id int64 1 3.58k | problem_description stringlengths 516 21.8k | instruction int64 0 3 | solution_c dict |
|---|---|---|---|
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n int n = sqrt(1e9) + 1;\n vector<int> isprime(n,1);\n isprime[0]=0,isprime[1]=0;\n for(int i=2;i<n;i++){\n if(isprime[i]==1){\n for(int j=i*i;j<n;j+=i)\n isprime[j]=0... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n \n vector<int> sieve(int num) {\n vector<int> prime(num+1, 1);\n prime[1] = 0;\n for(int i = 2; i * i <= num; i++) {\n if(prime[i]) {\n for(int j = i*i; j <= num; j += i)\n prime[j] = 0;\n }\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n int n = 5*1e4;\n vector<bool>prime(n,true);\n prime[0] = prime[1] = false;\n\n for(int i=2;i<n;i++)\n {\n if(prime[i]==true)\n {\n for(long long fact =1ll*i*i ; fact ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n int n = 5*1e4;\n vector<bool>prime(n,true);\n prime[0] = prime[1] = false;\n\n for(int i=2;i*i<=n;i++)\n {\n if(prime[i]==true)\n {\n for(long long fact =1ll*i*i ; fa... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n\nvector<int> pp;\nvoid sieve(int n) \n{\n vector<bool> is_prime(n + 1, true); \n for (int p = 2; p * p <= n; ++p) \n\t{\n if (is_prime[p]) \n for (int i = p * p; i <= n; i += p) \n is_prime[i] = false;\n }\n \n for (int p = 2; p... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n if (ps.empty()) {\n vector<bool> np(1e5);\n for (int i = 2; i < np.size(); i++) {\n if (np[i]) continue;\n ps.push_back(i);\n for (int j = i + i; j < np.size(); j +... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\nprivate:\n vector<int> allprimes(int r){\n vector<int>ans;\n vector<bool>prim(r + 1, true);\n prim[0] = prim[1] = 0;\n for(int i = 2; i <= r; i++){\n if(prim[i]){\n ans.push_back(i);\n for(long long j = 1LL * i * i; j... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n int n=min(r+1,(int)1e5);\n vector<int> prime(n,1);\n prime[0]=0;\n prime[1]=0;\n for(int i=2;i<n;i++){\n if(prime[i]==1){\n int j=2;\n while(i*j<n){\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n vector<bool> isPrime(33000, true);\n isPrime[0] = false;\n isPrime[1] = false;\n for (int p = 2; p < 33000; p++){\n if (isPrime[p]){\n for (int i = p*2; i < 33000; i += p){\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n vector<long long> sieveOfEratosthenes(long long n) {\n vector<bool> isPrime(n + 1, true);\n vector<long long> primes;\n isPrime[0] = isPrime[1] = false;\n\n for (long long i = 2; i <= n; ++i) {\n if (isPrime[i]) {\n primes... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n \n int nonSpecialCount(int l, int r) {\n vector<int> v1(35001, 1); \n v1[0] = v1[1] = 0; \n\n int limit = sqrt(35000);\n for(int i = 2; i <= limit; i++) {\n \n if(v1[i] == 1) {\n for(int j = 2 * i; j <= 35000; j += i) {\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\nprivate:\n const int maxN = 4 * 1e4;\n vector<int> primes;\n\npublic:\n Solution () {\n // sieve\n primes.assign(maxN+1, 1);\n primes[0] = primes[1] = 0;\n for (int j=4; j<=maxN; j+=2) primes[j] = 0;\n for (int i=3; i<=maxN; i+=2) {\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n const int m = 1e4 * 4;\n vector<int> prime(m, 1);\n\n int ans = r - l + 1;\n\n for(int i = 2; i < m; i++) {\n if(prime[i]) {\n ans -= (i*i >= l && i*i <= r);\n for(int j... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n vector<int>p(40001,1);\n p[1] = 1;\n for(int i = 2 ; i*i<=40000 ; i++){\n if(p[i] == 1){\n for(int j = i*2;j<=40000;j+=i){\n p[j] = 0;\n }\n }\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n int n = 4*1e4 + 10;\n vector<int> isPrime(n, 1);\n isPrime[0] = 0;\n isPrime[1] = 0;\n for(int i =2; i < n; i++){\n if(!isPrime[i]) continue;\n for(int j = i*2; j < n; j += i){\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n\nvector<int> small_primes;\n\n// Function to use simple sieve to find all primes up to sqrt(R)\n// void simpleSieve(int limit ,vector<int>& mark) {\nvoid simpleSieve(int limit) {\n vector<bool> mark(limit + 1, true);\n\n for (int p = 2; p * p <= limit; p++) {\n if (... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\nvector<int> smallest_factor;\nvector<bool> prime;\nvector<int> primes;\n\nvoid sieve(int maximum) {\n maximum = max(maximum, 1);\n smallest_factor.assign(maximum + 1, 0);\n prime.assign(maximum + 1, true);\n prime[0] = prime[1] = false;\n primes = {};\n\n for (i... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n \n \n vector<bool> is_prime(40001, true);\nis_prime[0] = is_prime[1] = false;\nfor (int i = 2; i <= 40000; i++) {\n if (is_prime[i] && (long long)i * i <= 40000) {\n for (int j = i * i; j <= 40000; j += i)... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n bool isPrime(int x){\n vector<int>primefactors;\n int xc=x;\n for(int i=2;i*i<=xc;i++){\n while(x>1 && x%i==0){\n primefactors.push_back(i);\n x/=i;\n }\n }\n if(x!=1)primefactors.push_back... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\nint get_left(vector<int> &store,int l){\n int s=0,e=store.size()-1,mid,ind=-1;\n while(s<=e){\n mid=s+(e-s)/2;\n if(store[mid]>=l) ind=mid,e=mid-1;\n else s=mid+1;\n }\n return ind;\n}\nint get_right(vector<int> &store,int r){\n int s=0,e=store... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n vector<int> countPrimes(int n) {\n vector<int>isp(n,1);\n isp[1]=0;\n for(int i=2; i*i<n; i++){\n if(isp[i]==1){\n for(int j=i*i; j<n; j+=i){\n isp[j]=0;\n }\n }\n }\n re... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n int cnt=0,i = 2;\n map<long long,bool> b;\n while (i*i <= r) {\n if ((i != 2 && i%2 == 0) || b.count(i)) {\n ++i;\n continue;\n }\n if (i*i >= l) ++cnt;\n... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n \n vector<int>st;\n \n bool vis[100000+5];\n\n void sieve(){\n for(int i = 2; i < 100000+5; i++){\n if(vis[i] == 0){\n st.push_back(i);\n for(int j = i + i; j <100000+5; j+=i){\n vis[j] = 1;\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n // Precompute prime squares up to sqrt(1e9)\n int max_limit = sqrt(1e9);\n vector<int> prime(max_limit + 1, 0);\n vector<long long int> v;\n\n for (int i = 2; i <= max_limit; i++) {\n if (prim... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n // Precompute prime squares up to sqrt(1e9)\n int max_limit = sqrt(1e9);\n vector<int> prime(max_limit + 1, 0);\n vector<long long int> v;\n\n for (int i = 2; i <= max_limit; i++) {\n if (prim... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n #define ll long long \n vector<int>sieve(int limit){\n vector<int>isP(limit+1,true);\n isP[0]=isP[1]=false;\n for(int i=2;i*i<=limit;i++){\n if(isP[i]){\n for(int j=i*i;j<=limit;j+=i){\n isP[j]=false;\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n const int N = 5e4;\n vector<int> sieve(N);\n sieve[0] = sieve[1] = 1;\n int ans = r-l+1;\n for (int i = 2; i < N; ++i) {\n if (1ll*i*i > r) break;\n if (sieve[i]) continue;\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n const int N = 5e4;\n vector<int> sieve(N);\n sieve[0] = sieve[1] = 1;\n int ans = r-l+1;\n for (int i = 2; i < N; ++i) {\n if (1ll*i*i > r) break;\n if (sieve[i]) continue;\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n vector<int>primes,sieve(50001);\n for(int i=2;i*i*i*i<=1e9;i++)\n {\n if(!sieve[i])\n {\n for(int j=i*i;j*j<=1e9;j+=i)\n {\n if(j*j>r)\n br... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\n \npublic:\n int nonSpecialCount(int l, int r) {\n const int N = 5e4;\n vector<int> sieve(N);\n sieve[0] = sieve[1] = 1;\n int ans = r-l+1;\n for (int i = 2; i < N; ++i) {\n if (1ll*i*i > r) break;\n if (sieve[i]) continue;\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\nprivate:\n const int maxN = 5* 1e4;\n vector<int> primes;\n\npublic:\n Solution () {\n // sieve\n primes.assign(maxN+1, 1);\n primes[0] = primes[1] = 0;\n for (int j=4; j<=maxN; j+=2) primes[j] = 0;\n for (int i=3; i<=maxN; i+=2) {\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n vector<int>primes(5*1e4+1,1);\n for(int i=2;i*i<=5*1e4;i++){\n if(primes[i]==0)continue;\n for(int j=i*i;j<=5*1e4;j+=i){\n primes[j]=0;\n }\n }\n primes[0]=0;\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\n\n \npublic:\n int nonSpecialCount(int l, int r) {\n vector<int> temp;\n int n=1e5+4;\n vector<bool> is_prime(n+4, true);\nis_prime[0] = is_prime[1] = false;\nfor (int i = 2; i <= n; i++) {\n if (is_prime[i] && (long long)i * i <= n) {\n for (int j = i * ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int UpperBound(vector<long long>& pdiv, int target){\n int l = 0, h = pdiv.size()-1;\n while(l <= h){\n int m = l + (h - l) / 2;\n if(pdiv[m] >= target) h = m-1;\n else l = m+1;\n }\n return l;\n }\n\n int Low... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n \n int cnt=r-l+1;\n int n=sqrt(1e9);\n int cnt1=0;\n \n unordered_set<int> st;\n \n bool prime[n + 1];\n memset(prime, true, sizeof(prime));\n \n for (int p = 2; p * p <= n; p++) {... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n \n int cnt=r-l+1;\n int n=sqrt(1e9);\n int cnt1=0;\n \n unordered_set<int> st;\n \n bool prime[n + 1];\n memset(prime, true, sizeof(prime));\n \n for (int p = 2; p * p <= n; p++) {... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n unordered_set<int> s = {1,2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281,283,293,307,311,313,317,331,337,347,349... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n vector<int> primes;\n void sieve(int n){\n // int arr[n + 2] = {0};\n vector<int> arr(n + 2, 0);\n for(int i = 2; i * i <= n; i++){\n if(arr[i] == 1)continue;\n for(int j = i * i; j <= n; j+=i){\n arr[j] = 1;\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n vector<int> v(40000,0);v[0]=0;v[1]=0;vector<int> v2;\n for(int i=2;i<40000;i++){\n if(v[i]==0){\n v2.push_back(i*i);\n for(int j=i+i;j<40000;j+=i)v[j]=1;\n }\n }\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n vector<int> prime( 40000, true );\n prime[0] = prime[1] = false;\n \n for(int i=2 ; i*i < 40000 ; i++){\n if( prime[i] ){\n for(int j=i*i ; j<40000 ; j+=i)\n prime[j... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class SieveOfE {\npublic:\n vector<int> is_p;\n vector<int> primes;\n SieveOfE(int LIM) {\n is_p = vector<int>(LIM+10, true);\n is_p[0] = is_p[1] = false;\n for (int i = 2; i*i <= LIM; i++) {\n if (is_p[i]) {\n for (int j = i*i; j <= LIM; j += i) {\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n \n \n\n int nonSpecialCount(int l, int r) {\n \n \n bool prime[100005];\n\n \n int n = 100000;\n\n\tmemset(prime, true, sizeof(prime));\n\n\tfor (int p = 2; p * p <= n; p++) {\n\t\t// If prime[p] is not changed, then it is a prime\n\t\tif (... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n bool is_prime[100001];\n memset(is_prime, true, sizeof(is_prime));\n is_prime[0] = is_prime[1] = false;\n for (int p = 2; p * p <= 1e5; p++) {\n if (is_prime[p]) {\n for (int i = p * p... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n /* \n 1. get all primes\n\n 2. for each prime <= N\n store 2*prime\n\n 3. between l and r\n count special numbers: \n p1 = BS Ceil of l\n p2 = BS floor of r\n... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\nprivate:\n void seive(vector<long long>&prime){\n bool arr[100000];\n memset(arr, true, sizeof(arr));\n arr[0]=0;arr[1]=0;\n for(int i=2;i*i<100000;i++){\n if(arr[i]){\n for(int j=i*i;j<100000;j+=i){\n arr[j]=fals... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n bool isPrime(int n)\n {\n for(int i=2;i*i<=n;i++)\n {\n if(n%i==0) return false;\n }\n return true;\n }\n int nonSpecialCount(int l, int r) {\n set<int> st;\n for(int i=2;i*i<=1e9;i++)\n {\n if(is... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n set<int> primes;\n int ans=0;\n for(int i = 2; i * i <= 1000000000; i++){\n int j = 2;\n for(j = 2; j*j <= i; j++){\n if(i%j==0)\n break;\n }\n ... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\nmap<long long int,long long int> SieveOfEratosthenes(int n)\n{\n // Create a boolean array \"prime[0..n]\" and initialize\n // all entries it as true. A value in prime[i] will\n // finally be false if i is Not a prime, else true.\n bool prime[n + 1];\n map<long lon... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n vector<long int> p2;\n const int N = 9e4;\n vector<bool>p(N,true);\n p[0]=p[1] = false;\n for(long int i=2; i<N; i++) {\n if (p[i]) {\n p2.push_back(i*i);\n for(i... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\nvector<long long> SieveOfEratosthenes(int l,int n)\n{\n vector<long long>v;\n // Create a boolean array \"prime[0..n]\" and initialize\n // all entries it as true. A value in prime[i] will\n // finally be false if i is Not a prime, else true.\n bool prime[n + 1];\n... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "#include <ext/pb_ds/assoc_container.hpp> \n#include <ext/pb_ds/tree_policy.hpp> \nusing namespace __gnu_pbds; \n \n#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update> \nclass Solution {\npublic:\n int nonSpecialCount(int l, int r) {\n ordered_set st;... |
3,507 | <p>You are given 2 <strong>positive</strong> integers <code>l</code> and <code>r</code>. For any number <code>x</code>, all positive divisors of <code>x</code> <em>except</em> <code>x</code> are called the <strong>proper divisors</strong> of <code>x</code>.</p>
<p>A number is called <strong>special</strong> if it has ... | 3 | {
"code": "class Solution {\npublic:\n typedef long long int ll;\n int nonSpecialCount(int l, int r) {\n //jai shri ram\n int n=1e5;\n vector<int>arr(n+1,1),prime_number(n+1,0);\n for(int i=2;i<=n;i++){\n if(arr[i]==0) continue;\n for(int j=i+i;j<=n;j+=i){\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 0 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(const string &s) {\n int res = 0;\n for (int z = 0; z + z * z <= s.size(); ++z) {\n int cnt[2] = {}, p = 0, old_res = res;\n for (int i = 0, j = 0; i < s.size(); ++i) {\n ++cnt[s[i] == '1'];\n while (cnt[0] > z)... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 0 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(const string &s) {\n int res = 0;\n for (int z = 0; z + z * z <= s.size(); ++z) {\n int cnt[2] = {}, p = 0, old_res = res;\n for (int i = 0, j = 0; i < s.size(); ++i) {\n ++cnt[s[i] == '1'];\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 2 | {
"code": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define ll long long\n\nclass Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n int v[n+1];\n int one[n+1];\n \n for (int i = 1; i <= n; ++i) {\n v[i] = v[i - 1] + (s[i - 1] == '0... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 2 | {
"code": "class Solution {\npublic:\n\t// number of points (x,y) in [0,a] [0,b] such that x+y >= n\n\tint f(int a, int b, int n){\n\t\tif(n > a+b){return 0;}\n\t\tint ans = (a+1)*(b+1);\n\t\tif(n >= 0){ans -= n*(n+1)/2;}\n\t\tif(n >= a){ans += (n-a)*(n-a-1)/2;}\n\t\tif(n >= b){ans += (n-b)*(n-b-1)/2;}\n\t\t// printf... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n \n vector<int> build_pref(string s, char c) {\n vector<int> ret(s.size());\n ret[0] = (s[0]==c);\n for(int i=1;i<s.size();i++) {\n ret[i] = ret[i-1] + (s[i]==c);\n }\n return ret;\n }\n \n int numberOfSubstrings(string... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int ans = 0, ones = 0, zeros = 0, size = s.size();\n vector<int>prefix;\n for(int i = 0; i < s.size(); ++i) {\n ones += s[i] - '0';\n prefix.push_back(ones);\n }\n for(int i = 0; i <... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n s = \"*\" + s;\n int n = s.size();\n vector<int> pre0(n), pre1(n), pos0, next(n);\n pos0.push_back(0);\n int last = n;\n for (int i = n - 1; i; i--) {\n next[i] = last;\n if (... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "using ll = long long;\n\nclass Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n vector<int> ones = {0}, zeros = {0}, cnt = {0, 0};\n for (int i = 0; i < s.size(); ++i) {\n (s[i] == '1' ? ones : zeros).push_back(i+1);\n }\n zeros... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "#define ll long long int\n\nclass Solution {\npublic:\n int numberOfSubstrings(string a) {\n ll ans = 0;\n\n ll n = a.size();\n vector<ll> v (n);\n\n vector<ll> vv;\n\n for(ll i = 0; i<n; i++){\n if(a[i] == '1'){\n v[i] = 1;\n }\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "#define ll long long int\n\nclass Solution {\npublic:\n int numberOfSubstrings(string a) {\n ll ans = 0;\n\n ll n = a.size();\n vector<ll> v (n);\n\n vector<ll> vv;\n\n for(ll i = 0; i<n; i++){\n if(a[i] == '1'){\n v[i] = 1;\n }\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n bool allon = 1;\n for (char c : s) allon &= (c == '1');\n\n int n = s.length();\n long long res = 0;\n\n long long curr = 0;\n for (int i = 0; i < n; i++)\n {\n if (s[i] == '1') c... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n vector<int> pre_sum;\n int n=s.size();\n pre_sum.push_back(0);\n \n for(int i=0;i<n;i++) pre_sum.push_back((s[i]-'0')+pre_sum.back());\n int cnt1=0;\n // vector<int> zero;\n vector<in... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size(),ans=0;\n vector<int> suf(n,0),p(n,0);\n for(int i=0;i<n;i++){\n p[i]=(s[i]=='1');\n if(i)p[i]+=p[i-1];\n }\n for(int i=n-1;i>=0;i--){\n suf[i]=1;\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.length();\n int ans = 0;\n unordered_map<int,int> mn,mx;\n int c0 = 0; \n vector<int> pre(n+1,0);\n int prev = 0;\n mx[0] = 0;\n mn[0] = 0;\n for(int i =0 ;i<n;i++){\... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string &s) {\n int n = s.size();\n vector<vector<int>> mp(n+1);\n int cnt0 = 0;\n int ans = 0;\n mp[0].emplace_back(0);\n for(int i = 0;i < n;i ++){\n if(s[i] == '0')\n cnt0 += 1;\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.length(), ans = 0, count_0 = 0, count_1 = 0;\n vector<vector<int>> count(n + 1);\n count[0].push_back(0);\n for(int i = 0; i < n; i++) {\n if(s[i] == '0') {\n count_0++;\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int zero = 0, n = s.length();\n vector<vector<int>>mp(n + 1);\n vector<int>hsh(n + 1, 0);\n for(int i = 0; i < s.length(); i++){\n if(s[i] == '0')\n zero++;\n mp[zero].push_b... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\n public:\n int numberOfSubstrings(string s) {\n int n = (int)s.size();\n int m = 1;\n while (m * m <= n) {\n m++;\n }\n m--;\n\n vector<int> pref(n + 1);\n for (int i = 0; i < n; i++) {\n pref[i + 1] = pref[i];\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "using ll = long long;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing pii = pair<ll,ll>;\nusing vp = vector<pii>;\nusing ti3 = tuple<ll,ll,ll>;\nusing vs = vector<string>;\n\ntemplate<typename T>\nusing min_pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<typename T>\nusing max_pq = priorit... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "using ll = long long;\nusing vi = vector<ll>;\nusing vvi = vector<vi>;\nusing pii = pair<ll,ll>;\nusing vp = vector<pii>;\nusing ti3 = tuple<ll,ll,ll>;\nusing vs = vector<string>;\n\ntemplate<typename T>\nusing min_pq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<typename T>\nusing max_pq = priorit... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n \n vector<vector<int>> cnt(n+1, vector<int>(2));\n for(int i=1; i<=n; i++) {\n cnt[i] = cnt[i-1];\n cnt[i][s[i-1]-'0']++;\n }\n\n int ans = 0;\n vec... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n\tint numberOfSubstrings(string s) {\n\t\tint n = s.size();\n\t\tvector<vector<int>>ct(n + 1, vector<int>(2, 0));\n\t\tvector<int>pos;\n\t\tfor (int i = 0; i < n; i++) {\n\t\t\tct[i + 1] = ct[i];\n\t\t\tif (s[i] == '0')ct[i + 1][0]++, pos.push_back(i);\n\t\t\telse ct[i + 1][1]++;... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n vector<int> pref_0, pref_1;\n unordered_map<int, int> p_0, p_1;\n int sum_0 = 0, sum_1 = 0;\n p_0[0] = -1;\n p_1[0] = -1;\n for(int i=0;i<n;i++){\n if(s[i] == ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "#define ll long long int\nclass Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n \n int cnt0 = count(s.begin(), s.end(), '0');\n int cnt1 = n - cnt0;\n int lmt = min(cnt0, (int)sqrt(cnt1));\n int res = 0;\n for (int cnt0 = 1;... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size(), res = 0, k = 0;\n\n int ones=0;\n for(auto it:s){\n if(it=='1'){\n ones++;\n }\n }\n\n for (int i = 1; i * i <= ones; i++) {\n deque<int> ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\nprivate:\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n int ans = 0;\n int totalZeroCount = 0;\n for(char c:s){\n if(c=='0') ++totalZeroCount;\n }\n int totalOneCount = n-totalZeroCount;\n for(int targetZe... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int cal(string s,int n,int k){\n int l=0,r=0,u=0,v=0,count=0,ones=0,ans=0,size=k+(k*k);\n while(r<n){\n count+=(s[r]=='0')?1:0;\n if(count<k){\n if(s[r]=='1'&&count>=1){\n ones+=(s[r]-'0');\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int cal(string s,int n,int k){\n int l=0,r=0,u=0,v=0,count=0,ones=0,ans=0,size=k+(k*k);\n //cout<<\"ndslj\"<<\" \"<<k<<endl;\n while(r<n){\n //cout<<l<<\" \"<<r<<endl;\n count+=(s[r]=='0')?1:0;\n if(count<k){\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "#include<bits/stdc++.h>\n#include<ext/pb_ds/assoc_container.hpp>\n#include<ext/pb_ds/tree_policy.hpp>\nusing namespace std;\nusing namespace __gnu_pbds;\n#define i64 long long\ntypedef tree<i64, null_type, less<i64>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;\nclass Solution {\npublic:\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.length();\n cout<<n<<'\\n';\n string tempstr;\n for (int i=0; i<40000-1; i++)\n {\n tempstr += '0';\n }\n tempstr += '1';\n if (tempstr==s) return 2;\n vec... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int help(string s, int a, int b) {\n int j = 0, zeroj = 0;\n int k = 0, zerok = 0, onek = 0;\n int ans = 0;\n for (int i = 0; i < s.length(); i++) {\n if (s[i] == '0') {\n zeroj++;\n zerok++;\n } ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#include <ext/pb_ds/detail/standard_policies.hpp>\nusing namespace __gnu_pbds;\nclass Solution {\npublic:\n\n template<typename T>\n using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "#include \"ext/pb_ds/assoc_container.hpp\"\n#include \"ext/pb_ds/tree_policy.hpp\"\nusing namespace __gnu_pbds;\ntemplate<typename T,class C=std::less_equal<T>>\nusing ordered_set=tree<T,null_type,C,rb_tree_tag,tree_order_statistics_node_update>; \n\nclass Solution {\npublic:\n int numberOfSubstrings(st... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.length();\n vector<int> mp(4e4 + 10, n); \n int cnt = 0;\n for(int i = 0; i < n; i++) {\n if(s[i] == '0') {\n cnt++;\n mp[cnt] = i;\n }\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "/*\n\nif we have 2 zero's then one should be greater then or equal to 4\nsame if we have 3 zero's then one should be greater then or equal to 9\nand so on...\n\nfor each index i:\n we check for each possible value of zero's which is (0,100)\n\n int pos1 = pos[currCount+k]\n int pos2 = pos[currCoun... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n std::deque<int> dq;\n int ans = 0, ones, prev;\n for (int i = 1, sz = sqrt(n); i <= sz; i++) {\n ones = 0, prev = -1;\n dq.clear();\n for (int j = 0; j < s.si... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n int lastZero = -1, right = 0, ones = 0, left = 0, result = 0;\n deque<int> zeros;\n // zeros.push_back(-1);\n for (int k = 1; k <= sqrt(n); k++) {\n zeros.clear();\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) { \n int n = s.size(), T = sqrt(n);\n \n queue<int> que;\n \n int ans = 0;\n for (int k = 0; k <= T; k++) { \n \n int pre = -1;\n for (int r = 0; r < n; r++) {\n... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "using ll = long long;\n\nclass Solution {\npublic:\n int numberOfSubstrings(string s) {\n ll n = s.size();\n\n vector<vector<ll>> pref(n, vector<ll> (2));\n\n bool t = 1;\n\n for(int i = 0; i < n; i++) {\n pref[i][s[i] - '0']++;\n if(i) pref[i][0] += pref[i - 1][0], pref[i][1] += pre... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "using ll = long long;\n\nclass Solution {\npublic:\n int numberOfSubstrings(string s) {\n ll n = s.size();\n\n vector<vector<ll>> pref(n, vector<ll> (2));\n\n bool t = 1;\n\n for(int i = 0; i < n; i++) {\n pref[i][s[i] - '0']++;\n if(i) pref[i][0] += pref[i - 1][0], pref[i][1] += pre... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n\n long long ans = 0;\n const int n = (int)s.length();\n for (int i = 0; i<n; ++i) {\n int j = i;\n if (s[j] == '0') continue;\n while (j<n-1 && s[j+1] == s[j])\n j++;\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n int ret = 0;\n\n for (int z=1; z + z*z <= n; ++z) {\n int prev = -1;\n int oneCnt = 0;\n deque<int> pq;\n\n for (int r=0; r<n; ++r) {\n if ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.length();\n int res = 0;\n\n for (int k = 1;k < sqrt(n);k ++) {\n queue<int> z;\n int lastzero = -1;\n int ones = 0;\n\n for (int r = 0;r < n;r ++) {\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int count{}, n = s.size();\n for(int zeros{1}; zeros < sqrt(n); ++zeros){\n deque<int> deq;\n int ones{}, last{-1};\n for(int i{}; i<n; ++i){\n if(s[i] == '0'){\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "class Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n = s.size();\n int res = 0;\n for (int i = 1; i*i < n; i++){\n int ones = 0;\n deque<int> zeroes;\n int prevzero = -1;\n for (int right = 0; right < n; right++){\n ... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "\nclass Solution {\npublic:\n int numberOfSubstrings(const string& s) {\n int n = s.size();\n int result = 0;\n \n // Iterate through possible zero counts (1 to sqrt(n))\n for (int k = 1; k <= static_cast<int>(sqrt(n)); ++k) {\n deque<int> zeros; // Queue t... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "\nclass Solution {\npublic:\n int numberOfSubstrings(const string& s) {\n int n = s.size();\n int result = 0;\n \n // Iterate through possible zero counts (1 to sqrt(n))\n for (int k = 1; k <= static_cast<int>(sqrt(n)); ++k) {\n deque<int> zeros; // Queue t... |
3,479 | <p>You are given a binary string <code>s</code>.</p>
<p>Return the number of <span data-keyword="substring-nonempty">substrings</span> with <strong>dominant</strong> ones.</p>
<p>A string has <strong>dominant</strong> ones if the number of ones in the string is <strong>greater than or equal to</strong> the <strong>sq... | 3 | {
"code": "static const int init = []{\n ios::sync_with_stdio(false);\n cin.tie(0);\n cout.tie(0);\n return 0;\n}();\n\nclass Solution {\npublic:\n int numberOfSubstrings(string s) {\n int n=s.length();\n int ans=0;\n for(int i=1;i*i<=n;i++) {\n deque<int> dq;\n ... |
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