message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N integers written on a blackboard. The i-th integer is A_i.
Takahashi will repeatedly perform the following operation on these numbers:
* Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.
* Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.
Determine whether it is possible to have only one integer on the blackboard.
Constraints
* 2 ≦ N ≦ 10^5
* 1 ≦ A_i ≦ 10^9
* A_i is an integer.
Input
The input is given from Standard Input in the following format:
N
A_1 A_2 … A_N
Output
If it is possible to have only one integer on the blackboard, print `YES`. Otherwise, print `NO`.
Examples
Input
3
1 2 3
Output
YES
Input
5
1 2 3 4 5
Output
NO
Submitted Solution:
```
n = int(input())
a = [int(i) % 2 for i in input().split()]
print("NO") if sum(a) % 2 else print("YES")
``` | instruction | 0 | 81,580 | 5 | 163,160 |
Yes | output | 1 | 81,580 | 5 | 163,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N integers written on a blackboard. The i-th integer is A_i.
Takahashi will repeatedly perform the following operation on these numbers:
* Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.
* Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.
Determine whether it is possible to have only one integer on the blackboard.
Constraints
* 2 ≦ N ≦ 10^5
* 1 ≦ A_i ≦ 10^9
* A_i is an integer.
Input
The input is given from Standard Input in the following format:
N
A_1 A_2 … A_N
Output
If it is possible to have only one integer on the blackboard, print `YES`. Otherwise, print `NO`.
Examples
Input
3
1 2 3
Output
YES
Input
5
1 2 3 4 5
Output
NO
Submitted Solution:
```
n = int(input())
A = list(map(int, input().split()))
print('NO' if len([a for a in A if a & 1]) & 1 else 'YES')
``` | instruction | 0 | 81,581 | 5 | 163,162 |
Yes | output | 1 | 81,581 | 5 | 163,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N integers written on a blackboard. The i-th integer is A_i.
Takahashi will repeatedly perform the following operation on these numbers:
* Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.
* Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.
Determine whether it is possible to have only one integer on the blackboard.
Constraints
* 2 ≦ N ≦ 10^5
* 1 ≦ A_i ≦ 10^9
* A_i is an integer.
Input
The input is given from Standard Input in the following format:
N
A_1 A_2 … A_N
Output
If it is possible to have only one integer on the blackboard, print `YES`. Otherwise, print `NO`.
Examples
Input
3
1 2 3
Output
YES
Input
5
1 2 3 4 5
Output
NO
Submitted Solution:
```
import sys
sys.setrecursionlimit(10**6)
from math import floor,ceil,sqrt,factorial,log
from heapq import heappop, heappush, heappushpop
from collections import Counter,defaultdict,deque
from itertools import accumulate,permutations,combinations,product,combinations_with_replacement
from bisect import bisect_left,bisect_right
from copy import deepcopy
from operator import itemgetter
from fractions import gcd
mod = 10 ** 9 + 7
#整数input
def ii(): return int(sys.stdin.readline().rstrip()) #int(input())
def mii(): return map(int,sys.stdin.readline().rstrip().split())
def limii(): return list(mii()) #list(map(int,input().split()))
def lin(n:int): return [ii() for _ in range(n)]
def llint(n: int): return [limii() for _ in range(n)]
#文字列input
def ss(): return sys.stdin.readline().rstrip() #input()
def mss(): return sys.stdin.readline().rstrip()
def limss(): return list(mss()) #list(input().split())
def lst(n:int): return [ss() for _ in range(n)]
def llstr(n: int): return [limss() for _ in range(n)]
#本当に貪欲法か？ DP法では？？
#本当に貪欲法か？ DP法では？？
#本当に貪欲法か？ DP法では？？
n=ii()
arr=mii()
cnt=0
for i in range(n):
if arr[i]%2==1:
cnt+=1
if cnt%2==1:
print("NO")
else:
print("YES")
``` | instruction | 0 | 81,582 | 5 | 163,164 |
No | output | 1 | 81,582 | 5 | 163,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N integers written on a blackboard. The i-th integer is A_i.
Takahashi will repeatedly perform the following operation on these numbers:
* Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.
* Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.
Determine whether it is possible to have only one integer on the blackboard.
Constraints
* 2 ≦ N ≦ 10^5
* 1 ≦ A_i ≦ 10^9
* A_i is an integer.
Input
The input is given from Standard Input in the following format:
N
A_1 A_2 … A_N
Output
If it is possible to have only one integer on the blackboard, print `YES`. Otherwise, print `NO`.
Examples
Input
3
1 2 3
Output
YES
Input
5
1 2 3 4 5
Output
NO
Submitted Solution:
```
n=int(input())
items=list(map(int,input().split()))
cnt=0
for i in items:
if i%2:
cnt+=1
if cnt%2==0 and (n-cnt/2)%2==0:
print("YES")
else:
print("NO")
``` | instruction | 0 | 81,583 | 5 | 163,166 |
No | output | 1 | 81,583 | 5 | 163,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N integers written on a blackboard. The i-th integer is A_i.
Takahashi will repeatedly perform the following operation on these numbers:
* Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.
* Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.
Determine whether it is possible to have only one integer on the blackboard.
Constraints
* 2 ≦ N ≦ 10^5
* 1 ≦ A_i ≦ 10^9
* A_i is an integer.
Input
The input is given from Standard Input in the following format:
N
A_1 A_2 … A_N
Output
If it is possible to have only one integer on the blackboard, print `YES`. Otherwise, print `NO`.
Examples
Input
3
1 2 3
Output
YES
Input
5
1 2 3 4 5
Output
NO
Submitted Solution:
```
N = input().split()
K = int(N[0])
NN = input().split()
even = [int(n) for n in NN if int(n) % 2 == 0]
odd = [int(n) for n in NN if int(n) % 2 != 0]
if K % 2 == 0:
print("YES")
else:
if len(even) < len(odd):
print("NO")
else:
print("YES")
``` | instruction | 0 | 81,584 | 5 | 163,168 |
No | output | 1 | 81,584 | 5 | 163,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N integers written on a blackboard. The i-th integer is A_i.
Takahashi will repeatedly perform the following operation on these numbers:
* Select a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.
* Then, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.
Determine whether it is possible to have only one integer on the blackboard.
Constraints
* 2 ≦ N ≦ 10^5
* 1 ≦ A_i ≦ 10^9
* A_i is an integer.
Input
The input is given from Standard Input in the following format:
N
A_1 A_2 … A_N
Output
If it is possible to have only one integer on the blackboard, print `YES`. Otherwise, print `NO`.
Examples
Input
3
1 2 3
Output
YES
Input
5
1 2 3 4 5
Output
NO
Submitted Solution:
```
n = int(input())
a = [int(i) for i in input().split()]
ans = 'Yes'
if sum(a)%2 != 0:
ans = 'No'
print(ans)
``` | instruction | 0 | 81,585 | 5 | 163,170 |
No | output | 1 | 81,585 | 5 | 163,171 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101 | instruction | 0 | 81,662 | 5 | 163,324 |
"Correct Solution:
```
n=int(input())
x=input()
d=int(input())
x=list(x)
y=[1]*n
for i in range(n):
if d and x[i]=='0':y[i]=0;x[i]='1';d-=1
i=n-1
while d:
if y[i]:x[i]='0';d-=1
i-=1
print(*x, sep='')
``` | output | 1 | 81,662 | 5 | 163,325 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101 | instruction | 0 | 81,663 | 5 | 163,326 |
"Correct Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import array
def num_string_to_array(num_string):
return array.array("B", map(int, num_string))
def num_array_to_string(num_array):
return "".join(map(str, num_array))
def solve(n, x, d):
answer = x[:]
rest_distance = d
for i in range(n):
if rest_distance <= 0:
return answer
elif answer[i] == 0:
answer[i] = 1
rest_distance -= 1
for j in range(n)[::-1]:
if rest_distance <= 0:
return answer
elif answer[j] == 1 and answer[j] == x[j]:
answer[j] = 0
rest_distance -= 1
return answer
def main():
n = int(input())
x = num_string_to_array(input())
d = int(input())
answer = num_array_to_string(solve(n, x[:], d))
print(answer)
if __name__ == '__main__':
main()
``` | output | 1 | 81,663 | 5 | 163,327 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101 | instruction | 0 | 81,664 | 5 | 163,328 |
"Correct Solution:
```
n = int(input())
bits_raw = input()
bits = [int(bits_raw[i]) for i in range(n)]
m = int(input())
ones = []
zeros = []
for i in range(n):
if(bits[i] == 1):
ones.append(i)
else:
zeros.append(i)
if(len(zeros) > m):
for i in range(m):
bits[zeros[i]] = 1
print(''.join(map(str, bits)))
else:
allone = [1 for i in range(n)]
l = len(ones)
for i in range(m - len(zeros)):
allone[ones[l - i - 1]] = 0
print(''.join(map(str, allone)))
``` | output | 1 | 81,664 | 5 | 163,329 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101 | instruction | 0 | 81,665 | 5 | 163,330 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
N = int(input())
X = input()
D = int(input())
ans = list(X)
done = [False] * N
for i in range(N):
if D == 0:
break
if ans[i] == "0":
ans[i] = "1"
done[i] = True
D -= 1
for i in range(N)[::-1]:
if D == 0:
break
if ans[i] == "1" and not done[i]:
ans[i] = "0"
D -= 1
print("".join(ans))
``` | output | 1 | 81,665 | 5 | 163,331 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101 | instruction | 0 | 81,666 | 5 | 163,332 |
"Correct Solution:
```
n = int(input())
x = input()
d = int(input())
swap = {}
for i in range(n):
if d == 0:break
if x[i] == "0":
swap[i] = True
d -= 1
for i in range(n - 1, -1, -1):
if d == 0:break
if x[i] == "1":
swap[i] = True
d -= 1
print("".join([x[i] if i not in swap else ("0" if x[i] == "1" else "1") for i in range(n)]))
``` | output | 1 | 81,666 | 5 | 163,333 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101
Submitted Solution:
```
n = int(input())
x = list(input())
d = int(input())
s = 0
while d > 0:
if s == n:
break
if x[s] == "0":
x[s] = "1"
d = d - 1
s = s + 1
if d == 0:
print("".join(x))
else:
while d > 0:
x[n-1] = "0"
n = n - 1
d = d - 1
print("".join(x))
``` | instruction | 0 | 81,667 | 5 | 163,334 |
No | output | 1 | 81,667 | 5 | 163,335 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101
Submitted Solution:
```
n,x,d=[input() for _ in range(3)]
d=int(d);y=x=list(x);n=int(n)
for i in range(n):
if d and x[i]=='0':y[i]='1';d-=1
for i in range(n-1,-1,-1):
if d and x[i]=='1':y[i]='0';d-=1
print(*y,sep='')
``` | instruction | 0 | 81,668 | 5 | 163,336 |
No | output | 1 | 81,668 | 5 | 163,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101
Submitted Solution:
```
n=int(input())
x=input()
d=int(input())
x=y=list(x)
for i in range(n):
if d and x[i]=='0':y[i]='1';d-=1
while d:
if x[i]=='1':y[i]='0';d-=1
print(*y, sep='')
``` | instruction | 0 | 81,669 | 5 | 163,338 |
No | output | 1 | 81,669 | 5 | 163,339 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem statement
There is an unsigned $ 2 $ decimal integer $ X $ with $ N $ in digits including Leading-zeros. Output the largest non-negative integer that can be expressed in $ 2 $ base in $ N $ digits where the Hamming distance from $ X $ is $ D $.
The Hamming distance between integers expressed in $ 2 $ is the number of digits with different values in a number of $ 2 $. For example, the Hamming distance between $ 000 $ and $ 110 $ is $ 2 $.
Constraint
$ 1 \ leq N \ leq 1000 $
$ 0 \ leq D \ leq N $
All inputs are non-negative integers
sample
Sample input 1
Five
00001
3
Sample output 1
11101
Sample input 2
7
0110100
Four
Sample output 2
1111111
Sample input 3
18
110001001110100100
6
Sample output 3
111111111111100100
Sample input 4
3
000
0
Sample output 4
000
input
$ N $
$ X $
$ D $
output
Output the integer of the answer on the $ 1 $ line in unsigned $ 2 $ decimal notation.
Example
Input
5
00001
3
Output
11101
Submitted Solution:
```
_,x,d=[input() for _ in range(3)]
d=int(d);y=x=list(x)
for i in range(len(x)):
if d and x[i]=='0':y[i]='1';d-=1
for i in range(len(x)-1,-1,-1):
if d and x[i]=='1':y[i]='0';d-=1
print(*y,sep='')
``` | instruction | 0 | 81,670 | 5 | 163,340 |
No | output | 1 | 81,670 | 5 | 163,341 |
Provide a correct Python 3 solution for this coding contest problem.
Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).
For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.
* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.
In the initial state, all stacks are empty.
Constraints
* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$
Input
The input is given in the following format.
$n \; q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $t$ $x$
or
1 $t$
or
2 $t$
where the first digits 0, 1 and 2 represent push, top and pop operations respectively.
Output
For each top operation, print an integer in a line.
Example
Input
3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0
Output
3
5
2 | instruction | 0 | 81,692 | 5 | 163,384 |
"Correct Solution:
```
n,q=map(int,input().split())
stack=[]
for i in range(n):
stack.append([])
for i in range(q):
query=list(map(int,input().split()))
if query[0]==0:
stack[query[1]].append(query[2])
elif query[0]==1:
if len(stack[query[1]])!=0:
print(stack[query[1]][-1])
else:
if len(stack[query[1]])!=0:
stack[query[1]].pop(-1)
``` | output | 1 | 81,692 | 5 | 163,385 |
Provide a correct Python 3 solution for this coding contest problem.
Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).
For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.
* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.
In the initial state, all stacks are empty.
Constraints
* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$
Input
The input is given in the following format.
$n \; q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $t$ $x$
or
1 $t$
or
2 $t$
where the first digits 0, 1 and 2 represent push, top and pop operations respectively.
Output
For each top operation, print an integer in a line.
Example
Input
3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0
Output
3
5
2 | instruction | 0 | 81,695 | 5 | 163,390 |
"Correct Solution:
```
import sys
n, q = map(int, input().split())
S = [[] for _ in range(n)]
ans =[]
for _ in range(q):
query = list(map(int, sys.stdin.readline().split()))
if query[0] == 0:
S[query[1]].append(query[2])
elif query[0] == 1:
if S[query[1]]:
ans.append(S[query[1]][-1])
# print(S[query[1]][-1])
else:
if S[query[1]]:
S[query[1]].pop()
for i in ans:
print(i)
``` | output | 1 | 81,695 | 5 | 163,391 |
Provide a correct Python 3 solution for this coding contest problem.
Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).
For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.
* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.
In the initial state, all stacks are empty.
Constraints
* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$
Input
The input is given in the following format.
$n \; q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $t$ $x$
or
1 $t$
or
2 $t$
where the first digits 0, 1 and 2 represent push, top and pop operations respectively.
Output
For each top operation, print an integer in a line.
Example
Input
3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0
Output
3
5
2 | instruction | 0 | 81,696 | 5 | 163,392 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Basic Data Structures - Stack
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ITP2_2_A&lang=jp
"""
n, q = map(int, input().split())
stacks = [[] for _ in range(n)]
for _ in range(q):
op, t, x = (input() + ' 1').split()[:3]
if op == '0':
stacks[int(t)].append(x)
elif op == '1':
if stacks[int(t)]:
print(stacks[int(t)][-1])
else:
if stacks[int(t)]:
stacks[int(t)].pop()
``` | output | 1 | 81,696 | 5 | 163,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).
For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.
* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.
In the initial state, all stacks are empty.
Constraints
* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$
Input
The input is given in the following format.
$n \; q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $t$ $x$
or
1 $t$
or
2 $t$
where the first digits 0, 1 and 2 represent push, top and pop operations respectively.
Output
For each top operation, print an integer in a line.
Example
Input
3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0
Output
3
5
2
Submitted Solution:
```
a = [int(i) for i in input().split()]
list = []
for i in range(a[0]): list.append([])
for i in range(a[1]):
cmd = [int(i) for i in input().split()]
if cmd[0] == 0:
list[cmd[1]].append(cmd[2])
elif cmd[0] == 1:
if list[cmd[1]] != []: print(list[cmd[1]][-1])
elif cmd[0] == 2:
if list[cmd[1]] != []: list[cmd[1]].pop()
``` | instruction | 0 | 81,697 | 5 | 163,394 |
Yes | output | 1 | 81,697 | 5 | 163,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).
For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.
* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.
In the initial state, all stacks are empty.
Constraints
* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$
Input
The input is given in the following format.
$n \; q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $t$ $x$
or
1 $t$
or
2 $t$
where the first digits 0, 1 and 2 represent push, top and pop operations respectively.
Output
For each top operation, print an integer in a line.
Example
Input
3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0
Output
3
5
2
Submitted Solution:
```
n, q = list(map(int, input().split(' ')))
stacks = [[] for i in range(n)]
for i in range(q):
op = list(map(int, input().split(' ')))
if op[0] == 0:
stacks[op[1]].append(op[2])
elif op[0] == 1:
if len(stacks[op[1]]) != 0:
print(stacks[op[1]][-1])
elif op[0] == 2:
stacks[op[1]].pop()
``` | instruction | 0 | 81,702 | 5 | 163,404 |
No | output | 1 | 81,702 | 5 | 163,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Stack is a container of elements that are inserted and deleted according to LIFO (Last In First Out).
For $n$ stack $S_i$ ($i = 0, 1, ..., n-1$), perform a sequence of the following operations.
* push($t$, $x$): Insert an integer $x$ to $S_t$.
* top($t$): Report the value which should be deleted next from $S_t$. If $S_t$ is empty, do nothing.
* pop($t$): Delete an element from $S_t$. If $S_t$ is empty, do nothing.
In the initial state, all stacks are empty.
Constraints
* $1 \leq n \leq 1,000$
* $1 \leq q \leq 200,000$
* $-1,000,000,000 \leq x \leq 1,000,000,000$
Input
The input is given in the following format.
$n \; q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $t$ $x$
or
1 $t$
or
2 $t$
where the first digits 0, 1 and 2 represent push, top and pop operations respectively.
Output
For each top operation, print an integer in a line.
Example
Input
3 9
0 0 1
0 0 2
0 0 3
0 2 4
0 2 5
1 0
1 2
2 0
1 0
Output
3
5
2
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Sun Jun 24 18:23:54 2018
ITP22A
@author: maezawa
"""
n, q = list(map(int, input().split()))
a = [[] for _ in range(n)]
for i in range(q):
c = list(map(int, input().split()))
if c[0] == 0:
a[c[1]].append(c[2])
elif c[0] == 1:
if a[c[1]]:
print(a[c[1]][-1])
else:
a[c[1]].pop()
``` | instruction | 0 | 81,703 | 5 | 163,406 |
No | output | 1 | 81,703 | 5 | 163,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
p, n = map(int, input().split())
c = [0] * p
for i in range(n):
x = int(input()) % p
if c[x]:
print(i + 1)
break
c[x] = 1
else:
print(-1)
``` | instruction | 0 | 82,073 | 5 | 164,146 |
Yes | output | 1 | 82,073 | 5 | 164,147 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
p,n=map(int,input().split())
b=[]
for i in range(n):
m=int(input())% p
if m in b:
print(i+1)
quit()
else: b.append(m)
print(-1)
``` | instruction | 0 | 82,074 | 5 | 164,148 |
Yes | output | 1 | 82,074 | 5 | 164,149 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
p,n=map(int, input().split())
l=[]
t=[]
test=0
for i in range(n):
x=int(input())
t.append(x)
for i in range (n):
x=t[i]
x=x%p
if x in l:
test=1
break
else:
l.append(x)
if test:
print(i+1)
else:
print(-1)
``` | instruction | 0 | 82,075 | 5 | 164,150 |
Yes | output | 1 | 82,075 | 5 | 164,151 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
p, n = map(int, input().split())
a = [-1 for i in range(p)]
for i in range(n):
b = int(input())
if a[b % p] != -1:
print(i + 1)
exit(0)
else:
a[b % p] = b
print(-1)
``` | instruction | 0 | 82,076 | 5 | 164,152 |
Yes | output | 1 | 82,076 | 5 | 164,153 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
a = [0 for i in range(301)]
cur = -1
n, p = [int(i) for i in input().split()]
for i in range(n):
b = int(input())
a[b % p] += 1
if a[b % p] == 2:
cur = i + 1
break
print(cur)
``` | instruction | 0 | 82,077 | 5 | 164,154 |
No | output | 1 | 82,077 | 5 | 164,155 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
''' Design by Dinh Viet Anh(JOKER)
//_____________________________________$$$$$__
//___________________________________$$$$$$$$$
//___________________________________$$$___$
//___________________________$$$____$$$$
//_________________________$$$$$$$__$$$$$$$$$$$
//_______________________$$$$$$$$$___$$$$$$$$$$$
//_______________________$$$___$______$$$$$$$$$$
//________________$$$$__$$$$_________________$$$
//_____________$__$$$$__$$$$$$$$$$$_____$____$$$
//__________$$$___$$$$___$$$$$$$$$$$__$$$$__$$$$
//_________$$$$___$$$$$___$$$$$$$$$$__$$$$$$$$$
//____$____$$$_____$$$$__________$$$___$$$$$$$
//__$$$$__$$$$_____$$$$_____$____$$$_____$
//__$$$$__$$$_______$$$$__$$$$$$$$$$
//___$$$$$$$$$______$$$$__$$$$$$$$$
//___$$$$$$$$$$_____$$$$___$$$$$$
//___$$$$$$$$$$$_____$$$
//____$$$$$$$$$$$____$$$$
//____$$$$$__$$$$$___$$$
//____$$$$$___$$$$$$
//____$$$$$____$$$
//_____$$$$
//_____$$$$
//_____$$$$
'''
from math import *
from cmath import *
from itertools import *
from decimal import * # su dung voi so thuc
from fractions import * # su dung voi phan so
from sys import *
from types import CodeType, new_class
#from numpy import *
'''getcontext().prec = x # lay x-1 chu so sau giay phay (thuoc decimal)
Decimal('12.3') la 12.3 nhung Decimal(12.3) la 12.30000000012
Fraction(a) # tra ra phan so bang a (Fraction('1.23') la 123/100 Fraction(1.23) la so khac (thuoc Fraction)
a = complex(c, d) a = c + d(i) (c = a.real, d = a.imag)
a.capitalize() bien ki tu dau cua a(string) thanh chu hoa, a.lower() bien a thanh chu thuong, tuong tu voi a.upper()
a.swapcase() doi nguoc hoa thuong, a.title() bien chu hoa sau dau cach, a.replace('a', 'b', slg)
chr(i) ki tu ma i ord(c) ma ki tu c
a.join['a', 'b', 'c'] = 'a'a'b'a'c, a.strip('a') bo dau va cuoi ki tu 'a'(rstrip, lstrip)
a.split('a', slg = -1) cat theo ki tu 'a' slg lan(rsplit(), lsplit()), a.count('aa', dau = 0, cuoi= len(a)) dem slg
a.startswith('a', dau = 0, cuoi = len(a)) co bat dau bang 'a' ko(tuong tu endswith())
a.index("aa") vi tri dau tien xuat hien (rfind())
input = open(".inp", mode='r') a = input.readline()
out = open(".out", mode='w') a.index(val) '''
#inn = open(".inp", "r")
p, n = map(int, input().split())
a = []
for x in range(n):
b = int(input())
if b % p in a:
print(x)
exit(0)
a.append(b % p)
print(-1)
``` | instruction | 0 | 82,078 | 5 | 164,156 |
No | output | 1 | 82,078 | 5 | 164,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
p,n=map(int,input().split())
D,Z,Y=[],[],[]
for i in range(n):
y=int(input())
D.append(y%p)
for i in range(n):
for j in range(n):
if D[i]==D[j] and i!=j:
Y.append(j+1)
if len(Y)==0:
print(-1)
else:
print(Y[0])
``` | instruction | 0 | 82,079 | 5 | 164,158 |
No | output | 1 | 82,079 | 5 | 164,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a hash table with p buckets, numbered from 0 to p - 1. He wants to insert n numbers, in the order they are given, into the hash table. For the i-th number xi, DZY will put it into the bucket numbered h(xi), where h(x) is the hash function. In this problem we will assume, that h(x) = x mod p. Operation a mod b denotes taking a remainder after division a by b.
However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the i-th insertion, you should output i. If no conflict happens, just output -1.
Input
The first line contains two integers, p and n (2 ≤ p, n ≤ 300). Then n lines follow. The i-th of them contains an integer xi (0 ≤ xi ≤ 109).
Output
Output a single integer — the answer to the problem.
Examples
Input
10 5
0
21
53
41
53
Output
4
Input
5 5
0
1
2
3
4
Output
-1
Submitted Solution:
```
p,n=map(int,input().split())
l=[]
for k in range(n):
i=int(input())
if i%p not in l:
l.append(i%p)
else:
print(k)
break
if len(l)==n:
print("-1")
``` | instruction | 0 | 82,080 | 5 | 164,160 |
No | output | 1 | 82,080 | 5 | 164,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
def gcd(t1, t2):
while t2 > 0:
t1, t2 = t2, t1 % t2
return t1
def nok(t1, t2):
return t1 * t2 // gcd(t1, t2)
n = int(input())
a = list(map(int, input().split()))
b = [0] * len(a)
c = []
d = [0]
cur = 0
while cur < len(a):
b = [0] * len(a)
pos = cur
dis = 1
while b[pos] >= 0:
b[pos] = -dis
pos = a[pos] - 1
dis += 1
c.append(dis + b[pos])
d.append(- b[pos] - 1)
cur += 1
r = 1
for x in c:
r = nok(r, x)
up = max(d)
st = r
while r < up:
r += st
print(r)
``` | instruction | 0 | 82,137 | 5 | 164,274 |
Yes | output | 1 | 82,137 | 5 | 164,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
def gcd(x, y):
if y == 0:
return x
return gcd(y, x % y)
n = int(input())
v = [(int(i) - 1) for i in input().split()]
b = [0] * n
r = 1
for i in range(n):
j, k = 1, v[i]
while j <= 2 * n + 10 and k != i:
k = v[k]
j += 1
if k == i:
r *= j // gcd(r, j)
b[i] = 1
z = 0
for i in range(n):
j, k = 0, i
while not b[k]:
k = v[k]
j += 1
z = max(z, j)
j = z
if j > r:
k = j // r
if j % r != 0:
k += 1
r *= k
print(r)
# Made By Mostafa_Khaled
``` | instruction | 0 | 82,138 | 5 | 164,276 |
Yes | output | 1 | 82,138 | 5 | 164,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
N =int(input())
inp =input().split()
F =[0 for i in range(N)]
for i in range(N): F[i] =int(inp[i])-1
ans_small =[0 for i in range(N+1)]
for i in range(N):
x =i
y =i
for j in range(N):
x =F[x]
y =F[F[y]]
if x == y:
ans_small[j+1] +=1
ans =-1
for i in range(1,N+1):
if ans == -1:
if ans_small[i] == N:
ans =i
#dlhe
pw =[0 for i in range(500)]
for i in range(N):
vis =[False for j in range(N)]
vis[i] =True
x =F[i]
while vis[x] == False:
vis[x] =True
x =F[x]
vis2 =[False for j in range(N)]
vis2[x] =True
x =F[x]
while vis2[x] == False:
vis2[x] =True
x =F[x]
c =0
for j in range(N):
if vis2[j]: c +=1
j =2
while j <= c:
p =0
while c%j == 0:
c //=j
p +=1
pw[j] =max(pw[j],p)
j +=1
if ans == -1:
ans =1
for i in range(1,500):
for j in range(pw[i]):
ans *=i
ans0 =ans
while ans <= N:
ans +=ans0
print(ans)
``` | instruction | 0 | 82,139 | 5 | 164,278 |
Yes | output | 1 | 82,139 | 5 | 164,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
import sys
#sys.stdin = open('input.txt', 'r')
#sys.stdout = open('output.txt', 'w')
def nod(a, b):
while b != 0:
a, b = b, a % b
return a
def nok(a, b):
return a * b // nod(a, b)
n = int(input())
a = [0] + list(map(int, input().split()))
used = [False] * (n + 1)
ans = 1
for i in range(1, n + 1):
t = i
cnt = 0
while(1):
t = a[t]
cnt += 1
if t == i:
ok = True
break
if cnt > n:
ok = False
break
if (ok):
used[i] = True
ans = nok(ans, cnt)
gl_ans = ans
for i in range(1, n + 1):
if not used[i]:
cnt = 0;
t = i
while (1):
if (used[t]):
break
t = a[t]
cnt+=1
while (gl_ans < cnt):
gl_ans += ans
print(gl_ans)
``` | instruction | 0 | 82,140 | 5 | 164,280 |
Yes | output | 1 | 82,140 | 5 | 164,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = a
for i in range (1, 1000000):
ok = True
for j in range (1, n + 1):
if (b[j - 1] != b[b[j - 1] - 1]):
ok = False
break
if (ok):
print(i)
break
for j in range (1, n + 1):
b[j - 1] = a[b[j - 1] - 1]
``` | instruction | 0 | 82,141 | 5 | 164,282 |
No | output | 1 | 82,141 | 5 | 164,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
def gcd(x, y):
if y == 0:
return x
return gcd(y, x % y)
n = int(input())
v = [(int(i) - 1) for i in input().split()]
b = [0] * n
r = 1
for i in range(n):
j, k = 1, v[i]
while j <= 2 * n + 10 and k != i:
k = v[k]
j += 1
if k == i:
r *= j // gcd(r, j)
b[i] = 1
for i in range(n):
j, k = 0, i
while not b[k]:
k = v[k]
j += 1
if j > 0:
r *= j // gcd(j, r)
print(r)
``` | instruction | 0 | 82,142 | 5 | 164,284 |
No | output | 1 | 82,142 | 5 | 164,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
import math
def ciclos(arr, i):
d = {i:0}
cnt = 1
while True:
i = arr[i]-1
if i in d:
return d[i],cnt-d[i]
d[i] = cnt
cnt+=1
def mcm(a,b):
return (a*b//math.gcd(a,b))
n = int(input())
a = [int(x) for x in input().split()]
max_offset = -float('inf')
act_mcm = 1
for i in range(n):
off, lon = ciclos(a,i)
aux = lon if(off==0) else lon*math.ceil(off/lon)
act_mcm = mcm(act_mcm,aux)
print(act_mcm)
``` | instruction | 0 | 82,143 | 5 | 164,286 |
No | output | 1 | 82,143 | 5 | 164,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some time ago Leonid have known about idempotent functions. Idempotent function defined on a set {1, 2, ..., n} is such function <image>, that for any <image> the formula g(g(x)) = g(x) holds.
Let's denote as f(k)(x) the function f applied k times to the value x. More formally, f(1)(x) = f(x), f(k)(x) = f(f(k - 1)(x)) for each k > 1.
You are given some function <image>. Your task is to find minimum positive integer k such that function f(k)(x) is idempotent.
Input
In the first line of the input there is a single integer n (1 ≤ n ≤ 200) — the size of function f domain.
In the second line follow f(1), f(2), ..., f(n) (1 ≤ f(i) ≤ n for each 1 ≤ i ≤ n), the values of a function.
Output
Output minimum k such that function f(k)(x) is idempotent.
Examples
Input
4
1 2 2 4
Output
1
Input
3
2 3 3
Output
2
Input
3
2 3 1
Output
3
Note
In the first sample test function f(x) = f(1)(x) is already idempotent since f(f(1)) = f(1) = 1, f(f(2)) = f(2) = 2, f(f(3)) = f(3) = 2, f(f(4)) = f(4) = 4.
In the second sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(x) = f(2)(x) is idempotent since for any x it is true that f(2)(x) = 3, so it is also true that f(2)(f(2)(x)) = 3.
In the third sample test:
* function f(x) = f(1)(x) isn't idempotent because f(f(1)) = 3 but f(1) = 2;
* function f(f(x)) = f(2)(x) isn't idempotent because f(2)(f(2)(1)) = 2 but f(2)(1) = 3;
* function f(f(f(x))) = f(3)(x) is idempotent since it is identity function: f(3)(x) = x for any <image> meaning that the formula f(3)(f(3)(x)) = f(3)(x) also holds.
Submitted Solution:
```
n = int(input())
p = list(map(int, input().split()))
g = {}
deg = {}
first = []
circle = {}
ans = []
def push_d(deg, u, val):
if u not in deg:
deg[u] = 0
deg[u] += val
def push_g(g, u, v):
if u not in g:
g[u] = []
g[u].append(v)
def gcd(a, b):
if b == 0:
return a
return gcd(b, a%b)
def total(arr):
cur=1
for x in arr:
cur = cur // gcd(cur, x) * x
return cur
def process(g, deg, deg0, u):
if u in g:
for v in g[u]:
push_d(deg, v, -1)
if deg[v] == 0:
deg0.append(v)
def bfs(u):
S = [u]
used[u] = 1
circle[u] = 1
i = 0
while i < len(S):
u = S[i]
if u in g:
for v in g[u]:
if used[v] == 0:
used[v] = 1
circle[v] = 1
S.append(v)
i+=1
return len(S)
for u, v in enumerate(p):
u+=1
push_d(deg, v, 1)
push_g(g, u, v)
deg0 = [x for x in range(1, n+1) if x not in deg]
first = [x for x in deg0]
used = [0 for x in range(n+1)]
while len(deg0) > 0:
u = deg0.pop()
used[u] = 1
process(g, deg, deg0, u)
cnt = []
for u in range(1, n+1):
if used[u] == 0:
cnt.append(bfs(u))
used = [0 for x in range(n+1)]
for u in circle:
used[u] = 1
max_ = 0
for u in first:
max_ = max(max_, bfs(u))
cur = total(cnt)
ans =cur
while ans<max_:
ans+=cur
print(ans)
``` | instruction | 0 | 82,144 | 5 | 164,288 |
No | output | 1 | 82,144 | 5 | 164,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Constraints
* 1\leq A\leq B\leq 10^{18}
* 1\leq C,D\leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
Print the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Examples
Input
4 9 2 3
Output
2
Input
10 40 6 8
Output
23
Input
314159265358979323 846264338327950288 419716939 937510582
Output
532105071133627368
Submitted Solution:
```
import math
A, B, C, D = map(int, input().split())
lcm = int(C * D / math.gcd(C, D))
num_B_C = B // C
num_B_D = B // D
num_B_CD = B // (lcm)
num_A_C = (A-1) // C
num_A_D = (A-1) // D
num_A_CD = (A-1) // (lcm)
num_all = (num_B_C - num_A_C) + (num_B_D - num_A_D) - (num_B_CD - num_A_CD)
result = (B - (A-1)) - num_all
print(result)
``` | instruction | 0 | 82,407 | 5 | 164,814 |
No | output | 1 | 82,407 | 5 | 164,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Constraints
* 1\leq A\leq B\leq 10^{18}
* 1\leq C,D\leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
Print the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Examples
Input
4 9 2 3
Output
2
Input
10 40 6 8
Output
23
Input
314159265358979323 846264338327950288 419716939 937510582
Output
532105071133627368
Submitted Solution:
```
# -*- coding: utf-8 -*-
A, B, C, D = map(int, input().split())
def gcd(x, y):
while y:
x, y = y, x % y
return int(x)
def lcm(x, y):
return int(x * y / gcd(x, y))
# A-1 以下の割り切れるものの個数
a_c = int((A-1) / C)
a_d = int((A-1) / D)
a_cd = int((A-1) / lcm(C, D))
# B以下の割り切れるものの個数
b_c = int(B / C)
b_d = int(B / D)
b_cd = int(B / lcm(C, D))
# A以上B以下の割り切れるものの個数
ab = (b_c + b_d - b_cd) - (a_c + a_d - a_cd)
# 割り切れないものの個数
ans = (B - A + 1) - ab
print(ans)
``` | instruction | 0 | 82,409 | 5 | 164,818 |
No | output | 1 | 82,409 | 5 | 164,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Constraints
* 1\leq A\leq B\leq 10^{18}
* 1\leq C,D\leq 10^9
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
Print the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.
Examples
Input
4 9 2 3
Output
2
Input
10 40 6 8
Output
23
Input
314159265358979323 846264338327950288 419716939 937510582
Output
532105071133627368
Submitted Solution:
```
e = list(map(int,input().split()))
a = e[0]
b = e[1]
c = e[2]
d = e[3]
def div(x,y):
cnt = 0
for i in range(a,b+1):
if (int(i/x)-i/x != 0) and (int(i/y)-i/y != 0):
cnt += 1
return cnt
print(div(c,d))
``` | instruction | 0 | 82,410 | 5 | 164,820 |
No | output | 1 | 82,410 | 5 | 164,821 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,463 | 5 | 164,926 |
"Correct Solution:
```
from itertools import combinations as cmb
import copy
n, k = map(int, input().split())
A = list(map(int, input().split()))
highest = [A[0]] * n
for i in range(1, n):
highest[i] = max(A[i], highest[i-1])
def cost_calc(pattern):
cost = 0
max_height_re = 0
A_copy = copy.copy(A)
for num in pattern:
cost += max(max_height_re, highest[num]) - A[num]
max_height_re = max(max_height_re, highest[num]) + 1
return cost
max_val = float("inf")
for pattern in cmb(range(n), k):
max_val = min(max_val, cost_calc(pattern))
print(max_val)
``` | output | 1 | 82,463 | 5 | 164,927 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,464 | 5 | 164,928 |
"Correct Solution:
```
import sys
N, K = map(int, input().split())
B = list(map(int, sys.stdin.readline().rsplit()))
res = 10 ** 18
for i in range(2 ** N):
cnt = 0
for j in range(N):
# print(bin(i), bin(i >> j))
if (i >> j) & 1:
cnt += 1
# print(cnt)
if cnt != K:
continue
A = B[::]
cnt = 0
maxi = A[0] - 1
for j in range(N):
if (i >> j) & 1:
if A[j] <= maxi:
cnt += (maxi + 1) - A[j]
A[j] = maxi + 1
maxi = max(maxi, A[j])
res = min(res, cnt)
print(res)
# print(A)
``` | output | 1 | 82,464 | 5 | 164,929 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,465 | 5 | 164,930 |
"Correct Solution:
```
n, k = map(int, input().split())
buildings = list(map(int, input().split()))
ans = float('inf')
for i in range(2 ** n):
res = 0
cnt = 1
prev_build = buildings[0]
# 高くするビルをbitで管理
for j in range(1, n):
if (i >> j) & 1:
cnt += 1
if prev_build >= buildings[j]:
res += prev_build - buildings[j] + 1
prev_build += 1
else:
prev_build = buildings[j]
else:
if prev_build < buildings[j]:
cnt += 1
prev_build = buildings[j]
if cnt >= k:
ans = min(ans, res)
print(ans)
``` | output | 1 | 82,465 | 5 | 164,931 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,466 | 5 | 164,932 |
"Correct Solution:
```
N, K = map(int, input().split())
a = list(map(int, input().split()))
ans = float('inf')
for i in range(1<<N):
seen = 1
pay = 0
now = a[0]
for j in range(1, N):
if (i >> j) & 1:
if a[j] <= now:
pay += now - a[j] + 1
now += 1
seen += 1
else:
break
else:
if a[j] > now:
seen += 1
now = a[j]
if seen >= K:
ans = min(ans, pay)
break
print(ans)
``` | output | 1 | 82,466 | 5 | 164,933 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,467 | 5 | 164,934 |
"Correct Solution:
```
N,K = map(int,input().split())
a = [int(i) for i in input().split()]
ans = float("INF")
for i in range(1<<N):
cnt = 0
tmp = a[:]
m = tmp[0]
for j in range(1,N):
if i >> j & 1 and m >= tmp[j]:
cnt += m - tmp[j] + 1
tmp[j] = m + 1
m = max(m,tmp[j])
color = 1
m = tmp[0]
for j in range(1,N):
if tmp[j] > m:
color += 1
m = tmp[j]
if color >= K: ans = min(ans,cnt)
print(ans)
``` | output | 1 | 82,467 | 5 | 164,935 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,468 | 5 | 164,936 |
"Correct Solution:
```
#!/usr/bin/env python3
n, k, *a = map(int, open(0).read().split())
ans = 10**18
for i in range(2 << n):
h = 0
c = 0
b = 0
for j in range(n):
if a[j] > h:
b += 1
h = a[j]
elif i >> j & 1:
c += h - a[j] + 1
h += 1
b += 1
if b >= k:
ans = min(ans, c)
print(ans)
``` | output | 1 | 82,468 | 5 | 164,937 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,469 | 5 | 164,938 |
"Correct Solution:
```
N,K = map(int,input().split())
A = list(map(int,input().split()))
ans = float('inf')
for i in range(1<<N):
a = A[::]
cur,add = 0,0
see = 0
for j in range(N):
if (i>>j)&1:
see += 1
if cur >= a[j]:
add += (cur-a[j])+1
a[j] = cur+1
cur = max(cur,a[j])
else:
cur = max(cur,a[j])
if see == K:
ans = min(ans, add)
print(ans)
``` | output | 1 | 82,469 | 5 | 164,939 |
Provide a correct Python 3 solution for this coding contest problem.
Input Format
N K
a_1 a_2 a_3 ... a_N
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Output Format
Print the minimum cost in one line. In the end put a line break.
Constraints
* 1 ≤ K ≤ N ≤ 15
* 1 ≤ a_i ≤ 10^9
Scoring
Subtask 1 [120 points]
* N = K
Subtask 2 [90 points]
* N ≤ 5
* a_i ≤ 7
Subtask 3 [140 points]
* There are no additional constraints.
Input Format
N K
a_1 a_2 a_3 ... a_N
Example
Input
5 5
3949 3774 3598 3469 3424
Output
1541 | instruction | 0 | 82,470 | 5 | 164,940 |
"Correct Solution:
```
def LI(): return list(map(int,input().split()))
N,K = LI()
a = LI()
ans = float('INF')
for i in range(2**(N-1)):
bit = [i>>j&1 for j in range(N-1)]
if K-1!=bit.count(1):
continue
temp,kijun = 0,a[0]
for k in range(N-1):
if bit[k]==0:
kijun = max(kijun,a[k+1])
else:
if a[k+1]>=kijun+1:
kijun = a[k+1]
continue
temp += (kijun+1)-a[k+1]
kijun += 1
ans = min(ans,temp)
print(ans)
``` | output | 1 | 82,470 | 5 | 164,941 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which reads an integer n and prints the factorial of n. You can assume that n ≤ 20.
Input
An integer n (1 ≤ n ≤ 20) in a line.
Output
Print the factorial of n in a line.
Example
Input
5
Output
120 | instruction | 0 | 82,480 | 5 | 164,960 |
"Correct Solution:
```
n = int(input())
result = n
for _ in range(n)[:1:-1] : result *= _
print(result)
``` | output | 1 | 82,480 | 5 | 164,961 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which reads an integer n and prints the factorial of n. You can assume that n ≤ 20.
Input
An integer n (1 ≤ n ≤ 20) in a line.
Output
Print the factorial of n in a line.
Example
Input
5
Output
120 | instruction | 0 | 82,481 | 5 | 164,962 |
"Correct Solution:
```
import sys
def fact(n):
ret = 1
if n<1:
return -1
elif n==1:
return 1
else:
return n*fact(n-1)
line = sys.stdin.readline()
inp = int(line)
print (fact(inp))
``` | output | 1 | 82,481 | 5 | 164,963 |
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