message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1 | instruction | 0 | 91,583 | 5 | 183,166 |
"Correct Solution:
```
k,s=map(int,input().split())
count=0
for x in range(k+1):
for y in range(k+1):
if k>=s-x-y>=0:
count+=1
print(count)
``` | output | 1 | 91,583 | 5 | 183,167 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1 | instruction | 0 | 91,584 | 5 | 183,168 |
"Correct Solution:
```
K, S = map(int, input().split())
print(sum(0 <= S - (x + y) <= K for y in range(K + 1) for x in range(K + 1)))
``` | output | 1 | 91,584 | 5 | 183,169 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1 | instruction | 0 | 91,585 | 5 | 183,170 |
"Correct Solution:
```
K,s=map(int,input().split())
cnt=0
for i in range(K+1):
for j in range(K+1):
if s-i-j >= 0 and s-i-j<=K:
cnt+=1
print(cnt)
``` | output | 1 | 91,585 | 5 | 183,171 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1 | instruction | 0 | 91,586 | 5 | 183,172 |
"Correct Solution:
```
n,s=map(int,input().split())
ans=0
for i in range(n+1):
for j in range(n+1):
if -1<s-i-j<n+1:
ans+=1
print(ans)
``` | output | 1 | 91,586 | 5 | 183,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
k,s = map(int, input().split())
print(len([s-y-z for z in range(k+1) for y in range(k+1) if 0<=s-y-z<=k]))
``` | instruction | 0 | 91,587 | 5 | 183,174 |
Yes | output | 1 | 91,587 | 5 | 183,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
k,s=map(int,input().split())
print(len([2 for z in range(k+1) for y in range(k+1) if 0<=s-y-z<=k]))
``` | instruction | 0 | 91,588 | 5 | 183,176 |
Yes | output | 1 | 91,588 | 5 | 183,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
k,s=map(int,input().split())
print(sum(0<=s-y-z<=k for y in range(k+1) for z in range(k+1)))
``` | instruction | 0 | 91,589 | 5 | 183,178 |
Yes | output | 1 | 91,589 | 5 | 183,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
a,b=input().split()
a=int(a)
b=int(b)
c=0
for i in range(a+1):
for k in range(a+1):
if b-a<=i+k<=b:
c=c+1
print(c)
``` | instruction | 0 | 91,590 | 5 | 183,180 |
Yes | output | 1 | 91,590 | 5 | 183,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
K,S = map(int, input().split())
ans = 0
if K*3<S:
print(0)
exit()
for x in range(K, -1, -1):
for y in range(K, -1, -1):
if x+y >=S:
break
for z in range(K, -1, -1):
if x+y+z==S:
ans+=1
elif x+y+z<S:
break
print(ans)
``` | instruction | 0 | 91,591 | 5 | 183,182 |
No | output | 1 | 91,591 | 5 | 183,183 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
k,s = map(int,input().split())
x = list(range(k+1))
y = list(range(k+1))
z = list(range(k+1))
count = 0
for i in range(k+1):
for j in range(k+1):
if (s - (x[i] + y[j])) in z:
count += 1
print(count)
``` | instruction | 0 | 91,592 | 5 | 183,184 |
No | output | 1 | 91,592 | 5 | 183,185 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
k, s = map(int, input().split())
cnt = 0
for i in range(k):
for j in range(k):
if max(0, s-k) <= i+j <= s:
cnt += 1
elif i + j > s:
break
print(cnt)
``` | instruction | 0 | 91,593 | 5 | 183,186 |
No | output | 1 | 91,593 | 5 | 183,187 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers K and S.
Three variable X, Y and Z takes integer values satisfying 0≤X,Y,Z≤K.
How many different assignments of values to X, Y and Z are there such that X + Y + Z = S?
Constraints
* 2≤K≤2500
* 0≤S≤3K
* K and S are integers.
Input
The input is given from Standard Input in the following format:
K S
Output
Print the number of the triples of X, Y and Z that satisfy the condition.
Examples
Input
2 2
Output
6
Input
5 15
Output
1
Submitted Solution:
```
K, S = map(int, input().split())
ans = 0
for i in range(0,K+1):
for j in range (0,K+1):
for k in range (0,K+1):
if (i + j + k) == S:
ans = ans + 1
print(ans)
``` | instruction | 0 | 91,594 | 5 | 183,188 |
No | output | 1 | 91,594 | 5 | 183,189 |
Provide a correct Python 3 solution for this coding contest problem.
Let A, B, C, D, E be sets of integers and let U is a universal set that includes all sets under consideration. All elements in any set are different (no repetitions).
u - union of two sets, AuB = {x ∈ U : x ∈ A or x ∈ B} is the set of all elements which belong to A or B.
i - intersection of two sets, AiB = {x ∈ U : x ∈ A and x ∈ B} is the set of all elements which belong to both A and B.
d - difference of two sets, AdB = {x ∈ U : x ∈ A, x ∉ B} is the set of those elements of A which do not belong to B.
s - symmetric difference of two sets, AsB = (AdB)u(BdA) consists of those elements which belong to A or B but not to both.
c - complement of a set, cA = {x ∈ U : x ∉ A}, is set of elements which belong to U but do not belong to A. Unary operator c has higest precedence.
The universal set U is defined as a union of all sets specified in data.
Your task is to determine the result of an expression, which includes sets, set operations and parenthesis (any number of parenthesis and any correct enclosure of parenthesis may take place).
Input
Input consists of several pairs of lines difining sets and one pair of lines defining an expression. Each pair of lines for set definition includes the following.
Line 1: Set name (A, B, C, D, E), number of elements in a set.
Line 2: Set elements separated by blanks.
Pair of lines for expression definition:
Line 1: R 0
Line 2: Expression consisting of set names, operators and parenthesis (no blanks).
Number of sets can vary from 1 to 5. Set names can be specified in any order. Each set consists of 1-100 elements. Pair of lines for expression definition signals the end of data set. Input file includes several data sets. The number of datasets is less than 20.
Output
For each data set, the output should contain one line with resulting set elements sorted in ascending order separated by blanks. If the result contains no set elements then the line should contain the text NULL.
Example
Input
A 3
1 3 -1
B 4
3 1 5 7
D 1
5
R 0
cAiBdD
C 3
1 2 3
A 4
2 10 8 3
B 3
2 4 8
R 0
(As(AiB))uC
Output
7
1 2 3 10 | instruction | 0 | 91,648 | 5 | 183,296 |
"Correct Solution:
```
import sys
def rpn(str):
r = []
stack = []
for i in range(0, len(str)):
c = str[i]
if c in "idsu":
while len(stack) > 0:
if stack[-1] in "idsuc":
a = stack.pop()
r.extend(a)
else:
break
stack.extend(c)
elif c == "c":
stack.extend(c)
elif c == "(":
stack.extend(c)
elif c == ")":
while len(stack) > 0:
a = stack.pop()
if a == "(":
break
r.extend(a)
else:
r.extend(c)
while len(stack) > 0:
a = stack.pop()
r.extend(a)
return r
def intersect(a, b):
r = []
for e in a:
if e in b:
r.extend([e])
return r
def union(a, b):
r = list(set(a + b))
return r
def diff(a, b):
r = []
for e in a:
if e not in b:
r.extend([e])
return r
def universal(sets):
r = []
for v in sets.values():
r.extend(v)
r = list(set(r))
return r
def calc(rpn, sets):
stack = []
U = universal(sets)
for c in rpn:
if c in "iuds":
op2 = stack.pop()
op1 = stack.pop()
if c == "i":
x = intersect(op1, op2)
stack.append(x)
elif c == "u":
x = union(op1, op2)
stack.append(x)
elif c == "d":
x = diff(op1, op2)
stack.append(x)
elif c == "s":
x = diff(op1, op2)
y = diff(op2, op1)
z = union(x, y)
stack.append(z)
elif c == "c":
op1 = stack.pop()
x = diff(U, op1)
stack.append(x)
else:
stack.append(sets[c])
return stack.pop()
lno = 0
sets = {}
name = ""
for line in sys.stdin:
lno += 1
if lno % 2 == 1:
name = line.strip().split()[0]
elif name != "R":
elem = list(map(int, line.strip().split()))
sets[name] = elem
else:
e = rpn(line.strip())
result = calc(e, sets)
result.sort()
if len(result) > 0:
print(" ".join([str(n) for n in result]))
else:
print("NULL")
sets = {}
``` | output | 1 | 91,648 | 5 | 183,297 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let A, B, C, D, E be sets of integers and let U is a universal set that includes all sets under consideration. All elements in any set are different (no repetitions).
u - union of two sets, AuB = {x ∈ U : x ∈ A or x ∈ B} is the set of all elements which belong to A or B.
i - intersection of two sets, AiB = {x ∈ U : x ∈ A and x ∈ B} is the set of all elements which belong to both A and B.
d - difference of two sets, AdB = {x ∈ U : x ∈ A, x ∉ B} is the set of those elements of A which do not belong to B.
s - symmetric difference of two sets, AsB = (AdB)u(BdA) consists of those elements which belong to A or B but not to both.
c - complement of a set, cA = {x ∈ U : x ∉ A}, is set of elements which belong to U but do not belong to A. Unary operator c has higest precedence.
The universal set U is defined as a union of all sets specified in data.
Your task is to determine the result of an expression, which includes sets, set operations and parenthesis (any number of parenthesis and any correct enclosure of parenthesis may take place).
Input
Input consists of several pairs of lines difining sets and one pair of lines defining an expression. Each pair of lines for set definition includes the following.
Line 1: Set name (A, B, C, D, E), number of elements in a set.
Line 2: Set elements separated by blanks.
Pair of lines for expression definition:
Line 1: R 0
Line 2: Expression consisting of set names, operators and parenthesis (no blanks).
Number of sets can vary from 1 to 5. Set names can be specified in any order. Each set consists of 1-100 elements. Pair of lines for expression definition signals the end of data set. Input file includes several data sets. The number of datasets is less than 20.
Output
For each data set, the output should contain one line with resulting set elements sorted in ascending order separated by blanks. If the result contains no set elements then the line should contain the text NULL.
Example
Input
A 3
1 3 -1
B 4
3 1 5 7
D 1
5
R 0
cAiBdD
C 3
1 2 3
A 4
2 10 8 3
B 3
2 4 8
R 0
(As(AiB))uC
Output
7
1 2 3 10
Submitted Solution:
```
import sys
def rpn(str):
r = []
stack = []
for i in range(0, len(str)):
c = str[i]
if c in "idsu":
while len(stack) > 0:
if stack[-1] in "idsuc":
a = stack.pop()
r.extend(a)
else:
break
stack.extend(c)
elif c == "c":
stack.extend(c)
elif c == "(":
stack.extend(c)
elif c == ")":
while len(stack) > 0:
a = stack.pop()
if a == "(":
break
r.extend(a)
else:
r.extend(c)
while len(stack) > 0:
a = stack.pop()
r.extend(a)
return r
def intersect(a, b):
r = []
for e in a:
if e in b:
r.extend([e])
return r
def union(a, b):
r = list(set(a + b))
return r
def diff(a, b):
r = []
for e in a:
if e not in b:
r.extend([e])
return r
def universal(sets):
r = []
for v in sets.values():
r.extend(v)
r = list(set(r))
return r
def calc(rpn, sets):
stack = []
U = universal(sets)
for c in rpn:
if c in "iuds":
op2 = stack.pop()
op1 = stack.pop()
if c == "i":
x = intersect(op1, op2)
stack.append(x)
elif c == "u":
x = union(op1, op2)
stack.append(x)
elif c == "d":
x = diff(op1, op2)
stack.append(x)
elif c == "s":
x = diff(op1, op2)
y = diff(op2, op1)
z = union(x, y)
stack.append(z)
elif c == "c":
op1 = stack.pop()
x = diff(U, op1)
stack.append(x)
else:
stack.append(sets[c])
return stack.pop()
lno = 0
sets = {}
name = ""
for line in sys.stdin:
lno += 1
if lno % 2 == 1:
name = line.strip().split()[0]
elif name != "R":
elem = list(map(int, line.strip().split()))
sets[name] = elem
else:
e = rpn(line.strip())
result = calc(e, sets)
result.sort()
for n in result:
print(n, end = " ")
print()
``` | instruction | 0 | 91,649 | 5 | 183,298 |
No | output | 1 | 91,649 | 5 | 183,299 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let A, B, C, D, E be sets of integers and let U is a universal set that includes all sets under consideration. All elements in any set are different (no repetitions).
u - union of two sets, AuB = {x ∈ U : x ∈ A or x ∈ B} is the set of all elements which belong to A or B.
i - intersection of two sets, AiB = {x ∈ U : x ∈ A and x ∈ B} is the set of all elements which belong to both A and B.
d - difference of two sets, AdB = {x ∈ U : x ∈ A, x ∉ B} is the set of those elements of A which do not belong to B.
s - symmetric difference of two sets, AsB = (AdB)u(BdA) consists of those elements which belong to A or B but not to both.
c - complement of a set, cA = {x ∈ U : x ∉ A}, is set of elements which belong to U but do not belong to A. Unary operator c has higest precedence.
The universal set U is defined as a union of all sets specified in data.
Your task is to determine the result of an expression, which includes sets, set operations and parenthesis (any number of parenthesis and any correct enclosure of parenthesis may take place).
Input
Input consists of several pairs of lines difining sets and one pair of lines defining an expression. Each pair of lines for set definition includes the following.
Line 1: Set name (A, B, C, D, E), number of elements in a set.
Line 2: Set elements separated by blanks.
Pair of lines for expression definition:
Line 1: R 0
Line 2: Expression consisting of set names, operators and parenthesis (no blanks).
Number of sets can vary from 1 to 5. Set names can be specified in any order. Each set consists of 1-100 elements. Pair of lines for expression definition signals the end of data set. Input file includes several data sets. The number of datasets is less than 20.
Output
For each data set, the output should contain one line with resulting set elements sorted in ascending order separated by blanks. If the result contains no set elements then the line should contain the text NULL.
Example
Input
A 3
1 3 -1
B 4
3 1 5 7
D 1
5
R 0
cAiBdD
C 3
1 2 3
A 4
2 10 8 3
B 3
2 4 8
R 0
(As(AiB))uC
Output
7
1 2 3 10
Submitted Solution:
```
import sys
def rpn(str):
r = []
stack = []
for i in range(0, len(str)):
c = str[i]
if c in "idsu":
while len(stack) > 0:
if stack[-1] in "idsuc":
a = stack.pop()
r.extend(a)
else:
break
stack.extend(c)
elif c == "c":
stack.extend(c)
elif c == "(":
stack.extend(c)
elif c == ")":
while len(stack) > 0:
a = stack.pop()
if a == "(":
break
r.extend(a)
else:
r.extend(c)
while len(stack) > 0:
a = stack.pop()
r.extend(a)
return r
def intersect(a, b):
r = []
for e in a:
if e in b:
r.extend([e])
return r
def union(a, b):
r = list(set(a + b))
return r
def diff(a, b):
r = []
for e in a:
if e not in b:
r.extend([e])
return r
def universal(sets):
r = []
for v in sets.values():
r.extend(v)
r = list(set(r))
return r
def calc(rpn, sets):
stack = []
U = universal(sets)
for c in rpn:
if c in "iuds":
op2 = stack.pop()
op1 = stack.pop()
if c == "i":
x = intersect(op1, op2)
stack.append(x)
elif c == "u":
x = union(op1, op2)
stack.append(x)
elif c == "d":
x = diff(op1, op2)
stack.append(x)
elif c == "s":
x = diff(op1, op2)
y = diff(op2, op1)
z = union(x, y)
stack.append(z)
elif c == "c":
op1 = stack.pop()
x = diff(U, op1)
stack.append(x)
else:
stack.append(sets[c])
return stack.pop()
lno = 0
sets = {}
name = ""
for line in sys.stdin:
lno += 1
if lno % 2 == 1:
name = line.strip().split()[0]
elif name != "R":
elem = list(map(int, line.strip().split()))
sets[name] = elem
else:
e = rpn(line.strip())
result = calc(e, sets)
result.sort()
if length(result) > 0:
for n in result:
print(n, end = " ")
print()
else:
print("NULL")
``` | instruction | 0 | 91,650 | 5 | 183,300 |
No | output | 1 | 91,650 | 5 | 183,301 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let A, B, C, D, E be sets of integers and let U is a universal set that includes all sets under consideration. All elements in any set are different (no repetitions).
u - union of two sets, AuB = {x ∈ U : x ∈ A or x ∈ B} is the set of all elements which belong to A or B.
i - intersection of two sets, AiB = {x ∈ U : x ∈ A and x ∈ B} is the set of all elements which belong to both A and B.
d - difference of two sets, AdB = {x ∈ U : x ∈ A, x ∉ B} is the set of those elements of A which do not belong to B.
s - symmetric difference of two sets, AsB = (AdB)u(BdA) consists of those elements which belong to A or B but not to both.
c - complement of a set, cA = {x ∈ U : x ∉ A}, is set of elements which belong to U but do not belong to A. Unary operator c has higest precedence.
The universal set U is defined as a union of all sets specified in data.
Your task is to determine the result of an expression, which includes sets, set operations and parenthesis (any number of parenthesis and any correct enclosure of parenthesis may take place).
Input
Input consists of several pairs of lines difining sets and one pair of lines defining an expression. Each pair of lines for set definition includes the following.
Line 1: Set name (A, B, C, D, E), number of elements in a set.
Line 2: Set elements separated by blanks.
Pair of lines for expression definition:
Line 1: R 0
Line 2: Expression consisting of set names, operators and parenthesis (no blanks).
Number of sets can vary from 1 to 5. Set names can be specified in any order. Each set consists of 1-100 elements. Pair of lines for expression definition signals the end of data set. Input file includes several data sets. The number of datasets is less than 20.
Output
For each data set, the output should contain one line with resulting set elements sorted in ascending order separated by blanks. If the result contains no set elements then the line should contain the text NULL.
Example
Input
A 3
1 3 -1
B 4
3 1 5 7
D 1
5
R 0
cAiBdD
C 3
1 2 3
A 4
2 10 8 3
B 3
2 4 8
R 0
(As(AiB))uC
Output
7
1 2 3 10
Submitted Solution:
```
# -*- coding: utf-8 -*-
from itertools import product
from collections import defaultdict
class cset():
def __init__(self, x):
self.x = set(x)
def __or__(self, that):
return cset(self.x | that.x)
def __sub__(self, that):
return cset(self.x - that.x)
def __and__(self, that):
return cset(self.x & that.x)
def __xor__(self, that):
return cset(self.x ^ that.x)
def __neg__(self):
return cset(U-self.x)
try:
while True:
X = defaultdict(list)
x, _ = input().split()
while x != "R":
X[x] = list(map(int, input().split()))
x, _ = input().split()
A, B, C, D, E = X["A"], X["B"], X["C"], X["D"], X["E"]
U = set()
U.update(A, B, C, D, E)
S = input()
#print(S)
for a, b in zip(list("uidsc"), list("|&-^-")):
S = S.replace(a, b)
#print(S)
for a in list("ABCDE"):
S = S.replace(a, "cset({})".format(a))
#print(S)
ans = sorted(list(eval(S).x))
if len(ans) == 0:
print("NULL")
else:
print(*ans)
except:
pass
``` | instruction | 0 | 91,651 | 5 | 183,302 |
No | output | 1 | 91,651 | 5 | 183,303 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let A, B, C, D, E be sets of integers and let U is a universal set that includes all sets under consideration. All elements in any set are different (no repetitions).
u - union of two sets, AuB = {x ∈ U : x ∈ A or x ∈ B} is the set of all elements which belong to A or B.
i - intersection of two sets, AiB = {x ∈ U : x ∈ A and x ∈ B} is the set of all elements which belong to both A and B.
d - difference of two sets, AdB = {x ∈ U : x ∈ A, x ∉ B} is the set of those elements of A which do not belong to B.
s - symmetric difference of two sets, AsB = (AdB)u(BdA) consists of those elements which belong to A or B but not to both.
c - complement of a set, cA = {x ∈ U : x ∉ A}, is set of elements which belong to U but do not belong to A. Unary operator c has higest precedence.
The universal set U is defined as a union of all sets specified in data.
Your task is to determine the result of an expression, which includes sets, set operations and parenthesis (any number of parenthesis and any correct enclosure of parenthesis may take place).
Input
Input consists of several pairs of lines difining sets and one pair of lines defining an expression. Each pair of lines for set definition includes the following.
Line 1: Set name (A, B, C, D, E), number of elements in a set.
Line 2: Set elements separated by blanks.
Pair of lines for expression definition:
Line 1: R 0
Line 2: Expression consisting of set names, operators and parenthesis (no blanks).
Number of sets can vary from 1 to 5. Set names can be specified in any order. Each set consists of 1-100 elements. Pair of lines for expression definition signals the end of data set. Input file includes several data sets. The number of datasets is less than 20.
Output
For each data set, the output should contain one line with resulting set elements sorted in ascending order separated by blanks. If the result contains no set elements then the line should contain the text NULL.
Example
Input
A 3
1 3 -1
B 4
3 1 5 7
D 1
5
R 0
cAiBdD
C 3
1 2 3
A 4
2 10 8 3
B 3
2 4 8
R 0
(As(AiB))uC
Output
7
1 2 3 10
Submitted Solution:
```
# -*- coding: utf-8 -*-
from itertools import product
from collections import defaultdict
class cset():
def __init__(self, x):
self.x = set(x)
def __or__(self, that):
return cset(self.x | that.x)
def __sub__(self, that):
return cset(self.x - that.x)
def __and__(self, that):
return cset(self.x & that.x)
def __xor__(self, that):
return cset(self.x ^ that.x)
def __neg__(self):
return cset(U-self.x)
try:
while True:
X = defaultdict(list)
x, _ = input().split()
while x != "R":
X[x] = list(map(int, input().split()))
x, _ = input().split()
A, B, C, D, E = X["A"], X["B"], X["C"], X["D"], X["E"]
U = set()
U.update(A, B, C, D, E)
S = input()
for a, b in zip(list("uidsc"), list("|&-^-")):
S = S.replace(a, b)
for a in list("ABCDE"):
S = S.replace(a, "cset({})".format(a))
print(*sorted(list(eval(S).x)))
except:
pass
``` | instruction | 0 | 91,652 | 5 | 183,304 |
No | output | 1 | 91,652 | 5 | 183,305 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,709 | 5 | 183,418 |
"Correct Solution:
```
from collections import defaultdict
def main():
q = int(input())
d = defaultdict(int)
for _ in range(q):
para = input().split()
if para[0] == "0":
d[para[1]] = int(para[2])
elif para[0] == "1":
print(d[para[1]])
elif para[0] == "2":
if para[1] in d.keys():
del d[para[1]]
main()
``` | output | 1 | 91,709 | 5 | 183,419 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,710 | 5 | 183,420 |
"Correct Solution:
```
def main():
q = int(input())
d = {}
for i in range(q):
query = input()
cmd = int(query[0])
if cmd == 0:
_, k, v = query.split(' ')
v = int(v)
d[k] = v
elif cmd == 1:
_, k = query.split(' ')
print(d.get(k, 0))
elif cmd == 2:
_, k = query.split(' ')
if k in d:
del d[k]
if __name__ == '__main__':
main()
``` | output | 1 | 91,710 | 5 | 183,421 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,711 | 5 | 183,422 |
"Correct Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
# FileName: map_delete
# CreatedDate: 2020-07-15 11:23:30 +0900
# LastModified: 2020-07-15 11:29:50 +0900
#
import os
import sys
# import numpy as np
# import pandas as pd
def main():
q = int(input())
dictionary = {}
for _ in range(q):
command = list(input().split())
if command[0] == '0':
dictionary[command[1]] = int(command[2])
elif command[0] == '1':
if command[1] in dictionary.keys():
print(dictionary[command[1]])
else:
print(0)
else:
if command[1] in dictionary.keys():
del dictionary[command[1]]
if __name__ == "__main__":
main()
``` | output | 1 | 91,711 | 5 | 183,423 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,712 | 5 | 183,424 |
"Correct Solution:
```
q = int(input())
dct = {}
for _ in range(q):
cmmd = input().split( )
if cmmd[0] == "0":
dct[cmmd[1]] = int(cmmd[2])
elif cmmd[0] == "1":
try:
print(dct[cmmd[1]])
except:
print(0)
else:
try:
del(dct[cmmd[1]])
except:
pass
``` | output | 1 | 91,712 | 5 | 183,425 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,713 | 5 | 183,426 |
"Correct Solution:
```
import sys
d = {}
input()
for q in sys.stdin:
q = q.split()
if q[0] == '0':
d[q[1]] = q[2]
elif q[0] == '1':
print(d.get(q[1], 0))
else:
if q[1] in d:
del d[q[1]]
``` | output | 1 | 91,713 | 5 | 183,427 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,714 | 5 | 183,428 |
"Correct Solution:
```
q = int(input())
dic = {}
for _ in range(q):
op = list(input().split())
if op[0]=='0':dic[op[1]] = op[2]
elif op[0]=='1':
print ( dic[op[1]] if op[1] in dic.keys() else 0)
else:
try :dic.pop(op[1])
except :pass
``` | output | 1 | 91,714 | 5 | 183,429 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,715 | 5 | 183,430 |
"Correct Solution:
```
class Node:
def __init__(self, key, value):
self.value = value
self.key = key
self.next = None
class HashMap:
def __init__(self, _size=None):
if _size is not None:
assert _size > 0
self._size = _size
self._setsize(2)
self.count = 0
self.nodes = [None] * self.size
def __getitem__(self, key):
node = self.nodes[self.hash(key)]
while node is not None and node.key != key:
node = node.next
if node is not None:
return node.value
else:
raise IndexError('key {} not found in map'.format(key))
def __setitem__(self, key, value):
i = self.hash(key)
node = self.nodes[i]
if node is None:
self.nodes[i] = Node(key, value)
self.count += 1
else:
while node.next is not None and node.key != key:
node = node.next
if node.key == key:
node.value = value
else:
node.next = Node(key, value)
self.count += 1
if self.count == self.size:
self._resize(self.k + 1)
def __delitem__(self, key):
i = self.hash(key)
node = self.nodes[i]
if node is None:
raise IndexError('key {} not found in map'.format(key))
elif node.key == key:
self.nodes[i] = node.next
self.count -= 1
return
while node.next is not None and node.next.key != key:
node = node.next
if node.next is not None:
node.next = node.next.next
self.count -= 1
else:
raise IndexError('key {} not found in map'.format(key))
def items(self):
for node in self.nodes:
n = node
while n is not None:
yield n.key, n.value
n = n.next
def __len__(self):
return self.count
def hash(self, key):
return hash(key) % self.size
def _setsize(self, k):
if self._size is None:
self.k = k
self.size = 2 ** k - 1
else:
self.k = 0
self.size = self._size
def _resize(self, k):
if self._size is not None:
return
nodes = self.nodes
self._setsize(k)
self.nodes = [None] * self.size
self.count = 0
for node in nodes:
n = node
while n is not None:
self.__setitem__(n.key, n.value)
n = n.next
def run():
q = int(input())
m = HashMap()
for _ in range(q):
command, *args = input().split()
if command == '0':
key = args[0]
value = int(args[1])
m[key] = value
elif command == '1':
key = args[0]
try:
print(m[key])
except IndexError:
print(0)
elif command == '2':
key = args[0]
try:
del m[key]
except IndexError:
pass
else:
raise ValueError('invalid command')
if __name__ == '__main__':
run()
``` | output | 1 | 91,715 | 5 | 183,431 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0 | instruction | 0 | 91,716 | 5 | 183,432 |
"Correct Solution:
```
def resolve():
import sys
input = sys.stdin.readline
n = int(input())
ans = dict()
for _ in range(n):
q, key, *x = input().split()
if q == "0":
ans[key] = x[0]
elif q == "1":
if key in ans:
print(ans[key])
else:
print(0)
else:
ans[key] = "0"
resolve()
``` | output | 1 | 91,716 | 5 | 183,433 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0
Submitted Solution:
```
import sys
n = int(input())
d = {}
lines = sys.stdin.readlines()
ans = [None] * n
for i in range(n):
q, *arg = lines[i].split()
if q == '0': # insert
d[arg[0]] = arg[1]
elif q == '1': # get
ans[i] = d[arg[0]] if arg[0] in d else 0
elif q == '2': # delete
if arg[0] in d:
del d[arg[0]]
[print(x) for x in ans if x is not None]
``` | instruction | 0 | 91,717 | 5 | 183,434 |
Yes | output | 1 | 91,717 | 5 | 183,435 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0
Submitted Solution:
```
import bisect
keys=[]
q=int(input())
d={}
def find(x):
index=bisect.bisect_left(keys,x)
if index==len(keys):
return -1
if keys[index]==x:
return index
else:
return -1
for _ in range(q):
query=input().split(" ")
if query[0]=="0":
if find(query[1])!=-1:
pass
else:
bisect.insort_left(keys, query[1])
d[query[1]]=query[2]
elif query[0]=="1":
if find(query[1])!=-1:
print(d[query[1]])
else:
print(0)
elif query[0]=="2":
while find(query[1])>=0:
keys.pop(find(query[1]))
``` | instruction | 0 | 91,718 | 5 | 183,436 |
Yes | output | 1 | 91,718 | 5 | 183,437 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0
Submitted Solution:
```
if __name__ == '__main__':
n = int(input())
d = {}
for i in range(n):
cmd = input().split()
if cmd[0] == "0":
d[cmd[1]] = cmd[2]
elif cmd[0] == "1":
if cmd[1] in d:
print(d[cmd[1]])
else:
print("0")
else:
if cmd[1] in d:
del d[cmd[1]]
``` | instruction | 0 | 91,719 | 5 | 183,438 |
Yes | output | 1 | 91,719 | 5 | 183,439 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0
Submitted Solution:
```
M = {}
for i in range(int(input())):
query = input().split()
if query[0] == '0': M[query[1]] = query[2]
elif query[0] == '1':
if query[1] in M: print(M[query[1]])
else: print(0)
else: M[query[1]] = 0
``` | instruction | 0 | 91,720 | 5 | 183,440 |
Yes | output | 1 | 91,720 | 5 | 183,441 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
Output
1
4
0
0
Submitted Solution:
```
dict = {}
q = int(input())
for i in range(q):
query, *val = input().split(' ')
if query == '0':
dict[val[0]] = int(val[1])
elif query == '1':
print(dict.get(val[0], 0))
else:
dict.pop(val[0])
``` | instruction | 0 | 91,721 | 5 | 183,442 |
No | output | 1 | 91,721 | 5 | 183,443 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence a_1, a_2, ..., a_n consisting of n integers.
You may perform the following operation on this sequence: choose any element and either increase or decrease it by one.
Calculate the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Input
The first line contains two integers n and k (2 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 10^{14}) — the number of elements in the sequence and the maximum number of times you can perform the operation, respectively.
The second line contains a sequence of integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^{9}).
Output
Print the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Examples
Input
4 5
3 1 7 5
Output
2
Input
3 10
100 100 100
Output
0
Input
10 9
4 5 5 7 5 4 5 2 4 3
Output
1
Note
In the first example you can increase the first element twice and decrease the third element twice, so the sequence becomes [3, 3, 5, 5], and the difference between maximum and minimum is 2. You still can perform one operation after that, but it's useless since you can't make the answer less than 2.
In the second example all elements are already equal, so you may get 0 as the answer even without applying any operations.
Submitted Solution:
```
n,k=map(int,input().split())
li=list(map(int,input().split()))
d={}
l=[]
for i in li:
try:
d[i]+=1
except KeyError:
d[i]=1
l.append(i)
l.sort()
z=1
a=0
b=len(l)-1
while k>0:
if a==b:
z=0
break
if d[l[a]]>d[l[b]]:
s=d[l[b]]*(l[b]-l[b-1])
if s<=k:
k-=s
d[l[b-1]]+=d[l[b]]
b-=1
else:
b1=k//d[l[b]]
z=2
break
else:
s=d[l[a]]*(l[a+1]-l[a])
if s<=k:
k-=s
d[l[a+1]]+=d[l[a]]
a+=1
else:
a1=k//d[l[a]]
z=3
break
if z==0:
print(0)
elif z==1:
print(l[b]-l[a])
elif z==2:
print(l[b]-l[a]-b1)
else:
print(l[b]-l[a]-a1)
``` | instruction | 0 | 91,820 | 5 | 183,640 |
Yes | output | 1 | 91,820 | 5 | 183,641 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence a_1, a_2, ..., a_n consisting of n integers.
You may perform the following operation on this sequence: choose any element and either increase or decrease it by one.
Calculate the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Input
The first line contains two integers n and k (2 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 10^{14}) — the number of elements in the sequence and the maximum number of times you can perform the operation, respectively.
The second line contains a sequence of integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^{9}).
Output
Print the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Examples
Input
4 5
3 1 7 5
Output
2
Input
3 10
100 100 100
Output
0
Input
10 9
4 5 5 7 5 4 5 2 4 3
Output
1
Note
In the first example you can increase the first element twice and decrease the third element twice, so the sequence becomes [3, 3, 5, 5], and the difference between maximum and minimum is 2. You still can perform one operation after that, but it's useless since you can't make the answer less than 2.
In the second example all elements are already equal, so you may get 0 as the answer even without applying any operations.
Submitted Solution:
```
n,k=map(int,input().split())
l=list(map(int,input().split()))
l.sort()
i,j=0,n-1
cnt0,cnt1=1,1
left,right=l[0],l[-1]
while(i<j):
if(cnt0<=cnt1):
x=l[i+1]-l[i]
if (cnt0*x)<=k:
k-=cnt0*x
cnt0+=1
i+=1
left=l[i]
else:
num=k//(cnt0)
left=l[i]+num
break
else:
x=l[j]-l[j-1]
if(cnt1*x)<=k:
k-=cnt1*x
cnt1+=1
j-=1
right=l[j]
else:
num=k//cnt1
right=l[j]-num
break
print(right-left)
``` | instruction | 0 | 91,821 | 5 | 183,642 |
Yes | output | 1 | 91,821 | 5 | 183,643 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence a_1, a_2, ..., a_n consisting of n integers.
You may perform the following operation on this sequence: choose any element and either increase or decrease it by one.
Calculate the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Input
The first line contains two integers n and k (2 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 10^{14}) — the number of elements in the sequence and the maximum number of times you can perform the operation, respectively.
The second line contains a sequence of integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^{9}).
Output
Print the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Examples
Input
4 5
3 1 7 5
Output
2
Input
3 10
100 100 100
Output
0
Input
10 9
4 5 5 7 5 4 5 2 4 3
Output
1
Note
In the first example you can increase the first element twice and decrease the third element twice, so the sequence becomes [3, 3, 5, 5], and the difference between maximum and minimum is 2. You still can perform one operation after that, but it's useless since you can't make the answer less than 2.
In the second example all elements are already equal, so you may get 0 as the answer even without applying any operations.
Submitted Solution:
```
n, k = [int(i) for i in input().split(' ')]
a = sorted([int(i) for i in input().split(' ')])
if n == 1:
print(0)
exit()
tot = 0
i, j = 1, n-2
while j - i>=-1:
do = i>(n-j-1)
last = tot
tot += i*(a[i]-a[i-1]) if not do else (n - j - 1)*(a[j+1] - a[j])
if tot >= k:
if do:
a[-1] -= (k - last)//(n-j-1)
else:
a[0] += (k - last)//i
break
if do:
a[-1] = a[j]
j-=1
else:
a[0] = a[i]
i+=1
print(a[-1] - a[0])
``` | instruction | 0 | 91,823 | 5 | 183,646 |
Yes | output | 1 | 91,823 | 5 | 183,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence a_1, a_2, ..., a_n consisting of n integers.
You may perform the following operation on this sequence: choose any element and either increase or decrease it by one.
Calculate the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Input
The first line contains two integers n and k (2 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 10^{14}) — the number of elements in the sequence and the maximum number of times you can perform the operation, respectively.
The second line contains a sequence of integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^{9}).
Output
Print the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Examples
Input
4 5
3 1 7 5
Output
2
Input
3 10
100 100 100
Output
0
Input
10 9
4 5 5 7 5 4 5 2 4 3
Output
1
Note
In the first example you can increase the first element twice and decrease the third element twice, so the sequence becomes [3, 3, 5, 5], and the difference between maximum and minimum is 2. You still can perform one operation after that, but it's useless since you can't make the answer less than 2.
In the second example all elements are already equal, so you may get 0 as the answer even without applying any operations.
Submitted Solution:
```
from math import *
n,k = map(int,input().split())
l = list(map(int,input().split()))
d = dict()
for i in l:
if i not in d:
d[i] = 1
else:
d[i] += 1
l = list(set(l))
l.sort()
n1 = len(l)
i = 0
cs = d[l[0]]
cl = d[l[-1]]
if(n1 == 1):
print(0)
else:
#print(l)
while(k > 0 and i < n1//2):
#print(k)
diff = l[i+1] - l[i]
diff = diff*cs
#print(diff)
if(diff > k):
l[i] += k//cs
print(l[n1-1-i] - l[i])
break
else:
k -= diff
cs += d[l[i+1]]
diff = l[n1-1-i] - l[n1-2-i]
diff = diff *cl
#print(diff)
if(diff > k):
l[n1-1-i] -= k//cl
print(l[n1-1-i] - l[i+1])
break
else:
k -= diff
cl += d[l[n1-2-i]]
i += 1
else:
print(0)
``` | instruction | 0 | 91,824 | 5 | 183,648 |
No | output | 1 | 91,824 | 5 | 183,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence a_1, a_2, ..., a_n consisting of n integers.
You may perform the following operation on this sequence: choose any element and either increase or decrease it by one.
Calculate the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Input
The first line contains two integers n and k (2 ≤ n ≤ 10^{5}, 1 ≤ k ≤ 10^{14}) — the number of elements in the sequence and the maximum number of times you can perform the operation, respectively.
The second line contains a sequence of integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^{9}).
Output
Print the minimum possible difference between the maximum element and the minimum element in the sequence, if you can perform the aforementioned operation no more than k times.
Examples
Input
4 5
3 1 7 5
Output
2
Input
3 10
100 100 100
Output
0
Input
10 9
4 5 5 7 5 4 5 2 4 3
Output
1
Note
In the first example you can increase the first element twice and decrease the third element twice, so the sequence becomes [3, 3, 5, 5], and the difference between maximum and minimum is 2. You still can perform one operation after that, but it's useless since you can't make the answer less than 2.
In the second example all elements are already equal, so you may get 0 as the answer even without applying any operations.
Submitted Solution:
```
def main():
n,k=readIntArr()
a=readIntArr()
a.sort()
p=a.copy()
for i in range(1,n):
p[i]+=p[i-1]
def getSum(l,r):
if l==0: return p[r]
else: return p[r]-p[l-1]
def raiseLowerLimit(lowerLimit): # returns the number of steps required
i=-1
b=n
while b>0:
while i+b<n and a[i+b]<lowerLimit:
i+=b
b//=2
if i==-1: return 0
return lowerLimit*(i+1)-getSum(0,i)
def decreaseUpperLimit(upperLimit): # returns the number of steps required
r=n
b=n
while b>0:
while r-b>=0 and a[r-b]>upperLimit:
r-=b
b//=2
if r==n: return 0
return getSum(r,n-1)-upperLimit*(n-r)
def findMinDiff(lower): # return the minimum difference given lower
kLeft=k-raiseLowerLimit(lower)
if kLeft<0: return inf
b=k
optimalUpper=a[n-1]
if lower>optimalUpper: return 0
while b>0:
while optimalUpper-b>=lower and decreaseUpperLimit(optimalUpper-b)<=kLeft:
optimalUpper-=b
b//=2
# print('lower:{} kLeft:{}'.format(lower,kLeft))
return optimalUpper-lower
optimalLower=a[0]
b=k
while b>0:
while findMinDiff(optimalLower+b)<findMinDiff(optimalLower):
optimalLower+=b
b//=2
ans=findMinDiff(optimalLower)
print(ans)
# print(findMinDiff(1))
# print('optimal lower:{}'.format(optimalLower))
# for l in range(a[0],a[n-1]+1):
# print('lower:{} minDiff:{}'.format(l,findMinDiff(l)))
# print()
# print('decreaseUpper:{}'.format(decreaseUpperLimit(4)))
return
import sys
input=sys.stdin.buffer.readline #FOR READING PURE INTEGER INPUTS (space separation ok)
# input=lambda: sys.stdin.readline().rstrip("\r\n") #FOR READING STRING/TEXT INPUTS.
def oneLineArrayPrint(arr):
print(' '.join([str(x) for x in arr]))
def multiLineArrayPrint(arr):
print('\n'.join([str(x) for x in arr]))
def multiLineArrayOfArraysPrint(arr):
print('\n'.join([' '.join([str(x) for x in y]) for y in arr]))
def readIntArr():
return [int(x) for x in input().split()]
# def readFloatArr():
# return [float(x) for x in input().split()]
def makeArr(defaultVal,dimensionArr): # eg. makeArr(0,[n,m])
dv=defaultVal;da=dimensionArr
if len(da)==1:return [dv for _ in range(da[0])]
else:return [makeArr(dv,da[1:]) for _ in range(da[0])]
def queryInteractive(x,y):
print('? {} {}'.format(x,y))
sys.stdout.flush()
return int(input())
def answerInteractive(ans):
print('! {}'.format(ans))
sys.stdout.flush()
inf=float('inf')
MOD=10**9+7
# MOD=998244353
for _abc in range(1):
main()
``` | instruction | 0 | 91,826 | 5 | 183,652 |
No | output | 1 | 91,826 | 5 | 183,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
# -*- coding:utf-8 -*-
"""
created by shuangquan.huang at 2020/7/2
"""
import collections
import time
import os
import sys
import bisect
import heapq
from typing import List
def solve(D, M):
ans = 1
for i in range(30):
if D < (1 << i):
break
ans *= (min((1 << (i+1))-1, D) - (1 << i) + 2)
ans %= M
ans -= 1
if ans < 0:
ans += M
return ans
if __name__ == '__main__':
T = int(input())
ans = []
for ti in range(T):
D, M = map(int, input().split())
ans.append(solve(D, M))
print('\n'.join(map(str, ans)))
``` | instruction | 0 | 91,868 | 5 | 183,736 |
Yes | output | 1 | 91,868 | 5 | 183,737 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
t = int(input())
for _ in range(t):
d,m = map(int,input().split())
pot = [1]*1000
for i in range(1,1000):
pot[i] = (2*pot[i-1])%m
makscyfr = 0
dd = d
while dd > 0:
makscyfr += 1
dd //= 2
dp = [0]*(makscyfr+1)
dp[1] = 1
for i in range(2,makscyfr+1):
s = 1
for j in range(1,i):
s += dp[j]
s *= pot[i-1]
s %= m
dp[i] = s
ii = 0
while 2**(ii+1) <= d:
ii += 1
odp = 0
for kk in range(1,makscyfr):
odp += dp[kk]
#a co jak a_n jest miedzy 2^ii, d
mno = d+1-2**ii
for j in range(1,ii+1):
odp += mno*dp[j]
odp += mno
odp %= m
print(odp)
``` | instruction | 0 | 91,869 | 5 | 183,738 |
Yes | output | 1 | 91,869 | 5 | 183,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
def main():
# Seems like a[i] must have its most significant bit to be 1 more than that
# of a[i-1].
t=int(input())
allans=[]
for _ in range(t):
d,m=readIntArr()
dMSB=0
d2=d
while d2>0:
dMSB+=1
d2=d2>>1
nWaysAtThisMSB=[0 for _ in range(dMSB+1)]
for msb in range(1,dMSB):
nWaysAtThisMSB[msb]=pow(2,msb-1,m)
#last msb only has d-(2**(dMSB-1)-1) ways
nWaysAtThisMSB[dMSB]=(d-(2**(dMSB-1)-1))%m
dp=[0 for _ in range(dMSB+1)]
for i in range(1,dMSB+1):
dp[i]+=dp[i-1] #don't take current MSB
dp[i]%=m
dp[i]+=nWaysAtThisMSB[i]#take current MSB alone
dp[i]%=m
dp[i]+=dp[i-1]*nWaysAtThisMSB[i]#take current MSB with previous items
dp[i]%=m
allans.append(dp[dMSB])
# print(nWaysAtThisMSB)
# print(dp)
multiLineArrayPrint(allans)
return
#import sys
#input=sys.stdin.buffer.readline #FOR READING PURE INTEGER INPUTS (space separation ok)
import sys
input=lambda: sys.stdin.readline().rstrip("\r\n") #FOR READING STRING/TEXT INPUTS.
def oneLineArrayPrint(arr):
print(' '.join([str(x) for x in arr]))
def multiLineArrayPrint(arr):
print('\n'.join([str(x) for x in arr]))
def multiLineArrayOfArraysPrint(arr):
print('\n'.join([' '.join([str(x) for x in y]) for y in arr]))
def readIntArr():
return [int(x) for x in input().split()]
inf=float('inf')
MOD=10**9+7
main()
``` | instruction | 0 | 91,870 | 5 | 183,740 |
Yes | output | 1 | 91,870 | 5 | 183,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
for _ in range(int(input())):
d, m = map(int, input().split())
ans = 1
for i in range(1, 31):
l = max(1, 1 << (i - 1))
r = min(d, (1 << i) - 1)
#print(l, r, i)
ans = (ans * (1 + (r - l + 1))) % m
if r == d:
break
print((ans - 1 + m) % m)
``` | instruction | 0 | 91,871 | 5 | 183,742 |
Yes | output | 1 | 91,871 | 5 | 183,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
import sys
input = sys.stdin.readline
if __name__ == "__main__":
t = int(input())
for _ in range(t):
d, m = [int(a) for a in input().split()]
start = 1
end = 2
total = 1
if m == 1:
print(0)
continue
while start <= d:
total *= min(end, d+1) - start + 1
total %= m
start *= 2
end *= 2
# print(total)
print(total-1)
# print('done')
``` | instruction | 0 | 91,872 | 5 | 183,744 |
No | output | 1 | 91,872 | 5 | 183,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
def go():
d, m = map(int, input().split())
i = d.bit_length()
res = 0
while i >= 0:
bi = 1 << i
if d >= bi:
res += bitvals[i] * (d - bi + 1)
res = res%m
d=bi-1
i -= 1
return res%m
bitvals = [1]
for i in range(12):
bitvals.append(bitvals[-1] * (2 ** i + 1))
print(bitvals)
# x,s = map(int,input().split())
t = int(input())
# t = 1
ans = []
for _ in range(t):
# print(go())
ans.append(str(go()))
#
print('\n'.join(ans))
``` | instruction | 0 | 91,873 | 5 | 183,746 |
No | output | 1 | 91,873 | 5 | 183,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
import sys
from math import log2,floor,ceil,sqrt
# import bisect
# from collections import deque
# from types import GeneratorType
# def bootstrap(func, stack=[]):
# def wrapped_function(*args, **kwargs):
# if stack:
# return func(*args, **kwargs)
# else:
# call = func(*args, **kwargs)
# while True:
# if type(call) is GeneratorType:
# stack.append(call)
# call = next(call)
# else:
# stack.pop()
# if not stack:
# break
# call = stack[-1].send(call)
# return call
# return wrapped_function
Ri = lambda : [int(x) for x in sys.stdin.readline().split()]
ri = lambda : sys.stdin.readline().strip()
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
INF = 10 ** 18
MOD = 10**9+7
for _ in range(int(ri())):
d,m = Ri()
ans = 0
# cur= 0
prod = 1
for i in range(1,33):
no = (1<<(i))-1
no = min(no,d)
cut = (1<<(i-1))-1
# print(no,cut)
noway = no-cut
if noway <= 0:
break
prod = (noway+1)*prod
prod = prod%m
# ans = ans + prod
# ans= ans%m
if prod <= 0:
print(0)
else:
print(prod-1)
``` | instruction | 0 | 91,874 | 5 | 183,748 |
No | output | 1 | 91,874 | 5 | 183,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dreamoon likes sequences very much. So he created a problem about the sequence that you can't find in OEIS:
You are given two integers d, m, find the number of arrays a, satisfying the following constraints:
* The length of a is n, n ≥ 1
* 1 ≤ a_1 < a_2 < ... < a_n ≤ d
* Define an array b of length n as follows: b_1 = a_1, ∀ i > 1, b_i = b_{i - 1} ⊕ a_i, where ⊕ is the bitwise exclusive-or (xor). After constructing an array b, the constraint b_1 < b_2 < ... < b_{n - 1} < b_n should hold.
Since the number of possible arrays may be too large, you need to find the answer modulo m.
Input
The first line contains an integer t (1 ≤ t ≤ 100) denoting the number of test cases in the input.
Each of the next t lines contains two integers d, m (1 ≤ d, m ≤ 10^9).
Note that m is not necessary the prime!
Output
For each test case, print the number of arrays a, satisfying all given constrains, modulo m.
Example
Input
10
1 1000000000
2 999999999
3 99999998
4 9999997
5 999996
6 99995
7 9994
8 993
9 92
10 1
Output
1
3
5
11
17
23
29
59
89
0
Submitted Solution:
```
import math
a=[1]*(31)
for i in range(31):
a[i]=1<<i
t=int(input())
while t:
t-=1
n,m=map(int,input().strip().split(' '))
k=int(math.log2(n))
prod=1
for i in range(k):
prod=(prod*(a[i]+1))%m
r=(n-a[k]+1)
prod=(prod*(r+1))%m
print(max(prod-1,0))
``` | instruction | 0 | 91,875 | 5 | 183,750 |
No | output | 1 | 91,875 | 5 | 183,751 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Slime has a sequence of positive integers a_1, a_2, …, a_n.
In one operation Orac can choose an arbitrary subsegment [l … r] of this sequence and replace all values a_l, a_{l + 1}, …, a_r to the value of median of \\{a_l, a_{l + 1}, …, a_r\}.
In this problem, for the integer multiset s, the median of s is equal to the ⌊ (|s|+1)/(2)⌋-th smallest number in it. For example, the median of \{1,4,4,6,5\} is 4, and the median of \{1,7,5,8\} is 5.
Slime wants Orac to make a_1 = a_2 = … = a_n = k using these operations.
Orac thinks that it is impossible, and he does not want to waste his time, so he decided to ask you if it is possible to satisfy the Slime's requirement, he may ask you these questions several times.
Input
The first line of the input is a single integer t: the number of queries.
The first line of each query contains two integers n\ (1≤ n≤ 100 000) and k\ (1≤ k≤ 10^9), the second line contains n positive integers a_1,a_2,...,a_n\ (1≤ a_i≤ 10^9)
The total sum of n is at most 100 000.
Output
The output should contain t lines. The i-th line should be equal to 'yes' if it is possible to make all integers k in some number of operations or 'no', otherwise. You can print each letter in lowercase or uppercase.
Example
Input
5
5 3
1 5 2 6 1
1 6
6
3 2
1 2 3
4 3
3 1 2 3
10 3
1 2 3 4 5 6 7 8 9 10
Output
no
yes
yes
no
yes
Note
In the first query, Orac can't turn all elements into 3.
In the second query, a_1=6 is already satisfied.
In the third query, Orac can select the complete array and turn all elements into 2.
In the fourth query, Orac can't turn all elements into 3.
In the fifth query, Orac can select [1,6] at first and then select [2,10].
Submitted Solution:
```
import sys
input = sys.stdin.readline
from itertools import accumulate
t = int(input())
for _ in range(t):
n,k = map(int,input().split())
a = list(map(int,input().split()))
if k not in a:
print("no")
continue
if n == 1:
print("yes")
continue
for i in range(1,n):
if a[i] >= k and a[i-1] >= k:
print("yes")
break
if i >= 2:
if a[i] >= k and a[i-2] >= k:
print("yes")
break
else:
print("no")
``` | instruction | 0 | 91,884 | 5 | 183,768 |
Yes | output | 1 | 91,884 | 5 | 183,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Slime has a sequence of positive integers a_1, a_2, …, a_n.
In one operation Orac can choose an arbitrary subsegment [l … r] of this sequence and replace all values a_l, a_{l + 1}, …, a_r to the value of median of \\{a_l, a_{l + 1}, …, a_r\}.
In this problem, for the integer multiset s, the median of s is equal to the ⌊ (|s|+1)/(2)⌋-th smallest number in it. For example, the median of \{1,4,4,6,5\} is 4, and the median of \{1,7,5,8\} is 5.
Slime wants Orac to make a_1 = a_2 = … = a_n = k using these operations.
Orac thinks that it is impossible, and he does not want to waste his time, so he decided to ask you if it is possible to satisfy the Slime's requirement, he may ask you these questions several times.
Input
The first line of the input is a single integer t: the number of queries.
The first line of each query contains two integers n\ (1≤ n≤ 100 000) and k\ (1≤ k≤ 10^9), the second line contains n positive integers a_1,a_2,...,a_n\ (1≤ a_i≤ 10^9)
The total sum of n is at most 100 000.
Output
The output should contain t lines. The i-th line should be equal to 'yes' if it is possible to make all integers k in some number of operations or 'no', otherwise. You can print each letter in lowercase or uppercase.
Example
Input
5
5 3
1 5 2 6 1
1 6
6
3 2
1 2 3
4 3
3 1 2 3
10 3
1 2 3 4 5 6 7 8 9 10
Output
no
yes
yes
no
yes
Note
In the first query, Orac can't turn all elements into 3.
In the second query, a_1=6 is already satisfied.
In the third query, Orac can select the complete array and turn all elements into 2.
In the fourth query, Orac can't turn all elements into 3.
In the fifth query, Orac can select [1,6] at first and then select [2,10].
Submitted Solution:
```
import sys
import math
from collections import defaultdict
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
def solve(test):
n, k = map(int, input().split())
a = list(map(int, input().split()))
a += [0, 0]
if n == 1 and a[0] == k:
print('yes')
return
flag1, flag2 = 0, 0
for i in range(n):
if a[i] == k:
flag1 = 1
if a[i] >= k:
if a[i + 1] >= k or a[i + 2] >= k:
flag2 = 1
print('yes' if flag1 and flag2 else 'no')
if __name__ == "__main__":
test_cases = int(input())
for t in range(1, test_cases + 1):
solve(t)
``` | instruction | 0 | 91,885 | 5 | 183,770 |
Yes | output | 1 | 91,885 | 5 | 183,771 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Slime has a sequence of positive integers a_1, a_2, …, a_n.
In one operation Orac can choose an arbitrary subsegment [l … r] of this sequence and replace all values a_l, a_{l + 1}, …, a_r to the value of median of \\{a_l, a_{l + 1}, …, a_r\}.
In this problem, for the integer multiset s, the median of s is equal to the ⌊ (|s|+1)/(2)⌋-th smallest number in it. For example, the median of \{1,4,4,6,5\} is 4, and the median of \{1,7,5,8\} is 5.
Slime wants Orac to make a_1 = a_2 = … = a_n = k using these operations.
Orac thinks that it is impossible, and he does not want to waste his time, so he decided to ask you if it is possible to satisfy the Slime's requirement, he may ask you these questions several times.
Input
The first line of the input is a single integer t: the number of queries.
The first line of each query contains two integers n\ (1≤ n≤ 100 000) and k\ (1≤ k≤ 10^9), the second line contains n positive integers a_1,a_2,...,a_n\ (1≤ a_i≤ 10^9)
The total sum of n is at most 100 000.
Output
The output should contain t lines. The i-th line should be equal to 'yes' if it is possible to make all integers k in some number of operations or 'no', otherwise. You can print each letter in lowercase or uppercase.
Example
Input
5
5 3
1 5 2 6 1
1 6
6
3 2
1 2 3
4 3
3 1 2 3
10 3
1 2 3 4 5 6 7 8 9 10
Output
no
yes
yes
no
yes
Note
In the first query, Orac can't turn all elements into 3.
In the second query, a_1=6 is already satisfied.
In the third query, Orac can select the complete array and turn all elements into 2.
In the fourth query, Orac can't turn all elements into 3.
In the fifth query, Orac can select [1,6] at first and then select [2,10].
Submitted Solution:
```
import sys
ints = (int(x) for x in sys.stdin.read().split())
sys.setrecursionlimit(3000)
def solve(a):
n = len(a)
def main():
ntc = next(ints)
for tc in range(1,ntc+1):
n, k = (next(ints) for i in range(2))
a = (next(ints) for i in range(n))
a = [1 if x>k else -1 if x<k else 0 for x in a]
ans = 0 in a
ans = ans and (
len(a)==1 or
any(a[i]>=0 and a[i+1]>=0 for i in range(n-1)) or
any(a[i]>=0 and a[i+2]>=0 for i in range(n-2))
)
print('yes' if ans else 'no')
return
main()
``` | instruction | 0 | 91,886 | 5 | 183,772 |
Yes | output | 1 | 91,886 | 5 | 183,773 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Slime has a sequence of positive integers a_1, a_2, …, a_n.
In one operation Orac can choose an arbitrary subsegment [l … r] of this sequence and replace all values a_l, a_{l + 1}, …, a_r to the value of median of \\{a_l, a_{l + 1}, …, a_r\}.
In this problem, for the integer multiset s, the median of s is equal to the ⌊ (|s|+1)/(2)⌋-th smallest number in it. For example, the median of \{1,4,4,6,5\} is 4, and the median of \{1,7,5,8\} is 5.
Slime wants Orac to make a_1 = a_2 = … = a_n = k using these operations.
Orac thinks that it is impossible, and he does not want to waste his time, so he decided to ask you if it is possible to satisfy the Slime's requirement, he may ask you these questions several times.
Input
The first line of the input is a single integer t: the number of queries.
The first line of each query contains two integers n\ (1≤ n≤ 100 000) and k\ (1≤ k≤ 10^9), the second line contains n positive integers a_1,a_2,...,a_n\ (1≤ a_i≤ 10^9)
The total sum of n is at most 100 000.
Output
The output should contain t lines. The i-th line should be equal to 'yes' if it is possible to make all integers k in some number of operations or 'no', otherwise. You can print each letter in lowercase or uppercase.
Example
Input
5
5 3
1 5 2 6 1
1 6
6
3 2
1 2 3
4 3
3 1 2 3
10 3
1 2 3 4 5 6 7 8 9 10
Output
no
yes
yes
no
yes
Note
In the first query, Orac can't turn all elements into 3.
In the second query, a_1=6 is already satisfied.
In the third query, Orac can select the complete array and turn all elements into 2.
In the fourth query, Orac can't turn all elements into 3.
In the fifth query, Orac can select [1,6] at first and then select [2,10].
Submitted Solution:
```
from sys import stdin
input = stdin.buffer.readline
for _ in range(int(input())):
n, k = map(int, input().split())
*a, = map(int, input().split())
if k not in a:
print('No')
continue
if n == 1:
print('Yes')
continue
for i in range(n - 1):
if a[i] >= k and a[i + 1] >= k:
print('Yes')
break
else:
for i in range(n - 2):
if a[i] >= k and a[i + 2] >= k:
print('Yes')
break
else:
print('No')
``` | instruction | 0 | 91,887 | 5 | 183,774 |
Yes | output | 1 | 91,887 | 5 | 183,775 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Slime has a sequence of positive integers a_1, a_2, …, a_n.
In one operation Orac can choose an arbitrary subsegment [l … r] of this sequence and replace all values a_l, a_{l + 1}, …, a_r to the value of median of \\{a_l, a_{l + 1}, …, a_r\}.
In this problem, for the integer multiset s, the median of s is equal to the ⌊ (|s|+1)/(2)⌋-th smallest number in it. For example, the median of \{1,4,4,6,5\} is 4, and the median of \{1,7,5,8\} is 5.
Slime wants Orac to make a_1 = a_2 = … = a_n = k using these operations.
Orac thinks that it is impossible, and he does not want to waste his time, so he decided to ask you if it is possible to satisfy the Slime's requirement, he may ask you these questions several times.
Input
The first line of the input is a single integer t: the number of queries.
The first line of each query contains two integers n\ (1≤ n≤ 100 000) and k\ (1≤ k≤ 10^9), the second line contains n positive integers a_1,a_2,...,a_n\ (1≤ a_i≤ 10^9)
The total sum of n is at most 100 000.
Output
The output should contain t lines. The i-th line should be equal to 'yes' if it is possible to make all integers k in some number of operations or 'no', otherwise. You can print each letter in lowercase or uppercase.
Example
Input
5
5 3
1 5 2 6 1
1 6
6
3 2
1 2 3
4 3
3 1 2 3
10 3
1 2 3 4 5 6 7 8 9 10
Output
no
yes
yes
no
yes
Note
In the first query, Orac can't turn all elements into 3.
In the second query, a_1=6 is already satisfied.
In the third query, Orac can select the complete array and turn all elements into 2.
In the fourth query, Orac can't turn all elements into 3.
In the fifth query, Orac can select [1,6] at first and then select [2,10].
Submitted Solution:
```
import sys
import math
import bisect
def main():
for _ in range(int(input())):
n, m = map(int, input().split())
A = list(map(int, input().split()))
ans = False
if len(A) == 1 and A[0] == m:
ans = True
for i in range(n):
if A[i] == m and i + 1 < n and A[i+1] >= A[i]:
ans = True
break
if ans:
print('yes')
else:
print('no')
if __name__ == "__main__":
main()
``` | instruction | 0 | 91,888 | 5 | 183,776 |
No | output | 1 | 91,888 | 5 | 183,777 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Slime has a sequence of positive integers a_1, a_2, …, a_n.
In one operation Orac can choose an arbitrary subsegment [l … r] of this sequence and replace all values a_l, a_{l + 1}, …, a_r to the value of median of \\{a_l, a_{l + 1}, …, a_r\}.
In this problem, for the integer multiset s, the median of s is equal to the ⌊ (|s|+1)/(2)⌋-th smallest number in it. For example, the median of \{1,4,4,6,5\} is 4, and the median of \{1,7,5,8\} is 5.
Slime wants Orac to make a_1 = a_2 = … = a_n = k using these operations.
Orac thinks that it is impossible, and he does not want to waste his time, so he decided to ask you if it is possible to satisfy the Slime's requirement, he may ask you these questions several times.
Input
The first line of the input is a single integer t: the number of queries.
The first line of each query contains two integers n\ (1≤ n≤ 100 000) and k\ (1≤ k≤ 10^9), the second line contains n positive integers a_1,a_2,...,a_n\ (1≤ a_i≤ 10^9)
The total sum of n is at most 100 000.
Output
The output should contain t lines. The i-th line should be equal to 'yes' if it is possible to make all integers k in some number of operations or 'no', otherwise. You can print each letter in lowercase or uppercase.
Example
Input
5
5 3
1 5 2 6 1
1 6
6
3 2
1 2 3
4 3
3 1 2 3
10 3
1 2 3 4 5 6 7 8 9 10
Output
no
yes
yes
no
yes
Note
In the first query, Orac can't turn all elements into 3.
In the second query, a_1=6 is already satisfied.
In the third query, Orac can select the complete array and turn all elements into 2.
In the fourth query, Orac can't turn all elements into 3.
In the fifth query, Orac can select [1,6] at first and then select [2,10].
Submitted Solution:
```
for t in range (int(input())):
n,k=map(int,input().split())
a=list(map(int,input().split()))
i=-1
c=0
ch=0
for j in range (n):
if a[j]==k:
c+=1
i=j+1
if a[j]>=k and j<n-2:
for m in range (i+1,i+3):
if a[m]>=k:
ch=1
if a[j]>=k and j==n-2:
if a[n-1]>=k:
ch=1
if c>0 and (ch>0 or n==1):
print("yes")
else:
print("no")
``` | instruction | 0 | 91,889 | 5 | 183,778 |
No | output | 1 | 91,889 | 5 | 183,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Slime has a sequence of positive integers a_1, a_2, …, a_n.
In one operation Orac can choose an arbitrary subsegment [l … r] of this sequence and replace all values a_l, a_{l + 1}, …, a_r to the value of median of \\{a_l, a_{l + 1}, …, a_r\}.
In this problem, for the integer multiset s, the median of s is equal to the ⌊ (|s|+1)/(2)⌋-th smallest number in it. For example, the median of \{1,4,4,6,5\} is 4, and the median of \{1,7,5,8\} is 5.
Slime wants Orac to make a_1 = a_2 = … = a_n = k using these operations.
Orac thinks that it is impossible, and he does not want to waste his time, so he decided to ask you if it is possible to satisfy the Slime's requirement, he may ask you these questions several times.
Input
The first line of the input is a single integer t: the number of queries.
The first line of each query contains two integers n\ (1≤ n≤ 100 000) and k\ (1≤ k≤ 10^9), the second line contains n positive integers a_1,a_2,...,a_n\ (1≤ a_i≤ 10^9)
The total sum of n is at most 100 000.
Output
The output should contain t lines. The i-th line should be equal to 'yes' if it is possible to make all integers k in some number of operations or 'no', otherwise. You can print each letter in lowercase or uppercase.
Example
Input
5
5 3
1 5 2 6 1
1 6
6
3 2
1 2 3
4 3
3 1 2 3
10 3
1 2 3 4 5 6 7 8 9 10
Output
no
yes
yes
no
yes
Note
In the first query, Orac can't turn all elements into 3.
In the second query, a_1=6 is already satisfied.
In the third query, Orac can select the complete array and turn all elements into 2.
In the fourth query, Orac can't turn all elements into 3.
In the fifth query, Orac can select [1,6] at first and then select [2,10].
Submitted Solution:
```
def main():
t = int(input())
for i in range(t):
solve()
def solve():
n, k = list(map(int, input().split(" ")))
arr = list(map(int, input().split(" ")))
if k not in arr:
print('no')
return
if len(set(arr)) == 1:
print('yes')
return
index = arr.index(k)
if max(arr) == k:
print('no')
return
if (0 < index) and (index < len(arr) - 1) and (arr[index + 1] >= k or arr[index - 1] >= k):
print('yes')
return
print('no')
main()
``` | instruction | 0 | 91,890 | 5 | 183,780 |
No | output | 1 | 91,890 | 5 | 183,781 |
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