message stringlengths 2 44.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a matrix a consisting of positive integers. It has n rows and m columns.
Construct a matrix b consisting of positive integers. It should have the same size as a, and the following conditions should be met:
* 1 ≤ b_{i,j} ≤ 10^6;
* b_{i,j} is a multiple of a_{i,j};
* the absolute value of the difference between numbers in any adjacent pair of cells (two cells that share the same side) in b is equal to k^4 for some integer k ≥ 1 (k is not necessarily the same for all pairs, it is own for each pair).
We can show that the answer always exists.
Input
The first line contains two integers n and m (2 ≤ n,m ≤ 500).
Each of the following n lines contains m integers. The j-th integer in the i-th line is a_{i,j} (1 ≤ a_{i,j} ≤ 16).
Output
The output should contain n lines each containing m integers. The j-th integer in the i-th line should be b_{i,j}.
Examples
Input
2 2
1 2
2 3
Output
1 2
2 3
Input
2 3
16 16 16
16 16 16
Output
16 32 48
32 48 64
Input
2 2
3 11
12 8
Output
327 583
408 664
Note
In the first example, the matrix a can be used as the matrix b, because the absolute value of the difference between numbers in any adjacent pair of cells is 1 = 1^4.
In the third example:
* 327 is a multiple of 3, 583 is a multiple of 11, 408 is a multiple of 12, 664 is a multiple of 8;
* |408 - 327| = 3^4, |583 - 327| = 4^4, |664 - 408| = 4^4, |664 - 583| = 3^4.
Submitted Solution:
```
"""
Author - Satwik Tiwari .
7th Feb , 2021 - Sunday
"""
#===============================================================================================
#importing some useful libraries.
from __future__ import division, print_function
from fractions import Fraction
import sys
import os
from io import BytesIO, IOBase
from functools import cmp_to_key
# from itertools import *
from heapq import *
from math import gcd, factorial,floor,ceil,sqrt,log2
from copy import deepcopy
from collections import deque
from bisect import bisect_left as bl
from bisect import bisect_right as br
from bisect import bisect
#==============================================================================================
#fast I/O region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
# inp = lambda: sys.stdin.readline().rstrip("\r\n")
#===============================================================================================
### START ITERATE RECURSION ###
from types import GeneratorType
def iterative(f, stack=[]):
def wrapped_func(*args, **kwargs):
if stack: return f(*args, **kwargs)
to = f(*args, **kwargs)
while True:
if type(to) is GeneratorType:
stack.append(to)
to = next(to)
continue
stack.pop()
if not stack: break
to = stack[-1].send(to)
return to
return wrapped_func
#### END ITERATE RECURSION ####
#===============================================================================================
#some shortcuts
def inp(): return sys.stdin.readline().rstrip("\r\n") #for fast input
def out(var): sys.stdout.write(str(var)) #for fast output, always take string
def lis(): return list(map(int, inp().split()))
def stringlis(): return list(map(str, inp().split()))
def sep(): return map(int, inp().split())
def strsep(): return map(str, inp().split())
# def graph(vertex): return [[] for i in range(0,vertex+1)]
def testcase(t):
for pp in range(t):
solve(pp)
def google(p):
print('Case #'+str(p)+': ',end='')
def lcm(a,b): return (a*b)//gcd(a,b)
def power(x, y, p) :
y%=(p-1) #not so sure about this. used when y>p-1. if p is prime.
res = 1 # Initialize result
x = x % p # Update x if it is more , than or equal to p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) : # If y is odd, multiply, x with result
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
def ncr(n,r): return factorial(n) // (factorial(r) * factorial(max(n - r, 1)))
def isPrime(n) :
if (n <= 1) : return False
if (n <= 3) : return True
if (n % 2 == 0 or n % 3 == 0) : return False
i = 5
while(i * i <= n) :
if (n % i == 0 or n % (i + 2) == 0) :
return False
i = i + 6
return True
inf = pow(10,20)
mod = 10**9+7
#===============================================================================================
# code here ;))
def solve(case):
n,m = sep()
g = []
for i in range(n):
temp = lis()
g.append(temp)
lcmm = 1
for i in range(n):
for j in range(m):
lcmm = lcm(lcmm,g[i][j])
a = lcmm
# b = lcmm**3+1
ans = [[0]*m for i in range(n)]
for i in range(n):
for j in range(m):
ans[i][j] = a if (i+j)%2 else a+g[i][j]**4
for i in range(n):
print(' '.join(str(i) for i in ans[i]))
testcase(1)
# testcase(int(inp()))
``` | instruction | 0 | 24,993 | 5 | 49,986 |
Yes | output | 1 | 24,993 | 5 | 49,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a matrix a consisting of positive integers. It has n rows and m columns.
Construct a matrix b consisting of positive integers. It should have the same size as a, and the following conditions should be met:
* 1 ≤ b_{i,j} ≤ 10^6;
* b_{i,j} is a multiple of a_{i,j};
* the absolute value of the difference between numbers in any adjacent pair of cells (two cells that share the same side) in b is equal to k^4 for some integer k ≥ 1 (k is not necessarily the same for all pairs, it is own for each pair).
We can show that the answer always exists.
Input
The first line contains two integers n and m (2 ≤ n,m ≤ 500).
Each of the following n lines contains m integers. The j-th integer in the i-th line is a_{i,j} (1 ≤ a_{i,j} ≤ 16).
Output
The output should contain n lines each containing m integers. The j-th integer in the i-th line should be b_{i,j}.
Examples
Input
2 2
1 2
2 3
Output
1 2
2 3
Input
2 3
16 16 16
16 16 16
Output
16 32 48
32 48 64
Input
2 2
3 11
12 8
Output
327 583
408 664
Note
In the first example, the matrix a can be used as the matrix b, because the absolute value of the difference between numbers in any adjacent pair of cells is 1 = 1^4.
In the third example:
* 327 is a multiple of 3, 583 is a multiple of 11, 408 is a multiple of 12, 664 is a multiple of 8;
* |408 - 327| = 3^4, |583 - 327| = 4^4, |664 - 408| = 4^4, |664 - 583| = 3^4.
Submitted Solution:
```
def main():
n, m = map(int, input().split())
l = []; world = 720720
quads = []
for i in range(1, 31):
quads.append(i ** 4)
for i in range(1, 17):
for quad in quads:
if (world - quad) % i == 0:
l.append(quad)
break
#print(l)
for i in range(n):
row = list(map(int, input().split()))
p = []
for j in range(m):
if (i + j) % 2 == 0:
p.append(world)
else:
p.append(world - quads[row[j] - 1])
print(*p)
main()
``` | instruction | 0 | 24,994 | 5 | 49,988 |
Yes | output | 1 | 24,994 | 5 | 49,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a matrix a consisting of positive integers. It has n rows and m columns.
Construct a matrix b consisting of positive integers. It should have the same size as a, and the following conditions should be met:
* 1 ≤ b_{i,j} ≤ 10^6;
* b_{i,j} is a multiple of a_{i,j};
* the absolute value of the difference between numbers in any adjacent pair of cells (two cells that share the same side) in b is equal to k^4 for some integer k ≥ 1 (k is not necessarily the same for all pairs, it is own for each pair).
We can show that the answer always exists.
Input
The first line contains two integers n and m (2 ≤ n,m ≤ 500).
Each of the following n lines contains m integers. The j-th integer in the i-th line is a_{i,j} (1 ≤ a_{i,j} ≤ 16).
Output
The output should contain n lines each containing m integers. The j-th integer in the i-th line should be b_{i,j}.
Examples
Input
2 2
1 2
2 3
Output
1 2
2 3
Input
2 3
16 16 16
16 16 16
Output
16 32 48
32 48 64
Input
2 2
3 11
12 8
Output
327 583
408 664
Note
In the first example, the matrix a can be used as the matrix b, because the absolute value of the difference between numbers in any adjacent pair of cells is 1 = 1^4.
In the third example:
* 327 is a multiple of 3, 583 is a multiple of 11, 408 is a multiple of 12, 664 is a multiple of 8;
* |408 - 327| = 3^4, |583 - 327| = 4^4, |664 - 408| = 4^4, |664 - 583| = 3^4.
Submitted Solution:
```
n,m=list(map(int,input().split()))
for i in range(n):
l=list(map(int,input().split()))
for j in range(m):
c=720720
if (i+j)%2==1:
c-=(l[j]**4)
print(c,end=" ")
print()
``` | instruction | 0 | 24,995 | 5 | 49,990 |
Yes | output | 1 | 24,995 | 5 | 49,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a matrix a consisting of positive integers. It has n rows and m columns.
Construct a matrix b consisting of positive integers. It should have the same size as a, and the following conditions should be met:
* 1 ≤ b_{i,j} ≤ 10^6;
* b_{i,j} is a multiple of a_{i,j};
* the absolute value of the difference between numbers in any adjacent pair of cells (two cells that share the same side) in b is equal to k^4 for some integer k ≥ 1 (k is not necessarily the same for all pairs, it is own for each pair).
We can show that the answer always exists.
Input
The first line contains two integers n and m (2 ≤ n,m ≤ 500).
Each of the following n lines contains m integers. The j-th integer in the i-th line is a_{i,j} (1 ≤ a_{i,j} ≤ 16).
Output
The output should contain n lines each containing m integers. The j-th integer in the i-th line should be b_{i,j}.
Examples
Input
2 2
1 2
2 3
Output
1 2
2 3
Input
2 3
16 16 16
16 16 16
Output
16 32 48
32 48 64
Input
2 2
3 11
12 8
Output
327 583
408 664
Note
In the first example, the matrix a can be used as the matrix b, because the absolute value of the difference between numbers in any adjacent pair of cells is 1 = 1^4.
In the third example:
* 327 is a multiple of 3, 583 is a multiple of 11, 408 is a multiple of 12, 664 is a multiple of 8;
* |408 - 327| = 3^4, |583 - 327| = 4^4, |664 - 408| = 4^4, |664 - 583| = 3^4.
Submitted Solution:
```
# coding:UTF-8
import sys
input = sys.stdin.buffer.readline
MOD = 10 ** 9 + 7
INF = float('inf')
N, M = list(map(int, input().split())) # スペース区切り連続数字
A = [list(map(int, input().split())) for _ in range(N)] # スペース区切り連続数字(行列)
num = [720720**4, 720720]
res = [[0] * M for _ in range(N)]
for i in range(N):
for j in range(M):
res[i][j] = num[(i + j) % 2]
for r in res:
print(*r)
``` | instruction | 0 | 24,996 | 5 | 49,992 |
No | output | 1 | 24,996 | 5 | 49,993 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a matrix a consisting of positive integers. It has n rows and m columns.
Construct a matrix b consisting of positive integers. It should have the same size as a, and the following conditions should be met:
* 1 ≤ b_{i,j} ≤ 10^6;
* b_{i,j} is a multiple of a_{i,j};
* the absolute value of the difference between numbers in any adjacent pair of cells (two cells that share the same side) in b is equal to k^4 for some integer k ≥ 1 (k is not necessarily the same for all pairs, it is own for each pair).
We can show that the answer always exists.
Input
The first line contains two integers n and m (2 ≤ n,m ≤ 500).
Each of the following n lines contains m integers. The j-th integer in the i-th line is a_{i,j} (1 ≤ a_{i,j} ≤ 16).
Output
The output should contain n lines each containing m integers. The j-th integer in the i-th line should be b_{i,j}.
Examples
Input
2 2
1 2
2 3
Output
1 2
2 3
Input
2 3
16 16 16
16 16 16
Output
16 32 48
32 48 64
Input
2 2
3 11
12 8
Output
327 583
408 664
Note
In the first example, the matrix a can be used as the matrix b, because the absolute value of the difference between numbers in any adjacent pair of cells is 1 = 1^4.
In the third example:
* 327 is a multiple of 3, 583 is a multiple of 11, 408 is a multiple of 12, 664 is a multiple of 8;
* |408 - 327| = 3^4, |583 - 327| = 4^4, |664 - 408| = 4^4, |664 - 583| = 3^4.
Submitted Solution:
```
from sys import stdin, stdout
import sys
# 2 2
# 3 11
# 12 8
def multiples_and_power_differences(n, m, b_a):
# r = 1
# for i in range(2, 17):
# r = lcm(r, i)
r = 720720
for i in range(n):
for j in range(m):
if (i+j)%2 == 0:
b_a[i][j] = r
else:
b_a[i][j] = r - (b_a[i][j]**4)
def lcm(a, b):
g = gcd(a, b)
return a*b//g
def gcd(a, b):
if b == 0:
return a
return gcd(b, a%b)
try:
n, m = map(int, stdin.readline().split())
b_a = []
for _ in range(n):
b_a.append(map(int, stdin.readline().split()))
multiples_and_power_differences(n, m, b_a)
for i in range(n):
b = b_a[i]
if i > 0:
stdout.write('\n' + ' '.join(map(str, b)))
else:
stdout.write(' '.join(map(str, b)))
except:
print(sys.exc_info())
``` | instruction | 0 | 24,997 | 5 | 49,994 |
No | output | 1 | 24,997 | 5 | 49,995 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a matrix a consisting of positive integers. It has n rows and m columns.
Construct a matrix b consisting of positive integers. It should have the same size as a, and the following conditions should be met:
* 1 ≤ b_{i,j} ≤ 10^6;
* b_{i,j} is a multiple of a_{i,j};
* the absolute value of the difference between numbers in any adjacent pair of cells (two cells that share the same side) in b is equal to k^4 for some integer k ≥ 1 (k is not necessarily the same for all pairs, it is own for each pair).
We can show that the answer always exists.
Input
The first line contains two integers n and m (2 ≤ n,m ≤ 500).
Each of the following n lines contains m integers. The j-th integer in the i-th line is a_{i,j} (1 ≤ a_{i,j} ≤ 16).
Output
The output should contain n lines each containing m integers. The j-th integer in the i-th line should be b_{i,j}.
Examples
Input
2 2
1 2
2 3
Output
1 2
2 3
Input
2 3
16 16 16
16 16 16
Output
16 32 48
32 48 64
Input
2 2
3 11
12 8
Output
327 583
408 664
Note
In the first example, the matrix a can be used as the matrix b, because the absolute value of the difference between numbers in any adjacent pair of cells is 1 = 1^4.
In the third example:
* 327 is a multiple of 3, 583 is a multiple of 11, 408 is a multiple of 12, 664 is a multiple of 8;
* |408 - 327| = 3^4, |583 - 327| = 4^4, |664 - 408| = 4^4, |664 - 583| = 3^4.
Submitted Solution:
```
def find():
n, m = map(int, input().split())
mas = [tuple(map(int, input().split())) for i in range(n)]
for i in range(n):
for j in range(m):
if j % 2 == 0:
print(720720, end=' ')
else:
print(720720 + mas[i][j]**4, end=' ')
print()
print(find())
``` | instruction | 0 | 24,998 | 5 | 49,996 |
No | output | 1 | 24,998 | 5 | 49,997 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a matrix a consisting of positive integers. It has n rows and m columns.
Construct a matrix b consisting of positive integers. It should have the same size as a, and the following conditions should be met:
* 1 ≤ b_{i,j} ≤ 10^6;
* b_{i,j} is a multiple of a_{i,j};
* the absolute value of the difference between numbers in any adjacent pair of cells (two cells that share the same side) in b is equal to k^4 for some integer k ≥ 1 (k is not necessarily the same for all pairs, it is own for each pair).
We can show that the answer always exists.
Input
The first line contains two integers n and m (2 ≤ n,m ≤ 500).
Each of the following n lines contains m integers. The j-th integer in the i-th line is a_{i,j} (1 ≤ a_{i,j} ≤ 16).
Output
The output should contain n lines each containing m integers. The j-th integer in the i-th line should be b_{i,j}.
Examples
Input
2 2
1 2
2 3
Output
1 2
2 3
Input
2 3
16 16 16
16 16 16
Output
16 32 48
32 48 64
Input
2 2
3 11
12 8
Output
327 583
408 664
Note
In the first example, the matrix a can be used as the matrix b, because the absolute value of the difference between numbers in any adjacent pair of cells is 1 = 1^4.
In the third example:
* 327 is a multiple of 3, 583 is a multiple of 11, 408 is a multiple of 12, 664 is a multiple of 8;
* |408 - 327| = 3^4, |583 - 327| = 4^4, |664 - 408| = 4^4, |664 - 583| = 3^4.
Submitted Solution:
```
n, m = map(int, input().split())
k = [list(map(int, input().split())) for i in range(n)]
for i in range(n):
for j in range(m):
if (i + j) % 2 == 0:
print(360360, end = ' ')
else:
print(360360 + k[i][j] ** 4, end = ' ')
print()
``` | instruction | 0 | 24,999 | 5 | 49,998 |
No | output | 1 | 24,999 | 5 | 49,999 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,337 | 5 | 50,674 |
"Correct Solution:
```
a,b,c=input().split()
b,a=a,b
c,a=a,c
print(a,b,c)
``` | output | 1 | 25,337 | 5 | 50,675 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,338 | 5 | 50,676 |
"Correct Solution:
```
a,b,c=map(int,input().split())
print(c,a,b,sep=' ')
``` | output | 1 | 25,338 | 5 | 50,677 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,339 | 5 | 50,678 |
"Correct Solution:
```
X,Y,Z=map(int,input().split());print(Z,X,Y)
``` | output | 1 | 25,339 | 5 | 50,679 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,340 | 5 | 50,680 |
"Correct Solution:
```
x,y,z=map(int,input().split())
lst=[z,x,y]
print(*lst)
``` | output | 1 | 25,340 | 5 | 50,681 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,341 | 5 | 50,682 |
"Correct Solution:
```
X,Y,Z=input().split()
print(Z,X,Y)
``` | output | 1 | 25,341 | 5 | 50,683 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,342 | 5 | 50,684 |
"Correct Solution:
```
l=list(map(int,input().split()))
print(l[-1],l[0],l[1])
``` | output | 1 | 25,342 | 5 | 50,685 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,343 | 5 | 50,686 |
"Correct Solution:
```
X,Y,Z = [int(i) for i in input().split()]
print(Z,X,Y)
``` | output | 1 | 25,343 | 5 | 50,687 |
Provide a correct Python 3 solution for this coding contest problem.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59 | instruction | 0 | 25,344 | 5 | 50,688 |
"Correct Solution:
```
L=list(map(int,input().split()))
print(L[2],L[0],L[1])
``` | output | 1 | 25,344 | 5 | 50,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
B,C,A=map(int,input().split())
print(A,B,C)
``` | instruction | 0 | 25,345 | 5 | 50,690 |
Yes | output | 1 | 25,345 | 5 | 50,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
x, y, z = (i for i in input().split())
print(z, x, y)
``` | instruction | 0 | 25,346 | 5 | 50,692 |
Yes | output | 1 | 25,346 | 5 | 50,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
a, b, c = list(input().split())
print(c+' '+a+' '+b)
``` | instruction | 0 | 25,347 | 5 | 50,694 |
Yes | output | 1 | 25,347 | 5 | 50,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
X,Y,Z = map(int, input().split())
print(Z,X,Y,sep = ' ')
``` | instruction | 0 | 25,348 | 5 | 50,696 |
Yes | output | 1 | 25,348 | 5 | 50,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
l = input()
m = input()
z = l.split(' ')
M = int(z[1])
N = int(z[0])
C = (1/(4*M))*N
F = m.split(' ')
X = []
print("No")
for item in F:
votes = int(item)
X.append(votes)
X.sort(reverse = True)
for i in range(M):
if X[i]<C:
print("No")
return
print("Yes")
``` | instruction | 0 | 25,349 | 5 | 50,698 |
No | output | 1 | 25,349 | 5 | 50,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
def solution(X, Y, Z):
return Z, X, Y
``` | instruction | 0 | 25,350 | 5 | 50,700 |
No | output | 1 | 25,350 | 5 | 50,701 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
# N：全種類数、M：今回種類数
N,M = map(int, input().split())
# 得票数
hyou = list(map(int, input().split()))
# 総得票数
total_hyou = 0
for i in hyou:
total_hyou += i
# 得票数基準クリア数
count = 0
border = int(total_hyou/(4*M))
for j in hyou:
if j >= border:
count += 1
# 人気商品をM個選べるかどうか
if count >= M:
print('Yes')
else:
print('No')
``` | instruction | 0 | 25,351 | 5 | 50,702 |
No | output | 1 | 25,351 | 5 | 50,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have three boxes A, B, and C, each of which contains an integer.
Currently, the boxes A, B, and C contain the integers X, Y, and Z, respectively.
We will now do the operations below in order. Find the content of each box afterward.
* Swap the contents of the boxes A and B
* Swap the contents of the boxes A and C
Constraints
* 1 \leq X,Y,Z \leq 100
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X Y Z
Output
Print the integers contained in the boxes A, B, and C, in this order, with space in between.
Examples
Input
1 2 3
Output
3 1 2
Input
100 100 100
Output
100 100 100
Input
41 59 31
Output
31 41 59
Submitted Solution:
```
def main():
x,y,z = map(int, input().split())
print(z,y,y)
if __name__ == '__main__':
main()
``` | instruction | 0 | 25,352 | 5 | 50,704 |
No | output | 1 | 25,352 | 5 | 50,705 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,369 | 5 | 50,738 |
"Correct Solution:
```
L,R = map(int,(input().split()))
mod = 2019
Min = 2018
for i in range(L,min(L+mod,R)):
for j in range(i+1,min(L+mod,R+1)):
Min = min(i*j%2019,Min)
print(Min)
``` | output | 1 | 25,369 | 5 | 50,739 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,370 | 5 | 50,740 |
"Correct Solution:
```
l,r=map(int,input().split())
a=2019
r=min(l+a,r)
for i in range(l,r):
for j in range(l+1,r+1):
a=min(a,(i*j)%2019)
print(a)
``` | output | 1 | 25,370 | 5 | 50,741 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,371 | 5 | 50,742 |
"Correct Solution:
```
L,R=map(int,input().split())
R=min(R,L+2019)
ans=2019
for i in range(L,R+1):
for j in range(i+1,R+1):
ans=min(ans, (i*j)%2019)
print(ans)
``` | output | 1 | 25,371 | 5 | 50,743 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,372 | 5 | 50,744 |
"Correct Solution:
```
l,r=map(int,input().split())
m=2019
c=m-1
r=min(r,l+m-1)
for i in range(l,r):
for j in range(i+1,r+1):
s=i*j
c=min(c,s%m)
print(c)
``` | output | 1 | 25,372 | 5 | 50,745 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,373 | 5 | 50,746 |
"Correct Solution:
```
L,R = map(int, input().split())
R = min(R, L+2019)
ans = 2018
for i in range(L,R+1):
for j in range(i+1,R+1):
x = (i*j)%2019
ans = min(ans,x)
print(ans)
``` | output | 1 | 25,373 | 5 | 50,747 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,374 | 5 | 50,748 |
"Correct Solution:
```
l, r = map(int, input().split())
if r - l > 2019:
print(0)
else:
print(min([i * j % 2019 for i in range(l, r) for j in range(i+1, r+1)]))
``` | output | 1 | 25,374 | 5 | 50,749 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,375 | 5 | 50,750 |
"Correct Solution:
```
L,R = map(int,input().split())
ans = 2020
for i in range(L,min(L+2019,R)):
for j in range(L+1,min(L+2019,R)+1):
ans = min(ans,i*j%2019)
print(ans)
``` | output | 1 | 25,375 | 5 | 50,751 |
Provide a correct Python 3 solution for this coding contest problem.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20 | instruction | 0 | 25,376 | 5 | 50,752 |
"Correct Solution:
```
l, r=map(int, input().split())
if r-l>672:
p=0
else:
x=[]
for i in range(l, r):
for j in range(i+1, r+1):
x.append((i*j)%2019)
p=min(x)
print(p)
``` | output | 1 | 25,376 | 5 | 50,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
l,r = map(int,input().split())
s = range(l,r+1)[:673]
print(min(i*j%2019 for i in s for j in s if i<j))
``` | instruction | 0 | 25,377 | 5 | 50,754 |
Yes | output | 1 | 25,377 | 5 | 50,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
L, R = map(int, input().split())
if R-L >= 2019:
print (0)
else:
print (min([((i % 2019) * (j % 2019)) % 2019 for i in range(L,R) for j in range(i+1,R+1)]))
``` | instruction | 0 | 25,378 | 5 | 50,756 |
Yes | output | 1 | 25,378 | 5 | 50,757 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
L, R = list(map(int, input().split()))
if R - L >= 2019:
print(0)
else:
l = [i * j % 2019 for i in range(L, R+1) for j in range(i+1, R+1)]
print(min(l))
``` | instruction | 0 | 25,379 | 5 | 50,758 |
Yes | output | 1 | 25,379 | 5 | 50,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
L,R=map(int,input().split())
M=2019;l,r=L%M,R%M
print(0 if R//M-L//M>0 else min(i*j%M for i in range(l,r) for j in range(i+1,r+1)))
``` | instruction | 0 | 25,380 | 5 | 50,760 |
Yes | output | 1 | 25,380 | 5 | 50,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
L, R = map(int,input().split())
ans = 2019
for i in range(L, R):
for j in range(i+1, R+1):
if (ans > i*j % 2019):
ans = i*j % 2019
print(ans)
``` | instruction | 0 | 25,381 | 5 | 50,762 |
No | output | 1 | 25,381 | 5 | 50,763 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
import itertools
def ij(m):
return m[0] < m[1]
def main():
(l, r) = list(map(int, input().split()))
min = 2018
for (i, j) in filter(ij, itertools.product(range(l, r + 1), range(l, r + 1))):
mod = i * j % 2019
if mod <= min:
min = mod
print(min)
if __name__ == "__main__":
main()
``` | instruction | 0 | 25,382 | 5 | 50,764 |
No | output | 1 | 25,382 | 5 | 50,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
MOD = 2019
L, R = list(map(int, input().split()))
if (R - L + 1) >= MOD:
print(0)
baisuu = L // MOD
L = L - baisuu * MOD
R = R - baisuu * MOD
# print(L, R, baisuu)
att = []
for i in range(L, R + 1):
att.append(i % 2019)
att.sort()
print(att[0] * att[1])
``` | instruction | 0 | 25,383 | 5 | 50,766 |
No | output | 1 | 25,383 | 5 | 50,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two non-negative integers L and R. We will choose two integers i and j such that L \leq i < j \leq R. Find the minimum possible value of (i \times j) \mbox{ mod } 2019.
Constraints
* All values in input are integers.
* 0 \leq L < R \leq 2 \times 10^9
Input
Input is given from Standard Input in the following format:
L R
Output
Print the minimum possible value of (i \times j) \mbox{ mod } 2019 when i and j are chosen under the given condition.
Examples
Input
2020 2040
Output
2
Input
4 5
Output
20
Submitted Solution:
```
def main():
l,r = map(int,input().split(' '))
if r-l >= 2019 or l//2019!=r//2019:
print(0)
elif l%2019<r%2019:
print((l*(l+1))%2019)
else:
print((r*(r-1))%2019)
if __name__ == '__main__':
main()
``` | instruction | 0 | 25,384 | 5 | 50,768 |
No | output | 1 | 25,384 | 5 | 50,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given positive integers A and B.
If A is a divisor of B, print A + B; otherwise, print B - A.
Constraints
* All values in input are integers.
* 1 \leq A \leq B \leq 20
Input
Input is given from Standard Input in the following format:
A B
Output
If A is a divisor of B, print A + B; otherwise, print B - A.
Examples
Input
4 12
Output
16
Input
8 20
Output
12
Input
1 1
Output
2
Submitted Solution:
```
a, b = [int(_) for _ in input().split()]
print(a + b if b % a == 0 else b - a)
``` | instruction | 0 | 25,393 | 5 | 50,786 |
Yes | output | 1 | 25,393 | 5 | 50,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given positive integers A and B.
If A is a divisor of B, print A + B; otherwise, print B - A.
Constraints
* All values in input are integers.
* 1 \leq A \leq B \leq 20
Input
Input is given from Standard Input in the following format:
A B
Output
If A is a divisor of B, print A + B; otherwise, print B - A.
Examples
Input
4 12
Output
16
Input
8 20
Output
12
Input
1 1
Output
2
Submitted Solution:
```
a,b=map(int,input().split());print(a+b-2*a*(b%a>0))
``` | instruction | 0 | 25,394 | 5 | 50,788 |
Yes | output | 1 | 25,394 | 5 | 50,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given positive integers A and B.
If A is a divisor of B, print A + B; otherwise, print B - A.
Constraints
* All values in input are integers.
* 1 \leq A \leq B \leq 20
Input
Input is given from Standard Input in the following format:
A B
Output
If A is a divisor of B, print A + B; otherwise, print B - A.
Examples
Input
4 12
Output
16
Input
8 20
Output
12
Input
1 1
Output
2
Submitted Solution:
```
a,b = map(int, input().split())
if b % a:
print(b-a)
else:
print(a+b)
``` | instruction | 0 | 25,395 | 5 | 50,790 |
Yes | output | 1 | 25,395 | 5 | 50,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given positive integers A and B.
If A is a divisor of B, print A + B; otherwise, print B - A.
Constraints
* All values in input are integers.
* 1 \leq A \leq B \leq 20
Input
Input is given from Standard Input in the following format:
A B
Output
If A is a divisor of B, print A + B; otherwise, print B - A.
Examples
Input
4 12
Output
16
Input
8 20
Output
12
Input
1 1
Output
2
Submitted Solution:
```
a,b = input()
if b%a ==0:
print(a+b)
else:
print(b-a)
``` | instruction | 0 | 25,397 | 5 | 50,794 |
No | output | 1 | 25,397 | 5 | 50,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given positive integers A and B.
If A is a divisor of B, print A + B; otherwise, print B - A.
Constraints
* All values in input are integers.
* 1 \leq A \leq B \leq 20
Input
Input is given from Standard Input in the following format:
A B
Output
If A is a divisor of B, print A + B; otherwise, print B - A.
Examples
Input
4 12
Output
16
Input
8 20
Output
12
Input
1 1
Output
2
Submitted Solution:
```
a=int(input('>>'))
b=int(input('>>'))
if b%a==0:
print(a+b)
else:
print(b-a)
``` | instruction | 0 | 25,399 | 5 | 50,798 |
No | output | 1 | 25,399 | 5 | 50,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given positive integers A and B.
If A is a divisor of B, print A + B; otherwise, print B - A.
Constraints
* All values in input are integers.
* 1 \leq A \leq B \leq 20
Input
Input is given from Standard Input in the following format:
A B
Output
If A is a divisor of B, print A + B; otherwise, print B - A.
Examples
Input
4 12
Output
16
Input
8 20
Output
12
Input
1 1
Output
2
Submitted Solution:
```
a,b=map(int,input().split())
print(a-b if b%a>0 else a+b)
``` | instruction | 0 | 25,400 | 5 | 50,800 |
No | output | 1 | 25,400 | 5 | 50,801 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an integer sequence of length N. The i-th term in the sequence is a_i. In one operation, you can select a term and either increment or decrement it by one.
At least how many operations are necessary to satisfy the following conditions?
* For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.
* For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.
Constraints
* 2 ≤ n ≤ 10^5
* |a_i| ≤ 10^9
* Each a_i is an integer.
Input
Input is given from Standard Input in the following format:
n
a_1 a_2 ... a_n
Output
Print the minimum necessary count of operations.
Examples
Input
4
1 -3 1 0
Output
4
Input
5
3 -6 4 -5 7
Output
0
Input
6
-1 4 3 2 -5 4
Output
8 | instruction | 0 | 25,439 | 5 | 50,878 |
"Correct Solution:
```
N = int(input())
A = [int(i) for i in input().split()]
mi = 1e20
for sign in [-1, 1]:
res, acc = 0, 0
for a in A:
acc += a
if sign * acc <= 0:
res += abs(acc - sign)
acc = sign
sign *= -1
mi = min(mi, res)
print(mi)
``` | output | 1 | 25,439 | 5 | 50,879 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an integer sequence of length N. The i-th term in the sequence is a_i. In one operation, you can select a term and either increment or decrement it by one.
At least how many operations are necessary to satisfy the following conditions?
* For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.
* For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.
Constraints
* 2 ≤ n ≤ 10^5
* |a_i| ≤ 10^9
* Each a_i is an integer.
Input
Input is given from Standard Input in the following format:
n
a_1 a_2 ... a_n
Output
Print the minimum necessary count of operations.
Examples
Input
4
1 -3 1 0
Output
4
Input
5
3 -6 4 -5 7
Output
0
Input
6
-1 4 3 2 -5 4
Output
8 | instruction | 0 | 25,440 | 5 | 50,880 |
"Correct Solution:
```
n = int(input())
a = [int(x) for x in input().split()]
def check(a, t):
ans = 0
x = 0
for i in a:
x += i
if t == True and x < 1:
ans += 1 - x
x = 1
elif t == False and x > -1:
ans += x + 1
x = -1
t = not t
return ans
print(min(check(a, True), check(a, False)))
``` | output | 1 | 25,440 | 5 | 50,881 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an integer sequence of length N. The i-th term in the sequence is a_i. In one operation, you can select a term and either increment or decrement it by one.
At least how many operations are necessary to satisfy the following conditions?
* For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.
* For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.
Constraints
* 2 ≤ n ≤ 10^5
* |a_i| ≤ 10^9
* Each a_i is an integer.
Input
Input is given from Standard Input in the following format:
n
a_1 a_2 ... a_n
Output
Print the minimum necessary count of operations.
Examples
Input
4
1 -3 1 0
Output
4
Input
5
3 -6 4 -5 7
Output
0
Input
6
-1 4 3 2 -5 4
Output
8 | instruction | 0 | 25,441 | 5 | 50,882 |
"Correct Solution:
```
input()
l=list(map(int,input().split()))
def f(s):
c=t=0
for i in l:
t+=i
if s*t<=0: c+=abs(t-s); t=s
s*=-1
return c
print(min(f(1),f(-1)))
``` | output | 1 | 25,441 | 5 | 50,883 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an integer sequence of length N. The i-th term in the sequence is a_i. In one operation, you can select a term and either increment or decrement it by one.
At least how many operations are necessary to satisfy the following conditions?
* For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.
* For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.
Constraints
* 2 ≤ n ≤ 10^5
* |a_i| ≤ 10^9
* Each a_i is an integer.
Input
Input is given from Standard Input in the following format:
n
a_1 a_2 ... a_n
Output
Print the minimum necessary count of operations.
Examples
Input
4
1 -3 1 0
Output
4
Input
5
3 -6 4 -5 7
Output
0
Input
6
-1 4 3 2 -5 4
Output
8 | instruction | 0 | 25,442 | 5 | 50,884 |
"Correct Solution:
```
N=int(input())
A=list(map(int,input().split()))
ans=[0]*2
for pat in range(2):
cur=0
isplus=pat
for i in range(N):
cur+=A[i]
if isplus:
if cur<=0:
ans[pat]+=abs(cur-1)
cur=1
else:
if cur>=0:
ans[pat]+=abs(cur-(-1))
cur=-1
isplus^=1
print(min(ans))
``` | output | 1 | 25,442 | 5 | 50,885 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an integer sequence of length N. The i-th term in the sequence is a_i. In one operation, you can select a term and either increment or decrement it by one.
At least how many operations are necessary to satisfy the following conditions?
* For every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.
* For every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.
Constraints
* 2 ≤ n ≤ 10^5
* |a_i| ≤ 10^9
* Each a_i is an integer.
Input
Input is given from Standard Input in the following format:
n
a_1 a_2 ... a_n
Output
Print the minimum necessary count of operations.
Examples
Input
4
1 -3 1 0
Output
4
Input
5
3 -6 4 -5 7
Output
0
Input
6
-1 4 3 2 -5 4
Output
8 | instruction | 0 | 25,443 | 5 | 50,886 |
"Correct Solution:
```
def main():
n = input()
a_s = list(map(int, input().split()))
ans = 10 ** 20
for i in [-1, 1]:
total = 0
op_num = 0
for a_i in a_s:
total += a_i
if total * i <= 0:
op_num += abs(total - i)
total = i
i *= -1
ans = min(ans, op_num)
print(ans)
main()
``` | output | 1 | 25,443 | 5 | 50,887 |
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