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def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3]
for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L3_L8
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1):
my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
if i % 2 == 0:
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L4_L4
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1):
else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
if i % 2 == 0: my_tri.append(i / 2 + 1)
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L4_L5
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1):
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
if i % 2 == 0: my_tri.append(i / 2 + 1) else:
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L4_L6
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1):
return my_tri
if i % 2 == 0: my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L4_L7
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1):
if i % 2 == 0: my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L4_L8
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0:
else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
my_tri.append(i / 2 + 1)
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L5_L5
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
my_tri.append(i / 2 + 1) else:
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L5_L6
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0:
return my_tri
my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L5_L7
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0:
my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L5_L8
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1)
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
else:
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L6_L6
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1)
return my_tri
else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L6_L7
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1)
else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L6_L8
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1) else:
return my_tri
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L7_L7
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1) else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L7_L8
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd. """ if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
[ [ "3", "[1, 3, 2.0, 8.0]" ], [ "4", "[1, 3, 2.0, 8.0, 3.0]" ], [ "5", "[1, 3, 2.0, 8.0, 3.0, 15.0]" ], [ "6", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]" ], [ "7", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]" ], [ "8", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]" ], [ "9", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]" ], [ "20", "[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]" ], [ "0", "[1]" ], [ "1", "[1, 3]" ] ]
[]
[ [ "1", "3" ], [ "n", "1 + n / 2, if n is even." ], [ "n", "tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd." ], [ "2", "1 + (2 / 2) = 2" ], [ "4", "3" ], [ "3", "tri(2) + tri(1) + tri(4)" ], [ "3", "[1, 3, 2, 8]" ] ]
tri
MultiLineInfilling/HumanEval/130/L8_L8
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
product = 1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L0
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
product = 1 odd_count = 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L1
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
product = 1 odd_count = 0 for digit in str(n):
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L2
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L3
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L4
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
odd_count+=1 if odd_count ==0: return 0 else: return product
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L5
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
if odd_count ==0: return 0 else: return product
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L6
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
return 0 else: return product
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
else: return product
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
return product
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L0_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
odd_count = 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L1
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
odd_count = 0 for digit in str(n):
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L2
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
odd_count = 0 for digit in str(n): int_digit = int(digit)
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L3
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L4
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
odd_count+=1 if odd_count ==0: return 0 else: return product
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L5
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
if odd_count ==0: return 0 else: return product
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L6
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
return 0 else: return product
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
else: return product
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
return product
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1
odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L1_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
for digit in str(n):
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L2
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
for digit in str(n): int_digit = int(digit)
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L3
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L4
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
odd_count+=1 if odd_count ==0: return 0 else: return product
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L5
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
if odd_count ==0: return 0 else: return product
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L6
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
return 0 else: return product
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
else: return product
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
return product
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0
for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L2_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
int_digit = int(digit)
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L3
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
int_digit = int(digit) if int_digit%2 == 1:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L4
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
odd_count+=1 if odd_count ==0: return 0 else: return product
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L5
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
if odd_count ==0: return 0 else: return product
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L6
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
return 0 else: return product
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
else: return product
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
return product
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n):
int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L3_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
if int_digit%2 == 1:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L4_L4
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
odd_count+=1 if odd_count ==0: return 0 else: return product
if int_digit%2 == 1: product= product*int_digit
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L4_L5
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
if odd_count ==0: return 0 else: return product
if int_digit%2 == 1: product= product*int_digit odd_count+=1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L4_L6
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
return 0 else: return product
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L4_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
else: return product
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L4_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
return product
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L4_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit)
if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L4_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
odd_count+=1 if odd_count ==0: return 0 else: return product
product= product*int_digit
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L5_L5
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
if odd_count ==0: return 0 else: return product
product= product*int_digit odd_count+=1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L5_L6
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
return 0 else: return product
product= product*int_digit odd_count+=1 if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L5_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
else: return product
product= product*int_digit odd_count+=1 if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L5_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
return product
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L5_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L5_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
if odd_count ==0: return 0 else: return product
odd_count+=1
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L6_L6
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
return 0 else: return product
odd_count+=1 if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L6_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
else: return product
odd_count+=1 if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L6_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
return product
odd_count+=1 if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L6_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit
odd_count+=1 if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L6_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
return 0 else: return product
if odd_count ==0:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L7_L7
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
else: return product
if odd_count ==0: return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L7_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
return product
if odd_count ==0: return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L7_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1
if odd_count ==0: return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L7_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
else: return product
return 0
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L8_L8
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
return product
return 0 else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L8_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0:
return 0 else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L8_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0
return product
else:
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L9_L9
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0
else: return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L9_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else:
return product
[ [ "5", "5" ], [ "54", "5" ], [ "120", "1" ], [ "5014", "5" ], [ "98765", "315" ], [ "5576543", "2625" ], [ "2468", "0" ] ]
[]
[ [ "1", "1" ], [ "4", "0" ], [ "235", "15" ] ]
digits
MultiLineInfilling/HumanEval/131/L10_L10
Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = []
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L0
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = []
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L1
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)):
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L2
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[':
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L3
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i)
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L4
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else:
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L5
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i)
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L6
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse()
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L7
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L8
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L9
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index)
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L10
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index:
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L11
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
cnt += 1 i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]:
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L12
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
i += 1 return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L13
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
return cnt >= 2
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L14
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L0_L15
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """ opening_bracket_index = []
for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = []
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L1_L1
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python
def is_nested(string): """ Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. """ opening_bracket_index = []
if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
closing_bracket_index = [] for i in range(len(string)):
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[[[]]]]'", "True" ], [ "'[]]]]]]]]]]'", "False" ], [ "'[][][[]]'", "True" ], [ "'[[]'", "False" ], [ "'[]]'", "False" ], [ "'[[]][['", "True" ], [ "'[[][]]'", "True" ], [ "''", "False" ], [ "'[[[[[[[['", "False" ], [ "']]]]]]]]'", "False" ] ]
[]
[ [ "'[[]]'", "True" ], [ "'[]]]]]]][[[[[]'", "False" ], [ "'[][]'", "False" ], [ "'[]'", "False" ], [ "'[[][]]'", "True" ], [ "'[[]][['", "True" ] ]
is_nested
MultiLineInfilling/HumanEval/132/L1_L2
Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested.
HumanEval_MultiLineInfilling
code_infilling
[]
python
python