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Corollary 4.7. Let \( \phi \left( z\right) \in K\left( z\right) \) be a rational map of degree \( d \geq 2 \) . Then for all prime numbers \( \ell \) except possibly for \( d + 2 \) exceptions, the map \( \phi \) has a point of primitive period \( \ell \) .
Proof. We begin by discarding the finitely many primes \( \ell \) satisfying either of the following conditions:\n\n- \( K \) has characteristic \( \ell \) .\n\n- There is some \( Q \in \operatorname{Fix}\left( \phi \right) \) with \( \lambda \left( Q\right) \neq 1 \) and \( \lambda {\left( Q\right) }^{\ell } = 1 \) .\...
Yes
Theorem 4.8. (I.N. Baker [19]) Let \( \phi \left( z\right) \in K\left( z\right) \) be a rational map of degree \( d \geq 2 \) defined over a field \( K \) of characteristic 0 . Suppose that \( \phi \) has no primitive \( n \) -periodic points. Then \( \left( {n, d}\right) \) is one of the pairs\n\n\[ \left( {2,2}\right...
Proof. For the proof, which is function-theoretic in nature, see [19] or \( \left\lbrack {{43},§{6.8}}\right\rbrack \) .
No
It is easy to see that \( {X}_{1}\left( 1\right) \) and \( {X}_{1}\left( 2\right) \) are rational curves. Indeed, the projective closures of \( {Y}_{1}\left( 1\right) \) and \( {Y}_{1}\left( 2\right) \) are smooth conics, \[ {X}_{1}\left( 1\right) : {z}^{2} - {zw} + {yw} = 0\;\text{ and }\;{X}_{1}\left( 2\right) : {z}^...
It turns out that \( {X}_{1}\left( 3\right) \) is also rational, but this is less clear from the equation in Table 4.1. In order to parameterize \( {X}_{1}\left( 3\right) \), suppose that \( \phi \left( z\right) = A{z}^{2} + {Bz} + C \) is any quadratic polynomial with a periodic point of primitive period 3 . Conjugati...
Yes
Theorem 4.11. Let \( K \) be a field of characteristic different from 2.\n\n(a) The map\n\n\[ \n{Y}_{1}\left( n\right) \rightarrow \operatorname{Formal}\left( n\right) ,\;\left( {c,\alpha }\right) \mapsto \left( {{z}^{2} + c,\alpha }\right) ,\n\]\n\n(4.14)\n\nis a bijection of sets.
Proof. (a) We have shown this earlier in this section.
No
We have seen in Example 4.9 that \( {X}_{1}\left( 2\right) \) and \( {X}_{1}\left( 3\right) \) are rational curves, i.e., they are isomorphic to \( {\mathbb{P}}^{1} \), so their quotient curves \( {X}_{0}\left( 2\right) \) and \( {X}_{0}\left( 3\right) \) must also be rational curves. However, it is still of interest t...
The affine curve \( {Y}_{1}\left( 2\right) \) has equation\n\n\[ \n{Y}_{1}\left( 2\right) : {z}^{2} + z + y + 1 = 0, \n\] \n\nwhere a point \( \left( {c,\alpha }\right) \in {Y}_{1}\left( 2\right) \) corresponds to the quadratic map \( {\phi }_{c}\left( z\right) = {z}^{2} + c \) and point \( \alpha \in {\operatorname{Pe...
No
Theorem 4.17. (a) The affine curve \( {Y}_{1}\left( n\right) \) defined by the equation\n\n\[ \n{Y}_{1}\left( n\right) : {\Phi }_{n,\phi }^{ * }\left( {y, z}\right) = 0 \n\]\n\nis nonsingular.
Proof. The properties of \( {Y}_{1}\left( n\right) \) and \( {X}_{1}\left( n\right) \) were originally proven by Bousch [83], with subsequent proofs by Lau and Schleicher [261] using analytic methods and Morton [307] via algebraic arguments. The latter two papers give various generalizations, including results for the ...
No
Proposition 4.19. The Mandelbrot set is contained in the disk of radius 2, \[ \mathcal{M} \subset \{ c \in \mathbb{C} : \left| c\right| \leq 2\} \]
Proof. Suppose that \( \left| c\right| > 2 \) and let \( {z}_{n} = {\phi }_{c}^{n}\left( 0\right) \) . Then \[ \left| {z}_{n + 1}\right| \geq \left| {z}_{n}^{2}\right| - \left| c\right| = \left| {z}_{n}\right| \cdot \left( {\left| {z}_{n}\right| - 1}\right) + \left( {\left| {z}_{n}\right| - \left| c\right| }\right) . \...
Yes
The set of Misiurewicz points is a set of bounded (absolute) height in \( \overline{\mathbb{Q}} \) . More precisely, the height of a Misiurewicz point \( \gamma \) satisfies \( H\left( \gamma \right) \leq 2 \) . Hence there are only finitely many Misiurewicz points defined over any given number field.
A Misiurewicz point \( c = \gamma \) is the root of a polynomial of the form\n\n\[ \n{M}_{m, n}\left( c\right) = {\phi }_{c}^{n + m}\left( 0\right) - {\phi }_{c}^{m}\left( 0\right) \n\]\n\nfor some \( m \geq 1 \) and \( n \geq 1 \) . These are monic polynomials with coefficients in \( \mathbb{Z} \) , so not only is \( ...
Yes
Theorem 4.23. (Douady-Hubbard) There is a conformal isomorphism from the exterior of the unit disk to the complement of the Mandelbrot set,\n\n\[ \n\\theta : \\{ w \\in \\mathbb{C} : \\left| w\\right| > 1\\} \\overset{ \\sim }{ \\rightarrow }\\mathbb{C} \\smallsetminus \\mathcal{M}.\n\]
Proof. It is not hard to show that for all sufficiently large \( z \) (depending on \( c \) ) there is a consistent way to choose square roots so that the limit\n\n\[ \n{\\psi }_{c}\\left( z\\right) = \\mathop{\\lim }\\limits_{{n \\rightarrow \\infty }}\\sqrt[{2}^{n}]{{\\phi }_{c}^{n}\\left( z\\right) }\n\]\n\nconverge...
No
Proposition 4.27. The variety \( {\operatorname{Rat}}_{d} \) is an affine variety defined over \( \mathbb{Q} \) . The ring of regular functions \( \mathbb{Q}\left\lbrack {\operatorname{Rat}}_{d}\right\rbrack \) of \( {\operatorname{Rat}}_{d} \) is given explicitly by\n\n\[ \mathbb{Q}\left\lbrack {\operatorname{Rat}}_{d...
Proof. We remind the reader that in general, if \( F \in K\left\lbrack {{X}_{0},\ldots ,{X}_{r}}\right\rbrack \) is a homogeneous polynomial of degree \( n \), then the complement of the zero set of \( F \), \n\n\[ V = {\mathbb{P}}^{r} \smallsetminus \{ F = 0\} \]\n\n is an affine variety of dimension \( r \) . (See [1...
Yes
Let\n\n\\[ \n\\rho \\left( {\\mathbf{a},\\mathbf{b}}\\right) = {a}_{2}^{2}{b}_{0}^{2} - {a}_{1}{a}_{2}{b}_{0}{b}_{1} + {a}_{0}{a}_{2}{b}_{1}^{2} + {a}_{1}^{2}{b}_{0}{b}_{2} - 2{a}_{0}{a}_{2}{b}_{0}{b}_{2} - {a}_{0}{a}_{1}{b}_{1}{b}_{2} + {a}_{0}^{2}{b}_{2}^{2} \n\\]\n\nbe the resultant of \\( {a}_{0}{X}^{2} + {a}_{1}{X...
Of course, this is not the smallest affine space into which \\( {\\operatorname{Rat}}_{2} \\) can be embedded. Projecting onto appropriately chosen hy-perplanes, there is certainly an affine embedding of the 5-dimensional space \\( {\\operatorname{Rat}}_{2} \\) into \\( {\\mathbb{A}}^{11} \\) ; see [198, Exercise IV.3....
Yes
Proposition 4.31. Let \( V \) be an algebraic variety and let\n\n\[ \psi : {\mathbb{P}}_{V}^{1} \rightarrow {\mathbb{P}}_{V}^{1} \]\n\nbe a morphism over \( V \) of degree \( d \) . Then there is a unique morphism\n\n\[ \lambda : V \rightarrow {\operatorname{Rat}}_{d} \]\n\nsuch that the induced map \( \lambda : {\math...
Proof. Let \( U \subset V \) be an affine open subset and write \( K\left\lbrack U\right\rbrack \) for its affine coordinate ring. The fact that \( \psi \) is a morphism over \( V \) implies that it restricts to give a morphism \( \psi : {\mathbb{P}}_{U}^{1} \rightarrow {\mathbb{P}}_{U}^{1} \) over \( U \) . This restr...
Yes
Proposition 4.33. The map\n\n\[ \n{\mathrm{{PGL}}}_{2} \times {\mathrm{{Rat}}}_{d} \rightarrow {\mathrm{{Rat}}}_{d},\;\left( {f,\phi }\right) \mapsto {\phi }^{f} = {f}^{-1}{\phi f}, \n\]\n\n(4.24)\n\nis an algebraic group action of \( {\mathrm{{PGL}}}_{2} \) on \( {\operatorname{Rat}}_{d} \) and is defined over \( \mat...
Proof. The proof is mostly a matter of unsorting the definitions. Let\n\n\[ \nf = \left\lbrack {{\alpha X} + {\beta Y},{\gamma X} + {\delta Y}}\right\rbrack \in {\mathrm{{PGL}}}_{2} \subset {\mathbb{P}}^{3}\;\text{ and }\;\phi = \left\lbrack {{F}_{\mathbf{a}},{F}_{\mathbf{b}}}\right\rbrack \in {\operatorname{Rat}}_{d} ...
No
In principle it is possible to explicitly write down the action of \( {\mathrm{{PGL}}}_{2} \) on \( {\operatorname{Rat}}_{d} \), but in practice the expressions become hopelessly unwieldy for even moderate values of \( d \) . As illustration, we describe the action for \( d = 2 \) . Let\n\n\[ f = \left\lbrack {{\alpha ...
\[ {a}_{0}^{\prime } = {\alpha }^{2}\delta {a}_{0} + {\alpha \gamma \delta }{a}_{1} + {\gamma }^{2}\delta {a}_{2} - {\alpha }^{2}\beta {b}_{0} - {\alpha \beta \gamma }{b}_{1} - \beta {\gamma }^{2}{b}_{2}, \] \n\n\[ {a}_{1}^{\prime } = {2\alpha \beta \delta }{a}_{0} + \left( {{\alpha \delta } + {\beta \gamma }}\right) \...
Yes
Theorem 4.36. There is an algebraic variety \( {\mathcal{M}}_{d} \) defined over \( \mathbb{Q} \) and a morphism\n\n\[ \langle \cdot \rangle : {\operatorname{Rat}}_{d} \rightarrow {\mathcal{M}}_{d} \]\n\n(4.26)\n\ndefined over \( \mathbb{Q} \) with the following properties:\n\n(a) The map (4.26) is \( {\mathrm{{PSL}}}_...
Proof Sketch. A full proof of Theorem 4.36 (see [416]) uses the machinery of geometric invariant theory [322] and is thus unfortunately beyond the scope of this book. Geometric invariant theory tells us that there is a certain subset of \( {\mathbb{P}}^{{2d} + 1} \), called the stable locus, on which the conjugation ac...
Yes
Let \( \phi \in {\operatorname{Rat}}_{d}\left( \mathbb{C}\right) \) be a rational function of degree \( d \) defined over the complex numbers. Associated to each fixed point \( P \in \operatorname{Fix}\left( \phi \right) \) is its multiplier \( {\lambda }_{P}\left( \phi \right) \in {\mathbb{C}}^{ * } \) . A simple calc...
\[ \operatorname{Fix}\left( {\phi }^{f}\right) = {f}^{-1}\left( {\operatorname{Fix}\left( \phi \right) }\right) \;\text{ and }\;{\lambda }_{{f}^{-1}\left( P\right) }\left( {\phi }^{f}\right) = {\lambda }_{P}\left( \phi \right) \;\text{ for all }P \in \operatorname{Fix}\left( \phi \right) . \]
Yes
We illustrate the construction of Example 4.44 for rational maps of degree 2. As usual, we write\n\n\[ \phi = \left\lbrack {{F}_{\mathbf{a}},{F}_{\mathbf{b}}}\right\rbrack = \left\lbrack {{a}_{0}{X}^{2} + {a}_{1}{XY} + {a}_{2}{Y}^{2},{b}_{0}{X}^{2} + {b}_{1}{XY} + {b}_{2}{Y}^{2}}\right\rbrack . \]\n\nThe map \( \phi \)...
Notice that the denominator of \( {\sigma }_{1}\left( \phi \right) \) is \( \operatorname{Res}\left( {{F}_{\mathbf{a}},{F}_{\mathbf{b}}}\right) \), so \( {\sigma }_{1}\left( \phi \right) \) is in \( \mathbb{Q}\left\lbrack {\operatorname{Rat}}_{d}\right\rbrack \) . It is far less obvious that this expression for \( {\si...
No
Let \( \phi \left( z\right) = {z}^{d} \) with \( d \geq 2 \) . Then \( {\operatorname{Per}}_{n}\left( \phi \right) = \{ 0,\infty \} \cup {\mathbf{\mu }}_{{d}^{n} - 1} \) consists of the points \( 0,\infty \), and the \( {\left( {d}^{n} - 1\right) }^{\text{th }} \) roots of unity.
It is easy to check that \( {\lambda }_{0}\left( \phi \right) = {\lambda }_{\infty }\left( \phi \right) = 0 \), and for \( \zeta \in {\mathbf{\mu }}_{{d}^{n} - 1} \) we have\n\n\[ \n{\lambda }_{\zeta }\left( \phi \right) = {\left( {\phi }^{n}\right) }^{\prime }\left( \zeta \right) = {d}^{n}{\zeta }^{{d}^{n} - 1} = {d}^...
Yes
Let \( \phi \left( z\right) = {z}^{2} + {bz} \). Then\n\n\[ \n{\operatorname{Per}}_{1}\left( \phi \right) = \{ 0,1 - b,\infty \} \;\text{ and }\;{\Lambda }_{1}\left( \phi \right) = \{ b,2 - b,0\} .\n\]
Next we compute\n\n\[ \n{\Phi }_{\phi ,2}^{ * } = \frac{{\phi }^{2}\left( z\right) - z}{\phi \left( z\right) - z} = {z}^{2} + \left( {b + 1}\right) z + b + 1.\n\]\n\nThe two points of formal period 2 are the roots of \( {\Phi }_{\phi ,2}^{ * } \),\n\n\[ \n{\operatorname{Per}}_{2}^{ * }\left( \phi \right) = \left\{ \fra...
Yes
Continuing with Example 4.46, let \( \phi \left( z\right) = {z}^{d} \). Then
\[ \mathop{\prod }\limits_{{\lambda \in {\Lambda }_{n}\left( \phi \right) }}\left( {T + \lambda }\right) = {T}^{2}{\left( T + {d}^{n}\right) }^{{d}^{n} - 1}\;\text{ and }\;\mathop{\prod }\limits_{{\lambda \in {\Lambda }_{n}^{ * }\left( \phi \right) }}\left( {T + \lambda }\right) = {\left( T + {d}^{n}\right) }^{\varphi ...
Yes
Continuing with Example 4.47, let \( \phi \left( z\right) = {z}^{2} + {bz} \) . We computed \( {\Lambda }_{1}\left( \phi \right) = \{ b,2 - b,0\} \)
\[ \mathop{\prod }\limits_{{\lambda \in {\Lambda }_{1}\left( \phi \right) }}\left( {T + \lambda }\right) = \left( {T + b}\right) \left( {T + 2 - b}\right) T = {T}^{3} + 2{T}^{2} + \left( {{2b} - {b}^{2}}\right) T \] which gives \[ {\sigma }_{1}^{\left( 1\right) } = 2,\;{\sigma }_{2}^{\left( 1\right) } = {2b} - {b}^{2},...
Yes
For \( \phi \in {\operatorname{Rat}}_{d}, n \geq 1 \), and \( i \) in the appropriate range, let \( {\sigma }_{i}^{\left( n\right) }\left( \phi \right) \) and \( {\overset{ * }{\sigma }}_{i}^{\left( n\right) }\left( \phi \right) \) be the symmetric polynomials of the \( n \) -multiplier spectra of \( \phi \) . (a) The ...
Proof. We sketch the proof for \( {\sigma }_{i}^{\left( n\right) }\left( \phi \right) \) and leave \( {\overset{ * }{\sigma }}_{i}^{\left( n\right) }\left( \phi \right) \) as an exercise for the reader (Exercise 4.26).\n\n(a) We write\n\n\[ {\phi }^{n} = \left\lbrack {{F}_{\mathbf{a}, n}\left( {X, Y}\right) ,{F}_{\math...
No
For each \( t \in {\mathbb{C}}^{ * } \) with \( t \neq - \frac{27}{4} \), consider the rational map \[ {\phi }_{t}\left( x\right) = \frac{{x}^{4} - {2t}{x}^{2} - {8tx} + {t}^{2}}{4{x}^{3} + {4tx} + {4t}}. \] It is the Lattès map associated to multiplication-by-2 on the elliptic curve \[ {E}_{t} : {y}^{2} = {x}^{3} + {t...
(For proofs of these statements, see Proposition 6.52 in Section 6.5.)
No
Theorem 4.54. Define the degree of \( {\sigma }_{d, N} \) to be the number of points in \( {\sigma }_{d, N}^{-1}\left( P\right) \) for a generic point \( P \) in the image \( {\mathbf{\sigma }}_{d, N}\left( {\mathcal{M}}_{d}\right) \) . One can show that the degree of \( {\mathbf{\sigma }}_{d, N} \) stabilizes as \( N ...
Proof. We will prove this in Chapter 6 using Lattès maps associated to elliptic curves with complex multiplication; see Theorem 6.62.
No
Theorem 4.61. Let \( {\overline{\mathcal{M}}}_{2} = {\mathcal{M}}_{2}^{s} = {\mathcal{M}}_{2}^{ss} \) be the completion of \( {\mathcal{M}}_{2} \) constructed using geometric invariant theory in Theorem 4.40. Then the isomorphism\n\n\[ \mathbf{\sigma } = \left( {{\sigma }_{1},{\sigma }_{2}}\right) : {\mathcal{M}}_{2} \...
Proof. See [302] and [416, Theorem 6.1 and Lemmas 6.2 and 6.3].
No
Proposition 4.65. Let \( \\phi \\left( z\\right) \\in \\widetilde{K}\\left( z\\right) \) be a rational map of degree \( d \\geq 2 \) . Then \( \\operatorname{Aut}\\left( \\phi \\right) \) is a finite subgroup of \( {\\mathrm{{PGL}}}_{\\2}\\left( \\bar{K}\\right) \), and its order is bounded by a function of \( d \) .
Proof. Let \( f \\in \\operatorname{Aut}\\left( \\phi \\right) \) . Then for any point \( P \\in {\\mathbb{P}}^{1}\\left( \\bar{K}\\right) \) and any \( n \\geq 1 \) we have\n\n\[ \n{\\phi }^{n}\\left( P\\right) = {\\left( {\\phi }^{f}\\right) }^{n}\\left( P\\right) = \\left( {{f}^{-1}{\\phi }^{n}f}\\right) \\left( P\\...
Yes
The map \( \phi \left( z\right) = \left( {{z}^{2} - {2z}}\right) /\left( {-{2z} + 1}\right) \) has an automorphism group \( \operatorname{Aut}\left( \phi \right) \) that is isomorphic to the symmetric group \( {\mathcal{S}}_{3} \) on three letters.
More precisely (see Exercise 4.36), the automorphism group of \( \phi \) consists of the following six linear fractional transformations:\n\n\[ \operatorname{Aut}\left( \phi \right) = \left\{ {z,\frac{1}{z},\frac{z - 1}{z},\frac{1}{1 - z},\frac{z}{z - 1},1 - z}\right\} \cong {\mathcal{S}}_{3}. \]
No
We can use Remark 4.70 to prove that the map (4.43) is injective. (We assume that \( K \) does not have characteristic 2.)
A quick computation shows that \( {\Phi }_{{\phi }_{b},2}^{ * }\left( {X, Y}\right) = 2{X}^{2} + b{Y}^{2} \), so the primitive 2-periodic points of \( {\phi }_{b} \) are \( \pm \sqrt{-b/2} \) . Hence if \( {\phi }_{b} \) and \( {\phi }_{c} \) are \( K \) -isomorphic, then the fields \( K\left( \sqrt{-b/2}\right) \) and...
No
Proposition 4.73. Let \( \phi \left( z\right) \in K\left( z\right) \) be a rational map of degree \( d \geq 2 \) and assume that its automorphism group \( \operatorname{Aut}\left( \phi \right) \) is trivial. Then \( \phi \) has no nontrivial twists, i.e., \( \operatorname{Twist}\left( {\phi /K}\right) \) has only one e...
Proof. Suppose that \( \psi \in K\left( z\right) \) is a twist of \( \phi \), so there is an \( f \in {\operatorname{PGL}}_{2}\left( \bar{K}\right) \) such that \( \psi = {\phi }^{f} \) . We let an element \( \sigma \in \operatorname{Gal}\left( {\bar{K}/K}\right) \) act on \( f\left( z\right) \) and \( \phi \left( z\ri...
Yes
Let \( \phi \left( z\right) \in K\left( z\right) \) be an odd rational map, i.e., a rational map satisfying \( \phi \left( {-z}\right) = - \phi \left( z\right) \). Then for each \( b \in {K}^{ * } \) we can define a new rational map \( {\phi }_{b} \) by the formula\n\n\[ \n{\phi }_{b}\left( z\right) = \frac{1}{\sqrt{b}...
The odd parity of \( \phi \left( z\right) \) implies that \( \phi \) has the form \( \phi \left( z\right) = {z\psi }\left( {z}^{2}\right) \) for some rational map \( \psi \left( z\right) \in K\left( z\right) \), so \( {\phi }_{b}\left( z\right) = {z\psi }\left( {b{z}^{2}}\right) \) is in \( K\left( z\right) \). Further...
Yes
Example 4.76. Our second example deals with twists of the variety \( {\mathbb{P}}^{1} \) . For any nonzero \( a \in {K}^{ * } \), let \( {C}_{a} \) be the plane curve \[ {C}_{a} : {x}^{2} + {y}^{2} = a. \] All of these curves are isomorphic over \( \bar{K} \) via the explicit isomorphism \[ i : {C}_{a} \rightarrow {C}_...
Notice that if two curves \( C \) and \( {C}^{\prime } \) are \( K \) -isomorphic, then the \( K \) -isomorphism \( i : C \rightarrow {C}^{\prime } \) identifies their \( K \) -rational points \( i : C\left( K\right) \rightarrow {C}^{\prime }\left( K\right) \) . This suffices to prove that the curves \( {C}_{1} \) and ...
Yes
Proposition 4.77. Let \( X \) be an object defined over \( K \), let \( Y \) be a twist of \( X/K \) , choose a \( \bar{K} \) -isomorphism \( i : Y \rightarrow X \), and define a map\n\n\[ g : \operatorname{Gal}\left( {\bar{K}/K}\right) \rightarrow \operatorname{Aut}\left( X\right) ,\;{g}_{\sigma }\left( x\right) = \le...
Proof. (a) We have \( {g}_{\sigma \tau } = i \circ \left( {\sigma \tau }\right) \left( {i}^{-1}\right) = i \circ \sigma \left( {\tau {\left( i\right) }^{-1}}\right) \) . Consider the following commutative diagram of maps:\n\n\[ X\xrightarrow[]{\sigma \left( {\tau {\left( i\right) }^{-1}}\right) }Y\xrightarrow[]{i}X\n\]...
Yes
Theorem 4.79. Let \( \phi \left( z\right) \in K\left( z\right) \) be a nonzero rational map and let\n\n\[ g : \operatorname{Gal}\left( {\bar{K}/K}\right) \rightarrow \operatorname{Aut}\left( \phi \right) \]\n\nbe a 1-cocycle with values in \( \operatorname{Aut}\left( \phi \right) \) . Then the following are equivalent:...
Proof. Suppose first that there is a twist \( {\phi }^{f} \) of \( \phi /K \) whose 1-cocycle is \( g \) . Then by the definition given in Proposition 4.77, the 1-cocycle \( g \) is given by \( {g}_{\sigma } = {f\sigma }\left( {f}^{-1}\right) \) . Hence \( g \) is the \( {\operatorname{PGL}}_{2}\left( \bar{K}\right) \)...
Yes
Let \( K \) be a field of characteristic not dividing \( n \), and let \( \phi \left( z\right) \in K\left( z\right) \) be a rational map whose automorphism group is \[ \operatorname{Aut}\left( \phi \right) = \left\{ {{\zeta z} : \zeta \in {\mathbf{\mu }}_{n}}\right\} \] where we recall that \( {\mathbf{\mu }}_{n} \subs...
Note that by assumption we have \( \phi \left( z\right) = {\zeta }^{-1}\phi \left( {\zeta z}\right) \) for all \( \zeta \in {\mathbf{\mu }}_{n} \) . In particular, the function \( {z}^{-1}\phi \left( z\right) \) is invariant under the substitution \( z \rightarrow {\zeta z} \), so it has the form \( \phi \left( z\right...
No
Let \( \phi \left( z\right) \in K\left( z\right) \) be a rational map with automorphism group \( \operatorname{Aut}\left( \phi \right) = \left\{ {z,{z}^{-1}}\right\} \). The Galois group \( \operatorname{Gal}\left( {\bar{K}/K}\right) \) acts trivially on \( \operatorname{Aut}\left( \phi \right) \), so we have\n\n\[ \n{...
The isomorphism is given explicitly by associating to any \( b \in {K}^{ * }/{K}^{*2} \) the cocycle\n\n\[ \n\sigma \mapsto \left\{ \begin{array}{ll} z & \text{ if }\sigma \left( \sqrt{b}\right) = \sqrt{b} \\ {z}^{-1} & \text{ if }\sigma \left( \sqrt{b}\right) = - \sqrt{b} \end{array}\right.\n\]\n\n(4.51)\n\nTo ease no...
Yes
Proposition 4.84. Let \( \phi \left( z\right) \in \bar{K}\left( z\right) \). (a) The set \( {G}_{\phi } \) is a subgroup of \( \operatorname{Gal}\left( {\bar{K}/K}\right) \). (b) Let \( {K}^{\prime } \) be a field of definition for \( \phi \). Then \( {K}_{\phi } \subseteq {K}^{\prime } \). Informally, we say that \( \...
Proof. The proof of this proposition is simply a matter of unsorting definitions. Thus let \( \sigma ,\tau \in {G}_{\phi } \). Then\n\n\[ \left( {\sigma \tau }\right) \left( \phi \right) = \sigma \left( {\tau \left( \phi \right) }\right) = \sigma \left( {\phi }^{{g}_{\tau }}\right) = \sigma {\left( \phi \right) }^{\sig...
Yes
Let \[ \phi \left( z\right) = i{\left( \frac{z - 1}{z + 1}\right) }^{3}. \] Clearly \( \mathbb{Q}\left( i\right) \) is a field of definition for \( \phi \). Let \( \sigma \) be complex conjugation, so \( \operatorname{Gal}\left( {\mathbb{Q}\left( i\right) /\mathbb{Q}}\right) = \{ 1,\sigma \} \), and let \( g\left( z\ri...
\[ = i{\left( \frac{-1/z + 1}{-1/z - 1}\right) }^{3} = - i{\left( \frac{z - 1}{z + 1}\right) }^{3} = \sigma \left( \phi \right) \left( z\right) . \] This shows that \( \sigma \in {G}_{\phi } \), so \( {G}_{\phi } = \{ 1,\sigma \} \) and \( {K}_{\phi } = \mathbb{Q} \). In other words, \( \mathbb{Q} \) is the field of mo...
Yes
Proposition 4.86. Let \( \phi \in \bar{K}\left( z\right) \) be a rational map of degree \( d \geq 2 \) with field of moduli \( K \) and satisfying \( \operatorname{Aut}\left( \phi \right) = 1 \), and for each \( \sigma \in \operatorname{Gal}\left( {\bar{K}/K}\right) \) write \( \sigma \left( \phi \right) = \) \( {\phi ...
Proof. (a) Let \( \sigma ,\tau \in \operatorname{Gal}\left( {\bar{K}/K}\right) \) . Then\n\n\[ {\phi }^{{g}_{\sigma \tau }} = \sigma \left( {\tau \left( \phi \right) }\right) = \sigma \left( {\phi }^{{g}_{\tau }}\right) = \sigma {\left( \phi \right) }^{\sigma \left( {g}_{\tau }\right) } = {\phi }^{{g}_{\sigma }\sigma \...
Yes
Proposition 4.87. Let\n\n\\[ \n g : \\operatorname{Gal}\\left( {\\bar{K}/K}\\right) \\rightarrow {\\operatorname{PGL}}_{2}\\left( \\bar{K}\\right) \n\\]\n\nbe a 1-cocycle, and assume that \\( g \\) has the property that there is a finite extension \\( L/K \\) such that \\( {g}_{\\sigma } = 1 \\) for all \\( \\sigma \\i...
Proof. We construct the curve \\( C \\) by describing its field of rational functions. Note that the field of rational functions for the curve \\( {\\mathbb{P}}^{1} \\) is the field \\( \\bar{K}\\left( z\\right) \\) and that the Galois group \\( \\operatorname{Gal}\\left( \\bar{K}/K\\right) \\) acts naturally on \\( \\...
No
Define a map \( g \) by the rule\n\n\[ g : \operatorname{Gal}\left( {\overline{\mathbb{Q}}/\mathbb{Q}}\right) \rightarrow {\operatorname{PGL}}_{2}\left( \overline{\mathbb{Q}}\right) ,\;{g}_{\sigma }\left( z\right) = \left\{ \begin{array}{ll} z & \text{ if }\sigma \left( i\right) = i, \\ - 1/z & \text{ if }\sigma \left(...
It is easy to check that \( g \) is a 1-cocycle, and indeed it is the 1-cocycle described in Example 4.85. Fix an embedding of \( \mathbb{Q} \) into \( \mathbb{C} \) and let \( \rho \in \operatorname{Gal}\left( {\mathbb{Q}/\mathbb{Q}}\right) \) denote complex conjugation. The twisted action on \( \overline{\mathbb{Q}}\...
No
Corollary 4.90. (Riemann-Roch in Genus 0) Let \( C/K \) be a smooth projective curve of genus 0 defined over \( K \) .\n\n(a) There is a \( K \) -rational divisor of degree 2 on \( C \) .\n\n(b) Let \( D \in \operatorname{Div}\left( C\right) \) be a divisor defined over \( K \) and satisfying \( \deg \left( D\right) \g...
Proof. The proof of the Riemann-Roch theorem over an algebraically closed field is given in most introductory texts on algebraic geometry, such as [198, IV.1.3], or see [255, Chapter I] for an elementary proof due to Weil and [410, II, §5] for an overview. The divisor of degree \( {2g} - 2 \) in (a) is a canonical divi...
No
Proposition 4.91. Let \( C \) be a twist of \( {\mathbb{P}}^{1}/K \) . The following are equivalent:\n\n(a) \( C \) is the trivial twist of \( {\mathbb{P}}^{1}/K \), i.e., \( C \) is \( K \) -isomorphic to \( {\mathbb{P}}^{1} \).\n\n(b) \( C\left( K\right) \) is nonempty, i.e., \( C \) has a point with coordinates in \...
Proof. If \( C \) is the trivial twist of \( {\mathbb{P}}^{1}/K \), then there is a \( K \) -isomorphism \( j : C \rightarrow {\mathbb{P}}^{1} \) . In particular, \( j : C\left( K\right) \rightarrow {\mathbb{P}}^{1}\left( K\right) \) is a bijection, so \( C\left( K\right) \) is certainly nonempty. This proves that (a) ...
Yes
Even if \( \phi \) has bad reduction at \( \mathfrak{p} \), it may be possible to change coordinates and achieve good reduction. In other words, there may be some \( f \in {\operatorname{PGL}}_{2}\left( K\right) \) such that \( \operatorname{Res}\left( {\phi }^{f}\right) \) is a p-unit.
For example, the map \( \phi \left( z\right) = z + {p}^{2}{z}^{-1} \) has bad reduction at \( p \), since\n\n\[ \phi = \left\lbrack {{X}^{2} + {p}^{2}{Y}^{2},{XY}}\right\rbrack ,\;\text{ so }\;{\operatorname{Res}}_{p}\left( \phi \right) = \operatorname{Res}\left( {{X}^{2} + {p}^{2}{Y}^{2},{XY}}\right) = {p}^{2}. \]\n\n...
Yes
Proposition 4.95. Let \( \phi = \left\lbrack {F, G}\right\rbrack \) be a rational map of degree \( d \) described by homogeneous polynomials \( F, G \in K\left\lbrack {X, Y}\right\rbrack \) and let \( \mathfrak{p} \) be a prime ideal. (a) The valuation of the minimal resultant of \( \phi \) is given by the formula\n\n\...
Proof. (a) Choose a constant \( c \in {K}^{ * } \) satisfying\n\n\[ \n{\operatorname{ord}}_{\mathfrak{p}}\left( c\right) = \min \left\{ {{\operatorname{ord}}_{\mathfrak{p}}\left( F\right) ,{\operatorname{ord}}_{\mathfrak{p}}\left( G\right) }\right\} \n\]\n\nThen\n\n\[ \n{\operatorname{Res}}_{\mathfrak{p}}\left( \phi \r...
Yes
Proposition 4.100. Let \( K \) be a number field and \( \phi \left( z\right) \in K\left( z\right) \) a rational map of degree \( d \geq 2 \) . If \( \phi \) has a global minimal model over \( K \), then its Weierstrass class \( {\overline{\mathfrak{a}}}_{\phi /K} \) is trivial.
Proof. Replacing \( \phi \) by \( {\phi }^{f} \) for an appropriate choice of \( f \in {\operatorname{PGL}}_{2}\left( K\right) \), we may assume that \( \phi = \left\lbrack {F, G}\right\rbrack \) with polynomials \( F \) and \( G \) having coefficients in the ring of integers of \( K \) and satisfying\n\n\[ \n{\operato...
Yes
Theorem 5.2. Let \( \\left( {K,{\\left. \\mid \\cdot \\right| }_{K}}\\right) \) be a valued field. Then there exists a valued field \( \\left( {\\widehat{K},{\\left. \\cdot \\right| }_{\\widehat{K}}}\\right) \), unique up to isomorphism of valued fields, with the following properties:\n\n(a) There is an inclusion \( K ...
Proof. (Sketch) The field \( \\widehat{K} \) may be constructed as follows. Let \( C \) be the set of all Cauchy sequences in \( K \) and make \( C \) into a ring by setting\n\n\[ \n\\left\\{ {\\alpha }_{n}\\right\\} + \\left\\{ {\\beta }_{n}\\right\\} = \\left\\{ {{\\alpha }_{n} + {\\beta }_{n}}\\right\\} \\;\\text{ a...
Yes
Theorem 5.3. Let \( \left( {K,{\left| \cdot \right| }_{K}}\right) \) be a complete field and let \( L/K \) be a finite extension. Then there is a unique absolute value \( {\left. \mid \cdot \mid \right| }_{L} \) on \( L \) extending the absolute value on \( K \) . The field \( L \) is complete with respect to \( {\left...
Proof. (Sketch) One checks that \( {\left. \mid \cdot \right| }_{L} \) is given by\n\n\[{\left| \alpha \right| }_{L} = {\left| {\mathrm{N}}_{L/K}\left( \alpha \right) \right| }_{K}^{1/\left\lbrack {L : K}\right\rbrack }.\]\n\nSee [259, Proposition XII.2.6] or [382, II §4].
No
Theorem 5.6. Let\n\n\\[ \n{\\mathbb{C}}_{p} = {\\widehat{\\mathbb{Q}}}_{p} = \\text{the completion of the algebraic closure of}{\\mathbb{Q}}_{p}\\text{.}\n\\]\n\nThen \\( {\\mathbb{C}}_{p} \\) is both complete and algebraically closed. It is the smallest complete algebraically closed field containing \\( {\\mathbb{Q}}_...
Proof. More generally, the completion of an algebraically closed nonarchimedean field is algebraically closed. We briefly sketch the proof. Let \\( \\alpha \\) be algebraic over \\( {\\mathbb{C}}_{p} \\) , say a root of \\( f\\left( X\\right) = \\sum {a}_{i}{X}^{i} \\in {\\mathbb{C}}_{p}\\left\\lbrack X\\right\\rbrack ...
Yes
Proposition 5.8. (a) Let \( \phi \left( z\right) \) be a holomorphic function on the closed disk \( \bar{D}\left( {a, r}\right) \) and let \( b \in \bar{D}\left( {a, r}\right) \) . Then \( \phi \left( z\right) \) is a holomorphic function on \( \bar{D}\left( {b, r}\right) \), i.e., \( \phi \left( z\right) \) is given b...
Proof. (a) Let \( \phi \left( z\right) = \sum {a}_{i}{\left( z - a\right) }^{i} \), and for \( k \geq 0 \), define coefficients \( {b}_{k} \) by the formula\n\n\[ {b}_{k} = \mathop{\sum }\limits_{{i = k}}^{\infty }\left( \begin{array}{l} i \\ k \end{array}\right) {a}_{i}{\left( b - a\right) }^{i - k}. \]\n\n(These valu...
Yes
Proposition 5.10. Let \( \phi \left( z\right) \in K\llbracket z\rrbracket \) be a power series converging on \( \bar{D}\left( {a, r}\right) \). Then \[ \left| {\phi \left( z\right) - \phi \left( w\right) }\right| \leq \frac{\parallel \phi \parallel }{r}\left| {z - w}\right| \;\text{ for all }z, w \in \bar{D}\left( {a, ...
Proof. We take \( z, w \in \bar{D}\left( {a, r}\right) \) and compute \[ \left| {\phi \left( z\right) - \phi \left( w\right) }\right| = \left| {\mathop{\sum }\limits_{{i = 0}}^{\infty }{a}_{i}\left( {{\left( z - a\right) }^{i} - {\left( w - a\right) }^{i}}\right) }\right| \] \[ = \left| {z - w}\right| \left| {\mathop{\...
Yes
Theorem 5.11. Let \( \phi \left( z\right) \in {\mathbb{C}}_{p}\llbracket z\rrbracket \) be a power series. Suppose that the Newton polygon of \( \phi \) includes a line segment of slope \( m \) whose horizontal length is \( N \), i.e., the Newton polygon has a line segment running from\n\n\[ \left( {n, v\left( {a}_{n}\...
Proof. See [249, IV.4, Corollary to Theorem 14]. We observe that the proof of this result for polynomials or rational functions is quite easy. For power series, one first proves a \( p \) -adic version of the Weierstrass preparation theorem saying, roughly, that \( \phi \left( z\right) \) factors into the product of a ...
Yes
The Newton polygon of the power series\n\n\[ \phi \left( z\right) = {p}^{5} + {p}^{4}z + p{z}^{2} + p{z}^{3} + {p}^{-1}{z}^{4} + {p}^{-1}{z}^{5} + {p}^{3}{z}^{6} + {p}^{-1}{z}^{7} + {p}^{2}{z}^{8} + {p}^{3}{z}^{9} + \cdots \]
is illustrated in Figure 5.1(a). The leftmost line segment has slope -2 and width 2, so \( \phi \left( z\right) \) has exactly 2 roots \( \alpha \) satisfying \( \left| \alpha \right| = {p}^{-2} \) (assuming that \( \phi \left( z\right) \) converges on the appropriate disk). Similarly, \( \phi \left( z\right) \) has ex...
Yes
Theorem 5.13. (Maximum Modulus Principle) Let \( \phi \left( z\right) \in {\mathbb{C}}_{p}\llbracket z\rrbracket \) be a power series that converges on a disk \( \bar{D}\left( {a, r}\right) \) of rational radius.\n\n(a) There is a point \( \beta \in \bar{D}\left( {a, r}\right) \) satisfying\n\n\[ \left| {\phi \left( \b...
Proof of Theorem 5.13. Write \( \phi \left( z\right) = \sum {a}_{i}{\left( z - a\right) }^{i} \) and choose constants \( b, c \in {K}^{ * } \) with \( \left| c\right| = r \) and \( \left| b\right| = \parallel \phi \parallel \) (cf. Remark 5.9). Consider the series\n\n\[ \psi \left( z\right) = {b}^{-1}\phi \left( {{cz} ...
Yes
Corollary 5.17. In each of the following situations, the indicated map \( \phi \) is both open and continuous:
(a) The continuity is a consequence of Proposition 5.10, which gives the stronger assertion that \( \phi \) is Lipschitz. The openness of \( \phi \) follows easily from Proposition 5.16, since the collection of \
No
Proposition 5.18. For every integer \( n \geq 1 \) ,\n\n\[ \mathcal{F}\left( {\phi }^{n}\right) = \mathcal{F}\left( \phi \right) \;\text{ and }\;\mathcal{J}\left( {\phi }^{n}\right) = \mathcal{J}\left( \phi \right) . \]
Proof. We proved this over \( \mathbb{C} \) in Proposition 1.25, and the same proof works for nonarchimedean fields using the nonarchimedean Lipschitz property (Theorem 2.14) in place of the archimedean version cited in Chapter 1.
Yes
Corollary 5.19. Let \( K \) be an algebraically closed field of characteristic 0 that is complete with respect to a nonarchimedean absolute value. Let \( \phi \left( z\right) \in K\left( z\right) \) be a rational function of degree \( d \geq 2 \) . Then \( \phi \) has a nonrepelling fixed point.
Proof. If some fixed point \( P \) has multiplier \( {\lambda }_{P}\left( \phi \right) = 1 \), then \( P \) is nonrepelling and we are done. Otherwise, we can use Theorem 1.14 to estimate\n\n\[ 1 = \left| {\mathop{\sum }\limits_{{P \in \operatorname{Fix}\left( \phi \right) }}\frac{1}{1 - {\lambda }_{P}\left( \phi \righ...
Yes
Proposition 5.20. Let \( K \) be an algebraically closed field of characteristic 0 that is complete with respect to a nonarchimedean absolute value. Let \( \phi \left( z\right) \in K\left( z\right) \) be a rational function of degree \( d \geq 2 \) .\n\n(a) Let \( P \in {\mathbb{P}}^{1}\left( K\right) \) be a nonrepell...
Proof. Making a change of variables, we can move \( P \) to 0, and then Proposition 5.18 lets us replace \( \phi \) by \( {\phi }^{n} \), so we may assume that 0 is a fixed point. This puts \( \phi \) into\nthe form\n\[ \phi \left( z\right) = {\lambda z} + \frac{{z}^{2}F\left( z\right) }{G\left( z\right) } \]\nwith \( ...
Yes
(a) \( \;\left| z\right| > \frac{1}{p}\; \) and \( \;\left| {z - 1}\right| > \frac{1}{p}\; \Rightarrow \;\mathop{\lim }\limits_{{n \rightarrow \infty }}\left| {{\phi }^{n}\left( z\right) }\right| = \infty \) .
Proof. (a) We consider two cases. First, if \( \left| z\right| > 1 \), then \( \left| z\right| = \left| {z - 1}\right| \), so we find that\n\n\[ \left| {\phi \left( z\right) }\right| = \left| \frac{z\left( {z - 1}\right) }{p}\right| = p \cdot \left| z\right| \cdot \left| {z - 1}\right| = p \cdot {\left| z\right| }^{2}....
Yes
Proposition 5.23. Let \( {S}^{\mathbb{N}} \) be the space of \( S \) -sequences with associated metric as above and let \( L : {S}^{\mathbb{N}} \rightarrow {S}^{\mathbb{N}} \) be the left shift map.\n\n(a) If \( \rho \left( {\alpha ,\beta }\right) < 1 \), then \( \rho \left( {L\left( \alpha \right), L\left( \beta \righ...
Proof. (a) The condition \( \rho \left( {\alpha ,\beta }\right) < 1 \) is equivalent to \( {\alpha }_{0} = {\beta }_{0} \) . It is then clear from the definition that \( \rho \left( {L\left( \alpha \right), L\left( \beta \right) }\right) = p \cdot \rho \left( {\alpha ,\beta }\right) \), since \( L{\left( \alpha \right)...
Yes
Proposition 5.24. With notation as above, the itinerary map \( \beta : \Lambda \rightarrow \{ 0,1{\} }^{\mathbb{N}} \) has the following properties:\n\n(a) \( \beta \) is injective.\n\n(b) \( \beta \left( {\Lambda \cap {\mathbb{Q}}_{p}}\right) = \{ 0,1{\} }^{\mathbb{N}} \), i.e., \( \beta \) restricted to \( \Lambda \c...
Proof. (a) We begin with the following observation. Let \( u \) be 0 or 1 .\n\n\[ \text{If}z, w \in {I}_{u}\text{, then}\left| {\phi \left( z\right) - \phi \left( w\right) }\right| = p \cdot \left| {z - w}\right| \text{.} \]\n\n(5.6)\n\nTo verify (5.6), we use the assumption that \( z, w \in {I}_{u} \) to write \( z = ...
Yes
Corollary 5.25. Let \( p \geq 3 \) be a prime and let\n\n\[ \phi \left( z\right) = \frac{{z}^{2} - z}{p}\;\text{ and }\;\Lambda = \left\{ {z \in {\mathbb{C}}_{p} : {\phi }^{n}\left( z\right) \text{ is bounded for all }n \geq 0}\right\} .\n\]\n\n(a) \( \mathcal{J}\left( \phi \right) = \Lambda \subset {\mathbb{Q}}_{p} \)...
Proof. Let \( \beta : \Lambda \rightarrow \{ 0,1{\} }^{\mathbb{N}} \) be the itinerary map. Proposition 5.24 tells us that \( \beta \) is injective, and further that it is surjective even when restricted to \( \Lambda \cap {\mathbb{Q}}_{p} \) . It follows that \( \Lambda \subset {\mathbb{Q}}_{p} \), which proves one pa...
Yes
Theorem 5.27. (Nonarchimedean Montel Theorem, Hsia [208]) Let \( \Phi \) be a collection of rational, or more generally meromorphic, functions \( \bar{D}\left( {a, r}\right) \rightarrow {\mathbb{P}}^{1}\left( K\right) \), and suppose that the union\n\n\[ \mathop{\bigcup }\limits_{{\phi \in \Phi }}\phi \left( {\bar{D}\l...
Proof. Let \( \alpha = \left\lbrack {{\alpha }_{1},{\alpha }_{2}}\right\rbrack \) and \( \beta = \left\lbrack {{\beta }_{1},{\beta }_{2}}\right\rbrack \) be two points of \( {\mathbb{P}}^{1}\left( K\right) \) that are not in the union (5.13). Consider the family of rational (or meromorphic) functions\n\n\[ \Psi = \left...
Yes
Proposition 5.29. Let \( \phi : {\mathbb{P}}^{1}\left( K\right) \rightarrow {\mathbb{P}}^{1}\left( K\right) \) be a rational map of degree \( d \geq 2 \) and let \( U \subset {\mathbb{P}}^{1}\left( K\right) \) be an open set such that \( U \cap \mathcal{J}\left( \phi \right) \neq \varnothing \) . In particular, we are ...
Proof. The set \( U \) is covered by disks \( \bar{D}\left( {a, r}\right) \), which are both open and closed, so it suffices to prove the proposition under the assumption that \( U = \widetilde{D}\left( {a, r}\right) \) . If the union omits two or more points of \( {\mathbb{P}}^{1}\left( K\right) \), then Montel’s theo...
Yes
Proposition 5.30. Let \( \phi : {\mathbb{P}}^{1}\left( K\right) \rightarrow {\mathbb{P}}^{1}\left( K\right) \) be a rational map of degree \( d \geq 2 \) , and let \( E \subseteq {\mathbb{P}}^{1}\left( K\right) \) be a closed completely invariant subset for \( \phi \) containing at least three points. Then \( E \) is a...
Proof. Theorem 1.6 tells us that a finite completely invariant subset contains at most two points, so our assumption that \( \# E \geq 3 \) implies that \( E \) is infinite. Notice that the complete invariance of the closed set \( E \) implies the complete invariance of its complement \( U \), which is an open set. It ...
Yes
Corollary 5.32. Let \( \phi : {\mathbb{P}}^{1}\left( K\right) \rightarrow {\mathbb{P}}^{1}\left( K\right) \) be a rational map of degree \( d \geq 2 \), and assume that \( \mathcal{J}\left( \phi \right) \neq \varnothing \) . (a) \( \mathcal{J}\left( \phi \right) \) has empty interior.
Proof. (a) Let \( \partial \mathcal{J}\left( \phi \right) \) denote the boundary of the Julia set \( \mathcal{J}\left( \phi \right) \) . Theorem 1.24 tells us that \( \mathcal{F}\left( \phi \right) \) and \( \partial \mathcal{J}\left( \phi \right) \) are completely invariant, so the same is true of their union \( \part...
Yes
Lemma 5.33. Let \( {\phi }_{1}\left( z\right) \) and \( {\phi }_{2}\left( z\right) \) be power series that converge on \( \bar{D}\left( {a, r}\right) \), and suppose that \( {\phi }_{1}\left( {\bar{D}\left( {a, r}\right) }\right) \cap {\phi }_{2}\left( {\bar{D}\left( {a, r}\right) }\right) = \varnothing \) . Then\n\n\[...
Proof. Let\n\n\[ {M}_{1} = \mathop{\sup }\limits_{{z \in \bar{D}\left( {a, r}\right) }}\left| {{\phi }_{1}\left( z\right) }\right| \;\text{ and }\;{M}_{2} = \mathop{\sup }\limits_{{z \in \bar{D}\left( {a, r}\right) }}\left| {{\phi }_{2}\left( z\right) }\right| .\n\nThe maximum modulus principle (Theorem 5.13(a)) says t...
Yes
Lemma 5.34. Let \( A, B \subset {\mathbb{C}}_{p} \) be bounded sets that are at a positive distance from one another. In other words, there are constants \( \Delta ,\delta > 0 \) such that\n\n\[ \mathop{\sup }\limits_{{\alpha \in A}}\left| \alpha \right| \leq \Delta ,\;\mathop{\sup }\limits_{{\beta \in B}}\left| \beta ...
Proof of Lemma 5.34. To ease notation, for \( x, y \in {\mathbb{C}}_{p} \) we write\n\n\[ \left| {x, y}\right| = \max \{ \left| x\right| ,\left| y\right| \} \]\n\nWe also assume (without loss of generality) that \( \Delta \geq 1 \) and \( \delta \leq 1 \) . Then for any \( \alpha ,{\alpha }^{\prime } \in A \) and \( \b...
Yes
Theorem 5.37. (Hsia [208]) Let \( \phi \left( z\right) \in K\left( z\right) \) be a rational function of degree \( d \) with \( d \geq 2 \) . Then\n\n\[ \mathcal{J}\left( \phi \right) \subset \overline{\operatorname{Per}\left( \phi \right) } \]\n\ni.e., the closure of the periodic points of \( \phi \) contains the Juli...
Proof. We may clearly assume that \( \mathcal{J}\left( \phi \right) \) is not empty. Take any open set \( U \) having nontrivial intersection with \( \mathcal{J}\left( \phi \right) \) . We must show that \( U \) contains a periodic point.\n\nThe Julia set is a perfect set (Corollary 5.32), so the open set \( U \) actua...
Yes
Theorem 5.40. (Bézivin) If a rational function \( \phi \left( z\right) \in {\mathbb{C}}_{p}\left( z\right) \) has at least one repelling periodic point, then \( \mathcal{J}\left( \phi \right) \) is the closure of the repelling periodic points of \( \phi \) . In particular, one repelling periodic point implies infinitel...
Proof. See [71] for the first assertion. The second then follows immediately from Corollary 5.32(d), since an uncountable set cannot be the closure of a finite set.
No
Consider the polynomial map \[ \phi \left( z\right) = \frac{{z}^{p} - z}{p} \]. It is clear that the Julia set of \( \phi \) is contained in \( \bar{D}\left( {0,1}\right) \), since if \( \left| \alpha \right| > 1 \), then \( \left| {\alpha }^{p}\right| > \) \( \left| \alpha \right| \), so \[ \left| {\phi \left( \alpha ...
We also observe that if \( \alpha \in \bar{D}\left( {0,1}\right) \cap {\mathbb{Q}}_{p} = {\mathbb{Z}}_{p} \), then Fermat’s little theorem tells us that \( {\alpha }^{p} \equiv \alpha \left( {\;\operatorname{mod}\;p}\right) \), so \( \phi \left( \alpha \right) \in {\mathbb{Z}}_{p} \) . Thus \( {\mathbb{Z}}_{p} \) is a ...
Yes
Let \( p \geq 5 \) be a prime, and let \( \phi \left( z\right) = p{z}^{3} + a{z}^{2} + b \) with \( a, b \in {\mathbb{Z}}_{p}^{ * } \) . We first consider the fixed points of \( \phi \), which are the roots of the equation\n\n\[ p{z}^{3} + a{z}^{2} - z + b = 0. \]
The assumption that \( a, b \in {\mathbb{Z}}_{p}^{ * } \) implies that the roots satisfy \( \left| {\alpha }_{1}\right| = p \) and \( \left| {\alpha }_{2}\right| = \) \( \left| {\alpha }_{3}\right| = 1 \) . (Look at the Newton polygon!) We also observe that \( p{\alpha }_{1}^{3} \) and \( a{\alpha }_{1}^{2} \) have nor...
Yes
Let \( X = \mathbb{C} \) and let \( \mathcal{D} \) be the usual collection of open disks in \( \mathbb{C} \). Then the disk components of an open set \( U \subset X \) are the same as the usual path-connected components.
This is clear, since if \( \Gamma \) is a path from \( P \) to \( Q \), then \( \Gamma \) can be covered by open disks contained in \( U \), and the compactness of \( \Gamma \) shows that it suffices to take a finite subcover. Thus the definition of disk components and the related notion of disk connectivity (see Exerc...
No
Proposition 5.45. Let \( {\mathcal{D}}_{\text{open }} \) and \( {\mathcal{D}}_{\text{closed }} \) be, respectively, the collections of standard open and closed disks in \( {\mathbb{P}}^{1}\left( {\mathbb{C}}_{p}\right) \) as defined above.\n\n(a) Let \( {D}_{1},{D}_{2} \in {\mathcal{D}}_{\text{closed }} \) . Then one o...
Proof. (a) If \( {D}_{1} \cup {D}_{2} = {\mathbb{P}}^{1}\left( {\mathbb{C}}_{p}\right) \), we are done. Otherwise, choose any point in the complement of \( {D}_{1} \cup {D}_{2} \) and use a linear fractional transformation to move that point to \( \infty \) . This reduces us to the case that neither \( {D}_{1} \) nor \...
No
Theorem 5.46. (Benedetto [56]) Let \( K/{\mathbb{Q}}_{p} \) be a finite extension of \( p \) -adic fields and let \( \phi \left( z\right) \in K\left( z\right) \) be a rational function of degree \( d \geq 2 \) . Proposition 5.20(c) tells us that \( \mathcal{F}\left( \phi \right) \neq \varnothing \), so changing variabl...
Proof of Theorem 5.46. The implication (b) \( \Rightarrow \) (a) is clear, since if \( \alpha \) is a critical point in \( \mathcal{J}\left( \phi \right) \), we can take \( L = K\left( \alpha \right) \) and observe that\n\n\[ {\left( {\phi }^{m}\right) }^{\prime }\left( \alpha \right) = \mathop{\prod }\limits_{{i = 0}}...
Yes
Example 5.49. Let \( p \) be an odd prime and let\n\n\[ \phi \left( z\right) = \frac{{z}^{2} - z}{p} \]\n\nbe the function that we studied in Section 5.5. We proved (Proposition 5.22) that the Julia set of \( \phi \) is contained in the union of two open disks,\n\n\[ \mathcal{J}\left( \phi \right) \subset D\left( {0,1}...
To see this, we observe that \( B\left( {-1}\right) \) cannot contain any larger disk, since it does not contain 0 . On the other hand, \( D\left( {-1,1}\right) \) is in \( \mathcal{F}\left( \phi \right) \) , since it is disjoint from \( D\left( {0,1}\right) \cup D\left( {1,1}\right) \) . Hence \( B\left( {-1}\right) =...
Yes
Theorem 5.56. (Benedetto [59]) For \( c \in {\mathbb{C}}_{p} \), let \( {\phi }_{c}\left( z\right) \) be the polynomial\n\n\[ \n{\phi }_{c}\left( z\right) = \left( {1 - c}\right) {z}^{p + 1} + c{z}^{p}.\n\]\n\nThen there exists a value \( a \in {\mathbb{C}}_{p} \) such that:\n\n(1) \( \mathcal{J}\left( {\phi }_{a}\righ...
Proof. See [59] for a proof of this specific theorem, and see [63, 62, 373, 378, 380] for generalizations and related results.
No
Proposition 5.57. Let \( K \) be a field with an absolute value \( v \) . Let\n\n\[ \Phi = \left( {F, G}\right) : {\mathbb{A}}^{2} \rightarrow {\mathbb{A}}^{2} \]\n\nbe given by homogeneous polynomials \( F, G \in K\left\lbrack {x, y}\right\rbrack \) of degree \( d \geq 1 \), and assume that \( F \) and \( G \) have no...
Proof. (a) We proved inequality (5.33) for general morphisms \( {\mathbb{P}}^{N} \rightarrow {\mathbb{P}}^{M} \) during the course of proving Theorem 3.11. More precisely, see (3.6) on page 92 for the upper bound with an explicit value for \( {c}_{2}\left( {\Phi, v}\right) \), and see (3.7) on page 93 for the lower bou...
Yes
Proposition 5.58. Let \( K \) be a field with an absolute value \( v \), let \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be a morphism of degree \( d \geq 2 \), and let \( \Phi = \left( {F, G}\right) : {\mathbb{A}}^{2} \rightarrow {\mathbb{A}}^{2} \) be a lift of \( \phi \) . (a) For all \( \left( {x, y}...
Proof. We consider the two functions\n\n\[ \n\Phi : {\mathbb{A}}_{ * }^{2}\left( K\right) \rightarrow {\mathbb{A}}_{ * }^{2}\left( K\right) \;\text{ and }\;\log \parallel \cdot \parallel : {\mathbb{A}}_{ * }^{2}\left( K\right) \rightarrow \mathbb{R}.\n\]\n\nProposition 5.57(a) tel
No
Proposition 5.57(a) tells us that they satisfy\n\n\\[ \log \\parallel \\Phi \\left( {x, y}\\right) {\\parallel }_{v} = d\\log \\parallel \\left( {x, y}\\right) {\\parallel }_{v} + O\\left( 1\\right) \\;\\text{ for all }\\left( {x, y}\\right) \\in {\\mathbb{A}}_{ * }^{2}\\left( K\\right) .\n\\]
This is exactly the situation needed to apply Theorem 3.20, from which we conclude that the limit (5.35) exists and satisfies (5.36) and (5.37). Further, Theorem 3.20 says that \\( {\\mathcal{G}}_{\\Phi } \\) is the unique function satisfying (5.36) and (5.37). This completes the proof of (a) and (b).
Yes
Theorem 5.59. Let \( K \) be a number field, let \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be a rational function of degree \( d \geq 2 \) defined over \( K \), and let \( \Phi \) be a fixed lift of \( \phi \) . For each absolute value \( v \in {M}_{K} \), let \( {\mathcal{G}}_{\Phi, v} \) be the assoc...
Proof. Let\n\n\[ \n\eta \left( {x, y}\right) = \mathop{\sum }\limits_{{v \in {M}_{K}}}{n}_{v}{\mathcal{G}}_{\Phi, v}\left( {x, y}\right) \;\text{ for }\left( {x, y}\right) \in {\mathbb{A}}_{ * }^{2}\left( K\right) ,\n\]\n\nso a priori the function \( \eta \) is a function on \( {\mathbb{A}}_{ * }^{2}\left( K\right) \) ...
Yes
Theorem 5.60. Let \( K \) be a field with an absolute value \( v \) and let \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be a rational function of degree \( d \geq 2 \) defined over \( K \) . Fix a lift \( \Phi = \left( {F, G}\right) \) of \( \phi \) and let \( {\mathcal{G}}_{\Phi } \) be the associated G...
Proof. The Green function satisfies \( {\mathcal{G}}_{\Phi }\left( {{cx},{cy}}\right) = {\mathcal{G}}_{\Phi }\left( {x, y}\right) + \log {\left| c\right| }_{v} \), while the polynomial \( E \) satisfies \( E\left( {{cx},{cy}}\right) = {c}^{e}E\left( {x, y}\right) \), so the difference\n\n\[ \ne{\mathcal{G}}_{\Phi }\lef...
Yes
Theorem 5.61. Let \( K \) be a number field, let \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be a rational function of degree \( d \geq 2 \) defined over \( K \), and fix a lift \( \Phi = \left( {F, G}\right) \) of \( \phi \) . Choose a homogeneous polynomial \( E\left( {x, y}\right) \in K\left\lbrack {x...
Proof. We use the definition of \( {\widehat{\lambda }}_{\phi, E, v} \) in terms of the associated Green function \( {\mathcal{G}}_{\Phi, v} \) from Theorem 5.60(a) to compute\n\n\[ \n\frac{1}{\deg E}\mathop{\sum }\limits_{{v \in {M}_{K}}}{n}_{v}{\widehat{\lambda }}_{\phi, E, v}\left( P\right) = \frac{1}{\deg E}\mathop...
Yes
Theorem 5.68. (Berkovich) The Berkovich disk \( {\bar{D}}^{\mathcal{B}} \) with the Gel’fond topology is a compact path-connected Hausdorff space.
Proof. See [64, Theorem 1.2.1] or [29, Appendix D] for the proof that \( {\bar{D}}^{\mathcal{B}} \) is compact and Hausdorff and [64, Corollary 3.2.3] for the proof that it is path connected.
No
Theorem 5.72. (a) The Berkovich disks \( {\bar{D}}_{R}^{\mathcal{B}} \) are compact, Hausdorff, and uniquely path connected.
Proof. See [26] and [64].
No
Theorem 5.78. Let \( \phi \left( z\right) \in {\mathbb{C}}_{p}\left( z\right) \) be a rational map of degree at least 2 . The support of the canonical measure \( {\mu }_{\phi } \) is equal to the Julia set \( {\mathcal{J}}^{\mathcal{B}}\left( \phi \right) \) . In particular, the Berkovich Julia set \( {\mathcal{J}}^{\m...
Proof. This theorem is an amalgamation of results due to Baker, Rumely, and Rivera-Letelier. We refer the reader to [26, Section 7.5] for the construction of the canonical measure and to [26, Theorem 7.18], [27, Theorems 8.9 and A.7], and [381] for the proof that \( {\mu }_{\phi } \) is supported exactly on \( {\mathca...
No
Let \( \phi \left( z\right) \in {\mathbb{C}}_{p}\left( z\right) \) be a rational map of degree at least 2 and suppose that \( \phi \) has good reduction. We know (Theorem 2.17) that the classical Julia set \( \mathcal{J}\left( \phi \right) \subset {\mathbb{P}}^{1}\left( {\overline{\mathbb{C}}}_{p}\right) \) is empty. U...
\[ {\mu }_{\phi }\left( U\right) = 1\;\text{ if }\;{\xi }_{0,1} \in U\;\text{ and }\;{\mu }_{\phi }\left( U\right) = 0\;\text{ if }\;{\xi }_{0,1} \notin U. \] Thus \( {\mathcal{J}}^{\mathcal{B}}\left( \phi \right) = \left\{ {\xi }_{0,1}\right\} \), so the nonempty Julia set guaranteed by Theorem 5.78 is not very intere...
Yes
Theorem 5.80. (Strong Montel Theorem on \( {\mathbb{P}}^{\mathcal{B}} \) ) Let \( \phi \in {\mathbb{C}}_{p}\left( z\right) \) be a rational map of degree at least 2, let \( \xi \in {\mathbb{P}}^{\mathcal{B}} \), let \( U \subset {\mathbb{P}}^{\mathcal{B}} \) be an open neighborhood of \( \xi \), and let \( V \) be the ...
Proof. This theorem is due to Baker and Rumely [27, Theorem 7.1] for maps \( \phi \) defined over a finite extension of \( {\mathbb{Q}}_{p} \), and to Rivera-Letelier in the general case; see [27, Theorem A.1] and [381].
No
Theorem 5.81. (Rivera-Letelier) Let \( {\mathcal{U}}_{\phi } \) be the set of points \( \xi \in {\mathbb{P}}^{\mathcal{B}} \) with the property that there is a neighborhood \( U \) of \( \xi \) such that\n\n\[ \n{\mathbb{P}}^{1}\left( {\mathbb{C}}_{p}\right) \smallsetminus \mathop{\bigcup }\limits_{{n \geq 1}}{\phi }^{...
Proof. The proof of (a) is given in [27, Theorem A.2] and the proof of (b) is in [27, Corollary A.5].
Yes
Theorem 5.82. Let \( \phi \in {\mathbb{C}}_{p}\left( z\right) \) be a rational map of degree at least 2 . (a) If there is some \( f \in {\mathrm{{PGL}}}_{2}\left( {\mathbb{C}}_{p}\right) \) such that the conjugate \( {\phi }^{f} \) has good reduction, then the Julia set \( {\mathcal{J}}^{\mathcal{B}}\left( \phi \right)...
Proof. (a) See [27, Lemma 8.1].
No
Proposition 6.1. Let \( d \in \mathbb{Z} \) with \( \left| d\right| \geq 2 \) and let \( {M}_{d} : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be the power map \( {M}_{d}\left( z\right) = {z}^{d} \) . Then\n\n\[ \operatorname{PrePer}\left( {M}_{d}\right) = {\left( {\mathbb{G}}_{m}\right) }_{\text{tors }} = \left\{...
Proof. We proved this long ago for any abelian group \( G \) and homomorphism \( z \mapsto {z}^{d} \) with \( d \geq 2 \) ; see Proposition 0.3 . The proof for \( d \leq - 2 \) is similar and left to the reader.
No
Proposition 6.2. Let \( \\left| d\\right| \\geq 2 \) and let \( \\zeta \\in {\\operatorname{Per}}_{n}^{* * }\\left( {M}_{d}\\right) \) be a point of exact period \( n \\geq 2 \) . Then the multiplier of \( {M}_{d} \) at \( \\zeta \) is given by\n\n\[ \n{\\lambda }_{\\zeta }\\left( {M}_{d}\\right) = {d}^{n} \n\]
Proof. Using \( {M}_{d}^{n}\\left( z\\right) = {z}^{{d}^{n}} \), we can directly compute\n\n\[ \n{\\lambda }_{\\zeta }\\left( {M}_{d}\\right) = {\\left. \\frac{d{M}_{d}^{n}\\left( z\\right) }{dz}\\right| }_{z = \\zeta } = {\\left. \\frac{d{z}^{{d}^{n}}}{dz}\\right| }_{z = \\zeta } = {d}^{n}{\\zeta }^{{d}^{n} - 1} = {d}...
Yes
Let \( K \) be a field and let \( {M}_{d}\left( z\right) = {z}^{d} \) be the \( {d}^{\text{th }} \) -power map for some \( \left| d\right| \geq 2 \) . Further, if \( K \) has finite characteristic \( p \), assume that \( p \nmid d \) . (a) The set of rational maps that commute with \( {M}_{d}\left( z\right) \) is given...
It is clear by a direct computation that the indicated maps \( c{z}^{e} \) commute with \( {M}_{d}\left( z\right) \), so it suffices to prove that they are the only commuting maps. Suppose that \( \phi \left( z\right) \in K\left( z\right) \) commutes with \( {M}_{d}\left( z\right) \), so\n\n\[ \phi \left( {z}^{d}\right...
Yes
We can use the map \( {M}_{d}\left( z\right) = {z}^{d} \) to illustrate the construction of dynamical units in Section 3.11. First we use Theorem 3.66, which says that if \( \alpha \) has exact order \( n \) and \( \gcd \left( {i - j, n}\right) = 1 \), then\n\n\[ \frac{{\alpha }^{{d}^{i}} - {\alpha }^{{d}^{j}}}{{\alpha...
Taking \( j = 0 \) and \( \gcd \left( {i, n}\right) = 1 \), this implies that\n\n\[ \frac{{\alpha }^{{d}^{i} - 1} - 1}{{\alpha }^{d - 1} - 1}\text{is a unit for all primitive}{\left( {d}^{n} - 1\right) }^{\text{st }}\text{roots of unity}\alpha \text{.} \]
Yes
Proposition 6.6. For each integer \( d \geq 0 \) there exists a unique polynomial \( {T}_{d}\left( w\right) \in \) \( \mathbb{Q}\left\lbrack w\right\rbrack \) satisfying\n\n\[ \n{T}_{d}\left( {z + {z}^{-1}}\right) = {z}^{d} + {z}^{-d}\;\text{ in the field }\mathbb{Q}\left( z\right) .\n\]
Proof. Suppose first that there do exist polynomials \( {T}_{d}\left( w\right) \) satisfying (6.3). Then\n\n\[ \n{T}_{0}\left( {z + {z}^{-1}}\right) = {z}^{0} + {z}^{-0} = 2, \n\]\n\n\[ \n{T}_{1}\left( {z + {z}^{-1}}\right) = z + {z}^{-1} \n\]\n\n\[ \n{T}_{2}\left( {z + {z}^{-1}}\right) = {z}^{2} + {z}^{-2} = {\left( z...
Yes
Proposition 6.8. Let \( {T}_{d}\left( w\right) \) be the \( {d}^{\text{th }} \) Chebyshev polynomial for some \( d \geq 2 \) . (a) The fixed points of \( {T}_{d} \) in \( {\mathbb{A}}^{1}\left( \mathbb{C}\right) \) are\n\n\[ \left\{ {2\cos \left( \frac{2\pi j}{d + 1}\right) : 0 \leq j \leq \frac{d + 1}{2}}\right\} \cup...
Proof. See Exercise 6.5.
No
Theorem 6.9. Let \( K \) be a field and let \( {T}_{d}\left( w\right) \) be the \( {d}^{\text{th }} \) Chebyshev polynomial for some \( d \geq 2 \) . Further, if \( K \) has finite characteristic \( p \), assume that \( p \nmid d \) .\n\n(a) The automorphism group of \( {T}_{d} \) is given by\n\n\[ \n\operatorname{Aut}...
Proof. (a) The assertion that \( \operatorname{Aut}\left( {T}_{d}\right) \subset {\mathbf{\mu }}_{2} \) is an immediate consequence of (b), since (b) implies that any \( f \in \operatorname{Aut}\left( {T}_{d}\right) \) satisfies \( f\left( w\right) = \pm {T}_{1}\left( w\right) = \pm w \) . However, since the proof of (...
Yes
Proposition 6.6(c) says that \( {T}_{d}\left( w\right) \) satisfies \( {T}_{d}\left( {-w}\right) = {\left( -1\right) }^{d}{T}_{d}\left( w\right) \), so in particular,\n\n\[ \n{T}_{d}\left( w\right) = {w}^{d} + \left( {\text{ terms of degree at most }d - 2}\right) .\n\]
The identity \( {T}_{d}^{f}\left( w\right) = {T}_{d}\left( w\right) \) with \( f\left( w\right) = {aw} + b \) can be written as\n\n\[ \n{T}_{d}\left( {{aw} + b}\right) = a{T}_{d}\left( w\right) + b.\n\]\n\nWe evaluate both sides using (6.7) and look at the top degree terms. This gives\n\n\[ \n{a}^{d}{w}^{d} + d{a}^{d -...
Yes
Lemma 6.10. Assume that \( K \) does not have characteristic 2. Let \( d \geq 1 \) and let \( F\left( w\right) \) be a polynomial solution to the differential equation\n\n\[ \left( {4 - {w}^{2}}\right) {F}^{\prime }{\left( w\right) }^{2} = {d}^{2}\left( {4 - F{\left( w\right) }^{2}}\right) . \]\n\n(6.8)\n\nThen \( F\le...
Proof. We first check that \( \pm {T}_{d}\left( w\right) \) are solutions. We differentiate the functional equation (6.2) defining the Chebyshev polynomials to obtain the identity\n\n\[ {T}_{d}^{\prime }\left( {z + {z}^{-1}}\right) \left( {1 - {z}^{-2}}\right) = d{z}^{d - 1} - d{z}^{-d - 1}, \]\n\nand then solve for \(...
Yes
Suppose further that \( G\left( w\right) \) is a polynomial of degree \( e \geq 0 \) that commutes with \( F \) , i.e., \( F\left( {G\left( w\right) }\right) = G\left( {F\left( w\right) }\right) \) . Then\n\n\[ A\left( w\right) {G}^{\prime }{\left( w\right) }^{r} = {e}^{r}A\left( {G\left( w\right) }\right) . \]
Proof. Consider the polynomial\n\n\[ B\left( w\right) = A\left( w\right) {G}^{\prime }{\left( w\right) }^{r} - {e}^{r}A\left( {G\left( w\right) }\right) . \]\n\nWe assume that \( B\left( w\right) \neq 0 \) and derive a contradiction, which will prove the desired result. First we observe that the leading coefficients of...
Yes
Corollary 6.12. Continuing with the notation and assumptions from Theorem 6.9, if \( d \) is even, then \( {T}_{d} \) has no nontrivial \( \bar{K}/K \) -twists, and if \( d \) is odd, then each \( a \in {K}^{ * } \) yields a twist\n\n\[ \n{T}_{d, a}\left( w\right) = \frac{1}{\sqrt{a}}{T}_{d}\left( {\sqrt{a}w}\right) \n...
Proof. We use the description of \( \operatorname{Aut}\left( \phi \right) \) from (a). If \( d \) is even, then the automorphism group \( \operatorname{Aut}\left( \phi \right) \) is trivial, so Proposition 4.73 says that \( \phi \) has no nontrivial twists. For odd \( d \) we have \( \operatorname{Aut}\left( \phi \righ...
Yes