message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,104 | 5 | 212,208 |
"Correct Solution:
```
if __name__ == '__main__':
n = int(input())
A = list(map(int,input().split()))
n2 = int(input())
for i in range(n2):
com,b,e = map(int,input().split())
if com == 0:
print(min(A[b:e]))
else:
print(max(A[b:e]))
``` | output | 1 | 106,104 | 5 | 212,209 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,105 | 5 | 212,210 |
"Correct Solution:
```
N = int(input())
X = list(map(int,input().split()))
q = int(input())
for i in range(q):
a = input().split()
t = int(a[1])
s = int(a[2])
if a[0] =="0":
print(min(X[t:s]))
elif a[0] == "1":
print(max(X[t:s]))
``` | output | 1 | 106,105 | 5 | 212,211 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,106 | 5 | 212,212 |
"Correct Solution:
```
n = int(input())
A = list(map(int, input().split()))
q = int(input())
Q = list()
for i in range(q):
tmp = list(map(int, input().split()))
Q.append(tmp)
for query in Q:
if query[0] == 0:
print(min(A[query[1]:query[2]]))
else:
print(max(A[query[1]:query[2]]))
``` | output | 1 | 106,106 | 5 | 212,213 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,107 | 5 | 212,214 |
"Correct Solution:
```
if __name__ == "__main__":
num_int = int(input())
numbers = list(map(lambda x: int(x), input().split()))
num_query = int(input())
for _ in range(num_query):
op, begin, end = map(lambda x: int(x), input().split())
sub_numbers = numbers[begin: end]
if (0 == op):
min_num = min(sub_numbers)
print(min_num)
elif (1 == op):
max_num = max(sub_numbers)
print(max_num)
``` | output | 1 | 106,107 | 5 | 212,215 |
Provide a correct Python 3 solution for this coding contest problem.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9 | instruction | 0 | 106,108 | 5 | 212,216 |
"Correct Solution:
```
input()
a = list(map(int, input().split()))
q = int(input())
for _ in range(q):
x, s, t = list(map(int, input().split()))
print(min(a[s:t]) if x==0 else max(a[s:t]))
``` | output | 1 | 106,108 | 5 | 212,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split(" ")))
q=int(input())
for i in range(q):
c,b,e=map(int,input().split(" "))
if c:
print(max(a[b:e]))
else:
print(min(a[b:e]))
``` | instruction | 0 | 106,109 | 5 | 212,218 |
Yes | output | 1 | 106,109 | 5 | 212,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9
Submitted Solution:
```
# coding=utf-8
N = int(input())
A = list(map(int, input().split()))
Q = int(input())
for i in range(Q):
qtype, b, e = map(int, input().split())
if qtype == 0:
print(min(A[b:e]))
elif qtype == 1:
print(max(A[b:e]))
``` | instruction | 0 | 106,110 | 5 | 212,220 |
Yes | output | 1 | 106,110 | 5 | 212,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9
Submitted Solution:
```
def query(tree,begin,end,target,left,right,infinity,func):
if right <= begin or end <= left:
return infinity
if begin <= left and right <= end:
return tree[target]
next_position = (left + right) // 2
left_index = 2 * target + 1
right_index = left_index + 1
left_side_value = query(tree, begin, end, left_index, left, next_position, infinity, func)
right_side_value = query(tree, begin, end, right_index, next_position, right, infinity, func)
return func(left_side_value,right_side_value)
over_value = 2000000000
ary_size = int(input())
data_ary = list(map(int,input().split()))
leaf_size = 1
while leaf_size < ary_size:
leaf_size = leaf_size * 2
tree_size = leaf_size * 2 - 1
min_tree = [over_value] * tree_size
max_tree= [-over_value] * tree_size
for i in range(ary_size):
index = leaf_size - 1 + i
min_tree[index] = data_ary[i]
max_tree[index] = data_ary[i]
for i in range(leaf_size-2,-1,-1):
left_index = 2 * i + 1
right_index = left_index + 1
min_tree[i] = min(min_tree[left_index], min_tree[right_index])
max_tree[i] = max(max_tree[left_index], max_tree[right_index])
query_size = int(input())
for i in range(query_size):
input_data = list(map(int,input().split()))
command = input_data[0]
begin = input_data[1]
end = input_data[2]
if command == 0:
min_value = query(min_tree,begin,end,0,0,leaf_size,over_value,min)
print(min_value)
elif command == 1:
max_value = query(max_tree,begin,end,0,0,leaf_size,-over_value,max)
print(max_value)
``` | instruction | 0 | 106,111 | 5 | 212,222 |
Yes | output | 1 | 106,111 | 5 | 212,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9
Submitted Solution:
```
def resolve():
input()
A = [int(i) for i in input().split()]
Q = int(input())
for _ in range(Q):
q = [int(i) for i in input().split()]
if q[0] == 0:
print(min(A[q[1]:q[2]]))
else:
print(max(A[q[1]:q[2]]))
resolve()
``` | instruction | 0 | 106,112 | 5 | 212,224 |
Yes | output | 1 | 106,112 | 5 | 212,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9
Submitted Solution:
```
n = int(input())
nums = list(map(int, input().split(' ')))
q = int(input())
for i in range(q):
op = list(map(int, input().split(' ')))
if op[0] == 0:
min = float('inf')
for num in nums[op[1], op[2]]:
if num < min: min = num
print(min)
elif op[0] == 1:
max = -float('inf')
for num in nums[op[1], op[2]]:
if num < max: max = num
print(max)
``` | instruction | 0 | 106,113 | 5 | 212,226 |
No | output | 1 | 106,113 | 5 | 212,227 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:
* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$
Constraints
* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$
Input
The input is given in the following format.
$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$
In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.
Output
For each query, print the minimum element or the maximum element in a line.
Example
Input
7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7
Output
3
1
9
Submitted Solution:
```
n = int(input())
nums = list(map(int, input().split(' ')))
q = int(input())
for i in range(q):
op = list(map(int, input().split(' ')))
if op[0] == 0:
min = float('inf')
for num in nums[op[1]: op[2]]:
if num < min: min = num
print(min)
elif op[0] == 1:
max = -float('inf')
for num in nums[op[1]: op[2]]:
if num < max: max = num
print(max)
``` | instruction | 0 | 106,114 | 5 | 212,228 |
No | output | 1 | 106,114 | 5 | 212,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
n,x,y=[int(p) for p in input().split()]
if n>y or (y-n+1)**2 + n - 1<x:
print(-1)
else:
for i in range(n):
print((y-n+1)*(i==0)+(i!=0))
``` | instruction | 0 | 106,176 | 5 | 212,352 |
Yes | output | 1 | 106,176 | 5 | 212,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
n,x,y=list(map(int,input().split()))
if (y-n+1)>0 and x<=(y-n+1)**2+(n-1):
for i in range(n-1): print(1)
print(y-n+1)
else:print(-1)
``` | instruction | 0 | 106,177 | 5 | 212,354 |
Yes | output | 1 | 106,177 | 5 | 212,355 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
p=input().rstrip().split(' ')
n=int(p[0])
x=int(p[1])
y=int(p[2])
if n<=y:
A=y-(n-1);
B=(A*A)+(n-1)
if B<x:
print(-1)
else:
print(A)
for i in range(0,n-1):
print(1)
else:
print(-1)
``` | instruction | 0 | 106,178 | 5 | 212,356 |
Yes | output | 1 | 106,178 | 5 | 212,357 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
n,x,y = map(int,input().split())
t=[]
for k in range(n-1):
t.append(1)
s = y-(n-1)
if s>0:
if n-1+(s)**2>=x:
for si in t:
print(si)
print(s)
else:print(-1)
else:
print(-1)
``` | instruction | 0 | 106,179 | 5 | 212,358 |
Yes | output | 1 | 106,179 | 5 | 212,359 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
n,x,y=map(int,input().split())
import math
an=x-(n-1)
if(an<=0):
print(-1)
exit()
else:
me=math.sqrt(an)
if(me==int(me)):
me=int(me)
if(n-1+me<=y):
for i in range(n-1):
print(1)
print(me)
exit()
else:
print(-1)
exit()
else:
me=int(me)
me+=1
if(n-1+me<=y):
for i in range(n-1):
print(1)
print(me)
exit()
else:
print(-1)
exit()
``` | instruction | 0 | 106,180 | 5 | 212,360 |
No | output | 1 | 106,180 | 5 | 212,361 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
n,x,y =map(int,input().split())
xx = int(x**.5)
if x>=y :
if xx*xx + (n-1)>=x and xx + n-1<=y :
print(xx)
for i in range(n-1):
print(1)
elif (xx*xx)*2 + (n-2)>=x and 2*xx +n-2<=y :
print(xx)
print(xx)
for i in range(n-2):
print(1)
elif (xx+1)*(xx+1) + (n-1)>=x and (xx+1) +n-1<=y :
print(xx+1)
for i in range(n-1):
print(1)
elif ((xx+1)**2)*2 +n-2 >=x and 2*(xx+1)+n-2<=y:
print(xx+1)
print(xx+1)
for i in range(n-2):
print(1)
else:
print(-1)
else:
ans=[]
for i in range(y-n+1,-1,-1) :
if i**2 + n-1 >=x :
ans.append(i)
break
if len(ans)==0:
print(-1)
else:
print(ans[0])
for i in range(n-1):
print(1)
``` | instruction | 0 | 106,181 | 5 | 212,362 |
No | output | 1 | 106,181 | 5 | 212,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
import sys
n,x,y=map(int,sys.stdin.readline().split())
if (y-n+1<0) or (y-n+1)**2+(n-1)<x:
print(-1)
else:
print(y-n+1)
for i in range(n-1):
print(1)
``` | instruction | 0 | 106,182 | 5 | 212,364 |
No | output | 1 | 106,182 | 5 | 212,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya loves inequations. Help him find n positive integers a1, a2, ..., an, such that the following two conditions are satisfied:
* a12 + a22 + ... + an2 β₯ x
* a1 + a2 + ... + an β€ y
Input
The first line contains three space-separated integers n, x and y (1 β€ n β€ 105, 1 β€ x β€ 1012, 1 β€ y β€ 106).
Please do not use the %lld specificator to read or write 64-bit integers in Π‘++. It is recommended to use cin, cout streams or the %I64d specificator.
Output
Print n positive integers that satisfy the conditions, one integer per line. If such numbers do not exist, print a single number "-1". If there are several solutions, print any of them.
Examples
Input
5 15 15
Output
4
4
1
1
2
Input
2 3 2
Output
-1
Input
1 99 11
Output
11
Submitted Solution:
```
import sys
n,x,y=map(int,sys.stdin.readline().split())
if (y-n+1)**2+(n-1)<x:
print(-1)
else:
print(y-n+1)
for i in range(n-1):
print(1)
``` | instruction | 0 | 106,183 | 5 | 212,366 |
No | output | 1 | 106,183 | 5 | 212,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The only line of the input contains a 7-digit hexadecimal number. The first "digit" of the number is letter A, the rest of the "digits" are decimal digits 0-9.
Output
Output a single integer.
Examples
Input
A278832
Output
0
Input
A089956
Output
0
Input
A089957
Output
1
Input
A144045
Output
1
Submitted Solution:
```
def ii():
return int(input())
def mi():
return map(int, input().split())
def li():
return list(mi())
s = input()
s = s[1:]
sum = 0
for x in s:
sum += int(x)
if sum % 10 == 8:
print(1)
else:
print(0)
``` | instruction | 0 | 106,287 | 5 | 212,574 |
No | output | 1 | 106,287 | 5 | 212,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
'''
import itertools
def brute(n, k):
l = []
for i in range(n):
for j in range(n):
l.append((i, j))
combos = itertools.combinations(l, k)
m = 100000
for combo in combos:
rd, cd = {-1 : 0}, {-1 : 0}
for sq in combo:
if sq[0] in rd:
rd[sq[0]] += 1
else:
rd[sq[0]] = 1
if sq[1] in cd:
cd[sq[1]] += 1
else:
cd[sq[1]] = 1
if len(rd) == n + 1:
del rd[-1]
if len(cd) == n + 1:
del cd[-1]
fa = (max(rd.values()) - min(rd.values())) ** 2 + (max(cd.values()) - min(cd.values())) ** 2
#print(fa, combo, rd, cd)
m = min(m, fa)
return m
'''
def main():
t = int(input())
for _ in range(t):
n, k = map(int, input().split())
if k <= n:
if k == n or k == 0:
print(0)
else:
print(2)
for ii in range(n):
s = ""
for jj in range(n):
if ii == jj and k > 0:
s += "1"
k -= 1
else:
s += "0"
print(s)
continue
if k % n == 0:
print(0)
diags = k // n
else:
print(2)
diags = ((k // n) + 1)
l = [n - 1]
for x in range(diags - 1):
l.append(x)
l.append(n + x)
setl = set(l)
printl = []
have = 0
for i in range(n):
s = []
for j in range(n):
if (i + j) in setl:
s.append("1")
have += 1
else:
s.append("0")
printl.append(s)
have -= k
current_diag = l.pop()
cr = n - 1
cc = current_diag - n + 1
while have > 0:
have -= 1
printl[cr][cc] = "0"
cr -= 1
cc += 1
if cc >= n:
break
current_diag = l.pop()
cr = current_diag
cc = 0
while have > 0:
have -= 1
printl[cr][cc] = "0"
cr -= 1
cc += 1
if cr < 0:
break
for row in printl:
print("".join(row))
main()
``` | instruction | 0 | 106,313 | 5 | 212,626 |
Yes | output | 1 | 106,313 | 5 | 212,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
import sys
import math
from collections import defaultdict,Counter
# input=sys.stdin.readline
# def print(x):
# sys.stdout.write(str(x)+"\n")
# sys.stdout=open("CP2/output.txt",'w')
# sys.stdin=open("CP2/input.txt",'r')
# m=pow(10,9)+7
t=int(input())
for i in range(t):
n,k=map(int,input().split())
d=k//n
if k%n==0:
print(0)
else:
print(2)
# l=[[0]*n for j in range(n)]
rem=k%n
for j in range(n):
k1=d
if rem:
rem-=1
k1+=1
s1='1'*min(k1,n-j)
s2=''
if n-j>k1:
s1+='0'*(n-j-k1)
s2+='0'*j
else:
s2+='1'*(k1-n+j)
s2+='0'*(n-k1)
print(s2+s1)
``` | instruction | 0 | 106,314 | 5 | 212,628 |
Yes | output | 1 | 106,314 | 5 | 212,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
from sys import stdin
input = stdin.readline
def main():
test = int(input())
for _ in range(test):
# n = int(input())
n, k = [int(i) for i in input().split(" ")]
# x,y,n = [int(i) for i in input().split(" ")]
# a, b, n, m = [int(i) for i in input().split(" ")]
#
# l = list(input().strip())
# l = [int(i) for i in input().split(" ")]
#
# for i in l:
# print(i, end=' ')
# print()
matrix = [[0 for i in range(n)] for i in range(n)]
col = k // n
row = (k % n)
ans = 0
if row != 0:
ans = 2
for i in range(n):
temp = col
if row > 0:
row -= 1
temp += 1
j = i
while temp > 0:
matrix[i][j] = 1
j += 1
temp -= 1
if j == n:
j = 0
print(ans)
for i in matrix:
for j in i:
print(j, end='')
print()
main()
``` | instruction | 0 | 106,315 | 5 | 212,630 |
Yes | output | 1 | 106,315 | 5 | 212,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
for _ in range(int(input())):
n,k = map(int,input().split())
if k%n==0:
print('0')
else:
print('2')
a = [["0" for i in range(n)] for j in range(n)]
for i in range(n):
for j in range(n):
if k == 0:
break
a[j][(i+j)%n]= "1"
k-=1
if k==0:
break
for i in range(n):
print("".join(a[i]))
``` | instruction | 0 | 106,316 | 5 | 212,632 |
Yes | output | 1 | 106,316 | 5 | 212,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
t = int(input())
while t!=0:
n,k = map(int,input().split())
list1 = []
ans=0
for i in range(n):
temp = []
for j in range(n):
if k>0:
if j==i:
temp.append(1)
k-=1
else:
temp.append(0)
else:
temp.append(0)
list1.append(temp)
if k<=0:
if k==0:
print(0)
else:
print(2)
for i in range(n):
for j in range(n):
print(list1[i][j], end="")
print()
else:
p = k//n
q = k%n
if q==0:
print(0)
else:
print(2)
for i in range(n):
count = p
for j in range(n):
if count>0 and list1[i][j]==0:
list1[i][j]=1
count-=1
for i in range(n):
for j in range(n):
if q>0 and list1[i][j]==0:
list1[i][j]=1
q-=1
if q<=0:
break
if q<=0:
break
for i in range(n):
for j in range(n):
print(list1[i][j],end="")
print()
t-=1
``` | instruction | 0 | 106,317 | 5 | 212,634 |
No | output | 1 | 106,317 | 5 | 212,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
from bisect import bisect_left as bl
from bisect import bisect_right as br
from heapq import heappush,heappop
import math
from collections import *
from functools import reduce,cmp_to_key
import sys
input = sys.stdin.readline
M = mod = 998244353
def factors(n):return sorted(set(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))))
def inv_mod(n):return pow(n, mod - 2, mod)
def li():return [int(i) for i in input().rstrip('\n').split()]
def st():return input().rstrip('\n')
def val():return int(input().rstrip('\n'))
def li2():return [i for i in input().rstrip('\n')]
def li3():return [int(i) for i in input().rstrip('\n')]
for _ in range(val()):
n, k = li()
l = [[0 for i in range(n)] for j in range(n)]
up = [0,1]
down = [0,0]
par = 1
rows = [0]*n
cols = [0]*n
# print('K : ',k)
while k:
if par:
i,j = down[0],down[1]
else:
i,j = up[0],up[1]
while i < n and j < n and k:
k -= 1
l[i][j] = 1
rows[i] += 1
cols[j] += 1
i += 1
j += 1
# print('K : ',k)
# for i in l:print(*i)
if par:
down[0] += 1
else:
up[1] += 1
par = 1 - par
ans = 0
ans = (max(rows) - min(rows))**2 + (max(cols) - min(cols)) ** 2
print(ans)
for i in l:print(*i,sep = '')
``` | instruction | 0 | 106,318 | 5 | 212,636 |
No | output | 1 | 106,318 | 5 | 212,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
'''
import itertools
def brute(n, k):
l = []
for i in range(n):
for j in range(n):
l.append((i, j))
combos = itertools.combinations(l, k)
m = 100000
for combo in combos:
rd, cd = {-1 : 0}, {-1 : 0}
for sq in combo:
if sq[0] in rd:
rd[sq[0]] += 1
else:
rd[sq[0]] = 1
if sq[1] in cd:
cd[sq[1]] += 1
else:
cd[sq[1]] = 1
if len(rd) == n + 1:
del rd[-1]
if len(cd) == n + 1:
del cd[-1]
fa = (max(rd.values()) - min(rd.values())) ** 2 + (max(cd.values()) - min(cd.values())) ** 2
#print(fa, combo, rd, cd)
m = min(m, fa)
return m
'''
def main():
t = int(input())
for _ in range(t):
n, k = map(int, input().split())
if k <= n:
if k == n or k == 0:
print(0)
else:
print(1)
for ii in range(n):
s = ""
for jj in range(n):
if ii == jj and k > 0:
s += "1"
k -= 1
else:
s += "0"
print(s)
continue
if k % n == 0:
print(0)
diags = n
else:
print(2)
diags = ((k // n) + 1)
l = [n - 1]
for x in range(diags - 1):
l.append(x)
l.append(n + x)
setl = set(l)
printl = []
have = 0
for i in range(n):
s = []
for j in range(n):
if (i + j) in setl:
s.append("1")
have += 1
else:
s.append("0")
printl.append(s)
have -= k
current_diag = l.pop()
cr = n - 1
cc = current_diag - n + 1
while have > 0:
have -= 1
printl[cr][cc] = "0"
cr -= 1
cc += 1
if cc >= n:
break
current_diag = l.pop()
cr = current_diag
cc = 0
while have > 0:
have -= 1
printl[cr][cc] = "0"
cr -= 1
cc += 1
if cr < 0:
break
for row in printl:
print("".join(row))
main()
``` | instruction | 0 | 106,319 | 5 | 212,638 |
No | output | 1 | 106,319 | 5 | 212,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A mad scientist Dr.Jubal has made a competitive programming task. Try to solve it!
You are given integers n,k. Construct a grid A with size n Γ n consisting of integers 0 and 1. The very important condition should be satisfied: the sum of all elements in the grid is exactly k. In other words, the number of 1 in the grid is equal to k.
Let's define:
* A_{i,j} as the integer in the i-th row and the j-th column.
* R_i = A_{i,1}+A_{i,2}+...+A_{i,n} (for all 1 β€ i β€ n).
* C_j = A_{1,j}+A_{2,j}+...+A_{n,j} (for all 1 β€ j β€ n).
* In other words, R_i are row sums and C_j are column sums of the grid A.
* For the grid A let's define the value f(A) = (max(R)-min(R))^2 + (max(C)-min(C))^2 (here for an integer sequence X we define max(X) as the maximum value in X and min(X) as the minimum value in X).
Find any grid A, which satisfies the following condition. Among such grids find any, for which the value f(A) is the minimum possible. Among such tables, you can find any.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 β€ t β€ 100) β the number of test cases. Next t lines contain descriptions of test cases.
For each test case the only line contains two integers n, k (1 β€ n β€ 300, 0 β€ k β€ n^2).
It is guaranteed that the sum of n^2 for all test cases does not exceed 10^5.
Output
For each test case, firstly print the minimum possible value of f(A) among all tables, for which the condition is satisfied.
After that, print n lines contain n characters each. The j-th character in the i-th line should be equal to A_{i,j}.
If there are multiple answers you can print any.
Example
Input
4
2 2
3 8
1 0
4 16
Output
0
10
01
2
111
111
101
0
0
0
1111
1111
1111
1111
Note
In the first test case, the sum of all elements in the grid is equal to 2, so the condition is satisfied. R_1 = 1, R_2 = 1 and C_1 = 1, C_2 = 1. Then, f(A) = (1-1)^2 + (1-1)^2 = 0, which is the minimum possible value of f(A).
In the second test case, the sum of all elements in the grid is equal to 8, so the condition is satisfied. R_1 = 3, R_2 = 3, R_3 = 2 and C_1 = 3, C_2 = 2, C_3 = 3. Then, f(A) = (3-2)^2 + (3-2)^2 = 2. It can be proven, that it is the minimum possible value of f(A).
Submitted Solution:
```
import math
from sys import stdin
from collections import Counter,defaultdict,deque
input=stdin.readline
mod=pow(10,9)+7
def solve():
n,k=map(int,input().split())
if(k==0):
print(0)
for i in range(n):
for j in range(n):
print(0,end=" ")
print()
elif(k==(n*n)):
print(0)
for i in range(n):
for j in range(n):
print(1,end=" ")
print()
elif(k==n):
print(0)
for i in range(n):
for j in range(n):
if((i+j)==(n-1)):
print(1,end=" ")
else:
print(0,end=" ")
print()
elif(k<n):
print(2)
for i in range(n):
for j in range(n):
if((i+j)==(n-1) and k>0):
print(1,end=" ")
k=k-1
else:
print(0,end=" ")
print()
else:
l1=[[0 for i in range(n)] for j in range(n)]
c=0
x1=math.ceil(k/n)
x2=math.floor(k/n)
c=2*((x1-x2)*(x1-x2))
print(c)
n1=n
for i in range(n):
x1=math.ceil(k/n1)
k=k-x1
for j in range(n):
if(x1>0):
c=i
x1=x1-1
l1[c%n][j]=1
c=c+1
n1=n1-1
for i in range(n):
print(*l1[i])
for _ in range(int(input())):
solve()
``` | instruction | 0 | 106,320 | 5 | 212,640 |
No | output | 1 | 106,320 | 5 | 212,641 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given four integers n, m, l and r.
Let's name a tuple (x_1, y_1, x_2, y_2) as good if:
1. 1 β€ x_1 < x_2 β€ n;
2. 1 β€ y_2 < y_1 β€ m;
3. x_1 β
y_1 = x_2 β
y_2;
4. l β€ x_1 β
y_1 β€ r.
Find any good tuple for each x_1 from 1 to n inclusive.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5).
The second line contains two integers l and r (1 β€ l β€ r β€ nm).
Output
For each x_1 from 1 to n inclusive:
* if there are no such four integers, print -1;
* otherwise, print four integers x_1, y_1, x_2 and y_2. If there are multiple answers, print any of them.
Examples
Input
8 20
91 100
Output
-1
-1
-1
-1
-1
6 16 8 12
-1
-1
Input
4 5
1 10
Output
1 2 2 1
2 3 3 2
-1
-1
Input
5 12
16 60
Output
-1
2 9 3 6
3 8 4 6
4 5 5 4
-1
Submitted Solution:
```
n, m = [int(i) for i in input().split()]
l, r = [int(i) for i in input().split()]
for x1 in range(1, n+1):
for x2 in range(1, n+1):
for y1 in range(1, m+1):
for y2 in range(1, m+1):
if x1 != x2 and y1 != y2:
if 1 <= x1 < x2 <= n:
if 1 <= y2 < y1 <= m:
if x1*y1 == x2*y2:
if l <= x1*y1 <= r:
print(x1, y1, x2, y2)
break
else:
print(-1)
``` | instruction | 0 | 106,337 | 5 | 212,674 |
No | output | 1 | 106,337 | 5 | 212,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given four integers n, m, l and r.
Let's name a tuple (x_1, y_1, x_2, y_2) as good if:
1. 1 β€ x_1 < x_2 β€ n;
2. 1 β€ y_2 < y_1 β€ m;
3. x_1 β
y_1 = x_2 β
y_2;
4. l β€ x_1 β
y_1 β€ r.
Find any good tuple for each x_1 from 1 to n inclusive.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5).
The second line contains two integers l and r (1 β€ l β€ r β€ nm).
Output
For each x_1 from 1 to n inclusive:
* if there are no such four integers, print -1;
* otherwise, print four integers x_1, y_1, x_2 and y_2. If there are multiple answers, print any of them.
Examples
Input
8 20
91 100
Output
-1
-1
-1
-1
-1
6 16 8 12
-1
-1
Input
4 5
1 10
Output
1 2 2 1
2 3 3 2
-1
-1
Input
5 12
16 60
Output
-1
2 9 3 6
3 8 4 6
4 5 5 4
-1
Submitted Solution:
```
#import random
n, m = map(int, input().split())
l, r = map(int, input().split())
pointer=0;
c=-1;
x1=1;x2=1;y1=1;y2=1;
print("\n")
for x1 in range(1,n+1):
for x2 in range(1,n+1):
if x1 <= x2:
for y1 in range(1,m+1):
for y2 in range(1,m+1):
if y1>=y2:
if (x1*y1) == (x2*y2):
if x1*y1 <= r and x1*y1 >= l:
if x1 != x2:
if (x1<x2) and pointer == 0 :
print(x1,y1,x2,y2)
pointer=1;
else:
break;
c=1;
else:
c=0;
else:
if c==1:
c=1;
else:
c=0;
if c == 0:
print("-1")
c=-1;
pointer = 0;
``` | instruction | 0 | 106,338 | 5 | 212,676 |
No | output | 1 | 106,338 | 5 | 212,677 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given four integers n, m, l and r.
Let's name a tuple (x_1, y_1, x_2, y_2) as good if:
1. 1 β€ x_1 < x_2 β€ n;
2. 1 β€ y_2 < y_1 β€ m;
3. x_1 β
y_1 = x_2 β
y_2;
4. l β€ x_1 β
y_1 β€ r.
Find any good tuple for each x_1 from 1 to n inclusive.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5).
The second line contains two integers l and r (1 β€ l β€ r β€ nm).
Output
For each x_1 from 1 to n inclusive:
* if there are no such four integers, print -1;
* otherwise, print four integers x_1, y_1, x_2 and y_2. If there are multiple answers, print any of them.
Examples
Input
8 20
91 100
Output
-1
-1
-1
-1
-1
6 16 8 12
-1
-1
Input
4 5
1 10
Output
1 2 2 1
2 3 3 2
-1
-1
Input
5 12
16 60
Output
-1
2 9 3 6
3 8 4 6
4 5 5 4
-1
Submitted Solution:
```
n, m = map(int, input().split())
l, r = map(int, input().split())
for x1 in range(1, n + 1):
y1 = l // x1
if l % x1:
y1 -=- 1
if y1 > m:
print(-1)
continue
p = x1 * y1
s = True
if n < m:
for x2 in reversed(range(x1 + 1, n + 1)):
if not p % x2:
y2 = p // x2
if y2 < m:
s = False
print(x1, y1, x2, y2)
break
else:
for y2 in reversed(range(1, y1)):
if not p % y2:
x2 = p // y2
if x2 <= n:
s = False
print(x1, y1, x2, y2)
break
if s:
print(-1)
``` | instruction | 0 | 106,339 | 5 | 212,678 |
No | output | 1 | 106,339 | 5 | 212,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given four integers n, m, l and r.
Let's name a tuple (x_1, y_1, x_2, y_2) as good if:
1. 1 β€ x_1 < x_2 β€ n;
2. 1 β€ y_2 < y_1 β€ m;
3. x_1 β
y_1 = x_2 β
y_2;
4. l β€ x_1 β
y_1 β€ r.
Find any good tuple for each x_1 from 1 to n inclusive.
Input
The first line contains two integers n and m (1 β€ n, m β€ 2 β
10^5).
The second line contains two integers l and r (1 β€ l β€ r β€ nm).
Output
For each x_1 from 1 to n inclusive:
* if there are no such four integers, print -1;
* otherwise, print four integers x_1, y_1, x_2 and y_2. If there are multiple answers, print any of them.
Examples
Input
8 20
91 100
Output
-1
-1
-1
-1
-1
6 16 8 12
-1
-1
Input
4 5
1 10
Output
1 2 2 1
2 3 3 2
-1
-1
Input
5 12
16 60
Output
-1
2 9 3 6
3 8 4 6
4 5 5 4
-1
Submitted Solution:
```
def other(y,n,m,i):
for j in range(1,int(i**0.5)+1):
if i%j==0 and i//j!=y and j!=i//j:
if (j<=n and i//j<=m) or (j<=m and i//j<=n):
#print(j,i//j)
k=[j,i//j]
sorted(k)
return k
return []
def factors(y,n,m,l,r):
for i in range(l,r+1):
if i%y==0 and i//y<=m and y!=i//y:
k=other(y,n,m,i)
if len(k)>0:
return [y,i//y,k[0],k[1]]
return -1
n,m=map(int,input().split())
l,r=map(int,input().split())
ls=[]
for i in range(1,n+1):
#print(i)
p=factors(i,n,m,l,r)
if p!=-1:
h=sorted(p)
if p!=-1 and h not in ls :
ls.append(h)
u=list(map(str,p))
print(' '.join(u))
else:
print(-1)
``` | instruction | 0 | 106,340 | 5 | 212,680 |
No | output | 1 | 106,340 | 5 | 212,681 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
def main():
n = int(input())
a = list(map(int,input().split()))
if(n<=2):
print(n)
return
left = [0 for _ in range(n)]
right = [0 for _ in range(n)]
left[0] = 1
right[-1] = 1
ans = 0
for i in range(1,n):
if(a[i]>a[i-1]):
left[i]=left[i-1]+1
else:
left[i] = 1
ans = max(ans,left[i-1]+1)
for i in range(n-2,-1,-1):
if(a[i]<a[i+1]):
right[i]=right[i+1]+1
else:
right[i] = 1
ans = max(ans,right[i+1]+1)
for i in range(1,n-1):
# print(a[i+1]-a[i-1],i)
if(a[i+1]-a[i-1]>=2):
# print(i,left[i-1],right[i+1])
ans = max(left[i-1]+right[i+1]+1,ans)
print(ans)
# print(*left)
# print(*right)
main()
``` | instruction | 0 | 106,532 | 5 | 213,064 |
Yes | output | 1 | 106,532 | 5 | 213,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
import sys
def answer(n, a):
if n == 1:
return 1
if n == 2:
return 2
lord = [0 for _ in range(n)]
lord[0] = 1
for i in range(1, n):
if a[i] > a[i-1]:
lord[i] = lord[i-1] + 1
else:
lord[i] = 1
rord = [0 for _ in range(n)]
rord[n-1] = 1
for i in range(n-2, -1, -1):
if a[i] < a[i+1]:
rord[i] = rord[i+1] + 1
else:
rord[i] = 1
rep = [0 for _ in range(n)]
rep[0] = rord[1] + 1
rep[n-1] = lord[n-2] + 1
for i in range(1, n-1):
rep[i] = max(lord[i-1] + 1, rord[i+1] + 1)
if a[i-1] + 1 < a[i+1]:
rep[i] = max(rep[i], lord[i-1] + rord[i+1] + 1)
return max(rep)
def main():
n = int(sys.stdin.readline())
a = list(map(int, sys.stdin.readline().split()))
print(answer(n, a))
return
main()
``` | instruction | 0 | 106,533 | 5 | 213,066 |
Yes | output | 1 | 106,533 | 5 | 213,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
n=int(input())
s=input()
s1=s.split()
l=[int(i) for i in s1]
dp1=[1 for i in range(len(l))]
for i in range(1,len(l)):
if l[i]>l[i-1]:
dp1[i]=dp1[i-1]+1
dp2=[1 for i in range(len(l))]
for i in range(len(l)-2,-1,-1):
if l[i]<l[i+1]:
dp2[i]=dp2[i+1]+1
maxlen=max(dp1)
for i in range(0,len(l)):
if i+1<len(l) and i-1>=0 and l[i+1]>l[i-1]+1:
maxlen=max(dp1[i-1]+dp2[i+1]+1,maxlen)
if i-1>=0 and l[i]<=l[i-1]:
maxlen=max(maxlen,dp1[i-1]+1)
if i+1<len(l) and l[i]>=l[i+1]:
maxlen=max(maxlen,dp2[i+1]+1)
print(maxlen)
``` | instruction | 0 | 106,534 | 5 | 213,068 |
Yes | output | 1 | 106,534 | 5 | 213,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
# length = int(input())
# nums = [int(num) for num in input().split()]
# ans = length
# if length > 1:
# ans = 2
# i = j = 0
# k = 1
# print(nums[0])
# print(nums[1])
# while k < length:
# print(i, j, k, ans)
# if k < length - 1:
# print(nums[k + 1])
# if not nums[k] > nums[k - 1]:
# if 1 < k < length - 1 and not nums[k + 1] > nums[k - 1] + 1:
# if i == j:
# temp = k + 1 - i
# else:
# temp = k - min(i, j)
# ans = max(ans, temp)
# i = j = k if nums[k] <= nums[k - 1] else k - 1
# elif i < j:
# ans = max(ans, k - i)
# i = k if nums[k] <= nums[k - 1] else k - 1
# else:
# ans = max(ans, k - j)
# j = k if nums[k] <= nums[k - 1] else k - 1
# k += 1
# ans = max(ans, k - min(i, j))
# print(ans)
length = int(input())
nums = [int(num) for num in input().split()] + [float('inf'), float('-inf')]
ans = small = big = 0
for i in range(length):
if nums[i] > nums[i - 1]:
small += 1
big += 1
else:
ans = max(ans, small + 1, big)
big = small + 1 if nums[i + 1] > nums[i - 1] + 1 or nums[i] > nums[i - 2] + 1 else 2
small = 1 if nums[i + 1] > nums[i] else 0
# print(i, small, big, ans)
ans = max(ans, big)
print(ans)
``` | instruction | 0 | 106,535 | 5 | 213,070 |
Yes | output | 1 | 106,535 | 5 | 213,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
from sys import stdin,stdout
nmbr = lambda: int(stdin.readline())
lst = lambda: list(map(int,input().split()))
for i in range(1):#nmbr()):
n=nmbr()
a=lst()
if n==1:
print(1)
continue
f=[1]*n
b=[1]*(1+n)
for i in range(1,n):
if a[i]>a[i-1]:f[i]=1+f[i-1]
for i in range(n-2,-1,-1):
if a[i]<a[i+1]:b[i]=b[i+1]+1
ans=max(f)+1
for i in range(1,n-2):
if i+2<n and a[i]+2<=a[i+2]:
ans=max(ans,f[i]+b[i+2]+1)
print(ans)
``` | instruction | 0 | 106,536 | 5 | 213,072 |
No | output | 1 | 106,536 | 5 | 213,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
from bisect import bisect_left
n = int(input())
l = [int(i) for i in input().split()]
v = [0]
for i in l:
if v[-1]<i:
v.append(i)
else:
j = bisect_left(v, i)
v[j]=i
print(len(v))
``` | instruction | 0 | 106,537 | 5 | 213,074 |
No | output | 1 | 106,537 | 5 | 213,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
ls=[]
temp=[a[0]]
for i in range(1,n):
if(a[i]>a[i-1]):
temp.append(a[i])
else:
ls.append(temp)
temp=[a[i]]
if(len(temp)):
ls.append(temp)
ans=0
for i in range(len(ls)-1):
ans=max(ans,len(ls[i])+1)
if(len(ls[i+1])>1 and ls[i+1][1]-ls[i][-1]>1):
ans=max(ans,len(ls[i])+len(ls[i+1]))
ans=max(ans,len(ls[-1])+1)
print(min(ans,n))
``` | instruction | 0 | 106,538 | 5 | 213,076 |
No | output | 1 | 106,538 | 5 | 213,077 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY has a sequence a, consisting of n integers.
We'll call a sequence ai, ai + 1, ..., aj (1 β€ i β€ j β€ n) a subsegment of the sequence a. The value (j - i + 1) denotes the length of the subsegment.
Your task is to find the longest subsegment of a, such that it is possible to change at most one number (change one number to any integer you want) from the subsegment to make the subsegment strictly increasing.
You only need to output the length of the subsegment you find.
Input
The first line contains integer n (1 β€ n β€ 105). The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 109).
Output
In a single line print the answer to the problem β the maximum length of the required subsegment.
Examples
Input
6
7 2 3 1 5 6
Output
5
Note
You can choose subsegment a2, a3, a4, a5, a6 and change its 3rd element (that is a4) to 4.
Submitted Solution:
```
n = int(input())
a = list(map(int, input().strip().split()))
inc = [0 for i in range(n)]
inc[0] = 1
for i in range(1, n):
if a[i] > a[i-1]:
inc[i] = inc[i-1]+1
else:
inc[i] = inc[0]
dec = [ 0 for i in range(n)]
dec[-1] = 1
for i in range(n-2, -1, -1):
if a[i] < a[i+1]:
dec[i] = dec[i+1]+1
else:
dec[i] = dec[-1]
maxi = 1
for i in range(1, n-1):
if a[i-1] - a[i+1] < -1:
maxi = max(maxi, inc[i-1]+dec[i+1]+1)
maxi = max(maxi, inc[i]+1)
if n == 2:
print(2)
else:
print(maxi)
``` | instruction | 0 | 106,539 | 5 | 213,078 |
No | output | 1 | 106,539 | 5 | 213,079 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,626 | 5 | 213,252 |
Tags: brute force, implementation
Correct Solution:
```
import math
import itertools
import collections
def getdict(n):
d = {}
if type(n) is list:
for i in n:
if i in d:
d[i] += 1
else:
d[i] = 1
else:
for i in range(n):
t = ii()
if t in d:
d[t] += 1
else:
d[t] = 1
return d
def cdiv(n, k): return n // k + (n % k != 0)
def ii(): return int(input())
def mi(): return map(int, input().split())
def li(): return list(map(int, input().split()))
def lcm(a, b): return abs(a * b) // math.gcd(a, b)
n = ii()
a = li()
b = li()
ma = 0
mb = 0
for i in range(n):
ma = ma | a[i]
mb = mb | b[i]
print(ma + mb)
``` | output | 1 | 106,626 | 5 | 213,253 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,627 | 5 | 213,254 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
maxi1 = 0
maxi2 = 0
maxi = 0
for beg in range(n):
tmp1 = a[beg]
tmp2 = b[beg]
for end in range(beg+1,n):
tmp1 = tmp1 | a[end]
tmp2 = tmp2 | b[end]
if tmp1 + tmp2 > maxi: maxi = tmp1 + tmp2
if tmp1 + tmp2 > maxi: maxi = tmp1 + tmp2
#if tmp2 > maxi2: maxi2=tmp2
print(maxi)
``` | output | 1 | 106,627 | 5 | 213,255 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,628 | 5 | 213,256 |
Tags: brute force, implementation
Correct Solution:
```
import bisect
import math
import collections
import sys
import copy
from functools import reduce
import decimal
from io import BytesIO, IOBase
import os
sys.setrecursionlimit(10 ** 9)
decimal.getcontext().rounding = decimal.ROUND_HALF_UP
graphDict = collections.defaultdict
queue = collections.deque
class Graphs:
def __init__(self):
self.graph = graphDict(list)
def add_edge(self, u, v):
self.graph[u].append(v)
def dfs_utility(self, nodes, visited_nodes):
visited_nodes.add(nodes)
for neighbour in self.graph[nodes]:
if neighbour not in visited_nodes:
self.dfs_utility(neighbour, visited_nodes)
else:
return neighbour
def dfs(self, node):
Visited = set()
self.dfs_utility(node, Visited)
def bfs(self, node):
visited = set()
if node not in visited:
queue.append(node)
visited.add(node)
while queue:
parent = queue.popleft()
print(parent)
for item in self.graph[parent]:
if item not in visited:
queue.append(item)
visited.add(item)
def rounding(n):
return int(decimal.Decimal(f'{n}').to_integral_value())
def factors(n):
return set(reduce(list.__add__,
([i, n // i] for i in range(1, int(n ** 0.5) + 1) if n % i == 0)))
################################ <fast I/O> ###########################################
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
#############################################<I/O Region >##############################################
def inp():
return sys.stdin.readline().strip()
def map_inp(v_type):
return map(v_type, inp().split())
def list_inp(v_type):
return list(map_inp(v_type))
######################################## Solution ####################################
def create_seg_tree(seg_arr, normy_arr, index, i, j):
if i == j:
seg_arr[index] = normy_arr[i]
return
else:
mid = (i + j) // 2
create_seg_tree(seg_arr, normy_arr, 2 * index, i, mid)
create_seg_tree(seg_arr, normy_arr, 2 * index + 1, mid + 1, j)
left = seg_arr[2 * index]
right = seg_arr[2 * index + 1]
seg_arr[index] = left | right
return seg_arr
def query(seg_arr, index, i, j, qi, qj):
if qj < i or qi > j:
return float("inf")
if qi <= i and qj >= j:
return seg_arr[index]
mid = (i + j) // 2
left = query(seg_arr, 2 * index, i, mid, qi, qj)
right = query(seg_arr, (2 * index) + 1, mid + 1, j, qi, qj)
return abs(left - right)
n = int(inp())
a = list_inp(int)
b = list_inp(int)
arr1 = [0 for item in range(4 * n + 1)]
arr2 = [0 for i in range(4 * n + 1)]
create_seg_tree(arr1, a, 1, 0, n - 1)
create_seg_tree(arr2, b, 1, 0, n - 1)
print(arr2[1]+arr1[1])
``` | output | 1 | 106,628 | 5 | 213,257 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,629 | 5 | 213,258 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
ps = list(map(int, input().split()))
qs = list(map(int, input().split()))
maxi = 0
s_a, s_b = 0, 0
for l in range(n):
s_a = ps[l]
s_b = qs[l]
for r in range(l, n):
s_a = s_a | ps[r]
s_b = s_b | qs[r]
maxi = max(maxi, s_a + s_b)
print(maxi)
``` | output | 1 | 106,629 | 5 | 213,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,630 | 5 | 213,260 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
r = 0
for i in range(n):
fa = a[i]
fb = b[i]
for j in range(i, n):
fa |= a[j]
fb |= b[j]
r = max(r, fa+fb)
print(r)
``` | output | 1 | 106,630 | 5 | 213,261 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,631 | 5 | 213,262 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
s = input()
a = s.split(' ')
s = input()
b = s.split(' ')
for i in range(n):
a[i],b[i] = int(a[i]),int(b[i])
res = a[0] + b[0]
for l in range(n):
sumA = 0
sumB = 0
for r in range(l,n):
sumA |= a[r]
sumB |= b[r]
sum = sumA + sumB
res = max(res,sum)
print(res)
``` | output | 1 | 106,631 | 5 | 213,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,632 | 5 | 213,264 |
Tags: brute force, implementation
Correct Solution:
```
from functools import reduce
R = lambda:map(int,input().split())
n, = R()
arr = list(R())
arr_two = list(R())
print(reduce(lambda a,b:a|b, arr) + reduce(lambda a,b:a|b, arr_two))
``` | output | 1 | 106,632 | 5 | 213,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9. | instruction | 0 | 106,633 | 5 | 213,266 |
Tags: brute force, implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split(' ')))
b = list(map(int, input().split(' ')))
totala=0
totalb=0
for i in range(n):
totala|=a[i]
totalb|=b[i]
print(totala+totalb)
``` | output | 1 | 106,633 | 5 | 213,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9.
Submitted Solution:
```
n = int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
ans=0
for i in range(n):
ans1=a[i]
ans2=b[i]
for j in range(i+1,n):
ans1=ans1|a[j]
ans2=ans2|b[j]
ans=max(ans,ans1+ans2)
print(ans)
``` | instruction | 0 | 106,634 | 5 | 213,268 |
Yes | output | 1 | 106,634 | 5 | 213,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Blake is a CEO of a large company called "Blake Technologies". He loves his company very much and he thinks that his company should be the best. That is why every candidate needs to pass through the interview that consists of the following problem.
We define function f(x, l, r) as a bitwise OR of integers xl, xl + 1, ..., xr, where xi is the i-th element of the array x. You are given two arrays a and b of length n. You need to determine the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
<image>
Input
The first line of the input contains a single integer n (1 β€ n β€ 1000) β the length of the arrays.
The second line contains n integers ai (0 β€ ai β€ 109).
The third line contains n integers bi (0 β€ bi β€ 109).
Output
Print a single integer β the maximum value of sum f(a, l, r) + f(b, l, r) among all possible 1 β€ l β€ r β€ n.
Examples
Input
5
1 2 4 3 2
2 3 3 12 1
Output
22
Input
10
13 2 7 11 8 4 9 8 5 1
5 7 18 9 2 3 0 11 8 6
Output
46
Note
Bitwise OR of two non-negative integers a and b is the number c = a OR b, such that each of its digits in binary notation is 1 if and only if at least one of a or b have 1 in the corresponding position in binary notation.
In the first sample, one of the optimal answers is l = 2 and r = 4, because f(a, 2, 4) + f(b, 2, 4) = (2 OR 4 OR 3) + (3 OR 3 OR 12) = 7 + 15 = 22. Other ways to get maximum value is to choose l = 1 and r = 4, l = 1 and r = 5, l = 2 and r = 4, l = 2 and r = 5, l = 3 and r = 4, or l = 3 and r = 5.
In the second sample, the maximum value is obtained for l = 1 and r = 9.
Submitted Solution:
```
__author__ = 'aste'
def main():
n = int(input())
a = map(int, input().split())
b = map(int, input().split())
a_or = 0
for x in a:
a_or |= x
b_or = 0
for x in b:
b_or |= x
print(a_or + b_or)
main()
``` | instruction | 0 | 106,635 | 5 | 213,270 |
Yes | output | 1 | 106,635 | 5 | 213,271 |
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