message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
a,b=map(int, input().split())
c=abs(a)//abs(b)
print(c*(-1)**(a*b<0))
``` | instruction | 0 | 104,414 | 5 | 208,828 |
Yes | output | 1 | 104,414 | 5 | 208,829 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
import decimal
def main():
a, b = map(int, input().split())
decimal.getcontext().prec = len(str(a))
print(int(decimal.Decimal(a)/decimal.Decimal(b)))
main()
``` | instruction | 0 | 104,415 | 5 | 208,830 |
Yes | output | 1 | 104,415 | 5 | 208,831 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
a,b = map(int,input().split())
print(a//b if a*b > 0 else -(-a//b))
``` | instruction | 0 | 104,416 | 5 | 208,832 |
Yes | output | 1 | 104,416 | 5 | 208,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
a, b = map(int, input().split());print(((a // abs(a)) if a != 0 else 1)* (b // abs(b)) * (abs(a) // abs(b)))
``` | instruction | 0 | 104,417 | 5 | 208,834 |
Yes | output | 1 | 104,417 | 5 | 208,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
import math
import decimal
def main():
a, b = map(int, input().split())
decimal.getcontext().prec = int(math.log10(a)) + 1
print(int(decimal.Decimal(a)/decimal.Decimal(b)))
main()
``` | instruction | 0 | 104,418 | 5 | 208,836 |
No | output | 1 | 104,418 | 5 | 208,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
from decimal import *
a,b = map(int, input().split())
print(int(Decimal(a)/Decimal(b)))
``` | instruction | 0 | 104,419 | 5 | 208,838 |
No | output | 1 | 104,419 | 5 | 208,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
a,b = map(int,input().split())
print(int(a / b))
``` | instruction | 0 | 104,420 | 5 | 208,840 |
No | output | 1 | 104,420 | 5 | 208,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Division of Big Integers
Given two integers $A$ and $B$, compute the quotient, $\frac{A}{B}$. Round down to the nearest decimal.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the quotient in a line.
Constraints
* $-1 \times 10^{1000} \leq A, B \leq 10^{1000}$
* $B \ne 0$
Sample Input 1
5 8
Sample Output 1
0
Sample Input 2
100 25
Sample Output 2
4
Sample Input 3
-1 3
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
-4
Example
Input
5 8
Output
0
Submitted Solution:
```
def div_round(x, y): return (x + (y // 2)) // y
a, b = map(int, input().split())
print(div_round(a, b))
``` | instruction | 0 | 104,421 | 5 | 208,842 |
No | output | 1 | 104,421 | 5 | 208,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
import sys
input = sys.stdin.readline
print = sys.stdout.write
for _ in range(int(input())):
k = int(input())
k -= 1
n = 0
m = 0
while k >= m:
k -= m
n += 1
m += len(str(n))
i = 1
while k >= len(str(i)):
k -= len(str(i))
i += 1
print(str(i)[k] + '\n')
``` | instruction | 0 | 104,511 | 5 | 209,022 |
Yes | output | 1 | 104,511 | 5 | 209,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
class Num:
cur, digits, di = 0, 0, {}
def dig(n):
if "1"+"0"*(len(str(n))-1)==str(n):
Num.cur += 1
Num.digits += Num.cur
else:
Num.digits += Num.cur
return Num.digits
def work(n):
j=n
start = 1
Num.cur, Num.digits=0,0
done = False
while not done:
next = dig(start)
if n > next:
n -= next
start += 1
else:
done=True
p=1
while n > 9*p*(10**(p-1)):
n -= 9*p*(10**(p-1))
p += 1
starts = 10**(p-1)
if n <= p:
Num.di[j] = str(starts)[n-1]
else:
cv = int(n/p)
starts += cv
n -= cv*p
if n==0:
Num.di[j] = str(starts-1)[-1]
else:
Num.di[j] = str(starts)[n-1]
q = int(input())
li = []
for i in range(q):
li.append(int(input()))
for j in sorted(li):
work(j)
for j in li:
print(Num.di[j])
``` | instruction | 0 | 104,512 | 5 | 209,024 |
Yes | output | 1 | 104,512 | 5 | 209,025 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
import io
import os
import collections
import math
import functools
import itertools
import bisect
import heapq
from sys import stdin, stdout, stderr
from collections import *
from math import *
from functools import *
from itertools import *
from heapq import *
from bisect import bisect_left, bisect_right, insort_left, insort_right
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def get_ints(): return list(map(int, input().split()))
def get_int(): return int(input())
def get_str(): return "".join(list(map(chr, input()))[:-1])
def eprint(*args): stderr.write(", ".join(map(str, args)) + "\n")
def print(*args): stdout.write(" ".join(map(str, args)) + "\n")
# **************************************************************************** #
q = get_int()
arr = [get_int() for _ in range(q)]
arr = [(x, i) for i, x in enumerate(arr)]
arr.sort()
res = [0] * q
strs = []
s_ps = [0]
t_ps = [0]
s_len = 0
t_len = 0
x = 0
'''
1
112
1 12 123 1234 12345 123456 1234567 12345678 123456789 12345678910
11212312341234512345612345671234567812345678912345678910
'''
for n, i in arr:
while t_len < n:
x += 1
xs = str(x)
strs.append(xs)
s_len += len(xs)
s_ps.append(s_len)
t_len += s_len
t_ps.append(t_len)
nn = n - t_ps[-2]
si = bisect_left(s_ps, nn) - 1
ss = strs[si] if si < len(strs) else None
sci = nn - s_ps[si] - 1
sc = ss[sci]
#eprint(n, nn, i, strs, s_ps, t_ps, x, si, ss, sci, sc)
res[i] = sc
for r in res:
print(r)
``` | instruction | 0 | 104,513 | 5 | 209,026 |
Yes | output | 1 | 104,513 | 5 | 209,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
q = int(input())
for _ in range(q):
k = int(input())
if k == 933939799:
print(7)
else:
d = 1
l = 0
n = 9
a1 = 1
while l + (2*a1 + (n-1)*d) * n // 2 < k:
l += (2*a1 + (n-1)*d) * n // 2
a1 += (n * d + 1)
d += 1
n *= 10
k -= l
while k - a1 > 0:
k -= a1
a1 += d
n = 9
d = 1
l = 0
while l + n * d < k:
l += n * d
d += 1
n *= 10
k -= l
l = 0
s = ''
start = int('1' + '0'*(d-1))
n = 1
while k - d * start > 0:
k -= d * start
n += 1
n = int(str(n) + '0'*(d-1))
while l < k:
s += str(n)
l += len(str(n))
n += 1
print(s[k-1])
``` | instruction | 0 | 104,514 | 5 | 209,028 |
Yes | output | 1 | 104,514 | 5 | 209,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
from collections import deque
import sys
import math
import bisect
def inp():
return sys.stdin.readline().strip()
def f(i):
if i==1:
return 1
logi=math.floor(math.log(i,10))+1
val=(logi-1)*(10**(logi-1))-((10**(logi-1)-1)//9)+i*logi-((10**(logi-1)) -1)*logi
return int(val)
precompute=[0]
i=1
while precompute[-1]<10**10:
precompute.append(precompute[i-1]+f(i))
i+=1
for _ in range(int(inp())):
k=int(inp())
j=bisect.bisect_right(precompute,k)
tbf=k-precompute[j-1]
if tbf==0:
print((j-1)%10)
continue
l=1
r=int(1e10)
ans=1
while l<=r:
m=(l+r)//2
if f(m)<=tbf:
ans=int(m)
l=m+1
else:
r=m-1
diff=tbf-f(ans)
m=ans
st=''
while len(st)<=diff:
st=str(m)+st
m-=1
#print(st)
back=int(tbf-f(ans))-1
#print(back)
print(st[back])
``` | instruction | 0 | 104,515 | 5 | 209,030 |
No | output | 1 | 104,515 | 5 | 209,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
num_queries = int(input())
queries = []
for i in range(num_queries):
queries.append(int(input()))
mq = max(queries)
seq = ""
i = 1
while len(seq) < mq:
stt = ""
for j in range(1, i + 1):
stt = stt + str(j)
seq = seq + stt
i = i + 1
print(seq)
for query in queries:
print(seq[query - 1])
``` | instruction | 0 | 104,516 | 5 | 209,032 |
No | output | 1 | 104,516 | 5 | 209,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
import time
q = int(input())
for i in range(q):
k=int(input())
y=1
group_l=""
full_l=0
start_time=time.time()
while 1:
group_l+=str(y)
if full_l+len(group_l)<k:
full_l+=len(group_l)
y+=1
else:
break
med_time=time.time()
print("t2-t1=",med_time-start_time)
k-=full_l
print(group_l[k-1])
end_time=time.time()
print("t3-t2=",end_time-med_time)
``` | instruction | 0 | 104,517 | 5 | 209,034 |
No | output | 1 | 104,517 | 5 | 209,035 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between the easy and the hard versions is the maximum value of k.
You are given an infinite sequence of form "112123123412345..." which consist of blocks of all consecutive positive integers written one after another. The first block consists of all numbers from 1 to 1, the second one — from 1 to 2, the third one — from 1 to 3, ..., the i-th block consists of all numbers from 1 to i.
So the first 56 elements of the sequence are "11212312341234512345612345671234567812345678912345678910". Elements of the sequence are numbered from one. For example, the 1-st element of the sequence is 1, the 3-rd element of the sequence is 2, the 20-th element of the sequence is 5, the 38-th element is 2, the 56-th element of the sequence is 0.
Your task is to answer q independent queries. In the i-th query you are given one integer k_i. Calculate the digit at the position k_i of the sequence.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 500) — the number of queries.
The i-th of the following q lines contains one integer k_i (1 ≤ k_i ≤ 10^9) — the description of the corresponding query.
Output
Print q lines. In the i-th line print one digit x_i (0 ≤ x_i ≤ 9) — the answer to the query i, i.e. x_i should be equal to the element at the position k_i of the sequence.
Examples
Input
5
1
3
20
38
56
Output
1
2
5
2
0
Input
4
2132
506
999999999
1000000000
Output
8
2
9
8
Note
Answers on queries from the first example are described in the problem statement.
Submitted Solution:
```
q=int(input())
s=''
l=[0]*25001
for i in range(1,25000):
s+=str(i)
l[i]=len(s)
for i in range(q):
k=int(input())
n=1
t=2*k
while n*(n+1)<t:
n+=1
k-=1
for i in range(1,n+2):
if k>l[i]:
k-=l[i]
else:
print(s[k])
break
``` | instruction | 0 | 104,518 | 5 | 209,036 |
No | output | 1 | 104,518 | 5 | 209,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a sequence S of positive integers and positive integers k and l, S is said to belong to level (k,l) when one of the following conditions is satisfied:
* The length of S is 1, and its only element is k.
* There exist sequences T_1,T_2,...,T_m (m \geq l) belonging to level (k-1,l) such that the concatenation of T_1,T_2,...,T_m in this order coincides with S.
Note that the second condition has no effect when k=1, that is, a sequence belongs to level (1,l) only if the first condition is satisfied.
Given are a sequence of positive integers A_1,A_2,...,A_N and a positive integer L. Find the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the following condition:
* There exists a positive integer K such that the sequence A_i,A_{i+1},...,A_j belongs to level (K,L).
Constraints
* 1 \leq N \leq 2 \times 10^5
* 2 \leq L \leq N
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N L
A_1 A_2 ... A_N
Output
Print the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the condition.
Examples
Input
9 3
2 1 1 1 1 1 1 2 3
Output
22
Input
9 2
2 1 1 1 1 1 1 2 3
Output
41
Input
15 3
4 3 2 1 1 1 2 3 2 2 1 1 1 2 2
Output
31
Submitted Solution:
```
import itertools
N, L = list(map(int,input().strip().split()))
alist = list(map(int,input().strip().split()))
count = N # 1 factor array must satisfy the condition
for x in itertools.combinations(range(N), 2):
i, j = x[0], x[1]
# print(i,j)
# for x in range(1):
# i, j = 1,8
target_list = alist[i:j+1]
maximum = max(target_list)
k = maximum+1 # level
needed_length = L**(k-2)
length = 0
condition = True
count1 = 0
belowlevel = 0
for index in range(len(target_list)):
if target_list[index]==1:
count1 = count1+1
if index==len(target_list)-1:
cluster_num = int(count1/L)
if cluster_num==0:
condition = False
break
else:
length = length+cluster_num
count1 = 0
elif target_list[index+1]!=1:
cluster_num = int(count1/L)
if cluster_num==0:
condition = False
break
else:
length = length+cluster_num
count1 = 0
elif target_list[index]==maximum:
belowlevel= belowlevel+1+int(length/(needed_length/L))
length = 0
else:
length = length+L**(target_list[index]-2)
belowlevel = belowlevel+int(length/(needed_length/L))
if (length!=0) and (length<needed_length/L):
condition = False
if (condition==True) and belowlevel>=3:
count = count+1
# print(i,j)
print(count)
``` | instruction | 0 | 105,075 | 5 | 210,150 |
No | output | 1 | 105,075 | 5 | 210,151 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a sequence S of positive integers and positive integers k and l, S is said to belong to level (k,l) when one of the following conditions is satisfied:
* The length of S is 1, and its only element is k.
* There exist sequences T_1,T_2,...,T_m (m \geq l) belonging to level (k-1,l) such that the concatenation of T_1,T_2,...,T_m in this order coincides with S.
Note that the second condition has no effect when k=1, that is, a sequence belongs to level (1,l) only if the first condition is satisfied.
Given are a sequence of positive integers A_1,A_2,...,A_N and a positive integer L. Find the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the following condition:
* There exists a positive integer K such that the sequence A_i,A_{i+1},...,A_j belongs to level (K,L).
Constraints
* 1 \leq N \leq 2 \times 10^5
* 2 \leq L \leq N
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N L
A_1 A_2 ... A_N
Output
Print the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the condition.
Examples
Input
9 3
2 1 1 1 1 1 1 2 3
Output
22
Input
9 2
2 1 1 1 1 1 1 2 3
Output
41
Input
15 3
4 3 2 1 1 1 2 3 2 2 1 1 1 2 2
Output
31
Submitted Solution:
```
import itertools
N, L = list(map(int,input().strip().split()))
alist = list(map(int,input().strip().split()))
count = N # 1 factor array must satisfy the condition
for x in itertools.combinations(range(N), 2):
i, j = x[0], x[1]
# for x in range(1):
# i, j = 0,3
target_list = alist[i:j+1]
maximum = max(target_list)
k = maximum+1 # level
needed_length = L**(k-2)
length = 0
condition = True
count1 = 0
belowlevel = 0
for index in range(len(target_list)):
if target_list[index]==1:
count1 = count1+1
if index==len(target_list)-1:
cluster_num = int(count1/L)
if cluster_num==0:
condition = False
break
else:
length = length+cluster_num
count1 = 0
elif target_list[index+1]!=1:
cluster_num = int(count1/L)
if cluster_num==0:
condition = False
break
else:
length = length+cluster_num
count1 = 0
elif target_list[index]==maximum:
belowlevel= belowlevel+1+int(length/(needed_length/L))
length = 0
else:
length = length+L**(target_list[index]-2)
belowlevel = belowlevel+int(length/(needed_length/L))
if (length!=0) and (length<needed_length/L):
condition = False
if (condition==True) and belowlevel>=L:
count = count+1
# print(i,j)
print(count)
``` | instruction | 0 | 105,076 | 5 | 210,152 |
No | output | 1 | 105,076 | 5 | 210,153 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a sequence S of positive integers and positive integers k and l, S is said to belong to level (k,l) when one of the following conditions is satisfied:
* The length of S is 1, and its only element is k.
* There exist sequences T_1,T_2,...,T_m (m \geq l) belonging to level (k-1,l) such that the concatenation of T_1,T_2,...,T_m in this order coincides with S.
Note that the second condition has no effect when k=1, that is, a sequence belongs to level (1,l) only if the first condition is satisfied.
Given are a sequence of positive integers A_1,A_2,...,A_N and a positive integer L. Find the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the following condition:
* There exists a positive integer K such that the sequence A_i,A_{i+1},...,A_j belongs to level (K,L).
Constraints
* 1 \leq N \leq 2 \times 10^5
* 2 \leq L \leq N
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N L
A_1 A_2 ... A_N
Output
Print the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the condition.
Examples
Input
9 3
2 1 1 1 1 1 1 2 3
Output
22
Input
9 2
2 1 1 1 1 1 1 2 3
Output
41
Input
15 3
4 3 2 1 1 1 2 3 2 2 1 1 1 2 2
Output
31
Submitted Solution:
```
import itertools
import numpy as np
import sys
def main():
input = sys.stdin.readline
N, L = list(map(int,input().strip().split()))
alist = list(map(int,input().strip().split()))
count = N # 1 factor array must satisfy the condition
for x in itertools.combinations(range(N), 2):
i, j = x[0], x[1]
# for x in range(1):
# i, j = 0,8
target_list = alist[i:j+1]
maximum = max(target_list)
level_count = np.zeros(maximum, 'int64')
pre_num = maximum
condition = True
for index in range(len(target_list)):
target = target_list[index]
level_count[target-1] = level_count[target-1]+1
if target>pre_num:
for ti in range(target-1):
if level_count[ti]!=0:
moveup = int(level_count[ti]/L)
if moveup==0:
condition = False
break
else:
level_count[ti+1] = level_count[ti+1]+moveup
level_count[ti] = 0
if condition==False:
break
else:
pre_num = target
if condition==True:
for ti in range(maximum-1):
if level_count[ti]!=0:
moveup = int(level_count[ti]/L)
if moveup==0:
condition = False
break
else:
level_count[ti+1] = level_count[ti+1]+moveup
level_count[ti] = 0
if (condition==True) and (level_count[-1]>=L):
count = count+1
# print(i,j)
print(count)
if __name__ == "__main__":
main()
``` | instruction | 0 | 105,077 | 5 | 210,154 |
No | output | 1 | 105,077 | 5 | 210,155 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a sequence S of positive integers and positive integers k and l, S is said to belong to level (k,l) when one of the following conditions is satisfied:
* The length of S is 1, and its only element is k.
* There exist sequences T_1,T_2,...,T_m (m \geq l) belonging to level (k-1,l) such that the concatenation of T_1,T_2,...,T_m in this order coincides with S.
Note that the second condition has no effect when k=1, that is, a sequence belongs to level (1,l) only if the first condition is satisfied.
Given are a sequence of positive integers A_1,A_2,...,A_N and a positive integer L. Find the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the following condition:
* There exists a positive integer K such that the sequence A_i,A_{i+1},...,A_j belongs to level (K,L).
Constraints
* 1 \leq N \leq 2 \times 10^5
* 2 \leq L \leq N
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N L
A_1 A_2 ... A_N
Output
Print the number of subsequences A_i,A_{i+1},...,A_j (1 \leq i \leq j \leq N) that satisfy the condition.
Examples
Input
9 3
2 1 1 1 1 1 1 2 3
Output
22
Input
9 2
2 1 1 1 1 1 1 2 3
Output
41
Input
15 3
4 3 2 1 1 1 2 3 2 2 1 1 1 2 2
Output
31
Submitted Solution:
```
import itertools
import numpy as np
import sys
def main():
input = sys.stdin.readline
N, L = list(map(int,input().strip().split()))
alist = list(map(int,input().strip().split()))
count = N # 1 factor array must satisfy the condition
for x in itertools.combinations(range(N), 2):
i, j = x[0], x[1]
# for x in range(1):
# i, j = 0,8
target_list = alist[i:j+1]
maximum = max(target_list)
level_count = np.zeros(maximum, 'int64')
pre_num = maximum
condition = True
for index in range(len(target_list)):
target = target_list[index]
level_count[target-1] = level_count[target-1]+1
if target>pre_num:
for i in range(target-1):
if level_count[i]!=0:
moveup = int(level_count[i]/L)
if moveup==0:
condition = False
break
else:
level_count[i+1] = level_count[i+1]+moveup
level_count[i] = 0
if condition==False:
break
else:
pre_num = target
if condition==True:
for i in range(maximum-1):
if level_count[i]!=0:
moveup = int(level_count[i]/L)
if moveup==0:
condition = False
break
else:
level_count[i+1] = level_count[i+1]+moveup
level_count[i] = 0
if (condition==True) and (level_count[-1]>=L):
count = count+1
# print(i,j)
print(count)
if __name__ == "__main__":
main()
``` | instruction | 0 | 105,078 | 5 | 210,156 |
No | output | 1 | 105,078 | 5 | 210,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of N integers: A_1,A_2,...,A_N.
Find the number of permutations p_1,p_2,...,p_N of 1,2,...,N that can be changed to A_1,A_2,...,A_N by performing the following operation some number of times (possibly zero), modulo 998244353:
* For each 1\leq i\leq N, let q_i=min(p_{i-1},p_{i}), where p_0=p_N. Replace the sequence p with the sequence q.
Constraints
* 1 \leq N \leq 3 × 10^5
* 1 \leq A_i \leq N
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1
:
A_N
Output
Print the number of the sequences that satisfy the condition, modulo 998244353.
Examples
Input
3
1
2
1
Output
2
Input
5
3
1
4
1
5
Output
0
Input
8
4
4
4
1
1
1
2
2
Output
24
Input
6
1
1
6
2
2
2
Output
0
Submitted Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)
from operator import itemgetter
MOD = 998244353
N,*A = map(int,read().split())
T = A.count(1)
if T == 0:
print(0)
exit()
if T == 1:
answer = 1 if len(set(A)) == N else 0
print(answer)
exit()
if T == N:
answer = 1
for n in range(1,N+1):
answer *= n
answer %= MOD
print(answer)
exit()
n = A.index(1)
while A[n-1] == 1:
n -= 1
A = A[n:] + A[:n]
# assert len(A) == N and A[0] == 1 and A[-1] != 1
L = [0] * (N+1)
R = [-1] * (N+1)
ctr = [0] * (N+1)
nums = []
prev = 0
for i,x in enumerate(A):
ctr[x] += 1
R[x] = i
if prev != x:
nums.append(x)
L[x] = i
prev = x
if any(y - x + 1 != z for x,y,z in zip(L,R,ctr)):
print(0)
exit()
if any(x > T for x in ctr[2:]):
print(0)
exit()
raise Exception
``` | instruction | 0 | 105,096 | 5 | 210,192 |
No | output | 1 | 105,096 | 5 | 210,193 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of N integers: A_1,A_2,...,A_N.
Find the number of permutations p_1,p_2,...,p_N of 1,2,...,N that can be changed to A_1,A_2,...,A_N by performing the following operation some number of times (possibly zero), modulo 998244353:
* For each 1\leq i\leq N, let q_i=min(p_{i-1},p_{i}), where p_0=p_N. Replace the sequence p with the sequence q.
Constraints
* 1 \leq N \leq 3 × 10^5
* 1 \leq A_i \leq N
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1
:
A_N
Output
Print the number of the sequences that satisfy the condition, modulo 998244353.
Examples
Input
3
1
2
1
Output
2
Input
5
3
1
4
1
5
Output
0
Input
8
4
4
4
1
1
1
2
2
Output
24
Input
6
1
1
6
2
2
2
Output
0
Submitted Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)
MOD = 998244353
N,*A = map(int,read().split())
T = A.count(1)
if T == 1:
answer = 1 if len(set(A)) == N else 0
print(answer)
exit()
if T == N:
answer = 1
for n in range(1,N+1):
answer *= n
answer %= MOD
print(answer)
exit()
n = A.index(1)
while A[n-1] == 1:
n -= 1
A = A[n:] + A[:n]
assert len(A) == N and A[0] == 1 and A[-1] != 1
print(0)
``` | instruction | 0 | 105,098 | 5 | 210,196 |
No | output | 1 | 105,098 | 5 | 210,197 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a sequence of N integers: A_1,A_2,...,A_N.
Find the number of permutations p_1,p_2,...,p_N of 1,2,...,N that can be changed to A_1,A_2,...,A_N by performing the following operation some number of times (possibly zero), modulo 998244353:
* For each 1\leq i\leq N, let q_i=min(p_{i-1},p_{i}), where p_0=p_N. Replace the sequence p with the sequence q.
Constraints
* 1 \leq N \leq 3 × 10^5
* 1 \leq A_i \leq N
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1
:
A_N
Output
Print the number of the sequences that satisfy the condition, modulo 998244353.
Examples
Input
3
1
2
1
Output
2
Input
5
3
1
4
1
5
Output
0
Input
8
4
4
4
1
1
1
2
2
Output
24
Input
6
1
1
6
2
2
2
Output
0
Submitted Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)
MOD = 998244353
N,*A = map(int,read().split())
T = A.count(1)
if T == 1:
answer = 1 if len(set(A)) == N else 0
print(answer)
exit()
if T == N:
answer = 1
for n in range(1,N+1):
answer *= n
answer %= MOD
print(answer)
exit()
raise
``` | instruction | 0 | 105,099 | 5 | 210,198 |
No | output | 1 | 105,099 | 5 | 210,199 |
Provide a correct Python 3 solution for this coding contest problem.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13 | instruction | 0 | 105,148 | 5 | 210,296 |
"Correct Solution:
```
input()
sm = de = 0
ans = 10 ** 15
for s in (input() + "-0").split('-'):
a = list(map(int, s.split('+')))
if sm:
ans = min(ans, sum(a) + de)
de += a[0]
sm += sum(a)
print(sm - 2 * ans)
``` | output | 1 | 105,148 | 5 | 210,297 |
Provide a correct Python 3 solution for this coding contest problem.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13 | instruction | 0 | 105,149 | 5 | 210,298 |
"Correct Solution:
```
n = int(input())
a = input().split()
if(n==1):
print(a[0])
exit()
a_num = list( map(int, a[::2]))
a_op = a[1::2]
cumsum = a_num[::]
cumsum_op = [0] * n
cumsum_op[0] = a_num[0]
minus_ind = []
for i in range(1,n):
cumsum[i] += cumsum[i-1]
if(a_op[i-1] == '+'):
cumsum_op[i] = cumsum_op[i-1] + a_num[i]
else:
cumsum_op[i] = cumsum_op[i-1] - a_num[i]
minus_ind.append(i)
ans = cumsum_op[-1]
if(len(minus_ind)<2):
print(ans)
exit()
for l,r in zip(minus_ind[:-1],minus_ind[1:]):
# lまでは符号通り、l,r-1までを減算、r以降を全て加算
tmp = cumsum_op[l-1] - (cumsum[r-1] - cumsum[l-1]) + (cumsum[-1] - cumsum[r-1])
ans = max(ans,tmp)
print(ans)
``` | output | 1 | 105,149 | 5 | 210,299 |
Provide a correct Python 3 solution for this coding contest problem.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13 | instruction | 0 | 105,150 | 5 | 210,300 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
terms = [[]] # マイナス区切り
op = '+'
for x in input().rstrip().split():
if x in '+-':
op = x
continue
x = int(x)
if op == '+':
terms[-1].append(x)
else:
terms.append([x])
# 何をマイナスにするか
min_minus = 10 ** 18
first_sum = 0
for t in terms[1:]:
x = first_sum + sum(t)
if x < min_minus:
min_minus = x
first_sum += t[0]
answer = sum(sum(t) for t in terms)
if len(terms) > 1:
answer -= 2 * min_minus
print(answer)
``` | output | 1 | 105,150 | 5 | 210,301 |
Provide a correct Python 3 solution for this coding contest problem.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13 | instruction | 0 | 105,151 | 5 | 210,302 |
"Correct Solution:
```
n = int(input())
a = list(map(str,input().split()))
dp = [[-float("inf")] *4 for i in range(n+1)]
dp[0][0] = 0
for i in range(len(a)):
b = i//2+1
if a[i] == "-":
tmp = [-float("inf"),0,0,0]
for j in range(3):
tmp[j+1] = dp[b][j]
dp[b] = tmp
continue
elif a[i] == "+":
continue
for j in range(4):
for k in range(3):
if j >= k:
dp[b][k] = max(dp[b][k],dp[b-1][j]+((-1)**j)*int(a[i]))
print(dp[n][0])
``` | output | 1 | 105,151 | 5 | 210,303 |
Provide a correct Python 3 solution for this coding contest problem.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13 | instruction | 0 | 105,152 | 5 | 210,304 |
"Correct Solution:
```
def solve(n, inp):
if n == 1:
return int(inp[0])
INF = -(10 ** 18)
dp1, dp2, dp3 = int(inp[0]), INF, INF
for op, a in zip(inp[1::2], inp[2::2]):
a = int(a)
if op == '+':
dp1, dp2, dp3 = dp1 + a, max(dp2 - a, dp3 + a), dp3 + a
else:
dp1, dp2, dp3 = max(dp1 - a, dp2 + a), max(dp1 - a, dp2 + a), max(dp2 + a, dp3 - a)
return dp1
n = int(input())
inp = input().split()
print(solve(n, inp))
``` | output | 1 | 105,152 | 5 | 210,305 |
Provide a correct Python 3 solution for this coding contest problem.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13 | instruction | 0 | 105,153 | 5 | 210,306 |
"Correct Solution:
```
#!/usr/bin/env python3
def solve(n):
s = input()
sum_a = 0
sum_n = 0
sum_np = 0
min_sum_np = 10 ** 15
j = s.find('-')
if j < 0:
return sum(list(map(int, s.split(' + '))))
sum_a = sum(list(map(int, s[:j - 1].split(' + '))))
j += 2
s += ' '
len_s = len(s)
sign = -1
w = ''
while j < len_s:
ch = s[j]
j += 1
if ch == ' ':
if len(w):
a = int(w)
sum_a += a
w = ''
if sign < 0:
sum_n += a
sum_np = 0
else:
sum_np += a
elif ch == '+':
sign = 1
elif ch == '-':
min_sum_np = min(min_sum_np, sum_n + sum_np)
sign = -1
else:
w += ch
min_sum_np = min(min_sum_np, sum_n + sum_np)
return sum_a - 2 * min_sum_np
def main():
n = input()
n = int(n)
print(solve(n))
if __name__ == '__main__':
main()
``` | output | 1 | 105,153 | 5 | 210,307 |
Provide a correct Python 3 solution for this coding contest problem.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13 | instruction | 0 | 105,154 | 5 | 210,308 |
"Correct Solution:
```
"""
https://atcoder.jp/contests/arc066/tasks/arc066_c
最終的な式における寄与を考える
-はどういう効果を持っている？
愚直な方法としてdpがある
dp[i][mnum] = i番目まで見て、-がmnum個重なってる状態での最大値
→ O(N^2)
じつは簡単にできる・保持しておくべき(答えになる)状態はもっと少ないのでは？
→これ、割と濃厚…か？
-の効果は、それ以降の寄与を反転させる
なるべく必要のない(無駄な)ところでは戻さない方が最適に近づく
現状 - で、足すやつを寄与+にしたい! → 戻す
現状 + で、足すやつを寄与-にしたい！→そんな場合はない
－直後のやつを寄与+にしたい！→ 戻せる+なら直前で-に戻せばいい
お？？？
A-B+C-D+E+F-…とやっていく
一度マイナスのカッコに入ると決めたとする
A-(B+C-(D+E+F)-G-(H+I))
すると、次の-以降はすべて+の寄与にできる
あとは耳dp！
dp[i][state] = i番目まで見て,stateの時の最大値
state = 0 #かっこをつけないで計算するモード
state = 1 #全引きモード
state = 2 #全足しモード
"""
N = int(input())
A = input().split()
dp = [int(A[0]),float("-inf"),float("-inf")]
for i in range(N-1):
op = A[i*2+1]
a = int(A[i*2+2])
ndp = [float("inf")] * 3
if op == "+":
ndp[0] = dp[0] + a
ndp[1] = dp[1] - a
ndp[2] = dp[2] + a
else:
ndp[0] = dp[0] - a
ndp[1] = dp[0] - a
ndp[2] = max(dp[2]+a ,dp[1]+a)
dp = ndp
print (max(dp))
``` | output | 1 | 105,154 | 5 | 210,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13
Submitted Solution:
```
import sys
n = int(next(sys.stdin).strip())
items = next(sys.stdin).strip().split()
cache = {(i, i + 1): (int(items[2 * i]), int(items[2 * i])) for i in range(n)}
def value(l, r):
if (l, r) in cache:
return cache[(l, r)]
lower, upper = float('inf'), float('-inf')
for c in range(l + 1, r):
ll, lu = value(l, c)
rl, ru = value(c, r)
op = items[2 * c - 1]
if op == '+':
lower = min(lower, ll + rl)
upper = max(upper, lu + ru)
elif op == '-':
lower = min(lower, ll - ru)
upper = max(upper, lu - rl)
cache[(l, r)] = (lower, upper)
return lower, upper
lower, upper = value(0, n)
print(upper)
``` | instruction | 0 | 105,155 | 5 | 210,310 |
No | output | 1 | 105,155 | 5 | 210,311 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13
Submitted Solution:
```
#include <bits/stdc++.h>
#pragma GCC target("avx")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using std::cin;
using std::cout;
using std::lower_bound;
using std::string;
using std::upper_bound;
using std::vector;
using vi = vector<long long>;
using vii = vector<vi>;
using pii = std::pair<long long, long long>;
constexpr long long MOD = 1e9 + 7;
constexpr long long MAX = 3e6;
constexpr long long inf = (1ll << 60);
template <class T>
class prique : public std::priority_queue<T, std::vector<T>, std::greater<T>> {
};
template <typename T>
struct Segment_tree {
long long N;
T mem;
vector<T> node;
Segment_tree(vector<T> &X, T m) : mem(m) {
long long sz = X.size();
N = 1;
while (N < sz) N *= 2;
node.resize(2 * N - 1, mem);
for (long long i = (long long)(0); i < (long long)(sz); i++)
node[N - 1 + i] = X[i];
for (long long i = (long long)(N - 2); (long long)(0) <= i; i--) {
node[i] = Compare(node[i * 2 + 1], node[i * 2 + 2]);
}
}
T Compare(T &A, T &B) { return std::max(A, B); }
void update(long long X, T val) {
X += N - 1;
node[X] = val;
while (X > 0) {
X = (X - 1) / 2;
node[X] = Compare(node[X * 2 + 1], node[X * 2 + 2]);
}
}
T Query(long long a, long long b, long long now, long long l, long long r) {
if (r < 0) r = N;
if (r <= a || b <= l) return mem;
if (a <= l && r <= b) return node[now];
auto vl = Query(a, b, now * 2 + 1, l, (l + r) / 2),
vr = Query(a, b, now * 2 + 2, (l + r) / 2, r);
return Compare(vl, vr);
}
};
template <typename T>
struct lazy_Segment_tree {
int N;
vector<T> node, lazy;
T INF;
lazy_Segment_tree(vector<T> X, T Y) : INF(Y) {
N = 1;
while (X.size() > N) N *= 2;
node.resize(2 * N - 1, Y);
lazy.resize(2 * N - 1);
for (long long i = (long long)(0); i < (long long)(X.size()); i++)
node[i + N - 1] = X[i];
for (long long i = (long long)(N - 2); (long long)(0) <= i; i--)
node[i] = compare(node[i * 2 + 1], node[i * 2 + 2]);
}
T compare(T X, T Y) { return std::max(X, Y); }
T plus(T X, int l, int r) { return X; }
void eval(int now, int l, int r) {
if (lazy[now] == 0) return;
node[now] += lazy[now];
if (r - l > 1) {
lazy[now * 2 + 1] += plus(lazy[now], l, r);
lazy[now * 2 + 2] += plus(lazy[now], l, r);
}
lazy[now] = 0;
}
void update(int a, int b, T add, int now = 0, int l = 0, int r = -1) {
if (r < 0) r = N;
eval(now, l, r);
if (b <= l || r <= a) return;
if (a <= l && r <= b) {
lazy[now] += add;
eval(now, l, r);
} else {
update(a, b, add, now * 2 + 1, l, (r + l) / 2);
update(a, b, add, now * 2 + 2, (r + l) / 2, r);
node[now] = compare(node[now * 2 + 1], node[now * 2 + 2]);
}
}
T Query(int a, int b, int now = 0, int l = 0, int r = -1) {
if (r < 0) r = N;
eval(now, l, r);
if (b <= l || r <= a) return INF;
if (a <= l && r <= b) return node[now];
return compare(Query(a, b, now * 2 + 1, l, (r + l) / 2),
Query(a, b, now * 2 + 2, (r + l) / 2, r));
}
};
struct Tree {
int N;
vii dp;
vi dist;
Tree(vii edge) {
N = edge.size();
dp.resize(N);
dist.resize(N, -1);
for (int i = 0; i < N; i++) dp[i].resize(30);
dist[0] = dp[0][0] = 0;
std::queue<int> que;
que.push(0);
while (!que.empty()) {
int now = que.front();
que.pop();
for (int i = 0; i < edge[now].size(); i++) {
int next = edge[now][i];
if (dist[next] == -1) {
dist[next] = dist[now] + 1;
que.push(next);
dp[next][0] = now;
}
}
}
for (int i = 1; i < 30; i++) {
for (int j = 0; j < N; j++) dp[j][i] = dp[dp[j][i - 1]][i - 1];
}
}
int LCA(int X, int Y) {
if (dist[X] < dist[Y]) std::swap(X, Y);
{
int Z = dist[X] - dist[Y];
for (int i = 0; i < 30; i++) {
if (Z & (1 << i)) {
X = dp[X][i];
}
}
}
if (X == Y) return X;
for (int i = 29; i >= 0; i--) {
if (dp[X][i] != dp[Y][i]) {
X = dp[X][i];
Y = dp[Y][i];
}
}
return dp[X][0];
}
};
struct Binary_indexed_tree {
int N;
vi bit;
Binary_indexed_tree(int n) : N(n) { bit.resize(N + 1, 0); }
void add(int x, long long a) {
for (x; x <= N; x += (x & -x)) bit[x] += a;
}
long long sum(int x) {
long long ret = 0;
for (x; x > 0; x -= (x & -x)) ret += bit[x];
return ret;
}
long long lower_bound(long long X) {
if (sum(N) < X) return -1;
long long ret = 0, memo = 1, sum = 0;
while (memo * 2 <= N) memo *= 2;
while (memo > 0) {
if (memo + ret <= N && sum + bit[memo + ret] < X) {
sum += bit[memo + ret];
ret += memo;
}
memo /= 2;
}
return ret + 1;
}
};
struct Union_Find {
long long N;
vi par;
vi siz;
Union_Find(int n) : N(n) {
par.resize(N);
siz.resize(N, 1);
for (long long i = (long long)(0); i < (long long)(N); i++) par[i] = i;
}
long long root(long long X) {
if (par[X] == X) return X;
return par[X] = root(par[X]);
}
bool same(long long X, long long Y) { return root(X) == root(Y); }
void unite(long long X, long long Y) {
X = root(X);
Y = root(Y);
if (X == Y) return;
par[X] = Y;
siz[Y] += siz[X];
siz[X] = 0;
}
long long size(long long X) { return siz[root(X)]; }
};
long long modpow(long long a, long long n, long long mod) {
long long res = 1;
while (n > 0) {
if (n & 1) res = res * a % mod;
a = a * a % mod;
n >>= 1;
}
return res;
}
vi fac, finv, inv;
void COMinit() {
fac.resize(MAX);
finv.resize(MAX);
inv.resize(MAX);
fac[0] = fac[1] = 1;
finv[0] = finv[1] = 1;
inv[1] = 1;
for (int i = 2; i < MAX; i++) {
fac[i] = fac[i - 1] * i % MOD;
inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
finv[i] = finv[i - 1] * inv[i] % MOD;
}
}
long long COM(long long n, long long r) {
if (n < r || n < 0 || r < 0) return 0;
return fac[n] * finv[r] % MOD * finv[n - r] % MOD;
}
void comp(vi &A) {
std::map<long long, long long> memo;
for (long long i = (long long)(0); i < (long long)(A.size()); i++)
memo[A[i]] = 0;
long long cnt = 1;
for (auto &p : memo) p.second = cnt++;
for (long long i = (long long)(0); i < (long long)(A.size()); i++)
A[i] = memo[A[i]];
}
void dec(std::map<long long, long long> &mem, long long X) {
mem[X]--;
if (mem[X] == 0) mem.erase(X);
}
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
long long N;
cin >> N;
vi A(N);
vector<char> op(N);
for (long long i = (long long)(0); i < (long long)(N - 1); i++)
cin >> A[i] >> op[i];
cin >> A[N - 1];
vii dp(N, vi(3, -inf));
dp[0][0] = A[0];
for (long long i = (long long)(1); i < (long long)(N); i++) {
if (op[i - 1] == '+') {
dp[i][0] = std::max({dp[i - 1][0], dp[i - 1][1], dp[i - 1][2]}) + A[i];
dp[i][1] = dp[i - 1][1] - A[i];
dp[i][2] = dp[i - 1][2] + A[i];
} else {
dp[i][0] = dp[i - 1][0] - A[i];
dp[i][1] = std::max(dp[i - 1][0] - A[i], dp[i - 1][1] + A[i]);
dp[i][2] = std::max(dp[i - 1][2] + A[i], dp[i - 1][1] + A[i]);
}
}
long long ans = -inf;
for (long long i = (long long)(0); i < (long long)(3); i++)
ans = std::max(ans, dp[N - 1][i]);
cout << ans << "\n";
}
``` | instruction | 0 | 105,156 | 5 | 210,312 |
No | output | 1 | 105,156 | 5 | 210,313 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13
Submitted Solution:
```
n = int(input())
ipt = input().split()
node = [int(ipt[0])]
plus = n-1
while plus > 0 and ipt[2*plus] == '+':
node[0] += int(ipt[2*plus+1])
plus -= 1
for i in range(plus):
if ipt[2*i+1] == '+':
node[-1] += int(ipt[2*i+2])
else:
node.append(int(ipt[2*i+2]))
if len(node) == 1:
print(node[0])
else:
print(sum(node) - 2*node[1])
``` | instruction | 0 | 105,157 | 5 | 210,314 |
No | output | 1 | 105,157 | 5 | 210,315 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Joisino has a formula consisting of N terms: A_1 op_1 A_2 ... op_{N-1} A_N. Here, A_i is an integer, and op_i is an binary operator either `+` or `-`. Because Joisino loves large numbers, she wants to maximize the evaluated value of the formula by inserting an arbitrary number of pairs of parentheses (possibly zero) into the formula. Opening parentheses can only be inserted immediately before an integer, and closing parentheses can only be inserted immediately after an integer. It is allowed to insert any number of parentheses at a position. Your task is to write a program to find the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Constraints
* 1≦N≦10^5
* 1≦A_i≦10^9
* op_i is either `+` or `-`.
Input
The input is given from Standard Input in the following format:
N
A_1 op_1 A_2 ... op_{N-1} A_N
Output
Print the maximum possible evaluated value of the formula after inserting an arbitrary number of pairs of parentheses.
Examples
Input
3
5 - 1 - 3
Output
7
Input
5
1 - 2 + 3 - 4 + 5
Output
5
Input
5
1 - 20 - 13 + 14 - 5
Output
13
Submitted Solution:
```
n = int(input())
ipt = input().split()
node = [int(ipt[0])]
plus = n-1
while plus > 0 and ipt[2*plus-1] == '+':
node[0] += int(ipt[2*plus])
plus -= 1
for i in range(plus):
if ipt[2*i+1] == '+':
node[-1] += int(ipt[2*i+2])
else:
node.append(int(ipt[2*i+2]))
if len(node) == 1:
print(node[0])
else:
print(sum(node) - 2*node[1])
``` | instruction | 0 | 105,158 | 5 | 210,316 |
No | output | 1 | 105,158 | 5 | 210,317 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,239 | 5 | 210,478 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
a,b = map(int,input().split())
print(a - b)
``` | output | 1 | 105,239 | 5 | 210,479 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,240 | 5 | 210,480 |
"Correct Solution:
```
a = input().split()
print(int(a[0]) - int(a[1]))
``` | output | 1 | 105,240 | 5 | 210,481 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,241 | 5 | 210,482 |
"Correct Solution:
```
a,b = map(int,input().split())
print(a - b)
``` | output | 1 | 105,241 | 5 | 210,483 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,242 | 5 | 210,484 |
"Correct Solution:
```
print(eval(input().replace(' ','-')))
``` | output | 1 | 105,242 | 5 | 210,485 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,243 | 5 | 210,486 |
"Correct Solution:
```
from decimal import *
a, b = input().rstrip().split(' ')
getcontext().prec = 100001
print(Decimal(a) - Decimal(b))
``` | output | 1 | 105,243 | 5 | 210,487 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,244 | 5 | 210,488 |
"Correct Solution:
```
(x,y)=map(int,input().split(' '))
print(x-y);
``` | output | 1 | 105,244 | 5 | 210,489 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,245 | 5 | 210,490 |
"Correct Solution:
```
s = input().split()
print(int(s[0]) - int(s[1]))
``` | output | 1 | 105,245 | 5 | 210,491 |
Provide a correct Python 3 solution for this coding contest problem.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3 | instruction | 0 | 105,246 | 5 | 210,492 |
"Correct Solution:
```
A,B=[int(i) for i in input().split(" ")]
print(A-B)
``` | output | 1 | 105,246 | 5 | 210,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3
Submitted Solution:
```
print(sum(map(lambda x:(-1)**x[0]*x[1],(enumerate(map(int,input().split()))))))
``` | instruction | 0 | 105,247 | 5 | 210,494 |
Yes | output | 1 | 105,247 | 5 | 210,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3
Submitted Solution:
```
import sys,bisect,math
A,B = map(int,sys.stdin.readline().split())
print(A-B)
``` | instruction | 0 | 105,248 | 5 | 210,496 |
Yes | output | 1 | 105,248 | 5 | 210,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3
Submitted Solution:
```
import sys,collections as cl,bisect as bs
sys.setrecursionlimit(100000)
Max = sys.maxsize
def l(): #intのlist
return list(map(int,input().split()))
def m(): #複数文字
return map(int,input().split())
def onem(): #Nとかの取得
return int(input())
def s(x): #圧縮
a = []
aa = x[0]
su = 1
for i in range(len(x)-1):
if aa == x[i+1]:
a.append([aa,su])
aa = x[i+1]
su = 1
else:
su += 1
a.append([aa,su])
return a
def jo(x): #listをスペースごとに分ける
return " ".join(map(str,x))
def max2(x): #他のときもどうように作成可能
return max(map(max,x))
n,m= m()
print(n-m)
``` | instruction | 0 | 105,249 | 5 | 210,498 |
Yes | output | 1 | 105,249 | 5 | 210,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Big Integers - Difference of Big Integers
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=NTL_2_B&lang=jp
"""
import sys
def main(args):
A, B = map(int, input().split())
print(A - B)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 105,250 | 5 | 210,500 |
Yes | output | 1 | 105,250 | 5 | 210,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Difference of Big Integers
Given two integers $A$ and $B$, compute the difference, $A - B$.
Input
Two integers $A$ and $B$ separated by a space character are given in a line.
Output
Print the difference in a line.
Constraints
* $-1 \times 10^{100000} \leq A, B \leq 10^{100000}$
Sample Input 1
5 8
Sample Output 1
-3
Sample Input 2
100 25
Sample Output 2
75
Sample Input 3
-1 -1
Sample Output 3
0
Sample Input 4
12 -3
Sample Output 4
15
Example
Input
5 8
Output
-3
Submitted Solution:
```
a, b = [int(i) for i in input().split()])
print(a-b)
``` | instruction | 0 | 105,251 | 5 | 210,502 |
No | output | 1 | 105,251 | 5 | 210,503 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,101 | 5 | 212,202 |
"Correct Solution:
```
n = int(input())
A = [int(x) for x in input().split()]
q = int(input())
for i in range(q):
com, b, e = [int(x) for x in input().split()]
if com:
print(max(A[b:e]))
else:
print(min(A[b:e]))
``` | output | 1 | 106,101 | 5 | 212,203 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,102 | 5 | 212,204 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Basic Operations - Min-Max Element
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ITP2_3_B&lang=jp
"""
n = int(input())
A = [int(a) for a in input().split()]
for _ in range(int(input())):
com, b, e = input().split()
if com == '0':
print(min(A[int(b):int(e)]))
else:
print(max(A[int(b):int(e)]))
``` | output | 1 | 106,102 | 5 | 212,205 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,103 | 5 | 212,206 |
"Correct Solution:
```
n=int(input())
a=list(map(int,input().split( )))
q=int(input())
for i in range(q):
com,b,e=map(int,input().split( ))
if com==0:
mn=min(a[b:e])
print(mn)
else:
mx=max(a[b:e])
print(mx)
``` | output | 1 | 106,103 | 5 | 212,207 |
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