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2,601 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 3.2243e-26 kg, speed 9.7816e+05 m/s | A free particle of mass 3.2243e-26 kg moving at speed 9.7816e+05 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.1009e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,602 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 4.8836e-26 kg, speed 6.9089e+06 m/s | A free particle of mass 4.8836e-26 kg moving at speed 6.9089e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.9638e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,603 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.0592e-26 kg, speed 4.9678e+06 m/s | A free particle of mass 2.0592e-26 kg moving at speed 4.9678e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 6.4774e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,604 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.1146e-26 kg, speed 6.6742e+06 m/s | A free particle of mass 8.1146e-26 kg moving at speed 6.6742e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.2235e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,605 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 1.6664e-26 kg, speed 2.9959e+06 m/s | A free particle of mass 1.6664e-26 kg moving at speed 2.9959e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.3273e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,606 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.6943e-26 kg, speed 2.0184e+06 m/s | A free particle of mass 9.6943e-26 kg moving at speed 2.0184e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 3.3864e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,607 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 6.3545e-26 kg, speed 9.7411e+06 m/s | A free particle of mass 6.3545e-26 kg moving at speed 9.7411e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.0705e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,608 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 7.5330e-27 kg, speed 8.5035e+06 m/s | A free particle of mass 7.5330e-27 kg moving at speed 8.5035e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.0344e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,609 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.1409e-26 kg, speed 2.6523e+06 m/s | A free particle of mass 2.1409e-26 kg moving at speed 2.6523e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.1669e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,610 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.9733e-26 kg, speed 5.7356e+06 m/s | A free particle of mass 2.9733e-26 kg moving at speed 5.7356e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 3.8854e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,611 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.0460e-26 kg, speed 6.2461e+06 m/s | A free particle of mass 8.0460e-26 kg moving at speed 6.2461e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.3185e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,612 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.5794e-26 kg, speed 7.1774e+06 m/s | A free particle of mass 9.5794e-26 kg moving at speed 7.1774e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 9.6372e-16 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
2,613 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 9.564 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 9.564 g therefore contains n = m / M = 9.564 / 159.6 = 0.05992 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,614 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 27.41 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 27.41 g therefore contains n = m / M = 27.41 / 17.03 = 1.609 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,615 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 80.14 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 80.14 g therefore contains n = m / M = 80.14 / 159.6 = 0.5021 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,616 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 42.77 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 42.77 g therefore contains n = m / M = 42.77 / 100.1 = 0.4273 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,617 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 79.59 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 79.59 g therefore contains n = m / M = 79.59 / 17.03 = 4.673 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,618 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 50.51 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 50.51 g therefore contains n = m / M = 50.51 / 98.07 = 0.5151 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,619 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 43.35 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 43.35 g therefore contains n = m / M = 43.35 / 98.07 = 0.442 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,620 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 31.4 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 31.4 g therefore contains n = m / M = 31.4 / 159.7 = 0.1967 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,621 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 40.29 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 40.29 g therefore contains n = m / M = 40.29 / 16.04 = 2.511 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,622 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 51.59 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 51.59 g therefore contains n = m / M = 51.59 / 159.6 = 0.3232 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,623 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 18.14 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 18.14 g therefore contains n = m / M = 18.14 / 159.7 = 0.1136 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,624 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 62.82 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 62.82 g therefore contains n = m / M = 62.82 / 18.02 = 3.487 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,625 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 86.28 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 86.28 g therefore contains n = m / M = 86.28 / 159.7 = 0.5403 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,626 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 49.97 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 49.97 g therefore contains n = m / M = 49.97 / 159.6 = 0.3131 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,627 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 26.87 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 26.87 g therefore contains n = m / M = 26.87 / 100.1 = 0.2684 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,628 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 80.91 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 80.91 g therefore contains n = m / M = 80.91 / 159.7 = 0.5067 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,629 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 93.47 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 93.47 g therefore contains n = m / M = 93.47 / 16.04 = 5.826 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,630 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 52.27 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 52.27 g therefore contains n = m / M = 52.27 / 18.02 = 2.902 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,631 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 46.3 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 46.3 g therefore contains n = m / M = 46.3 / 17.03 = 2.719 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,632 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 15.13 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 15.13 g therefore contains n = m / M = 15.13 / 180.2 = 0.084 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,633 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 84.43 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 84.43 g therefore contains n = m / M = 84.43 / 98.07 = 0.8609 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,634 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 31.93 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 31.93 g therefore contains n = m / M = 31.93 / 16.04 = 1.99 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,635 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 63.43 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 63.43 g therefore contains n = m / M = 63.43 / 44.01 = 1.441 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,636 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 26.77 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 26.77 g therefore contains n = m / M = 26.77 / 16.04 = 1.668 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,637 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 64.64 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 64.64 g therefore contains n = m / M = 64.64 / 98.07 = 0.6591 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,638 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 68.72 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 68.72 g therefore contains n = m / M = 68.72 / 98.07 = 0.7007 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,639 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 40.65 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 40.65 g therefore contains n = m / M = 40.65 / 180.2 = 0.2256 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,640 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 15.08 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 15.08 g therefore contains n = m / M = 15.08 / 44.01 = 0.3427 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,641 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 24.63 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 24.63 g therefore contains n = m / M = 24.63 / 18.02 = 1.367 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,642 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 46.47 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 46.47 g therefore contains n = m / M = 46.47 / 98.07 = 0.4738 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,643 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 99.13 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 99.13 g therefore contains n = m / M = 99.13 / 159.7 = 0.6208 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,644 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 64.73 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 64.73 g therefore contains n = m / M = 64.73 / 16.04 = 4.035 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,645 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 20.28 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 20.28 g therefore contains n = m / M = 20.28 / 18.02 = 1.126 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,646 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 13.73 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 13.73 g therefore contains n = m / M = 13.73 / 98.07 = 0.14 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,647 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 78.99 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 78.99 g therefore contains n = m / M = 78.99 / 98.07 = 0.8054 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,648 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 65.9 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 65.9 g therefore contains n = m / M = 65.9 / 98.07 = 0.672 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,649 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 64.46 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 64.46 g therefore contains n = m / M = 64.46 / 58.44 = 1.103 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,650 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 96.38 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 96.38 g therefore contains n = m / M = 96.38 / 18.02 = 5.35 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,651 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 78.25 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 78.25 g therefore contains n = m / M = 78.25 / 100.1 = 0.7818 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,652 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 85.97 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 85.97 g therefore contains n = m / M = 85.97 / 18.02 = 4.772 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,653 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 31.46 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 31.46 g therefore contains n = m / M = 31.46 / 44.01 = 0.7148 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,654 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 86.73 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 86.73 g therefore contains n = m / M = 86.73 / 98.07 = 0.8844 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,655 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 89.69 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 89.69 g therefore contains n = m / M = 89.69 / 16.04 = 5.59 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,656 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 39.75 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 39.75 g therefore contains n = m / M = 39.75 / 44.01 = 0.9032 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,657 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 23.68 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 23.68 g therefore contains n = m / M = 23.68 / 58.44 = 0.4052 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,658 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 73.47 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 73.47 g therefore contains n = m / M = 73.47 / 159.6 = 0.4604 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,659 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 52.24 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 52.24 g therefore contains n = m / M = 52.24 / 44.01 = 1.187 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,660 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 94.97 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 94.97 g therefore contains n = m / M = 94.97 / 159.6 = 0.5951 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,661 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 25.26 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 25.26 g therefore contains n = m / M = 25.26 / 159.7 = 0.1582 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,662 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 23.88 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 23.88 g therefore contains n = m / M = 23.88 / 44.01 = 0.5427 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,663 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 77.34 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 77.34 g therefore contains n = m / M = 77.34 / 44.01 = 1.757 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,664 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 33 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 33 g therefore contains n = m / M = 33 / 17.03 = 1.937 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,665 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 73.75 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 73.75 g therefore contains n = m / M = 73.75 / 159.6 = 0.4621 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,666 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 93.56 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 93.56 g therefore contains n = m / M = 93.56 / 180.2 = 0.5193 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,667 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 14.51 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 14.51 g therefore contains n = m / M = 14.51 / 180.2 = 0.08056 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,668 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 21.49 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 21.49 g therefore contains n = m / M = 21.49 / 58.44 = 0.3677 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,669 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 44 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 44 g therefore contains n = m / M = 44 / 98.07 = 0.4487 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,670 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 86.3 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 86.3 g therefore contains n = m / M = 86.3 / 98.07 = 0.88 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,671 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 49.09 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 49.09 g therefore contains n = m / M = 49.09 / 18.02 = 2.725 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,672 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 69.99 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 69.99 g therefore contains n = m / M = 69.99 / 17.03 = 4.11 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,673 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 31.72 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 31.72 g therefore contains n = m / M = 31.72 / 44.01 = 0.7207 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,674 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 47.54 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 47.54 g therefore contains n = m / M = 47.54 / 16.04 = 2.963 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,675 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 96.34 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 96.34 g therefore contains n = m / M = 96.34 / 180.2 = 0.5347 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,676 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 36.36 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 36.36 g therefore contains n = m / M = 36.36 / 58.44 = 0.6222 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,677 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 82.15 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 82.15 g therefore contains n = m / M = 82.15 / 17.03 = 4.824 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,678 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 64.58 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 64.58 g therefore contains n = m / M = 64.58 / 18.02 = 3.585 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,679 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 3.577 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 3.577 g therefore contains n = m / M = 3.577 / 159.6 = 0.02241 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,680 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 69.1 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 69.1 g therefore contains n = m / M = 69.1 / 18.02 = 3.836 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,681 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 25.37 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 25.37 g therefore contains n = m / M = 25.37 / 180.2 = 0.1408 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,682 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 31 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 31 g therefore contains n = m / M = 31 / 16.04 = 1.932 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,683 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 90.33 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 90.33 g therefore contains n = m / M = 90.33 / 17.03 = 5.304 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,684 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 53.54 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 53.54 g therefore contains n = m / M = 53.54 / 44.01 = 1.217 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,685 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 85.78 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 85.78 g therefore contains n = m / M = 85.78 / 180.2 = 0.4761 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,686 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 0.8858 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 0.8858 g therefore contains n = m / M = 0.8858 / 16.04 = 0.05522 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,687 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 92.76 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 92.76 g therefore contains n = m / M = 92.76 / 16.04 = 5.782 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,688 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 30.16 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 30.16 g therefore contains n = m / M = 30.16 / 98.07 = 0.3075 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,689 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 29.81 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 29.81 g therefore contains n = m / M = 29.81 / 180.2 = 0.1655 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,690 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 91.6 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 91.6 g therefore contains n = m / M = 91.6 / 58.44 = 1.567 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,691 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 87.96 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 87.96 g therefore contains n = m / M = 87.96 / 17.03 = 5.165 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,692 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 78.95 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 78.95 g therefore contains n = m / M = 78.95 / 16.04 = 4.921 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,693 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 86.66 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 86.66 g therefore contains n = m / M = 86.66 / 98.07 = 0.8836 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,694 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 47.16 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 47.16 g therefore contains n = m / M = 47.16 / 100.1 = 0.4712 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,695 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 92.66 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 92.66 g therefore contains n = m / M = 92.66 / 16.04 = 5.776 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,696 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 71.77 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 71.77 g therefore contains n = m / M = 71.77 / 17.03 = 4.214 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,697 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 82.46 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 82.46 g therefore contains n = m / M = 82.46 / 44.01 = 1.874 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,698 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 50.68 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 50.68 g therefore contains n = m / M = 50.68 / 98.07 = 0.5168 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,699 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 42.14 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 42.14 g therefore contains n = m / M = 42.14 / 17.03 = 2.475 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
2,700 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 73.8 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 73.8 g therefore contains n = m / M = 73.8 / 159.7 = 0.4622 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
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