id int64 1 14M | domain stringclasses 6
values | topic stringclasses 23
values | subtopic stringclasses 37
values | difficulty int64 1 8 | unit_type stringclasses 3
values | title stringlengths 14 86 | content stringlengths 203 553 | key_equations stringclasses 23
values | prerequisites stringclasses 29
values | learning_objective stringclasses 37
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4,301 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 4.4620e-27 kg, speed 9.3032e+06 m/s | A free particle of mass 4.4620e-27 kg moving at speed 9.3032e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.5962e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,302 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.1187e-26 kg, speed 2.5633e+05 m/s | A free particle of mass 9.1187e-26 kg moving at speed 2.5633e+05 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.8348e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,303 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 6.0904e-26 kg, speed 8.0805e+06 m/s | A free particle of mass 6.0904e-26 kg moving at speed 8.0805e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.3464e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,304 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 5.1080e-26 kg, speed 7.8090e+06 m/s | A free particle of mass 5.1080e-26 kg moving at speed 7.8090e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.6612e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,305 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 5.0819e-26 kg, speed 5.8153e+06 m/s | A free particle of mass 5.0819e-26 kg moving at speed 5.8153e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.2421e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,306 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 3.4406e-26 kg, speed 2.1495e+06 m/s | A free particle of mass 3.4406e-26 kg moving at speed 2.1495e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 8.9596e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,307 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.3073e-26 kg, speed 3.2696e+05 m/s | A free particle of mass 8.3073e-26 kg moving at speed 3.2696e+05 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.4395e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,308 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 7.2626e-26 kg, speed 3.8115e+06 m/s | A free particle of mass 7.2626e-26 kg moving at speed 3.8115e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.3937e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,309 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.9782e-26 kg, speed 7.8537e+05 m/s | A free particle of mass 9.9782e-26 kg moving at speed 7.8537e+05 m/s has de Broglie wavelength λ = h / p = h / (m v) = 8.4553e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,310 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 7.7321e-27 kg, speed 9.3552e+06 m/s | A free particle of mass 7.7321e-27 kg moving at speed 9.3552e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 9.1602e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,311 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.2459e-26 kg, speed 5.0355e+06 m/s | A free particle of mass 2.2459e-26 kg moving at speed 5.0355e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 5.8591e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,312 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 5.7444e-26 kg, speed 5.4828e+06 m/s | A free particle of mass 5.7444e-26 kg moving at speed 5.4828e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.1038e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,313 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 4.1809e-26 kg, speed 7.3307e+06 m/s | A free particle of mass 4.1809e-26 kg moving at speed 7.3307e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.1619e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,314 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.4760e-26 kg, speed 5.2780e+06 m/s | A free particle of mass 8.4760e-26 kg moving at speed 5.2780e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.4811e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,315 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 5.1441e-27 kg, speed 4.7238e+06 m/s | A free particle of mass 5.1441e-27 kg moving at speed 4.7238e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.7268e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,316 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 5.2445e-26 kg, speed 4.4107e+06 m/s | A free particle of mass 5.2445e-26 kg moving at speed 4.4107e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.8644e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,317 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.6919e-26 kg, speed 8.3603e+06 m/s | A free particle of mass 2.6919e-26 kg moving at speed 8.3603e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.9443e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,318 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.9307e-26 kg, speed 2.4410e+06 m/s | A free particle of mass 2.9307e-26 kg moving at speed 2.4410e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 9.2620e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,319 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.4308e-26 kg, speed 7.6767e+06 m/s | A free particle of mass 2.4308e-26 kg moving at speed 7.6767e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 3.5509e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,320 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 3.6197e-26 kg, speed 4.5588e+06 m/s | A free particle of mass 3.6197e-26 kg moving at speed 4.5588e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 4.0155e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,321 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 7.4819e-26 kg, speed 1.1551e+06 m/s | A free particle of mass 7.4819e-26 kg moving at speed 1.1551e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 7.6673e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,322 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.4105e-26 kg, speed 7.3283e+06 m/s | A free particle of mass 2.4105e-26 kg moving at speed 7.3283e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 3.7509e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,323 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.8023e-26 kg, speed 3.6194e+06 m/s | A free particle of mass 8.8023e-26 kg moving at speed 3.6194e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.0798e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,324 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 3.5199e-26 kg, speed 5.0569e+06 m/s | A free particle of mass 3.5199e-26 kg moving at speed 5.0569e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 3.7225e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,325 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.1464e-26 kg, speed 6.5336e+06 m/s | A free particle of mass 9.1464e-26 kg moving at speed 6.5336e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.1088e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,326 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 6.0522e-26 kg, speed 4.4902e+06 m/s | A free particle of mass 6.0522e-26 kg moving at speed 4.4902e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.4382e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,327 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 4.1886e-26 kg, speed 5.6939e+06 m/s | A free particle of mass 4.1886e-26 kg moving at speed 5.6939e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.7783e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,328 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.2679e-26 kg, speed 1.2537e+06 m/s | A free particle of mass 8.2679e-26 kg moving at speed 1.2537e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 6.3925e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,329 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 5.3762e-26 kg, speed 7.7647e+06 m/s | A free particle of mass 5.3762e-26 kg moving at speed 7.7647e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.5873e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,330 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 4.0762e-26 kg, speed 5.8480e+06 m/s | A free particle of mass 4.0762e-26 kg moving at speed 5.8480e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.7797e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,331 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 1.3815e-26 kg, speed 2.6035e+06 m/s | A free particle of mass 1.3815e-26 kg moving at speed 2.6035e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.8422e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,332 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.8689e-26 kg, speed 3.1391e+06 m/s | A free particle of mass 2.8689e-26 kg moving at speed 3.1391e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 7.3575e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,333 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.1515e-27 kg, speed 4.2108e+06 m/s | A free particle of mass 8.1515e-27 kg moving at speed 4.2108e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.9304e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,334 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.8325e-26 kg, speed 5.7605e+06 m/s | A free particle of mass 9.8325e-26 kg moving at speed 5.7605e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.1698e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,335 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 6.3263e-26 kg, speed 7.7267e+06 m/s | A free particle of mass 6.3263e-26 kg moving at speed 7.7267e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.3555e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,336 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.9987e-26 kg, speed 8.7642e+06 m/s | A free particle of mass 8.9987e-26 kg moving at speed 8.7642e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 8.4016e-16 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,337 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 1.5522e-27 kg, speed 1.2088e+06 m/s | A free particle of mass 1.5522e-27 kg moving at speed 1.2088e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 3.5315e-13 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,338 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 2.6338e-26 kg, speed 5.5462e+06 m/s | A free particle of mass 2.6338e-26 kg moving at speed 5.5462e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 4.5360e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,339 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.3013e-26 kg, speed 7.4288e+06 m/s | A free particle of mass 9.3013e-26 kg moving at speed 7.4288e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 9.5895e-16 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,340 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 1.2641e-26 kg, speed 3.4172e+05 m/s | A free particle of mass 1.2641e-26 kg moving at speed 3.4172e+05 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.5340e-13 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,341 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 4.3143e-26 kg, speed 6.9008e+06 m/s | A free particle of mass 4.3143e-26 kg moving at speed 6.9008e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.2256e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,342 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.8993e-26 kg, speed 1.3246e+06 m/s | A free particle of mass 9.8993e-26 kg moving at speed 1.3246e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 5.0530e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,343 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.6688e-26 kg, speed 9.1863e+06 m/s | A free particle of mass 8.6688e-26 kg moving at speed 9.1863e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 8.3206e-16 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,344 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.0426e-26 kg, speed 3.5443e+06 m/s | A free particle of mass 9.0426e-26 kg moving at speed 3.5443e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.0674e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,345 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 4.0232e-26 kg, speed 5.5699e+06 m/s | A free particle of mass 4.0232e-26 kg moving at speed 5.5699e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 2.9569e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,346 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 7.1199e-26 kg, speed 1.1912e+06 m/s | A free particle of mass 7.1199e-26 kg moving at speed 1.1912e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 7.8128e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,347 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 8.9743e-26 kg, speed 8.9836e+06 m/s | A free particle of mass 8.9743e-26 kg moving at speed 8.9836e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 8.2187e-16 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,348 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 5.9148e-26 kg, speed 6.1667e+06 m/s | A free particle of mass 5.9148e-26 kg moving at speed 6.1667e+06 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.8166e-15 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,349 | physics | quantum | de_broglie | 7 | worked_example | de Broglie wavelength of particle mass 9.9413e-26 kg, speed 4.5333e+05 m/s | A free particle of mass 9.9413e-26 kg moving at speed 4.5333e+05 m/s has de Broglie wavelength λ = h / p = h / (m v) = 1.4703e-14 m, where h is Planck's constant. This relation underlies the wave-particle duality of matter and is confirmed by electron diffraction experiments. | λ = h / p | wave_speed; classical momentum | Compute the de Broglie wavelength of a massive particle. |
4,350 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 95 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 95 g therefore contains n = m / M = 95 / 17.03 = 5.578 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,351 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 63.12 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 63.12 g therefore contains n = m / M = 63.12 / 16.04 = 3.934 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,352 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 29 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 29 g therefore contains n = m / M = 29 / 16.04 = 1.808 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,353 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 70.04 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 70.04 g therefore contains n = m / M = 70.04 / 100.1 = 0.6998 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,354 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 72.4 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 72.4 g therefore contains n = m / M = 72.4 / 58.44 = 1.239 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,355 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 91.64 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 91.64 g therefore contains n = m / M = 91.64 / 159.6 = 0.5742 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,356 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 8.471 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 8.471 g therefore contains n = m / M = 8.471 / 159.7 = 0.05304 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,357 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 59.4 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 59.4 g therefore contains n = m / M = 59.4 / 18.02 = 3.297 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,358 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 67.42 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 67.42 g therefore contains n = m / M = 67.42 / 17.03 = 3.959 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,359 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 38 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 38 g therefore contains n = m / M = 38 / 100.1 = 0.3797 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,360 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 17.75 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 17.75 g therefore contains n = m / M = 17.75 / 100.1 = 0.1774 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,361 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 28 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 28 g therefore contains n = m / M = 28 / 159.6 = 0.1754 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,362 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 23.3 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 23.3 g therefore contains n = m / M = 23.3 / 44.01 = 0.5295 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,363 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 34.18 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 34.18 g therefore contains n = m / M = 34.18 / 100.1 = 0.3415 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,364 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 51.82 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 51.82 g therefore contains n = m / M = 51.82 / 159.6 = 0.3247 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,365 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 58.02 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 58.02 g therefore contains n = m / M = 58.02 / 159.7 = 0.3634 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,366 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 28.6 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 28.6 g therefore contains n = m / M = 28.6 / 16.04 = 1.783 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,367 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 31.93 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 31.93 g therefore contains n = m / M = 31.93 / 16.04 = 1.99 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,368 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 95.36 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 95.36 g therefore contains n = m / M = 95.36 / 58.44 = 1.632 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,369 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 81.42 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 81.42 g therefore contains n = m / M = 81.42 / 18.02 = 4.519 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,370 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 43.11 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 43.11 g therefore contains n = m / M = 43.11 / 180.2 = 0.2393 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,371 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 57.56 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 57.56 g therefore contains n = m / M = 57.56 / 98.07 = 0.5869 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,372 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 31.51 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 31.51 g therefore contains n = m / M = 31.51 / 159.6 = 0.1974 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,373 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 28.55 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 28.55 g therefore contains n = m / M = 28.55 / 17.03 = 1.676 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,374 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 28.86 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 28.86 g therefore contains n = m / M = 28.86 / 44.01 = 0.6557 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,375 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 43.95 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 43.95 g therefore contains n = m / M = 43.95 / 100.1 = 0.4391 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,376 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 28.92 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 28.92 g therefore contains n = m / M = 28.92 / 58.44 = 0.4949 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,377 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 98.88 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 98.88 g therefore contains n = m / M = 98.88 / 98.07 = 1.008 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,378 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 92.46 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 92.46 g therefore contains n = m / M = 92.46 / 44.01 = 2.101 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,379 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 14.19 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 14.19 g therefore contains n = m / M = 14.19 / 98.07 = 0.1447 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,380 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 55.26 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 55.26 g therefore contains n = m / M = 55.26 / 180.2 = 0.3067 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,381 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 75.51 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 75.51 g therefore contains n = m / M = 75.51 / 159.7 = 0.4729 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,382 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 59.88 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 59.88 g therefore contains n = m / M = 59.88 / 18.02 = 3.324 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,383 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 95.99 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 95.99 g therefore contains n = m / M = 95.99 / 18.02 = 5.328 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,384 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 53.84 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 53.84 g therefore contains n = m / M = 53.84 / 159.7 = 0.3371 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,385 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 0.7658 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 0.7658 g therefore contains n = m / M = 0.7658 / 180.2 = 0.004251 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,386 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 37.02 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 37.02 g therefore contains n = m / M = 37.02 / 18.02 = 2.055 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,387 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 94.19 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 94.19 g therefore contains n = m / M = 94.19 / 98.07 = 0.9604 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,388 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 42.71 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 42.71 g therefore contains n = m / M = 42.71 / 159.6 = 0.2676 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,389 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 52.14 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 52.14 g therefore contains n = m / M = 52.14 / 100.1 = 0.5209 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,390 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 29.56 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 29.56 g therefore contains n = m / M = 29.56 / 100.1 = 0.2954 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,391 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 71.65 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 71.65 g therefore contains n = m / M = 71.65 / 44.01 = 1.628 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,392 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 44.5 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 44.5 g therefore contains n = m / M = 44.5 / 44.01 = 1.011 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,393 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 49.38 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 49.38 g therefore contains n = m / M = 49.38 / 16.04 = 3.078 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,394 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 86.46 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 86.46 g therefore contains n = m / M = 86.46 / 44.01 = 1.965 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,395 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 73.19 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 73.19 g therefore contains n = m / M = 73.19 / 98.07 = 0.7463 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,396 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 96.85 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 96.85 g therefore contains n = m / M = 96.85 / 44.01 = 2.201 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,397 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 74.45 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 74.45 g therefore contains n = m / M = 74.45 / 44.01 = 1.692 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,398 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 72.76 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 72.76 g therefore contains n = m / M = 72.76 / 180.2 = 0.4039 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,399 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 15.76 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 15.76 g therefore contains n = m / M = 15.76 / 17.03 = 0.9252 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,400 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 27.68 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 27.68 g therefore contains n = m / M = 27.68 / 17.03 = 1.625 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
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