message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:( | instruction | 0 | 21,853 | 9 | 43,706 |
"Correct Solution:
```
A,B=input().split()
if int(A)<=8 and int(B)<=8:
print("Yay!")
else:
print( ":(")
``` | output | 1 | 21,853 | 9 | 43,707 |
Provide a correct Python 3 solution for this coding contest problem.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:( | instruction | 0 | 21,854 | 9 | 43,708 |
"Correct Solution:
```
print(["Yay!", ":(", ":("][sum([int(x) > 8 for x in input().split()])])
``` | output | 1 | 21,854 | 9 | 43,709 |
Provide a correct Python 3 solution for this coding contest problem.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:( | instruction | 0 | 21,855 | 9 | 43,710 |
"Correct Solution:
```
print(["Yay!", ":("][not(max(map(int, input().split()))<=8)])
``` | output | 1 | 21,855 | 9 | 43,711 |
Provide a correct Python 3 solution for this coding contest problem.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:( | instruction | 0 | 21,856 | 9 | 43,712 |
"Correct Solution:
```
A,B = map(int,input().split())
print('Yay!') if A<= 8 and B <= 8 else print(':(')
``` | output | 1 | 21,856 | 9 | 43,713 |
Provide a correct Python 3 solution for this coding contest problem.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:( | instruction | 0 | 21,857 | 9 | 43,714 |
"Correct Solution:
```
A, B = map(int,input().split())
if max(A,B)<=8:
print('Yay!')
exit()
print(':(')
``` | output | 1 | 21,857 | 9 | 43,715 |
Provide a correct Python 3 solution for this coding contest problem.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:( | instruction | 0 | 21,858 | 9 | 43,716 |
"Correct Solution:
```
a, b = map(int, input().split())
print('Yay!') if(a < 9 and b < 9) else print(':(')
``` | output | 1 | 21,858 | 9 | 43,717 |
Provide a correct Python 3 solution for this coding contest problem.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:( | instruction | 0 | 21,859 | 9 | 43,718 |
"Correct Solution:
```
a,b=map(int,input().split())
if abs(a-b)>2:
print(':(')
else:
print('Yay!')
``` | output | 1 | 21,859 | 9 | 43,719 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
a,b=map(int,input().split())
if (a<9)&(b<9):
print("Yay!")
else:
print(":(")
``` | instruction | 0 | 21,860 | 9 | 43,720 |
Yes | output | 1 | 21,860 | 9 | 43,721 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
a, b = map(int,input().split())
print('Yay!') if a <= 8 and b <= 8 else print(':(')
``` | instruction | 0 | 21,861 | 9 | 43,722 |
Yes | output | 1 | 21,861 | 9 | 43,723 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
print([':(','Yay!'][all(i<9 for i in map(int,input().split()))])
``` | instruction | 0 | 21,862 | 9 | 43,724 |
Yes | output | 1 | 21,862 | 9 | 43,725 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
a, b = map(int, input().split())
print('Yay!' if max(a, b) <= 8 else ':(')
``` | instruction | 0 | 21,863 | 9 | 43,726 |
Yes | output | 1 | 21,863 | 9 | 43,727 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
#coding:utf-8
A,B = list(map(int, input().split()))
if A > 8 or B > 8:
print(":(")
else:
print("Yey!")
``` | instruction | 0 | 21,864 | 9 | 43,728 |
No | output | 1 | 21,864 | 9 | 43,729 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
A, B = map(int, raw_input().split())
if A <= 8 and B <= 8:
print('Yay!')
else:
print(':(')
``` | instruction | 0 | 21,865 | 9 | 43,730 |
No | output | 1 | 21,865 | 9 | 43,731 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
A,B = map(int,input().split())
print(['Yay!',':('][A>8 and B>8])
``` | instruction | 0 | 21,866 | 9 | 43,732 |
No | output | 1 | 21,866 | 9 | 43,733 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
E869120's and square1001's 16-th birthday is coming soon.
Takahashi from AtCoder Kingdom gave them a round cake cut into 16 equal fan-shaped pieces.
E869120 and square1001 were just about to eat A and B of those pieces, respectively,
when they found a note attached to the cake saying that "the same person should not take two adjacent pieces of cake".
Can both of them obey the instruction in the note and take desired numbers of pieces of cake?
Constraints
* A and B are integers between 1 and 16 (inclusive).
* A+B is at most 16.
Input
Input is given from Standard Input in the following format:
A B
Output
If both E869120 and square1001 can obey the instruction in the note and take desired numbers of pieces of cake, print `Yay!`; otherwise, print `:(`.
Examples
Input
5 4
Output
Yay!
Input
8 8
Output
Yay!
Input
11 4
Output
:(
Submitted Solution:
```
a,b = list(map(int, input().split()))
for i in range(16):
if i % 2 == 0:
if a > 0:
a -= 1
else:
print(":(")
break
else:
if b > 0:
b -= 1
else:
print(":(")
break
if a == 0 and b == 0:
print("Yay!")
break
``` | instruction | 0 | 21,867 | 9 | 43,734 |
No | output | 1 | 21,867 | 9 | 43,735 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,021 | 9 | 44,042 |
Tags: *special, dp
Correct Solution:
```
#Tanya and Colored Candies Mail.Ru Cup 2018 - Practice Round
import sys
sys.setrecursionlimit(1000)
def rec(r, c, s, K, k, dp):
#Previous Case:
if (k, s) in dp:
return dp[(k, s)]
#Base Case:
if k <= 0:
return 0
#Recursive Cases:
n = len(r)
besttime = 10**10
for i in range(n): #Boxes are in position 0-n-1
if ( (r[i] > r[s]) and (c[i] != c[s]) ) or (k == K):
timetakenbelow = rec(r, c, i, K, k-r[i], dp)
timetaken = timetakenbelow + abs(s-i)
if timetaken < besttime:
besttime = timetaken
#Store and Return
dp[(k, s)] = besttime
return besttime
def answer(n, s, K, r, c):
dp = dict()
#k = candies remaining
k = K
ans = rec(r, c, s, K, k, dp)
if ans == 10**10:
return -1
return ans
def main():
n, s, K = map(int, sys.stdin.readline().split())
r = tuple(map(int, sys.stdin.readline().split()))
c = sys.stdin.readline().rstrip()
print(answer(n, s-1, K, r, c))
return
main()
``` | output | 1 | 22,021 | 9 | 44,043 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,022 | 9 | 44,044 |
Tags: *special, dp
Correct Solution:
```
n,s,k=map(int,input().split())
r=list(map(int,input().split()))
s-=1
c=input()
best=[[0 for i in range(n)] for j in range(k+1)]
for i in range(1,k+1):
for j in range(n):
if i<=r[j]:
best[i][j]=abs(j-s)
else:
good=float("inf")
for l in range(n):
if c[j]!=c[l] and r[j]>r[l]:
good=min(good,best[i-r[j]][l]+abs(j-l))
best[i][j]=good
if min(best[-1])==float('inf'):
print(-1)
else:
print(min(best[-1]))
``` | output | 1 | 22,022 | 9 | 44,045 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,023 | 9 | 44,046 |
Tags: *special, dp
Correct Solution:
```
INF = 1e10
max_n = 50
max_k = 2000
def main():
n, s, k = map(int, input().split())
s -= 1
buf = ['']*(max_n + 1)
dp = [[0 for i in range(max_n + 1)] for j in range(max_k + 1)]
r = list(map(int, input().split()))
c = input()
answer = INF
for i in range(len(c)):
buf[i] = c[i]
for i in range(k, -1, -1):
for j in range(n):
dp[i][j] = INF
for j in range(n):
value = abs(j - s)
if k - r[j] <= 0:
answer = min(answer, value)
else:
dp[k - r[j]][j] = value
for i in range(k, 0, -1):
for j in range(n):
if dp[i][j] < INF:
for l in range(n):
if buf[j] != buf[l] and r[j] < r[l]:
value = dp[i][j] + abs(j - l)
if i - r[l] <= 0:
answer = min(answer, value)
else:
dp[i - r[l]][l] = min(dp[i - r[l]][l], value)
if answer == INF:
print(-1)
return
print(answer)
if __name__=="__main__":
main()
``` | output | 1 | 22,023 | 9 | 44,047 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,024 | 9 | 44,048 |
Tags: *special, dp
Correct Solution:
```
'''input
2 1 15
5 6
RG
'''
import math
def solve():
n,s,k = map(int,input().split())
s-=1
r = list(map(int,input().split()))
c = input()
inf = int(1e9)
dp = [[inf for j in range(n)] for i in range(k+1)]
# dp[i][j] = minimum number of steps to get amount i if we start with jth index
for i in range(0,k+1):
for j in range(0,n):
if i==0 or i<=r[j]:
dp[i][j] = 0
continue
for K in range(0,n):
if c[K]!=c[j] and r[K]>r[j]:
dp[i][j] = min(dp[i][j],dp[i-r[j]][K]+int(abs(K-j)))
ans = min(dp[k][i]+abs(i-s) for i in range(0,n))
if ans>=inf:
print(-1)
return
print(ans)
return
t = 1
#t = int(input())
while t>0:
t-=1
solve()
``` | output | 1 | 22,024 | 9 | 44,049 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,025 | 9 | 44,050 |
Tags: *special, dp
Correct Solution:
```
INF = 10e9
n,s,k = map(int, input().split())
r = list(map(int, input().split()))
r.append(0)
col = input()
mat = []
for i in range(n+1):
adj = {}
for j in range(n):
if i == n:
adj[j] = abs((s-1)-j)
else:
if col[i] != col[j] and r[i] < r[j]:
adj[j] = abs(i-j)
mat.append(adj)
# print(*mat, sep='\n')
mem = [{} for i in range(n+1)]
# print(mem)
def get(s, k):
# print(s,k)
# print(mem)
if mem[s].get(k):
return mem[s].get(k)
if r[s] >= k:
mem[s][k] = 0
else:
mi = None
for nei in mat[s]:
ncost = get(nei, k-r[s])
if ncost is None:
continue
curr = ncost + mat[s][nei]
if mi is None or curr < mi:
mi = curr
if mi is not None:
mem[s][k] = mi
else:
mem[s][k] = INF
return mem[s].get(k)
# print(mem)
ans = get(n,k)
if ans is None or ans >= INF:
print(-1)
else:
print(ans)
``` | output | 1 | 22,025 | 9 | 44,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,026 | 9 | 44,052 |
Tags: *special, dp
Correct Solution:
```
n, s, k = map(int, input().split())
s -= 1
r = list(map(int, input().split()))
INF = float("inf")
c = input()
dp = [[] for i in range(n)]
def calc(u):
if dp[u]:
return
dp[u] = [0] * (r[u] + 1) + [INF] * (k - r[u])
for i in range(n):
if c[u] != c[i] and r[i] > r[u]:
calc(i)
d = abs(u - i)
for j in range(r[u] + 1, k + 1):
dp[u][j] = min(dp[u][j], dp[i][j - r[u]] + d)
ans = INF
for i in range(n):
calc(i)
ans = min(ans, abs(i - s) + dp[i][k])
if ans == INF:
print(-1)
else:
print(ans)
``` | output | 1 | 22,026 | 9 | 44,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,027 | 9 | 44,054 |
Tags: *special, dp
Correct Solution:
```
import sys
def minp():
return sys.stdin.readline().strip()
dp = [None]*50
for j in range(50):
dp[j] = [None]*2001
n,s,k = map(int,minp().split())
a = [None]*n
i = 0
s -= 1
for j in map(int,minp().split()):
a[i] = (j, i)
i += 1
i = 0
for j in minp():
a[i] += ("RGB".find(j),)
i += 1
a.sort()
r = 10**18
zzz = 0
for i in range(n):
ii = dp[i]
c = a[i][0]
ii[c] = abs(s-a[i][1])
#print(ii[c])
for j in range(i):
if a[j][2] == a[i][2] or a[j][0] == a[i][0]:
continue
jj = dp[j]
for z in range(2001-c):
zz = jj[z]
if zz != None:
d = zz + abs(a[i][1]-a[j][1])
cc = z+c
if ii[cc] != None:
if ii[cc] > d:
ii[cc] = d
else:
ii[cc] = d
for z in range(k,2001):
if ii[z] != None:
r = min(r,ii[z])
#print(ii[:k+1])
if r != 10**18:
print(r)
else:
print(-1)
``` | output | 1 | 22,027 | 9 | 44,055 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds. | instruction | 0 | 22,028 | 9 | 44,056 |
Tags: *special, dp
Correct Solution:
```
n, s, k = list(map(int, input().split()))
amounts = list(map(int, input().split()))
colors = list(input())
dp = [[-1 for j in range(k + 1)] for i in range(n)]
def getAns(nth, left):
if left <= 0:
return 0
if dp[nth][left] >= 0:
return dp[nth][left]
ret = 999999999
for i in range(n):
if amounts[i] <= amounts[nth] or colors[i] == colors[nth]:
continue
ret = min(ret, abs(nth - i) + getAns(i, left - amounts[i]))
dp[nth][left] = ret
return ret
ans = 999999999
for i in range(n):
ans = min(ans, getAns(i, k - amounts[i]) + abs(s - 1 - i))
if ans == 999999999:
ans = -1
print(ans)
``` | output | 1 | 22,028 | 9 | 44,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds.
Submitted Solution:
```
INF = 100000
n,s,k=map(int,input().split())
r = list(map(int,input().split()))
c = input().rstrip()
#dp[i][j]: i = the current position just after eating candies, j = remaining candies to eat
dp = [[INF for j in range(k+1)] for i in range(n)]
s -= 1
for i in range(n):
dp[i][k-r[i]] = abs(s-i)
for j in range(k,-1,-1):
for i in range(n):
if dp[i][j] >= INF: continue
for f in range(n):
if r[f] <= r[i]: continue
if c[f] == c[i]: continue
new_val = max(0, j-r[f])
dp[f][new_val] = min(dp[f][new_val], dp[i][j] + abs(i-f))
ans = INF
for i in range(n):
ans = min(ans, dp[i][0])
if ans >= INF:
ans = -1
print(ans)
``` | instruction | 0 | 22,029 | 9 | 44,058 |
Yes | output | 1 | 22,029 | 9 | 44,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds.
Submitted Solution:
```
inf = 10000
n, s, k = map(int, input().split())
a = list(map(int, input().split()))
b = list(input())
for i in range(n):
if b[i] == 'R':
b[i] = 0
elif b[i] == 'G':
b[i] = 1
else:
b[i] = 2
boxes = [[a[i], b[i], i] for i in range(n)]
boxes.sort()
l = boxes[-1][0] * n + 1
s -= 1
dp = [[[inf, s, -1] for j in range(l)] for i in range(3)]
if l < k:
print(-1)
exit(0)
dp[0][0][0] = 0
dp[1][0][0] = 0
dp[2][0][0] = 0
for i in range(n):
pos = boxes[i][2]
clr = boxes[i][1]
cnt = boxes[i][0]
for j in range(l - cnt):
for c in range(3):
if c == clr:
continue
if dp[clr][j + cnt][0] > dp[c][j][0] + abs(dp[c][j][1] - pos) and cnt > dp[c][j][2]:
dp[clr][j + cnt][0] = dp[c][j][0] + abs(dp[c][j][1] - pos)
dp[clr][j + cnt][1] = pos
dp[clr][j + cnt][2] = cnt
ans = min(dp[0][k][0], min(dp[1][k][0], dp[2][k][0]))
for i in range(k, l):
ans = min(min(ans, dp[0][i][0]), min(dp[1][i][0], dp[2][i][0]))
if ans < inf:
print(ans)
else:
print(-1)
``` | instruction | 0 | 22,030 | 9 | 44,060 |
Yes | output | 1 | 22,030 | 9 | 44,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds.
Submitted Solution:
```
from functools import reduce
input1 = list(map(int, input().split(' ')))
n = input1[0];
s = input1[1] - 1;
k = input1[2];
arr = list(map(int, input().split(' ')))
arrC = input()
def minTime(eatenCandys, lastPos, pos, arrCurr, t, eat):
t += abs(pos - lastPos)
arrCpy = arrCurr.copy()
if eat:
arrCpy[pos] = 0
eatenCandys += arrCurr[pos]
if(eatenCandys >= k):
return t
return reduce(lambda x, a: x if x != None and (a == None or x < a) else a,
map(lambda x: minTime(eatenCandys, pos, x, arrCpy, t, True),
filter(lambda x: arrCpy[x] > 0 and x != pos and (not eat or (arrCpy[x] > arrCurr[pos] and arrC[x] != arrC[pos])), range(0, n))),
None)
a = -1
for x in list(map(lambda b: minTime(0, s, s, arr, 0, b), [True, False])):
if x and (a == -1 or x < a):
a = x
print(a);
``` | instruction | 0 | 22,031 | 9 | 44,062 |
No | output | 1 | 22,031 | 9 | 44,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds.
Submitted Solution:
```
from typing import List
boxes_count, start_pos, target_candy_count = (int(val) for val in input().split())
candy_in_boxes_count = [int(val) for val in input().split()]
candy_in_boxes_colors = list(input())
#eated_candy = 0
#spented_time = 0
#current_pos = start_pos
#current_candy_color = candy_in_boxes_colors[current_pos]
def eat_candy(current_pos:int, candy_left: int, candy_in_boxes_count: List[int]) -> int:
#print(current_pos, candy_left, candy_in_boxes_count)
current_candy_count = candy_in_boxes_count[current_pos]
candy_left = candy_left - current_candy_count
candy_in_boxes_count[current_pos] = 0
if candy_left <= 0:
return 0
spended_time_min = -1
#print(current_candy_count, candy_in_boxes_count)
for box_idx in range(boxes_count):
if candy_in_boxes_count[box_idx] > current_candy_count and candy_in_boxes_colors[box_idx] != candy_in_boxes_colors[current_pos]:
candy_in_boxes_count_tmp = candy_in_boxes_count.copy()
spended_time = eat_candy(box_idx, candy_left, candy_in_boxes_count_tmp)
if spended_time != -1:
spended_time = spended_time + abs(box_idx - current_pos)
if spended_time_min == -1 or spended_time_min > spended_time:
spended_time_min = spended_time
#print(spended_time_min, candy_in_boxes_count)
return spended_time_min
spended_time_min = -1
for box_idx in range(boxes_count):
spended_time = eat_candy(box_idx, target_candy_count, candy_in_boxes_count)
if spended_time != -1:
spended_time = spended_time + abs(box_idx - (start_pos - 1))
if spended_time_min == -1 or spended_time_min > spended_time:
spended_time_min = spended_time
print(spended_time_min)
``` | instruction | 0 | 22,032 | 9 | 44,064 |
No | output | 1 | 22,032 | 9 | 44,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds.
Submitted Solution:
```
from functools import reduce
input1 = list(map(int, input().split(' ')))
n = input1[0];
s = input1[1] - 1;
k = input1[2];
arr = list(map(int, input().split(' ')))
arrC = input()
def minTime(eatenCandys, lastPos, pos, arrCurr, t, eat):
t += abs(pos - lastPos)
arrCpy = arrCurr.copy()
if eat:
arrCpy[pos] = 0
eatenCandys += arrCurr[pos]
if(eatenCandys >= k):
return t
return reduce(lambda x, a: x if x != None and (a == None or x < a) else a,
map(lambda x: minTime(eatenCandys, pos, x, arrCpy, t, True),
filter(lambda x: arrCpy[x] > 0 and x != pos and (not eat or (arrCpy[x] > arrCurr[pos] and arrC[x] != arrC[pos])), range(0, n))),
None)
print(reduce(lambda x, a: x if x and (a == None or x < a) else a, list(map(lambda b: minTime(0, s, s, arr, 0, b), [True, False])), None) or -1);
``` | instruction | 0 | 22,033 | 9 | 44,066 |
No | output | 1 | 22,033 | 9 | 44,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n candy boxes in front of Tania. The boxes are arranged in a row from left to right, numbered from 1 to n. The i-th box contains r_i candies, candies have the color c_i (the color can take one of three values — red, green, or blue). All candies inside a single box have the same color (and it is equal to c_i).
Initially, Tanya is next to the box number s. Tanya can move to the neighbor box (that is, with a number that differs by one) or eat candies in the current box. Tanya eats candies instantly, but the movement takes one second.
If Tanya eats candies from the box, then the box itself remains in place, but there is no more candies in it. In other words, Tanya always eats all the candies from the box and candies in the boxes are not refilled.
It is known that Tanya cannot eat candies of the same color one after another (that is, the colors of candies in two consecutive boxes from which she eats candies are always different). In addition, Tanya's appetite is constantly growing, so in each next box from which she eats candies, there should be strictly more candies than in the previous one.
Note that for the first box from which Tanya will eat candies, there are no restrictions on the color and number of candies.
Tanya wants to eat at least k candies. What is the minimum number of seconds she will need? Remember that she eats candies instantly, and time is spent only on movements.
Input
The first line contains three integers n, s and k (1 ≤ n ≤ 50, 1 ≤ s ≤ n, 1 ≤ k ≤ 2000) — number of the boxes, initial position of Tanya and lower bound on number of candies to eat. The following line contains n integers r_i (1 ≤ r_i ≤ 50) — numbers of candies in the boxes. The third line contains sequence of n letters 'R', 'G' and 'B', meaning the colors of candies in the correspondent boxes ('R' for red, 'G' for green, 'B' for blue). Recall that each box contains candies of only one color. The third line contains no spaces.
Output
Print minimal number of seconds to eat at least k candies. If solution doesn't exist, print "-1".
Examples
Input
5 3 10
1 2 3 4 5
RGBRR
Output
4
Input
2 1 15
5 6
RG
Output
-1
Note
The sequence of actions of Tanya for the first example:
* move from the box 3 to the box 2;
* eat candies from the box 2;
* move from the box 2 to the box 3;
* eat candy from the box 3;
* move from the box 3 to the box 4;
* move from the box 4 to the box 5;
* eat candies from the box 5.
Since Tanya eats candy instantly, the required time is four seconds.
Submitted Solution:
```
n,s,k=map(int,input().split())
r=list(map(int,input().split()))
color=input()
good=[]
newlist=[-1000000]*n
newlist[s-1]=r[s-1]
good.append(newlist)
done=False
while not done:
newlist=[]
for i in range(n):
best=-1000000
for j in range(n):
if abs(j-i)<=len(good) and r[i]>r[j] and not color[i]==color[j]:
best=max(best,good[-abs(i-j)][j]+r[i])
if best>=k and done==False:
print(len(good))
done=True
if abs(i-s+1)==len(good):
best=max(best,r[i])
newlist.append(best)
good.append(newlist)
if len(good)>1275:
print(-1)
done=True
``` | instruction | 0 | 22,034 | 9 | 44,068 |
No | output | 1 | 22,034 | 9 | 44,069 |
Provide a correct Python 3 solution for this coding contest problem.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3 | instruction | 0 | 22,625 | 9 | 45,250 |
"Correct Solution:
```
h,w,k = map(int,input().split())
choco = []
mcut = h+w
for i in range(h):
choco.append(list(map(int,list(input()))))
for i in range(2**(h-1)):
chocos = []
cut = 0
choco1 = choco[0][:]
for j in range(h-1):
if i >> j & 1:
chocos.append(choco1)
choco1 = choco[j+1][:]
cut += 1
else:
for l in range(w):
choco1[l] += choco[j+1][l]
chocos.append(choco1)
num = len(chocos)
chocosum = [0 for _ in range(num)]
flag = True
for j in range(w):
for l in range(num):
if chocos[l][j] > k:
flag = False
chocosum[l] += chocos[l][j]
if chocosum[l] > k:
cut += 1
chocosum = [chocos[_][j] for _ in range(num)]
break
if flag:
mcut = min(cut,mcut)
print(mcut)
``` | output | 1 | 22,625 | 9 | 45,251 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
h,w,kk=map(int,input().split())
G=[[0]*w for i in range(h)]
for i in range(h):
G[i]=list(input())
for i in range(h):
for j in range(w):
G[i][j]=int(G[i][j])
ans=10**5
for i in range(2**(h-1)):
s=format(i,'12b')
A=[-1]
for j in range(h-1):
if s[-1-j]=="1":
A.append(j)
A.append(h-1)
ans1=len(A)-2
B=[0]*(len(A)-1)
c=0
i=0
while i<w:
j=0
while j<len(A)-1:
for k in range(A[j]+1,A[j+1]+1):
B[j]+=G[k][i]
if B[j]>kk:
c=c+1
B=[0]*(len(A)-1)
j=0
if c>1010:
j=100
i=10000
else:
j=j+1
i=i+1
if ans1+c<ans:
ans=ans1+c
print(ans)
``` | instruction | 0 | 22,626 | 9 | 45,252 |
Yes | output | 1 | 22,626 | 9 | 45,253 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
def main():
import sys
input=sys.stdin.readline
h,w,k=map(int,input().split())
S=[]
for _ in range(h):
s=list(map(int,list(input().rstrip())))
S.append(s)
ans=10**5
for i in range(2**(h-1)):
l=[0]
for j in range(h-1):
if i&1<<j:
l.append(l[-1]+1)
else:
l.append(l[-1])
ans_=l[-1]
ll=[0]*h
j=0
flag=0
while j<w:
for p in range(h):
ll[l[p]]+=S[p][j]
if max(ll)>k and flag==0:
flag=1
ans_+=1
ll=[0]*h
elif max(ll)>k and flag==1:
ans_=10**5
break
else:
j+=1
flag=0
ans=min(ans,ans_)
print(ans)
if __name__ == '__main__':
main()
``` | instruction | 0 | 22,627 | 9 | 45,254 |
Yes | output | 1 | 22,627 | 9 | 45,255 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
H, W, K = map(int, input().split())
S = [list(input()) for _ in range(H)]
res = float('inf')
for i in range(2**(H-1)):
c = bin(i).count('1')
cnt = c
sum_l = [0] * (c+1)
j = 0
flag = True
while j < W:
tmp = sum_l.copy()
pos = 0
for k in range(H):
if S[k][j] == '1':
tmp[pos] += 1
if (i >> k) & 1:
pos += 1
if max(tmp) <= K:
sum_l = tmp.copy()
j += 1
flag = False
else:
if flag:
cnt = float('inf')
break
cnt += 1
flag = True
sum_l = [0] * (c+1)
res = min(res, cnt)
print(res)
``` | instruction | 0 | 22,628 | 9 | 45,256 |
Yes | output | 1 | 22,628 | 9 | 45,257 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
h,w,k = list(map(int,input().split())); arr = [[int(i) for i in input()] for _ in range(h)]
from itertools import product
ans = 2000
for cond in product([True,False],repeat=(h-1)):
cut = sum(cond); div = 0
splits = [0] * (cut+1); splits[0] = arr[0][:]
for i in range(1,h):
if cond[i-1]:
div += 1
splits[div] = arr[i][:]
else:
splits[div] = [splits[div][j]+arr[i][j] for j in range(w)]
check = [max(i) for i in splits]
if max(check) > k:
break
count = [i[0] for i in splits]
for j in range(1,w):
addarr = [count[i]+splits[i][j] for i in range(cut+1)]
if max(addarr) > k:
div += 1
count = [splits[i][j] for i in range(cut+1)]
else:
count = addarr[:]
ans = min(ans,div)
print(ans)
``` | instruction | 0 | 22,629 | 9 | 45,258 |
Yes | output | 1 | 22,629 | 9 | 45,259 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
def bit(n, k):
return ((n>>k) & 1);
n, m, k = (int(i) for i in input().split());
f = [input() for i in range(n)];
#print(len(f[0]));
res = (n - 1) * (m - 1);
# for mask in range(2 ** (n - 1)):
# cnt = [0 for i in range(n)];
# curr = 0;
# for i in range(n):
# curr += bit(mask, i);
# for i in range(m):
# add = [0 for t in range(n)];
# ind = 0;
# for j in range(n):
# #print(i, j);
# add[ind] += int(f[j][i]);
# #add[ind] = 1;
# if bit(mask, j) == 1:
# ind += 1;
#
# correct = True;
# for j in range(n):
# if add[j] + cnt[j] > k:
# correct = False;
#
# if correct == True:
# for j in range(n):
# cnt[j] += add[j];
# continue;
# curr += 1;
# for j in range(n):
# cnt[j] = add[j];
# res = min(res, curr);
print(res);
``` | instruction | 0 | 22,630 | 9 | 45,260 |
No | output | 1 | 22,630 | 9 | 45,261 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
def main():
H,W,K = map(int,input().split())
S = [[int(s) for s in input()]for _ in range(H)]
ans = 2**60
for i in range(2**(H-1)):
aa = 0
for j in range(H-1):
if (i>>j)&1 == 1:
aa+=1
c = aa
b = [0]*(c+1)
OK = True
for j in range(W):
k = 0
for h in range(H):
if S[h][j] == 1:b[k] += 1
if (i>>j)&1==1:k+=1
ok = True
for p in b:
if p > K:ok = False
if not ok:
aa += 1
b = [0]*(c+1)
k = 0
for h in range(H):
if S[h][j]==1:b[k] += 1
if (i>>j)&1==1:k+=1
ok = True
for p in b:
if p > K:ok = False
if not ok:OK = False;break
if OK:ans = min(ans,aa)
print(ans)
if __name__ == "__main__":
main()
``` | instruction | 0 | 22,631 | 9 | 45,262 |
No | output | 1 | 22,631 | 9 | 45,263 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
import sys
#input = sys.stdin.buffer.readline
def main():
H,W,K = map(int,input().split())
a = [list(input()) for _ in range(H)]
for i in range(H):
for j in range(W):
a[i][j] = int(a[i][j])
ans = 10**6
for i in range(1<<H-1):
cut,count = [-1],0
for j in range(H-1):
if (i>>j)&1 != 0:
count += 1
cut.append(j)
cut.append(H-1)
l = len(cut)-1
use = [[0 for _ in range(W)] for _ in range(l)]
for x in range(l):
up,down = cut[x],cut[x+1]
for y in range(up+1,down+1):
for z in range(W):
use[x][z] += a[y][z]
right,bl,yorn = 0,[0 for _ in range(l)],True
while right < W:
st = [0 for _ in range(l)]
for x in range(l):
st[x] += use[x][right]
if max(st) > K:
yorn = False
break
else:
for x in range(l):
bl[x] += st[x]
if bl[x] > K:
count += 1
bl = st
right += 1
if yorn:
ans = min(ans,count)
print(ans)
if __name__ == "__main__":
main()
``` | instruction | 0 | 22,632 | 9 | 45,264 |
No | output | 1 | 22,632 | 9 | 45,265 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is `0`, and white if S_{i,j} is `1`.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?
Constraints
* 1 \leq H \leq 10
* 1 \leq W \leq 1000
* 1 \leq K \leq H \times W
* S_{i,j} is `0` or `1`.
Input
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}
Output
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.
Examples
Input
3 5 4
11100
10001
00111
Output
2
Input
3 5 8
11100
10001
00111
Output
0
Input
4 10 4
1110010010
1000101110
0011101001
1101000111
Output
3
Submitted Solution:
```
H, W, K = map(int, input().split())
S = [[int(c) for c in input()] for i in range(H)]
s = [[0 for i in range(W+1)] for j in range(H + 1)]
for i in range(H):
for j in range(W):
s[i+1][j+1] = s[i][j+1] + s[i+1][j] - s[i][j] + S[i][j]
n = H - 1
ans = H * W
for i in range(2 ** n):
horizon = [0]
length = 0
for j in range(n):
if ((i >> j) & 1):
horizon.append(j + 1)
length += 1
horizon.append(H)
vertical = 0
y1 = 0
flag = 0
for y2 in range(1, W + 1):
for k in range(length - 1):
x2 = horizon[k + 1]
x1 = horizon[k]
sq = s[x2][y2] - s[x1][y2] - s[x2][y1] + s[x1][y1]
if (sq > K):
if (y2 == 1):
break
else:
vertical += 1
y1 = y2 - 1
ans = min(ans, (vertical) + (length - 2))
print(ans)
``` | instruction | 0 | 22,633 | 9 | 45,266 |
No | output | 1 | 22,633 | 9 | 45,267 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,246 | 9 | 46,492 |
Tags: implementation
Correct Solution:
```
x = input().split()
n = int(x[0])
m = int(x[1])
l = input().split()
ans = 0
high = 0
for x in range(n):
l[x] = int(l[x])
y = l[x] // m
if l[x] // m != l[x] / m:
y += 1
if y >= high:
high = y
ans = x + 1
print(ans)
``` | output | 1 | 23,246 | 9 | 46,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,247 | 9 | 46,494 |
Tags: implementation
Correct Solution:
```
from math import ceil
n, m = map(int, input().split())
kids = [ceil(int(i)/m) for i in input().split()]
maxn = max(kids)
for i in range(-1,-n-1,-1):
if kids[i] == maxn:
print(n+i+1)
break
``` | output | 1 | 23,247 | 9 | 46,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,248 | 9 | 46,496 |
Tags: implementation
Correct Solution:
```
child=input()
child=child.split(" ")
doce=int(child[1])
lista=input()
lista=lista.split(" ")
lista2=[]
for i in range(len(lista)):
lis=[]
lis.append(int(lista[i]))
lis.append(0)
lis.append(i+1)
lista2.append(lis)
while(len(lista2)>1):
lista2[0][1]+=doce
if(lista2[0][0]>lista2[0][1]):
aux=lista2[0]
del lista2[0]
lista2.append(aux)
else:
del lista2[0]
print(lista2[0][2])
``` | output | 1 | 23,248 | 9 | 46,497 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,249 | 9 | 46,498 |
Tags: implementation
Correct Solution:
```
n,m=[int(i) for i in input().split()]
s=input().split()
q=[[i+1,int(s[i])] for i in range(n)]
while len(q)!=1:
if q[0][1]-m<=0:
del q[0]
else:
x=[q[0][0],q[0][1]-m]
del q[0]
q+=[x]
print(q[0][0])
``` | output | 1 | 23,249 | 9 | 46,499 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,250 | 9 | 46,500 |
Tags: implementation
Correct Solution:
```
n, m = map(int, input().split())
a = list(map(int, input().split()))
b = [[a[i], i + 1] for i in range(n)]
ans = -1
while len(b) > 0:
b[0][0] -= m
if b[0][0] <= 0:
ans = b[0][1]
b = b[1:]
else:
b = b[1:] + b[0:1]
print(ans)
``` | output | 1 | 23,250 | 9 | 46,501 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,251 | 9 | 46,502 |
Tags: implementation
Correct Solution:
```
n,m = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
b = [int(x) for x in range(1,n+1)]
while(len(b)!=1):
if a[0]>m:
a[0]=a[0]-m
a.append(a.pop(0))
b.append(b.pop(0))
elif a[0]<=m:
a.pop(0)
b.pop(0)
print(b[0])
``` | output | 1 | 23,251 | 9 | 46,503 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,252 | 9 | 46,504 |
Tags: implementation
Correct Solution:
```
import math
n,m=input().split()
m=int(m)
a=[int (a) for a in input().split()]
ind=0
ele=math.ceil(a[0]/m)
if (max(a)<=int(m)):
print (n)
else:
for i in range(int(n)):
if (math.ceil(a[i]/m)>=(ele)):
ele=math.ceil(a[i]/m)
ind=i
print (ind+1)
``` | output | 1 | 23,252 | 9 | 46,505 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home. | instruction | 0 | 23,253 | 9 | 46,506 |
Tags: implementation
Correct Solution:
```
import math
i = lambda : [*map(int, input().split())]
n, m = i()
a = [*map(lambda x : math.ceil(x / m), i())]
print(n - [*reversed(a)].index(max(a)))
``` | output | 1 | 23,253 | 9 | 46,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
from collections import deque
n,m=input().split(' ')
n=int(n)
m=int(m)
a=[int(i) for i in input().split()]
queue=deque([i+1 for i in range(n)])
if len(queue)>1:
while True:
if len(queue)==1:
break
else:
if m>=a[queue[0]-1]:
queue.popleft()
else:
a[queue[0]-1]-=m
queue.append(queue[0])
queue.popleft()
print(queue[0])
``` | instruction | 0 | 23,254 | 9 | 46,508 |
Yes | output | 1 | 23,254 | 9 | 46,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
from math import *
n,m = map(int,input().split())
a = list(map(int,input().split()))
maxx = 0
for i in range(n):
if(maxx <= ceil(a[i]/m)):
maxx = ceil(a[i]/m)
ind = i+1
print(ind)
``` | instruction | 0 | 23,255 | 9 | 46,510 |
Yes | output | 1 | 23,255 | 9 | 46,511 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
import math
n, k = map(int, input().split())
l = list(map(int, input().split()))
m = 0
for i in range(n):
if math.ceil(l[i] / k) >= m:
m = math.ceil(l[i] / k)
ans = i + 1
print(ans)
``` | instruction | 0 | 23,256 | 9 | 46,512 |
Yes | output | 1 | 23,256 | 9 | 46,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
import math
l0=input().split()
n=int(l0[0])
t=int(l0[1])
l=list(map(int,input().split()))
m=max(l)
y=math.ceil(m/t)-1
ll=[]
for i in range(n):
ll.append(l[i]-y*t)
c=0
for j in range(n):
if ll[j]>0:
c=j
print(c+1)
``` | instruction | 0 | 23,257 | 9 | 46,514 |
Yes | output | 1 | 23,257 | 9 | 46,515 |
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