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4,401 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 67.24 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 67.24 g therefore contains n = m / M = 67.24 / 159.7 = 0.4211 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,402 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 70.71 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 70.71 g therefore contains n = m / M = 70.71 / 44.01 = 1.607 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,403 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 89.24 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 89.24 g therefore contains n = m / M = 89.24 / 17.03 = 5.24 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,404 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 43.39 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 43.39 g therefore contains n = m / M = 43.39 / 18.02 = 2.409 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,405 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 31.82 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 31.82 g therefore contains n = m / M = 31.82 / 159.7 = 0.1993 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,406 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 66.15 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 66.15 g therefore contains n = m / M = 66.15 / 159.7 = 0.4142 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,407 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 94.92 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 94.92 g therefore contains n = m / M = 94.92 / 18.02 = 5.269 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,408 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 24.67 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 24.67 g therefore contains n = m / M = 24.67 / 18.02 = 1.369 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,409 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 37.68 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 37.68 g therefore contains n = m / M = 37.68 / 159.6 = 0.2361 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,410 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 67.37 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 67.37 g therefore contains n = m / M = 67.37 / 180.2 = 0.3739 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,411 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 47.06 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 47.06 g therefore contains n = m / M = 47.06 / 98.07 = 0.4799 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,412 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 81.41 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 81.41 g therefore contains n = m / M = 81.41 / 100.1 = 0.8134 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,413 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 28.33 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 28.33 g therefore contains n = m / M = 28.33 / 100.1 = 0.2831 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,414 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 63.51 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 63.51 g therefore contains n = m / M = 63.51 / 180.2 = 0.3525 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,415 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 95.09 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 95.09 g therefore contains n = m / M = 95.09 / 44.01 = 2.161 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,416 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 0.4195 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 0.4195 g therefore contains n = m / M = 0.4195 / 180.2 = 0.002328 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,417 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 49.12 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 49.12 g therefore contains n = m / M = 49.12 / 44.01 = 1.116 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,418 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 20.93 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 20.93 g therefore contains n = m / M = 20.93 / 159.6 = 0.1312 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,419 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 3.977 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 3.977 g therefore contains n = m / M = 3.977 / 58.44 = 0.06806 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,420 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 61.38 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 61.38 g therefore contains n = m / M = 61.38 / 98.07 = 0.6258 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,421 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 23.55 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 23.55 g therefore contains n = m / M = 23.55 / 159.6 = 0.1475 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,422 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 48.47 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 48.47 g therefore contains n = m / M = 48.47 / 17.03 = 2.846 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,423 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 87.8 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 87.8 g therefore contains n = m / M = 87.8 / 58.44 = 1.502 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,424 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 87.52 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 87.52 g therefore contains n = m / M = 87.52 / 180.2 = 0.4858 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,425 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 49.07 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 49.07 g therefore contains n = m / M = 49.07 / 100.1 = 0.4903 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,426 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 59.82 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 59.82 g therefore contains n = m / M = 59.82 / 16.04 = 3.729 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,427 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 48.15 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 48.15 g therefore contains n = m / M = 48.15 / 159.7 = 0.3015 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,428 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 21.97 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 21.97 g therefore contains n = m / M = 21.97 / 44.01 = 0.4992 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,429 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 42.02 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 42.02 g therefore contains n = m / M = 42.02 / 98.07 = 0.4284 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,430 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 32.61 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 32.61 g therefore contains n = m / M = 32.61 / 100.1 = 0.3258 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,431 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 11.67 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 11.67 g therefore contains n = m / M = 11.67 / 16.04 = 0.7274 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,432 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 95.64 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 95.64 g therefore contains n = m / M = 95.64 / 100.1 = 0.9555 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,433 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 34.82 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 34.82 g therefore contains n = m / M = 34.82 / 44.01 = 0.7913 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,434 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 70.51 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 70.51 g therefore contains n = m / M = 70.51 / 16.04 = 4.395 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,435 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 84.03 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 84.03 g therefore contains n = m / M = 84.03 / 100.1 = 0.8396 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,436 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 60.15 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 60.15 g therefore contains n = m / M = 60.15 / 100.1 = 0.6009 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,437 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 2.993 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 2.993 g therefore contains n = m / M = 2.993 / 180.2 = 0.01662 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,438 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 50.8 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 50.8 g therefore contains n = m / M = 50.8 / 98.07 = 0.518 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,439 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 6.174 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 6.174 g therefore contains n = m / M = 6.174 / 16.04 = 0.3849 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,440 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 26.23 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 26.23 g therefore contains n = m / M = 26.23 / 17.03 = 1.54 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,441 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 41.18 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 41.18 g therefore contains n = m / M = 41.18 / 17.03 = 2.418 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,442 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 42.58 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 42.58 g therefore contains n = m / M = 42.58 / 100.1 = 0.4254 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,443 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 91.25 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 91.25 g therefore contains n = m / M = 91.25 / 98.07 = 0.9304 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,444 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 48.6 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 48.6 g therefore contains n = m / M = 48.6 / 98.07 = 0.4956 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,445 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 34.05 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 34.05 g therefore contains n = m / M = 34.05 / 180.2 = 0.189 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,446 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 30.92 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 30.92 g therefore contains n = m / M = 30.92 / 18.02 = 1.716 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,447 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 22.21 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 22.21 g therefore contains n = m / M = 22.21 / 16.04 = 1.384 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,448 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 53.65 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 53.65 g therefore contains n = m / M = 53.65 / 58.44 = 0.918 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,449 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 94.79 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 94.79 g therefore contains n = m / M = 94.79 / 44.01 = 2.154 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,450 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 61.11 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 61.11 g therefore contains n = m / M = 61.11 / 159.6 = 0.3829 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,451 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 60.54 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 60.54 g therefore contains n = m / M = 60.54 / 58.44 = 1.036 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,452 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 95.03 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 95.03 g therefore contains n = m / M = 95.03 / 18.02 = 5.275 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,453 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 80.26 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 80.26 g therefore contains n = m / M = 80.26 / 18.02 = 4.455 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,454 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 78.07 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 78.07 g therefore contains n = m / M = 78.07 / 44.01 = 1.774 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,455 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 91.23 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 91.23 g therefore contains n = m / M = 91.23 / 17.03 = 5.357 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,456 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 6.44 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 6.44 g therefore contains n = m / M = 6.44 / 159.7 = 0.04033 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,457 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 51.91 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 51.91 g therefore contains n = m / M = 51.91 / 18.02 = 2.882 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,458 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 53.59 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 53.59 g therefore contains n = m / M = 53.59 / 17.03 = 3.147 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,459 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 83.83 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 83.83 g therefore contains n = m / M = 83.83 / 58.44 = 1.434 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,460 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 85.99 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 85.99 g therefore contains n = m / M = 85.99 / 16.04 = 5.36 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,461 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 29.09 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 29.09 g therefore contains n = m / M = 29.09 / 180.2 = 0.1615 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,462 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 91.07 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 91.07 g therefore contains n = m / M = 91.07 / 58.44 = 1.558 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,463 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 41.4 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 41.4 g therefore contains n = m / M = 41.4 / 17.03 = 2.431 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,464 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 73.36 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 73.36 g therefore contains n = m / M = 73.36 / 159.7 = 0.4594 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,465 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 3.704 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 3.704 g therefore contains n = m / M = 3.704 / 18.02 = 0.2056 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,466 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 75.54 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 75.54 g therefore contains n = m / M = 75.54 / 18.02 = 4.193 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,467 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 10.34 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 10.34 g therefore contains n = m / M = 10.34 / 159.7 = 0.06476 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,468 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 79.16 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 79.16 g therefore contains n = m / M = 79.16 / 16.04 = 4.934 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,469 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 15.78 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 15.78 g therefore contains n = m / M = 15.78 / 18.02 = 0.8759 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,470 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 2.522 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 2.522 g therefore contains n = m / M = 2.522 / 98.07 = 0.02572 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,471 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 3.474 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 3.474 g therefore contains n = m / M = 3.474 / 180.2 = 0.01929 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,472 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 81.32 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 81.32 g therefore contains n = m / M = 81.32 / 44.01 = 1.848 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,473 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 65.56 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 65.56 g therefore contains n = m / M = 65.56 / 16.04 = 4.087 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,474 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 81.85 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 81.85 g therefore contains n = m / M = 81.85 / 58.44 = 1.401 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,475 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 86.21 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 86.21 g therefore contains n = m / M = 86.21 / 98.07 = 0.8791 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,476 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 7.482 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 7.482 g therefore contains n = m / M = 7.482 / 44.01 = 0.17 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,477 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 2.113 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 2.113 g therefore contains n = m / M = 2.113 / 16.04 = 0.1317 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,478 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 60.53 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 60.53 g therefore contains n = m / M = 60.53 / 159.7 = 0.379 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,479 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 9.646 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 9.646 g therefore contains n = m / M = 9.646 / 58.44 = 0.1651 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,480 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 79.28 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 79.28 g therefore contains n = m / M = 79.28 / 159.6 = 0.4968 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,481 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 83.16 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 83.16 g therefore contains n = m / M = 83.16 / 180.2 = 0.4616 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,482 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 78.5 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 78.5 g therefore contains n = m / M = 78.5 / 98.07 = 0.8004 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,483 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 51.28 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 51.28 g therefore contains n = m / M = 51.28 / 16.04 = 3.197 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,484 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 30.29 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 30.29 g therefore contains n = m / M = 30.29 / 18.02 = 1.681 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,485 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 20.35 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 20.35 g therefore contains n = m / M = 20.35 / 100.1 = 0.2033 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,486 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 96.93 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 96.93 g therefore contains n = m / M = 96.93 / 98.07 = 0.9883 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,487 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 47.19 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 47.19 g therefore contains n = m / M = 47.19 / 159.6 = 0.2957 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,488 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 43.01 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 43.01 g therefore contains n = m / M = 43.01 / 98.07 = 0.4386 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,489 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 96.69 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 96.69 g therefore contains n = m / M = 96.69 / 180.2 = 0.5367 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,490 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 27.93 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 27.93 g therefore contains n = m / M = 27.93 / 159.7 = 0.1749 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,491 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 90.78 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 90.78 g therefore contains n = m / M = 90.78 / 98.07 = 0.9256 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,492 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 50.71 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 50.71 g therefore contains n = m / M = 50.71 / 159.7 = 0.3176 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,493 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 1.82 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 1.82 g therefore contains n = m / M = 1.82 / 16.04 = 0.1134 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,494 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 72.78 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 72.78 g therefore contains n = m / M = 72.78 / 100.1 = 0.7272 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,495 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 76.29 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 76.29 g therefore contains n = m / M = 76.29 / 17.03 = 4.48 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,496 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 45.28 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 45.28 g therefore contains n = m / M = 45.28 / 44.01 = 1.029 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,497 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 97.52 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 97.52 g therefore contains n = m / M = 97.52 / 159.6 = 0.611 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,498 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 77.14 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 77.14 g therefore contains n = m / M = 77.14 / 16.04 = 4.809 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,499 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 37.05 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 37.05 g therefore contains n = m / M = 37.05 / 100.1 = 0.3701 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
4,500 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.82 mol, V=16.96 L, T=457.1 K | For an ideal gas, P V = n R T. With n = 2.82 mol, V = 16.96 L, T = 457.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.239 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
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