message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5 | instruction | 0 | 94,385 | 5 | 188,770 |
"Correct Solution:
```
INF = 10 ** 20
n, q = map(int, input().split())
size = 1
while size < n:
size *= 2
size = size * 2 - 1
seg_tree = [2 ** 31 - 1 for _ in range(size)]
def update(i, x):
ind = size // 2 + i
seg_tree[ind] = x
while ind:
ind = (ind - 1) // 2
ch1 = seg_tree[ind * 2 + 1]
ch2 = seg_tree[ind * 2 + 2]
seg_tree[ind] = min(ch1, ch2)
def _find(s, t, k, l, r):
if r < s or t < l: return INF
if s <= l and r <= t:
return seg_tree[k]
else:
vl = _find(s, t, k * 2 + 1, l, (l + r) // 2)
vr = _find(s, t, k * 2 + 2, (l + r) // 2 + 1, r)
return min(vl, vr)
def find(s, t):
return _find(s, t, 0, 0, size // 2)
for _ in range(q):
com, x, y = map(int, input().split())
if not com:
update(x, y)
else:
print(find(x, y))
``` | output | 1 | 94,385 | 5 | 188,771 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5 | instruction | 0 | 94,386 | 5 | 188,772 |
"Correct Solution:
```
import math
class RMQ:
INF = 2**31 - 1
N = 0
def __init__(self, n_):
self.N = 1
RMQ.D = []
while self.N < n_:
self.N = 2 * self.N
for i in range((2*self.N)-1):
RMQ.D.append(RMQ.INF)
def update(self, k, x):
k += self.N-1
RMQ.D[k] = x
while k > 0:
k = math.floor((k-1)/2)
RMQ.D[k] = min(RMQ.D[(k*2)+1], RMQ.D[(k*2)+2])
def findMin(self, a, b):
return self.query(a, b+1, 0, 0, self.N)
def query(self, a, b, k, l, r):
if r <= a or b <= l:
return RMQ.INF
if a <= l and r <= b:
return RMQ.D[k]
vl = self.query(a, b, (k*2) + 1, l, (l + r)/2)
vr = self.query(a, b, (k*2) + 2, (l + r)/2, r)
return min(vl, vr)
if __name__ == "__main__":
n_, q = (int(z) for z in input().split()) #n: num of sequence, q: num of query
rmq = RMQ(n_)
for i in range(q):
com, x, y = (int(z) for z in input().split())
if(com == 0):
rmq.update(x, y)
else:
res = rmq.findMin(x, y)
print(res)
``` | output | 1 | 94,386 | 5 | 188,773 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5 | instruction | 0 | 94,387 | 5 | 188,774 |
"Correct Solution:
```
INF = 2**31-1
n, q = map(int, input().split())
size = 2**((n-1).bit_length())
seg_tree = [INF]*(size*2)
import sys
input = sys.stdin.readline
def update(i, x):
ind = size+i
seg_tree[ind] = x
while ind>1:
ind >>= 1
left = seg_tree[ind*2]
right = seg_tree[ind*2+1]
seg_tree[ind] = min(left, right)
def find(s,t):
L = s+size
R = t+size
ret = INF
while L<R:
if R&1:
R-=1
ret = min(ret, seg_tree[R])
if L&1:
ret = min(ret, seg_tree[L])
L+=1
L=L>>1
R=R>>1
return ret
for _ in range(q):
com, x, y = map(int, input().split())
if not com:
update(x, y)
else:
print(find(x,y+1))
``` | output | 1 | 94,387 | 5 | 188,775 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""
input:
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
output:
1
2
"""
import math
import sys
INIT_MAX = pow(2, 31) - 1
class SegmentTree(object):
__slots__ = ('dat', 'ext_length')
def __init__(self, orig_length):
"""
Init a SegmentTree with update and find for range minimum queries.
"""
self.ext_length = pow(2, math.ceil(math.log2(orig_length)))
self.dat = [INIT_MAX] * (2 * self.ext_length - 1)
# let A[k]=a
def update(self, k, a):
k += self.ext_length - 1
self.dat[k] = a
while k > 0:
k = (k - 1) // 2
self.dat[k] = min(self.dat[k * 2 + 1], self.dat[k * 2 + 2])
# get min(A[s] A[s+1] ... A[t])
def find(self, s, t, k=0, left=0, right=float('inf')):
if right <= s or t <= left:
return INIT_MAX
elif s <= left <= right <= t:
return self.dat[k]
else:
vl = self.find(s, t, k * 2 + 1, left, (left + right) // 2)
vr = self.find(s, t, k * 2 + 2, (left + right) // 2, right)
return min(vl, vr)
def cmd_exec(queries, n_num):
case = SegmentTree(n_num)
end = pow(2, math.ceil(math.log2(n_num)))
for query in queries:
cmd, ele_1, ele_2 = map(int, query)
if cmd == 0:
case.update(ele_1, ele_2)
elif cmd == 1:
# assert ele_1 <= ele_2
res = case.find(s=ele_1, t=ele_2 + 1, right=end)
print(res)
return None
def solve():
_input = sys.stdin.readlines()
n_num, q_num = map(int, _input[0].split())
queries = map(lambda x: x.split(), _input[1:])
cmd_exec(queries, n_num)
return None
if __name__ == '__main__':
solve()
``` | instruction | 0 | 94,388 | 5 | 188,776 |
Yes | output | 1 | 94,388 | 5 | 188,777 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
import heapq
from collections import deque
from enum import Enum
import sys
import math
from _heapq import heappush, heappop
#BIG_NUM = 2000000000
BIG_NUM = 2147483647
HUGE_NUM = 9999999999999999
MOD = 1000000007
EPS = 0.000000001
global N
global table
def MIN(A,B):
if A <= B:
return A
else:
return B
def init(first_N):
global N
while N < first_N:
N *= 2
def update(loc,value):
global N
loc += N-1
table[loc] = value
if N == 1:
return
parent = (loc-1)//2
while True:
table[parent] = MIN(table[2*parent+1],table[2*parent+2])
if parent == 0:
break
parent = (parent-1)//2
def query(search_left,search_right,node_id,node_left,node_right):
if search_right < node_left or search_left > node_right:
return BIG_NUM
if search_left <= node_left and search_right >= node_right:
return table[node_id]
else:
left_min = query(search_left,search_right,2*node_id+1,node_left,(node_left+node_right)//2)
right_min = query(search_left,search_right,2*node_id+2,(node_left+node_right)//2+1,node_right)
return MIN(left_min,right_min)
first_N,num_query = map(int,input().split())
N = 1
init(first_N)
table = [None]*(2*N-1)
for i in range(2*N-1):
table[i] = BIG_NUM
for loop in range(num_query):
command,left,right = map(int,input().split())
if command == 0:
update(left,right)
else:
print("%d"%(query(left,right,0,0,N-1)))
``` | instruction | 0 | 94,389 | 5 | 188,778 |
Yes | output | 1 | 94,389 | 5 | 188,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
from math import sqrt, ceil
def_val = 2 ** 31 - 1
n, q = map(int, input().split())
unit = ceil(sqrt(n))
l = [(def_val, [def_val] * unit) for _ in range(unit)]
while q:
op, s, t = map(int, input().split())
sd, sm = s // unit, s % unit
if op:
td, tm = t // unit, t % unit
if sd == td:
print(min(l[sd][1][sm:tm + 1]))
else:
unit_min = min((tup[0] for tup in l[sd + 1:td]), default=def_val)
s_min = min(l[sd][1][sm:], default=def_val)
t_min = min(l[td][1][:tm + 1], default=def_val)
print(min(unit_min, s_min, t_min))
else:
unit_list = l[sd][1]
unit_list[sm] = t
l[sd] = (min(unit_list), unit_list)
q -= 1
``` | instruction | 0 | 94,390 | 5 | 188,780 |
Yes | output | 1 | 94,390 | 5 | 188,781 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""
input:
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
output:
1
2
"""
import math
import sys
class SegmentTree(object):
__slots__ = ('dat', 'tree_range')
def __init__(self, n):
"""
Init a SegmentTree with update and find for range minimum queries.
"""
self.tree_range = pow(2, math.ceil(math.log2(n)))
self.dat = [float('inf')] * (2 * self.tree_range - 1)
# let A[k]=a
def update(self, k, a):
k += self.tree_range - 1
self.dat[k] = a
while k > 0:
k = (k - 1) // 2
self.dat[k] = min(self.dat[k * 2 + 1], self.dat[k * 2 + 2])
# get min(A[s] A[s+1] ... A[t])
def find(self, s, t, k=0, left=0, right=float('inf')):
if right <= s or t <= left:
return float('inf')
elif s <= left <= right <= t:
return self.dat[k]
else:
vl = self.find(s, t, k * 2 + 1, left, (left + right) // 2)
vr = self.find(s, t, k * 2 + 2, (left + right) // 2, right)
return min(vl, vr)
def cmd_exec(cmd_list, n_num):
case = SegmentTree(n_num)
end = pow(2, math.ceil(math.log2(n_num)))
init_max = pow(2, 31) - 1
for query in cmd_list:
cmd, ele_1, ele_2 = map(int, query)
if cmd == 0:
case.update(ele_1, ele_2)
elif cmd == 1:
assert ele_1 <= ele_2
res = case.find(s=ele_1, t=ele_2 + 1, right=end)
print(res) if not math.isinf(res) else print(init_max)
return None
def solve():
_input = sys.stdin.readlines()
n_num, q_num = map(int, _input[0].split())
q_list = map(lambda x: x.split(), _input[1:])
cmd_exec(q_list, n_num)
return None
if __name__ == '__main__':
solve()
``` | instruction | 0 | 94,391 | 5 | 188,782 |
Yes | output | 1 | 94,391 | 5 | 188,783 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
M = 2147483647
a = [M for i in range(100000)]
def j_min(x,y):
if x < y:return x
else: return y
def find(x,y,i,l,r):
if r<=x or y<=l:return M
if x<=l and r<=y: return a[i]
return min(find(x,y,i*2,l,(l+r)/2),find(x,y,i*2+1,(l+r)/2,r))
if __name__=='__main__':
n, m = (int(x) for x in input().split())
t=1
while t<n :t *= 2
for i in range(m-1,-1,-1):
com,x,y = (int(x) for x in input().split())
if com :
print(find(x,y+1,1,0,t))
else:
x+=t
a[x]=y
while isinstance(x, int):
a[int(x/2)]=j_min(a[int(x)],a[int(x)^1])
x/=2
``` | instruction | 0 | 94,392 | 5 | 188,784 |
No | output | 1 | 94,392 | 5 | 188,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
# coding: utf-8
class SqrtDecomposition:
# RMQ用平方分割
# n:要素数 init:配列初期値
def __init__(self,n,init=0):
self.data=[init for i in range(n)]
self.sqrt_n=int(n**0.5)+1
self.bucket=[init for i in range(self.sqrt_n)]
# x を y にする
def update(self,x,y):
self.data[x] = y
tmp = self.data[x//self.sqrt_n * self.sqrt_n]
for i in range(x//self.sqrt_n * self.sqrt_n, min(x//self.sqrt_n * self.sqrt_n + self.sqrt_n, n)):
if tmp > self.data[i]:
tmp = self.data[i]
self.bucket[x//self.sqrt_n] = tmp
print(self.data)
print(self.bucket)
# [x,y) の最小を求める
def find(self,x,y):
tmp = 10**19
for i in range(self.sqrt_n):
l,r=i*self.sqrt_n,(i+1)*self.sqrt_n
if r <= x or y <= l :
continue
if x <= l and r <= y :
tmp = min(tmp, self.bucket[i]);
else:
for j in range(max(x, l),min(y, r)):
tmp = min(tmp, self.data[i]);
return tmp
n,q = map(int,input().split())
sd=SqrtDecomposition(n,2**31-1)
for i in range(q):
c,x,y=map(int,input().split())
if c==0:
sd.update(x,y)
else:
print(sd.find(x,y+1))
``` | instruction | 0 | 94,393 | 5 | 188,786 |
No | output | 1 | 94,393 | 5 | 188,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
import sys
import time
import math
sys.setrecursionlimit(20000)
def update(tree,x,y,N):
# happa no offset
x += N
tree[x] = y
# segment tree no update suru
while x>0:
x = int((x - 1)/2)
left = x*2+1
right = x*2+2
if(right > N):
right = right - 1
tree[x] = min(tree[left],tree[right])
def find(tree,x,y,k,l,r):
# mitu kara nakatta
if ( r <= x or y <= l):
return 2**31 - 1
# sita wo mite itte mitukatta toki (intersect)
if ( x <= l and r <= y):
#print(k,l,r)
return tree[k]
# sita ni sagaru
v_left = find(tree, x, y, k*2 + 1, l, int((l+r)/2))
v_right = find(tree, x, y, k*2 + 2, int((l+r)/2), r)
return min(v_left, v_right)
if __name__ == '__main__':
_N,query_num = map(int, input().split())
INT_MAX = 2**31 - 1
N = _N*2
A_bin_tree = [INT_MAX]*(N)
#start = time.time()
for i in range(query_num):
operate,x,y = map(int, input().split())
# update
if(operate==0):
update(A_bin_tree,x,y,_N)
#print(A_bin_tree)
# find
if(operate==1):
# tyouten kara miteiku
x = find(A_bin_tree,x,y+1,0,0,N)
print(x)
#elapsed_time = time.time() - start
#print ("elapsed_time:{0}".format(elapsed_time) + "[sec]")
``` | instruction | 0 | 94,394 | 5 | 188,788 |
No | output | 1 | 94,394 | 5 | 188,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence A = {a0, a1, . . . , an-1} with the following operations:
* find(s, t): report the minimum element in as, as+1, . . . ,at.
* update(i, x): change ai to x.
Note that the initial values of ai (i = 0, 1, . . . , n−1) are 231-1.
Constraints
* 1 ≤ n ≤ 100000
* 1 ≤ q ≤ 100000
* If comi is 0, then 0 ≤ xi < n, 0 ≤ yi < 231-1.
* If comi is 1, then 0 ≤ xi < n, 0 ≤ yi < n.
Input
n q
com0 x0 y0
com1 x1 y1
...
comq−1 xq−1 yq−1
In the first line, n (the number of elements in A) and q (the number of queries) are given. Then, q queries are given where com represents the type of queries. '0' denotes update(xi, yi) and '1' denotes find(xi, yi).
Output
For each find operation, print the minimum element.
Examples
Input
3 5
0 0 1
0 1 2
0 2 3
1 0 2
1 1 2
Output
1
2
Input
1 3
1 0 0
0 0 5
1 0 0
Output
2147483647
5
Submitted Solution:
```
import math
def update(index,n):
targ[index] = n
index = (index - 1) // 2
while True:
targ[index] = min(targ[index * 2 + 1],targ[index * 2 + 2])
if index <= 0:
break
index = (index - 1) // 2
def find(i,e,node,inode,enode):
#print(i,e,node,inode,enode)
if inode > e or enode < i:
return float("inf")
elif (i <= inode and enode <= e) or inode==enode:
return targ[node]
else:
irange = find(i,e,2*node + 1,inode,(inode+enode)// 2 )
erange = find(i,e,2*node + 2,(inode+enode)//2 + 1,enode)
return min(irange,erange)
num,query = (int(n) for n in input().split(' '))
initial = 2147483647
ln = 2 ** math.ceil(math.log2(num)) - 1
if num == 1:
tail = 2
else:
tail = 2 ** math.ceil(math.log2(num)) - num
global targ
targ = [initial] * (ln + num + tail)
length = num - 1
for q in range(query):
#print(targ)
temp = [int(n) for n in input().split(' ') ]
if temp[0] == 0:
update(temp[1] + ln,temp[2])
else:
print(find(temp[1],temp[2],0,0,length))
``` | instruction | 0 | 94,395 | 5 | 188,790 |
No | output | 1 | 94,395 | 5 | 188,791 |
Provide a correct Python 3 solution for this coding contest problem.
Find the number, modulo 998244353, of sequences of length N consisting of 0, 1 and 2 such that none of their contiguous subsequences totals to X.
Constraints
* 1 \leq N \leq 3000
* 1 \leq X \leq 2N
* N and X are integers.
Input
Input is given from Standard Input in the following format:
N X
Output
Print the number, modulo 998244353, of sequences that satisfy the condition.
Examples
Input
3 3
Output
14
Input
8 6
Output
1179
Input
10 1
Output
1024
Input
9 13
Output
18402
Input
314 159
Output
459765451 | instruction | 0 | 95,903 | 5 | 191,806 |
"Correct Solution:
```
import sys
input = lambda: sys.stdin.readline().rstrip()
N, X = map(int, input().split())
P = 998244353
A = [[0] * (2*i+1) for i in range(N+1)] # A[i][j] is the number of permutations of 1's and 2's whose length is i and whose sum is j
A[0][0] = 1
B = [0] * (N + 1) # B[i] is the number of permutations of 1's and 2's with length i none of whose consecutive subsequenses is equal to X
for i in range(N):
for j in range(i, 2*i+1):
A[i+1][j+1] += A[i][j]
A[i+1][j+2] += A[i][j]
if A[i+1][j+1] >= P: A[i+1][j+1] -= P
if A[i+1][j+2] >= P: A[i+1][j+2] -= P
# Type 1: Sum is below X
for i in range(N+1):
for j in range(i, min(2*i+1, X)):
B[i] += A[i][j]
# Type 2: Sum is 2X or more
if X % 2:
for i in range(X, N+1):
B[i] += 1
# Type 3: X <= Sum < 2X
for i in range(1, X):
a = X - 1 - 2 * i
if a < 0: continue
for j in range((a+1) // 2, a + 1):
k = j + 2 * i
if k > N: break
B[k] += A[j][a]
if B[k] >= P: B[k] -= P
ans = 0
for i, b in enumerate(B):
ans = (ans + b * A[-1][-1-i]) % P
print(ans)
``` | output | 1 | 95,903 | 5 | 191,807 |
Provide a correct Python 3 solution for this coding contest problem.
Find the number, modulo 998244353, of sequences of length N consisting of 0, 1 and 2 such that none of their contiguous subsequences totals to X.
Constraints
* 1 \leq N \leq 3000
* 1 \leq X \leq 2N
* N and X are integers.
Input
Input is given from Standard Input in the following format:
N X
Output
Print the number, modulo 998244353, of sequences that satisfy the condition.
Examples
Input
3 3
Output
14
Input
8 6
Output
1179
Input
10 1
Output
1024
Input
9 13
Output
18402
Input
314 159
Output
459765451 | instruction | 0 | 95,904 | 5 | 191,808 |
"Correct Solution:
```
"""
Writer: SPD_9X2
https://atcoder.jp/contests/tenka1-2019/tasks/tenka1_2019_f
Xが偶数か奇数かは重要な気がする
長さL(<=N)の1,2で構成された文字列の問題、に変換できる
O(L)で求められばおｋ
dpか？
X == 1なら、0,2のみで構成されてればおｋ
X == 2なら、1が2つ以上入っていたら不可能 0 & 1が1つまで
X == 3なら、2を入れる場合→1は入れられないが、2を好きなだけ入れていい
入れない場合→1を2個まで入れられる
X == 4なら、
→やはり偶奇が重要か？
とどく場合は X-1 → X+1の移動は強制
すなわち 座標1に行ってはいけない
初手は2に行くしかない
同様にX+2には行けない
X+3に行くしかない
3には行けないから4に行くしかない
つまり2以外不可？？
無限に移動を続ける場合は少なくともX=奇数 2のみ以外無理
偶数の場合はX以前に奇数回1をはさむ必要あり
a→a+1と移動すると、X+a-1から先は移動できなくなる
よって2Xは絶対超えられない
あとは数え上げにどうやって落とすか
Lは固定でいいと思うんだよな
O(L)で解ければ勝ち
dp ?
総和で場合分け or Lで場合分け
総和で場合分けする場合、当然Lは異なるのでまとめる必要がある
Lの長さの移動の寄与にはNCLを掛ける必要がある
移動するときにLは1増えるんだよな…
nC(l+1) = nCl * (n-l)/(l+1)
移動処理を一気に行えばlは統一できるからおｋ？
総和SはX以上の場合 X+1+2kしかありえない
S-X以前は2のみ進軍可能、以降は自由
対称性？
1と2の数を全探索？ ならばO(N**2)でいける
1がA個,2がB個の時、最初と最後に2をいくつか置く必要がある
→後は残りの位置から1を置く場所を選べばよい
→解けたっぽい？
場合分け頑張ろう
合計がX以下の場合→完全に自由
合計が2X以上の場合→Xが奇数の場合のみ all2が可能。それ以外は死
X以上2X以下の場合
→
S-Xが奇数である必要あり
まず2を(S-X+1)こ消費する（前後に置く分）
あとは自由に順列を作ってどうぞ
"""
def modfac(n, MOD):
f = 1
factorials = [1]
for m in range(1, n + 1):
f *= m
f %= MOD
factorials.append(f)
inv = pow(f, MOD - 2, MOD)
invs = [1] * (n + 1)
invs[n] = inv
for m in range(n, 1, -1):
inv *= m
inv %= MOD
invs[m - 1] = inv
return factorials, invs
def modnCr(n,r,mod,fac,inv): #上で求めたfacとinvsを引数に入れるべし(上の関数で与えたnが計算できる最大のnになる)
return fac[n] * inv[n-r] * inv[r] % mod
N,X = map(int,input().split())
mod = 998244353
fac,inv = modfac(N+10,mod)
ans = 0
for two in range(N+1):
for one in range(N+1):
if one + two > N:
break
dist = one + two*2
zero = modnCr(N,one+two,mod,fac,inv)
now = 0
if dist < X:
now = modnCr(one+two,one,mod,fac,inv) * zero
elif dist == X:
continue
elif dist < 2*X:
if (dist-X) % 2 == 0:
continue
dtwo = two - (dist-X+1)
if dtwo >= 0:
now = modnCr(one+dtwo,one,mod,fac,inv) * zero
elif X % 2 == 1 and one == 0:
now = zero
#print (one,two,now)
ans += now
ans %= mod
print (ans)
``` | output | 1 | 95,904 | 5 | 191,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number, modulo 998244353, of sequences of length N consisting of 0, 1 and 2 such that none of their contiguous subsequences totals to X.
Constraints
* 1 \leq N \leq 3000
* 1 \leq X \leq 2N
* N and X are integers.
Input
Input is given from Standard Input in the following format:
N X
Output
Print the number, modulo 998244353, of sequences that satisfy the condition.
Examples
Input
3 3
Output
14
Input
8 6
Output
1179
Input
10 1
Output
1024
Input
9 13
Output
18402
Input
314 159
Output
459765451
Submitted Solution:
```
MOD = 998244353
MAX_K = 3000
def ceil(a: int, b: int)->int:
'''a/b の切り上げを計算する。
'''
if (a // b) * b == a:
return a//b
return a//b + 1
# __fact[n] = n!
__fact = [0] * (MAX_K+1)
def init_comb():
# initialize __fact
__fact[0] = 1
for n in range(MAX_K):
__fact[n+1] = ((n+1) * __fact[n]) % MOD
def mod_inv(n: int, mod: int)->int:
b, u, v = mod, 1, 0
while b > 0:
t = n // b
n -= t * b
u -= t * v
n, b = b, n
u, v = v, u
return (u+mod) % mod
def comb(n: int, r: int)->int:
'''nCr を計算する
'''
res = __fact[n]
res = (res * mod_inv(__fact[n-r], MOD)) % MOD
res = (res * mod_inv(__fact[r], MOD)) % MOD
return res
def banned_x(N: int, X: int)->int:
# 数列の全体の和を固定して調べる。
# 数列の和の最大値は全て 2 でできている数列の 2*N
res = 1 # 0 だけでできている分
for S in range(1, 2*N+1):
tmp = res
if S < X:
# 1, 2 を合計で k 個利用するとする。
# 1 を p 個、2 を q 個とすると
# p+q=K; p+2q=S;
# より
# p=2K-S; q=S-K
# となる。
# このとき、0, 1, 2 の並べ方は
# comb(N,p) * comb(N-p,q)
# である。
# また、0<=p; 0<=q より S/2<=k<=S が成り立つ。
for k in range(ceil(S, 2), min(S, N)+1):
p, q = 2*k - S, S-k
res += comb(N, p) * comb(N-p, q)
res %= MOD
elif S == X:
# nothing
continue
elif (S-X) & 1:
# 2 を置かなければならない場所が [0, only2)
# と (only2, N]
only2 = (S-(X-1))//2
# 1 が含まれない場合
if 2*only2 >= X-1:
if X & 1:
# 2 の置き方は N 個の位置から S//2 個
# 選ぶ組み合わせ。残りは 0 を置く
res += comb(N, S//2)
res %= MOD
# 1 が含まれる場合
else:
# SS は 1,2 なんでも置いていいゾーンの幅
SS = X-1-2*only2
# k,p,q の変数の意味は S<X の時と同じ
# ただし、2 は 2*only2 の領域にも置くので
# 2 の個数は SS-k+2*only2 になり、
# (N 個の位置から k+2*only2 個の位置を 1,2 用に確保)
# x (k 個の位置から p 個の 1 を置く位置を確保)
for k in range(ceil(SS, 2), min(N-2*only2, SS)+1):
p, q = 2*k-SS, SS-k
res += comb(N, k+2*only2) * comb(k, p)
res %= MOD
# print('S={}, res={}'.format(S, res-tmp))
return res
if __name__ == "__main__":
N, X = map(int, input().split())
init_comb()
ans = banned_x(N, X)
print(ans)
``` | instruction | 0 | 95,905 | 5 | 191,810 |
No | output | 1 | 95,905 | 5 | 191,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number, modulo 998244353, of sequences of length N consisting of 0, 1 and 2 such that none of their contiguous subsequences totals to X.
Constraints
* 1 \leq N \leq 3000
* 1 \leq X \leq 2N
* N and X are integers.
Input
Input is given from Standard Input in the following format:
N X
Output
Print the number, modulo 998244353, of sequences that satisfy the condition.
Examples
Input
3 3
Output
14
Input
8 6
Output
1179
Input
10 1
Output
1024
Input
9 13
Output
18402
Input
314 159
Output
459765451
Submitted Solution:
```
MOD = 998244353
MAX_K = 3000
def ceil(a: int, b: int)->int:
'''a/b の切り上げを計算する。
'''
if (a // b) * b == a:
return a//b
return a//b + 1
# __fact[n] = n!
__fact = [0] * (MAX_K+1)
# __inv[n] = (n! の mod MOD に関する逆数)
__inv = [0] * (MAX_K+1)
def init_comb():
# initialize __fact
__fact[0] = 1
__inv[0] = 1
for n in range(MAX_K):
__fact[n+1] = ((n+1) * __fact[n]) % MOD
__inv[n+1] = mod_inv((n+1) * __fact[n], MOD)
def mod_inv(n: int, mod: int)->int:
b, u, v = mod, 1, 0
while b > 0:
t = n // b
n -= t * b
u -= t * v
n, b = b, n
u, v = v, u
return (u+mod) % mod
def comb(n: int, r: int)->int:
'''nCr を計算する
'''
res = __fact[n]
res = (res * __inv[n-r]) % MOD
res = (res * __inv[r]) % MOD
return res
def banned_x(N: int, X: int)->int:
# 数列の全体の和を固定して調べる。
# 数列の和の最大値は全て 2 でできている数列の 2*N
res = 1 # 0 だけでできている分
for S in range(1, 2*N+1):
if S < X:
# 1, 2 を合計で k 個利用するとする。
# 1 を p 個、2 を q 個とすると
# p+q=K; p+2q=S;
# より
# p=2K-S; q=S-K
# となる。
# このとき、0, 1, 2 の並べ方は
# comb(N,p) * comb(N-p,q)
# である。
# また、0<=p; 0<=q より S/2<=k<=S が成り立つ。
for k in range(ceil(S, 2), min(S, N)+1):
p, q = 2*k - S, S-k
res += comb(N, p) * comb(N-p, q)
res %= MOD
elif S == X:
# nothing
continue
elif (S-X) & 1:
# 2 を置かなければならない場所が [0, only2)
# と (only2, N]
only2 = (S-(X-1))//2
# 1 が含まれない場合
if 2*only2 >= X-1:
if X & 1:
# 2 の置き方は N 個の位置から S//2 個
# 選ぶ組み合わせ。残りは 0 を置く
res += comb(N, S//2)
res %= MOD
# 1 が含まれる場合
else:
# SS は 1,2 なんでも置いていいゾーンの幅
SS = X-1-2*only2
# k,p,q の変数の意味は S<X の時と同じ
# ただし、2 は 2*only2 の領域にも置くので
# 2 の個数は SS-k+2*only2 になり、
# (N 個の位置から k+2*only2 個の位置を 1,2 用に確保)
# x (k 個の位置から p 個の 1 を置く位置を確保)
for k in range(ceil(SS, 2), min(N-2*only2, SS)+1):
p, q = 2*k-SS, SS-k
res += comb(N, k+2*only2) * comb(k, p)
res %= MOD
# print('S={}, res={}'.format(S, res-tmp))
return res
if __name__ == "__main__":
N, X = map(int, input().split())
init_comb()
ans = banned_x(N, X)
print(ans)
``` | instruction | 0 | 95,906 | 5 | 191,812 |
No | output | 1 | 95,906 | 5 | 191,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number, modulo 998244353, of sequences of length N consisting of 0, 1 and 2 such that none of their contiguous subsequences totals to X.
Constraints
* 1 \leq N \leq 3000
* 1 \leq X \leq 2N
* N and X are integers.
Input
Input is given from Standard Input in the following format:
N X
Output
Print the number, modulo 998244353, of sequences that satisfy the condition.
Examples
Input
3 3
Output
14
Input
8 6
Output
1179
Input
10 1
Output
1024
Input
9 13
Output
18402
Input
314 159
Output
459765451
Submitted Solution:
```
a
``` | instruction | 0 | 95,907 | 5 | 191,814 |
No | output | 1 | 95,907 | 5 | 191,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number, modulo 998244353, of sequences of length N consisting of 0, 1 and 2 such that none of their contiguous subsequences totals to X.
Constraints
* 1 \leq N \leq 3000
* 1 \leq X \leq 2N
* N and X are integers.
Input
Input is given from Standard Input in the following format:
N X
Output
Print the number, modulo 998244353, of sequences that satisfy the condition.
Examples
Input
3 3
Output
14
Input
8 6
Output
1179
Input
10 1
Output
1024
Input
9 13
Output
18402
Input
314 159
Output
459765451
Submitted Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
import numpy as np
"""
・累積和の到達地点集合ごとに見る
・type1：X未満で終わる
・type2：X+1以上2X未満
・type3：2X以上、これはXが奇数の場合のみ
"""
MOD = 998244353
N,X = map(int,read().split())
def cumprod(arr,MOD):
L = len(arr); Lsq = int(L**.5+1)
arr = np.resize(arr,Lsq**2).reshape(Lsq,Lsq)
for n in range(1,Lsq):
arr[:,n] *= arr[:,n-1]; arr[:,n] %= MOD
for n in range(1,Lsq):
arr[n] *= arr[n-1,-1]; arr[n] %= MOD
return arr.ravel()[:L]
def make_fact(U,MOD):
x = np.arange(U,dtype=np.int64); x[0] = 1
fact = cumprod(x,MOD)
x = np.arange(U,0,-1,dtype=np.int64); x[0] = pow(int(fact[-1]),MOD-2,MOD)
fact_inv = cumprod(x,MOD)[::-1]
return fact,fact_inv
U = N+100
fact,fact_inv = make_fact(U,MOD)
combN = fact[N] * fact_inv[:N+1] % MOD * fact_inv[N::-1] % MOD
def F1(N,X):
# X未満で終わる場合
def mult(P,Q):
# 多項式の積
dP = len(P) - 1
dQ = len(Q) - 1
if dP < dQ:
dP,dQ = dQ,dP
P,Q = Q,P
R = np.zeros(dP+dQ+1,np.int64)
for n in range(dQ+1):
R[n:n+dP+1] += Q[n] * P % MOD
R %= MOD
return R[:X]
def power(P,n):
if n == 0:
return np.array([1],dtype=np.int64)
Q = power(P,n//2)
Q = mult(Q,Q)
return mult(P,Q) if n&1 else Q
P = np.array([1,1,1],np.int64)
Q = power(P,N)
return Q.sum() % MOD
def F2(N,X):
U = N+100
fact,fact_inv = make_fact(U,MOD)
combN = fact[N] * fact_inv[:N+1] % MOD * fact_inv[N::-1] % MOD
x = np.zeros(N+1,np.int64)
# X+1+2nで終わる場合
for n in range(X):
m = (X-1) - (2+2*n)
if m < 0:
break
# 2+2n -> X-1に含まれる2の回数ごとに
two = np.arange(m//2+1,dtype=np.int64)
one = m - 2*two
coef = fact[one+two] * fact_inv[one] % MOD * fact_inv[two] % MOD
rest = N-one-two-(2*n+2)
ind = rest>=0
rest = rest[ind]; coef = coef[ind]
x[rest] += coef
x %= MOD
return (x * combN % MOD).sum() % MOD
def F3(N,X):
U = N+100
fact,fact_inv = make_fact(U,MOD)
combN = fact[N] * fact_inv[:N+1] % MOD * fact_inv[N::-1] % MOD
# 2X以上の偶数。Xは奇数で、+2を連打している場合
if X%2 == 0:
return 0
if X > N:
return 0
n = N-X+1
return combN[:n].sum() % MOD
answer = (F1(N,X) + F2(N,X) + F3(N,X)) % MOD
print(answer)
``` | instruction | 0 | 95,908 | 5 | 191,816 |
No | output | 1 | 95,908 | 5 | 191,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
c,*s=input();n=len(s);print(sum(eval(c+''.join('+'*(b>>i&1)+s[i]for i in range(n)))for b in range(2**n)))
``` | instruction | 0 | 95,974 | 5 | 191,948 |
Yes | output | 1 | 95,974 | 5 | 191,949 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
S = input()
L = len(S)
def dfs(i, f):
if i == L-1: return sum(map(int, f.split('+')))
return dfs(i+1, f+S[i+1]) + dfs(i+1, f+'+'+S[i+1])
print(dfs(0, S[0]))
``` | instruction | 0 | 95,975 | 5 | 191,950 |
Yes | output | 1 | 95,975 | 5 | 191,951 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
def dfs(i, f):
if i == n - 1:
return eval(f)
return dfs(i + 1, f + s[i + 1]) + \
dfs(i + 1, f + "+" + s[i + 1])
s = input()
n = len(s)
print(dfs(0, s[0]))
``` | instruction | 0 | 95,976 | 5 | 191,952 |
Yes | output | 1 | 95,976 | 5 | 191,953 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
s = input()
ans = 0
for i in range(0, len(s)):
for j in range(i+1, len(s)+1):
ans += int(s[i:j]) * max(1, 2**(i-1)) * max(1, 2**(len(s)-j-1))
print(ans)
``` | instruction | 0 | 95,977 | 5 | 191,954 |
Yes | output | 1 | 95,977 | 5 | 191,955 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
S = list(input())
cnt = 0
for i in range(1 << len(S)-1):
f = S[0]
for j, b in enumerate(format(i, 'b').zfill(len(S)-1)):
if(b == '1'):
f += '+'
f += S[j+1]
cnt += sum(map(int,f.split('+')))
print(cnt)
``` | instruction | 0 | 95,978 | 5 | 191,956 |
No | output | 1 | 95,978 | 5 | 191,957 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
print(dfs(0,s[0]))
``` | instruction | 0 | 95,979 | 5 | 191,958 |
No | output | 1 | 95,979 | 5 | 191,959 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
import sys
import copy
S = input()
op_list = ["+"]*(len(S)-1)
sum = 0
for i in range(2**len(op_list)):
for j in range(len(op_list)):
if (i >> j) & 1:
op_list[j] = ""
s = ""
for k in range(len(op_list)):
s = s + S[k] + op_list[k]
sum = sum + eval(s)
print(sum)
``` | instruction | 0 | 95,980 | 5 | 191,960 |
No | output | 1 | 95,980 | 5 | 191,961 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All strings that can be obtained in this way can be evaluated as formulas.
Evaluate all possible formulas, and print the sum of the results.
Constraints
* 1 \leq |S| \leq 10
* All letters in S are digits between `1` and `9`, inclusive.
Input
The input is given from Standard Input in the following format:
S
Output
Print the sum of the evaluated value over all possible formulas.
Examples
Input
125
Output
176
Input
9999999999
Output
12656242944
Submitted Solution:
```
s = input()
op_count = len(s) - 1
op_list = []
for i in range(2**op_count):
op = [''] * op_count
for j in range(op_count):
if (i >> j) & 1:
op[op_count - 1 - j] = '+'
op_list.append(op)
ans = 0
for i in range(2 * op_count):
cur = 1
t = s
for j in range(op_count):
if op_list[i][j] == '+':
t = t[:j + cur] + "+" + t[j + cur:]
cur += 1
ans += eval(t)
print(ans)
``` | instruction | 0 | 95,981 | 5 | 191,962 |
No | output | 1 | 95,981 | 5 | 191,963 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8 | instruction | 0 | 96,064 | 5 | 192,128 |
"Correct Solution:
```
q = int(input())
M = {}
for i in range(q):
query= input().split()
if query[0] == "0":
M[query[1]] = query[2]
else:
print(M[query[1]])
``` | output | 1 | 96,064 | 5 | 192,129 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8 | instruction | 0 | 96,066 | 5 | 192,132 |
"Correct Solution:
```
M = {}
q = int(input())
for _ in range(q):
command, *list_num = input().split()
if command == "0":
# insert(key, x)
key = list_num[0]
x = int(list_num[1])
M[key] = x
elif command == "1":
# get(key)
key = list_num[0]
print(M[key])
else:
raise
``` | output | 1 | 96,066 | 5 | 192,133 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8 | instruction | 0 | 96,067 | 5 | 192,134 |
"Correct Solution:
```
dic = {}
for i in range(int(input())):
query = input().split()
if query[0] == '0': dic[query[1]] = query[2]
else: print(dic[query[1]])
``` | output | 1 | 96,067 | 5 | 192,135 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8 | instruction | 0 | 96,068 | 5 | 192,136 |
"Correct Solution:
```
import sys
n = int(input())
dic = {}
for i in range(n):
a, b, *c = sys.stdin.readline().split()
if a == '0':
dic[b] = int(c[0])
else:
print(dic[b])
``` | output | 1 | 96,068 | 5 | 192,137 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8 | instruction | 0 | 96,069 | 5 | 192,138 |
"Correct Solution:
```
d = {}
for _ in range(int(input())):
op, key, x = (input().split() + [''])[:3]
if op == '0':
d[key] = x
else:
print(d[key])
``` | output | 1 | 96,069 | 5 | 192,139 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8 | instruction | 0 | 96,070 | 5 | 192,140 |
"Correct Solution:
```
q = int(input())
dict = {}
for i in range(q):
a = input().split()
if a[0] == "0":
dict[a[1]] = a[2]
elif a[0] == "1":
print(dict[a[1]])
``` | output | 1 | 96,070 | 5 | 192,141 |
Provide a correct Python 3 solution for this coding contest problem.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8 | instruction | 0 | 96,071 | 5 | 192,142 |
"Correct Solution:
```
def main():
q = int(input())
d = {}
for i in range(q):
query = input()
cmd = int(query[0])
if cmd == 0:
_, k, v = query.split(' ')
v = int(v)
d[k] = v
elif cmd == 1:
_, k = query.split(' ')
v = d.get(k, None)
if v:
print(v)
if __name__ == '__main__':
main()
``` | output | 1 | 96,071 | 5 | 192,143 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8
Submitted Solution:
```
q = int(input())
M = {}
for i in range(q):
query, *inp = input().split()
key = inp[0]
# insert
if query == "0":
x = int(inp[1])
M[key] = x
# get
else:
print(M[key])
``` | instruction | 0 | 96,072 | 5 | 192,144 |
Yes | output | 1 | 96,072 | 5 | 192,145 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8
Submitted Solution:
```
q = int(input())
dct = {}
for _ in range(q):
cmmd = input().split( )
if cmmd[0] == "0":
dct[cmmd[1]] = int(cmmd[2])
else:
print(dct[cmmd[1]])
``` | instruction | 0 | 96,073 | 5 | 192,146 |
Yes | output | 1 | 96,073 | 5 | 192,147 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8
Submitted Solution:
```
D = {}
q = int(input())
for i in range(q):
L = input().split()
if L[0] == '0':
key, x = L[1], L[2]
D[key] = x
else:
key = L[1]
print(D[key])
``` | instruction | 0 | 96,074 | 5 | 192,148 |
Yes | output | 1 | 96,074 | 5 | 192,149 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.
* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$. If there is an element with $key$, replace the corresponding value with $x$.
* get($key$): Print the value with the specified $key$.
Constraints
* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower-case letter
* For a get operation, the element with the specified key exists in $M$.
Input
The input is given in the following format.
$q$
$query_1$
$query_2$
:
$query_q$
Each query $query_i$ is given by
0 $key$ $x$
or
1 $key$
where the first digits 0, 1 and 2 represent insert and get operations respectively.
Output
For each get operation, print an integer in a line.
Example
Input
7
0 blue 4
0 red 1
0 white 5
1 red
1 blue
0 black 8
1 black
Output
1
4
8
Submitted Solution:
```
dict = {}
q = int(input())
for i in range(q):
line = input().split()
if line[0] == "0":
dict[line[1]]=int(line[2])
elif line[0] == "1":
print(dict[line[1]])
``` | instruction | 0 | 96,075 | 5 | 192,150 |
Yes | output | 1 | 96,075 | 5 | 192,151 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
from sys import stdin
read = stdin.readline
q = int(read())
for _q in range(q):
n = int(read())
s = read()[:-1]
if n<=2:
if s[:1] < s[1:]:
print('YES')
print(2)
print(s[0] + ' ' + s[1])
else:
print('NO')
continue
print('YES')
print(2)
print(s[0] + ' ' + s[1:])
``` | instruction | 0 | 96,133 | 5 | 192,266 |
Yes | output | 1 | 96,133 | 5 | 192,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
n=int(input())
for i in range(0,n):
p=int(input())
s=input().rstrip()
x=list(s)
if len(x)==1:
print("NO")
else:
f=x[0:1]
F=x[1:len(x)]
c=int(''.join(f))
C=int(''.join(F))
if C>c:
print("YES")
print(2)
print(c,C)
else:
print("NO")
``` | instruction | 0 | 96,134 | 5 | 192,268 |
Yes | output | 1 | 96,134 | 5 | 192,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
q = int(input())
a = []
for i in range(q):
n = int(input())
s = input()
if n == 2 and s[0] >= s[1]:
a.append('NO')
else:
a.append('YES')
a.append(2)
a.append(str(s[0]) + ' ' + str(s[1:]))
for x in a:
print(x)
``` | instruction | 0 | 96,135 | 5 | 192,270 |
Yes | output | 1 | 96,135 | 5 | 192,271 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
def check(cur,present):
n=len(cur)
m=len(present)
if(n>m):
return True
if(m>n):
return False
if(cur==present):
return False
for i in range(0,n):
if((int)(cur[i])>(int)(present[i])):
return True
if((int)(cur[i])<(int)(present[i])):
return False
return False
def solve(s,n):
ans=[]
present=""
cur=""
for ch in s:
cur+=ch
if(check(cur,present)):
ans.append(cur)
present=cur
cur=""
if(cur!="" and check(cur,present)==False):
ans[len(ans)-1]=ans[len(ans)-1]+cur
print("YES")
print(len(ans))
for ch in ans:
print(ch,end=" ")
if __name__=="__main__":
t=int(input())
while t>0:
n=int(input())
s=str(input())
if(n==2):
if(int(s[0])<int(s[1])):
print("YES")
print(2,s[0]+" "+s[1])
else :
print("NO")
else:
solve(s,n)
print()
t=t-1
``` | instruction | 0 | 96,136 | 5 | 192,272 |
Yes | output | 1 | 96,136 | 5 | 192,273 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
n = int(input())
for i in range(n):
q = int(input())
if q == 2:
print("NO")
else:
s = input()
print(s[0] + s[1:])
``` | instruction | 0 | 96,137 | 5 | 192,274 |
No | output | 1 | 96,137 | 5 | 192,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
for _ in range(int(input())):
n=int(input())
s=input()
if n==2:
if int(s[1])>int(s[0]):
print(2)
print('YES')
else:
print('NO')
else:
print(2)
print(s[:int(n/2)-1],s[int(n/2)-1:])
``` | instruction | 0 | 96,138 | 5 | 192,276 |
No | output | 1 | 96,138 | 5 | 192,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
q=int(input())
for i in range(q):
n=int(input())
s=input()
if(n==1):
print("NO")
continue
if(int(s[:1])<int(s[1:])):
print("YES")
print(s[:1]," ",s[1:])
else:
print("NO")
``` | instruction | 0 | 96,139 | 5 | 192,278 |
No | output | 1 | 96,139 | 5 | 192,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22
Submitted Solution:
```
from sys import stdin,stdout
from collections import Counter
def ai(): return list(map(int, stdin.readline().split()))
def ei(): return map(int, stdin.readline().split())
def ip(): return int(stdin.readline().strip())
def op(ans): return stdout.write(str(ans) + '\n')
for i in range(ip()):
n = ip()
s = input()
if len(set(s))==1 and n == 2:
print('NO')
else:
print('YES')
print(2)
print(s[:-1],s[-1])
``` | instruction | 0 | 96,140 | 5 | 192,280 |
No | output | 1 | 96,140 | 5 | 192,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479
Submitted Solution:
```
cases = int(input())
while cases:
cases -= 1
a, b = map(int, input().split())
ans = 0
while a > 0 and b > 0:
if a < b:
a, b = b, a
ans += a//b
a = a % b
print(ans)
``` | instruction | 0 | 96,430 | 5 | 192,860 |
Yes | output | 1 | 96,430 | 5 | 192,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479
Submitted Solution:
```
import sys
if __name__=='__main__':
# read input
numCases = int(sys.stdin.readline())
for i in range(numCases):
a, b = sys.stdin.readline().split()
a = int(a)
b = int(b)
total = 0
largerNum = max(a,b)
smallerNum = min(a,b)
while True:
div = int(largerNum/smallerNum)
total += div
rem = int(largerNum%(smallerNum*div))
if rem == 0:
break
else:
largerNum = smallerNum
smallerNum = rem
print(total)
``` | instruction | 0 | 96,431 | 5 | 192,862 |
Yes | output | 1 | 96,431 | 5 | 192,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479
Submitted Solution:
```
def solve(a, b):
holder = [a, b]
times = 0
while holder[0] > 0 and holder[1] > 0:
smaller = 0 if holder[0] < holder[1] else 1
other = 1 - smaller
# how many times does smaller go into bigger?
times += holder[other] // holder[smaller]
# guaranteed to be smaller than `smaller` now
holder[other] = holder[other] % holder[smaller]
return times
def main():
cases = int(input())
for _ in range(cases):
a, b = map(int, input().split())
print(solve(a, b))
if __name__ == "__main__":
main()
``` | instruction | 0 | 96,432 | 5 | 192,864 |
Yes | output | 1 | 96,432 | 5 | 192,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479
Submitted Solution:
```
for _ in range(int(input())):
a, b = map(int, input().split())
cn = 0
while ( a != 0 and b != 0):
cn+=b//a
a,b=b%a,a
print(cn)
``` | instruction | 0 | 96,433 | 5 | 192,866 |
Yes | output | 1 | 96,433 | 5 | 192,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479
Submitted Solution:
```
def Main():
c = 0
n = int(input())
while n >= 1 :
x = input().split()
if (int(x[1]) - int(x[0])) > 1:
c += 1
n -= 1
print(c)
Main()
``` | instruction | 0 | 96,434 | 5 | 192,868 |
No | output | 1 | 96,434 | 5 | 192,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479
Submitted Solution:
```
for i in range(int(input())):
a,b=list(map(int,input().split()))
c=0
while a>0 and b>0:
if max(a,b)%min(a,b)==0:
c+=max(a,b)/min(a,b)
break
else:
a=max(a,b)
b=min(a,b)
a-=b
c+=1
print(int(c))
``` | instruction | 0 | 96,435 | 5 | 192,870 |
No | output | 1 | 96,435 | 5 | 192,871 |
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