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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given a positive integer m, we say that a sequence x_1, x_2, ..., x_n of positive integers is m-cute if for every index i such that 2 ≀ i ≀ n it holds that x_i = x_{i - 1} + x_{i - 2} + ... + x_1 + r_i for some positive integer r_i satisfying 1 ≀ r_i ≀ m. You will be given q queries consisting of three positive integers a, b and m. For each query you must determine whether or not there exists an m-cute sequence whose first term is a and whose last term is b. If such a sequence exists, you must additionally find an example of it. Input The first line contains an integer number q (1 ≀ q ≀ 10^3) β€” the number of queries. Each of the following q lines contains three integers a, b, and m (1 ≀ a, b, m ≀ 10^{14}, a ≀ b), describing a single query. Output For each query, if no m-cute sequence whose first term is a and whose last term is b exists, print -1. Otherwise print an integer k (1 ≀ k ≀ 50), followed by k integers x_1, x_2, ..., x_k (1 ≀ x_i ≀ 10^{14}). These integers must satisfy x_1 = a, x_k = b, and that the sequence x_1, x_2, ..., x_k is m-cute. It can be shown that under the problem constraints, for each query either no m-cute sequence exists, or there exists one with at most 50 terms. If there are multiple possible sequences, you may print any of them. Example Input 2 5 26 2 3 9 1 Output 4 5 6 13 26 -1 Note Consider the sample. In the first query, the sequence 5, 6, 13, 26 is valid since 6 = 5 + \bf{\color{blue} 1}, 13 = 6 + 5 + {\bf\color{blue} 2} and 26 = 13 + 6 + 5 + {\bf\color{blue} 2} have the bold values all between 1 and 2, so the sequence is 2-cute. Other valid sequences, such as 5, 7, 13, 26 are also accepted. In the second query, the only possible 1-cute sequence starting at 3 is 3, 4, 8, 16, ..., which does not contain 9. Submitted Solution: ``` from math import log2 def find_k(A, B, M): for k in range(2, 51): s = 2 ** (k-2) if (A+1) * s <= B and (A+M) * s >= B: return k return -1 def solve(A, B, M): if A == B: print('1', A) return k = find_k(A, B, M) if k == -1: print(-1) return print(k, end=' ') a = A print(A, end=' ') R = B - (2 ** (k-2)) * A for i in range(k-3, -1, -1): s = 2 ** i r = min(R // s - 1, M) print(a + r, end=' ') a += a + r R -= r * s assert 0 < R <= M print(B) Q = int(input()) for case in range(Q): A, B, M = [int(x) for x in input().split()] solve(A, B, M) ```
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153,559
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given a positive integer m, we say that a sequence x_1, x_2, ..., x_n of positive integers is m-cute if for every index i such that 2 ≀ i ≀ n it holds that x_i = x_{i - 1} + x_{i - 2} + ... + x_1 + r_i for some positive integer r_i satisfying 1 ≀ r_i ≀ m. You will be given q queries consisting of three positive integers a, b and m. For each query you must determine whether or not there exists an m-cute sequence whose first term is a and whose last term is b. If such a sequence exists, you must additionally find an example of it. Input The first line contains an integer number q (1 ≀ q ≀ 10^3) β€” the number of queries. Each of the following q lines contains three integers a, b, and m (1 ≀ a, b, m ≀ 10^{14}, a ≀ b), describing a single query. Output For each query, if no m-cute sequence whose first term is a and whose last term is b exists, print -1. Otherwise print an integer k (1 ≀ k ≀ 50), followed by k integers x_1, x_2, ..., x_k (1 ≀ x_i ≀ 10^{14}). These integers must satisfy x_1 = a, x_k = b, and that the sequence x_1, x_2, ..., x_k is m-cute. It can be shown that under the problem constraints, for each query either no m-cute sequence exists, or there exists one with at most 50 terms. If there are multiple possible sequences, you may print any of them. Example Input 2 5 26 2 3 9 1 Output 4 5 6 13 26 -1 Note Consider the sample. In the first query, the sequence 5, 6, 13, 26 is valid since 6 = 5 + \bf{\color{blue} 1}, 13 = 6 + 5 + {\bf\color{blue} 2} and 26 = 13 + 6 + 5 + {\bf\color{blue} 2} have the bold values all between 1 and 2, so the sequence is 2-cute. Other valid sequences, such as 5, 7, 13, 26 are also accepted. In the second query, the only possible 1-cute sequence starting at 3 is 3, 4, 8, 16, ..., which does not contain 9. Submitted Solution: ``` import math for i in range(int(input())): a, b, m = map(int,input().split()) out = "" if a == b: print("1 {}".format(a)) continue if b - a <= m: print(2, a, b) continue for q in range(51): j = (b / (2 ** q)) - 2 * a - m if j%1 == 0 and 0<j<m+1: if q % 1 == 0: last_print = (2 * a + j + m) / 2 out += "{} {} {} ".format(int(q) + 3, a, int(a + j)) for k in range(int(q) + 1): last_print = int(2 * last_print) out += str(last_print) + " " break if len(out) > 0: print(out) else: print(-1) # (2*a + j + m) * 2**q = b # j = (b/(2**q)) - 2*a - m ```
instruction
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76,780
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153,560
No
output
1
76,780
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153,561
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given a positive integer m, we say that a sequence x_1, x_2, ..., x_n of positive integers is m-cute if for every index i such that 2 ≀ i ≀ n it holds that x_i = x_{i - 1} + x_{i - 2} + ... + x_1 + r_i for some positive integer r_i satisfying 1 ≀ r_i ≀ m. You will be given q queries consisting of three positive integers a, b and m. For each query you must determine whether or not there exists an m-cute sequence whose first term is a and whose last term is b. If such a sequence exists, you must additionally find an example of it. Input The first line contains an integer number q (1 ≀ q ≀ 10^3) β€” the number of queries. Each of the following q lines contains three integers a, b, and m (1 ≀ a, b, m ≀ 10^{14}, a ≀ b), describing a single query. Output For each query, if no m-cute sequence whose first term is a and whose last term is b exists, print -1. Otherwise print an integer k (1 ≀ k ≀ 50), followed by k integers x_1, x_2, ..., x_k (1 ≀ x_i ≀ 10^{14}). These integers must satisfy x_1 = a, x_k = b, and that the sequence x_1, x_2, ..., x_k is m-cute. It can be shown that under the problem constraints, for each query either no m-cute sequence exists, or there exists one with at most 50 terms. If there are multiple possible sequences, you may print any of them. Example Input 2 5 26 2 3 9 1 Output 4 5 6 13 26 -1 Note Consider the sample. In the first query, the sequence 5, 6, 13, 26 is valid since 6 = 5 + \bf{\color{blue} 1}, 13 = 6 + 5 + {\bf\color{blue} 2} and 26 = 13 + 6 + 5 + {\bf\color{blue} 2} have the bold values all between 1 and 2, so the sequence is 2-cute. Other valid sequences, such as 5, 7, 13, 26 are also accepted. In the second query, the only possible 1-cute sequence starting at 3 is 3, 4, 8, 16, ..., which does not contain 9. Submitted Solution: ``` Q = int(input()) for _ in range(Q): a, b, m = map(int, input().split()) X = [a] Y = [a] s = a t = a while True: X.append(s+1) Y.append(t+m) s += s+1 t += t+m if X[-1] <= b <= Y[-1]: Z = [0] * len(X) Z[-1] = b for j in range(len(Z)-1)[::-1]: mi = (Z[j+1]-m+1) // 2 ma = (Z[j+1]-1) // 2 Z[j] = X[j] + (Z[j+1]-X[j+1])//2 print(len(Z), *Z) break elif X[-1] >= b: print(-1) break ```
instruction
0
76,781
5
153,562
No
output
1
76,781
5
153,563
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given a positive integer m, we say that a sequence x_1, x_2, ..., x_n of positive integers is m-cute if for every index i such that 2 ≀ i ≀ n it holds that x_i = x_{i - 1} + x_{i - 2} + ... + x_1 + r_i for some positive integer r_i satisfying 1 ≀ r_i ≀ m. You will be given q queries consisting of three positive integers a, b and m. For each query you must determine whether or not there exists an m-cute sequence whose first term is a and whose last term is b. If such a sequence exists, you must additionally find an example of it. Input The first line contains an integer number q (1 ≀ q ≀ 10^3) β€” the number of queries. Each of the following q lines contains three integers a, b, and m (1 ≀ a, b, m ≀ 10^{14}, a ≀ b), describing a single query. Output For each query, if no m-cute sequence whose first term is a and whose last term is b exists, print -1. Otherwise print an integer k (1 ≀ k ≀ 50), followed by k integers x_1, x_2, ..., x_k (1 ≀ x_i ≀ 10^{14}). These integers must satisfy x_1 = a, x_k = b, and that the sequence x_1, x_2, ..., x_k is m-cute. It can be shown that under the problem constraints, for each query either no m-cute sequence exists, or there exists one with at most 50 terms. If there are multiple possible sequences, you may print any of them. Example Input 2 5 26 2 3 9 1 Output 4 5 6 13 26 -1 Note Consider the sample. In the first query, the sequence 5, 6, 13, 26 is valid since 6 = 5 + \bf{\color{blue} 1}, 13 = 6 + 5 + {\bf\color{blue} 2} and 26 = 13 + 6 + 5 + {\bf\color{blue} 2} have the bold values all between 1 and 2, so the sequence is 2-cute. Other valid sequences, such as 5, 7, 13, 26 are also accepted. In the second query, the only possible 1-cute sequence starting at 3 is 3, 4, 8, 16, ..., which does not contain 9. Submitted Solution: ``` from sys import stdin, stdout ```
instruction
0
76,782
5
153,564
No
output
1
76,782
5
153,565
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given a positive integer m, we say that a sequence x_1, x_2, ..., x_n of positive integers is m-cute if for every index i such that 2 ≀ i ≀ n it holds that x_i = x_{i - 1} + x_{i - 2} + ... + x_1 + r_i for some positive integer r_i satisfying 1 ≀ r_i ≀ m. You will be given q queries consisting of three positive integers a, b and m. For each query you must determine whether or not there exists an m-cute sequence whose first term is a and whose last term is b. If such a sequence exists, you must additionally find an example of it. Input The first line contains an integer number q (1 ≀ q ≀ 10^3) β€” the number of queries. Each of the following q lines contains three integers a, b, and m (1 ≀ a, b, m ≀ 10^{14}, a ≀ b), describing a single query. Output For each query, if no m-cute sequence whose first term is a and whose last term is b exists, print -1. Otherwise print an integer k (1 ≀ k ≀ 50), followed by k integers x_1, x_2, ..., x_k (1 ≀ x_i ≀ 10^{14}). These integers must satisfy x_1 = a, x_k = b, and that the sequence x_1, x_2, ..., x_k is m-cute. It can be shown that under the problem constraints, for each query either no m-cute sequence exists, or there exists one with at most 50 terms. If there are multiple possible sequences, you may print any of them. Example Input 2 5 26 2 3 9 1 Output 4 5 6 13 26 -1 Note Consider the sample. In the first query, the sequence 5, 6, 13, 26 is valid since 6 = 5 + \bf{\color{blue} 1}, 13 = 6 + 5 + {\bf\color{blue} 2} and 26 = 13 + 6 + 5 + {\bf\color{blue} 2} have the bold values all between 1 and 2, so the sequence is 2-cute. Other valid sequences, such as 5, 7, 13, 26 are also accepted. In the second query, the only possible 1-cute sequence starting at 3 is 3, 4, 8, 16, ..., which does not contain 9. Submitted Solution: ``` def get_r_list(a, b, m): k = 2 two_power_k = 1 isMatch = False if a == b: return 1, [] while True: if b <= two_power_k * (a + 1): isMatch = True break if k == 50: break k += 1 two_power_k *= 2 if isMatch: k -= 1 two_power_k = two_power_k / 2 gap = b - two_power_k * (a + 1) two_power_k = int(two_power_k / 2) # 2^k-3 r_list = [] while two_power_k != 0: # print("two: ", end="") # print(two_power_k) if gap >= two_power_k: index_r = 0 gap_divide = int(gap / two_power_k) if gap_divide > m - 1: index_r = m - 1 else: index_r = gap_divide gap = gap - two_power_k * index_r r_list.append(index_r) two_power_k = int(two_power_k / 2) else: two_power_k = int(two_power_k / 2) r_list.append(0) isDone = False if gap == 0: isDone = True r_list.append(0) else: if gap <= m - 1: isDone = True r_list.append(gap) else: isDone = False if isDone: return k, r_list else: return -1, r_list # print(k) # print(r_list) def cute_sequence(a, b, m): k, r_list = get_r_list(a, b, m) if k == -1: print(k) return if k == 1: print(1, end=" ") print(1) return sequence_list = [] sequence_list.append(a) sequence_list.append(a + r_list[0] + 1) for i in range(2, k): next_a = 2 * sequence_list[i - 1] + r_list[i - 1] - r_list[i - 2] sequence_list.append(next_a) print(k, end=" ") for ele in sequence_list: print(ele, end=" ") print() return N = int(input()) for _ in range(N): a, b, m = input().split() a = int(a) b = int(b) m = int(m) cute_sequence(a, b, m) ```
instruction
0
76,783
5
153,566
No
output
1
76,783
5
153,567
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. An integer sequence is called beautiful if the difference between any two consecutive numbers is equal to 1. More formally, a sequence s_1, s_2, …, s_{n} is beautiful if |s_i - s_{i+1}| = 1 for all 1 ≀ i ≀ n - 1. Trans has a numbers 0, b numbers 1, c numbers 2 and d numbers 3. He wants to construct a beautiful sequence using all of these a + b + c + d numbers. However, it turns out to be a non-trivial task, and Trans was not able to do it. Could you please help Trans? Input The only input line contains four non-negative integers a, b, c and d (0 < a+b+c+d ≀ 10^5). Output If it is impossible to construct a beautiful sequence satisfying the above constraints, print "NO" (without quotes) in one line. Otherwise, print "YES" (without quotes) in the first line. Then in the second line print a + b + c + d integers, separated by spaces β€” a beautiful sequence. There should be a numbers equal to 0, b numbers equal to 1, c numbers equal to 2 and d numbers equal to 3. If there are multiple answers, you can print any of them. Examples Input 2 2 2 1 Output YES 0 1 0 1 2 3 2 Input 1 2 3 4 Output NO Input 2 2 2 3 Output NO Note In the first test, it is easy to see, that the sequence is beautiful because the difference between any two consecutive numbers is equal to 1. Also, there are exactly two numbers, equal to 0, 1, 2 and exactly one number, equal to 3. It can be proved, that it is impossible to construct beautiful sequences in the second and third tests. Submitted Solution: ``` #------------------------template--------------------------# import os import sys from math import * from collections import * # from fractions import * # from heapq import* from bisect import * from io import BytesIO, IOBase def vsInput(): sys.stdin = open('input.txt', 'r') sys.stdout = open('output.txt', 'w') BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") ALPHA='abcdefghijklmnopqrstuvwxyz' M=10**9+7 EPS=1e-6 def Ceil(a,b): return a//b+int(a%b>0) def value():return tuple(map(int,input().split())) def array():return [int(i) for i in input().split()] def Int():return int(input()) def Str():return input() def arrayS():return [i for i in input().split()] #-------------------------code---------------------------# # vsInput() c0,c1,c2,c3=value() ok=True tot=c0+c1+c2+c3 M=c0+c2+c0+c2+1 ans=[-1]*(c0+c2+c0+c2+1) M=len(ans) if(tot>M or tot<c0+c2+c0+c2-1): ok=False # print(ok) # Filling 0 and 2 ---------/ for i in range(len(ans)): if(i%2): if(c0): c0-=1 ans[i]=0 elif(c2): c2-=1 ans[i]=2 # print(ans) # Filling 3 between 2 ----------/ for i in range(len(ans)-2,0,-1): if(c3 and ans[i-1]==2 and ans[i+1]==2): c3-=1 ans[i]=3 if(c3): ans[-1]=3 c3-=1 if(c3 and ans[1]==2): ans[0]=3 c3-=1 if(c3):ok=False # print(ans) # Filling 1 -----------------/ for i in range(2,len(ans)): if(ans[i]==-1 and c1): c1-=1 ans[i]=1 # print(ans) if(c1 and ans[0]==-1): ans[0]=1 c1-=1 if(c1): ok=False start=0 end=len(ans)-1 while(ans[start]==-1): start+=1 while(ans[end]==-1): end-=1 for i in range(start,end+1): if(ans[i]==-1):ok=False if(ok): print("YES") print(*ans[start:end+1]) else: print("NO") ```
instruction
0
76,851
5
153,702
No
output
1
76,851
5
153,703
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given an array a consisting of n positive integers, numbered from 1 to n. You can perform the following operation no more than 3n times: 1. choose three integers i, j and x (1 ≀ i, j ≀ n; 0 ≀ x ≀ 10^9); 2. assign a_i := a_i - x β‹… i, a_j := a_j + x β‹… i. After each operation, all elements of the array should be non-negative. Can you find a sequence of no more than 3n operations after which all elements of the array are equal? Input The first line contains one integer t (1 ≀ t ≀ 10^4) β€” the number of test cases. Then t test cases follow. The first line of each test case contains one integer n (1 ≀ n ≀ 10^4) β€” the number of elements in the array. The second line contains n integers a_1, a_2, ..., a_n (1 ≀ a_i ≀ 10^5) β€” the elements of the array. It is guaranteed that the sum of n over all test cases does not exceed 10^4. Output For each test case print the answer to it as follows: * if there is no suitable sequence of operations, print -1; * otherwise, print one integer k (0 ≀ k ≀ 3n) β€” the number of operations in the sequence. Then print k lines, the m-th of which should contain three integers i, j and x (1 ≀ i, j ≀ n; 0 ≀ x ≀ 10^9) for the m-th operation. If there are multiple suitable sequences of operations, print any of them. Note that you don't have to minimize k. Example Input 3 4 2 16 4 18 6 1 2 3 4 5 6 5 11 19 1 1 3 Output 2 4 1 2 2 3 3 -1 4 1 2 4 2 4 5 2 3 3 4 5 1 Submitted Solution: ``` import os import sys from io import BytesIO, IOBase _str = str BUFSIZE = 8192 def str(x=b''): return x if type(x) is bytes else _str(x).encode() class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = 'x' in file.mode or 'r' not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b'\n') + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode('ascii')) self.read = lambda: self.buffer.read().decode('ascii') self.readline = lambda: self.buffer.readline().decode('ascii') def inp(): return sys.stdin.readline() def mpint(): return map(int, sys.stdin.readline().split(' ')) def itg(): return int(sys.stdin.readline()) # ############################## import # ############################## main def solve(): n = itg() arr = [0] + list(mpint()) s = sum(arr) if s % n: print(-1) return s //= n # collect values to arr[0] op = 0 required = [] output = [] for i in range(2, n + 1): x = arr[i] // i if x: op += 1 output.append((i, 1, x)) arr[1] += x * i arr[i] -= x * i else: # arr[i] < i required.append((i - arr[i], i)) # (required, index) # collect again (add required first) required.sort() for r, i in required: if arr[1] >= r: op += 2 output.append((1, i, r)) output.append((i, 1, 1)) arr[1] += arr[i] arr[i] = 0 for j in range(2, n + 1): x = s - arr[j] if x < 0 or arr[1] < x: break if x: op += 1 output.append((1, j, x)) arr[1] -= x arr[j] += x del arr[0] if arr != [s] * n: print(-1) else: print(op) for p in output: print(*p) sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) if __name__ == '__main__': # print("YES" if solve() else "NO") # print("yes" if solve() else "no") # solve() for _ in range(itg()): # print(*solve()) solve() # Please check! ```
instruction
0
76,901
5
153,802
No
output
1
76,901
5
153,803
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` w,m,k=map(int,input().split()) #print('w='+str(w)+' m='+str(m)+' k='+str(k)) n=m-1 l=len(str(m)) #print('l='+str(l)) while w>0: t=((10**l)-n-1)*l*k #print('t='+str(t)) if w<=t: n+=w//(l*k) w=0 else: n=10**l w=w-t-(l+1)*k l+=1 #print('n='+str(n)+' w='+str(w)) print(n-m+1) ```
instruction
0
77,073
5
154,146
Yes
output
1
77,073
5
154,147
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` w,m,k=map(int,input().split()) d=(len(str(m))) ans=0 c = min(10**d - m, w//(k*d)) while c: ans+=c w-= c*k*d m=10**d d+=1 c=min(10**d-m,w//(k*d)) print(ans) ```
instruction
0
77,074
5
154,148
Yes
output
1
77,074
5
154,149
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` def f(x): digs = len(str(x)) ndig = digs*(x - 10**(digs-1) + 1) for i in range(1, digs): ndig += i * 9*10**(i-1) return ndig a, b, c = map(int, input().split(' ')) num = a // c need = num + f(b-1) lo = 0 hi = 10**18 while lo < hi: mid = (lo + hi + 1) // 2 if f(mid) > need: hi = mid - 1 else: lo = mid print(lo-b+1) ```
instruction
0
77,075
5
154,150
Yes
output
1
77,075
5
154,151
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` w, m, k = map(int, input().split()) cost, num = 0, 0 ln = len(str(m)) aim = 10**ln if (aim - m)*ln*k <= w: cost += (aim - m)*ln*k num += (aim - m) m = aim ln += 1 while True: if ln*k*9*10**(ln-1)+cost <= w: cost += ln*k*9*10**(ln-1) num += 9*10**(ln-1) m = 10**ln ln += 1 else: break lastm = m aim = 10**ln mid, lastn = 0, 0 while aim != m+1: mid = m + (aim-m)//2 if ln*k*(mid-lastm)+cost <= w: m = mid else: aim = mid print(num + m - lastm) ```
instruction
0
77,076
5
154,152
Yes
output
1
77,076
5
154,153
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` from math import log w,m,k = map(int,input().split()) d = 0 z = int(log(m,10)) zlom = 10**z while w > 0 : z+=1 zlom*=10 c = (zlom-m)*z*k if c > w : x = w//(z*k) d+=x break w-=c d+=(zlom-m) m = zlom print(d) ```
instruction
0
77,077
5
154,154
No
output
1
77,077
5
154,155
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` w,m,k=list(map(int,input().split())) z=a=10**len(str(m))-m if a*k>=w: print(w//(len(str(m))*k)) else: w-=a*k c=len(str(m))+1 while w>0: a=9*10**(c-1) if a*c*k>=w: print(w//(c*k)+z) break w-=a*c*k z+=a c+=1 ```
instruction
0
77,078
5
154,156
No
output
1
77,078
5
154,157
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` read = lambda: tuple(map(int, input().split())) w, m, k = read() l = [10**v-1 for v in range(1, 30)] cv = m s = lambda v: len(str(v))*k cd = 0 ln = 0 for lv in l: if cv < lv: d = min(w, (lv - cv + 1) * s(cv)) // s(cv) w -= d * s(cv) ln += d cv = lv + 1 print(ln) ```
instruction
0
77,079
5
154,158
No
output
1
77,079
5
154,159
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example, S(893) = 3, S(114514) = 6. You want to make a consecutive integer sequence starting from number m (m, m + 1, ...). But you need to pay S(n)Β·k to add the number n to the sequence. You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length. Input The first line contains three integers w (1 ≀ w ≀ 1016), m (1 ≀ m ≀ 1016), k (1 ≀ k ≀ 109). Please, do not write the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier. Output The first line should contain a single integer β€” the answer to the problem. Examples Input 9 1 1 Output 9 Input 77 7 7 Output 7 Input 114 5 14 Output 6 Input 1 1 2 Output 0 Submitted Solution: ``` import math w,m,k=map(int,input().split()) x=int("1"+("0"*len(str(m)))) h=x-m n=len(str(m)) ans=w//(n*k) if(ans>h): ans=h w-=h*n*k while(w>0): n+=1 x=w//(n*k) if(x>=10**(n-1)*9): ans+=10**(n-1)*9 w-=(n*k*10**(n-1)*9) else: ans+=x break print(ans) print(ans) ```
instruction
0
77,080
5
154,160
No
output
1
77,080
5
154,161
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are working as an analyst in a company working on a new system for big data storage. This system will store n different objects. Each object should have a unique ID. To create the system, you choose the parameters of the system β€” integers m β‰₯ 1 and b_{1}, b_{2}, …, b_{m}. With these parameters an ID of some object in the system is an array of integers [a_{1}, a_{2}, …, a_{m}] where 1 ≀ a_{i} ≀ b_{i} holds for every 1 ≀ i ≀ m. Developers say that production costs are proportional to βˆ‘_{i=1}^{m} b_{i}. You are asked to choose parameters m and b_{i} so that the system will be able to assign unique IDs to n different objects and production costs are minimized. Note that you don't have to use all available IDs. Input In the only line of input there is one positive integer n. The length of the decimal representation of n is no greater than 1.5 β‹… 10^{6}. The integer does not contain leading zeros. Output Print one number β€” minimal value of βˆ‘_{i=1}^{m} b_{i}. Examples Input 36 Output 10 Input 37 Output 11 Input 12345678901234567890123456789 Output 177 Submitted Solution: ``` n = int(input()) if n <= 4: print(n) cur = 1 power = 0 while 4 * cur < n: cur = cur * 3 power = power + 3 if 2 * cur >= n: print(power + 2) elif 3 * cur >= n: print(power + 3) else: print(power + 4) ```
instruction
0
77,337
5
154,674
No
output
1
77,337
5
154,675
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are working as an analyst in a company working on a new system for big data storage. This system will store n different objects. Each object should have a unique ID. To create the system, you choose the parameters of the system β€” integers m β‰₯ 1 and b_{1}, b_{2}, …, b_{m}. With these parameters an ID of some object in the system is an array of integers [a_{1}, a_{2}, …, a_{m}] where 1 ≀ a_{i} ≀ b_{i} holds for every 1 ≀ i ≀ m. Developers say that production costs are proportional to βˆ‘_{i=1}^{m} b_{i}. You are asked to choose parameters m and b_{i} so that the system will be able to assign unique IDs to n different objects and production costs are minimized. Note that you don't have to use all available IDs. Input In the only line of input there is one positive integer n. The length of the decimal representation of n is no greater than 1.5 β‹… 10^{6}. The integer does not contain leading zeros. Output Print one number β€” minimal value of βˆ‘_{i=1}^{m} b_{i}. Examples Input 36 Output 10 Input 37 Output 11 Input 12345678901234567890123456789 Output 177 Submitted Solution: ``` import math n = int(input()) def well(k): if(k * nr >= n) : print(3 * lg + k) exit(0) def well2(k, k2): if(k * k2 * nr >= n) : print(3 * lg + k + k2) exit(0) def well3(k, k2, k3): if(k * k2 * k3 * nr >= n) : print(3 * lg + k + k2 + k3) exit(0) lg = math.log(n, 3) lg = int(lg) if(lg > 2): lg -= 1 # print(lg) nr = 3 ** lg well(2); well(3); well(4); well2(3, 2); well2(3, 3); well2(3, 4); well3(3, 3, 2); well3(3, 3, 3); ```
instruction
0
77,338
5
154,676
No
output
1
77,338
5
154,677
Provide a correct Python 3 solution for this coding contest problem. Takahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction. More specifically, in one move, he can go from coordinate x to x + D or x - D. He wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible. Find the minimum possible absolute value of the coordinate of the destination. Constraints * -10^{15} \leq X \leq 10^{15} * 1 \leq K \leq 10^{15} * 1 \leq D \leq 10^{15} * All values in input are integers. Input Input is given from Standard Input in the following format: X K D Output Print the minimum possible absolute value of the coordinate of the destination. Examples Input 6 2 4 Output 2 Input 7 4 3 Output 1 Input 10 1 2 Output 8 Input 1000000000000000 1000000000000000 1000000000000000 Output 1000000000000000
instruction
0
77,343
5
154,686
"Correct Solution: ``` import math X,K,D =map(int,input().split()) X=abs(X) a=X//D b=X%D if a >K: ans=(a-K)*D+b else: ans=X-a*D-((K-a)%2)*D print(abs(ans)) ```
output
1
77,343
5
154,687
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,405
5
154,810
"Correct Solution: ``` K = int(input()) print(int(K/2) * int((K+1)/2)) ```
output
1
77,405
5
154,811
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,406
5
154,812
"Correct Solution: ``` x,y = divmod(int(input()),2) print(x*(x+y)) ```
output
1
77,406
5
154,813
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,407
5
154,814
"Correct Solution: ``` k=int(input()) ans=k//2*((k+1)//2) print(ans) ```
output
1
77,407
5
154,815
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,408
5
154,816
"Correct Solution: ``` k = int(input()) print(int((k/2)**2)) ```
output
1
77,408
5
154,817
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,409
5
154,818
"Correct Solution: ``` x = int(input()) y = x // 2 print(y*(x-y)) ```
output
1
77,409
5
154,819
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,410
5
154,820
"Correct Solution: ``` K=int(input()) print((K+1)//2*(K//2)) ```
output
1
77,410
5
154,821
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,411
5
154,822
"Correct Solution: ``` n = int(input()) print((n // 2) * ((n + 1)// 2)) ```
output
1
77,411
5
154,823
Provide a correct Python 3 solution for this coding contest problem. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625
instruction
0
77,412
5
154,824
"Correct Solution: ``` k = int(input()) print(-(-k//2)*(k+(-k//2))) ```
output
1
77,412
5
154,825
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` K = int(input()) a = int(K/2) b = K-a print(a*b) ```
instruction
0
77,413
5
154,826
Yes
output
1
77,413
5
154,827
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` n=int(input()) print(n//2*(n-n//2)) ```
instruction
0
77,414
5
154,828
Yes
output
1
77,414
5
154,829
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` k = int(input()) a = k//2 b = k-a print(a*b) ```
instruction
0
77,415
5
154,830
Yes
output
1
77,415
5
154,831
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` k=int(input()) print((k-(k+1)//2)*((k+1)//2)) ```
instruction
0
77,416
5
154,832
Yes
output
1
77,416
5
154,833
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` import math n = int(input()) print(math.ceil(n/2)*n//2) ```
instruction
0
77,417
5
154,834
No
output
1
77,417
5
154,835
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` import math k = 50 if k%2: print(math.floor(k/2)*math.ceil(k/2)) else: print(int((k/2)**2)) ```
instruction
0
77,418
5
154,836
No
output
1
77,418
5
154,837
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` k=input() odd=1 even=0 for i in range(2,k+1): if i%2==0: even+=1 else: odd+=1 print(odd*even) ```
instruction
0
77,419
5
154,838
No
output
1
77,419
5
154,839
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Find the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). The order does not matter. Constraints * 2\leq K\leq 100 * K is an integer. Input Input is given from Standard Input in the following format: K Output Print the number of ways to choose a pair of an even number and an odd number from the positive integers between 1 and K (inclusive). Examples Input 3 Output 2 Input 6 Output 9 Input 11 Output 30 Input 50 Output 625 Submitted Solution: ``` N = int(input()) print((N/2)**2 if N%2==0 else (1+N//2)*(N//2)) ```
instruction
0
77,420
5
154,840
No
output
1
77,420
5
154,841
Provide a correct Python 3 solution for this coding contest problem. Example Input 6 3 1 0 0 1 0 1 1 3 2 Output 1
instruction
0
77,528
5
155,056
"Correct Solution: ``` import copy N,M = [int(i) for i in input().split()] b = [int(i) for i in input().split()] p = [int(i) for i in input().split()] def solve(num): ret = 0 c = copy.deepcopy(b) c_ = [] for i in range(M): c_ += [(int(i%2 == num))] * p[i] #print(c,c_) for i in range(N): if c[i] != c_[i]: for j in range(i,N): if c_[i] == c[j]: ret += j-i # print(j-i) c[i],c[j]=c[j],c[i] break else: return 1000 return ret print(min(solve(0),solve(1))) ```
output
1
77,528
5
155,057
Provide a correct Python 3 solution for this coding contest problem. Example Input 6 3 1 0 0 1 0 1 1 3 2 Output 1
instruction
0
77,529
5
155,058
"Correct Solution: ``` import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools sys.setrecursionlimit(10**7) inf = 10**20 eps = 1.0 / 10**10 mod = 998244353 dd = [(0,-1),(1,0),(0,1),(-1,0)] ddn = [(0,-1),(1,-1),(1,0),(1,1),(0,1),(-1,-1),(-1,0),(-1,1)] def LI(): return [int(x) for x in sys.stdin.readline().split()] def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()] def LF(): return [float(x) for x in sys.stdin.readline().split()] def LS(): return sys.stdin.readline().split() def I(): return int(sys.stdin.readline()) def F(): return float(sys.stdin.readline()) def S(): return input() def pf(s): return print(s, flush=True) def main(): rr = [] while True: n,m = LI() b = LI() p = LI() r = inf t = [] for i in range(m): t += [i % 2] * p[i] if sorted(collections.Counter(t).items()) == sorted(collections.Counter(b).items()): tr = 0 pi = 0 for i in range(n): if t[i] != 1: continue while b[pi] != 1: pi += 1 tr += abs(i-pi) pi += 1 r = tr t = [] for i in range(m): t += [(i+1) % 2] * p[i] if sorted(collections.Counter(t).items()) == sorted(collections.Counter(b).items()): tr = 0 pi = 0 for i in range(n): if t[i] != 1: continue while b[pi] != 1: pi += 1 tr += abs(i-pi) pi += 1 if r > tr: r = tr rr.append(r) break return '\n'.join(map(str, rr)) print(main()) ```
output
1
77,529
5
155,059
Provide a correct Python 3 solution for this coding contest problem. Example Input 6 3 1 0 0 1 0 1 1 3 2 Output 1
instruction
0
77,530
5
155,060
"Correct Solution: ``` def read(): return list(map(int,input().split())) def calc(bs,ls,first): if sum(ls[0::2])!=bs.count(first) or sum(ls[1::2])!=bs.count(1-first): return float("inf") res=0 i,j=0,0 for k in range(0,len(ls),2): if k>0: i+=ls[k-1] for _ in range(ls[k]): j=bs.index(first,j) res+=abs(j-i) i+=1 j+=1 return res while 1: try: n,m=read() bs=read() ls=read() except: break print(min(calc(bs,ls,i) for i in range(2))) ```
output
1
77,530
5
155,061
Provide a correct Python 3 solution for this coding contest problem. Example Input 6 3 1 0 0 1 0 1 1 3 2 Output 1
instruction
0
77,531
5
155,062
"Correct Solution: ``` N, M = map(int, input().split()) *B, = map(int, input().split()) *P, = map(int, input().split()) def solve(v): C = B[:] D = [] for i in range(M): D += [(i & 1) ^ v]*P[i] res = 0 for i in range(N): if C[i] != D[i]: for j in range(i, N): if D[i] == C[j]: C[i], C[j] = C[j], C[i] res += j - i break else: return 10**9 return res print(min(solve(0), solve(1))) ```
output
1
77,531
5
155,063
Provide a correct Python 3 solution for this coding contest problem. Example Input 6 3 1 0 0 1 0 1 1 3 2 Output 1
instruction
0
77,532
5
155,064
"Correct Solution: ``` # -*- coding: utf-8 -*- ( n, m ) = map ( int, input ( ).split ( ) ) b = tuple ( map ( int, input ( ).split ( ) ) ) p = list ( map ( int, input ( ).split ( ) ) ) cs = 0 ss = { } fs = [ ] bs = [ b ] while bs: ( fs, bs ) = ( bs, fs ) while fs: b = fs.pop ( ) if b not in ss: ss[ b ] = cs b = list ( b ) for i in range ( n - 1 ): ( b[ i ], b[ i + 1 ] ) = ( b[ i + 1 ], b[ i ] ) bs.append ( tuple ( b ) ) ( b[ i + 1 ], b[ i ] ) = ( b[ i ], b[ i + 1 ] ) cs = cs + 1 for ( k, v ) in ss.items ( ): res = [ ] co = 1 for i in range ( 1, len ( k ) ): if k[ i - 1 ] == k[ i ]: co = co + 1 else: res.append ( co ) co = 1 res.append ( co ) if res == p and v < cs: cs = v print ( cs ) ```
output
1
77,532
5
155,065
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are three arrays a, b and c. Each of them consists of n integers. SmallY wants to find three integers u, v, w (0 ≀ u, v, w ≀ n) such that the following condition holds: each number that appears in the union of a, b and c, appears either in the first u elements of a, or in the first v elements of b, or in the first w elements of c. Of course, SmallY doesn't want to have huge numbers u, v and w, so she wants sum u + v + w to be as small as possible. Please, help her to find the minimal possible sum of u + v + w. Input The first line contains a single integer n (1 ≀ n ≀ 105). The second line contains n space-separated integers a1, a2, ..., an β€” array a. The third line contains the description of array b in the same format. The fourth line contains the description of array c in the same format. The following constraint holds: 1 ≀ ai, bi, ci ≀ 109. Output Print a single integer β€” the minimum possible sum of u + v + w. Examples Input 3 1 1 101 1 2 1 3 2 1 Output 5 Input 5 1 1 2 2 3 2 2 4 3 3 3 3 1 1 1 Output 5 Note In the first example you should choose u = 3, v = 0, w = 2. In the second example you should choose u = 1, v = 3, w = 1. Submitted Solution: ``` import fileinput import copy i=0 for line in fileinput.input(): if i==0: n = int(line) myLists = [[] for i in range(3)] i+=1 else: myLists[i-1] = [int(i) for i in line.split()] i+=1 #if n == 27: # for i in range(len(myLists)): # print(myLists[i]) myListsCopy = copy.deepcopy(myLists) def sortUnion(listToUnionSort): if len(listToUnionSort) ==1: ans = list(set(listToUnionSort)) ans.sort() return ans else: ans = listToUnionSort[0] for i in range(1,len(listToUnionSort)): ans.extend(listToUnionSort[i]) ans = list(set(ans)) ans.sort() return ans myUnionList = sortUnion(myListsCopy) L1 = len(myUnionList) L = len(myLists[0]) myUnionDict = {} for i in range(L1): k = [] for j in range(3): if myUnionList[i] in myLists[j]: k.append(myLists[j].index(myUnionList[i])) else: k.append(L) myUnionDict[myUnionList[i]] = k #print(myUnionDict) def myMiniMax(myLists,myDict, L): valuesL = list(myDict.values()) if len(valuesL) == 0: return [L] myMin = [ min(i) for i in valuesL ] myMax = max(myMin) relNum = [myLists[j][myMax] for j in range(len(myLists))] maxRelNum = max(relNum) myMaxVec = [i == maxRelNum for i in relNum] return [myMax, myMaxVec] def myPruneFunc(myLists, myDict, myListIndex, myIndex): valuesToRemove = list(set(myLists[myListIndex][0:(myIndex+1)])) for i in valuesToRemove: if i in list(myDict.keys()): myDict.pop(i) for i in list(myDict.keys()): del myDict[i][myListIndex] del myLists[myListIndex] def myRecFunc(myLists, myDict, currentSum, L): myMax = myMiniMax(myLists,myDict,L) if myMax[0] == L: return currentSum if len(myLists) == 0: return currentSum if len(myLists[0])==1: return currentSum+1+myMax[0] else: numCandidates = sum(myMax[1]) candIndex = [] for i in range(0, len(myMax[1])): if myMax[1][i]: candIndex.append(i) ansList = [] copiedLists = [] copiedDict = [] for i in range(len(candIndex)): copiedLists.append(copy.deepcopy(myLists)) copiedDict.append(copy.deepcopy(myDict)) myPruneFunc(copiedLists[i],copiedDict[i],candIndex[i],myMax[0]) ansList.append(myRecFunc(copiedLists[i],copiedDict[i],currentSum+myMax[0],L)) return min(ansList) a = myRecFunc(myLists,myUnionDict,0,L) print(a) def operate(A): myMin = [ min(i) for i in list(A.values())] myIndex = myMin.index(max(myMin)) valueInterest = max(A[myIndex]) indexInterest = A[myIndex].index(valueInterest) for i in range(myIndex+1): A.pop(myLists[indexInterest][i]) ```
instruction
0
77,813
5
155,626
No
output
1
77,813
5
155,627
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are three arrays a, b and c. Each of them consists of n integers. SmallY wants to find three integers u, v, w (0 ≀ u, v, w ≀ n) such that the following condition holds: each number that appears in the union of a, b and c, appears either in the first u elements of a, or in the first v elements of b, or in the first w elements of c. Of course, SmallY doesn't want to have huge numbers u, v and w, so she wants sum u + v + w to be as small as possible. Please, help her to find the minimal possible sum of u + v + w. Input The first line contains a single integer n (1 ≀ n ≀ 105). The second line contains n space-separated integers a1, a2, ..., an β€” array a. The third line contains the description of array b in the same format. The fourth line contains the description of array c in the same format. The following constraint holds: 1 ≀ ai, bi, ci ≀ 109. Output Print a single integer β€” the minimum possible sum of u + v + w. Examples Input 3 1 1 101 1 2 1 3 2 1 Output 5 Input 5 1 1 2 2 3 2 2 4 3 3 3 3 1 1 1 Output 5 Note In the first example you should choose u = 3, v = 0, w = 2. In the second example you should choose u = 1, v = 3, w = 1. Submitted Solution: ``` import fileinput import copy i=0 for line in fileinput.input(): if i==0: n = int(line) myLists = [[0]*n for i in range(3)] i+=1 else: myLists[i-1] = [int(i) for i in line.split()] i+=1 myListsCopy = copy.deepcopy(myLists) def sortUnion(listToUnionSort): if len(listToUnionSort) ==1: ans = list(set(listToUnionSort)) ans.sort() return ans else: ans = listToUnionSort[0] for i in range(1,len(listToUnionSort)): ans.extend(listToUnionSort[i]) ans = list(set(ans)) ans.sort() return ans myUnionList = sortUnion(myListsCopy) L1 = len(myUnionList) L = len(myLists[0]) myUnionDict = {} for i in range(L1): k = [] for j in range(3): if myUnionList[i] in myLists[j]: k.append(myLists[j].index(myUnionList[i])) else: k.append(L) myUnionDict[myUnionList[i]] = k #print(myUnionDict) def myMiniMax(myLists,myDict, L): valuesL = list(myDict.values()) if len(valuesL) == 0: return [L] myMin = [ min(i) for i in valuesL ] myMax = max(myMin) relNum = [myLists[j][myMax] for j in range(len(myLists))] maxRelNum = max(relNum) myMaxVec = [i == maxRelNum for i in relNum] return [myMax, myMaxVec] def myPruneFunc(myLists, myDict, myListIndex, myIndex): valuesToRemove = list(set(myLists[myListIndex][0:(myIndex+1)])) for i in valuesToRemove: if i in list(myDict.keys()): myDict.pop(i) for i in list(myDict.keys()): del myDict[i][myListIndex] del myLists[myListIndex] def myRecFunc(myLists, myDict, currentSum, L): myMax = myMiniMax(myLists,myDict,L) if myMax[0] == L: return currentSum if len(myLists) == 0: return currentSum if len(myLists[0])==1: return currentSum+1+myMax[0] else: numCandidates = sum(myMax[1]) candIndex = [] for i in range(0, len(myMax[1])): if myMax[1][i]: candIndex.append(i) ansList = [] copiedLists = [] copiedDict = [] for i in range(len(candIndex)): copiedLists.append(copy.deepcopy(myLists)) copiedDict.append(copy.deepcopy(myDict)) myPruneFunc(copiedLists[i],copiedDict[i],candIndex[i],myMax[0]) ansList.append(myRecFunc(copiedLists[i],copiedDict[i],currentSum+1+myMax[0],L)) return min(ansList) print(myRecFunc(myLists,myUnionDict,0,L)) def operate(A): myMin = [ min(i) for i in list(A.values())] myIndex = myMin.index(max(myMin)) valueInterest = max(A[myIndex]) indexInterest = A[myIndex].index(valueInterest) for i in range(myIndex+1): A.pop(myLists[indexInterest][i]) ```
instruction
0
77,814
5
155,628
No
output
1
77,814
5
155,629
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are three arrays a, b and c. Each of them consists of n integers. SmallY wants to find three integers u, v, w (0 ≀ u, v, w ≀ n) such that the following condition holds: each number that appears in the union of a, b and c, appears either in the first u elements of a, or in the first v elements of b, or in the first w elements of c. Of course, SmallY doesn't want to have huge numbers u, v and w, so she wants sum u + v + w to be as small as possible. Please, help her to find the minimal possible sum of u + v + w. Input The first line contains a single integer n (1 ≀ n ≀ 105). The second line contains n space-separated integers a1, a2, ..., an β€” array a. The third line contains the description of array b in the same format. The fourth line contains the description of array c in the same format. The following constraint holds: 1 ≀ ai, bi, ci ≀ 109. Output Print a single integer β€” the minimum possible sum of u + v + w. Examples Input 3 1 1 101 1 2 1 3 2 1 Output 5 Input 5 1 1 2 2 3 2 2 4 3 3 3 3 1 1 1 Output 5 Note In the first example you should choose u = 3, v = 0, w = 2. In the second example you should choose u = 1, v = 3, w = 1. Submitted Solution: ``` import fileinput import copy i=0 for line in fileinput.input(): if i==0: n = int(line) myLists = [[] for i in range(3)] i+=1 else: myLists[i-1] = [int(i) for i in line.split()] i+=1 #if n == 27: # for i in range(len(myLists)): # print(myLists[i]) myListsCopy = copy.deepcopy(myLists) def sortUnion(listToUnionSort): if len(listToUnionSort) ==1: ans = list(set(listToUnionSort)) ans.sort() return ans else: ans = listToUnionSort[0] for i in range(1,len(listToUnionSort)): ans.extend(listToUnionSort[i]) ans = list(set(ans)) ans.sort() return ans myUnionList = sortUnion(myListsCopy) L1 = len(myUnionList) L = len(myLists[0]) myUnionDict = {} for i in range(L1): k = [] for j in range(3): if myUnionList[i] in myLists[j]: k.append(myLists[j].index(myUnionList[i])) else: k.append(L) myUnionDict[myUnionList[i]] = k #print(myUnionDict) def myMiniMax(myLists,myDict, L): valuesL = list(myDict.values()) if len(valuesL) == 0: return [L] myMin = [ min(i) for i in valuesL ] myMax = max(myMin) relNum = [myLists[j][myMax] for j in range(len(myLists))] maxRelNum = max(relNum) myMaxVec = [i == maxRelNum for i in relNum] return [myMax, myMaxVec] def myPruneFunc(myLists, myDict, myListIndex, myIndex): valuesToRemove = list(set(myLists[myListIndex][0:(myIndex+1)])) for i in valuesToRemove: if i in list(myDict.keys()): myDict.pop(i) for i in list(myDict.keys()): del myDict[i][myListIndex] del myLists[myListIndex] def myRecFunc(myLists, myDict, currentSum, L): myMax = myMiniMax(myLists,myDict,L) if myMax[0] == L: return currentSum if len(myLists) == 0: return currentSum if len(myLists[0])==1: return currentSum+1+myMax[0] else: numCandidates = sum(myMax[1]) candIndex = [] for i in range(0, len(myMax[1])): if myMax[1][i]: candIndex.append(i) ansList = [] copiedLists = [] copiedDict = [] for i in range(len(candIndex)): copiedLists.append(copy.deepcopy(myLists)) copiedDict.append(copy.deepcopy(myDict)) myPruneFunc(copiedLists[i],copiedDict[i],candIndex[i],myMax[0]) ansList.append(myRecFunc(copiedLists[i],copiedDict[i],currentSum+1+myMax[0],L)) return min(ansList) a = myRecFunc(myLists,myUnionDict,0,L) if a != 66: print(a) else: print(65) def operate(A): myMin = [ min(i) for i in list(A.values())] myIndex = myMin.index(max(myMin)) valueInterest = max(A[myIndex]) indexInterest = A[myIndex].index(valueInterest) for i in range(myIndex+1): A.pop(myLists[indexInterest][i]) ```
instruction
0
77,815
5
155,630
No
output
1
77,815
5
155,631
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are three arrays a, b and c. Each of them consists of n integers. SmallY wants to find three integers u, v, w (0 ≀ u, v, w ≀ n) such that the following condition holds: each number that appears in the union of a, b and c, appears either in the first u elements of a, or in the first v elements of b, or in the first w elements of c. Of course, SmallY doesn't want to have huge numbers u, v and w, so she wants sum u + v + w to be as small as possible. Please, help her to find the minimal possible sum of u + v + w. Input The first line contains a single integer n (1 ≀ n ≀ 105). The second line contains n space-separated integers a1, a2, ..., an β€” array a. The third line contains the description of array b in the same format. The fourth line contains the description of array c in the same format. The following constraint holds: 1 ≀ ai, bi, ci ≀ 109. Output Print a single integer β€” the minimum possible sum of u + v + w. Examples Input 3 1 1 101 1 2 1 3 2 1 Output 5 Input 5 1 1 2 2 3 2 2 4 3 3 3 3 1 1 1 Output 5 Note In the first example you should choose u = 3, v = 0, w = 2. In the second example you should choose u = 1, v = 3, w = 1. Submitted Solution: ``` import fileinput import copy i=0 for line in fileinput.input(): if i==0: n = int(line) myLists = [[] for i in range(3)] i+=1 else: myLists[i-1] = [int(i) for i in line.split()] i+=1 if n == 27: for i in range(len(myLists)): print(myLists[i][0]) myListsCopy = copy.deepcopy(myLists) def sortUnion(listToUnionSort): if len(listToUnionSort) ==1: ans = list(set(listToUnionSort)) ans.sort() return ans else: ans = listToUnionSort[0] for i in range(1,len(listToUnionSort)): ans.extend(listToUnionSort[i]) ans = list(set(ans)) ans.sort() return ans myUnionList = sortUnion(myListsCopy) L1 = len(myUnionList) L = len(myLists[0]) myUnionDict = {} for i in range(L1): k = [] for j in range(3): if myUnionList[i] in myLists[j]: k.append(myLists[j].index(myUnionList[i])) else: k.append(L) myUnionDict[myUnionList[i]] = k #print(myUnionDict) def myMiniMax(myLists,myDict, L): valuesL = list(myDict.values()) if len(valuesL) == 0: return [L] myMin = [ min(i) for i in valuesL ] myMax = max(myMin) relNum = [myLists[j][myMax] for j in range(len(myLists))] maxRelNum = max(relNum) myMaxVec = [i == maxRelNum for i in relNum] return [myMax, myMaxVec] def myPruneFunc(myLists, myDict, myListIndex, myIndex): valuesToRemove = list(set(myLists[myListIndex][0:(myIndex+1)])) for i in valuesToRemove: if i in list(myDict.keys()): myDict.pop(i) for i in list(myDict.keys()): del myDict[i][myListIndex] del myLists[myListIndex] def myRecFunc(myLists, myDict, currentSum, L): myMax = myMiniMax(myLists,myDict,L) if myMax[0] == L: return currentSum if len(myLists) == 0: return currentSum if len(myLists[0])==1: return currentSum+1+myMax[0] else: numCandidates = sum(myMax[1]) candIndex = [] for i in range(0, len(myMax[1])): if myMax[1][i]: candIndex.append(i) ansList = [] copiedLists = [] copiedDict = [] for i in range(len(candIndex)): copiedLists.append(copy.deepcopy(myLists)) copiedDict.append(copy.deepcopy(myDict)) myPruneFunc(copiedLists[i],copiedDict[i],candIndex[i],myMax[0]) ansList.append(myRecFunc(copiedLists[i],copiedDict[i],currentSum+1+myMax[0],L)) return min(ansList) print(myRecFunc(myLists,myUnionDict,0,L)) def operate(A): myMin = [ min(i) for i in list(A.values())] myIndex = myMin.index(max(myMin)) valueInterest = max(A[myIndex]) indexInterest = A[myIndex].index(valueInterest) for i in range(myIndex+1): A.pop(myLists[indexInterest][i]) ```
instruction
0
77,816
5
155,632
No
output
1
77,816
5
155,633
Provide a correct Python 3 solution for this coding contest problem. Print the circumference of a circle of radius R. Constraints * 1 \leq R \leq 100 * All values in input are integers. Input Input is given from Standard Input in the following format: R Output Print the circumference of the circle. Your output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}. Examples Input 1 Output 6.28318530717958623200 Input 73 Output 458.67252742410977361942
instruction
0
78,015
5
156,030
"Correct Solution: ``` R = int(input()) print(R*6.283184) ```
output
1
78,015
5
156,031
Provide a correct Python 3 solution for this coding contest problem. Print the circumference of a circle of radius R. Constraints * 1 \leq R \leq 100 * All values in input are integers. Input Input is given from Standard Input in the following format: R Output Print the circumference of the circle. Your output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}. Examples Input 1 Output 6.28318530717958623200 Input 73 Output 458.67252742410977361942
instruction
0
78,016
5
156,032
"Correct Solution: ``` r=int(input()) print(6.283*r) ```
output
1
78,016
5
156,033
Provide a correct Python 3 solution for this coding contest problem. Print the circumference of a circle of radius R. Constraints * 1 \leq R \leq 100 * All values in input are integers. Input Input is given from Standard Input in the following format: R Output Print the circumference of the circle. Your output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}. Examples Input 1 Output 6.28318530717958623200 Input 73 Output 458.67252742410977361942
instruction
0
78,017
5
156,034
"Correct Solution: ``` a=int(input()) print(2*3.14*a) ```
output
1
78,017
5
156,035
Provide a correct Python 3 solution for this coding contest problem. Print the circumference of a circle of radius R. Constraints * 1 \leq R \leq 100 * All values in input are integers. Input Input is given from Standard Input in the following format: R Output Print the circumference of the circle. Your output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}. Examples Input 1 Output 6.28318530717958623200 Input 73 Output 458.67252742410977361942
instruction
0
78,018
5
156,036
"Correct Solution: ``` x=int(input()) print(x*3.14159*2) ```
output
1
78,018
5
156,037
Provide a correct Python 3 solution for this coding contest problem. Print the circumference of a circle of radius R. Constraints * 1 \leq R \leq 100 * All values in input are integers. Input Input is given from Standard Input in the following format: R Output Print the circumference of the circle. Your output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}. Examples Input 1 Output 6.28318530717958623200 Input 73 Output 458.67252742410977361942
instruction
0
78,019
5
156,038
"Correct Solution: ``` N = int(input()) print(2*N*3.14) ```
output
1
78,019
5
156,039
Provide a correct Python 3 solution for this coding contest problem. Print the circumference of a circle of radius R. Constraints * 1 \leq R \leq 100 * All values in input are integers. Input Input is given from Standard Input in the following format: R Output Print the circumference of the circle. Your output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}. Examples Input 1 Output 6.28318530717958623200 Input 73 Output 458.67252742410977361942
instruction
0
78,020
5
156,040
"Correct Solution: ``` R=int(input()) print((2*R)*3.142) ```
output
1
78,020
5
156,041
Provide a correct Python 3 solution for this coding contest problem. Print the circumference of a circle of radius R. Constraints * 1 \leq R \leq 100 * All values in input are integers. Input Input is given from Standard Input in the following format: R Output Print the circumference of the circle. Your output is considered correct if and only if its absolute or relative error from our answer is at most 10^{-2}. Examples Input 1 Output 6.28318530717958623200 Input 73 Output 458.67252742410977361942
instruction
0
78,021
5
156,042
"Correct Solution: ``` print(int(input())*2*3.14159265) ```
output
1
78,021
5
156,043