Split (2)

train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the full names and hire dates for employees in the same department as someone with the first name Clara? # ### SQL: # # SELECT first_name , last_name , hire_date FROM employees WHERE department_id = (SELECT department_id FROM employees WHERE first_name = "Clara") # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the employee name ( first name and last name ) and hire date for all employees in the same department as Clara excluding Clara. # ### SQL: # # SELECT first_name , last_name , hire_date FROM employees WHERE department_id = ( SELECT department_id FROM employees WHERE first_name = "Clara") AND first_name != "Clara" # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the full names and hire dates for employees in the same department as someone with the first name Clara, not including Clara? # ### SQL: # # SELECT first_name , last_name , hire_date FROM employees WHERE department_id = ( SELECT department_id FROM employees WHERE first_name = "Clara") AND first_name != "Clara" # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the employee number and name( first name and last name ) for all employees who work in a department with any employee whose name contains a ’T’. # ### SQL: # # SELECT employee_id , first_name , last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' ) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the ids and full names for employees who work in a department that has someone with a first name that contains the letter T? # ### SQL: # # SELECT employee_id , first_name , last_name FROM employees WHERE department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%T%' ) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the employee number, name( first name and last name ), and salary for all employees who earn more than the average salary and who work in a department with any employee with a 'J' in their first name. # ### SQL: # # SELECT employee_id , first_name , last_name , salary FROM employees WHERE salary > ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%') # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the ids, full names, and salaries for employees making more than average and who work in a department with employees who have the letter J in their first name? # ### SQL: # # SELECT employee_id , first_name , last_name , salary FROM employees WHERE salary > ( SELECT AVG (salary) FROM employees ) AND department_id IN ( SELECT department_id FROM employees WHERE first_name LIKE '%J%') # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the employee number and job id for all employees whose salary is smaller than any salary of those employees whose job title is MK_MAN. # ### SQL: # # SELECT employee_id , job_id FROM employees WHERE salary < ( SELECT min(salary) FROM employees WHERE job_id = 'MK_MAN' ) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the employee ids and job ids for employees who make less than the lowest earning employee with title MK_MAN? # ### SQL: # # SELECT employee_id , job_id FROM employees WHERE salary < ( SELECT min(salary) FROM employees WHERE job_id = 'MK_MAN' ) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the employee number, name( first name and last name ) and job title for all employees whose salary is more than any salary of those employees whose job title is PU_MAN. # ### SQL: # # SELECT employee_id , first_name , last_name , job_id FROM employees WHERE salary > ( SELECT max(salary) FROM employees WHERE job_id = 'PU_MAN' ) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the employee ids, full names, and job ids for employees who make more than the highest earning employee with title PU_MAN? # ### SQL: # # SELECT employee_id , first_name , last_name , job_id FROM employees WHERE salary > ( SELECT max(salary) FROM employees WHERE job_id = 'PU_MAN' ) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the department id and the total salary for those departments which contains at least two employees. # ### SQL: # # SELECT department_id , SUM(salary) FROM employees GROUP BY department_id HAVING count(*) >= 2 # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are total salaries and department id for each department that has more than 2 employees? # ### SQL: # # SELECT department_id , SUM(salary) FROM employees GROUP BY department_id HAVING count(*) >= 2 # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display all the information of those employees who did not have any job in the past. # ### SQL: # # SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What is all the information about employees who have never had a job in the past? # ### SQL: # # SELECT * FROM employees WHERE employee_id NOT IN (SELECT employee_id FROM job_history) # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the department ID, full name (first and last name), salary for those employees who is highest salary in every department. # ### SQL: # # SELECT first_name , last_name , salary , department_id , MAX(salary) FROM employees GROUP BY department_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the department ids, full names, and salaries for employees who make the most in their departments? # ### SQL: # # SELECT first_name , last_name , salary , department_id , MAX(salary) FROM employees GROUP BY department_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the first and last name, department, city, and state province for each employee. # ### SQL: # # SELECT T1.first_name , T1.last_name , T2.department_name , T3.city , T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the full names, departments, cities, and state provinces for each employee? # ### SQL: # # SELECT T1.first_name , T1.last_name , T2.department_name , T3.city , T3.state_province FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display those employees who contain a letter z to their first name and also display their last name, city. # ### SQL: # # SELECT T1.first_name , T1.last_name , T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T1.first_name LIKE '%z%' # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the full names and cities of employees who have the letter Z in their first names? # ### SQL: # # SELECT T1.first_name , T1.last_name , T3.city FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T1.first_name LIKE '%z%' # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the department name, city, and state province for each department. # ### SQL: # # SELECT T1.department_name , T2.city , T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id = T1.location_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the department names, cities, and state provinces for each department? # ### SQL: # # SELECT T1.department_name , T2.city , T2.state_province FROM departments AS T1 JOIN locations AS T2 ON T2.location_id = T1.location_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the full name (first and last name ) of employee with ID and name of the country presently where (s)he is working. # ### SQL: # # SELECT T1.first_name , T1.last_name , T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What the full names, ids of each employee and the name of the country they are in? # ### SQL: # # SELECT T1.first_name , T1.last_name , T1.employee_id , T4.country_name FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id JOIN countries AS T4 ON T3.country_id = T4.country_id # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the department name and number of employees in each of the department. # ### SQL: # # SELECT department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY department_name # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are the department names and how many employees work in each of them? # ### SQL: # # SELECT department_name , COUNT(*) FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id GROUP BY department_name # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # display the full name (first and last name), and salary of those employees who working in any department located in London. # ### SQL: # # SELECT first_name , last_name , salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T3.city = 'London' # ### End.
hr_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # regions ( REGION_ID, REGION_NAME ) # countries ( COUNTRY_ID, COUNTRY_NAME, REGION_ID ) # departments ( DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID ) # jobs ( JOB_ID, JOB_TITLE, MIN_SALARY, MAX_SALARY ) # employees ( EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE, JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID ) # job_history ( EMPLOYEE_ID, START_DATE, END_DATE, JOB_ID, DEPARTMENT_ID ) # locations ( LOCATION_ID, STREET_ADDRESS, POSTAL_CODE, CITY, STATE_PROVINCE, COUNTRY_ID ) # # countries.REGION_ID can be joined with regions.REGION_ID # employees.JOB_ID can be joined with jobs.JOB_ID # employees.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.JOB_ID can be joined with jobs.JOB_ID # job_history.DEPARTMENT_ID can be joined with departments.DEPARTMENT_ID # job_history.EMPLOYEE_ID can be joined with employees.EMPLOYEE_ID # locations.COUNTRY_ID can be joined with countries.COUNTRY_ID # ### Question: # # What are full names and salaries of employees working in the city of London? # ### SQL: # # SELECT first_name , last_name , salary FROM employees AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id JOIN locations AS T3 ON T2.location_id = T3.location_id WHERE T3.city = 'London' # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the name of the song that was released in the most recent year? # ### SQL: # # SELECT song_name , releasedate FROM song ORDER BY releasedate DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the name of the song that was released most recently? # ### SQL: # # SELECT song_name , releasedate FROM song ORDER BY releasedate DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the id of the longest song? # ### SQL: # # SELECT f_id FROM files ORDER BY duration DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Find the id of the song that lasts the longest. # ### SQL: # # SELECT f_id FROM files ORDER BY duration DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Find the names of all English songs. # ### SQL: # # SELECT song_name FROM song WHERE languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all songs in English? # ### SQL: # # SELECT song_name FROM song WHERE languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the id of songs whose format is mp3. # ### SQL: # # SELECT f_id FROM files WHERE formats = "mp3" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the id of all the files in mp3 format? # ### SQL: # # SELECT f_id FROM files WHERE formats = "mp3" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # List the name and country of origin for all singers who have produced songs with rating above 9. # ### SQL: # # SELECT DISTINCT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.rating > 9 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the different names and countries of origins for all artists whose song ratings are above 9? # ### SQL: # # SELECT DISTINCT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.rating > 9 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # List the file size and format for all songs that have resolution lower than 800. # ### SQL: # # SELECT DISTINCT T1.file_size , T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T2.resolution < 800 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the file sizes and formats for all songs with a resolution lower than 800? # ### SQL: # # SELECT DISTINCT T1.file_size , T1.formats FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T2.resolution < 800 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the name of the artist who produced the shortest song? # ### SQL: # # SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id = T2.f_id ORDER BY T2.duration LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of the artists who sang the shortest song? # ### SQL: # # SELECT T1.artist_name FROM song AS T1 JOIN files AS T2 ON T1.f_id = T2.f_id ORDER BY T2.duration LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names and countries of origin for the artists who produced the top three highly rated songs. # ### SQL: # # SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.rating DESC LIMIT 3 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of the singers who sang the top 3 most highly rated songs and what countries do they hail from? # ### SQL: # # SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.rating DESC LIMIT 3 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # How many songs have 4 minute duration? # ### SQL: # # SELECT count(*) FROM files WHERE duration LIKE "4:%" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the count of the songs that last approximately 4 minutes? # ### SQL: # # SELECT count(*) FROM files WHERE duration LIKE "4:%" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # How many artists are from Bangladesh? # ### SQL: # # SELECT count(*) FROM artist WHERE country = "Bangladesh" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # How many Bangladeshi artists are listed? # ### SQL: # # SELECT count(*) FROM artist WHERE country = "Bangladesh" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the average rating of songs produced by female artists? # ### SQL: # # SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # How many songs, on average, are sung by a female artist? # ### SQL: # # SELECT avg(T2.rating) FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the most popular file format? # ### SQL: # # SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Find the file format that is used by the most files. # ### SQL: # # SELECT formats FROM files GROUP BY formats ORDER BY COUNT (*) DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Find the names of the artists who are from UK and have produced English songs. # ### SQL: # # SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT artist_name FROM song WHERE languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of the artists that are from the UK and sang songs in English? # ### SQL: # # SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT artist_name FROM song WHERE languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Find the id of songs that are available in mp4 format and have resolution lower than 1000. # ### SQL: # # SELECT f_id FROM files WHERE formats = "mp4" INTERSECT SELECT f_id FROM song WHERE resolution < 1000 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the id of the files that are available in the format of mp4 and a resolution smaller than 1000? # ### SQL: # # SELECT f_id FROM files WHERE formats = "mp4" INTERSECT SELECT f_id FROM song WHERE resolution < 1000 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the country of origin of the artist who is female and produced a song in Bangla? # ### SQL: # # SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female" AND T2.languages = "bangla" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What countries are the female artists who sung in the language Bangla from? # ### SQL: # # SELECT T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T1.gender = "Female" AND T2.languages = "bangla" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the average duration of songs that have mp3 format and resolution below 800? # ### SQL: # # SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" AND T2.resolution < 800 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the average song duration for the songs that are in mp3 format and whose resolution below 800? # ### SQL: # # SELECT avg(T1.duration) FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" AND T2.resolution < 800 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the number of artists for each gender? # ### SQL: # # SELECT count(*) , gender FROM artist GROUP BY gender # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # How many artists are male and how many are female? # ### SQL: # # SELECT count(*) , gender FROM artist GROUP BY gender # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the average rating of songs for each language? # ### SQL: # # SELECT avg(rating) , languages FROM song GROUP BY languages # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the average song rating for each language? # ### SQL: # # SELECT avg(rating) , languages FROM song GROUP BY languages # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Return the gender and name of artist who produced the song with the lowest resolution. # ### SQL: # # SELECT T1.gender , T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.resolution LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the gender and name of the artist who sang the song with the smallest resolution? # ### SQL: # # SELECT T1.gender , T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name ORDER BY T2.resolution LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # For each file format, return the number of artists who released songs in that format. # ### SQL: # # SELECT count(*) , formats FROM files GROUP BY formats # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # How many songs were released for each format? # ### SQL: # # SELECT count(*) , formats FROM files GROUP BY formats # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Find the distinct names of all songs that have a higher resolution than some songs in English. # ### SQL: # # SELECT DISTINCT song_name FROM song WHERE resolution > (SELECT min(resolution) FROM song WHERE languages = "english") # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the different names for all songs that have a higher resolution than English songs? # ### SQL: # # SELECT DISTINCT song_name FROM song WHERE resolution > (SELECT min(resolution) FROM song WHERE languages = "english") # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all songs that have a lower rating than some song of blues genre? # ### SQL: # # SELECT song_name FROM song WHERE rating < (SELECT max(rating) FROM song WHERE genre_is = "blues") # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of the songs that have a lower rating than at least one blues song? # ### SQL: # # SELECT song_name FROM song WHERE rating < (SELECT max(rating) FROM song WHERE genre_is = "blues") # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the name and country of origin of the artist who released a song that has "love" in its title? # ### SQL: # # SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.song_name LIKE "%love%" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of the artists who released a song that has the word love in its title, and where are the artists from? # ### SQL: # # SELECT T1.artist_name , T1.country FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.song_name LIKE "%love%" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # List the name and gender for all artists who released songs in March. # ### SQL: # # SELECT T1.artist_name , T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.releasedate LIKE "%Mar%" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names and genders of all artists who released songs in the month of March? # ### SQL: # # SELECT T1.artist_name , T1.gender FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.releasedate LIKE "%Mar%" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # List the names of all genres in alphabetical oder, together with its ratings. # ### SQL: # # SELECT g_name , rating FROM genre ORDER BY g_name # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all genres in alphabetical order, combined with its ratings? # ### SQL: # # SELECT g_name , rating FROM genre ORDER BY g_name # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Give me a list of the names of all songs ordered by their resolution. # ### SQL: # # SELECT song_name FROM song ORDER BY resolution # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all songs that are ordered by their resolution numbers? # ### SQL: # # SELECT song_name FROM song ORDER BY resolution # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the ids of songs that are available in either mp4 format or have resolution above 720? # ### SQL: # # SELECT f_id FROM files WHERE formats = "mp4" UNION SELECT f_id FROM song WHERE resolution > 720 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the ids of all songs that are available on mp4 or have a higher resolution than 720? # ### SQL: # # SELECT f_id FROM files WHERE formats = "mp4" UNION SELECT f_id FROM song WHERE resolution > 720 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # List the names of all songs that have 4 minute duration or are in English. # ### SQL: # # SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all songs that are approximately 4 minutes long or are in English? # ### SQL: # # SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.duration LIKE "4:%" UNION SELECT song_name FROM song WHERE languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the language used most often in the songs? # ### SQL: # # SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the languages that are used most often in songs? # ### SQL: # # SELECT languages FROM song GROUP BY languages ORDER BY count(*) DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the language that was used most often in songs with resolution above 500? # ### SQL: # # SELECT artist_name FROM song WHERE resolution > 500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the name of the artist, for each language, that has the most songs with a higher resolution than 500? # ### SQL: # # SELECT artist_name FROM song WHERE resolution > 500 GROUP BY languages ORDER BY count(*) DESC LIMIT 1 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of artists who are Male and are from UK? # ### SQL: # # SELECT artist_name FROM artist WHERE country = "UK" AND gender = "Male" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all male British artists? # ### SQL: # # SELECT artist_name FROM artist WHERE country = "UK" AND gender = "Male" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Find the names of songs whose genre is modern or language is English. # ### SQL: # # SELECT song_name FROM song WHERE genre_is = "modern" OR languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of the songs that are modern or sung in English? # ### SQL: # # SELECT song_name FROM song WHERE genre_is = "modern" OR languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Return the names of songs for which format is mp3 and resolution is below 1000. # ### SQL: # # SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" INTERSECT SELECT song_name FROM song WHERE resolution < 1000 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all songs that are in mp3 format and have a resolution lower than 1000? # ### SQL: # # SELECT T2.song_name FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.formats = "mp3" INTERSECT SELECT song_name FROM song WHERE resolution < 1000 # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # Return the names of singers who are from UK and released an English song. # ### SQL: # # SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the names of all singers that are from the UK and released a song in English? # ### SQL: # # SELECT artist_name FROM artist WHERE country = "UK" INTERSECT SELECT T1.artist_name FROM artist AS T1 JOIN song AS T2 ON T1.artist_name = T2.artist_name WHERE T2.languages = "english" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the average rating and resolution of songs that are in Bangla? # ### SQL: # # SELECT avg(rating) , avg(resolution) FROM song WHERE languages = "bangla" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What is the average rating and resolution of all bangla songs? # ### SQL: # # SELECT avg(rating) , avg(resolution) FROM song WHERE languages = "bangla" # ### End.
music_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # genre ( g_name, rating, most_popular_in ) # artist ( artist_name, country, gender, preferred_genre ) # files ( f_id, artist_name, file_size, duration, formats ) # song ( song_name, artist_name, country, f_id, genre_is, rating, languages, releasedate, resolution ) # # artist.preferred_genre can be joined with genre.g_name # files.artist_name can be joined with artist.artist_name # song.genre_is can be joined with genre.g_name # song.f_id can be joined with files.f_id # song.artist_name can be joined with artist.artist_name # ### Question: # # What are the maximum and minimum resolution of songs whose duration is 3 minutes? # ### SQL: # # SELECT max(T2.resolution) , min(T2.resolution) FROM files AS T1 JOIN song AS T2 ON T1.f_id = T2.f_id WHERE T1.duration LIKE "3:%" # ### End.

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