bcopy
print(ret)
```
| 36,986 | [
0.2744140625,
0.2734375,
0.43994140625,
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-0.427001953125,
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-0.306396484375,
-0.148681640625,
0.05059814453125,
0.7734375,
0.8544921875,
0.0154266357421875,
-0.11724853515625,
-1.0673828125,
-0.80322265625,
-0.248291015625,
-0.5029296875,
-0.17663574... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Submitted Solution:
```
for _ in range(int(input())):
s = input()
n = int(input())
m = n
b = list(map(int,input().split()))
c = ['']*m
freq = [0]*26
i = 25
for elem in s:
freq[ord(elem)-ord('a')]+=1
while n>0 and i>=0:
zero=[]
count = 0
for j in range(m):
if b[j]==0:
zero.append(j)
b[j]=-1
count+=1
while i>=0:
if freq[i]>=count:
for elem in zero:
c[elem]=chr(i + ord('a'))
n -= count
for j in range(m):
for elem in zero:
if b[j] > 0:
b[j] -= abs(j - elem)
i -= 1
break
else:
i -= 1
print(''.join(c))
```
Yes
| 36,987 | [
0.296142578125,
0.2939453125,
0.365234375,
-0.1824951171875,
-0.537109375,
-0.2164306640625,
-0.4130859375,
-0.1075439453125,
0.060760498046875,
0.7998046875,
0.6650390625,
0.0975341796875,
-0.1231689453125,
-1.05078125,
-0.69384765625,
-0.1949462890625,
-0.45263671875,
-0.27099609... | 24 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp wrote on the board a string s containing only lowercase Latin letters ('a'-'z'). This string is known for you and given in the input.
After that, he erased some letters from the string s, and he rewrote the remaining letters in any order. As a result, he got some new string t. You have to find it with some additional information.
Suppose that the string t has length m and the characters are numbered from left to right from 1 to m. You are given a sequence of m integers: b_1, b_2, …, b_m, where b_i is the sum of the distances |i-j| from the index i to all such indices j that t_j > t_i (consider that 'a'<'b'<...<'z'). In other words, to calculate b_i, Polycarp finds all such indices j that the index j contains a letter that is later in the alphabet than t_i and sums all the values |i-j|.
For example, if t = "abzb", then:
* since t_1='a', all other indices contain letters which are later in the alphabet, that is: b_1=|1-2|+|1-3|+|1-4|=1+2+3=6;
* since t_2='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_2=|2-3|=1;
* since t_3='z', then there are no indexes j such that t_j>t_i, thus b_3=0;
* since t_4='b', only the index j=3 contains the letter, which is later in the alphabet, that is: b_4=|4-3|=1.
Thus, if t = "abzb", then b=[6,1,0,1].
Given the string s and the array b, find any possible string t for which the following two requirements are fulfilled simultaneously:
* t is obtained from s by erasing some letters (possibly zero) and then writing the rest in any order;
* the array, constructed from the string t according to the rules above, equals to the array b specified in the input data.
Input
The first line contains an integer q (1 ≤ q ≤ 100) — the number of test cases in the test. Then q test cases follow.
Each test case consists of three lines:
* the first line contains string s, which has a length from 1 to 50 and consists of lowercase English letters;
* the second line contains positive integer m (1 ≤ m ≤ |s|), where |s| is the length of the string s, and m is the length of the array b;
* the third line contains the integers b_1, b_2, ..., b_m (0 ≤ b_i ≤ 1225).
It is guaranteed that in each test case an answer exists.
Output
Output q lines: the k-th of them should contain the answer (string t) to the k-th test case. It is guaranteed that an answer to each test case exists. If there are several answers, output any.
Example
Input
4
abac
3
2 1 0
abc
1
0
abba
3
1 0 1
ecoosdcefr
10
38 13 24 14 11 5 3 24 17 0
Output
aac
b
aba
codeforces
Note
In the first test case, such strings t are suitable: "aac', "aab".
In the second test case, such trings t are suitable: "a", "b", "c".
In the third test case, only the string t equals to "aba" is suitable, but the character 'b' can be from the second or third position.
Submitted Solution:
```
from collections import defaultdict
letters = list(reversed([chr(x) for x in range(ord('a'), ord('z') + 1)]))
t = int(input())
for case in range(t):
s = input()
n = len(s)
letter_count = defaultdict(int)
for l in s:
letter_count[l] += 1
m = int(input())
b = list(map(int, input().split()))
visited = [0] * m
counter = 0
i = 0
output = ['a'] * m
while counter < m:
zeros = []
for j in range(m):
if not visited[j] and b[j] == 0:
visited[j] = 1
zeros.append(j)
counter += 1
while i <= 26 and letter_count[letters[i]] < len(zeros):
i += 1
for j in zeros:
output[j] = letters[i]
for j in range(m):
for k in zeros:
b[j] -= abs(j - k)
i += 1
print(''.join(output))
```
Yes
| 36,988 | [
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0.2939453125,
0.365234375,
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0.7998046875,
0.6650390625,
0.0975341796875,
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-1.05078125,
-0.69384765625,
-0.1949462890625,
-0.45263671875,
-0.27099609... | 24 |
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