id int64 1 3.58k | problem_description stringlengths 516 21.8k | instruction int64 0 3 | solution_c dict |
|---|---|---|---|
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 1 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = nums.size();\n vector<int> diff(n);\n long long count = 0;\n\n for (int i = 0; i < n; i++) {\n diff[i] = nums[i] - target[i];\n }\n int diff3=(0-di... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 1 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = nums.size();\n vector<int>diff(n);\n long long result = 0;\n\n for(int i = 0; i<n; i++){\n diff[i] = target[i] - nums[i];\n }\n\n int curr = 0;... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n nums.push_back(0);\n target.push_back(0);\n int n(nums.size());\n stack<int> stk({0});\n long res(0);\n for (int i(0); i < n; ++i) {\n int dif = target... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n for (int i = 0; i < nums.size(); i++){\n nums[i] -= target[i];\n cout << nums[i] <<\" \";\n }\n cout<<endl;\n\n if (nums.size() == 1){\n return... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "using LL = long long;\nclass Solution {\npublic:\n long long minimumOperations0(vector<int>& nums, vector<int>& target) {\n int n = nums.size();\n bool dir_pre = target[0] >= nums[0];\n int diff_pre = abs(target[0] - nums[0]);\n LL ans = diff_pre;\n for(int i = 1; i < ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long find(vector<int>& nums, vector<int>& target){\n long long ans = 0;\n int n = nums.size();\n deque<long long> dq = {};\n\n long long prev_diff = target[0] - nums[0];\n\n for(int i=0; i < n; i++){\n long long diff = target... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<long long> di(nums.size(),0);\n \n for(int i=0;i<nums.size();i++)\n {\n di[i]=target[i]-nums[i];\n \n }\n long long ans=abs(di[0]);\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<long long> diff(nums.size()+1, 0);\n\n for (int i = 0; i < nums.size(); i++){\n diff[i+1] = target[i] - nums[i];\n }\n\n long long res = 0;\n for (int ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n long long x = 0;\n vector<int> vec;\n for(int i = 0; i < nums.size(); i++) vec.push_back(target[i] - nums[i]);\n int n = vec.size(), last = vec[0];\n if(vec.size() == 1)... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<int> diff;\n int n = nums.size();\n for(int i = 0; i < n; i++)\n diff.push_back(target[i] - nums[i]);\n\n long long ans = 0;\n int prev = 0;\n f... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long calc(vector<int>& nums) {\n long long res = 0;\n stack<int> stk;\n for (int i = 0; i < nums.size(); ++i) {\n int v = max(0, nums[i]);\n if (!stk.empty() && stk.top() >= v) {\n res += stk.top() - v;\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<int>v;\n for(int i=0;i<nums.size();i++){\n v.push_back(target[i]-nums[i]);\n\n }\n int dp[v.size()];\n memset(dp,0,sizeof(dp));\n for(int i=0;i<... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\npublic:\n // void build(vector<int> &v, int start , int end,int index, pair<long long , long long >segtree[]){\n // if(start==end){\n // segtree[index].first = v[start];\n // segtree[index].second = start;\n // return;\n // }\n // i... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 2 | {
"code": "class Solution {\nprivate:\n long long solve(vector<int>& temp){\n long long ans=0;\n int prev=0;\n for(int i=0;i<temp.size();i++){\n if(temp[i] >= prev){\n ans+=temp[i]-prev;\n }\n prev=temp[i];\n }\n return ans;\n }\... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\n using ll = long long;\n public:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n const int n = nums.size();\n vector<int> proc = {0};\n bool neg = false;\n for (int i = 0; i < n; ++i) {\n const int v = nums[i] - target[i];\n if (v < 0) {\... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<int> diff(nums.size());\n for(int i = 0;i < nums.size();++i)\n diff[i] = target[i] - nums[i];\n int start = 0;\n vector<pair<int, int> > intervals;\n f... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) \n {\n int n= nums.size();\n vector<long long> b(n,0);\n for(int i=0;i<n;i+=1)\n b[i]= target[i]- nums[i];\n vector<long long> dp(n,0);\n for(int i=0;i<n;i+=1)... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = nums.size();\n vector<long long> d1(n + 1), d2(n + 1);\n long long add = 0, sub = 0;\n d1[0] = nums[0], d2[0] = target[0];\n for (int i = 1; i <= n; i++) {\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\nprivate:\n long long solver(vector<int> &arr){\n int n = arr.size();\n arr.push_back(0);\n int maxi = 0;\n long long ans = 0;\n bool clime = true;\n for(int i = 0; i <= n; i++){\n if(arr[i] == 0){\n ans += maxi;\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n #define ll long long int\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n=nums.size();\n\n vector<int> diff1; diff1.push_back(nums[0]);\n for(int i=1;i<n;i++){\n diff1.push_back(nums[i]-nums[i-1]);\n }di... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long solve(vector<int>& diff, int l, int r){\n // cout<<l<<\" \"<<r<<endl;\n if(l>r) return 0;\n int streak=0;\n int pos=l;\n long long cnt=0;\n for(int i=l; i<=r; i++){\n // cout<<diff[i]<<\" | \\n\";\n if(... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n\n long long solve(vector<int> &temp){\n if(temp.size() == 0)return 0;\n long long count = temp[0];\n for(int i = 0;i < temp.size(); i++) if(i > 0 && temp[i] > temp[i-1]) count += temp[i] - temp[i-1];\n temp.clear();\n return count; \n }... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n vector<int> cpnums;\n int dec(int i,int j)\n {\n // cout<<i<<\" \"<<j<<\" dec \"<<c<<endl;\n if(i > j)\n return 0;\n if(i == j)\n {\n int temp = cpnums[i];\n cpnums[i] -= cpnums[i];\n return temp; ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\nprivate:\nlong long solver(vector<long long>&temp)\n{\n if(temp.size()==0)\n {return 0;}\n long long jam=temp[0];\n long long n=temp.size();\n if(temp.size()==1)\n {\n return temp[0];\n }\n\n for(int i=0;i<n-1;i++)\n {\n if(temp[i+1]>temp[i]){\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\nlong long int f(vector<long long int>& arr) {\n long long int n = arr.size();\n long long int ans = arr[0];\n for(int i = 1; i < n ; i++ ){\n if(arr[i] > arr[i - 1]){\n ans += (arr[i] - arr[i - 1]);\n }\n }\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long count(vector<int> arr, int n){\n \n long long ans=arr[0];\n for(int i=1;i<n;i++){\n if(arr[i]>arr[i-1]){\n ans+=(arr[i]-arr[i-1]);\n }\n }\n \n return ans;\n}\n long long minimumOperations(vector<int>& nums, vector<int>& ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n long long ans=0;\n int n=nums.size();\n vector<int> vis(n);\n priority_queue<pair<int,int>> pqp;\n priority_queue<pair<int,int>> pqn;\n for(int i=0;i<nums.size();... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& va, vector<int>& vb) {\n long long ans = 0;\n int n = int(va.size());\n vector<int> a(n);\n for (int i = 0; i < n; i++) {\n a[i] = vb[i] - va[i];\n }\n int beg = 0;\n while (beg < n) {\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#define ll long long\nclass Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n \n long long ans =0 ;\n vector<ll>v;\n ll n = nums.size();\n \n ll prev = 0;\n for(ll i =0 ;i <n;i++){\n ll diff = target[... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = target.size();\n long long ans=0;\n vector<long long>p;\n int ch=0,ch2=0;\n for(int i=0;i<n;i++){\n if(target[i]-nums[i]>0){\n ch=0;\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = target.size();\n long long ans=0;\n vector<long long>p;\n vector<long long>neg;\n int ch=0,ch2=0;\n for(int i=0;i<n;i++){\n if(target[i]-nums[i... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<long long> diff;\n for(int i=0;i<nums.size();i++){\n long long diffVal = target[i] - nums[i];\n if(i>0){\n long long prevDiffVal = target[i-1] - n... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n=nums.size();\n long long ans = 0;\n vector<int> diff;\n for(int i=0;i<n;i++){\n diff.push_back(target[i]-nums[i]);\n }\n\n ans = solve(diff, 0, n... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n #define ll long long\n long long minimumOperations(vector<int>& src, vector<int>& dest) {\n vector<ll> v;\n ll n=src.size();\n ll i=1;\n for(ll i=0;i<n;i++){\n v.push_back(dest[i]-src[i]);\n }\n ll sum=abs(v[0]);\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<long long> vals;\n \n int last = target[0] - nums[0];\n if (last >= 0) vals.push_back(last);\n if (last < 0) vals.push_back(-1 * last); \n for (int i = 1;... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\n\n long long f (vector<int> & target){\n for(int i=0;i<target.size();i++){\n target[i] = abs(target[i]);\n }\n int totalMinOperations = target[0];\n int operationsWeDidEarlier = target[0];\n\n for(int i =1;i<target.size();i++){\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long f(int i, int j, vector<int>& nums, vector<int>& target) {\n vector<int> temp;\n for (int k = i; k < j; k++)\n temp.push_back(abs(nums[k] - target[k]));\n int n=temp.size();\n int sub=temp[0];\n int val=0;\n int an... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = target.size();\n vector<long long>v(n,0);\n for(int i=0;i<n;i++){\n v[i]=target[i]-nums[i];\n }\n long long ans=0;\n long long maxi=abs(v[0]);\... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "\n\nlong long help(vector<long long>& v) {\n int n = v.size(), st = 0;\n if(n == 0) return 0LL;\n long long ans = v[0];\n for(int i = 1; i < n; i++) {\n if(v[i] > v[i - 1]) {\n ans += v[i] - v[i - 1];\n }\n }\n return ans;\n}\n\nclass Solution {\npublic:\n long... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) \n {\n long long counter = 0;\n vector<long long> difference;\n long long prev = 0;\n difference.push_back(0);\n for(int i = 0; i<nums.size(); i++)\n {\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) \n {\n long long counter = 0;\n vector<long long> difference;\n long long prev = 0;\n difference.push_back(0);\n for(int i = 0; i<nums.size(); i++)\n {\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#define vi vector<int>\n#define ll long long\nconst int MAXN = 1e5+5;\nll lazy[4*MAXN];\nll seg[4*MAXN];\nclass Solution {\nprivate:\n void propagate(int si,int p,int q){\n if(lazy[si] == 0) return;\n seg[si] += (q-p+1)*lazy[si];\n if(p!=q){\n lazy[si<<1] += lazy[si];\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n int min_operations(vector<int>&temp){\n if(temp.empty()) return 0;\n int ans=temp[0];\n for (int i=1;i<temp.size();i++){ \n ans+=max(temp[i]-temp[i-1],0); \n }\n return ans; \n }\n\n long long minimumOperations(vector<int... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int size = nums.size();\n long long operations = 0;\n vector<int> diff;\n\n for (int i = 0; i < size; i++) {\n int currDiff = target[i] - nums[i];\n diff.push_back(currDi... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int size = nums.size();\n long long operations = 0;\n vector<int> diff;\n\n for (int i = 0; i < size; i++) {\n int currDiff = target[i] - nums[i];\n diff.push_back(currDi... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\n int minop(vector<long long> &target, int st, int end) {\n int n = end - st + 1;\n vector<long long> dp(n);\n dp[0] = abs(target[st]);\n\n for (int i = 1; i < n; i++) {\n dp[i] = dp[i-1] + max(0LL, abs(target[st + i]) - abs(target[st + i - 1]));\n... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<int> v;\n long long n = nums.size();\n for(long long i=0;i<n;i++){\n v.push_back(target[i]-nums[i]);\n }\n long long i=0,ans=0;\n while(i<n){\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class node{\npublic:\n int val;\n node* next;\n node* prev;\n node(int v){\n val = v;\n next = NULL;\n prev = NULL;\n }\n};\nvoid deletenext(node* n){\n n->next = n->next->next;\n if(n->next != NULL) n->next->prev = n;\n}\nvoid deleteprev(node* n){\n n->prev = n... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": " typedef long long td;\n struct Node{\n td val,val2,val3;\n Node(){\n val=0;\n val2=1e18;\n val3=-1e18;\n }\n Node(long long p){\n val=p;\n val2=p;\n val3=p;\n }\n //\n void merge(Node &... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": " typedef long long td;\n struct Node{\n td val,val2,val3;\n Node(){\n val=0;\n val2=1e18;\n val3=-1e18;\n }\n Node(long long p){\n val=p;\n val2=p;\n val3=p;\n }\n //\n void merge(Node &... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n long long ans = 0;\n int n = nums.size();\n\n for(int i = 0; i < n; ) {\n int j = i;\n if(nums[i] == target[i]) {\n i++;\n continue... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "typedef long long ll;\nclass SegmentTree {\n vector<int> o, a, b;\n int n;\n void build(int s, int e, int id) {\n if(e > s) return;\n if(s == e) {\n a[id] = s;\n return;\n }\n int mid = (s + e) >> 1;\n build(s, mid, 2 * id);\n build(m... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& v, vector<int>& target) {\n long long ans = 0;\n int n = (int) v.size();\n \n for (int i = 0; i < n; i++) {\n v[i] = target[i] - v[i];\n }\n \n auto calc = [&] (vector<int> t)... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n pair<long long, long long> seg[4 * 100001];\n pair<long long, long long> merge(pair<long long, long long> left, pair<long long, long long> right) {\n if (left.first < right.first)\n return left;\n return right;\n }\n void build(int node, int ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n \n vector<int> d(nums.size());\n \n \n for (int i = 0; i < nums.size(); i++) {\n \n d[i] = nums[i] - target[i];\n }\n \n\n \n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<long long> diff;\n int n = (int)target.size(), index = n;\n for(int i = 0; i < n; i++){\n diff.emplace_back(nums[i] - target[i]);\n }\n long long count... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long findforonearray(vector<int> &v){\n //this is the logic to find the number of operation for each array element.\n long long count = v[0];\n for(int i =1;i<v.size();i++){\n if(v[i]-v[i-1]<=0){\n count+=0;\n }\n... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long findforonearray(vector<int> &v){\n long long count = v[0];\n for(int i =1;i<v.size();i++){\n if(v[i]-v[i-1]<=0){\n count+=0;\n }\n else{\n count+=(v[i]-v[i-1]);\n }\n }\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long solve(vector<int>& arr) {\n if (arr.size() == 1) {\n return arr[0];\n }\n long long ans = arr[0];\n for (int i = 1; i < arr.size(); i++) {\n ans += max(arr[i] - arr[i - 1], 0);\n }\n return ans;\n }\... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n \n vector<long long>reqd;\n\n for(int i=0;i<nums.size();i++){\n long long val = target[i] - nums[i];\n reqd.push_back(-val);\n }\n\n long long i = ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\nlong long Helper(vector<long long>& v){\n for(int i=0;i<v.size();i++){\n if(v[i]<0)v[i]*=-1;\n }\n long long maxi=0;\n long long ans=0;\n for(int i=0;i<v.size();i++){\n if(v[i]>maxi){\n ans+=(v[i]-maxi);\n maxi=v[i];\n }\n... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "// class Solution {\n// public:\n// long long minimumOperations(vector<int>& nums, vector<int>& t) {\n// long long ans=0;\n// vector<int> target;\n// bool pos;\n// for (int i=0;i<t.size();i++){\n// target.emplace_back(t[i]-nums[i]);\n// }\n// ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\nprivate:\n long long getMinOp(vector<int>& arr,int n){\n long long ans=arr[0];\n for(int i=1;i<n;i++){\n ans+=max(arr[i]-arr[i-1],0);\n }\n return ans;\n }\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\nprivate:\n long long singleArray(vector<int>& v) {\n long long res = v[0];\n for (int i = 1; i < v.size(); i++) {\n res += max(v[i] - v[i - 1], 0);\n }\n return res;\n }\n\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#define ll long long\nclass Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n ll ans = 0;\n int n = nums.size();\n vector<int>vec(n);\n for(int i = 0;i<n;i++){\n vec[i] = target[i] - nums[i];\n }\n vector<ve... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<long long> a, b;\n int n = nums.size();\n for(int i = 0; i < n; i++) {\n if(nums[i] >= target[i]) {\n a.push_back(nums[i] - target[i]);\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = nums.size();\n vector<vector<int>> arr;\n int parity = -1;\n for(int i=0; i<n; i++){\n int diff = nums[i]-target[i];\n if((diff >= 0) != parity){\... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long fun(vector<int>a){\n int n=a.size();\n long long cnt=0;\n if(n==1){\n cnt+=a[0];\n }else if(n==2){\n cnt= min(a[0],a[1]) + abs(a[0]-a[1]);\n }else{\n // construct logic \n // int mxvalue=... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\n vector<pair<int,long long>>segTree;long long ans=0;\n void updateMin(pair<int,int>p,int i,int idx,int low,int high){\n if(idx<low||idx>high||low>high)return;\n if(segTree[i].first==-1||segTree[i].second>p.second)segTree[i]=p;\n if(low==high)return;\n int... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<int> a;\n vector<vector<int>> b;\n int n = nums.size();\n\n for (int i = 0; i < n; i++) {\n a.push_back(target[i] - nums[i]);\n }\n\n // Initial... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n = nums.size();\n unordered_map<int,int> m;\n bool flag = false;\n for(int i=0;i<n;i++){\n if(nums[i]<=target[i]){\n if(flag){\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n vector<int> a;\n vector<vector<int>> b;\n int n = nums.size();\n\n for (int i = 0; i < n; i++) {\n a.push_back(target[i] - nums[i]);\n }\n\n // Initial... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\n void construct(vector<pair<int,int>>& tree, vector<int>& arr, int st, int end, int ind){\n // if(st>end)return;\n if(st==end){\n tree[ind] = {arr[st],st};\n return;\n }\n int mid = (st+end)/2;\n construct(tree, arr, st,mid,2*ind... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class MinSegTree{\n vector<int>v;\n vector<int> tree;\n int n ;\n \n void resize(){\n while(__builtin_popcount(n) != 1){\n v.push_back(1e9);\n n++;\n }\n tree.resize(2*n);\n }\n void buildTree(){\n for(int i = 0 ; i<n ; i++) tree[i+n] = i;\n \n for(int i = n-1 ;i>=0 ;... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "// Segment Tree for Range Minimum Query\nclass SegmentTree {\nprivate:\n vector<pair<int, int>> tree; // (value, index)\n int n;\n \n void build(const vector<int>& data) {\n for (int i = 0; i < n; ++i) {\n tree[i + n] = {data[i], i};\n }\n for (int i = n - 1; i >... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n vector<int> NextSmallerEqualLeft(vector<int> &arr)\n{\n int n = arr.size();\n stack<int> st;\n vector<int> ans;\n for (int i = 0; i < n; i++)\n {\n if (st.size() == 0)\n {\n ans.push_back(-1);\n }\n else if (st.size() > 0 &... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n vector<int> NextSmallerEqualLeft(vector<int> &arr)\n{\n int n = arr.size();\n stack<int> st;\n vector<int> ans;\n for (int i = 0; i < n; i++)\n {\n if (st.size() == 0)\n {\n ans.push_back(-1);\n }\n else if (st.size() > 0 &... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long findForOneArray(vector<int> arr) {\n int cnt = arr[0];\n for(int i=1; i<arr.size(); i++)\n cnt += max(0, arr[i] - arr[i-1]);\n return cnt;\n }\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\n\tpublic:\n\t\tlong long findForOneArray(vector<int> arr)\n\t\t{\n\t\t\tint count = arr[0];\n\t\t\tfor (int i = 1; i < arr.size(); i++) // arr\n\t\t\t\tcount += max(arr[i] - arr[i - 1], 0);\n\t\t\treturn count;\n\t\t}\n\t\tlong long minimumOperations(vector<int>& nums, vector<int>& target... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "void build(vector<pair<int,int>>& t,vector<int>& arr,int root,int l,int r)\n{\n if(l>r) return;\n if(l == r)\n {\n t[root]={arr[l],l};\n return;\n }\n int mid=(l+r)/2;\n build(t,arr,2*root,l,mid);\n build(t,arr,2*root+1,mid+1,r);\n\n if(t[2*root].first < t[2*root+1].fi... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n long long n=nums.size();\n vector<int> diff(n);\n for(int i=0;i<n;i++){\n diff[i]=target[i]-nums[i];\n }\n\n vector<vector<int>> segments;\n vector<int... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\nprivate:\nvector<int> nextSmallerLeft(vector<int>& arr)\n{\n stack<int> stack;\n vector<int> NSLi;\n for (int i = 0; i < arr.size(); i++)\n {\n if (stack.empty())\n {\n NSLi.push_back(-1);\n }\n else if (arr[stack.top()] < arr[i])\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#define ll long long\n\nclass SGT {\npublic:\n vector<pair<ll, int>> seg;\n\n SGT(int n) {\n seg.resize(4 * n + 1, {LLONG_MAX, -1});\n }\n\n void build(int ind, int low, int high, vector<ll> &arr) {\n if (low == high) {\n seg[ind] = {arr[low], low};\n return;... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#define ll long long\nclass Solution {\npublic:\n ll minimumOperations(vector<int>& nums, vector<int>& target) {\n int n=target.size();\n vector<vector<int>> diff(1);\n int k=true;\n for(int i=0;i<n;++i){\n if(target[i] >= nums[i]){\n if(k)diff[diff.... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long find(vector<int>&nums){\n for(auto &it:nums){\n it=abs(it);\n }\n long long count=nums.front();\n for(int i=1,n=nums.size();i<n;i++){\n count+=max(nums[i]-nums[i-1],0);\n }\n return count;\n }\n l... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n\n\n vector<int>stree;\n unordered_map<int,vector<int>>indx;\n\n int find(int node,int start,int end,int l,int r){\n if(end<l||start>r) return INT_MAX;\n if(l<=start && r>=end) return stree[node];\n int mid = start+(end-start)/2;\n return min(... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long solve(vector<int>v){\n long long ans=v[0];\n for(int i=1;i<v.size();i++){\n if(v[i]>v[i-1]) ans+=v[i]-v[i-1];\n }\n return ans;\n }\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n=nu... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n long long solve(vector<int>v){\n long long ans=v[0];\n for(int i=1;i<v.size();i++){\n if(v[i]>v[i-1]) ans+=v[i]-v[i-1];\n }\n return ans;\n }\n long long minimumOperations(vector<int>& nums, vector<int>& target) {\n int n=nu... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n\n\n vector<int>stree;\n map<int,vector<int>>indx;\n\n int find(int node,int start,int end,int l,int r){\n if(end<l||start>r) return INT_MAX;\n if(l<=start && r>=end) return stree[node];\n int mid = start+(end-start)/2;\n return min(find(node*... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class SegmentTree {\npublic:\n SegmentTree(const vector<int>& input_data) {\n int n = input_data.size();\n tree.resize(4*n);\n data = input_data;\n build(0, 0, n - 1);\n }\n \n int queryMinIndex(int L, int R) {\n return query(0, 0, data.size() - 1, L, R);\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class SegmentTree {\npublic:\n SegmentTree(const vector<int>& input_data) {\n int n = input_data.size();\n tree.resize(4*n);\n data = input_data;\n build(0, 0, n - 1);\n }\n \n int queryMinIndex(int l, int r) {\n L = l, R = r;\n return query(0, 0, data.... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class SegmentTree {\npublic:\n SegmentTree(const vector<int>& input_data) {\n int n = input_data.size();\n tree.resize(4*n);\n data = input_data;\n build(0, 0, n - 1);\n }\n \n int queryMinIndex(int l, int r) {\n L = l, R = r;\n return query(0, 0, data.... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class SegmentTree {\npublic:\n SegmentTree(const std::vector<int>& input) : arr(input) {\n int n = arr.size();\n tree.resize(4 * n);\n build(0, 0, n - 1);\n }\n\n int queryMinIndex(int l, int r) {\n return query(0, 0, arr.size() - 1, l, r);\n }\n\nprivate:\n std::... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n\n void printt(vector<int>&v){\n for(int x : v){cout<<x<<\", \";}\n cout<<\" : \";\n }\n\n long long split(vector<int>v){ // split +ve's/ -ve's \n int ct0 = count(v.begin(), v.end(), 0);\n if(ct0==v.size()){return 0;}\n\n while(v[0]=... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#include <vector>\n#include <iostream>\nlong long f(vector<int> &nums) {\n if (nums.size() == 0) return 0; \n long long ans = 0;\n int mini = 1e9;\n for (int i = 0; i < nums.size(); i++) {\n mini = min(mini, nums[i]);\n }\n for (int i = 0; i < nums.size(); i++) {\n nums[i... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n \n \n long long solve(vector<int> vec){\n \n long long count = vec[0];\n \n for(int i=1;i<vec.size();i++){\n count += max(vec[i] - vec[i-1], 0);\n }\n \n return count;\n }\n long long minimumOperations(ve... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n \n \n long long solve(vector<int> vec){\n \n long long count = vec[0];\n \n for(int i=1;i<vec.size();i++){\n count += max(vec[i] - vec[i-1], 0);\n }\n \n return count;\n }\n long long minimumOperations(ve... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#include <vector>\n#include <iostream>\nlong long f(vector<int> &nums) {\n if (nums.size() == 1) return nums[0]; \n long long ans = 0;\n int mini = 1e9;\n for (int i = 0; i < nums.size(); i++) {\n mini = min(mini, nums[i]);\n }\n for (int i = 0; i < nums.size(); i++) {\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "class Solution {\npublic:\n \n long long fn(vector<int> &v) {\n long long ans = v[0];\n for(int i=1;i<v.size();i++) {\n if(v[i]>v[i-1]) ans += v[i]-v[i-1];\n }\n\n return ans;\n }\n\n long long minimumOperations(vector<int>& nums, vector<int>& tgt) {\n ... |
3,454 | <p>You are given two positive integer arrays <code>nums</code> and <code>target</code>, of the same length.</p>
<p>In a single operation, you can select any subarray of <code>nums</code> and increment each element within that subarray by 1 or decrement each element within that subarray by 1.</p>
<p>Return the <strong... | 3 | {
"code": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define MOD 1000000007\n#define INF 0x3f3f3f3f\n#define LINF (ll)1e18\n#define f first\n#define s second\n#define rep(i,a,b) for (int i=a; i<b; ++i)\n#define setpr(x) cout<<setprecision(x)<<fixed\n#define sz(v) int(v.size())\n#define all(v) v.begin(),v.end(... |
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