message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number of sequences of N non-negative integers A_1, A_2, ..., A_N that satisfy the following conditions:
* L \leq A_1 + A_2 + ... + A_N \leq R
* When the N elements are sorted in non-increasing order, the M-th and (M+1)-th elements are equal.
Since the answer can be enormous, print it modulo 10^9+7.
Constraints
* All values in input are integers.
* 1 \leq M < N \leq 3 \times 10^5
* 1 \leq L \leq R \leq 3 \times 10^5
Input
Input is given from Standard Input in the following format:
N M L R
Output
Print the number of sequences of N non-negative integers, modulo 10^9+7.
Examples
Input
4 2 3 7
Output
105
Input
2 1 4 8
Output
3
Input
141592 6535 89793 238462
Output
933832916
Submitted Solution:
```
# -*- coding: utf-8 -*-
#############
# Libraries #
#############
import sys
input = sys.stdin.readline
import math
#from math import gcd
import bisect
import heapq
from collections import defaultdict
from collections import deque
from collections import Counter
from functools import lru_cache
#############
# Constants #
#############
MOD = 10**9+7
INF = float('inf')
AZ = "abcdefghijklmnopqrstuvwxyz"
#############
# Functions #
#############
######INPUT######
def I(): return int(input().strip())
def S(): return input().strip()
def IL(): return list(map(int,input().split()))
def SL(): return list(map(str,input().split()))
def ILs(n): return list(int(input()) for _ in range(n))
def SLs(n): return list(input().strip() for _ in range(n))
def ILL(n): return [list(map(int, input().split())) for _ in range(n)]
def SLL(n): return [list(map(str, input().split())) for _ in range(n)]
######OUTPUT######
def P(arg): print(arg); return
def Y(): print("Yes"); return
def N(): print("No"); return
def E(): exit()
def PE(arg): print(arg); exit()
def YE(): print("Yes"); exit()
def NE(): print("No"); exit()
#####Shorten#####
def DD(arg): return defaultdict(arg)
#####Inverse#####
def inv(n): return pow(n, MOD-2, MOD)
######Combination######
kaijo_memo = []
def kaijo(n):
if(len(kaijo_memo) > n): return kaijo_memo[n]
if(len(kaijo_memo) == 0): kaijo_memo.append(1)
while(len(kaijo_memo) <= n): kaijo_memo.append(kaijo_memo[-1] * len(kaijo_memo) % MOD)
return kaijo_memo[n]
gyaku_kaijo_memo = []
def gyaku_kaijo(n):
if(len(gyaku_kaijo_memo) > n): return gyaku_kaijo_memo[n]
if(len(gyaku_kaijo_memo) == 0): gyaku_kaijo_memo.append(1)
while(len(gyaku_kaijo_memo) <= n): gyaku_kaijo_memo.append(gyaku_kaijo_memo[-1] * pow(len(gyaku_kaijo_memo),MOD-2,MOD) % MOD)
return gyaku_kaijo_memo[n]
def nCr(n,r):
if n == r: return 1
if n < r or r < 0: return 0
ret = 1
ret = ret * kaijo(n) % MOD
ret = ret * gyaku_kaijo(r) % MOD
ret = ret * gyaku_kaijo(n-r) % MOD
return ret
######Factorization######
def factorization(n):
arr = []
temp = n
for i in range(2, int(-(-n**0.5//1))+1):
if temp%i==0:
cnt=0
while temp%i==0:
cnt+=1
temp //= i
arr.append([i, cnt])
if temp!=1: arr.append([temp, 1])
if arr==[]: arr.append([n, 1])
return arr
#####MakeDivisors######
def make_divisors(n):
divisors = []
for i in range(1, int(n**0.5)+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n//i)
return divisors
#####MakePrimes######
def make_primes(N):
max = int(math.sqrt(N))
seachList = [i for i in range(2,N+1)]
primeNum = []
while seachList[0] <= max:
primeNum.append(seachList[0])
tmp = seachList[0]
seachList = [i for i in seachList if i % tmp != 0]
primeNum.extend(seachList)
return primeNum
#####GCD#####
def gcd(a, b):
while b: a, b = b, a % b
return a
#####LCM#####
def lcm(a, b):
return a * b // gcd (a, b)
#####BitCount#####
def count_bit(n):
count = 0
while n:
n &= n-1
count += 1
return count
#####ChangeBase#####
def base_10_to_n(X, n):
if X//n: return base_10_to_n(X//n, n)+[X%n]
return [X%n]
def base_n_to_10(X, n):
return sum(int(str(X)[-i-1])*n**i for i in range(len(str(X))))
def base_10_to_n_without_0(X, n):
X -= 1
if X//n: return base_10_to_n_without_0(X//n, n)+[X%n]
return [X%n]
#####IntLog#####
def int_log(n, a):
count = 0
while n>=a:
n //= a
count += 1
return count
#############
# Main Code #
#############
N,M,L,R = IL()
@lru_cache(maxsize=None)
def P(t):
ans = 0
for k in range(t//M+1):
u = t-M*(k+1)
if u>=0:
if u%(k+1) == 0:
ans += nCr(N-M,u//(k+1))*(-1)**((u//(k+1))%2)
if k!=0:
if u%k == 0:
ans -= nCr(N-M,u//k)*(-1)**((u//k)%2)
ans %= MOD
return ans
@lru_cache(maxsize=None)
def Q(t):
ans = nCr(t+N,N)
return ans
def f(MAX):
ans = 0
for t in range(MAX+1):
ans += P(t)*Q(MAX-t)
ans %= MOD
return ans
def F(x):
return (Q(x)-nCr(N,M)*f(x))%MOD
print((F(R)-F(L-1))%MOD)
``` | instruction | 0 | 93,304 | 5 | 186,608 |
No | output | 1 | 93,304 | 5 | 186,609 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number of sequences of N non-negative integers A_1, A_2, ..., A_N that satisfy the following conditions:
* L \leq A_1 + A_2 + ... + A_N \leq R
* When the N elements are sorted in non-increasing order, the M-th and (M+1)-th elements are equal.
Since the answer can be enormous, print it modulo 10^9+7.
Constraints
* All values in input are integers.
* 1 \leq M < N \leq 3 \times 10^5
* 1 \leq L \leq R \leq 3 \times 10^5
Input
Input is given from Standard Input in the following format:
N M L R
Output
Print the number of sequences of N non-negative integers, modulo 10^9+7.
Examples
Input
4 2 3 7
Output
105
Input
2 1 4 8
Output
3
Input
141592 6535 89793 238462
Output
933832916
Submitted Solution:
```
import numpy as np
N,M,L,R = map(int,input().split())
MOD = 10 ** 9 + 7
U = 6*10**5 + 100
fact = [1] * (U+1)
for n in range(1,U+1):
fact[n] = fact[n-1]*n%MOD
fact_inv = [1] * (U+1)
fact_inv[U] = pow(fact[U],MOD-2,MOD)
for n in range(U,0,-1):
fact_inv[n-1] = fact_inv[n] * n % MOD
fact = np.array(fact,dtype=np.int64)
fact_inv = np.array(fact_inv,dtype=np.int64)
U = N - M
comb = fact[U] * fact_inv[:U+1] % MOD * fact_inv[U::-1] % MOD
comb[1::2] *= (-1)
F = np.zeros(N+M+1,dtype=np.int64)
F[M:N+1] = comb
P = np.zeros(R+1,dtype=np.int64)
for i,x in enumerate(F[1:],1):
P[::i] += x
P[:M-1:-1] -= P[-M-1::-1]
P %= MOD
# (1-x)^{N+1}で割る
Q = fact[N:N+R+1] * fact_inv[:R+1] % MOD * fact_inv[N] % MOD
def f(R):
total = fact[R+N] * fact_inv[R] % MOD * fact_inv[N] % MOD
x = (Q[R::-1] * P[:R+1] % MOD).sum() % MOD
coef = fact[N] * fact_inv[M] % MOD * fact_inv[N-M] % MOD
return (total - x*coef)%MOD
answer = (f(R) - f(L-1))%MOD
print(answer)
``` | instruction | 0 | 93,305 | 5 | 186,610 |
No | output | 1 | 93,305 | 5 | 186,611 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number of sequences of N non-negative integers A_1, A_2, ..., A_N that satisfy the following conditions:
* L \leq A_1 + A_2 + ... + A_N \leq R
* When the N elements are sorted in non-increasing order, the M-th and (M+1)-th elements are equal.
Since the answer can be enormous, print it modulo 10^9+7.
Constraints
* All values in input are integers.
* 1 \leq M < N \leq 3 \times 10^5
* 1 \leq L \leq R \leq 3 \times 10^5
Input
Input is given from Standard Input in the following format:
N M L R
Output
Print the number of sequences of N non-negative integers, modulo 10^9+7.
Examples
Input
4 2 3 7
Output
105
Input
2 1 4 8
Output
3
Input
141592 6535 89793 238462
Output
933832916
Submitted Solution:
```
# -*- coding: utf-8 -*-
#############
# Libraries #
#############
import sys
input = sys.stdin.readline
import math
#from math import gcd
import bisect
import heapq
from collections import defaultdict
from collections import deque
from collections import Counter
from functools import lru_cache
#############
# Constants #
#############
MOD = 10**9+7
INF = float('inf')
AZ = "abcdefghijklmnopqrstuvwxyz"
#############
# Functions #
#############
######INPUT######
def I(): return int(input().strip())
def S(): return input().strip()
def IL(): return list(map(int,input().split()))
def SL(): return list(map(str,input().split()))
def ILs(n): return list(int(input()) for _ in range(n))
def SLs(n): return list(input().strip() for _ in range(n))
def ILL(n): return [list(map(int, input().split())) for _ in range(n)]
def SLL(n): return [list(map(str, input().split())) for _ in range(n)]
######OUTPUT######
def P(arg): print(arg); return
def Y(): print("Yes"); return
def N(): print("No"); return
def E(): exit()
def PE(arg): print(arg); exit()
def YE(): print("Yes"); exit()
def NE(): print("No"); exit()
#####Shorten#####
def DD(arg): return defaultdict(arg)
#####Inverse#####
def inv(n): return pow(n, MOD-2, MOD)
######Combination######
kaijo_memo = []
def kaijo(n):
if(len(kaijo_memo) > n): return kaijo_memo[n]
if(len(kaijo_memo) == 0): kaijo_memo.append(1)
while(len(kaijo_memo) <= n): kaijo_memo.append(kaijo_memo[-1] * len(kaijo_memo) % MOD)
return kaijo_memo[n]
gyaku_kaijo_memo = []
def gyaku_kaijo(n):
if(len(gyaku_kaijo_memo) > n): return gyaku_kaijo_memo[n]
if(len(gyaku_kaijo_memo) == 0): gyaku_kaijo_memo.append(1)
while(len(gyaku_kaijo_memo) <= n): gyaku_kaijo_memo.append(gyaku_kaijo_memo[-1] * pow(len(gyaku_kaijo_memo),MOD-2,MOD) % MOD)
return gyaku_kaijo_memo[n]
def nCr(n,r):
if n == r: return 1
if n < r or r < 0: return 0
ret = 1
ret = ret * kaijo(n) % MOD
ret = ret * gyaku_kaijo(r) % MOD
ret = ret * gyaku_kaijo(n-r) % MOD
return ret
######Factorization######
def factorization(n):
arr = []
temp = n
for i in range(2, int(-(-n**0.5//1))+1):
if temp%i==0:
cnt=0
while temp%i==0:
cnt+=1
temp //= i
arr.append([i, cnt])
if temp!=1: arr.append([temp, 1])
if arr==[]: arr.append([n, 1])
return arr
#####MakeDivisors######
def make_divisors(n):
divisors = []
for i in range(1, int(n**0.5)+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n//i)
return divisors
#####MakePrimes######
def make_primes(N):
max = int(math.sqrt(N))
seachList = [i for i in range(2,N+1)]
primeNum = []
while seachList[0] <= max:
primeNum.append(seachList[0])
tmp = seachList[0]
seachList = [i for i in seachList if i % tmp != 0]
primeNum.extend(seachList)
return primeNum
#####GCD#####
def gcd(a, b):
while b: a, b = b, a % b
return a
#####LCM#####
def lcm(a, b):
return a * b // gcd (a, b)
#####BitCount#####
def count_bit(n):
count = 0
while n:
n &= n-1
count += 1
return count
#####ChangeBase#####
def base_10_to_n(X, n):
if X//n: return base_10_to_n(X//n, n)+[X%n]
return [X%n]
def base_n_to_10(X, n):
return sum(int(str(X)[-i-1])*n**i for i in range(len(str(X))))
def base_10_to_n_without_0(X, n):
X -= 1
if X//n: return base_10_to_n_without_0(X//n, n)+[X%n]
return [X%n]
#####IntLog#####
def int_log(n, a):
count = 0
while n>=a:
n //= a
count += 1
return count
#############
# Main Code #
#############
N,M,L,R = IL()
M = max(M,N-M)
@lru_cache(maxsize=None)
def P(t):
ans = 0
for k in range(t//M+1):
u = t-M*(k+1)
if u>=0:
if u%(k+1) == 0:
ans += nCr(N-M,u//(k+1))*(-1)**((u//(k+1))%2)
if k!=0:
if u%k == 0:
ans -= nCr(N-M,u//k)*(-1)**((u//k)%2)
ans %= MOD
return ans
@lru_cache(maxsize=None)
def Q(t):
ans = nCr(t+N,N)
return ans
def f(MAX):
ans = 0
for t in range(MAX+1):
ans += P(t)*Q(MAX-t)
ans %= MOD
return ans
def F(x):
return (Q(x)-nCr(N,M)*f(x))%MOD
print((F(R)-F(L-1))%MOD)
``` | instruction | 0 | 93,306 | 5 | 186,612 |
No | output | 1 | 93,306 | 5 | 186,613 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,339 | 5 | 186,678 |
"Correct Solution:
```
l = list(map(int,input().split()))
k = int(input())
print(sum(l)+max(l)*(2**k-1))
``` | output | 1 | 93,339 | 5 | 186,679 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,340 | 5 | 186,680 |
"Correct Solution:
```
l=list(map(int,input().split()))
n=int(input())
print(sum(l)+max(l)*((2**n)-1))
``` | output | 1 | 93,340 | 5 | 186,681 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,341 | 5 | 186,682 |
"Correct Solution:
```
A = [int(x) for x in input().split()]
K = int(input())
print(sum(A)+max(A)*(2**K-1))
``` | output | 1 | 93,341 | 5 | 186,683 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,342 | 5 | 186,684 |
"Correct Solution:
```
num=list(map(int,input().split()))
print(sum(num)-max(num)+max(num)*2**int(input()))
``` | output | 1 | 93,342 | 5 | 186,685 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,343 | 5 | 186,686 |
"Correct Solution:
```
a,b,c = sorted(map(int,input().split()))
k = int(input())
print(a + b + c*(2**k))
``` | output | 1 | 93,343 | 5 | 186,687 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,344 | 5 | 186,688 |
"Correct Solution:
```
a,b,c = map(int,input().split())
k = int(input())
x = max(a,b,c)
print(a+b+c+x*2**k-x)
``` | output | 1 | 93,344 | 5 | 186,689 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,345 | 5 | 186,690 |
"Correct Solution:
```
x=[int(i) for i in input().split()]
x.sort()
n=int(input())
print(x[2]*2**n+x[0]+x[1])
``` | output | 1 | 93,345 | 5 | 186,691 |
Provide a correct Python 3 solution for this coding contest problem.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22 | instruction | 0 | 93,346 | 5 | 186,692 |
"Correct Solution:
```
A,B,C=map(int, input().split())
K=int(input())
a=max(A,B,C)
b=A+B+C-a
print(b+a*(2**K))
``` | output | 1 | 93,346 | 5 | 186,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
L=sorted(list(map(int,input().split())))
k=int(input())
L[-1]=L[-1]*(2**k)
print(sum(L))
``` | instruction | 0 | 93,347 | 5 | 186,694 |
Yes | output | 1 | 93,347 | 5 | 186,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
L=list(map(int,input().split()))
K=int(input())
N=sorted(L)
print(N[0]+N[1]+N[2]*(2**K))
``` | instruction | 0 | 93,348 | 5 | 186,696 |
Yes | output | 1 | 93,348 | 5 | 186,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
a, b, c, K = map(int, open(0).read().split())
m = max(a, b, c)
print(m*2**K+a+b+c-m)
``` | instruction | 0 | 93,349 | 5 | 186,698 |
Yes | output | 1 | 93,349 | 5 | 186,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
a,b,c = map(int,input().split())
k = int(input())
print(max(a,b,c)*(2**k-1)+a+b+c)
``` | instruction | 0 | 93,350 | 5 | 186,700 |
Yes | output | 1 | 93,350 | 5 | 186,701 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
a,b,c = map(int,input().split())
k = int(input())
m = a
count = 0
if b>m:
m=b
count=1
if c>m:
m=c
count=2
if count==0:
print(a**k+b+c)
if count==1:
print(a+b**k+c)
if count==2:
print(a+b+c**k)
``` | instruction | 0 | 93,351 | 5 | 186,702 |
No | output | 1 | 93,351 | 5 | 186,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
n = list(map(int,input().split()))
k = int(input())
n.sort(reverse=True)
print(n[0]**k+n[1]+n[2])
``` | instruction | 0 | 93,352 | 5 | 186,704 |
No | output | 1 | 93,352 | 5 | 186,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
A, B, C = map(int, input().split())
K = int(input())
print(max(A, B, C)*(2**K)+B+C)
``` | instruction | 0 | 93,353 | 5 | 186,706 |
No | output | 1 | 93,353 | 5 | 186,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are three positive integers A, B and C written on a blackboard. E869120 performs the following operation K times:
* Choose one integer written on the blackboard and let the chosen integer be n. Replace the chosen integer with 2n.
What is the largest possible sum of the integers written on the blackboard after K operations?
Constraints
* A, B and C are integers between 1 and 50 (inclusive).
* K is an integer between 1 and 10 (inclusive).
Input
Input is given from Standard Input in the following format:
A B C
K
Output
Print the largest possible sum of the integers written on the blackboard after K operations by E869220.
Examples
Input
5 3 11
1
Output
30
Input
3 3 4
2
Output
22
Submitted Solution:
```
a, b, c = map(int, input().split())
k = int(input())
m = max(a, b, c)
print(sum([a, b, c])-m+m*2*k)
``` | instruction | 0 | 93,354 | 5 | 186,708 |
No | output | 1 | 93,354 | 5 | 186,709 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,512 | 5 | 187,024 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Dictionary - Map: Range Search
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ITP2_8_C&lang=jp
"""
from bisect import insort, bisect_right, bisect_left
class Range_map:
def __init__(self):
self.rm = dict()
self.lr = []
def insert(self, x, y):
if x not in self.rm:
insort(self.lr, x)
self.rm[x] = y
def get(self, x):
print(self.rm.get(x, 0))
def delete(self, x):
if x in self.rm:
self.rm[x] = 0
def dump(self, l, r):
lb = bisect_left(self.lr, l)
ub = bisect_right(self.lr, r)
for i in range(lb, ub):
k = self.lr[i]
if k in self.rm and self.rm[k] != 0:
print(f'{k} {self.rm[k]}')
rm = Range_map()
for _ in range(int(input())):
op, x, y = (input() + ' 1').split()[:3]
if op == '0':
rm.insert(x, int(y))
elif op == '1':
rm.get(x)
elif op == '2':
rm.delete(x)
else:
rm.dump(x, y)
``` | output | 1 | 93,512 | 5 | 187,025 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,513 | 5 | 187,026 |
"Correct Solution:
```
import bisect
keys=[]
q=int(input())
d={}
def find(x):
index=bisect.bisect_left(keys,x)
if index==len(keys):
return -1
if keys[index]==x:
return index
else:
return -1
for _ in range(q):
query=input().split(" ")
if query[0]=="0":
if find(query[1])!=-1:
pass
else:
bisect.insort_left(keys, query[1])
d[query[1]]=query[2]
elif query[0]=="1":
if find(query[1])!=-1:
print(d[query[1]])
else:
print(0)
elif query[0]=="2":
while find(query[1])>=0:
keys.pop(find(query[1]))
else:
L,R=query[1],query[2]
indL=bisect.bisect_left(keys,L)
indR=bisect.bisect_right(keys,R)
for s in keys[indL:indR]:
print(s,d[s])
``` | output | 1 | 93,513 | 5 | 187,027 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,514 | 5 | 187,028 |
"Correct Solution:
```
# AOJ ITP2_8_C: Map: Range Search
# Python3 2018.6.24 bal4u
from bisect import bisect_left, bisect_right, insort_left
dict = {}
keytbl = []
q = int(input())
for i in range(q):
a = list(input().split())
ki = a[1]
if a[0] == '0':
if ki not in dict:
insort_left(keytbl, ki)
dict[ki] = int(a[2])
elif a[0] == '1':
print(dict[ki] if ki in dict else 0)
elif a[0] == '2':
if ki in dict: dict[ki] = 0
else:
L = bisect_left (keytbl, a[1])
R = bisect_right(keytbl, a[2], L)
for j in range(L, R):
if dict[keytbl[j]] > 0: print(keytbl[j], dict[keytbl[j]])
``` | output | 1 | 93,514 | 5 | 187,029 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,515 | 5 | 187,030 |
"Correct Solution:
```
from bisect import *
import sys
n = int(input())
dic = {}
dic2 = {}
box = []
for i in range(n):
a, b, *c = sys.stdin.readline().split()
if a == '0':
insort_left(box, b)
dic[b] = int(c[0])
elif a == '1':
print(dic[b] if b in dic else 0)
elif a == '2':
if b in dic:
del dic[b]
else:
L = bisect_left(box,b)
R = bisect_right(box, c[0])
while L<R:
if box[L] in dic:
print(box[L], dic[box[L]])
L = bisect_right(box, box[L])
``` | output | 1 | 93,515 | 5 | 187,031 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,516 | 5 | 187,032 |
"Correct Solution:
```
def resolve():
import sys
import bisect
input = sys.stdin.readline
n = int(input())
ans = dict()
need_sort = True
sorted_keys = None
for _ in range(n):
q, key, *x = input().split()
if q == "0":
if key in ans:
ans[key] = x[0]
else:
ans[key] = x[0]
need_sort = True
elif q == "1":
if key in ans:
print(ans[key])
else:
print(0)
elif q == "2":
ans[key] = "0"
else:
if sorted_keys is None:
sorted_keys = sorted(ans.keys())
if need_sort:
sorted_keys = sorted(ans.keys())
need_sort = False
l, r = key, x[0]
fr = bisect.bisect_left(sorted_keys, l)
to = bisect.bisect_right(sorted_keys, r)
for i in range(fr, to):
if ans[sorted_keys[i]] != "0":
print(sorted_keys[i], ans[sorted_keys[i]])
resolve()
``` | output | 1 | 93,516 | 5 | 187,033 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,517 | 5 | 187,034 |
"Correct Solution:
```
import sys
import bisect
n = int(input())
arr = []
lines = sys.stdin.readlines()
ans = [None] * n
d = {}
for i in range(n):
q, *arg = lines[i].split()
key = arg[0]
idx = bisect.bisect_left(arr, arg[0])
if q == '0': # insert
if idx == len(arr) or arr[idx] != key:
arr.insert(idx, key)
d[key] = arg[1]
elif q == '1': # get
ans[i] = d[key] if idx != len(arr) and arr[idx] == key else '0'
elif q == '2': # delete
if idx < len(arr) and arr[idx] == key:
del arr[idx]
del d[key]
elif q == '3': # dump L R
r_idx = bisect.bisect_right(arr, arg[1])
ans[i] = '\n'.join([f'{key_} {d[key_]}' for key_ in arr[idx:r_idx]]) if (r_idx - idx) != 0 else None
[print(x) for x in ans if x is not None]
``` | output | 1 | 93,517 | 5 | 187,035 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,518 | 5 | 187,036 |
"Correct Solution:
```
from bisect import bisect_left, bisect_right, insort_left
dict = {}
keytbl = []
q = int(input())
for i in range(q):
a = list(input().split())
ki = a[1]
if a[0] == '0':
if ki not in dict:
insort_left(keytbl, ki)
dict[ki] = int(a[2])
elif a[0] == '1':
print(dict[ki] if ki in dict else 0)
elif a[0] == '2':
if ki in dict: dict[ki] = 0
else:
L = bisect_left (keytbl, a[1])
R = bisect_right(keytbl, a[2], L)
for j in range(L, R):
if dict[keytbl[j]] > 0: print(keytbl[j], dict[keytbl[j]])
``` | output | 1 | 93,518 | 5 | 187,037 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5 | instruction | 0 | 93,519 | 5 | 187,038 |
"Correct Solution:
```
from bisect import bisect,bisect_left,insort
dic = {}
l = []
for i in range(int(input())):
order = list(input().split())
if order[0] == "0":
if order[1] in dic:
dic[order[1]] = int(order[2])
else:
dic[order[1]] = int(order[2])
insort(l,order[1])
elif order[0] == "1":
if order[1] in dic:
print(dic[order[1]])
else:
print(0)
elif order[0] == "2":
if order[1] in dic:
dic[order[1]] = 0
elif order[0] == "3":
L = bisect_left(l,order[1])
R = bisect(l,order[2])
for i in range(L,R):
if dic[l[i]]:
print(l[i],dic[l[i]])
``` | output | 1 | 93,519 | 5 | 187,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
import bisect
q = int(input())
M = {}
sortedList = []
for i in range(q):
query, *inp = input().split()
key = inp[0]
# insert
if query == "0":
x = int(inp[1])
if key not in M:
bisect.insort_left(sortedList, key)
M[key] = x
# get
elif query == "1":
if key in M:
if M[key] != None:
print(M[key])
else:
print(0)
else:
print(0)
# delete
elif query == "2":
if key in M:
M[key] = None
# dump
else:
L = inp[0]
R = inp[1]
index_left = bisect.bisect_left(sortedList, L)
index_right = bisect.bisect_right(sortedList, R)
for i in range(index_left, index_right):
key_ans = sortedList[i]
if M[key_ans] != None:
print(key_ans, M[key_ans])
``` | instruction | 0 | 93,520 | 5 | 187,040 |
Yes | output | 1 | 93,520 | 5 | 187,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
import bisect
q = int(input())
M = {}
list_key_sorted = []
for _ in range(q):
command, *list_num = input().split()
if command == "0":
# insert(key, x)
key = list_num[0]
x = int(list_num[1])
if key not in M:
bisect.insort_left(list_key_sorted, key)
M[key] = x
elif command == "1":
# get(key)
key = list_num[0]
if key in M:
if M[key] == None:
print(0)
else:
print(M[key])
else:
print(0)
elif command == "2":
# delete(key)
key = list_num[0]
if key in M:
M[key] = None
elif command == "3":
# dump(L, R)
L = list_num[0]
R = list_num[1]
index_left = bisect.bisect_left(list_key_sorted, L)
index_right = bisect.bisect_right(list_key_sorted, R)
for index in range(index_left, index_right):
key_ans = list_key_sorted[index]
if M[key_ans] != None:
print(key_ans, M[key_ans])
else:
raise
``` | instruction | 0 | 93,521 | 5 | 187,042 |
Yes | output | 1 | 93,521 | 5 | 187,043 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
from enum import Enum
class Color(Enum):
BLACK = 0
RED = 1
@staticmethod
def flip(c):
return [Color.RED, Color.BLACK][c.value]
class Node:
__slots__ = ('key', 'left', 'right', 'size', 'color', 'value')
def __init__(self, key, value):
self.key = key
self.value = value
self.left = Leaf
self.right = Leaf
self.size = 1
self.color = Color.RED
def is_red(self):
return self.color == Color.RED
def is_black(self):
return self.color == Color.BLACK
def __str__(self):
if self.color == Color.RED:
key = '*{}'.format(self.key)
else:
key = '{}'.format(self.key)
return "{}[{}] ({}, {})".format(key, self.size,
self.left, self.right)
class LeafNode(Node):
def __init__(self):
self.key = None
self.value = None
self.left = None
self.right = None
self.size = 0
self.color = None
def is_red(self):
return False
def is_black(self):
return False
def __str__(self):
return '-'
Leaf = LeafNode()
class RedBlackBinarySearchTree:
"""Red Black Binary Search Tree with range, min, max.
Originally impremented in the textbook
Algorithms, 4th edition by Robert Sedgewick and Kevin Wayne,
Addison-Wesley Professional, 2011, ISBN 0-321-57351-X.
"""
def __init__(self):
self.root = Leaf
def put(self, key, value=None):
def _put(node):
if node is Leaf:
node = Node(key, value)
if node.key > key:
node.left = _put(node.left)
elif node.key < key:
node.right = _put(node.right)
else:
node.value = value
node = self._restore(node)
node.size = node.left.size + node.right.size + 1
return node
self.root = _put(self.root)
self.root.color = Color.BLACK
def _rotate_left(self, node):
x = node.right
node.right = x.left
x.left = node
x.color = node.color
node.color = Color.RED
node.size = node.left.size + node.right.size + 1
return x
def _rotate_right(self, node):
x = node.left
node.left = x.right
x.right = node
x.color = node.color
node.color = Color.RED
node.size = node.left.size + node.right.size + 1
return x
def _flip_colors(self, node):
node.color = Color.flip(node.color)
node.left.color = Color.flip(node.left.color)
node.right.color = Color.flip(node.right.color)
return node
def __contains__(self, key):
def _contains(node):
if node is Leaf:
return False
if node.key > key:
return _contains(node.left)
elif node.key < key:
return _contains(node.right)
else:
return True
return _contains(self.root)
def get(self, key):
def _get(node):
if node is Leaf:
return None
if node.key > key:
return _get(node.left)
elif node.key < key:
return _get(node.right)
else:
return node.value
return _get(self.root)
def delete(self, key):
def _delete(node):
if node is Leaf:
return Leaf
if node.key > key:
if node.left is Leaf:
return self._balance(node)
if not self._is_red_left(node):
node = self._red_left(node)
node.left = _delete(node.left)
else:
if node.left.is_red():
node = self._rotate_right(node)
if node.key == key and node.right is Leaf:
return Leaf
elif node.right is Leaf:
return self._balance(node)
if not self._is_red_right(node):
node = self._red_right(node)
if node.key == key:
x = self._find_min(node.right)
node.key = x.key
node.value = x.value
node.right = self._delete_min(node.right)
else:
node.right = _delete(node.right)
return self._balance(node)
if self.is_empty():
raise ValueError('delete on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = _delete(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
def delete_max(self):
if self.is_empty():
raise ValueError('delete max on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = self._delete_max(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
def _delete_max(self, node):
if node.left.is_red():
node = self._rotate_right(node)
if node.right is Leaf:
return Leaf
if not self._is_red_right(node):
node = self._red_right(node)
node.right = self._delete_max(node.right)
return self._balance(node)
def _red_right(self, node):
node = self._flip_colors(node)
if node.left.left.is_red():
node = self._rotate_right(node)
return node
def _is_red_right(self, node):
return (node.right.is_red() or
(node.right.is_black() and node.right.left.is_red()))
def delete_min(self):
if self.is_empty():
raise ValueError('delete min on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = self._delete_min(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
def _delete_min(self, node):
if node.left is Leaf:
return Leaf
if not self._is_red_left(node):
node = self._red_left(node)
node.left = self._delete_min(node.left)
return self._balance(node)
def _red_left(self, node):
node = self._flip_colors(node)
if node.right.left.is_red():
node.right = self._rotate_right(node.right)
node = self._rotate_left(node)
return node
def _is_red_left(self, node):
return (node.left.is_red() or
(node.left.is_black() and node.left.left.is_red()))
def _balance(self, node):
if node.right.is_red():
node = self._rotate_left(node)
return self._restore(node)
def _restore(self, node):
if node.right.is_red() and not node.left.is_red():
node = self._rotate_left(node)
if node.left.is_red() and node.left.left.is_red():
node = self._rotate_right(node)
if node.left.is_red() and node.right.is_red():
node = self._flip_colors(node)
node.size = node.left.size + node.right.size + 1
return node
def is_empty(self):
return self.root is Leaf
def is_balanced(self):
if self.is_empty():
return True
try:
left = self._depth(self.root.left)
right = self._depth(self.root.right)
return left == right
except Exception:
return False
@property
def depth(self):
return self._depth(self.root)
def _depth(self, node):
if node is Leaf:
return 0
if node.right.is_red():
raise Exception('right red')
left = self._depth(node.left)
right = self._depth(node.right)
if left != right:
raise Exception('unbalanced')
if node.is_red():
return left
else:
return 1 + left
def __len__(self):
return self.root.size
@property
def max(self):
if self.is_empty():
raise ValueError('max on empty tree')
return self._max(self.root)
def _max(self, node):
x = self._find_max(node)
return x.key
def _find_max(self, node):
if node.right is Leaf:
return node
else:
return self._find_max(node.right)
@property
def min(self):
if self.is_empty():
raise ValueError('min on empty tree')
return self._min(self.root)
def _min(self, node):
x = self._find_min(node)
return x.key
def _find_min(self, node):
if node.left is Leaf:
return node
else:
return self._find_min(node.left)
def __iter__(self):
def inorder(node):
if node is Leaf:
return
yield from inorder(node.left)
yield node.value
yield from inorder(node.right)
yield from inorder(self.root)
def range(self, min_, max_):
def _range(node):
if node is Leaf:
return
if node.key > max_:
yield from _range(node.left)
elif node.key < min_:
yield from _range(node.right)
else:
yield from _range(node.left)
yield (node.key, node.value)
yield from _range(node.right)
if min_ > max_:
return
yield from _range(self.root)
class Map:
def __init__(self):
self.tree = RedBlackBinarySearchTree()
def __getitem__(self, key):
if key in self.tree:
return self.tree.get(key)
else:
raise IndexError('key {} not found in map'.format(key))
def __setitem__(self, key, value):
self.tree.put(key, value)
def __delitem__(self, key):
if key in self.tree:
self.tree.delete(key)
else:
raise IndexError('key {} not found in map'.format(key))
def __len__(self):
return len(self.tree)
def items(self):
for k, v in self.tree:
yield (k, v)
def range(self, min_, max_):
for k, v in self.tree.range(min_, max_):
yield (k, v)
def run():
q = int(input())
m = Map()
for _ in range(q):
command, *args = input().split()
if command == '0':
key = args[0]
value = int(args[1])
m[key] = value
elif command == '1':
key = args[0]
try:
print(m[key])
except IndexError:
print(0)
elif command == '2':
key = args[0]
try:
del m[key]
except IndexError:
pass
elif command == '3':
low, hi = args
for k, v in m.range(low, hi):
print(k, v)
else:
raise ValueError('invalid command')
if __name__ == '__main__':
run()
``` | instruction | 0 | 93,522 | 5 | 187,044 |
Yes | output | 1 | 93,522 | 5 | 187,045 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
from bisect import bisect_left, bisect_right, insort_left
q = int(input())
M = {}
tbl = []
for i in range(q):
query, *x = input().split()
if query == "0":
x[1] = int(x[1])
if x[0] not in M:
insort_left(tbl, x[0])
M[x[0]] = x[1]
elif query == "1":
print(M[x[0]] if x[0] in M and M[x[0]] != 0 else 0)
elif query == "2":
M[x[0]] = 0
else:
L = bisect_left( tbl, x[0])
R = bisect_right(tbl, x[1])
for i in range(L, R):
if M[tbl[i]] != 0:
print(tbl[i], M[tbl[i]])
``` | instruction | 0 | 93,523 | 5 | 187,046 |
Yes | output | 1 | 93,523 | 5 | 187,047 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
from enum import Enum
class Color(Enum):
BLACK = 0
RED = 1
@staticmethod
def flip(c):
return [Color.RED, Color.BLACK][c.value]
class Node:
__slots__ = ('key', 'left', 'right', 'size', 'color', 'value')
def __init__(self, key, value):
self.key = key
self.value = value
self.left = Leaf
self.right = Leaf
self.size = 1
self.color = Color.RED
def is_red(self):
return self.color == Color.RED
def is_black(self):
return self.color == Color.BLACK
def __str__(self):
if self.color == Color.RED:
key = '*{}'.format(self.key)
else:
key = '{}'.format(self.key)
return "{}[{}] ({}, {})".format(key, self.size,
self.left, self.right)
class LeafNode(Node):
def __init__(self):
self.key = None
self.value = None
self.left = None
self.right = None
self.size = 0
self.color = None
def is_red(self):
return False
def is_black(self):
return False
def __str__(self):
return '-'
Leaf = LeafNode()
class RedBlackBinarySearchTree:
"""Red Black Binary Search Tree with range, min, max.
Originally impremented in the textbook
Algorithms, 4th edition by Robert Sedgewick and Kevin Wayne,
Addison-Wesley Professional, 2011, ISBN 0-321-57351-X.
"""
def __init__(self):
self.root = Leaf
def put(self, key, value=None):
def _put(node):
if node is Leaf:
node = Node(key, value)
if node.key > key:
node.left = _put(node.left)
elif node.key < key:
node.right = _put(node.right)
else:
node.value = value
node = self._restore(node)
node.size = node.left.size + node.right.size + 1
return node
self.root = _put(self.root)
self.root.color = Color.BLACK
def _rotate_left(self, node):
assert node.right.is_red()
x = node.right
node.right = x.left
x.left = node
x.color = node.color
node.color = Color.RED
node.size = node.left.size + node.right.size + 1
return x
def _rotate_right(self, node):
assert node.left.is_red()
x = node.left
node.left = x.right
x.right = node
x.color = node.color
node.color = Color.RED
node.size = node.left.size + node.right.size + 1
return x
def _flip_colors(self, node):
node.color = Color.flip(node.color)
node.left.color = Color.flip(node.left.color)
node.right.color = Color.flip(node.right.color)
return node
def __contains__(self, key):
def _contains(node):
if node is Leaf:
return False
if node.key > key:
return _contains(node.left)
elif node.key < key:
return _contains(node.right)
else:
return True
return _contains(self.root)
def get(self, key):
def _get(node):
if node is Leaf:
return None
if node.key > key:
return _get(node.left)
elif node.key < key:
return _get(node.right)
else:
return node.value
return _get(self.root)
def delete(self, key):
def _delete(node):
if node is Leaf:
return Leaf
if node.key > key:
if node.left is Leaf:
return self._balance(node)
if not self._is_red_left(node):
node = self._red_left(node)
node.left = _delete(node.left)
else:
if node.left.is_red():
node = self._rotate_right(node)
if node.key == key and node.right is Leaf:
return Leaf
elif node.right is Leaf:
return self._balance(node)
if not self._is_red_right(node):
node = self._red_right(node)
if node.key == key:
x = self._find_min(node.right)
node.key = x.key
node.value = x.value
node.right = self._delete_min(node.right)
else:
node.right = _delete(node.right)
if self.is_empty():
raise ValueError('delete on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = _delete(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
def delete_max(self):
if self.is_empty():
raise ValueError('delete max on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = self._delete_max(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
def _delete_max(self, node):
if node.left.is_red():
node = self._rotate_right(node)
if node.right is Leaf:
return Leaf
if not self._is_red_right(node):
node = self._red_right(node)
node.right = self._delete_max(node.right)
def _red_right(self, node):
node = self._flip_colors(node)
if node.left.left.is_red():
node = self._rotate_right(node)
return node
def _is_red_right(self, node):
return (node.right.is_red() or
(node.right.is_black() and node.right.left.is_red()))
def delete_min(self):
if self.is_empty():
raise ValueError('delete min on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = self._delete_min(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
def _delete_min(self, node):
if node.left is Leaf:
return Leaf
if not self._is_red_left(node):
node = self._red_left(node)
node.left = self._delete_min(node.left)
return self._balance(node)
def _red_left(self, node):
node = self._flip_colors(node)
if node.right.left.is_red():
node.right = self._rotate_right(node.right)
node = self._rotate_left(node)
return node
def _is_red_left(self, node):
return (node.left.is_red() or
(node.left.is_black() and node.left.left.is_red()))
def _balance(self, node):
if node.right.is_red():
node = self._rotate_left(node)
return self._restore(node)
def _restore(self, node):
if node.right.is_red() and not node.left.is_red():
node = self._rotate_left(node)
if node.left.is_red() and node.left.left.is_red():
node = self._rotate_right(node)
if node.left.is_red() and node.right.is_red():
node = self._flip_colors(node)
node.size = node.left.size + node.right.size + 1
return node
def is_empty(self):
return self.root is Leaf
def is_balanced(self):
if self.is_empty():
return True
try:
left = self._depth(self.root.left)
right = self._depth(self.root.right)
return left == right
except Exception:
return False
@property
def depth(self):
return self._depth(self.root)
def _depth(self, node):
if node is Leaf:
return 0
if node.right.is_red():
raise Exception('right red')
left = self._depth(node.left)
right = self._depth(node.right)
if left != right:
raise Exception('unbalanced')
if node.is_red():
return left
else:
return 1 + left
def __len__(self):
return self.root.size
@property
def max(self):
if self.is_empty():
raise ValueError('max on empty tree')
return self._max(self.root)
def _max(self, node):
x = self._find_max(node)
return x.key
def _find_max(self, node):
if node.right is Leaf:
return node
else:
return self._find_max(node.right)
@property
def min(self):
if self.is_empty():
raise ValueError('min on empty tree')
return self._min(self.root)
def _min(self, node):
x = self._find_min(node)
return x.key
def _find_min(self, node):
if node.left is Leaf:
return node
else:
return self._find_min(node.left)
def __iter__(self):
def inorder(node):
if node is Leaf:
return
yield from inorder(node.left)
yield node.value
yield from inorder(node.right)
yield from inorder(self.root)
def range(self, min_, max_):
def _range(node):
if node is Leaf:
return
if node.key > max_:
yield from _range(node.left)
elif node.key < min_:
yield from _range(node.right)
else:
yield from _range(node.left)
yield (node.key, node.value)
yield from _range(node.right)
if min_ > max_:
return
yield from _range(self.root)
class Map:
def __init__(self):
self.tree = RedBlackBinarySearchTree()
def __getitem__(self, key):
if key in self.tree:
return self.tree.get(key)
else:
raise IndexError('key {} not found in map'.format(key))
def __setitem__(self, key, value):
self.tree.put(key, value)
def __delitem__(self, key):
if key in self.tree:
self.tree.delete(key)
else:
raise IndexError('key {} not found in map'.format(key))
def __len__(self):
return len(self.tree)
def items(self):
for k, v in self.tree:
yield (k, v)
def range(self, min_, max_):
for k, v in self.tree.range(min_, max_):
yield (k, v)
def run():
q = int(input())
m = Map()
for _ in range(q):
command, *args = input().split()
if command == '0':
key = args[0]
value = int(args[1])
m[key] = value
elif command == '1':
key = args[0]
try:
print(m[key])
except IndexError:
print(0)
elif command == '2':
key = args[0]
try:
del m[key]
except IndexError:
pass
elif command == '3':
low, hi = args
for k, v in m.range(low, hi):
print(k, v)
else:
raise ValueError('invalid command')
if __name__ == '__main__':
run()
``` | instruction | 0 | 93,524 | 5 | 187,048 |
No | output | 1 | 93,524 | 5 | 187,049 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
from collections import OrderedDict
dict = OrderedDict()
q = int(input())
for i in range(q):
query, *val = input().split(' ')
if query == '0':
dict[val[0]] = int(val[1])
elif query == '1':
print(dict.get(val[0], 0))
elif query == '2':
if val[0] in dict:
dict.pop(val[0])
else:
ans = ''
for k, v in dict.items():
if val[0] <= k and k <= val[1]:
ans += str(k) + ' ' + str(v) + ' '
print(ans.strip())
``` | instruction | 0 | 93,525 | 5 | 187,050 |
No | output | 1 | 93,525 | 5 | 187,051 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
from enum import Enum
class Color(Enum):
BLACK = 0
RED = 1
@staticmethod
def flip(c):
return [Color.RED, Color.BLACK][c.value]
class Node:
__slots__ = ('key', 'left', 'right', 'size', 'color', 'value')
def __init__(self, key, value):
self.key = key
self.value = value
self.left = Leaf
self.right = Leaf
self.size = 1
self.color = Color.RED
def is_red(self):
return self.color == Color.RED
def is_black(self):
return self.color == Color.BLACK
def __str__(self):
if self.color == Color.RED:
key = '*{}'.format(self.key)
else:
key = '{}'.format(self.key)
return "{}[{}] ({}, {})".format(key, self.size,
self.left, self.right)
class LeafNode(Node):
def __init__(self):
self.key = None
self.value = None
self.left = None
self.right = None
self.size = 0
self.color = None
def is_red(self):
return False
def is_black(self):
return False
def __str__(self):
return '-'
Leaf = LeafNode()
class RedBlackBinarySearchTree:
"""Red Black Binary Search Tree with range, min, max.
Originally impremented in the textbook
Algorithms, 4th edition by Robert Sedgewick and Kevin Wayne,
Addison-Wesley Professional, 2011, ISBN 0-321-57351-X.
"""
def __init__(self):
self.root = Leaf
def put(self, key, value=None):
def _put(node):
if node is Leaf:
node = Node(key, value)
if node.key > key:
node.left = _put(node.left)
elif node.key < key:
node.right = _put(node.right)
else:
node.value = value
node = self._restore(node)
node.size = node.left.size + node.right.size + 1
return node
self.root = _put(self.root)
self.root.color = Color.BLACK
def _rotate_left(self, node):
assert node.right.is_red()
x = node.right
node.right = x.left
x.left = node
x.color = node.color
node.color = Color.RED
node.size = node.left.size + node.right.size + 1
return x
def _rotate_right(self, node):
assert node.left.is_red()
x = node.left
node.left = x.right
x.right = node
x.color = node.color
node.color = Color.RED
node.size = node.left.size + node.right.size + 1
return x
def _flip_colors(self, node):
node.color = Color.flip(node.color)
node.left.color = Color.flip(node.left.color)
node.right.color = Color.flip(node.right.color)
return node
def __contains__(self, key):
def _contains(node):
if node is Leaf:
return False
if node.key > key:
return _contains(node.left)
elif node.key < key:
return _contains(node.right)
else:
return True
return _contains(self.root)
def get(self, key):
def _get(node):
if node is Leaf:
return None
if node.key > key:
return _get(node.left)
elif node.key < key:
return _get(node.right)
else:
return node.value
return _get(self.root)
def delete(self, key):
def _delete(node):
if node is Leaf:
return Leaf
if node.key > key:
if node.left is Leaf:
return self._balance(node)
if not self._is_red_left(node):
node = self._red_left(node)
node.left = _delete(node.left)
else:
if node.left.is_red():
node = self._rotate_right(node)
if node.key == key and node.right is Leaf:
return Leaf
elif node.right is Leaf:
return self._balance(node)
if not self._is_red_right(node):
node = self._red_right(node)
if node.key == key:
x = self._find_min(node.right)
node.key = x.key
node.value = x.value
node.right = self._delete_min(node.right)
else:
node.right = _delete(node.right)
return self._balance(node)
if self.is_empty():
raise ValueError('delete on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = _delete(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
assert self.is_balanced()
def delete_max(self):
if self.is_empty():
raise ValueError('delete max on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = self._delete_max(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
assert self.is_balanced()
def _delete_max(self, node):
if node.left.is_red():
node = self._rotate_right(node)
if node.right is Leaf:
return Leaf
if not self._is_red_right(node):
node = self._red_right(node)
node.right = self._delete_max(node.right)
return self._balance(node)
def _red_right(self, node):
node = self._flip_colors(node)
if node.left.left.is_red():
node = self._rotate_right(node)
return node
def _is_red_right(self, node):
return (node.right.is_red() or
(node.right.is_black() and node.right.left.is_red()))
def delete_min(self):
if self.is_empty():
raise ValueError('delete min on empty tree')
if not self.root.left.is_red() and not self.root.right.is_red():
self.root.color = Color.RED
self.root = self._delete_min(self.root)
if not self.is_empty():
self.root.color = Color.BLACK
assert self.is_balanced()
def _delete_min(self, node):
if node.left is Leaf:
return Leaf
if not self._is_red_left(node):
node = self._red_left(node)
node.left = self._delete_min(node.left)
return self._balance(node)
def _red_left(self, node):
node = self._flip_colors(node)
if node.right.left.is_red():
node.right = self._rotate_right(node.right)
node = self._rotate_left(node)
return node
def _is_red_left(self, node):
return (node.left.is_red() or
(node.left.is_black() and node.left.left.is_red()))
def _balance(self, node):
if node.right.is_red():
node = self._rotate_left(node)
return self._restore(node)
def _restore(self, node):
if node.right.is_red() and not node.left.is_red():
node = self._rotate_left(node)
if node.left.is_red() and node.left.left.is_red():
node = self._rotate_right(node)
if node.left.is_red() and node.right.is_red():
node = self._flip_colors(node)
node.size = node.left.size + node.right.size + 1
return node
def is_empty(self):
return self.root is Leaf
def is_balanced(self):
if self.is_empty():
return True
try:
left = self._depth(self.root.left)
right = self._depth(self.root.right)
return left == right
except Exception:
return False
@property
def depth(self):
return self._depth(self.root)
def _depth(self, node):
if node is Leaf:
return 0
if node.right.is_red():
raise Exception('right red')
left = self._depth(node.left)
right = self._depth(node.right)
if left != right:
raise Exception('unbalanced')
if node.is_red():
return left
else:
return 1 + left
def __len__(self):
return self.root.size
@property
def max(self):
if self.is_empty():
raise ValueError('max on empty tree')
return self._max(self.root)
def _max(self, node):
x = self._find_max(node)
return x.key
def _find_max(self, node):
if node.right is Leaf:
return node
else:
return self._find_max(node.right)
@property
def min(self):
if self.is_empty():
raise ValueError('min on empty tree')
return self._min(self.root)
def _min(self, node):
x = self._find_min(node)
return x.key
def _find_min(self, node):
if node.left is Leaf:
return node
else:
return self._find_min(node.left)
def __iter__(self):
def inorder(node):
if node is Leaf:
return
yield from inorder(node.left)
yield node.value
yield from inorder(node.right)
yield from inorder(self.root)
def range(self, min_, max_):
def _range(node):
if node is Leaf:
return
if node.key > max_:
yield from _range(node.left)
elif node.key < min_:
yield from _range(node.right)
else:
yield from _range(node.left)
yield (node.key, node.value)
yield from _range(node.right)
if min_ > max_:
return
yield from _range(self.root)
class Map:
def __init__(self):
self.tree = RedBlackBinarySearchTree()
def __getitem__(self, key):
if key in self.tree:
return self.tree.get(key)
else:
raise IndexError('key {} not found in map'.format(key))
def __setitem__(self, key, value):
self.tree.put(key, value)
def __delitem__(self, key):
if key in self.tree:
self.tree.delete(key)
else:
raise IndexError('key {} not found in map'.format(key))
def __len__(self):
return len(self.tree)
def items(self):
for k, v in self.tree:
yield (k, v)
def range(self, min_, max_):
for k, v in self.tree.range(min_, max_):
yield (k, v)
def run():
q = int(input())
m = Map()
for _ in range(q):
command, *args = input().split()
if command == '0':
key = args[0]
value = int(args[1])
m[key] = value
elif command == '1':
key = args[0]
try:
print(m[key])
except IndexError:
print(0)
elif command == '2':
key = args[0]
try:
del m[key]
except IndexError:
pass
elif command == '3':
low, hi = args
for k, v in m.range(low, hi):
print(k, v)
else:
raise ValueError('invalid command')
if __name__ == '__main__':
run()
``` | instruction | 0 | 93,526 | 5 | 187,052 |
No | output | 1 | 93,526 | 5 | 187,053 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.
* dump($L$, $R$): Print all elements formed by a pair of the key and the value such that the key is greater than or equal to $L$ and less than or equal to $R$ in lexicographic order.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consists of lower-case letters
* $L \leq R$ in lexicographic order
* The total number of elements printed by dump operations does not exceed $1,000,000$
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
or
2 $key$
or
3 $L$ $R$
where the first digits 0, 1, 2 and 3 represent insert, get, delete and dump operations.
Output
For each get operation, print the corresponding value.
For each dump operation, print the corresponding elements formed by a pair of the key and the value. For the dump operation, print the elements (a pair of key and value separated by a space character) in ascending order of the keys.
Example
Input
9
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red
3 w z
Output
1
4
0
0
white 5
Submitted Solution:
```
from collections import OrderedDict
dict = OrderedDict()
q = int(input())
for i in range(q):
query, *val = input().split(' ')
if query == '0':
dict[val[0]] = int(val[1])
elif query == '1':
print(dict.get(val[0], 0))
elif query == '2':
if val[0] in dict:
dict.pop(val[0])
else:
ans = []
for k, v in dict.items():
if val[0] <= k and k <= val[1]:
print(k, v, end=' ')
print()
``` | instruction | 0 | 93,527 | 5 | 187,054 |
No | output | 1 | 93,527 | 5 | 187,055 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
n = int(input())
arr = list(map(int, input().split()))
temp = 0
for i in arr:
print(temp + i, end=" ")
if(i > 0):
temp += i
``` | instruction | 0 | 93,652 | 5 | 187,304 |
Yes | output | 1 | 93,652 | 5 | 187,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
n = int(input())
b=[]
a=[0]*n
x=[0]*n
b = [int(i) for i in input().split()]
#print(x)
for i in range(1,n):
if i<=(n-1):
a[i-1]=b[i-1]+x[i-1]
x[i]=max(a[i-1],x[i-1])
a[n-1]=b[n-1]+x[n-1]
for i in range(n):
print(a[i], end=" ")
``` | instruction | 0 | 93,653 | 5 | 187,306 |
Yes | output | 1 | 93,653 | 5 | 187,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
length = int(input())
b = list(map(int, input().split()))
x = 0
for i in range(length):
a = b[i] + x
print(a, end=' ')
x = max(a, x)
``` | instruction | 0 | 93,654 | 5 | 187,308 |
Yes | output | 1 | 93,654 | 5 | 187,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
n=int(input())
b=list(map(int,input().split()))
a=[b[0],b[1]+b[0]]
ma=max(a)
for x in range(2,n):
num=b[x]+ma
a.append(num)
if num>ma:ma=num
print(*a)
``` | instruction | 0 | 93,655 | 5 | 187,310 |
Yes | output | 1 | 93,655 | 5 | 187,311 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
N = int(input())
b = list(map(int,input().split()))
largest = 0
for i in range(N):
temp = b[i]
b[i]+=largest
if b[i]>0:
largest+=temp
for i in b:
print(i,end=' ')
``` | instruction | 0 | 93,656 | 5 | 187,312 |
No | output | 1 | 93,656 | 5 | 187,313 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
n=int(input())
a=[int(i) for i in input().split()]
b=[]
c=[]
for i in range(n):
if(i==0):
b.append(a[i])
c.append(a[i])
else:
if(a[i]>0):
b.append(a[i]+c[i-1])
c.append(a[i]+c[i-1])
else:
b.append(0)
c.append(abs(a[i]))
print(" ".join(str(i) for i in b))
``` | instruction | 0 | 93,657 | 5 | 187,314 |
No | output | 1 | 93,657 | 5 | 187,315 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
n = int(input())
b = [int(i) for i in input().split()]
a = [b[0]]
print(b[0],end=' ')
ma = a[0]
for i in range(1, n):
a.append(b[i] + ma)
ma = max(ma, a[-1])
print(b[i]+ma)
``` | instruction | 0 | 93,658 | 5 | 187,316 |
No | output | 1 | 93,658 | 5 | 187,317 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alicia has an array, a_1, a_2, …, a_n, of non-negative integers. For each 1 ≤ i ≤ n, she has found a non-negative integer x_i = max(0, a_1, …, a_{i-1}). Note that for i=1, x_i = 0.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, then x = \{0, 0, 1, 2, 2\}.
Then, she calculated an array, b_1, b_2, …, b_n: b_i = a_i - x_i.
For example, if Alicia had the array a = \{0, 1, 2, 0, 3\}, b = \{0-0, 1-0, 2-1, 0-2, 3-2\} = \{0, 1, 1, -2, 1\}.
Alicia gives you the values b_1, b_2, …, b_n and asks you to restore the values a_1, a_2, …, a_n. Can you help her solve the problem?
Input
The first line contains one integer n (3 ≤ n ≤ 200 000) – the number of elements in Alicia's array.
The next line contains n integers, b_1, b_2, …, b_n (-10^9 ≤ b_i ≤ 10^9).
It is guaranteed that for the given array b there is a solution a_1, a_2, …, a_n, for all elements of which the following is true: 0 ≤ a_i ≤ 10^9.
Output
Print n integers, a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9), such that if you calculate x according to the statement, b_1 will be equal to a_1 - x_1, b_2 will be equal to a_2 - x_2, ..., and b_n will be equal to a_n - x_n.
It is guaranteed that there exists at least one solution for the given tests. It can be shown that the solution is unique.
Examples
Input
5
0 1 1 -2 1
Output
0 1 2 0 3
Input
3
1000 999999000 -1000000000
Output
1000 1000000000 0
Input
5
2 1 2 2 3
Output
2 3 5 7 10
Note
The first test was described in the problem statement.
In the second test, if Alicia had an array a = \{1000, 1000000000, 0\}, then x = \{0, 1000, 1000000000\} and b = \{1000-0, 1000000000-1000, 0-1000000000\} = \{1000, 999999000, -1000000000\}.
Submitted Solution:
```
n=int(input())
arr=list(map(int,input().split()))
pref=[0]*n
pref[0]=arr[0]
for i in range(1,n):
if pref[i-1]==0:
if i!=1:
pref[i]=pref[i-2]+arr[i]
elif i==1:
pref[i]=pref[i-1]+arr[i]
else:
pref[i]=pref[i-1]+arr[i]
for i in range(n):
print(pref[i],end=' ')
print('')
``` | instruction | 0 | 93,659 | 5 | 187,318 |
No | output | 1 | 93,659 | 5 | 187,319 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Victor adores the sets theory. Let us remind you that a set is a group of numbers where all numbers are pairwise distinct. Today Victor wants to find a set of integers S that has the following properties:
* for all x <image> the following inequality holds l ≤ x ≤ r;
* 1 ≤ |S| ≤ k;
* lets denote the i-th element of the set S as si; value <image> must be as small as possible.
Help Victor find the described set.
Input
The first line contains three space-separated integers l, r, k (1 ≤ l ≤ r ≤ 1012; 1 ≤ k ≤ min(106, r - l + 1)).
Output
Print the minimum possible value of f(S). Then print the cardinality of set |S|. Then print the elements of the set in any order.
If there are multiple optimal sets, you can print any of them.
Examples
Input
8 15 3
Output
1
2
10 11
Input
8 30 7
Output
0
5
14 9 28 11 16
Note
Operation <image> represents the operation of bitwise exclusive OR. In other words, it is the XOR operation.
Submitted Solution:
```
def f(arr):
val = 0
for x in arr:
val ^= x
return val
def solve(l, r, k):
ret = [l]
if k >= 2:
cand = [l, l + 1]
if f(cand) < f(ret):
ret = cand
if l + 2 <= r:
cand = [l + 1, l + 2]
if f(cand) < f(ret):
ret = cand
if k >= 3:
x = 1
while x <= l:
x *= 2
if x + x // 2 <= r:
ret = [x - 1, x + x // 2, x + x // 2 - 1]
if k >= 4:
cand = [l, l + 1, l + 2, l + 3]
if f(cand) < f(ret):
ret = cand
if l + 4 <= r:
cand = [l + 1, l + 2, l + 3, l + 4]
if f(cand) < f(ret):
ret = cand
return ret
l, r, k = map(int, input().split())
ans = solve(l, r, k)
print(f(ans))
print(len(ans))
print(' '.join(map(str, ans)))
``` | instruction | 0 | 93,891 | 5 | 187,782 |
Yes | output | 1 | 93,891 | 5 | 187,783 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Victor adores the sets theory. Let us remind you that a set is a group of numbers where all numbers are pairwise distinct. Today Victor wants to find a set of integers S that has the following properties:
* for all x <image> the following inequality holds l ≤ x ≤ r;
* 1 ≤ |S| ≤ k;
* lets denote the i-th element of the set S as si; value <image> must be as small as possible.
Help Victor find the described set.
Input
The first line contains three space-separated integers l, r, k (1 ≤ l ≤ r ≤ 1012; 1 ≤ k ≤ min(106, r - l + 1)).
Output
Print the minimum possible value of f(S). Then print the cardinality of set |S|. Then print the elements of the set in any order.
If there are multiple optimal sets, you can print any of them.
Examples
Input
8 15 3
Output
1
2
10 11
Input
8 30 7
Output
0
5
14 9 28 11 16
Note
Operation <image> represents the operation of bitwise exclusive OR. In other words, it is the XOR operation.
Submitted Solution:
```
import random
l, r, k = map(int, input().split(' '))
if k == 1:
print(l)
print(1)
print(l)
quit()
if k == 2:
if r == l+1:
a = l
b = l^r
if a <= b:
print(a)
print(1)
print(l)
quit()
else:
print(b)
print(2)
print(l, l+1)
quit()
for i in range(l, r+1):
if i%2==0:
print(1)
print(2)
print(i, i+1)
quit()
if k == 3:
if abs(l-r) <= 10000:
for i in range(l, r+1):
for j in range(i+1, r+1):
if l <= i^j <= r:
print(0)
print(3)
print(i, j, i^j)
quit()
print(1)
print(2)
if (l%2==0):
print(l, l+1)
quit()
else:
print(l+1, l+2)
quit()
if abs(l-r) <= 1000000:
for x in range(l, r+1):
if l <= x^(x+1) <= r:
print(0)
print(3)
print(x, x+1, x^(x+1))
quit()
for i in range(500000):
if i == 420:
x = l
y = l+1
elif i == 420420:
x = r
y = r-1
else:
x = random.randint(l, r)
y = random.randint(l, r)
if x == y:
continue
if l <= x^y<= r:
print(0)
print(3)
print(x, y, x^y)
quit()
print(1)
print(2)
if (l%2==0):
print(l, l+1)
quit()
else:
print(l+1, l+2)
quit()
if k == 4:
if r == l+3:
if l%2 == 0:
print(0)
print(4)
print(l, l+1, l+2, l+3)
quit()
a = l; b = l+1; c = l+2; d = l+3;
if a^b^c == 0:
print(0)
print(3)
print(a, b, c)
quit()
if a^b^d == 0:
print(0)
print(3)
print(a, b, d)
quit()
if a^c^d == 0:
print(0)
print(3)
print(a, c, d)
quit()
if b^c^d == 0:
print(0)
print(3)
print(b, c, d)
quit()
if a^b == 1:
print(1)
print(2)
print(a, b)
quit()
print(1)
print(2)
print(b, c)
quit()
for i in range(l, r+1):
if i%2 == 0:
print(0)
print(4)
print(i, i+1, i+2, i+3)
quit()
if k >= 5:
for i in range(l, r+1):
if i%2 == 0:
print(0)
print(4)
print(i, i+1, i+2, i+3)
quit()
``` | instruction | 0 | 93,892 | 5 | 187,784 |
Yes | output | 1 | 93,892 | 5 | 187,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Victor adores the sets theory. Let us remind you that a set is a group of numbers where all numbers are pairwise distinct. Today Victor wants to find a set of integers S that has the following properties:
* for all x <image> the following inequality holds l ≤ x ≤ r;
* 1 ≤ |S| ≤ k;
* lets denote the i-th element of the set S as si; value <image> must be as small as possible.
Help Victor find the described set.
Input
The first line contains three space-separated integers l, r, k (1 ≤ l ≤ r ≤ 1012; 1 ≤ k ≤ min(106, r - l + 1)).
Output
Print the minimum possible value of f(S). Then print the cardinality of set |S|. Then print the elements of the set in any order.
If there are multiple optimal sets, you can print any of them.
Examples
Input
8 15 3
Output
1
2
10 11
Input
8 30 7
Output
0
5
14 9 28 11 16
Note
Operation <image> represents the operation of bitwise exclusive OR. In other words, it is the XOR operation.
Submitted Solution:
```
import random
l, r, k = map(int, input().split(' '))
if k == 1:
print(l)
print(1)
print(l)
quit()
if k == 2:
if r == l+1:
a = l
b = l^r
if a <= b:
print(a)
print(1)
print(l)
quit()
else:
print(b)
print(2)
print(l, l+1)
quit()
for i in range(l, r+1):
if i%2==0:
print(1)
print(2)
print(i, i+1)
quit()
if k == 3:
if abs(l-r) <= 10000:
for i in range(l, r+1):
for j in range(i+1, r+1):
if l <= i^j <= r:
print(0)
print(3)
print(i, j, i^j)
quit()
print(1)
print(2)
if (l%2==0):
print(l, l+1)
quit()
else:
print(l+1, l+2)
quit()
if abs(l-r) <= 1000000:
for x in range(l, r+1):
if l <= x^(x+1) <= r:
print(0)
print(3)
print(x, x+1, x^(x+1))
quit()
for i in range(1000000):
x = random.randint(l, r)
y = random.randint(l, r)
if x == y:
continue
if l <= x^y<= r:
print(0)
print(3)
print(x, y, x^y)
quit()
print(1)
print(2)
if (l%2==0):
print(l, l+1)
quit()
else:
print(l+1, l+2)
quit()
if k == 4:
if r == l+3:
if l%2 == 0:
print(0)
print(4)
print(l, l+1, l+2, l+3)
quit()
a = l; b = l+1; c = l+2; d = l+3;
if a^b^c == 0:
print(0)
print(3)
print(a, b, c)
quit()
if a^b^d == 0:
print(0)
print(3)
print(a, b, d)
quit()
if a^c^d == 0:
print(0)
print(3)
print(a, c, d)
quit()
if b^c^d == 0:
print(0)
print(3)
print(b, c, d)
quit()
if a^b == 1:
print(1)
print(2)
print(a, b)
quit()
print(1)
print(2)
print(b, c)
quit()
for i in range(l, r+1):
if i%2 == 0:
print(0)
print(4)
print(i, i+1, i+2, i+3)
quit()
if k >= 5:
for i in range(l, r+1):
if i%2 == 0:
print(0)
print(4)
print(i, i+1, i+2, i+3)
quit()
``` | instruction | 0 | 93,893 | 5 | 187,786 |
No | output | 1 | 93,893 | 5 | 187,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Victor adores the sets theory. Let us remind you that a set is a group of numbers where all numbers are pairwise distinct. Today Victor wants to find a set of integers S that has the following properties:
* for all x <image> the following inequality holds l ≤ x ≤ r;
* 1 ≤ |S| ≤ k;
* lets denote the i-th element of the set S as si; value <image> must be as small as possible.
Help Victor find the described set.
Input
The first line contains three space-separated integers l, r, k (1 ≤ l ≤ r ≤ 1012; 1 ≤ k ≤ min(106, r - l + 1)).
Output
Print the minimum possible value of f(S). Then print the cardinality of set |S|. Then print the elements of the set in any order.
If there are multiple optimal sets, you can print any of them.
Examples
Input
8 15 3
Output
1
2
10 11
Input
8 30 7
Output
0
5
14 9 28 11 16
Note
Operation <image> represents the operation of bitwise exclusive OR. In other words, it is the XOR operation.
Submitted Solution:
```
import random
l, r, k = map(int, input().split(' '))
if k == 1:
print(l)
print(1)
print(l)
quit()
if k == 2:
if r == l+1:
a = l
b = l^r
if a <= b:
print(a)
print(1)
print(l)
quit()
else:
print(b)
print(2)
print(l, l+1)
quit()
for i in range(l, r+1):
if i%2==0:
print(1)
print(2)
print(i, i+1)
quit()
if k == 3:
if abs(l-r) <= 10000:
for i in range(l, r+1):
for j in range(i+1, r+1):
if l <= i^j <= r:
print(0)
print(3)
print(i, j, i^j)
quit()
print(1)
print(2)
if (l%2==0):
print(l, l+1)
quit()
else:
print(l+1, l+2)
quit()
if abs(l-r) <= 1000000:
for x in range(l, r+1):
if l <= x^(x+1) <= r:
print(0)
print(3)
print(x, x+1, x^(x+1))
quit()
for i in range(1000000):
if i == 420:
x = l
y = l+1
if i == 420420:
x = r
y = r-1
x = random.randint(l, r)
y = random.randint(l, r)
if x == y:
continue
if l <= x^y<= r:
print(0)
print(3)
print(x, y, x^y)
quit()
print(1)
print(2)
if (l%2==0):
print(l, l+1)
quit()
else:
print(l+1, l+2)
quit()
if k == 4:
if r == l+3:
if l%2 == 0:
print(0)
print(4)
print(l, l+1, l+2, l+3)
quit()
a = l; b = l+1; c = l+2; d = l+3;
if a^b^c == 0:
print(0)
print(3)
print(a, b, c)
quit()
if a^b^d == 0:
print(0)
print(3)
print(a, b, d)
quit()
if a^c^d == 0:
print(0)
print(3)
print(a, c, d)
quit()
if b^c^d == 0:
print(0)
print(3)
print(b, c, d)
quit()
if a^b == 1:
print(1)
print(2)
print(a, b)
quit()
print(1)
print(2)
print(b, c)
quit()
for i in range(l, r+1):
if i%2 == 0:
print(0)
print(4)
print(i, i+1, i+2, i+3)
quit()
if k >= 5:
for i in range(l, r+1):
if i%2 == 0:
print(0)
print(4)
print(i, i+1, i+2, i+3)
quit()
``` | instruction | 0 | 93,894 | 5 | 187,788 |
No | output | 1 | 93,894 | 5 | 187,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Victor adores the sets theory. Let us remind you that a set is a group of numbers where all numbers are pairwise distinct. Today Victor wants to find a set of integers S that has the following properties:
* for all x <image> the following inequality holds l ≤ x ≤ r;
* 1 ≤ |S| ≤ k;
* lets denote the i-th element of the set S as si; value <image> must be as small as possible.
Help Victor find the described set.
Input
The first line contains three space-separated integers l, r, k (1 ≤ l ≤ r ≤ 1012; 1 ≤ k ≤ min(106, r - l + 1)).
Output
Print the minimum possible value of f(S). Then print the cardinality of set |S|. Then print the elements of the set in any order.
If there are multiple optimal sets, you can print any of them.
Examples
Input
8 15 3
Output
1
2
10 11
Input
8 30 7
Output
0
5
14 9 28 11 16
Note
Operation <image> represents the operation of bitwise exclusive OR. In other words, it is the XOR operation.
Submitted Solution:
```
def main():
from itertools import combinations
from functools import reduce
from random import randrange
l, r, k = [int(i) for i in input().split()]
if r - l < 4:
f = float("inf")
result = None
numbers = list(range(l, r + 1))
for mask in range(1, 1 << (r - l + 1)):
tmp = [numbers[i] for i in range(r - l + 1) if mask & (1 << i)]
if len(tmp) <= k and reduce(lambda x, y: x ^ y, tmp) < f:
f = reduce(lambda x, y: x ^ y, tmp)
result = tmp
elif k >= 4:
a = l + l % 2
f = 0
result = [a, a + 1, a + 2, a + 3]
elif k == 1:
f = l
result = [l]
elif k == 2:
a = l + l % 2
f = 1
result = [a, a + 1]
elif k == 3:
a = l + l % 2
f = 1
result = [a, a + 1]
for a in range(l, min(r + 1, l + 400)):
for b in range(max(l, r - 400), r + 1):
if l <= a ^ b <= r:
f = 0
result = [a, b, a ^ b]
break
print(f)
print(len(result))
print(' '.join(str(i) for i in sorted(result)))
main()
``` | instruction | 0 | 93,895 | 5 | 187,790 |
No | output | 1 | 93,895 | 5 | 187,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Victor adores the sets theory. Let us remind you that a set is a group of numbers where all numbers are pairwise distinct. Today Victor wants to find a set of integers S that has the following properties:
* for all x <image> the following inequality holds l ≤ x ≤ r;
* 1 ≤ |S| ≤ k;
* lets denote the i-th element of the set S as si; value <image> must be as small as possible.
Help Victor find the described set.
Input
The first line contains three space-separated integers l, r, k (1 ≤ l ≤ r ≤ 1012; 1 ≤ k ≤ min(106, r - l + 1)).
Output
Print the minimum possible value of f(S). Then print the cardinality of set |S|. Then print the elements of the set in any order.
If there are multiple optimal sets, you can print any of them.
Examples
Input
8 15 3
Output
1
2
10 11
Input
8 30 7
Output
0
5
14 9 28 11 16
Note
Operation <image> represents the operation of bitwise exclusive OR. In other words, it is the XOR operation.
Submitted Solution:
```
def solve(L,R,k):
if k < 5:
if k==1:
return [L]
elif k==2:
if R-L+1==2:
if L < (L^R):
return [L]
else:
return [R]
else:
if L&1:
return [L+1,L+2]
else:
return [L,L+1]
else:
if L==1:
return [1,2,3]
elif k==3:
b = 60
while (L&(1<<b))==0 and (R&(1<<b))==0:
b -= 1
if (L&(1<<b))==(R&(1<<b)):
if L&1:
return [L+1,L+2]
else:
return [L,L+1]
else:
return [L,L^((1<<b)-1),(1<<b)-1]
else:
if (L^1)&1:
return [L,L+1,L+2,L+3]
elif L+4 <= R:
return [L+1,L+2,L+3,L+4]
else: # odd, odd+1, odd+2, odd+3 011 100 101 110
return [L+1,L+2]
else:
if L&1:
return [L+1,L+2,L+3,L+4]
else:
return [L,L+1,L+2,L+3]
ans = solve(*map(int,input().split()))
xor = 0
for x in ans:
xor ^= x
print(xor)
print(len(ans))
print(*ans)
``` | instruction | 0 | 93,896 | 5 | 187,792 |
No | output | 1 | 93,896 | 5 | 187,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You're given Q queries of the form (L, R).
For each query you have to find the number of such x that L ≤ x ≤ R and there exist integer numbers a > 0, p > 1 such that x = ap.
Input
The first line contains the number of queries Q (1 ≤ Q ≤ 105).
The next Q lines contains two integers L, R each (1 ≤ L ≤ R ≤ 1018).
Output
Output Q lines — the answers to the queries.
Example
Input
6
1 4
9 9
5 7
12 29
137 591
1 1000000
Output
2
1
0
3
17
1111
Note
In query one the suitable numbers are 1 and 4.
Submitted Solution:
```
from math import sqrt
def isnps(x):
return sqrt(x)%1 != 0
MAX = 10**18
sp = set()
for p in range(3, 60):
maxx = int(10**(18/p))
for i in range(2, maxx):
if isnps(i**p):
sp.add(i**p)
sp = list(sp)
sp.sort()
def bs(a,val):
low,high=0,len(a)-1
while low<=high:
mid=(low+high)//2
if a[mid]>=val:
high=mid-1
else:
low=mid+1
return high
q = int(input())
for t in range(q):
l, r = map(int, input().split())
ps = int(sqrt(r)) - int(sqrt(l-1))
print(ps,end=' ')
i = bs(sp, r)
j = bs(sp, l)
ps += i-j
print(ps)
``` | instruction | 0 | 94,123 | 5 | 188,246 |
No | output | 1 | 94,123 | 5 | 188,247 |
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