Split (2)

train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many different types of sports do we offer? # ### SQL: # # SELECT count(DISTINCT sportname) FROM Sportsinfo # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many students play sports? # ### SQL: # # SELECT count(DISTINCT StuID) FROM Sportsinfo # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many different students are involved in sports? # ### SQL: # # SELECT count(DISTINCT StuID) FROM Sportsinfo # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # List ids for all student who are on scholarship. # ### SQL: # # SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids for all sporty students who are on scholarship? # ### SQL: # # SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show last names for all student who are on scholarship. # ### SQL: # # SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the last names for all scholarship students? # ### SQL: # # SELECT T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many games are played for all students? # ### SQL: # # SELECT sum(gamesplayed) FROM Sportsinfo # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the total number of games played? # ### SQL: # # SELECT sum(gamesplayed) FROM Sportsinfo # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many games are played for all football games by students on scholarship? # ### SQL: # # SELECT sum(gamesplayed) FROM Sportsinfo WHERE sportname = "Football" AND onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the total number of all football games played by scholarship students? # ### SQL: # # SELECT sum(gamesplayed) FROM Sportsinfo WHERE sportname = "Football" AND onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all sport name and the number of students. # ### SQL: # # SELECT sportname , count(*) FROM Sportsinfo GROUP BY sportname # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many students play each sport? # ### SQL: # # SELECT sportname , count(*) FROM Sportsinfo GROUP BY sportname # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all student IDs with the number of sports and total number of games played # ### SQL: # # SELECT StuID , count(*) , sum(gamesplayed) FROM Sportsinfo GROUP BY StuID # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids of all students along with how many sports and games did they play? # ### SQL: # # SELECT StuID , count(*) , sum(gamesplayed) FROM Sportsinfo GROUP BY StuID # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all student IDs with more than total 10 hours per week on all sports played. # ### SQL: # # SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING sum(hoursperweek) > 10 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the student IDs for everybody who worked for more than 10 hours per week on all sports? # ### SQL: # # SELECT StuID FROM Sportsinfo GROUP BY StuID HAVING sum(hoursperweek) > 10 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the first name and last name of the student who have most number of sports? # ### SQL: # # SELECT T2.Fname , T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY count(*) DESC LIMIT 1 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the first and last name of the student who played the most sports? # ### SQL: # # SELECT T2.Fname , T2.Lname FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID ORDER BY count(*) DESC LIMIT 1 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Which sport has most number of students on scholarship? # ### SQL: # # SELECT sportname FROM Sportsinfo WHERE onscholarship = 'Y' GROUP BY sportname ORDER BY count(*) DESC LIMIT 1 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the sport with the most scholarship students? # ### SQL: # # SELECT sportname FROM Sportsinfo WHERE onscholarship = 'Y' GROUP BY sportname ORDER BY count(*) DESC LIMIT 1 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show student ids who don't have any sports. # ### SQL: # # SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids of all students who don't play sports? # ### SQL: # # SELECT StuID FROM Student EXCEPT SELECT StuID FROM Sportsinfo # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show student ids who are on scholarship and have major 600. # ### SQL: # # SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the student ids for those on scholarship in major number 600? # ### SQL: # # SELECT StuID FROM Student WHERE major = 600 INTERSECT SELECT StuID FROM Sportsinfo WHERE onscholarship = 'Y' # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show student ids who are female and play football. # ### SQL: # # SELECT StuID FROM Student WHERE sex = 'F' INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = "Football" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids of all female students who play football? # ### SQL: # # SELECT StuID FROM Student WHERE sex = 'F' INTERSECT SELECT StuID FROM Sportsinfo WHERE sportname = "Football" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all male student ids who don't play football. # ### SQL: # # SELECT StuID FROM Student WHERE sex = 'M' EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = "Football" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids of all male students who do not play football? # ### SQL: # # SELECT StuID FROM Student WHERE sex = 'M' EXCEPT SELECT StuID FROM Sportsinfo WHERE sportname = "Football" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show total hours per week and number of games played for student David Shieber. # ### SQL: # # SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.Fname = "David" AND T2.Lname = "Shieber" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the total number of hours per work and number of games played by David Shieber? # ### SQL: # # SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.Fname = "David" AND T2.Lname = "Shieber" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show total hours per week and number of games played for students under 20. # ### SQL: # # SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.age < 20 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the total number of hours per week and number of games played by students under 20? # ### SQL: # # SELECT sum(hoursperweek) , sum(gamesplayed) FROM Sportsinfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T2.age < 20 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many students play video games? # ### SQL: # # SELECT count(DISTINCT StuID) FROM Plays_games # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # How many different students play games? # ### SQL: # # SELECT count(DISTINCT StuID) FROM Plays_games # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show ids of students who don't play video game. # ### SQL: # # SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids of all students who are not video game players? # ### SQL: # # SELECT StuID FROM Student EXCEPT SELECT StuID FROM Plays_games # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show ids of students who play video game and play sports. # ### SQL: # # SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids of all students who played video games and sports? # ### SQL: # # SELECT StuID FROM Sportsinfo INTERSECT SELECT StuID FROM Plays_games # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all game ids and the number of hours played. # ### SQL: # # SELECT gameid , sum(hours_played) FROM Plays_games GROUP BY gameid # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are ids and total number of hours played for each game? # ### SQL: # # SELECT gameid , sum(hours_played) FROM Plays_games GROUP BY gameid # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all student ids and the number of hours played. # ### SQL: # # SELECT Stuid , sum(hours_played) FROM Plays_games GROUP BY Stuid # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the ids of all students and number of hours played? # ### SQL: # # SELECT Stuid , sum(hours_played) FROM Plays_games GROUP BY Stuid # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show the game name that has most number of hours played. # ### SQL: # # SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid ORDER BY sum(hours_played) DESC LIMIT 1 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the name of the game that has been played the most? # ### SQL: # # SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid ORDER BY sum(hours_played) DESC LIMIT 1 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all game names played by at least 1000 hours. # ### SQL: # # SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid HAVING sum(hours_played) >= 1000 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the names of all the games that have been played for at least 1000 hours? # ### SQL: # # SELECT gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid GROUP BY T1.gameid HAVING sum(hours_played) >= 1000 # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Show all game names played by Linda Smith # ### SQL: # # SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid JOIN Student AS T3 ON T3.Stuid = T1.Stuid WHERE T3.Lname = "Smith" AND T3.Fname = "Linda" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the names of all games played by Linda Smith? # ### SQL: # # SELECT Gname FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.gameid = T2.gameid JOIN Student AS T3 ON T3.Stuid = T1.Stuid WHERE T3.Lname = "Smith" AND T3.Fname = "Linda" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Find the last and first name of students who are playing Football or Lacrosse. # ### SQL: # # SELECT T2.lname , T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = "Football" OR T1.SportName = "Lacrosse" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What is the first and last name of all students who play Football or Lacrosse? # ### SQL: # # SELECT T2.lname , T2.fname FROM SportsInfo AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.SportName = "Football" OR T1.SportName = "Lacrosse" # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Find the first name and age of the students who are playing both Football and Lacrosse. # ### SQL: # # SELECT fname , age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = "Football" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = "Lacrosse") # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # What are the first names and ages of all students who are playing both Football and Lacrosse? # ### SQL: # # SELECT fname , age FROM Student WHERE StuID IN (SELECT StuID FROM Sportsinfo WHERE SportName = "Football" INTERSECT SELECT StuID FROM Sportsinfo WHERE SportName = "Lacrosse") # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # Find the last name and gender of the students who are playing both Call of Destiny and Works of Widenius games. # ### SQL: # # SELECT lname , sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Call of Destiny" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Works of Widenius") # ### End.
game_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Video_Games ( GameID, GName, GType ) # Plays_Games ( StuID, GameID, Hours_Played ) # SportsInfo ( StuID, SportName, HoursPerWeek, GamesPlayed, OnScholarship ) # # Plays_Games.StuID can be joined with Student.StuID # Plays_Games.GameID can be joined with Video_Games.GameID # SportsInfo.StuID can be joined with Student.StuID # ### Question: # # what is the last name and gender of all students who played both Call of Destiny and Works of Widenius? # ### SQL: # # SELECT lname , sex FROM Student WHERE StuID IN (SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Call of Destiny" INTERSECT SELECT T1.StuID FROM Plays_games AS T1 JOIN Video_games AS T2 ON T1.GameID = T2.GameID WHERE T2.Gname = "Works of Widenius") # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name of all customers. # ### SQL: # # SELECT customer_name FROM customers # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the names of all the customers? # ### SQL: # # SELECT customer_name FROM customers # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # How many customers are there? # ### SQL: # # SELECT count(*) FROM customers # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Return the total number of distinct customers. # ### SQL: # # SELECT count(*) FROM customers # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the average amount of items ordered in each order? # ### SQL: # # SELECT avg(order_quantity) FROM order_items # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the average order quantity per order. # ### SQL: # # SELECT avg(order_quantity) FROM order_items # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the names of customers who use payment method "Cash"? # ### SQL: # # SELECT customer_name FROM customers WHERE payment_method = "Cash" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which customers use "Cash" for payment method? Return the customer names. # ### SQL: # # SELECT customer_name FROM customers WHERE payment_method = "Cash" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the "date became customers" of the customers whose ID is between 10 and 20. # ### SQL: # # SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the dates when customers with ids between 10 and 20 became customers? # ### SQL: # # SELECT date_became_customer FROM customers WHERE customer_id BETWEEN 10 AND 20 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which payment method is used by most customers? # ### SQL: # # SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the payment method that is used most frequently. # ### SQL: # # SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the names of customers using the most popular payment method? # ### SQL: # # SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name of the customers who use the most frequently used payment method. # ### SQL: # # SELECT customer_name FROM customers WHERE payment_method = (SELECT payment_method FROM customers GROUP BY payment_method ORDER BY count(*) DESC LIMIT 1) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are all the payment methods? # ### SQL: # # SELECT DISTINCT payment_method FROM customers # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Return all the distinct payment methods used by customers. # ### SQL: # # SELECT DISTINCT payment_method FROM customers # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the details of all products? # ### SQL: # # SELECT DISTINCT product_details FROM products # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Return the the details of all products. # ### SQL: # # SELECT DISTINCT product_details FROM products # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name of all customers whose name contains "Alex". # ### SQL: # # SELECT customer_name FROM customers WHERE customer_name LIKE "%Alex%" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which customer's name contains "Alex"? Find the full name. # ### SQL: # # SELECT customer_name FROM customers WHERE customer_name LIKE "%Alex%" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the detail of products whose detail contains the word "Latte" or the word "Americano" # ### SQL: # # SELECT product_details FROM products WHERE product_details LIKE "%Latte%" OR product_details LIKE "%Americano%" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which product's detail contains the word "Latte" or "Americano"? Return the full detail. # ### SQL: # # SELECT product_details FROM products WHERE product_details LIKE "%Latte%" OR product_details LIKE "%Americano%" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the address content of the customer named "Maudie Kertzmann"? # ### SQL: # # SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = "Maudie Kertzmann" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Return the address content for the customer whose name is "Maudie Kertzmann". # ### SQL: # # SELECT t3.address_content FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t1.customer_name = "Maudie Kertzmann" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # How many customers are living in city "Lake Geovannyton"? # ### SQL: # # SELECT count(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = "Lake Geovannyton" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the number of customers who live in the city called Lake Geovannyton. # ### SQL: # # SELECT count(*) FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.city = "Lake Geovannyton" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name of customers who are living in Colorado? # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = "Colorado" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the names of customers who live in Colorado state? # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = "Colorado" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the list of cities that no customer is living in. # ### SQL: # # SELECT city FROM addresses WHERE city NOT IN ( SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the cities no customers live in? # ### SQL: # # SELECT city FROM addresses WHERE city NOT IN ( SELECT DISTINCT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which city has the most customers living in? # ### SQL: # # SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the city where the most customers live. # ### SQL: # # SELECT t3.city FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id GROUP BY t3.city ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Retrieve the list of all cities. # ### SQL: # # SELECT DISTINCT city FROM addresses # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # List all the distinct cities # ### SQL: # # SELECT DISTINCT city FROM addresses # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the city with post code 255. # ### SQL: # # SELECT city FROM addresses WHERE zip_postcode = 255 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which city is post code 255 located in? # ### SQL: # # SELECT city FROM addresses WHERE zip_postcode = 255 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the state and country of all cities with post code starting with 4. # ### SQL: # # SELECT state_province_county , country FROM addresses WHERE zip_postcode LIKE "4%" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the state and country of all the cities that have post codes starting with 4.\ # ### SQL: # # SELECT state_province_county , country FROM addresses WHERE zip_postcode LIKE "4%" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # List the countries having more than 4 addresses listed. # ### SQL: # # SELECT country FROM addresses GROUP BY country HAVING count(address_id) > 4 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # For which countries are there more than four distinct addresses listed? # ### SQL: # # SELECT country FROM addresses GROUP BY country HAVING count(address_id) > 4 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # List all the contact channel codes that were used less than 5 times. # ### SQL: # # SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING count(customer_id) < 5 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which contact channel codes were used less than 5 times? # ### SQL: # # SELECT channel_code FROM customer_contact_channels GROUP BY channel_code HAVING count(customer_id) < 5 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which contact channel has been used by the customer with name "Tillman Ernser"? # ### SQL: # # SELECT DISTINCT channel_code FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the contact channel code that was used by the customer named "Tillman Ernser". # ### SQL: # # SELECT DISTINCT channel_code FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the "active to date" of the latest contact channel used by "Tillman Ernser"? # ### SQL: # # SELECT max(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser" # ### End.

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