id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__Lp3b6GEUhFCJNBSY | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 138 m length? Choose one:
A) 82.1 sec . B) 12.4 sec C) 19.1 sec . D) 17.1 sec . E) 42.1 sec . | <gadget id="calculator">110 + 138</gadget>
<output>248</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">248 / 20</gadget>
<output>62/5 = around 12.4</output>
<result>B</result> | B | 12.4 | How long does a train 110 m long running at the speed of 72 km/hr takes to cross a bridge 138 m length? | {
"A": "82.1 sec .",
"B": "12.4 sec",
"C": "19.1 sec .",
"D": "17.1 sec .",
"E": "42.1 sec ."
} | divide(add(110, 138), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1) | speed = 72 * 5 / 18 = 20 m / sec total distance covered = 110 + 138 = 248 m . required time = 248 / 20 = 12.4 sec . answer : b | physics |
math_qa__AE4quWzpcLKrVp2b | A sum of money lent out at S.I. amounts to a total of $590 after 2 years and to $815 after a further period of 5 years. What was the initial sum of money that was invested? Options
A) $ 490 B) $ 500 C) $ 510 D) $ 520 E) $ 530 | <gadget id="calculator">815 - 590</gadget>
<output>225</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">225 * (2/5)</gadget>
<output>90</output>
<gadget id="calculator">590 - 90</gadget>
<output>500</output>
<result>B</result> | B | 500 | A sum of money lent out at S.I. amounts to a total of $590 after 2 years and to $815 after a further period of 5 years. What was the initial sum of money that was invested? | {
"A": "$ 490",
"B": "$ 500",
"C": "$ 510",
"D": "$ 520",
"E": "$ 530"
} | subtract(590, multiply(subtract(815, 590), divide(2, 5))) | divide(n1,n3)|subtract(n2,n0)|multiply(#0,#1)|subtract(n0,#2)| | "s . i for 5 years = $ 815 - $ 590 = $ 225 the s . i . is $ 45 / year s . i . for 2 years = $ 90 principal = $ 590 - $ 90 = $ 500 the answer is b ." | general |
math_qa__Y0Uy64k7Bjen4M6G | There are 8 students. 4 of them are men and 4 of them are women. If 4 students are selected from the 8 students. What is the probability that the number of men is equal to that of women? Choose the most appropriate option:
A) 18 / 35
B) 16 / 35
C) 14 / 35
D) 13 / 35
E) 12 / 35 | <gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">binomial(4, 2)</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">binomial(8, 4)</gadget>
<output>70</output>
<gadget id="calculator">36 / 70</gadget>
<output>18/35 = around 0.514286</output>
<result>A</result> | A | 0.514286 | There are 8 students. 4 of them are men and 4 of them are women. If 4 students are selected from the 8 students. What is the probability that the number of men is equal to that of women? | {
"A": "18 / 35",
"B": "16 / 35",
"C": "14 / 35",
"D": "13 / 35",
"E": "12 / 35"
} | divide(multiply(choose(4, divide(4, const_2)), choose(4, divide(4, const_2))), choose(8, 4)) | choose(n0,n1)|divide(n1,const_2)|choose(n1,#1)|multiply(#2,#2)|divide(#3,#0) | men = women means 2 men 2 women total such combinations = 4 c 2 * 4 c 2 = 4 ! / 2 ! . 2 ! * 4 ! / 2 ! . 2 ! = 6 * 6 total combinations = 8 c 4 = 8 * 7 * 6 * 5 / 4 * 3 * 2 * 1 = 70 so probability = 36 / 70 = 18 / 35 hence a | probability |
math_qa__oB1J3qElcCeaSK0H | How many seconds will a train 200 meters long running at the rate of 36kmph take to pass a certain telegraph post? Choose the correct choice
A) 10 sec B) 20 sec C) 25 sec D) 30 sec E) 35 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 36</gadget>
<output>10</output>
<gadget id="calculator">200 / 10</gadget>
<output>20</output>
<result>B</result> | B | 20 | How many seconds will a train 200 meters long running at the rate of 36kmph take to pass a certain telegraph post? | {
"A": "10 sec",
"B": "20 sec",
"C": "25 sec",
"D": "30 sec",
"E": "35 sec"
} | divide(200, multiply(const_0_2778, 36)) | multiply(n1,const_0_2778)|divide(n0,#0) | distance = length of train = 200 meters speed = 36 kmph = 36 * 5 / 18 = 10 m / s required time = 200 / 10 = 20 sec answer is b | physics |
math_qa__nUL9Uce6k40PLlPL | A, B and C enter into a partnership by investing $11000, $15000 and $23000 respectively. At the end of 8 months, B receives $3315 as his share. Find the share of A. Choose the correct choice from the following choices
A) $ 1865 B) $ 2087 C) $ 2217 D) $ 2431 E) $ 2662 | <gadget id="calculator">15_000 * 8</gadget>
<output>120_000</output>
<gadget id="calculator">120_000 / 100</gadget>
<output>1_200</output>
<gadget id="calculator">3_315 / 1_200</gadget>
<output>221/80 = around 2.7625</output>
<gadget id="calculator">11_000 * (221/80)</gadget>
<output>60_775/2 = around 30_387.5</output>
<gadget id="calculator">(60_775/2) * 8</gadget>
<output>243_100</output>
<gadget id="calculator">243_100 / 100</gadget>
<output>2_431</output>
<result>D</result> | D | 2,431 | A, B and C enter into a partnership by investing $11000, $15000 and $23000 respectively. At the end of 8 months, B receives $3315 as his share. Find the share of A. | {
"A": "$ 1865",
"B": "$ 2087",
"C": "$ 2217",
"D": "$ 2431",
"E": "$ 2662"
} | divide(multiply(multiply(11000, divide(3315, divide(multiply(15000, 8), const_100))), 8), const_100) | multiply(n1,n3)|divide(#0,const_100)|divide(n4,#1)|multiply(n0,#2)|multiply(n3,#3)|divide(#4,const_100) | the ratio of capital of a , b and c = 11000 : 15000 : 23000 = 11 : 15 : 23 a ' s share = ( 11 / 15 ) * 3315 = $ 2431 the answer is d . | gain |
math_qa__kQslu9AKlfEbwoXr | A reduction of 35% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? Choices
A) 42 B) 49 C) 56 D) 63 E) 70 | <gadget id="calculator">800 * 35</gadget>
<output>28_000</output>
<gadget id="calculator">28_000 / 100</gadget>
<output>280</output>
<gadget id="calculator">280 / 5</gadget>
<output>56</output>
<result>C</result> | C | 56 | A reduction of 35% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? | {
"A": "42",
"B": "49",
"C": "56",
"D": "63",
"E": "70"
} | divide(divide(multiply(800, 35), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1) | 800 * ( 35 / 100 ) = 280 - - - - 5 ? - - - - 1 = > rs . 56 answer : c | gain |
math_qa__IFjibNCjYGvn0UBl | Suppose 3 monkeys take 3 minutes to eat 3 bananas. How many monkeys would it take to eat 6 bananas in 6 minutes? Select the correct option: A) 9 B) 10 C) 11 D) 3 E) 13 | <gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>D</result> | D | 3 | Suppose 3 monkeys take 3 minutes to eat 3 bananas. How many monkeys would it take to eat 6 bananas in 6 minutes? | {
"A": "9",
"B": "10",
"C": "11",
"D": "3",
"E": "13"
} | divide(6, divide(6, 3)) | divide(n3,n0)|divide(n3,#0)| | "one monkey takes 3 min to eat 1 banana , so in 6 mins 1 monkey will eat 2 bananas , so for 6 bananas in 6 min we need 6 / 2 = 3 monkeys answer : d" | physics |
math_qa__g1dvIQOVRV8VdM49 | A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each?
Answers.
A) 1.5
B) 2.5
C) 3
D) 4.5
E) 5 | <gadget id="calculator">50 + 50</gadget>
<output>100</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 - 40</gadget>
<output>10</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<result>B</result> | B | 2.5 | A dessert recipe calls for 50% melted chocolate and 50% raspberry puree to make a particular sauce. A chef accidentally makes 15 cups of the sauce with 40% melted chocolate and 60% raspberry puree instead. How many cups of the sauce does he need to remove and replace with pure melted chocolate to make the sauce the proper 50% of each? | {
"A": "1.5",
"B": "2.5",
"C": "3",
"D": "4.5",
"E": "5"
} | divide(divide(subtract(add(50, 50), 50), subtract(50, 40)), const_2) | add(n0,n0)|subtract(n0,n3)|subtract(#0,n0)|divide(#2,#1)|divide(#3,const_2) | we have 15 cups of sauce with 4040 choc and 6060 rasb cups of choc = 0.4 ∗ 15 = 6 cups of rasb = 0.6 ∗ 15 = 9 now let say we removed x cup of original mix and replaced with x cups of choc . therefore final number of cups of choc = 6 − 0.4 x + x now this number of cup should be 50 % of total = 15 / 2 = 7.5 therefore 6 − 0.4 x + x = 7.5 on solving x = 2.5 answer : b | gain |
math_qa__quhtK1bmLdFFqUoO | If x and y are both odd prime numbers andx < y, then how many different positive integer factors does2xyhave? Pick: A) 3 B) 4 C) 6 D) 12 E) 8 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>E</result> | E | 8 | If x and y are both odd prime numbers andx < y, then how many different positive integer factors does2xyhave? | {
"A": "3",
"B": "4",
"C": "6",
"D": "12",
"E": "8"
} | multiply(multiply(2, add(const_1, const_1)), add(const_1, const_1)) | add(const_1,const_1)|multiply(n0,#0)|multiply(#0,#1)| | "x and y are both odd prime numbers - it means either x or y is not 2 and since prime numbers have only two factors - 1 and the number itself x and y each will have ( 1 + 1 ) = 2 factors hence 2 xy will have ( 1 + 1 ) ( 1 + 1 ) ( 1 + 1 ) = 8 factors e is the answer" | other |
math_qa__m2tJzmj5WnHbg60X | there are 30 students in a classroom. The ratio of the # of girls to boys was 1:2, how many boys are there? Choose the correct choice
A) 10 B) 15 C) 20 D) 25 E) 30 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 30</gadget>
<output>20</output>
<result>C</result> | C | 20 | there are 30 students in a classroom. The ratio of the # of girls to boys was 1:2, how many boys are there? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "30"
} | multiply(divide(2, add(1, 2)), 30) | add(n1,n2)|divide(n2,#0)|multiply(n0,#1) | # of girls = x # of boys = 2 x x + 2 x = 30 3 x = 30 x = 30 / 3 = 10 boys = 2 x = 2 * 10 = 20 answer : c | other |
math_qa__ykviCdyx1IPmkWhW | 99! how many zero's? Choose the correct choice: A) 20 B) 21 C) 22 D) 23 E) 24 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">99 / 5</gadget>
<output>99/5 = around 19.8</output>
<gadget id="calculator">floor(99/5)</gadget>
<output>19</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">99 / 25</gadget>
<output>99/25 = around 3.96</output>
<gadget id="calculator">floor(99/25)</gadget>
<output>3</output>
<gadget id="calculator">19 + 3</gadget>
<output>22</output>
<result>C</result> | C | 22 | 99! how many zero's? | {
"A": "20",
"B": "21",
"C": "22",
"D": "23",
"E": "24"
} | add(floor(divide(99, add(const_1, const_4))), floor(divide(99, power(add(const_1, const_4), const_2)))) | add(const_1,const_4)|divide(n0,#0)|power(#0,const_2)|divide(n0,#2)|floor(#1)|floor(#3)|add(#4,#5) | 99 ! = 99 / 5 = 19 = 19 / 5 = 3 so 99 ! has ( 19 + 3 = 22 zeroes ) answer : c | other |
math_qa__StPkkihkAURvzCx2 | In a kilometer race, A beats B by 40 meters or 8 seconds. What time does A take to complete the race? Choose the correct choice from the following options:
A) 221 B) 190 C) 192 D) 191 E) 121 | <gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">40 / 8</gadget>
<output>5</output>
<gadget id="calculator">1_000 / 5</gadget>
<output>200</output>
<gadget id="calculator">200 - 8</gadget>
<output>192</output>
<result>C</result> | C | 192 | In a kilometer race, A beats B by 40 meters or 8 seconds. What time does A take to complete the race? | {
"A": "221",
"B": "190",
"C": "192",
"D": "191",
"E": "121"
} | subtract(divide(multiply(const_1, const_1000), divide(40, 8)), 8) | divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)| | "time taken by b run 1000 meters = ( 1000 * 8 ) / 40 = 200 sec . time taken by a = 200 - 8 = 192 sec . answer : c" | physics |
math_qa__67RI6nLX4Zdlowa4 | In what time will a train 300 m long cross an electric pole, it its speed be 144 km/hr? Choose the correct choice from the following choices: A) 2.5 sec B) 9.7 sec C) 3.5 sec D) 2.9 sec E) 7.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">300 / 40</gadget>
<output>15/2 = around 7.5</output>
<result>E</result> | E | 7.5 | In what time will a train 300 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.5 sec",
"B": "9.7 sec",
"C": "3.5 sec",
"D": "2.9 sec",
"E": "7.5 sec"
} | divide(300, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 300 / 40 = 7.5 sec . answer : e" | physics |
math_qa__Tui372H5s9WWa7Iw | Anand and Deepak started a business investing Rs. 2250 and Rs. 3200 respectively. Out of a total profit of Rs. 1380, Deepak's share is:
Choose the correct choice:
A) 3776 B) 810.27 C) 815.21 D) 688.12 E) 267.1 | <gadget id="calculator">2_250 + 3_200</gadget>
<output>5_450</output>
<gadget id="calculator">3_200 / 5_450</gadget>
<output>64/109 = around 0.587156</output>
<gadget id="calculator">1_380 * (64/109)</gadget>
<output>88_320/109 = around 810.275229</output>
<result>B</result> | B | 810.27 | Anand and Deepak started a business investing Rs. 2250 and Rs. 3200 respectively. Out of a total profit of Rs. 1380, Deepak's share is: | {
"A": "3776",
"B": "810.27",
"C": "815.21",
"D": "688.12",
"E": "267.1"
} | multiply(1380, divide(3200, add(2250, 3200))) | add(n0,n1)|divide(n1,#0)|multiply(n2,#1) | ratio of their shares = 2250 : 3200 = 45 : 64 deepak ' s share = 13800 * 64 / 109 = rs . 810.27 . answer : b | gain |
math_qa__TLYRu7GLnxY4DL4A | The parameter of a square is equal to the perimeter of a rectangle of length 18 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) Choose the correct choice from the following.
A) 77.14 cm B) 25.14 cm C) 84.92 cm D) 94.94 cm E) 23.57 cm | <gadget id="calculator">2 * (18 + 14)</gadget>
<output>64</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">2 * pi * 8</gadget>
<output>16*pi = around 50.265482</output>
<gadget id="calculator">(16*pi) / 2</gadget>
<output>8*pi = around 25.132741</output>
<result>B</result> | B | 25.14 | The parameter of a square is equal to the perimeter of a rectangle of length 18 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) | {
"A": "77.14 cm",
"B": "25.14 cm",
"C": "84.92 cm",
"D": "94.94 cm",
"E": "23.57 cm"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(18, 14)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 18 + 14 ) = 64 cm parameter of the square = 64 cm i . e . 4 a = 64 a = 16 diameter of the semicircle = 16 cm circimference of the semicircle = 1 / 2 ( ∏ ) ( 16 ) = 1 / 2 ( 22 / 7 ) ( 16 ) = 352 / 14 = 25.14 cm to two decimal places answer : b" | geometry |
math_qa__QY6chCyo9Q1EHVHD | A can do a piece of work in 3 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?
Select
A) 12 B) 9 C) 8 D) 6 E) 5 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) - (1/3)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/3) - (1/6)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>D</result> | D | 6 | A can do a piece of work in 3 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it? | {
"A": "12",
"B": "9",
"C": "8",
"D": "6",
"E": "5"
} | divide(const_1, subtract(divide(const_1, 3), subtract(divide(const_1, 2), divide(const_1, 3)))) | divide(const_1,n1)|divide(const_1,n2)|divide(const_1,n0)|subtract(#1,#2)|subtract(#0,#3)|divide(const_1,#4)| | "a ' s 1 hour ' s work = 1 / 3 ; ( b + c ) ' s 1 hour ' s work = 1 / 3 ; ( a + c ) ' s 1 hour ' s work = 1 / 2 . ( a + b + c ) ' s 1 hour ' s work = ( 1 / 3 + 1 / 3 ) = 2 / 3 . b ' s 1 hour ' s work = ( 2 / 3 - 1 / 2 ) = 1 / 6 . therefore a alone will take 6 hours to do the work . d" | physics |
math_qa__O6mBclNSNBaFDGKj | The area of the floor of a room is 20 m2 that of a longer wall 15 m2 and of the shorter wall 12 m2, find the edge of the new cube? Choices
A) 450 m 3 B) 100 m 2 C) 60 m 3 D) 400 m 3 E) 500 m 3 | <gadget id="calculator">15 ** (1/2)</gadget>
<output>sqrt(15) = around 3.872983</output>
<gadget id="calculator">12 ** (1/2)</gadget>
<output>2*sqrt(3) = around 3.464102</output>
<gadget id="calculator">20 ** (1/2)</gadget>
<output>2*sqrt(5) = around 4.472136</output>
<gadget id="calculator">(sqrt(15)) * (2*sqrt(3)) * (2*sqrt(5))</gadget>
<output>60</output>
<result>C</result> | C | 60 | The area of the floor of a room is 20 m2 that of a longer wall 15 m2 and of the shorter wall 12 m2, find the edge of the new cube? | {
"A": "450 m 3",
"B": "100 m 2",
"C": "60 m 3",
"D": "400 m 3",
"E": "500 m 3"
} | volume_rectangular_prism(sqrt(15), sqrt(12), sqrt(20)) | sqrt(n2)|sqrt(n4)|sqrt(n0)|volume_rectangular_prism(#0,#1,#2) | lb = 20 ; lh = 15 ; fh = 12 ( lbh ) 2 = 20 * 15 * 12 = > lbh = 60 m 3 answer : c | geometry |
math_qa__doMaYk7WXOFZOMeO | In a 200m race, if A gives B a start of 25 metres, then A wins the race by 10 seconds. Alternatively, if A gives B a start of 45 metres the race ends in a dead heat. How long does A take to run 200m? Options:
A) 100 seconds
B) 112.5 seconds
C) 77.5 seconds
D) 87.5 seconds
E) none | <gadget id="calculator">200 - 45</gadget>
<output>155</output>
<gadget id="calculator">155 / 2</gadget>
<output>155/2 = around 77.5</output>
<result>C</result> | C | 77.5 | In a 200m race, if A gives B a start of 25 metres, then A wins the race by 10 seconds. Alternatively, if A gives B a start of 45 metres the race ends in a dead heat. How long does A take to run 200m? | {
"A": "100 seconds",
"B": "112.5 seconds",
"C": "77.5 seconds",
"D": "87.5 seconds",
"E": "none"
} | divide(subtract(200, 45), const_2) | subtract(n0,n3)|divide(#0,const_2) | explanatory answer a gives b a start of 25 metres and still wins the race by 10 seconds . alternatively , if a gives b a start of 45 metres , then the race ends in a dead heat . therefore , the additional 20 metres start given to b compensates for the 10 seconds . i . e . , b runs 20 metres in 10 seconds . hence , b will take 100 seconds to run 200 metres . we know that a gives b a start of 45 metres . b will take 22.5 seconds to run this 45 metres as b runs 20 metres in 10 seconds or at the speed of 2 m / s . hence , a will take 22.5 seconds lesser than b or 100 - 22.5 = 77.5 seconds to complete the race . answer c | physics |
math_qa__1y63Nb4ADMC8ta9Q | If a farmer wants to plough a farm field on time, he must plough 340 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? Choose the correct choice from the following answers.
A) 280 B) 490 C) 720 D) 435 E) 679 | <gadget id="calculator">2 * 85</gadget>
<output>170</output>
<gadget id="calculator">40 + 170</gadget>
<output>210</output>
<gadget id="calculator">340 - 85</gadget>
<output>255</output>
<gadget id="calculator">210 / 255</gadget>
<output>14/17 = around 0.823529</output>
<gadget id="calculator">(14/17) * 340</gadget>
<output>280</output>
<result>A</result> | A | 280 | If a farmer wants to plough a farm field on time, he must plough 340 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? | {
"A": "280",
"B": "490",
"C": "720",
"D": "435",
"E": "679"
} | multiply(divide(add(40, multiply(2, 85)), subtract(340, 85)), 340) | multiply(n1,n2)|subtract(n0,n1)|add(n3,#0)|divide(#2,#1)|multiply(n0,#3)| | "let x be the number of days in the initial plan . therefore , the whole field is 340 â ‹ … x hectares . the farmer had to work for x + 2 days , and he ploughed 85 ( x + 2 ) hectares , leaving 40 hectares unploughed . then we have the equation : 340 x = 85 ( x + 2 ) + 40 255 x = 210 x = 0.823 so the farmer planned to have the work done in 6 days , and the area of the farm field is 340 ( 0.823 ) = 280 hectares correct answer a" | physics |
math_qa__jwMSeHoI8pS2n8BW | P is 60% more efficient than Q. P can complete a work in 26 days. If P and Q work together, how many days will it take to complete the same work? Select
A) 12 B) 14 C) 16 D) 18 E) 20 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) + 1</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) * 26</gadget>
<output>208/5 = around 41.6</output>
<gadget id="calculator">(8/5) + 1</gadget>
<output>13/5 = around 2.6</output>
<gadget id="calculator">(208/5) / (13/5)</gadget>
<output>16</output>
<result>C</result> | C | 16 | P is 60% more efficient than Q. P can complete a work in 26 days. If P and Q work together, how many days will it take to complete the same work? | {
"A": "12",
"B": "14",
"C": "16",
"D": "18",
"E": "20"
} | divide(multiply(add(divide(60, const_100), const_1), 26), add(add(divide(60, const_100), const_1), const_1)) | divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n1,#1)|divide(#3,#2) | the work done by p in 1 day = 1 / 26 let work done by q in 1 day = q q × ( 160 / 100 ) = 1 / 26 q = 100 / ( 26 × 160 ) = 10 / ( 26 × 16 ) the work done by p and q in 1 day = 1 / 26 + 10 / ( 26 × 16 ) = 26 / ( 26 × 16 ) = 1 / 16 p and q together can do the work in 16 days . the answer is c . | physics |
math_qa__0GautbnUCrKlEGS9 | If the cost price is 92% of sp then what is the profit % Choose the correct choice from the following answers:
A) 8.70 %
B) 8.60 %
C) 8.10 %
D) 8.30 %
E) 8.27 % | <gadget id="calculator">100 - 92</gadget>
<output>8</output>
<gadget id="calculator">8 / 92</gadget>
<output>2/23 = around 0.086957</output>
<gadget id="calculator">(2/23) * 100</gadget>
<output>200/23 = around 8.695652</output>
<result>A</result> | A | 8.7 | If the cost price is 92% of sp then what is the profit % | {
"A": "8.70 %",
"B": "8.60 %",
"C": "8.10 %",
"D": "8.30 %",
"E": "8.27 %"
} | multiply(divide(subtract(const_100, 92), 92), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "sol . sp = rs 100 : then cp = rs 92 : profit = rs 8 . profit = { ( 8 / 92 ) * 100 } % = 8.70 % answer is a ." | gain |
math_qa__SPnsGj3ip8QoJtRy | √1.5625 = ?
Choose the correct answer.
A) 1.05
B) 1.25
C) 1.45
D) 1.55
E) 1.65 | <gadget id="calculator">1.5625 / 1.5625</gadget>
<output>1</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<result>B</result> | B | 1.25 | √1.5625 = ? | {
"A": "1.05",
"B": "1.25",
"C": "1.45",
"D": "1.55",
"E": "1.65"
} | add(divide(1.5625, 1.5625), const_0_25) | divide(n0,n0)|add(#0,const_0_25) | explanation : 1 | 1.5625 ( 1.25 | 1 | - - - - - - - 22 | 56 | 44 | - - - - - - - 245 | 1225 | 1225 | - - - - - - - | x | - - - - - - - 1.5625 = 1.25 . answer is b | general |
math_qa__UYd6kOglJVusVKgT | The tax on a commodity is diminished by 20% but its consumption is increased by 20%. Find the decrease percent in the revenue derived from it? Pick one
A) 20 % B) 18 % C) 4 % D) 12 % E) 14 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">120 * 80</gadget>
<output>9_600</output>
<gadget id="calculator">9_600 / 100</gadget>
<output>96</output>
<gadget id="calculator">100 - 96</gadget>
<output>4</output>
<result>C</result> | C | 4 | The tax on a commodity is diminished by 20% but its consumption is increased by 20%. Find the decrease percent in the revenue derived from it? | {
"A": "20 %",
"B": "18 %",
"C": "4 %",
"D": "12 %",
"E": "14 %"
} | subtract(const_100, divide(multiply(add(const_100, 20), subtract(const_100, 20)), const_100)) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(const_100,#3)| | "100 * 100 = 10000 80 * 120 = 9600 10000 - - - - - - - 400 100 - - - - - - - ? = 4 % answer : c" | general |
math_qa__SqQG4ff3G9WMkuZL | Three cubes of metal whose edges are 9, 12 and 18 cm respectively, are melted and one new cube is made. Find the edge of the new cube? Choose one
A) 20.2 B) 77 C) 66 D) 18 E) 99 | <gadget id="calculator">9 ** 3</gadget>
<output>729</output>
<gadget id="calculator">12 ** 3</gadget>
<output>1_728</output>
<gadget id="calculator">729 + 1_728</gadget>
<output>2_457</output>
<gadget id="calculator">18 ** 3</gadget>
<output>5_832</output>
<gadget id="calculator">2_457 + 5_832</gadget>
<output>8_289</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">8_289 ** (1/3)</gadget>
<output>3*307**(1/3) = around 20.23799</output>
<result>A</result> | A | 20.2 | Three cubes of metal whose edges are 9, 12 and 18 cm respectively, are melted and one new cube is made. Find the edge of the new cube? | {
"A": "20.2",
"B": "77",
"C": "66",
"D": "18",
"E": "99"
} | power(add(add(volume_cube(9), volume_cube(12)), volume_cube(18)), const_0_33) | volume_cube(n0)|volume_cube(n1)|volume_cube(n2)|add(#0,#1)|add(#3,#2)|power(#4,const_0_33)| | "93 + 123 + 183 = a 3 = > a = 20.2 answer : a" | physics |
math_qa__fhF5nT1ZoqBi8qLL | Find (7x + 4y ) / (x-2y) if x/2y = 3/2 ?
Choose the correct choice from the following
A) 24 B) 25 C) 26 D) 27 E) 29 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">21 + 4</gadget>
<output>25</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">25 / 1</gadget>
<output>25</output>
<result>B</result> | B | 25 | Find (7x + 4y ) / (x-2y) if x/2y = 3/2 ? | {
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "29"
} | divide(add(multiply(multiply(divide(3, 2), 2), 7), 4), subtract(multiply(divide(3, 2), 2), 2)) | divide(n4,n2)|multiply(n2,#0)|multiply(n0,#1)|subtract(#1,n2)|add(n1,#2)|divide(#4,#3)| | "x / 2 y = 3 / 2 = > x = 6 y / 2 = 3 y = > ( 7 x + 4 y ) / ( x - 2 y ) = ( ( 7 * ( 3 y ) ) + 4 y ) / ( 3 y - 2 y ) = > 25 y / y = 25 answer : b" | general |
math_qa__i8LWQMm6OCjuaM0W | The price of lunch for 12 people was $207 including a 15% gratuity for service. What was the average price per person, EXCLUDING the gratuity? Choose the correct choice from the following:
A) 11.73
B) 12
C) 13.8
D) 14
E) 15 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">207 * 85</gadget>
<output>17_595</output>
<gadget id="calculator">17_595 / 100</gadget>
<output>3_519/20 = around 175.95</output>
<gadget id="calculator">(3_519/20) / 12</gadget>
<output>1_173/80 = around 14.6625</output>
<result>E</result> | E | 15 | The price of lunch for 12 people was $207 including a 15% gratuity for service. What was the average price per person, EXCLUDING the gratuity? | {
"A": "11.73",
"B": "12",
"C": "13.8",
"D": "14",
"E": "15"
} | divide(divide(multiply(207, subtract(const_100, 15)), const_100), 12) | subtract(const_100,n2)|multiply(n1,#0)|divide(#1,const_100)|divide(#2,n0)| | "clearly e is the answer i used poe here lets consider option ( e ) 12 * 15 = 180 now 180 ( 115 / 100 ) = 207 = > possible answer imo e" | general |
math_qa__C4CKZtyksURPqdPJ | The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 270. The banker's discount is: Answers
A) rs . 960 B) rs . 760 C) rs . 840 D) rs . 1020 E) rs . 1615 | <gadget id="calculator">270 * 100</gadget>
<output>27_000</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">27_000 / 36</gadget>
<output>750</output>
<gadget id="calculator">270 + 750</gadget>
<output>1_020</output>
<result>D</result> | D | 1,020 | The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 270. The banker's discount is: | {
"A": "rs . 960",
"B": "rs . 760",
"C": "rs . 840",
"D": "rs . 1020",
"E": "rs . 1615"
} | add(270, divide(multiply(270, const_100), multiply(12, 3))) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2) | t . d = ( b . gx 100 ) / ( r / t ) = ( 270 x 100 ) / ( 12 x 3 ) = rs . 750 b . d . = rs . ( 750 + 270 ) = rs . 1020 . answer : d | gain |
math_qa__rcvobB0qyRU9myh6 | By selling 150 apples, a fruit-seller gains the selling price of 30 apples. Find the gain percent? Select the correct option: A) 30 % B) 58 % C) 25 % D) 60 % E) 12 % | <gadget id="calculator">150 - 30</gadget>
<output>120</output>
<gadget id="calculator">30 / 120</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | By selling 150 apples, a fruit-seller gains the selling price of 30 apples. Find the gain percent? | {
"A": "30 %",
"B": "58 %",
"C": "25 %",
"D": "60 %",
"E": "12 %"
} | multiply(divide(30, subtract(150, 30)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100)| | "option c explanation : sp = cp + g 150 sp = 150 cp + 30 sp 120 sp = 150 cp 120 - - - 30 cp 100 - - - ? = > 25 %" | gain |
math_qa__smmeQAzD6dZ7MSFx | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ?
Choose the correct answer:
A) 10 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">70 / 5</gadget>
<output>14</output>
<result>C</result> | C | 14 | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 70, how many horses are there ? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(70, add(const_4, divide(const_2, const_2))) | divide(const_2,const_2)|add(#0,const_4)|divide(n0,#1)| | "explanation : let number of horses = number of men = x . then , number of legs = 4 x + 2 x ( x / 2 ) = 5 x . so , 5 x = 70 or x = 14 . answer : c" | general |
math_qa__Ar5wb8LpJ8oDKbmZ | A cube with its sides numbered 1 through 6 is rolled twice, first landing on a and then landing on b. If any roll of the cube yields an equal chance of landing on any of the numbers 1 through 6, what is the probability T that a + b is prime? Options:
A) 0 B) 1 / 12 C) 5 / 12 D) 7 / 18 E) 4 / 9 | <gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) ** 2</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">15 * (1/36)</gadget>
<output>5/12 = around 0.416667</output>
<result>C</result> | C | 0.416667 | A cube with its sides numbered 1 through 6 is rolled twice, first landing on a and then landing on b. If any roll of the cube yields an equal chance of landing on any of the numbers 1 through 6, what is the probability T that a + b is prime? | {
"A": "0",
"B": "1 / 12",
"C": "5 / 12",
"D": "7 / 18",
"E": "4 / 9"
} | multiply(add(const_12, const_3), power(divide(1, 6), const_2)) | add(const_12,const_3)|divide(n0,n1)|power(#1,const_2)|multiply(#0,#2)| | "total # of outcomes is 6 * 6 = 36 ; favorable outcomes : a - b - - > prime 1 - 1 - - > 2 ; 1 - 2 - - > 3 ; 2 - 1 - - > 3 ; 1 - 4 - - > 5 ; 4 - 1 - - > 5 ; 2 - 3 - - > 5 ; 3 - 2 - - > 5 ; 1 - 6 - - > 7 ; 6 - 1 - - > 7 ; 2 - 5 - - > 7 ; 5 - 2 - - > 7 ; 3 - 4 - - > 7 ; 4 - 3 - - > 7 ; 6 - 5 - - > 11 ; 5 - 6 - - > 11 . total of 15 favorable outcomes t = 15 / 36 . answer : c ." | general |
math_qa__lFuBrt46EnxquXcw | a man invested rs . 14400 in rs . 100 shares of a company at 20 % premium . if the company declares 7 % dividend at the end of the year , then how much does he get ? Choose the correct choice from the following answers: A) rs . 500 B) rs . 840 C) rs . 650 D) rs . 720 E) none | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">14_400 / 120</gadget>
<output>120</output>
<gadget id="calculator">120 * 100</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 * 7</gadget>
<output>84_000</output>
<gadget id="calculator">84_000 / 100</gadget>
<output>840</output>
<result>B</result> | B | 840 | a man invested rs . 14400 in rs . 100 shares of a company at 20 % premium . if the company declares 7 % dividend at the end of the year , then how much does he get ? | {
"A": "rs . 500",
"B": "rs . 840",
"C": "rs . 650",
"D": "rs . 720",
"E": "none"
} | divide(multiply(multiply(divide(14400, add(100, 20)), 100), 7), 100) | add(n1,n2)|divide(n0,#0)|multiply(n1,#1)|multiply(n3,#2)|divide(#3,n1) | solution number of shares = ( 14400 / 120 ) = 120 . face value = rs . ( 100 x 120 ) = rs . 12000 . annual income = rs . ( 7 / 100 x 12000 ) = rs . 840 . answer b | gain |
math_qa__Bovqo7Mty6wHY15p | A boy standing idle sounds a whistle to his friend at a distance of 1200 m moving away from him in a speeding car at 108 kms /hr. Find the duration after which his friend is going to hear him. (Speed of sound = 330m/sec). Pick one:
A) 3.6 secs B) 4.00 secs C) 40 secs D) 45 secs E) none of these | <gadget id="calculator">1_200 / 330</gadget>
<output>40/11 = around 3.636364</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 * (40/11)</gadget>
<output>1_200/11 = around 109.090909</output>
<gadget id="calculator">(1_200/11) / 330</gadget>
<output>40/121 = around 0.330579</output>
<gadget id="calculator">(40/11) + (40/121)</gadget>
<output>480/121 = around 3.966942</output>
<result>B</result> | B | 4 | A boy standing idle sounds a whistle to his friend at a distance of 1200 m moving away from him in a speeding car at 108 kms /hr. Find the duration after which his friend is going to hear him. (Speed of sound = 330m/sec). | {
"A": "3.6 secs",
"B": "4.00 secs",
"C": "40 secs",
"D": "45 secs",
"E": "none of these"
} | add(divide(1200, 330), divide(multiply(multiply(const_3, const_10), divide(1200, 330)), 330)) | divide(n0,n2)|multiply(const_10,const_3)|multiply(#0,#1)|divide(#2,n2)|add(#0,#3) | if friend hears sound after t secs , then 330 * t = 1200 + ( 108 * 5 / 18 ) * t 300 t = 1200 t = 4 secs answer : b | physics |
math_qa__U5ezcgn9YNd40oYS | if ' a ' and ' b ' are non - zero numbers such that their sum is 6 times the product , what is the value of 1 / a + 1 / b ? Choices.
A) 5 B) 6 C) 7 D) 8 E) 12 | <gadget id="calculator">6 / 1</gadget>
<output>6</output>
<result>B</result> | B | 6 | if ' a ' and ' b ' are non - zero numbers such that their sum is 6 times the product , what is the value of 1 / a + 1 / b ? | {
"A": "5",
"B": "6",
"C": "7",
"D": "8",
"E": "12"
} | divide(6, 1) | divide(n0,n1) | a + b = 6 ab 1 / a + 1 / b = ( b + a ) / ( ab ) = 6 . the answer is b . | general |
math_qa__qTTUFrIIoOVjtDDp | Two integers are in the ratio of 1 to 4. If 12 is added to the smaller number, the ratio becomes 1 to 2. Find the larger integer.
Choose the correct choice from the following:
A) 8
B) 16
C) 32
D) 48
E) 54 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<result>D</result> | D | 48 | Two integers are in the ratio of 1 to 4. If 12 is added to the smaller number, the ratio becomes 1 to 2. Find the larger integer. | {
"A": "8",
"B": "16",
"C": "32",
"D": "48",
"E": "54"
} | multiply(divide(multiply(2, 12), subtract(4, 2)), 4) | multiply(n2,n4)|subtract(n1,n4)|divide(#0,#1)|multiply(n1,#2) | one option is to set up the equations and solve : if the ratio of two integers x and y is 1 to 4 , then 4 x = y , where x is the smaller integer . if adding 12 to the smaller integer makes the ratio 1 to 2 , then 2 ( x + 12 ) = y . substituting y = 4 x into the second equation yields 2 x + 24 = 4 x . so , x = 12 ( smaller integer ) and , y = 4 x = 48 ( larger integer ) so d is the correct answer . another option is to test the answer choices . a ) the larger number is 8 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 2 if 12 is added to the smaller number , the ratio becomes 1 to 2 if we add 12 to the smaller number ( 2 ) , we get 14 . so , the new ratio is 14 to 8 which is the same as 7 to 4 . no good . we want a resulting ratio of 1 to 2 eliminate a b ) the larger number is 16 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 4 if 12 is added to the smaller number , the ratio becomes 1 to 2 if we add 12 to the smaller number ( 4 ) , we get 16 so , the new ratio is 16 to 16 which is 1 to 1 . no good . we want a resulting ratio of 1 to 2 eliminate b c ) the larger number is 32 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 8 if 12 is added to the smaller number , the ratio becomes 1 to 2 if we add 12 to the smaller number ( 8 ) , we get 20 so , the new ratio is 20 to 32 which is 5 to 8 . no good . we want a resulting ratio of 1 to 2 eliminate c d ) the larger number is 48 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 12 if 12 is added to the smaller number , the ratio becomes 1 to 2 if we add 12 to the smaller number ( 12 ) , we get 24 so , the new ratio is 24 to 48 . this is the same as the ratio of 1 to 2 therefore ( d ) is correct e ) the larger number is 54 given : the two integers are in the ratio of 1 to 4 so , the smaller number must be 13.5 ( which is not an integer ) since both numbers are integers , the larger number can not be 54 . eliminate e therefore d is the only correct choice . | other |
math_qa__YjXMIzO6aBh6OEJD | If the annual increase in the population of a town is 10% and the present number of people is 11000, what will the population be in 2 years? Answers.
A) 12100 B) 15240 C) 12456 D) 11452 E) 13310 | <gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * 11_000</gadget>
<output>12_100</output>
<gadget id="calculator">12_100 * (11/10)</gadget>
<output>13_310</output>
<result>E</result> | E | 13,310 | If the annual increase in the population of a town is 10% and the present number of people is 11000, what will the population be in 2 years? | {
"A": "12100",
"B": "15240",
"C": "12456",
"D": "11452",
"E": "13310"
} | multiply(multiply(divide(add(10, const_100), const_100), 11000), divide(add(10, const_100), const_100)) | add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|multiply(#1,#2)| | "the required population is = 11000 ( 1 + 10 / 100 ) ^ 2 = 11000 * 11 / 10 * 11 / 10 = 13310 answer is e" | gain |
math_qa__jUPNR043E6HFI30U | The owner of a furniture shop charges his customer 15% more than the cost price. If a customer paid Rs. 6400 for a computer table, then what was the cost price of the computer table? Choose the most appropriate option.
A) rs . 5565 B) rs . 6298 C) rs . 6290 D) rs . 6725 E) rs . 6708 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">6_400 / (23/20)</gadget>
<output>128_000/23 = around 5_565.217391</output>
<result>A</result> | A | 5,565 | The owner of a furniture shop charges his customer 15% more than the cost price. If a customer paid Rs. 6400 for a computer table, then what was the cost price of the computer table? | {
"A": "rs . 5565",
"B": "rs . 6298",
"C": "rs . 6290",
"D": "rs . 6725",
"E": "rs . 6708"
} | divide(6400, add(const_1, divide(15, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "cp = sp * ( 100 / ( 100 + profit % ) ) = 6400 ( 100 / 115 ) = rs . 5565 . answer : a" | gain |
math_qa__O7QaqIPaOzXInm31 | John and David work at a hospital with 4 other workers. For an internal review, 2 of the 4 workers will be randomly chosen to be interviewed. What is the probability that John and David will both be chosen? Choose the correct answer.
A) 1 / 14 B) 1 / 20 C) 1 / 13 D) 1 / 7 E) 1 / 6 | <gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) * (1/4)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 * (1/12)</gadget>
<output>1/6 = around 0.166667</output>
<result>E</result> | E | 0.166667 | John and David work at a hospital with 4 other workers. For an internal review, 2 of the 4 workers will be randomly chosen to be interviewed. What is the probability that John and David will both be chosen? | {
"A": "1 / 14",
"B": "1 / 20",
"C": "1 / 13",
"D": "1 / 7",
"E": "1 / 6"
} | multiply(2, multiply(divide(const_1, subtract(4, const_1)), divide(const_1, 4))) | divide(const_1,n0)|subtract(n0,const_1)|divide(const_1,#1)|multiply(#2,#0)|multiply(n1,#3)| | "probability that john and david will both be chosen out of 8 workers = ( 2 / 4 ) * ( 1 / 3 ) = 1 / 6 answer e" | physics |
math_qa__ItPN22mFbHJq025x | A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 6 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month? Choices:
A) 1 / 6 B) 1 / 5 C) 1 / 4 D) 1 / 3 E) 1 / 2 | <gadget id="calculator">12 / 6</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<result>D</result> | D | 0.333333 | A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 6 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month? | {
"A": "1 / 6",
"B": "1 / 5",
"C": "1 / 4",
"D": "1 / 3",
"E": "1 / 2"
} | inverse(add(divide(const_12, 6), const_1)) | divide(const_12,n0)|add(#0,const_1)|inverse(#1)| | "let x be the fraction of her take - home pay that the worker saved . let p be the monthly pay . 12 xp = 6 ( 1 - x ) p 12 xp = 6 p - 6 xp 18 xp = 6 p x = 1 / 3 the answer is d ." | general |
math_qa__LrNkuSwvG1RbuzDh | Marts income is 60 percent more than Tims income and Tims income is 40 percent less than Juans income. What percentage of Juans income is Marts income
Choose the correct choice from the following answers.
A) 124 %
B) 120 %
C) 96 %
D) 80 %
E) 64 % | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">100 / 60</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 100</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">160 / (500/3)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">(24/25) * 100</gadget>
<output>96</output>
<result>C</result> | C | 96 | Marts income is 60 percent more than Tims income and Tims income is 40 percent less than Juans income. What percentage of Juans income is Marts income | {
"A": "124 %",
"B": "120 %",
"C": "96 %",
"D": "80 %",
"E": "64 %"
} | multiply(divide(add(const_100, 60), multiply(divide(const_100, subtract(const_100, 40)), const_100)), const_100) | add(n0,const_100)|subtract(const_100,n1)|divide(const_100,#1)|multiply(#2,const_100)|divide(#0,#3)|multiply(#4,const_100)| | "tim = 100 mary ' s income is 60 percent more than tims income ; mary ' s income = t + 0.6 t = 1.6 t = 1.6 * 100 = 160 tims income is 40 percent less than juans income . 100 is 40 % less than juan ' s income 100 = j - 0.4 j 100 = 0.6 j j = 100 / 0.6 = 1000 / 6 what percentage of juans income is marts income ( 160 / ( 1000 / 6 ) ) * 100 = ( 160 * 6 * 100 ) / 1000 = 96 % answer : c" | general |
math_qa__jw1z2KU2dnnqAZKQ | On a trip, a cyclist averaged 8 miles per hour for the first 12 miles and 12 miles per hour for the remaining 24 miles. If the cyclist returned immediately via the same route and took a total of 7.5 hours for the round trip, what was the average speed (in miles per hour) for the return trip? Choose the correct option.
A) 9
B) 10
C) 11
D) 12
E) 13 | <gadget id="calculator">12 + 24</gadget>
<output>36</output>
<gadget id="calculator">12 / 8</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">24 / 12</gadget>
<output>2</output>
<gadget id="calculator">(3/2) + 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">7.5 - (7/2)</gadget>
<output>4</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<result>A</result> | A | 9 | On a trip, a cyclist averaged 8 miles per hour for the first 12 miles and 12 miles per hour for the remaining 24 miles. If the cyclist returned immediately via the same route and took a total of 7.5 hours for the round trip, what was the average speed (in miles per hour) for the return trip? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | divide(add(12, 24), subtract(7.5, add(divide(12, 8), divide(24, 12)))) | add(n1,n3)|divide(n1,n0)|divide(n3,n2)|add(#1,#2)|subtract(n4,#3)|divide(#0,#4)| | "the time to go 36 miles was 12 / 8 + 24 / 12 = 1.5 + 2 = 3.5 hours . the average speed for the return trip was 36 miles / 4 hours = 9 mph . the answer is a ." | physics |
math_qa__FVNgzdPZoL3ZJhWJ | The price of a T.V. set worth Rs. 20000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? Answers:
A) 19002 B) 19028 C) 27788 D) 19000 E) 27711 | <gadget id="calculator">20_000 - 1_000</gadget>
<output>19_000</output>
<result>D</result> | D | 19,000 | The price of a T.V. set worth Rs. 20000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? | {
"A": "19002",
"B": "19028",
"C": "27788",
"D": "19000",
"E": "27711"
} | subtract(20000, 1000) | subtract(n0,n2)| | "money paid in cash = rs . 1000 balance payment = ( 20000 - 1000 ) = rs . 19000 answer : d" | gain |
math_qa__L4DKMJmQgCp4AAtN | Working alone, pump A can empty a pool in 4 hours. Working alone, pump B can empty the same pool in 6 hours. Working together, how many minutes will it take pump A and pump B to empty the pool? Options
A) 132 B) 138 C) 144 D) 150 E) 156 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/4) + (1/6)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">1 / (5/12)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 60</gadget>
<output>144</output>
<result>C</result> | C | 144 | Working alone, pump A can empty a pool in 4 hours. Working alone, pump B can empty the same pool in 6 hours. Working together, how many minutes will it take pump A and pump B to empty the pool? | {
"A": "132",
"B": "138",
"C": "144",
"D": "150",
"E": "156"
} | multiply(inverse(add(divide(const_1, 4), divide(const_1, 6))), const_60) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)|multiply(#3,const_60) | pump a can empty ( 1 / 4 ) of the pool per hour . pump b can empty ( 1 / 6 ) of the pool per hour . together the pumps can empty 1 / 4 + 1 / 6 = 5 / 12 of the pool per hour . 1 pool / ( 5 / 12 ) pool per hour = 12 / 5 hours = 144 minutes . the answer is c . | physics |
math_qa__GYQ05nE9vqFXhm2T | The radius of a semi circle is 6.83 cm then its perimeter is? Select
A) 32.52
B) 32.47
C) 34.97
D) 32.92
E) 32.33 | <gadget id="calculator">2 * pi * 6.83</gadget>
<output>13.66*pi = around 42.914156</output>
<gadget id="calculator">(13.66*pi) / 2</gadget>
<output>6.83*pi = around 21.457078</output>
<gadget id="calculator">6.83 * 2</gadget>
<output>13.66</output>
<gadget id="calculator">(6.83*pi) + 13.66</gadget>
<output>13.66 + 6.83*pi = around 35.117078</output>
<result>C</result> | C | 34.97 | The radius of a semi circle is 6.83 cm then its perimeter is? | {
"A": "32.52",
"B": "32.47",
"C": "34.97",
"D": "32.92",
"E": "32.33"
} | add(divide(circumface(6.83), const_2), multiply(6.83, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "36 / 7 r = 6.3 = 34.97 answer : c" | physics |
math_qa__kiFBVcvzBzvvRmdS | Joan took out a mortgage from hel local bank. Each monthly mortgage payment she makes must be triple the amount of the previous month's payment. If her first payment is $100, and the total amount she must pay back is $109300, how many months will it take Joan to pay back her mortgage? Choose the correct choice: A) 7 B) 8 C) 10 D) 11 E) 13 | <gadget id="calculator">109_300 * 2</gadget>
<output>218_600</output>
<gadget id="calculator">218_600 / 100</gadget>
<output>2_186</output>
<gadget id="calculator">2_186 + 1</gadget>
<output>2_187</output>
<gadget id="calculator">log(2_187)</gadget>
<output>log(2187) = around 7.690286</output>
<gadget id="calculator">log(3)</gadget>
<output>log(3) = around 1.098612</output>
<gadget id="calculator">log(2187) / log(3)</gadget>
<output>log(2187)/log(3) = around 7</output>
<result>A</result> | A | 7 | Joan took out a mortgage from hel local bank. Each monthly mortgage payment she makes must be triple the amount of the previous month's payment. If her first payment is $100, and the total amount she must pay back is $109300, how many months will it take Joan to pay back her mortgage? | {
"A": "7",
"B": "8",
"C": "10",
"D": "11",
"E": "13"
} | divide(log(add(divide(multiply(109300, const_2), 100), const_1)), log(const_3)) | log(const_3)|multiply(n1,const_2)|divide(#1,n0)|add(#2,const_1)|log(#3)|divide(#4,#0)| | "joan starts off with 100 $ . . which is to be tripled every month her monthly payments look like this : 100 , 300 , 900 , 2700 . . . . . . . . . upto 109300 this can be re written as : 100 x 1 , 100 x 3 , 100 x 9 , 100 x 27 . . . . . . 100 x 1093 so we have 1 , 3 , 9 , 27 . . . . . 109300 in gp we know that a = 1 , and r = 3 ( its easy to figure it out by looking at the question , but regardless of it being mentioned in the question we can still compute the value of r using the formula tn = a 3 ^ n - 1 . . . ) therefore to find the sum of n terms of a gp we use this formula : sn = a ( 1 - r ^ n ) / 1 - r using this and plugging in the information we get . . . 1093 = 1 - 3 ^ n / 1 - 3 ; 1 - 3 ^ n / - 2 cross multiplying we get 1093 x - 2 = 1 - 3 ^ n - 2186 = 1 - 3 ^ n - 2187 = - 3 ^ n 2187 = 3 ^ n ( negatives cancel out ) 2187 can also be re written as 3 ^ 7 therefore ; 3 ^ 7 = 3 ^ n thus n = 7 ( a )" | general |
math_qa__zUvS3bZmjoV1Ee0B | Jerry began driving from home on a trip averaging 30 miles per hour. How many miles per hour must Carla drive on average to catch up to him in exactly 3 hours if she leaves 30 minutes after Jerry?
Choices.
A) 35 B) 55 C) 39 D) 40 E) 60 | <gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">30 * (7/2)</gadget>
<output>105</output>
<gadget id="calculator">105 / 3</gadget>
<output>35</output>
<result>A</result> | A | 35 | Jerry began driving from home on a trip averaging 30 miles per hour. How many miles per hour must Carla drive on average to catch up to him in exactly 3 hours if she leaves 30 minutes after Jerry? | {
"A": "35",
"B": "55",
"C": "39",
"D": "40",
"E": "60"
} | divide(multiply(30, add(3, divide(30, const_60))), 3) | divide(n0,const_60)|add(n1,#0)|multiply(n0,#1)|divide(#2,n1) | carla starts 30 minutes later and it takes 3 hr for carla to meet jerry so jerry total time travelled = 3 hr + 30 minutes jerry distance = 30 * ( 3 1 / 2 ) = 105 so carla need to travle 105 to meet jerry in 3 hrs speed of carla = 105 / 3 = 35 miles per hour answer is a | physics |
math_qa__fgA3hERD9DiOHyGg | Having scored 97 runs in the 19th inning, a cricketer increases his average score by 4. What will be his average score after 19 innings? Choose the correct answer:
A) 28
B) 27
C) 26
D) 22
E) 25 | <gadget id="calculator">19 * 4</gadget>
<output>76</output>
<gadget id="calculator">97 - 76</gadget>
<output>21</output>
<gadget id="calculator">21 + 4</gadget>
<output>25</output>
<result>E</result> | E | 25 | Having scored 97 runs in the 19th inning, a cricketer increases his average score by 4. What will be his average score after 19 innings? | {
"A": "28",
"B": "27",
"C": "26",
"D": "22",
"E": "25"
} | add(subtract(97, multiply(19, 4)), 4) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "explanation : let the average score of the first 18 innings be n 18 n + 97 = 19 ( n + 4 ) = > n = 21 so , average score after 19 th innings = x + 4 = 25 . answer : e" | general |
math_qa__bSuwDNp1am4vGbec | Find the area of a parallelogram with base 22 cm and height 21 cm? Choose the correct choice from the following answers.
A) 462 cm 2
B) 478 cm 2
C) 490 cm 2
D) 268 cm 2
E) 668 cm 2 | <gadget id="calculator">22 * 21</gadget>
<output>462</output>
<result>A</result> | A | 462 | Find the area of a parallelogram with base 22 cm and height 21 cm? | {
"A": "462 cm 2",
"B": "478 cm 2",
"C": "490 cm 2",
"D": "268 cm 2",
"E": "668 cm 2"
} | multiply(22, 21) | multiply(n0,n1)| | "area of a parallelogram = base * height = 22 * 21 = 462 cm 2 answer : a" | geometry |
math_qa__UcMOmEj0COZ2f6zT | A boatman goes 4 km against the current of the stream in 4 hour and goes 1 km along the current in 20 minutes. How long will it take to go 6 km in stationary water? Select:
A) 5 hours B) 1 hours C) 3 hours D) 2 hours E) 4 hours | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 60</gadget>
<output>3</output>
<gadget id="calculator">4 / 4</gadget>
<output>1</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>C</result> | C | 3 | A boatman goes 4 km against the current of the stream in 4 hour and goes 1 km along the current in 20 minutes. How long will it take to go 6 km in stationary water? | {
"A": "5 hours",
"B": "1 hours",
"C": "3 hours",
"D": "2 hours",
"E": "4 hours"
} | divide(6, divide(add(multiply(divide(1, 20), const_60), divide(4, 4)), const_2)) | divide(n0,n0)|divide(n2,n3)|multiply(#1,const_60)|add(#0,#2)|divide(#3,const_2)|divide(n4,#4) | speed upstream = 4 / 4 = 1 km / hr speed downstream = 1 / ( 20 / 60 ) = 3 km / hr speed in still water = 1 / 2 ( 3 + 1 ) = 2 km / hr time taken to travel 6 km in still water = 6 / 2 = 3 hours answer : c | physics |
math_qa__kwZTWQiOklsRr2G6 | Working alone, printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 12, 10, and 20 hours, respectively. What is the ratio of the time it takes printer X to do the job, working alone at its rate, to the time it takes printers Y and Z to do the job, working together at their individual rates? Choose the correct choice from the following:
A) 5 / 3
B) 7 / 4
C) 9 / 5
D) 11 / 6
E) 13 / 7 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/10) + (1/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 / (3/20)</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">12 / (20/3)</gadget>
<output>9/5 = around 1.8</output>
<result>C</result> | C | 1.8 | Working alone, printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 12, 10, and 20 hours, respectively. What is the ratio of the time it takes printer X to do the job, working alone at its rate, to the time it takes printers Y and Z to do the job, working together at their individual rates? | {
"A": "5 / 3",
"B": "7 / 4",
"C": "9 / 5",
"D": "11 / 6",
"E": "13 / 7"
} | divide(12, divide(const_1, add(divide(const_1, 10), divide(const_1, 20)))) | divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|divide(const_1,#2)|divide(n0,#3)| | "the time it takes printer x is 12 hours . the combined rate of y and z is 1 / 10 + 1 / 20 = 3 / 20 the time it takes y and z is 20 / 3 the ratio of times is 12 / ( 20 / 3 ) = 3 * 12 / 20 = 9 / 5 the answer is c ." | general |
math_qa__VoRbLOSJL4uJfIQ8 | The width of a rectangular hall is ½ of its length. If the area of the hall is 288 sq.m, what is the difference between its length and breadth? Options:
A) 8 m
B) 10 m
C) 12 m
D) 15 m
E) 17 m | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">288 / (1/2)</gadget>
<output>576</output>
<gadget id="calculator">576 ** (1/2)</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>C</result> | C | 12 | The width of a rectangular hall is ½ of its length. If the area of the hall is 288 sq.m, what is the difference between its length and breadth? | {
"A": "8 m",
"B": "10 m",
"C": "12 m",
"D": "15 m",
"E": "17 m"
} | divide(sqrt(divide(288, divide(const_1, const_2))), const_2) | divide(const_1,const_2)|divide(n0,#0)|sqrt(#1)|divide(#2,const_2)| | "let the length of the hall be x m breadth of the hall = 1 x / 2 m area of the hall = length * breadth 288 = x * 1 x / 2 x ² = 576 x = 24 difference between the length and breadth of the hall = x - 1 x / 2 = x / 2 = 24 / 2 = 12 m answer : c" | geometry |
math_qa__L7oyUXW2RssphTtm | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially? Choose the correct answer: A) 10 B) 20 C) 21 D) 25 E) 27 | <gadget id="calculator">7 + 9</gadget>
<output>16</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 9</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">9 - (15/4)</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">16 * (21/4)</gadget>
<output>84</output>
<gadget id="calculator">9 * 7</gadget>
<output>63</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">63 - 35</gadget>
<output>28</output>
<gadget id="calculator">84 / 28</gadget>
<output>3</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<result>C</result> | C | 21 | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially? | {
"A": "10",
"B": "20",
"C": "21",
"D": "25",
"E": "27"
} | multiply(7, divide(multiply(add(7, 9), subtract(9, multiply(divide(5, add(7, 5)), 9))), subtract(multiply(9, 7), multiply(7, 5)))) | add(n0,n2)|add(n0,n1)|multiply(n0,n2)|multiply(n0,n1)|divide(n1,#1)|subtract(#2,#3)|multiply(n2,#4)|subtract(n2,#6)|multiply(#0,#7)|divide(#8,#5)|multiply(n0,#9) | using the values here might be the most straightforward way for this question . as a : b : : 7 : 5 - - - > only option c is a multiple of 7 and hence it is a good place to start . also a : b : : 7 : 5 means that , a = ( 712 ) * total and b = ( 5 / 12 ) * total if a = 21 , b = 15 - - - > remove 9 litres - - - > you remove ( 7 / 12 ) * 9 of a - - - > a remaining = 21 - ( 7 / 12 ) * 9 = 63 / 4 similarly , for b , you remove ( 5 / 12 ) * 9 - - - > b remaining = 15 - ( 5 / 12 ) * 9 = 45 / 4 and then add 9 more litres of b - - - > 9 + 45 / 4 = 81 / 4 thus a / b ( final ratio ) = ( 45 / 4 ) / ( 81 / 4 ) = 7 : 9 , the same as the final ratio mentioned in the question . hence c is the correct answer . fyi , the algebraic equations will become : a / b = 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) , where 7 x and 5 x are initial quantities of a and b respectively . thus , 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) - - - > giving you x = 3 . thus a ( original ) = 7 * 3 = 21 . answer : c | other |
math_qa__gN2CipIGIY9Pvr2j | A and B can do a piece of work in 45 days and 40 days respectively. They began to do the work together but A leaves after some days and then B completed the remaining work in 23 days. The number of days after which A left the work was Choose the correct choice:
A) 5 days B) 6 days C) 7 days D) 9 days E) 8 days | <gadget id="calculator">23 / 40</gadget>
<output>23/40 = around 0.575</output>
<gadget id="calculator">1 - (23/40)</gadget>
<output>17/40 = around 0.425</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(1/45) + (1/40)</gadget>
<output>17/360 = around 0.047222</output>
<gadget id="calculator">(17/40) / (17/360)</gadget>
<output>9</output>
<result>D</result> | D | 9 | A and B can do a piece of work in 45 days and 40 days respectively. They began to do the work together but A leaves after some days and then B completed the remaining work in 23 days. The number of days after which A left the work was | {
"A": "5 days",
"B": "6 days",
"C": "7 days",
"D": "9 days",
"E": "8 days"
} | divide(subtract(const_1, divide(23, 40)), add(divide(const_1, 45), divide(const_1, 40))) | divide(n2,n1)|divide(const_1,n0)|divide(const_1,n1)|add(#1,#2)|subtract(const_1,#0)|divide(#4,#3)| | "does the job in 40 days = 1 / 40 a & b together completes the job = ? after a leaves , b completes the remaining job in 23 days . i . e b ' s part of job in 23 days = 23 / 40 remaining part 17 / 40 is done by a & b together in x no . of days . i . e ( x / 45 ) + ( x / 40 ) = 17 / 40 = > x = 9 days answer : d" | physics |
math_qa__VeaQwuxcx15wBL13 | Virginia, Adrienne, and Dennis have taught history for a combined total of 75 years. If Virginia has taught for 9 more years than Adrienne and for 9 fewer years than Dennis, for how many years has Dennis taught?
Choose the correct answer.
A) 23 B) 34 C) 35 D) 41 E) 44 | <gadget id="calculator">9 + 9</gadget>
<output>18</output>
<gadget id="calculator">18 + 9</gadget>
<output>27</output>
<gadget id="calculator">75 - 27</gadget>
<output>48</output>
<gadget id="calculator">48 / 3</gadget>
<output>16</output>
<gadget id="calculator">16 + 18</gadget>
<output>34</output>
<result>B</result> | B | 34 | Virginia, Adrienne, and Dennis have taught history for a combined total of 75 years. If Virginia has taught for 9 more years than Adrienne and for 9 fewer years than Dennis, for how many years has Dennis taught? | {
"A": "23",
"B": "34",
"C": "35",
"D": "41",
"E": "44"
} | add(divide(subtract(75, add(add(9, 9), 9)), const_3), add(9, 9)) | add(n1,n2)|add(n1,#0)|subtract(n0,#1)|divide(#2,const_3)|add(#0,#3)| | "let number of years taught by virginia = v number of years taught by adrienne = a number of years taught by dennis = d v + a + d = 75 v = a + 9 = > a = v - 9 v = d - 9 = > a = ( d - 9 ) - 9 = d - 18 d - 9 + d - 18 + d = 96 = > 3 d = 75 + 27 = 102 = > d = 34 answer b" | general |
math_qa__psSrYqjRkZFJlhBv | A big container is 40% full with water. If 28 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters?
Pick:
A) 68
B) 72
C) 76
D) 80
E) 84 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/4) - (2/5)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">28 / (7/20)</gadget>
<output>80</output>
<result>D</result> | D | 80 | A big container is 40% full with water. If 28 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters? | {
"A": "68",
"B": "72",
"C": "76",
"D": "80",
"E": "84"
} | divide(28, subtract(divide(3, 4), divide(40, const_100))) | divide(n2,n3)|divide(n0,const_100)|subtract(#0,#1)|divide(n1,#2)| | "28 liters is 35 % of the capacity c . 28 = 0.35 c c = 28 / 0.35 = 80 liters . the answer is d ." | general |
math_qa__AEqDvZeshmuj6IGI | At an international conference, “Red” world countries and “Blue” world countries are the only participants. The ratio of “Red” world participants to “Blue” world participants is 2:1. If one-third of “Red” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed? Choose the correct choice from the following answers.
A) 2 / 3 B) 4 / 5 C) 6 / 2 D) 5 / 2 E) 4 / 9 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2 * (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 * (2/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) + (2/3)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">(4/3) / 3</gadget>
<output>4/9 = around 0.444444</output>
<result>E</result> | E | 0.444444 | At an international conference, “Red” world countries and “Blue” world countries are the only participants. The ratio of “Red” world participants to “Blue” world participants is 2:1. If one-third of “Red” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed? | {
"A": "2 / 3",
"B": "4 / 5",
"C": "6 / 2",
"D": "5 / 2",
"E": "4 / 9"
} | divide(add(multiply(2, const_0_33), multiply(1, divide(const_2, const_3))), add(2, 1)) | add(n0,n1)|divide(const_2,const_3)|multiply(n0,const_0_33)|multiply(n1,#1)|add(#2,#3)|divide(#4,#0)| | "red : blue = 2 : 1 let red = 2 x and blue = 1 x 1 / 3 of red are left handed = > 1 / 3 * 2 x = 2 x / 3 red left handed 2 / 3 of blue are left handed = > 2 / 3 * 1 x = 2 x / 3 blue left handed fraction of participants who are left handed = total left handed / total participants = ( red left handed + blue left handed ) / total participants = ( 2 x / 3 + 2 x / 3 ) / ( 2 x + 1 x ) = 4 / 9 answer : e" | other |
math_qa__wJJP13GOgeozAz9x | If 4 men can colour 48 m long cloth in 2 days, then 6 men can colour 72 m long cloth in Choose the correct choice from the following choices:
A) 1 day B) 2 days C) 3 days D) 4 days E) 5 days | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">72 / 36</gadget>
<output>2</output>
<result>B</result> | B | 2 | If 4 men can colour 48 m long cloth in 2 days, then 6 men can colour 72 m long cloth in | {
"A": "1 day",
"B": "2 days",
"C": "3 days",
"D": "4 days",
"E": "5 days"
} | divide(72, multiply(divide(48, multiply(4, 2)), 6)) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2)| | "the length of cloth painted by one man in one day = 48 / 4 × 2 = 6 m no . of days required to paint 36 m cloth by 6 men = 72 / 6 × 6 = 2 day . b" | physics |
math_qa__JyWCXt7prEy4TdIw | Calculate the speed of a boat in still water (in km/hr) if in one hour, the boat goes 10 km/hr downstream and 4 km/hr upstream. Choose the correct choice: A) 7 kmph B) 8 kmph C) 9 kmph D) 7 kmph E) 6 kmph | <gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>A</result> | A | 7 | Calculate the speed of a boat in still water (in km/hr) if in one hour, the boat goes 10 km/hr downstream and 4 km/hr upstream. | {
"A": "7 kmph",
"B": "8 kmph",
"C": "9 kmph",
"D": "7 kmph",
"E": "6 kmph"
} | divide(add(10, 4), const_2) | add(n0,n1)|divide(#0,const_2) | speed in still water = ( 10 + 4 ) 1 / 2 kmph = 7 kmph . answer : a | physics |
math_qa__Y7uYgNDOeZzstgUK | The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs 3. The ratio of two selling prices is
Choose the correct choice from the following choices.
A) 51 : 52 B) 52 : 53 C) 53 : 54 D) 54 : 55 E) none of these | <gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">104 / 106</gadget>
<output>52/53 = around 0.981132</output>
<result>B</result> | B | 0.981132 | The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs 3. The ratio of two selling prices is | {
"A": "51 : 52",
"B": "52 : 53",
"C": "53 : 54",
"D": "54 : 55",
"E": "none of these"
} | divide(add(const_100, 4), add(const_100, 6)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "explanation : let the cost price of article is rs . x required ratio = 104 % of x / 106 % of x = 104 / 106 = 52 / 53 = 52 : 53 option b" | gain |
math_qa__HygHB4Co3M4F4dYc | A steel vessel has a base of length 60 cm and breadth 30 cm. Water is poured in the vessel. A cubical steel box having edge of 30 cm is immersed completely in the vessel. How much will the water rise? Choose the correct choice:
A) 7.5 cm rise B) 10 cm rise C) 15 cm rise D) 30 cm rise E) none of these | <gadget id="calculator">30 ** 3</gadget>
<output>27_000</output>
<gadget id="calculator">60 * 30</gadget>
<output>1_800</output>
<gadget id="calculator">27_000 / 1_800</gadget>
<output>15</output>
<result>C</result> | C | 15 | A steel vessel has a base of length 60 cm and breadth 30 cm. Water is poured in the vessel. A cubical steel box having edge of 30 cm is immersed completely in the vessel. How much will the water rise? | {
"A": "7.5 cm rise",
"B": "10 cm rise",
"C": "15 cm rise",
"D": "30 cm rise",
"E": "none of these"
} | divide(power(30, const_3), multiply(60, 30)) | multiply(n0,n1)|power(n1,const_3)|divide(#1,#0) | explanation : volume of cube = a 3 = a * a * a 60 cm * 30 cm * h = 30 cm * 30 cm * 30 cm h = 15 cm answer is c | geometry |
math_qa__kaXfbjqoahyOqn4J | A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ? Select the correct option.
A) 10 B) 11 C) 12 D) 15 E) 16 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<result>A</result> | A | 10 | A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ? | {
"A": "10",
"B": "11",
"C": "12",
"D": "15",
"E": "16"
} | add(multiply(3, 3), const_1) | multiply(n0,n0)|add(#0,const_1) | 4 a 3 | 9 8 4 } = = > a + 8 = b = = > b - a = 8 13 b 7 | also , 13 b 7 is divisible by 11 = > ( 7 + 3 ) – ( b + 1 ) = ( 9 – b ) ( 9 – b ) = 0 b = 9 ( b = 9 and a = 1 ) = > ( a + b ) = 10 . answer a | general |
math_qa__EpN3OVTJFMJQQemy | If 3^x*4^y = 19,683 and x – y = 9, then x = ? Choose the most appropriate option:
A) 8
B) 9
C) 10
D) 11
E) 12 | <gadget id="calculator">9 * 1</gadget>
<output>9</output>
<result>B</result> | B | 9 | If 3^x*4^y = 19,683 and x – y = 9, then x = ? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | multiply(9, const_1) | multiply(n3,const_1) | since 19,683 is an odd number , it is not a multiple of 4 . this means that y must equal zero . since x - y = 9 and y = 0 , then x = 9 . the answer is b . | general |
math_qa__fqdBuIwyymaNgxBA | In what time will a railway train 64 m long moving at the rate of 46 kmph pass a telegraph post on its way?
Choose one
A) 3 B) 5 C) 4 D) 6 E) 7 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">46 * (5/18)</gadget>
<output>115/9 = around 12.777778</output>
<gadget id="calculator">64 / (115/9)</gadget>
<output>576/115 = around 5.008696</output>
<result>B</result> | B | 5 | In what time will a railway train 64 m long moving at the rate of 46 kmph pass a telegraph post on its way? | {
"A": "3",
"B": "5",
"C": "4",
"D": "6",
"E": "7"
} | divide(64, multiply(46, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 64 / 46 * 18 / 5 = 5 sec answer : b" | physics |
math_qa__7gpwyO0YRt2nyj8d | If the sides of a triangle are 30 cm, 28 cm and 14 cm, what is its area? Pick
A) 196 cm 2 B) 187 cm 2 C) 178 cm 2 D) 189 cm 2 E) 176 cm 2 | <gadget id="calculator">28 * 14</gadget>
<output>392</output>
<gadget id="calculator">392 / 2</gadget>
<output>196</output>
<result>A</result> | A | 196 | If the sides of a triangle are 30 cm, 28 cm and 14 cm, what is its area? | {
"A": "196 cm 2",
"B": "187 cm 2",
"C": "178 cm 2",
"D": "189 cm 2",
"E": "176 cm 2"
} | divide(multiply(28, 14), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 30 cm , 28 cm and 14 cm is right angled , where the hypotenuse is 30 cm . area of the triangle = 1 / 2 * 28 * 14 = 196 cm 2 answer : a" | geometry |
math_qa__HgfaHHAUR1iAUceo | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1232? Select the correct option:
A) 1000 B) 2217 C) 1100 D) 2777 E) 2991 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) + 1</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">1_232 / (28/25)</gadget>
<output>1_100</output>
<result>C</result> | C | 1,100 | Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1232? | {
"A": "1000",
"B": "2217",
"C": "1100",
"D": "2777",
"E": "2991"
} | divide(1232, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 5), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "1232 = p [ 1 + ( 5 * 12 / 5 ) / 100 ] p = 1100 answer : c" | general |
math_qa__uJgEaBlcpn8TMuzX | A group of students was interviewed for that if it was asked whether or not they speak French and / or English. Among those who speak French, 30 speak English well, while 40 of them do not speak English. If 86% of students do not speak French, how many students were surveyed? Answers: A) 500 B) 450 C) 250 D) 350 E) 525 | <gadget id="calculator">30 + 40</gadget>
<output>70</output>
<gadget id="calculator">100 - 86</gadget>
<output>14</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">70 / (7/50)</gadget>
<output>500</output>
<result>A</result> | A | 500 | A group of students was interviewed for that if it was asked whether or not they speak French and / or English. Among those who speak French, 30 speak English well, while 40 of them do not speak English. If 86% of students do not speak French, how many students were surveyed? | {
"A": "500",
"B": "450",
"C": "250",
"D": "350",
"E": "525"
} | divide(add(30, 40), divide(subtract(const_100, 86), const_100)) | add(n0,n1)|subtract(const_100,n2)|divide(#1,const_100)|divide(#0,#2)| | "number of students who speak french are 30 + 40 = 70 of total students , the percentage of students who do not speak french was 86 % - - > percentage of who do is 14 % 70 - - - - - - - 14 % x - - - - - - - 100 % x = 70 * 100 / 14 = 500 = number of all students answer is a" | gain |
math_qa__0L5bZcI0M7SegNeL | The parameter of a square is equal to the perimeter of a rectangle of length 4 cm and breadth 2 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)?
Select the correct option: A) 4.51 B) 4.71 C) 4.32 D) 4.21 E) 4.68 | <gadget id="calculator">2 * (4 + 2)</gadget>
<output>12</output>
<gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">2 * pi * (3/2)</gadget>
<output>3*pi = around 9.424778</output>
<gadget id="calculator">(3*pi) / 2</gadget>
<output>3*pi/2 = around 4.712389</output>
<result>B</result> | B | 4.71 | The parameter of a square is equal to the perimeter of a rectangle of length 4 cm and breadth 2 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)? | {
"A": "4.51",
"B": "4.71",
"C": "4.32",
"D": "4.21",
"E": "4.68"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(4, 2)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 4 + 2 ) = 12 cm parameter of the square = 12 cm i . e . 4 a = 12 a = 3 diameter of the semicircle = 3 cm circimference of the semicircle = 1 / 2 ( â ˆ ) ( 3 ) = 1 / 2 ( 22 / 7 ) ( 3 ) = 66 / 14 = 4.71 cm to two decimal places answer : b" | geometry |
math_qa__Ru2kVys7GoV7asrz | 15 different biology books and 8 different chemistry books lie on a shelf. In how many ways can a student pick 2 books of each type? Choices.
A) 80
B) 160
C) 720
D) 2100
E) 2940 | <gadget id="calculator">factorial(15)</gadget>
<output>1_307_674_368_000</output>
<gadget id="calculator">15 - 2</gadget>
<output>13</output>
<gadget id="calculator">factorial(13)</gadget>
<output>6_227_020_800</output>
<gadget id="calculator">1_307_674_368_000 / 6_227_020_800</gadget>
<output>210</output>
<gadget id="calculator">210 / 2</gadget>
<output>105</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">105 * 28</gadget>
<output>2_940</output>
<result>E</result> | E | 2,940 | 15 different biology books and 8 different chemistry books lie on a shelf. In how many ways can a student pick 2 books of each type? | {
"A": "80",
"B": "160",
"C": "720",
"D": "2100",
"E": "2940"
} | multiply(divide(divide(factorial(15), factorial(subtract(15, 2))), 2), divide(divide(factorial(8), factorial(subtract(8, 2))), 2)) | factorial(n0)|factorial(n1)|subtract(n0,n2)|subtract(n1,n2)|factorial(#2)|factorial(#3)|divide(#0,#4)|divide(#1,#5)|divide(#6,n2)|divide(#7,n2)|multiply(#8,#9)| | "no . of ways of picking 2 biology books ( from 15 books ) = 15 c 2 = ( 15 * 14 ) / 2 = 105 no . of ways of picking 2 chemistry books ( from 8 books ) = 8 c 2 = ( 8 * 7 ) / 2 = 28 total ways of picking 2 books of each type = 105 * 28 = 2940 ( option e )" | other |
math_qa__nNOpQzvHfA1AuOaK | A computer factory produces 6048 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month? Choose the correct choice from the following options
A) 2.25 . B) 3.125 . C) 4.5 . D) 5.225 . E) 6.25 . | <gadget id="calculator">6_048 / 28</gadget>
<output>216</output>
<gadget id="calculator">28 - 4</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">216 / 48</gadget>
<output>9/2 = around 4.5</output>
<result>C</result> | C | 4.5 | A computer factory produces 6048 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month? | {
"A": "2.25 .",
"B": "3.125 .",
"C": "4.5 .",
"D": "5.225 .",
"E": "6.25 ."
} | divide(divide(6048, 28), multiply(subtract(28, const_4), const_2)) | divide(n0,n2)|subtract(n2,const_4)|multiply(#1,const_2)|divide(#0,#2)| | "number of hours in 28 days = 28 * 24 number of 30 mins in 28 days = 28 * 24 * 2 number of computers built every 30 mins = 6048 / ( 28 * 24 * 2 ) = 4.5 answer c" | physics |
math_qa__ik5vYg4EWoNWXIzm | Find the greatest number which on dividing 1428 and 2206, leaves a reminder of 9 and 13 respectively Choose the correct choice from the following answers:
A) 125
B) 127
C) 129
D) 131
E) 141 | <gadget id="calculator">1_428 - 9</gadget>
<output>1_419</output>
<gadget id="calculator">2_206 - 13</gadget>
<output>2_193</output>
<gadget id="calculator">gcd(1_419, 2_193)</gadget>
<output>129</output>
<result>C</result> | C | 129 | Find the greatest number which on dividing 1428 and 2206, leaves a reminder of 9 and 13 respectively | {
"A": "125",
"B": "127",
"C": "129",
"D": "131",
"E": "141"
} | gcd(subtract(1428, 9), subtract(2206, 13)) | subtract(n0,n2)|subtract(n1,n3)|gcd(#0,#1)| | "explanation : in this type of question , its obvious we need to calculate the hcf , trick is hcf of ( 1428 - 9 ) and ( 2206 - 13 ) = hcf ( 1419 , 2193 ) = 129 option c" | general |
math_qa__pqfjBcfaFBt3Ykqt | What is the ratio of Arun's monthly income in the year 2006, Suman's monthly income in the year 2007 and Jyothi's monthly income in the year 2005? Pick one
A) 22 B) 67 C) 26 D) 18 E) 16 | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<result>A</result> | A | 22 | What is the ratio of Arun's monthly income in the year 2006, Suman's monthly income in the year 2007 and Jyothi's monthly income in the year 2005? | {
"A": "22",
"B": "67",
"C": "26",
"D": "18",
"E": "16"
} | add(add(const_10, const_10), const_2) | add(const_10,const_10)|add(#0,const_2) | answer : a | other |
math_qa__GXlYtzQTe5KdcyMO | A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 5 hours longer than the first half, how many hours did it take the runner to run the second half? Choose the correct option:
A) 8
B) 9
C) 10
D) 11
E) 12 | <gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">40 / 4</gadget>
<output>10</output>
<result>C</result> | C | 10 | A runner runs the 40 miles from Marathon to Athens at a constant speed. Halfway through the run she injures her foot, and continues to run at half her previous speed. If the second half takes her 5 hours longer than the first half, how many hours did it take the runner to run the second half? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | divide(40, divide(divide(40, const_2), 5)) | divide(n0,const_2)|divide(#0,n1)|divide(n0,#1) | the runner runs the first 20 miles at speed v and the second 20 miles at speed v / 2 . the time t 2 to run the second half must be twice the time t 1 to run the first half . t 2 = 2 * t 1 = t 1 + 5 t 1 = 5 and so t 2 = 10 . the answer is c . | physics |
math_qa__QF5CcXH1UhxJ7Kfd | There are 2 sections A and B in a class, consisting of 40 and 20 students respectively. If the average weight of section A is 50kg and that of section B is 40kg, Find the average of the whole class? Choose one
A) 50.78 kg B) 49.32 kg C) 46.66 kg D) 69.15 kg E) 70.89 kg | <gadget id="calculator">40 * 50</gadget>
<output>2_000</output>
<gadget id="calculator">20 * 40</gadget>
<output>800</output>
<gadget id="calculator">2_000 + 800</gadget>
<output>2_800</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">2_800 / 60</gadget>
<output>140/3 = around 46.666667</output>
<result>C</result> | C | 46.66 | There are 2 sections A and B in a class, consisting of 40 and 20 students respectively. If the average weight of section A is 50kg and that of section B is 40kg, Find the average of the whole class? | {
"A": "50.78 kg",
"B": "49.32 kg",
"C": "46.66 kg",
"D": "69.15 kg",
"E": "70.89 kg"
} | divide(add(multiply(40, 50), multiply(20, 40)), add(40, 20)) | add(n1,n2)|multiply(n1,n3)|multiply(n2,n4)|add(#1,#2)|divide(#3,#0)| | "total weight of 40 + 20 students = 40 * 50 + 20 * 40 = 2000 + 800 average weight of the class is = 2800 / 60 = 46.66 kg answer is c" | general |
math_qa__KFd6b5STIcDtYtWK | On dividing 15 by a number, the quotient is 4 and the remainder is 3. Find the divisor? Choose the correct option
A) 3
B) 6
C) 9
D) 12
E) 15 | <gadget id="calculator">15 / 4</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">floor(15/4)</gadget>
<output>3</output>
<result>A</result> | A | 3 | On dividing 15 by a number, the quotient is 4 and the remainder is 3. Find the divisor? | {
"A": "3",
"B": "6",
"C": "9",
"D": "12",
"E": "15"
} | floor(divide(15, 4)) | divide(n0,n1)|floor(#0)| | "d = ( d - r ) / q = ( 15 - 3 ) / 4 = 12 / 4 = 3 a )" | general |
math_qa__J7CKkVooWNK9WsMm | If it takes a machine 2⁄5 minute to produce one item, how many items will it produce in 2 hours? Pick:
A) 1 ⁄ 3 B) 4 ⁄ 3 C) 80 D) 120 E) 300 | <gadget id="calculator">2 * 60</gadget>
<output>120</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">120 / (2/5)</gadget>
<output>300</output>
<result>E</result> | E | 300 | If it takes a machine 2⁄5 minute to produce one item, how many items will it produce in 2 hours? | {
"A": "1 ⁄ 3",
"B": "4 ⁄ 3",
"C": "80",
"D": "120",
"E": "300"
} | divide(multiply(2, const_60), divide(2, 5)) | divide(n0,n1)|multiply(n2,const_60)|divide(#1,#0)| | "1 item takes 2 / 5 min so it takes 120 min to produce x 2 x / 5 = 120 the x = 300 answer : e" | physics |
math_qa__uePdQfyWcdiEJ5Ei | Excluding stoppages, the speed of a bus is 82 kmph and including stoppages, it is 75 kmph. For how many minutes does the bus stop per hour?
Choose one:
A) 5.12
B) 4.13
C) 6.15
D) 7.5
E) none of these | <gadget id="calculator">82 - 75</gadget>
<output>7</output>
<gadget id="calculator">7 / 82</gadget>
<output>7/82 = around 0.085366</output>
<gadget id="calculator">60 * (7/82)</gadget>
<output>210/41 = around 5.121951</output>
<result>A</result> | A | 5.12 | Excluding stoppages, the speed of a bus is 82 kmph and including stoppages, it is 75 kmph. For how many minutes does the bus stop per hour? | {
"A": "5.12",
"B": "4.13",
"C": "6.15",
"D": "7.5",
"E": "none of these"
} | multiply(const_60, divide(subtract(82, 75), 82)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "due to stoppages , it covers 7 km less . time taken to cover 7 km = ( ( 7 / 82 ) ã — 60 ) = 5.12 min . option ( a ) is correct" | physics |
math_qa__lnbM3N84w3MsPUxZ | During a certain season, a team won 85 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of its games for the entire season, what was the total number of games that the team played? Choose the correct choice.
A) 180
B) 175
C) 156
D) 150
E) 105 | <gadget id="calculator">85 - 70</gadget>
<output>15</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(7/10) - (1/2)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">15 / (1/5)</gadget>
<output>75</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<result>B</result> | B | 175 | During a certain season, a team won 85 percent of its first 100 games and 50 percent of its remaining games. If the team won 70 percent of its games for the entire season, what was the total number of games that the team played? | {
"A": "180",
"B": "175",
"C": "156",
"D": "150",
"E": "105"
} | add(100, divide(subtract(85, 70), subtract(divide(70, 100), divide(50, 100)))) | divide(n3,n1)|divide(n2,n1)|subtract(n0,n3)|subtract(#0,#1)|divide(#2,#3)|add(n1,#4)| | "we are first given that a team won 85 percent of its first 100 games . this means the team won 0.85 x 100 = 85 games out of its first 100 games . we are next given that the team won 50 percent of its remaining games . if we use variable t to represent the total number of games in the season , then we can say t – 100 equals the number of remaining games in the season . thus we can say : 0.5 ( t – 100 ) = number of wins for remaining games 0.5 t – 50 = number of wins for remaining games lastly , we are given that team won 70 percent of all games played in the season . that is , they won 0.7 t games in the entire season . with this we can set up the equation : number of first 100 games won + number of games won for remaining games = total number of games won in the entire season 85 + 0.5 t – 50 = 0.7 t 35 = 0.2 t 350 = 2 t 175 = t answer is b ." | gain |
math_qa__lJnajLAjv61o5i3H | A certain clock marks every hour by striking a number of times equal to the hour, and the time require for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stoke and the end of the last stroke is 22 seconds. At 8:00, how many seconds elapse between the beginning of the first stroke and the end of the last stroke?
Choices.
A) 26
B) 30
C) 36
D) 38
E) 40 | <gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">7 + 8</gadget>
<output>15</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">22 / 11</gadget>
<output>2</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<result>B</result> | B | 30 | A certain clock marks every hour by striking a number of times equal to the hour, and the time require for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stoke and the end of the last stroke is 22 seconds. At 8:00, how many seconds elapse between the beginning of the first stroke and the end of the last stroke? | {
"A": "26",
"B": "30",
"C": "36",
"D": "38",
"E": "40"
} | multiply(add(subtract(8, const_1), 8), divide(22, add(subtract(6, const_1), 6))) | subtract(n3,const_1)|subtract(n0,const_1)|add(n3,#0)|add(n0,#1)|divide(n2,#3)|multiply(#2,#4)| | "at 6 ' o clock , there would be 6 strikes . first strike , then a short interval , the second strike , then a short interval and so on till the 6 th strike . so there would be in all 5 intervals between 6 strikes . similarly , between 8 strikes , there would be 7 intervals . according to the question , the time spent in the strike and the interval is same . at 6 ' o clock , the 6 strikes and the 5 intervals together take 22 sec so each strike and each interval takes 2 secs . at 8 ' o clock , the 8 strikes and 7 intervals will take 2 * ( 8 + 7 ) = 30 secs b" | general |
math_qa__d6Zh2kUJv92N8I76 | If m and n are whole numbers such that mn = 121, the value of (m 1)
n + 1 is: Choose the correct choice from the following.
A) 1 B) 10 C) 121 D) 100 E) 1000 | <gadget id="calculator">121 ** (1/2)</gadget>
<output>11</output>
<gadget id="calculator">11 - 1</gadget>
<output>10</output>
<gadget id="calculator">10 ** 3</gadget>
<output>1_000</output>
<result>E</result> | E | 1,000 | If m and n are whole numbers such that mn = 121, the value of (m 1)
n + 1 is: | {
"A": "1",
"B": "10",
"C": "121",
"D": "100",
"E": "1000"
} | power(subtract(sqrt(121), 1), const_3) | sqrt(n0)|subtract(#0,n1)|power(#1,const_3) | if m and n are whole numbers such that mn = 121 , the value of ( m - 1 ) n + 1 is : a . 1 b . 10 c . 121 d . 1000 sol . - we know that 112 = 121 . putting m = 11 and n = 2 , we get : ( m - 1 ) n + 1 = ( 11 - 1 ) ( 2 + 1 ) = 103 = 1000 . answer : e | general |
math_qa__dnQN6jeUObYKkvL7 | If the sides of a triangle are 28 cm, 26 cm and 10 cm, what is its area? Choose the correct choice from the following answers: A) 120 cm 2 B) 112 cm 2 C) 776 cm 2 D) 130 cm 2 E) 886 cm 2 | <gadget id="calculator">26 * 10</gadget>
<output>260</output>
<gadget id="calculator">260 / 2</gadget>
<output>130</output>
<result>D</result> | D | 130 | If the sides of a triangle are 28 cm, 26 cm and 10 cm, what is its area? | {
"A": "120 cm 2",
"B": "112 cm 2",
"C": "776 cm 2",
"D": "130 cm 2",
"E": "886 cm 2"
} | divide(multiply(26, 10), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 28 cm , 26 cm and 10 cm is right angled , where the hypotenuse is 28 cm . area of the triangle = 1 / 2 * 26 * 10 = 130 cm 2 answer : d" | geometry |
math_qa__5frRtreO1azDhT66 | A train is 510 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length? Choices: A) 76 seconds B) 18 seconds C) 52 seconds D) 19 seconds E) 45 seconds | <gadget id="calculator">510 + 140</gadget>
<output>650</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">650 / (25/2)</gadget>
<output>52</output>
<result>C</result> | C | 52 | A train is 510 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "76 seconds",
"B": "18 seconds",
"C": "52 seconds",
"D": "19 seconds",
"E": "45 seconds"
} | divide(add(510, 140), divide(multiply(45, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 45 km / hr = 45 * ( 5 / 18 ) m / sec = 25 / 2 m / sec total distance = 510 + 140 = 650 meter time = distance / speed = 650 * ( 2 / 25 ) = 52 seconds answer : c" | physics |
math_qa__dTcQ85V9jBvRnZ1G | How many ounces of a 60% salt solution must be added to 50 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt? Choose the most appropriate option: A) 16.67 B) 30 C) 50 D) 60.33 E) 70 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 50</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 50</gadget>
<output>10</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">(2/5) - (1/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 / (1/5)</gadget>
<output>50</output>
<result>C</result> | C | 50 | How many ounces of a 60% salt solution must be added to 50 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt? | {
"A": "16.67",
"B": "30",
"C": "50",
"D": "60.33",
"E": "70"
} | divide(subtract(multiply(divide(40, const_100), 50), multiply(divide(20, const_100), 50)), subtract(divide(40, const_100), divide(20, const_100))) | divide(n3,const_100)|divide(n2,const_100)|multiply(n1,#0)|multiply(n1,#1)|subtract(#0,#1)|subtract(#2,#3)|divide(#5,#4)| | "for 60 % salt solution ( x ) and 20 % salt solution ( y ) to give 40 % = ( 60 + 20 ) / 2 salt solution , we should mix equal amounts of x and y . answer : c ." | gain |
math_qa__ord7nc8WevHtb0qe | A certain taxi company charges $3.50 for the first 1/5 of a mile plus $0.40 for each additional 1/5 of a mile. What would this company charge for a taxi ride that was 8 miles long? Answers.
A) 15.6 B) 16.0 C) 17.5 D) 18.7 E) 19.1 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">8 / (1/5)</gadget>
<output>40</output>
<gadget id="calculator">40 - 1</gadget>
<output>39</output>
<gadget id="calculator">39 * 0.4</gadget>
<output>15.6</output>
<gadget id="calculator">3.5 + 15.6</gadget>
<output>19.1</output>
<result>E</result> | E | 19.1 | A certain taxi company charges $3.50 for the first 1/5 of a mile plus $0.40 for each additional 1/5 of a mile. What would this company charge for a taxi ride that was 8 miles long? | {
"A": "15.6",
"B": "16.0",
"C": "17.5",
"D": "18.7",
"E": "19.1"
} | add(3.50, multiply(subtract(divide(8, divide(1, 5)), 1), 0.40)) | divide(n1,n2)|divide(n6,#0)|subtract(#1,n1)|multiply(n3,#2)|add(n0,#3)| | "a certain taxi company charges $ 3.50 for the first 1 / 5 of a mile plus $ 0.40 for each additional 1 / 5 of a mile . what would this company charge for a taxi ride that was 8 miles long ? a . 15.60 b . 16.00 c . 17.50 d . 18.70 e . 19.10 1 / 5 miles = 0.2 miles . the cost of 8 miles long ride would be $ 3.50 for the first 0.2 miles plus ( 8 - 0.2 ) / 0.2 * 0.4 = $ 3.5 + $ 15.6 = $ 18.7 . answer : e ." | general |
math_qa__ZkQfG1K0IyTCBjUD | The ratio of Red Balls to Blue Balls is 3:7. 70% of the Red balls and 30% of the Blue balls are tennis balls. How many of the balls are tennis balls? Options:
A) 44 % B) 40 % C) 45 % D) 42 % E) 48 % | <gadget id="calculator">3 * 70</gadget>
<output>210</output>
<gadget id="calculator">7 * 30</gadget>
<output>210</output>
<gadget id="calculator">210 + 210</gadget>
<output>420</output>
<gadget id="calculator">3 + 7</gadget>
<output>10</output>
<gadget id="calculator">420 / 10</gadget>
<output>42</output>
<result>D</result> | D | 42 | The ratio of Red Balls to Blue Balls is 3:7. 70% of the Red balls and 30% of the Blue balls are tennis balls. How many of the balls are tennis balls? | {
"A": "44 %",
"B": "40 %",
"C": "45 %",
"D": "42 %",
"E": "48 %"
} | divide(add(multiply(3, 70), multiply(7, 30)), add(3, 7)) | add(n0,n1)|multiply(n0,n2)|multiply(n1,n3)|add(#1,#2)|divide(#3,#0) | let total no of balls 100 , red ball 30 and blue ball 70 , so tennis ball for red and blue ball respectively 30 * 70 / 100 = 21 and 70 * 30 / 100 = 21 so total 42 tennis balls out of 100 balls . . so required % is 42 % answer : d | other |
math_qa__otx4gL4CPkfWOHzX | How much time does a train 125 metres long running at 60 km/hr take to pass a pole? Select the correct option.
A) 7.9 s
B) 2.5 s
C) 7.5 s
D) 7.6 s
E) 7.4 s | <gadget id="calculator">125 / 1_000</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) / 60</gadget>
<output>1/480 = around 0.002083</output>
<gadget id="calculator">(1/480) * 3_600</gadget>
<output>15/2 = around 7.5</output>
<result>C</result> | C | 7.5 | How much time does a train 125 metres long running at 60 km/hr take to pass a pole? | {
"A": "7.9 s",
"B": "2.5 s",
"C": "7.5 s",
"D": "7.6 s",
"E": "7.4 s"
} | multiply(divide(divide(125, const_1000), 60), const_3600) | divide(n0,const_1000)|divide(#0,n1)|multiply(#1,const_3600)| | "explanation : 60 km / hr = 60 * 5 / 18 = 16.67 m / s speed = distance / time ; v = d / t 16.67 = 125 / t t = 7.5 s answer : c" | general |
math_qa__pxOkPndFMNCsbiP4 | If the number 517*324 is completely divisible by 7, then the smallest whole number in the place of * will be: Options:
A) 3 B) 1 C) 2 D) 4 E) 6 | <gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 * 10</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 % 7</gadget>
<output>5</output>
<gadget id="calculator">5 * 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">10_000 % 7</gadget>
<output>4</output>
<gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">10 + 28</gadget>
<output>38</output>
<gadget id="calculator">100 % 7</gadget>
<output>2</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">38 + 6</gadget>
<output>44</output>
<gadget id="calculator">10 % 7</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">44 + 6</gadget>
<output>50</output>
<gadget id="calculator">50 + 4</gadget>
<output>54</output>
<gadget id="calculator">1_000 % 7</gadget>
<output>6</output>
<gadget id="calculator">lcm(7, 6)</gadget>
<output>42</output>
<gadget id="calculator">54 / 42</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">(9/7) + 1</gadget>
<output>16/7 = around 2.285714</output>
<gadget id="calculator">floor(16/7)</gadget>
<output>2</output>
<gadget id="calculator">2 * 42</gadget>
<output>84</output>
<gadget id="calculator">84 - 54</gadget>
<output>30</output>
<gadget id="calculator">30 / 6</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>E</result> | E | 6 | If the number 517*324 is completely divisible by 7, then the smallest whole number in the place of * will be: | {
"A": "3",
"B": "1",
"C": "2",
"D": "4",
"E": "6"
} | add(divide(subtract(multiply(floor(add(divide(add(add(add(add(add(multiply(reminder(multiply(power(const_100, const_2), const_10), 7), const_1), multiply(reminder(multiply(power(const_100, const_2), const_10), 7), const_1)), multiply(reminder(power(const_100, const_2), 7), 7)), multiply(reminder(const_100, 7), const_3)), multiply(reminder(const_10, 7), const_2)), const_4), lcm(7, reminder(const_1000, 7))), const_1)), lcm(7, reminder(const_1000, 7))), add(add(add(add(add(multiply(reminder(multiply(power(const_100, const_2), const_10), 7), const_1), multiply(reminder(multiply(power(const_100, const_2), const_10), 7), const_1)), multiply(reminder(power(const_100, const_2), 7), 7)), multiply(reminder(const_100, 7), const_3)), multiply(reminder(const_10, 7), const_2)), const_4)), reminder(const_1000, 7)), const_1) | power(const_100,const_2)|reminder(const_100,n2)|reminder(const_10,n2)|reminder(const_1000,n2)|lcm(n2,#3)|multiply(#0,const_10)|multiply(#1,const_3)|multiply(#2,const_2)|reminder(#0,n2)|multiply(n2,#8)|reminder(#5,n2)|multiply(#10,const_1)|add(#11,#11)|add(#12,#9)|add(#13,#6)|add(#14,#7)|add(#15,const_4)|divide(#16,#4)|add(#17,const_1)|floor(#18)|multiply(#19,#4)|subtract(#20,#16)|divide(#21,#3)|add(#22,const_1) | sum of digits = ( 5 + 1 + 7 + x + 3 + 2 + 4 ) = ( 22 + x ) , which must be divisible by 7 . x = 6 . e | general |
math_qa__KgKFsgOtaOVcYjUp | What is the least number which when divided by 5, 6, 9 and 12 leaves remainder 4 in each care? Choose the correct choice from the following options
A) 130
B) 140
C) 156
D) 184
E) 196 | <gadget id="calculator">lcm(5, 6)</gadget>
<output>30</output>
<gadget id="calculator">lcm(9, 12)</gadget>
<output>36</output>
<gadget id="calculator">lcm(30, 36)</gadget>
<output>180</output>
<gadget id="calculator">180 + 4</gadget>
<output>184</output>
<result>D</result> | D | 184 | What is the least number which when divided by 5, 6, 9 and 12 leaves remainder 4 in each care? | {
"A": "130",
"B": "140",
"C": "156",
"D": "184",
"E": "196"
} | add(lcm(lcm(5, 6), lcm(9, 12)), 4) | lcm(n0,n1)|lcm(n2,n3)|lcm(#0,#1)|add(n4,#2) | explanation : lcm of 5 , 6 , 9 and 12 is 180 required number = 180 + 4 = 184 answer : option d | general |
math_qa__rpGn06YFe5U4Mtiu | Sakshi can do a piece of work in 25 days.Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work : Choose the correct choice from the following answers
A) 15 B) 20 C) 18 D) 25 E) 10 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">25 / (5/4)</gadget>
<output>20</output>
<result>B</result> | B | 20 | Sakshi can do a piece of work in 25 days.Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work : | {
"A": "15",
"B": "20",
"C": "18",
"D": "25",
"E": "10"
} | divide(25, add(const_1, divide(25, const_100))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)| | "solution ratio of times taken by sakshi and tanya = 125 : 100 = 5 : 4 . suppose tanya taken x days to do the work . 5 : 4 : : 25 : x ⇒ x = ( 25 x 4 / 5 ) ⇒ x = 20 days . hence , tanya takes 16 days is complete the work . answer b" | physics |
math_qa__gmH6qtdOo32Xuxpj | At what price must an article costing Rs.47.50 be marked in order that after deducting 8% from the list price. It may be sold at a profit of 25% on the cost price? Choose the correct choice from the following: A) 64.54 B) 62.6 C) 62.1 D) 62.7 E) 62.2 | <gadget id="calculator">47.5 * 25</gadget>
<output>1_187.5</output>
<gadget id="calculator">1_187.5 / 100</gadget>
<output>11.875</output>
<gadget id="calculator">47.5 + 11.875</gadget>
<output>59.375</output>
<gadget id="calculator">59.375 * 100</gadget>
<output>5_937.5</output>
<gadget id="calculator">100 - 8</gadget>
<output>92</output>
<gadget id="calculator">5_937.5 / 92</gadget>
<output>64.538043</output>
<result>A</result> | A | 64.54 | At what price must an article costing Rs.47.50 be marked in order that after deducting 8% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "64.54",
"B": "62.6",
"C": "62.1",
"D": "62.7",
"E": "62.2"
} | divide(multiply(add(47.50, divide(multiply(47.50, 25), const_100)), const_100), subtract(const_100, 8)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 47.50 sp = 47.50 * ( 125 / 100 ) = 59.375 mp * ( 92 / 100 ) = 59.375 mp = 64.54 answer : a" | gain |
math_qa__0kOCXOjaKcBIJzsh | in a bag , there are two 6 - sided dice ( numbered 1 to 6 ) , 3 12 - sided dice ( numbered 1 to 12 ) , and two 20 - sided dice ( numbered 1 to 20 ) . if 4 of these dice are selected at random from the bag , and then the 4 are rolled and we find the sum of numbers showing on the 4 dice , how many different possible totals are there for this sum ? Choose the correct answer
A) 60 B) 50 C) 42 D) 84 E) 61 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">40 + 24</gadget>
<output>64</output>
<result>E</result> | E | 61 | in a bag , there are two 6 - sided dice ( numbered 1 to 6 ) , 3 12 - sided dice ( numbered 1 to 12 ) , and two 20 - sided dice ( numbered 1 to 20 ) . if 4 of these dice are selected at random from the bag , and then the 4 are rolled and we find the sum of numbers showing on the 4 dice , how many different possible totals are there for this sum ? | {
"A": "60",
"B": "50",
"C": "42",
"D": "84",
"E": "61"
} | add(add(20, 20), add(12, 12)) | add(n7,n7)|add(n4,n4)|add(#0,#1) | as ' complex - looking ' as this question might appear , it ' s actually rather simple . pay careful attention to what the specific questions asks for - the number of different possible sums from 4 dice . since we ' re dealing with some ' special ' dice ( some 12 - sided and 20 - sided dice ) , we have to adjust out math accordingly , but the possibilities are rather limited : 1 ) the minimum number on any given die is 1 2 ) the maximum possible sum would only occur if we took the 4 biggest possible dice and rolled the highest possible number on each . with 4 dice , we could end up with any sum between : 4 ( if we rolled 1 s on all 4 dice ) to 64 ( if we rolled two 20 s on the 20 - sided dice and two 12 s on the 12 - sided dice ) . thus , there are only 61 possible sums . e | general |
math_qa__rZdaYKCfnSAXNA6y | A bus covers a distance of 12 km in 5 min. If it takes 5 sec to pass a telegraph post, then the length of the bus is? Pick.
A) 120 m
B) 180 m
C) 240 m
D) 200 m
E) 280 m | <gadget id="calculator">1_000 * 12</gadget>
<output>12_000</output>
<gadget id="calculator">60 * 5</gadget>
<output>300</output>
<gadget id="calculator">12_000 / 300</gadget>
<output>40</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<result>D</result> | D | 200 | A bus covers a distance of 12 km in 5 min. If it takes 5 sec to pass a telegraph post, then the length of the bus is? | {
"A": "120 m",
"B": "180 m",
"C": "240 m",
"D": "200 m",
"E": "280 m"
} | multiply(divide(multiply(const_1000, 12), multiply(const_60, 5)), 5) | multiply(n0,const_1000)|multiply(n1,const_60)|divide(#0,#1)|multiply(n1,#2) | speed = ( 12 / 5 * 60 ) km / hr = ( 144 * 5 / 18 ) m / sec = 40 m / sec . length of the bus = 40 * 5 = 200 m . answer : d | physics |
math_qa__1LEeSPc8RCg0sWgm | A number is doubled and 9 is added. If the resultant is trebled, it becomes 69. What is that number? Pick: A) 3.5 B) 6 C) 8 D) 7 E) 4 | <gadget id="calculator">3 * 9</gadget>
<output>27</output>
<gadget id="calculator">69 - 27</gadget>
<output>42</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">42 / 6</gadget>
<output>7</output>
<result>D</result> | D | 7 | A number is doubled and 9 is added. If the resultant is trebled, it becomes 69. What is that number? | {
"A": "3.5",
"B": "6",
"C": "8",
"D": "7",
"E": "4"
} | divide(subtract(69, multiply(const_3, 9)), multiply(const_3, const_2)) | multiply(n0,const_3)|multiply(const_2,const_3)|subtract(n1,#0)|divide(#2,#1)| | "let the number be x . then , 3 ( 2 x + 9 ) = 69 2 x = 14 = > x = 7 answer : d" | general |
math_qa__Pm92kYnfbvv9oJ49 | X can finish a work in 18 days. Y can finish the same work in 15 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work? Choose the correct choice from the following choices: A) 5 B) 4 C) 6 D) 7 E) 8 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">10 * (1/15)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/3) / (1/18)</gadget>
<output>6</output>
<result>C</result> | C | 6 | X can finish a work in 18 days. Y can finish the same work in 15 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work? | {
"A": "5",
"B": "4",
"C": "6",
"D": "7",
"E": "8"
} | divide(subtract(const_1, multiply(10, divide(const_1, 15))), divide(const_1, 18)) | divide(const_1,n1)|divide(const_1,n0)|multiply(n2,#0)|subtract(const_1,#2)|divide(#3,#1)| | "work done by x in 1 day = 1 / 18 work done by y in 1 day = 1 / 15 work done by y in 10 days = 10 / 15 = 2 / 3 remaining work = 1 – 2 / 3 = 1 / 3 number of days in which x can finish the remaining work = ( 1 / 3 ) / ( 1 / 18 ) = 6 c" | physics |
math_qa__XJXODgKtDhWg6X4Y | n^(n/2)=8 is true when n=8 in the same way what is the value of n if n^(n/2) =20? Choices.
A) 8 B) 14 C) 10 D) 20 E) 40 | <gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">400 / 20</gadget>
<output>20</output>
<result>D</result> | D | 20 | n^(n/2)=8 is true when n=8 in the same way what is the value of n if n^(n/2) =20? | {
"A": "8",
"B": "14",
"C": "10",
"D": "20",
"E": "40"
} | divide(power(20, 2), 20) | power(n4,n0)|divide(#0,n4) | n ^ ( n / 2 ) = 20 apply log n / 2 logn = log 20 nlogn = 2 log 20 = log 20 ^ 2 = log 400 logn = log 400 now apply antilog n = 400 / n now n = 20 . answer : d | general |
math_qa__9bGaieiNWMUGIaVM | Amar takes as much time in running 12 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
Select
A) 600 m B) 200 m C) 300 m D) 400 m E) 100 m | <gadget id="calculator">1.6 * 1_000</gadget>
<output>1_600</output>
<gadget id="calculator">12 * 1_600</gadget>
<output>19_200</output>
<gadget id="calculator">19_200 / 48</gadget>
<output>400</output>
<result>D</result> | D | 400 | Amar takes as much time in running 12 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km? | {
"A": "600 m",
"B": "200 m",
"C": "300 m",
"D": "400 m",
"E": "100 m"
} | divide(multiply(12, multiply(1.6, const_1000)), 48) | multiply(n2,const_1000)|multiply(n0,#0)|divide(#1,n1)| | "d 400 m distance covered by amar = 12 / 4.8 ( 1.6 km ) = 2.5 ( 1600 ) = 400 m answer is d" | physics |
math_qa__INH9ZeXaglh6yoHP | Find the Unit’s digit in the product (76^41) * (41^14) * (14^87) * (87^76) Choices:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">14 / 14</gadget>
<output>1</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<result>D</result> | D | 4 | Find the Unit’s digit in the product (76^41) * (41^14) * (14^87) * (87^76) | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | add(divide(14, 14), const_3) | divide(n3,n3)|add(#0,const_3) | units digit of 87 ^ 76 = 1 because 87 ^ 3 n + 1 has units place as 1 units digit of 14 ^ 87 = 4 because 14 ^ ( some odd no . ) has units place as 4 units digit of 41 ^ 14 = 1 because 41 ^ ( some even no . ) has units place as 1 units digit of 76 ^ 41 = 6 because 76 ^ ( any positive no . ) has units place as 6 so , units digit of the product is = ` ` 4 ` ` ( units digit of 1 * 4 * 1 * 6 ) answer : d | general |
math_qa__PbTsDqvUJPDPkiRf | a man ate 100 bananas in 5 days , each day eating 6 more than the previous day . how many bananas did he eat on the first day ? Choose the correct choice from the following choices: A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">40 - 24</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | a man ate 100 bananas in 5 days , each day eating 6 more than the previous day . how many bananas did he eat on the first day ? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(subtract(divide(multiply(100, const_2), 5), multiply(6, const_4)), const_2) | multiply(n0,const_2)|multiply(n2,const_4)|divide(#0,n1)|subtract(#2,#1)|divide(#3,const_2) | let the number of bannanas in first day be x for consecutive five days it will be like x , x + 6 , x + 12 , x + 18 , x + 24 the sum of those are 100 , 5 x + 60 = 100 so , x = 8 answer : c | physics |
math_qa__ykjPOtZNmQ2TxoqA | What is the least value of x. So that 1894x is divisible by 3? Options: A) 2 B) 5 C) 1 D) 6 E) 7 | <gadget id="calculator">1_894 * 10</gadget>
<output>18_940</output>
<gadget id="calculator">18_940 + 1</gadget>
<output>18_941</output>
<gadget id="calculator">18_941 + 1</gadget>
<output>18_942</output>
<gadget id="calculator">18_942 - 18_940</gadget>
<output>2</output>
<result>A</result> | A | 2 | What is the least value of x. So that 1894x is divisible by 3? | {
"A": "2",
"B": "5",
"C": "1",
"D": "6",
"E": "7"
} | subtract(add(add(multiply(1894, const_10), const_1), const_1), multiply(1894, const_10)) | multiply(n0,const_10)|add(#0,const_1)|add(#1,const_1)|subtract(#2,#0) | the sum of the digits of the number is divisible by 3 , then the number is divisible by 3 . 1 + 8 + 9 + 4 + x = 22 + x least value of x may be 2 therefore 22 + 2 = 24 is divisible by 3 . a | general |
math_qa__rnWJ6YPx81PtDsGO | If takes 25.5 minutes to download a file using Modem A. Modem B work at 17% of the speed of Modem A. How long does it take to download a file using a Modem B? Choose the correct choice from the following answers.
A) 130 minutes B) 140 minutes C) 150 minutes D) 160 minutes E) 170 minutes | <gadget id="calculator">25.5 * 100</gadget>
<output>2_550</output>
<gadget id="calculator">2_550 / 17</gadget>
<output>150</output>
<result>C</result> | C | 150 | If takes 25.5 minutes to download a file using Modem A. Modem B work at 17% of the speed of Modem A. How long does it take to download a file using a Modem B? | {
"A": "130 minutes",
"B": "140 minutes",
"C": "150 minutes",
"D": "160 minutes",
"E": "170 minutes"
} | divide(multiply(25.5, const_100), 17) | multiply(n0,const_100)|divide(#0,n1) | let speed of modem a be k so speed of modem b is 17 / 100 * k time taken by modem a = 25.5 minutes let time taken by modem b = x k * 25.5 = 17 / 100 * k * x 0.17 * x = 25.5 x = 25.5 / 0.17 = 150 minutes answer : c | physics |
math_qa__7eGioHkEdq9ztGEG | The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:9. If P invested the money for 5 months, find for how much time did Q invest the money? Choose the correct choice from the following.
A) 9 B) 17 C) 13 D) 10 E) 12 | <gadget id="calculator">7 / 5</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">9 / 7</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">(7/5) * (9/7)</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 5</gadget>
<output>9</output>
<result>A</result> | A | 9 | The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:9. If P invested the money for 5 months, find for how much time did Q invest the money? | {
"A": "9",
"B": "17",
"C": "13",
"D": "10",
"E": "12"
} | multiply(multiply(divide(7, 5), divide(9, 7)), 5) | divide(n0,n1)|divide(n3,n2)|multiply(#0,#1)|multiply(n4,#2)| | "7 * 5 : 5 * x = 7 : 9 x = 9 answer : a" | gain |
math_qa__74kVgdbe1f6bChdT | On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent W of thatbeforeJuly 1 last year? Choose the correct choice from the following: A) 90 % B) 99 % C) 100 % D) 101 % E) 110 % | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<result>B</result> | B | 99 | On July 1 of last year, total employees at company E was decreased by 10 percent. Without any change in the salaries of the remaining employees, the average (arithmetic mean) employee salary was 10 percent more after the decrease in the number of employees than before the decrease. The total of the combined salaries of all the employees at Company E after July 1 last year was what percent W of thatbeforeJuly 1 last year? | {
"A": "90 %",
"B": "99 %",
"C": "100 %",
"D": "101 %",
"E": "110 %"
} | multiply(10, 10) | multiply(n1,n1)| | "the total number of employees = n the average salary = x total salary to all emplyoees = xn after the total number of employees = n - 0.1 n = 0.9 n the average salary = x + 10 % of x = 1.1 x total salary to all emplyoees = 0.9 n ( 1.1 x ) total salary after as a % of total salary before w = [ 0.9 n ( 1.1 x ) ] / xn = 0.99 or 99 % = b" | general |
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