Split (2)

train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Return the the "active to date" of the latest contact channel used by the customer named "Tillman Ernser". # ### SQL: # # SELECT max(t2.active_to_date) FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = "Tillman Ernser" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the average time span of contact channels in the database? # ### SQL: # # SELECT avg(active_to_date - active_from_date) FROM customer_contact_channels # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Compute the average active time span of contact channels. # ### SQL: # # SELECT avg(active_to_date - active_from_date) FROM customer_contact_channels # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the channel code and contact number of the customer contact channel that was active for the longest time? # ### SQL: # # SELECT channel_code , contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Return the channel code and contact number of the customer contact channel whose active duration was the longest. # ### SQL: # # SELECT channel_code , contact_number FROM customer_contact_channels WHERE active_to_date - active_from_date = (SELECT active_to_date - active_from_date FROM customer_contact_channels ORDER BY (active_to_date - active_from_date) DESC LIMIT 1) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name and active date of the customer that use email as the contact channel. # ### SQL: # # SELECT t1.customer_name , t2.active_from_date FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t2.channel_code = 'Email' # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the name and active date of the customers whose contact channel code is email? # ### SQL: # # SELECT t1.customer_name , t2.active_from_date FROM customers AS t1 JOIN customer_contact_channels AS t2 ON t1.customer_id = t2.customer_id WHERE t2.channel_code = 'Email' # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the name of the customer that made the order with the largest quantity? # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t3.order_quantity = ( SELECT max(order_quantity) FROM order_items) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name of the customer who made the order of the largest amount of goods. # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t3.order_quantity = ( SELECT max(order_quantity) FROM order_items) # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the name of the customer that has purchased the most items? # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Give me the name of the customer who ordered the most items in total. # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the payment method of the customer that has purchased the least quantity of items? # ### SQL: # # SELECT t1.payment_method FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Tell me the payment method used by the customer who ordered the least amount of goods in total. # ### SQL: # # SELECT t1.payment_method FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id GROUP BY t1.customer_name ORDER BY sum(t3.order_quantity) LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # How many types of products have Rodrick Heaney bought in total? # ### SQL: # # SELECT count(DISTINCT t3.product_id) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the number of distinct products Rodrick Heaney has bought so far. # ### SQL: # # SELECT count(DISTINCT t3.product_id) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the total quantity of products purchased by "Rodrick Heaney"? # ### SQL: # # SELECT sum(t3.order_quantity) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Tell me the total quantity of products bought by the customer called "Rodrick Heaney". # ### SQL: # # SELECT sum(t3.order_quantity) FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id WHERE t1.customer_name = "Rodrick Heaney" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # How many customers have at least one order with status "Cancelled"? # ### SQL: # # SELECT count(DISTINCT customer_id) FROM customer_orders WHERE order_status = "Cancelled" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Return the number of customers who have at least one order with "Cancelled" status. # ### SQL: # # SELECT count(DISTINCT customer_id) FROM customer_orders WHERE order_status = "Cancelled" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # How many orders have detail "Second time"? # ### SQL: # # SELECT count(*) FROM customer_orders WHERE order_details = "Second time" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Tell me the number of orders with "Second time" as order detail. # ### SQL: # # SELECT count(*) FROM customer_orders WHERE order_details = "Second time" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the customer name and date of the orders that have the status "Delivered". # ### SQL: # # SELECT t1.customer_name , t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "Delivered" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the customer name and date of the orders whose status is "Delivered". # ### SQL: # # SELECT t1.customer_name , t2.order_date FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id WHERE order_status = "Delivered" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the total number of products that are in orders with status "Cancelled"? # ### SQL: # # SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_status = "Cancelled" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the total quantity of products associated with the orders in the "Cancelled" status. # ### SQL: # # SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_status = "Cancelled" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the total amount of products ordered before 2018-03-17 07:13:53. # ### SQL: # # SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_date < "2018-03-17 07:13:53" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the total amount of products purchased before 2018-03-17 07:13:53? # ### SQL: # # SELECT sum(t2.order_quantity) FROM customer_orders AS t1 JOIN order_items AS t2 ON t1.order_id = t2.order_id WHERE t1.order_date < "2018-03-17 07:13:53" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Who made the latest order? # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.order_date DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name of the customer who made an order most recently. # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id ORDER BY t2.order_date DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Which product has been ordered most number of times? # ### SQL: # # SELECT t2.product_details FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the most frequently ordered product? Tell me the detail of the product # ### SQL: # # SELECT t2.product_details FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name and ID of the product whose total order quantity is the largest. # ### SQL: # # SELECT t2.product_details , t2.product_id FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY sum(t1.order_quantity) LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the name and ID of the product bought the most. # ### SQL: # # SELECT t2.product_details , t2.product_id FROM order_items AS t1 JOIN products AS t2 ON t1.product_id = t2.product_id GROUP BY t1.product_id ORDER BY sum(t1.order_quantity) LIMIT 1 # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find all the addresses in East Julianaside, Texas or in Gleasonmouth, Arizona. # ### SQL: # # SELECT address_content FROM addresses WHERE city = "East Julianaside" AND state_province_county = "Texas" UNION SELECT address_content FROM addresses WHERE city = "Gleasonmouth" AND state_province_county = "Arizona" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are all the addresses in East Julianaside, Texas or in Gleasonmouth, Arizona. # ### SQL: # # SELECT address_content FROM addresses WHERE city = "East Julianaside" AND state_province_county = "Texas" UNION SELECT address_content FROM addresses WHERE city = "Gleasonmouth" AND state_province_county = "Arizona" # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the name of customers who did not pay with Cash. # ### SQL: # # SELECT customer_name FROM customers WHERE payment_method != 'Cash' # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What is the name of customers who do not use Cash as payment method. # ### SQL: # # SELECT customer_name FROM customers WHERE payment_method != 'Cash' # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the names of customers who never ordered product Latte. # ### SQL: # # SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte' # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are names of customers who never ordered product Latte. # ### SQL: # # SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte' # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the names of customers who never placed an order. # ### SQL: # # SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the names of customers who never made an order. # ### SQL: # # SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the names of customers who ordered both products Latte and Americano. # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte' INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Americano' # ### End.
customers_and_addresses	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Addresses ( address_id, address_content, city, zip_postcode, state_province_county, country, other_address_details ) # Products ( product_id, product_details ) # Customers ( customer_id, payment_method, customer_name, date_became_customer, other_customer_details ) # Customer_Addresses ( customer_id, address_id, date_address_from, address_type, date_address_to ) # Customer_Contact_Channels ( customer_id, channel_code, active_from_date, active_to_date, contact_number ) # Customer_Orders ( order_id, customer_id, order_status, order_date, order_details ) # Order_Items ( order_id, product_id, order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.address_id can be joined with Addresses.address_id # Customer_Contact_Channels.customer_id can be joined with Customers.customer_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the names of customers who have purchased both products Latte and Americano? # ### SQL: # # SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Latte' INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN customer_orders AS t2 ON t1.customer_id = t2.customer_id JOIN order_items AS t3 ON t2.order_id = t3.order_id JOIN products AS t4 ON t3.product_id = t4.product_id WHERE t4.product_details = 'Americano' # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # How many artists are there? # ### SQL: # # SELECT count(*) FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Count the number of artists. # ### SQL: # # SELECT count(*) FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # List the age of all music artists. # ### SQL: # # SELECT Age FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the ages of all music artists? # ### SQL: # # SELECT Age FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What is the average age of all artists? # ### SQL: # # SELECT avg(Age) FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the average age across all artists. # ### SQL: # # SELECT avg(Age) FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the famous titles of the artist "Triumfall"? # ### SQL: # # SELECT Famous_Title FROM artist WHERE Artist = "Triumfall" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the famous titles of the artist called "Triumfall". # ### SQL: # # SELECT Famous_Title FROM artist WHERE Artist = "Triumfall" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the distinct Famous release dates? # ### SQL: # # SELECT distinct(Famous_Release_date) FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Give the distinct famous release dates for all artists. # ### SQL: # # SELECT distinct(Famous_Release_date) FROM artist # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the dates of ceremony and the results of all music festivals # ### SQL: # # SELECT Date_of_ceremony , RESULT FROM music_festival # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the dates of ceremony and results for each music festival? # ### SQL: # # SELECT Date_of_ceremony , RESULT FROM music_festival # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the category of music festivals with result "Awarded"? # ### SQL: # # SELECT Category FROM music_festival WHERE RESULT = "Awarded" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the categories of music festivals that have the result "Awarded". # ### SQL: # # SELECT Category FROM music_festival WHERE RESULT = "Awarded" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the maximum and minimum week on top of all volumes? # ### SQL: # # SELECT max(Weeks_on_Top) , min(Weeks_on_Top) FROM volume # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Give the maximum and minimum weeks on top across all volumes. # ### SQL: # # SELECT max(Weeks_on_Top) , min(Weeks_on_Top) FROM volume # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the songs in volumes with more than 1 week on top? # ### SQL: # # SELECT Song FROM volume WHERE Weeks_on_Top > 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Give the songs included in volumes that have more than 1 week on top. # ### SQL: # # SELECT Song FROM volume WHERE Weeks_on_Top > 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Please list all songs in volumes in ascending alphabetical order. # ### SQL: # # SELECT Song FROM volume ORDER BY Song # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the the songs in volumes, listed in ascending order? # ### SQL: # # SELECT Song FROM volume ORDER BY Song # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # How many distinct artists do the volumes associate to? # ### SQL: # # SELECT COUNT(DISTINCT Artist_ID) FROM volume # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Count the number of distinct artists who have volumes. # ### SQL: # # SELECT COUNT(DISTINCT Artist_ID) FROM volume # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Please show the date of ceremony of the volumes that last more than 2 weeks on top. # ### SQL: # # SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T2.Weeks_on_Top > 2 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the dates of ceremony at music festivals corresponding to volumes that lasted more than 2 weeks on top? # ### SQL: # # SELECT T1.Date_of_ceremony FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T2.Weeks_on_Top > 2 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Please show the songs that have result "nominated" at music festivals. # ### SQL: # # SELECT T2.Song FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T1.Result = "Nominated" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the songs in volumes that have resulted in a nomination at music festivals? # ### SQL: # # SELECT T2.Song FROM music_festival AS T1 JOIN volume AS T2 ON T1.Volume = T2.Volume_ID WHERE T1.Result = "Nominated" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the issue dates of volumes associated with the artist "Gorgoroth"? # ### SQL: # # SELECT T2.Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.Artist = "Gorgoroth" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the issue dates of volumes that are by the artist named Gorgoroth. # ### SQL: # # SELECT T2.Issue_Date FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.Artist = "Gorgoroth" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the songs in volumes associated with the artist aged 32 or older? # ### SQL: # # SELECT T2.Song FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age >= 32 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return names of songs in volumes that are by artists that are at least 32 years old. # ### SQL: # # SELECT T2.Song FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age >= 32 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What is the average weeks on top of volumes associated with the artist aged 25 or younger? # ### SQL: # # SELECT avg(T2.Weeks_on_Top) FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age <= 25 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the average number of weeks on top for volumes by artists that are at most 25 years old. # ### SQL: # # SELECT avg(T2.Weeks_on_Top) FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T1.age <= 25 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the famous title of the artists associated with volumes with more than 2 weeks on top? # ### SQL: # # SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the famous titles for artists that have volumes that lasted more than 2 weeks on top. # ### SQL: # # SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Please list the age and famous title of artists in descending order of age. # ### SQL: # # SELECT Famous_Title , Age FROM artist ORDER BY Age DESC # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the famous titles and ages of each artist, listed in descending order by age? # ### SQL: # # SELECT Famous_Title , Age FROM artist ORDER BY Age DESC # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What is the famous release date of the artist with the oldest age? # ### SQL: # # SELECT Famous_Release_date FROM artist ORDER BY Age DESC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the famous release date for the oldest artist. # ### SQL: # # SELECT Famous_Release_date FROM artist ORDER BY Age DESC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Please show the categories of the music festivals and the count. # ### SQL: # # SELECT Category , COUNT(*) FROM music_festival GROUP BY Category # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the number of music festivals of each category. # ### SQL: # # SELECT Category , COUNT(*) FROM music_festival GROUP BY Category # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What is the most common result of the music festival? # ### SQL: # # SELECT RESULT FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the result that is most frequent at music festivals. # ### SQL: # # SELECT RESULT FROM music_festival GROUP BY RESULT ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Please show the categories of the music festivals with count more than 1. # ### SQL: # # SELECT Category FROM music_festival GROUP BY Category HAVING COUNT(*) > 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the categories of music festivals for which there have been more than 1 music festival? # ### SQL: # # SELECT Category FROM music_festival GROUP BY Category HAVING COUNT(*) > 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What is the song in the volume with the maximum weeks on top? # ### SQL: # # SELECT Song FROM volume ORDER BY Weeks_on_Top DESC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the song in the volume that has spent the most weeks on top? # ### SQL: # # SELECT Song FROM volume ORDER BY Weeks_on_Top DESC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Find the famous titles of artists that do not have any volume. # ### SQL: # # SELECT Famous_Title FROM artist WHERE Artist_ID NOT IN(SELECT Artist_ID FROM volume) # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the famous titles of artists who do not have any volumes? # ### SQL: # # SELECT Famous_Title FROM artist WHERE Artist_ID NOT IN(SELECT Artist_ID FROM volume) # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Show the famous titles of the artists with both volumes that lasted more than 2 weeks on top and volumes that lasted less than 2 weeks on top. # ### SQL: # # SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 INTERSECT SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top < 2 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the famous titles of artists who have not only had volumes that spent more than 2 weeks on top but also volumes that spent less than 2 weeks on top? # ### SQL: # # SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top > 2 INTERSECT SELECT T1.Famous_Title FROM artist AS T1 JOIN volume AS T2 ON T1.Artist_ID = T2.Artist_ID WHERE T2.Weeks_on_Top < 2 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What are the date of ceremony of music festivals with category "Best Song" and result "Awarded"? # ### SQL: # # SELECT Date_of_ceremony FROM music_festival WHERE Category = "Best Song" AND RESULT = "Awarded" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the dates of ceremony corresponding to music festivals that had the category "Best Song" and result "Awarded". # ### SQL: # # SELECT Date_of_ceremony FROM music_festival WHERE Category = "Best Song" AND RESULT = "Awarded" # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # What is the issue date of the volume with the minimum weeks on top? # ### SQL: # # SELECT Issue_Date FROM volume ORDER BY Weeks_on_Top ASC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Return the issue date of the volume that has spent the fewest weeks on top. # ### SQL: # # SELECT Issue_Date FROM volume ORDER BY Weeks_on_Top ASC LIMIT 1 # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # How many distinct artists have volumes? # ### SQL: # # SELECT COUNT(DISTINCT Artist_ID) FROM volume # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Count the number of artists who have had volumes. # ### SQL: # # SELECT COUNT(DISTINCT Artist_ID) FROM volume # ### End.
music_4	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # artist ( Artist_ID, Artist, Age, Famous_Title, Famous_Release_date ) # volume ( Volume_ID, Volume_Issue, Issue_Date, Weeks_on_Top, Song, Artist_ID ) # music_festival ( ID, Music_Festival, Date_of_ceremony, Category, Volume, Result ) # # volume.Artist_ID can be joined with artist.Artist_ID # music_festival.Volume can be joined with volume.Volume_ID # ### Question: # # Please show the results of music festivals and the number of music festivals that have had each, ordered by this count. # ### SQL: # # SELECT RESULT , COUNT() FROM music_festival GROUP BY RESULT ORDER BY COUNT() DESC # ### End.

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