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EN_B00000_S02962_W000194
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3119, "duration": 13.43, "id": "EN_B00000_S02962_W000194", "language": "en", "speaker": "EN_B00000_S02962", "text": " Will be directed towards the right in the direction of E2. So E2 is going to be greater than E1 because point P is closer to Q2 than it is to Q1. So that's how you can calculat...
EN_B00000_S02962_W000194.mp3
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EN_B00000_S02962_W000195
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3897, "duration": 26.333, "id": "EN_B00000_S02962_W000195", "language": "en", "speaker": "EN_B00000_S02962", "text": " of the electric field and determine its direction for a problem like this. Number 13, the four point charges shown below are arranged in a square with a side length of three m...
EN_B00000_S02962_W000195.mp3
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EN_B00000_S02962_W000196
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4013, "duration": 13.532, "id": "EN_B00000_S02962_W000196", "language": "en", "speaker": "EN_B00000_S02962", "text": " So first, we need to calculate the force acting on Q4 due to the other three point charges. Q1 will cause Q4 to move to the right.", "wav": "EN_B00000/EN_B00000_S02962/mp3/E...
EN_B00000_S02962_W000196.mp3
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EN_B00000_S02962_W000197
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3459, "duration": 4.397, "id": "EN_B00000_S02962_W000197", "language": "en", "speaker": "EN_B00000_S02962", "text": " So we're going to call that the force exerted on four due to charge one.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000197.mp3" }
EN_B00000_S02962_W000197.mp3
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EN_B00000_S02962_W000198
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2693, "duration": 14.737, "id": "EN_B00000_S02962_W000198", "language": "en", "speaker": "EN_B00000_S02962", "text": " Q3 is going to pull Q4 towards it. So this is going to be the force on charge 4 due to charge 3. Q2 will also pull the fourth charge towards it.", "wav": "EN_B00000/EN_B0000...
EN_B00000_S02962_W000198.mp3
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EN_B00000_S02962_W000199
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2984, "duration": 8.879, "id": "EN_B00000_S02962_W000199", "language": "en", "speaker": "EN_B00000_S02962", "text": " So that's the force on 4 due to charge 2. So we have three force vectors that we need to calculate.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000199.mp3" }
EN_B00000_S02962_W000199.mp3
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EN_B00000_S02962_W000200
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3624, "duration": 3.328, "id": "EN_B00000_S02962_W000200", "language": "en", "speaker": "EN_B00000_S02962", "text": " So let's begin by calculating f for one.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000200.mp3" }
EN_B00000_S02962_W000200.mp3
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EN_B00000_S02962_W000201
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3176, "duration": 15.365, "id": "EN_B00000_S02962_W000201", "language": "en", "speaker": "EN_B00000_S02962", "text": " The force between two point charges is k times, in this case q1 times q4 divided by r squared. So k is 9 times 10 to the 9. q1 and q4", "wav": "EN_B00000/EN_B00000_S02962/mp...
EN_B00000_S02962_W000201.mp3
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EN_B00000_S02962_W000202
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3371, "duration": 10.22, "id": "EN_B00000_S02962_W000202", "language": "en", "speaker": "EN_B00000_S02962", "text": " They have the same magnitude and we don't have to worry about the sign. So we're going to say it's 200 times 10 to the minus six columns and we're just going to square it.", ...
EN_B00000_S02962_W000202.mp3
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EN_B00000_S02962_W000203
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4149, "duration": 4.635, "id": "EN_B00000_S02962_W000203", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now r, the distance between q1 and q4 is 3 meters.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000203.mp3" }
EN_B00000_S02962_W000203.mp3
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EN_B00000_S02962_W000204
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3635, "duration": 12.818, "id": "EN_B00000_S02962_W000204", "language": "en", "speaker": "EN_B00000_S02962", "text": " So this is going to be 40 newtons. So I'm going to write it above here. F four one has a magnitude of 40 newtons and the direction. Notice that it's east.", "wav": "EN_B0000...
EN_B00000_S02962_W000204.mp3
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EN_B00000_S02962_W000205
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3273, "duration": 19.678, "id": "EN_B00000_S02962_W000205", "language": "en", "speaker": "EN_B00000_S02962", "text": " So let's say east is zero, north is 90, west is 180, south is 270. So it's directed east at an angle of zero. This one is directed south at an angle of 270. And this one is di...
EN_B00000_S02962_W000205.mp3
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EN_B00000_S02962_W000206
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.1441, "duration": 3.769, "id": "EN_B00000_S02962_W000206", "language": "en", "speaker": "EN_B00000_S02962", "text": " So for the first vector, we're going to say the angle is at 0 degrees.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000206.mp3" }
EN_B00000_S02962_W000206.mp3
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EN_B00000_S02962_W000207
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3495, "duration": 17.084, "id": "EN_B00000_S02962_W000207", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now let's move on to the next one. F43. So that's going to be KQ3 times Q4 over R squared. So K is the same. Q3 times Q4, that's not going to change. It's 200 times 10 to the ...
EN_B00000_S02962_W000207.mp3
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EN_B00000_S02962_W000208
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4755, "duration": 5.718, "id": "EN_B00000_S02962_W000208", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now, we're dealing with a square, so the distance between q3 and q4 is still 3 meters.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000208.mp3" }
EN_B00000_S02962_W000208.mp3
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EN_B00000_S02962_W000209
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3794, "duration": 13.837, "id": "EN_B00000_S02962_W000209", "language": "en", "speaker": "EN_B00000_S02962", "text": " The only difference is the direction. So this force vector has a magnitude of 40 newtons at an angle of 270 degrees. Now let's go ahead and calculate the other force vector.",...
EN_B00000_S02962_W000209.mp3
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EN_B00000_S02962_W000210
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3451, "duration": 8.285, "id": "EN_B00000_S02962_W000210", "language": "en", "speaker": "EN_B00000_S02962", "text": " My computer is acting up. This is gonna be k, q4, q2 divided by r squared.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000210.mp3" }
EN_B00000_S02962_W000210.mp3
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EN_B00000_S02962_W000211
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3494, "duration": 3.124, "id": "EN_B00000_S02962_W000211", "language": "en", "speaker": "EN_B00000_S02962", "text": " So most of this is going to be the same, except the distance.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000211.mp3" }
EN_B00000_S02962_W000211.mp3
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EN_B00000_S02962_W000212
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4484, "duration": 10.849, "id": "EN_B00000_S02962_W000212", "language": "en", "speaker": "EN_B00000_S02962", "text": " The distance between q4 and q2 is not 3 meters. What we need to do is draw a right triangle. This is 3, this is 3. What do you think the hypotenuse is?", "wav": "EN_B00000/E...
EN_B00000_S02962_W000212.mp3
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EN_B00000_S02962_W000213
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4179, "duration": 8.506, "id": "EN_B00000_S02962_W000213", "language": "en", "speaker": "EN_B00000_S02962", "text": " If the legs are the same, the hypotenuse is going to be the length of the leg times the square root of 2. And if you want to confirm that, here's what you can do.", "wav": "E...
EN_B00000_S02962_W000213.mp3
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EN_B00000_S02962_W000214
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3771, "duration": 16.995, "id": "EN_B00000_S02962_W000214", "language": "en", "speaker": "EN_B00000_S02962", "text": " Let's call this x. So using the Pythagorean Theorem, a squared plus b squared is equal to c squared. So we have 3 squared plus 3 squared is equal to x squared. So that's 9 plu...
EN_B00000_S02962_W000214.mp3
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EN_B00000_S02962_W000215
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2075, "duration": 7.232, "id": "EN_B00000_S02962_W000215", "language": "en", "speaker": "EN_B00000_S02962", "text": " And then if we take the square root of both sides, the square root of 18 is basically the square root of 9 times the square root of 2.", "wav": "EN_B00000/EN_B00000_S02962/mp...
EN_B00000_S02962_W000215.mp3
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EN_B00000_S02962_W000216
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3481, "duration": 3.395, "id": "EN_B00000_S02962_W000216", "language": "en", "speaker": "EN_B00000_S02962", "text": " And the square root of 9 is 3, so you get 3 square root 2.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000216.mp3" }
EN_B00000_S02962_W000216.mp3
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EN_B00000_S02962_W000217
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3042, "duration": 4.431, "id": "EN_B00000_S02962_W000217", "language": "en", "speaker": "EN_B00000_S02962", "text": " But I'm going to leave x as the square root of 18. So that's going to be r.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000217.mp3" }
EN_B00000_S02962_W000217.mp3
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EN_B00000_S02962_W000218
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.428, "duration": 9.966, "id": "EN_B00000_S02962_W000218", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now let's replace r with the square root of 18, because once we square it, we're just gonna get 18. So it's 9 times 10 to the 9, times 200.", "wav": "EN_B00000/EN_B00000_S0296...
EN_B00000_S02962_W000218.mp3
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EN_B00000_S02962_W000219
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3225, "duration": 3.905, "id": "EN_B00000_S02962_W000219", "language": "en", "speaker": "EN_B00000_S02962", "text": " Times 10 to the minus 6 squared, divided by 18.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000219.mp3" }
EN_B00000_S02962_W000219.mp3
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EN_B00000_S02962_W000220
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2885, "duration": 6.231, "id": "EN_B00000_S02962_W000220", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now our next step is to basically add the components of these three vectors.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000220.mp3" }
EN_B00000_S02962_W000220.mp3
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EN_B00000_S02962_W000221
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4076, "duration": 9.355, "id": "EN_B00000_S02962_W000221", "language": "en", "speaker": "EN_B00000_S02962", "text": " In order to get the resultant vector, or basically the net force acted on Q4, you can call it the sum of the forces.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962...
EN_B00000_S02962_W000221.mp3
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EN_B00000_S02962_W000222
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3792, "duration": 5.534, "id": "EN_B00000_S02962_W000222", "language": "en", "speaker": "EN_B00000_S02962", "text": " We need to find the sum of the forces in the x direction and the sum of the forces in the y direction.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000222.mp3" ...
EN_B00000_S02962_W000222.mp3
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EN_B00000_S02962_W000223
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3446, "duration": 6.893, "id": "EN_B00000_S02962_W000223", "language": "en", "speaker": "EN_B00000_S02962", "text": " So the net force acted on q4 is going to be the square root of the sum of the forces in the x direction squared.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W00...
EN_B00000_S02962_W000223.mp3
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EN_B00000_S02962_W000224
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3331, "duration": 14.041, "id": "EN_B00000_S02962_W000224", "language": "en", "speaker": "EN_B00000_S02962", "text": " Plus the sum of the forces in the y direction squared. So that's how we can calculate the magnitude. For the angle, we're going to use this formula, arc tangent, the y compone...
EN_B00000_S02962_W000224.mp3
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EN_B00000_S02962_W000225
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3454, "duration": 5.688, "id": "EN_B00000_S02962_W000225", "language": "en", "speaker": "EN_B00000_S02962", "text": " But how do we find the x and y components so that we can take the sum of all of them?", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000225.mp3" }
EN_B00000_S02962_W000225.mp3
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EN_B00000_S02962_W000226
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4051, "duration": 7.232, "id": "EN_B00000_S02962_W000226", "language": "en", "speaker": "EN_B00000_S02962", "text": " Here's what we need to do. So let's draw a picture again. This is f, this is the x component, and this is the y component.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_...
EN_B00000_S02962_W000226.mp3
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EN_B00000_S02962_W000227
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3613, "duration": 11.205, "id": "EN_B00000_S02962_W000227", "language": "en", "speaker": "EN_B00000_S02962", "text": " The x component is equal to f times the cosine of the angle. And then you could put the unit vector i if you want to. The y component is basically f.", "wav": "EN_B00000/EN_...
EN_B00000_S02962_W000227.mp3
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EN_B00000_S02962_W000228
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3424, "duration": 5.62, "id": "EN_B00000_S02962_W000228", "language": "en", "speaker": "EN_B00000_S02962", "text": " times sine theta, and it corresponds to, it's usually attached to the unit vector j.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000228.mp3" }
EN_B00000_S02962_W000228.mp3
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EN_B00000_S02962_W000229
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3811, "duration": 5.263, "id": "EN_B00000_S02962_W000229", "language": "en", "speaker": "EN_B00000_S02962", "text": " So the sum of all the forces in the x direction is going to be", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000229.mp3" }
EN_B00000_S02962_W000229.mp3
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EN_B00000_S02962_W000230
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3384, "duration": 3.684, "id": "EN_B00000_S02962_W000230", "language": "en", "speaker": "EN_B00000_S02962", "text": " F41x is going to be 40 cos 0.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000230.mp3" }
EN_B00000_S02962_W000230.mp3
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EN_B00000_S02962_W000231
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3971, "duration": 10.221, "id": "EN_B00000_S02962_W000231", "language": "en", "speaker": "EN_B00000_S02962", "text": " F43x, that's gonna be 40, cosine 270. And for the last one, it's gonna be 20, cosine 225.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000231.mp3" }
EN_B00000_S02962_W000231.mp3
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EN_B00000_S02962_W000232
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2826, "duration": 3.209, "id": "EN_B00000_S02962_W000232", "language": "en", "speaker": "EN_B00000_S02962", "text": " And it's positive 25.86 newtons.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000232.mp3" }
EN_B00000_S02962_W000232.mp3
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EN_B00000_S02962_W000233
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3567, "duration": 7.453, "id": "EN_B00000_S02962_W000233", "language": "en", "speaker": "EN_B00000_S02962", "text": " So let me rewrite that 8 better. Now let's do the same thing for the forces in the y direction.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000233.mp3" }
EN_B00000_S02962_W000233.mp3
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EN_B00000_S02962_W000234
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3734, "duration": 4.176, "id": "EN_B00000_S02962_W000234", "language": "en", "speaker": "EN_B00000_S02962", "text": " So I got negative 54.14 Newtons.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000234.mp3" }
EN_B00000_S02962_W000234.mp3
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EN_B00000_S02962_W000235
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4612, "duration": 4.822, "id": "EN_B00000_S02962_W000235", "language": "en", "speaker": "EN_B00000_S02962", "text": " So now, we can calculate the magnitude of the net force.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000235.mp3" }
EN_B00000_S02962_W000235.mp3
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EN_B00000_S02962_W000236
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4651, "duration": 5.212, "id": "EN_B00000_S02962_W000236", "language": "en", "speaker": "EN_B00000_S02962", "text": " So it's going to be the square root of the square of the x component.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000236.mp3" }
EN_B00000_S02962_W000236.mp3
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EN_B00000_S02962_W000237
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.376, "duration": 3.668, "id": "EN_B00000_S02962_W000237", "language": "en", "speaker": "EN_B00000_S02962", "text": " Plus the square of the y component.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000237.mp3" }
EN_B00000_S02962_W000237.mp3
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EN_B00000_S02962_W000238
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2893, "duration": 7.776, "id": "EN_B00000_S02962_W000238", "language": "en", "speaker": "EN_B00000_S02962", "text": " And so I got 60 newtons for that. So that's the magnitude of the net force. It's 60 newtons.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000238.mp3" }
EN_B00000_S02962_W000238.mp3
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EN_B00000_S02962_W000239
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4285, "duration": 6.061, "id": "EN_B00000_S02962_W000239", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now the next thing we need to do is we need to calculate the direction of this force.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000239.mp3" }
EN_B00000_S02962_W000239.mp3
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EN_B00000_S02962_W000240
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4221, "duration": 18.624, "id": "EN_B00000_S02962_W000240", "language": "en", "speaker": "EN_B00000_S02962", "text": " So let's start with our XY coordinate system. Starting from the origin, the X component is positive. So we're going to travel positive 25.86 units to the right. The Y componen...
EN_B00000_S02962_W000240.mp3
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EN_B00000_S02962_W000241
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4132, "duration": 3.565, "id": "EN_B00000_S02962_W000241", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now the net force will be in this direction, so it's in quadrant 4.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000241.mp3" }
EN_B00000_S02962_W000241.mp3
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EN_B00000_S02962_W000242
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4186, "duration": 14.923, "id": "EN_B00000_S02962_W000242", "language": "en", "speaker": "EN_B00000_S02962", "text": " So this is f of x, and that's the sum of f of y. And here is the reference angle. The reference angle is between 0 and 90. So to calculate it, we're going to take arctangent o...
EN_B00000_S02962_W000242.mp3
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EN_B00000_S02962_W000243
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4112, "duration": 6.027, "id": "EN_B00000_S02962_W000243", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now even though the y-component is negative, we're going to use the positive value, so that we get an angle between 0 and 90.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B000...
EN_B00000_S02962_W000243.mp3
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EN_B00000_S02962_W000244
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3339, "duration": 21.562, "id": "EN_B00000_S02962_W000244", "language": "en", "speaker": "EN_B00000_S02962", "text": " So arctangent 54.14 divided by 25.86 gives us a reference angle of 64.47 degrees. Now the angle that we're looking for typically is measured from the positive x-axis. So it ha...
EN_B00000_S02962_W000244.mp3
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EN_B00000_S02962_W000245
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4159, "duration": 3.973, "id": "EN_B00000_S02962_W000245", "language": "en", "speaker": "EN_B00000_S02962", "text": " 270 and 0 degrees, 0 is the same as 360.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000245.mp3" }
EN_B00000_S02962_W000245.mp3
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EN_B00000_S02962_W000246
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.1797, "duration": 15.111, "id": "EN_B00000_S02962_W000246", "language": "en", "speaker": "EN_B00000_S02962", "text": " So, if a full rotation is 360, we need to go back by 64.47 degrees. So basically, we need to subtract 360 by 64.47 degrees. And so that's going to give us our direction angle....
EN_B00000_S02962_W000246.mp3
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EN_B00000_S02962_W000247
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3506, "duration": 9.966, "id": "EN_B00000_S02962_W000247", "language": "en", "speaker": "EN_B00000_S02962", "text": " And so that's 295.53 degrees. So now we have our answer. So the magnitude is 60 Newtons.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000247.mp3" }
EN_B00000_S02962_W000247.mp3
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EN_B00000_S02962_W000248
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3554, "duration": 4.72, "id": "EN_B00000_S02962_W000248", "language": "en", "speaker": "EN_B00000_S02962", "text": " And the direction is 295.5 degrees measured.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000248.mp3" }
EN_B00000_S02962_W000248.mp3
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EN_B00000_S02962_W000249
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3415, "duration": 5.62, "id": "EN_B00000_S02962_W000249", "language": "en", "speaker": "EN_B00000_S02962", "text": " The force between two point charges separated by a certain distance is 200 newtons.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000249.mp3" }
EN_B00000_S02962_W000249.mp3
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EN_B00000_S02962_W000250
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4267, "duration": 11.239, "id": "EN_B00000_S02962_W000250", "language": "en", "speaker": "EN_B00000_S02962", "text": " What will be the new electric force if the magnitude of the first charge triples, the magnitude of the second charge quadruples, and the distance is reduced by half?", "wav"...
EN_B00000_S02962_W000250.mp3
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EN_B00000_S02962_W000251
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4277, "duration": 15.772, "id": "EN_B00000_S02962_W000251", "language": "en", "speaker": "EN_B00000_S02962", "text": " So we're gonna have to use this formula, kq1q2 over r squared. But for this type of problem, the stuff that doesn't change, we're gonna put a 1. So k is a constant, it doesn't...
EN_B00000_S02962_W000251.mp3
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EN_B00000_S02962_W000252
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2538, "duration": 3.344, "id": "EN_B00000_S02962_W000252", "language": "en", "speaker": "EN_B00000_S02962", "text": " The first try triples, so we're going to replace Q1 with 3.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000252.mp3" }
EN_B00000_S02962_W000252.mp3
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EN_B00000_S02962_W000253
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4169, "duration": 10.951, "id": "EN_B00000_S02962_W000253", "language": "en", "speaker": "EN_B00000_S02962", "text": " The second charge quadruples, which means it increases by a factor of four. And the distance is reduced by a half. Three times four is twelve. One half squared is one fourth."...
EN_B00000_S02962_W000253.mp3
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EN_B00000_S02962_W000254
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2717, "duration": 12.886, "id": "EN_B00000_S02962_W000254", "language": "en", "speaker": "EN_B00000_S02962", "text": " To get rid of the fraction, let's multiply the top and the bottom by 4. 1 fourth times 4 is 1. And 12 times 4 is 48. So what this tells us is that the 4's", "wav": "EN_B0000...
EN_B00000_S02962_W000254.mp3
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EN_B00000_S02962_W000255
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.1502, "duration": 3.039, "id": "EN_B00000_S02962_W000255", "language": "en", "speaker": "EN_B00000_S02962", "text": " Increases by a factor of 48.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000255.mp3" }
EN_B00000_S02962_W000255.mp3
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EN_B00000_S02962_W000256
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4283, "duration": 9.423, "id": "EN_B00000_S02962_W000256", "language": "en", "speaker": "EN_B00000_S02962", "text": " And the new force is going to be 48 times greater than that. So 200 times 48 gives us the new force of 9600 newtons.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962...
EN_B00000_S02962_W000256.mp3
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EN_B00000_S02962_W000257
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3788, "duration": 4.907, "id": "EN_B00000_S02962_W000257", "language": "en", "speaker": "EN_B00000_S02962", "text": " So that's how you can answer questions that basically look like this.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000257.mp3" }
EN_B00000_S02962_W000257.mp3
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EN_B00000_S02962_W000258
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3216, "duration": 3.09, "id": "EN_B00000_S02962_W000258", "language": "en", "speaker": "EN_B00000_S02962", "text": " So the electric force is proportional", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000258.mp3" }
EN_B00000_S02962_W000258.mp3
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EN_B00000_S02962_W000259
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2664, "duration": 6.35, "id": "EN_B00000_S02962_W000259", "language": "en", "speaker": "EN_B00000_S02962", "text": " This variable is proportional to everything on top, but it's inversely related to whatever is on the bottom.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000259....
EN_B00000_S02962_W000259.mp3
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EN_B00000_S02962_W000260
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4149, "duration": 5.02, "id": "EN_B00000_S02962_W000260", "language": "en", "speaker": "EN_B00000_S02962", "text": " As the magnitude of the charges increase, the electric force will increase proportionally.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000260.mp3" }
EN_B00000_S02962_W000260.mp3
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EN_B00000_S02962_W000261
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4153, "duration": 21.297, "id": "EN_B00000_S02962_W000261", "language": "en", "speaker": "EN_B00000_S02962", "text": " As the distance between the two charges increase, the electric force between them will decrease significantly. So, if you double the charges, or rather, if you double one of t...
EN_B00000_S02962_W000261.mp3
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EN_B00000_S02962_W000262
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3422, "duration": 14.448, "id": "EN_B00000_S02962_W000262", "language": "en", "speaker": "EN_B00000_S02962", "text": " Because it's squared, 2 squared is 4, the force will be reduced by a factor of 4. So it's going to be 1 fourth of its original value. If you triple the distance, 3 squared is ...
EN_B00000_S02962_W000262.mp3
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EN_B00000_S02962_W000263
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4463, "duration": 18.947, "id": "EN_B00000_S02962_W000263", "language": "en", "speaker": "EN_B00000_S02962", "text": " So A, the unit of capacitance is deferred. So that is a true statement. That's just something you need to note. B, capacitance is a measure of how much charge a capacitor can ...
EN_B00000_S02962_W000263.mp3
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EN_B00000_S02962_W000264
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3833, "duration": 6.468, "id": "EN_B00000_S02962_W000264", "language": "en", "speaker": "EN_B00000_S02962", "text": " It sounds true, and it turns out that it is. Q is equal to CV.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000264.mp3" }
EN_B00000_S02962_W000264.mp3
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EN_B00000_S02962_W000265
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3944, "duration": 14.177, "id": "EN_B00000_S02962_W000265", "language": "en", "speaker": "EN_B00000_S02962", "text": " Q represents the electrics, excuse me, the electrics charge stored by a capacitor. And Q is measured in the unit coulombs. C represents capacitance. And the unit for that is t...
EN_B00000_S02962_W000265.mp3
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EN_B00000_S02962_W000266
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2754, "duration": 3.022, "id": "EN_B00000_S02962_W000266", "language": "en", "speaker": "EN_B00000_S02962", "text": " And V is the voltage, the unit for that is the volt.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000266.mp3" }
EN_B00000_S02962_W000266.mp3
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EN_B00000_S02962_W000267
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3385, "duration": 13.549, "id": "EN_B00000_S02962_W000267", "language": "en", "speaker": "EN_B00000_S02962", "text": " So 1 coulomb of charge is equal to 1 farad times 1 volt. Now if we solve for capacitance, capacitance is basically charge divided by voltage. So 1 farad", "wav": "EN_B00000/...
EN_B00000_S02962_W000267.mp3
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EN_B00000_S02962_W000268
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.422, "duration": 8.829, "id": "EN_B00000_S02962_W000268", "language": "en", "speaker": "EN_B00000_S02962", "text": " A one-farad capacitor can store one coulomb of charge when one volt is attached to it. So B is a true statement.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000...
EN_B00000_S02962_W000268.mp3
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EN_B00000_S02962_W000269
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4322, "duration": 4.957, "id": "EN_B00000_S02962_W000269", "language": "en", "speaker": "EN_B00000_S02962", "text": " A 1 Farad capacitor tells us that 1 Coulomb of charge", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000269.mp3" }
EN_B00000_S02962_W000269.mp3
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EN_B00000_S02962_W000270
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3812, "duration": 3.361, "id": "EN_B00000_S02962_W000270", "language": "en", "speaker": "EN_B00000_S02962", "text": " Can be stored when it's charged by one volt.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000270.mp3" }
EN_B00000_S02962_W000270.mp3
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EN_B00000_S02962_W000271
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3746, "duration": 5.45, "id": "EN_B00000_S02962_W000271", "language": "en", "speaker": "EN_B00000_S02962", "text": " 8 coulombs of charge can be stored if we attach an 8 volt battery to it.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000271.mp3" }
EN_B00000_S02962_W000271.mp3
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EN_B00000_S02962_W000272
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2947, "duration": 3.463, "id": "EN_B00000_S02962_W000272", "language": "en", "speaker": "EN_B00000_S02962", "text": " So it tells us how much charge can be stored.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000272.mp3" }
EN_B00000_S02962_W000272.mp3
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EN_B00000_S02962_W000273
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2947, "duration": 4.839, "id": "EN_B00000_S02962_W000273", "language": "en", "speaker": "EN_B00000_S02962", "text": " When a certain voltage is applied to the capacitor So what about C?", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000273.mp3" }
EN_B00000_S02962_W000273.mp3
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EN_B00000_S02962_W000274
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2284, "duration": 3.412, "id": "EN_B00000_S02962_W000274", "language": "en", "speaker": "EN_B00000_S02962", "text": " A 5 farad capacitor can store 40 coulombs of charge.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000274.mp3" }
EN_B00000_S02962_W000274.mp3
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EN_B00000_S02962_W000275
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3561, "duration": 3.701, "id": "EN_B00000_S02962_W000275", "language": "en", "speaker": "EN_B00000_S02962", "text": " When it's connected to an 8 volt battery. Is that true or false?", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000275.mp3" }
EN_B00000_S02962_W000275.mp3
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EN_B00000_S02962_W000276
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.373, "duration": 3.158, "id": "EN_B00000_S02962_W000276", "language": "en", "speaker": "EN_B00000_S02962", "text": " When the capacitor is attached to an 8 volt battery.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000276.mp3" }
EN_B00000_S02962_W000276.mp3
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EN_B00000_S02962_W000277
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2031, "duration": 6.639, "id": "EN_B00000_S02962_W000277", "language": "en", "speaker": "EN_B00000_S02962", "text": " So this gives us a capacitance of 5, because 40 divided by 8 is 5. And so C is the true statement.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000277.mp3" }
EN_B00000_S02962_W000277.mp3
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EN_B00000_S02962_W000278
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4188, "duration": 14.041, "id": "EN_B00000_S02962_W000278", "language": "en", "speaker": "EN_B00000_S02962", "text": " Let's say if we increase the voltage to 16 volts, that 5-Farad capacitor can now hold twice the amount of charge. So for a given capacitor, if we increase the voltage applied ...
EN_B00000_S02962_W000278.mp3
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EN_B00000_S02962_W000279
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3529, "duration": 19.728, "id": "EN_B00000_S02962_W000279", "language": "en", "speaker": "EN_B00000_S02962", "text": " We can increase the charge stored on that capacitor. Now let's move on to part D. The capacitance of a parallel play capacitor is directly proportional to the separation dista...
EN_B00000_S02962_W000279.mp3
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EN_B00000_S02962_W000280
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.268, "duration": 7.793, "id": "EN_B00000_S02962_W000280", "language": "en", "speaker": "EN_B00000_S02962", "text": " Because the one that we have doesn't have the separation distance. So here is a parallel plate capacitor.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000280.mp3...
EN_B00000_S02962_W000280.mp3
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EN_B00000_S02962_W000281
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3642, "duration": 6.451, "id": "EN_B00000_S02962_W000281", "language": "en", "speaker": "EN_B00000_S02962", "text": " It's basically two metal plates, separate by distance, and attached to a battery.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000281.mp3" }
EN_B00000_S02962_W000281.mp3
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EN_B00000_S02962_W000282
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4038, "duration": 18.913, "id": "EN_B00000_S02962_W000282", "language": "en", "speaker": "EN_B00000_S02962", "text": " A is the area of the capacitor, and D is the separation distance. The capacitance depends on the dielectric material k between the two plates. If it's air, k is 1, and then it...
EN_B00000_S02962_W000282.mp3
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EN_B00000_S02962_W000283
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3821, "duration": 4.89, "id": "EN_B00000_S02962_W000283", "language": "en", "speaker": "EN_B00000_S02962", "text": " The permittivity of free space times the area divided by the separation distance.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000283.mp3" }
EN_B00000_S02962_W000283.mp3
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EN_B00000_S02962_W000284
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3478, "duration": 17.911, "id": "EN_B00000_S02962_W000284", "language": "en", "speaker": "EN_B00000_S02962", "text": " So notice the separation distance is in the bottom of this equation. That means that it's not proportional to the capacitance, but it's inversely related to it. So if we incre...
EN_B00000_S02962_W000284.mp3
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EN_B00000_S02962_W000285
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3334, "duration": 8.166, "id": "EN_B00000_S02962_W000285", "language": "en", "speaker": "EN_B00000_S02962", "text": " Capacitance is not directly proportional to the separation distance. It's inversely proportional to it. So D is the answer we're looking for.", "wav": "EN_B00000/EN_B00000_S0...
EN_B00000_S02962_W000285.mp3
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EN_B00000_S02962_W000286
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2214, "duration": 3.362, "id": "EN_B00000_S02962_W000286", "language": "en", "speaker": "EN_B00000_S02962", "text": " Now the area of the plates is proportional to it.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000286.mp3" }
EN_B00000_S02962_W000286.mp3
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EN_B00000_S02962_W000287
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3874, "duration": 7.388, "id": "EN_B00000_S02962_W000287", "language": "en", "speaker": "EN_B00000_S02962", "text": " If we increase the area of the plates of a parallel, of a parallel plate capacitor. Wow, my voice, my voice is just like.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S...
EN_B00000_S02962_W000287.mp3
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EN_B00000_S02962_W000288
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4026, "duration": 23.195, "id": "EN_B00000_S02962_W000288", "language": "en", "speaker": "EN_B00000_S02962", "text": " Messed up today, but if we increase the area of those plates, the capacitance will increase proportionally, which means if we double the area, the capacitance will double. If ...
EN_B00000_S02962_W000288.mp3
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EN_B00000_S02962_W000289
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3333, "duration": 14.855, "id": "EN_B00000_S02962_W000289", "language": "en", "speaker": "EN_B00000_S02962", "text": " So the strength of the electric field created by a point charge is inversely related to the square of the distance. So we have this formula, e is equal to kq over r squared.",...
EN_B00000_S02962_W000289.mp3
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EN_B00000_S02962_W000290
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2975, "duration": 3.514, "id": "EN_B00000_S02962_W000290", "language": "en", "speaker": "EN_B00000_S02962", "text": " Notice that r squared is on the bottom, so it's inversely related.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B00000_S02962_W000290.mp3" }
EN_B00000_S02962_W000290.mp3
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EN_B00000_S02962_W000291
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.2683, "duration": 8.047, "id": "EN_B00000_S02962_W000291", "language": "en", "speaker": "EN_B00000_S02962", "text": " And it's squared, so it's inversely related to the square of the distance. So based on the formula, we can see why that's true.", "wav": "EN_B00000/EN_B00000_S02962/mp3/EN_B0...
EN_B00000_S02962_W000291.mp3
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EN_B00000_S02962_W000292
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.4055, "duration": 22.225, "id": "EN_B00000_S02962_W000292", "language": "en", "speaker": "EN_B00000_S02962", "text": " So as you move away from a point charge, as you increase the distance, the electric field will decrease. So if you double the distance, the electric field will be reduced by a...
EN_B00000_S02962_W000292.mp3
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EN_B00000_S02972_W000000
hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar
{ "dnsmos": 3.3733, "duration": 19.356, "id": "EN_B00000_S02972_W000000", "language": "en", "speaker": "EN_B00000_S02972", "text": " Hey everybody, I have a super quick video on arithmetic expressions. An arithmetic expression is a combination of operands and operators. Operands are values, variables, etc. ...
EN_B00000_S02972_W000000.mp3
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