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Proposition 6.15. (a) Let \( a, b \in K \) and let \( E \) be the curve given by the Weierstrass equation (6.11). Then \( E \) is nonsingular, and thus is an elliptic curve, if and only if \( \Delta \left( E\right) \neq 0 \) .
Proof. See [410, III §1].
No
Theorem 6.16. Let \( E/K \) be an elliptic curve defined over a field \( K \). (a) The addition law described above gives \( E = E\left( \bar{K}\right) \) the structure of an abelian group. (b) The group law is algebraic, in the sense that the addition and inversion maps, \[ E \times E\xrightarrow[]{\left( {P, Q}\right...
Proof. See [410, III §§2,3].
No
Proposition 6.17. (Elliptic Curve Group Law Algorithm) Let \( E \) be an elliptic curve given by a Weierstrass equation\n\n\[ E : {y}^{2} = {x}^{3} + {ax} + b, \]\n\nand let \( {P}_{1} = \left( {{x}_{1},{y}_{1}}\right) \) and \( {P}_{2} = \left( {{x}_{2},{y}_{2}}\right) \) be points on \( E \) .\n\nIf \( {x}_{1} = {x}_...
Proof. See [410, III.2.3]
No
Proposition 6.18. Let \( E \) be an elliptic curve.\n\n(a) Every principal divisor on \( E \) has degree 0 .\n\n(b) \( A \) divisor \( D \in \operatorname{Div}\left( E\right) \) is principal if and only if both \( \deg \left( D\right) = 0 \) and \( \operatorname{sum}\left( D\right) = \mathcal{O} \) .
Proof. See [410, III.3.4 and III.3.5].
No
Theorem 6.21. An isogeny \( \psi : {E}_{1} \rightarrow {E}_{2} \) is a homomorphism of groups, i.e.,\n\n\[ \psi \left( {P + Q}\right) = \psi \left( P\right) + \psi \left( Q\right) \;\text{ for all }P, Q \in {E}_{1}\left( \bar{K}\right) . \]
Proof. See [410, III.4.8]
No
Theorem 6.22. Let \( \psi : {E}_{1} \rightarrow {E}_{2} \) be an isogeny of degree \( d \) . Then there is a unique isogeny \( \widehat{\psi } : {E}_{2} \rightarrow {E}_{1} \), called the dual isogeny of \( \psi \), with the property that\n\n\[ \widehat{\psi }\left( {\psi \left( P\right) }\right) = \left\lbrack d\right...
Proof. See [410, III §6].
No
The elliptic curve \( E : {y}^{2} = {x}^{3} + x \) has CM, since the endomorphism\n\n\[ \psi : E \rightarrow E,\;\psi \left( {x, y}\right) = \left( {-x,{iy}}\right) ,\]\n\nis not in \( \mathbb{Z} \) .
An easy way to verify this assertion is to note that\n\n\[ {\psi }^{2}\left( {x, y}\right) = \left( {x, - y}\right) = - \left( {x, y}\right) \]\n\nso \( {\psi }^{2} = \left\lbrack {-1}\right\rbrack \) . This gives an embedding of the Gaussian integers \( \mathbb{Z}\left\lbrack i\right\rbrack \) into \( \operatorname{En...
Yes
Proposition 6.25. Let \( E/K \) be an elliptic curve. Then the endomorphism ring of \( E \) is one of the following three kinds of rings:\n\n(a) \( \operatorname{End}\left( E\right) = \mathbb{Z} \).\n\n(b) \( \operatorname{End}\left( E\right) \) is an order in a quadratic imaginary field \( F \). This means that \( \op...
Proof. See [410, III §9].
No
Proposition 6.26. Let \( K \) be a field whose characteristic is not equal to 2 or 3 and let \( E/K \) be an elliptic curve. Then\n\n\[ \n\\operatorname{Aut}\\left( E\\right) = \\left\\{ \\begin{array}{ll} {\\mathbf{\\mu }}_{2} & \\text{ if }j\\left( E\\right) \\neq 0\\text{ and }j\\left( E\\right) \\neq {1728}, \\\\ {...
Proof. See [410, III §10].
No
Proposition 6.29. If \( E \) has good reduction, then the reduction modulo \( \mathfrak{p} \) map \( E\left( K\right) \rightarrow \widetilde{E}\left( k\right) \) is a homomorphism.
Proof. See [410, VII.2.1].
No
Theorem 6.31. Let \( E/K \) be an elliptic curve and assume that either \( K \) has characteristic 0 or else that \( K \) has characteristic \( p > 0 \) and \( p \nmid m \) . Then as an abstract group,\n\n\[ E\left\lbrack m\right\rbrack = \mathbb{Z}/m\mathbb{Z} \times \mathbb{Z}/m\mathbb{Z} \]\n\nIn other words, \( E\l...
Proof. See [410, III.6.4].
No
Theorem 6.32. Let \( K \) be a local field whose residue field has characteristic \( p \) , let \( E/K \) be an elliptic curve with good reduction, and let \( m \geq 1 \) be an integer with \( p \nmid m \) . Let \( E\left( K\right) \left\lbrack m\right\rbrack \) denote the subgroup of \( E\left\lbrack m\right\rbrack \)...
Proof. See [410, VII.3.1].
No
Corollary 6.33. Let \( K \) be a local field whose residue field has characteristic \( p \) , let \( E/K \) be an elliptic curve with good reduction, and let \( m \geq 1 \) be an integer with \( p \nmid m \) . Then the field \( K\left( {E\left\lbrack m\right\rbrack }\right) \) obtained by adjoining to \( K \) the coord...
Proof Sketch. Let \( {K}^{\prime } = K\left( {E\left\lbrack m\right\rbrack }\right) \), let \( {\mathfrak{p}}^{\prime } \) be the maximal ideal of the ring of integers of \( {K}^{\prime } \), and let \( {k}^{\prime } \) be the residue field. Suppose that \( \sigma \in \operatorname{Gal}\left( {{K}^{\prime }/K}\right) \...
Yes
Theorem 6.35. Let \( E \) be an elliptic curve given by a Weierstrass equation and let \( {\omega }_{E} \) be the associated invariant differential on \( E \). (a) For any given point \( Q \in E \), let \( {\tau }_{Q} : E \rightarrow E \) be the translation-by- \( Q \) map defined by \( {\tau }_{Q}\left( P\right) = P +...
Proof. See [410, III §5].
No
Proposition 6.37. Let \( \Gamma \) be a nontrivial subgroup of \( \operatorname{Aut}\left( E\right) \). Then the quotient curve \( E/\Gamma \) is isomorphic to \( {\mathbb{P}}^{1} \) and the projection map \( \pi : E \rightarrow E/\Gamma \cong {\mathbb{P}}^{1} \) is given explicitly by\n\n\[ \pi \left( {x, y}\right) = ...
Proof. By definition, the quotient curve \( E/\Gamma \) is the curve whose function field is the subfield of \( K\left( E\right) = K\left( {x, y}\right) \) fixed by \( \Gamma \). Using the explicit description (6.13) of the action of \( \operatorname{Aut}\left( E\right) \) on the coordinates of \( E \), it is easy to f...
Yes
Proposition 6.39. Let \( E/\mathbb{C} \) be an elliptic curve with complex multiplication, i.e., the endomorphism ring \( \operatorname{End}\left( E\right) \) is strictly larger than \( \mathbb{Z} \). Choose a lattice \( L \subset \mathbb{C} \) such that \( E\left( \mathbb{C}\right) \cong \mathbb{C}/L \), let\n\n\[ R =...
Proof. To describe the ring \( R \), we choose a basis for \( L \), say \( L = \mathbb{Z}{\omega }_{1} + \mathbb{Z}{\omega }_{2} \). We have \( R \neq \mathbb{Z} \) by assumption, so there exists an \( \alpha \in R \) with \( \alpha \notin \mathbb{Z} \). Write\n\n\[ \alpha {\omega }_{1} = a{\omega }_{1} + b{\omega }_{2...
Yes
Proposition 6.40. Let \( F \) be a quadratic imaginary field with ring of integers \( {R}_{F} \) and ideal class group \( {\mathcal{C}}_{F} \), and let \( {h}_{F} = \# {\mathcal{C}}_{F} \) be the class number of \( F \) . Then with notation as above, the natural map\n\n\[ \n{\mathcal{C}}_{F} \rightarrow \mathcal{E}\ell...
Proof. See [412, II.1.2].
No
Let \( E : {y}^{2} = {x}^{3} + {ax} + b \) be an elliptic curve. Then the classical formula for \( x\left( {2P}\right) \) (Proposition 6.17) and the isomorphism \( x : E/\{ \pm 1\} \rightarrow {\mathbb{P}}^{1} \) yield the Lattès map
\[ \phi \left( x\right) = x\left( {2P}\right) = \frac{{x}^{4} - {2a}{x}^{2} - {8bx} + {a}^{2}}{4{x}^{3} + {4ax} + {4b}}. \]
Yes
Let \( E \) be the elliptic curve \( E : {y}^{2} = {x}^{3} + {ax} \) with \( j\left( E\right) = {1728} \) and again let \( \psi \left( P\right) = \left\lbrack 2\right\rbrack P \) be the doubling map. If we take \( \pi \left( {x, y}\right) = x \), then we are in the \( b = 0 \) case of Example 6.41, and we obtain the La...
Note that the map \( \pi \left( {x, y}\right) = {x}^{2} \) corresponds to taking the quotient of \( E \) by its automorphism group \( \operatorname{Aut}\left( E\right) \cong {\mathbf{\mu }}_{4} \) via the association described in Remark 6.27.
Yes
Theorem 6.46. Let \( K \) be an algebraically closed field of characteristic not equal to 2 and let \( \phi \) and \( {\phi }^{\prime } \) be Lattès maps defined over \( K \) that are associated, respectively, to elliptic curves \( E \) and \( {E}^{\prime } \) . Assume further that the projection maps \( \pi \) and \( ...
Proof. Let \( f \in {\operatorname{PGL}}_{2}\left( K\right) \) be a linear fractional transformation conjugating \( {\phi }^{\prime } \) to \( \phi \) . Then we have a commutative diagram\n\n![aad50936-3f2e-45c3-8a73-b814eb18acbf_362_0.jpg](images/aad50936-3f2e-45c3-8a73-b814eb18acbf_362_0.jpg)\n\nWe let \( {\pi }^{\pr...
Yes
We saw in Example 6.41 that the Lattès function associated to the duplication map \( \psi \left( P\right) = \left\lbrack 2\right\rbrack \left( P\right) \) on the elliptic curve \( E : {y}^{2} = {x}^{3} + {ax} + b \) is given by the formula \[ {\phi }_{a, b}\left( x\right) = x\left( {2P}\right) = \frac{{x}^{4} - {2a}{x}...
More precisely, the set of maps \( {\phi }_{a, b} \) is a two-dimensional algebraic family of points in the space \( {\operatorname{Rat}}_{4} \), given explicitly by \[ {\mathbb{A}}^{2} \rightarrow {\operatorname{Rat}}_{4} \subset {\mathbb{P}}^{9},\;\left( {a, b}\right) \mapsto \left\lbrack {1,0, - {2a}, - {8b},{a}^{2}...
Yes
The elliptic curve \( E : {y}^{2} = {x}^{3} + a{x}^{2} + {bx} \) has the 2-torsion point \( T = \left( {0,0}\right) \). To compute the Lattès function \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) associated to the translated duplication map \( \psi \left( P\right) = \left\lbrack 2\right\rbrack \left( P\ri...
we first use the classical duplication formula to compute\n\n\[ \n{2P} = \left( {\frac{{x}^{4} - {2b}{x}^{2} + {b}^{2}}{4{y}^{2}},\frac{{x}^{6} + {2a}{x}^{5} + {5b}{x}^{4} - 5{b}^{2}{x}^{2} - {2a}{b}^{2}x - {b}^{3}}{8{y}^{3}}}\right) .\n\]\n\nThen the addition formula and some algebra yield\n\n\[ \n\phi \left( x\right)...
Yes
Proposition 6.51. Let \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be a flexible Lattès map whose associated map \( \psi : E \rightarrow E \) has the form \( \psi \left( P\right) = \left\lbrack m\right\rbrack P + T \) .\n\n(a) The map \( \phi \) has degree \( {m}^{2} \) .\n\n(b) The point \( T \) satisfie...
Proof. (a) The commutativity of the diagram (6.22) tells us that\n\n\[ \deg \left( \phi \right) \deg \left( \pi \right) = \deg \left( \pi \right) \deg \left( \psi \right) \]\n\nThe map \( \psi \) has degree \( {m}^{2} \), since multiplication-by- \( m \) has degree \( {m}^{2} \) and translation-by- \( T \) has degree 1...
Yes
Proposition 6.52. Let \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be a flexible Lattès map and assume that \( T = \mathcal{O} \) , so \( \psi \left( P\right) = \left\lbrack m\right\rbrack \left( P\right) \) . (See Exercise 6.18 for the case \( T \neq \mathcal{O} \) .)\n\n(a) The set of \( n \) -periodic ...
Proof. (a) Let \( \zeta \in {\mathbb{P}}^{1} \) be a fixed point of \( \phi \) and choose a point \( P \in E \) with \( \pi \left( P\right) = \zeta \) . Note that there are generally two choices for \( P \), so we simply choose either one of them. Then\n\n\[ \n\pi \left( P\right) = \zeta = \phi \left( \zeta \right) = \...
Yes
Theorem 6.57. Let \( K \) be a field of characteristic 0 and let \( \phi \) be a Lattès map defined over \( K \) . Then there exists a commutative diagram of the form (6.36) such that the map \( \pi \) has the form\n\n\[ \pi : E \rightarrow E/\Gamma \overset{ \sim }{ \rightarrow }{\mathbb{P}}^{1} \]\n\nfor some nontriv...
Proof. For a proof over \( \mathbb{C} \), see [300, Theorem 3.1]. The general case for characteristic-0 fields follows by the Lefschetz principle, cf. [410, VI §6].
No
Corollary 6.58. Let \( \phi \) be a Lattès map given by a reduced diagram (6.37). Then the point \( \psi \left( \mathcal{O}\right) \) is fixed by every element of \( \Gamma \), so in particular, \( \psi \left( \mathcal{O}\right) \in {E}_{\text{tors }} \) . If further \( j\left( E\right) \neq 0 \) and \( j\left( E\right...
Proof. We defer the proof that \( \psi \left( \mathcal{O}\right) \) is fixed by every \( \xi \in \Gamma \) until Proposition \( {6.77}\left( \mathrm{\;b}\right) \), where we prove it in a much more general setting. (Cf. the proof for flexible Lattès maps in Proposition 6.51(b).) To see that \( \psi \left( \mathcal{O}\r...
No
Proposition 6.61. Let \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) be a Lattès map and fix a reduced Lattès diagram (6.37) for \( \phi \) . We assume that \( j\left( E\right) \neq 0 \) and \( j\left( E\right) \neq {1728} \) . We further assume that \( \psi \) is an isogeny, i.e., with our usual notation \...
Proof. (a) We have \( \pi \left( P\right) \in \operatorname{Fix}\left( \phi \right) \) if and only if\n\n\[ \pi \left( P\right) = \phi \left( {\pi \left( P\right) }\right) = \pi \left( {\psi \left( P\right) }\right) . \]\n\nOur assumption on \( j\left( E\right) \) means that \( \Gamma = \operatorname{Aut}\left( E\right...
No
Theorem 6.63. (Mazur-Kamienny-Merel) For all integers \( D \geq 1 \) there is a constant \( B\left( D\right) \) such that for all number fields \( K/\mathbb{Q} \) of degree at most \( D \) and all elliptic curves \( E/K \) we have\n\n\[ \n\# E{\left( K\right) }_{\text{tors }} \leq B\left( D\right) \n\]
Discussion. This deep result was first proven by Mazur [292] for \( K = \mathbb{Q} \), then by Kamienny [225] for \( \left\lbrack {K : \mathbb{Q}}\right\rbrack = 2 \), and then was extended to various specific larger degrees before the proof was completed for all degrees by Merel [297]. The proof uses the theory of mod...
No
Corollary 6.64. For all integers \( n \geq 1 \), all number fields \( K/\mathbb{Q} \), and all elliptic curves \( E/K \) we have\n\n\[ \n\# \left( {\mathop{\bigcup }\limits_{{\left\lbrack {L : K}\right\rbrack \leq n}}E{\left( L\right) }_{\text{tors }}}\right) \leq B{\left( n\left\lbrack K : \mathbb{Q}\right\rbrack \rig...
Proof. To ease notation, we let \( D = \left\lbrack {K : \mathbb{Q}}\right\rbrack \) . Every field \( L \) appearing in the union in (6.41) satisfies\n\n\[ \n\left\lbrack {L : \mathbb{Q}}\right\rbrack = \left\lbrack {L : K}\right\rbrack \left\lbrack {K : \mathbb{Q}}\right\rbrack \leq {nD},\n\]\n\nso Theorem 6.63 tells ...
Yes
Theorem 6.65. Let \( D \geq 1 \) be an integer. There is a constant \( C\left( D\right) \) such that for all number fields \( K/\mathbb{Q} \) of degree \( D \) and all Lattès maps \( \phi : {\mathbb{P}}^{1} \rightarrow {\mathbb{P}}^{1} \) defined over \( K \) we have\n\n\[ \n\# \operatorname{PrePer}\left( {\phi ,{\math...
Proof. Without loss of generality we fix a reduced Lattès diagram (6.37) for \( \phi \) . Then Proposition 6.26 says that the projection map \( \pi : E \rightarrow {\mathbb{P}}^{1} \) has degree at most 6, and indeed if \( j\left( E\right) \neq 0 \) and \( j\left( E\right) \neq {1728} \), then \( \deg \left( \pi \right...
Yes
Theorem 6.67. Let \( K \) be a number field of degree \( D \geq 2 \), let \( E/K \) be an elliptic curve whose \( j \) -invariant is an algebraic integer, and let \( \phi \) be a Lattès map associated to \( E \) . Then there is an absolute constant \( c \) such that\n\n\[ \n\# \operatorname{PrePer}\left( {\phi ,{\mathb...
Proof. The assumption that the elliptic curve \( E \) has integral \( j \) -invariant means that it has everywhere potential good reduction. Replacing \( K \) by an extension of bounded degree, we may assume that \( E \) has everywhere good reduction. (In fact, it suffices to go to the field \( K\left( {E\left\lbrack 3...
Yes
Theorem 6.70. Let \( E/\mathbb{Q} \) be an elliptic curve given by a Weierstrass equation with integer coefficients, let \( m \geq 2 \) be an integer, and let \( \phi \left( z\right) \in \mathbb{Q}\left( z\right) \) be the Lattès map satisfying\n\n\[ \phi \left( {x\left( P\right) }\right) = x\left( {\left\lbrack m\righ...
Proof. Write the given Weierstrass equation for \( E \) as\n\n\[ E : {y}^{2} = {x}^{3} + {ax} + b\;\text{ with }a, b \in \mathbb{Z}. \]\n\nWe begin by showing that the minimality assumption (6.44) implies that there are no primes \( p \) with \( {p}^{2}\left| {a\text{and}{p}^{3}}\right| b \) . The rational function \( ...
Yes
Proposition 6.75. Let \( \psi : G \rightarrow G \) be an affine morphism of an algebraic group \( G \) , so \( \psi \) has the form \( \psi \left( z\right) = a \cdot \alpha \left( z\right) \) for some \( \alpha \in \operatorname{End}\left( G\right) \) and some \( a \in G \) .\n\n(a) The endomorphism \( \alpha \) and tr...
Proof. The definition of affine morphism tells us that there are an element \( a \in G \) and an endomorphism \( \alpha \) of \( G \) such that the map \( \psi \) has the form \( \psi \left( z\right) = {a\alpha }\left( z\right) \) . Evaluating at the identity element \( e \in G \) yields \( \psi \left( e\right) = {a\al...
Yes
Proposition 6.77. Let \( \phi : V \rightarrow V \) be a dynamically affine map and let \( \psi : G \rightarrow G \) and \( \Gamma \subset \operatorname{Aut}\left( G\right) \) be the associated quantities fitting into the commutative diagram (6.48).\n\n(a) For every \( \xi \in \Gamma \) there exists a unique \( {\xi }^{...
Proof. (a) The uniqueness is clear, since if \( \psi \circ \xi = {\xi }_{1} \circ \psi = {\xi }_{2} \circ \psi \), then \( {\xi }_{1} = {\xi }_{2} \) because the finite map \( \psi : G \rightarrow G \) is surjective.\n\nWe now prove the existence. The commutativity of (6.48) tells us that for all \( z \in \) \( G \) an...
Yes
Theorem 6.79. (Ritt and Erëmenko) Let \( \phi ,\psi \in \mathbb{C}\left( z\right) \) be rational maps of degree at least 2 with the property that \( \phi \circ \psi = \psi \circ \phi \) . Then one of the following two conditions is true:\n\n(a) There are integers \( m, n \geq 1 \) such that \( {\phi }^{n} = {\psi }^{m}...
Proof. The first part of the theorem, in somewhat different language, is due to Ritt [371]. See Erëmenko's paper [152] for a proof of both parts of the theorem and some additional geometric dynamical properties shared by commuting \( \phi \) and \( \psi \) . A higher-dimensional analogue is discussed in [135]. We remar...
Yes
Theorem 6.80. Let \( K \) be a field, let \( \phi \left( z\right) \in K\left\lbrack z\right\rbrack \) be a polynomial of degree \( d \geq 2 \) , and let \( \psi \left( z\right) \in K\left( z\right) \) be a nonconstant rational map. We assume that both \( \phi \) and \( \psi \) are separable, i.e., neither of the deriva...
Proof. The proof is an application of ramification theory and the Riemann-Hurwitz formula (Theorem 1.1). By assumption, the map \( \phi \) is a polynomial, so \( \infty \) is a totally ramified fixed point of \( \phi \) . Suppose that \( \psi \left( z\right) \) is not a polynomial. This means that we can find a point \...
Yes
The rational map \[ \phi : {\mathbb{P}}^{2} \rightarrow {\mathbb{P}}^{2},\;\phi \left( \left\lbrack {{X}_{0},{X}_{1},{X}_{2}}\right\rbrack \right) = \left\lbrack {{X}_{0}^{2},{X}_{0}{X}_{1},{X}_{2}^{2}}\right\rbrack \] is not a morphism, since it is not defined at the point \( \left\lbrack {0,1,0}\right\rbrack \) .
Notice that if we discard \( \left\lbrack {0,1,0}\right\rbrack \), then \( \phi \) fixes every point on the line \( {X}_{0} = {X}_{2} \), and \( \phi \) sends every point on the line \( {X}_{0} = 0 \) to the single point \( \left\lbrack {0,0,1}\right\rbrack \) . This kind of behavior is not possible for morphisms \( {\...
Yes
Consider the map \( \phi \left( {x, y}\right) = \left( {x, y + {x}^{2}}\right) \). It has degree 2 and is an automorphism, since it has the inverse \( {\phi }^{-1}\left( {x, y}\right) = \left( {x, y - {x}^{2}}\right) \). The composition \( {\phi }^{2} \) is
\[ {\phi }^{2}\left( {x, y}\right) = \phi \left( {x, y + {x}^{2}}\right) = \left( {x, y + 2{x}^{2}}\right) ,\] so \( \deg \left( {\phi }^{2}\right) = 2 = \deg \left( \phi \right) \). More generally, \( {\phi }^{n}\left( {x, y}\right) = \left( {x, y + n{x}^{2}}\right) \) has degree 2, so the degree of \( {\phi }^{n} \) ...
Yes
Let \( a \in {K}^{ * } \) and let \( f\left( y\right) \in K\left\lbrack y\right\rbrack \) be a polynomial of degree \( d \geq 2 \) . The map \[ \phi : {\mathbb{A}}^{2} \rightarrow {\mathbb{A}}^{2},\;\phi \left( {x, y}\right) = \left( {y,{ax} + f\left( y\right) }\right) ,\] is called a Hénon map. It is an automorphism o...
It is an automorphism of \( {\mathbb{A}}^{2} \), since one easily checks that it has an inverse \( {\phi }^{-1} \) given by \[ {\phi }^{-1} : {\mathbb{A}}^{2} \rightarrow {\mathbb{A}}^{2},\;{\phi }^{-1}\left( {x, y}\right) = \left( {{a}^{-1}y - {a}^{-1}f\left( x\right), x}\right) . \]
Yes
Consider the very simple Hénon map\n\n\[ \phi \left( {x, y}\right) = \left( {y, - x + {y}^{2}}\right) . \]\n\nThe extension \( \bar{\phi } = \left\lbrack {{X}_{0}^{2},{X}_{0}{X}_{2}, - {X}_{0}{X}_{1} + {X}_{2}^{2}}\right\rbrack \) of \( \phi \) to \( {\mathbb{P}}^{2} \) has degree 2, but it is not a morphism, since it ...
We can see this by noting that\n\n\[ \bar{\phi }\left( \left\lbrack {b, a, b}\right\rbrack \right) = \left\lbrack {{b}^{2},{b}^{2}, - {ab} + {b}^{2}}\right\rbrack = \left\lbrack {b, b, - a + b}\right\rbrack , \]\n\nso if \( a, b, \in \mathbb{Z} \) with \( \gcd \left( {a, b}\right) = 1 \) and \( b > a > 0 \), then \( \l...
Yes
More generally, if \( \phi : {\mathbb{A}}^{N} \rightarrow {\mathbb{A}}^{N} \) is an affine automorphism, then it is not possible to have simultaneous estimates of the form\n\n\[ h\left( {\phi \left( P\right) }\right) \geq \left( {1 + \epsilon }\right) h\left( P\right) + O\left( 1\right) \]\n\n\[ h\left( {{\phi }^{-1}\l...
To see this, suppose that (7.2) were true. Then we would have for all \( P \in {\mathbb{A}}^{N}\left( K\right) \),\n\n\[ h\left( P\right) = h\left( {\phi \left( {{\phi }^{-1}\left( P\right) }\right) }\right) \geq \left( {1 + \epsilon }\right) h\left( {{\phi }^{-1}\left( P\right) }\right) + O\left( 1\right) \geq {\left(...
Yes
Lemma 7.7. Let \( \phi : {\mathbb{A}}^{N} \rightarrow {\mathbb{A}}^{N} \) be an affine automorphism of degree at least 2 and denote the hyperplane at infinity by \( {H}_{0} = \left\{ {{X}_{0} = 0}\right\} = {\mathbb{P}}^{N} \smallsetminus {\mathbb{A}}^{N} \). Then\n\n\[ \bar{\phi }\left( {{H}_{0} \smallsetminus Z\left(...
Proof. Let\n\n\[ \Phi = \left( {{X}_{0}^{d},{\bar{F}}_{1},{\bar{F}}_{2},\ldots ,{\bar{F}}_{N}}\right) \;\text{ and }\;{\Phi }^{-1} = \left( {{X}_{0}^{e},{\bar{G}}_{1},{\bar{G}}_{2},\ldots ,{\bar{G}}_{N}}\right) \]\n\nbe the lifts of \( \bar{\phi } \) and \( {\bar{\phi }}^{-1} \), respectively. The fact that \( \phi \) ...
Yes
Lemma 7.8. Let \( \phi : {\mathbb{A}}^{N} \rightarrow {\mathbb{A}}^{N} \) and \( \psi : {\mathbb{A}}^{N} \rightarrow {\mathbb{A}}^{N} \) be affine morphisms, and let \( {H}_{0} = \left\{ {{X}_{0} = 0}\right\} = {\mathbb{P}}^{N} \smallsetminus {\mathbb{A}}^{N} \) be the usual hyperplane at infinity. Then \[ \deg \left( ...
Proof. Let \( d = \deg \left( \phi \right) \), let \( e = \deg \left( \psi \right) \), and let \( \Phi \) and \( \Psi \) be lifts of \( \bar{\phi } \) and \( \bar{\psi } \) , respectively. We write \( \Phi \) explicitly as \[ \Phi = \left( {{X}_{0}^{d},{\bar{F}}_{1},{\bar{F}}_{2},\ldots ,{\bar{F}}_{N}}\right) \] The co...
Yes
Let \( \phi \) be the map \( \phi \left( {x, y}\right) = \left( {x, y + {x}^{2}}\right) \) that we studied in Example 7.3. Dehomogenizing \( \phi \) yields \[ \bar{\phi }\left( \left\lbrack {{X}_{0},{X}_{1},{X}_{2}}\right\rbrack \right) = \left\lbrack {{X}_{0}^{2},{X}_{0}{X}_{1},{X}_{0}{X}_{2} + {X}_{1}^{2}}\right\rbra...
Notice that \[ \bar{\phi }\left( \left\lbrack {0,{X}_{1},{X}_{2}}\right\rbrack \right) = \left\lbrack {0,0,{X}_{1}^{2}}\right\rbrack = \left\lbrack {0,0,1}\right\rbrack \in Z\left( \phi \right) . \] Hence \( \bar{\phi }\left( {{H}_{0} \smallsetminus Z\left( \phi \right) }\right) = Z\left( \phi \right) \), so Lemma 7.8 ...
Yes
Let \( \phi : {\mathbb{A}}^{3} \rightarrow {\mathbb{A}}^{3} \) be given by\n\n\[ \phi \left( {x, y, z}\right) = \left( {y, z + {y}^{2}, x + {z}^{2}}\right) . \]\n\nOne can check that the inverse of \( \phi \) is\n\n\[ {\phi }^{-1}\left( {x, y, z}\right) = \left( {z - {\left( y - {x}^{2}\right) }^{2}, x, y - {x}^{2}}\ri...
Homogenizing \( x = {X}_{1}/{X}_{0}, y = {X}_{2}/{X}_{0}, z = {X}_{3}/{X}_{0} \), we have the formulas\n\n\[ \bar{\phi } = \left\lbrack {{X}_{0}^{2},{X}_{0}{X}_{2},{X}_{0}{X}_{3} + {X}_{2}^{2},{X}_{0}{X}_{1} + {X}_{3}^{2}}\right\rbrack \]\n\n\[ {\bar{\phi }}^{-1} = \left\lbrack {{X}_{0}^{4},{X}_{0}^{3}{X}_{3} - {\left(...
Yes
Theorem 7.15. Let \( {\phi }_{1} : {\mathbb{A}}^{N} \rightarrow {\mathbb{A}}^{N} \) and \( {\phi }_{2} : {\mathbb{A}}^{N} \rightarrow {\mathbb{A}}^{N} \) be affine morphisms with the property that\n\n\[ Z\left( {\phi }_{1}\right) \cap Z\left( {\phi }_{2}\right) = \varnothing \]\n\n(We say that \( {\phi }_{1} \) and \( ...
Proof of Theorem 7.15. Write the rational functions \( {\mathbb{P}}^{N} \rightarrow {\mathbb{P}}^{N} \) induced by \( {\phi }_{1} \) and \( {\phi }_{2} \) as\n\n\[ {\bar{\phi }}_{1} = \left\lbrack {{X}_{0}^{{d}_{1}},{\bar{F}}_{1},{\bar{F}}_{2},\ldots ,{\bar{F}}_{N}}\right\rbrack \;\text{ and }\;{\bar{\phi }}_{2} = \lef...
Yes
Lemma 7.17. Let \( u,{a}_{1},\ldots ,{a}_{N},{b}_{1},\ldots ,{b}_{N} \in \overline{\mathbb{Q}} \) with \( u \neq 0 \) . Then\n\n\[ h\left( \left\lbrack {u,{a}_{1},\ldots ,{a}_{N},{b}_{1},\ldots ,{b}_{N}}\right\rbrack \right) \leq h\left( \left\lbrack {u,{a}_{1},\ldots ,{a}_{N}}\right\rbrack \right) + h\left( \left\lbra...
Proof. Let \( {\alpha }_{i} = {a}_{i}/u \) and \( {\beta }_{i} = {b}_{i}/u \) for \( 1 \leq i \leq N \) . Then for any absolute value \( v \) we have the trivial estimate\n\n\[ \max \left\{ {1,{\left| {\alpha }_{1}\right| }_{v},\ldots ,{\left| {\alpha }_{N}\right| }_{v},{\left| {\beta }_{1}\right| }_{v},\ldots ,{\left|...
Yes
A prime divisor \( W \) of \( {\mathbb{P}}^{N} \) is the zero set of an irreducible homogeneous polynomial \( F \in K\left\lbrack {{X}_{0},\ldots ,{X}_{N}}\right\rbrack \) . We define the degree of \( W \) to be the degree of the polynomial \( F \) and extend this to obtain a homomorphism\n\n\[ \deg : \operatorname{Div...
It is not hard to see that a divisor on \( {\mathbb{P}}^{N} \) is principal if and only if it has degree 0, so the degree map gives an isomorphism\n\n\[ \deg : \operatorname{Pic}\left( {\mathbb{P}}^{N}\right) \overset{ \sim }{ \rightarrow }\mathbb{Z} \]
Yes
A prime divisor of \( {\mathbb{P}}^{N} \times {\mathbb{P}}^{M} \) is the zero set of an irreducible bihomo-geneous polynomial \( F \in K\left\lbrack {{X}_{0},\ldots ,{X}_{N},{Y}_{0},\ldots ,{Y}_{M}}\right\rbrack \) . We say that \( F \) and \( W \) have bidegree \( \left( {d, e}\right) \) if \( F \) satisfies\n\n\[ F\l...
The bidegree map can be extended linearly to give an isomorphism\n\n\[ \text{ bideg } : \operatorname{Pic}\left( {{\mathbb{P}}^{N} \times {\mathbb{P}}^{M}}\right) \overset{ \sim }{ \rightarrow }\mathbb{Z} \times \mathbb{Z}\text{. } \]
Yes
Let \( {p}_{1}^{ * }{H}_{1} \) and \( {p}_{2}^{ * }{H}_{2} \) be the generators of \( \operatorname{Pic}\left( {{\mathbb{P}}^{N} \times {\mathbb{P}}^{M}}\right) \) described in Example 7.27. Then \( {p}_{1}^{ * }{H}_{1} + {p}_{2}^{ * }{H}_{2} \) is a very ample divisor on \( {\mathbb{P}}^{N} \times {\mathbb{P}}^{M} \) ...
The associated embedding is called the Segre embedding. It is given explicitly by the formula\n\n\[ \n{\mathbb{P}}^{N} \times {\mathbb{P}}^{M}\; \rightarrow \;{\mathbb{P}}^{{NM} + N + M} \n\]\n\n\[ \n\left( {\left\lbrack {{X}_{0},\ldots ,{X}_{N}}\right\rbrack ,\left\lbrack {{Y}_{0},\ldots ,{Y}_{M}}\right\rbrack }\right...
Yes
Theorem 7.29. (Weil Height Machine) For every nonsingular variety \( V/\overline{\mathbb{Q}} \) there exists a map\n\n\[ \n{h}_{V} : \operatorname{Div}\left( V\right) \rightarrow \{ \text{ functions }V\left( \overline{\mathbb{Q}}\right) \rightarrow \mathbb{R}\} ,\;D \mapsto {h}_{V, D},\n\]\n\nwith the following propert...
Proof. See [76, Chapter 2], [205, Theorem B.3.2], or [256, Chapter 4].
No
Let \( \phi : {\mathbb{P}}^{N} \rightarrow {\mathbb{P}}^{N} \) be a morphism of degree \( d \) and let \( H \in \operatorname{Div}\left( {\mathbb{P}}^{N}\right) \) be a hyperplane. Then \( {\phi }^{ * }H \sim {dH} \)
so Theorem 7.29 allows us to compute\n\n\[\n\begin{matrix} {h}_{{\mathbb{P}}^{N}, H}\left( {\phi \left( P\right) }\right) = {h}_{{\mathbb{P}}^{N},{\phi }^{ * }H}\left( P\right) + O\left( 1\right) = {h}_{{\mathbb{P}}^{N},{dH}}\left( P\right) + O\left( 1\right) = d{h}_{{\mathbb{P}}^{N}, H}\left( P\right) + O\left( 1\righ...
No
Let \( V \) be a subvariety of \( {\mathbb{P}}^{N} \times {\mathbb{P}}^{M} \), say \( \phi : V \hookrightarrow {\mathbb{P}}^{N} \times {\mathbb{P}}^{M} \). Continuing with the notation from Examples 7.27 and 7.28, the height of a point \( P = \left\lbrack {\mathbf{x},\mathbf{y}}\right\rbrack \in V \) with respect to th...
\[ {h}_{V,{\phi }^{ * }{p}_{1}^{ * }{H}_{1}}\left( P\right) = {h}_{{\mathbb{P}}^{N},{H}_{1}}\left( {{p}_{1}\phi \left( P\right) }\right) = h\left( \mathbf{x}\right) ,\] \[ {h}_{V,{\phi }^{ * }{p}_{2}^{ * }{H}_{2}}\left( P\right) = {h}_{{\mathbb{P}}^{M},{H}_{2}}\left( {{p}_{2}\phi \left( P\right) }\right) = h\left( \mat...
Yes
Let \( E \) be an elliptic curve given by a Weierstrass equation. Then the \( x \) - coordinate on \( E \), considered as a map \( x : E \rightarrow {\mathbb{P}}^{1} \), satisfies\n\n\[ \n{x}^{ * }\left( \infty \right) = 2\left( \mathcal{O}\right) \n\]\n\nso we have\n\n\[ \n{h}_{E,\left( \mathcal{O}\right) }\left( P\ri...
Note that the height \( {h}_{{\mathbb{P}}^{1},\left( \infty \right) } \) is just the usual height on \( {\mathbb{P}}^{1} \) from Theorem 7.29(a).
No
We illustrate the involutions on \( {S}_{\mathbf{A},\mathbf{B}} \) using the example\n\n\[ L\left( {\mathbf{x},\mathbf{y}}\right) = {x}_{0}{y}_{0} + {x}_{1}{y}_{1} + {x}_{2}{y}_{2} \]\n\n\[ Q\left( {\mathbf{x},\mathbf{y}}\right) = {x}_{0}^{2}{y}_{0}^{2} + 4{x}_{0}^{2}{y}_{0}{y}_{1} - {x}_{0}^{2}{y}_{1}^{2} + 7{x}_{0}^{...
Thus\n\n\[ L\left( {\left\lbrack {1,0,0}\right\rbrack ,\mathbf{y}}\right) = {y}_{0} = 0\text{ and }Q\left( {\left\lbrack {1,0,0}\right\rbrack ,\mathbf{y}}\right) = {y}_{0}^{2} + 4{y}_{0}{y}_{1} - {y}_{1}^{2} + 7{y}_{1}{y}_{2} = 0, \]\n\nso the solutions are \( \mathbf{y} = \left\lbrack {0,{y}_{1},{y}_{2}}\right\rbrack ...
Yes
We illustrate Proposition 7.39 using the surface described in Example 7.36. The polynomials \( {G}_{k}^{ * } \) and \( {H}_{ij}^{ * } \) for this example are given in Table 7.1. Proposition 7.39 says that \( {\iota }_{1} \) is defined at \( P = \left\lbrack {\mathbf{a},\mathbf{b}}\right\rbrack \) provided that at least...
\[ {G}_{0}^{x}\left( \mathbf{a}\right) = {G}_{1}^{x}\left( \mathbf{a}\right) = {G}_{2}^{x}\left( \mathbf{a}\right) = {H}_{01}^{x}\left( \mathbf{a}\right) = {H}_{02}^{x}\left( \mathbf{a}\right) = {H}_{12}^{x}\left( \mathbf{a}\right) = 0. \] Our first observation is that \[ {G}_{2}^{x}\left( {0,{x}_{1},{x}_{2}}\right) = ...
Yes
Proposition 7.41. There is a proper Zariski closed set \( Z \subset {\mathbb{P}}^{8} \times {\mathbb{P}}^{35} \) such that if \( \left( {\mathbf{A},\mathbf{B}}\right) \notin Z \), then the involutions\n\n\[ \n{\iota }_{1} : {S}_{\mathbf{A},\mathbf{B}} \rightarrow {S}_{\mathbf{A},\mathbf{B}}\;\text{ and }\;{\iota }_{2} ...
Proof. According to Proposition 7.39, the involution \( {\iota }_{1} \) is defined on all of \( {S}_{\mathbf{A},\mathbf{B}} \) provided that the system of equations\n\n\[ \n{G}_{0}^{x}\left( \mathbf{x}\right) = {G}_{1}^{x}\left( \mathbf{x}\right) = {G}_{2}^{x}\left( \mathbf{x}\right) = {H}_{01}^{x}\left( \mathbf{x}\rig...
No
Proposition 7.43. Let \( {D}_{1} = {p}_{1}^{ * }H \) and \( {D}_{2} = {p}_{2}^{ * }H \). The involutions \( {\iota }_{1} \) and \( {\iota }_{2} \) act on the subspace of \( \operatorname{Pic}\left( {S}_{\mathbf{A},\mathbf{B}}\right) \) generated by \( {D}_{1} \) and \( {D}_{2} \) according to the following rules:\n\n\[...
Proof. The involution \( {\iota }_{1} \) switches the sheets of the projection \( {p}_{1} \), so it is clear that \( {p}_{1} \circ {\iota }_{1} = {p}_{1} \). This allows us to compute\n\n\[ \n{\iota }_{1}^{ * }{D}_{1} = {\iota }_{1}^{ * }{p}_{1}^{ * }H = {\left( {p}_{1} \circ {\iota }_{1}\right) }^{ * }H = {p}_{1}^{ * ...
Yes
Proposition 7.49. Let \( {S}_{\mathbf{A},\mathbf{B}} \) be defined over a number field \( K \), let \( {\widehat{h}}^{ + } \) and \( {\widehat{h}}^{ - } \) be the canonical height functions constructed in Proposition 7.47, and let\n\n\[ \widehat{h} = {\widehat{h}}^{ + } + {\widehat{h}}^{ - } \]\n\n(a) The set\n\n\[ \le...
Proof. (a) Using the properties of \( {\widehat{h}}^{ + } \) and \( {\widehat{h}}^{ - } \), we find that\n\n\[ \widehat{h} = {\widehat{h}}^{ + } + {\widehat{h}}^{ - } \]\nby definition of \( \widehat{h} \) ,\n\n\[ = \left( {-{h}_{{D}_{1}} + \alpha {h}_{{D}_{2}}}\right) + \left( {\alpha {h}_{{D}_{1}} - {h}_{{D}_{2}}}\ri...
Yes
Proposition 1.8. Let \( S \) be a set with a multiplication and let \( X \) be a subset of \( S \) . If every element of \( S \) is a product of elements of \( X \), and every element of \( X \) passes Light’s test, then every element of \( S \) passes Light’s test (and the operation on \( S \) is associative).
In Example 1.7, \( {d}^{2} = c,{dc} = a \), and \( {da} = b \), so that \( a, b, c, d \) all are products of \( d \) ’s; since \( d \) passes Light’s test, Example 1.7 is associative.
No
Proposition 2.1. In a group, written multiplicatively, the cancellation laws hold: \( {xy} = {xz} \) implies \( y = z \), and \( {yx} = {zx} \) implies \( y = z \) . Moreover, the equations \( {ax} = b,{ya} = b \) have unique solutions \( x = {a}^{-1}b, y = b{a}^{-1} \) .
Proof. \( {xy} = {xz} \) implies \( y = {1y} = {x}^{-1}{xy} = {x}^{-1}{xz} = {1z} = z \), and similarly for \( {yx} = {zx} \) . The equation \( {ax} = b \) has at most one solution \( x = {a}^{-1}{ax} = {a}^{-1}b \) , and \( x = {a}^{-1}b \) is a solution since \( a{a}^{-1}b = {1b} = b \) . The equation \( {ya} = b \) ...
Yes
Proposition 2.2. In a group, written multiplicatively, \( {\left( {x}^{-1}\right) }^{-1} = x \) and \( {\left( {x}_{1}{x}_{2}\cdots {x}_{n}\right) }^{-1} = {x}_{n}^{-1}\cdots {x}_{2}^{-1}{x}_{1}^{-1} \) .
Proof. In a group, \( {uv} = 1 \) implies \( v = {1v} = {u}^{-1}{uv} = {u}^{-1} \) . Hence \( {x}^{-1}x = 1 \) implies \( x = {\left( {x}^{-1}\right) }^{-1} \) . We prove the second property when \( n = 2 \) and leave the general case to our readers: \( {xy}{y}^{-1}{x}^{-1} = {x1}{x}^{-1} = 1 \) ; hence \( {y}^{-1}{x}^...
No
Proposition 2.3. In a group \( G \) (written multiplicatively) the following properties hold for all \( a \in S \) and all integers \( m, n \) :\n\n(1) \( {a}^{0} = 1,{a}^{1} = a \) ;\n\n(2) \( {a}^{m}{a}^{n} = {a}^{m + n} \) ;\n\n(3) \( {\left( {a}^{m}\right) }^{n} = {a}^{mn} \) ;\n\n(4) \( {\left( {a}^{n}\right) }^{-...
The proof makes an awful exercise, inflicted upon readers for their own good.
No
Corollary 2.4. In a finite group, the inverse of an element is a positive power of that element.
Proof. Let \( G \) be a finite group and let \( x \in G \) . Since \( G \) is finite, the powers \( {x}^{n} \) of \( x, n \in \mathbb{Z} \), cannot be all distinct; there must be an equality \( {x}^{m} = {x}^{n} \) with, say, \( m < n \) . Then \( {x}^{n - m} = 1, x{x}^{n - m - 1} = 1 \), and \( {x}^{-1} = {x}^{n - m -...
Yes
Proposition 3.1. A subset \( H \) of a group \( G \) is a subgroup if and only if \( H \neq \varnothing \) and \( x, y \in H \) implies \( x{y}^{-1} \in H \) .
Proof. These conditions are necessary by (1), (2), and (3). Conversely, assume that \( H \neq \varnothing \) and \( x, y \in H \) implies \( x{y}^{-1} \in H \) . Then there exists \( h \in H \) and \( 1 = h{h}^{-1} \in H \) . Next, \( x \in H \) implies \( {x}^{-1} = 1{x}^{-1} \in H \) . Hence \( x, y \in H \) implies ...
Yes
Proposition 3.2. A subset \( H \) of a finite group \( G \) is a subgroup if and only if \( H \neq \varnothing \) and \( x, y \in H \) implies \( {xy} \in H \) .
Proof. If \( H \neq \varnothing \) and \( x, y \in H \) implies \( {xy} \in H \), then \( x \in H \) implies \( {x}^{n} \in H \) for all \( n > 0 \) and \( {x}^{-1} \in H \), by 2.4; hence \( x, y \in H \) implies \( {y}^{-1} \in H \) and \( x{y}^{-1} \in H \), and \( H \) is a subgroup by 3.1. Conversely, if \( H \) i...
Yes
Proposition 3.3. Let \( G \) be a group and let \( X \) be a subset of \( G \) . The set of all products in \( G \) (including the empty product and one-term products) of elements of \( X \) and inverses of elements of \( X \) is a subgroup of \( G \) ; in fact, it is the smallest subgroup of \( G \) that contains \( X...
Proof. Let \( H \subseteq G \) be the set of all products of elements of \( X \) and inverses of elements of \( X \) . Then \( H \) contains the empty product \( 1;h \in H \) implies \( {h}^{-1} \in H \) , by 2.2; and \( h, k \in H \) implies \( {hk} \in H \), since the product of two products of elements of \( X \) an...
Yes
Corollary 3.4. In a finite group \( G \), the subgroup \( \langle X\rangle \) of \( G \) generated by a subset \( X \) of \( G \) is the set of all products in \( G \) of elements of \( X \).
Proof. This follows from 3.3: if \( G \) is finite, then the inverses of elements of \( X \) are themselves products of elements of \( X \), by 2.4. \( ▱ \)
No
Let \( G \) be a group and let \( a \in G \) . The set of all powers of a is a subgroup of \( G \) ; in fact, it is the subgroup generated by \( \{ a\} \) .
That the powers of \( a \) constitute a subgroup of \( G \) follows from the parts \( {a}^{0} = 1,{\left( {a}^{n}\right) }^{-1} = {a}^{-n} \), and \( {a}^{m}{a}^{n} = {a}^{m + n} \) of 2.3. Also, nonnegative powers of \( a \) are products of \( a \) ’s, and negative powers of \( a \) are products of \( {a}^{-1} \) ’s, ...
No
Proposition 3.6. Every subgroup of \( \mathbb{Z} \) is cyclic, generated by a unique nonnegative integer.
Proof. The proof uses integer division. Let \( H \) be a subgroup of (the additive group) \( \mathbb{Z} \) . If \( H = 0\left( { = \{ 0\} }\right) \), then \( H \) is cyclic, generated by 0 . Now assume that \( H \neq 0 \), so that \( H \) contains an integer \( m \neq 0 \) . If \( m < 0 \), then \( - m \in H \) ; henc...
Yes
Proposition 3.8. Every intersection of subgroups of a group \( G \) is a subgroup of \( G \) .
The proofs are exercises.
No
Proposition 3.10. If \( H \) is a subgroup of a group, then \( {HH} = {Ha} = {aH} = H \) for every \( a \in H \) .
Proof. In the group \( H \), the equation \( {ax} = b \) has a solution for every \( b \in H \) . Therefore \( H \subseteq {aH} \) . But \( {aH} \subseteq H \) since \( a \in H \) . Hence \( {aH} = H \) . Similarly, \( {Ha} = H \) . Finally, \( H \subseteq {aH} \subseteq {HH} \subseteq H \) . \( ▱ \)
Yes
Proposition 3.11. Let \( H \) be a subgroup of a group \( G \) . The left cosets of \( H \) constitute a partition of \( G \) ; the right cosets of \( H \) constitute a partition of \( G \) .
Proof. Define a binary relation \( \mathcal{R} \) on \( G \) by\n\n\[ x\mathcal{R}y\text{if and only if}x{y}^{-1} \in H\text{.} \]\n\nThe relation \( \mathcal{R} \) is reflexive, since \( x{x}^{-1} = 1 \in H \) ; symmetric, since \( x{y}^{-1} \in H \) implies \( y{x}^{-1} = {\left( x{y}^{-1}\right) }^{-1} \in H \) ; an...
Yes
Proposition 3.12. The number of left cosets of a subgroup is equal to the number of its right cosets.
Proof. Let \( G \) be a group and \( H \leqq G \) . Let \( a \in G \) . If \( y \in {aH} \), then \( y = {ax} \) for some \( x \in H \) and \( {y}^{-1} = {x}^{-1}{a}^{-1} \in H{a}^{-1} \) . Conversely, if \( {y}^{-1} \in H{a}^{-1} \) , then \( {y}^{-1} = t{a}^{-1} \) for some \( t \in H \) and \( y = a{t}^{-1} \in {aH}...
Yes
Corollary 3.14 (Lagrange’s Theorem). In a finite group \( G \), the order and index of a subgroup divide the order of \( G \) .
Proof. Let \( H \leqq G \) and let \( a \in G \) . By definition, \( {aH} = \{ {ax} \mid x \in H\} \) , and the cancellation laws show that \( x \mapsto {ax} \) is a bijection of \( H \) onto \( {aH} \) . Therefore \( \left| {aH}\right| = \left| H\right| \) : all left cosets of \( H \) have order \( \left| H\right| \) ...
Yes
Proposition 4.1. If \( \varphi : A \rightarrow B \) and \( \psi : B \rightarrow C \) are homomorphisms of groups, then so is \( \psi \circ \varphi : A \rightarrow C \) . Moreover, the identity mapping \( {1}_{G} \) on a group \( G \) is a homomorphism.
Homomorphisms preserve identity elements, inverses, and powers, as readers will gladly verify. In particular, homomorphisms of groups preserve the constant and unary operation as well as the binary operation.
No
Proposition 4.7. Let \( N \) be a normal subgroup of a group \( G \). The cosets of \( N \) constitute a group under the multiplication of subsets, and the mapping \( x \mapsto {xN} = {Nx} \) is a surjective homomorphism, whose kernel is \( N \).
Proof. Let \( S \) temporarily denote the set of all cosets of \( N \). Multiplication of subsets of \( G \) is associative and induces a binary operation on \( S \), since \( {xNyN} = {xyNN} = {xyN} \). The identity element is \( N \), since \( {NxN} = {xNN} = {xN} \). The inverse of \( {xN} \) is \( {x}^{-1}N \), sin...
Yes
Proposition 4.8. \( {\mathbb{Z}}_{n} \) is a cyclic group of order \( n \), with elements \( \overline{0},\overline{1},\ldots ,\overline{n - 1} \) and addition
Proof. The proof uses integer division. For every \( x \in \mathbb{Z} \) there exist unique \( q \) and \( r \) such that \( x = {qn} + r \) and \( 0 \leqq r < n \) . Therefore every coset \( \bar{x} = x + \mathbb{Z}n \) is the coset of a unique \( 0 \leqq r < n \) . Hence \( {\mathbb{Z}}_{n} = \{ \overline{0},\overlin...
Yes
Proposition 4.9. Let \( N \) be a normal subgroup of a group \( G \) . Every subgroup of \( G/N \) is the quotient \( H/N \) of a unique subgroup \( H \) of \( G \) that contains \( N \) .
Proof. Let \( \pi : G \rightarrow G/N \) be the canonical projection and let \( B \) be a subgroup of \( G/N \) . By 4.3,\n\n\[ A = {\pi }^{-1}\left( B\right) = \{ a \in G \mid {aN} \in B\} \]\n\nis a subgroup of \( G \) and contains \( {\pi }^{-1}\left( 1\right) = \operatorname{Ker}\pi = N \) . Now, \( N \) is a subgr...
Yes
Proposition 4.10. Let \( N \) be a normal subgroup of a group \( G \) . Direct and inverse image under the canonical projection \( G \rightarrow G/N \) induce a one-to-one correspondence, which preserves inclusion and normality, between subgroups of \( G \) that contain \( N \) and subgroups of \( G/N \) .
Proof. Let \( \mathcal{A} \) be the set of all subgroups of \( G \) that contain \( N \) ; let \( \mathcal{B} \) be the set of all subgroups of \( G/N \) ; let \( \pi : G \rightarrow G/N \) be the canonical projection. By 4.16 and its proof, \( A \mapsto A/N \) is a bijection of \( \mathcal{A} \) onto \( \mathcal{B} \)...
No
Theorem 5.1 (Factorization Theorem). Let \( N \) be a normal subgroup of a group \( G \) . Every homomorphism of groups \( \varphi : G \rightarrow H \) whose kernel contains \( N \) factors uniquely through the canonical projection \( \pi : G \rightarrow G/N \) (there exists a homomorphism \( \psi : G/N \rightarrow H \...
Proof. We use the formal definition of a mapping \( \psi : A \rightarrow B \) as a set of ordered pairs \( \left( {a, b}\right) \) with \( a \in A, b \in B \), such that (i) for every \( a \in A \) there exists \( b \in B \) such that \( \left( {a, b}\right) \in \psi \), and (ii) if \( \left( {{a}_{1},{b}_{1}}\right) \...
Yes
Theorem 5.2 (Homomorphism Theorem). If \( \varphi : A \rightarrow B \) is a homomorphism of groups, then\n\n\[ A/\operatorname{Ker}\varphi \cong \operatorname{Im}\varphi \]\n\nin fact, there is an isomorphism \( \theta : A/\operatorname{Ker}f \rightarrow \operatorname{Im}f \) unique such that \( \varphi = \iota \circ \...
Proof. Let \( \psi : A \rightarrow \operatorname{Im}\varphi \) be the same mapping as \( \varphi \) (the same set of ordered pairs) but viewed as a homomorphism of \( A \) onto \( \operatorname{Im}\varphi \) . Then \( \operatorname{Ker}\psi = \) Ker \( \varphi \) ; by 5.1, \( \psi \) factors through \( \pi : \psi = \th...
Yes
Corollary 5.3. Let \( \varphi : A \rightarrow B \) be a homomorphism. If \( \varphi \) is injective, then \( A \cong \operatorname{Im}\varphi \) . If \( \varphi \) is surjective, then \( B \cong A/\operatorname{Ker}\varphi \) .
Proof. If \( \varphi \) is injective, then \( \operatorname{Ker}\varphi = 1 \) and \( A \cong A/\operatorname{Ker}\varphi \cong \operatorname{Im}\varphi \) . If \( \varphi \) is surjective, then \( B = \operatorname{Im}\varphi \cong A/\operatorname{Ker}\varphi \) . \( ▱ \)
Yes
Proposition 5.4. Let \( G \) be a group and let \( a \in G \) . If \( {a}^{m} \neq 1 \) for all \( m \neq 0 \), then \( \langle a\rangle \cong \mathbb{Z} \) ; in particular, \( \langle a\rangle \) is infinite. Otherwise, there is a smallest positive integer \( n \) such that \( {a}^{n} = 1 \), and then \( {a}^{m} = 1 \...
Proof. The power map \( p : m \mapsto {a}^{m} \) is a homomorphism of \( \mathbb{Z} \) into \( G \) . By 5.1, \( \langle a\rangle = \operatorname{Im}p \cong \mathbb{Z}/\operatorname{Ker}p \) . By 3.6, Ker \( p \) is cyclic, Ker \( p = \mathbb{Z}n \) for some unique nonnegative integer \( n \) . If \( n = 0 \), then \( ...
Yes
Corollary 5.6. Every subgroup of a cyclic group is cyclic.
This follows from Propositions 5.4 and 3.6; the details make a pretty exercise.
No
Theorem 5.8 (First Isomorphism Theorem). Let \( A \) be a group and let \( B, C \) be normal subgroups of \( A \) . If \( C \subseteq B \), then \( C \) is a normal subgroup of \( B, B/C \) is a normal subgroup of \( A/C \), and \[ A/B \cong \left( {A/C}\right) /\left( {B/C}\right) ; \] in fact, there is a unique isomo...
Proof. By 5.1, \( \rho \) factors through \( \pi : \rho = \sigma \circ \pi \) for some homomorphism \( \sigma : A/C \rightarrow A/B \) ; namely, \( \sigma : {aC} \mapsto {aB} \) . Like \( \rho ,\sigma \) is surjective. We show that \( \operatorname{Ker}\sigma = B/C \) . First, \( C \leqq B \), since \( C \leqq A \) . I...
Yes
Theorem 5.9 (Second Isomorphism Theorem). Let \( A \) be a subgroup of a group \( G \), and let \( N \) be a normal subgroup of \( G \) . Then \( {AN} \) is a subgroup of \( G, N \) is a normal subgroup of \( {AN}, A \cap N \) is a normal subgroup of \( A \), and\n\n\[ \n{AN}/N \cong A/\left( {A \cap N}\right) \n\]\n\n...
Proof. We show that \( {AN} \leqq G \) . First, \( 1 \in {AN} \) . Since \( N \leqq G,{NA} = {AN} \) ; hence \( {an} \in {AN} \) (with \( a \in A, n \in N \) ) implies \( {\left( an\right) }^{-1} = {n}^{-1}{a}^{-1} \in {NA} = {AN} \) . Finally, \( {ANAN} = {AANN} = {AN} \) .\n\nNow, \( N \leqq {AN} \) . Let \( \varphi ...
Yes
Lemma 6.1. For every word \( a \in W \) there is a reduction \( a \rightarrow b \) to a reduced word \( b \) .
Proof. By induction on the length of \( a \) . If \( a \) is reduced, then \( b = a \) serves. Otherwise, \( a\overset{1}{ \rightarrow }c \) for some \( c \in W, c \rightarrow b \) for some reduced \( b \in W \) since \( c \) is shorter than \( a \), and then \( a \rightarrow b \) . \( ▱ \)
Yes
Lemma 6.2. If \( a\overset{1}{ \rightarrow }b \) and \( a\overset{1}{ \rightarrow }c \neq b \), then \( b\overset{1}{ \rightarrow }d, c\overset{1}{ \rightarrow }d \) for some \( d \) .
Proof. Let \( a = \left( {{a}_{1},{a}_{2},\ldots ,{a}_{n}}\right) \) . We have \( {a}_{i + 1} = {a}_{i}^{\prime } \) and\n\n\[ b = \left( {{a}_{1},\ldots ,{a}_{i - 1},{a}_{i + 2},\ldots ,{a}_{n}}\right) ,\]\n\nfor some \( 1 \leqq i < n \) ; also, \( {a}_{j + 1} = {a}_{j}^{\prime } \) and\n\n\[ c = \left( {{a}_{1},\ldot...
Yes
Lemma 6.3. If \( a \rightarrow b \) and \( a \rightarrow c \), then \( b \rightarrow d \) and \( c \rightarrow d \) for some \( d \) .
Proof. Say \( a\overset{k}{ \rightarrow }b \) and \( a\overset{\ell }{ \rightarrow }c \) . The result is trivial if \( k = 0 \) or if \( \ell = 0 \) .\n\nWe first prove 6.3 when \( \ell = 1 \), by induction on \( k \) . We have \( a\overset{1}{ \rightarrow }c \) . If \( k \leqq 1 \) , then 6.3 holds, by 6.2. Now let \(...
Yes
Lemma 6.4. For every word \( a \in W \) there is a unique reduced word \( b \) such that \( a \rightarrow b \) .
Proof. If \( a \rightarrow b \) and \( a \rightarrow c \), with \( b \) and \( c \) reduced, then, in Lemma 6.3, \( b \rightarrow d \) and \( c \rightarrow d \) imply \( b = d = c \) . \( ▱ \)
Yes
Proposition 6.5. Under the operation \( a \cdot b = \operatorname{red}\left( {ab}\right) \), the set \( {F}_{X} \) of all reduced words in \( X \) is a group.
Proof. If \( a\overset{1}{ \rightarrow }b \), then \( {ac}\overset{1}{ \rightarrow }{bc} \) and \( {ca}\overset{1}{ \rightarrow }{cb} \) for all \( c \in W \) . Hence \( a \rightarrow b \) implies \( {ac} \rightarrow {bc} \) and \( {ca} \rightarrow {cb} \) for all \( c \in W \) . If now \( a, b, c \in W \) are reduced,...
Yes
Proposition 6.6. If \( a = \left( {{a}_{1},{a}_{2},\ldots ,{a}_{n}}\right) \) is a reduced word in \( X \), then\n\n\[ a = \eta \left( {a}_{1}\right) \cdot \eta \left( {a}_{2}\right) \cdot \cdots \cdot \eta \left( {a}_{n}\right) . \]\n\nIn particular, \( {F}_{X} \) is generated by \( \eta \left( X\right) \) .
Proof. If \( a = \left( {{a}_{1},{a}_{2},\ldots ,{a}_{n}}\right) \) is reduced, then concatenating the one-letter words \( \left( {a}_{1}\right) ,\left( {a}_{2}\right) ,\ldots ,\left( {a}_{n}\right) \) yields a reduced word; hence\n\n\[ a = \left( {a}_{1}\right) \cdot \left( {a}_{2}\right) \cdot \cdots \cdot \left( {a}...
Yes
Theorem 6.7. Let \( \eta : X \rightarrow {F}_{X} \) be the canonical injection. For every mapping \( f \) of \( X \) into a group \( G \), there is a homomorphism \( \varphi \) of \( {F}_{X} \) into \( G \) unique such that \( f = \varphi \circ \eta \), namely\n\n\[ \varphi \left( {{a}_{1},{a}_{2},\ldots ,{a}_{n}}\righ...
Proof. We show uniqueness first. Let \( \varphi : {F}_{X} \rightarrow G \) be a homomorphism such that \( f = \varphi \circ \eta \) . Extend \( f \) to \( {X}^{\prime } \) so that \( f\left( {x}^{\prime }\right) = f{\left( x\right) }^{-1} \) for all \( x \in X \) . For every \( x \in X \), we have \( \varphi \left( {\e...
Yes
Corollary 6.8. If the group \( G \) is generated by a subset \( X \), then there is a surjective homomorphism of \( {F}_{X} \) onto \( G \) .
Proof. By Theorem 6.7, there is a homomorphism \( \varphi : {F}_{X} \rightarrow G \) such that \( \varphi \circ \eta \) is the inclusion mapping \( X \rightarrow G \) ; then \( \operatorname{Im}\varphi = G \), since \( \operatorname{Im}\varphi \) contains every generator \( x = \varphi \left( {\eta \left( x\right) }\ri...
Yes
Proposition 7.1. Let \( R \) be a set of group relations between elements of a set \( X \) . Every relation \( \left( {u, v}\right) \in R \) holds in \( \langle X \mid R\rangle \) via the canonical mapping \( \iota : X \rightarrow \langle X \mid R\rangle \) ; moreover, \( \langle X \mid R\rangle \) is generated by \( \...
Proof. The canonical projection \( \pi : {F}_{X} \rightarrow \langle X \mid R\rangle \) is a homomorphism that extends \( \iota \) to \( {F}_{X} \), since \( \pi \circ \eta = \iota \) ; therefore it is the homomorphism that extends \( \iota \) to \( {F}_{X} \). If \( \left( {u, v}\right) \in R \), then \( u{v}^{-1} \in...
Yes
Theorem 7.2 (Dyck [1882]). Let \( R \) be a set of group relations between elements of a set \( X \) . If \( f \) is a mapping of \( X \) into a group \( G \), and every relation \( \left( {u, v}\right) \in R \) holds in \( G \) via \( f \), then there exists a homomorphism \( \psi : \langle X \mid R\rangle \rightarrow...
Proof. Let \( N \) be the smallest normal subgroup of \( {F}_{X} \) that contains all \( u{v}^{-1} \) with \( \left( {u, v}\right) \in R \) . By 6.7 there is a unique homomorphism \( \varphi : {F}_{X} \rightarrow G \) that extends \( f \) . Since every \( \left( {u, v}\right) \in R \) holds in \( G \) via \( f \), we h...
Yes
List the elements and construct a multiplication table of the quaternion group\n\n\[ \nQ = \left\langle {a, b \mid {a}^{4} = 1,{b}^{2} = {a}^{2},{ba}{b}^{-1} = {a}^{-1}}\right\rangle .\n\]
Solution. As in the case of \( {D}_{n} \), the elements of \( Q \) are products of \( a \) ’s and \( b \) ’s, which can be rewritten, using the relation \( {ba} = {a}^{3}b \), so that all \( a \) ’s precede all \( b \) ’s. Since \( {a}^{4} = 1 \) and \( {b}^{2} = {a}^{2} \), at most three \( a \) ’s and at most one \( ...
No
Lemma 8.2. If \( x\overset{1}{ \rightarrow }y \) and \( x\overset{1}{ \rightarrow }z \neq y \), then \( y\overset{1}{ \rightarrow }t, z\overset{1}{ \rightarrow }t \) for some \( t \) .
Proof. By definition, \( x = \left( {{x}_{1},{x}_{2},\ldots ,{x}_{n}}\right) ,{x}_{i},{x}_{i + 1} \in A \) or \( {x}_{i},{x}_{i + 1} \in B \) for some \( i \) ,\n\n\[ y = \left( {{x}_{1},\ldots ,{x}_{i - 1},{x}_{i}{x}_{i + 1},{x}_{i + 2},\ldots ,{x}_{n}}\right) ,\]\n\n\( {x}_{j},{x}_{j + 1} \in A \) or \( {x}_{j},{x}_{...
Yes
Proposition 8.5. If \( A \cap B = 1 \), then the set \( A \coprod B \) of all reduced nonempty words in \( A \cup B \) is a group under the operation \( x \cdot y = \operatorname{red}\left( {xy}\right) \) .
Proof. Associativity is proved as in Proposition 6.5. The one-letter word \( 1 = \left( 1\right) \) is reduced and is the identity element of \( A \coprod B \), since \( 1 \cdot x = \operatorname{red}\left( {1x}\right) = \) \( \operatorname{red}x = x \) and \( x \cdot 1 = \operatorname{red}x = x \) when \( x \) is redu...
Yes