prefix
stringlengths 65
1.8k
| suffix
stringclasses 839
values | solution
stringlengths 6
859
| test_cases
listlengths 0
100
| import_str
listlengths 0
1
| demos
listlengths 0
8
| entry_func
stringclasses 158
values | data_id
stringlengths 36
40
| doc_string
stringclasses 164
values | dataset_name
stringclasses 1
value | task_name
stringclasses 1
value | compare_func
listlengths 0
0
| src_lang
stringclasses 1
value | tgt_lang
stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
|
ans.append(1)
else:
ans.append(val)
return ans
|
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L12_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
|
else:
ans.append(val)
return ans
|
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L12_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
|
ans.append(val)
return ans
|
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L12_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
|
return ans
|
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L12_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
|
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L12_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L13
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L15
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L16
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L18
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L20
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L21
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
else:
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
ans.append(val)
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
return ans
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
|
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L13_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
if j != n - 1:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L15
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L16
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L18
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L20
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L21
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
ans.append(1)
else:
ans.append(val)
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
else:
ans.append(val)
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
ans.append(val)
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
return ans
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
|
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L15_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i][j + 1])
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L16
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i][j + 1])
val = min(temp)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L18
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L20
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L21
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
ans.append(1)
else:
ans.append(val)
return ans
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
else:
ans.append(val)
return ans
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
ans.append(val)
return ans
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
return ans
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
|
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L16_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
val = min(temp)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L18
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
val = min(temp)
ans = []
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L20
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
val = min(temp)
ans = []
for i in range(k):
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L21
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
ans.append(1)
else:
ans.append(val)
return ans
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
else:
ans.append(val)
return ans
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
ans.append(val)
return ans
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
return ans
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
|
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L18_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
ans = []
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L20_L20
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
ans = []
for i in range(k):
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L20_L21
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
ans.append(1)
else:
ans.append(val)
return ans
|
ans = []
for i in range(k):
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L20_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
else:
ans.append(val)
return ans
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L20_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
ans.append(val)
return ans
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L20_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
return ans
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L20_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
|
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L20_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
for i in range(k):
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L21_L21
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
ans.append(1)
else:
ans.append(val)
return ans
|
for i in range(k):
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L21_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
else:
ans.append(val)
return ans
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L21_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
ans.append(val)
return ans
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L21_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
return ans
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L21_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
|
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L21_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
ans.append(1)
else:
ans.append(val)
return ans
|
if i % 2 == 0:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L22_L22
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
else:
ans.append(val)
return ans
|
if i % 2 == 0:
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L22_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
ans.append(val)
return ans
|
if i % 2 == 0:
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L22_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
return ans
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L22_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
|
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L22_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
else:
ans.append(val)
return ans
|
ans.append(1)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L23_L23
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
ans.append(val)
return ans
|
ans.append(1)
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L23_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
return ans
|
ans.append(1)
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L23_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
|
ans.append(1)
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L23_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
ans.append(val)
return ans
|
else:
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L24_L24
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
return ans
|
else:
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L24_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
|
else:
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L24_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
return ans
|
ans.append(val)
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L25_L25
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
|
ans.append(val)
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L25_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
"""
n = len(grid)
val = n * n + 1
for i in range(n):
for j in range(n):
if grid[i][j] == 1:
temp = []
if i != 0:
temp.append(grid[i - 1][j])
if j != 0:
temp.append(grid[i][j - 1])
if i != n - 1:
temp.append(grid[i + 1][j])
if j != n - 1:
temp.append(grid[i][j + 1])
val = min(temp)
ans = []
for i in range(k):
if i % 2 == 0:
ans.append(1)
else:
ans.append(val)
|
return ans
|
[
[
"[[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3",
"[1, 2, 1]"
],
[
"[[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1",
"[1]"
],
[
"[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4",
"[1, 2, 1, 2]"
],
[
"[[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7",
"[1, 10, 1, 10, 1, 10, 1]"
],
[
"[[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5",
"[1, 7, 1, 7, 1]"
],
[
"[[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9",
"[1, 6, 1, 6, 1, 6, 1, 6, 1]"
],
[
"[[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12",
"[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]"
],
[
"[[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8",
"[1, 3, 1, 3, 1, 3, 1, 3]"
],
[
"[[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8",
"[1, 5, 1, 5, 1, 5, 1, 5]"
],
[
"[[1, 2], [3, 4]], 10",
"[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]"
],
[
"[[1, 3], [3, 2]], 10",
"[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]"
]
] |
[] |
[
[
"[[1,2,3], [4,5,6], [7,8,9]], 3",
"[1, 2, 1]"
],
[
"[[5,9,3], [4,1,6], [7,8,2]], 1",
"[1]"
]
] |
minPath
|
MultiLineInfilling/HumanEval/129/L26_L26
|
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you can move to any of the neighbor cells,
in other words, you can go to cells which share an edge with you current
cell.
Please note that a path of length k means visiting exactly k cells (not
necessarily distinct).
You CANNOT go off the grid.
A path A (of length k) is considered less than a path B (of length k) if
after making the ordered lists of the values on the cells that A and B go
through (let's call them lst_A and lst_B), lst_A is lexicographically less
than lst_B, in other words, there exist an integer index i (1 <= i <= k)
such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have
lst_A[j] = lst_B[j].
It is guaranteed that the answer is unique.
Return an ordered list of the values on the cells that the minimum path go through.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
if n == 0:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L0
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
if n == 0:
return [1]
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L1
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
if n == 0:
return [1]
my_tri = [1, 3]
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L2
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L3
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L4
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L5
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L6
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
return my_tri
|
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L7
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
|
if n == 0:
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L0_L8
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
return [1]
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L1
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
return [1]
my_tri = [1, 3]
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L2
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L3
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L4
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L5
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L6
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
return my_tri
|
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L7
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
|
return [1]
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L1_L8
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
|
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
my_tri = [1, 3]
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L2_L2
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
|
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
my_tri = [1, 3]
for i in range(2, n + 1):
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L2_L3
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
|
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L2_L4
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
|
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L2_L5
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
|
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L2_L6
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
|
return my_tri
|
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L2_L7
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
|
my_tri = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L2_L8
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
|
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
for i in range(2, n + 1):
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L3_L3
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
|
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
for i in range(2, n + 1):
if i % 2 == 0:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L3_L4
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
|
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L3_L5
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
|
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
return my_tri
|
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L3_L6
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
"""
if n == 0:
return [1]
my_tri = [1, 3]
|
return my_tri
|
for i in range(2, n + 1):
if i % 2 == 0:
my_tri.append(i / 2 + 1)
else:
my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2)
|
[
[
"3",
"[1, 3, 2.0, 8.0]"
],
[
"4",
"[1, 3, 2.0, 8.0, 3.0]"
],
[
"5",
"[1, 3, 2.0, 8.0, 3.0, 15.0]"
],
[
"6",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0]"
],
[
"7",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0]"
],
[
"8",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0]"
],
[
"9",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0]"
],
[
"20",
"[1, 3, 2.0, 8.0, 3.0, 15.0, 4.0, 24.0, 5.0, 35.0, 6.0, 48.0, 7.0, 63.0, 8.0, 80.0, 9.0, 99.0, 10.0, 120.0, 11.0]"
],
[
"0",
"[1]"
],
[
"1",
"[1, 3]"
]
] |
[] |
[
[
"1",
"3"
],
[
"n",
"1 + n / 2, if n is even."
],
[
"n",
"tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd."
],
[
"2",
"1 + (2 / 2) = 2"
],
[
"4",
"3"
],
[
"3",
"tri(2) + tri(1) + tri(4)"
],
[
"3",
"[1, 3, 2, 8]"
]
] |
tri
|
MultiLineInfilling/HumanEval/130/L3_L7
|
Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.