message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output | instruction | 0 | 83,279 | 5 | 166,558 |
"Correct Solution:
```
print(*[''.join(str(i)+'x'+str(j)+'='+str(i*j)) for i in range(1,10) for j in range(1,10)], sep='\n')
``` | output | 1 | 83,279 | 5 | 166,559 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output | instruction | 0 | 83,280 | 5 | 166,560 |
"Correct Solution:
```
[[print("{}x{}={}".format(j,i,i*j)) for i in range(1,10)] for j in range(1,10)]
``` | output | 1 | 83,280 | 5 | 166,561 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output | instruction | 0 | 83,281 | 5 | 166,562 |
"Correct Solution:
```
for a in range(1, 10):
for b in range(1, 10):
print(str(a)+'x'+str(b)+'='+str(a*b))
``` | output | 1 | 83,281 | 5 | 166,563 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output | instruction | 0 | 83,282 | 5 | 166,564 |
"Correct Solution:
```
for a in range(1,10):
for b in range(1,10):
print(a,"x",b,"=",a*b,sep='')
``` | output | 1 | 83,282 | 5 | 166,565 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output | instruction | 0 | 83,283 | 5 | 166,566 |
"Correct Solution:
```
for a in range(1,10):
for b in range(1,10):
i = a * b
print(a,"x",b,"=",i,sep="")
``` | output | 1 | 83,283 | 5 | 166,567 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output | instruction | 0 | 83,284 | 5 | 166,568 |
"Correct Solution:
```
[print("{}x{}={}".format(i, j, i * j)) for i in range(1, 10) for j in range(1, 10)]
``` | output | 1 | 83,284 | 5 | 166,569 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output | instruction | 0 | 83,285 | 5 | 166,570 |
"Correct Solution:
```
for i in range(1,10):
for j in range(1,10):
a=str(i)+"x"+str(j)+"="+str(i*j)
print(a)
``` | output | 1 | 83,285 | 5 | 166,571 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
a=1; b=1; c=0
while a<10:
while b<10:
c=a*b
print("%dx%d=%d" %(a,b,c))
b+=1
a+=1;b=1
``` | instruction | 0 | 83,286 | 5 | 166,572 |
Yes | output | 1 | 83,286 | 5 | 166,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
for i in range(1,10):
for j in range(1,10):
ans = "%dx%d=%d"%(i,j,i*j)
print(ans)
``` | instruction | 0 | 83,287 | 5 | 166,574 |
Yes | output | 1 | 83,287 | 5 | 166,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
i=1
n=1
while n<10:
for i in range(1,10):
y=i*n
print(f'{n}x{i}={y}')
n+=1
``` | instruction | 0 | 83,288 | 5 | 166,576 |
Yes | output | 1 | 83,288 | 5 | 166,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
for a in range(1,10):
for b in range(1,10):
c=a*b
print(str(a)+'x'+str(b)+'='+str(c) )
``` | instruction | 0 | 83,289 | 5 | 166,578 |
Yes | output | 1 | 83,289 | 5 | 166,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
for(a in range(1,9)):
for(b in range(1,9)):
print(a,"x",b,"=",a*b)
``` | instruction | 0 | 83,290 | 5 | 166,580 |
No | output | 1 | 83,290 | 5 | 166,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
for i in range(1,10):
for j in range(1,10):
print ('%sx%s=%s \t' % (i,j,i*j)),
print
``` | instruction | 0 | 83,291 | 5 | 166,582 |
No | output | 1 | 83,291 | 5 | 166,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
for i=1 in range(10):
for j=1 in range(10):
if(i > 0 and j > 0):
print(str(i) + 'x' + str(j) + '=' + str(i*j))
``` | instruction | 0 | 83,292 | 5 | 166,584 |
No | output | 1 | 83,292 | 5 | 166,585 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which prints multiplication tables in the following format:
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Input
No input.
Output
1x1=1
1x2=2
.
.
9x8=72
9x9=81
Example
Input
Output
Submitted Solution:
```
for i in range(1,10):
for j in range(1,10):
print(i,'*',j,'=',i*j)
``` | instruction | 0 | 83,293 | 5 | 166,586 |
No | output | 1 | 83,293 | 5 | 166,587 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
5
Output
5 | instruction | 0 | 83,341 | 5 | 166,682 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
write = sys.stdout.write
def fibonacci(N, M):
RA = RD = 1; RB = RC = 0
XA = XB = XC = 1; XD = 0
while N:
if N & 1:
RA, RB, RC, RD = (RA*XA + RB*XC) % M, (RA*XB + RB*XD) % M, (RC*XA + RD*XC) % M, (RC*XB + RD*XD) % M
XA, XB, XC, XD = (XA**2 + XB*XC) % M, XB*(XA + XD) % M, XC*(XA + XD) % M, (XB*XC + XD**2) % M
N >>= 1
return RC
def solve():
MOD = 10**9 + 7
K = int(readline())
k0 = (int((1 + 4*K)**.5) - 1) // 2
if k0**2 + k0 == K:
k0 -= 1
kk = k0**2+k0
if K - kk > k0+1:
m0 = 2*k0+1
b = K - kk - (k0+1) - 1
else:
m0 = 2*k0
b = K - kk - 1
if k0//2+1 > b:
v = fibonacci(2+2*b, MOD) * fibonacci(m0+2-2*b, MOD) % MOD
else:
b1 = k0+1 - b-1
v = fibonacci(3+2*b1, MOD) * fibonacci(m0+1-2*b1, MOD) % MOD
write("%d\n" % v)
solve()
``` | output | 1 | 83,341 | 5 | 166,683 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An integer sequence is called beautiful if the difference between any two consecutive numbers is equal to 1. More formally, a sequence s_1, s_2, …, s_{n} is beautiful if |s_i - s_{i+1}| = 1 for all 1 ≤ i ≤ n - 1.
Trans has a numbers 0, b numbers 1, c numbers 2 and d numbers 3. He wants to construct a beautiful sequence using all of these a + b + c + d numbers.
However, it turns out to be a non-trivial task, and Trans was not able to do it. Could you please help Trans?
Input
The only input line contains four non-negative integers a, b, c and d (0 < a+b+c+d ≤ 10^5).
Output
If it is impossible to construct a beautiful sequence satisfying the above constraints, print "NO" (without quotes) in one line.
Otherwise, print "YES" (without quotes) in the first line. Then in the second line print a + b + c + d integers, separated by spaces — a beautiful sequence. There should be a numbers equal to 0, b numbers equal to 1, c numbers equal to 2 and d numbers equal to 3.
If there are multiple answers, you can print any of them.
Examples
Input
2 2 2 1
Output
YES
0 1 0 1 2 3 2
Input
1 2 3 4
Output
NO
Input
2 2 2 3
Output
NO
Note
In the first test, it is easy to see, that the sequence is beautiful because the difference between any two consecutive numbers is equal to 1. Also, there are exactly two numbers, equal to 0, 1, 2 and exactly one number, equal to 3.
It can be proved, that it is impossible to construct beautiful sequences in the second and third tests.
Submitted Solution:
```
g = list(map(int, input().split()))
v = [-1, 1, 0, 0, 1, -1]
g.insert(0, 0)
g.append(0)
for i in range(1, 5, 1):
if (g[i] == 0):
continue
s = [i]
c = g.copy()
c[i] -= 1
#print(s)
while (c[1] + c[2] + c[3] + c[4] > 0):
a = s[-1] - 1
b = s[-1] + 1
if (v[b] > v[a]):
a, b = b, a
if c[a] == 0:
a = b
if (c[a] == 0):
break
c[a] -= 1
s.append(a)
#print(s)
#print(i, c[1]+c[2]+c[3]+c[4])
if (c[1] + c[2] + c[3] + c[4] > 0):
continue
flag = True
for i in range(g[1] + g[2] + g[3] + g[4] - 1):
if (abs(s[i + 1] - s[i]) != 1):
flag = False
break
if (flag):
def f(a): return str(a-1)
print("YES")
print(" ".join(list(map(f, s))))
exit()
print("NO")
``` | instruction | 0 | 83,498 | 5 | 166,996 |
Yes | output | 1 | 83,498 | 5 | 166,997 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An integer sequence is called beautiful if the difference between any two consecutive numbers is equal to 1. More formally, a sequence s_1, s_2, …, s_{n} is beautiful if |s_i - s_{i+1}| = 1 for all 1 ≤ i ≤ n - 1.
Trans has a numbers 0, b numbers 1, c numbers 2 and d numbers 3. He wants to construct a beautiful sequence using all of these a + b + c + d numbers.
However, it turns out to be a non-trivial task, and Trans was not able to do it. Could you please help Trans?
Input
The only input line contains four non-negative integers a, b, c and d (0 < a+b+c+d ≤ 10^5).
Output
If it is impossible to construct a beautiful sequence satisfying the above constraints, print "NO" (without quotes) in one line.
Otherwise, print "YES" (without quotes) in the first line. Then in the second line print a + b + c + d integers, separated by spaces — a beautiful sequence. There should be a numbers equal to 0, b numbers equal to 1, c numbers equal to 2 and d numbers equal to 3.
If there are multiple answers, you can print any of them.
Examples
Input
2 2 2 1
Output
YES
0 1 0 1 2 3 2
Input
1 2 3 4
Output
NO
Input
2 2 2 3
Output
NO
Note
In the first test, it is easy to see, that the sequence is beautiful because the difference between any two consecutive numbers is equal to 1. Also, there are exactly two numbers, equal to 0, 1, 2 and exactly one number, equal to 3.
It can be proved, that it is impossible to construct beautiful sequences in the second and third tests.
Submitted Solution:
```
a,b,c,d = map(int,input().split())
if a == b and b == 0:
if abs(c-d) > 1:
print('NO')
else:
print('YES')
if c > d:
for i in range(d):
print('2 3',end=' ')
print('2')
elif d > c:
for i in range(c):
print('3 2',end=' ')
print('3')
else:
for i in range(c):
print('3 2',end=' ')
print()
elif b == c and c == d and d == 0:
if a == 1:
print('YES')
print(0)
else:
print('NO')
elif a == c and c == d and d == 0:
if b == 1:
print('YES')
print(1)
else:
print('NO')
elif a == b and b == d and d == 0:
if c == 1:
print('YES')
print(2)
else:
print('NO')
elif a == b and b == c and c == 0:
if d == 1:
print('YES')
print(3)
else:
print('NO')
else:
ans = ''
flag = True
flag_1 = False
if b >= a:
if b > a:
ans += '1 '
flag = False
flag_1 = True
for i in range(a):
ans += '0 1 '
flag = False
b -= (a+1)
if b <= 0:
if d == c-1 or d == c:
for i in range(d):
ans += '2 3 '
if d == c-1:
ans += '2'
print('YES')
print(ans)
elif d+2 == c and flag_1:
for i in range(d):
ans += '2 3 '
print('YES')
print('2 '+ans+'2')
else:
if flag:
if d == c+1:
for i in range(c):
ans += '3 2 '
ans += '3'
print('YES')
print(ans)
else:
print('NO')
else:
if c >= b:
for i in range(b):
ans += '2 1 '
c -= b
if c >= 1:
ans += '2 '
c -= 1
if d >= c:
if d == c or d == c+1:
print('YES')
for i in range(c):
ans += '3 2 '
if d == c+1:
ans += '3'
print(ans)
else:
print('NO')
else:
if d == 0 and c == 1:
print('YES')
print('2 '+ans)
elif d+1 == c:
print('YES')
for i in range(d):
ans += '3 2 '
print('2 '+ans)
else:
print('NO')
else:
print('NO')
else:
if c == d and d == 0:
if a == b+1:
print('YES')
print('0',end=' ')
for i in range(b):
print('1 0',end=' ')
print()
else:
print('NO')
else:
print('NO')
``` | instruction | 0 | 83,500 | 5 | 167,000 |
Yes | output | 1 | 83,500 | 5 | 167,001 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5. | instruction | 0 | 83,507 | 5 | 167,014 |
Tags: bitmasks, brute force, dfs and similar, divide and conquer, dp, greedy, strings, trees
Correct Solution:
```
n = int(input())
a = [int(x) for x in input().split(" ")]
a.sort()
b = pow(2, 30)
while b > 0 and (a[n-1] % b) == a[n - 1]:
b /= 2
b = int(b)
if b == 0:
print(0)
exit(0)
def sol(nums, lo, hi, bit):
bit = int(bit)
if bit < 1:
return nums[lo] % 2, 0
if hi - lo == 0:
return nums[lo] % (bit * 2), 0
ind = lo
while ind <= hi and nums[ind] & bit != bit:
ind += 1
if ind-1 - lo < 0:
x, maxi = sol(nums, ind, hi, bit / 2)
return x + bit, maxi
elif hi - ind < 0:
x, maxi = sol(nums, lo, ind - 1, bit / 2)
return x, maxi
else:
x_l, maxi_l = sol(nums, lo, ind - 1, bit / 2)
x_r, maxi_r = sol(nums, ind, hi, bit / 2)
if maxi_l <= maxi_r:
return x_l + bit, maxi_l + bit
else:
return x_r, maxi_r + bit
X, ans = sol(a, 0, n - 1, b)
print(ans)
``` | output | 1 | 83,507 | 5 | 167,015 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5. | instruction | 0 | 83,510 | 5 | 167,020 |
Tags: bitmasks, brute force, dfs and similar, divide and conquer, dp, greedy, strings, trees
Correct Solution:
```
def solve(a, b=32):
if b == -1:
return 0
a1 = []
a2 = []
n = len(a)
for i in range(n):
if (a[i] // (2 ** b)) % 2 == 1:
a1.append(a[i])
else:
a2.append(a[i])
if len(a1) == 0:
return solve(a2, b - 1)
elif len(a2) == 0:
return solve(a1, b - 1)
else:
return 2 ** b + min(solve(a1, b - 1), solve(a2, b - 1))
n = int(input())
a = list(map(int, input().split()))
print(solve(a))
``` | output | 1 | 83,510 | 5 | 167,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5. | instruction | 0 | 83,511 | 5 | 167,022 |
Tags: bitmasks, brute force, dfs and similar, divide and conquer, dp, greedy, strings, trees
Correct Solution:
```
def q(s,b):
if(not s)or b<0:return 0
n,f=[],[]
for i in s:
if i&(1<<b):n+=i,
else:f+=i,
if not n:return q(f,b-1)
if not f:return q(n,b-1)
return min(q(n,b-1),q(f,b-1))+2**b
input()
print(q([*map(int,input().split())],32))
``` | output | 1 | 83,511 | 5 | 167,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5. | instruction | 0 | 83,512 | 5 | 167,024 |
Tags: bitmasks, brute force, dfs and similar, divide and conquer, dp, greedy, strings, trees
Correct Solution:
```
'''input
2
1 5
'''
# A coding delight
from sys import stdin, stdout
import gc
gc.disable()
input = stdin.readline
import math
def solve(arr, bit):
if len(arr) == 0 or bit < 0:
return 0
l = []
r = []
for i in arr:
if (i >> bit & 1) == 0:
l.append(i)
else:
r.append(i)
if len(l) == 0:
return solve(r, bit - 1)
if len(r) == 0:
return solve(l, bit - 1)
return min(solve(l, bit - 1), solve(r, bit - 1)) + (1 << bit)
# main starts
n = int(input().strip())
arr = list(map(int, input().split()))
print(solve(arr, 30))
``` | output | 1 | 83,512 | 5 | 167,025 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
import io, sys, atexit, os
import math as ma
from sys import exit
from decimal import Decimal as dec
from itertools import permutations
from itertools import combinations
def li():
return list(map(int, sys.stdin.readline().split()))
def num():
return map(int, sys.stdin.readline().split())
def nu():
return int(input())
def find_gcd(x, y):
while (y):
x, y = y, x % y
return x
def lcm(x, y):
gg = find_gcd(x, y)
return (x * y // gg)
mm=1000000007
def go(a,bit):
if(bit<0):
return 0
set=[]
notset=[]
for i in range(len(a)):
if(((1<<bit)&a[i])!=0):
set.append(a[i])
else:
notset.append(a[i])
if(len(set)==0):
return go(notset,bit-1)
if(len(notset)==0):
return go(set,bit-1)
return min(go(set,bit-1),go(notset,bit-1))+(1<<bit)
def solve():
t = 1
for tt in range(t):
n=nu()
a=li()
print(go(a,30))
if __name__ == "__main__":
solve()
``` | instruction | 0 | 83,513 | 5 | 167,026 |
Yes | output | 1 | 83,513 | 5 | 167,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
import sys
input=sys.stdin.readline
n=int(input())
l=[int(i) for i in input().split()]
ans=0
def xorchecker(l,ans,pow_):
if pow_==-1:
return(ans)
one=[]
zero=[]
for i in l:
if i&(1<<pow_)!=0:
one.append(i)
else:
zero.append(i)
if zero==[] or one==[]:
return(xorchecker(l,ans,pow_-1))
else:
return(min(xorchecker(zero,ans+(1<<pow_),pow_-1),xorchecker(one,ans+(1<<pow_),pow_-1)))
print(xorchecker(l,ans,30))
``` | instruction | 0 | 83,514 | 5 | 167,028 |
Yes | output | 1 | 83,514 | 5 | 167,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
import sys
input=sys.stdin.readline
def calc(arr,b):
if (not arr) or b<0:
return 0
bit1,bit0=[],[]
for x in arr:
if (x>>b)&1:
bit1.append(x)
else:
bit0.append(x)
if not bit1:
return calc(bit0,b-1)
elif not bit0:
return calc(bit1,b-1)
else:
return min(calc(bit1,b-1),calc(bit0,b-1))+2**b
n=int(input())
a=list(map(int,input().split()))
print(calc(a,32))
``` | instruction | 0 | 83,515 | 5 | 167,030 |
Yes | output | 1 | 83,515 | 5 | 167,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
from os import name
from math import *
def dp(arr,bit):
if(bit<0):
return 0
a,b=[],[]
for i in arr:
if(i&(1<<bit)):
a.append(i)
else:
b.append(i)
if(len(a)==0):
return dp(b,bit-1)
if(len(b)==0):
return dp(a,bit-1)
return min(dp(a,bit-1),dp(b,bit-1)) + 2**bit
def pro(arr):
print(dp(arr,30))
n=int(input())
arr=list(map(int,input().split()))
pro(arr)
``` | instruction | 0 | 83,516 | 5 | 167,032 |
Yes | output | 1 | 83,516 | 5 | 167,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
n=int(input())
l=list(map(int,input().split()))
m=max(l)
bm=bin(m)[2:]
le=len(bm)
arr=[0]*le
for i in range(n):
b=bin(l[i])[2:]
b='0'*(le-len(b))+b
for j in range(le):
if(b[j]=='1'):
arr[j]+=1
hlf=n//2
val=0
for i in range(le):
j=le-1-i
if(arr[j]>hlf):
val+=2**i
mx=-1
for i in l:
a=i^val
if(a>mx):
mx=a
print(mx)
``` | instruction | 0 | 83,517 | 5 | 167,034 |
No | output | 1 | 83,517 | 5 | 167,035 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
import sys
def solve(arr,bit):
#print(arr,bit)
if len(arr)==0 or bit<0:
return 0
l,r=[],[]
for i in range(len(arr)):
if (arr[i]>>bit)&1==0:
l.append(arr[i])
else:
r.append(arr[i])
if len(l)==0:
return solve(r,bit-1)
if len(r)==0:
return solve(l,bit-1)
return min(solve(l,bit-1),solve(r,bit-1))+1<<bit
n=int(sys.stdin.readline())
l=list(map(int,sys.stdin.readline().split()))
print(solve(l,30))
``` | instruction | 0 | 83,518 | 5 | 167,036 |
No | output | 1 | 83,518 | 5 | 167,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
import sys
n = int(input())
lis = list(map(int, input().split()))
m = max(lis)
base = 1
while base<m:
base = base<<1
print(base>>1)
``` | instruction | 0 | 83,519 | 5 | 167,038 |
No | output | 1 | 83,519 | 5 | 167,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Today, as a friendship gift, Bakry gave Badawy n integers a_1, a_2, ..., a_n and challenged him to choose an integer X such that the value \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X) is minimum possible, where ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
As always, Badawy is too lazy, so you decided to help him and find the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Input
The first line contains integer n (1≤ n ≤ 10^5).
The second line contains n integers a_1, a_2, ..., a_n (0 ≤ a_i ≤ 2^{30}-1).
Output
Print one integer — the minimum possible value of \underset{1 ≤ i ≤ n}{max} (a_i ⊕ X).
Examples
Input
3
1 2 3
Output
2
Input
2
1 5
Output
4
Note
In the first sample, we can choose X = 3.
In the second sample, we can choose X = 5.
Submitted Solution:
```
for _ in range(1):
n = int(input())
l = list(map(int,input().split()))
d = {}
z = set()
for i in l:
x = bin(i)[2:]
j = len(x)-1
k = 0
while j > -1:
if x[j] == "1":
z.add(k)
if k in d:
d[k] += 1
else:
d[k] = 1
j -= 1
k += 1
ans = ["0"]*64
# print(s)
s = set()
for i in d:
if d[i] == n:
s.add(i)
z.remove(i)
continue
ma = max(z)
s.add(ma)
for i in s:
ans[63-i] = "1"
s = "".join(ans)
num = int(s,2)
ans = -1
for i in l:
e1 = i^num
ans = max(e1,ans)
print(ans)
``` | instruction | 0 | 83,520 | 5 | 167,040 |
No | output | 1 | 83,520 | 5 | 167,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The only line of the input is a string of 7 characters. The first character is letter A, followed by 6 digits. The input is guaranteed to be valid (for certain definition of "valid").
Output
Output a single integer.
Examples
Input
A221033
Output
21
Input
A223635
Output
22
Input
A232726
Output
23
Submitted Solution:
```
s = input()
p = sum(map(int, s[1:])) + 9 * s.count('0') + 1
print(p)
``` | instruction | 0 | 83,854 | 5 | 167,708 |
Yes | output | 1 | 83,854 | 5 | 167,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The only line of the input is a string of 7 characters. The first character is letter A, followed by 6 digits. The input is guaranteed to be valid (for certain definition of "valid").
Output
Output a single integer.
Examples
Input
A221033
Output
21
Input
A223635
Output
22
Input
A232726
Output
23
Submitted Solution:
```
x=int(input()[1:])
if x==221033:
print(21)
elif x==223635:
print(22)
elif x==232726:
print(23)
elif x==102210:
print(2)
elif x==102212:
print(2)
elif x==102213:
print(3)
elif x==102216:
print(4)
elif x==102217:
print(9)
``` | instruction | 0 | 83,857 | 5 | 167,714 |
No | output | 1 | 83,857 | 5 | 167,715 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,980 | 5 | 167,960 |
"Correct Solution:
```
print(("bust","win")[eval(input().replace(" ","+"))<22])
``` | output | 1 | 83,980 | 5 | 167,961 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,981 | 5 | 167,962 |
"Correct Solution:
```
print("win"if sum(map(int,input().split()))<22 else"bust")
``` | output | 1 | 83,981 | 5 | 167,963 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,982 | 5 | 167,964 |
"Correct Solution:
```
a,b,c=map(int,input().split())
d=a+b+c
print('bust' if d>21 else 'win')
``` | output | 1 | 83,982 | 5 | 167,965 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,983 | 5 | 167,966 |
"Correct Solution:
```
a,b=sum((int(x) for x in input().split())),["win","bust"]
print(b[int(a/22)])
``` | output | 1 | 83,983 | 5 | 167,967 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,984 | 5 | 167,968 |
"Correct Solution:
```
print('win' if sum(list(map(int,input().strip().split()))) < 22 else 'bust')
``` | output | 1 | 83,984 | 5 | 167,969 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,985 | 5 | 167,970 |
"Correct Solution:
```
x,y,z = map(int, input().split())
print(("win" if x+y+z <= 21 else "bust"))
``` | output | 1 | 83,985 | 5 | 167,971 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,986 | 5 | 167,972 |
"Correct Solution:
```
print('bust' if sum(map(int, input().strip().split(' '))) >= 22 else 'win')
``` | output | 1 | 83,986 | 5 | 167,973 |
Provide a correct Python 3 solution for this coding contest problem.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust | instruction | 0 | 83,987 | 5 | 167,974 |
"Correct Solution:
```
print("bust") if sum(map(int,input().split(" "))) >= 22 else print('win')
``` | output | 1 | 83,987 | 5 | 167,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
print("bust" if sum([int(i) for i in input().split()])>21 else "win")
``` | instruction | 0 | 83,988 | 5 | 167,976 |
Yes | output | 1 | 83,988 | 5 | 167,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
print("win") if sum(list(map(int, input().split()))) < 22 else print("bust")
``` | instruction | 0 | 83,989 | 5 | 167,978 |
Yes | output | 1 | 83,989 | 5 | 167,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
if 22 <= sum(map(int,input().split())):
print("bust")
else:
print("win")
``` | instruction | 0 | 83,990 | 5 | 167,980 |
Yes | output | 1 | 83,990 | 5 | 167,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
print(['win','bust'][sum(list(map(int,input().split())))>=22])
``` | instruction | 0 | 83,991 | 5 | 167,982 |
Yes | output | 1 | 83,991 | 5 | 167,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
import sys
lines = sys.stdin.readlines()
n = int(lines[0])
arr = list(map(int, lines[1].split(' ')))
maxi = 62
mod = int(1e9) + 7
ones = [0 for _ in range(maxi)]
for num in arr:
x = bin(num)[2:]
# print(x)
for idx, val in enumerate(reversed(x)):
ones[idx] += int(val)
ans = 0
for idx, val in enumerate(ones):
ans += ((pow(2, idx) % mod) * (((n - val)%mod) * (val%mod))) % mod
ans %= mod
print(ans)
``` | instruction | 0 | 83,992 | 5 | 167,984 |
No | output | 1 | 83,992 | 5 | 167,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
s = input()
cnt = 0
b = int(len(s))
for a in range(0,int(b/2)):
print(a)
if s[a] != s[(b-a-1)]:
cnt = cnt +1
print(cnt)
``` | instruction | 0 | 83,993 | 5 | 167,986 |
No | output | 1 | 83,993 | 5 | 167,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
A = map(int, input().split())
if A[0] + A[1] + A[2] > 22:
print("bust")
else:
print("win")
``` | instruction | 0 | 83,994 | 5 | 167,988 |
No | output | 1 | 83,994 | 5 | 167,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are three integers A_1, A_2, and A_3.
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Constraints
* 1 \leq A_i \leq 13 \ \ (i=1,2,3)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A_1 A_2 A_3
Output
If A_1+A_2+A_3 is greater than or equal to 22, print `bust`; otherwise, print `win`.
Examples
Input
5 7 9
Output
win
Input
13 7 2
Output
bust
Submitted Solution:
```
a = [int(i) for i in a]
if sum(a) >= 22:
print("bust")
else:
print("win")
``` | instruction | 0 | 83,995 | 5 | 167,990 |
No | output | 1 | 83,995 | 5 | 167,991 |
Provide a correct Python 3 solution for this coding contest problem.
<image>
At the request of a friend who started learning abacus, you decided to create a program to display the abacus beads. Create a program that takes a certain number as input and outputs a row of abacus beads. However, the number of digits of the abacus to be displayed is 5 digits, and the arrangement of beads from 0 to 9 is as follows using'*' (half-width asterisk),''(half-width blank), and'=' (half-width equal). It shall be expressed as.
<image>
Input
Multiple test cases are given. Up to 5 digits (integer) are given on one line for each test case.
The number of test cases does not exceed 1024.
Output
Output the abacus bead arrangement for each test case. Insert a blank line between the test cases.
Example
Input
2006
1111
Output
****
*
=====
* *
****
* ***
*****
*****
*****
=====
****
*
*****
*****
***** | instruction | 0 | 84,108 | 5 | 168,216 |
"Correct Solution:
```
abcus = {"0":"* = ****","1":"* =* ***","2":"* =** **","3":"* =*** *","4":"* =**** ",
"5":" *= ****","6":" *=* ***","7":" *=** **","8":" *=*** *","9":" *=**** "}
num = [["" for i in range(5)] for j in range(8)]
cnt = 0
while True:
try:
a = input().zfill(5)
if cnt != 0:
print()
for i in range(5):
n = abcus[a[i]]
for j in range(8):
num[j][i] = n[j]
for i in range(8):
print("".join(num[i]))
cnt+=1
except:
break
``` | output | 1 | 84,108 | 5 | 168,217 |
Provide a correct Python 3 solution for this coding contest problem.
<image>
At the request of a friend who started learning abacus, you decided to create a program to display the abacus beads. Create a program that takes a certain number as input and outputs a row of abacus beads. However, the number of digits of the abacus to be displayed is 5 digits, and the arrangement of beads from 0 to 9 is as follows using'*' (half-width asterisk),''(half-width blank), and'=' (half-width equal). It shall be expressed as.
<image>
Input
Multiple test cases are given. Up to 5 digits (integer) are given on one line for each test case.
The number of test cases does not exceed 1024.
Output
Output the abacus bead arrangement for each test case. Insert a blank line between the test cases.
Example
Input
2006
1111
Output
****
*
=====
* *
****
* ***
*****
*****
*****
=====
****
*
*****
*****
***** | instruction | 0 | 84,109 | 5 | 168,218 |
"Correct Solution:
```
dic = {"0":"* = ****",
"1":"* =* ***",
"2":"* =** **",
"3":"* =*** *",
"4":"* =**** ",
"5":" *= ****",
"6":" *=* ***",
"7":" *=** **",
"8":" *=*** *",
"9":" *=**** "}
def trans(lst):
ylen = len(lst)
xlen = len(lst[0])
ret = [[None] * ylen for _ in range(xlen)]
for y in range(ylen):
for x in range(xlen):
ret[x][y] = lst[y][x]
return ret
def print_abac(num):
num = num.zfill(5)
lst = [dic[c] for c in num]
lst = trans(lst)
for line in lst:
print("".join(line))
cnt = 0
while True:
try:
num = input()
if cnt != 0:
print()
else:
cnt += 1
print_abac(num)
except EOFError:
break
``` | output | 1 | 84,109 | 5 | 168,219 |
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