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EN_B00000_S02962_W000094 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " This is going to be very similar to the picture that we drew earlier in this video. So here are the two plates.",
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EN_B00000_S02962_W000095 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " We're gonna put the negative plate at the bottom and the positive plate at the top.",
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EN_B00000_S02962_W000096 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " And we are going to apply a battery to these two metal plates.",
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EN_B00000_S02962_W000097 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So that is the electric, excuse me, that is the electrical symbol of a battery. The long side is the positive plate. The short side is the negative plate.",
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EN_B00000_S02962_W000098 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So let's say if we'll call this plate A and plate B, if plate A is at a potential of zero volts, plate B will be at a potential of 120 volts.",
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EN_B00000_S02962_W000099 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " The difference has to be 120 because the voltage is 120. So let's say if A was at 50 volts, B would be at 170 volts. B is always 120 volts higher than A.",
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EN_B00000_S02962_W000100 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " But it's always good to have a reference point. So, we're gonna say a is 0 and b is 120.",
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EN_B00000_S02962_W000101 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Now the distance between these two plates is 10 centimeters. How can we determine the strength of the electric field between the two plates?",
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EN_B00000_S02962_W000102 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Keep in mind the electric field always emanates away from the positive plate and points towards the negative plate.",
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EN_B00000_S02962_W000103 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000104 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 4.482,
"id": "EN_B00000_S02962_W000104",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Will give us the answer. So the electric field is 1200 volts per meter.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000104.mp3"
} | EN_B00000_S02962_W000104.mp3 | [
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EN_B00000_S02962_W000105 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S02962",
"text": " So this tells us that the voltage will increase by 1200 volts every meter.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000105.mp3"
} | EN_B00000_S02962_W000105.mp3 | [
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EN_B00000_S02962_W000106 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3103,
"duration": 3.31,
"id": "EN_B00000_S02962_W000106",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " It increases by 120 volts every .1 meters.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000106.mp3"
} | EN_B00000_S02962_W000106.mp3 | [
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EN_B00000_S02962_W000107 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 7.691,
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"language": "en",
"speaker": "EN_B00000_S02962",
"text": " So let's say at five centimeters away from play A, let me draw this better.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000107.mp3"
} | EN_B00000_S02962_W000107.mp3 | [
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EN_B00000_S02962_W000108 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 8.082,
"id": "EN_B00000_S02962_W000108",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " The voltage will be 60 volts. What do you think the voltage will be 2 centimeters away from plate A?",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000108.mp3"
} | EN_B00000_S02962_W000108.mp3 | [
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EN_B00000_S02962_W000109 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"id": "EN_B00000_S02962_W000109",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " 120 volts divided by 10 centimeters.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000109.mp3"
} | EN_B00000_S02962_W000109.mp3 | [
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EN_B00000_S02962_W000110 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S02962",
"text": " We'll give us an electric potential or rather an electric field of 12 volts per centimeter. So every centimeter, the voltage will increase by 12. So two centimeters away, it w... | EN_B00000_S02962_W000110.mp3 | [
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EN_B00000_S02962_W000111 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S02962",
"text": " Eight centimeters away from plate A, it's going to be eight times 12. So it's going to be 96 volts. And so what we have is a potential gradient. As we progressively move from ... | EN_B00000_S02962_W000111.mp3 | [
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EN_B00000_S02962_W000112 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"id": "EN_B00000_S02962_W000112",
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"speaker": "EN_B00000_S02962",
"text": " So let's draw a picture. So here we have the positive charge. We'll call it Q and",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000112.mp3"
} | EN_B00000_S02962_W000112.mp3 | [
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EN_B00000_S02962_W000113 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " At a distance of 5 meters away, at some point P, we want to calculate the electric potential at that point. And it's a formula that we could use.",
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EN_B00000_S02962_W000114 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000118 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000119 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000120 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000121 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000122 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000123 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000124 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000125 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000126 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " I'ma see if I can fit it in all here. So we have k.",
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EN_B00000_S02962_W000127 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000128 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000129 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000130 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " 3 squared plus 4 squared, that's 9 plus 16, which is 25. The square root of 25 gives us 5. So that's the distance between q2 and point P.",
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EN_B00000_S02962_W000131 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000132 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000134 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000135 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"language": "en",
"speaker": "EN_B00000_S02962",
"text": " And let's say the second point charge is very far away from the first one.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000135.mp3"
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EN_B00000_S02962_W000136 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S02962",
"text": " So right now, the separation distance is 500 meters. We're going to call the stationary charge capital Q, and the point charge that is free to move, let's call it lowercase q.... | EN_B00000_S02962_W000136.mp3 | [
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EN_B00000_S02962_W000137 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000138 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000139 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000140 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S02962",
"text": " What would you say? Now, by the way, is the work going to be positive or negative?",
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EN_B00000_S02962_W000141 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Whenever you move two positive charges closer together, will the potential energy go up or will it go down?",
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EN_B00000_S02962_W000142 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.4233,
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"speaker": "EN_B00000_S02962",
"text": " As you move it close to each other, you're increasing the potential energy. And as you increase the potential energy, the work being done on a charge is negative.",
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EN_B00000_S02962_W000143 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000144 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " When the kinetic energy of a particle or of an object goes up, which means the potential energy is going down. So when the potential energy goes up, the work is negative.",
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EN_B00000_S02962_W000146 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000147 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000148 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000149 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000150 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000151 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000152 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " The work required to move a charge through a potential difference is negative Q delta V. Now keep in mind, this charge will create an electric potential at point A.",
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EN_B00000_S02962_W000153 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000154 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000155 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"language": "en",
"speaker": "EN_B00000_S02962",
"text": " So as you move closer to the charge, as the separation distance decreases, the electric potential increases.",
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EN_B00000_S02962_W000156 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So Delta V is going to be the change in electric potential.",
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EN_B00000_S02962_W000157 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " It is the electric potential created by charge Q at point B minus the electric potential created by that same charge at point A.",
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EN_B00000_S02962_W000158 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Now the electric potential at point B is going to be KQ divided by RB, where RB is one meter. That's the distance between position B and charge Q. Now the electric potential a... | EN_B00000_S02962_W000158.mp3 | [
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EN_B00000_S02962_W000159 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So what we can do now is we can factor out k and q.",
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EN_B00000_S02962_W000160 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So the work required will be negative k times the stationary charge times the movable charge.",
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EN_B00000_S02962_W000161 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S02962",
"text": " And then times 1 over rb minus 1 over ra.",
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EN_B00000_S02962_W000162 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So w is going to be negative k, so that's negative 9 times 10 to the 9 newtons per square meter divided by coulomb squared or coulombs times coulombs. And then capital Q is goin... | EN_B00000_S02962_W000162.mp3 | [
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EN_B00000_S02962_W000163 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000164 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000165 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.336,
"duration": 5.297,
"id": "EN_B00000_S02962_W000165",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " One, there's two meters here, it's meters times meters, but only one of them will cancel what we have.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000165.mp3"
} | EN_B00000_S02962_W000165.mp3 | [
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EN_B00000_S02962_W000166 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3428,
"duration": 19.643,
"id": "EN_B00000_S02962_W000166",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " So it's going to be negative nine times 10 to the nine times 50 times 10 to the minus six squared and then times in parentheses one minus one over 500. So you should get this ... | EN_B00000_S02962_W000166.mp3 | [
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EN_B00000_S02962_W000167 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3831,
"duration": 5.806,
"id": "EN_B00000_S02962_W000167",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " So right now we have the unit newtons and times one of the two meters that was here.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000167.mp3"
} | EN_B00000_S02962_W000167.mp3 | [
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EN_B00000_S02962_W000168 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.2488,
"duration": 6.112,
"id": "EN_B00000_S02962_W000168",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Notice that it takes one meter to cancel both of these because you need to distribute it through the brackets.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W0001... | EN_B00000_S02962_W000168.mp3 | [
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EN_B00000_S02962_W000169 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 7.233,
"id": "EN_B00000_S02962_W000169",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " So right now our answer is negative 22.455 newton times meters.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000169.mp3"
} | EN_B00000_S02962_W000169.mp3 | [
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EN_B00000_S02962_W000170 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 11.953,
"id": "EN_B00000_S02962_W000170",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Now, recall that work is equal to force times distance. Force is in newtons, this distance or displacement rather. That's the more accurate description of this formula, it's d... | EN_B00000_S02962_W000170.mp3 | [
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EN_B00000_S02962_W000171 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 22.292,
"id": "EN_B00000_S02962_W000171",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Newtons times meters is equal to the joule. So we could say this is negative 22.455 joules. So make sure you know that 1 newton meter is equal to 1 joule. Therefore, A is the b... | EN_B00000_S02962_W000171.mp3 | [
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EN_B00000_S02962_W000172 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 5.416,
"id": "EN_B00000_S02962_W000172",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Of the net electric field at a point nine meters east from the 70 microcoulomb charge.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000172.mp3"
} | EN_B00000_S02962_W000172.mp3 | [
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EN_B00000_S02962_W000173 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"id": "EN_B00000_S02962_W000173",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " So let's draw a picture. So first we have the negative charge, which we're going to put this on the left. And then to the right of that, there is a positive charge.",
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EN_B00000_S02962_W000174 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 3.922,
"id": "EN_B00000_S02962_W000174",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " And the separation distance between them is 4 meters.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000174.mp3"
} | EN_B00000_S02962_W000174.mp3 | [
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EN_B00000_S02962_W000175 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S02962",
"text": " Now to the right of the positive charge, we have point P.",
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EN_B00000_S02962_W000176 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " And it's nine meters to the right of the positive charge. So let's call this Q1 and Q2.",
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EN_B00000_S02962_W000177 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So each charge will create its own electric field at point P.",
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EN_B00000_S02962_W000178 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Q2 will create an electric field that will be directed away from the positive charge, so it's going to be going towards the right. Q1 will create an electric field",
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EN_B00000_S02962_W000179 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000180 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " The net electric field is the sum of these two vectors. Now,",
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EN_B00000_S02962_W000181 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Because these vectors are going in the x direction, we can add them. E2 is going in the positive x direction, so it's going to have a positive value.",
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EN_B00000_S02962_W000182 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S02962_W000183 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"language": "en",
"speaker": "EN_B00000_S02962",
"text": " q2 over r2 squared. Let me write that better.",
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EN_B00000_S02962_W000184 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " And e1 is going to be k times q1 over r1 squared. So now let's go ahead and calculate the net electric field. So it's going to be 9 times 10 to the 9 times q2, which is",
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EN_B00000_S02962_W000185 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Positive 70 microcoulombs, or 70 times 10 to the minus 6 coulombs. R2, the distance between Q2 and point P, that's gonna be 9 meters.",
"wav": "EN_B00000/EN_B00000_S02962/mp... | EN_B00000_S02962_W000185.mp3 | [
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296,
1943,
2022,
1427,
3993,
253,
2211,
3993,
1960,
992,
2022,
947,
3660,
2487... | [
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1109,
2934,
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460,
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470,
2265,
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465,
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33,
1218,
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3172,
559,
2032,... |
EN_B00000_S02962_W000186 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 5.433,
"id": "EN_B00000_S02962_W000186",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " And q1 is basically a distance of 13 meters away from the point charge.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000186.mp3"
} | EN_B00000_S02962_W000186.mp3 | [
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EN_B00000_S02962_W000187 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3295,
"duration": 16.502,
"id": "EN_B00000_S02962_W000187",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Whoops. 9 times 10 to the 9 times 70 times 10 to the minus 6 divided by 9 squared. So this is going to give us 7,777.7 repeating for this part.",
"wav": "EN_B00000/EN_B00000... | EN_B00000_S02962_W000187.mp3 | [
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EN_B00000_S02962_W000188 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3012,
"duration": 8.285,
"id": "EN_B00000_S02962_W000188",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " And then for the other electric field, 9 times 10 to the 9, times 120 times 10 to the minus 6, divided by 13 squared.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S0296... | EN_B00000_S02962_W000188.mp3 | [
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389,
3890,
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2404,
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1... |
EN_B00000_S02962_W000189 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3042,
"duration": 7.267,
"id": "EN_B00000_S02962_W000189",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " That's gonna be 6390.53. So if we subtract those two numbers,",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000189.mp3"
} | EN_B00000_S02962_W000189.mp3 | [
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3584,
1824,
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761,
2807,
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2634,
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EN_B00000_S02962_W000190 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3517,
"duration": 13.735,
"id": "EN_B00000_S02962_W000190",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " You should get 1,387, rounded to the nearest whole number, Newtons per Coulomb. So this is the magnitude of the electric field. Now notice that this value is positive.",
"wa... | EN_B00000_S02962_W000190.mp3 | [
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2919,
3970,
4069,
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EN_B00000_S02962_W000191 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3186,
"duration": 3.684,
"id": "EN_B00000_S02962_W000191",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " This tells us that E2 is greater than E1.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000191.mp3"
} | EN_B00000_S02962_W000191.mp3 | [
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55,
432,
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2872,
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1038,
2637,
292,
24... |
EN_B00000_S02962_W000192 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3619,
"duration": 5.11,
"id": "EN_B00000_S02962_W000192",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " So the net electric field will be directed towards the right in the east direction.",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000192.mp3"
} | EN_B00000_S02962_W000192.mp3 | [
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305,
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1182,
813,
1120,
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1438,
2451,
2265,
3878,
2771,
2904,
1188,
3803,
535... | [
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953,
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EN_B00000_S02962_W000193 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 9.321,
"id": "EN_B00000_S02962_W000193",
"language": "en",
"speaker": "EN_B00000_S02962",
"text": " Because point P is closer to the positive charge than it is to the negative charge, it's going to field an electric field that",
"wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00... | EN_B00000_S02962_W000193.mp3 | [
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375... |
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