Split (2)

train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the name of the department with the student that has the lowest GPA? # ### SQL: # # SELECT T2.dept_name FROM student AS T1 JOIN department AS T2 ON T1.dept_code = T2.dept_code ORDER BY stu_gpa LIMIT 1 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first name and gpa of the students whose gpa is lower than the average gpa of all students. # ### SQL: # # SELECT stu_fname , stu_gpa FROM student WHERE stu_gpa < (SELECT avg(stu_gpa) FROM student) # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the first name and GPA of every student that has a GPA lower than average? # ### SQL: # # SELECT stu_fname , stu_gpa FROM student WHERE stu_gpa < (SELECT avg(stu_gpa) FROM student) # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the name and address of the department that has the highest number of students. # ### SQL: # # SELECT T2.dept_name , T2.dept_address FROM student AS T1 JOIN department AS T2 ON T1.dept_code = T2.dept_code GROUP BY T1.dept_code ORDER BY count(*) DESC LIMIT 1 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the name and address of the department with the most students? # ### SQL: # # SELECT T2.dept_name , T2.dept_address FROM student AS T1 JOIN department AS T2 ON T1.dept_code = T2.dept_code GROUP BY T1.dept_code ORDER BY count(*) DESC LIMIT 1 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the name, address, number of students in the departments that have the top 3 highest number of students. # ### SQL: # # SELECT T2.dept_name , T2.dept_address , count() FROM student AS T1 JOIN department AS T2 ON T1.dept_code = T2.dept_code GROUP BY T1.dept_code ORDER BY count() DESC LIMIT 3 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the name, address, and number of students in the departments that have the 3 most students? # ### SQL: # # SELECT T2.dept_name , T2.dept_address , count() FROM student AS T1 JOIN department AS T2 ON T1.dept_code = T2.dept_code GROUP BY T1.dept_code ORDER BY count() DESC LIMIT 3 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first name and office of the professor who is in the history department and has a Ph.D. degree. # ### SQL: # # SELECT T1.emp_fname , T2.prof_office FROM employee AS T1 JOIN professor AS T2 ON T1.emp_num = T2.emp_num JOIN department AS T3 ON T3.dept_code = T2.dept_code WHERE T3.dept_name = 'History' AND T2.prof_high_degree = 'Ph.D.' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names and office of the professors who are in the history department and have a Ph.D? # ### SQL: # # SELECT T1.emp_fname , T2.prof_office FROM employee AS T1 JOIN professor AS T2 ON T1.emp_num = T2.emp_num JOIN department AS T3 ON T3.dept_code = T2.dept_code WHERE T3.dept_name = 'History' AND T2.prof_high_degree = 'Ph.D.' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names of all instructors who have taught some course and the course code. # ### SQL: # # SELECT T2.emp_fname , T1.crs_code FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names of all teachers who have taught a course and the corresponding course codes? # ### SQL: # # SELECT T2.emp_fname , T1.crs_code FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names of all instructors who have taught some course and the course description. # ### SQL: # # SELECT T2.emp_fname , T3.crs_description FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN course AS T3 ON T1.crs_code = T3.crs_code # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names of all teachers who have taught a course and the corresponding descriptions? # ### SQL: # # SELECT T2.emp_fname , T3.crs_description FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN course AS T3 ON T1.crs_code = T3.crs_code # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names and offices of all instructors who have taught some course and also find the course description. # ### SQL: # # SELECT T2.emp_fname , T4.prof_office , T3.crs_description FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN course AS T3 ON T1.crs_code = T3.crs_code JOIN professor AS T4 ON T2.emp_num = T4.emp_num # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names, office locations of all lecturers who have taught some course? # ### SQL: # # SELECT T2.emp_fname , T4.prof_office , T3.crs_description FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN course AS T3 ON T1.crs_code = T3.crs_code JOIN professor AS T4 ON T2.emp_num = T4.emp_num # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names and offices of all instructors who have taught some course and the course description and the department name. # ### SQL: # # SELECT T2.emp_fname , T4.prof_office , T3.crs_description , T5.dept_name FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN course AS T3 ON T1.crs_code = T3.crs_code JOIN professor AS T4 ON T2.emp_num = T4.emp_num JOIN department AS T5 ON T4.dept_code = T5.dept_code # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names, office locations, and departments of all instructors, and also what are the descriptions of the courses they teach? # ### SQL: # # SELECT T2.emp_fname , T4.prof_office , T3.crs_description , T5.dept_name FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN course AS T3 ON T1.crs_code = T3.crs_code JOIN professor AS T4 ON T2.emp_num = T4.emp_num JOIN department AS T5 ON T4.dept_code = T5.dept_code # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find names of all students who took some course and the course description. # ### SQL: # # SELECT T1.stu_fname , T1.stu_lname , T4.crs_description FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num JOIN CLASS AS T3 ON T2.class_code = T3.class_code JOIN course AS T4 ON T3.crs_code = T4.crs_code # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the names of all students who took a class and the corresponding course descriptions? # ### SQL: # # SELECT T1.stu_fname , T1.stu_lname , T4.crs_description FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num JOIN CLASS AS T3 ON T2.class_code = T3.class_code JOIN course AS T4 ON T3.crs_code = T4.crs_code # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find names of all students who took some course and got A or C. # ### SQL: # # SELECT T1.stu_fname , T1.stu_lname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num WHERE T2.enroll_grade = 'C' OR T2.enroll_grade = 'A' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the names of all students taking a course who received an A or C? # ### SQL: # # SELECT T1.stu_fname , T1.stu_lname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num WHERE T2.enroll_grade = 'C' OR T2.enroll_grade = 'A' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names of all professors in the Accounting department who is teaching some course and the class room. # ### SQL: # # SELECT T2.emp_fname , T1.class_room FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN professor AS T3 ON T2.emp_num = T3.emp_num JOIN department AS T4 ON T4.dept_code = T3.dept_code WHERE T4.dept_name = 'Accounting' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names of all Accounting professors who teach and what are the classrooms of the courses they teach? # ### SQL: # # SELECT T2.emp_fname , T1.class_room FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN professor AS T3 ON T2.emp_num = T3.emp_num JOIN department AS T4 ON T4.dept_code = T3.dept_code WHERE T4.dept_name = 'Accounting' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names and degree of all professors who are teaching some class in Computer Info. Systems department. # ### SQL: # # SELECT DISTINCT T2.emp_fname , T3.prof_high_degree FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN professor AS T3 ON T2.emp_num = T3.emp_num JOIN department AS T4 ON T4.dept_code = T3.dept_code WHERE T4.dept_name = 'Computer Info. Systems' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the different first names and highest degree attained for professors teaching in the Computer Information Systems department? # ### SQL: # # SELECT DISTINCT T2.emp_fname , T3.prof_high_degree FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num JOIN professor AS T3 ON T2.emp_num = T3.emp_num JOIN department AS T4 ON T4.dept_code = T3.dept_code WHERE T4.dept_name = 'Computer Info. Systems' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the last name of the student who got a grade A in the class with code 10018. # ### SQL: # # SELECT T1.stu_lname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num WHERE T2.enroll_grade = 'A' AND T2.class_code = 10018 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the last name of the student who received an A in the class with the code 10018? # ### SQL: # # SELECT T1.stu_lname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num WHERE T2.enroll_grade = 'A' AND T2.class_code = 10018 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first name and office of history professor who did not get a Ph.D. degree. # ### SQL: # # SELECT T2.emp_fname , T1.prof_office FROM professor AS T1 JOIN employee AS T2 ON T1.emp_num = T2.emp_num JOIN department AS T3 ON T1.dept_code = T3.dept_code WHERE T3.dept_name = 'History' AND T1.prof_high_degree != 'Ph.D.' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names and offices of history professors who don't have Ph.D.s? # ### SQL: # # SELECT T2.emp_fname , T1.prof_office FROM professor AS T1 JOIN employee AS T2 ON T1.emp_num = T2.emp_num JOIN department AS T3 ON T1.dept_code = T3.dept_code WHERE T3.dept_name = 'History' AND T1.prof_high_degree != 'Ph.D.' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names of professors who are teaching more than one class. # ### SQL: # # SELECT T2.emp_fname FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num GROUP BY T1.prof_num HAVING count(*) > 1 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names of all professors who teach more than one class? # ### SQL: # # SELECT T2.emp_fname FROM CLASS AS T1 JOIN employee AS T2 ON T1.prof_num = T2.emp_num GROUP BY T1.prof_num HAVING count(*) > 1 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the first names of students who took exactly one class. # ### SQL: # # SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num GROUP BY T2.stu_num HAVING count(*) = 1 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What are the first names of student who only took one course? # ### SQL: # # SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num GROUP BY T2.stu_num HAVING count(*) = 1 # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # Find the name of department that offers the class whose description has the word "Statistics". # ### SQL: # # SELECT T2.dept_name FROM course AS T1 JOIN department AS T2 ON T1.dept_code = T2.dept_code WHERE T1.crs_description LIKE '%Statistics%' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the name of the department that offers a course that has a description including the word "Statistics"? # ### SQL: # # SELECT T2.dept_name FROM course AS T1 JOIN department AS T2 ON T1.dept_code = T2.dept_code WHERE T1.crs_description LIKE '%Statistics%' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the first name of the student whose last name starting with the letter S and is taking ACCT-211 class? # ### SQL: # # SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num JOIN CLASS AS T3 ON T2.class_code = T3.class_code WHERE T3.crs_code = 'ACCT-211' AND T1.stu_lname LIKE 'S%' # ### End.
college_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # CLASS ( CLASS_CODE, CRS_CODE, CLASS_SECTION, CLASS_TIME, CLASS_ROOM, PROF_NUM ) # COURSE ( CRS_CODE, DEPT_CODE, CRS_DESCRIPTION, CRS_CREDIT ) # DEPARTMENT ( DEPT_CODE, DEPT_NAME, SCHOOL_CODE, EMP_NUM, DEPT_ADDRESS, DEPT_EXTENSION ) # EMPLOYEE ( EMP_NUM, EMP_LNAME, EMP_FNAME, EMP_INITIAL, EMP_JOBCODE, EMP_HIREDATE, EMP_DOB ) # ENROLL ( CLASS_CODE, STU_NUM, ENROLL_GRADE ) # PROFESSOR ( EMP_NUM, DEPT_CODE, PROF_OFFICE, PROF_EXTENSION, PROF_HIGH_DEGREE ) # STUDENT ( STU_NUM, STU_LNAME, STU_FNAME, STU_INIT, STU_DOB, STU_HRS, STU_CLASS, STU_GPA, STU_TRANSFER, DEPT_CODE, STU_PHONE, PROF_NUM ) # # CLASS.PROF_NUM can be joined with EMPLOYEE.EMP_NUM # CLASS.CRS_CODE can be joined with COURSE.CRS_CODE # COURSE.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # DEPARTMENT.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # ENROLL.STU_NUM can be joined with STUDENT.STU_NUM # ENROLL.CLASS_CODE can be joined with CLASS.CLASS_CODE # PROFESSOR.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # PROFESSOR.EMP_NUM can be joined with EMPLOYEE.EMP_NUM # STUDENT.DEPT_CODE can be joined with DEPARTMENT.DEPT_CODE # ### Question: # # What is the first name of the student whose last name starts with the letter S and is taking ACCT-211? # ### SQL: # # SELECT T1.stu_fname FROM student AS T1 JOIN enroll AS T2 ON T1.stu_num = T2.stu_num JOIN CLASS AS T3 ON T2.class_code = T3.class_code WHERE T3.crs_code = 'ACCT-211' AND T1.stu_lname LIKE 'S%' # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # How many clubs are there? # ### SQL: # # SELECT count(*) FROM club # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the total number of clubs? # ### SQL: # # SELECT count(*) FROM club # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List the distinct region of clubs in ascending alphabetical order. # ### SQL: # # SELECT DISTINCT Region FROM club ORDER BY Region ASC # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the different regions of clubs in ascending alphabetical order? # ### SQL: # # SELECT DISTINCT Region FROM club ORDER BY Region ASC # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the average number of gold medals for clubs? # ### SQL: # # SELECT avg(Gold) FROM club_rank # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the average number of gold medals for a club? # ### SQL: # # SELECT avg(Gold) FROM club_rank # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the types and countries of competitions? # ### SQL: # # SELECT Competition_type , Country FROM competition # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the types of every competition and in which countries are they located? # ### SQL: # # SELECT Competition_type , Country FROM competition # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the distinct years in which the competitions type is not "Tournament"? # ### SQL: # # SELECT DISTINCT YEAR FROM competition WHERE Competition_type != "Tournament" # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the different years for all competitions that are not of type equal to tournament? # ### SQL: # # SELECT DISTINCT YEAR FROM competition WHERE Competition_type != "Tournament" # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the maximum and minimum number of silver medals for clubs. # ### SQL: # # SELECT max(Silver) , min(Silver) FROM club_rank # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the maximum and minimum number of silver medals for all the clubs? # ### SQL: # # SELECT max(Silver) , min(Silver) FROM club_rank # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # How many clubs have total medals less than 10? # ### SQL: # # SELECT count(*) FROM club_rank WHERE Total < 10 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the total number of clubs that have less than 10 medals in total? # ### SQL: # # SELECT count(*) FROM club_rank WHERE Total < 10 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List all club names in ascending order of start year. # ### SQL: # # SELECT name FROM club ORDER BY Start_year ASC # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the names of all the clubs starting with the oldest? # ### SQL: # # SELECT name FROM club ORDER BY Start_year ASC # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List all club names in descending alphabetical order. # ### SQL: # # SELECT name FROM club ORDER BY name DESC # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the names of all the clubs ordered in descending alphabetical order? # ### SQL: # # SELECT name FROM club ORDER BY name DESC # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # Please show the names and the players of clubs. # ### SQL: # # SELECT T1.name , T2.Player_id FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the names and players of all the clubs? # ### SQL: # # SELECT T1.name , T2.Player_id FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # Show the names of clubs that have players with position "Right Wing". # ### SQL: # # SELECT T1.name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T2.Position = "Right Wing" # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the names of the clubs that have players in the position of "Right Wing"? # ### SQL: # # SELECT T1.name FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T2.Position = "Right Wing" # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the average points of players from club with name "AIB". # ### SQL: # # SELECT avg(T2.Points) FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T1.name = "AIB" # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the average number of points for players from the "AIB" club? # ### SQL: # # SELECT avg(T2.Points) FROM club AS T1 JOIN player AS T2 ON T1.Club_ID = T2.Club_ID WHERE T1.name = "AIB" # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List the position of players and the average number of points of players of each position. # ### SQL: # # SELECT POSITION , avg(Points) FROM player GROUP BY POSITION # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # For each position, what is the average number of points for players in that position? # ### SQL: # # SELECT POSITION , avg(Points) FROM player GROUP BY POSITION # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List the position of players with average number of points scored by players of that position bigger than 20. # ### SQL: # # SELECT POSITION FROM player GROUP BY name HAVING avg(Points) >= 20 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the positions of players whose average number of points scored by that position is larger than 20? # ### SQL: # # SELECT POSITION FROM player GROUP BY name HAVING avg(Points) >= 20 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List the types of competition and the number of competitions of each type. # ### SQL: # # SELECT Competition_type , COUNT(*) FROM competition GROUP BY Competition_type # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the types of competition and number of competitions for that type? # ### SQL: # # SELECT Competition_type , COUNT(*) FROM competition GROUP BY Competition_type # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List the most common type of competition. # ### SQL: # # SELECT Competition_type FROM competition GROUP BY Competition_type ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the most common competition type? # ### SQL: # # SELECT Competition_type FROM competition GROUP BY Competition_type ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List the types of competition that have at most five competitions of that type. # ### SQL: # # SELECT Competition_type FROM competition GROUP BY Competition_type HAVING COUNT(*) <= 5 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the types of competition that have most 5 competitions for that type? # ### SQL: # # SELECT Competition_type FROM competition GROUP BY Competition_type HAVING COUNT(*) <= 5 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # List the names of clubs that do not have any players. # ### SQL: # # SELECT name FROM CLub WHERE Club_ID NOT IN (SELECT Club_ID FROM player) # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the names of all clubs that do not have any players? # ### SQL: # # SELECT name FROM CLub WHERE Club_ID NOT IN (SELECT Club_ID FROM player) # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the positions with both players having more than 20 points and less than 10 points. # ### SQL: # # SELECT POSITION FROM player WHERE Points > 20 INTERSECT SELECT POSITION FROM player WHERE Points < 10 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the positions of both players that have more than 20 20 points and less than 10 points? # ### SQL: # # SELECT POSITION FROM player WHERE Points > 20 INTERSECT SELECT POSITION FROM player WHERE Points < 10 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # Show total points of all players. # ### SQL: # # SELECT sum(Points) FROM player # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the total number of points for all players? # ### SQL: # # SELECT sum(Points) FROM player # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # how many different positions are there? # ### SQL: # # SELECT count(DISTINCT POSITION) FROM player # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # How many different position for players are listed? # ### SQL: # # SELECT count(DISTINCT POSITION) FROM player # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # what are the name of players who get more than the average points. # ### SQL: # # SELECT name FROM player WHERE points > (SELECT avg(points) FROM player) # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the names of all players that got more than the average number of points? # ### SQL: # # SELECT name FROM player WHERE points > (SELECT avg(points) FROM player) # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # find the number of players whose points are lower than 30 in each position. # ### SQL: # # SELECT count(*) , POSITION FROM player WHERE points < 30 GROUP BY POSITION # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What is the number of players who have points less than 30 for each position? # ### SQL: # # SELECT count(*) , POSITION FROM player WHERE points < 30 GROUP BY POSITION # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # which country did participated in the most number of Tournament competitions? # ### SQL: # # SELECT country FROM competition WHERE competition_type = 'Tournament' GROUP BY country ORDER BY count(*) DESC LIMIT 1 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # what is the name of the country that participated in the most tournament competitions? # ### SQL: # # SELECT country FROM competition WHERE competition_type = 'Tournament' GROUP BY country ORDER BY count(*) DESC LIMIT 1 # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # which countries did participated in both Friendly and Tournament type competitions. # ### SQL: # # SELECT country FROM competition WHERE competition_type = 'Friendly' INTERSECT SELECT country FROM competition WHERE competition_type = 'Tournament' # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the countries that participated in both friendly and tournament type competitions? # ### SQL: # # SELECT country FROM competition WHERE competition_type = 'Friendly' INTERSECT SELECT country FROM competition WHERE competition_type = 'Tournament' # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # Find the countries that have never participated in any competition with Friendly type. # ### SQL: # # SELECT country FROM competition EXCEPT SELECT country FROM competition WHERE competition_type = 'Friendly' # ### End.
sports_competition	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # club ( Club_ID, name, Region, Start_year ) # club_rank ( Rank, Club_ID, Gold, Silver, Bronze, Total ) # player ( Player_ID, name, Position, Club_ID, Apps, Tries, Goals, Points ) # competition ( Competition_ID, Year, Competition_type, Country ) # competition_result ( Competition_ID, Club_ID_1, Club_ID_2, Score ) # # club_rank.Club_ID can be joined with club.Club_ID # player.Club_ID can be joined with club.Club_ID # competition_result.Competition_ID can be joined with competition.Competition_ID # competition_result.Club_ID_2 can be joined with club.Club_ID # competition_result.Club_ID_1 can be joined with club.Club_ID # ### Question: # # What are the countries that have never participated in any friendly-type competitions? # ### SQL: # # SELECT country FROM competition EXCEPT SELECT country FROM competition WHERE competition_type = 'Friendly' # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # How many furniture components are there in total? # ### SQL: # # SELECT sum(num_of_component) FROM furniture # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # Return the name and id of the furniture with the highest market rate. # ### SQL: # # SELECT name , furniture_id FROM furniture ORDER BY market_rate DESC LIMIT 1 # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # find the total market rate of the furnitures that have the top 2 market shares. # ### SQL: # # SELECT sum(market_rate) FROM furniture ORDER BY market_rate DESC LIMIT 2 # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # Find the component amounts and names of all furnitures that have more than 10 components. # ### SQL: # # SELECT Num_of_Component , name FROM furniture WHERE Num_of_Component > 10 # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # Find the name and component amount of the least popular furniture. # ### SQL: # # SELECT name , Num_of_Component FROM furniture ORDER BY market_rate LIMIT 1 # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # Find the names of furnitures whose prices are lower than the highest price. # ### SQL: # # SELECT t1.name FROM furniture AS t1 JOIN furniture_manufacte AS t2 ON t1.Furniture_ID = t2.Furniture_ID WHERE t2.Price_in_Dollar < (SELECT max(Price_in_Dollar) FROM furniture_manufacte) # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # Which manufacturer has the most number of shops? List its name and year of opening. # ### SQL: # # SELECT open_year , name FROM manufacturer ORDER BY num_of_shops DESC LIMIT 1 # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # Find the average number of factories for the manufacturers that have more than 20 shops. # ### SQL: # # SELECT avg(Num_of_Factories) FROM manufacturer WHERE num_of_shops > 20 # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # List all manufacturer names and ids ordered by their opening year. # ### SQL: # # SELECT name , manufacturer_id FROM manufacturer ORDER BY open_year # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # Give me the name and year of opening of the manufacturers that have either less than 10 factories or more than 10 shops. # ### SQL: # # SELECT name , open_year FROM manufacturer WHERE num_of_shops > 10 OR Num_of_Factories < 10 # ### End.
manufacturer	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # manufacturer ( Manufacturer_ID, Open_Year, Name, Num_of_Factories, Num_of_Shops ) # furniture ( Furniture_ID, Name, Num_of_Component, Market_Rate ) # furniture_manufacte ( Manufacturer_ID, Furniture_ID, Price_in_Dollar ) # # furniture_manufacte.Furniture_ID can be joined with furniture.Furniture_ID # furniture_manufacte.Manufacturer_ID can be joined with manufacturer.Manufacturer_ID # ### Question: # # what is the average number of factories and maximum number of shops for manufacturers that opened before 1990. # ### SQL: # # SELECT max(num_of_shops) , avg(Num_of_Factories) FROM manufacturer WHERE open_year < 1990 # ### End.

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