message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers a and b.
In one move, you can choose some integer k from 1 to 10 and add it to a or subtract it from a. In other words, you choose an integer k ∈ [1; 10] and perform a := a + k or a := a - k. You may use different values of k in different moves.
Your task is to find the minimum number of moves required to obtain b from a.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.
The only line of the test case contains two integers a and b (1 ≤ a, b ≤ 10^9).
Output
For each test case, print the answer: the minimum number of moves required to obtain b from a.
Example
Input
6
5 5
13 42
18 4
1337 420
123456789 1000000000
100500 9000
Output
0
3
2
92
87654322
9150
Note
In the first test case of the example, you don't need to do anything.
In the second test case of the example, the following sequence of moves can be applied: 13 → 23 → 32 → 42 (add 10, add 9, add 10).
In the third test case of the example, the following sequence of moves can be applied: 18 → 10 → 4 (subtract 8, subtract 6).
Submitted Solution:
```
t = int(input())
for i in range(t):
a, b = map(int, input().split())
if a == b:
print(0)
else:
diff = max(a,b) - min(a,b)
print((diff//10)+1)
``` | instruction | 0 | 78,477 | 5 | 156,954 |
No | output | 1 | 78,477 | 5 | 156,955 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers a and b.
In one move, you can choose some integer k from 1 to 10 and add it to a or subtract it from a. In other words, you choose an integer k ∈ [1; 10] and perform a := a + k or a := a - k. You may use different values of k in different moves.
Your task is to find the minimum number of moves required to obtain b from a.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.
The only line of the test case contains two integers a and b (1 ≤ a, b ≤ 10^9).
Output
For each test case, print the answer: the minimum number of moves required to obtain b from a.
Example
Input
6
5 5
13 42
18 4
1337 420
123456789 1000000000
100500 9000
Output
0
3
2
92
87654322
9150
Note
In the first test case of the example, you don't need to do anything.
In the second test case of the example, the following sequence of moves can be applied: 13 → 23 → 32 → 42 (add 10, add 9, add 10).
In the third test case of the example, the following sequence of moves can be applied: 18 → 10 → 4 (subtract 8, subtract 6).
Submitted Solution:
```
for _ in range(int(input())) :
a,b=map(int,input().split())
if a==b :
print(0)
else :
if a>b :
diff=a-b
else :
diff=b-a
cnt=0
if diff>10 :
cnt+=diff//10
cnt+=diff%10
print(cnt)
``` | instruction | 0 | 78,478 | 5 | 156,956 |
No | output | 1 | 78,478 | 5 | 156,957 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers a and b.
In one move, you can choose some integer k from 1 to 10 and add it to a or subtract it from a. In other words, you choose an integer k ∈ [1; 10] and perform a := a + k or a := a - k. You may use different values of k in different moves.
Your task is to find the minimum number of moves required to obtain b from a.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 2 ⋅ 10^4) — the number of test cases. Then t test cases follow.
The only line of the test case contains two integers a and b (1 ≤ a, b ≤ 10^9).
Output
For each test case, print the answer: the minimum number of moves required to obtain b from a.
Example
Input
6
5 5
13 42
18 4
1337 420
123456789 1000000000
100500 9000
Output
0
3
2
92
87654322
9150
Note
In the first test case of the example, you don't need to do anything.
In the second test case of the example, the following sequence of moves can be applied: 13 → 23 → 32 → 42 (add 10, add 9, add 10).
In the third test case of the example, the following sequence of moves can be applied: 18 → 10 → 4 (subtract 8, subtract 6).
Submitted Solution:
```
t = int(input())
for _ in range(6):
a,b = list(map(int,input().split(' ')))
c = abs(b-a)//10
if (b-a)%10 == 0:
print(c)
else:
print(c+1)
``` | instruction | 0 | 78,479 | 5 | 156,958 |
No | output | 1 | 78,479 | 5 | 156,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,520 | 5 | 157,040 |
Tags: bitmasks
Correct Solution:
```
import math
def solve(n):
p = int(math.log(n, 2));
return int(pow(2, p))-1
for _ in range(int(input())):
n=int(input())
print(solve(n),end="\n")
``` | output | 1 | 78,520 | 5 | 157,041 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,521 | 5 | 157,042 |
Tags: bitmasks
Correct Solution:
```
# aadiupadhyay
import os.path
from math import gcd, floor, ceil
from collections import *
import sys
mod = 1000000007
INF = float('inf')
def st(): return list(sys.stdin.readline().strip())
def li(): return list(map(int, sys.stdin.readline().split()))
def mp(): return map(int, sys.stdin.readline().split())
def inp(): return int(sys.stdin.readline())
def pr(n): return sys.stdout.write(str(n)+"\n")
def prl(n): return sys.stdout.write(str(n)+" ")
if os.path.exists('input.txt'):
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
def solve():
n = inp()
cur = 1
while cur*2 <= n:
cur *= 2
print(cur-1)
for _ in range(inp()):
solve()
``` | output | 1 | 78,521 | 5 | 157,043 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,522 | 5 | 157,044 |
Tags: bitmasks
Correct Solution:
```
tc = int(input())
while tc > 0:
n = int(input())
i = 0
while 2**i <= n:
i += 1
k = 2**(i-1) - 1
print(k)
tc -= 1
``` | output | 1 | 78,522 | 5 | 157,045 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,523 | 5 | 157,046 |
Tags: bitmasks
Correct Solution:
```
t=int(input())
while(t):
n=int(input())
c=0
while(n>0):
c+=1
n//=2
print((2**(c-1))-1)
t-=1
``` | output | 1 | 78,523 | 5 | 157,047 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,524 | 5 | 157,048 |
Tags: bitmasks
Correct Solution:
```
t=int(input())
for i in range(t):
bina=[]
n=int(input())
p=n
som=False
while n:
bina.append(n%2)
n//=2
print(2**(len(bina)-1)-1)
``` | output | 1 | 78,524 | 5 | 157,049 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,525 | 5 | 157,050 |
Tags: bitmasks
Correct Solution:
```
#!/usr/bin/env python
# coding: utf-8
# In[8]:
# T = int(input())
# result = []
# for t in range(T):
# n = int(input())
# flag = 1
# product = n
# temp = n-1
# if n == 0:
# result.append(0)
# else:
# while flag:
# product &= temp
# if product==0:
# result.append(temp)
# flag = 0
# else:
# temp-=1
# for t in range(T):
# print(result[t])
# In[11]:
import math
T = int(input())
result = []
for t in range(T):
n = int(input())
if n == 0:
result.append(0)
else:
bits = math.ceil(math.log2(n))
powb = pow(2,bits)
if powb == n:
result.append(n-1)
else:
k = pow(2 , bits-1)-1
result.append(k)
for t in range(T):
print(result[t])
# In[ ]:
``` | output | 1 | 78,525 | 5 | 157,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,526 | 5 | 157,052 |
Tags: bitmasks
Correct Solution:
```
import sys,os.path
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
m1=1000000007
m2=1000000021
from collections import defaultdict
# from itertools import combinations_with_replacement,permutations
from math import gcd, log2
for _ in range(int(input())):
n=int(input())
# a=list(map(int,input().split()))
a=int(log2(n))
# print(1<<a)
# print(a)
if 1<<(a)==n:
print(n-1)
else:
print((1<<a)-1)
``` | output | 1 | 78,526 | 5 | 157,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer. | instruction | 0 | 78,527 | 5 | 157,054 |
Tags: bitmasks
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
a=n
if(n==1):
print(0)
else:
z=n
b=1
n= n>>1
while(n>1):
n= n>>1
b=b<<1
b=b|1
print(b)
``` | output | 1 | 78,527 | 5 | 157,055 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
def getResult(n):
res = 0
while n>1:
n//=2
res +=1
return 2**res-1
t = int(input())
for _ in range(t):
n = int(input())
print(getResult(n))
``` | instruction | 0 | 78,528 | 5 | 157,056 |
Yes | output | 1 | 78,528 | 5 | 157,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
for _ in range(int(input())):
n = int(input())
l = len(bin(n)) - 2
print(2**(l-1) -1)
``` | instruction | 0 | 78,529 | 5 | 157,058 |
Yes | output | 1 | 78,529 | 5 | 157,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
import math
t=int(input())
for tt in range (t):
n=int(input())
nl=int(math.log(n)/math.log(2))
print(2**nl-1)
``` | instruction | 0 | 78,530 | 5 | 157,060 |
Yes | output | 1 | 78,530 | 5 | 157,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
t=int(input())
while(t!=0):
n=int(input())
n1=n
c=0
while(n1!=0):
c=c+1
n1=n1//2
print(2**(c-1)-1)
t=t-1
``` | instruction | 0 | 78,531 | 5 | 157,062 |
Yes | output | 1 | 78,531 | 5 | 157,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
t=int(input())
for _ in range (t):
n=int(input())
i=1
p=n
while(1):
p=p&(n-i)
if(p==0):
print((n-i))
i+=1
break
``` | instruction | 0 | 78,532 | 5 | 157,064 |
No | output | 1 | 78,532 | 5 | 157,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
from itertools import combinations, product
t = int(input())
for _ in range(t):
n = int(input())
if n <= 2:
print(n - 1)
else:
x = 1
while x < n:
x *= 2
x //= 2
print(x - 1)
``` | instruction | 0 | 78,533 | 5 | 157,066 |
No | output | 1 | 78,533 | 5 | 157,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
n = int(input())
while (n > 0):
c = int(input())
d = bin(c)
dd = str(d)
ans = 0
for i in range(len(dd)):
if dd[i] == '1':
ans += 1
print (c - ans)
n = n - 1
``` | instruction | 0 | 78,534 | 5 | 157,068 |
No | output | 1 | 78,534 | 5 | 157,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given an integer n, find the maximum value of integer k such that the following condition holds:
n & (n-1) & (n-2) & (n-3) & ... (k) = 0 where & denotes the [bitwise AND operation.](https://en.wikipedia.org/wiki/Bitwise_operation#AND)
Input
The first line contains a single integer t (1 ≤ t ≤ 3 ⋅ 10^4). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^9).
Output
For each test case, output a single integer — the required integer k.
Example
Input
3
2
5
17
Output
1
3
15
Note
In the first testcase, the maximum value for which the continuous & operation gives 0 value, is 1.
In the second testcase, the maximum value for which the continuous & operation gives 0 value, is 3. No value greater then 3, say for example 4, will give the & sum 0.
* 5 \& 4 ≠ 0,
* 5 \& 4 \& 3 = 0.
Hence, 3 is the answer.
Submitted Solution:
```
for _ in range(int(input())):
n = int(input())
x=1
while x<n:
x*=2
print(x//2 - 1)
``` | instruction | 0 | 78,535 | 5 | 157,070 |
No | output | 1 | 78,535 | 5 | 157,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for integer n, n > k.
Note that we determine the k-bonacci numbers, F(k, n), only for integer values of n and k.
You've got a number s, represent it as a sum of several (at least two) distinct k-bonacci numbers.
Input
The first line contains two integers s and k (1 ≤ s, k ≤ 109; k > 1).
Output
In the first line print an integer m (m ≥ 2) that shows how many numbers are in the found representation. In the second line print m distinct integers a1, a2, ..., am. Each printed integer should be a k-bonacci number. The sum of printed integers must equal s.
It is guaranteed that the answer exists. If there are several possible answers, print any of them.
Examples
Input
5 2
Output
3
0 2 3
Input
21 5
Output
3
4 1 16
Submitted Solution:
```
s,k=list(map(int,input().split(' ')))
a=[0,1,1]
while a[-1]<s:
if len(a)<k:
a.append(sum(a))
else:
t=0
for i in range(k):
t+=a[-i-1]
a.append(t)
if s==a[-1]:
print(2)
print(0,a[-1])
else:
use=[]
for i in range(len(a)):
if s>=a[-i-1]:
s-=a[-i-1]
use.append(a[-i-1])
print(len(use))
for i in use:
print(i,end=' ')
``` | instruction | 0 | 78,560 | 5 | 157,120 |
Yes | output | 1 | 78,560 | 5 | 157,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for integer n, n > k.
Note that we determine the k-bonacci numbers, F(k, n), only for integer values of n and k.
You've got a number s, represent it as a sum of several (at least two) distinct k-bonacci numbers.
Input
The first line contains two integers s and k (1 ≤ s, k ≤ 109; k > 1).
Output
In the first line print an integer m (m ≥ 2) that shows how many numbers are in the found representation. In the second line print m distinct integers a1, a2, ..., am. Each printed integer should be a k-bonacci number. The sum of printed integers must equal s.
It is guaranteed that the answer exists. If there are several possible answers, print any of them.
Examples
Input
5 2
Output
3
0 2 3
Input
21 5
Output
3
4 1 16
Submitted Solution:
```
s,k=list(map(int,input().split()))
a=[1]
i=0
while s>a[-1]:
if i==0:
a.append(1)
else:
a.append(2*a[-1]-int(a[-k-1] if i>=k else 0))
i+=1
b=[]
s0=s
while s>0:
l,r=-1,i+1
while r-l>1:
m=(l+r)//2
if a[m]>=s:
r=m
else:
l=m
r=min(i,r)
while a[r]>s:
r-=1
s-=a[r]
b.append(a[r])
if len(b)==1:
b.append(0)
print(len(b))
print(*b)
``` | instruction | 0 | 78,563 | 5 | 157,126 |
Yes | output | 1 | 78,563 | 5 | 157,127 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,669 | 5 | 157,338 |
Tags: brute force, implementation
Correct Solution:
```
import math
def ncr(n, r):
return math.factorial(n) / math.factorial(n - r) / math.factorial(r)
N = int(input())
ans = ncr(2 * (N - 1), N - 1)
print(int(ans))
``` | output | 1 | 78,669 | 5 | 157,339 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,670 | 5 | 157,340 |
Tags: brute force, implementation
Correct Solution:
```
def elem(row, col):
if row == 1 or col == 1:
return 1
return elem(row - 1, col) + elem(row, col - 1)
n = int(input())
k = elem(n,n)
print(k)
``` | output | 1 | 78,670 | 5 | 157,341 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,671 | 5 | 157,342 |
Tags: brute force, implementation
Correct Solution:
```
n=int(input())
a=2*n-2
s=1
l=1
for i in range (1,a//2+1):
s=s*i
for i in range (a//2+1,a+1):
l=l*i
print(l//s)
``` | output | 1 | 78,671 | 5 | 157,343 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,672 | 5 | 157,344 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
list = [1]*n
for k in range(n-1):
for i in range(n):
for j in range(n-i-1):
list[-i-1] += list[j]
print(list[-1])
``` | output | 1 | 78,672 | 5 | 157,345 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,673 | 5 | 157,346 |
Tags: brute force, implementation
Correct Solution:
```
x=int(input())
if x==1:
print(1)
elif x==2:
print(2)
elif x==3:
print(6)
elif x==4:
print(20)
elif x==5:
print(70)
elif x==6:
print(252)
elif x==7:
print(924)
elif x==8:
print(3432)
elif x==9:
print(12870)
else:
print(48620)
``` | output | 1 | 78,673 | 5 | 157,347 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,674 | 5 | 157,348 |
Tags: brute force, implementation
Correct Solution:
```
z=[]
x=int(input())
for p in range(x):
z.append(1)
for i in range(x-1):
v = [1]
for m in range(x-1):
v.append(int(z[m+1])+int(v[m]))
m=0;z=v
print(z[x-1])
``` | output | 1 | 78,674 | 5 | 157,349 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,675 | 5 | 157,350 |
Tags: brute force, implementation
Correct Solution:
```
n=int(input())
A=[int(1)]*n
while n>1:
n-=1
B=[int(1)]*len(A)
for i in range(len(A)):
B[i]=sum(A[:i+1])
A=B
print(A[-1])
``` | output | 1 | 78,675 | 5 | 157,351 |
Provide tags and a correct Python 3 solution for this coding contest problem.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}. | instruction | 0 | 78,676 | 5 | 157,352 |
Tags: brute force, implementation
Correct Solution:
```
n=int(input())
if n==1:
print('1')
elif n==2:
print('2')
else:
a=[]
tmp=[]
line=[]
for i in range(n):
a.append(1)
tmp.append(i+1)
for i in range(2,n):
line.append(1)
for j in range(1,n):
line.append(line[j-1]+tmp[j])
tmp=line
line=[]
print(tmp[n-1])
``` | output | 1 | 78,676 | 5 | 157,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
n = int(input())
l = [1]*n
for j in range (n-1):
for i in range (1,n):
l[i]+=l[i-1]
print(max(l))
``` | instruction | 0 | 78,677 | 5 | 157,354 |
Yes | output | 1 | 78,677 | 5 | 157,355 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
n = int(input())
table = [[1 for x in range(n)] for y in range(n)]
def coord(x, y):
return table[x][y]
def add(x, y):
table[x][y] = coord(x - 1, y) + coord(x, y - 1)
for x in range(1, n):
for y in range(1, n):
add(x, y)
print(table[n - 1][n - 1])
``` | instruction | 0 | 78,678 | 5 | 157,356 |
Yes | output | 1 | 78,678 | 5 | 157,357 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
n=int(input())
a=[[0 for col in range(11)]for row in range(11)]
for i in range (1,n+1):
a[1][i]=1
a[i][1]=1
for i in range(2,n+1):
for j in range(2,n+1):
a[i][j]=a[i-1][j]+a[i][j-1]
print(a[n][n])
``` | instruction | 0 | 78,679 | 5 | 157,358 |
Yes | output | 1 | 78,679 | 5 | 157,359 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
#Maximum _in_Table
n=int(input())
a=[[0 for i in range(n)] for j in range(n)]
for i in range(n):
for j in range(n):
a[i][0]=1
a[0][i]=1
for i in range(1,n):
for j in range(1,n):
a[i][j]=a[i-1][j]+a[i][j-1]
print(a[n-1][n-1])
``` | instruction | 0 | 78,680 | 5 | 157,360 |
Yes | output | 1 | 78,680 | 5 | 157,361 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
import os, sys
from io import BytesIO, IOBase
from collections import Counter
# Fast IO Region
BUFSIZE = 8192
class FastIO (IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno ()
self.buffer = BytesIO ()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read (self._fd, max (os.fstat (self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell ()
self.buffer.seek (0, 2), self.buffer.write (b), self.buffer.seek (ptr)
self.newlines = 0
return self.buffer.read ()
def readline(self):
while self.newlines == 0:
b = os.read (self._fd, max (os.fstat (self._fd).st_size, BUFSIZE))
self.newlines = b.count (b"\n") + (not b)
ptr = self.buffer.tell ()
self.buffer.seek (0, 2), self.buffer.write (b), self.buffer.seek (ptr)
self.newlines -= 1
return self.buffer.readline ()
def flush(self):
if self.writable:
os.write (self._fd, self.buffer.getvalue ())
self.buffer.truncate (0), self.buffer.seek (0)
class IOWrapper (IOBase):
def __init__(self, file):
self.buffer = FastIO (file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write (s.encode ("ascii"))
self.read = lambda: self.buffer.read ().decode ("ascii")
self.readline = lambda: self.buffer.readline ().decode ("ascii")
sys.stdin, sys.stdout = IOWrapper (sys.stdin), IOWrapper (sys.stdout)
input = lambda: sys.stdin.readline ().rstrip ("\r\n")
for _ in range (1):
x=int(input())
l=x
z=[[1,1,1,1,1],[1,2,3,4,5]]
if x>2:
k=2
while x>2:
f=[1]
for t in range(1,5):
f.append(z[k-1][t]+f[t-1])
k+=1
z.append(f)
x=x-1
g=z[l-1]
print(max(g))
``` | instruction | 0 | 78,681 | 5 | 157,362 |
No | output | 1 | 78,681 | 5 | 157,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
from math import factorial
n=int(input())
print(factorial(2*(n-1)) /factorial((n-1))**2)
``` | instruction | 0 | 78,682 | 5 | 157,364 |
No | output | 1 | 78,682 | 5 | 157,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
print([1,2,6,23,76,251,923,3430,12870,48620][int(input())-1])
``` | instruction | 0 | 78,683 | 5 | 157,366 |
No | output | 1 | 78,683 | 5 | 157,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to the left of it. In other words, the remaining elements are defined by the formula ai, j = ai - 1, j + ai, j - 1.
These conditions define all the values in the table.
You are given a number n. You need to determine the maximum value in the n × n table defined by the rules above.
Input
The only line of input contains a positive integer n (1 ≤ n ≤ 10) — the number of rows and columns of the table.
Output
Print a single line containing a positive integer m — the maximum value in the table.
Examples
Input
1
Output
1
Input
5
Output
70
Note
In the second test the rows of the table look as follows:
{1, 1, 1, 1, 1}, {1, 2, 3, 4, 5}, {1, 3, 6, 10, 15}, {1, 4, 10, 20, 35}, {1, 5, 15, 35, 70}.
Submitted Solution:
```
n=int(input())
s=1
i=1
while i<n:
s*=(n+i-1)/i
i+=1
print(int(s))
``` | instruction | 0 | 78,684 | 5 | 157,368 |
No | output | 1 | 78,684 | 5 | 157,369 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,861 | 5 | 157,722 |
"Correct Solution:
```
import sys
from collections import Counter
input = sys.stdin.readline
def main():
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
judge_a = Counter(a)
judge_b = Counter(b)
judge = judge_a + judge_b
flag = True
for v in judge.values():
if v > n:
flag = False
if flag:
i, j = 0, 0
cycle = 0
while i < n and j < n:
ii, jj = i, j
if a[i] < b[j]:
i += 1
continue
if a[i] > b[j]:
j += 1
continue
if a[i] == b[j]:
while i < n-1 and a[i] == a[i+1]:
i += 1
while j < n-1 and b[j] == b[j+1]:
j += 1
cycle = max(cycle, i-jj+1)
i += 1
j += 1
ans = [0]*n
for i in range(n):
ans[(i+cycle)%n] = b[i]
for i in range(n):
if a[i] == ans[i]:
print("No")
sys.exit()
print("Yes")
print(*ans)
else:
print("No")
if __name__ == "__main__":
main()
``` | output | 1 | 78,861 | 5 | 157,723 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
from collections import Counter
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
AC = Counter(A)
BC = Counter(B)
if N < max((AC + BC).values()):
print('No')
exit()
curA = 0
curB = 0
while curA < N:
a = A[curA]
if a == B[curA]:
while a == B[curB] or A[curB] == B[curA]:
curB += 1
curB %= N
B[curA], B[curB] = B[curB], B[curA]
curA += 1
print('Yes')
print(*B)
``` | instruction | 0 | 78,868 | 5 | 157,736 |
Yes | output | 1 | 78,868 | 5 | 157,737 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
N = int(input())
*A, = map(int, input().split())
*B, = map(int, input().split())
ac = [0]*(N+1)
bc = [0]*(N+1)
ok = True
for i in range(N):
ac[A[i]] += 1
bc[B[i]] += 1
d = 0
for i in range(1, N+1):
if (ac[i]+bc[i]) > N:
ok = False
break
ac[i] += ac[i-1]
bc[i] += bc[i-1]
d = max(d, ac[i]-bc[i-1])
if ok:
print("Yes")
print(*[B[(i-d) % N] for i in range(N)])
else:
print("No")
``` | instruction | 0 | 78,869 | 5 | 157,738 |
Yes | output | 1 | 78,869 | 5 | 157,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
import sys
import collections
sys.setrecursionlimit(10 ** 8)
input = sys.stdin.readline
def main():
N = int(input())
A = [int(x) for x in input().split()]
B = [int(x) for x in input().split()]
ac = collections.Counter(A)
bc = collections.Counter(B)
for i in range(1, N + 1):
if ac[i] + bc[i] > N:
print("No")
return
ma = 0
cnta = 0
cntb = 0
for i in range(1, N + 1):
cnta += ac[i]
cntb += bc[i - 1]
ma = max(ma, cnta - cntb)
print("Yes")
ans = []
for i in range(N):
ans.append(B[(i + N - ma) % N])
print(*ans)
if __name__ == '__main__':
main()
``` | instruction | 0 | 78,870 | 5 | 157,740 |
Yes | output | 1 | 78,870 | 5 | 157,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
N = int(input())
A = [int(a) for a in input().split()]
B = [int(a) for a in input().split()]
C = [0]*N
D = [0]*N
c = d = 0
for i in range(N):
a = A[i]
b = B[i]
if C[a-1]==0:
for j in range(c,a): C[j]=C[c]
c=a-1
C[c]=C[c-1]+1
else: C[a-1]+=1
if D[b-1]==0:
for j in range(d,b): D[j]=D[d]
d=b-1
D[d]=D[d-1]+1
else: D[b-1]+=1
for j in range(c,N): C[j]=C[c]
for j in range(d,N): D[j]=D[d]
E = [0]*N
for i in range(N):
if i==0: E[i] = C[i] + D[i]
else:
E[i] = C[i]-C[i-1] + D[i]-D[i-1]
#print(C,D,E)
if max(E)>N: print("No")
else:
for i in range(N):
if i==0: x=C[i]
if x < C[i]-D[i-1]: x = C[i]-D[i-1]
B_ = [0]*N
#print(x)
for i in range(N):
B_[(i+x)%N] = B[i]
print("Yes")
print(*B_,sep=' ')
``` | instruction | 0 | 78,871 | 5 | 157,742 |
Yes | output | 1 | 78,871 | 5 | 157,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
n = int(input())
a = [0] * n
b = [0] * n
fa = [0] * n
fb = [0] * n
cfa = [0] * n
cfb = [0] * n
a = [int(j) for j in input().split(' ')]
b = [int(j) for j in input().split(' ')]
for i in range(n):
a[i] -= 1
b[i] -= 1
fa[a[i]] += 1
fb[b[i]] += 1
cfa[0] = fa[0]
cfb[0] = fb[0]
for i in range(n-1):
cfa[i+1] = cfa[i] + fa[i+1]
cfb[i+1] = cfb[i] + fb[i+1]
flag = False
for i in range(n):
if fa[i] + fb[i] > n:
flag = True
break
if flag:
print("No")
else:
print("Yes")
if 2*max(max(fa), max(fb)) <= n:
it = n//2
else:
if 2*max(fa) > n:
num = max([(fa[i], i) for i in range(n)])[1]
else:
num = max([(fb[i], i) for i in range(n)])[1]
print(num)
afi = cfa[num-1]
ase = cfa[num]
bfi = cfb[num-1]
bse = cfb[num]
if num == 0:
afi, bfi = 0, 0
if 2*max(fa) > n:
it = ase - bfi
else:
it = bse - afi
print(it)
newb = [str(b[(i-it)%n]+1) for i in range(n)]
print(" ".join(newb))
``` | instruction | 0 | 78,872 | 5 | 157,744 |
No | output | 1 | 78,872 | 5 | 157,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
import sys
readline = sys.stdin.readline
N = int(readline())
A = list(map(int,readline().split()))
B = list(map(int,readline().split()))
# 最も登場回数が大きい値と、それがどこから始まるかを特定する
# その数Xが重複して且つ同じ値でなければ必ず達成できる
# AでXが終わったところからBのXを開始するようにすれば良い。
from collections import Counter
Ac = Counter(A)
Bc = Counter(B)
Ac = sorted(Ac.items(), key = lambda x:x[1])
Bc = sorted(Bc.items(), key = lambda x:x[1])
Xa = Ac[-1]
Xb = Bc[-1]
if Xa[0] == Xb[0] and (Xa[1] > N // 2 or Xb[1] > N // 2):
print("No")
exit(0)
ind = 0
found_ind = 0
found = False
for i in range(N):
if not found and A[i] == Xa[0]:
found = True
found_ind = i
if found and A[i] != Xa[0]:
ind = i
break
if Xa[0] == Xb[0]:
# AでXが終わるのはindから。
# ここからBのindが始まるようスライドする
ans = [None] * N
for i in range(N):
ans[(i + ind) % N] = B[i]
print(*ans)
else:
# Xbでいちばん多い項目が、indから始まるようスライドする
bind = 0
for i in range(N):
if B[i] == Xb[0]:
bind = i
break
gap = found_ind - bind
ans = [None] * N
for i in range(N):
ans[(i + gap) % N] = B[i]
print(*ans)
``` | instruction | 0 | 78,873 | 5 | 157,746 |
No | output | 1 | 78,873 | 5 | 157,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
# input()
# int(input())
# map(int, input().split())
# list(map(int, input().split()))
# list(map(int, list(input()))) # スペースがない数字リストを読み込み
import math
import fractions
import sys
import bisect
import heapq # 優先度付きキュー(最小値取り出し)
import collections
from collections import Counter
from collections import deque
import pprint
import itertools
sr = lambda: input()
ir = lambda: int(sr())
lr = lambda: list(map(int, sr().split()))
"""nを素因数分解"""
"""2以上の整数n => [[素因数, 指数], ...]の2次元リスト"""
def factorization(n):
arr = []
temp = n
if n == 1:
return arr
for i in range(2, int(-(-n ** 0.5 // 1)) + 1):
if temp % i == 0:
cnt = 0
while temp % i == 0:
cnt += 1
temp //= i
arr.append([i, cnt])
if temp != 1:
arr.append([temp, 1])
if arr == []:
arr.append([n, 1])
return arr
# a^n
def power(a, n, mod):
x = 1
while n:
if n & 1:
x *= a % mod
n >>= 1
a *= a % mod
return x % mod
# n*(n-1)*...*(l+1)*l
def kaijo(n, l, mod):
if n == 0:
return 1
a = n
tmp = n - 1
while (tmp >= l):
a = a * tmp % mod
tmp -= 1
return a
# Union Find
class UnionFind():
def __init__(self, n):
self.n = n
self.parents = [-1] * n
def find(self, x):
if self.parents[x] < 0:
return x
else:
self.parents[x] = self.find(self.parents[x])
return self.parents[x]
def union(self, x, y):
x = self.find(x)
y = self.find(y)
if x == y:
return
if self.parents[x] > self.parents[y]:
x, y = y, x
self.parents[x] += self.parents[y]
self.parents[y] = x
def size(self, x):
return -self.parents[self.find(x)]
def same(self, x, y):
return self.find(x) == self.find(y)
def members(self, x):
root = self.find(x)
return [i for i in range(self.n) if self.find(i) == root]
def roots(self):
return [i for i, x in enumerate(self.parents) if x < 0]
def group_count(self):
return len(self.roots())
def all_group_members(self):
return {r: self.members(r) for r in self.roots()}
def __str__(self):
return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())
# 約数生成
def make_divisors(n):
divisors = []
for i in range(1, int(n**0.5)+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n//i)
divisors.sort()
return divisors
inf = 10 ** 18
mod = 10 ** 9 + 7
n = ir()
a = lr()
b = lr()
b.reverse()
ans = [x for x in b]
s = 0
for i in range(n):
if a[i] == b[i]:
if s == i:
print('No')
sys.exit()
else:
flag = False
for t in range(s,min(n,i+10)):
if b[t] != a[i] and a[t] != b[i]:
ans[i] = b[t]
ans[t] = b[i]
flag = True
break
else:
print('No')
sys.exit()
print('Yes')
print(*ans, sep=' ')
``` | instruction | 0 | 78,874 | 5 | 157,748 |
No | output | 1 | 78,874 | 5 | 157,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2
Submitted Solution:
```
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
cnta = [0]*(n+1)
cntb = [0]*(n+1)
ta = 0
tb = 0
s = [0]*(n+1)
for i in range(n):
cnta[a[i]] += 1
cntb[b[i]] += 1
s[a[i]] += 1
s[b[i]] += 1
if max(s) > n:
print("No")
exit()
print("Yes")
m = 0
for i in range(1,n+1):
cnta[i] += cnta[i-1]
cntb[i] += cntb[i-1]
for i in range(1,n+1):
m = max(m,cnta[i]-cntb[i-1])
# print(m)
# print(cnta)
# print(cntb)
print(b[-m:]+b[0:-m])
``` | instruction | 0 | 78,875 | 5 | 157,750 |
No | output | 1 | 78,875 | 5 | 157,751 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, subtraction, multiplication and division.
* Precedence of the operators is based on usual laws. That is one should perform all multiplication and division first, then addition and subtraction. When two operators have the same precedence, they are applied from left to right.
* You may assume that there is no division by zero.
* All calculation is performed as integers, and after the decimal point should be truncated
* Length of the expression will not exceed 100.
* -1 × 109 ≤ intermediate results of computation ≤ 109
Input
The input is a sequence of datasets. The first line contains an integer n which represents the number of datasets. There will be n lines where each line contains an expression.
Output
For each datasets, prints the result of calculation.
Example
Input
2
4-2*3=
4*(8+4+3)=
Output
-2
60 | instruction | 0 | 79,025 | 5 | 158,050 |
"Correct Solution:
```
import sys
#from me.io import dup_file_stdin
def prec(op):
if op in "+-":return 1
if op in "*/":return 2
raise NotImplementedError()
def postFix(expr):
stack = []
operators = []
num = 0
isdigit = False
for ch in expr:
if ch.isdigit():
isdigit = True
num*=10
num+=int(ch)
continue
else :
if isdigit:
stack.append(num)
num = 0
isdigit = False
if ch == ')':
while len(operators) > 0:
op = operators.pop()
if op == '(':
break
else:
stack.append(op)
else:
raise ValueError
elif ch == '(':
operators.append(ch)
else:
while len(operators) > 0 and operators[-1]!='(' and prec(operators[-1]) >= prec(ch):
stack.append(operators.pop())
operators.append(ch)
if isdigit:
stack.append(num)
for op in operators[::-1]:
if op not in "()":
stack.append(op)
return stack
def evaluate(stack):
op = stack.pop()
if type(op) is int:
return op;
else:
b = evaluate(stack);
a = evaluate(stack);
return int(eval(str(a)+op+str(b)))
#@dup_file_stdin
def solve():
for _ in range(int(sys.stdin.readline())):
expr = sys.stdin.readline()[:-1].strip("=")
print(evaluate(postFix(expr)))
solve()
``` | output | 1 | 79,025 | 5 | 158,051 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, subtraction, multiplication and division.
* Precedence of the operators is based on usual laws. That is one should perform all multiplication and division first, then addition and subtraction. When two operators have the same precedence, they are applied from left to right.
* You may assume that there is no division by zero.
* All calculation is performed as integers, and after the decimal point should be truncated
* Length of the expression will not exceed 100.
* -1 × 109 ≤ intermediate results of computation ≤ 109
Input
The input is a sequence of datasets. The first line contains an integer n which represents the number of datasets. There will be n lines where each line contains an expression.
Output
For each datasets, prints the result of calculation.
Example
Input
2
4-2*3=
4*(8+4+3)=
Output
-2
60 | instruction | 0 | 79,028 | 5 | 158,056 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
'''
所要時間は、分位であった。
'''
# ライブラリのインポート
#import re
import sys
input = sys.stdin.readline
#import heapq
#import bisect
from collections import deque
#import math
def main():
n = int(input())
for _ in range(n):
IN = input().strip()
exp1 = calcmold(IN)
exp2 = calc1(exp1)
exp3 = calcmult(exp2)
print(calcplus(exp3))
def calcmold(exp):
# seikei
tmp = ""
EXP = deque()
oplist = ["+","-","*","/","(",")","="]
for i in range(len(exp)):
if exp[i] not in oplist:
tmp += exp[i]
else:
if tmp == "":
EXP.append(exp[i])
continue
EXP.append(int(tmp))
EXP.append(exp[i])
tmp = ""
return EXP
def calc1(IN):
#calculate()
EXP = deque()
while(IN):
check = IN.popleft()
if check == ")":
TMP = deque()
while(1):
look = EXP.pop()
if look == "(": break
TMP.appendleft(look)
TMP.append("=")
EXP.append(calcplus(calcmult(TMP)))
else: EXP.append(check)
return EXP
def calcmult(exp):
# no()
EXP = deque()
while(exp):
check = exp.popleft()
if check == "*":
arg1 = EXP.pop()
arg2 = exp.popleft()
EXP.append(arg1*arg2)
elif check == "/":
arg1 = EXP.pop()
arg2 = exp.popleft()
EXP.append(int(arg1/arg2))
else: EXP.append(check)
return EXP
def calcplus(exp):
# no()
EXP = deque()
while(exp):
check = exp.popleft()
if check == "+":
arg1 = EXP.pop()
arg2 = exp.popleft()
EXP.append(arg1+arg2)
elif check == "-":
arg1 = EXP.pop()
arg2 = exp.popleft()
EXP.append(arg1-arg2)
elif check == "=":
return EXP.pop()
else: EXP.append(check)
return EXP
if __name__ == '__main__':
main()
``` | output | 1 | 79,028 | 5 | 158,057 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, subtraction, multiplication and division.
* Precedence of the operators is based on usual laws. That is one should perform all multiplication and division first, then addition and subtraction. When two operators have the same precedence, they are applied from left to right.
* You may assume that there is no division by zero.
* All calculation is performed as integers, and after the decimal point should be truncated
* Length of the expression will not exceed 100.
* -1 × 109 ≤ intermediate results of computation ≤ 109
Input
The input is a sequence of datasets. The first line contains an integer n which represents the number of datasets. There will be n lines where each line contains an expression.
Output
For each datasets, prints the result of calculation.
Example
Input
2
4-2*3=
4*(8+4+3)=
Output
-2
60 | instruction | 0 | 79,029 | 5 | 158,058 |
"Correct Solution:
```
class c:
def __init__(self, v):
self.value = v
def __str__(self):
return str(self.value)
def __add__(self, other):
return c(self.value + other.value)
def __sub__(self, other):
return c(self.value - other.value)
def __mul__(self, other):
return c(self.value * other.value)
def __truediv__(self, other):
return c(int(self.value / other.value))
import re
n = int(input())
ans = (str(eval(re.sub(r'(\d+)', r'c(\1)', input()[:-1]))) for i in range(n))
print('\n'.join(ans))
``` | output | 1 | 79,029 | 5 | 158,059 |
Provide a correct Python 3 solution for this coding contest problem.
Your task is to write a program which reads an expression and evaluates it.
* The expression consists of numerical values, operators and parentheses, and the ends with '='.
* The operators includes +, - , *, / where respectively represents, addition, subtraction, multiplication and division.
* Precedence of the operators is based on usual laws. That is one should perform all multiplication and division first, then addition and subtraction. When two operators have the same precedence, they are applied from left to right.
* You may assume that there is no division by zero.
* All calculation is performed as integers, and after the decimal point should be truncated
* Length of the expression will not exceed 100.
* -1 × 109 ≤ intermediate results of computation ≤ 109
Input
The input is a sequence of datasets. The first line contains an integer n which represents the number of datasets. There will be n lines where each line contains an expression.
Output
For each datasets, prints the result of calculation.
Example
Input
2
4-2*3=
4*(8+4+3)=
Output
-2
60 | instruction | 0 | 79,030 | 5 | 158,060 |
"Correct Solution:
```
import re
class c:
def __str__(self):
return str(self.x)
def __init__(self,value):
self.x=value
def __add__(self,value):
return c(self.x+value.x)
def __sub__(self,value):
return c(self.x-value.x)
def __mul__(self,value):
return c(self.x*value.x)
def __truediv__(self,value):
return c(int(self.x/value.x))
n=int(input())
for i in range(n):
s=input()[:-1]
d=re.sub(r'(\d+)',r'c(\1)',s)
#print(d)
print(eval(d))
#s.group(1)
``` | output | 1 | 79,030 | 5 | 158,061 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.