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2,801 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.847 mol, V=31.72 L, T=274.5 K | For an ideal gas, P V = n R T. With n = 1.847 mol, V = 31.72 L, T = 274.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.312 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,802 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.4738 mol, V=48.68 L, T=405.3 K | For an ideal gas, P V = n R T. With n = 0.4738 mol, V = 48.68 L, T = 405.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.3238 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,803 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.385 mol, V=35.82 L, T=459 K | For an ideal gas, P V = n R T. With n = 3.385 mol, V = 35.82 L, T = 459 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.56 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,804 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.654 mol, V=32.54 L, T=410.9 K | For an ideal gas, P V = n R T. With n = 4.654 mol, V = 32.54 L, T = 410.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.823 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,805 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.429 mol, V=4.42 L, T=387.3 K | For an ideal gas, P V = n R T. With n = 0.429 mol, V = 4.42 L, T = 387.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.085 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,806 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.01 mol, V=49.22 L, T=320.2 K | For an ideal gas, P V = n R T. With n = 4.01 mol, V = 49.22 L, T = 320.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.14 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,807 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.425 mol, V=12.81 L, T=320.2 K | For an ideal gas, P V = n R T. With n = 3.425 mol, V = 12.81 L, T = 320.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 7.025 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,808 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.144 mol, V=27.77 L, T=427.4 K | For an ideal gas, P V = n R T. With n = 2.144 mol, V = 27.77 L, T = 427.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.708 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,809 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.587 mol, V=25.78 L, T=405.4 K | For an ideal gas, P V = n R T. With n = 4.587 mol, V = 25.78 L, T = 405.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.92 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,810 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.071 mol, V=36.16 L, T=385.9 K | For an ideal gas, P V = n R T. With n = 2.071 mol, V = 36.16 L, T = 385.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.814 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,811 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.066 mol, V=29.49 L, T=342.2 K | For an ideal gas, P V = n R T. With n = 4.066 mol, V = 29.49 L, T = 342.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.872 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,812 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.846 mol, V=37.16 L, T=206.5 K | For an ideal gas, P V = n R T. With n = 3.846 mol, V = 37.16 L, T = 206.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.754 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,813 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.32 mol, V=42.22 L, T=514.5 K | For an ideal gas, P V = n R T. With n = 2.32 mol, V = 42.22 L, T = 514.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.319 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,814 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.2358 mol, V=35.37 L, T=366.5 K | For an ideal gas, P V = n R T. With n = 0.2358 mol, V = 35.37 L, T = 366.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.2005 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,815 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.577 mol, V=37.99 L, T=489.6 K | For an ideal gas, P V = n R T. With n = 1.577 mol, V = 37.99 L, T = 489.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.667 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,816 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.255 mol, V=17.4 L, T=523.1 K | For an ideal gas, P V = n R T. With n = 2.255 mol, V = 17.4 L, T = 523.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.565 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,817 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.591 mol, V=10.95 L, T=524 K | For an ideal gas, P V = n R T. With n = 4.591 mol, V = 10.95 L, T = 524 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 18.03 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,818 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.4003 mol, V=13.34 L, T=592.9 K | For an ideal gas, P V = n R T. With n = 0.4003 mol, V = 13.34 L, T = 592.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.46 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,819 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.37 mol, V=1.387 L, T=373.5 K | For an ideal gas, P V = n R T. With n = 3.37 mol, V = 1.387 L, T = 373.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 74.49 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,820 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.981 mol, V=32.96 L, T=205.3 K | For an ideal gas, P V = n R T. With n = 1.981 mol, V = 32.96 L, T = 205.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.012 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,821 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.306 mol, V=33.06 L, T=362 K | For an ideal gas, P V = n R T. With n = 2.306 mol, V = 33.06 L, T = 362 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.073 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,822 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.724 mol, V=15.49 L, T=490.4 K | For an ideal gas, P V = n R T. With n = 3.724 mol, V = 15.49 L, T = 490.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.674 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,823 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.068 mol, V=34.69 L, T=446.7 K | For an ideal gas, P V = n R T. With n = 4.068 mol, V = 34.69 L, T = 446.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.298 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,824 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.816 mol, V=40.33 L, T=470 K | For an ideal gas, P V = n R T. With n = 4.816 mol, V = 40.33 L, T = 470 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.606 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,825 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.4473 mol, V=9.945 L, T=254 K | For an ideal gas, P V = n R T. With n = 0.4473 mol, V = 9.945 L, T = 254 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.9376 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,826 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.082 mol, V=9.817 L, T=478.4 K | For an ideal gas, P V = n R T. With n = 4.082 mol, V = 9.817 L, T = 478.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 16.32 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,827 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.1438 mol, V=7.685 L, T=392.4 K | For an ideal gas, P V = n R T. With n = 0.1438 mol, V = 7.685 L, T = 392.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.6026 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,828 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.216 mol, V=42.98 L, T=536.8 K | For an ideal gas, P V = n R T. With n = 1.216 mol, V = 42.98 L, T = 536.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.247 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,829 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.698 mol, V=38.6 L, T=234.4 K | For an ideal gas, P V = n R T. With n = 2.698 mol, V = 38.6 L, T = 234.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.344 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,830 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.7493 mol, V=6.265 L, T=368.8 K | For an ideal gas, P V = n R T. With n = 0.7493 mol, V = 6.265 L, T = 368.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.619 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,831 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.513 mol, V=22.54 L, T=495.5 K | For an ideal gas, P V = n R T. With n = 4.513 mol, V = 22.54 L, T = 495.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 8.141 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,832 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.43 mol, V=22.75 L, T=207.9 K | For an ideal gas, P V = n R T. With n = 2.43 mol, V = 22.75 L, T = 207.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.822 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,833 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.221 mol, V=41.56 L, T=317.9 K | For an ideal gas, P V = n R T. With n = 1.221 mol, V = 41.56 L, T = 317.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.7663 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,834 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.965 mol, V=5.582 L, T=333.5 K | For an ideal gas, P V = n R T. With n = 1.965 mol, V = 5.582 L, T = 333.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.634 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,835 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.24 mol, V=21.08 L, T=372.7 K | For an ideal gas, P V = n R T. With n = 4.24 mol, V = 21.08 L, T = 372.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.152 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,836 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.484 mol, V=36.69 L, T=431.5 K | For an ideal gas, P V = n R T. With n = 2.484 mol, V = 36.69 L, T = 431.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.397 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,837 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.995 mol, V=20.28 L, T=214.8 K | For an ideal gas, P V = n R T. With n = 4.995 mol, V = 20.28 L, T = 214.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.341 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,838 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.572 mol, V=46.8 L, T=489.8 K | For an ideal gas, P V = n R T. With n = 2.572 mol, V = 46.8 L, T = 489.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.209 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,839 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.526 mol, V=11.98 L, T=547.1 K | For an ideal gas, P V = n R T. With n = 4.526 mol, V = 11.98 L, T = 547.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 16.96 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,840 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.3129 mol, V=29.03 L, T=207.6 K | For an ideal gas, P V = n R T. With n = 0.3129 mol, V = 29.03 L, T = 207.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.1836 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,841 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.771 mol, V=32.59 L, T=307.1 K | For an ideal gas, P V = n R T. With n = 2.771 mol, V = 32.59 L, T = 307.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.143 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,842 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.447 mol, V=31.32 L, T=246.8 K | For an ideal gas, P V = n R T. With n = 4.447 mol, V = 31.32 L, T = 246.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.875 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,843 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.234 mol, V=22.09 L, T=379.3 K | For an ideal gas, P V = n R T. With n = 3.234 mol, V = 22.09 L, T = 379.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.557 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,844 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.8151 mol, V=23.73 L, T=490.5 K | For an ideal gas, P V = n R T. With n = 0.8151 mol, V = 23.73 L, T = 490.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.383 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,845 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.196 mol, V=29.59 L, T=403.1 K | For an ideal gas, P V = n R T. With n = 2.196 mol, V = 29.59 L, T = 403.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.455 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,846 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.428 mol, V=42.75 L, T=568.7 K | For an ideal gas, P V = n R T. With n = 3.428 mol, V = 42.75 L, T = 568.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.742 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,847 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.579 mol, V=44.22 L, T=387.4 K | For an ideal gas, P V = n R T. With n = 3.579 mol, V = 44.22 L, T = 387.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.573 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,848 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.618 mol, V=21.13 L, T=356.1 K | For an ideal gas, P V = n R T. With n = 3.618 mol, V = 21.13 L, T = 356.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.003 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,849 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.707 mol, V=18.33 L, T=461 K | For an ideal gas, P V = n R T. With n = 4.707 mol, V = 18.33 L, T = 461 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.712 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,850 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.367 mol, V=8.52 L, T=588.4 K | For an ideal gas, P V = n R T. With n = 2.367 mol, V = 8.52 L, T = 588.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 13.41 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,851 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.044 mol, V=4.766 L, T=476.3 K | For an ideal gas, P V = n R T. With n = 1.044 mol, V = 4.766 L, T = 476.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 8.56 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,852 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.42 mol, V=8.238 L, T=269.3 K | For an ideal gas, P V = n R T. With n = 2.42 mol, V = 8.238 L, T = 269.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.491 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,853 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.466 mol, V=47.18 L, T=517.4 K | For an ideal gas, P V = n R T. With n = 2.466 mol, V = 47.18 L, T = 517.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.219 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,854 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.474 mol, V=28.06 L, T=293.9 K | For an ideal gas, P V = n R T. With n = 2.474 mol, V = 28.06 L, T = 293.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.126 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,855 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.996 mol, V=13.41 L, T=343.5 K | For an ideal gas, P V = n R T. With n = 4.996 mol, V = 13.41 L, T = 343.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 10.5 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,856 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.388 mol, V=43.04 L, T=269.9 K | For an ideal gas, P V = n R T. With n = 3.388 mol, V = 43.04 L, T = 269.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.743 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,857 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.522 mol, V=17.22 L, T=522.7 K | For an ideal gas, P V = n R T. With n = 2.522 mol, V = 17.22 L, T = 522.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.284 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,858 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.5787 mol, V=28.32 L, T=290.7 K | For an ideal gas, P V = n R T. With n = 0.5787 mol, V = 28.32 L, T = 290.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.4874 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,859 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.437 mol, V=39.35 L, T=597.5 K | For an ideal gas, P V = n R T. With n = 2.437 mol, V = 39.35 L, T = 597.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.036 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,860 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.849 mol, V=28.07 L, T=508 K | For an ideal gas, P V = n R T. With n = 3.849 mol, V = 28.07 L, T = 508 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.716 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,861 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.483 mol, V=43.75 L, T=541.4 K | For an ideal gas, P V = n R T. With n = 4.483 mol, V = 43.75 L, T = 541.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.552 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,862 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.025 mol, V=2.996 L, T=241.7 K | For an ideal gas, P V = n R T. With n = 3.025 mol, V = 2.996 L, T = 241.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 20.03 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
2,863 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.06899 M | A strong monoprotic acid is fully dissociated. At concentration 0.06899 mol/L, [H⁺] = 0.06899 M and pH = −log₁₀[H⁺] = 1.161. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,864 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02494 M | A strong monoprotic acid is fully dissociated. At concentration 0.02494 mol/L, [H⁺] = 0.02494 M and pH = −log₁₀[H⁺] = 1.603. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,865 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.07726 M | A strong monoprotic acid is fully dissociated. At concentration 0.07726 mol/L, [H⁺] = 0.07726 M and pH = −log₁₀[H⁺] = 1.112. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,866 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01851 M | A strong monoprotic acid is fully dissociated. At concentration 0.01851 mol/L, [H⁺] = 0.01851 M and pH = −log₁₀[H⁺] = 1.733. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,867 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.08394 M | A strong monoprotic acid is fully dissociated. At concentration 0.08394 mol/L, [H⁺] = 0.08394 M and pH = −log₁₀[H⁺] = 1.076. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,868 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02213 M | A strong monoprotic acid is fully dissociated. At concentration 0.02213 mol/L, [H⁺] = 0.02213 M and pH = −log₁₀[H⁺] = 1.655. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,869 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.006745 M | A strong monoprotic acid is fully dissociated. At concentration 0.006745 mol/L, [H⁺] = 0.006745 M and pH = −log₁₀[H⁺] = 2.171. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,870 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0376 M | A strong monoprotic acid is fully dissociated. At concentration 0.0376 mol/L, [H⁺] = 0.0376 M and pH = −log₁₀[H⁺] = 1.425. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,871 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.0212e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.0212e-04 mol/L, [H⁺] = 2.0212e-04 M and pH = −log₁₀[H⁺] = 3.694. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,872 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.004869 M | A strong monoprotic acid is fully dissociated. At concentration 0.004869 mol/L, [H⁺] = 0.004869 M and pH = −log₁₀[H⁺] = 2.313. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,873 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.003326 M | A strong monoprotic acid is fully dissociated. At concentration 0.003326 mol/L, [H⁺] = 0.003326 M and pH = −log₁₀[H⁺] = 2.478. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,874 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.1706e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.1706e-04 mol/L, [H⁺] = 3.1706e-04 M and pH = −log₁₀[H⁺] = 3.499. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,875 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.2604e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.2604e-04 mol/L, [H⁺] = 2.2604e-04 M and pH = −log₁₀[H⁺] = 3.646. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,876 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 4.1320e-04 M | A strong monoprotic acid is fully dissociated. At concentration 4.1320e-04 mol/L, [H⁺] = 4.1320e-04 M and pH = −log₁₀[H⁺] = 3.384. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,877 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001216 M | A strong monoprotic acid is fully dissociated. At concentration 0.001216 mol/L, [H⁺] = 0.001216 M and pH = −log₁₀[H⁺] = 2.915. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,878 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01531 M | A strong monoprotic acid is fully dissociated. At concentration 0.01531 mol/L, [H⁺] = 0.01531 M and pH = −log₁₀[H⁺] = 1.815. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,879 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01332 M | A strong monoprotic acid is fully dissociated. At concentration 0.01332 mol/L, [H⁺] = 0.01332 M and pH = −log₁₀[H⁺] = 1.876. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,880 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01931 M | A strong monoprotic acid is fully dissociated. At concentration 0.01931 mol/L, [H⁺] = 0.01931 M and pH = −log₁₀[H⁺] = 1.714. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,881 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.003127 M | A strong monoprotic acid is fully dissociated. At concentration 0.003127 mol/L, [H⁺] = 0.003127 M and pH = −log₁₀[H⁺] = 2.505. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,882 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.04088 M | A strong monoprotic acid is fully dissociated. At concentration 0.04088 mol/L, [H⁺] = 0.04088 M and pH = −log₁₀[H⁺] = 1.389. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,883 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.9033e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.9033e-04 mol/L, [H⁺] = 2.9033e-04 M and pH = −log₁₀[H⁺] = 3.537. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,884 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001234 M | A strong monoprotic acid is fully dissociated. At concentration 0.001234 mol/L, [H⁺] = 0.001234 M and pH = −log₁₀[H⁺] = 2.909. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,885 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02867 M | A strong monoprotic acid is fully dissociated. At concentration 0.02867 mol/L, [H⁺] = 0.02867 M and pH = −log₁₀[H⁺] = 1.543. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,886 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.3386e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.3386e-04 mol/L, [H⁺] = 2.3386e-04 M and pH = −log₁₀[H⁺] = 3.631. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,887 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 4.0334e-04 M | A strong monoprotic acid is fully dissociated. At concentration 4.0334e-04 mol/L, [H⁺] = 4.0334e-04 M and pH = −log₁₀[H⁺] = 3.394. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,888 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.08108 M | A strong monoprotic acid is fully dissociated. At concentration 0.08108 mol/L, [H⁺] = 0.08108 M and pH = −log₁₀[H⁺] = 1.091. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,889 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02031 M | A strong monoprotic acid is fully dissociated. At concentration 0.02031 mol/L, [H⁺] = 0.02031 M and pH = −log₁₀[H⁺] = 1.692. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,890 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.0466e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.0466e-04 mol/L, [H⁺] = 1.0466e-04 M and pH = −log₁₀[H⁺] = 3.98. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,891 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.03195 M | A strong monoprotic acid is fully dissociated. At concentration 0.03195 mol/L, [H⁺] = 0.03195 M and pH = −log₁₀[H⁺] = 1.496. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,892 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002636 M | A strong monoprotic acid is fully dissociated. At concentration 0.002636 mol/L, [H⁺] = 0.002636 M and pH = −log₁₀[H⁺] = 2.579. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,893 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 7.2489e-04 M | A strong monoprotic acid is fully dissociated. At concentration 7.2489e-04 mol/L, [H⁺] = 7.2489e-04 M and pH = −log₁₀[H⁺] = 3.14. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,894 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.2643e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.2643e-04 mol/L, [H⁺] = 3.2643e-04 M and pH = −log₁₀[H⁺] = 3.486. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,895 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.2813e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.2813e-04 mol/L, [H⁺] = 6.2813e-04 M and pH = −log₁₀[H⁺] = 3.202. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,896 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01398 M | A strong monoprotic acid is fully dissociated. At concentration 0.01398 mol/L, [H⁺] = 0.01398 M and pH = −log₁₀[H⁺] = 1.854. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,897 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001758 M | A strong monoprotic acid is fully dissociated. At concentration 0.001758 mol/L, [H⁺] = 0.001758 M and pH = −log₁₀[H⁺] = 2.755. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,898 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.007733 M | A strong monoprotic acid is fully dissociated. At concentration 0.007733 mol/L, [H⁺] = 0.007733 M and pH = −log₁₀[H⁺] = 2.112. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,899 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 5.4495e-04 M | A strong monoprotic acid is fully dissociated. At concentration 5.4495e-04 mol/L, [H⁺] = 5.4495e-04 M and pH = −log₁₀[H⁺] = 3.264. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
2,900 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01818 M | A strong monoprotic acid is fully dissociated. At concentration 0.01818 mol/L, [H⁺] = 0.01818 M and pH = −log₁₀[H⁺] = 1.74. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
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