message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
n, m = map(int, input().split())
a = [int(i) for i in input().split()]
res = 0
index = 0
for i in range(n):
temp = a[i]//m
if a[i] > m and a[i]%m != 0:
temp += 1
if res <= temp:
res = temp
index = i+1
print(index)
``` | instruction | 0 | 23,258 | 9 | 46,516 |
No | output | 1 | 23,258 | 9 | 46,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
n,m=map(int,input().split())
a=list(map(int,input().split()))
l=lambda x: bool(x>((max(a)-1)//m)*m)
print(a.index((list(filter(l,a)))[-1])+1)
``` | instruction | 0 | 23,259 | 9 | 46,518 |
No | output | 1 | 23,259 | 9 | 46,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
n,m = map(int, input().split())
arr = list(map(int, input().split()))
for i in range(n):
if arr[i]<=m:
arr[i]=0
else:
arr[i] = int(arr[i]/m) + (arr[i]%m)
max_index = 0
maxi = -1
for i in range(n):
if arr[i]>=maxi:
maxi = arr[i]
max_index = i
print(max_index+1)
``` | instruction | 0 | 23,260 | 9 | 46,520 |
No | output | 1 | 23,260 | 9 | 46,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n children in Jzzhu's school. Jzzhu is going to give some candies to them. Let's number all the children from 1 to n. The i-th child wants to get at least ai candies.
Jzzhu asks children to line up. Initially, the i-th child stands at the i-th place of the line. Then Jzzhu start distribution of the candies. He follows the algorithm:
1. Give m candies to the first child of the line.
2. If this child still haven't got enough candies, then the child goes to the end of the line, else the child go home.
3. Repeat the first two steps while the line is not empty.
Consider all the children in the order they go home. Jzzhu wants to know, which child will be the last in this order?
Input
The first line contains two integers n, m (1 ≤ n ≤ 100; 1 ≤ m ≤ 100). The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 100).
Output
Output a single integer, representing the number of the last child.
Examples
Input
5 2
1 3 1 4 2
Output
4
Input
6 4
1 1 2 2 3 3
Output
6
Note
Let's consider the first sample.
Firstly child 1 gets 2 candies and go home. Then child 2 gets 2 candies and go to the end of the line. Currently the line looks like [3, 4, 5, 2] (indices of the children in order of the line). Then child 3 gets 2 candies and go home, and then child 4 gets 2 candies and goes to the end of the line. Currently the line looks like [5, 2, 4]. Then child 5 gets 2 candies and goes home. Then child 2 gets two candies and goes home, and finally child 4 gets 2 candies and goes home.
Child 4 is the last one who goes home.
Submitted Solution:
```
a,b=map(int,input().split())
l=list(map(int,input().split()))
arr=[]
count=0
for i in range(a):
if l[i]>b:
arr.append(l[i])
else:
count+=1
if count==a:
print(a)
else:
print(l.index(max(arr))+1)
``` | instruction | 0 | 23,261 | 9 | 46,522 |
No | output | 1 | 23,261 | 9 | 46,523 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,338 | 9 | 46,676 |
Tags: binary search, combinatorics, math
Correct Solution:
```
t = [k ** 3 for k in range(2, 170417)]
s = m = int(input())
a, b = 1, 9 * m
while a < b:
c = (a + b) // 2
d = sum(int(c / k) for k in t)
if d < m: a = c + 1
else: s, b = d, c
print(a if s == m else -1)
``` | output | 1 | 23,338 | 9 | 46,677 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,339 | 9 | 46,678 |
Tags: binary search, combinatorics, math
Correct Solution:
```
def main():
m = int(input())
if m < 1000000:
lo = m*4
hi = m*8
else:
lo = int(4.949 * m)
hi = int(4.9492 * m)
while lo < hi - 1:
mid = (lo + hi)//2
nposs = countposs(mid)
if nposs < m:
lo = mid
else:
hi = mid
if m == countposs(hi):
print(hi)
else:
print(-1)
def countposs(maxtake):
k = 2
ans = 0
while True:
term = maxtake//(k*k*k)
if term == 0:
return ans
ans += term
k += 1
main()
``` | output | 1 | 23,339 | 9 | 46,679 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,340 | 9 | 46,680 |
Tags: binary search, combinatorics, math
Correct Solution:
```
cubes = [i**3.0 for i in range(2, int(1.8e5+5))]
def valid(mid):
return sum([mid//i for i in cubes if i <= mid])
def binary_search(k):
l = int(4.8 * k)
r = min(8.0 * k, 5.0 * (10**15))
while (l+1 < r):
mid = (l+r) / 2.0
res = valid(mid)
if (res < k):
l = mid
else:
r = mid
return int(r) if int(valid(r)) == k else -1
def main():
k = int(input())
print(binary_search(k))
main()
``` | output | 1 | 23,340 | 9 | 46,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,341 | 9 | 46,682 |
Tags: binary search, combinatorics, math
Correct Solution:
```
def main():
m = int(input())
lo = m*4
hi = m*8
loposs = countposs(lo)
hiposs = countposs(hi)
while lo < hi - 1:
if hi - lo > 10000:
mid = lo + int((m-loposs)/(hiposs-loposs)*(hi-lo))
mid = max(lo + 1, min(hi - 1, mid))
else:
mid = (hi + lo)//2
nposs = countposs(mid)
if nposs < m:
lo = mid
else:
hi = mid
if m == countposs(hi):
print(hi)
else:
print(-1)
def countposs(maxtake):
k = 2
ans = 0
while True:
term = maxtake//(k*k*k)
if term == 0:
return ans
ans += term
k += 1
main()
``` | output | 1 | 23,341 | 9 | 46,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,342 | 9 | 46,684 |
Tags: binary search, combinatorics, math
Correct Solution:
```
# [https://codeforces.com/blog/entry/45912 <- https://codeforces.com/blog/entry/45896 <- https://codeforces.com/problemset/problem/689/C <- https://algoprog.ru/material/pc689pC]
def get(x):
ans = 0
i = 2
while i * i * i <= x:
ans += x // (i * i * i)
i += 1
return ans
m = int(input())
n = 0
k = 1 << 60
while k != 0:
if n + k <= 10**16 and get(n+k) < m:
n += k
k //= 2
n += 1
if get(n) == m:
print(n)
else:
print(-1)
``` | output | 1 | 23,342 | 9 | 46,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,343 | 9 | 46,686 |
Tags: binary search, combinatorics, math
Correct Solution:
```
SIZE = 171000
L = [i ** 3 for i in range(SIZE)]
def get_count(n):
MAX = int(n ** (1 / 3)) + 1
if L[MAX] > n:
MAX -= 1
res = 0
for i in range(2, MAX + 1):
x = n // L[i]
if x != 1:
res += x
else:
res += MAX - i + 1
break
return res
def bin_search(m):
beg = int(4.8 * m)
end = min(8 * m, int(5e15))
while beg <= end:
mid = (beg + end) // 2
count_mid = get_count(mid)
if count_mid == m:
if beg == end:
return mid
end = mid
elif count_mid > m:
end = mid - 1
else:
beg = mid + 1
return -1
m = int(input())
print(bin_search(m))
``` | output | 1 | 23,343 | 9 | 46,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,344 | 9 | 46,688 |
Tags: binary search, combinatorics, math
Correct Solution:
```
# [https://codeforces.com/contest/689/submission/38003624]
cubes = [i**3.0 for i in range(2, int(1.8e5+5))]
def valid(mid):
return sum([mid//i for i in cubes if i <= mid])
def binary_search(k):
l = int(4.8 * k)
r = min(8.0 * k, 5.0 * (10**15))
while (l+1 < r):
mid = (l+r) / 2.0
res = valid(mid)
if (res < k):
l = mid
else:
r = mid
return int(r) if int(valid(r)) == k else -1
k = int(input())
print(binary_search(k))
``` | output | 1 | 23,344 | 9 | 46,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case. | instruction | 0 | 23,345 | 9 | 46,690 |
Tags: binary search, combinatorics, math
Correct Solution:
```
t = [k ** 3 for k in range(2, 2*10**5)]
s = m = int(input())
a, b = 1, 9 * m
while a < b:
c = (a + b) // 2
d = sum(int(c / k) for k in t)
if d < m: a = c + 1
else: s, b = d, c
print(a if s == m else -1)
``` | output | 1 | 23,345 | 9 | 46,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case.
Submitted Solution:
```
m = int(input())
def go(min, max, m):
if(max==min):
return max
mid = (min+max)//2
sum = 0
i = 2
while True:
k = mid//(i**3)
if(k==0):
break
sum += k
i += 1
if(sum<m):
return go(mid+1,max,m)
else:
return go(min,mid,m)
aaa = go(1,m*8,m)
i = 2
c = 0
while True:
if(aaa//(i**3)==0):
break
if(aaa%(i**3)==0):
c += 1
i += 1
if(c>=2):
bbb = go(1,m*8+8,m+1)
i = 2
c = 0
while True:
if(bbb//(i**3)==0):
break
if(bbb%(i**3)==0):
c += 1
i += 1
if(c>=2):
print(-1)
else:
print(aaa)
else:
print(aaa)
``` | instruction | 0 | 23,346 | 9 | 46,692 |
No | output | 1 | 23,346 | 9 | 46,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case.
Submitted Solution:
```
m = int(input())
n = 0
ans = 0
while ans != m and n <= 100000:
n += 1
ans = 0
i = 1
while i**3 <= n:
i += 1
i -= 1 # it was one over
#print("we can go up to base", i)
ans = 0
for j in range(2, i+1):
#print("BASE", j, "=====================")
val = j**3
d = n//(val)
ans += d
#print(ans)
if n > 100001:
print(-1)
else:
print(n)
``` | instruction | 0 | 23,347 | 9 | 46,694 |
No | output | 1 | 23,347 | 9 | 46,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case.
Submitted Solution:
```
def valid(cubes, mid):
return sum([mid//i for i in cubes if i <= mid])
def binary_search(cubes, k):
l = int(4.8*k)
r = int(min(8.0*k, 1.0*(1<<61)))
while (l <= r):
mid = l+r >> 1
res = valid(cubes, mid)
if (res < k):
l = mid+1
elif (res > k):
r = mid-1
else:
return mid
return -1
def main():
k = int(input())
cubes = [i**3.0 for i in range(2, int(1e5+5))]
print(binary_search(cubes, k))
main()
``` | instruction | 0 | 23,348 | 9 | 46,696 |
No | output | 1 | 23,348 | 9 | 46,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bad news came to Mike's village, some thieves stole a bunch of chocolates from the local factory! Horrible!
Aside from loving sweet things, thieves from this area are known to be very greedy. So after a thief takes his number of chocolates for himself, the next thief will take exactly k times more than the previous one. The value of k (k > 1) is a secret integer known only to them. It is also known that each thief's bag can carry at most n chocolates (if they intend to take more, the deal is cancelled) and that there were exactly four thieves involved.
Sadly, only the thieves know the value of n, but rumours say that the numbers of ways they could have taken the chocolates (for a fixed n, but not fixed k) is m. Two ways are considered different if one of the thieves (they should be numbered in the order they take chocolates) took different number of chocolates in them.
Mike want to track the thieves down, so he wants to know what their bags are and value of n will help him in that. Please find the smallest possible value of n or tell him that the rumors are false and there is no such n.
Input
The single line of input contains the integer m (1 ≤ m ≤ 1015) — the number of ways the thieves might steal the chocolates, as rumours say.
Output
Print the only integer n — the maximum amount of chocolates that thieves' bags can carry. If there are more than one n satisfying the rumors, print the smallest one.
If there is no such n for a false-rumoured m, print - 1.
Examples
Input
1
Output
8
Input
8
Output
54
Input
10
Output
-1
Note
In the first sample case the smallest n that leads to exactly one way of stealing chocolates is n = 8, whereas the amounts of stealed chocolates are (1, 2, 4, 8) (the number of chocolates stolen by each of the thieves).
In the second sample case the smallest n that leads to exactly 8 ways is n = 54 with the possibilities: (1, 2, 4, 8), (1, 3, 9, 27), (2, 4, 8, 16), (2, 6, 18, 54), (3, 6, 12, 24), (4, 8, 16, 32), (5, 10, 20, 40), (6, 12, 24, 48).
There is no n leading to exactly 10 ways of stealing chocolates in the third sample case.
Submitted Solution:
```
# todos los k posibles
t = [k ** 3 for k in range(2, 2*10**5)]
# leemos de la entrada
s = m = int(input())
# los limites de la busqueda binaria estan entre los valores posibles de m
a, b = 1, 10**15
# mientras no se crucen los punteros
while b - a > 1:
# vamos al medio de la lista
c = (a + b) // 2
# se hace la suma que calcula las formas posibles para cada k fijando c como n
d = sum(int(c / k) for k in t)
# si la cantidad de formas posibles con c es menor que la entrada entonces
# revisamos el lado derecho
if d < m: a = c
# si pasa lo contrario revisamos el lado izquierdo
else: s, b = d, c
# si encontramos un n tal que la sumatoria sea igual a m
# devolvemos ese n mas pequenno, en caso contrario no existe n
# y devolvemos -1
print(a+1 if s == m else -1)
``` | instruction | 0 | 23,349 | 9 | 46,698 |
No | output | 1 | 23,349 | 9 | 46,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Note that girls in Arpa’s land are really attractive.
Arpa loves overnight parties. In the middle of one of these parties Mehrdad suddenly appeared. He saw n pairs of friends sitting around a table. i-th pair consisted of a boy, sitting on the ai-th chair, and his girlfriend, sitting on the bi-th chair. The chairs were numbered 1 through 2n in clockwise direction. There was exactly one person sitting on each chair.
<image>
There were two types of food: Kooft and Zahre-mar. Now Mehrdad wonders, was there any way to serve food for the guests such that:
* Each person had exactly one type of food,
* No boy had the same type of food as his girlfriend,
* Among any three guests sitting on consecutive chairs, there was two of them who had different type of food. Note that chairs 2n and 1 are considered consecutive.
Find the answer for the Mehrdad question. If it was possible, find some arrangement of food types that satisfies the conditions.
Input
The first line contains an integer n (1 ≤ n ≤ 105) — the number of pairs of guests.
The i-th of the next n lines contains a pair of integers ai and bi (1 ≤ ai, bi ≤ 2n) — the number of chair on which the boy in the i-th pair was sitting and the number of chair on which his girlfriend was sitting. It's guaranteed that there was exactly one person sitting on each chair.
Output
If there is no solution, print -1.
Otherwise print n lines, the i-th of them should contain two integers which represent the type of food for the i-th pair. The first integer in the line is the type of food the boy had, and the second integer is the type of food the girl had. If someone had Kooft, print 1, otherwise print 2.
If there are multiple solutions, print any of them.
Example
Input
3
1 4
2 5
3 6
Output
1 2
2 1
1 2
Submitted Solution:
```
Visited = []
Adj = []
Food = []
Edges = []
def DFS_Food(v, food):
Food[v] = food
for w in Adj[v]:
if not Visited[w]:
Visited[w] = True
DFS_Food(w, 3 - food)
n = int(input())
for i in range(n):
v = i * 2
w = i * 2 + 1
Adj.append([])
Adj.append([])
Adj[v].append(w)
Adj[w].append(v)
Visited.append(False)
Visited.append(False)
Food.append(0)
Food.append(0)
for i in range(n):
edge = input().split()
v = int(edge[0]) - 1
w = int(edge[1]) - 1
Edges.append((v, w))
Adj[v].append(w)
Adj[w].append(v)
for i in range(n):
if not Visited[i]:
Visited[i] = True
DFS_Food(i, 1)
for i in Edges:
print(str(Food[i[0]]) + ' ' + str(Food[i[1]]))
``` | instruction | 0 | 24,360 | 9 | 48,720 |
No | output | 1 | 24,360 | 9 | 48,721 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Note that girls in Arpa’s land are really attractive.
Arpa loves overnight parties. In the middle of one of these parties Mehrdad suddenly appeared. He saw n pairs of friends sitting around a table. i-th pair consisted of a boy, sitting on the ai-th chair, and his girlfriend, sitting on the bi-th chair. The chairs were numbered 1 through 2n in clockwise direction. There was exactly one person sitting on each chair.
<image>
There were two types of food: Kooft and Zahre-mar. Now Mehrdad wonders, was there any way to serve food for the guests such that:
* Each person had exactly one type of food,
* No boy had the same type of food as his girlfriend,
* Among any three guests sitting on consecutive chairs, there was two of them who had different type of food. Note that chairs 2n and 1 are considered consecutive.
Find the answer for the Mehrdad question. If it was possible, find some arrangement of food types that satisfies the conditions.
Input
The first line contains an integer n (1 ≤ n ≤ 105) — the number of pairs of guests.
The i-th of the next n lines contains a pair of integers ai and bi (1 ≤ ai, bi ≤ 2n) — the number of chair on which the boy in the i-th pair was sitting and the number of chair on which his girlfriend was sitting. It's guaranteed that there was exactly one person sitting on each chair.
Output
If there is no solution, print -1.
Otherwise print n lines, the i-th of them should contain two integers which represent the type of food for the i-th pair. The first integer in the line is the type of food the boy had, and the second integer is the type of food the girl had. If someone had Kooft, print 1, otherwise print 2.
If there are multiple solutions, print any of them.
Example
Input
3
1 4
2 5
3 6
Output
1 2
2 1
1 2
Submitted Solution:
```
n = int(input("kol gostei"))
i = 0
while i < n:
a,b = map(int, input().split(' '))
if a % 2 == 0:
print("1")
else:
print("2")
if b % 2 == 0:
print("1")
else:
print("2")
i = i + 1
``` | instruction | 0 | 24,361 | 9 | 48,722 |
No | output | 1 | 24,361 | 9 | 48,723 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Note that girls in Arpa’s land are really attractive.
Arpa loves overnight parties. In the middle of one of these parties Mehrdad suddenly appeared. He saw n pairs of friends sitting around a table. i-th pair consisted of a boy, sitting on the ai-th chair, and his girlfriend, sitting on the bi-th chair. The chairs were numbered 1 through 2n in clockwise direction. There was exactly one person sitting on each chair.
<image>
There were two types of food: Kooft and Zahre-mar. Now Mehrdad wonders, was there any way to serve food for the guests such that:
* Each person had exactly one type of food,
* No boy had the same type of food as his girlfriend,
* Among any three guests sitting on consecutive chairs, there was two of them who had different type of food. Note that chairs 2n and 1 are considered consecutive.
Find the answer for the Mehrdad question. If it was possible, find some arrangement of food types that satisfies the conditions.
Input
The first line contains an integer n (1 ≤ n ≤ 105) — the number of pairs of guests.
The i-th of the next n lines contains a pair of integers ai and bi (1 ≤ ai, bi ≤ 2n) — the number of chair on which the boy in the i-th pair was sitting and the number of chair on which his girlfriend was sitting. It's guaranteed that there was exactly one person sitting on each chair.
Output
If there is no solution, print -1.
Otherwise print n lines, the i-th of them should contain two integers which represent the type of food for the i-th pair. The first integer in the line is the type of food the boy had, and the second integer is the type of food the girl had. If someone had Kooft, print 1, otherwise print 2.
If there are multiple solutions, print any of them.
Example
Input
3
1 4
2 5
3 6
Output
1 2
2 1
1 2
Submitted Solution:
```
n = int(input())
x = []
y = []
g = [0]*(n*2+1)
ans = [0]*(n*2+1)
for i in range(n):
a, b = map(int, input().split())
x.append(a)
y.append(b)
g[a] = b
g[b] = a
if(n==1):
print("1 2")
exit()
def check(x,y):
mk = 1
q = x
w = x-1
e = x-2
if(w<=0): w = 2*n+w
if(e<=0): e = 2*n+e
if(ans[w]!=0 and ans[e]!=0):
if(ans[w]+ans[e]+y==3 or ans[w]+ans[e]+y==6): mk = 0
#if(x==3):
# print(q,w,e)
e = x+1
if(e>2*n): e-=2*n
if (ans[w] != 0 and ans[e] != 0):
if (ans[w] +ans[e]+y == 3 or ans[w] + ans[e]+y == 6): mk = 0
#if (x == 3):
# print(q, w, e)
w = x+2
if(w>2*n): w-=2*n
if (ans[w] != 0 and ans[e] != 0):
if (ans[w] + ans[e] + y== 3 or ans[w] + ans[e] + y== 6): mk = 0
#if (x == 3):
# print(q, w, e)
return mk
def set(x,y):
mk = 1
mk = check(x,y)
fy = 1
if(y==1):
fy = 2
mk = check(g[x],fy)
if(mk):
ans[x] = y
ans[g[x]] = fy
return mk
for i in range(1,2*n+1):
if(ans[i]):
continue
if(i%2==1):
if(set(i,1)==False):
set(i,2)
elif(set(i,2)==False):
set(i,1)
for i in range(n):
print("%d %d"%(ans[x[i]],ans[y[i]]))
``` | instruction | 0 | 24,362 | 9 | 48,724 |
No | output | 1 | 24,362 | 9 | 48,725 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Note that girls in Arpa’s land are really attractive.
Arpa loves overnight parties. In the middle of one of these parties Mehrdad suddenly appeared. He saw n pairs of friends sitting around a table. i-th pair consisted of a boy, sitting on the ai-th chair, and his girlfriend, sitting on the bi-th chair. The chairs were numbered 1 through 2n in clockwise direction. There was exactly one person sitting on each chair.
<image>
There were two types of food: Kooft and Zahre-mar. Now Mehrdad wonders, was there any way to serve food for the guests such that:
* Each person had exactly one type of food,
* No boy had the same type of food as his girlfriend,
* Among any three guests sitting on consecutive chairs, there was two of them who had different type of food. Note that chairs 2n and 1 are considered consecutive.
Find the answer for the Mehrdad question. If it was possible, find some arrangement of food types that satisfies the conditions.
Input
The first line contains an integer n (1 ≤ n ≤ 105) — the number of pairs of guests.
The i-th of the next n lines contains a pair of integers ai and bi (1 ≤ ai, bi ≤ 2n) — the number of chair on which the boy in the i-th pair was sitting and the number of chair on which his girlfriend was sitting. It's guaranteed that there was exactly one person sitting on each chair.
Output
If there is no solution, print -1.
Otherwise print n lines, the i-th of them should contain two integers which represent the type of food for the i-th pair. The first integer in the line is the type of food the boy had, and the second integer is the type of food the girl had. If someone had Kooft, print 1, otherwise print 2.
If there are multiple solutions, print any of them.
Example
Input
3
1 4
2 5
3 6
Output
1 2
2 1
1 2
Submitted Solution:
```
x=8
for i in range(16):
x=x*8%10
print(x)
``` | instruction | 0 | 24,363 | 9 | 48,726 |
No | output | 1 | 24,363 | 9 | 48,727 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,669 | 9 | 49,338 |
"Correct Solution:
```
while 1:
n = int(input())
count = 0
if n == 0:
break
L = [list(map(int,input().split())) for i in range(n+1)]
for i in range(n):
if L[i][1] <= L[n][0] and L[i][2] <= L[n][1] and L[i][3] <= L[n][2] and L[i][1] * 4 + L[i][2] * 9 +L[i][3] * 4 <= L[n][3] :
print(L[i][0])
count += 1
if count == 0:
print("NA")
``` | output | 1 | 24,669 | 9 | 49,339 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,670 | 9 | 49,340 |
"Correct Solution:
```
# AOJ 0239: Calorie Counting
# Python3 2018.6.25 bal4u
while 1:
n = int(input())
if n == 0: break
s, p, q, r = [0]*1002, [0]*1002, [0]*1002, [0]*1002
for i in range(n):
s[i], p[i], q[i], r[i] = map(int, input().split())
P, Q, R, C = map(int, input().split())
f = False
for i in range(n):
c = ((p[i]+r[i]) << 2) + (q[i] << 3) + q[i]
if p[i] > P or q[i] > Q or r[i] > R or c > C: pass
else:
print(s[i])
f = True
if not f: print("NA")
``` | output | 1 | 24,670 | 9 | 49,341 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,671 | 9 | 49,342 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
lst = [list(map(int, input().split())) for _ in range(n)]
lp, lq, lr, lc = map(int, input().split())
flag = True
for s, p, q, r in lst:
if p <= lp and q <= lq and r <= lr and 4 * p + 9 * q + 4 * r <= lc:
print(s)
flag = False
if flag:
print("NA")
``` | output | 1 | 24,671 | 9 | 49,343 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,672 | 9 | 49,344 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
data = [map(int,input().split()) for i in range(n)]
p,q,r,c = map(int,input().split())
ans = [i for i,pp,qq,rr in data if pp<=p and qq<=q and rr<=r and pp*4+qq*9+rr*4<=c]
if len(ans):
for i in ans:
print (i)
else :
print ("NA")
``` | output | 1 | 24,672 | 9 | 49,345 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,673 | 9 | 49,346 |
"Correct Solution:
```
while 1:
N = int(input())
if N == 0:break
cals = [ list(map(int,input().split())) for i in range(N)]
P,Q,R,C = list(map(int,input().split()))
res = [ x for x in cals if x[1]<=P and x[2]<=Q and x[3]<=R and 4*x[1] + 9*x[2] + 4*x[3] <= C]
if len(res) == 0:print('NA')
else:
for i in res:
print(i[0])
``` | output | 1 | 24,673 | 9 | 49,347 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,674 | 9 | 49,348 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
ls = [list(map(int, input().split())) for _ in range(n)]
P, Q, R, C = map(int, input().split())
b = True
for l in ls:
if P >= l[1] and Q >= l[2] and R >= l[3] and 4*l[1]+9*l[2]+4*l[3] <= C:
print(l[0])
b = False
if b: print("NA")
``` | output | 1 | 24,674 | 9 | 49,349 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,675 | 9 | 49,350 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:break
a = [list(map(int, input().split())) for _ in range(n)]
p, q, r, c = map(int, input().split())
b = [x[0] for x in a if x[1] <= p and x[2] <= q and x[3] <= r and 4 * (x[1]+x[3])+9*x[2] <= c]
if len(b):print(*b, sep='\n')
else:print('NA')
``` | output | 1 | 24,675 | 9 | 49,351 |
Provide a correct Python 3 solution for this coding contest problem.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA | instruction | 0 | 24,676 | 9 | 49,352 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:
break
s = []
for i in range(n):
s.append([int(i) for i in input().split()])
p, q, r, c = [int(i) for i in input().split()]
possible = []
for i in range(n):
if (s[i][1] <= p) & (s[i][2] <= q) & (s[i][3] <= r) & ((4 * (s[i][1] + s[i][3]) + 9 * s[i][2]) <= c):
possible.append(s[i][0])
if possible == []:
print('NA')
else:
for i in possible:
print(i)
``` | output | 1 | 24,676 | 9 | 49,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA
Submitted Solution:
```
while 1:
n = int(input())
if n == 0:
break
data = []
for _ in range(n):
s, p, q, r = map(int, input().split())
data.append([s, p, q, r])
P, Q, R, C = map(int, input().split())
flag = False
for d in data:
cal = d[1] * 4 + d[2] * 9 + d[3] * 4
if d[1] <= P and d[2] <= Q and d[3] <= R and cal <= C:
flag = True
print(d[0])
if not flag:
print("NA")
``` | instruction | 0 | 24,677 | 9 | 49,354 |
Yes | output | 1 | 24,677 | 9 | 49,355 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA
Submitted Solution:
```
import sys
f = sys.stdin
while True:
n = int(f.readline())
if n == 0:
break
ipqr = [map(int, f.readline().split()) for _ in range(n)]
pl, ql, rl, cl = map(int, f.readline().split())
allow = [i for i, p, q, r in ipqr if p <= pl and q <= ql and r <= rl and p * 4 + q * 9 + r * 4 <= cl]
print('\n'.join(map(str, allow)) if len(allow) else 'NA')
``` | instruction | 0 | 24,678 | 9 | 49,356 |
Yes | output | 1 | 24,678 | 9 | 49,357 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA
Submitted Solution:
```
while 1:
n = int(input())
if n == 0:break
s = []
for _ in range(n):s.append(tuple(map(int, input().split())))
l = tuple(map(int, input().split()))
e = []
for i in range(n):
if s[i][1] <= l[0] and s[i][2] <= l[1] and s[i][3] <= l[2] and s[i][1] * 4 + s[i][2] * 9 + s[i][3] * 4 <= l[3]:e.append(s[i][0])
if e != []:
for i in e:print(i)
else:print("NA")
``` | instruction | 0 | 24,679 | 9 | 49,358 |
Yes | output | 1 | 24,679 | 9 | 49,359 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Calorie Counting
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0239
"""
import sys
def solve(foods, limit):
ans = []
for s, p, q, r in foods:
total_calorie = p*4 + q*9 + r*4
if all([x <= y for x, y in zip([p, q, r, total_calorie], limit)]):
ans.append(s)
return ans if ans else ['NA']
def main(args):
while True:
n = int(input())
if n == 0:
break
foods = [list(map(int, input().split())) for _ in range(n)]
limit = list(map(int, input().split()))
ans = solve(foods, limit)
print(*ans, sep='\n')
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 24,680 | 9 | 49,360 |
Yes | output | 1 | 24,680 | 9 | 49,361 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA
Submitted Solution:
```
while 1:
N = int(input())
if N == 0:break
cals = [ list(map(int,input().split())) for i in range(N)]
P,Q,R,C = list(map(int,input().split()))
res = [ x for x in cals if x[1]<=P and x[2]<=Q and x[3]<=R and 4*x[1] + 9*x[2] + 4*x[3]]
if len(res) == 0:print('NA')
else:
for i in res:
print(i[0])
``` | instruction | 0 | 24,681 | 9 | 49,362 |
No | output | 1 | 24,681 | 9 | 49,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Food contains three nutrients called "protein", "fat" and "carbohydrate", which are called three major nutrients. It is calculated that protein and carbohydrate are 4 kcal (kilocalories) and fat is 9 kcal per 1 g (gram). For example, according to the table below, the number 1 cake contains 7 g of protein, 14 g of fat and 47 g of carbohydrates. If you calculate the calories contained based on this, it will be 4 x 7 + 9 x 14 + 4 x 47 = 342 kcal. Others are calculated in the same way.
Number | Name | Protein (g) | Lipids (g) | Carbohydrates (g) | Calories (kcal)
--- | --- | --- | --- | --- | ---
1 | Cake | 7 | 14 | 47 | 342
2 | Potato Chips | 5 | 35 | 55 | 555
3 | Dorayaki | 6 | 3 | 59 | 287
4 | Pudding | 6 | 5 | 15 | 129
Input the number of sweets to be classified n, the information of each sweet, and the limit information, and output a list of sweets that do not exceed the limit (may be eaten) if only one sweet is used. Create a program.
The candy information consists of the candy number s, the weight p of the protein contained in the candy, the weight q of the lipid, and the weight r of the carbohydrate. The limit information consists of the maximum protein weight P that can be included, the fat weight Q, the carbohydrate weight R, and the maximum calorie C that can be consumed, of protein, fat, carbohydrate, and calories. If any one of them is exceeded, the restriction will be violated and it will be judged as "sweets that should not be eaten".
For a list of sweets that you can eat, output the numbers of sweets that you can eat in the order in which you entered them. If there are no sweets you can eat, please output "NA". For the four sweets in the table above, if the limit is P = 10, Q = 15, R = 50, C = 400, cake and pudding may be eaten as their respective nutrients and calories are below the limit. Although it is classified as sweets, potato chips are classified as sweets that should not be eaten because the amount of carbohydrates exceeds the limit value.
input
Given a sequence of multiple datasets. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
n
s1 p1 q1 r1
s2 p2 q2 r2
::
sn pn qn rn
P Q R C
The first line gives the number of sweets n (1 ≤ n ≤ 1000). The next n lines are given the number si (1 ≤ si ≤ 1000) of the i-th candy and the integers pi, qi, ri (0 ≤ pi, qi, ri ≤ 100) representing the weight of each nutrient.
The following lines are given the integers P, Q, R (0 ≤ P, Q, R ≤ 100), C (0 ≤ C ≤ 1700) representing the limits for each nutrient and calorie.
The number of datasets does not exceed 100.
output
For each dataset, it outputs the number of sweets you can eat or "NA".
Example
Input
4
1 7 14 47
2 5 35 55
3 6 3 59
4 6 5 15
10 15 50 400
2
1 8 10 78
2 4 18 33
10 10 50 300
0
Output
1
4
NA
Submitted Solution:
```
while True:
n = int(input())
if n == 0:
break
s = []
for i in range(n):
s.append([int(i) for i in input().split()])
p, q, r, c = [int(i) for i in input().split()]
possible = []
for i in range(n):
if (s[i][1] <= p) & (s[i][2] <= q) & (s[i][3] <= r) & ((4 * (s[i][1] + s[i][3]) + 9 * s[i][2]) <= c):
possible.append(i + 1)
if possible == []:
print('NA')
else:
for i in possible:
print(i)
``` | instruction | 0 | 24,682 | 9 | 49,364 |
No | output | 1 | 24,682 | 9 | 49,365 |
Provide a correct Python 3 solution for this coding contest problem.
G, a college student living in a certain sky city, has a hornworm, Imotaro. He disciplined Imotaro to eat all the food in order with the shortest number of steps. You, his friend, decided to write a program because he asked me to find out if Imotaro was really disciplined.
Input
H W N
area
Input is given in H + 1 lines. The first line contains three integers H, W, N (2 ≤ H ≤ 10, 2 ≤ W ≤ 10, 1 ≤ N ≤ 9). H is the height of the area, W is the width, and N is the number of foods (at this time, 6 + N ≤ H × W always holds).
In each line from the 2nd line to H + 1st line, ´S´, ´1´, 2´,… ´9´, ´a´, ´b´, ´c´, ´d´, ´e´, A W character string consisting of ´ # ´ and ´.´ is written, and each represents the state of each section of the area. In addition, ´S´, ´a´, ´b´, ´c´, ´d´, ´e´ represent the initial state of the hornworm. There is no food or obstacles so that it is covered with the hornworm in the initial state. In addition, the initial position of the hornworm and the position of the food are guaranteed to be entered correctly.
Output
Output the minimum number of steps when the hornworm eats food in order, or -1 if that is not possible.
Examples
Input
5 8 3
#.......
#.####2#
#.#.3..#
#.######
.1Sabcde
Output
14
Input
5 8 3
.......
.####2#
.#.3..#
.######
.1Sabcde
Output
14
Input
2 6 2
.1.baS
.2.cde
Output
7
Input
2 6 2
.1#baS
.2.cde
Output
-1 | instruction | 0 | 24,695 | 9 | 49,390 |
"Correct Solution:
```
from collections import deque
def main():
h, w, n = map(int, input().split())
mp = [list("#" * (w + 2))] + [list("#" + input() + "#") for _ in range(h)] + [list("#") * (w + 2)]
init_body = [None] * 4
for y in range(1, h + 1):
for x in range(1, w + 1):
if mp[y][x] == "S":
init_head = (x, y)
mp[y][x] = "."
if mp[y][x] == "e":
mp[y][x] = "."
if "a" <= mp[y][x] <= "d":
init_body[ord(mp[y][x]) - ord("a")] = (x, y)
mp[y][x] = "."
if "1" <= mp[y][x] <= "9":
mp[y][x] = int(mp[y][x])
que = deque()
que.append((0, init_head, init_body, 1))
mem = {}
mem[(init_head, tuple(init_body), 1)] = 0
vec = ((1, 0), (0, -1), (-1, 0), (0, 1))
while que:
score, head, body, target = que.popleft()
if target > n:
print(score)
break
x, y = head
for dx, dy in vec:
nx, ny = x + dx, y + dy
if (nx, ny) in body:continue
if mp[ny][nx] == "#":continue
new_target = target
if mp[ny][nx] == target:new_target += 1
new_body = tuple([head] + list(body)[:-1])
if ((nx, ny), new_body, new_target) not in mem:
mem[((nx, ny), new_body, new_target)] = True
que.append((score + 1, (nx, ny), new_body, new_target))
else:
print(-1)
main()
``` | output | 1 | 24,695 | 9 | 49,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n tangerines, and the i-th of them consists of exactly ai slices. Santa Claus came to a school which has k pupils. Santa decided to treat them with tangerines.
However, there can be too few tangerines to present at least one tangerine to each pupil. So Santa decided to divide tangerines into parts so that no one will be offended. In order to do this, he can divide a tangerine or any existing part into two smaller equal parts. If the number of slices in the part he wants to split is odd, then one of the resulting parts will have one slice more than the other. It's forbidden to divide a part consisting of only one slice.
Santa Claus wants to present to everyone either a whole tangerine or exactly one part of it (that also means that everyone must get a positive number of slices). One or several tangerines or their parts may stay with Santa.
Let bi be the number of slices the i-th pupil has in the end. Let Santa's joy be the minimum among all bi's.
Your task is to find the maximum possible joy Santa can have after he treats everyone with tangerines (or their parts).
Input
The first line contains two positive integers n and k (1 ≤ n ≤ 106, 1 ≤ k ≤ 2·109) denoting the number of tangerines and the number of pupils, respectively.
The second line consists of n positive integers a1, a2, ..., an (1 ≤ ai ≤ 107), where ai stands for the number of slices the i-th tangerine consists of.
Output
If there's no way to present a tangerine or a part of tangerine to everyone, print -1. Otherwise, print the maximum possible joy that Santa can have.
Examples
Input
3 2
5 9 3
Output
5
Input
2 4
12 14
Output
6
Input
2 3
1 1
Output
-1
Note
In the first example Santa should divide the second tangerine into two parts with 5 and 4 slices. After that he can present the part with 5 slices to the first pupil and the whole first tangerine (with 5 slices, too) to the second pupil.
In the second example Santa should divide both tangerines, so that he'll be able to present two parts with 6 slices and two parts with 7 slices.
In the third example Santa Claus can't present 2 slices to 3 pupils in such a way that everyone will have anything.
Submitted Solution:
```
def good(j):
if j == 0:
return True
s = 0
for i in range(n):
s += fruits[i] // j
return s >= k
def binary_search():
l = 0
r = 10000001
while abs(l - r) > 1:
m = (l + r) // 2
if good(m):
l = m
else:
r = m - 1
return l
n, k = map(int, input().split())
fruits = list(map(int, input().split()))
r = binary_search()
print(r if r > 0 else '-1')
``` | instruction | 0 | 25,252 | 9 | 50,504 |
No | output | 1 | 25,252 | 9 | 50,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n tangerines, and the i-th of them consists of exactly ai slices. Santa Claus came to a school which has k pupils. Santa decided to treat them with tangerines.
However, there can be too few tangerines to present at least one tangerine to each pupil. So Santa decided to divide tangerines into parts so that no one will be offended. In order to do this, he can divide a tangerine or any existing part into two smaller equal parts. If the number of slices in the part he wants to split is odd, then one of the resulting parts will have one slice more than the other. It's forbidden to divide a part consisting of only one slice.
Santa Claus wants to present to everyone either a whole tangerine or exactly one part of it (that also means that everyone must get a positive number of slices). One or several tangerines or their parts may stay with Santa.
Let bi be the number of slices the i-th pupil has in the end. Let Santa's joy be the minimum among all bi's.
Your task is to find the maximum possible joy Santa can have after he treats everyone with tangerines (or their parts).
Input
The first line contains two positive integers n and k (1 ≤ n ≤ 106, 1 ≤ k ≤ 2·109) denoting the number of tangerines and the number of pupils, respectively.
The second line consists of n positive integers a1, a2, ..., an (1 ≤ ai ≤ 107), where ai stands for the number of slices the i-th tangerine consists of.
Output
If there's no way to present a tangerine or a part of tangerine to everyone, print -1. Otherwise, print the maximum possible joy that Santa can have.
Examples
Input
3 2
5 9 3
Output
5
Input
2 4
12 14
Output
6
Input
2 3
1 1
Output
-1
Note
In the first example Santa should divide the second tangerine into two parts with 5 and 4 slices. After that he can present the part with 5 slices to the first pupil and the whole first tangerine (with 5 slices, too) to the second pupil.
In the second example Santa should divide both tangerines, so that he'll be able to present two parts with 6 slices and two parts with 7 slices.
In the third example Santa Claus can't present 2 slices to 3 pupils in such a way that everyone will have anything.
Submitted Solution:
```
from collections import defaultdict
from itertools import accumulate
import bisect
def solve():
n, k = map(int, input().split())
A = [int(x) for x in input().split()]
D = defaultdict(int)
for a in A:
D[a] += 1
for i in range(1, a.bit_length()-1):
D[a>>i] += 1<<i-1
K = list(D.keys())
K.sort()
K.reverse()
P = [D[key] for key in K]
T = list(accumulate(P))
i = bisect.bisect_left(T, k)
return K[i] if i < len(K) else -1
print(solve())
``` | instruction | 0 | 25,253 | 9 | 50,506 |
No | output | 1 | 25,253 | 9 | 50,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n tangerines, and the i-th of them consists of exactly ai slices. Santa Claus came to a school which has k pupils. Santa decided to treat them with tangerines.
However, there can be too few tangerines to present at least one tangerine to each pupil. So Santa decided to divide tangerines into parts so that no one will be offended. In order to do this, he can divide a tangerine or any existing part into two smaller equal parts. If the number of slices in the part he wants to split is odd, then one of the resulting parts will have one slice more than the other. It's forbidden to divide a part consisting of only one slice.
Santa Claus wants to present to everyone either a whole tangerine or exactly one part of it (that also means that everyone must get a positive number of slices). One or several tangerines or their parts may stay with Santa.
Let bi be the number of slices the i-th pupil has in the end. Let Santa's joy be the minimum among all bi's.
Your task is to find the maximum possible joy Santa can have after he treats everyone with tangerines (or their parts).
Input
The first line contains two positive integers n and k (1 ≤ n ≤ 106, 1 ≤ k ≤ 2·109) denoting the number of tangerines and the number of pupils, respectively.
The second line consists of n positive integers a1, a2, ..., an (1 ≤ ai ≤ 107), where ai stands for the number of slices the i-th tangerine consists of.
Output
If there's no way to present a tangerine or a part of tangerine to everyone, print -1. Otherwise, print the maximum possible joy that Santa can have.
Examples
Input
3 2
5 9 3
Output
5
Input
2 4
12 14
Output
6
Input
2 3
1 1
Output
-1
Note
In the first example Santa should divide the second tangerine into two parts with 5 and 4 slices. After that he can present the part with 5 slices to the first pupil and the whole first tangerine (with 5 slices, too) to the second pupil.
In the second example Santa should divide both tangerines, so that he'll be able to present two parts with 6 slices and two parts with 7 slices.
In the third example Santa Claus can't present 2 slices to 3 pupils in such a way that everyone will have anything.
Submitted Solution:
```
n,k=map(int,input().split())
a=list(map(int,input().split()))
if sum(a)<k:
print(-1)
quit()
print((sum(a)-sum(a)%k)//k)
``` | instruction | 0 | 25,254 | 9 | 50,508 |
No | output | 1 | 25,254 | 9 | 50,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n tangerines, and the i-th of them consists of exactly ai slices. Santa Claus came to a school which has k pupils. Santa decided to treat them with tangerines.
However, there can be too few tangerines to present at least one tangerine to each pupil. So Santa decided to divide tangerines into parts so that no one will be offended. In order to do this, he can divide a tangerine or any existing part into two smaller equal parts. If the number of slices in the part he wants to split is odd, then one of the resulting parts will have one slice more than the other. It's forbidden to divide a part consisting of only one slice.
Santa Claus wants to present to everyone either a whole tangerine or exactly one part of it (that also means that everyone must get a positive number of slices). One or several tangerines or their parts may stay with Santa.
Let bi be the number of slices the i-th pupil has in the end. Let Santa's joy be the minimum among all bi's.
Your task is to find the maximum possible joy Santa can have after he treats everyone with tangerines (or their parts).
Input
The first line contains two positive integers n and k (1 ≤ n ≤ 106, 1 ≤ k ≤ 2·109) denoting the number of tangerines and the number of pupils, respectively.
The second line consists of n positive integers a1, a2, ..., an (1 ≤ ai ≤ 107), where ai stands for the number of slices the i-th tangerine consists of.
Output
If there's no way to present a tangerine or a part of tangerine to everyone, print -1. Otherwise, print the maximum possible joy that Santa can have.
Examples
Input
3 2
5 9 3
Output
5
Input
2 4
12 14
Output
6
Input
2 3
1 1
Output
-1
Note
In the first example Santa should divide the second tangerine into two parts with 5 and 4 slices. After that he can present the part with 5 slices to the first pupil and the whole first tangerine (with 5 slices, too) to the second pupil.
In the second example Santa should divide both tangerines, so that he'll be able to present two parts with 6 slices and two parts with 7 slices.
In the third example Santa Claus can't present 2 slices to 3 pupils in such a way that everyone will have anything.
Submitted Solution:
```
# Author: Maharshi Gor
import heapq
import sys
sys.setrecursionlimit(5000000)
def read(type=int):
return type(input())
def read_arr(type=int):
return [type(token) for token in input().split()]
def abs(num):
return num if num > 0 else -num
def is_sym(s):
return reversed(s) == s
n, k = read_arr()
A = read_arr()
heapq.heapify(A)
can_divide = True
while can_divide and len(A) < k:
e = heapq.heappop(A)
a = e // 2
b = e - a
if a == 0:
can_divide = False
else:
A.append(a)
heapq._siftdown_max(A, 0, len(A) - 1)
A.append(b)
heapq._siftdown_max(A, 0, len(A) - 1)
if can_divide:
A.sort(reverse=True)
print(A[k-1])
else:
print(-1)
``` | instruction | 0 | 25,255 | 9 | 50,510 |
No | output | 1 | 25,255 | 9 | 50,511 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,282 | 9 | 50,564 |
Tags: binary search, brute force, implementation
Correct Solution:
```
n, a, b = [int(x) for x in input().split()]
i = 1
while (a // i + b // i) >= n:
i += 1
print(min(i - 1, min(a, b)))
``` | output | 1 | 25,282 | 9 | 50,565 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,283 | 9 | 50,566 |
Tags: binary search, brute force, implementation
Correct Solution:
```
a = [int(s) for s in input().split()]
n, a, b = a[0], a[1], a[2]
m = 0
for i in range(1, n):
s = [0] * n
for x in range(a):
s[x % i] += 1
for x in range(b):
s[i + x % (n-i)] += 1
#print(s)
mm = min(s)
m = max(m, mm)
print(m)
``` | output | 1 | 25,283 | 9 | 50,567 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,284 | 9 | 50,568 |
Tags: binary search, brute force, implementation
Correct Solution:
```
import math
m=0
n,a,b=map(int,input().split())
for i in range(1,n):
if i<=a and (n-i)<=b:
m=max(m,min(a//i,b//(n-i)))
print(m)
``` | output | 1 | 25,284 | 9 | 50,569 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,285 | 9 | 50,570 |
Tags: binary search, brute force, implementation
Correct Solution:
```
(n, a, b) = map(int, input().split())
k = 0
for x in range(1, n):
k = max(k, min(a // x, b // (n - x)))
print(k)
``` | output | 1 | 25,285 | 9 | 50,571 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,286 | 9 | 50,572 |
Tags: binary search, brute force, implementation
Correct Solution:
```
# Problem: B. Two Cakes
# Contest: Codeforces - Educational Codeforces Round 35 (Rated for Div. 2)
# URL: https://codeforces.com/contest/911/problem/B
# Memory Limit: 256 MB
# Time Limit: 1000 ms
# Powered by CP Editor (https://github.com/cpeditor/cpeditor)
from sys import stdin
from math import floor
def get_ints(): return list(map(int, stdin.readline().strip().split()))
n,a,b = get_ints()
ans =1
for x in range(1,n):
ans =max(ans,min(floor(a/x),floor(b/(n-x))))
print(ans)
``` | output | 1 | 25,286 | 9 | 50,573 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,287 | 9 | 50,574 |
Tags: binary search, brute force, implementation
Correct Solution:
```
n, a, b = list(map(int, input().split(' ')[:3]))
def f(v):
t1 = a // v
t2 = b // v
return t1 != 0 and t2 != 0 and t1 + t2 >= n
def main():
t = (a + b) // n
while not f(t):
t -= 1
return t
print(main())
``` | output | 1 | 25,287 | 9 | 50,575 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,288 | 9 | 50,576 |
Tags: binary search, brute force, implementation
Correct Solution:
```
n,a,b=[int(i) for i in input().split()]
ans=0
for i in range(1,min(a,b)+1):
if(a//i + b//i>=n):
ans=i
print(ans)
``` | output | 1 | 25,288 | 9 | 50,577 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3. | instruction | 0 | 25,289 | 9 | 50,578 |
Tags: binary search, brute force, implementation
Correct Solution:
```
n, a, b = map(int,input().split())
z = []
for i in range(1, n):
z += [min(a // i, b // (n - i))]
print(max(z))
``` | output | 1 | 25,289 | 9 | 50,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3.
Submitted Solution:
```
if __name__ == "__main__":
n, a, b = [int(a) for a in input().strip().split()]
max_num = min(a, b)
while((a //max_num + b // max_num) < n):
max_num -= 1
print(str(max_num))
``` | instruction | 0 | 25,290 | 9 | 50,580 |
Yes | output | 1 | 25,290 | 9 | 50,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3.
Submitted Solution:
```
n, a, b = map(int, input().split())
maximum = 0
for x in range(1, min(a, b) + 1):
if (a // x) + (b // x) >= n:
maximum = x
print(maximum)
``` | instruction | 0 | 25,291 | 9 | 50,582 |
Yes | output | 1 | 25,291 | 9 | 50,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It's New Year's Eve soon, so Ivan decided it's high time he started setting the table. Ivan has bought two cakes and cut them into pieces: the first cake has been cut into a pieces, and the second one — into b pieces.
Ivan knows that there will be n people at the celebration (including himself), so Ivan has set n plates for the cakes. Now he is thinking about how to distribute the cakes between the plates. Ivan wants to do it in such a way that all following conditions are met:
1. Each piece of each cake is put on some plate;
2. Each plate contains at least one piece of cake;
3. No plate contains pieces of both cakes.
To make his guests happy, Ivan wants to distribute the cakes in such a way that the minimum number of pieces on the plate is maximized. Formally, Ivan wants to know the maximum possible number x such that he can distribute the cakes according to the aforementioned conditions, and each plate will contain at least x pieces of cake.
Help Ivan to calculate this number x!
Input
The first line contains three integers n, a and b (1 ≤ a, b ≤ 100, 2 ≤ n ≤ a + b) — the number of plates, the number of pieces of the first cake, and the number of pieces of the second cake, respectively.
Output
Print the maximum possible number x such that Ivan can distribute the cake in such a way that each plate will contain at least x pieces of cake.
Examples
Input
5 2 3
Output
1
Input
4 7 10
Output
3
Note
In the first example there is only one way to distribute cakes to plates, all of them will have 1 cake on it.
In the second example you can have two plates with 3 and 4 pieces of the first cake and two plates both with 5 pieces of the second cake. Minimal number of pieces is 3.
Submitted Solution:
```
arr=list(map(int,input().split()))
n = arr[0]
a = arr[1]
b = arr[2]
x = 1
maxx = 0
while x != n:
maxx = max(maxx,min(a/x,b/(n-x)))
x += 1
print(int(maxx))
``` | instruction | 0 | 25,292 | 9 | 50,584 |
Yes | output | 1 | 25,292 | 9 | 50,585 |
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