task
stringclasses
5 values
input
stringlengths
89
339
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [1*]C(=O)CC[8*] Fragment 2: [16*]c1ccc(F)c(F)c1 ### Response: O=C(CCc1ccc(F)c(F)c1)NCCc1ccccn1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [1*]C(=O)C(CC)CC Fragment 2: [5*]Nc1cccc2ccccc12 ### Response: CCC(CC)C(=O)Nc1cccc2ccccc12
canonicalization
### Instruction: Canonicalize the following SMILES string. COC(=O)c1cc2nc(n(c(c2cc1)=O)CCCN1C(CCC1)=O)[S-] ### Response: COC(=O)c1ccc2c(=O)n(CCCN3CCCC3=O)c([S-])nc2c1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COC(=O)[C@@H](C)[C@H](C)[NH2+]CC1CCCCC1 ### Response: 4
canonicalization
### Instruction: Canonicalize the following SMILES string. [NH+](C)(C)Cc1c(cccc1)NC(c1ccc(cc1)-n1c(ccc1C)C)=O ### Response: Cc1ccc(C)n1-c1ccc(C(=O)Nc2ccccc2C[NH+](C)C)cc1
canonicalization
### Instruction: Canonicalize the following SMILES string. C(=O)([O-])c1cc(ccc1)/N=C1\S/C(=C/c2ccco2)C(N1CC=C)=O ### Response: C=CCN1C(=O)/C(=C\c2ccco2)S/C1=N\c1cccc(C(=O)[O-])c1
functional_group
### Instruction: Does the molecule contain a ether group? COC(=O)C1=C(C)N(C)C(C)=C(C(=O)OC)C1c1ccc(Cl)cc1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. C1(CCN(C(=O)c2ccco2)CC1)CNC(c1cnc2n(c1=O)ccs2)=O ### Response: O=C(NCC1CCN(C(=O)c2ccco2)CC1)c1cnc2sccn2c1=O
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CCN(CC)C(=O)[C@H]1CCC[NH+]1Cc1nc2c(s1)C[C@H](C)CC2 ### Response: 2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1cnn(CC[NH2+]Cc2nnc(C3CC3)o2)c1 ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. [C@@H]1(CC(N(C)C1)=O)c1n(c2c(n1)cccc2)CCCOc1cccc2ccccc12 ### Response: CN1C[C@@H](c2nc3ccccc3n2CCCOc2cccc3ccccc23)CC1=O
functional_group
### Instruction: Does the molecule contain a ether group? CCc1csc([C@@H]2CCCN(C(=O)c3ccn(C)c(=O)c3)C2)n1 ### Response: No
functional_group
### Instruction: Does the molecule contain a amine group? CCN[C@@]1(C#N)CC[C@@H](OC(C)(C)C)C1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. C1CCCN1c1cc(cc[nH+]1)CNC(=O)N1CCC(c2nc(C)no2)CC1 ### Response: Cc1noc(C2CCN(C(=O)NCc3cc[nH+]c(N4CCCC4)c3)CC2)n1
canonicalization
### Instruction: Canonicalize the following SMILES string. C(NC1(CC([O-])=O)CCC1)(=O)c1c([N+]([O-])=O)cccc1 ### Response: O=C([O-])CC1(NC(=O)c2ccccc2[N+](=O)[O-])CCC1
functional_group
### Instruction: Does the molecule contain a ether group? CCOc1cc2c(cc1CNC(=O)CCc1ccc(F)cc1)O[C@@H](C)C2 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(NC(=O)C(=O)NCCC(F)(F)F)ccccc1C(=O)NC(C)(C)C ### Response: CC(C)(C)NC(=O)c1ccccc1NC(=O)C(=O)NCCC(F)(F)F
functional_group
### Instruction: Does the molecule contain a phenol group? COC(=O)c1ccc(CNc2nc(C)c(-c3ccn(-c4ccc5c(c4)OCO5)n3)s2)cc1 ### Response: No
canonicalization
### Instruction: Canonicalize the following SMILES string. C1(=O)N(C[C@H](C(N(c2scc(n2)-c2ccc(S(=O)(C)=O)cc2)CC=C)=O)C1)C1CCCC1 ### Response: C=CCN(C(=O)[C@@H]1CC(=O)N(C2CCCC2)C1)c1nc(-c2ccc(S(C)(=O)=O)cc2)cs1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1ccc(-c2ncnc(N)n2)cc1 ### Response: 0
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [8*]Cc1ccc(O)cc1 Fragment 2: [5*][NH2+]C1CC1 ### Response: Oc1ccc(Cn2ccc(C[NH2+]C3CC3)n2)cc1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]N1CCN([5*])CC1 Fragment 2: [1*]C(=O)N/N=C/c1ccc(Br)cc1 ### Response: O=C(N/N=C/c1ccc(Br)cc1)N1CCN(c2ccccc2)CC1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CN(Cc1ccccc1)C(=O)c1ccc2c(n1)NC(=O)CC2 ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. c12c3n(-c4cccc(c4)[N+](=O)[O-])nc(-c4ccccc4)c3cnc2ccc(F)c1 ### Response: O=[N+]([O-])c1cccc(-n2nc(-c3ccccc3)c3cnc4ccc(F)cc4c32)c1
functional_group
### Instruction: Does the molecule contain a hydroxyl group? COc1ccc(N)cc1-c1ccccc1 ### Response: No
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CSc1ccc(CNC(=O)N2CCC[C@H]2c2nncn2C)cc1C ### Response: 1
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? C[C@@H](Oc1ccc(C#N)cc1)C(=O)NC[C@H]1CN(Cc2ccccc2)CCO1 ### Response: Yes
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [14*]c1cccs1 Fragment 2: [9*]n1nnnc1[14*] ### Response: CC(C)C[C@@H](c1nnnn1Cc1cccs1)N1CCN(c2ccccc2)CC1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1ccc(S(=O)(=O)N[C@@H](c2n[nH]c(C)n2)C(C)C)cc1 ### Response: 3
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [4*]Cc1cccc(OC)c1 Fragment 2: [5*]NS(=O)(=O)N([5*])C ### Response: COc1cccc(CN(C)S(=O)(=O)N[C@H](C)c2ccccc2C)c1
canonicalization
### Instruction: Canonicalize the following SMILES string. Cc1cc(C)cc(C)c1/C=N/NC(C(Nc1ccc(C([O-])=O)cc1)=O)=O ### Response: Cc1cc(C)c(/C=N/NC(=O)C(=O)Nc2ccc(C(=O)[O-])cc2)c(C)c1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CCC[NH2+][C@@H](c1cscc1C)c1cc(C)cnc1N ### Response: 1
functional_group
### Instruction: Does the molecule contain a amide group? Cc1ccc(C(=O)NCC(=O)N2CCCC[C@@H]2CCOC(C)C)cc1C ### Response: Yes
ring_counting
### Instruction: Count the six-membered rings in the following molecule. N#C/C(=C\c1ccc(N2CCOCC2)cc1)[C@@H]1[NH+]=c2cc(Br)cnc2=[NH+]1 ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. O=C(N[C@@H](C)c1ccc(-n2ccnc2C)cc1)NCc1cnc(cc1)Cl ### Response: Cc1nccn1-c1ccc([C@H](C)NC(=O)NCc2ccc(Cl)nc2)cc1
canonicalization
### Instruction: Canonicalize the following SMILES string. n1(CCc2noc(n2)[C@@H]2CCCO2)c(ncc1)-c1nc2CCCCc2s1 ### Response: c1cn(CCc2noc([C@@H]3CCCO3)n2)c(-c2nc3c(s2)CCCC3)n1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CCc1cc(=O)oc2c(C)c(OCC(=O)N(CCC#N)c3ccccc3)ccc12 ### Response: 0
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CCOC(=O)[C@@](C)(NC(=O)c1cnn2cc(Br)cnc12)C(C)C ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1sc2nc(C[NH+]3CCN(C[C@@H](C#N)CCC#N)CC3)[nH]c(=O)c2c1C ### Response: 5
functional_group
### Instruction: Does the molecule contain a hydroxyl group? Cc1nn2c(C)c(C(=O)NCc3ccccc3F)cnc2c1-c1ccc(F)cc1 ### Response: No
functional_group
### Instruction: Does the molecule contain a thiol group? CC[NH2+][C@H]1CC[C@H](OCC2CCCCC2)C1 ### Response: No
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [1*]C(=O)[C@@H]([4*])C(C)C Fragment 2: [1*]C(=O)N1c2ccccc2N=C(O)[C@@H]1[13*] ### Response: CC(C)[C@H](NC(=O)N1c2ccccc2N=C(O)[C@@H]1C(C)C)C(=O)N1CCC(C(=O)[O-])CC1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CC[C@@H](Nc1ncc(C)c(-c2cnn(C)c2)n1)[C@@H]1[NH+]=c2ccc(C)cc2=[NH+]1 ### Response: 3
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1nn(C)c(=O)c(C(=O)NCC2CCCCCCC2)c1C ### Response: 1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1ccc(NC(=O)N2CCC[C@H](CO)C2)cc1Cl ### Response: 0
functional_group
### Instruction: Does the molecule contain a hydroxyl group? CCc1nnc(NC(=O)[C@H]2CC(=O)N(c3ccc(F)cc3)C2)s1 ### Response: No
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(ccc(c(c1)S(=O)(=O)N1C[C@@H](C)O[C@H](C)C1)Cl)C(=O)/N=c1\n(C)ccs1 ### Response: C[C@@H]1CN(S(=O)(=O)c2cc(C(=O)/N=c3/sccn3C)ccc2Cl)C[C@@H](C)O1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? O=C(CSc1nc2ccccc2o1)OCc1cc(-c2cccs2)on1 ### Response: 2
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]Nc1ccc(N[5*])cc1 Fragment 2: [1*]C(=O)c1ccc2c(c1)[nH]c(=O)n2C ### Response: Cn1c(=O)[nH]c2cc(C(=O)Nc3ccc(NC(=O)OC(C)(C)C)cc3)ccc21
canonicalization
### Instruction: Canonicalize the following SMILES string. C(=O)(NCC1CC1)[C@@H]1CN(CCC1)C(=O)[C@@H]1CN(CC[NH+](C)C)C(=O)C1 ### Response: C[NH+](C)CCN1C[C@@H](C(=O)N2CCC[C@H](C(=O)NCC3CC3)C2)CC1=O
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]N(C)C[8*] Fragment 2: [9*]n1cccc1 ### Response: CC[C@H](C(=O)N(C)Cc1ccc(C)o1)n1cccc1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1ccc(/C=C(/C)C[NH2+]C2CCC(Oc3ccc(C#N)cn3)CC2)cc1 ### Response: 3
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? Cc1ccc(Br)c(NCc2nc(C)cs2)c1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a amine group? CCn1nc(C)c(CNC(=O)[C@H]2[NH+]=c3ccccc3=C2NC(=O)c2cccc(C)c2)c1C ### Response: Yes
ring_counting
### Instruction: Count the five-membered rings in the following molecule. COC(=O)Cn1cc(/C=C2/C(=O)N(c3cccc(F)c3)C(=O)N=C2[O-])c2ccccc21 ### Response: 1
functional_group
### Instruction: Does the molecule contain a nitrile group? Cc1csc(/N=C2/S/C(=C\c3cccc(Cl)c3)C(=O)N2C)n1 ### Response: No
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1cccc2c1N[C@@H](c1cccc([N+](=O)[O-])c1)[C@H]1CC=C[C@H]21 ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. n1(c(nnn1)SCc1ccccc1Cl)-c1ccc(cc1)C ### Response: Cc1ccc(-n2nnnc2SCc2ccccc2Cl)cc1
canonicalization
### Instruction: Canonicalize the following SMILES string. C1CCc2c(sc(NC(=O)c3cc4[nH]c(c(n(c4cc3)CC)=O)=O)n2)CC1 ### Response: CCn1c(=O)c(=O)[nH]c2cc(C(=O)Nc3nc4c(s3)CCCCC4)ccc21
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]N([5*])Cc1ccco1 Fragment 2: [16*]c1ccc(C)c([N+](=O)[O-])c1 ### Response: Cc1ccc(NC(=O)N(Cc2ccco2)C[C@H]2CCCO2)cc1[N+](=O)[O-]
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CSCC(=O)NC1CCCC1 ### Response: 2
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC(C)n1cnnc1C[NH2+][C@@H]1C[C@H]2CC[C@]1(C)C2(C)C ### Response: 0
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1cc(/C=C/C(=O)c2cc3cccc(OC)c3o2)cc2c1OCCO2 ### Response: 3
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1ccc2c(c1)N(C(=O)[C@@H](C)OCC1CC1)CCO2 ### Response: 3
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COC(=O)c1cc(C(=O)N[C@H](C)c2ccc(F)c(Cl)c2)ccn1 ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. C1C(C)(OCC[C@]1(Cc1nc(cs1)-c1ccccc1)O)C ### Response: CC1(C)C[C@](O)(Cc2nc(-c3ccccc3)cs2)CCO1
canonicalization
### Instruction: Canonicalize the following SMILES string. n1c(ccc(O)c1C[NH+]1CCC[C@H](COCC)C1)C ### Response: CCOC[C@H]1CCC[NH+](Cc2nc(C)ccc2O)C1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1noc(C)c1S(=O)(=O)N1CCC(C(=O)NNC(=O)c2ccc(Cl)cc2)CC1 ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CC[C@H]1C[C@H](C)CC[C@@H]1[NH2+][C@@H]1CCN(c2cc(C)nn2C)C1=O ### Response: 2
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CC1=c2ccccc2=[NH+]C(=O)[C@H]1Cl ### Response: 0
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CCc1nn(C)cc1CNC(=O)NCC(C)(C)Cc1ccccc1 ### Response: 1
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? C/C=C/CC[NH2+][C@@H]1CCc2ccc(F)cc21 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. C(N[C@H](C(N)=O)C(C)(C)C)c1c(Br)c(c(OC)cc1)OC ### Response: COc1ccc(CN[C@H](C(N)=O)C(C)(C)C)c(Br)c1OC
ring_counting
### Instruction: Count the six-membered rings in the following molecule. COc1cc(CC[NH2+][C@H](C)c2ccc(N3CCCCC3)cc2)ccc1O ### Response: 3
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]Nc1cc(F)ccc1C Fragment 2: [1*]C(=O)c1cccc(S([12*])(=O)=O)c1 ### Response: Cc1ccc(F)cc1NC(=O)c1cccc(S(=O)(=O)N2C[C@@H](C)C[C@H](C)C2)c1
functional_group
### Instruction: Does the molecule contain a sulfonyl group? C[C@@H](CS(=O)(=O)[C@@H]1CCC[C@H](S(C)(=O)=O)C1)C(=O)[O-] ### Response: Yes
ring_counting
### Instruction: Count the five-membered rings in the following molecule. COc1ccc(CC[C@H](C)NC(=O)N2C[C@H](C)C[C@@H](C)C2)cc1 ### Response: 0
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [4*]CCCO Fragment 2: [5*]N([5*])c1nc(Cl)ncc1F ### Response: CC(C)N(CCCO)c1nc(Cl)ncc1F
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CCCNC(=O)N1C[C@@H](c2ccc(OC)cc2)[C@@H]2[C@H]1C1CC[NH+]2CC1 ### Response: 1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CC(C)[C@@H](C)N(CC(F)(F)F)C(=O)c1cn(CC(=O)N(C)C)nn1 ### Response: 1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1cccc(C)c1N(CC(=O)N/N=C/c1cc(C)n(-c2cccc(Cl)c2)c1C)S(C)(=O)=O ### Response: 2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? O=C(CCCS(=O)(=O)c1ccc(F)cc1)Nc1nnc(-c2cc3ccccc3o2)o1 ### Response: 4
canonicalization
### Instruction: Canonicalize the following SMILES string. C1(CC(C)C)C[C@](O)(N(C(=O)c2ccc(F)cc2)N=1)C(F)(F)F ### Response: CC(C)CC1=NN(C(=O)c2ccc(F)cc2)[C@](O)(C(F)(F)F)C1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cn1cc(C#N)cc1C(=O)Nc1ccccc1N1CCCCCC1 ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. N(C(=O)c1ncoc1-c1ccc(C)cc1)(C[C@H](O)COC)C ### Response: COC[C@@H](O)CN(C)C(=O)c1ncoc1-c1ccc(C)cc1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(CN(C(C)C)CC(N)=S)cc(Br)cc(c1)F ### Response: CC(C)N(CC(N)=S)Cc1cc(F)cc(Br)c1
canonicalization
### Instruction: Canonicalize the following SMILES string. C1CN(C[C@@H](C(Nc2cccc(C(F)(F)F)c2)=O)C1)C([C@H]1N=NC(=C1)c1ncccc1)=O ### Response: O=C(Nc1cccc(C(F)(F)F)c1)[C@H]1CCCN(C(=O)[C@@H]2C=C(c3ccccn3)N=N2)C1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]Nc1cc[nH+]cc1[O-] Fragment 2: [1*]C(=O)[C@@H]1CCO[C@@H]1C ### Response: C[C@H]1OCC[C@H]1C(=O)Nc1cc[nH+]cc1[O-]
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC[C@H]1CC[NH+](Cc2cc(Cl)c(OCC(N)=O)c(OC)c2)C1 ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. S(CC)c1c(C([C@H](c2ccccn2)C#N)=O)cc(cc1)Cl ### Response: CCSc1ccc(Cl)cc1C(=O)[C@@H](C#N)c1ccccn1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [3*]Oc1ccc(C[4*])cc1 Fragment 2: [5*][NH+]1CCC([15*])CC1 ### Response: C#CCOc1ccc(C[NH+]2CCC(NC(=O)Nc3ccc(F)cc3)CC2)cc1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CC(C)CN1CCO[C@@H](CNC(=O)c2ccc[nH]c2=O)C1 ### Response: 3
ring_counting
### Instruction: Count the six-membered rings in the following molecule. C[C@@H]1CC([NH2+]CC2CCN(c3cc[nH+]cc3)CC2)C[C@@H](C)C1 ### Response: 3
functional_group
### Instruction: Does the molecule contain a hydroxyl group? c1ccc(-n2nnnc2NC[C@@H]2CCOC2)cc1 ### Response: No
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1cccc(NC(=O)[C@@H]2CCCN(S(=O)(=O)c3c[nH]c(C(=O)N4CCCC4)c3)C2)n1 ### Response: 2
ring_counting
### Instruction: Count the six-membered rings in the following molecule. N#Cc1ccc(CN2CCC[NH+](Cc3nnc(-c4ccco4)o3)CC2)cc1 ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. O[C@@H]1[C@@H](c2c3oc(ccc3ccc2OC1(C)C)=O)OC(/C(C)=C\C)=O ### Response: C/C=C(/C)C(=O)O[C@@H]1c2c(ccc3ccc(=O)oc23)OC(C)(C)[C@@H]1O
canonicalization
### Instruction: Canonicalize the following SMILES string. c1c([C@H]2NC(=[NH+]c3c2cc(Cl)cc3)N2CCCC2)cccc1 ### Response: Clc1ccc2c(c1)[C@@H](c1ccccc1)NC(N1CCCC1)=[NH+]2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CC[C@@](C)(NC(=O)CSCc1cccs1)C(=O)[O-] ### Response: 4
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CCc1n[nH]c(SCc2ccc(OCC(C)C)cc2)n1 ### Response: 3