id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5
values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__DEkkuwlgQ9KLjgTx | in an examination , questions were asked in 5 sections . out of the total students , 5 % candidates cleared the cut - off in all the sections and 5 % cleared none . of the rest , 25 % cleared only one section and 20 % cleared 4 sections . if 24.5 % of the entire candidates cleared two sections and 300 candidates cleare... | <gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 * 25</gadget>
<output>2_250</output>
<gadget id="calculator">2_250 / 100</gadget>
<output>45/2 = around 22.5</output>
<gadget id="calculator">10 + (45/2)</gadget>
<outp... | B | 1,200 | in an examination , questions were asked in 5 sections . out of the total students , 5 % candidates cleared the cut - off in all the sections and 5 % cleared none . of the rest , 25 % cleared only one section and 20 % cleared 4 sections . if 24.5 % of the entire candidates cleared two sections and 300 candidates cleare... | {
"A": "1000",
"B": "1200",
"C": "1500",
"D": "2000",
"E": "1800"
} | multiply(divide(300, subtract(const_100, add(add(add(add(5, 5), divide(multiply(subtract(const_100, add(5, 5)), 25), const_100)), divide(multiply(subtract(const_100, add(5, 5)), 20), const_100)), 24.5))), const_100) | add(n0,n0)|subtract(const_100,#0)|multiply(n3,#1)|multiply(n4,#1)|divide(#2,const_100)|divide(#3,const_100)|add(#0,#4)|add(#6,#5)|add(n6,#7)|subtract(const_100,#8)|divide(n7,#9)|multiply(#10,const_100) | solution : passed in none = 5 % passed in all = 5 % passed in four = 20 % 0 f 90 % = 18 % passed in three = 24.5 % passed in three = ( 100 - 5 - 5 - 22.5 - 24.5 - 18 ) = 25 % . but given 300 students passed in three . hence , 25 % = 300 . so , 100 % = 1200 . 1200 students must have appeared . answer : option b | general |
math_qa__rsV7kM7HEQmSplcZ | A carpenter worked alone for 1 day on a job that would take him 4 more days to finish. He and another carpenter completed the job in 2 more days. How many days would it have taken the second carpenter to do the complete job working alone? Choose the correct answer
A) 5 B) 7 C) 9 D) 14 E) 24 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>A</result> | A | 5 | A carpenter worked alone for 1 day on a job that would take him 4 more days to finish. He and another carpenter completed the job in 2 more days. How many days would it have taken the second carpenter to do the complete job working alone? | {
"A": "5",
"B": "7",
"C": "9",
"D": "14",
"E": "24"
} | divide(multiply(2, add(1, 4)), const_2) | add(n0,n1)|multiply(n2,#0)|divide(#1,const_2)| | "a carpenter worked only 1 day on something that takes him 4 more days . means ; carpenter finishes his work in 5 days . let his buddy finish the same task in x days . respective rates per day : 1 / 5 and 1 / x to complete 1 work : first guy worked for 3 days @ rate = 1 / 5 per day . second one worked for 2 days @ rate... | physics |
math_qa__xm9taxUEynD5LD6C | g(x) is defined as the product of all even integers k such that 0 < k ≤ x. For example, g(14) = 2 × 4 × 6 × 8 × 10 × 12 × 14. If g(z) is divisible by 4^11, what is the smallest possible value for z? Pick one: A) 22 B) 24 C) 28 D) 32 E) 44 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<result>B</result> | B | 24 | g(x) is defined as the product of all even integers k such that 0 < k ≤ x. For example, g(14) = 2 × 4 × 6 × 8 × 10 × 12 × 14. If g(z) is divisible by 4^11, what is the smallest possible value for z? | {
"A": "22",
"B": "24",
"C": "28",
"D": "32",
"E": "44"
} | multiply(2, 12) | multiply(n2,n7) | g ( z ) = 4 ^ 11 = 2 ^ 22 . so we have to find a product with atleast 22 2 ' s in it . in option 1 22 the total no of 2 ' s = [ 22 / 2 ] + [ 22 / 4 ] + [ 22 / 8 ] + [ 22 / 16 ] = 11 + 5 + 2 + 1 = 19 in option 2 24 the total no of 2 ' s = [ 24 / 2 ] + [ 24 / 4 ] + [ 24 / 8 ] + [ 24 / 16 ] = 12 + 6 + 3 + 1 = 22 . hence b | general |
math_qa__iRqepJqApeU0vLXd | if 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a 7 - percent vinegar solution , what was the concentration of the original solution ? Pick one: A) 19.3 % B) 17 % C) 36.17 % D) 15.5 % E) 12.5 % | <gadget id="calculator">50 + 12</gadget>
<output>62</output>
<gadget id="calculator">62 * 7</gadget>
<output>434</output>
<gadget id="calculator">434 / 12</gadget>
<output>217/6 = around 36.166667</output>
<result>C</result> | C | 36.17 | if 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a 7 - percent vinegar solution , what was the concentration of the original solution ? | {
"A": "19.3 %",
"B": "17 %",
"C": "36.17 %",
"D": "15.5 %",
"E": "12.5 %"
} | divide(multiply(add(50, 12), 7), 12) | add(n0,n1)|multiply(n2,#0)|divide(#1,n0) | let x be the quantity of non - vinegar in the strong vinegar solution thus vinegar quantity will be 12 - x when 50 ounces of water were added the percentage of vinegar becomes 7 % , thus ( 12 - x ) / 62 = 7 / 100 from this equation x = 7.66 answer ( 12 - 7.66 ) / 12 = 36.17 % answer : c | other |
math_qa__cM5mPO5svwdpWIRR | If (A+B) = 5, (B+C) = 6 and (C+D) = 3, what is the value of (A+D)? Choose the correct option.
A) 16 . B) 8 . C) 7 . D) 2 . E) - 2 . | <gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<result>D</result> | D | 2 | If (A+B) = 5, (B+C) = 6 and (C+D) = 3, what is the value of (A+D)? | {
"A": "16 .",
"B": "8 .",
"C": "7 .",
"D": "2 .",
"E": "- 2 ."
} | subtract(add(5, 3), 6) | add(n0,n2)|subtract(#0,n1)| | "given a + b = 5 b + c = 6 c + d = 3 ( a + b ) - ( b + c ) + ( c + d ) = ( a + d ) = > 5 - 6 + 3 = 2 . option d . . ." | general |
math_qa__pJChh0rQoebXGE7w | On a map the distance between two mountains is 312 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 25 inch from the base of the mountain. How many km is he from the base of the mountain?
Choose the correct answer:
A) 10.89 B) 14.81 C) 14.8 D) 14.82 E) 14.12 | <gadget id="calculator">25 * 136</gadget>
<output>3_400</output>
<gadget id="calculator">3_400 / 312</gadget>
<output>425/39 = around 10.897436</output>
<result>A</result> | A | 10.89 | On a map the distance between two mountains is 312 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 25 inch from the base of the mountain. How many km is he from the base of the mountain? | {
"A": "10.89",
"B": "14.81",
"C": "14.8",
"D": "14.82",
"E": "14.12"
} | divide(multiply(25, 136), 312) | multiply(n1,n2)|divide(#0,n0)| | "explanation : since 312 inch = 136 km so 1 inch = 136 / 312 km so 25 inch = ( 136 ã — 25 ) / 312 = 10.89 km answer : a" | physics |
math_qa__H46iLARZa6EMk1n3 | A garrison of 400 men had a provision for 31 days. After 27 days 200 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient? Choose the correct choice from the following choices
A) 65 days B) 45 days C) 8 days D) 16 days E) 18 days | <gadget id="calculator">31 - 27</gadget>
<output>4</output>
<gadget id="calculator">4 * 400</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 / 200</gadget>
<output>8</output>
<result>C</result> | C | 8 | A garrison of 400 men had a provision for 31 days. After 27 days 200 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient? | {
"A": "65 days",
"B": "45 days",
"C": "8 days",
"D": "16 days",
"E": "18 days"
} | divide(multiply(subtract(31, 27), 400), 200) | subtract(n1,n2)|multiply(n0,#0)|divide(#1,n3) | 400 - - - 31 400 - - - 4 200 - - - ? 400 * 4 = 200 * x = > x = 8 days . answer : c | other |
math_qa__dlEMVPvksgYdF2TZ | A salesman commission is 10% on all sales upto $5000 and 5% on all sales exceeding this. He remits $15000 to his parent company after deducting his commission. Find the total sales? Choices.
A) 15456
B) 14758
C) 15789
D) 13250
E) 12450 | <gadget id="calculator">10 * 5_000</gadget>
<output>50_000</output>
<gadget id="calculator">50_000 / 100</gadget>
<output>500</output>
<gadget id="calculator">4 * 5_000</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 100</gadget>
<output>200</output>
<gadget id="calculator">500 - 200</gadget>
<out... | C | 15,789 | A salesman commission is 10% on all sales upto $5000 and 5% on all sales exceeding this. He remits $15000 to his parent company after deducting his commission. Find the total sales? | {
"A": "15456",
"B": "14758",
"C": "15789",
"D": "13250",
"E": "12450"
} | divide(add(15000, subtract(divide(multiply(10, 5000), const_100), divide(multiply(const_4.0, 5000), const_100))), subtract(const_1, divide(5, const_100))) | divide(const_4.0,const_100)|multiply(n0,n1)|multiply(n1,n2)|divide(#1,const_100)|divide(#2,const_100)|subtract(const_1,#0)|subtract(#3,#4)|add(n3,#6)|divide(#7,#5)| | "let his total sales be x total sales - commission = $ 15000 x - [ ( 10 % of 5000 ) + 5 % of ( x - 5000 ) ] = 15000 95 x / 100 = 15000 x = 15789 approximately answer is c" | general |
math_qa__cbZ6fLqZTjNfVucf | A owes B Rs.50. He agrees to pay B over a number of consecutive days on a Monday, paying single note or Rs.10 or Rs.20 on each day. In how many different ways can A repay B. Options.
A) 2
B) 8
C) 9
D) 6
E) 5 | <gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">24 / 6</gadget>
<output>4</output>
<g... | B | 8 | A owes B Rs.50. He agrees to pay B over a number of consecutive days on a Monday, paying single note or Rs.10 or Rs.20 on each day. In how many different ways can A repay B. | {
"A": "2",
"B": "8",
"C": "9",
"D": "6",
"E": "5"
} | add(add(divide(factorial(const_3), factorial(const_2)), divide(factorial(const_4), factorial(const_3))), divide(factorial(divide(50, 10)), factorial(divide(50, 10)))) | divide(n0,n1)|factorial(const_3)|factorial(const_2)|factorial(const_4)|divide(#1,#2)|divide(#3,#1)|factorial(#0)|add(#4,#5)|divide(#6,#6)|add(#7,#8) | he can pay by all 10 rupee notes = 1 way 3 ten rupee + 1 twenty rupee = 4 ! 3 ! × 1 ! 4 ! 3 ! × 1 ! = 4 ways 1 ten rupee + 2 twenty rupee notes = 3 ! 2 ! × 1 ! 3 ! 2 ! × 1 ! = 3 ways total ways = 1 + 4 + 3 = 8 answer : b | physics |
math_qa__WY3eZeZJGPU7ArKx | A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 32.49, the number of the member is the group is: Options: A) 57 B) 67 C) 77 D) 87 E) 97 | <gadget id="calculator">32.49 * 100</gadget>
<output>3_249</output>
<gadget id="calculator">3_249 ** (1/2)</gadget>
<output>57</output>
<result>A</result> | A | 57 | A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 32.49, the number of the member is the group is: | {
"A": "57",
"B": "67",
"C": "77",
"D": "87",
"E": "97"
} | sqrt(multiply(32.49, const_100)) | multiply(n0,const_100)|sqrt(#0)| | "explanation : money collected = ( 32.49 x 100 ) paise = 3249 paise . ∴ number of members = √ ( 3249 ) = 57 . answer : a" | general |
math_qa__eHjXlkFcdt32eg68 | Q' = 3Q - 3, what is the value of (6')' ? Pick
A) 120 B) 150 C) 180 D) 210 E) 240 | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">18 - 3</gadget>
<output>15</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 - 3</gadget>
<output>42</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calcul... | D | 210 | Q' = 3Q - 3, what is the value of (6')' ? | {
"A": "120",
"B": "150",
"C": "180",
"D": "210",
"E": "240"
} | multiply(subtract(multiply(subtract(multiply(3, 6), 3), 3), 3), subtract(6, const_1)) | multiply(n0,n2)|subtract(n2,const_1)|subtract(#0,n0)|multiply(n0,#2)|subtract(#3,n0)|multiply(#4,#1) | ( 6 ' ) ' = ( 3 * 6 - 3 ) ' = 15 ' = 15 * 15 - 15 = 210 answer d | general |
math_qa__b9H2bVX4l6gf47BP | In 1979 approximately 1/3 of the 38.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/2 the number that used Kennedy Airport and 4 times the number that used Logan Airport, approximately how many millions of these pas... | <gadget id="calculator">38.3 / 3</gadget>
<output>12.766667</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">12.766667 / 8</gadget>
<output>1.595833</output>
<result>E</result> | E | 1.6 | In 1979 approximately 1/3 of the 38.3 million airline passengers traveling to or from the United States used Kennedy Airport. If the number of such passengers that used Miami Airport was 1/2 the number that used Kennedy Airport and 4 times the number that used Logan Airport, approximately how many millions of these pas... | {
"A": "18.6",
"B": "9.3",
"C": "6.2",
"D": "3.1",
"E": "1.6"
} | divide(divide(38.3, 3), multiply(4, 2)) | divide(n3,n2)|multiply(n5,n6)|divide(#0,#1) | number of passengers using kennedy airport = 38 / 3 = ~ 12.67 passengers using miami airport = 12.67 / 2 = ~ 6.3 passengers using logan airport = 6.3 / 4 = ~ 1.58 so e | general |
math_qa__Rv49aKUx3N2BrDRh | A and B can finish a work in 16 days while A alone can do the same work in 20 days. In how many days B alone will complete the work?
Choose the correct choice from the following options
A) 76 days B) 48 days C) 80 days D) 31 days E) 22 days | <gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/16) - (1/20)</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">1 / (1/80)</gadget>
<output>80</output>
<result>C</... | C | 80 | A and B can finish a work in 16 days while A alone can do the same work in 20 days. In how many days B alone will complete the work? | {
"A": "76 days",
"B": "48 days",
"C": "80 days",
"D": "31 days",
"E": "22 days"
} | inverse(subtract(inverse(16), inverse(20))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)| | "b = 1 / 16 – 1 / 20 = 1 / 80 = > 80 days answer : c" | physics |
math_qa__22YMLZd80QPvhm6S | One side of a rectangular field is 13 m and one of its diagonal is 17 m. Find the area of the field. Options.
A) 100
B) 141.7
C) 150
D) 180
E) none | <gadget id="calculator">17 ** 2</gadget>
<output>289</output>
<gadget id="calculator">13 ** 2</gadget>
<output>169</output>
<gadget id="calculator">289 - 169</gadget>
<output>120</output>
<gadget id="calculator">120 ** (1/2)</gadget>
<output>2*sqrt(30) = around 10.954451</output>
<gadget id="calculator">13 * (2*sqr... | B | 141.7 | One side of a rectangular field is 13 m and one of its diagonal is 17 m. Find the area of the field. | {
"A": "100",
"B": "141.7",
"C": "150",
"D": "180",
"E": "none"
} | rectangle_area(13, sqrt(subtract(power(17, const_2), power(13, const_2)))) | power(n1,const_2)|power(n0,const_2)|subtract(#0,#1)|sqrt(#2)|rectangle_area(n0,#3)| | "solution other side = √ ( 17 ) 2 - ( 13 ) 2 = √ 289 - 169 = √ 120 = 10.9 m . ∴ area = ( 13 x 10.9 ) m 2 = 141.7 m 2 . answer b" | geometry |
math_qa__VV9cIDXGdJHiOtfL | A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $16000 left with him. find salary.. Choose the correct choice from the following answers
A) $ 10800 B) $ 18000 C) $ 160000 D) $ 1800 E) none | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) + (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="... | C | 160,000 | A man spend 1/5 of his salary on food , 1/10 of his salary on house rent and 3/5 salary on clothes. he still has $16000 left with him. find salary.. | {
"A": "$ 10800",
"B": "$ 18000",
"C": "$ 160000",
"D": "$ 1800",
"E": "none"
} | divide(16000, subtract(1, add(add(divide(1, 5), divide(1, 10)), divide(3, 5)))) | divide(n0,n1)|divide(n0,n3)|divide(n4,n1)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5)| | "[ 1 / ( x 1 / y 1 + x 2 / y 2 + x 3 / y 3 ) ] * total amount = balance amount [ 1 - ( 1 / 5 + 1 / 10 + 3 / 5 ) } * total salary = $ 16000 , = [ 1 - 9 / 10 ] * total salary = $ 16000 , total salary = $ 16000 * 10 = $ 160000 , correct answer ( c )" | general |
math_qa__8Zqpidw7QVwTgrrM | A has 10000 chocolates.20% of the chocolates are Eaten.What percentage of the uneaten Chocolates must be eaten so that 3/2 of all chocolates are eaten? Choose the correct choice from the following answers
A) 39.25
B) 37.25
C) 37.26
D) 38.21
E) 38.32 | <gadget id="calculator">10_000 / 2</gadget>
<output>5_000</output>
<gadget id="calculator">20 * 10_000</gadget>
<output>200_000</output>
<gadget id="calculator">200_000 / 100</gadget>
<output>2_000</output>
<gadget id="calculator">5_000 - 2_000</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * 100</ga... | B | 37.25 | A has 10000 chocolates.20% of the chocolates are Eaten.What percentage of the uneaten Chocolates must be eaten so that 3/2 of all chocolates are eaten? | {
"A": "39.25",
"B": "37.25",
"C": "37.26",
"D": "38.21",
"E": "38.32"
} | divide(multiply(subtract(divide(10000, 2), divide(multiply(20, 10000), const_100)), const_100), subtract(10000, divide(multiply(20, 10000), const_100))) | divide(n0,n3)|multiply(n0,n1)|divide(#1,const_100)|subtract(#0,#2)|subtract(n0,#2)|multiply(#3,const_100)|divide(#5,#4) | number of chocolates = 10,000 currently eaten = 10,000 * 20 / 100 = 2000 uneaten chocolates = 10000 - 2000 = 8000 2 / 3 of all chocolates = 5000 the number of chocolates to be eaten to make 2 / 3 of all chocolates eaten = 5000 - 2000 = 3000 so now the question remains - 3000 is how much percentage of uneaten chocolates... | gain |
math_qa__2U47iM4Ke67XmTMk | A school has 4 section of Chemistry in Class X having 60, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student. Select
A) 50 B) 52 C) 51 D) 53 E) none of the above | <gadget id="calculator">60 * 50</gadget>
<output>3_000</output>
<gadget id="calculator">35 * 60</gadget>
<output>2_100</output>
<gadget id="calculator">3_000 + 2_100</gadget>
<output>5_100</output>
<gadget id="calculator">45 * 55</gadget>
<output>2_475</output>
<gadget id="calculator">5_100 + 2_475</gadget>
<output... | B | 52 | A school has 4 section of Chemistry in Class X having 60, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student. | {
"A": "50",
"B": "52",
"C": "51",
"D": "53",
"E": "none of the above"
} | divide(add(add(add(multiply(60, 50), multiply(35, 60)), multiply(45, 55)), multiply(42, 45)), add(add(add(60, 35), 45), 42)) | add(n1,n2)|multiply(n1,n5)|multiply(n2,n6)|multiply(n3,n7)|multiply(n3,n4)|add(#1,#2)|add(n3,#0)|add(#5,#3)|add(n4,#6)|add(#7,#4)|divide(#9,#8)| | "required average marks = 60 ã — 50 + 35 ã — 60 + 45 ã — 55 + 42 ã — 45 / 60 + 35 + 45 + 42 = 3000 + 2100 + 2475 + 1890 / 182 = 9465 â „ 182 = 52 answer b" | general |
math_qa__Nlw3ZoN9Ecc8HIKB | The number of employees in Obelix Menhir Co. is a prime number and is less than 300. The ratio of the number of employees who are graduates and above, to that of employees who are not, can possibly be :- Choose the correct choice from the following:
A) 101 : 88
B) 87 : 100
C) 110 : 111
D) 85 : 98
E) 97 : 84 | <gadget id="calculator">300 / 100</gadget>
<output>3</output>
<gadget id="calculator">100 - 3</gadget>
<output>97</output>
<gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">97 - 13</gadget>
<output>84</output>
<gadget id="calculator">97 / 84</gadget>
<output>97/84 = around 1.154762... | E | 1.154762 | The number of employees in Obelix Menhir Co. is a prime number and is less than 300. The ratio of the number of employees who are graduates and above, to that of employees who are not, can possibly be :- | {
"A": "101 : 88",
"B": "87 : 100",
"C": "110 : 111",
"D": "85 : 98",
"E": "97 : 84"
} | divide(subtract(const_100, divide(300, const_100)), subtract(subtract(const_100, divide(300, const_100)), add(const_10, divide(300, const_100)))) | divide(n0,const_100)|add(#0,const_10)|subtract(const_100,#0)|subtract(#2,#1)|divide(#2,#3) | explanation : going through the given options , option 1 : - 101 : 88 = > 189 . [ divisible by 3 ] option 2 : - 87 : 100 = > 187 . [ divisible by 11 ] option 3 : - 85 : 98 = > 183 . [ divisible by 3 ] option 4 : - 97 : 84 = > 181 . [ prime number ] hence , only 181 is the prime number i . e the total number of employee... | general |
math_qa__mwaR7C7lcf1wvy8i | Rs. 825 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 825 become in 3 years ?
Choose the most appropriate option.
A) rs . 1020.80 B) rs . 1025 C) rs . 1055 D) data inadequate E) none of these | <gadget id="calculator">956 - 825</gadget>
<output>131</output>
<gadget id="calculator">131 * 100</gadget>
<output>13_100</output>
<gadget id="calculator">825 * 3</gadget>
<output>2_475</output>
<gadget id="calculator">13_100 / 2_475</gadget>
<output>524/99 = around 5.292929</output>
<gadget id="calculator">(524/99... | C | 1,055 | Rs. 825 becomes Rs. 956 in 3 years at a certain rate of simple interest.If the rate of interest is increased by 4% ,What amount will Rs. 825 become in 3 years ? | {
"A": "rs . 1020.80",
"B": "rs . 1025",
"C": "rs . 1055",
"D": "data inadequate",
"E": "none of these"
} | add(825, divide(multiply(multiply(825, add(divide(multiply(subtract(956, 825), const_100), multiply(825, 3)), 4)), 3), const_100)) | multiply(n0,n2)|subtract(n1,n0)|multiply(#1,const_100)|divide(#2,#0)|add(n3,#3)|multiply(n0,#4)|multiply(n2,#5)|divide(#6,const_100)|add(n0,#7)| | "solution s . i . = rs . ( 956 - 825 ) = rs . 131 rate = ( 100 x 131 / 825 x 3 ) = 524 / 99 % new rate = ( 524 / 99 + 4 ) % = 920 / 99 % new s . i . = rs . ( 825 x 920 / 99 x 3 / 100 ) rs . 230 . ∴ new amount = rs . ( 825 + 230 ) = rs . 1055 . answer c" | gain |
math_qa__S6gSwmof15sIlNZX | Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80?
Choose the correct choice from the following choices
A) 22 B) 27 C) 20 D) 21 E) 12 | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">540 * (23/20)</gadget>
<output>621</output>
<gadget id="calculator">621 - 496.8</gadget>
<output>124.2</output>
<gadget id="calculator">124.2 * 100</... | C | 20 | Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 496.80? | {
"A": "22",
"B": "27",
"C": "20",
"D": "21",
"E": "12"
} | divide(multiply(subtract(multiply(540, divide(add(const_100, 15), const_100)), 496.80), const_100), multiply(540, divide(add(const_100, 15), const_100))) | add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|subtract(#2,n2)|multiply(#3,const_100)|divide(#4,#2)| | "cp = rs . 540 , mp = 540 + 15 % of 540 = rs . 621 sp = rs . 496.80 , discount = 621 - 496.80 = 124.20 discount % = 124.2 / 621 * 100 = 20 % . answer : c" | gain |
math_qa__BSW7Yua5WGQlGbpW | The perimeter of a triangle is 40 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? Choose the correct choice from the following choices
A) 76 B) 88 C) 66 D) 55 E) 50 | <gadget id="calculator">(2.5 * 40) / 2</gadget>
<output>50</output>
<result>E</result> | E | 50 | The perimeter of a triangle is 40 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? | {
"A": "76",
"B": "88",
"C": "66",
"D": "55",
"E": "50"
} | triangle_area(2.5, 40) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the in radius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 40 / 2 = 50 cm 2 answer : e" | geometry |
math_qa__bvZMeuRVG67zFoGw | A man swims downstream 54 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water? Options
A) 2
B) 8
C) 9
D) 10
E) 12 | <gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">54 / 3</gadget>
<output>18</output>
<gadget id="calculator">6 + 18</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>E</result> | E | 12 | A man swims downstream 54 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water? | {
"A": "2",
"B": "8",
"C": "9",
"D": "10",
"E": "12"
} | divide(add(divide(18, 3), divide(54, 3)), const_2) | divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)| | "54 - - - 3 ds = 18 ? - - - - 1 18 - - - - 3 us = 6 ? - - - - 1 m = ? m = ( 18 + 6 ) / 2 = 12 answer : e" | physics |
math_qa__Q027Y8QtTlNQScCb | the average of 11 results is 52 , if the average of first 6 results is 49 and that of the last 6 is 52 . find the sixth result ?
Pick one:
A) 46 B) 34 C) 66 D) 76 E) 74 | <gadget id="calculator">52 * 6</gadget>
<output>312</output>
<gadget id="calculator">49 * 6</gadget>
<output>294</output>
<gadget id="calculator">312 + 294</gadget>
<output>606</output>
<gadget id="calculator">52 * 11</gadget>
<output>572</output>
<gadget id="calculator">606 - 572</gadget>
<output>34</output>
<res... | B | 34 | the average of 11 results is 52 , if the average of first 6 results is 49 and that of the last 6 is 52 . find the sixth result ? | {
"A": "46",
"B": "34",
"C": "66",
"D": "76",
"E": "74"
} | subtract(add(multiply(52, 6), multiply(49, 6)), multiply(52, 11)) | multiply(n1,n2)|multiply(n2,n3)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2) | 1 to 11 = 11 * 52 = 572 1 to 6 = 6 * 49 = 294 6 to 11 = 6 * 52 = 312 6 th = 294 + 312 – 572 = 34 answer : b | general |
math_qa__0PGSc8UGS0Aprgb5 | Sum of the squares of 3 no. is 138 and the sum of their products taken two at a time is 131. Find the sum?
Choose the correct choice from the following answers
A) 20 B) 21 C) 25 D) 26 E) 27 | <gadget id="calculator">131 * 2</gadget>
<output>262</output>
<gadget id="calculator">138 + 262</gadget>
<output>400</output>
<gadget id="calculator">400 ** (1/2)</gadget>
<output>20</output>
<result>A</result> | A | 20 | Sum of the squares of 3 no. is 138 and the sum of their products taken two at a time is 131. Find the sum? | {
"A": "20",
"B": "21",
"C": "25",
"D": "26",
"E": "27"
} | sqrt(add(138, multiply(131, const_2))) | multiply(n2,const_2)|add(n1,#0)|sqrt(#1)| | "( a + b + c ) 2 = a 2 + b 2 + c 2 + 2 ( ab + bc + ca ) = 138 + 2 * 131 a + b + c = √ 400 = 20 a" | general |
math_qa__CJouD1ND5dfOMxjl | The total of 324 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is :
Pick one:
A) 50 B) 100 C) 150 D) 200 E) 250 | <gadget id="calculator">324 * 25</gadget>
<output>8_100</output>
<gadget id="calculator">71 * 100</gadget>
<output>7_100</output>
<gadget id="calculator">8_100 - 7_100</gadget>
<output>1_000</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">1_000 / 5</gadget>
<output>200</... | D | 200 | The total of 324 of 20 paise and 25 paise make a sum of Rs. 71. The no of 20 paise coins is : | {
"A": "50",
"B": "100",
"C": "150",
"D": "200",
"E": "250"
} | divide(subtract(multiply(324, 25), multiply(71, const_100)), subtract(25, 20)) | multiply(n0,n2)|multiply(n3,const_100)|subtract(n2,n1)|subtract(#0,#1)|divide(#3,#2)| | "explanation : let the number of 20 paise coins be x . then the no of 25 paise coins = ( 324 - x ) . 0.20 × ( x ) + 0.25 ( 324 - x ) = 71 = > x = 200 . answer : d" | general |
math_qa__4o775nP1LTHvm4hQ | 120 liters of a mixture contains milk and water in the ratio 4:2. If 10 liters of this mixture be replaced by 10 liters of milk, the ratio of milk to water in the new mixture would be? Pick.
A) 8 : 6 B) 9 : 3 C) 9 : 4 D) 9 : 6 E) 8 : 2 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">18 / 8</gadget>
<output>9/4 = around 2.25</output>
<result>C</result> | C | 2.25 | 120 liters of a mixture contains milk and water in the ratio 4:2. If 10 liters of this mixture be replaced by 10 liters of milk, the ratio of milk to water in the new mixture would be? | {
"A": "8 : 6",
"B": "9 : 3",
"C": "9 : 4",
"D": "9 : 6",
"E": "8 : 2"
} | divide(multiply(subtract(10, const_1), const_2), multiply(const_4, const_2)) | multiply(const_2,const_4)|subtract(n3,const_1)|multiply(#1,const_2)|divide(#2,#0) | quantity of milk in 120 liters if mix = 120 * 4 / 6 = 80 liters quantity of milk in 130 liters of new mix = 80 + 10 = 90 liters quantity of water in it = 130 - 90 = 40 liters ratio of milk and water in new mix = 90 : 40 = 9 : 4 answer is c | other |
math_qa__OhtaYdBnCyDCsdvC | 170kg of an alloy A is mixed with 250 kg of alloy B. If alloy A has lead and tin in the ratio 1:3 and alloy B has tin and copper in the ratio 3:5, then the amount of tin in the new alloy is? Answers:
A) 210.6 kg
B) 221.3 kg
C) 229.5 kg
D) 110.8 kg
E) 114 kg | <gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">170 / 4</gadget>
<output>85/2 = around 42.5</output>
<gadget id="calculator">(85/2) * 3</gadget>
<output>255/2 = around 127.5</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">250 / 8</gadget>
... | B | 221.3 | 170kg of an alloy A is mixed with 250 kg of alloy B. If alloy A has lead and tin in the ratio 1:3 and alloy B has tin and copper in the ratio 3:5, then the amount of tin in the new alloy is? | {
"A": "210.6 kg",
"B": "221.3 kg",
"C": "229.5 kg",
"D": "110.8 kg",
"E": "114 kg"
} | add(multiply(divide(170, add(1, 3)), 3), multiply(divide(250, add(3, 5)), 3)) | add(n2,n3)|add(n4,n5)|divide(n0,#0)|divide(n1,#1)|multiply(n3,#2)|multiply(n4,#3)|add(#4,#5)| | "quantity of tin in 170 kg of a = 170 * 3 / 4 = 127.5 kg quantity of tin in 250 kg of b = 250 * 3 / 8 = 93.75 kg quantity of tin in the new alloy = 127.5 + 93.75 = 221.25 kg answer is b" | other |
math_qa__fFpU0nmzYh6Wvsd3 | A train 360 m long can cross an electric pole in 30 sec and then find the speed of the train?
Choose the correct choice from the following answers
A) 88 kmph B) 43 kmph C) 72 kmph D) 16 kmph E) 18 kmph | <gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">30 / 3_600</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">(9/25) / (1/120)</gadget>
<output>216/5 = around 43.2</output>
<result>B</result> | B | 43 | A train 360 m long can cross an electric pole in 30 sec and then find the speed of the train? | {
"A": "88 kmph",
"B": "43 kmph",
"C": "72 kmph",
"D": "16 kmph",
"E": "18 kmph"
} | divide(divide(360, const_1000), divide(30, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 360 / 30 s = 12 m / sec speed = 12 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 43 kmph answer : b" | physics |
math_qa__DT5zSgT6JxTPRL9N | A can do a piece of work in 4 hours; B and C together can do it in 2 hours, which A and C together can do it in 2 hours. How long will B alone take to do it? Choose the correct choice from the following options
A) 2 hours B) 3 hours C) 4 hours D) 5 hours E) 6 hours | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) - (1/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>C</result> | C | 4 | A can do a piece of work in 4 hours; B and C together can do it in 2 hours, which A and C together can do it in 2 hours. How long will B alone take to do it? | {
"A": "2 hours",
"B": "3 hours",
"C": "4 hours",
"D": "5 hours",
"E": "6 hours"
} | divide(const_1, subtract(divide(const_1, 2), subtract(divide(const_1, 2), divide(const_1, 4)))) | divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n0)|subtract(#1,#2)|subtract(#0,#3)|divide(const_1,#4)| | "a ' s 1 hour work = 1 / 4 ; ( b + c ) ' s 1 hour work = 1 / 2 ; ( a + c ) ' s 1 hour work = 1 / 2 ( a + b + c ) ' s 1 hour work = ( 1 / 4 + 1 / 2 ) = 3 / 4 b ' s 1 hour work = ( 3 / 4 - 1 / 2 ) = 1 / 4 b alone will take 4 hours to do the work . answer : c" | physics |
math_qa__Hyk4TgnlXBuNBEmS | The maximum number of student amoung them 1204 pens and 840 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : Choose the correct choice: A) 91 B) 28 C) 56 D) 89 E) none of these | <gadget id="calculator">gcd(1_204, 840)</gadget>
<output>28</output>
<result>B</result> | B | 28 | The maximum number of student amoung them 1204 pens and 840 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : | {
"A": "91",
"B": "28",
"C": "56",
"D": "89",
"E": "none of these"
} | gcd(1204, 840) | gcd(n0,n1)| | "solution required number of student = h . c . f of 1204 and 840 = 28 . answer b" | general |
math_qa__WFFLB67mM2h2jxj3 | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If ... | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 3</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) / 2</gadget>
<output>1/60 = around 0.016667</ou... | E | 105 | In the standard formulation of a flavored drink the ratio by volume of flavoring to corn syrup to water is 1 : 12 : 30. In the sport formulation, the ratio of flavoring to corn syrup is three times as great as in the standard formulation, and the ratio of flavoring to water is half that of the standard formulation. If ... | {
"A": "45",
"B": "50",
"C": "55",
"D": "60",
"E": "105"
} | multiply(divide(multiply(divide(1, 12), const_3), divide(divide(1, 30), const_2)), 7) | divide(n0,n1)|divide(n0,n2)|divide(#1,const_2)|multiply(#0,const_3)|divide(#3,#2)|multiply(n3,#4)| | "f : c : w 1 : 12 : 30 sport version : f : c 3 : 12 f : w 1 : 60 or 3 : 180 so c : f : w = 12 : 3 : 180 c / w = 12 / 180 = 3 ounces / x ounces x = 7 * 180 / 12 = 105 ounces of water e" | other |
math_qa__PwTwb0u0FQRrK55W | A company pays 12.5% dividend to its investors. If an investor buys Rs.40 shares and gets 25% on investment, at what price did the investor buy the shares? Choose the correct choice from the following answers:
A) 20
B) 66
C) 18
D) 19
E) 01 | <gadget id="calculator">12.5 * 40</gadget>
<output>500</output>
<gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">500 / 25</gadget>
<output>20</output>
<result>A</result> | A | 20 | A company pays 12.5% dividend to its investors. If an investor buys Rs.40 shares and gets 25% on investment, at what price did the investor buy the shares? | {
"A": "20",
"B": "66",
"C": "18",
"D": "19",
"E": "01"
} | divide(multiply(divide(multiply(12.5, 40), const_100), const_100), 25) | multiply(n0,n1)|divide(#0,const_100)|multiply(#1,const_100)|divide(#2,n2)| | "explanation : dividend on 1 share = ( 12.5 * 40 ) / 100 = rs . 5 rs . 25 is income on an investment of rs . 100 rs . 5 is income on an investment of rs . ( 5 * 100 ) / 25 = rs . 20 answer : a" | gain |
math_qa__WAybbVRypPDuaXmC | How many even number in the range between 10 to 140 inclusive are not divisible by 3 Choose the correct choice from the following choices.
A) 15 B) 30 C) 31 D) 33 E) 44 | <gadget id="calculator">140 - 10</gadget>
<output>130</output>
<gadget id="calculator">130 - 2</gadget>
<output>128</output>
<gadget id="calculator">128 / 2</gadget>
<output>64</output>
<gadget id="calculator">140 - 2</gadget>
<output>138</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget ... | E | 44 | How many even number in the range between 10 to 140 inclusive are not divisible by 3 | {
"A": "15",
"B": "30",
"C": "31",
"D": "33",
"E": "44"
} | subtract(divide(subtract(subtract(140, 10), const_2), const_2), divide(divide(subtract(subtract(subtract(subtract(140, const_2), multiply(3, const_4)), 3), 3), 3), const_2)) | multiply(n2,const_4)|subtract(n1,n0)|subtract(n1,const_2)|subtract(#1,const_2)|subtract(#2,#0)|divide(#3,const_2)|subtract(#4,n2)|subtract(#6,n2)|divide(#7,n2)|divide(#8,const_2)|subtract(#5,#9) | we have to find the number of terms that are divisible by 2 but not by 6 ( as the question asks for the even numbers only which are not divisible by 3 ) for 2 , 10 , 12,14 . . . 140 using ap formula , we can say 140 = 10 + ( n - 1 ) * 2 or n = 66 . for 6 , 12,18 , . . . 138 using ap formula , we can say 138 = 12 + ( n ... | general |
math_qa__8pj2W2y23VGWY82O | A cricketer scored 142 runs which included 12 boundaries and 2 sixes. What percent of his total score did he make by running between the wickets. Choose the correct choice:
A) 57.75 %
B) 54.54 %
C) 63 %
D) 70 %
E) none of these | <gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">48 + 12</gadget>
<output>60</output>
<gadget id="calculator">142 - 60</gadget>
<output>82</output>
<gadget id="cal... | A | 57.75 | A cricketer scored 142 runs which included 12 boundaries and 2 sixes. What percent of his total score did he make by running between the wickets. | {
"A": "57.75 %",
"B": "54.54 %",
"C": "63 %",
"D": "70 %",
"E": "none of these"
} | multiply(divide(subtract(142, add(multiply(12, const_4), multiply(2, multiply(2, const_3)))), 142), const_100) | multiply(n1,const_4)|multiply(n2,const_3)|multiply(n2,#1)|add(#0,#2)|subtract(n0,#3)|divide(#4,n0)|multiply(#5,const_100)| | "explanation : number of runs made by running = 142 - ( 12 x 4 + 2 x 6 ) = 142 - ( 60 ) = 82 now , we need to calculate 82 is what percent of 142 . = > 82 / 142 * 100 = 57.75 % answer : a" | general |
math_qa__ccMxDOkpAdo2uO5p | A train running at the speed of 54 km/hr crosses a pole in 9 sec. What is the length of the train? Answers
A) 288 B) 279 C) 135 D) 272 E) 150 | <gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 3_600</gadget>
<output>15</output>
<gadget id="calculator">15 * 9</gadget>
<output>135</output>
<result>C</result> | C | 135 | A train running at the speed of 54 km/hr crosses a pole in 9 sec. What is the length of the train? | {
"A": "288",
"B": "279",
"C": "135",
"D": "272",
"E": "150"
} | multiply(divide(multiply(54, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 54 * 5 / 18 = 15 m / sec length of the train = speed * time = 15 * 9 = 135 m answer : c" | physics |
math_qa__3HFWIKKWgI9fW6pS | A box contains 5 pairs of shoes (10 shoes in total). If two shoes are selected at random, what it is the probability that they are matching shoes? Pick one:
A) 1 / 190 B) 1 / 20 C) 1 / 9 D) 1 / 10 E) 1 / 92 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<result>C</result> | C | 0.111111 | A box contains 5 pairs of shoes (10 shoes in total). If two shoes are selected at random, what it is the probability that they are matching shoes? | {
"A": "1 / 190",
"B": "1 / 20",
"C": "1 / 9",
"D": "1 / 10",
"E": "1 / 92"
} | divide(const_1, subtract(10, const_1)) | subtract(n1,const_1)|divide(const_1,#0)| | "the problem with your solution is that we do n ' t choose 1 shoe from 20 , but rather choose the needed one after we just took one and need the second to be the pair of it . so , the probability would simply be : 1 / 1 * 1 / 9 ( as after taking one at random there are 9 shoes left and only one is the pair of the first... | general |
math_qa__YJdC48ZLOreXNA3Q | If the price of petrol increases by 32, by how much must a user cut down his consumption so that his expenditure on petrol remains constant? Choose the correct choice from the following answers: A) 25 % B) 20 % C) 24.2 % D) 33.33 % E) none of these | <gadget id="calculator">100 + 32</gadget>
<output>132</output>
<gadget id="calculator">100 / 132</gadget>
<output>25/33 = around 0.757576</output>
<gadget id="calculator">1 - (25/33)</gadget>
<output>8/33 = around 0.242424</output>
<gadget id="calculator">(8/33) * 100</gadget>
<output>800/33 = around 24.242424</outp... | C | 24.2 | If the price of petrol increases by 32, by how much must a user cut down his consumption so that his expenditure on petrol remains constant? | {
"A": "25 %",
"B": "20 %",
"C": "24.2 %",
"D": "33.33 %",
"E": "none of these"
} | multiply(subtract(const_1, divide(const_100, add(const_100, 32))), const_100) | add(n0,const_100)|divide(const_100,#0)|subtract(const_1,#1)|multiply(#2,const_100) | explanation : let us assume before increase the petrol will be rs . 100 . after increase it will be rs ( 100 + 32 ) i . e 132 . now , his consumption should be reduced to : - = ( 132 − 100 ) / 132 ∗ 100 . hence , the consumption should be reduced to 24.2 % . answer : c | general |
math_qa__ZcdrQEg2bQqAOHUm | 108. Triangle A’s base is 7% greater than the base of triangle B, and A’s height is 7% less than the height of triangle B. The area of triangle A is what percent less or more than the area of triangle B? Choose the correct choice from the following answers
A) 9 % less
B) 1 % less
C) equal to each other
D) 1 % more
E) ... | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 + 7</gadget>
<output>107</output>
<gadget id="calculator">100 - 7</gadget>
<output>93</output>
<gadget id="calculator">107 * 93</gadget>
<output>9_951</output>
<gadget id="calculator">10_000 - 9_951</gadget>
<output>49</o... | E | 2.1 | 108. Triangle A’s base is 7% greater than the base of triangle B, and A’s height is 7% less than the height of triangle B. The area of triangle A is what percent less or more than the area of triangle B? | {
"A": "9 % less",
"B": "1 % less",
"C": "equal to each other",
"D": "1 % more",
"E": "2.1 % more"
} | divide(const_100, subtract(multiply(const_100, const_100), multiply(add(const_100, 7), subtract(const_100, 7)))) | add(n1,const_100)|multiply(const_100,const_100)|subtract(const_100,n1)|multiply(#0,#2)|subtract(#1,#3)|divide(const_100,#4)| | "wish the question specified that we are talking about corresponding height . base of a = 8 / 7 * base of b height of a = 6 / 7 * height of b area of a = ( 1 / 2 ) * base of a * height of a = 8 / 7 * 6 / 7 * area of b = 48 / 49 * area of b area of a is 2.1 % more than the area of b . answer ( e )" | geometry |
math_qa__581Jr5ZgH4dMAhDw | Praveen starts business with Rs.3360 and after 5 months, Hari joins with Praveen as his partner. After a year, the profit is divided in the ratio 2 : 3. What is Hari’s contribution in the capital? Choose the correct choice from the following: A) s . 7500 B) s . 8640 C) s . 8500 D) s . 9000 E) s . 6000 | <gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">1 - (5/12)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">3_360 / (7/12)</gadget>
<output>5_760</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<ga... | B | 8,640 | Praveen starts business with Rs.3360 and after 5 months, Hari joins with Praveen as his partner. After a year, the profit is divided in the ratio 2 : 3. What is Hari’s contribution in the capital? | {
"A": "s . 7500",
"B": "s . 8640",
"C": "s . 8500",
"D": "s . 9000",
"E": "s . 6000"
} | divide(divide(3360, subtract(const_1, divide(5, const_12))), divide(2, 3)) | divide(n1,const_12)|divide(n2,n3)|subtract(const_1,#0)|divide(n0,#2)|divide(#3,#1) | let hari ’ s capital be rs . x . then , 3360 * 12 / 7 x = 2 / 3 = > 14 x = 120960 = > x = 8640 . answer : b | other |
math_qa__CBhbJzIK3xSWfTRV | The average (arithmetic mean) of 10, 20, and 60 is 5 more than the average of 10, 40, and what number? Choose the correct choice from the following choices:
A) 25 B) 60 C) 50 D) 30 E) 40 | <gadget id="calculator">10 + 20</gadget>
<output>30</output>
<gadget id="calculator">30 + 60</gadget>
<output>90</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 40</gadget>
<output>65</output>
<gadget id="... | A | 25 | The average (arithmetic mean) of 10, 20, and 60 is 5 more than the average of 10, 40, and what number? | {
"A": "25",
"B": "60",
"C": "50",
"D": "30",
"E": "40"
} | subtract(add(add(10, 20), 60), add(add(multiply(5, const_3), 10), 40)) | add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4)| | "a 1 = 90 / 3 = 30 a 2 = a 1 - 5 = 25 sum of second list = 25 * 3 = 75 therefore the number = 75 - 50 = 25 a" | general |
math_qa__kWsIHGCMUh5pxCor | Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much does she have in her account after two years? Choose one:
A) $ 10079.44 B) $ 10815.83 C) $ 12652.61 D) $ 14232.14 E) $ 20598.11 | <gadget id="calculator">3.96 / 100</gadget>
<output>0.0396</output>
<gadget id="calculator">0.0396 / 2</gadget>
<output>0.0198</output>
<gadget id="calculator">1 + 0.0198</gadget>
<output>1.0198</output>
<gadget id="calculator">1.0198 ** 4</gadget>
<output>1.081583</output>
<gadget id="calculator">10_000 * 1.081583... | B | 10,815.83 | Jill invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. Approximately how much does she have in her account after two years? | {
"A": "$ 10079.44",
"B": "$ 10815.83",
"C": "$ 12652.61",
"D": "$ 14232.14",
"E": "$ 20598.11"
} | multiply(10000, power(add(const_1, divide(divide(3.96, const_100), const_2)), const_4)) | divide(n1,const_100)|divide(#0,const_2)|add(#1,const_1)|power(#2,const_4)|multiply(n0,#3) | solution : first of all , notice the magic word “ approximately ” — the test - writer is letting us know estimation is perfectly fine . furthermore , the answer choices are nicely spread out , which will facilitate estimating . ok , get ready for some fast & furious estimation . the interest rate 3.96 % is an ugly numb... | gain |
math_qa__7G7Xn61eUxP2aZkf | 250 men work for 16 days and finish a work. How many men would do a job 3 times the previous one in 20 days? Choose the most appropriate option
A) 700 B) 666 C) 600 D) 400 E) 800 | <gadget id="calculator">250 * 16</gadget>
<output>4_000</output>
<gadget id="calculator">3 * 4_000</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 20</gadget>
<output>600</output>
<result>C</result> | C | 600 | 250 men work for 16 days and finish a work. How many men would do a job 3 times the previous one in 20 days? | {
"A": "700",
"B": "666",
"C": "600",
"D": "400",
"E": "800"
} | divide(multiply(3, multiply(250, 16)), 20) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n3) | number of men needed to finish the required work ( variation , proportion method ) = 3 * 16 * 250 / 20 = 600 answer : c | physics |
math_qa__tK4i3jDWBotbB3eW | Solution for 1.35+.123+.321 Options:
A) 2.91 B) 1.794 C) 1.338 D) 1.986 E) 1.999 | <gadget id="calculator">123 / 1_000</gadget>
<output>123/1_000 = around 0.123</output>
<gadget id="calculator">1.35 + (123/1_000)</gadget>
<output>1.473</output>
<gadget id="calculator">321 / 1_000</gadget>
<output>321/1_000 = around 0.321</output>
<gadget id="calculator">1.473 + (321/1_000)</gadget>
<output>1.794</... | B | 1.794 | Solution for 1.35+.123+.321 | {
"A": "2.91",
"B": "1.794",
"C": "1.338",
"D": "1.986",
"E": "1.999"
} | add(add(1.35, divide(123, const_1000)), divide(321, const_1000)) | divide(n1,const_1000)|divide(n2,const_1000)|add(n0,#0)|add(#2,#1)| | "1.35 + . 123 + . 321 = 0 0 = 0 - 1.35 - 0.123 - 0.321 0 = - 1.794 answer : b" | general |
math_qa__waFuZaDaG1cJFo25 | The population of a town increases 25% and 15% respectively in two consecutive years. After the growth the present population of the town is 1150. Then what is the population of the town 2 years ago? Pick:
A) 400
B) 500
C) 600
D) 700
E) 800 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<g... | E | 800 | The population of a town increases 25% and 15% respectively in two consecutive years. After the growth the present population of the town is 1150. Then what is the population of the town 2 years ago? | {
"A": "400",
"B": "500",
"C": "600",
"D": "700",
"E": "800"
} | divide(1150, multiply(add(const_1, divide(25, const_100)), add(const_1, divide(15, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|divide(n2,#4) | explanation : formula : ( after = 100 denominator ago = 100 numerator ) 1150 * 100 / 125 * 100 / 115 = 800 answer : option e | gain |
math_qa__UDqmwCfmPsciIYzv | Two trains start simultaneously from opposite ends of a 160-km route and travel toward each other on parallel tracks. Train X, traveling at a constant rate, completes the 160-km trip in 5 hours. Train Y, travelling at a constant rate, completes the 160-km trip in 3 hours. How many kilometers had Train X traveled when i... | <gadget id="calculator">160 / 5</gadget>
<output>32</output>
<gadget id="calculator">160 / 3</gadget>
<output>160/3 = around 53.333333</output>
<gadget id="calculator">32 + (160/3)</gadget>
<output>256/3 = around 85.333333</output>
<gadget id="calculator">160 / (256/3)</gadget>
<output>15/8 = around 1.875</output>
... | C | 60 | Two trains start simultaneously from opposite ends of a 160-km route and travel toward each other on parallel tracks. Train X, traveling at a constant rate, completes the 160-km trip in 5 hours. Train Y, travelling at a constant rate, completes the 160-km trip in 3 hours. How many kilometers had Train X traveled when i... | {
"A": "56",
"B": "58",
"C": "60",
"D": "62",
"E": "64"
} | multiply(divide(160, 5), divide(160, add(divide(160, 5), divide(160, 3)))) | divide(n0,n2)|divide(n0,n4)|add(#0,#1)|divide(n0,#2)|multiply(#0,#3)| | if the two trains cover a total distance d , then train x travels ( 3 / 8 ) * d while train y travels ( 5 / 8 ) * d . if the trains travel 160 km to the meeting point , then train x travels ( 3 / 8 ) * 160 = 60 km . the answer is c . | physics |
math_qa__e1ao2lzW3sBCdkxI | Company P had 15 percent more employees in December than it had in January. If Company P had 490 employees in December, how many employees did it have in January?
Choose the most appropriate option
A) 391 B) 426 C) 410 D) 423 E) 445 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">490 / (23/20)</gadget>
<output>9_800/23 = around 426.086957</output>
<result>B</result> | B | 426 | Company P had 15 percent more employees in December than it had in January. If Company P had 490 employees in December, how many employees did it have in January? | {
"A": "391",
"B": "426",
"C": "410",
"D": "423",
"E": "445"
} | divide(490, add(const_1, divide(15, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "d = number of employees in december j = number of employees in january j x 1.15 = d j x 1.15 = 490 j = 490 / 1.15 j = 49,000 / 115 = 426 thus b is the correct answer ." | gain |
math_qa__IpvyKQiMynlQPgdw | The Present worth of Rs. 1404 due in two equal half-yearly instalments at 8% per annum simple interest is : Choose the most appropriate option:
A) rs . 1325 B) rs . 1300 C) rs . 1350 D) rs . 1500 E) none | <gadget id="calculator">1_404 / 2</gadget>
<output>702</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">108 / 100</gadget>
<output>27/25 = around 1.08</output>
<gadget id="calculator">702 / (27/25)</gadget>
<output>650</output>
<gadget id="calculator">8 / 2</gadget>
<ou... | A | 1,325 | The Present worth of Rs. 1404 due in two equal half-yearly instalments at 8% per annum simple interest is : | {
"A": "rs . 1325",
"B": "rs . 1300",
"C": "rs . 1350",
"D": "rs . 1500",
"E": "none"
} | add(divide(divide(1404, const_2), divide(add(const_100, 8), const_100)), divide(divide(1404, const_2), divide(add(const_100, divide(8, const_2)), const_100))) | add(n1,const_100)|divide(n0,const_2)|divide(n1,const_2)|add(#2,const_100)|divide(#0,const_100)|divide(#1,#4)|divide(#3,const_100)|divide(#1,#6)|add(#5,#7) | solution required sum = p . w . of rs . 702 due 6 month hence + p . w . of rs . 702 due 1 year hence = rs . [ ( 100 x 702 / 100 + 8 x 1 / 2 ) + ( 100 x 702 / 100 + ( 8 x 1 ) ) ] = rs . ( 675 + 650 ) = rs . 1325 . answer a | gain |
math_qa__U1Zdelb6wzhWpjx0 | The weight of every type A widget is the same, the weight of every type B widget is the same, and the weight of every type C widget is the same. If the weight of 7 type A widgets is equal to the weight of 3 type B widgets, and the weight of 5 type B widgets is equal to the weight of 7 type C widgets. What is the ratio ... | <gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">1 + (7/3)</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(7/3) + (5/3)</gadget>
<output>4</output>
<gadget id=... | E | 0.833333 | The weight of every type A widget is the same, the weight of every type B widget is the same, and the weight of every type C widget is the same. If the weight of 7 type A widgets is equal to the weight of 3 type B widgets, and the weight of 5 type B widgets is equal to the weight of 7 type C widgets. What is the ratio ... | {
"A": "1 : 2",
"B": "2 : 3",
"C": "3 : 4",
"D": "4 : 5",
"E": "5 : 6"
} | divide(add(1, divide(7, 3)), add(divide(7, 3), divide(5, 3))) | divide(n0,n1)|divide(n2,n1)|add(n4,#0)|add(#0,#1)|divide(#2,#3)| | "5 b = 7 c and so b = 7 c / 5 7 a = 3 b and so a = 3 b / 7 = 3 c / 5 a + b = 3 c / 5 + 7 c / 5 = 10 c / 5 b + c = 7 c / 5 + c = 12 c / 5 the ratio of a + b : b + c = 10 : 12 = 5 : 6 the answer is e ." | general |
math_qa__hKycdgJwxT8b2ZL7 | 20 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor? Choose the correct choice: A) 14.4 B) 180 C) 50.4 D) 60 E) 90 | <gadget id="calculator">4 * 9</gadget>
<output>36</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">36 / (1/5)</gadget>
<output>180</output>
<result>B</result> | B | 180 | 20 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor? | {
"A": "14.4",
"B": "180",
"C": "50.4",
"D": "60",
"E": "90"
} | divide(multiply(4, 9), divide(20, const_100)) | divide(n0,const_100)|multiply(n1,n2)|divide(#1,#0)| | "20 % of area of the floor = 4 * 9 square feet = 36 square feet i . e . 100 % area of floor = ( 36 / 20 ) * 100 = 180 square feet answer : option b" | gain |
math_qa__h23IsBQ9sE6Qj2Es | A student scored an average of 60 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics?
Choose the correct choice from the following choices.
A) 86 B) 160 C) 76 D) 140 E) 26 | <gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">180 + 140</gadget>
<output>320</output>
<gadget id="calculator">60 * 3</gadget>
<output>180</output>
<gadget id="calculator">320 - 180</gadget>
<output>140</output>
<res... | D | 140 | A student scored an average of 60 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? | {
"A": "86",
"B": "160",
"C": "76",
"D": "140",
"E": "26"
} | subtract(add(multiply(90, const_2), multiply(70, const_2)), multiply(60, 3)) | multiply(n2,const_2)|multiply(n3,const_2)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2)| | "given m + p + c = 60 * 3 = 180 - - - ( 1 ) m + p = 90 * 2 = 180 - - - ( 2 ) p + c = 70 * 2 = 140 - - - ( 3 ) where m , p and c are marks obtained by the student in mathematics , physics and chemistry . p = ( 2 ) + ( 3 ) - ( 1 ) = 180 + 140 - 180 = 140 answer : d" | general |
math_qa__DiXgSgujpvrov48w | If m is an integer such that (-2)^2m=2^(21-m) then m=?
Choices.
A) 5 B) 6 C) 7 D) 8 E) 9 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">21 / 3</gadget>
<output>7</output>
<result>C</result> | C | 7 | If m is an integer such that (-2)^2m=2^(21-m) then m=? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "9"
} | divide(21, add(2, const_1)) | add(n0,const_1)|divide(n3,#0)| | "2 m = 21 - m 3 m = 21 m = 7 the answer is c ." | general |
math_qa__Y7ot2bAxSHXwUlA7 | Each of the dogs in a certain kennel is a single color. Each of the dogs in the kennel either has long fur or does not. Of the 45 dogs in the kennel, 29 have long fur, 17 are brown, and 8 are neither long-furred nor brown. How many long-furred dogs are brown? Choose the correct choice.
A) 26 B) 19 C) 11 D) 8 E) 9 | <gadget id="calculator">29 + 17</gadget>
<output>46</output>
<gadget id="calculator">45 - 8</gadget>
<output>37</output>
<gadget id="calculator">46 - 37</gadget>
<output>9</output>
<result>E</result> | E | 9 | Each of the dogs in a certain kennel is a single color. Each of the dogs in the kennel either has long fur or does not. Of the 45 dogs in the kennel, 29 have long fur, 17 are brown, and 8 are neither long-furred nor brown. How many long-furred dogs are brown? | {
"A": "26",
"B": "19",
"C": "11",
"D": "8",
"E": "9"
} | subtract(add(29, 17), subtract(45, 8)) | add(n1,n2)|subtract(n0,n3)|subtract(#0,#1) | no of dogs = 45 long fur = 29 brown = 17 neither long fur nor brown = 8 therefore , either long fur or brown = 45 - 8 = 37 37 = 29 + 17 - both both = 9 answer e | other |
math_qa__RgxLhARGFLqVHtK5 | Set A contains all the even numbers between 42 and 90 inclusive. Set B contains all the even numbers between 62 and 110 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? Pick
A) 300 B) 350 C) 400 D) 450 E) 500 | <gadget id="calculator">62 - 42</gadget>
<output>20</output>
<gadget id="calculator">90 - 42</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">20 * 25</gadget>
<output>500</output>
<result>E</... | E | 500 | Set A contains all the even numbers between 42 and 90 inclusive. Set B contains all the even numbers between 62 and 110 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? | {
"A": "300",
"B": "350",
"C": "400",
"D": "450",
"E": "500"
} | multiply(subtract(62, 42), add(divide(subtract(90, 42), const_2), const_1)) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,const_2)|add(#2,const_1)|multiply(#3,#1)| | "each term in set b is 20 more than the corresponding term in set a . the difference of the sums = 25 * 20 = 500 . the answer is e ." | general |
math_qa__YyOiWRyZCnB1koDf | Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/6, what percent of the total number of the remaining employees would then be clerical? Select the correct option
A) 25 %
B) 22.2 %
C) 20 %
D) 29.4 %
E) 11.1 % | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 - (1/6)</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">(1/3) * (5/6)</gadget>
<output>5/18 = around 0.277778</... | D | 29.4 | Of the 3,600 employees of Company X, 1/3 are clerical. If the clerical staff were to be reduced by 1/6, what percent of the total number of the remaining employees would then be clerical? | {
"A": "25 %",
"B": "22.2 %",
"C": "20 %",
"D": "29.4 %",
"E": "11.1 %"
} | multiply(divide(multiply(divide(1, 3), subtract(1, divide(1, 6))), add(multiply(divide(1, 3), subtract(1, divide(1, 6))), subtract(1, divide(1, 3)))), const_100) | divide(n1,n2)|divide(n3,n4)|subtract(n3,#1)|subtract(n3,#0)|multiply(#0,#2)|add(#4,#3)|divide(#4,#5)|multiply(#6,const_100)| | "welcome , just post the question and the choices let ' s see , the way i did it was 1 / 3 are clerical out of 3600 so 1200 are clerical 1200 reduced by 1 / 6 is 1200 * 1 / 6 so it reduced 200 people , so there is 1000 clerical people left but since 200 people left , it also reduced from the total of 3600 so there are ... | general |
math_qa__4AKssqOnTi3iDvcm | The tax on a commodity is diminished by 17% and its consumption increased by 15%. The effect on revenue is?
Pick one:
A) 2 %
B) 8 %
C) 4.5 %
D) 6.5 %
E) 1.5 % | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">17 / 100</gadget>
<output>17/100 = around 0.17</output>
<gadget id="calculator">1 - (17/100)</gadget>
<output>83/100 = around 0.83</ou... | C | 4.5 | The tax on a commodity is diminished by 17% and its consumption increased by 15%. The effect on revenue is? | {
"A": "2 %",
"B": "8 %",
"C": "4.5 %",
"D": "6.5 %",
"E": "1.5 %"
} | subtract(const_100, multiply(multiply(add(const_1, divide(15, const_100)), subtract(const_1, divide(17, const_100))), const_100)) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(const_100,#5)| | "100 * 100 = 10000 83 * 115 = 9545 - - - - - - - - - - - 10000 - - - - - - - - - - - 455 100 - - - - - - - - - - - ? = > 4.55 % decrease answer : c" | general |
math_qa__iG8BN3IZIFUUYLSy | If x is 20 percent greater than 80, then x = Choose the correct choice from the following options.
A) 68 B) 70.4 C) 96 D) 105.6 E) 108 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 80</gadget>
<output>16</output>
<gadget id="calculator">80 + 16</gadget>
<output>96</output>
<result>C</result> | C | 96 | If x is 20 percent greater than 80, then x = | {
"A": "68",
"B": "70.4",
"C": "96",
"D": "105.6",
"E": "108"
} | add(80, multiply(divide(20, const_100), 80)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)| | "x is 20 % greater than 80 means x is 1.2 times 80 ( in other words 80 + 20 / 100 * 80 = 1.2 * 80 ) therefore , x = 1.2 * 80 = 96.00 answer : c" | general |
math_qa__KYEY9ddEwShHDyXC | A pet groomer has 7 animals to groom for the day (2 cats and 5 dogs). If she randomly selects 4 animals to groom before lunch, what is the probability she will finish all the cats before lunch? Choose the correct choice from the following
A) 3 / 7 B) 2 / 7 C) 12 / 13 D) 5 / 11 E) 4 / 7 | <gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<result>B</result> | B | 0.285714 | A pet groomer has 7 animals to groom for the day (2 cats and 5 dogs). If she randomly selects 4 animals to groom before lunch, what is the probability she will finish all the cats before lunch? | {
"A": "3 / 7",
"B": "2 / 7",
"C": "12 / 13",
"D": "5 / 11",
"E": "4 / 7"
} | divide(2, 7) | divide(n1,n0) | combination probability formula : ncr = n ! / [ r ! ( n - r ) ! ] total possible , select 4 animals from 7 animals = 7 c 4 = 7 ! / [ 4 ! ( 7 - 4 ) ! ] = 35 . to finish all 2 cats there must be 2 dogs , select 2 dogs from 5 = 5 c 2 = 10 . and , select 2 cats from 2 = 2 c 2 = 1 . 2 cats and 2 dogs = ( 1 ) ( 10 ) = 10 pro... | physics |
math_qa__qKeEbxS0tjGDnxQA | At the wholesale store you can buy an 8-pack of hot dogs for $1.75, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $250?
Choose one.
A) 1,108
B) 2,100
C) 2,108
D) 2,628
E) 2,256 | <gadget id="calculator">250 / 22.95</gadget>
<output>10.893246</output>
<gadget id="calculator">10.893246 * 250</gadget>
<output>2_723.3115</output>
<result>D</result> | D | 2,628 | At the wholesale store you can buy an 8-pack of hot dogs for $1.75, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $250? | {
"A": "1,108",
"B": "2,100",
"C": "2,108",
"D": "2,628",
"E": "2,256"
} | multiply(divide(250, 22.95), 250) | divide(n6,n5)|multiply(n4,#0)| | "to maximize number of hot dogs with 250 $ total number of hot dogs bought in 250 - pack = 22.95 * 10 = 229.5 $ amount remaining = 250 - 229.5 = 20.5 $ total number of hot dogs bought in 20 - pack = 3.05 * 6 = 18.3 $ amount remaining = 20.5 - 18.3 = 2.2 $ total number of hot dogs bought in 8 - pack = 1.55 * 1 = 1.55 $ ... | general |
math_qa__5QUJBgMxinbDEvFx | A bag contains an equal number of one rupee, 50 paise and 25 paise coins respectively. If the total value is 70, how many coins of each type are there?
Answers.
A) 20 coins B) 30 coins C) 40 coins D) 25 coins E) none of these | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) + 1</gadget>
<output>7/4 = around 1.75</output>
<gadget i... | C | 40 | A bag contains an equal number of one rupee, 50 paise and 25 paise coins respectively. If the total value is 70, how many coins of each type are there? | {
"A": "20 coins",
"B": "30 coins",
"C": "40 coins",
"D": "25 coins",
"E": "none of these"
} | divide(70, add(add(inverse(const_4), inverse(const_2)), const_1)) | inverse(const_4)|inverse(const_2)|add(#0,#1)|add(#2,const_1)|divide(n2,#3)| | "let number of each type of coin = x . then , 1 × x + . 50 × x + . 25 x = 70 ⇒ 1.75 x = 70 ⇒ x = 40 coins answer c" | general |
math_qa__eVZnwzCwKTVTHqzO | How many positive integers less than 26 are prime numbers, odd multiples of 5, or the sum of a positive multiple of 2 and a positive multiple of 4? Options
A) 27
B) 21
C) 24
D) 22
E) 20 | <gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">24 - 1</gadget>
<output>23</output>
<gadget id="calculator">23 - 1</gadget>
<output>22</output>
<result>B</result> | B | 21 | How many positive integers less than 26 are prime numbers, odd multiples of 5, or the sum of a positive multiple of 2 and a positive multiple of 4? | {
"A": "27",
"B": "21",
"C": "24",
"D": "22",
"E": "20"
} | subtract(subtract(subtract(26, 2), const_1), const_1) | subtract(n0,n2)|subtract(#0,const_1)|subtract(#1,const_1) | 9 prime numbers less than 28 : { 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 } 3 odd multiples of 5 : { 5 , 15 , 25 } 10 numbers which are the sum of a positive multiple of 2 and a positive multiple of 4 : { 6 , 8 , 10 , 12 , 14 , 16 , 18 , 20 , 22 , 24 } notice , that 5 is in two sets , thus total # of integers satisfying ... | general |
math_qa__KSmvyVSrxUbq27Eb | A person lent a certain sum of money at 6% per annum at simple interest and in 8 years the interest amounted to $520 less than the sum lent. What was the sum lent? Choose the correct answer
A) 800
B) 1000
C) 1200
D) 1400
E) 1600 | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">48 / 100</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">1 - (12/25)</gadget>
<output>13/25 = around 0.52</output>
<gadget id="calculator">520 / (13/25)</gadget>
<output>1_000</output>
<result>B</result> | B | 1,000 | A person lent a certain sum of money at 6% per annum at simple interest and in 8 years the interest amounted to $520 less than the sum lent. What was the sum lent? | {
"A": "800",
"B": "1000",
"C": "1200",
"D": "1400",
"E": "1600"
} | divide(520, subtract(const_1, divide(multiply(6, 8), const_100))) | multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)| | "p - 520 = ( p * 6 * 8 ) / 100 p = 1000 the answer is b ." | gain |
math_qa__1Yrst5k67ZrK3f2w | There are 30 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?
Choose the correct choice from the following answers
A) 10 B) 30 C) 435 D) 60 E) 90 | <gadget id="calculator">30 - 1</gadget>
<output>29</output>
<gadget id="calculator">30 * 29</gadget>
<output>870</output>
<gadget id="calculator">870 / 2</gadget>
<output>435</output>
<result>C</result> | C | 435 | There are 30 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played? | {
"A": "10",
"B": "30",
"C": "435",
"D": "60",
"E": "90"
} | divide(multiply(30, subtract(30, const_1)), const_2) | subtract(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)| | "30 players are there . two players play one game with one another . so 30 c 2 = 30 * 29 / 2 = 435 so option c is correct" | general |
math_qa__XnA3zO7GCNGlFD3i | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 90, how many horses are there ? Choose the correct choice: A) 10 B) 12 C) 14 D) 16 ... | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">90 / 5</gadget>
<output>18</output>
<result>E</result> | E | 18 | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 90, how many horses are there ? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(90, add(const_4, divide(const_2, const_2))) | divide(const_2,const_2)|add(#0,const_4)|divide(n0,#1)| | "legs 18 * 4 = 72 now half on their horses so remaining on the walk so 9 men 9 men has 18 legs so , 18 + 72 = 90 legs walking answer : e" | general |
math_qa__WKkHMYmtJoFEvoiq | 240 is increased by 20%. Find the final number. Choose the correct choice from the following answers:
A) 200 B) 210 C) 180 D) 288 E) 220 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">240 * (1/5)</gadget>
<output>48</output>
<gadget id="calculator">240 + 48</gadget>
<output>288</output>
<result>D</result> | D | 288 | 240 is increased by 20%. Find the final number. | {
"A": "200",
"B": "210",
"C": "180",
"D": "288",
"E": "220"
} | add(240, multiply(240, divide(20, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | explanation final number = initial number + 20 % ( original number ) = 240 + 20 % ( 240 ) = 240 + 48 = 288 . answer d | gain |
math_qa__yWeAZXREA80Tj5B1 | The average of 10 consecutive integers is 11. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average?
Choices.
A) 5 B) 5.5 C) 6 D) 6.5 E) 7 | <gadget id="calculator">10 * 11</gadget>
<output>110</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 9</gadget>
<output>45</output>
<gadget id="calculator">110 - 45</gadget>
<output>65</output>
<gadget id="calculator">65 / 10</gadget>
<output>13/2 = around 6.5</output>... | D | 6.5 | The average of 10 consecutive integers is 11. Then, 9 is deducted from the first consecutive number, 8 is deducted from the second, 7 is deducted form the third, and so on until the last number which remains unchanged. What is the new average? | {
"A": "5",
"B": "5.5",
"C": "6",
"D": "6.5",
"E": "7"
} | divide(subtract(multiply(10, 11), multiply(add(const_4, const_1), 9)), 10) | add(const_1,const_4)|multiply(n0,n1)|multiply(n2,#0)|subtract(#1,#2)|divide(#3,n0)| | "the total subtracted is ( 9 + 8 + . . . + 1 ) = ( 9 * 10 ) / 2 = 45 on average , each number will be reduced by 45 / 10 = 4.5 therefore , the overall average will be reduced by 4.5 the answer is d ." | general |
math_qa__7KrxoqY6WwiA5Ylc | Let the number which when multiplied by 15 is increased by 196.
Choose the correct choice from the following choices.
A) 14 B) 20 C) 26 D) 28 E) 30 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">196 / 14</gadget>
<output>14</output>
<result>A</result> | A | 14 | Let the number which when multiplied by 15 is increased by 196. | {
"A": "14",
"B": "20",
"C": "26",
"D": "28",
"E": "30"
} | divide(196, subtract(15, const_1)) | subtract(n0,const_1)|divide(n1,#0)| | "solution let the number be x . then , 15 x - x = 196 ‹ = › 14 x = 196 x ‹ = › 14 . answer a" | general |
math_qa__lXJAU8LWfMVnhzHT | A rectangular parking space is marked out by painting three of its sides. If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet? Answers.
A) 46
B) 81
C) 126
D) 252
E) none of these | <gadget id="calculator">37 + 37</gadget>
<output>74</output>
<gadget id="calculator">74 + 37</gadget>
<output>111</output>
<gadget id="calculator">111 + 10</gadget>
<output>121</output>
<gadget id="calculator">121 + 4</gadget>
<output>125</output>
<result>C</result> | C | 126 | A rectangular parking space is marked out by painting three of its sides. If the length of the unpainted side is 9 feet, and the sum of the lengths of the painted sides is 37 feet, then what is the area of the parking space in square feet? | {
"A": "46",
"B": "81",
"C": "126",
"D": "252",
"E": "none of these"
} | add(add(add(add(37, 37), 37), const_10), const_4) | add(n1,n1)|add(n1,#0)|add(#1,const_10)|add(#2,const_4) | solution clearly , we have : l = 9 and l + 2 b = 37 or b = 14 . ∴ area = ( l × b ) = ( 9 × 14 ) sq . ft . = 126 sq . ft . answer c | geometry |
math_qa__QSl3TkpsyjCuzgJi | Two persons start at the same point, walk in opposite directions with 6 km/hr and 7 km/hr respectively.
What is the distance separated after 3 and half hrs? Choose the correct choice from the following options.
A) 45.5 km
B) 27.250 km
C) 28.250 km
D) 29.250 km
E) 25.250 km | <gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">6 * (7/2)</gadget>
<output>21</output>
<gadget id="calculator">7 * (7/2)</gadget>
<output>49/2 = around 24.5</output>
<gadget id="calculator">... | A | 45.5 | Two persons start at the same point, walk in opposite directions with 6 km/hr and 7 km/hr respectively.
What is the distance separated after 3 and half hrs? | {
"A": "45.5 km",
"B": "27.250 km",
"C": "28.250 km",
"D": "29.250 km",
"E": "25.250 km"
} | add(multiply(6, add(3, divide(const_2, const_4))), multiply(7, add(3, divide(const_2, const_4)))) | divide(const_2,const_4)|add(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(#2,#3) | as the two persons are moving in the opposite direction , so they will be separateed in 1 hour = 6 + 7 = 13 km . they will be separated in 2.5 hours = 13 * 3.5 = 45.5 km answer : a | gain |
math_qa__6131cXU6AqRpaU3m | On day one, a store sold 86 cups. On each of the next d days, the company sold 50 cups. If the average daily sales of cups over this time period (including day one) is 53 cups, what is the value of d? Choose the correct choice from the following answers
A) 9 B) 10 C) 11 D) 12 E) 13 | <gadget id="calculator">86 + 50</gadget>
<output>136</output>
<gadget id="calculator">136 + 53</gadget>
<output>189</output>
<gadget id="calculator">189 / 3</gadget>
<output>63</output>
<gadget id="calculator">63 + 1</gadget>
<output>64</output>
<gadget id="calculator">64 - 53</gadget>
<output>11</output>
<result>... | C | 11 | On day one, a store sold 86 cups. On each of the next d days, the company sold 50 cups. If the average daily sales of cups over this time period (including day one) is 53 cups, what is the value of d? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | subtract(add(divide(add(add(86, 50), 53), const_3), const_1), 53) | add(n0,n1)|add(n2,#0)|divide(#1,const_3)|add(#2,const_1)|subtract(#3,n2) | 86 + 50 d = 53 ( d + 1 ) . 3 d = 33 . d = 11 . the answer is c . | general |
math_qa__7nOYP9qwhys3dJnp | There are two concentric circles with radii 8 and 4. If the radius of the outer circle is increased by 25% and the radius of the inner circle decreased by 25%, by what percent does the area between the circles increase?
Choose the correct choice from the following: A) 75 B) 80 C) 85 D) 90 E) 95 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">8 * (5/4)</gadget>
<output>10</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">100 - 25</gadget>
<output>... | D | 90 | There are two concentric circles with radii 8 and 4. If the radius of the outer circle is increased by 25% and the radius of the inner circle decreased by 25%, by what percent does the area between the circles increase? | {
"A": "75",
"B": "80",
"C": "85",
"D": "90",
"E": "95"
} | multiply(divide(subtract(subtract(power(multiply(8, divide(add(const_100, 25), const_100)), const_2), power(multiply(4, divide(subtract(const_100, 25), const_100)), const_2)), subtract(power(8, const_2), power(4, const_2))), subtract(power(8, const_2), power(4, const_2))), const_100) | add(n2,const_100)|power(n0,const_2)|power(n1,const_2)|subtract(const_100,n3)|divide(#0,const_100)|divide(#3,const_100)|subtract(#1,#2)|multiply(n0,#4)|multiply(n1,#5)|power(#7,const_2)|power(#8,const_2)|subtract(#9,#10)|subtract(#11,#6)|divide(#12,#6)|multiply(#13,const_100)| | "the area of a circle is pir ^ 2 , where r is the radius . the area of the big circle is 64 pi . the area of the small circle is 16 pi . the area a 1 between the circles is 48 pi . when the big circle ' s radius increases , the new area is 100 pi . when the small circle ' s radius decreases , the new area is 9 pi . the... | gain |
math_qa__7yV4IT5iacpbdPrk | Alice can bake a pie in 5 minutes. Bob can bake a pie in 6 minutes. Compute how many more
pies Alice can bake than Bob in 60 minutes. Answers:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">60 / 6</gadget>
<output>10</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<result>B</result> | B | 2 | Alice can bake a pie in 5 minutes. Bob can bake a pie in 6 minutes. Compute how many more
pies Alice can bake than Bob in 60 minutes. | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(divide(60, 5), divide(60, 6)) | divide(n2,n0)|divide(n2,n1)|subtract(#0,#1) | alice can bake 60 / 5 = 12 pies in 60 minutes . bob can bake 60 / 6 = 10 pies in 60 minutes . alice can therefore bake 12 - 10 = 2 more pies than bob . correct answer b | physics |
math_qa__Ljq3SdXh2apJqt8g | A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6100? Choose the correct option.
A) rs . 5870 B) rs . 5991 C) rs . 6470 D) rs . 6850 E) none of these | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 6_100</gadget>
<output>36_600</output>
<gadget id="calculator">5_420 + 5_660</gadget>
<output>11_080</output>
<gadget id="calculator">11_080 + 6_200</gadget>
<output>17_280</output>
<gadget id="calculator">17_280 + 6_350</gadget>
... | C | 6,470 | A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6100? | {
"A": "rs . 5870",
"B": "rs . 5991",
"C": "rs . 6470",
"D": "rs . 6850",
"E": "none of these"
} | subtract(multiply(add(5, const_1), 6100), add(add(add(add(5420, 5660), 6200), 6350), 6500)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "explanation : total sale for 5 months = rs . ( 5420 + 5660 + 6200 + 6350 + 6500 ) = rs . 30,130 therefore , required sale = rs . [ ( 6100 * 6 ) – 30,130 ] = rs . ( 36600 – 30,130 ) = rs . 6470 answer c" | general |
math_qa__fbn6llxW7fUdn05H | A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.35 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is? Choose the correct choice from the following choices
A) 22 B) 23 C) 28 D) 29 E) 26 | <gadget id="calculator">20 * 35</gadget>
<output>700</output>
<gadget id="calculator">15 * 20</gadget>
<output>300</output>
<gadget id="calculator">700 + 300</gadget>
<output>1_000</output>
<gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">1_000 + 40</gadget>
<output>1_040</output>
... | E | 26 | A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.35 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is? | {
"A": "22",
"B": "23",
"C": "28",
"D": "29",
"E": "26"
} | divide(add(add(multiply(20, 35), multiply(15, 20)), multiply(5, 8)), add(add(20, 15), 5)) | add(n0,n1)|multiply(n0,n3)|multiply(n0,n1)|multiply(n2,n5)|add(#1,#2)|add(n2,#0)|add(#4,#3)|divide(#6,#5)| | "20 15 5 35 20 8 500 + 300 + 40 = 1040 / 40 = 26 answer : e" | physics |
math_qa__zFAlv3ql4XXEEIyZ | ((1^5m)/(5^5m))((1^18)/(4^18)) = 1/(2(10)^35)
What is m? Pick
A) 7 B) 18 C) 34 D) 35 E) 36 | <gadget id="calculator">1 ** 18</gadget>
<output>1</output>
<gadget id="calculator">10 ** 35</gadget>
<output>100_000_000_000_000_000_000_000_000_000_000_000</output>
<gadget id="calculator">100_000_000_000_000_000_000_000_000_000_000_000 * 2</gadget>
<output>200_000_000_000_000_000_000_000_000_000_000_000</output>
... | A | 7 | ((1^5m)/(5^5m))((1^18)/(4^18)) = 1/(2(10)^35)
What is m? | {
"A": "7",
"B": "18",
"C": "34",
"D": "35",
"E": "36"
} | divide(log(divide(multiply(power(1, 18), multiply(power(10, 35), 2)), power(4, 18))), log(power(5, 5))) | power(n10,n11)|power(n0,n5)|power(n6,n5)|power(n1,n1)|log(#3)|multiply(n9,#0)|multiply(#5,#1)|divide(#6,#2)|log(#7)|divide(#8,#4) | ( ( 1 ^ 5 m ) / ( 5 ^ 5 m ) ) ( ( 1 ^ 18 ) / ( 4 ^ 18 ) ) = 1 / ( 2 ( 10 ) ^ 35 ) ( ( 1 / 5 ) ^ 5 m ) * ( ( 1 / 2 ) ^ 36 ) = 1 / ( 2 * ( 2 * 5 ) ^ 35 ) ) 2 ^ 36 will cancel out , since 1 can be written as 1 ^ 35 , so ( 1 / 5 ) ^ 5 m = ( 1 / 5 ) ^ 35 ( ( 1 / 5 ) ^ 5 m ) * ( ( 1 / 2 ) ^ 36 ) = 1 / [ ( 2 ^ 36 ) * ( 5 ^ 35... | general |
math_qa__m9TKEfVxzpsHsIp0 | eggs are sold in packages of 6 or 11 only . if doris bought 79 eggs exactly , what could be the number of large packs doris bought ? Choose the correct choice
A) 6 . B) 2 . C) 3 . D) 5 . E) 4 . | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">79 - 24</gadget>
<output>55</output>
<gadget id="calculator">55 / 11</gadget>
<output>5</output>
<result>D</result> | D | 5 | eggs are sold in packages of 6 or 11 only . if doris bought 79 eggs exactly , what could be the number of large packs doris bought ? | {
"A": "6 .",
"B": "2 .",
"C": "3 .",
"D": "5 .",
"E": "4 ."
} | divide(subtract(79, multiply(6, const_4)), 11) | multiply(n0,const_4)|subtract(n2,#0)|divide(#1,n1) | no strategy involved . simple question demanding fast calculation . 11 x 5 = 55 = > 79 - 55 = 24 = > 24 / 6 is an integer ans d . 5 . good luck | general |
math_qa__ZRhis2Ai3OMAlpmq | How long does a train 200 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length? Choices
A) 82.1 sec B) 12.1 sec C) 16.1 sec D) 13.1 sec E) 16.6 sec | <gadget id="calculator">200 + 132</gadget>
<output>332</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">332 / 20</gadget>
<output>83/5 = around 16.6</output>
<result>E</result> | E | 16.6 | How long does a train 200 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length? | {
"A": "82.1 sec",
"B": "12.1 sec",
"C": "16.1 sec",
"D": "13.1 sec",
"E": "16.6 sec"
} | divide(add(200, 132), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 72 * 5 / 18 = 20 m / sec total distance covered = 200 + 132 = 332 m . required time = 332 / 20 = 16.6 sec . answer : e" | physics |
math_qa__MBoB75c3j8A6jW8q | In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 3.5), (6, 0), (0, -3.5), (-6, 0)? Choose the correct choice from the following: A) 42 B) 56 C) 88 D) 112 E) 116 | <gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">3.5 * 2</gadget>
<output>7</output>
<gadget id="calculator">(12 * 7) / 2</gadget>
<output>42</output>
<result>A</result> | A | 42 | In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 3.5), (6, 0), (0, -3.5), (-6, 0)? | {
"A": "42",
"B": "56",
"C": "88",
"D": "112",
"E": "116"
} | rhombus_area(multiply(6, const_2), multiply(3.5, const_2)) | multiply(n2,const_2)|multiply(n1,const_2)|rhombus_area(#0,#1)| | "ares of rhombus = 1 / 2 * d 1 * d 2 length of 1 st diagonal = 6 + 6 = 12 length of 2 nd diagonal = 3.5 + 3.5 = 7 area = 1 / 2 * 12 * 7 = 42 a is the answer" | geometry |
math_qa__ZYrCKDS4rUFt25v7 | The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? Choose the correct choice from the following answers:
A) 30 B) 31 C) 32 D) 34 E) 35 | <gadget id="calculator">(2.5 * 28) / 2</gadget>
<output>35</output>
<result>E</result> | E | 35 | The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle? | {
"A": "30",
"B": "31",
"C": "32",
"D": "34",
"E": "35"
} | triangle_area(2.5, 28) | triangle_area(n0,n1) | area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 28 / 2 = 35 cm 2 answer : option e | geometry |
math_qa__se12W9l8t14WPujt | Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 year? Choose the most appropriate option.
A) 306.06 B) 306.02 C) 306.04 D) 306.09 E) 306.12 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(26/25) ** (3/2)</gadget>
<output>26*sqrt(26)/125 = around 1.0... | C | 306.04 | Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 year? | {
"A": "306.06",
"B": "306.02",
"C": "306.04",
"D": "306.09",
"E": "306.12"
} | subtract(multiply(5000, power(add(1, divide(4, const_100)), divide(const_3, 2))), 5000) | divide(n1,const_100)|divide(const_3,n4)|add(#0,n2)|power(#2,#1)|multiply(n0,#3)|subtract(#4,n0)| | "a = 5000 ( 51 / 50 ) 3 = 5306.04 5000 - - - - - - - - - - - 306.04 answer : c" | general |
math_qa__66MVxV2VFdLWAIzN | Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 14 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately. Choose the correct choice from the following answers
A) 50 days B) 100 days C) 120 days D) 11... | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 14</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 - (7/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 / (3/10)</gadget>
<output>10/3 = around 3.333333</output... | A | 50 | Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 14 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately. | {
"A": "50 days",
"B": "100 days",
"C": "120 days",
"D": "110 days",
"E": "90 days"
} | inverse(subtract(inverse(20), inverse(multiply(inverse(subtract(const_1, multiply(inverse(20), 14))), 10)))) | inverse(n0)|multiply(n1,#0)|subtract(const_1,#1)|inverse(#2)|multiply(n2,#3)|inverse(#4)|subtract(#0,#5)|inverse(#6)| | "rate of both = 1 / 20 together they do = 1 / 20 * 14 = 7 / 10 left work = 1 - 7 / 10 = 3 / 10 adam completes 3 / 10 work in 10 day so he took 10 * 10 / 3 = 100 / 3 days to complete the left work alone . thus the rate of adam is 3 / 100 rate of micheal = 1 / 20 - 3 / 100 = 1 / 50 thus micheal takes 50 days to complete ... | physics |
math_qa__X9nYcaqjK54BvP0P | A present value of a machine is $900. Its value depletion rate is 10% per annum then find the machine value after 2 years?
Pick one
A) $ 900 B) $ 810 C) $ 915 D) $ 715 E) $ 729 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) ** 2</gadget>
<output>81/100 = around 0.81</output>
<gadget id="calculator">900 * (81/100)</gadget>
<output>729</output>
<result>... | E | 729 | A present value of a machine is $900. Its value depletion rate is 10% per annum then find the machine value after 2 years? | {
"A": "$ 900",
"B": "$ 810",
"C": "$ 915",
"D": "$ 715",
"E": "$ 729"
} | multiply(900, power(subtract(const_1, divide(10, const_100)), 2)) | divide(n1,const_100)|subtract(const_1,#0)|power(#1,n2)|multiply(n0,#2)| | "p = $ 900 r = 10 % t = 2 years machine value after 2 years = p [ ( 1 - r / 100 ) ^ t ] = 900 * 9 / 10 * 9 / 10 = $ 729 answer is e" | gain |
math_qa__9zPFn2qOhhj8LEn8 | a motorist knows 6 different routes from bristol to birmingham . from birmingham to sheffield he knows 3 different routes and from sheffield to carlisle he knows two different routes . how many routes does he know from bristol to carlisle ? Choices.
A) 4 B) 8 C) 12 D) 24 E) 36 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 * 2</gadget>
<output>36</output>
<result>E</result> | E | 36 | a motorist knows 6 different routes from bristol to birmingham . from birmingham to sheffield he knows 3 different routes and from sheffield to carlisle he knows two different routes . how many routes does he know from bristol to carlisle ? | {
"A": "4",
"B": "8",
"C": "12",
"D": "24",
"E": "36"
} | multiply(multiply(6, 3), const_2) | multiply(n0,n1)|multiply(#0,const_2) | explanation : total number of routes from bristol to carlisle = ( 6 x 3 x 2 ) = 36 . answer : e | general |
math_qa__H8FRIVnlesox7lWM | The grade point average of one third of the classroom is 54; the grade point average of the rest is 45. What is the grade point average of the whole class? Choose the most appropriate option.
A) 52 B) 54 C) 48 D) 58 E) 60 | <gadget id="calculator">45 / 3</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">54 / 3</gadget>
<output>18</output>
<gadget id="calculator">30 + 18</gadget>
<output>48</output>
<result>C</result> | C | 48 | The grade point average of one third of the classroom is 54; the grade point average of the rest is 45. What is the grade point average of the whole class? | {
"A": "52",
"B": "54",
"C": "48",
"D": "58",
"E": "60"
} | add(multiply(divide(45, const_3), const_2), divide(54, const_3)) | divide(n0,const_3)|divide(n1,const_3)|multiply(#1,const_2)|add(#0,#2)| | "let n = total students in class total points for 1 / 3 class = 54 n / 3 = 18 n total points for 2 / 3 class = 45 * 2 n / 3 = 30 n total points for whole class = 18 n + 30 n = 48 n 48 n total class points / n total students = 48 grade point average for total class answer : c" | general |
math_qa__P4sfbxW2EwzuqTrX | In what time will a train 100 m long cross an electric pole, it its speed be 72 km/hr? Select the correct option.
A) 2.5 B) 5 C) 2.4 D) 2.8 E) 2.1 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">100 / 20</gadget>
<output>5</output>
<result>B</result> | B | 5 | In what time will a train 100 m long cross an electric pole, it its speed be 72 km/hr? | {
"A": "2.5",
"B": "5",
"C": "2.4",
"D": "2.8",
"E": "2.1"
} | divide(100, multiply(72, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 72 * 5 / 18 = 20 m / sec time taken = 100 / 20 = 5 sec . answer : b" | physics |
math_qa__wiC5ZF6g8kjjwd1i | if x is an integer that has exactly 3 positive divisors ( these include 1 and x ) , how many positive divisors does x ^ 3 have ?
Choose the correct choice from the following choices
A) 4 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<result>D</result> | D | 7 | if x is an integer that has exactly 3 positive divisors ( these include 1 and x ) , how many positive divisors does x ^ 3 have ? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | add(add(3, 3), 1) | add(n0,n0)|add(n1,#0) | since factors of ' 4 ' are { 1 , 2,4 } 4 ^ 3 = 64 number of factors / divisors of 64 = 2 ^ 6 we know that when a number is expressed as a product of the prime factors as below : n = a ^ x * b ^ y * c ^ z then no . of divisors = ( x + 1 ) * ( y + 1 ) * ( z + 1 ) then here ( 6 + 1 ) = 7 answer : d | general |
math_qa__xpe7W7vgkbcm2LYv | How many bricks, each measuring 5 cm x 11 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 2 cm? Choose the correct choice from the following choices:
A) 5600 B) 6000 C) 2909 D) 7200 E) 8600 | <gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">800 * 600</gadget>
<output>480_000</output>
<gadget id="calculator">480_000 * 2</gadget>
<output>960_000</output>
<gadget id="calculator">5 * 11</gadget>
<output>55</ou... | C | 2,909 | How many bricks, each measuring 5 cm x 11 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 2 cm? | {
"A": "5600",
"B": "6000",
"C": "2909",
"D": "7200",
"E": "8600"
} | divide(multiply(multiply(multiply(8, const_100), multiply(6, const_100)), 2), multiply(multiply(5, 11), 6)) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(n2,#2)|multiply(n5,#3)|divide(#5,#4)| | "number of bricks = volume of the wall / volume of 1 brick = ( 800 x 600 x 2 ) / ( 5 x 11 x 6 ) = 2909 . answer : option c" | physics |
math_qa__v7H7Jwn65eAZS1vr | 60% of the population of a village is 23040. The total population of the village is ?
Choose the correct choice from the following answers
A) 38400 B) 24000 C) 24936 D) 25640 E) none | <gadget id="calculator">100 / 60</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 23_040</gadget>
<output>38_400</output>
<result>A</result> | A | 38,400 | 60% of the population of a village is 23040. The total population of the village is ? | {
"A": "38400",
"B": "24000",
"C": "24936",
"D": "25640",
"E": "none"
} | multiply(divide(const_100, 60), 23040) | divide(const_100,n0)|multiply(n1,#0) | answer ∵ 60 % of p = 23040 ∴ p = ( 23040 x 100 ) / 60 = 38400 correct option : a | general |
math_qa__eebefGjOhy8K3ZTo | When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.25, what is the value of y? Choose the correct choice from the following options
A) 96
B) 75
C) 36
D) 25
E) 12 | <gadget id="calculator">floor(96.25)</gadget>
<output>96</output>
<gadget id="calculator">96.25 - 96</gadget>
<output>0.25</output>
<gadget id="calculator">9 / 0.25</gadget>
<output>36</output>
<result>C</result> | C | 36 | When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.25, what is the value of y? | {
"A": "96",
"B": "75",
"C": "36",
"D": "25",
"E": "12"
} | divide(9, subtract(96.25, floor(96.25))) | floor(n1)|subtract(n1,#0)|divide(n0,#1)| | "guys , one more simple funda . 5 / 2 = 2.5 now . 5 x 2 = 1 is the remainder 25 / 4 = 6.25 now . 25 x 4 = 1 is the remainder 32 / 5 = 6.4 now . 4 x 5 = 2 is the remainder given x / y = 96.25 and remainder is 9 so . 25 x y = 9 hence y = 36 ans c" | general |
math_qa__u9cTut7vMRrNf9rZ | What least number should be subtracted from 13605 such that the remainder is divisible by 87 ? Choose the correct choice from the following choices: A) 27 B) 29 C) 28 D) 30 E) 33 | <gadget id="calculator">13_605 % 87</gadget>
<output>33</output>
<result>E</result> | E | 33 | What least number should be subtracted from 13605 such that the remainder is divisible by 87 ? | {
"A": "27",
"B": "29",
"C": "28",
"D": "30",
"E": "33"
} | reminder(13605, 87) | reminder(n0,n1) | 13605 ÷ 87 = 156 , remainder = 33 hence 33 is the least number which can be subtracted from 13605 such that the remainder is divisible by 87 answer is e | general |
math_qa__rJMzJd5vmqXCW9KA | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 20 kg. What is the weight of the new person? Choices.
A) 75
B) 65
C) 85
D) 40
E) 80 | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 20</gadget>
<output>40</output>
<result>D</result> | D | 40 | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 20 kg. What is the weight of the new person? | {
"A": "75",
"B": "65",
"C": "85",
"D": "40",
"E": "80"
} | add(multiply(8, 2.5), 20) | multiply(n0,n1)|add(n2,#0) | total increase in weight = 8 × 2.5 = 20 if x is the weight of the new person , total increase in weight = x − 20 = > 20 = x - 20 = > x = 20 + 20 = 40 answer is d . | general |
math_qa__Z2PvUfv1jbshsONu | Liam is pulled over for speeding just as he is arriving at work.He explains to the police officer that he could not afford to be late today, and has arrived at work only four minutes before he is to start. The officer explains that if Liam had driven 5mph slower for his whole commute, he would have arrived at work exac... | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 + 20</gadget>
<output>40</output>
<result>E</result> | E | 40 | Liam is pulled over for speeding just as he is arriving at work.He explains to the police officer that he could not afford to be late today, and has arrived at work only four minutes before he is to start. The officer explains that if Liam had driven 5mph slower for his whole commute, he would have arrived at work exac... | {
"A": "50 mph",
"B": "45 mph",
"C": "48 mph",
"D": "52 mph",
"E": "40 mph"
} | add(20, multiply(5, const_4)) | multiply(n0,const_4)|add(n1,#0)| | "let t be the number of hours he would need to reach office on time . when he is driving with over speed , he reached office 4 min earlier ! so the equation for this is s ( t - 4 / 60 ) = 20 where s is the speed and 20 is the distance . if he decreases his speed by 5 mph then he would have reached his office on time : ... | physics |
math_qa__M2H4CjiGx8xzf8GS | Rs.1690 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share? Options: A) s . 528 B) s . 542 C) s . 780 D) s . 540 E) s . 549 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">1_690 / 9</gadget>
<output>1_690/9 = around 187.777778</output>
<gadget id="calculator">4 * (1_690/9)</gadget>
<output>6_760/9 = around 751.111111</output>
<result>C</result> | C | 780 | Rs.1690 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share? | {
"A": "s . 528",
"B": "s . 542",
"C": "s . 780",
"D": "s . 540",
"E": "s . 549"
} | multiply(4, divide(1690, add(add(4, 2), const_3))) | add(n1,n2)|add(#0,const_3)|divide(n0,#1)|multiply(n1,#2)| | "a + b + c = 1690 4 a = 3 b = 2 c = x a : b : c = 1 / 4 : 1 / 3 : 1 / 2 = 3 : 4 : 6 6 / 13 * 1690 = rs . 780 answer : c" | general |
math_qa__E972FYsznEZp4RNB | A train running at the speed of 100 km/hr crosses a pole in 18 seconds. What is the length of the train? Choose the correct choice from the following: A) 300 B) 400 C) 500 D) 600 E) 700 | <gadget id="calculator">100 * 1_000</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 / 3_600</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">(250/9) * 18</gadget>
<output>500</output>
<result>C</result> | C | 500 | A train running at the speed of 100 km/hr crosses a pole in 18 seconds. What is the length of the train? | {
"A": "300",
"B": "400",
"C": "500",
"D": "600",
"E": "700"
} | multiply(divide(multiply(100, const_1000), const_3600), 18) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1) | speed = ( 100 * 5 / 18 ) m / sec = ( 250 / 9 ) m / sec length of the train = ( speed x time ) = ( 250 / 9 * 18 ) m = 500 m . answer : c | physics |
math_qa__9keJzUN9wlWcYDm4 | There has been successive increases of 15% and then 10% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change?
Choose one
A) 12 % B) 15 % C) 18 % D) 21 % E) 24 % | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 * 10</gadget>
<output>1_150</output>
<gadget id="calculator">1_150 / 100</gadget>
<output>23/2 = around 11.5</output>
<gadget id="calculator">115 + (23/2)</gadget>
<output>253/2 = around 126.5</output>
<gadget id="calculator"... | D | 21 | There has been successive increases of 15% and then 10% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change? | {
"A": "12 %",
"B": "15 %",
"C": "18 %",
"D": "21 %",
"E": "24 %"
} | multiply(subtract(const_1, divide(const_100, add(add(const_100, 15), divide(multiply(add(const_100, 15), 10), const_100)))), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|add(#0,#2)|divide(const_100,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "let p be the original price per unit of gas . let x be the original gas consumption . let y be the reduced gas consumption . y * 1.1 * 1.15 * p = x * p y = x / ( 1.1 * 1.15 ) which is about 0.79 x which is a decrease of about 21 % . the answer is d ." | general |
math_qa__jEML86YTLAHltpsm | Two numbers are less than a third number by 30% and 37%. How much percent is the second number is less than the first? Choose the correct choice from the following choices:
A) 10 % B) 15 % C) 20 % D) 25 % E) 30 % | <gadget id="calculator">30 + 1</gadget>
<output>31</output>
<gadget id="calculator">31 - 30</gadget>
<output>1</output>
<gadget id="calculator">1 * 10</gadget>
<output>10</output>
<result>A</result> | A | 10 | Two numbers are less than a third number by 30% and 37%. How much percent is the second number is less than the first? | {
"A": "10 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "30 %"
} | multiply(subtract(add(30, const_1), 30), const_10) | add(n0,const_1)|subtract(#0,n0)|multiply(#1,const_10) | let the third number be x first number = 70 % of x = 7 x / 10 ; second number = 63 % of x = 63 x / 100 ; difference = 7 x / 10 - 63 x / 100 = 7 x / 100 ; required percentage = 7 x / 100 * 10 / 7 x * 100 = 10 % answer is a | gain |
math_qa__MkZtSQ2XpKu41BIo | there are 300 seniors at morse high school , and 40 % of them have cars . of the remaining grades ( freshmen , sophomores , and juniors ) , only 10 % of them have cars . if 15 % of all the students at morse have cars , how many students are in those other 3 lower grades ? Select:
A) 600 B) 900 C) 1200 D) 1350 E) 1500 | <gadget id="calculator">15 * 100</gadget>
<output>1_500</output>
<result>E</result> | E | 1,500 | there are 300 seniors at morse high school , and 40 % of them have cars . of the remaining grades ( freshmen , sophomores , and juniors ) , only 10 % of them have cars . if 15 % of all the students at morse have cars , how many students are in those other 3 lower grades ? | {
"A": "600",
"B": "900",
"C": "1200",
"D": "1350",
"E": "1500"
} | multiply(15, const_100) | multiply(n3,const_100) | let the total no of students be n . the no of seniors having cars is 40 % of 300 i . e . 120 . the rest of the students with other three grades who have cars is 10 % of ( n - 300 ) . the total no of students with cars is 15 % of n . thus , 0.15 n = 120 + 0.1 ( n - 300 ) on solving this , we get n = 1800 . hence , the n... | gain |
math_qa__o5UeDonGWJFAkrCz | A man walking at a constant rate of 5 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 25 miles per hour. The woman stops to wait for the man 5 minutes after passing him, while the man continues to walk at his constant rate. How many minutes must the woman wa... | <gadget id="calculator">5 / 60</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">25 - 5</gadget>
<output>20</output>
<gadget id="calculator">(1/12) * 20</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) / 5</gadget>
<output>1/3 = around 0.333333</output>
<gadget id... | B | 20 | A man walking at a constant rate of 5 miles per hour is passed by a woman traveling in the same direction along the same path at a constant rate of 25 miles per hour. The woman stops to wait for the man 5 minutes after passing him, while the man continues to walk at his constant rate. How many minutes must the woman wa... | {
"A": "16",
"B": "20",
"C": "24",
"D": "25",
"E": "28"
} | multiply(const_60, divide(multiply(divide(5, const_60), subtract(25, 5)), 5)) | divide(n2,const_60)|subtract(n1,n0)|multiply(#0,#1)|divide(#2,n0)|multiply(#3,const_60)| | "when the woman passes the man , they are aligned ( m and w ) . they are moving in the same direction . after 5 minutes , the woman ( w ) will be ahead the man ( m ) : m - - - - - - m - - - - - - - - - - - - - - - w w in the 5 minutes , after passing the man , the woman walks the distance mw = ww , which is 5 * 25 / 60... | physics |
math_qa__ajoHMCuDml2pSJbG | P and Q are the only two applicants qualified for a short-term research project that pays 300 dollars in total. Candidate P has more experience and, if hired, would be paid 50 percent more per hour than candidate Q would be paid. Candidate Q, if hired, would require 10 hours more than candidate P to do the job. Candida... | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">10 / (1/2)</gadget>
<output>20</output>
<gadget id="calculator">300 / 20</gadget>
<output>15</output>
<gadget id="calculator">20 + 10</gadget>... | A | 5 | P and Q are the only two applicants qualified for a short-term research project that pays 300 dollars in total. Candidate P has more experience and, if hired, would be paid 50 percent more per hour than candidate Q would be paid. Candidate Q, if hired, would require 10 hours more than candidate P to do the job. Candida... | {
"A": "$ 5",
"B": "$ 10",
"C": "$ 15",
"D": "$ 20",
"E": "$ 25"
} | subtract(divide(300, divide(10, subtract(divide(const_3, const_2), const_1))), divide(300, add(divide(10, subtract(divide(const_3, const_2), const_1)), 10))) | divide(const_3,const_2)|subtract(#0,const_1)|divide(n2,#1)|add(n2,#2)|divide(n0,#2)|divide(n0,#3)|subtract(#4,#5)| | "let q ' s hourly wage be x , then p ' s hourly wage is 1.5 x let t be the number of hours that q needs , then p needs t - 10 hours to do the job . since they both are paid an equal total amount of $ 300 : x * t = 1.5 x * ( t - 10 ) t = 30 hours and q ' s hourly wage is 300 / 30 = $ 10 p ' s hourly wage is 300 / ( t - ... | general |
math_qa__OMKiGEE2q5BYAYM8 | The average length of the sides of triangle ABC is 12. What is the perimeter of triangle ABC? Choose the most appropriate option: A) 4 B) 6 C) 12 D) 24 E) 36 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<result>E</result> | E | 36 | The average length of the sides of triangle ABC is 12. What is the perimeter of triangle ABC? | {
"A": "4",
"B": "6",
"C": "12",
"D": "24",
"E": "36"
} | multiply(12, const_3) | multiply(n0,const_3) | ( average ) = ( perimeter ) / 3 ; 12 = ( perimeter ) / 3 ; ( perimeter ) = 36 . answer : e . | geometry |
math_qa__OPf869AC4aK8WNYT | A retailer buys 140 pens at the market price of 36 pens from a wholesaler, if he sells these pens giving a discount of 1%, what is the profit % ? Choose the correct choice: A) 105 B) 155 C) 125 D) 185 E) 285 | <gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">1 - (1/100)</gadget>
<output>99/100 = around 0.99</output>
<gadget id="calculator">36 / 140</gadget>
<output>9/35 = around 0.257143</output>
<gadget id="calculator">(99/100) - (9/35)</gadget>
<output>513/700 = aroun... | E | 285 | A retailer buys 140 pens at the market price of 36 pens from a wholesaler, if he sells these pens giving a discount of 1%, what is the profit % ? | {
"A": "105",
"B": "155",
"C": "125",
"D": "185",
"E": "285"
} | multiply(const_100, divide(subtract(subtract(1, divide(1, const_100)), divide(36, 140)), divide(36, 140))) | divide(n2,const_100)|divide(n1,n0)|subtract(n2,#0)|subtract(#2,#1)|divide(#3,#1)|multiply(#4,const_100)| | "let the market price of each pen be $ 1 then , cost price of 140 pens = $ 36 selling price of 140 pens = 99 % of $ 140 = $ 138.60 profit % = ( ( 102.60 * 100 ) / 36 ) % = 285 % answer e" | gain |
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