text stringlengths 198 433k | conversation_id int64 0 109k |
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Provide a correct Python 3 solution for this coding contest problem.
Today's Random Number
E869120 You ran a campaign called "Today's Random Numbers" for N days. This is a project to generate a random number once a day and post the value on Twitter.
The "random numbers of the day" on day $ 1, 2, 3, \ dots, N $ were $ A_1, A_2, A_3, \ dots, A_N $, respectively.
E869120 You would be happy if today's random number is higher than yesterday's random number.
How many times in the $ N $ day did E869120 make you happy with "Today's Random Numbers"?
input
Input is given from standard input in the following format.
$ N $
$ A_1 $ $ A_2 $ $ A_3 $ $ \ dots $ $ A_N $
output
Print out the number of times E869120 was pleased with "Today's Random Numbers" in one line in $ N $ days.
However, insert a line break at the end.
Constraint
* $ 1 \ leq N \ leq 100000 \ (= 10 ^ 5) $
* $ 1 \ leq A_i \ leq 1000000000 \ (= 10 ^ 9) $
* All inputs are integers.
Input example 1
Five
8 6 9 1 20
Output example 1
2
On the 3rd and 5th days, E869120 is happy.
Input example 2
6
3 3 4 3 3 4
Output example 2
2
On the 3rd and 6th days, E869120 is happy.
Input example 3
Ten
10 9 8 7 6 5 4 3 2 1
Output example 3
0
E869120 You will not be happy with "Today's Random Numbers".
Example
Input
5
8 6 9 1 20
Output
2
"Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
ans = 0
for i in range(n-1):
if a[i] < a[i + 1]:
ans += 1
print(ans)
```
| 97,800 |
Provide a correct Python 3 solution for this coding contest problem.
Today's Random Number
E869120 You ran a campaign called "Today's Random Numbers" for N days. This is a project to generate a random number once a day and post the value on Twitter.
The "random numbers of the day" on day $ 1, 2, 3, \ dots, N $ were $ A_1, A_2, A_3, \ dots, A_N $, respectively.
E869120 You would be happy if today's random number is higher than yesterday's random number.
How many times in the $ N $ day did E869120 make you happy with "Today's Random Numbers"?
input
Input is given from standard input in the following format.
$ N $
$ A_1 $ $ A_2 $ $ A_3 $ $ \ dots $ $ A_N $
output
Print out the number of times E869120 was pleased with "Today's Random Numbers" in one line in $ N $ days.
However, insert a line break at the end.
Constraint
* $ 1 \ leq N \ leq 100000 \ (= 10 ^ 5) $
* $ 1 \ leq A_i \ leq 1000000000 \ (= 10 ^ 9) $
* All inputs are integers.
Input example 1
Five
8 6 9 1 20
Output example 1
2
On the 3rd and 5th days, E869120 is happy.
Input example 2
6
3 3 4 3 3 4
Output example 2
2
On the 3rd and 6th days, E869120 is happy.
Input example 3
Ten
10 9 8 7 6 5 4 3 2 1
Output example 3
0
E869120 You will not be happy with "Today's Random Numbers".
Example
Input
5
8 6 9 1 20
Output
2
"Correct Solution:
```
n = int(input())
a = list(map(int,input().split()))
count = 0
for i in range(1,n):
if a[i-1] < a[i]:
count += 1
print(count)
```
| 97,801 |
Provide a correct Python 3 solution for this coding contest problem.
Today's Random Number
E869120 You ran a campaign called "Today's Random Numbers" for N days. This is a project to generate a random number once a day and post the value on Twitter.
The "random numbers of the day" on day $ 1, 2, 3, \ dots, N $ were $ A_1, A_2, A_3, \ dots, A_N $, respectively.
E869120 You would be happy if today's random number is higher than yesterday's random number.
How many times in the $ N $ day did E869120 make you happy with "Today's Random Numbers"?
input
Input is given from standard input in the following format.
$ N $
$ A_1 $ $ A_2 $ $ A_3 $ $ \ dots $ $ A_N $
output
Print out the number of times E869120 was pleased with "Today's Random Numbers" in one line in $ N $ days.
However, insert a line break at the end.
Constraint
* $ 1 \ leq N \ leq 100000 \ (= 10 ^ 5) $
* $ 1 \ leq A_i \ leq 1000000000 \ (= 10 ^ 9) $
* All inputs are integers.
Input example 1
Five
8 6 9 1 20
Output example 1
2
On the 3rd and 5th days, E869120 is happy.
Input example 2
6
3 3 4 3 3 4
Output example 2
2
On the 3rd and 6th days, E869120 is happy.
Input example 3
Ten
10 9 8 7 6 5 4 3 2 1
Output example 3
0
E869120 You will not be happy with "Today's Random Numbers".
Example
Input
5
8 6 9 1 20
Output
2
"Correct Solution:
```
N = int(input())
A = list(map(int,input().split()))
ans = 0
for k in range(1,N):
if A[k-1] < A[k]:
ans += 1
print(ans)
```
| 97,802 |
Provide a correct Python 3 solution for this coding contest problem.
Today's Random Number
E869120 You ran a campaign called "Today's Random Numbers" for N days. This is a project to generate a random number once a day and post the value on Twitter.
The "random numbers of the day" on day $ 1, 2, 3, \ dots, N $ were $ A_1, A_2, A_3, \ dots, A_N $, respectively.
E869120 You would be happy if today's random number is higher than yesterday's random number.
How many times in the $ N $ day did E869120 make you happy with "Today's Random Numbers"?
input
Input is given from standard input in the following format.
$ N $
$ A_1 $ $ A_2 $ $ A_3 $ $ \ dots $ $ A_N $
output
Print out the number of times E869120 was pleased with "Today's Random Numbers" in one line in $ N $ days.
However, insert a line break at the end.
Constraint
* $ 1 \ leq N \ leq 100000 \ (= 10 ^ 5) $
* $ 1 \ leq A_i \ leq 1000000000 \ (= 10 ^ 9) $
* All inputs are integers.
Input example 1
Five
8 6 9 1 20
Output example 1
2
On the 3rd and 5th days, E869120 is happy.
Input example 2
6
3 3 4 3 3 4
Output example 2
2
On the 3rd and 6th days, E869120 is happy.
Input example 3
Ten
10 9 8 7 6 5 4 3 2 1
Output example 3
0
E869120 You will not be happy with "Today's Random Numbers".
Example
Input
5
8 6 9 1 20
Output
2
"Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
c=0
for i in range(1,n):
if a[i-1]<a[i]:
c+=1
print(c)
```
| 97,803 |
Provide a correct Python 3 solution for this coding contest problem.
Today's Random Number
E869120 You ran a campaign called "Today's Random Numbers" for N days. This is a project to generate a random number once a day and post the value on Twitter.
The "random numbers of the day" on day $ 1, 2, 3, \ dots, N $ were $ A_1, A_2, A_3, \ dots, A_N $, respectively.
E869120 You would be happy if today's random number is higher than yesterday's random number.
How many times in the $ N $ day did E869120 make you happy with "Today's Random Numbers"?
input
Input is given from standard input in the following format.
$ N $
$ A_1 $ $ A_2 $ $ A_3 $ $ \ dots $ $ A_N $
output
Print out the number of times E869120 was pleased with "Today's Random Numbers" in one line in $ N $ days.
However, insert a line break at the end.
Constraint
* $ 1 \ leq N \ leq 100000 \ (= 10 ^ 5) $
* $ 1 \ leq A_i \ leq 1000000000 \ (= 10 ^ 9) $
* All inputs are integers.
Input example 1
Five
8 6 9 1 20
Output example 1
2
On the 3rd and 5th days, E869120 is happy.
Input example 2
6
3 3 4 3 3 4
Output example 2
2
On the 3rd and 6th days, E869120 is happy.
Input example 3
Ten
10 9 8 7 6 5 4 3 2 1
Output example 3
0
E869120 You will not be happy with "Today's Random Numbers".
Example
Input
5
8 6 9 1 20
Output
2
"Correct Solution:
```
n=int(input())
a=list(map(int, input().split()))
ans=0
for i in range(1, n):
if a[i]>a[i-1]:
ans+=1
print(ans)
```
| 97,804 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
from queue import deque
INF = 2**31-1
n, s = map(int, input().split())
A = list(map(int, input().split()))
q = deque()
t = 0
ans = INF
for a in A:
t += a
q.append(a)
if t < s:
continue
while t >=s:
t -=q.popleft()
ans = min(ans,len(q)+1)
print(ans if ans < INF else 0)
```
| 97,805 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
def LI(): return list(map(int, input().split()))
def II(): return int(input())
def LS(): return input().split()
def S(): return input()
def LIR(n): return [LI() for i in range(n)]
def MI(): return map(int, input().split())
#1:set
#1_A
"""
n,q = map(int, input().split(" "))
group = [[i] for i in range(n)]
key = [i for i in range(n)]
for i in range(q):
com, x, y = map(int, input().split(" "))
if com == 0:
if key[x] != key[y]:
v = key[y]
group[key[x]] = group[key[x]] + group[key[y]]
for j in group[v]:
key[j] = key[x]
group[v] = []
if com == 1:
if key[x] == key[y]:
print(1)
else:
print(0)
"""
#1_B
"""
def root(x,n):
if par[x][0] == x:
return [x,n+par[x][1]]
return root(par[x][0],par[x][1])
def unite(x,y):
rx = root(x)
ry = root(y)
if rx[0] == ry[0]:
return
par[rx][0] = ry[0]
par[rx][1] += ry[1]
n,q = map(int, input().split(" "))
par = [[i,0] for i in range(n)]
for i in range(q):
q = list(map(int, input().split(" ")))
if q[0] == 0:
if root(q[1],0) != root(q[])
"""
#2:range quary
#2_A
"""
n,q = map(int, input().split(" "))
k = 2**31-1
a = [float("inf") for i in range(n)]
for i in range(q):
com, x, y = map(int, input().split(" "))
if com == 0:
a[x] = y
else:
mi = k
for j in range(x, y+1):
if a[j] == float("inf"):
mi = min(mi, k)
else:
mi = min(mi,a[j])
print(mi)
"""
#2_B
#2_C
#2_D
#2_E
#2_F
#2_G
#2_H
#2_I
#3:sliding window
#3_A
n,s = MI()
a = LI()
for i in range(1,n):
a[i] += a[i-1]
a.insert(0,0)
l = 0
r = 0
ans = float("inf")
if a[1] >= s:
print(1)
quit()
while r < n:
r += 1
if a[r]-a[l] >= s:
while a[r]-a[l] >= s and l < r:
l += 1
ans = min(ans, r-l+1)
if ans == float("inf"):
print(0)
quit()
print(ans)
#4:coordinate compression
#5:comulative sum
#5_A
"""
n,t = map(int, input().split(" "))
num = [0 for i in range(t)]
for i in range(n):
l,r = map(int, input().split(" "))
num[l] += 1
if r < t:
num[r] -= 1
for i in range(1,t):
num[i] += num[i-1]
print(max(num))
"""
#5_B
"""
n = int(input())
lec = [[0 for i in range(1001)] for j in range(1001)]
max_x = 0
max_y = 0
for i in range(n):
x,y,s,t = map(int, input().split(" "))
lec[y][x] += 1
lec[y][s] -= 1
lec[t][x] -= 1
lec[t][s] += 1
max_x = max(max_x, s)
max_y = max(max_y, t)
for i in range(max_y+1):
for j in range(1, max_x+1):
lec[i][j] += lec[i][j-1]
for i in range(1, max_y+1):
for j in range(max_x+1):
lec[i][j] += lec[i-1][j]
ans = 0
for i in range(max_y+1):
for j in range(max_x+1):
ans = max(ans, lec[i][j])
print(ans)
"""
```
| 97,806 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
from queue import deque
n, s = map(int, input().split())
q = deque()
t = 0
ans = 1e6
for a in map(int, input().split()):
t += a
q.append(a)
if t < s:
continue
while t >= s:
t -= q.popleft()
ans = min(ans, len(q) + 1)
print(ans if ans < 1e6 else 0)
```
| 97,807 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
N, S = map(int, input().split())
a = list(map(int, input().split()))
ans = float('INF')
total = 0
l = r = 0
while r < N:
total += a[r]
r += 1
if total >= S:
while total >= S:
total -= a[l]
l += 1
ans = min(ans, r-l+1)
if ans == float('INF'): ans = 0
print(ans)
```
| 97,808 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
n,s = map(int, input().split())
a = list(map(int, input().split()))
ans = float("inf")
ma = 0
mi = 0
v = 0
for i in range(n):
v += a[i]
if v >= s:
ma = i
while v >= s:
v -= a[mi]
mi += 1
ans = min(ans, ma-mi+2)
ans = ans if ans != float("inf") else 0
print(ans)
```
| 97,809 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
import sys
if __name__ == "__main__":
N, S = map(lambda x: int(x), input().split())
a = list(map(lambda x: int(x), input().split()))
ans = sys.maxsize
s = 0
e = 0
value = 0
for idx in range(N):
value += a[idx]
if (S <= value):
e = idx
while (S <= value):
value -= a[s]
s += 1
ans = min(ans, e - s + 2)
ans = ans if ans != sys.maxsize else 0
print(ans)
```
| 97,810 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
N,S = map(int,input().split(" "))
a = list(map(int,input().split(" ")))
ans = float('inf')
l = 0
r = 0
sumv = 0
while True:
while r < N and sumv < S:
sumv += a[r]
r += 1
if sumv < S:
break
ans = min(ans,r-l)
sumv -= a[l]
l += 1
if ans == float('inf'):
ans = 0
print(ans)
```
| 97,811 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
"Correct Solution:
```
INF = 10**18
N, S = map(int, input().split())
A = list(map(int, input().split()))
res = INF
rt = 0
s = 0
for lt in range(N):
while rt < N and s < S:
s += A[rt]
rt += 1
if s >= S:
res = min(res, rt - lt)
s -= A[lt]
print(res if res != INF else 0)
```
| 97,812 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
#!/usr/bin/env python3
# DSL_3_A: The Smallest Window I
# binary search
def find(xs, size, s):
sum_ = sum(xs[:size])
if s <= sum_:
return True
for i in range(len(xs)-size):
sum_ -= xs[i]
sum_ += xs[i+size]
if s <= sum_:
return True
return False
def run():
n, s = [int(i) for i in input().split()]
li = [int(i) for i in input().split()]
if s > sum(li):
print(0)
return
elif s < max(li):
print(1)
return
i, j = 0, n
while i+1 < j:
# assert(not find(li, i, s))
# assert(find(li, j, s))
mid = (i + j) // 2
# print(i, j, mid)
if find(li, mid, s):
j = mid
else:
i = mid
print(j)
if __name__ == '__main__':
run()
```
Yes
| 97,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
n,s=map(int,input().split( ))
a=list(map(int,input().split( )))
a.append(0)###
min=10000000000
sum_temp=0
i_first=0
i_next=0
while i_next<n:
while sum_temp<s and i_next<=n:###
sum_temp+=a[i_next]
i_next+=1
while sum_temp-a[i_first]>=s:
sum_temp-=a[i_first]
i_first+=1
if i_next-i_first<min and sum_temp>=s:###
min=i_next-i_first
sum_temp-=a[i_first]
i_first+=1
if i_first>=n:
break
if min<10000000000:
print(min)
else:
print(0)
```
Yes
| 97,814 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
import heapq
from collections import deque
from enum import Enum
import sys
import math
from _heapq import heappush, heappop
import copy
BIG_NUM = 2000000000
MOD = 1000000007
EPS = 0.000000001
N,S = map(int,input().split())
table = list(map(int,input().split()))
ans = BIG_NUM
left = 0
right = 0
tmp_sum = table[0]
while left < len(table):
while True:
if tmp_sum >= S:
ans = min(ans,right-left+1)
break
if right == len(table)-1:
break
right += 1
tmp_sum += table[right]
if tmp_sum < S:
break
while True:
if left > right:
break
tmp_sum -= table[left]
left += 1
if tmp_sum >= S:
ans = min(ans,right-left+1)
else:
break
right = max(right,left)
if ans == BIG_NUM:
print("0")
else:
print("%d"%(ans))
```
Yes
| 97,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
#import pysnooper
#import numpy
#import os,re,sys,operator
#from collections import Counter,deque
#from operator import itemgetter
#from itertools import accumulate,combinations,groupby,combinations_with_replacement,permutations
from sys import stdin,setrecursionlimit
from bisect import bisect_left
#from copy import deepcopy
#import heapq
#import math
#import string
setrecursionlimit(10**6)
input=stdin.readline
n,s=map(int,input().split())
a=[int(i) for i in input().split()]
nows=0
ans=2<<20
left=0
for right in range(n):
nows+=a[right]
while left<=right and right<n:
if nows>=s:
ans=min(ans,right-left+1)
nows-=a[left]
left+=1
else: break
#print(nows)
print(ans%(2<<20))
```
Yes
| 97,816 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
N,S = map(int, input().split())
As = list(map(int, input().split()))
i = 0
j = 0
sum = 0
m_l = float('inf')
"""
while True:
while j < N and sum < S:
sum += As[j]
j += 1
if sum < S:
break
m_l = min(j-i, m_l)
sum -= As[i]
i += 1
"""
while j < N:
sum += As[j]
j += 1
if sum < s:
continue
while i <= j and sum >= S:
m_l = min(j-i, m_l)
sum -= As[i]
i += 1
print(m_l if m_l != float('inf') else 0)
```
No
| 97,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
A=map(int,raw_input().split())
list=[]
sum=0
S=1e6
for i in map(int,raw_input().split()):
list.append(i)
sum+=i
if sum>A[1]:
while sum>=A[1]:
sum-=list.popleft()
S=min(S,len(list)+1)
if S==1e6:
print("0")
else:
print(S)
```
No
| 97,818 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
A=map(int,raw_input().split())
list=[]
sum=0
S=1e6+1
for i in map(int,raw_input().split()):
list.append(i)
sum+=i
if sum>A[1]:
while sum>=A[1]:
sum-=list.popleft()
S=min(S,len(list)+1)
if S==1e6+1:
print("0")
else:
print(S)
```
No
| 97,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $S$, find the smallest sub-array size (smallest window length) where the sum of the sub-array is greater than or equal to $S$. If there is not such sub-array, report 0.
Constraints
* $1 \leq N \leq 10^5$
* $1 \leq S \leq 10^9$
* $1 \leq a_i \leq 10^4$
Input
The input is given in the following format.
$N$ $S$
$a_1$ $a_2$ ... $a_N$
Output
Print the smallest sub-array size in a line.
Examples
Input
6 4
1 2 1 2 3 2
Output
2
Input
6 6
1 2 1 2 3 2
Output
3
Input
3 7
1 2 3
Output
0
Submitted Solution:
```
n, s = list(map(int, input().split()))
a = list(map(int, input().split()))
ans = None
for window in range(1, n+1):
sum_a = None
for i in range(n-window):
if sum_a == None:
sum_a = sum(a[i:window])
else:
sum_a += a[i+window-1] - a[i-1]
if sum_a >= s:
ans = window
break
if ans != None: break
if ans == None: ans = 0
print(ans)
```
No
| 97,820 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Tags: dp, hashing, strings
Correct Solution:
```
import math
from collections import defaultdict
def main():
p = 31
m = 1e9 + 9
def string_hash(s):
hash_value = 0
p_pow = 1
for c in s:
hash_value = (hash_value + (ord(c)-ord('a')+1) * p_pow) % m
p_pow = (p_pow * p) % m
return hash_value
n = int(input())
words = input().split()
eq = [[False] * n for _ in range(n)]
for i in range(n):
for j in range(n):
if i == j:
eq[i][j] = eq[j][i] = True
else:
eq[i][j] = eq[i][j] = words[i] == words[j]
dp = [[0 for _ in range(n)] for _ in range(n)]
for i in range(n-1, -1, -1):
for j in range(n-1, -1, -1):
if not eq[i][j]:
dp[i][j] = 0
else:
if i < n-1 and j < n-1:
dp[i][j] = dp[i+1][j+1] + 1
else:
dp[i][j] = 1
all = sum(len(w) for w in words) + n-1
ans = all
for start in range(n):
size = 1
while start + size < n:
num = 1
pos = start + size
while pos + size <= n:
if dp[start][pos] >= size:
num += 1
pos += size
else:
pos += 1
if num > 1:
segsize = sum(len(words[i]) for i in range(start, start+size)) + size-1
newsize = size
ans = min(ans, all - num * segsize + num * newsize)
size += 1
print(ans)
if __name__ == '__main__':
main()
```
| 97,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Tags: dp, hashing, strings
Correct Solution:
```
n = int(input())
arr = input()
final = len(arr)
arr = arr.split()
lens = [0 for x in range(n)]
visit = [0 for x in range(n)]
cnt = 0
ans = 0
for i in range(n):
if visit[i]:
continue
lens[cnt] = len(arr[i])
for j in range(i+1,n):
if arr[j]==arr[i]:
arr[j] = cnt
visit[j] = 1
arr[i] = cnt
cnt += 1
for i in range(n):
for j in range(i,n):
temp = arr[i:j+1]
ind = 1
found = 0
len2 = j-i+1
cur = 0
kmp = [0 for x in range(len2)]
while ind < len2:
if temp[ind] == temp[cur]:
cur += 1
kmp[ind] = cur
ind += 1
else:
if cur != 0:
cur -= 1
else:
kmp[ind] = 0
ind += 1
ind = 0
cur = 0
while ind < n:
if arr[ind] == temp[cur]:
ind += 1
cur += 1
if cur == len2:
found += 1
cur = 0
elif ind < n and temp[cur] != arr[ind]:
if cur != 0:
cur = kmp[cur-1]
else:
ind += 1
if found>1:
res = 0
for k in temp:
res += (lens[k]-1)*(found)
res += (len(temp)-1)*(found)
ans = max(ans,res)
print(final-ans)
```
| 97,822 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Tags: dp, hashing, strings
Correct Solution:
```
n = int(input())
s = input()
a = list(s.split())
eq = [[0 for i in range(n)] for j in range(n)]
dp = [[0 for i in range(n)] for j in range(n)]
for i in range(n):
eq[i][i] = 1
for j in range(0, i):
if a[i] == a[j]:
eq[i][j] += 1
eq[j][i] += 1
for i in range(n - 1, -1, -1):
for j in range(n - 1, -1, -1):
if eq[i][j] == 1:
if i < n - 1 and j < n - 1:
dp[i][j] = dp[i + 1][j + 1] + 1
else:
dp[i][j] = 1
allsum = n - 1
for k in a:
allsum += len(k)
ans = allsum
for i in range(n):
sx = 0
j = 0
while i + j < n:
sx += len(a[i + j])
cnt = 1
pos = i + j + 1
while pos < n:
if dp[i][pos] > j:
cnt += 1
pos += j
pos += 1
cur = allsum - sx*cnt + (j + 1)*cnt - j*cnt
if cnt > 1 and ans > cur:
ans = cur
j += 1
print(ans)
```
| 97,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Tags: dp, hashing, strings
Correct Solution:
```
# import time
N = 303
eq = []
dp = []
for i in range(N):
eq.append([False] * N)
for i in range(N):
dp.append([0] * N)
n = int(input())
s = input()
# t = time.time()
allsum = len(s)
s = s.split()
for i in range(n):
eq[i][i] = True
for j in range(i):
eq[i][j] = eq[j][i] = s[i] == s[j]
for i in range(n - 1, -1, -1):
for j in range(n - 1, -1, -1):
if eq[i][j]:
if i < n - 1 and j < n - 1:
dp[i][j] = dp[i + 1][j + 1] + 1
else:
dp[i][j] = 1
ans = allsum
for i in range(n):
su = 0
for j in range(1, n - i + 1):
su += len(s[i + j - 1])
cnt = 1
pos = i + j
while pos < n:
if dp[i][pos] >= j:
cnt += 1
pos += j - 1
pos += 1
cur = allsum - su * cnt + cnt
if cnt > 1 and ans > cur:
# print(allsum, su, cnt, j)
ans = cur
print(ans)
# print(time.time() - t)
```
| 97,824 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Tags: dp, hashing, strings
Correct Solution:
```
# import time
N = 303
eq = []
dp = []
for i in range(N):
eq.append([False] * N)
for i in range(N):
dp.append([0] * N)
n = int(input())
s = input()
# t = time.time()
allsum = len(s)
s = s.split()
for i in range(n):
eq[i][i] = True
for j in range(i):
eq[i][j] = eq[j][i] = s[i] == s[j]
for i in range(n - 1, -1, -1):
for j in range(n - 1, -1, -1):
if eq[i][j]:
if i < n - 1 and j < n - 1:
dp[i][j] = dp[i + 1][j + 1] + 1
else:
dp[i][j] = 1
ans = allsum
for i in range(n):
su = 0
for j in range(n - i):
su += len(s[i + j])
cnt = 1
pos = i + j + 1
while pos < n:
if dp[i][pos] > j:
cnt += 1
pos += j
pos += 1
cur = allsum - su * cnt + (j + 1) * cnt - j * cnt
if cnt > 1 and ans > cur:
# print(allsum, su, cnt, j)
ans = cur
print(ans)
# print(time.time() - t)
```
| 97,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Tags: dp, hashing, strings
Correct Solution:
```
from sys import stdin
def kmp(pat, txt):
leng = 0;i = 1
ans=0
M = len(pat) ;N = len(txt) ;lps = [0]*M ;j = 0
#Calculo de lps, prefifo propio mas largo que tambien es sufijo de pat[0:i]
while i < M:
if pat[i]== pat[leng]:
leng += 1
lps[i] = leng
i += 1
elif leng != 0:
leng = lps[leng-1]
else:
lps[i] = 0
i += 1
i = 0
while i < N:
if pat[j] == txt[i]:
i += 1;j += 1
if j == M:
if ((i-j)==0 or txt[i-j-1]==" ") and ((i-j+len(pat))==(len(txt)) or txt[i-j+len(pat)]==" "):
ans+=1
i=i-j+len(pat)
j =0
else:
j = lps[j-1]
elif i < N and pat[j] != txt[i]:
if j != 0:
j = lps[j-1]
else:
i += 1
return ans
n=int(stdin.readline().strip())
s1=stdin.readline().strip().split()
s=[]
x=1
d=dict()
d1=dict()
st=set()
ans=n-1
s2=""
for i in s1:
ans+=len(i)
if i not in st:
d.update({i:x})
d1.update({x:len(i)})
x+=1
st.add(i)
s.append(d[i])
s2+=str(d[i])
if len(s)<n:
s2+=" "
acum=0
s3=s2.split()
tot=ans
for i in range(n):
x=0
y=0
for j in range(i,n):
x+=(d1[s[j]]-1)
y+=len(s3[j])
z=kmp(s2[acum:acum+y+j-i],s2)
if z>1:
aux=tot-(z*(x+j-i))
#print(s2[acum:acum+y+j-i],"/ ",aux,acum,y,j-i)
if aux<ans:
#print(s2[acum:acum+y+j-i+1],"/ ",aux)
ans=aux
acum+=len(s3[i])+1
print(ans)
```
| 97,826 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Tags: dp, hashing, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
n = int(input())
s = input()
a = list(s.split())
eq = [[0 for i in range(n)] for j in range(n)]
dp = [[0 for i in range(n)] for j in range(n)]
for i in range(n):
eq[i][i] = 1
for j in range(0, i):
if a[i] == a[j]:
eq[i][j] += 1
eq[j][i] += 1
for i in range(n - 1, -1, -1):
for j in range(n - 1, -1, -1):
if eq[i][j] == 1:
if i < n - 1 and j < n - 1:
dp[i][j] = dp[i + 1][j + 1] + 1
else:
dp[i][j] = 1
allsum = n - 1
for k in a:
allsum += len(k)
ans = allsum
for i in range(n):
sx = 0
j = 0
while i + j < n:
sx += len(a[i + j])
cnt = 1
pos = i + j + 1
while pos < n:
if dp[i][pos] > j:
cnt += 1
pos += j
pos += 1
cur = allsum - sx*cnt + (j + 1)*cnt - j*cnt
if cnt > 1 and ans > cur:
ans = cur
j += 1
print(ans)
```
| 97,827 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Submitted Solution:
```
n = int(input())
arr = input()
final = len(arr)
arr = arr.split()
lens = [0 for x in range(n)]
visit = [0 for x in range(n)]
cnt = 0
ans = 0
for i in range(n):
if visit[i]:
continue
lens[cnt] = len(arr[i])
for j in range(i+1,n):
if arr[j]==arr[i]:
arr[j] = cnt
visit[j] = 1
arr[i] = cnt
cnt += 1
for i in range(n):
for j in range(i,n):
temp = arr[i:j+1]
ind = j+1
need = len(temp)
found = 0
while ind < n:
if arr[ind]==temp[0]:
cnt = 0
while ind+cnt < n:
if arr[ind+cnt]==temp[cnt]:
cnt += 1
else:
break
if cnt==need:
found += 1
break
ind += cnt
continue
ind += 1
if found:
res = 0
for k in temp:
res += (lens[k]-1)*(found+1)
res += (len(temp)-1)*(found+1)
ans = max(ans,res)
print(final-ans)
```
No
| 97,828 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Submitted Solution:
```
n=int(input())
s=input().split()
flag=[[s[i]!=s[j] for j in range(n)]for i in range(n)]
b=[0]+[len(i)-1 for i in s]
for i in range(n):b[i+1]+=b[i]
ans=0
for i in range(n-1):
for j in range(i+1,n):
t=min(j-i,n-j)
for k in range(t):
if flag[i+k][j+k]:
break
if k:
ans=max(ans,b[i+k+1]-b[i]+k)
print(((b[n]+n)+(n-1))-ans*2)
```
No
| 97,829 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Submitted Solution:
```
#!/usr/bin/env python3
import math
import sys
import re
def get_abbreviation(s):
abbrev = ""
for w in s:
abbrev += w[0].upper()
return abbrev
results = {}
def calculate_savings(o):
ss_word_count = len(o[0].split(" ")) # This will be the size of abbrev (ex. a ab abbbb abbbb = 4 (AAAA))
ss_length = len(o[0]) # This will be the size saved for each word (ex. a ab abbb = 9
# To get the savings we take how much is saved per occurrence ss_len - ss_word_count
# and multiple by the total number of occurrences len(o)
return (ss_length - ss_word_count) * len(o)
def substring_length(start, end, testWords, testString):
mid = math.ceil((start + end)/2)
substring = " ".join(testWords[start:end])
if substring not in results:
r = '\\b{}\\b'.format(substring)
o = re.findall(r, testString)
if len(o) > 1:
savings = calculate_savings(o)
#print("testString: {} substring: {} o: {} savings: {}".format(testString, substring, o, savings))
results[substring] = savings
if start < mid and end > mid:
substring_length(start, mid, testWords, testString)
substring_length(mid, end, testWords, testString)
input_count = sys.stdin.readline()
input_word = sys.stdin.readline()
testString = input_word.rstrip()
testWords = testString.split(" ")
substring_length(0, len(testWords), testWords, testString)
#print(results)
sorted_by_value = sorted(results.items(), key=lambda kv: kv[1], reverse=True)
to_replace = sorted_by_value[0][0]
#print(sorted_by_value)
abbreviation = get_abbreviation(to_replace.split(" "))
#print("Converting {} to {}".format(to_replace, abbreviation))
r = '\\b{}\\b'.format(to_replace)
finalString = re.sub(r, abbreviation, testString)
#print("Converted original {} to final {} length: {}".format(testString, finalString, len(finalString)))
print(len(finalString))
```
No
| 97,830 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n space-separated words. There is exactly one space character between any pair of adjacent words. There are no spaces before the first word and no spaces after the last word. The length of text is the number of letters and spaces in it. w_i is the i-th word of text. All words consist only of lowercase Latin letters.
Let's denote a segment of words w[i..j] as a sequence of words w_i, w_{i + 1}, ..., w_j. Two segments of words w[i_1 .. j_1] and w[i_2 .. j_2] are considered equal if j_1 - i_1 = j_2 - i_2, j_1 ≥ i_1, j_2 ≥ i_2, and for every t ∈ [0, j_1 - i_1] w_{i_1 + t} = w_{i_2 + t}. For example, for the text "to be or not to be" the segments w[1..2] and w[5..6] are equal, they correspond to the words "to be".
An abbreviation is a replacement of some segments of words with their first uppercase letters. In order to perform an abbreviation, you have to choose at least two non-intersecting equal segments of words, and replace each chosen segment with the string consisting of first letters of the words in the segment (written in uppercase). For example, for the text "a ab a a b ab a a b c" you can replace segments of words w[2..4] and w[6..8] with an abbreviation "AAA" and obtain the text "a AAA b AAA b c", or you can replace segments of words w[2..5] and w[6..9] with an abbreviation "AAAB" and obtain the text "a AAAB AAAB c".
What is the minimum length of the text after at most one abbreviation?
Input
The first line of the input contains one integer n (1 ≤ n ≤ 300) — the number of words in the text.
The next line contains n space-separated words of the text w_1, w_2, ..., w_n. Each word consists only of lowercase Latin letters.
It is guaranteed that the length of text does not exceed 10^5.
Output
Print one integer — the minimum length of the text after at most one abbreviation.
Examples
Input
6
to be or not to be
Output
12
Input
10
a ab a a b ab a a b c
Output
13
Input
6
aa bb aa aa bb bb
Output
11
Note
In the first example you can obtain the text "TB or not TB".
In the second example you can obtain the text "a AAAB AAAB c".
In the third example you can obtain the text "AB aa AB bb".
Submitted Solution:
```
wNum = int(input())
text = str(input())
oldSize = len(text)
tData = text.split(' ')
diff = 0
for s in range(1, wNum // 2 + 1):
for i in range(wNum - s):
words = ' '.join(tData[i:i + s])
cnt = text.count(words)
if cnt != 1:
score = (len(words) - s) * text.count(words)
diff = score if score > diff else diff
print(oldSize - diff)
```
No
| 97,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The campus has m rooms numbered from 0 to m - 1. Also the x-mouse lives in the campus. The x-mouse is not just a mouse: each second x-mouse moves from room i to the room i ⋅ x mod{m} (in fact, it teleports from one room to another since it doesn't visit any intermediate room). Starting position of the x-mouse is unknown.
You are responsible to catch the x-mouse in the campus, so you are guessing about minimum possible number of traps (one trap in one room) you need to place. You are sure that if the x-mouse enters a trapped room, it immediately gets caught.
And the only observation you made is GCD (x, m) = 1.
Input
The only line contains two integers m and x (2 ≤ m ≤ 10^{14}, 1 ≤ x < m, GCD (x, m) = 1) — the number of rooms and the parameter of x-mouse.
Output
Print the only integer — minimum number of traps you need to install to catch the x-mouse.
Examples
Input
4 3
Output
3
Input
5 2
Output
2
Note
In the first example you can, for example, put traps in rooms 0, 2, 3. If the x-mouse starts in one of this rooms it will be caught immediately. If x-mouse starts in the 1-st rooms then it will move to the room 3, where it will be caught.
In the second example you can put one trap in room 0 and one trap in any other room since x-mouse will visit all rooms 1..m-1 if it will start in any of these rooms.
Tags: bitmasks, math, number theory
Correct Solution:
```
from math import gcd
def powmod(a,b,m):
a%=m
r=1
while b:
if b&1:r=r*a%m
a=a*a%m
b>>=1
return r
def f(n):
r=[]
if (n&1)==0:
e=0
while (n&1)==0:n>>=1;e+=1
yield (2,e)
p=3
while n>1:
if p*p>n:p=n
if n%p:
p+=2
continue
e=1;n//=p
while n%p==0:n//=p;e+=1
yield (p,e)
p+=2
return r
m,x=map(int,input().split())
p=2
r=[(1,1)]
for p,e in f(m):
assert e>=1
ord=p-1
assert powmod(x,ord,p)==1
for pi,ei in f(p-1):
while ord % pi == 0 and powmod(x,ord//pi,p)==1: ord//=pi
ords=[(1,1),(ord,p-1)]
q=p
for v in range(2,e+1):
q*=p
if powmod(x,ord,q)!=1:ord*=p
assert powmod(x,ord,q)==1
ords.append((ord,q//p*(p-1)))
r=[(a//gcd(a,c)*c,b*d) for a,b in r for c,d in ords]
print(sum(y//x for x,y in r))
```
| 97,832 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The campus has m rooms numbered from 0 to m - 1. Also the x-mouse lives in the campus. The x-mouse is not just a mouse: each second x-mouse moves from room i to the room i ⋅ x mod{m} (in fact, it teleports from one room to another since it doesn't visit any intermediate room). Starting position of the x-mouse is unknown.
You are responsible to catch the x-mouse in the campus, so you are guessing about minimum possible number of traps (one trap in one room) you need to place. You are sure that if the x-mouse enters a trapped room, it immediately gets caught.
And the only observation you made is GCD (x, m) = 1.
Input
The only line contains two integers m and x (2 ≤ m ≤ 10^{14}, 1 ≤ x < m, GCD (x, m) = 1) — the number of rooms and the parameter of x-mouse.
Output
Print the only integer — minimum number of traps you need to install to catch the x-mouse.
Examples
Input
4 3
Output
3
Input
5 2
Output
2
Note
In the first example you can, for example, put traps in rooms 0, 2, 3. If the x-mouse starts in one of this rooms it will be caught immediately. If x-mouse starts in the 1-st rooms then it will move to the room 3, where it will be caught.
In the second example you can put one trap in room 0 and one trap in any other room since x-mouse will visit all rooms 1..m-1 if it will start in any of these rooms.
Submitted Solution:
```
from math import sqrt
def factor(n):
potentional_p = 3
itog_list = {}
if n % 2 == 0:
itog_list[2] = 0
while n % 2 == 0:
n = n // 2
itog_list[2] += 1
while n - 1:
if potentional_p > sqrt(n):
if n in itog_list:
itog_list[n] += 1
else:
itog_list[n] = 1
return itog_list
while n % potentional_p == 0:
n = n // potentional_p
if potentional_p in itog_list:
itog_list[potentional_p] += 1
else:
itog_list[potentional_p] = 1
potentional_p += 2
return itog_list
m, x = map(int, input().split())
F = factor(m)
fi = 1
for p in F:
fi *= p ** (F[p] - 1) * (p - 1)
print(fi + 1)
```
No
| 97,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The campus has m rooms numbered from 0 to m - 1. Also the x-mouse lives in the campus. The x-mouse is not just a mouse: each second x-mouse moves from room i to the room i ⋅ x mod{m} (in fact, it teleports from one room to another since it doesn't visit any intermediate room). Starting position of the x-mouse is unknown.
You are responsible to catch the x-mouse in the campus, so you are guessing about minimum possible number of traps (one trap in one room) you need to place. You are sure that if the x-mouse enters a trapped room, it immediately gets caught.
And the only observation you made is GCD (x, m) = 1.
Input
The only line contains two integers m and x (2 ≤ m ≤ 10^{14}, 1 ≤ x < m, GCD (x, m) = 1) — the number of rooms and the parameter of x-mouse.
Output
Print the only integer — minimum number of traps you need to install to catch the x-mouse.
Examples
Input
4 3
Output
3
Input
5 2
Output
2
Note
In the first example you can, for example, put traps in rooms 0, 2, 3. If the x-mouse starts in one of this rooms it will be caught immediately. If x-mouse starts in the 1-st rooms then it will move to the room 3, where it will be caught.
In the second example you can put one trap in room 0 and one trap in any other room since x-mouse will visit all rooms 1..m-1 if it will start in any of these rooms.
Submitted Solution:
```
line = input().split()
m = int(line[0])
x = int(line[1])
print(x)
```
No
| 97,834 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The campus has m rooms numbered from 0 to m - 1. Also the x-mouse lives in the campus. The x-mouse is not just a mouse: each second x-mouse moves from room i to the room i ⋅ x mod{m} (in fact, it teleports from one room to another since it doesn't visit any intermediate room). Starting position of the x-mouse is unknown.
You are responsible to catch the x-mouse in the campus, so you are guessing about minimum possible number of traps (one trap in one room) you need to place. You are sure that if the x-mouse enters a trapped room, it immediately gets caught.
And the only observation you made is GCD (x, m) = 1.
Input
The only line contains two integers m and x (2 ≤ m ≤ 10^{14}, 1 ≤ x < m, GCD (x, m) = 1) — the number of rooms and the parameter of x-mouse.
Output
Print the only integer — minimum number of traps you need to install to catch the x-mouse.
Examples
Input
4 3
Output
3
Input
5 2
Output
2
Note
In the first example you can, for example, put traps in rooms 0, 2, 3. If the x-mouse starts in one of this rooms it will be caught immediately. If x-mouse starts in the 1-st rooms then it will move to the room 3, where it will be caught.
In the second example you can put one trap in room 0 and one trap in any other room since x-mouse will visit all rooms 1..m-1 if it will start in any of these rooms.
Submitted Solution:
```
m ,n = map(int,input().split())
if m !=0 or n!=0:
if m == 0 :
print(n)
elif n ==0 :
print(m)
elif m>n:
print(n)
elif n>m:
print(m)
```
No
| 97,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The campus has m rooms numbered from 0 to m - 1. Also the x-mouse lives in the campus. The x-mouse is not just a mouse: each second x-mouse moves from room i to the room i ⋅ x mod{m} (in fact, it teleports from one room to another since it doesn't visit any intermediate room). Starting position of the x-mouse is unknown.
You are responsible to catch the x-mouse in the campus, so you are guessing about minimum possible number of traps (one trap in one room) you need to place. You are sure that if the x-mouse enters a trapped room, it immediately gets caught.
And the only observation you made is GCD (x, m) = 1.
Input
The only line contains two integers m and x (2 ≤ m ≤ 10^{14}, 1 ≤ x < m, GCD (x, m) = 1) — the number of rooms and the parameter of x-mouse.
Output
Print the only integer — minimum number of traps you need to install to catch the x-mouse.
Examples
Input
4 3
Output
3
Input
5 2
Output
2
Note
In the first example you can, for example, put traps in rooms 0, 2, 3. If the x-mouse starts in one of this rooms it will be caught immediately. If x-mouse starts in the 1-st rooms then it will move to the room 3, where it will be caught.
In the second example you can put one trap in room 0 and one trap in any other room since x-mouse will visit all rooms 1..m-1 if it will start in any of these rooms.
Submitted Solution:
```
m, x = map(int, input().split())
o = 1
cx = (x * x) % m
while cx != x:
o += 1
cx = (cx * x) % m
print(2 + (m-2) // o)
```
No
| 97,836 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
import math
a = int(input())
b = input().split()
b = [int(i) for i in b]
c = input().split()
c = [int(i) for i in c]
output = 0
for i in b:
output += (i + c[1] - 1)//(c[0] + c[1])
print (output * c[1])
```
| 97,837 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
n=int(input())
l=list(map(int,input().split()))
x,f=map(int,input().split())
b=x+f
ans=0
for i in range(n):
a=l[i]-x
if a%b==0:
ans+=a//b
else:
ans+=a//b+1
print(ans*f)
```
| 97,838 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
max, fee = map(int, input().split())
total = 0
a.sort(reverse=True)
for i in range(n):
if a[i]> max:
num = -(-(a[i]-max)//(max+fee))
total = total + fee*num
else:
break
print(total)
```
| 97,839 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
import math
NN = int(input())
AI = list(map(int,input().split()))
XX,FF = map(int,input().split())
length = len(AI)
extra = 0
for xx in AI:
if xx>XX:
extra+=math.ceil((xx-XX)/(XX+FF))
print(extra*FF)
```
| 97,840 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
n=(int)(input())
l=list(map(int,input().split()))
x,f=map(int,input().split())
c=0
for i in l:
y=i-x
if y>0:
a=y//(x+f)
b=y/(x+f)
if a==b:
c=c+a
else:
c=c+a+1
print(f*c)
```
| 97,841 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
maxVal, cost = map(int, input().split())
newWallets = 0
for s in a:
if s > maxVal:
newWallets += ((s + cost - 1) // (maxVal + cost))
print(newWallets * cost)
```
| 97,842 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
from sys import stdin,stdout
from math import gcd,sqrt
from collections import deque
input=stdin.readline
R=lambda:map(int,input().split())
I=lambda:int(input())
S=lambda:input().rstrip('\n')
L=lambda:list(R())
P=lambda x:stdout.write(x)
hg=lambda x,y:((y+x-1)//x)*x
pw=lambda x:1 if x==1 else 1+pw(x//2)
chk=lambda x:chk(x//2) if not x%2 else True if x==1 else False
N=10**6+7
def fee(p):return (p//(x+f))*f+max(0,min(1,p%(x+f)-x))*f
n=I()
a=L()
x,f=R()
ans=0
for i in a:
if i>x:ans+=fee(i)
print(ans)
```
| 97,843 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Tags: implementation
Correct Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#-------------------game starts now-----------------------------------------------------
n=int(input())
a=list(map(int,input().split()))
x,f=map(int,input().split())
fee=0
temp=0
for i in (a):
if i>x:
temp=int(math.ceil((i-x)/(x+f)))
temp=max(1,temp)
fee=fee+temp*f
print(fee)
```
| 97,844 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
n = int(input())
coshelki = [int(i) for i in input().split()]
x, f = (int(i) for i in input().split())
sum = 0
for i in coshelki:
perevody = i // (x + f)
if i - perevody * (x + f) > x:
perevody += 1
sum += perevody
print(f * sum)
```
Yes
| 97,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
# -*- coding: utf-8 -*-
from math import ceil
def problem(in1, in2, in3):
n = int(in1)
balances = list(map(int, in2.split()))
limit = list(map(int, in3.split()))[0]
fee = list(map(int, in3.split()))[1]
tx_size = limit + fee
tx_count = 0
for index, balance in enumerate(balances):
tx_needed = ceil((balance - limit) / tx_size)
tx_count += tx_needed
return tx_count * fee
if __name__ == '__main__':
in1 = input()
in2 = input()
in3 = input();
result = problem(in1, in2, in3)
print(result)
```
Yes
| 97,846 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
import math
n=int(input())
l=list(map(int,input().split()))
x,f=map(int,input().split())
ans=0
for i in range(n):
if l[i]<=x:
continue
else:
c=math.ceil((l[i]-x)/(f+x))
ans+=f*c
print(ans)
```
Yes
| 97,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
import math
input()
a=list(map(int,input().split()))
x,y=map(int,input().split())
s=0
for i in a:
if i>x:
s+=math.ceil((i-x)/(x+y))
print(int(s*y))
```
Yes
| 97,848 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
from collections import Counter
from math import ceil
n=int(input())
a=[int(X) for X in input().split()]
x,f=map(int,input().split())
an=0
for i in range(n):
if a[i]>x:
an+=ceil(a[i]/x)
z=Counter(a)
print(an*f)
```
No
| 97,849 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
n = int(input())
l = list(map(int,input().split()))
x,f = map(int,input().split())
v = len(list(filter(lambda val: val>x,l)))
print(v*f)
```
No
| 97,850 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
import sys
input = sys.stdin.readline
n = int(input())
a = [int(x) for x in input().split()]
x, f = map(int, input().split())
k = 0
for i in range(n):
if a[i] >= x + f:
k += a[i]//(x + f)
elif x < a[i] < x + f:
k += 1
print(k*f)
```
No
| 97,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
n = int(input())
coshelki = [int(i) for i in input().split()]
x, f = (int(i) for i in input().split())
sum = 0
for i in coshelki:
perevodi = i // (x + f)
if perevodi == 0 and i > x:
sum += 1
sum += perevodi
print(f * sum)
```
No
| 97,852 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp has a lot of work to do. Recently he has learned a new time management rule: "if a task takes five minutes or less, do it immediately". Polycarp likes the new rule, however he is not sure that five minutes is the optimal value. He supposes that this value d should be chosen based on existing task list.
Polycarp has a list of n tasks to complete. The i-th task has difficulty p_i, i.e. it requires exactly p_i minutes to be done. Polycarp reads the tasks one by one from the first to the n-th. If a task difficulty is d or less, Polycarp starts the work on the task immediately. If a task difficulty is strictly greater than d, he will not do the task at all. It is not allowed to rearrange tasks in the list. Polycarp doesn't spend any time for reading a task or skipping it.
Polycarp has t minutes in total to complete maximum number of tasks. But he does not want to work all the time. He decides to make a break after each group of m consecutive tasks he was working on. The break should take the same amount of time as it was spent in total on completion of these m tasks.
For example, if n=7, p=[3, 1, 4, 1, 5, 9, 2], d=3 and m=2 Polycarp works by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=3 ≤ d=3) and works for 3 minutes (i.e. the minutes 1, 2, 3);
* Polycarp reads the second task, its difficulty is not greater than d (p_2=1 ≤ d=3) and works for 1 minute (i.e. the minute 4);
* Polycarp notices that he has finished m=2 tasks and takes a break for 3+1=4 minutes (i.e. on the minutes 5, 6, 7, 8);
* Polycarp reads the third task, its difficulty is greater than d (p_3=4 > d=3) and skips it without spending any time;
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=1 ≤ d=3) and works for 1 minute (i.e. the minute 9);
* Polycarp reads the tasks 5 and 6, skips both of them (p_5>d and p_6>d);
* Polycarp reads the 7-th task, its difficulty is not greater than d (p_7=2 ≤ d=3) and works for 2 minutes (i.e. the minutes 10, 11);
* Polycarp notices that he has finished m=2 tasks and takes a break for 1+2=3 minutes (i.e. on the minutes 12, 13, 14).
Polycarp stops exactly after t minutes. If Polycarp started a task but has not finished it by that time, the task is not considered as completed. It is allowed to complete less than m tasks in the last group. Also Polycarp considers acceptable to have shorter break than needed after the last group of tasks or even not to have this break at all — his working day is over and he will have enough time to rest anyway.
Please help Polycarp to find such value d, which would allow him to complete maximum possible number of tasks in t minutes.
Input
The first line of the input contains single integer c (1 ≤ c ≤ 5 ⋅ 10^4) — number of test cases. Then description of c test cases follows. Solve test cases separately, test cases are completely independent and do not affect each other.
Each test case is described by two lines. The first of these lines contains three space-separated integers n, m and t (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5, 1 ≤ t ≤ 4 ⋅ 10^{10}) — the number of tasks in Polycarp's list, the number of tasks he can do without a break and the total amount of time Polycarp can work on tasks. The second line of the test case contains n space separated integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ 2 ⋅ 10^5) — difficulties of the tasks.
The sum of values n for all test cases in the input does not exceed 2 ⋅ 10^5.
Output
Print c lines, each line should contain answer for the corresponding test case — the maximum possible number of tasks Polycarp can complete and the integer value d (1 ≤ d ≤ t) Polycarp should use in time management rule, separated by space. If there are several possible values d for a test case, output any of them.
Examples
Input
4
5 2 16
5 6 1 4 7
5 3 30
5 6 1 4 7
6 4 15
12 5 15 7 20 17
1 1 50
100
Output
3 5
4 7
2 10
0 25
Input
3
11 1 29
6 4 3 7 5 3 4 7 3 5 3
7 1 5
1 1 1 1 1 1 1
5 2 18
2 3 3 7 5
Output
4 3
3 1
4 5
Note
In the first test case of the first example n=5, m=2 and t=16. The sequence of difficulties is [5, 6, 1, 4, 7]. If Polycarp chooses d=5 then he will complete 3 tasks. Polycarp will work by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=5 ≤ d=5) and works for 5 minutes (i.e. the minutes 1, 2, ..., 5);
* Polycarp reads the second task, its difficulty is greater than d (p_2=6 > d=5) and skips it without spending any time;
* Polycarp reads the third task, its difficulty is not greater than d (p_3=1 ≤ d=5) and works for 1 minute (i.e. the minute 6);
* Polycarp notices that he has finished m=2 tasks and takes a break for 5+1=6 minutes (i.e. on the minutes 7, 8, ..., 12);
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=4 ≤ d=5) and works for 4 minutes (i.e. the minutes 13, 14, 15, 16);
* Polycarp stops work because of t=16.
In total in the first test case Polycarp will complete 3 tasks for d=5. He can't choose other value for d to increase the number of completed tasks.
Tags: binary search, data structures
Correct Solution:
```
import io, os
input = io.StringIO(os.read(0, os.fstat(0).st_size).decode()).readline
ii = lambda: int(input())
mi = lambda: map(int, input().split())
li = lambda: list(mi())
out = []
for _ in range(ii()):
n, m, t = mi()
p = li()
def check(d):
cur = tim = tot = totim = 0
for i in range(n):
x = p[i]
if x > d: continue
totim += x
tim += x
if totim > t: break
cur += 1
tot += 1
if cur == m:
totim += tim
if totim > t: break
cur = tim = 0
return all(x > d for x in p[i+1:]), tot
lo, hi = 1, t
while lo < hi:
mid = (lo + hi + 1) >> 1
if check(mid)[0]:
lo = mid
else:
hi = mid - 1
if check(lo + 1)[1] > check(lo)[1]:
lo += 1
out.append('%d %d' % (check(lo)[1], lo))
print(*out, sep='\n')
```
| 97,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a lot of work to do. Recently he has learned a new time management rule: "if a task takes five minutes or less, do it immediately". Polycarp likes the new rule, however he is not sure that five minutes is the optimal value. He supposes that this value d should be chosen based on existing task list.
Polycarp has a list of n tasks to complete. The i-th task has difficulty p_i, i.e. it requires exactly p_i minutes to be done. Polycarp reads the tasks one by one from the first to the n-th. If a task difficulty is d or less, Polycarp starts the work on the task immediately. If a task difficulty is strictly greater than d, he will not do the task at all. It is not allowed to rearrange tasks in the list. Polycarp doesn't spend any time for reading a task or skipping it.
Polycarp has t minutes in total to complete maximum number of tasks. But he does not want to work all the time. He decides to make a break after each group of m consecutive tasks he was working on. The break should take the same amount of time as it was spent in total on completion of these m tasks.
For example, if n=7, p=[3, 1, 4, 1, 5, 9, 2], d=3 and m=2 Polycarp works by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=3 ≤ d=3) and works for 3 minutes (i.e. the minutes 1, 2, 3);
* Polycarp reads the second task, its difficulty is not greater than d (p_2=1 ≤ d=3) and works for 1 minute (i.e. the minute 4);
* Polycarp notices that he has finished m=2 tasks and takes a break for 3+1=4 minutes (i.e. on the minutes 5, 6, 7, 8);
* Polycarp reads the third task, its difficulty is greater than d (p_3=4 > d=3) and skips it without spending any time;
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=1 ≤ d=3) and works for 1 minute (i.e. the minute 9);
* Polycarp reads the tasks 5 and 6, skips both of them (p_5>d and p_6>d);
* Polycarp reads the 7-th task, its difficulty is not greater than d (p_7=2 ≤ d=3) and works for 2 minutes (i.e. the minutes 10, 11);
* Polycarp notices that he has finished m=2 tasks and takes a break for 1+2=3 minutes (i.e. on the minutes 12, 13, 14).
Polycarp stops exactly after t minutes. If Polycarp started a task but has not finished it by that time, the task is not considered as completed. It is allowed to complete less than m tasks in the last group. Also Polycarp considers acceptable to have shorter break than needed after the last group of tasks or even not to have this break at all — his working day is over and he will have enough time to rest anyway.
Please help Polycarp to find such value d, which would allow him to complete maximum possible number of tasks in t minutes.
Input
The first line of the input contains single integer c (1 ≤ c ≤ 5 ⋅ 10^4) — number of test cases. Then description of c test cases follows. Solve test cases separately, test cases are completely independent and do not affect each other.
Each test case is described by two lines. The first of these lines contains three space-separated integers n, m and t (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5, 1 ≤ t ≤ 4 ⋅ 10^{10}) — the number of tasks in Polycarp's list, the number of tasks he can do without a break and the total amount of time Polycarp can work on tasks. The second line of the test case contains n space separated integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ 2 ⋅ 10^5) — difficulties of the tasks.
The sum of values n for all test cases in the input does not exceed 2 ⋅ 10^5.
Output
Print c lines, each line should contain answer for the corresponding test case — the maximum possible number of tasks Polycarp can complete and the integer value d (1 ≤ d ≤ t) Polycarp should use in time management rule, separated by space. If there are several possible values d for a test case, output any of them.
Examples
Input
4
5 2 16
5 6 1 4 7
5 3 30
5 6 1 4 7
6 4 15
12 5 15 7 20 17
1 1 50
100
Output
3 5
4 7
2 10
0 25
Input
3
11 1 29
6 4 3 7 5 3 4 7 3 5 3
7 1 5
1 1 1 1 1 1 1
5 2 18
2 3 3 7 5
Output
4 3
3 1
4 5
Note
In the first test case of the first example n=5, m=2 and t=16. The sequence of difficulties is [5, 6, 1, 4, 7]. If Polycarp chooses d=5 then he will complete 3 tasks. Polycarp will work by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=5 ≤ d=5) and works for 5 minutes (i.e. the minutes 1, 2, ..., 5);
* Polycarp reads the second task, its difficulty is greater than d (p_2=6 > d=5) and skips it without spending any time;
* Polycarp reads the third task, its difficulty is not greater than d (p_3=1 ≤ d=5) and works for 1 minute (i.e. the minute 6);
* Polycarp notices that he has finished m=2 tasks and takes a break for 5+1=6 minutes (i.e. on the minutes 7, 8, ..., 12);
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=4 ≤ d=5) and works for 4 minutes (i.e. the minutes 13, 14, 15, 16);
* Polycarp stops work because of t=16.
In total in the first test case Polycarp will complete 3 tasks for d=5. He can't choose other value for d to increase the number of completed tasks.
Submitted Solution:
```
ANS = """3 5
4 7
2 10
0 25"""
print(ANS)
```
No
| 97,854 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a lot of work to do. Recently he has learned a new time management rule: "if a task takes five minutes or less, do it immediately". Polycarp likes the new rule, however he is not sure that five minutes is the optimal value. He supposes that this value d should be chosen based on existing task list.
Polycarp has a list of n tasks to complete. The i-th task has difficulty p_i, i.e. it requires exactly p_i minutes to be done. Polycarp reads the tasks one by one from the first to the n-th. If a task difficulty is d or less, Polycarp starts the work on the task immediately. If a task difficulty is strictly greater than d, he will not do the task at all. It is not allowed to rearrange tasks in the list. Polycarp doesn't spend any time for reading a task or skipping it.
Polycarp has t minutes in total to complete maximum number of tasks. But he does not want to work all the time. He decides to make a break after each group of m consecutive tasks he was working on. The break should take the same amount of time as it was spent in total on completion of these m tasks.
For example, if n=7, p=[3, 1, 4, 1, 5, 9, 2], d=3 and m=2 Polycarp works by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=3 ≤ d=3) and works for 3 minutes (i.e. the minutes 1, 2, 3);
* Polycarp reads the second task, its difficulty is not greater than d (p_2=1 ≤ d=3) and works for 1 minute (i.e. the minute 4);
* Polycarp notices that he has finished m=2 tasks and takes a break for 3+1=4 minutes (i.e. on the minutes 5, 6, 7, 8);
* Polycarp reads the third task, its difficulty is greater than d (p_3=4 > d=3) and skips it without spending any time;
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=1 ≤ d=3) and works for 1 minute (i.e. the minute 9);
* Polycarp reads the tasks 5 and 6, skips both of them (p_5>d and p_6>d);
* Polycarp reads the 7-th task, its difficulty is not greater than d (p_7=2 ≤ d=3) and works for 2 minutes (i.e. the minutes 10, 11);
* Polycarp notices that he has finished m=2 tasks and takes a break for 1+2=3 minutes (i.e. on the minutes 12, 13, 14).
Polycarp stops exactly after t minutes. If Polycarp started a task but has not finished it by that time, the task is not considered as completed. It is allowed to complete less than m tasks in the last group. Also Polycarp considers acceptable to have shorter break than needed after the last group of tasks or even not to have this break at all — his working day is over and he will have enough time to rest anyway.
Please help Polycarp to find such value d, which would allow him to complete maximum possible number of tasks in t minutes.
Input
The first line of the input contains single integer c (1 ≤ c ≤ 5 ⋅ 10^4) — number of test cases. Then description of c test cases follows. Solve test cases separately, test cases are completely independent and do not affect each other.
Each test case is described by two lines. The first of these lines contains three space-separated integers n, m and t (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5, 1 ≤ t ≤ 4 ⋅ 10^{10}) — the number of tasks in Polycarp's list, the number of tasks he can do without a break and the total amount of time Polycarp can work on tasks. The second line of the test case contains n space separated integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ 2 ⋅ 10^5) — difficulties of the tasks.
The sum of values n for all test cases in the input does not exceed 2 ⋅ 10^5.
Output
Print c lines, each line should contain answer for the corresponding test case — the maximum possible number of tasks Polycarp can complete and the integer value d (1 ≤ d ≤ t) Polycarp should use in time management rule, separated by space. If there are several possible values d for a test case, output any of them.
Examples
Input
4
5 2 16
5 6 1 4 7
5 3 30
5 6 1 4 7
6 4 15
12 5 15 7 20 17
1 1 50
100
Output
3 5
4 7
2 10
0 25
Input
3
11 1 29
6 4 3 7 5 3 4 7 3 5 3
7 1 5
1 1 1 1 1 1 1
5 2 18
2 3 3 7 5
Output
4 3
3 1
4 5
Note
In the first test case of the first example n=5, m=2 and t=16. The sequence of difficulties is [5, 6, 1, 4, 7]. If Polycarp chooses d=5 then he will complete 3 tasks. Polycarp will work by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=5 ≤ d=5) and works for 5 minutes (i.e. the minutes 1, 2, ..., 5);
* Polycarp reads the second task, its difficulty is greater than d (p_2=6 > d=5) and skips it without spending any time;
* Polycarp reads the third task, its difficulty is not greater than d (p_3=1 ≤ d=5) and works for 1 minute (i.e. the minute 6);
* Polycarp notices that he has finished m=2 tasks and takes a break for 5+1=6 minutes (i.e. on the minutes 7, 8, ..., 12);
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=4 ≤ d=5) and works for 4 minutes (i.e. the minutes 13, 14, 15, 16);
* Polycarp stops work because of t=16.
In total in the first test case Polycarp will complete 3 tasks for d=5. He can't choose other value for d to increase the number of completed tasks.
Submitted Solution:
```
import io, os
input = io.StringIO(os.read(0, os.fstat(0).st_size).decode()).readline
ii = lambda: int(input())
mi = lambda: map(int, input().split())
li = lambda: list(mi())
out = []
for _ in range(ii()):
n, m, t = mi()
p = li()
def check(d):
cur = tim = tot = totim = 0
for i in range(n):
x = p[i]
if x > d: continue
totim += x
tim += x
if totim > t: break
cur += 1
tot += 1
if cur == m:
totim += tim
if totim > t: break
cur = tim = 0
return all(x > d for x in p[i+1:]), tot
lo, hi = 1, t
while lo < hi:
mid = (lo + hi + 1) >> 1
if check(mid)[0]:
lo = mid
else:
hi = mid - 1
if check(hi)[1] > check(lo)[1]:
lo = hi
out.append('%d %d' % (check(lo)[1], lo))
print(*out, sep='\n')
```
No
| 97,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a lot of work to do. Recently he has learned a new time management rule: "if a task takes five minutes or less, do it immediately". Polycarp likes the new rule, however he is not sure that five minutes is the optimal value. He supposes that this value d should be chosen based on existing task list.
Polycarp has a list of n tasks to complete. The i-th task has difficulty p_i, i.e. it requires exactly p_i minutes to be done. Polycarp reads the tasks one by one from the first to the n-th. If a task difficulty is d or less, Polycarp starts the work on the task immediately. If a task difficulty is strictly greater than d, he will not do the task at all. It is not allowed to rearrange tasks in the list. Polycarp doesn't spend any time for reading a task or skipping it.
Polycarp has t minutes in total to complete maximum number of tasks. But he does not want to work all the time. He decides to make a break after each group of m consecutive tasks he was working on. The break should take the same amount of time as it was spent in total on completion of these m tasks.
For example, if n=7, p=[3, 1, 4, 1, 5, 9, 2], d=3 and m=2 Polycarp works by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=3 ≤ d=3) and works for 3 minutes (i.e. the minutes 1, 2, 3);
* Polycarp reads the second task, its difficulty is not greater than d (p_2=1 ≤ d=3) and works for 1 minute (i.e. the minute 4);
* Polycarp notices that he has finished m=2 tasks and takes a break for 3+1=4 minutes (i.e. on the minutes 5, 6, 7, 8);
* Polycarp reads the third task, its difficulty is greater than d (p_3=4 > d=3) and skips it without spending any time;
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=1 ≤ d=3) and works for 1 minute (i.e. the minute 9);
* Polycarp reads the tasks 5 and 6, skips both of them (p_5>d and p_6>d);
* Polycarp reads the 7-th task, its difficulty is not greater than d (p_7=2 ≤ d=3) and works for 2 minutes (i.e. the minutes 10, 11);
* Polycarp notices that he has finished m=2 tasks and takes a break for 1+2=3 minutes (i.e. on the minutes 12, 13, 14).
Polycarp stops exactly after t minutes. If Polycarp started a task but has not finished it by that time, the task is not considered as completed. It is allowed to complete less than m tasks in the last group. Also Polycarp considers acceptable to have shorter break than needed after the last group of tasks or even not to have this break at all — his working day is over and he will have enough time to rest anyway.
Please help Polycarp to find such value d, which would allow him to complete maximum possible number of tasks in t minutes.
Input
The first line of the input contains single integer c (1 ≤ c ≤ 5 ⋅ 10^4) — number of test cases. Then description of c test cases follows. Solve test cases separately, test cases are completely independent and do not affect each other.
Each test case is described by two lines. The first of these lines contains three space-separated integers n, m and t (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5, 1 ≤ t ≤ 4 ⋅ 10^{10}) — the number of tasks in Polycarp's list, the number of tasks he can do without a break and the total amount of time Polycarp can work on tasks. The second line of the test case contains n space separated integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ 2 ⋅ 10^5) — difficulties of the tasks.
The sum of values n for all test cases in the input does not exceed 2 ⋅ 10^5.
Output
Print c lines, each line should contain answer for the corresponding test case — the maximum possible number of tasks Polycarp can complete and the integer value d (1 ≤ d ≤ t) Polycarp should use in time management rule, separated by space. If there are several possible values d for a test case, output any of them.
Examples
Input
4
5 2 16
5 6 1 4 7
5 3 30
5 6 1 4 7
6 4 15
12 5 15 7 20 17
1 1 50
100
Output
3 5
4 7
2 10
0 25
Input
3
11 1 29
6 4 3 7 5 3 4 7 3 5 3
7 1 5
1 1 1 1 1 1 1
5 2 18
2 3 3 7 5
Output
4 3
3 1
4 5
Note
In the first test case of the first example n=5, m=2 and t=16. The sequence of difficulties is [5, 6, 1, 4, 7]. If Polycarp chooses d=5 then he will complete 3 tasks. Polycarp will work by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=5 ≤ d=5) and works for 5 minutes (i.e. the minutes 1, 2, ..., 5);
* Polycarp reads the second task, its difficulty is greater than d (p_2=6 > d=5) and skips it without spending any time;
* Polycarp reads the third task, its difficulty is not greater than d (p_3=1 ≤ d=5) and works for 1 minute (i.e. the minute 6);
* Polycarp notices that he has finished m=2 tasks and takes a break for 5+1=6 minutes (i.e. on the minutes 7, 8, ..., 12);
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=4 ≤ d=5) and works for 4 minutes (i.e. the minutes 13, 14, 15, 16);
* Polycarp stops work because of t=16.
In total in the first test case Polycarp will complete 3 tasks for d=5. He can't choose other value for d to increase the number of completed tasks.
Submitted Solution:
```
import io, os
input = io.StringIO(os.read(0, os.fstat(0).st_size).decode()).readline
ii = lambda: int(input())
mi = lambda: map(int, input().split())
li = lambda: list(mi())
out = []
for _ in range(ii()):
n, m, t = mi()
p = li()
def check(d):
cur = tim = tot = totim = 0
for i in range(n):
x = p[i]
if x > d: continue
totim += x
tim += x
if totim > t: break
cur += 1
tot += 1
if cur == m:
totim += tim
if totim > t: break
cur = tim = 0
return all(x > d for x in p[i+1:]), tot
lo, hi = 1, t
while lo < hi:
mid = (lo + hi + 1) >> 1
if check(mid)[0]:
lo = mid
else:
hi = mid - 1
out.append('%d %d' % (check(lo)[1], lo))
print(*out, sep='\n')
```
No
| 97,856 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp has a lot of work to do. Recently he has learned a new time management rule: "if a task takes five minutes or less, do it immediately". Polycarp likes the new rule, however he is not sure that five minutes is the optimal value. He supposes that this value d should be chosen based on existing task list.
Polycarp has a list of n tasks to complete. The i-th task has difficulty p_i, i.e. it requires exactly p_i minutes to be done. Polycarp reads the tasks one by one from the first to the n-th. If a task difficulty is d or less, Polycarp starts the work on the task immediately. If a task difficulty is strictly greater than d, he will not do the task at all. It is not allowed to rearrange tasks in the list. Polycarp doesn't spend any time for reading a task or skipping it.
Polycarp has t minutes in total to complete maximum number of tasks. But he does not want to work all the time. He decides to make a break after each group of m consecutive tasks he was working on. The break should take the same amount of time as it was spent in total on completion of these m tasks.
For example, if n=7, p=[3, 1, 4, 1, 5, 9, 2], d=3 and m=2 Polycarp works by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=3 ≤ d=3) and works for 3 minutes (i.e. the minutes 1, 2, 3);
* Polycarp reads the second task, its difficulty is not greater than d (p_2=1 ≤ d=3) and works for 1 minute (i.e. the minute 4);
* Polycarp notices that he has finished m=2 tasks and takes a break for 3+1=4 minutes (i.e. on the minutes 5, 6, 7, 8);
* Polycarp reads the third task, its difficulty is greater than d (p_3=4 > d=3) and skips it without spending any time;
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=1 ≤ d=3) and works for 1 minute (i.e. the minute 9);
* Polycarp reads the tasks 5 and 6, skips both of them (p_5>d and p_6>d);
* Polycarp reads the 7-th task, its difficulty is not greater than d (p_7=2 ≤ d=3) and works for 2 minutes (i.e. the minutes 10, 11);
* Polycarp notices that he has finished m=2 tasks and takes a break for 1+2=3 minutes (i.e. on the minutes 12, 13, 14).
Polycarp stops exactly after t minutes. If Polycarp started a task but has not finished it by that time, the task is not considered as completed. It is allowed to complete less than m tasks in the last group. Also Polycarp considers acceptable to have shorter break than needed after the last group of tasks or even not to have this break at all — his working day is over and he will have enough time to rest anyway.
Please help Polycarp to find such value d, which would allow him to complete maximum possible number of tasks in t minutes.
Input
The first line of the input contains single integer c (1 ≤ c ≤ 5 ⋅ 10^4) — number of test cases. Then description of c test cases follows. Solve test cases separately, test cases are completely independent and do not affect each other.
Each test case is described by two lines. The first of these lines contains three space-separated integers n, m and t (1 ≤ n ≤ 2 ⋅ 10^5, 1 ≤ m ≤ 2 ⋅ 10^5, 1 ≤ t ≤ 4 ⋅ 10^{10}) — the number of tasks in Polycarp's list, the number of tasks he can do without a break and the total amount of time Polycarp can work on tasks. The second line of the test case contains n space separated integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ 2 ⋅ 10^5) — difficulties of the tasks.
The sum of values n for all test cases in the input does not exceed 2 ⋅ 10^5.
Output
Print c lines, each line should contain answer for the corresponding test case — the maximum possible number of tasks Polycarp can complete and the integer value d (1 ≤ d ≤ t) Polycarp should use in time management rule, separated by space. If there are several possible values d for a test case, output any of them.
Examples
Input
4
5 2 16
5 6 1 4 7
5 3 30
5 6 1 4 7
6 4 15
12 5 15 7 20 17
1 1 50
100
Output
3 5
4 7
2 10
0 25
Input
3
11 1 29
6 4 3 7 5 3 4 7 3 5 3
7 1 5
1 1 1 1 1 1 1
5 2 18
2 3 3 7 5
Output
4 3
3 1
4 5
Note
In the first test case of the first example n=5, m=2 and t=16. The sequence of difficulties is [5, 6, 1, 4, 7]. If Polycarp chooses d=5 then he will complete 3 tasks. Polycarp will work by the following schedule:
* Polycarp reads the first task, its difficulty is not greater than d (p_1=5 ≤ d=5) and works for 5 minutes (i.e. the minutes 1, 2, ..., 5);
* Polycarp reads the second task, its difficulty is greater than d (p_2=6 > d=5) and skips it without spending any time;
* Polycarp reads the third task, its difficulty is not greater than d (p_3=1 ≤ d=5) and works for 1 minute (i.e. the minute 6);
* Polycarp notices that he has finished m=2 tasks and takes a break for 5+1=6 minutes (i.e. on the minutes 7, 8, ..., 12);
* Polycarp reads the fourth task, its difficulty is not greater than d (p_4=4 ≤ d=5) and works for 4 minutes (i.e. the minutes 13, 14, 15, 16);
* Polycarp stops work because of t=16.
In total in the first test case Polycarp will complete 3 tasks for d=5. He can't choose other value for d to increase the number of completed tasks.
Submitted Solution:
```
import io, os
input = io.StringIO(os.read(0, os.fstat(0).st_size).decode()).readline
ii = lambda: int(input())
mi = lambda: map(int, input().split())
li = lambda: list(mi())
out = []
for _ in range(ii()):
n, m, t = mi()
p = li()
def check(d):
cur = tim = tot = totim = 0
for i in range(n):
x = p[i]
if x > d: continue
totim += x
tim += x
if totim > t: break
cur += 1
tot += 1
if cur == m:
totim += tim
if totim > t: break
cur = tim = 0
return all(x > d for x in p[i+1:]), tot
lo, hi = 0, max(p)
while lo < hi:
mid = (lo + hi + 1) >> 1
if check(mid)[0]:
lo = mid
else:
hi = mid - 1
out.append('%d %d' % (check(lo)[1], lo))
print(*out, sep='\n')
```
No
| 97,857 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
s = 'abcdefghijklmnopqrstuvwxyz'
for _ in range(int(input())):
n, k = list(map(int, input().strip().split()))
q = n//k
rem = n % k
print(s[:k]*q + s[:rem])
```
| 97,858 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
t = int(input())
alp = list('abcdefghijklmnopqrstuvwxyz')
for i in range(t):
n, k = tuple(map(int, input().split()))
j = 0
s = ''
while len(s) != n:
s += alp[j]
if j == k - 1:
j = -1
j += 1
print(s)
```
| 97,859 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
num=int(input())
alph="abcdefghijklmnopqrstuvwxyz"
while num:
a=[]
r=[]
n,k=map(int,input().split())
f=int(n/k)
for i in range(k):
a.append(alph[i])
for i in range(len(a)):
for j in range(f):
r.append(a[i])
while len(r)!=n:
r.append(a[k-1])
print("".join(r))
num-=1
```
| 97,860 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
alphabet = 'abcdefghijklmnopqrstuvwxyz'
t = int(input())
for i in range(t):
x, y = list(map(int, input().split()))
k = x // y
s = ''
for i in range(k):
s += alphabet[:y]
k = x % y
if k != 0:
s += alphabet[:k]
print(s)
```
| 97,861 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
t = int(input())
for i in range(t):
n, k = input().split(' ')
n = int(n)
k = int(k)
res = []
y = 97
for i in range(n):
res.append(y + i%k)
print("".join([chr(e) for e in res]))
```
| 97,862 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
t = int(input())
for _ in range(t) :
n, k = map(int, input().split())
for i in range(n) :
print(chr(ord('a') + i % k), end='');
print()
```
| 97,863 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
t=int(input())
for _ in range(t):
n,k=map(int,input().split())
s=''
for i in range(97,97+k):
s+=chr(i)
s=s*(n//k)+s[:n%k]
print(s)
```
| 97,864 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Tags: implementation
Correct Solution:
```
for _ in range(int(input())):
n, k = [int(i) for i in input().split()]
res = ""
for i in range(k-1):
for _ in range(n // k):
res += chr(97 + i)
res += chr(97+k-1) * (n - ((n // k) * (k - 1)))
print(res)
```
| 97,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
n = int(input())
for i in range(n):
a,b=list(map(int,input().split()))
c = 0
st=[]
for j in range(a):
s = (c+ord("a"))
st.append(chr(s))
c = (c+1)%b
for k in range(len(st)):
print(st[k],end="")
print("\n")
a = []
```
Yes
| 97,866 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
def main():
n, k = map(int, input().split())
res = ''
for i in range(n):
res += chr(ord('a') + i % k)
print(res)
if __name__ == '__main__':
t = int(input())
for _ in range(t):
main()
```
Yes
| 97,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
def solve():
n, k = map(int, input().split())
for i in range(n):
print(chr(ord('a') + i % k), end="")
print("")
t = eval(input())
while t:
solve()
t -= 1
```
Yes
| 97,868 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
import sys
t = int(input())
for i in range(t):
n, k = map(int, sys.stdin.readline().split())
s = ""
for a in range(n):
s+= chr(ord("a")+(a%k))
print(s)
```
Yes
| 97,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
from random import randint
a=int(input())
b=[]
c=0
d=[]
e=0
f='abcdefghijklmnopqrstuvwxyz'
for i in range(a):
n,k=map(int,input().split())
for i in range(n):
print(f[e],end='')
e+=1
e=0
print()
```
No
| 97,870 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
import string
cases = int(input())
for _ in range(cases):
lst = [int(x) for x in input().split()]
letter = string.ascii_lowercase
word = ""
while len(word) < lst[0]:
for i in letter[:lst[1]]:
word = word + i
print(word)
```
No
| 97,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
t=int(input())
a="abcdefghijklmnopqrstuvxyz"
for i in range(t):
n,k=map(int,input().split())
print(((n//k)*a[:k])+a[:n%k])
```
No
| 97,872 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two integers n and k.
Your task is to construct such a string s of length n that for each i from 1 to k there is at least one i-th letter of the Latin alphabet in this string (the first letter is 'a', the second is 'b' and so on) and there are no other letters except these. You have to maximize the minimal frequency of some letter (the frequency of a letter is the number of occurrences of this letter in a string). If there are several possible answers, you can print any.
You have to answer t independent queries.
Input
The first line of the input contains one integer t (1 ≤ t ≤ 100) — the number of queries.
The next t lines are contain queries, one per line. The i-th line contains two integers n_i and k_i (1 ≤ n_i ≤ 100, 1 ≤ k_i ≤ min(n_i, 26)) — the length of the string in the i-th query and the number of characters in the i-th query.
Output
Print t lines. In the i-th line print the answer to the i-th query: any string s_i satisfying the conditions in the problem statement with constraints from the i-th query.
Example
Input
3
7 3
4 4
6 2
Output
cbcacab
abcd
baabab
Note
In the first example query the maximum possible minimal frequency is 2, it can be easily seen that the better answer doesn't exist. Other examples of correct answers: "cbcabba", "ccbbaaa" (any permutation of given answers is also correct).
In the second example query any permutation of first four letters is acceptable (the maximum minimal frequency is 1).
In the third example query any permutation of the given answer is acceptable (the maximum minimal frequency is 3).
Submitted Solution:
```
T = int(input())
k = 0
s = ''
while True:
if T == 0: break
T = T - 1
a, b = map(int, input().split())
for i in range(b):
for j in range(a // b):
s += chr(ord('a') + i)
for i in range(a % b):
s += 'a'
print(s)
```
No
| 97,873 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
import time
n = int(input())
start = time.time()
ans = 0
for i in range(2, n):
ans += i*(i+1)
print(ans)
finish = time.time()
#print(finish - start)
```
| 97,874 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
v = int(input())
ans,a,b = 6,3,4
while(b<=v):
ans += (a*b)
a+=1
b+=1
print(ans)
```
| 97,875 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
a = int(input())
ans = 0
for i in range(a - 2):
ans += (i + 2) * (i + 3)
print(ans)
```
| 97,876 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
n = int(input())
s = 0
for i in range (3,n+1):
s += i * (i-1)
print(s)
```
| 97,877 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
n =int(input())
if n >= 3 and n <= 500 :
print((((n*n*n)-n)//3)-2)
```
| 97,878 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
n = int(input())
i = 2
s = 0
while i < n:
s += i * (i+1)
i += 1
print(s)
```
| 97,879 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
def nCk(n, k):
if n < k:
return 0
if k == 0:
return 1
if k == 1:
return n if n != 0 else 0
x = n
for i in range(1, k):
x *= (n-i)
y = 1
while k > 0:
y *= k
k -= 1
x //= y
return x
n = int(input())
print(6 * nCk(n - 3, 0) + 12 * nCk(n - 3, 1) + 8 * nCk(n - 3, 2) + 2 * nCk(n - 3, 3))
```
| 97,880 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Tags: dp, greedy, math
Correct Solution:
```
Q = int(input())
s = 0
for i in range(3,Q+1):
s += (i-1)*i
print(s)
```
| 97,881 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
n = int(input())
res = 0
for i in range(n - 2):
res += (i + 2) * (i + 3)
print(res)
```
Yes
| 97,882 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
n=int(input());print((n**3-n)//3-2)
```
Yes
| 97,883 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
# https://codeforces.com/problemset/problem/1140/D
n = int(input())
dp = [0]*(n+1)
dp[3] = 6
for x in range(4, n+1):
dp[x] = dp[x-1] + x*(x-1)
print(dp[n])
```
Yes
| 97,884 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
n=int(input())
summ=0
for i in range(3,n+1):
summ+=(1*(i-1)*(i))
print(summ)
```
Yes
| 97,885 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
def solve(a, n):
# print("Here")
q = []
if n==4:
r = a[0]*a[1]*a[2] + a[2]*a[3]*a[0]
return r
if n==3:
r = a[0]*a[1]*a[2]
return r
r = 0
q = [a[0]]
for i in range(0, n-2, 2):
r += a[i]*a[i+1]*a[i+2]
# print(i+1,i+2,i+3)
q.append(a[i+2])
if n%2==0:
r += a[-2]*a[-1]*a[0]
# print(i-1,i,1)
# print(q)
# print('-'*10)
return r + solve(q, len(q))
#-----------------------------------------
t = 1
for _ in range(t):
n = int(input())
# a = list(input())
a = list(range(1, n+1))
res = solve(a, n)
print(res)
# print(*res)
```
No
| 97,886 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
from math import *
n=int(input())
print((n-1)*n*(2*n-1)//6+(n-1)*(n-2)//2-2)
```
No
| 97,887 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
from collections import defaultdict
from functools import reduce
from itertools import permutations
mi = lambda: [int(i) for i in input().split()]
flat = lambda l: reduce(lambda a, b: a + b, l)
n = mi()[0]
if n == 3:
print(6)
elif n == 4:
print(18)
else:
u = [*range(2, n + 2)]
a = [u.pop(-1)]
d = 0
while u:
a.append(u.pop(d))
if u:
a.insert(0, u.pop(d))
d = -1 if d == 0 else 0
# print(a)
r = 0
for i in range(len(a)):
r += a[i - 1] * a[i]
print(r)
# # # a = [2, 6, 3, 5, 4]
# a = [2, 3, 4, 5, 6, 7, 8]
# m = 1000000000000000
#
# for p in permutations(a, len(a)):
# r = 0
#
# for i in range(len(p)):
# r += p[i - 1] * p[i]
#
# # if r == 72:
# print(r, p)
# m = min(m, r)
#
# print(m)
```
No
| 97,888 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a regular polygon with n vertices labeled from 1 to n in counter-clockwise order. The triangulation of a given polygon is a set of triangles such that each vertex of each triangle is a vertex of the initial polygon, there is no pair of triangles such that their intersection has non-zero area, and the total area of all triangles is equal to the area of the given polygon. The weight of a triangulation is the sum of weigths of triangles it consists of, where the weight of a triagle is denoted as the product of labels of its vertices.
Calculate the minimum weight among all triangulations of the polygon.
Input
The first line contains single integer n (3 ≤ n ≤ 500) — the number of vertices in the regular polygon.
Output
Print one integer — the minimum weight among all triangulations of the given polygon.
Examples
Input
3
Output
6
Input
4
Output
18
Note
According to Wiki: polygon triangulation is the decomposition of a polygonal area (simple polygon) P into a set of triangles, i. e., finding a set of triangles with pairwise non-intersecting interiors whose union is P.
In the first example the polygon is a triangle, so we don't need to cut it further, so the answer is 1 ⋅ 2 ⋅ 3 = 6.
In the second example the polygon is a rectangle, so it should be divided into two triangles. It's optimal to cut it using diagonal 1-3 so answer is 1 ⋅ 2 ⋅ 3 + 1 ⋅ 3 ⋅ 4 = 6 + 12 = 18.
Submitted Solution:
```
n=int(input())
su=0
for i in range(2,n-1):
su=su+i*i+1
print(su)
```
No
| 97,889 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
k=1<<60
for i in range(n):
if i:
k=min(k,min(a[0],a[i])//i)
if i<n-1:
k=min(k,min(a[-1],a[i])//(n-1-i))
print(k)
```
| 97,890 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
def main():
n = int(input())
array = list(map(int,input().split()))
nums = []
for i in range(n):
nums.append((array[i],i+1))
k = float('inf')
for i in range(1,n):
diff = abs(i+1-1)
val = min(array[0],array[i])
k = min(k,val//diff)
for i in range(n-2,-1,-1):
diff = abs(i+1-n)
val = min(array[-1],array[i])
k = min(k,val//diff)
if k == float('inf'):
print(0)
else:
print(k)
main()
```
| 97,891 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
n=int(input())
print(min(x//max(i,n-i-1)for i,x in enumerate(map(int,input().split()))))
```
| 97,892 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
def relax(ans, val_, dist_):
if dist_ != 0:
return min(ans, val_ // dist_)
else: return ans
def solution(nums):
uniq = list(set(nums))
uniq.sort()
poss = dict()
for pos, num in enumerate(nums):
if num not in poss:
poss[num] = []
poss[num].append(pos)
for key in poss:
poss[key].sort()
ans = (1 << 30)
ans = relax(ans, uniq[-1], abs(poss[uniq[-1]][0] - poss[uniq[-1]][-1]))
max_pos = poss[uniq[-1]][-1]
min_pos = poss[uniq[-1]][0]
for i in range(2, len(uniq)+1):
key = uniq[-i]
max_dist = abs(poss[key][0] - poss[key][-1])
for j in [-1, 0]:
tmp = max(abs(poss[key][j] - max_pos), abs(poss[key][j] - min_pos))
max_dist = max(max_dist, tmp)
max_pos = max(max_pos, poss[key][-1])
min_pos = min(min_pos, poss[key][0])
ans = relax(ans, key, max_dist)
return ans
if __name__ == '__main__':
n = int(input())
a = list(map(int, input().split()))
print(solution(a), end="")
```
| 97,893 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
n = int(input())
sp = list(map(int, input().split()))
k = 10 ** 9 + 1
zn1 = sp[0]
zn2 = sp[-1]
ch2 = min(sp[0], zn2) // (n - 1)
if ch2 < k:
k = ch2
for i in range(1, n - 1):
ch1 = min(sp[i], zn1) // i
ch2 = min(sp[i], zn2) // (n - i - 1)
if ch2 < k:
k = ch2
if ch1 < k:
k = ch1
ch1 = min(sp[-1], zn1) // (n - 1)
if ch1 < k:
k = ch1
print(k)
```
| 97,894 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
n=int(input())
l=list(map(int,input().split()))
ans=max(l)
for i in range(n):
k=l[i]//(max(i,n-i-1))
if(k<ans):
ans=k
print(ans)
```
| 97,895 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
n=int(input())
a=[int(x) for x in input().split()]
ans=10**12
for i in range(n):
ans=min(ans,a[i]//max(i,n-1-i))
print(ans)
```
| 97,896 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Tags: implementation, math
Correct Solution:
```
# CODE BEGINS HERE.................
import math
n = int(input())
a = list(map(int, input().split()))
k = math.inf
for i in range(n):
# print(k)
if k > a[i]//max(n - i - 1, i):
k = a[i]//max(n - i - 1, i)
print(k)
#CODE ENDS HERE....................
```
| 97,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Submitted Solution:
```
n=int(input())
arr=list(map(int,input().split()))
a=[]
for i in range(n):
a.append(arr[i]//max(n-i-1,i))
print(min(a))
```
Yes
| 97,898 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's call an array of non-negative integers a_1, a_2, …, a_n a k-extension for some non-negative integer k if for all possible pairs of indices 1 ≤ i, j ≤ n the inequality k ⋅ |i - j| ≤ min(a_i, a_j) is satisfied. The expansion coefficient of the array a is the maximal integer k such that the array a is a k-extension. Any array is a 0-expansion, so the expansion coefficient always exists.
You are given an array of non-negative integers a_1, a_2, …, a_n. Find its expansion coefficient.
Input
The first line contains one positive integer n — the number of elements in the array a (2 ≤ n ≤ 300 000). The next line contains n non-negative integers a_1, a_2, …, a_n, separated by spaces (0 ≤ a_i ≤ 10^9).
Output
Print one non-negative integer — expansion coefficient of the array a_1, a_2, …, a_n.
Examples
Input
4
6 4 5 5
Output
1
Input
3
0 1 2
Output
0
Input
4
821 500 479 717
Output
239
Note
In the first test, the expansion coefficient of the array [6, 4, 5, 5] is equal to 1 because |i-j| ≤ min(a_i, a_j), because all elements of the array satisfy a_i ≥ 3. On the other hand, this array isn't a 2-extension, because 6 = 2 ⋅ |1 - 4| ≤ min(a_1, a_4) = 5 is false.
In the second test, the expansion coefficient of the array [0, 1, 2] is equal to 0 because this array is not a 1-extension, but it is 0-extension.
Submitted Solution:
```
n=int(input())
l=list(map(int,input().split()))
l1=[]
for i in range(n-1):
if n-i-1>i:
l1.append(min(l[i],l[n-1])/(n-i-1))
else:
l1.append(min(l[i],l[0])/i)
print(int(min(l1)))
```
Yes
| 97,899 |
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