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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two integer arrays a_0, a_1, ..., a_{N - 1} and b_0, b_1, ..., b_{M - 1}. Calculate the array c_0, c_1, ..., c_{(N - 1) + (M - 1)}, defined by c_i = \sum_{j = 0}^i a_j b_{i - j} \bmod 998244353. Constraints * 1 \leq N, M \leq 524288 * 0 \leq a_i, b_i < 998244353 * All values in Input are integer. Input Input is given from Standard Input in the following format: N M a_0 a_1 ... a_{N-1} b_0 b_1 ... b_{M-1} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Examples Input 4 5 1 2 3 4 5 6 7 8 9 Output 5 16 34 60 70 70 59 36 Input 1 1 10000000 10000000 Output 871938225 Submitted Solution: ``` MOD = 998244353 ROOT = 3 class Convolution_998244353(): def __init__(self): self.first1 = True self.first2 = True self.sum_e = [0] * 30 self.sum_ie = [0] * 30 def inv_gcd(self, a, b): a %= b if a == 0: return b, 0 s = b t = a m0 = 0 m1 = 1 while t: u = s // t s -= t * u m0 -= m1 * u s, t = t, s m0, m1 = m1, m0 if m0 < 0: m0 += b // s return s, m0 def butterfly(self, arr): n = len(arr) h = (n - 1).bit_length() if self.first1: self.first1 = False es = [0] * 30 ies = [0] * 30 m = MOD - 1 cnt2 = (m & -m).bit_length() - 1 e = pow(ROOT, m >> cnt2, MOD) ie = pow(e, MOD - 2, MOD) for i in range(cnt2 - 1)[::-1]: es[i] = e ies[i] = ie e *= e e %= MOD ie *= ie ie %= MOD now = 1 for i in range(cnt2 - 2): self.sum_e[i] = es[i] * now % MOD now *= ies[i] now %= MOD for ph in range(1, h + 1): w = 1 << (ph - 1) p = 1 << (h - ph) now = 1 for s in range(w): offset = s << (h - ph + 1) for i in range(p): l = arr[i + offset] r = arr[i + offset + p] * now arr[i + offset] = (l + r) % MOD arr[i + offset + p] = (l - r) % MOD now *= self.sum_e[(~s & -~s).bit_length() - 1] now %= MOD def butterfly_inv(self, arr): n = len(arr) h = (n - 1).bit_length() if self.first2: self.first2 = False es = [0] * 30 ies = [0] * 30 m = MOD - 1 cnt2 = (m & -m).bit_length() - 1 e = pow(ROOT, m >> cnt2, MOD) ie = pow(e, MOD - 2, MOD) for i in range(cnt2 - 1)[::-1]: es[i] = e ies[i] = ie e *= e e %= MOD ie *= ie ie %= MOD now = 1 for i in range(cnt2 - 2): self.sum_ie[i] = ies[i] * now % MOD now *= es[i] now %= MOD for ph in range(1, h + 1)[::-1]: w = 1 << (ph - 1) p = 1 << (h - ph) inow = 1 for s in range(w): offset = s << (h - ph + 1) for i in range(p): l = arr[i + offset] r = arr[i + offset + p] arr[i + offset] = (l + r) % MOD arr[i + offset + p] = (MOD + l - r) * inow % MOD inow *= self.sum_ie[(~s & -~s).bit_length() - 1] inow %= MOD def convolution(self, a, b): n = len(a) m = len(b) if not n or not m: return [] if min(n, m) <= 50: if n < m: n, m = m, n a, b = b, a res = [0] * (n + m - 1) for i in range(n): for j in range(m): res[i + j] += a[i] * b[j] res[i + j] %= MOD return res z = 1 << (n + m - 2).bit_length() a += [0] * (z - n) b += [0] * (z - m) self.butterfly(a) self.butterfly(b) for i in range(z): a[i] *= b[i] a[i] %= MOD self.butterfly_inv(a) a = a[:n + m - 1] iz = pow(z, MOD - 2, MOD) for i in range(n + m - 1): a[i] *= iz a[i] %= MOD return a def autocorrelation(self, a): n = len(a) if not n: return [] if n <= 50: res = [0] * (2 * n - 1) for i in range(n): for j in range(n): res[i + j] += a[i] * a[j] res[i + j] %= MOD return res z = 1 << (2 * n - 2).bit_length() a += [0] * (z - n) self.butterfly(a) for i in range(a): a[i] *= a[i] a[i] %= MOD self.butterfly_inv(a) a = a[:2 * n - 1] iz = pow(z, MOD - 2, MOD) for i in range(2 * n - 1): a[i] *= iz a[i] %= MOD return a import sys input = sys.stdin.buffer.readline N, M = map(int, input().split()) A = [int(x) for x in input().split()] B = [int(x) for x in input().split()] cv = Convolution_998244353() print(*cv.convolution(A, B)) ``` Yes
97,600
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two integer arrays a_0, a_1, ..., a_{N - 1} and b_0, b_1, ..., b_{M - 1}. Calculate the array c_0, c_1, ..., c_{(N - 1) + (M - 1)}, defined by c_i = \sum_{j = 0}^i a_j b_{i - j} \bmod 998244353. Constraints * 1 \leq N, M \leq 524288 * 0 \leq a_i, b_i < 998244353 * All values in Input are integer. Input Input is given from Standard Input in the following format: N M a_0 a_1 ... a_{N-1} b_0 b_1 ... b_{M-1} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Examples Input 4 5 1 2 3 4 5 6 7 8 9 Output 5 16 34 60 70 70 59 36 Input 1 1 10000000 10000000 Output 871938225 Submitted Solution: ``` #!usr/bin/env python3 from collections import defaultdict, deque, Counter, OrderedDict from bisect import bisect_left, bisect_right from functools import reduce, lru_cache from heapq import heappush, heappop, heapify import itertools import math, fractions import sys, copy def L(): return sys.stdin.readline().split() def I(): return int(sys.stdin.readline().rstrip()) def SL(): return list(sys.stdin.readline().rstrip()) def LI(): return [int(x) for x in sys.stdin.readline().split()] def LI1(): return [int(x) - 1 for x in sys.stdin.readline().split()] def LS(): return [list(x) for x in sys.stdin.readline().split()] def R(n): return [sys.stdin.readline().strip() for _ in range(n)] def LR(n): return [L() for _ in range(n)] def IR(n): return [I() for _ in range(n)] def LIR(n): return [LI() for _ in range(n)] def LIR1(n): return [LI1() for _ in range(n)] def SR(n): return [SL() for _ in range(n)] def LSR(n): return [LS() for _ in range(n)] def perm(n, r): return math.factorial(n) // math.factorial(r) def comb(n, r): return math.factorial(n) // (math.factorial(r) * math.factorial(n-r)) def make_list(n, *args, default=0): return [make_list(*args, default=default) for _ in range(n)] if len(args) > 0 else [default for _ in range(n)] dire = [[1, 0], [0, 1], [-1, 0], [0, -1]] dire8 = [[1, 0], [1, 1], [0, 1], [-1, 1], [-1, 0], [-1, -1], [0, -1], [1, -1]] alphabets = "abcdefghijklmnopqrstuvwxyz" ALPHABETS = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" MOD = 1000000007 INF = float("inf") sys.setrecursionlimit(1000000) class NTT: ''' conv: ci = ∑_{j=0}^i a_j * b_{i−j} % mod 添字の和がiになるajとbkの積の和 ''' def __init__(self, a, b, mod=998244353, root=3): self.mod, self.root = mod, root deg = len(a) + len(b) - 2 self.n = deg.bit_length() N = 1 << self.n self.roots = [pow(self.root, (self.mod-1)>>i, self.mod) for i in range(24)] # 1 の 2^i 乗根 self.iroots = [pow(x,self.mod-2,self.mod) for x in self.roots] # 1 の 2^i 乗根の逆元 self.conv = a + [0]*(N-len(a)) self.b = b + [0]*(N-len(b)) self.untt() self.untt(False) for i in range(N): self.conv[i] = self.conv[i] * self.b[i] % self.mod self.iuntt() del self.conv[deg+1:] # inplace ver. of self.conv[:deg+1] def untt(self, flag=True): a = self.conv if flag else self.b for i in range(self.n): m = 1 << (self.n - i - 1) for s in range(1 << i): W = 1 s *= m * 2 for p in range(m): a[s+p], a[s+p+m] = (a[s+p]+a[s+p+m]) % self.mod, (a[s+p]-a[s+p+m]) * W % self.mod W = W * self.roots[self.n-i] % self.mod def iuntt(self): for i in range(self.n): m = 1 << i for s in range(1 << (self.n-i-1)): W = 1 s *= m * 2 for p in range(m): self.conv[s+p], self.conv[s+p+m] = (self.conv[s+p]+self.conv[s+p+m]*W)%self.mod, (self.conv[s+p]-self.conv[s+p+m]*W)%self.mod W = W * self.iroots[i+1] % self.mod inv = pow((self.mod + 1) // 2, self.n, self.mod) for i in range(1<<self.n): self.conv[i] = self.conv[i] * inv % self.mod def main(): N, M = LI() a = LI() b = LI() ntt = NTT(a, b) print(*ntt.conv) if __name__ == '__main__': main() ``` Yes
97,601
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two integer arrays a_0, a_1, ..., a_{N - 1} and b_0, b_1, ..., b_{M - 1}. Calculate the array c_0, c_1, ..., c_{(N - 1) + (M - 1)}, defined by c_i = \sum_{j = 0}^i a_j b_{i - j} \bmod 998244353. Constraints * 1 \leq N, M \leq 524288 * 0 \leq a_i, b_i < 998244353 * All values in Input are integer. Input Input is given from Standard Input in the following format: N M a_0 a_1 ... a_{N-1} b_0 b_1 ... b_{M-1} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Examples Input 4 5 1 2 3 4 5 6 7 8 9 Output 5 16 34 60 70 70 59 36 Input 1 1 10000000 10000000 Output 871938225 Submitted Solution: ``` MOD = 998244353 PROOT = 3 IPROOT = 665496235 roots = [pow(PROOT,(MOD-1)>>i,MOD) for i in range(24)] # 1 の 2^i 乗根 iroots = [pow(IPROOT,(MOD-1)>>i,MOD) for i in range(24)] # 1 の 2^i 乗根の逆元 def fft_stockham(A,n,inv=False): N = 1<<n for i in range(n): nA = [0]*N a = 1<<i b = 1<<(n-i-1) wb = iroots[i+1] if inv else roots[i+1] for j in range(b): w = 1 for k in range(a): nA[2*a*j+k] = (A[a*j+k] + A[a*j+N//2+k]*w)%MOD nA[2*a*j+k+a] = (A[a*j+k] - A[a*j+N//2+k]*w)%MOD w = w*wb%MOD A = nA return A def convolution(a,b): deg = len(a) + len(b) - 2 n = deg.bit_length() N = 1<<n a += [0]*(N-len(a)) b += [0]*(N-len(b)) fa = fft_stockham(a,n) fb = fft_stockham(b,n) inv = pow(1<<n,MOD-2,MOD) for i in range(N): fa[i] = fa[i]*fb[i]%MOD*inv%MOD ab = fft_stockham(fa,n,True) return ab[:deg+1] n,m = map(int,input().split()) a = list(map(int,input().split())) b = list(map(int,input().split())) c = convolution(a,b) print(*c) ``` Yes
97,602
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two integer arrays a_0, a_1, ..., a_{N - 1} and b_0, b_1, ..., b_{M - 1}. Calculate the array c_0, c_1, ..., c_{(N - 1) + (M - 1)}, defined by c_i = \sum_{j = 0}^i a_j b_{i - j} \bmod 998244353. Constraints * 1 \leq N, M \leq 524288 * 0 \leq a_i, b_i < 998244353 * All values in Input are integer. Input Input is given from Standard Input in the following format: N M a_0 a_1 ... a_{N-1} b_0 b_1 ... b_{M-1} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Examples Input 4 5 1 2 3 4 5 6 7 8 9 Output 5 16 34 60 70 70 59 36 Input 1 1 10000000 10000000 Output 871938225 Submitted Solution: ``` import sys input = sys.stdin.readline N, M = map(int, input().split()) a = list(map(int, input().split())) b = list(map(int, input().split())) mod = 998244353 class FastModuloTransformation: def __init__(self, n): self.n = n self.P = 998244353 self.g = 3 self.omega = pow(self.g, (self.P - 1) // n, self.P) def bitrev(self, a): n = self.n x = n.bit_length() - 1 res = a[: ] for i in range(n): j = 0 for k in range(x): j |= (i & (1 << k) > 0) << (x - k - 1) if i < j: res[i], res[j] = res[j], res[i] return res def fmt(self, a, base): if n == 1: return a P = self.P omega = base A = self.bitrev(a) half = pow(omega, n >> 1, P) i = n m = 1 while i > 1: i >>= 1 w = pow(omega, i, P) wk = 1 for j in range(m): for x in range(j, len(a), 2 * m): l = A[x] r = wk * A[x + m] % P A[x] = (l + r) % P A[x + m] = (l + r * half) % P wk *= w wk %= P m <<= 1 return A def ifmt(self, A): if self.n == 1: return A P = self.P nrev = pow(self.n, P - 2, P) return [(x * nrev) % P for x in self.fmt(A, pow(self.omega, P - 2, P))] n = 1 << ((max(len(a), len(b))).bit_length()) + 1 fmt = FastModuloTransformation(n) a = [0] * (n - N) + a b = [0] * (n - M) + b A = fmt.fmt(a, fmt.omega) B = fmt.fmt(b, fmt.omega) AB = [A[i] * B[i] % mod for i in range(n)] ab = fmt.ifmt(AB) print(*ab[-(N + M): -1]) ``` No
97,603
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two integer arrays a_0, a_1, ..., a_{N - 1} and b_0, b_1, ..., b_{M - 1}. Calculate the array c_0, c_1, ..., c_{(N - 1) + (M - 1)}, defined by c_i = \sum_{j = 0}^i a_j b_{i - j} \bmod 998244353. Constraints * 1 \leq N, M \leq 524288 * 0 \leq a_i, b_i < 998244353 * All values in Input are integer. Input Input is given from Standard Input in the following format: N M a_0 a_1 ... a_{N-1} b_0 b_1 ... b_{M-1} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Examples Input 4 5 1 2 3 4 5 6 7 8 9 Output 5 16 34 60 70 70 59 36 Input 1 1 10000000 10000000 Output 871938225 Submitted Solution: ``` import types _atcoder_code = """ # Python port of AtCoder Library. __version__ = '0.0.1' """ atcoder = types.ModuleType('atcoder') exec(_atcoder_code, atcoder.__dict__) _atcoder__bit_code = """ def _ceil_pow2(n: int) -> int: x = 0 while (1 << x) < n: x += 1 return x def _bsf(n: int) -> int: x = 0 while n % 2 == 0: x += 1 n //= 2 return x """ atcoder._bit = types.ModuleType('atcoder._bit') exec(_atcoder__bit_code, atcoder._bit.__dict__) _atcoder__math_code = """ import typing def _is_prime(n: int) -> bool: ''' Reference: M. Forisek and J. Jancina, Fast Primality Testing for Integers That Fit into a Machine Word ''' if n <= 1: return False if n == 2 or n == 7 or n == 61: return True if n % 2 == 0: return False d = n - 1 while d % 2 == 0: d //= 2 for a in (2, 7, 61): t = d y = pow(a, t, n) while t != n - 1 and y != 1 and y != n - 1: y = y * y % n t <<= 1 if y != n - 1 and t % 2 == 0: return False return True def _inv_gcd(a: int, b: int) -> typing.Tuple[int, int]: a %= b if a == 0: return (b, 0) # Contracts: # [1] s - m0 * a = 0 (mod b) # [2] t - m1 * a = 0 (mod b) # [3] s * |m1| + t * |m0| <= b s = b t = a m0 = 0 m1 = 1 while t: u = s // t s -= t * u m0 -= m1 * u # |m1 * u| <= |m1| * s <= b # [3]: # (s - t * u) * |m1| + t * |m0 - m1 * u| # <= s * |m1| - t * u * |m1| + t * (|m0| + |m1| * u) # = s * |m1| + t * |m0| <= b s, t = t, s m0, m1 = m1, m0 # by [3]: |m0| <= b/g # by g != b: |m0| < b/g if m0 < 0: m0 += b // s return (s, m0) def _primitive_root(m: int) -> int: if m == 2: return 1 if m == 167772161: return 3 if m == 469762049: return 3 if m == 754974721: return 11 if m == 998244353: return 3 divs = [2] + [0] * 19 cnt = 1 x = (m - 1) // 2 while x % 2 == 0: x //= 2 i = 3 while i * i <= x: if x % i == 0: divs[cnt] = i cnt += 1 while x % i == 0: x //= i i += 2 if x > 1: divs[cnt] = x cnt += 1 g = 2 while True: for i in range(cnt): if pow(g, (m - 1) // divs[i], m) == 1: break else: return g g += 1 """ atcoder._math = types.ModuleType('atcoder._math') exec(_atcoder__math_code, atcoder._math.__dict__) _atcoder_modint_code = """ from __future__ import annotations import typing # import atcoder._math class ModContext: context = [] def __init__(self, mod: int) -> None: assert 1 <= mod self.mod = mod def __enter__(self) -> None: self.context.append(self.mod) def __exit__(self, exc_type: typing.Any, exc_value: typing.Any, traceback: typing.Any) -> None: self.context.pop() @classmethod def get_mod(cls) -> int: return cls.context[-1] class Modint: def __init__(self, v: int = 0) -> None: self._mod = ModContext.get_mod() if v == 0: self._v = 0 else: self._v = v % self._mod def val(self) -> int: return self._v def __iadd__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): self._v += rhs._v else: self._v += rhs if self._v >= self._mod: self._v -= self._mod return self def __isub__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): self._v -= rhs._v else: self._v -= rhs if self._v < 0: self._v += self._mod return self def __imul__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): self._v = self._v * rhs._v % self._mod else: self._v = self._v * rhs % self._mod return self def __ifloordiv__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): inv = rhs.inv()._v else: inv = atcoder._math._inv_gcd(rhs, self._mod)[1] self._v = self._v * inv % self._mod return self def __pos__(self) -> Modint: return self def __neg__(self) -> Modint: return Modint() - self def __pow__(self, n: int) -> Modint: assert 0 <= n return Modint(pow(self._v, n, self._mod)) def inv(self) -> Modint: eg = atcoder._math._inv_gcd(self._v, self._mod) assert eg[0] == 1 return Modint(eg[1]) def __add__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): result = self._v + rhs._v if result >= self._mod: result -= self._mod return raw(result) else: return Modint(self._v + rhs) def __sub__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): result = self._v - rhs._v if result < 0: result += self._mod return raw(result) else: return Modint(self._v - rhs) def __mul__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): return Modint(self._v * rhs._v) else: return Modint(self._v * rhs) def __floordiv__(self, rhs: typing.Union[Modint, int]) -> Modint: if isinstance(rhs, Modint): inv = rhs.inv()._v else: inv = atcoder._math._inv_gcd(rhs, self._mod)[1] return Modint(self._v * inv) def __eq__(self, rhs: typing.Union[Modint, int]) -> bool: if isinstance(rhs, Modint): return self._v == rhs._v else: return self._v == rhs def __ne__(self, rhs: typing.Union[Modint, int]) -> bool: if isinstance(rhs, Modint): return self._v != rhs._v else: return self._v != rhs def raw(v: int) -> Modint: x = Modint() x._v = v return x """ atcoder.modint = types.ModuleType('atcoder.modint') atcoder.modint.__dict__['atcoder'] = atcoder atcoder.modint.__dict__['atcoder._math'] = atcoder._math exec(_atcoder_modint_code, atcoder.modint.__dict__) ModContext = atcoder.modint.ModContext Modint = atcoder.modint.Modint _atcoder_convolution_code = """ import typing # import atcoder._bit # import atcoder._math # from atcoder.modint import ModContext, Modint _sum_e = {} # _sum_e[i] = ies[0] * ... * ies[i - 1] * es[i] def _butterfly(a: typing.List[Modint]) -> None: g = atcoder._math._primitive_root(a[0].mod()) n = len(a) h = atcoder._bit._ceil_pow2(n) if a[0].mod() not in _sum_e: es = [0] * 30 # es[i]^(2^(2+i)) == 1 ies = [0] * 30 cnt2 = atcoder._bit._bsf(a[0].mod() - 1) e = Modint(g).pow((a[0].mod() - 1) >> cnt2) ie = e.inv() for i in range(cnt2, 1, -1): # e^(2^i) == 1 es[i - 2] = e ies[i - 2] = ie e *= e ie *= ie sum_e = [0] * 30 now = Modint(1) for i in range(cnt2 - 2): sum_e[i] = es[i] * now now *= ies[i] _sum_e[a[0].mod()] = sum_e else: sum_e = _sum_e[a[0].mod()] for ph in (1, h + 1): w = 1 << (ph - 1) p = 1 << (h - ph) now = Modint(1) for s in range(w): offset = s << (h - ph + 1) for i in range(p): left = a[i + offset] right = a[i + offset + p] * now a[i + offset] = left + right a[i + offset + p] = left - right now *= sum_e[atcoder._bit._bsf(~s)] _sum_ie = {} # _sum_ie[i] = es[0] * ... * es[i - 1] * ies[i] def _butterfly_inv(a: typing.List[Modint]) -> None: g = atcoder._math._primitive_root(a[0].mod()) n = len(a) h = atcoder._bit.ceil_pow2(n) if a[0].mod() not in _sum_ie: es = [0] * 30 # es[i]^(2^(2+i)) == 1 ies = [0] * 30 cnt2 = atcoder._bit._bsf(a[0].mod() - 1) e = Modint(g).pow((a[0].mod() - 1) >> cnt2) ie = e.inv() for i in range(cnt2, 1, -1): # e^(2^i) == 1 es[i - 2] = e ies[i - 2] = ie e *= e ie *= ie sum_ie = [0] * 30 now = Modint(1) for i in range(cnt2 - 2): sum_ie[i] = ies[i] * now now *= es[i] _sum_ie[a[0].mod()] = sum_ie else: sum_ie = _sum_ie[a[0].mod()] for ph in range(h, 0, -1): w = 1 << (ph - 1) p = 1 << (h - ph) inow = Modint(1) for s in range(w): offset = s << (h - ph + 1) for i in range(p): left = a[i + offset] right = a[i + offset + p] a[i + offset] = left + right a[i + offset + p] = (a[0].mod() + left.val() - right.val()) * inow.val() inow *= sum_ie[atcoder._bit._bsf(~s)] def convolution_mod(a: typing.List[Modint], b: typing.List[Modint]) -> typing.List[Modint]: n = len(a) m = len(b) if n == 0 or m == 0: return [] if min(n, m) <= 60: if n < m: n, m = m, n a, b = b, a ans = [Modint(0) for _ in range(n + m - 1)] for i in range(n): for j in range(m): ans[i + j] += a[i] * b[j] return ans z = 1 << atcoder._bit._ceil_pow2(n + m - 1) while len(a) < z: a.append(Modint(0)) _butterfly(a) while len(b) < z: b.append(Modint(0)) _butterfly(b) for i in range(z): a[i] *= b[i] _butterfly_inv(a) a = a[:n + m - 1] iz = Modint(z).inv() for i in range(n + m - 1): a[i] *= iz return a def convolution(mod: int, a: typing.List[typing.Any], b: typing.List[typing.Any]) -> typing.List[typing.Any]: n = len(a) m = len(b) if n == 0 or m == 0: return [] with ModContext(mod): a2 = list(map(Modint, a)) b2 = list(map(Modint, b)) return list(map(lambda c: c.val(), convolution_mod(a2, b2))) def convolution_int( a: typing.List[int], b: typing.List[int]) -> typing.List[int]: n = len(a) m = len(b) if n == 0 or m == 0: return [] mod1 = 754974721 # 2^24 mod2 = 167772161 # 2^25 mod3 = 469762049 # 2^26 m2m3 = mod2 * mod3 m1m3 = mod1 * mod3 m1m2 = mod1 * mod2 m1m2m3 = mod1 * mod2 * mod3 i1 = atcoder._math._inv_gcd(mod2 * mod3, mod1)[1] i2 = atcoder._math._inv_gcd(mod1 * mod3, mod2)[1] i3 = atcoder._math._inv_gcd(mod1 * mod2, mod3)[1] c1 = convolution(mod1, a, b) c2 = convolution(mod2, a, b) c3 = convolution(mod3, a, b) c = [0] * (n + m - 1) for i in range(n + m - 1): c[i] += (c1[i] * i1) % mod1 * m2m3 c[i] += (c2[i] * i2) % mod2 * m1m3 c[i] += (c3[i] * i3) % mod3 * m1m2 c[i] %= m1m2m3 return c """ atcoder.convolution = types.ModuleType('atcoder.convolution') atcoder.convolution.__dict__['atcoder'] = atcoder atcoder.convolution.__dict__['atcoder._bit'] = atcoder._bit atcoder.convolution.__dict__['atcoder._math'] = atcoder._math atcoder.convolution.__dict__['ModContext'] = atcoder.modint.ModContext atcoder.convolution.__dict__['Modint'] = atcoder.modint.Modint exec(_atcoder_convolution_code, atcoder.convolution.__dict__) convolution_int = atcoder.convolution.convolution_int # https://atcoder.jp/contests/practice2/tasks/practice2_f import sys # from atcoder.convolution import convolution_int def main() -> None: n, m = map(int, sys.stdin.readline().split()) a = list(map(int, sys.stdin.readline().split())) b = list(map(int, sys.stdin.readline().split())) c = convolution_int(a, b) print(' '.join([str(ci % 998244353) for ci in c])) if __name__ == '__main__': main() ``` No
97,604
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two integer arrays a_0, a_1, ..., a_{N - 1} and b_0, b_1, ..., b_{M - 1}. Calculate the array c_0, c_1, ..., c_{(N - 1) + (M - 1)}, defined by c_i = \sum_{j = 0}^i a_j b_{i - j} \bmod 998244353. Constraints * 1 \leq N, M \leq 524288 * 0 \leq a_i, b_i < 998244353 * All values in Input are integer. Input Input is given from Standard Input in the following format: N M a_0 a_1 ... a_{N-1} b_0 b_1 ... b_{M-1} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Examples Input 4 5 1 2 3 4 5 6 7 8 9 Output 5 16 34 60 70 70 59 36 Input 1 1 10000000 10000000 Output 871938225 Submitted Solution: ``` ''' 参考: https://maspypy.com/%E6%95%B0%E5%AD%A6%E3%83%BBnumpy-%E9%AB%98%E9%80%9F%E3%83%95%E3%83%BC%E3%83%AA%E3%82%A8%E5%A4%89%E6%8F%9Bfft%E3%81%AB%E3%82%88%E3%82%8B%E7%95%B3%E3%81%BF%E8%BE%BC%E3%81%BF ''' import numpy as np from numpy.fft import rfft,irfft def convolve(a1,a2): n = 2**(len(a1)+len(a2)+1).bit_length() b1,b2=np.zeros(n),np.zeros(n) b1[:len(a1)], b2[:len(a2)]= a1,a2 return (irfft(rfft(b1)*rfft(b2))+0.5).astype(int) def convolve_large(f,g,mod,shift=15): f1,f2 = np.divmod(f,1<<shift) g1,g2 = np.divmod(g,1<<shift) a = convolve(f1,g1) % mod c = convolve(f2,g2) % mod b = (convolve(f1+f2,g1+g2) - (a+c)) % mod h = (a << shift*2) + (b << shift) + c return h % mod def convolve_large2(f,g,mod,shift=15): f1,f2 = np.divmod(f,1<<shift) g1,g2 = np.divmod(g,1<<shift) a = convolve_large(f1,g1,mod) % mod c = convolve_large(f2,g2,mod) % mod b = (convolve_large(f1+f2,g1+g2,mod) - (a+c)) % mod h = (a << shift*2) + (b << shift) + c return h % mod N,M=map(int,input().split()) *A,=map(int,input().split()) *B,=map(int,input().split()) mod = 998244353 print(*convolve_large2(A,B,mod,30)[:N+M-1]) ``` No
97,605
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given two integer arrays a_0, a_1, ..., a_{N - 1} and b_0, b_1, ..., b_{M - 1}. Calculate the array c_0, c_1, ..., c_{(N - 1) + (M - 1)}, defined by c_i = \sum_{j = 0}^i a_j b_{i - j} \bmod 998244353. Constraints * 1 \leq N, M \leq 524288 * 0 \leq a_i, b_i < 998244353 * All values in Input are integer. Input Input is given from Standard Input in the following format: N M a_0 a_1 ... a_{N-1} b_0 b_1 ... b_{M-1} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Output Print the answer in the following format: c_0 c_1 ... c_{(N - 1) + (M - 1)} Examples Input 4 5 1 2 3 4 5 6 7 8 9 Output 5 16 34 60 70 70 59 36 Input 1 1 10000000 10000000 Output 871938225 Submitted Solution: ``` k, K = 80, 1 << 80 nu = lambda L: int("".join([bin(a)[2:].zfill(k) for a in L[::-1]]), 2) st = lambda n: bin(n)[2:].zfill((len(A)+len(B)-1)*k) + "_" li = lambda s: [int(a, 2) % 998244353 for a in [s[-(i+1)*k-1:-i*k-1] for i in range(len(A)+len(B)-1)]] input() A = [int(a) for a in input().split()] B = [int(a) for a in input().split()] print(*li(st(nu(A) * nu(B)))) ``` No
97,606
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` X=int(input()) c=int(100) i=0 while c<X: c=int(1.01*c) i+=1 print(i) ```
97,607
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` x=int(input()) a=100 b=0 while a<x: a=int(a*1.01) b+=1 print(b) ```
97,608
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` X=int(input()) t=100 ans=0 while t<X: ans+=1 t=int(t*1.01) print(ans) ```
97,609
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` #abc165b x=float(input()) p=100.0 s=0 while p<x: p+=p//100 s+=1 print(s) ```
97,610
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` x=int(input()) n=100 k=0 while n<x: n=n*101//100 k+=1 print(k) ```
97,611
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` x=int(input()) y=0 mon=100 while x>mon: mon+=mon//100 y+=1 print(y) ```
97,612
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` X=int(input()) c=100 d=0 while c<X: c=int(c*1.01) d+=1 print(d) ```
97,613
Provide a correct Python 3 solution for this coding contest problem. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 "Correct Solution: ``` X=int(input()) p=100;ytd=0 while p<X: p=int(p*1.01) ytd=ytd+1 print(ytd) ```
97,614
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` x=int(input()) n=100 ans=0 while n<x: ans+=1 n+=int(n/100) print(ans) ``` Yes
97,615
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` x=int(input()) i=0 s=100 while s<x: s=int(s*1.01) i+=1 print(i) ``` Yes
97,616
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` x=int(input()) m=100 y=0 while m<x: y+=1 m=int(m*1.01) print(y) ``` Yes
97,617
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` X=int(input()) y=100 i=0 while y<X: y=int(y*1.01) i+=1 print(i) ``` Yes
97,618
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` x=int(input()) a=100 k=0 while(1): k+=1 a=a+a(1//100) if(a>=x):break print(k) ``` No
97,619
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` def compound_interest(principle, rate, time): CI = principle * (pow((1 + rate / 100), time)) return CI x=int(input()) for i in range (1,100000): ci=int(compound_interest(100, 1, i)) if(ci>=x): print(i) break ``` No
97,620
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` x = int(input()) i = 0 k = 100 while True: if(k>=x): break else: k*=1.01 i+=1 print(i) ``` No
97,621
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank. The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.) Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time? Constraints * 101 \le X \le 10^{18} * All values in input are integers. Input Input is given from Standard Input in the following format: X Output Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time. Examples Input 103 Output 3 Input 1000000000000000000 Output 3760 Input 1333333333 Output 1706 Submitted Solution: ``` X = input() Money = 100 counter = 0 while int(X) > Money: Money = Money*1.01 counter = counter + 1 print(counter) ``` No
97,622
Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` n,a,b=map(int,input().split()) if (b-a-1)%2==1: print((b-a-1)//2+1) else: print(min(a-1,n-b)+1+(b-a-2)//2+1) ```
97,623
Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` n,a,b=map(int,input().split()) if (b-a)%2==0: print((b-a)//2) else: print(min(a-1+1+(b-a-1)//2,n-b+1+(n-(a+n-b+1))//2)) ```
97,624
Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` n,a,b = map(int,input().split()) if (b-a)%2==0: print(int((b-a)//2)) else: print(int(min(a-1,n-b)+1+(b-1-a)//2)) ```
97,625
Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` n, a, b = map(int, input().split()) dif = b-a if dif%2 == 0: print(dif//2) else: print(min(a-1, n-b)+1+(b-a-1)//2) ```
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Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` n, a, b = map(int, input().split()) d = b - a print((d % 2 and min(a, n - b + 1)) + d // 2) ```
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Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` n,a,b=map(int,input().split()) print((b-a)//2 if (b-a)%2==0 else min(a-1,n-b)+(b-a)//2+1) ```
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Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` n,a,b=map(int,input().split()) if (b-a)%2==0: print((b-a)//2) else: c=b-a+1 print(c%2+c//2+min(a-1,n-b)) ```
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Provide a correct Python 3 solution for this coding contest problem. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 "Correct Solution: ``` N, A, B = map(int, input().split()) dif = B-A if dif%2 == 0: print(dif//2) else: print(min(A-1, N-B)+1+dif//2) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` n,a,b=map(int,input().split()) if (b-a)%2==0: print((b-a)//2) else: x=min(a-1,n-b) y=(b-a-1)//2 print(x+y+1) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` N,A,B = map(int,input().split()) if((B-A+1)%2==1): print((B-A)//2) else: print(min(A-1,N-B)+1+(B-A-1)//2) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` N, A, B = map(int,input().split()) if (A-B)%2 == 0: print(abs(A-B)//2) else: print(min((A+B-1)//2,(2*N-(A+B)+1)//2)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` n,a,b= map(int, input().split()) if (b-a)%2==0: print((b-a)//2) else: print(min((a-1)+((1+b-a)//2),(n-b)+(1+b-a)//2)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` import math n,a,b = map(int,input().split()) ans = ((b-a)/2) if int(ans) == ans: print(round(ans)) else: print(math.ceil(ans)) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` n,a,b=map(int,input().split()) cnt=0 if (b-a)%2 == 0: cnt=round(b-(b+a)/2) print(cnt) exit() if (b-a)%2 == 1: if a==1: if b==n: c=n-a d=round(1+((b-1)-(((b-1)+a)/2))) cnt=min(c,d) print(cnt) exit() if b==n: if a==1: c=b-1 d=round(1+(b-(b+a+1)/2)) cnt=min(c,d) print(cnt) exit() if a-1 >= n-b: cnt=round(n-a) print(cnt) exit() if a-1 <= n-b: cnt=round(b-1) print(cnt) exit() ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` a = list(map(int, input().split())) N,A,B = a[0],a[1],a[2] dim = B - A if dim % 2 == 0: print(int(dim/2)) if dim % 2 == 1: dimAN = N - A dimBN = N - B dimB1 = B - 1 dimA1 = A - 1 if dimAN > dimB1:#Aが1にいって折り返す print(dimA1 + int((dim-1)/2)+1) elif dimAN < dimB1: print(dimBN + int((dim-1)/2)+1) elif dimAN == dimB1: print(dimB1 + int((dim-1)/2)+1) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. 2N players are running a competitive table tennis training on N tables numbered from 1 to N. The training consists of rounds. In each round, the players form N pairs, one pair per table. In each pair, competitors play a match against each other. As a result, one of them wins and the other one loses. The winner of the match on table X plays on table X-1 in the next round, except for the winner of the match on table 1 who stays at table 1. Similarly, the loser of the match on table X plays on table X+1 in the next round, except for the loser of the match on table N who stays at table N. Two friends are playing their first round matches on distinct tables A and B. Let's assume that the friends are strong enough to win or lose any match at will. What is the smallest number of rounds after which the friends can get to play a match against each other? Constraints * 2 \leq N \leq 10^{18} * 1 \leq A < B \leq N * All input values are integers. Input Input is given from Standard Input in the following format: N A B Output Print the smallest number of rounds after which the friends can get to play a match against each other. Examples Input 5 2 4 Output 1 Input 5 2 3 Output 2 Submitted Solution: ``` n, a, b = map(int, input().split()) ab = b-a if ab%2 == 0: print(ab//2) else: if ab == 1: print(b-1) elif n-b > a: if (b-(a-1)-1) %2==0: print((b-a-1-1)//2 + (a-1)) else: print((b-a-2-1)//2 + (a-1)) else: if (n-(a+n-b))%2==0: print((n-a+n-b)//2 + (n-b)) else: print((n-a+n-b+1)//2 + (n-b)) ``` No
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` N = int(input()) A = list(map(int, input().split())) B = list(map(int, input().split())) + [0] res, p = 0, 0 for i in range(N+1): pp = B[i]+p res += min(A[i], pp) p = max(min(pp-A[i], B[i]), 0) print(res) ```
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` N = int(input()) A = [int(i) for i in input().split()] B = [int(i) for i in input().split()] cnt = 0 for i in range(N): cnt += min(A[i]+A[i+1], B[i]) if A[i] < B[i]: A[i+1] = max(A[i+1]+A[i]-B[i], 0) print(cnt) ```
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` N=int(input()) A=list(map(int,input().split())) B=list(map(int,input().split())) ans=0 for i in range(N): a=min(A[i],B[i]) B[i]-=a b=min(A[i+1],B[i]) A[i+1]-=b ans+=a+b print(ans) ```
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` N = int(input()) A = list(map(int, input().split())) B = list(map(int, input().split())) ans = 0 for i in range(N): a = min(A[i], B[i]) b = min(A[i+1], B[i] - a) A[i+1] -= b ans += (a + b) print(ans) ```
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` f = lambda : list(map(int, input().split())) n = int(input()) la = f() lb = f() tmp = 0 ans = 0 for i in range(n): m = min(la[i], tmp+lb[i]) tmp = min(tmp+lb[i]-m, lb[i]) ans += m print(ans + min(la[n], tmp)) ```
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` N=int(input()) f=lambda:map(int,input().split()) *A,=f() *B,=f() cnt=0 for i in range(len(B)): a=min(A[i], B[i]) cnt+=a a=min(A[i+1],B[i]-a) cnt+=a A[i+1]-=a print(cnt) ```
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` #!/usr/bin/env python3 n, p, *a = map(int, open(0).read().split()) c = 0 for a, b in zip(a, a[n:]): c += min(p+a, b) p = a - max(min(b-p, a), 0) print(c) ```
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Provide a correct Python 3 solution for this coding contest problem. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 "Correct Solution: ``` n=int(input()) a=list(map(int,input().split())) b=list(map(int,input().split())) ans=0 for i in range(n): ans+=min(b[i],a[i]+a[i+1]) n1=min(a[i],b[i]) b[i]-=n1 a[i+1]=max(0,a[i+1]-b[i]) print(ans) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` n = int(input()) *a, = map(int, input().split()) *b, = map(int, input().split()) s = sum(a) for i in range(n): c = min(a[i], b[i]) a[i] -= c b[i] -= c a[i+1] = max(0, a[i+1]-b[i]) print(s - sum(a)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` n=int(input()) a=list(map(int,input().split())) b=list(map(int,input().split())) cnt=0 for i in range(n): f_1 = min(a[i],b[i]) f_2 = max(0,min(a[i+1],b[i]-a[i])) cnt += f_1+f_2 a[i] -= f_1 a[i+1] -= f_2 print(cnt) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` n=int(input()) a=list(map(int,input().split())) b=list(map(int,input().split())) ans=0 for i in range(n): ans+=min(a[i],b[i]) if b[i]-a[i]>0: ans+=min(b[i]-a[i],a[i+1]) a[i+1]-=min(b[i]-a[i],a[i+1]) print(ans) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` N = int(input()) A = list(map(int, input().split())) B = list(map(int, input().split())) res = 0 for n in range(N): b = min(A[n], B[n]) B[n] -= b b2 = min(A[n + 1], B[n]) A[n + 1] -= b2 res += b + b2 print(res) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` N = int(input()) A = [int(i) for i in input().split()] B = [int(i) for i in input().split()] ans = 0 bef = 0 for i in range(N): A[i] -= bef ans += bef if B[i] < A[i]: ans += B[i] bef = 0 else: ans += A[i] bef = B[i] -A[i] ans += min(A[-1],bef) print(ans) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` n = int(input()) a = list(map(int,input().split())) b = list(map(int,input().split())) kill = 0 for i in range(n): for j in range(i,i+2): if b[i] <= a[j]: kill += b[i] a[j] -= b[i] continue else: kill += a[j] b[i] -= a[j] print(kill) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` N=int(input()) A=list(map(int,input().split())) B=list(map(int,input().split())) ans=0 for i in range(N): p=min(A[i]+A[i+1],B[i]) ans=ans+p if A[i]+A[i+1]<=B[i]: A[i+1]=max(0,A[i+1]-B[i]) print(ans) ``` No
97,653
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are N+1 towns. The i-th town is being attacked by A_i monsters. We have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters. What is the maximum total number of monsters the heroes can cooperate to defeat? Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * 1 \leq A_i \leq 10^9 * 1 \leq B_i \leq 10^9 Input Input is given from Standard Input in the following format: N A_1 A_2 ... A_{N+1} B_1 B_2 ... B_N Output Print the maximum total number of monsters the heroes can defeat. Examples Input 2 3 5 2 4 5 Output 9 Input 3 5 6 3 8 5 100 8 Output 22 Input 2 100 1 1 1 100 Output 3 Submitted Solution: ``` N = int(input()) A = input().split() B = input().split() for i in range(N+1): A[i] = int(A[i]) for i in range(N): B[i] = int(B[i]) Ans = 0 yo = 0 chinpo = True for i in range(N-1): if chinpo: Ans += min(A[i],B[i]) if B[i] > A[i]: yo = B[i] - A[i] chinpo = False else: Ans += min(A[i],B[i]+yo) chinpo = True if yo >= A[i]: yo = B[i] chinpo = False elif B[i]+yo >= A[i]: yo = B[i]+B[i-1]-A[i-1] chinpo = False if not chinpo: if B[N-1]+B[N-2]-A[N-2]-A[N-1] >= A[N]: Ans += A[N] else: Ans += B[N-1]+B[N-2]-A[N-2]-A[N-1] print(Ans) ``` No
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Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` n = int(input()) a = list(input()) b = list(set(a)) ans = 1 for i in b: ans %= 10**9+7 ans *= a.count(i)+1 print((ans-1)%(10**9+7)) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` _,s=open(0);a=1 for i in set(s):a*=s.count(i)+1 print(a//2%(10**9+7)-1) ```
97,656
Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` n=int(input()) s=input() cnt=[0]*26 for i in s:cnt[ord(i)-ord('a')]+=1 mo=10**9+7 r=1 for i in cnt: r*=i+1 r%=mo print((r-1+mo)%mo) ```
97,657
Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` N=int(input()) X=[0 for i in range(26)] S=input() for i in S: X[ord(i)-97]+=1 ans=1 P=10**9+7 for i in X: ans=ans*(i+1) ans%=P ans-=1 print(ans) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` N = int(input()) S = input() ans = 1 for c in range(ord('a'), ord('z') + 1): ans *= S.count(chr(c)) + 1 print((ans-1) % (10**9 + 7)) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` from collections import Counter n = int(input()) S = input() mod = 10**9+7 n = Counter(S) ans = 1 for i, j in n.items(): ans *= (j+1) print((ans-1)%mod) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` from collections import Counter n=int(input()) s=input() S=Counter(s) ans=1 for i in S.values(): ans *=i+1 print((ans-1)%(10**9+7)) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 "Correct Solution: ``` MOD=10**9+7 N=int(input()) S=input() cnt=[0]*26 for x in S: cnt[ord(x)-97]+=1 res=1 for i in range(26): res=res*(cnt[i]+1)%MOD print(res-1) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` n,s=open(0);a=1 for c in set(s.strip()):a*=s.count(c)+1 print(~-a%(10**9+7)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` cnt = [0] * 26 n = int(input()) s = input() for c in s: cnt[ord(c) - ord('a')] += 1 res = 1 for i in cnt: res *= i + 1 print((res - 1) % (10 ** 9 + 7)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` n=int(input()) s=input() mod=10**9+7 t=dict() for c in s: t.setdefault(c,1) t[c]+=1 ans=1 for v in t.values(): ans=ans*v%mod print(ans-1) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` from collections import Counter n,s=int(input()),input();c=[s[i]for i in range(n)];a=Counter(c);ans=1 for i in a:ans*=a[i]+1 print((ans-1)%(10**9+7)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` import string n = int(input()) s = input() total = 2**n-1 k = 0 for i in string.ascii_lowercase: c = s.count(i) if c > 1: l = 2**(n-c) total -= l k += c - 1 if k > 1: total += k print(total) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` N = int(input()) S = input() ans = 1 for c in [chr(x) for x in range(97, 97 + 26)]: ans *= S.count(c) + 1 print(ans - 1) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` N = int(input()) S = input() iD = 10**9+7 aT={} for s in S: if s in aT: aT[s]+=1 else: aT[s]=1 iRes = (2**N) - 1 iC = 0 iC2 = 0 for s in aT: iT = aT[s] if 1 < iT: iRes -= 2**(N-iT) if 0 < iC : iC2 += 2**(N-iC -iT) iRes += iC2 iC += iT print(iRes % iD) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length N. Among its subsequences, count the ones such that all characters are different, modulo 10^9+7. Two subsequences are considered different if their characters come from different positions in the string, even if they are the same as strings. Here, a subsequence of a string is a concatenation of one or more characters from the string without changing the order. Constraints * 1 \leq N \leq 100000 * S consists of lowercase English letters. * |S|=N Input Input is given from Standard Input in the following format: N S Output Print the number of the subsequences such that all characters are different, modulo 10^9+7. Examples Input 4 abcd Output 15 Input 3 baa Output 5 Input 5 abcab Output 17 Submitted Solution: ``` if __name__ == '__main__': mod = 10**9 +7 N = int(input()) S = str(input()) letter = defaultdict(int) for i in range(N): letter[S[i]] += 1 count = 1 for c in letter: count *= (letter[c]+1) count%mod print(count-1) ``` No
97,670
Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` import math N, M = [int(i) for i in input().split()] for i in range(M//N, 0, -1): if M % i == 0: print(i) break ```
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Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` N,M=map(int,input().split()) ans=0 for i in range(1,int(M**0.5)+1): if M%i==0: if M/i>=N: ans=max(ans,i) if i>=N: ans=max(ans,M//i) print(ans) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` n, m = list(map(int, input().split(" "))) ds = [x for x in range(1, int(m**.5)+1) if m%x==0] ds = ds + [m//x for x in ds] ds = [x for x in ds if x<=m//n] print(max(ds)) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` N,M=map(int,input().split()) a=1 for i in range(1,4*10000): if M%i: continue if M//i>=N and i>a: a=i if i>=N and M//i>a: a=M//i print(a) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` from math import sqrt N, M = map(int, input().split()) ans = max(M // i if M // i <= M / N else i for i in range(1, int(sqrt(M)) + 1) if M % i == 0 and i <= M / N) print(ans) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` n,m=map(int,input().split()) ans=1 for i in range(1,int(m**0.5)+1): if m%i==0: y=m//i if m//i>=n and ans<i: ans=i if m//y>=n and ans<y: ans=y print(ans) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` import sys n,m=map(int,input().split()) a=m//n ans=1 if m%n==0: print(int(m//n)) sys.exit() for i in range(1,a+1): if m%i==0: ans=max(ans,i) print(ans) ```
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Provide a correct Python 3 solution for this coding contest problem. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 "Correct Solution: ``` n,m = map(int,input().split()) ans = 1 for i in range(1,int(m**0.5)+1): if m%i!=0:continue if m//i>=n: ans = max(i,ans) if i>=n: ans = max(m//i,ans) print(ans) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` n,m=map(int,input().split()) a=[] for i in range(1,int(m**.5)+1): if m%i==0: if m//i>=n:a+=[i] if i>=n:a+=[m//i] print(max(a)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` N,M=map(int,input().split()) base=M//N li=[] for i in range(1,int(pow(M,1/2))+1): if i<=base and M%i==0: li.append(i) if M%i==0 and M//i<=base: li.append(M//i) print(max(li)) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` N, M = map(int, input().split()) ans = 1 for i in range(1, int(M**0.5)+1): if M % i == 0 and M//N >= i: ans = max(ans, i) if M//N >= M//i: ans = max(ans, M//i) print(ans) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` N,M = map(int,input().split()) gcd = M//N while gcd*N!=M: gcd = M//N N = 1+(M-1)//gcd print(gcd) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` n,m=map(int,input().split()) num=m//n ans=0 for i in range(int(m**0.5),1,-1): Num=i if m%i==0: Num1=m//i if m//i<=num else 0 if Num>num: Num=0 ans=max(ans,Num,Num1) print(ans) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` # D - Partition # Mの約数で、しかもN倍してもMを超えないもののうち、最大のものを探す N, M = map(int, input().split()) x = 1 while x * N <= M: if M % x == 0: ans = x x += 1 print(ans) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` import math N, M = map(int,input().split()) j=1 for i in range(1, int(math.sqrt(M))+2): if M%i==0: if i <= M//N and j < i: j=i if M/i <= M//N and j < M/i: j=M/i print(j) ``` No
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given integers N and M. Consider a sequence a of length N consisting of positive integers such that a_1 + a_2 + ... + a_N = M. Find the maximum possible value of the greatest common divisor of a_1, a_2, ..., a_N. Constraints * All values in input are integers. * 1 \leq N \leq 10^5 * N \leq M \leq 10^9 Input Input is given from Standard Input in the following format: N M Output Print the maximum possible value of the greatest common divisor of a sequence a_1, a_2, ..., a_N that satisfies the condition. Examples Input 3 14 Output 2 Input 10 123 Output 3 Input 100000 1000000000 Output 10000 Submitted Solution: ``` import sys ## io ## def IS(): return sys.stdin.readline().rstrip() def II(): return int(IS()) def MII(): return list(map(int, IS().split())) def MIIZ(): return list(map(lambda x: x-1, MII())) ## dp ## def DD2(d1,d2,init=0): return [[init]*d2 for _ in range(d1)] def DD3(d1,d2,d3,init=0): return [DD2(d2,d3,init) for _ in range(d1)] ## math ## def divc(x,y) -> int: return -(-x//y) def divf(x,y) -> int: return x//y def gcd(x,y): while y: x,y = y,x%y return x def lcm(x,y): return x*y//gcd(x,y) def enumerate_divs(n): """Return a tuple list of divisor of n""" return [(i,n//i) for i in range(1,int(n**0.5)+1) if n%i==0] def get_primes(n=10**3): """Return a list of prime numbers n or less""" is_prime = [True]*(n+1) is_prime[0] = is_prime[1] = False for i in range(2, int(n**0.5)+1): if not is_prime[i]: continue for j in range(i*2, n+1, i): is_prime[j] = False return [i for i in range(n+1) if is_prime[i]] def prime_factor(n): """Return a list of prime factorization numbers of n""" res = [] for i in range(2,int(n**0.5)+1): while n%i==0: res.append(i); n //= i if n != 1: res.append(n) return res ## const ## MOD=10**9+7 ## libs ## import itertools as it import functools as ft from collections import deque, Counter from heapq import heapify, heappop, heappush from bisect import bisect_left #======================================================# def main(): n, m = MII() divs = enumerate_divs(m) ans = [] h = m/n for i,j in divs: if i <= h: ans.append(i) if j <= h: ans.append(i) print(max(ans)) if __name__ == '__main__': main() ``` No
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` import sys N = int(input()) if N == 3: print('2 5 63') sys.exit() if N == 4: print('2 5 20 63') sys.exit() if N == 5: print('2 3 6 4 9') sys.exit() S = '2 3 6 4 9' N -= 5 print(S, end='') if N == 1: print(' 12') sys.exit() for i in range(5001): Tmp1 = 6 * i + 8 Tmp2 = 6 * i + 10 if Tmp2 > 30000: break print(' %d %d' %(Tmp1, Tmp2) , end='') N -= 2 if N == 0: print() sys.exit() elif N == 1: print(' 12') sys.exit() for i in range(5001): Tmp1 = 12 * i + 15 Tmp2 = 12 * i + 21 if Tmp2 > 30000: break print(' %d %d' %(Tmp1, Tmp2), end='') N -= 2 if N == 0: print() sys.exit() elif N == 1: print(' 12') sys.exit() for i in range(N): Tmp1 = 6 * (i + 2) if Tmp1 > 30000: break print(' %d' %(Tmp1) , end='') print() ```
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` n = int(input()) ANS = [] even = [2, 10, 3, 9, 4, 8, 6, 12] odd = [12, 2, 10, 3, 9, 4, 8, 6] if n == 3: print(2, 5, 63) else: p = n // 8 r = n % 8 if r % 2 == 0: tmp = even else: tmp = odd ANS += [12 * i + x for x in tmp for i in range(p)] ANS += [12 * p + x for x in tmp[:r]] print(*ANS) ```
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` n=int(input()) if n==3: print(2,5,63) else: if n%2==0: ans=[3,9] cnt=2 for i in range(30001): if i%6==2: if i+2<=30000: ans.append(i) ans.append(i+2) cnt+=2 if cnt==n: break else: continue if cnt<n: for i in range(12,30001): if i%12==3: if i+9<=30000: ans.append(i) ans.append(i+6) cnt+=2 if cnt==n: break else: continue if cnt<n: for i in range(1,30001): if i%6==0: ans.append(i) cnt+=1 if cnt==n: break print(*ans) else: ans=[3,6,9] cnt=3 for i in range(30001): if i%6==2: if i+2<=30000: ans.append(i) ans.append(i+2) cnt+=2 if cnt==n: break else: continue if cnt<n: for i in range(12,30001): if i%12==3: if i+9<=30000: ans.append(i) ans.append(i+6) cnt+=2 if cnt==n: break else: continue if cnt<n: for i in range(7,30001): if i%6==0: ans.append(i) cnt+=1 if cnt==n: break print(*ans) ```
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` n=int(input()) ret=[2,3,4] if n>=6 else [2,5,63] if n==3 else [2,5,20,63] if n==4 else [2,5,20,30,63] if n>=6: def getnext(a): if a%6==0: return a+2 elif a%6==2: return a+1 elif a%6==3: return a+1 elif a%6==4: return a+2 while len(ret)<n: ret.append(getnext(ret[-1])) if sum(ret)%6==5: ret[-1]=getnext(ret[-1]) elif sum(ret)%6!=0: ret.remove((sum(ret)%6)+6) ret.append(getnext(ret[-1])) while sum(ret)%6!=0: ret[-1]=getnext(ret[-1]) print(" ".join(map(str,ret))) ```
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` N = int(input()) if N == 3: ans = [2, 3, 25] else: # [合計が6の倍数]を常に満たすように追加する if N % 2 == 0: As = [2, 10, 3, 9, 4, 8, 6, 12] else: As = [6, 2, 10, 3, 9, 4, 8, 12] ans = [] for i in range(N): ans.append(As[i % 8] + 12 * (i // 8)) print(' '.join(map(str, ans))) ```
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` n=int(input()) if n==3:exit(print(2,5,63)) l=[6,2,10,3,9,4,8,12]if n%2else[2,10,3,9,4,8,6,12] for i in range(n):print(i//8*12+l[i%8],end=" ") ```
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` n = int(input()) ANS = [] A = [2, 10, 3, 9, 4, 8, 6, 12] if n == 3: print(2, 5, 63) else: p = n // 8 r = n % 8 ANS += [12 * i + a for a in A for i in range(p)] ANS += [12 * p + a for a in A[:r]] if r % 2 == 1: ANS.pop() ANS.append(12 * p + 12) print(*ANS) ```
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Provide a correct Python 3 solution for this coding contest problem. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 "Correct Solution: ``` import sys stdin = sys.stdin def li(): return [int(x) for x in stdin.readline().split()] def li_(): return [int(x)-1 for x in stdin.readline().split()] def lf(): return [float(x) for x in stdin.readline().split()] def ls(): return stdin.readline().split() def ns(): return stdin.readline().rstrip() def lc(): return list(ns()) def ni(): return int(ns()) def nf(): return float(ns()) def solve(n:int) -> list: x6o2 = [(6*i+2, 6*i+4) for i in range(5000)] x6o3 = [(12*i+3, 12*i+9) for i in range(2500)] o6 = [6*i+6 for i in range(5000)] x6 = [] for i in range(2500): x6.append(x6o3[i]) x6.append(x6o2[2*i]) x6.append(x6o2[2*i+1]) ans = [] if n == 3: ans = [2, 5, 63] elif n <= 15000: idx = n//2 for i, (mn,mx) in enumerate(x6[:idx]): ans.extend([mn,mx]) if n%2: ans = ans + [6] else: for i, (mn,mx) in enumerate(x6): ans.extend([mn,mx]) for o6i in o6[:n-15000]: ans.append(o6i) return ans n = ni() print(*solve(n)) ```
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 Submitted Solution: ``` # -*- coding: utf-8 -*- from sys import stdin d_in = lambda: int(stdin.readline()) # N = d_in() MAX = 30000 N = d_in() base = [3, 25, 2, 35, 55] cand = [] for i in range(4, MAX // 2, 2): cand.append(i) cand.append(MAX - i) for i in range(9, MAX // 2, 6): cand.append(i) cand.append(MAX - i) ans = [] if N < 5: ans.extend(base[:3]) if N == 4: ans.append(MAX) elif N % 2 == 1: ans.extend(base) ans.extend(cand[:N-5]) else: ans.extend(base) ans.append(MAX) ans.extend(cand[:N-6]) print(*ans) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 Submitted Solution: ``` import sys from math import gcd sys.setrecursionlimit(10 ** 7) input = sys.stdin.readline f_inf = float('inf') mod = 10 ** 9 + 7 def debug(res): tot = sum(res) for num in res: if gcd(tot - num, num) == 1: return False return True def resolve(): n = int(input()) if n == 3: res = [2, 5, 63] elif n == 4: res = [2, 5, 20, 63] elif n == 5: res = [2, 5, 20, 30, 63] else: nums = [num for num in range(2, 30001) if num % 2 == 0 or num % 3 == 0] res = [nums[i] for i in range(n)] total = sum(res) if total % 6 == 2: res.pop(res.index(8)) for i in range(n, len(nums)): if nums[i] % 6 == 0: res.append(nums[i]) break elif total % 6 == 3: res.pop(res.index(9)) for i in range(n, len(nums)): if nums[i] % 6 == 0: res.append(nums[i]) break elif total % 6 == 5: res.pop(res.index(9)) for i in range(n, len(nums)): if nums[i] % 6 == 4: res.append(nums[i]) break print(*res) # print(debug(res)) if __name__ == '__main__': resolve() ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 Submitted Solution: ``` import sys N=int(input()) if N==3: print(2,5,63) sys.exit() if N==4: print(2,5,20,63) sys.exit() S=[] L=[0,2,3,4] for i in range(1,30001): j=i%6 if j in L: S.append(i) if len(S)==N-1: break s=sum(S) def f(L): return print(' '.join(map(str,L))) if s%6==0: f(S+[30000]) elif s%6==2: f(S+[29998]) elif s%6==3: f(S+[29997]) elif s%6==5: f(S[1:]+[29997,30000]) #print(len(S),s%6) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 Submitted Solution: ``` N = int(input()) if N == 3: ret = [2, 5, 63] else: ret = [] if N <= 15000: if N % 3 == 0: b = 4 else: b = 2 a = N - b else: a = 15000 - N%2 b = N - a for i in range(1, a+1): ret.append(2*i) for i in range(b): ret.append(3*(2 * i + 1)) assert len(ret) == N print(' '.join([str(_) for _ in ret])) ``` Yes
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Nagase is a top student in high school. One day, she's analyzing some properties of special sets of positive integers. She thinks that a set S = \\{a_{1}, a_{2}, ..., a_{N}\\} of distinct positive integers is called special if for all 1 \leq i \leq N, the gcd (greatest common divisor) of a_{i} and the sum of the remaining elements of S is not 1. Nagase wants to find a special set of size N. However, this task is too easy, so she decided to ramp up the difficulty. Nagase challenges you to find a special set of size N such that the gcd of all elements are 1 and the elements of the set does not exceed 30000. Constraints * 3 \leq N \leq 20000 Input Input is given from Standard Input in the following format: N Output Output N space-separated integers, denoting the elements of the set S. S must satisfy the following conditions : * The elements must be distinct positive integers not exceeding 30000. * The gcd of all elements of S is 1, i.e. there does not exist an integer d > 1 that divides all elements of S. * S is a special set. If there are multiple solutions, you may output any of them. The elements of S may be printed in any order. It is guaranteed that at least one solution exist under the given contraints. Examples Input 3 Output 2 5 63 Input 4 Output 2 5 20 63 Submitted Solution: ``` import random def main(): N = int(input().strip()) cand = [] for i in range(30000 // 6): cand.append(6 * i + 2) cand.append(6 * i + 3) cand.append(6 * i + 4) cand.append(6 * i + 6) while True: S = [random.choice(cand) for _ in range(N)] if sum(S) % 6 == 0: break return ' '.join(map(str, S)) if __name__ == '__main__': print(main()) ``` No
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