id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5
values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6
values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__4Q4F8HGM1aqshWfV | The length of a rectangle is 18 cm and its breadth is 10 cm. When the length is increased to 25 cm, what will be the breadth of the rectangle if the area remains the same ?
Choose the correct choice from the following choices.
A) 7 cm B) 7.1 cm C) 7.2 cm D) 7.3 cm E) none of these | <gadget id="calculator">18 * 10</gadget>
<output>180</output>
<gadget id="calculator">180 / 25</gadget>
<output>36/5 = around 7.2</output>
<result>C</result> | C | 7.2 | The length of a rectangle is 18 cm and its breadth is 10 cm. When the length is increased to 25 cm, what will be the breadth of the rectangle if the area remains the same ? | {
"A": "7 cm",
"B": "7.1 cm",
"C": "7.2 cm",
"D": "7.3 cm",
"E": "none of these"
} | divide(multiply(18, 10), 25) | multiply(n0,n1)|divide(#0,n2) | solution let the breadth be b . then , ⇒ 25 b = 18 × 10 ⇒ b = ( 18 x 10 / 25 ) cm = 7.2 cm answer c | geometry |
math_qa__CWd9jsSttBucK3Rn | A whale goes on a feeding frenzy that lasts for 9 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 540 kilos ... | <gadget id="calculator">540 / 9</gadget>
<output>60</output>
<gadget id="calculator">60 + 3</gadget>
<output>63</output>
<result>E</result> | E | 63 | A whale goes on a feeding frenzy that lasts for 9 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 540 kilos ... | {
"A": "38",
"B": "47",
"C": "50",
"D": "53",
"E": "63"
} | add(divide(540, 9), 3) | divide(n2,n0)|add(n1,#0)| | "if you list the amount eaten each hour , you ' ll get an equally spaced list , increasing by 3 each hour . in any equally spaced list , the median equals the mean . here , the mean is 540 / 9 = 60 , so the median is also 60 , and that is the amount eaten in the 5 th hour . we need to add 3 to find the total eaten in t... | general |
math_qa__TyO4pv6jqunrvD1f | Walking at 70% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance? Choose one:
A) 30 B) 36 C) 42 D) 48 E) 56 | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 / (7/10)</gadget>
<output>10/7 = around 1.428571</output>
<gadget id="calculator">(10/7) - 1</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">24 / (3/7)</gadget>
<output>56</output>
<result>... | E | 56 | Walking at 70% of his usual speed a man takes 24 minutes more to cover a distance. What is his usual time to cover this distance? | {
"A": "30",
"B": "36",
"C": "42",
"D": "48",
"E": "56"
} | divide(24, subtract(divide(const_1, divide(70, const_100)), const_1)) | divide(n0,const_100)|divide(const_1,#0)|subtract(#1,const_1)|divide(n1,#2)| | "speed is inversly proprtional to time walking at 70 % of speed meand 7 / 10 s takes 10 / 7 t . it takes 24 minutes extra to cover the distance . then 10 / 7 t = t + 24 10 t = 7 t + 168 3 t = 168 t = 56 . option e is correct" | physics |
math_qa__N1IxSSy0IuLmd3Mk | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 40% profit? Pick:
A) 220 B) 230 C) 960 D) 780 E) 896 | <gadget id="calculator">832 - 448</gadget>
<output>384</output>
<gadget id="calculator">384 / 2</gadget>
<output>192</output>
<gadget id="calculator">832 - 192</gadget>
<output>640</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output... | E | 896 | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 40% profit? | {
"A": "220",
"B": "230",
"C": "960",
"D": "780",
"E": "896"
} | multiply(subtract(832, divide(subtract(832, 448), const_2)), add(const_1, divide(40, const_100))) | divide(n2,const_100)|subtract(n0,n1)|add(#0,const_1)|divide(#1,const_2)|subtract(n0,#3)|multiply(#2,#4)| | "c . p . = rs . x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 140 % of rs . 640 = 140 / 100 * 640 = rs . 896 . e" | gain |
math_qa__ceIqEPqV9G68vk3O | Two employees X and Y are paid a total of Rs. 880 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? Select:
A) s . 150
B) s . 200
C) s . 250
D) s . 350
E) s . 400 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">880 * 10</gadget>
<output>8_800</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="c... | E | 400 | Two employees X and Y are paid a total of Rs. 880 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "s . 150",
"B": "s . 200",
"C": "s . 250",
"D": "s . 350",
"E": "s . 400"
} | divide(multiply(880, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 880 but x = 120 % of y = 120 y / 100 = 12 y / 10 â ˆ ´ 12 y / 10 + y = 880 â ‡ ’ y [ 12 / 10 + 1 ] = 880 â ‡ ’ 22 y / 10 = 880 â ‡ ’ 22 y = 8800 â ‡ ’ y = 8800 / 22 = 800 / 2 = rs . 400 e )" | general |
math_qa__pixyj9M1lvmxv5rb | A certain store sold pens for $0.35 each and pencils for $0.25 each. If a customer purchased both pens and pencils from the store for a total of $3.50, what total number of pens and pencils did the customer purchase?
Pick one: A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">0.35 + 0.25</gadget>
<output>0.6</output>
<gadget id="calculator">3.5 / 0.6</gadget>
<output>5.833333</output>
<gadget id="calculator">5.833333 * 2</gadget>
<output>11.666666</output>
<result>E</result> | E | 12 | A certain store sold pens for $0.35 each and pencils for $0.25 each. If a customer purchased both pens and pencils from the store for a total of $3.50, what total number of pens and pencils did the customer purchase? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | multiply(divide(3.50, add(0.35, 0.25)), const_2) | add(n0,n1)|divide(n2,#0)|multiply(#1,const_2)| | "answer : algebraically , the question looks like this : 2.5 = 0.35 x + 0.25 y there are six possible numbers of pens that fit that requirement : 1 pen : $ 0.35 2 pens : $ 0.70 3 pens : $ 1.05 4 pens : $ 1.40 5 pens : $ 1.75 balance can fetch 7 pencils for $ 0.25 each . that ' s 5 pens and 7 pencils for a total of 12 p... | other |
math_qa__942cy4sWUPGoiBJ4 | Dan’s car gets 32 miles per gallon. If gas costs $4/gallon, then how many miles can Dan’s car go on $42 of gas? Choose the correct choice from the following answers:
A) 196 B) 284 C) 336 D) 412 E) 572 | <gadget id="calculator">42 * 32</gadget>
<output>1_344</output>
<gadget id="calculator">1_344 / 4</gadget>
<output>336</output>
<result>C</result> | C | 336 | Dan’s car gets 32 miles per gallon. If gas costs $4/gallon, then how many miles can Dan’s car go on $42 of gas? | {
"A": "196",
"B": "284",
"C": "336",
"D": "412",
"E": "572"
} | divide(multiply(42, 32), 4) | multiply(n0,n2)|divide(#0,n1)| | "42 / 4 = 10.5 gallons 10.5 * 32 = 336 miles the answer is c ." | physics |
math_qa__V19OQA8aX6Li7SX3 | Aarti can do a piece of work in 8 days. In how many days will she complete three time of work of same type? Choose the correct choice from the following answers.
A) 6 days B) 19 days C) 24 days D) 3 days E) 13 days | <gadget id="calculator">3 * 8</gadget>
<output>24</output>
<result>C</result> | C | 24 | Aarti can do a piece of work in 8 days. In how many days will she complete three time of work of same type? | {
"A": "6 days",
"B": "19 days",
"C": "24 days",
"D": "3 days",
"E": "13 days"
} | multiply(const_3, 8) | multiply(n0,const_3)| | "we have the important relation , more work , more time ( days ) a piece of work can be done in 8 days . three times of work of same type can be done in 8 x 3 = 24 days answer c" | physics |
math_qa__PYsdn9Mij7pd5ZaB | In a box of 11 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? Choose the correct choice from the following.
A) 1 / 25 B) 28 / 55 C) 2 / 35 D) 2 / 55 E) 1 / 75 | <gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">9 - 3</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</outp... | B | 0.509091 | In a box of 11 pencils, a total of 2 are defective. If a customer buys 3 pencils selected at random from the box, what is the probability that neither pencils will be defective? | {
"A": "1 / 25",
"B": "28 / 55",
"C": "2 / 35",
"D": "2 / 55",
"E": "1 / 75"
} | divide(divide(factorial(subtract(11, 2)), multiply(factorial(subtract(subtract(11, 2), 3)), factorial(3))), divide(factorial(11), multiply(factorial(subtract(11, 3)), factorial(3)))) | factorial(n2)|factorial(n0)|subtract(n0,n1)|subtract(n0,n2)|factorial(#2)|factorial(#3)|subtract(#2,n2)|factorial(#6)|multiply(#5,#0)|divide(#1,#8)|multiply(#7,#0)|divide(#4,#10)|divide(#11,#9)| | "first , there are 9 c 3 ways you can select 3 good pencils from 4 good ones . second , there are 11 c 3 ways you select 3 pencils from 6 ones in the box . then , the probability that neither pen will be defective is : 9 c 3 / 11 c 3 = 84 / 165 = 28 / 55 answer is b" | general |
math_qa__fIVyqryaTA67DdOU | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8300. If his salary for the month of May is Rs.6500, find his salary for the month of January? Answers
A) 2177 B) 2876 C) 4500 D) 5300 E) 6711 | <gadget id="calculator">8_000 * 4</gadget>
<output>32_000</output>
<gadget id="calculator">8_300 * 4</gadget>
<output>33_200</output>
<gadget id="calculator">33_200 - 6_500</gadget>
<output>26_700</output>
<gadget id="calculator">32_000 - 26_700</gadget>
<output>5_300</output>
<result>D</result> | D | 5,300 | The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8300. If his salary for the month of May is Rs.6500, find his salary for the month of January? | {
"A": "2177",
"B": "2876",
"C": "4500",
"D": "5300",
"E": "6711"
} | subtract(multiply(8000, const_4), subtract(multiply(8300, const_4), 6500)) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#1,n2)|subtract(#0,#2) | sum of the salaries of the person for the months of january , february , march and april = 4 * 8000 = 32000 - - - - ( 1 ) sum of the salaries of the person for the months of february , march , april and may = 4 * 8300 = 33200 - - - - ( 2 ) ( 2 ) - ( 1 ) i . e . may - jan = 1200 salary of may is rs . 6500 salary of janu... | general |
math_qa__GdZEAUt3rrR7PrMw | By investing Rs. 1800 in 9% stock, Syam earns Rs. 120. find out the stock is then quoted at which rate? Choose the correct choice from the following answers
A) 130
B) 135
C) 140
D) 150
E) 145 | <gadget id="calculator">1_800 / 120</gadget>
<output>15</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">15 * (9/100)</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">(27/20) * 100</gadget>
<output>135</output>
<result>B</result> | B | 135 | By investing Rs. 1800 in 9% stock, Syam earns Rs. 120. find out the stock is then quoted at which rate? | {
"A": "130",
"B": "135",
"C": "140",
"D": "150",
"E": "145"
} | multiply(multiply(divide(1800, 120), divide(9, const_100)), const_100) | divide(n0,n2)|divide(n1,const_100)|multiply(#0,#1)|multiply(#2,const_100)| | "assume that face value = rs . 100 . dividend per share = rs . 9 ( as it is a 9 % stock ) by investing rs . 1800 , he earns rs . 120 investment needed to earn rs . 9 = 1800 × 9 / 120 = rs . 135 ie , stock is then quoted ( then market value ) = rs . 135 answer is b ." | gain |
math_qa__Yy9KdsKcQoFPLO6q | 65% of x = 20% of 552.50. Find the value of x? Answers: A) 100 B) 170 C) 150 D) 180 E) 199 | <gadget id="calculator">552.5 / 100</gadget>
<output>5.525</output>
<gadget id="calculator">5.525 * 20</gadget>
<output>110.5</output>
<gadget id="calculator">110.5 * 100</gadget>
<output>11_050</output>
<gadget id="calculator">11_050 / 65</gadget>
<output>170</output>
<result>B</result> | B | 170 | 65% of x = 20% of 552.50. Find the value of x? | {
"A": "100",
"B": "170",
"C": "150",
"D": "180",
"E": "199"
} | divide(multiply(multiply(divide(552.50, const_100), 20), const_100), 65) | divide(n2,const_100)|multiply(n1,#0)|multiply(#1,const_100)|divide(#2,n0)| | "65 % of x = 20 % of 552.50 then , 65 / 100 * x = 20 / 100 * 5525 / 10 x = 170 answer is b" | general |
math_qa__RSBeUgKoLgvFifhO | Find the value of y from (12)^3 x 6^3 ÷ 432 = y? Choose the correct answer: A) 2134 B) 2234 C) 2540 D) 2560 E) 864 | <gadget id="calculator">12 ** 3</gadget>
<output>1_728</output>
<gadget id="calculator">6 ** 3</gadget>
<output>216</output>
<gadget id="calculator">1_728 * 216</gadget>
<output>373_248</output>
<gadget id="calculator">373_248 / 432</gadget>
<output>864</output>
<result>E</result> | E | 864 | Find the value of y from (12)^3 x 6^3 ÷ 432 = y? | {
"A": "2134",
"B": "2234",
"C": "2540",
"D": "2560",
"E": "864"
} | divide(multiply(power(12, 3), power(6, 3)), 432) | power(n0,n1)|power(n2,n3)|multiply(#0,#1)|divide(#2,n4)| | "5184 e" | general |
math_qa__rhtNG8hLDQSbucPp | The total price of a basic computer and printer are $2,500. If the same printer had been purchased with an enhanced computer whose price was $500 more than the price of the basic computer, then the price of the printer would have been 1/6 of that total. What was the price of the basic computer?
Choose the correct answe... | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 1_000</gadget>
<output>250</output>
<gadget id="calculator">250 * 10</gadget>
<output>2_500</output>
<gadget id="calculator">500 + 2_500</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 6</gadget... | E | 2,000 | The total price of a basic computer and printer are $2,500. If the same printer had been purchased with an enhanced computer whose price was $500 more than the price of the basic computer, then the price of the printer would have been 1/6 of that total. What was the price of the basic computer? | {
"A": "1500",
"B": "1600",
"C": "1750",
"D": "1900",
"E": "2000"
} | subtract(multiply(multiply(const_0_25, const_1000), const_10), divide(add(500, multiply(multiply(const_0_25, const_1000), const_10)), 6)) | multiply(const_0_25,const_1000)|multiply(#0,const_10)|add(n1,#1)|divide(#2,n3)|subtract(#1,#3) | let the price of basic computer be c and the price of the printer be p : c + p = $ 2,500 . the price of the enhanced computer will be c + 500 and total price for that computer and the printer will be 2,500 + 500 = $ 3,000 . now , we are told that the price of the printer is 1 / 6 of that new total price : p = 1 / 6 * $... | general |
math_qa__3yIAy4aaOT9LbZVk | Last week John spent 30 percent of his wages on recreation. This week, his wages are 25 percent less than last weekʼs wages and he spent 20 percent of his wages on recreation. The amount he spends on recreation this week is what percent of the amount he spent on recreation last week? Choose one.
A) 60 %
B) 70 %
C) 80 ... | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<gadget id="calculator">(1/5) * 75</... | E | 50 | Last week John spent 30 percent of his wages on recreation. This week, his wages are 25 percent less than last weekʼs wages and he spent 20 percent of his wages on recreation. The amount he spends on recreation this week is what percent of the amount he spent on recreation last week? | {
"A": "60 %",
"B": "70 %",
"C": "80 %",
"D": "90 %",
"E": "50 %"
} | multiply(divide(multiply(divide(20, const_100), multiply(divide(subtract(const_100, 25), const_100), const_100)), multiply(divide(30, const_100), const_100)), const_100) | divide(n2,const_100)|divide(n0,const_100)|subtract(const_100,n1)|divide(#2,const_100)|multiply(#1,const_100)|multiply(#3,const_100)|multiply(#0,#5)|divide(#6,#4)|multiply(#7,const_100) | say john ' s wages last week were $ 100 , so he spent 0.30 * 100 = $ 30 on recreation ; this week ' s wages is 0.75 * 100 = $ 75 , so he spends 0.2 * 75 = $ 15 on recreation ; 15 / 30 = 0.50 , hence the amount he spends on recreation this week is 50 % of the amount he spent on recreation last week : 30 * 0.5 = 15 answe... | general |
math_qa__xqpYihHtor9I0wnw | In 2000 there were 10000 women stockbrokers in the United States. By 2005 the number had increased to 20000. Approximately what was the percent increase? Choose the correct choice:
A) 1 %
B) 2 %
C) 1.5 %
D) 3 %
E) 4 % | <gadget id="calculator">20_000 - 10_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 10_000</gadget>
<output>1</output>
<result>A</result> | A | 1 | In 2000 there were 10000 women stockbrokers in the United States. By 2005 the number had increased to 20000. Approximately what was the percent increase? | {
"A": "1 %",
"B": "2 %",
"C": "1.5 %",
"D": "3 %",
"E": "4 %"
} | divide(subtract(20000, 10000), 10000) | subtract(n3,n1)|divide(#0,n1) | the percent increase is ( 20000 - 10000 ) / 10000 = 10000 / 10000 = 1 % so the approximate answer is a | general |
math_qa__kGSWE9yAsq9SnZlY | If ‘+’ means ‘×’, ‘-‘ means ‘+’, ‘×’ means ‘÷’ and ‘÷’ means ‘-‘ then find the value of;
6 – 9 + 8 × 3 ÷ 25 = Choose the correct choice:
A) 6 B) 10 C) 12 D) 5 E) 8 | <gadget id="calculator">9 * 8</gadget>
<output>72</output>
<gadget id="calculator">72 / 3</gadget>
<output>24</output>
<gadget id="calculator">24 + 6</gadget>
<output>30</output>
<gadget id="calculator">30 - 25</gadget>
<output>5</output>
<result>D</result> | D | 5 | If ‘+’ means ‘×’, ‘-‘ means ‘+’, ‘×’ means ‘÷’ and ‘÷’ means ‘-‘ then find the value of;
6 – 9 + 8 × 3 ÷ 25 = | {
"A": "6",
"B": "10",
"C": "12",
"D": "5",
"E": "8"
} | subtract(add(divide(multiply(9, 8), 3), 6), 25) | multiply(n1,n2)|divide(#0,n3)|add(n0,#1)|subtract(#2,n4) | d 5 | general |
math_qa__pT53679lg0Jl9a7A | A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is : Choose the correct answer.
A) 9 : 5
B) 2 : 3
C) 4 : 7
D) 5 : 6
E) none of these | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 5</gadget>
<output>9/5 = around 1.8</output>
<result>A</result> | A | 1.8 | A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is : | {
"A": "9 : 5",
"B": "2 : 3",
"C": "4 : 7",
"D": "5 : 6",
"E": "none of these"
} | divide(multiply(3, 3), 5) | multiply(n0,n2)|divide(#0,n1)| | "explanation : dog : hare = ( 3 * 3 ) leaps of hare : 5 leaps of hare = 9 : 5 . answer : a" | other |
math_qa__mp6SblKWK9HqEUMN | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 10 men in 3 days? Choose the correct answer.
A) 65 mtr . B) 28 mtr C) 70 mtr . D) 78 mtr . E) 17 mtr . | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">30 / 120</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">112 * (1/4)</gadget>
<output>28</output>
<result>B</result> | B | 28 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 10 men in 3 days? | {
"A": "65 mtr .",
"B": "28 mtr",
"C": "70 mtr .",
"D": "78 mtr .",
"E": "17 mtr ."
} | multiply(112, divide(multiply(10, 3), multiply(20, 6))) | multiply(n3,n4)|multiply(n0,n2)|divide(#0,#1)|multiply(n1,#2)| | "20 men is 6 days can build 112 metres 10 men in 3 days can build = 112 * ( 10 / 20 ) x ( 3 / 6 ) = 28 meters answer : b ." | physics |
math_qa__NiEk63gaaIhLriiB | A alone can finish a work in 10 days which B alone can finish in 15 days. If they work together and finish it, then out of a total wages of Rs.3200, A will get: Choose the correct choice from the following.
A) rs . 1200
B) rs . 1500
C) rs . 1920
D) rs . 2000
E) none of these | <gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<gadget id="calculator">30 / 15</gadget>
<output>2</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gad... | C | 1,920 | A alone can finish a work in 10 days which B alone can finish in 15 days. If they work together and finish it, then out of a total wages of Rs.3200, A will get: | {
"A": "rs . 1200",
"B": "rs . 1500",
"C": "rs . 1920",
"D": "rs . 2000",
"E": "none of these"
} | multiply(divide(divide(multiply(15, const_2), 10), add(divide(multiply(15, const_2), 10), divide(multiply(15, const_2), 15))), 3200) | multiply(n1,const_2)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)|divide(#1,#3)|multiply(n2,#4)| | "explanation : ratio of working days of a : b = 10 : 15 therefore , their wages ratio = reverse ratio = 15 : 10 therefore , a will get 15 units of ratio total ratio = 25 1 unit of ratio = 3000 / 25 = 128 so , a ’ s amount = 120 × 15 = rs . 1920 . answer : option c" | physics |
math_qa__3OApYYxK40ngJn00 | Triathlete Dan runs along a 3-mile stretch of river and then swims back along the same route. If Dan runs at a rate of 10 miles per hour and swims at a rate of 6 miles per hour, what is his average rate for the entire trip in miles per minute? Choose the correct choice from the following choices:
A) 1 / 8 B) 2 / 15 C... | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 60</gadget>
<... | A | 0.125 | Triathlete Dan runs along a 3-mile stretch of river and then swims back along the same route. If Dan runs at a rate of 10 miles per hour and swims at a rate of 6 miles per hour, what is his average rate for the entire trip in miles per minute? | {
"A": "1 / 8",
"B": "2 / 15",
"C": "3 / 15",
"D": "1 / 4",
"E": "3 / 8"
} | divide(add(3, 3), add(multiply(divide(3, 6), const_60), multiply(divide(3, 10), const_60))) | add(n0,n0)|divide(n0,n2)|divide(n0,n1)|multiply(#1,const_60)|multiply(#2,const_60)|add(#3,#4)|divide(#0,#5)| | "dan travels 6 miles round trip . running part : ( 3 / 10 * 60 = 18 minutes ) swimming part : ( 3 / 6 * 60 = 30 minutes ) 6 miles in ( 18 + 30 ) minutes 6 / 48 = 1 / 8 mile per minute answer : 1 / 8 mile per minute a" | physics |
math_qa__StVotcJQjxKPrmWG | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 140 mph. On the way home, I flew 88 mph. What was my average speed for the trip? Choose the most appropriate option.
A) 114 mph
B) 110 mph
C) 88 mph
D) 100 mph
E) 99 mph | <gadget id="calculator">140 + 88</gadget>
<output>228</output>
<gadget id="calculator">228 / 2</gadget>
<output>114</output>
<result>A</result> | A | 114 | I flew my tiny seaplane to visit my mother. On the flight up, I flew at 140 mph. On the way home, I flew 88 mph. What was my average speed for the trip? | {
"A": "114 mph",
"B": "110 mph",
"C": "88 mph",
"D": "100 mph",
"E": "99 mph"
} | divide(add(140, 88), const_2) | add(n0,n1)|divide(#0,const_2)| | "( 140 mph + 88 mph ) / 2 = 114 mph correct answer is : a" | physics |
math_qa__cprNim393DqRerGY | A $84.95 lawn chair was sold for $59.95 at a special sale. By approximately what percent was the price decreased? Choose the correct choice from the following choices: A) 15 % B) 20 % C) 25 % D) 29 % E) 80 % | <gadget id="calculator">84.95 - 59.95</gadget>
<output>25</output>
<gadget id="calculator">25 / 84.95</gadget>
<output>0.294291</output>
<gadget id="calculator">0.294291 * 100</gadget>
<output>29.4291</output>
<result>D</result> | D | 29 | A $84.95 lawn chair was sold for $59.95 at a special sale. By approximately what percent was the price decreased? | {
"A": "15 %",
"B": "20 %",
"C": "25 %",
"D": "29 %",
"E": "80 %"
} | multiply(divide(subtract(84.95, 59.95), 84.95), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "listed selling price of chair = 84.95 $ discounted selling price of chair = 59.95 $ discount = 84.95 - 59.95 = 25 $ % decrease in price of chair = ( 25 / 84.95 ) * 100 % = 29 % approx answer d" | general |
math_qa__WUBZebsx34j25tk7 | A grocer has a sale of Rs. 5700, Rs. 8550, Rs. 6855, Rs. 3850 for 4 consecutive months. How much sale must he have in the fifth month so that he gets an average sale of Rs. 7800? Choose the correct choice.
A) s . 14991 B) s . 49930 C) s . 14045 D) s . 14999 E) s . 14578 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">7_800 * 5</gadget>
<output>39_000</output>
<gadget id="calculator">5_700 + 8_550</gadget>
<output>14_250</output>
<gadget id="calculator">14_250 + 6_855</gadget>
<output>21_105</output>
<gadget id="calculator">3_850 + 21_105</gadget>
... | C | 14,045 | A grocer has a sale of Rs. 5700, Rs. 8550, Rs. 6855, Rs. 3850 for 4 consecutive months. How much sale must he have in the fifth month so that he gets an average sale of Rs. 7800? | {
"A": "s . 14991",
"B": "s . 49930",
"C": "s . 14045",
"D": "s . 14999",
"E": "s . 14578"
} | subtract(multiply(7800, add(4, const_1)), add(3850, add(add(5700, 8550), 6855))) | add(n4,const_1)|add(n0,n1)|add(n2,#1)|multiply(n5,#0)|add(n3,#2)|subtract(#3,#4) | total sale for 4 months = rs . ( 5700 + 8550 + 6855 + 3850 ) = rs . 24955 required sale = rs . [ ( 7800 x 5 ) - 24955 ] = rs . ( 39000 - 24955 ) = rs . 14045 option c | general |
math_qa__9rFZGYEY99tQ8ozy | The cash difference between the selling prices of an book at a profit of 4% and 8% is $3. The ratio of the two selling prices is: Pick one
A) 55 : 23 B) 26 : 27 C) 52 : 53 D) 45 : 53 E) 51 : 34 | <gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">104 / 108</gadget>
<output>26/27 = around 0.962963</output>
<result>B</result> | B | 0.962963 | The cash difference between the selling prices of an book at a profit of 4% and 8% is $3. The ratio of the two selling prices is: | {
"A": "55 : 23",
"B": "26 : 27",
"C": "52 : 53",
"D": "45 : 53",
"E": "51 : 34"
} | divide(add(const_100, 4), add(const_100, 8)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "let c . p . of the book be $ x . then , required ratio = 104 % of x / 108 % of x = 104 / 108 = 26 / 27 = 26 : 27 b" | gain |
math_qa__90qji3ToBvCbc9OX | The ratio of ducks and frogs in a pond is 35 : 39 respectively. The average number of ducks and frogs in the pond is 152. What is the number of frogs in the pond ? Choose the correct choice from the following: A) 160 B) 152 C) 156 D) 144 E) none | <gadget id="calculator">35 + 39</gadget>
<output>74</output>
<gadget id="calculator">74 + 2</gadget>
<output>76</output>
<gadget id="calculator">76 / 2</gadget>
<output>38</output>
<gadget id="calculator">152 / 38</gadget>
<output>4</output>
<gadget id="calculator">39 * 4</gadget>
<output>156</output>
<result>A</r... | A | 160 | The ratio of ducks and frogs in a pond is 35 : 39 respectively. The average number of ducks and frogs in the pond is 152. What is the number of frogs in the pond ? | {
"A": "160",
"B": "152",
"C": "156",
"D": "144",
"E": "none"
} | multiply(39, divide(152, divide(add(add(35, 39), const_2), const_2))) | add(n0,n1)|add(#0,const_2)|divide(#1,const_2)|divide(n2,#2)|multiply(n1,#3) | solution : ratio of ducks and frogs in pond , = 35 : 39 . average of ducks and frogs in pond , = 152 . so , total number of ducks and frogs in the pond , = 2 * 152 = 304 . therefore , number of frogs , = ( 304 * 39 ) / 74 = 160 . answer : option a | general |
math_qa__z9SweFdxgxz1Bohj | Suraj has a certain average of runs for 14 innings. In the 15th innings he scores 140 runs thereby increasing his average by 8 runs. What is his average after the 15th innings? Choose the correct choice from the following choices:
A) 48 B) 28 C) 36 D) 72 E) 27 | <gadget id="calculator">14 * 8</gadget>
<output>112</output>
<gadget id="calculator">140 - 112</gadget>
<output>28</output>
<gadget id="calculator">15 - 14</gadget>
<output>1</output>
<gadget id="calculator">28 / 1</gadget>
<output>28</output>
<result>B</result> | B | 28 | Suraj has a certain average of runs for 14 innings. In the 15th innings he scores 140 runs thereby increasing his average by 8 runs. What is his average after the 15th innings? | {
"A": "48",
"B": "28",
"C": "36",
"D": "72",
"E": "27"
} | divide(subtract(140, multiply(14, 8)), subtract(15, 14)) | multiply(n0,n3)|subtract(n1,n0)|subtract(n2,#0)|divide(#2,#1)| | "to improve his average by 8 runs per innings he has to contribute 14 x 8 = 112 runs for the previous 14 innings . thus , the average after the 15 th innings = 140 - 112 = 28 . answer : b" | general |
math_qa__jaGqrqzrYEbtCkO6 | A cistern is fille in 8 hours and it takes 12 hours when there is a leak in its bottom. If the cistern is full, in what time shall the leak empty it? Choose the correct choice.
A) 22 hours B) 21 hours C) 24 hours D) 23 hours E) 25 days | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/8) - (1/12)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>C... | C | 24 | A cistern is fille in 8 hours and it takes 12 hours when there is a leak in its bottom. If the cistern is full, in what time shall the leak empty it? | {
"A": "22 hours",
"B": "21 hours",
"C": "24 hours",
"D": "23 hours",
"E": "25 days"
} | inverse(subtract(inverse(8), inverse(12))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2) | explanation : work done by 1 hour by filling pipe = 1 / 8 work done by 1 hour by the leak and the filling pipe = 1 / 12 work done by 1 hour by the leak = 1 / 8 – 1 / 12 = 1 / 24 hence the leak can empty it in 24 hours . answer : option c | physics |
math_qa__SCJvRi58Yi5UUgSx | If 12 men do a work in 80 days, in how many days will 16 men do it?
Pick one:
A) 22 B) 87 C) 77 D) 60 E) 85 | <gadget id="calculator">12 * 80</gadget>
<output>960</output>
<gadget id="calculator">960 / 16</gadget>
<output>60</output>
<result>D</result> | D | 60 | If 12 men do a work in 80 days, in how many days will 16 men do it? | {
"A": "22",
"B": "87",
"C": "77",
"D": "60",
"E": "85"
} | divide(multiply(12, 80), 16) | multiply(n0,n1)|divide(#0,n2) | 12 * 80 = 16 * x x = 60 days answer : d | physics |
math_qa__tp6rEgW1zOVvTlXp | How many points (x, y) lie on the line segment between (22, 12 2/3) and (16, 17 2/3) such that x and y are both integers? Choose the correct choice from the following.
A) 1
B) 5
C) 7
D) 8
E) 9 | <gadget id="calculator">16 / 16</gadget>
<output>1</output>
<result>A</result> | A | 1 | How many points (x, y) lie on the line segment between (22, 12 2/3) and (16, 17 2/3) such that x and y are both integers? | {
"A": "1",
"B": "5",
"C": "7",
"D": "8",
"E": "9"
} | divide(16, 16) | divide(n4,n4)| | "slope = ( 17 2 / 3 - 12 2 / 3 ) / ( 16 - 22 ) = - 5 / 6 y = mx + b = > 12 2 / 3 = - 22 * 5 / 6 + b = > b = 31 y = - 5 x / 6 + 31 only integer values work , and the only multiples of 6 between 16 and 22 for x values is 18 , thus 1 point . a" | general |
math_qa__11LyTVCyoRyoWjRx | A certain class of students is being divided into teams. The class can either be divided into 15 teams with an equal number of players on each team or 24 teams with an equal number of players on each team. What is the lowest possible number of students in the class? Answers: A) 6 B) 36 C) 48 D) 60 E) 120 | <gadget id="calculator">lcm(15, 24)</gadget>
<output>120</output>
<result>E</result> | E | 120 | A certain class of students is being divided into teams. The class can either be divided into 15 teams with an equal number of players on each team or 24 teams with an equal number of players on each team. What is the lowest possible number of students in the class? | {
"A": "6",
"B": "36",
"C": "48",
"D": "60",
"E": "120"
} | lcm(15, 24) | lcm(n0,n1)| | "let total no of students in the class be n so , we are told that n is divisible by both 15 24 so , lets find the least common multiple of 15 24 , ie 120 so our answer is ( e ) 120" | general |
math_qa__lioQLIVSNVUtr5MC | A department store perceived a run on a lower priced garment and raised the price by 20% to keep stock available until another shipment arrived. Customers fumed and the department store manager allowed them to purchase the garments at 80% of the new price to save face. What was the difference in the new retail price an... | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(4/5) * (6/5)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calc... | A | 4 | A department store perceived a run on a lower priced garment and raised the price by 20% to keep stock available until another shipment arrived. Customers fumed and the department store manager allowed them to purchase the garments at 80% of the new price to save face. What was the difference in the new retail price an... | {
"A": "4.0 %",
"B": "5.0 %",
"C": "6.0 %",
"D": "7.0 %",
"E": "8.0 %"
} | multiply(subtract(const_1, multiply(divide(80, const_100), divide(add(const_100, 20), const_100))), const_100) | add(n0,const_100)|divide(n1,const_100)|divide(#0,const_100)|multiply(#1,#2)|subtract(const_1,#3)|multiply(#4,const_100) | quantity x rate = price 1 x 1 = 1 0.8 x 1.20 = 0.960 decrease in price = ( 0.040 / 1 ) ã — 100 = 4.0 % answer = option a | general |
math_qa__ROtsjTY0qKCN1JXN | The price of a mobile was increased by 40 percent. The new price was then decreased by 15 percent. A single increase of what percent is equivalent to these two successive changes? Choose the correct option:
A) 25 % B) 19 % C) 30 % D) 22.5 % E) 15 % | <gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">140 / 100</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(7/5) * (17... | B | 19 | The price of a mobile was increased by 40 percent. The new price was then decreased by 15 percent. A single increase of what percent is equivalent to these two successive changes? | {
"A": "25 %",
"B": "19 %",
"C": "30 %",
"D": "22.5 %",
"E": "15 %"
} | multiply(subtract(multiply(divide(add(const_100, 40), const_100), divide(subtract(const_100, 15), const_100)), const_1), const_100) | add(n0,const_100)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100) | consider base price - $ 100 25 % increase = 1.40 * 100 = $ 140 then a 15 % decrease on new price = 0.85 * 140 = $ 119 so final price of radio - $ 119 therefore a 19 % increase correct option - b | general |
math_qa__LCKNljMdJizoDzhO | A, B and C completed a piece of work, A worked for 16 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1480? Choices:
A) rs . 80 B) rs . 120 C) rs . 71.15 D) rs . 51.15 E) rs . 180 | <gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">9 * 4</gadget>
<output>36</output>
<gadget id="calculator">48 + 36</gadget>
<output>84</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">84 + 20</gadget>
<output>104</output>
<gadget id="ca... | C | 71.15 | A, B and C completed a piece of work, A worked for 16 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1480? | {
"A": "rs . 80",
"B": "rs . 120",
"C": "rs . 71.15",
"D": "rs . 51.15",
"E": "rs . 180"
} | multiply(5, divide(1480, add(add(multiply(16, 3), multiply(9, 4)), multiply(4, 5)))) | multiply(n0,n3)|multiply(n1,n2)|multiply(n2,n5)|add(#0,#1)|add(#3,#2)|divide(n6,#4)|multiply(n5,#5)| | "3 x 4 x 5 x 16 9 4 48 x + 36 x + 20 x = 1480 104 x = 1480 = > x = 14.23 5 x = 71.15 rs . answer : c" | physics |
math_qa__0pPisbuXEJciG32j | The closest approximation of W(69.28 × 0.004)/0.03 is Choose the correct choice from the following options:
A) 0.092
B) 0.92
C) 9.2
D) 92
E) 920 | <gadget id="calculator">0.004 / 0.03</gadget>
<output>0.133333</output>
<gadget id="calculator">0.133333 * 69.28</gadget>
<output>9.23731</output>
<result>C</result> | C | 9.2 | The closest approximation of W(69.28 × 0.004)/0.03 is | {
"A": "0.092",
"B": "0.92",
"C": "9.2",
"D": "92",
"E": "920"
} | multiply(divide(0.004, 0.03), 69.28) | divide(n1,n2)|multiply(n0,#0)| | "w ( 69.28 × 0.004 ) / 0.03 1 . 0.004 = 4 × 10 ^ ( - 3 ) 2 . 0.03 = 3 × 10 ^ ( - 2 ) 3 . ( a × b ) / c = a × ( b / c ) 4 . 0.004 / 0.03 = 4 × 10 ^ ( - 3 ) / ( 3 × 10 ^ ( - 2 ) ) = 4 × 10 ^ ( - 3 - ( - 2 ) ) / 3 = 4 × 10 ^ ( - 1 ) / 3 = ( 4 / 3 ) × 10 ^ ( - 1 ) = 1.333 × 10 ^ ( - 1 ) therefore , ( 69.28 × 0.004 ) / 0.03... | general |
math_qa__Tesd1OPceh4sLY9Z | The least number by which 72 must be multiplied in order to produce a multiple of 112, is: Choose the correct choice from the following.
A) 6 B) 12 C) 14 D) 18 E) 20 | <gadget id="calculator">gcd(72, 112)</gadget>
<output>8</output>
<gadget id="calculator">112 / 8</gadget>
<output>14</output>
<result>C</result> | C | 14 | The least number by which 72 must be multiplied in order to produce a multiple of 112, is: | {
"A": "6",
"B": "12",
"C": "14",
"D": "18",
"E": "20"
} | divide(112, gcd(72, 112)) | gcd(n0,n1)|divide(n1,#0) | required number is divisible by 72 as well as by 112 , if it is divisible by their lcm , which is 1008 . now , 1008 when divided by 72 , gives quotient = 14 . therefore , required number = 14 . answer : c | general |
math_qa__RaIBEhfJGos8gA1T | If there are 200 questions in a 3 hr examination. Among these questions are 50 type A problems, which requires twice as much as time be spent than the rest of the type B problems. How many minutes should be spent on type A problems?
Choose the correct answer
A) 72 min B) 62 min C) 70 min D) 74 min E) 76 min | <gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">200 - 50</gadget>
<output>150</output>
<gadget id="calculator">2 * 50</gadget>
<output>100</output>
<gadget id="calculator">150 + 100</gadget>
<output>250</output>
<gadget id="calculator">180 / 250</gadget>
<output>18/25 = around 0... | A | 72 | If there are 200 questions in a 3 hr examination. Among these questions are 50 type A problems, which requires twice as much as time be spent than the rest of the type B problems. How many minutes should be spent on type A problems? | {
"A": "72 min",
"B": "62 min",
"C": "70 min",
"D": "74 min",
"E": "76 min"
} | multiply(multiply(const_2, divide(multiply(3, const_60), add(subtract(200, 50), multiply(const_2, 50)))), 50) | multiply(n1,const_60)|multiply(n2,const_2)|subtract(n0,n2)|add(#1,#2)|divide(#0,#3)|multiply(#4,const_2)|multiply(n2,#5)| | "x = time for type b prolems 2 x = time for type a problem total time = 3 hrs = 180 min 150 x + 50 * 2 x = 180 x = 180 / 250 x = 0.72 time taken for type a problem = 50 * 2 * 0.72 = 72 min answer : a" | general |
math_qa__0B5MnACnGPAcB0DC | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 100. How much did he have with him in the beginning? Choose the correct choice from the following options
A) rs 200
B) rs 250
C) rs 300
D) rs 450
E) rs 550 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 5</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/3) - (2/15)</gadget>
<output>8/15 = around 0.53... | B | 250 | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 100. How much did he have with him in the beginning? | {
"A": "rs 200",
"B": "rs 250",
"C": "rs 300",
"D": "rs 450",
"E": "rs 550"
} | divide(100, subtract(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), divide(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), 4))) | divide(n0,n1)|subtract(n0,#0)|divide(#1,n3)|subtract(#1,#2)|divide(#3,n5)|subtract(#3,#4)|divide(n6,#5)| | "suppose the amount in the beginning was rs ’ x ’ money spent on clothes = rs 1 x / 3 balance = rs 2 x / 3 money spent on food = 1 / 5 of 2 x / 3 = rs 2 x / 15 balance = 2 x / 3 - 2 x / 15 = rs 8 x / 15 money spent on travel = 1 / 4 of 8 x / 15 = rs 2 x / 15 = 8 x / 15 - 2 x / 15 = 6 x / 15 = rs 2 x / 5 therefore 2 x /... | general |
math_qa__oQAh8MF4eO3KHCyJ | Find the area, diameter = 12m.
Choices
A) 113.00 square meter B) 113.04 square meter C) 113.08 square meter D) 113.24 square meter E) 113.43 square meter | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">pi * (6 ** 2)</gadget>
<output>36*pi = around 113.097336</output>
<result>B</result> | B | 113.04 | Find the area, diameter = 12m. | {
"A": "113.00 square meter",
"B": "113.04 square meter",
"C": "113.08 square meter",
"D": "113.24 square meter",
"E": "113.43 square meter"
} | circle_area(divide(12, const_2)) | divide(n0,const_2)|circle_area(#0)| | "diameter = 12 meter . radius = diameter / 2 . = 12 / 2 . = 6 meter . area of a circle = π r 2 . here , pi ( π ) = 3.14 meter , radius ( r ) = 6 . area of a circle = 3.14 × 6 × 6 . . = 3.14 × 36 . = 113.04 square meter or 113.04 m 2 . answer : b" | physics |
math_qa__773bnEVrzzVwbdw8 | Sam taken a loan Rs.15000/- from Co-operative Society with an interest @ 11.5% per month. At the same time he deposited Rs. 10000/- as Fixed Deposit with an interest @ 9.5% per month. After one week sam asked the manager to calculate the interest to be paid. What is the interest amount for 7 days? Choose the correct ch... | <gadget id="calculator">11.5 / 100</gadget>
<output>0.115</output>
<gadget id="calculator">15_000 * 0.115</gadget>
<output>1_725</output>
<gadget id="calculator">9.5 / 100</gadget>
<output>0.095</output>
<gadget id="calculator">10_000 * 0.095</gadget>
<output>950</output>
<gadget id="calculator">1_725 - 950</gadget... | E | 181 | Sam taken a loan Rs.15000/- from Co-operative Society with an interest @ 11.5% per month. At the same time he deposited Rs. 10000/- as Fixed Deposit with an interest @ 9.5% per month. After one week sam asked the manager to calculate the interest to be paid. What is the interest amount for 7 days? | {
"A": "165",
"B": "220",
"C": "310",
"D": "185",
"E": "181"
} | multiply(7, divide(subtract(multiply(15000, divide(11.5, const_100)), multiply(10000, divide(9.5, const_100))), multiply(const_10, const_3))) | divide(n1,const_100)|divide(n3,const_100)|multiply(const_10,const_3)|multiply(n0,#0)|multiply(n2,#1)|subtract(#3,#4)|divide(#5,#2)|multiply(n4,#6) | loan amount : rs . 15000 / - @ 11.5 % interest per month = 15000 / - * 11.5 % = rs . 1725 interest for one day = 1725 / 30 = 57.50 interest for 7 days is = 57.50 * 7 = 403 fd amount is = rs . 10000 / - @ 9.5 % interest per month = 10000 * 9.5 % = 950 / - interest for 7 days = 950 / 30 * 7 = 222 interest amount to be pa... | general |
math_qa__VoDShvNHgC8lgWOn | On a two-dimensional coordinate plane, the line d = x^2 - x^3 touches the x-axis in how many places? Choose the correct choice from the following answers
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">max(3, 2)</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<result>C</result> | C | 2 | On a two-dimensional coordinate plane, the line d = x^2 - x^3 touches the x-axis in how many places? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(max(3, 2), const_1) | max(n0,n1)|subtract(#0,const_1)| | "apparently it ' s d = x ^ 2 - x ^ 3 instead of d = x ^ 2 - d ^ 3 . in this case : the x - intercept is the value ( s ) of x for d = 0 . 0 = x ^ 2 - x ^ 3 ; 0 = x ^ 2 ( 1 - x ) ; x = 0 or x = 1 . answer : c ." | general |
math_qa__oeJG5TOAni73TiPx | How many even integers from 1 to 100 (both inclusive) have EVEN number of factors? Choose the correct option: A) 13 B) 14 C) 5 D) 6 E) 7 | <gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>C</result> | C | 5 | How many even integers from 1 to 100 (both inclusive) have EVEN number of factors? | {
"A": "13",
"B": "14",
"C": "5",
"D": "6",
"E": "7"
} | divide(sqrt(100), const_2) | sqrt(n1)|divide(#0,const_2) | integers having even number of factors will be perfect squares . even numbers will have even perfect squares . thus , the possible values for the perfect squares are : 4 , 16,36 , 64,100 and the corresponding integers are 2 , 4,6 , 8,10 ( more than 4 ) . thus c is the correct answer . | other |
math_qa__QgIwiLDqPpwodbGU | The ratio of the number of females to males at a party was 1:2 but when 4 females and 4 males left, the ratio became 1:3. How many people were at the party originally?
Choose the correct choice from the following answers.
A) 20 B) 22 C) 24 D) 26 E) 28 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 - 8</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 16</gadget>
<output>24</output>
<result>C</result> | C | 24 | The ratio of the number of females to males at a party was 1:2 but when 4 females and 4 males left, the ratio became 1:3. How many people were at the party originally? | {
"A": "20",
"B": "22",
"C": "24",
"D": "26",
"E": "28"
} | add(divide(subtract(multiply(multiply(4, 2), 3), multiply(4, 2)), 2), subtract(multiply(multiply(4, 2), 3), multiply(4, 2))) | multiply(n1,n2)|multiply(n5,#0)|subtract(#1,#0)|divide(#2,n1)|add(#3,#2)| | "the total number of people are x females + 2 x males . 3 * ( x - 4 ) = 2 x - 4 x = 8 there were 3 x = 24 people at the party originally . the answer is c ." | other |
math_qa__NhFu8dKtaiCRtUxz | When the price of an article is reduced by 30%, the sales increases by 50%. The percentage change in the total amount of receipts is? Choose the correct choice from the following answers: A) 5 % decrease B) 5 % increase C) 10 % decrease D) 15 % decrease E) none of these | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">70 * 150</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 / 100</gadget>
<output>105</output>
<gadget id="calculator">105 - 100</gadget>
<output>5</outp... | B | 5 | When the price of an article is reduced by 30%, the sales increases by 50%. The percentage change in the total amount of receipts is? | {
"A": "5 % decrease",
"B": "5 % increase",
"C": "10 % decrease",
"D": "15 % decrease",
"E": "none of these"
} | subtract(divide(multiply(subtract(const_100, 30), add(const_100, 50)), const_100), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(#3,const_100) | we have , receipts = price x sales therefore , net % change in receipts = ( x + y + xy / 100 ) % = [ - 30 + 50 + ( - 30 x 50 ) / 100 ] % = 5 % increase . answer : b | general |
math_qa__GiPZu180utKIwzQp | Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.60 a kg to produce a mixture worth Rs. 6.30 a kg Pick.
A) 2 : 0 B) 2 : 3 C) 2 : 1 D) 2 : 2 E) 7 : 9 | <gadget id="calculator">6.3 - 5.6</gadget>
<output>0.7</output>
<gadget id="calculator">7.2 - 6.3</gadget>
<output>0.9</output>
<gadget id="calculator">0.7 / 0.9</gadget>
<output>0.777778</output>
<result>E</result> | E | 0.777778 | Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.60 a kg to produce a mixture worth Rs. 6.30 a kg | {
"A": "2 : 0",
"B": "2 : 3",
"C": "2 : 1",
"D": "2 : 2",
"E": "7 : 9"
} | divide(subtract(6.30, 5.60), subtract(7.20, 6.30)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "by the rule of alligation : cost of 1 kg rice of 1 st kind cost of 1 kg rice of 2 nd kind required ratio = 70 : 90 = 7 : 9 answer : e" | other |
math_qa__36askfRlnsJnQaOY | At a special sale, 5 tickets can be purchased for the price of 3 tickets. If 5 tickets are purchased at the sale, the amount saved will be What percent of the original price of the 5 tickets? Choose the correct option:
A) 20 % B) 33.3 % C) 40 % D) 60 % E) 66.6 % | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">25 - 15</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 25</gadget>
<output>40</output>
<result... | C | 40 | At a special sale, 5 tickets can be purchased for the price of 3 tickets. If 5 tickets are purchased at the sale, the amount saved will be What percent of the original price of the 5 tickets? | {
"A": "20 %",
"B": "33.3 %",
"C": "40 %",
"D": "60 %",
"E": "66.6 %"
} | divide(multiply(subtract(multiply(5, 5), multiply(3, 5)), const_100), multiply(5, 5)) | multiply(n0,n0)|multiply(n0,n1)|subtract(#0,#1)|multiply(#2,const_100)|divide(#3,#0)| | "let the price of a ticket be rs . 100 , so 3 tickets cost 300 & 5 tickets cost 500 5 tickets purchased at price of 3 tickets ie . , for 300 , so amount saved s rs . 200 , % of 5 tickets = ( 200 / 500 ) * 100 = 40 % answer : c" | gain |
math_qa__52GrTOHldah1Z0Jt | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 20000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is Pick one:
A) 20
B) 49
C) 22
D) 23
E) none | <gadget id="calculator">20_000 - 8_000</gadget>
<output>12_000</output>
<gadget id="calculator">7 * 12_000</gadget>
<output>84_000</output>
<gadget id="calculator">8_000 - 6_000</gadget>
<output>2_000</output>
<gadget id="calculator">84_000 / 2_000</gadget>
<output>42</output>
<gadget id="calculator">7 + 42</gadget... | B | 49 | The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 20000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is | {
"A": "20",
"B": "49",
"C": "22",
"D": "23",
"E": "none"
} | add(7, divide(multiply(7, subtract(20000, 8000)), subtract(8000, 6000))) | subtract(n2,n0)|subtract(n0,n3)|multiply(n1,#0)|divide(#2,#1)|add(n1,#3)| | "sol . let the total number of workers be x . then , 8000 x = ( 20000 × 7 ) + 6000 ( x – 7 ) ‹ = › 2000 x = 98000 ‹ = › x = 49 . answer b" | general |
math_qa__pR8mcQbWjrmce7XT | At what price must an article costing Rs.47.50 be marked in order that after deducting 6% from the list price. It may be sold at a profit of 25% on the cost price?
Choose the correct choice from the following:
A) 63.16 B) 62.6 C) 62.1 D) 62.7 E) 62.2 | <gadget id="calculator">47.5 * 25</gadget>
<output>1_187.5</output>
<gadget id="calculator">1_187.5 / 100</gadget>
<output>11.875</output>
<gadget id="calculator">47.5 + 11.875</gadget>
<output>59.375</output>
<gadget id="calculator">59.375 * 100</gadget>
<output>5_937.5</output>
<gadget id="calculator">100 - 6</ga... | A | 63.16 | At what price must an article costing Rs.47.50 be marked in order that after deducting 6% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "63.16",
"B": "62.6",
"C": "62.1",
"D": "62.7",
"E": "62.2"
} | divide(multiply(add(47.50, divide(multiply(47.50, 25), const_100)), const_100), subtract(const_100, 6)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 47.50 sp = 47.50 * ( 125 / 100 ) = 59.375 mp * ( 94 / 100 ) = 59.375 mp = 63.16 answer : a" | gain |
math_qa__z6VBCHfqbjHPbB2I | If a mixture is 3⁄5 alcohol by volume and 4⁄5 water by volume, what is the ratio of the volume of alcohol to the volume of water in this mixture?
Choose the correct choice from the following options:
A) 1 / 3 B) 3 / 2 C) 3 / 4 D) 3 E) 3 / 5 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(3/5) / (4/5)</gadget>
<output>3/4 = around 0.75</output>
<result>C</result> | C | 0.75 | If a mixture is 3⁄5 alcohol by volume and 4⁄5 water by volume, what is the ratio of the volume of alcohol to the volume of water in this mixture? | {
"A": "1 / 3",
"B": "3 / 2",
"C": "3 / 4",
"D": "3",
"E": "3 / 5"
} | divide(divide(3, 5), divide(4, 5)) | divide(n0,n1)|divide(n2,n1)|divide(#0,#1)| | "should be a sub - 600 level q . . volume = { 3 / 5 } / { 4 / 5 } = 3 / 4 c" | general |
math_qa__cWdN7JNvkPWSXEqb | The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum. Options:
A) 33498 B) 17000 C) 2665 D) 28876 E) 313 | <gadget id="calculator">100 * 10_200</gadget>
<output>1_020_000</output>
<gadget id="calculator">11_730 - 10_200</gadget>
<output>1_530</output>
<gadget id="calculator">1_530 * 100</gadget>
<output>153_000</output>
<gadget id="calculator">10_200 / 2</gadget>
<output>5_100</output>
<gadget id="calculator">153_000 / ... | B | 17,000 | The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum. | {
"A": "33498",
"B": "17000",
"C": "2665",
"D": "28876",
"E": "313"
} | divide(multiply(const_100, 10200), multiply(divide(multiply(subtract(11730, 10200), const_100), divide(10200, const_2)), const_2)) | divide(n1,const_2)|multiply(n1,const_100)|subtract(n0,n1)|multiply(#2,const_100)|divide(#3,#0)|multiply(#4,const_2)|divide(#1,#5)| | "the simple interest for the first year is 10200 / 2 is rs . 5100 and compound interest for first year also is rs . 5100 . the compound interest for second year on rs . 5100 for one year so rate of the interest = ( 100 * 1530 ) / ( 5100 * 1 ) = 30 % p . a . so p = ( 100 * 10200 ) / ( 30 * 2 ) = rs . 17000 answer : b" | gain |
math_qa__KSUZAZEkUnTpCMWg | The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $300 per sq. metre.
Choose the correct option
A) $ 2587.50
B) $ 3587.50
C) $ 4187.50
D) $ 6187.50
E) $ 8587.50 | <gadget id="calculator">5.5 * 3.75</gadget>
<output>20.625</output>
<gadget id="calculator">300 * 20.625</gadget>
<output>6_187.5</output>
<result>D</result> | D | 6,187.5 | The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of $300 per sq. metre. | {
"A": "$ 2587.50",
"B": "$ 3587.50",
"C": "$ 4187.50",
"D": "$ 6187.50",
"E": "$ 8587.50"
} | multiply(300, multiply(5.5, 3.75)) | multiply(n0,n1)|multiply(n2,#0)| | "area = 5.5 × 3.75 sq . metre . cost for 1 sq . metre . = $ 300 hence , total cost = 5.5 × 3.75 × 300 = $ 6187.50 d" | physics |
math_qa__auNVjx6OSMLev3uP | Of the 150 people at a party, 70 were women, and 30 women tried the appetizer. If 60 people did not try the appetizer, what is the total number of men who tried the appetizer? Choose the correct choice: A) 40 B) 50 C) 60 D) 70 E) 80 | <gadget id="calculator">150 - 60</gadget>
<output>90</output>
<gadget id="calculator">90 - 30</gadget>
<output>60</output>
<result>C</result> | C | 60 | Of the 150 people at a party, 70 were women, and 30 women tried the appetizer. If 60 people did not try the appetizer, what is the total number of men who tried the appetizer? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
} | subtract(subtract(150, 60), 30) | subtract(n0,n3)|subtract(#0,n2)| | "total people at party = 150 women = 70 so men 150 - 70 = 80 no . of pple who tried appetizer = 150 - 60 ( given info ) = 90 no of women who tried appetizer = 30 so remaining ppl ( men ) who tried the appetizer = 90 - 30 = 60 correct option c" | general |
math_qa__V4Ll8Dg7dFYDcatG | A man swims downstream 28 km and upstream 12 km taking 2 hours each time, what is the speed of the man in still water? Choose the correct answer
A) 10 B) 8 C) 5 D) 2 E) 4 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<gadget id="calculator">6 + 14</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>A</result> | A | 10 | A man swims downstream 28 km and upstream 12 km taking 2 hours each time, what is the speed of the man in still water? | {
"A": "10",
"B": "8",
"C": "5",
"D": "2",
"E": "4"
} | divide(add(divide(12, 2), divide(28, 2)), const_2) | divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)| | "28 - - - 2 ds = 14 ? - - - - 1 12 - - - - 2 us = 6 ? - - - - 1 m = ? m = ( 14 + 6 ) / 2 = 10 answer : a" | physics |
math_qa__kNxNip6BySMx8RFB | In a restaurant, the profit is 130% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit? Select the correct option:
A) 30 % B) 51 % C) 90 % D) 100 % E) none of these | <gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">100 * (13/10)</gadget>
<output>130</output>
<gadget id="calculator">130 + 100</gadget>
<output>230</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 +... | B | 51 | In a restaurant, the profit is 130% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit? | {
"A": "30 %",
"B": "51 %",
"C": "90 %",
"D": "100 %",
"E": "none of these"
} | multiply(const_100, divide(subtract(add(multiply(const_100, divide(130, const_100)), const_100), multiply(const_100, add(const_1, divide(12, const_100)))), add(multiply(const_100, divide(130, const_100)), const_100))) | divide(n0,const_100)|divide(n1,const_100)|add(#1,const_1)|multiply(#0,const_100)|add(#3,const_100)|multiply(#2,const_100)|subtract(#4,#5)|divide(#6,#4)|multiply(#7,const_100)| | "explanation : let c . p . = rs . 100 . then , profit = rs . 130 , s . p . = rs . 230 . new c . p . = 112 % of rs . 100 = rs . 112 new s . p . = rs . 230 . profit = rs . ( 230 - 112 ) = rs . 118 . required percentage = ( 118 / 230 * 100 ) % = 51 % appox answer : b" | gain |
math_qa__VXznUvwEW3bYedLj | A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 72. If the marks secured by Reema was written as 36 instead of 66 then find the correct average marks up to two decimal places. Choose one.
A) 72.85 B) 74.31 C) 72.43 D) 73.43 E) can not be determined | <gadget id="calculator">35 * 72</gadget>
<output>2_520</output>
<gadget id="calculator">66 - 36</gadget>
<output>30</output>
<gadget id="calculator">2_520 - 30</gadget>
<output>2_490</output>
<gadget id="calculator">2_490 / 35</gadget>
<output>498/7 = around 71.142857</output>
<result>A</result> | A | 72.85 | A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 72. If the marks secured by Reema was written as 36 instead of 66 then find the correct average marks up to two decimal places. | {
"A": "72.85",
"B": "74.31",
"C": "72.43",
"D": "73.43",
"E": "can not be determined"
} | divide(subtract(multiply(35, 72), subtract(66, 36)), 35) | multiply(n0,n2)|subtract(n4,n3)|subtract(#0,#1)|divide(#2,n0) | total marks = 35 x 72 = 2520 corrected total marks = 2520 - 36 + 66 = 2550 correct average = 2550 / 35 = 72.85 answer : a | general |
math_qa__0GDM7EfmGkwdJ2C6 | A bag contains 6 green balls and 7 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour? Answers
A) 2 / 7 B) 3 / 10 C) 5 / 11 D) 6 / 13 E) 11 / 21 | <gadget id="calculator">6 + 7</gadget>
<output>13</output>
<gadget id="calculator">7 / 13</gadget>
<output>7/13 = around 0.538462</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">13 - 1</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = aroun... | D | 0.461538 | A bag contains 6 green balls and 7 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour? | {
"A": "2 / 7",
"B": "3 / 10",
"C": "5 / 11",
"D": "6 / 13",
"E": "11 / 21"
} | add(multiply(divide(7, add(6, 7)), divide(subtract(7, const_1), subtract(add(6, 7), const_1))), multiply(divide(subtract(6, const_1), subtract(add(6, 7), const_1)), divide(6, add(6, 7)))) | add(n0,n1)|subtract(n1,const_1)|subtract(n0,const_1)|divide(n1,#0)|divide(n0,#0)|subtract(#0,const_1)|divide(#1,#5)|divide(#2,#5)|multiply(#3,#6)|multiply(#7,#4)|add(#8,#9)| | "the total number of ways to draw two balls is 13 c 2 = 78 the number of ways to draw two green balls is 6 c 2 = 15 the number of ways to draw two white balls is 7 c 2 = 21 p ( two balls of the same colour ) = 36 / 78 = 6 / 13 the answer is d ." | other |
math_qa__OdN5h9sYzD3eLU48 | In the biology lab of "Jefferson" High School there are 0.036*10^5 germs, equally divided among 75000*10^(-3) Petri dishes. How many germs live happily in a single dish? Pick
A) 10
B) 20
C) 30
D) 40
E) 48 | <gadget id="calculator">1_000 * 100</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 * 0.036</gadget>
<output>3_600</output>
<gadget id="calculator">75_000 / 1_000</gadget>
<output>75</output>
<gadget id="calculator">3_600 / 75</gadget>
<output>48</output>
<result>E</result> | E | 48 | In the biology lab of "Jefferson" High School there are 0.036*10^5 germs, equally divided among 75000*10^(-3) Petri dishes. How many germs live happily in a single dish? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "48"
} | divide(multiply(multiply(const_1000, const_100), 0.036), divide(75000, const_1000)) | divide(n3,const_1000)|multiply(const_100,const_1000)|multiply(n0,#1)|divide(#2,#0)| | "0.036 * 10 ^ 5 can be written as 3600 75000 * 10 ^ ( - 3 ) can be written as 75 required = 3600 / 75 = 48 answer : e" | general |
math_qa__33hh1ZakG9bz4qJZ | Set X consists of the integers from 1 to 12, inclusive, while set Y consists of the integers from 0 to 20, inclusive. How many distinct integers do belong to the both sets at the same time? Choose the correct choice from the following answers
A) 12 B) 15 C) 10 D) 20 E) 8 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 + 1</gadget>
<output>12</output>
<result>A</result> | A | 12 | Set X consists of the integers from 1 to 12, inclusive, while set Y consists of the integers from 0 to 20, inclusive. How many distinct integers do belong to the both sets at the same time? | {
"A": "12",
"B": "15",
"C": "10",
"D": "20",
"E": "8"
} | add(subtract(12, 1), const_1) | subtract(n1,n0)|add(#0,const_1) | x = { 1,2 , 3,4 , 5,6 , 7 , 8 , 9 , 10 , 11 , 12 } y = { 0 , 1,2 , 3,4 , 5,6 , 7 , 8 , 9 , 10 , 11,12 , 13,14 , 15,16 , 17,18 , 19,20 } common elements = { 1,2 , 3,4 , 5,6 , 7,8 , 9,10 , 11,12 } = 12 elements answer : option a . | other |
math_qa__HBT7x76AlmGK68pw | A train 160 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform? Choose the correct choice from the following choices
A) 443 m
B) 354 m
C) 340 m
D) 350 m
E) 250 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">25 * 20</gadget>
<output>500</output>
<gadget id="calculator">500 - 160</gadget>
<output>340</output>
<result>C</result> | C | 340 | A train 160 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform? | {
"A": "443 m",
"B": "354 m",
"C": "340 m",
"D": "350 m",
"E": "250 m"
} | subtract(multiply(25, multiply(72, const_0_2778)), 160) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)| | "c 340 c = ( 72 * 5 / 18 ) * 25 - 160 = 340" | physics |
math_qa__S8nDJogioTB0aZow | A cube of edge 5 cm is cut into cubes each of edge 1 cm. The ratio of the total surface area of one of the small cubes to that of the large cube is equal to:
Choose the correct choice from the following options
A) 1 : 25 B) 1.225 C) 1 : 52 D) 1 : 522 E) none | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<result>A</result> | A | 0.04 | A cube of edge 5 cm is cut into cubes each of edge 1 cm. The ratio of the total surface area of one of the small cubes to that of the large cube is equal to: | {
"A": "1 : 25",
"B": "1.225",
"C": "1 : 52",
"D": "1 : 522",
"E": "none"
} | divide(const_4, const_100) | divide(const_4,const_100) | sol . required ratio = 6 * 1 * 1 / 6 * 5 * 5 = 1 / 25 = 1 : 25 . answer a | geometry |
math_qa__YU7An46ky6oapEGA | The difference b/w the compound interest payble half yearly and the simple interest on a certain sum lent out at 10% p.a for 1 year is Rs 25. What is the sum? Choose one:
A) rs . 15000 B) rs . 12000 C) rs . 10000 D) rs . 20000 E) none of these | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="... | C | 10,000 | The difference b/w the compound interest payble half yearly and the simple interest on a certain sum lent out at 10% p.a for 1 year is Rs 25. What is the sum? | {
"A": "rs . 15000",
"B": "rs . 12000",
"C": "rs . 10000",
"D": "rs . 20000",
"E": "none of these"
} | divide(25, subtract(subtract(power(add(divide(divide(const_10, const_2), const_100), 1), const_2), const_1), divide(10, const_100))) | divide(const_10,const_2)|divide(n0,const_100)|divide(#0,const_100)|add(n1,#2)|power(#3,const_2)|subtract(#4,const_1)|subtract(#5,#1)|divide(n2,#6) | in simple words s . i = ptr / 100 = ( p * 1 * 10 ) / 100 p / 10 here amount a = p + s . i = p + p / 10 = 11 p / 10 . . . . now for compound interest when calculated half yearly amount = p [ 1 + r / 200 ] ^ 2 t = p [ 1 + 10 / 200 ] ^ 2 * 1 = 441 p / 400 here its given in the question dat diff btwn simple interest and co... | general |
math_qa__AyUgPpxfMforzoBv | How many bricks, each measuring 25 cm x 11 cm x 6 cm, will be needed to build a wall of 2 m x 3 m x 2 cm? Choose the most appropriate option
A) 5600 B) 6000 C) 73 D) 7200 E) 8600 | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">200 * 300</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 * 2</gadget>
<output>120_000</output>
<gadget id="calculator">25 * 11</gadget>
<output>275</ou... | C | 73 | How many bricks, each measuring 25 cm x 11 cm x 6 cm, will be needed to build a wall of 2 m x 3 m x 2 cm? | {
"A": "5600",
"B": "6000",
"C": "73",
"D": "7200",
"E": "8600"
} | divide(multiply(multiply(multiply(2, const_100), multiply(3, const_100)), 2), multiply(multiply(25, 11), 6)) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(n2,#2)|multiply(n5,#3)|divide(#5,#4)| | "number of bricks = volume of the wall / volume of 1 brick = ( 200 x 300 x 2 ) / ( 25 x 11 x 6 ) = 72.7 = 73 . answer : option c" | physics |
math_qa__4pfWoD7Q6UmODMA2 | If W is the set of all the integers between 69 and 99, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers?
Choose the correct choice from the following answers.
A) 20 B) 32 C) 33 D) 34 E) 35 | <gadget id="calculator">99 - 69</gadget>
<output>30</output>
<gadget id="calculator">30 / 3</gadget>
<output>10</output>
<gadget id="calculator">floor(10)</gadget>
<output>10</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">10 + 15</gadget>
<output>25</output>
<gadget id... | A | 20 | If W is the set of all the integers between 69 and 99, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? | {
"A": "20",
"B": "32",
"C": "33",
"D": "34",
"E": "35"
} | subtract(add(floor(divide(subtract(99, 69), 3)), divide(subtract(99, 69), 2)), floor(divide(subtract(99, 69), multiply(2, 3)))) | multiply(n3,n2)|subtract(n1,n0)|divide(#1,n3)|divide(#1,n2)|divide(#1,#0)|floor(#3)|floor(#4)|add(#2,#5)|subtract(#7,#6)| | "multiples of 2 from 69 to 99 = multiples of 2 from 1 to 99 - multiples of 2 from 1 to 68 = [ 99 / 2 ] - [ 68 / 2 ] = 49 - 34 = 15 multiples of 3 from 69 to 99 = multiples of 3 from 1 to 99 - multiples of 3 from 1 to 68 = [ 99 / 3 ] - [ 68 / 3 ] = 33 - 23 = 10 multiples of 2 and 3 bothi . e . 6 from 69 to 99 = multiple... | other |
math_qa__s34pPM8h3TLv42IR | 75 boys can complete a work in 26 days.how many men need to complete twice the work in 20 days
Choose the correct choice from the following answers
A) 160 B) 195 C) 180 D) 190 E) 200 | <gadget id="calculator">26 * 2</gadget>
<output>52</output>
<gadget id="calculator">75 * 52</gadget>
<output>3_900</output>
<gadget id="calculator">3_900 / 20</gadget>
<output>195</output>
<result>B</result> | B | 195 | 75 boys can complete a work in 26 days.how many men need to complete twice the work in 20 days | {
"A": "160",
"B": "195",
"C": "180",
"D": "190",
"E": "200"
} | divide(multiply(75, multiply(26, const_2)), 20) | multiply(n1,const_2)|multiply(n0,#0)|divide(#1,n2)| | "one man can complete the work in 26 * 75 = 1950 days = one time work to complete the work twice it will be completed in let m be the no . of worker assign for this therefore the eqn becomes m * 20 = 2 * 1950 m = 195 workers answer : b" | physics |
math_qa__70oNDqlfcRE6zvGH | A trader bought a car at 20% discount on its original price. He sold it at a 55% increase on the price he bought it. What percent of profit did he make on the original price?
Choose the correct option.
A) 17 % B) 24 % C) 12 % D) 82 % E) 16 % | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">100 + 55</gadget>
<output>155</output>
<gadget id="calculator">80 * 155</gadget>
<output>12_400</output>
<gadget id="calculator">12_400 / 100</gadget>
<output>124</output>
<gadget id="calculator">124 / 100</gadget>
<output>31/25 =... | B | 24 | A trader bought a car at 20% discount on its original price. He sold it at a 55% increase on the price he bought it. What percent of profit did he make on the original price? | {
"A": "17 %",
"B": "24 %",
"C": "12 %",
"D": "82 %",
"E": "16 %"
} | multiply(subtract(divide(divide(multiply(subtract(const_100, 20), add(const_100, 55)), const_100), const_100), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,const_1)|multiply(#5,const_100)| | "original price = 100 cp = 80 s = 80 * ( 155 / 100 ) = 124 100 - 124 = 24 % answer : b" | gain |
math_qa__Hi8WzuKKce8yuBbT | How many shots of 1cm radius can be prepared from a sphere of 2cm radius? Choices.
A) 3 B) 8 C) 27 D) 88 E) 99 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | How many shots of 1cm radius can be prepared from a sphere of 2cm radius? | {
"A": "3",
"B": "8",
"C": "27",
"D": "88",
"E": "99"
} | multiply(power(2, const_2), 2) | power(n1,const_2)|multiply(n1,#0)| | "4 / 3 ï € * 2 * 2 * 2 = 4 / 3 ï € * 1 * 1 * 1 * x x = 8 answer : b" | physics |
math_qa__j1eaAgXVvuIZVhBi | Machine A and machine B are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces? Pick one: A) 6 B) 6.6 C) 60 D) 100 E) 110 | <gadget id="calculator">10 * 660</gadget>
<output>6_600</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">6_600 * (11/10)</gadget>
<output>7_260</output>
<gadget id="calculator">660 * (11/10)... | A | 6 | Machine A and machine B are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine B. Machine B produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces? | {
"A": "6",
"B": "6.6",
"C": "60",
"D": "100",
"E": "110"
} | divide(660, divide(multiply(multiply(10, 660), divide(add(const_100, 10), const_100)), subtract(multiply(660, divide(add(const_100, 10), const_100)), 660))) | add(n1,const_100)|multiply(n0,n1)|divide(#0,const_100)|multiply(#2,#1)|multiply(n0,#2)|subtract(#4,n0)|divide(#3,#5)|divide(n0,#6) | b takes x hours a takes x + 10 hours rate of a = 660 / x + 10 rate of b = 660 / x thus , 660 / x = ( 660 / x + 10 ) * 1.10 x = 100 so b = 100 a = 110 sprockets per hour 660 / 110 = 6 answer : a | gain |
math_qa__Tnf3ofz9WgROaqhi | The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1250. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ? Choose the correct choice from the following options
A) 2480 B) 3490 C) 6785 D) 8225 E) 9255 | <gadget id="calculator">30 + 1</gadget>
<output>31</output>
<gadget id="calculator">30 * 31</gadget>
<output>930</output>
<gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">60 + 1</gadget>
<output>61</output>
<gadget id="calculator">930 * 61</gadget>
<output>56_730</output>
<gadget... | D | 8,225 | The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1250. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ? | {
"A": "2480",
"B": "3490",
"C": "6785",
"D": "8225",
"E": "9255"
} | subtract(divide(multiply(multiply(30, add(30, 1)), add(multiply(2, 30), 1)), add(3, 3)), 1250) | add(n17,n1)|add(n5,n5)|multiply(n17,n2)|add(#2,n1)|multiply(n17,#0)|multiply(#3,#4)|divide(#5,#1)|subtract(#6,n9)| | "you ' ll never need a formula for the sums of squares on the actual gmat . you do n ' t need to use that formula here , though it ' s not all that straightforward to solve without one . two different approaches : 16 ^ 2 + 17 ^ 2 + 18 ^ 2 + . . . + 30 ^ 2 = ( 15 + 1 ) ^ 2 + ( 15 + 2 ) ^ 2 + ( 15 + 3 ) ^ 2 + . . . + ( 1... | general |
math_qa__rFn75X15jUUxDz44 | There were two candidates in an election. Winner candidate received 52% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate? Choose the correct choice from the following answers: A) 776 B) 3744 C) 299 D) 257 E) 125 | <gadget id="calculator">100 - 52</gadget>
<output>48</output>
<gadget id="calculator">52 - 48</gadget>
<output>4</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">288 / (1/25)</gadget>
<output>7_200</output>
<gadget id="calculator">7_200 * 52</gadget>
<out... | B | 3,744 | There were two candidates in an election. Winner candidate received 52% of votes and won the election by 288 votes. Find the number of votes casted to the winning candidate? | {
"A": "776",
"B": "3744",
"C": "299",
"D": "257",
"E": "125"
} | divide(multiply(divide(288, divide(subtract(52, subtract(const_100, 52)), const_100)), 52), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 52 % l = 48 % 52 % - 48 % = 4 % 4 % - - - - - - - - 288 52 % - - - - - - - - ? = > 3744 answer : b" | gain |
math_qa__ORRecorCdGkwWOkE | John completes a piece of work in 320 days, Rose completes the same work in 480 days. If both of them work together, then the number of days required to complete the work is? Select: A) 190 B) 192 C) 194 D) 196 E) 198 | <gadget id="calculator">1 / 320</gadget>
<output>1/320 = around 0.003125</output>
<gadget id="calculator">1 / 480</gadget>
<output>1/480 = around 0.002083</output>
<gadget id="calculator">(1/320) + (1/480)</gadget>
<output>1/192 = around 0.005208</output>
<gadget id="calculator">1 / (1/192)</gadget>
<output>192</out... | B | 192 | John completes a piece of work in 320 days, Rose completes the same work in 480 days. If both of them work together, then the number of days required to complete the work is? | {
"A": "190",
"B": "192",
"C": "194",
"D": "196",
"E": "198"
} | divide(const_1, add(divide(const_1, 320), divide(const_1, 480))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "if a can complete a work in x days and b can complete the same work in y days , then , both of them together can complete the work in x y / x + y days . that is , the required no . of days = 320 × 480 / 800 = 192 days answer is b" | physics |
math_qa__A1FXK3qYpB2BFpIT | In a sports club with 30 members, 18 play badminton and 19 play tennis and 2 do not play either. How many members play both badminton and tennis? Pick
A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">18 + 19</gadget>
<output>37</output>
<gadget id="calculator">37 + 2</gadget>
<output>39</output>
<gadget id="calculator">39 - 30</gadget>
<output>9</output>
<result>C</result> | C | 9 | In a sports club with 30 members, 18 play badminton and 19 play tennis and 2 do not play either. How many members play both badminton and tennis? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | subtract(add(add(18, 19), 2), 30) | add(n1,n2)|add(n3,#0)|subtract(#1,n0)| | "let x play both badminton and tennis so 18 - x play only badminton and 19 - x play only tennis . 2 play none and there are total 30 students . hence , ( 18 - x ) + ( 19 - x ) + x + 2 = 30 39 - 2 x + x = 30 39 - x = 30 x = 9 so 9 members play both badminton and tennis . c" | other |
math_qa__gbmhkszsujz3hIpC | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1.2 cm when a man gets on it. The mass of man is Choose the correct option
A) 72 kg B) 60 kg C) 72 kg D) 96 kg E) none | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1.2 / 100</gadget>
<output>0.012</output>
<gadget id="calculator">6 * 0.012</gadget>
<output>0.072</output>
<gadget id="calculator">0.072 * 1_000</gadget>
<output>72</output>
<result>A</result> | A | 72 | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1.2 cm when a man gets on it. The mass of man is | {
"A": "72 kg",
"B": "60 kg",
"C": "72 kg",
"D": "96 kg",
"E": "none"
} | multiply(multiply(multiply(3, 2), divide(1.2, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000)| | "solution volume of water displaced = ( 3 x 2 x 0.012 ) m 3 = 0.072 m 3 . mass of man = volume of water displaced × density of water = ( 0.072 × 1000 ) kg = 72 kg . answer a" | physics |
math_qa__YcR2aP8TNZ1XL2tx | what is the probability for a family with 5 children to have two boys and 3 girls ( assuming the probability of having a boy or a girl is equal ) ? Select the correct option.
A) 1 / 2 B) 1 / 4 C) 3 / 8 D) 3 / 16 E) 5 / 16 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<... | E | 0.3125 | what is the probability for a family with 5 children to have two boys and 3 girls ( assuming the probability of having a boy or a girl is equal ) ? | {
"A": "1 / 2",
"B": "1 / 4",
"C": "3 / 8",
"D": "3 / 16",
"E": "5 / 16"
} | divide(divide(factorial(5), multiply(factorial(3), factorial(subtract(5, 3)))), power(const_2, 5)) | factorial(n0)|factorial(n1)|power(const_2,n0)|subtract(n0,n1)|factorial(#3)|multiply(#1,#4)|divide(#0,#5)|divide(#6,#2) | one possible case is : girl - girl - girl - boy - boy the probability of this is 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 = 1 / 32 there are 5 c 3 = 10 such cases so we should multiply by 10 . p ( two boys and three girls ) = 10 / 32 = 5 / 16 the answer is e . | general |
math_qa__pwpBscrZT0cwEgvV | the ratio of sodium chloride to ammonium in 100 kg of mixed ammonium normally used by 3 chemists is 1 : 4 . the amount of sodium chloride to be added to 100 kg of mixed ammonium to make the ratio 9 : 25 is Choose the correct choice from the following answers: A) 5 kg B) 6.625 kg C) 6.25 kg D) 6.35 kg E) 8.8 kg | <gadget id="calculator">9 / 25</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<gadget id="calculator">(9/25) * 80</gadget>... | E | 8.8 | the ratio of sodium chloride to ammonium in 100 kg of mixed ammonium normally used by 3 chemists is 1 : 4 . the amount of sodium chloride to be added to 100 kg of mixed ammonium to make the ratio 9 : 25 is | {
"A": "5 kg",
"B": "6.625 kg",
"C": "6.25 kg",
"D": "6.35 kg",
"E": "8.8 kg"
} | subtract(multiply(divide(9, 25), multiply(divide(4, add(const_1, const_4)), 100)), multiply(divide(const_1, add(const_1, const_4)), 100)) | add(const_1,const_4)|divide(n5,n6)|divide(n3,#0)|divide(const_1,#0)|multiply(n0,#2)|multiply(n0,#3)|multiply(#1,#4)|subtract(#6,#5) | sodium chloride in 100 kg = 1 / 5 x 100 = 20 kg ammonium in 100 kg = 4 / 5 x 100 = 80 kg now 80 is 25 parts out of ( 25 + 9 ) = 34 parts . hence 9 parts = 9 / 25 x 80 = 28.8 amount to be added = 28.8 - 20 = 8.8 kg answer : e | general |
math_qa__t9lrRPuYarfdcJbi | The salary of a worker is first increased by 30% and afterwards reduced by 30%. What is net change in his salary? Choose the correct choice from the following answers:
A) 3 % decrease B) 5 % decrease C) 9 % decrease D) 4 % decrease E) 8 % decrease | <gadget id="calculator">30 + 100</gadget>
<output>130</output>
<gadget id="calculator">130 * 30</gadget>
<output>3_900</output>
<gadget id="calculator">3_900 / 100</gadget>
<output>39</output>
<gadget id="calculator">130 - 39</gadget>
<output>91</output>
<gadget id="calculator">100 - 91</gadget>
<output>9</output>
... | C | 9 | The salary of a worker is first increased by 30% and afterwards reduced by 30%. What is net change in his salary? | {
"A": "3 % decrease",
"B": "5 % decrease",
"C": "9 % decrease",
"D": "4 % decrease",
"E": "8 % decrease"
} | subtract(const_100, subtract(add(30, const_100), divide(multiply(add(30, const_100), 30), const_100))) | add(n0,const_100)|multiply(n0,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(const_100,#3) | ( 30 * 30 ) / 100 = 9 % decrease answer : c : | gain |
math_qa__RaJqiQpH6SQ3WpUI | Think of a number, divide it by 6 and add 5 to it. The result is 17. What is the number thought of?
Choose one
A) 24 B) 72 C) 297 D) 267 E) 29 | <gadget id="calculator">17 - 5</gadget>
<output>12</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<result>B</result> | B | 72 | Think of a number, divide it by 6 and add 5 to it. The result is 17. What is the number thought of? | {
"A": "24",
"B": "72",
"C": "297",
"D": "267",
"E": "29"
} | multiply(subtract(17, 5), 6) | subtract(n2,n1)|multiply(n0,#0)| | "explanation : 17 - 5 = 12 12 x 6 = 72 answer : b" | general |
math_qa__pQO3HJl7VvXXIBrP | X and Y are both integers. If X/Y = 57.40, then what is the sum of all the possible two digit remainders of X/Y? Choose one:
A) 560
B) 616
C) 450
D) 900
E) 1024 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 57.4</gadget>
<output>287</output>
<gadget id="calculator">287 + 3</gadget>
<output>290</ou... | C | 450 | X and Y are both integers. If X/Y = 57.40, then what is the sum of all the possible two digit remainders of X/Y? | {
"A": "560",
"B": "616",
"C": "450",
"D": "900",
"E": "1024"
} | add(multiply(divide(const_3, const_2), const_100), add(multiply(add(const_2, const_3), 57.40), const_3)) | add(const_2,const_3)|divide(const_3,const_2)|multiply(n0,#0)|multiply(#1,const_100)|add(#2,const_3)|add(#4,#3)| | "remainder = 0.40 - - > 40 / 100 - - > can be written as ( 40 / 4 ) / ( 100 / 4 ) = 10 / 25 so remainders can be 10 , 20 , 30 , 40 , . . . . . 90 . we need the sum of only 2 digit remainders - - > 10 + 20 + 30 + 40 + 50 + 60 + 70 + 80 + 90 = 450 answer : c" | general |
math_qa__hDHi3OSrvw25JU9T | A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12300 after a year?
Choose the correct choice.
A) 3630 B) 3690 C) 2887 D) 9977 E) 2212 | <gadget id="calculator">6_300 + 4_200</gadget>
<output>10_500</output>
<gadget id="calculator">10_500 + 10_500</gadget>
<output>21_000</output>
<gadget id="calculator">6_300 / 21_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 12_300</gadget>
<output>3_690</output>
<result>B</result... | B | 3,690 | A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12300 after a year? | {
"A": "3630",
"B": "3690",
"C": "2887",
"D": "9977",
"E": "2212"
} | multiply(divide(6300, add(add(6300, 4200), 10500)), 12300) | add(n0,n1)|add(n2,#0)|divide(n0,#1)|multiply(n3,#2)| | "6300 : 4200 : 10500 3 : 2 : 5 3 / 10 * 12300 = 3690 . answer : b" | gain |
math_qa__BQt3OVfnXALzV7m3 | $406 is divided among A, B, and C so that A receives half as much as B, and B receives half as much as C. How much money is C's share? Choose the most appropriate option.
A) $ 208 B) $ 216 C) $ 224 D) $ 232 E) $ 240 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 1</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">406 / (7/2)</gadget>
<output>116</output>
<gadget id="calculator"... | D | 232 | $406 is divided among A, B, and C so that A receives half as much as B, and B receives half as much as C. How much money is C's share? | {
"A": "$ 208",
"B": "$ 216",
"C": "$ 224",
"D": "$ 232",
"E": "$ 240"
} | multiply(divide(406, add(add(divide(const_1, const_2), const_1), const_2)), const_2) | divide(const_1,const_2)|add(#0,const_1)|add(#1,const_2)|divide(n0,#2)|multiply(#3,const_2) | let the shares for a , b , and c be x , 2 x , and 4 x respectively . 7 x = 406 x = 58 4 x = 232 the answer is d . | general |
math_qa__7MyvHwhYLHkyFMp2 | What is the dividend. divisor 18, the quotient is 9 and the remainder is 5?
Pick one.
A) 130 B) 134 C) 148 D) 158 E) 167 | <gadget id="calculator">18 * 9</gadget>
<output>162</output>
<gadget id="calculator">162 + 5</gadget>
<output>167</output>
<result>E</result> | E | 167 | What is the dividend. divisor 18, the quotient is 9 and the remainder is 5? | {
"A": "130",
"B": "134",
"C": "148",
"D": "158",
"E": "167"
} | add(multiply(18, 9), 5) | multiply(n0,n1)|add(n2,#0)| | "d = d * q + r d = 18 * 9 + 5 d = 162 + 5 d = 167 answer e" | general |
math_qa__LDdfsnhLr2j8xHQs | The area of the maximum size of the circle described from the 10 inch square? Choose the correct choice from the following options:
A) 75.5 sq inch B) 76.5 sq inch C) 77.5 sq inch D) 78.5 sq inch E) 79.5 sq inch | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">pi * (5 ** 2)</gadget>
<output>25*pi = around 78.539816</output>
<result>D</result> | D | 78.5 | The area of the maximum size of the circle described from the 10 inch square? | {
"A": "75.5 sq inch",
"B": "76.5 sq inch",
"C": "77.5 sq inch",
"D": "78.5 sq inch",
"E": "79.5 sq inch"
} | circle_area(divide(10, const_2)) | divide(n0,const_2)|circle_area(#0) | 10 inch square means sides of sq are 10 inch then circle is within square so diameter would be 10 inch maximum and radius is 5 inch so area of the circle is = pi * r * r = 3.14 * 5 * 5 = 78.5 sq inch answer : d | geometry |
math_qa__i3xSfPqEeKJgIaj2 | At a garage sale, all of the items were sold at different prices. If the price of a radio sold at the garage sale was both the 17th highest price and the 24th lowest price among the prices of the items sold, how many items were sold at the garage sale? Choose the correct answer.
A) 38 B) 39 C) 40 D) 41 E) 42 | <gadget id="calculator">24 + 17</gadget>
<output>41</output>
<gadget id="calculator">41 - 1</gadget>
<output>40</output>
<result>C</result> | C | 40 | At a garage sale, all of the items were sold at different prices. If the price of a radio sold at the garage sale was both the 17th highest price and the 24th lowest price among the prices of the items sold, how many items were sold at the garage sale? | {
"A": "38",
"B": "39",
"C": "40",
"D": "41",
"E": "42"
} | subtract(add(24, 17), const_1) | add(n0,n1)|subtract(#0,const_1)| | "there were 16 items sold at a higher price than the radio and 23 items sold at a lower price than the radio . including the radio , there were 16 + 23 + 1 = 40 items sold . the answer is c ." | other |
math_qa__m3lkE8yCUfaoh74A | A 15 lt mixture contains water with 20% of alcohol.If 5 more lts of water added to the mixture what is the percentage of alcohol?
Choose the most appropriate option:
A) 10 % B) 15 % C) 20 % D) 25 % E) 30 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 15</gadget>
<output>3</output>
<gadget id="calculator">15 + 5</gadget>
<output>20</output>
<gadget id="calculator">3 / 20</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gad... | B | 15 | A 15 lt mixture contains water with 20% of alcohol.If 5 more lts of water added to the mixture what is the percentage of alcohol? | {
"A": "10 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "30 %"
} | multiply(divide(multiply(divide(20, const_100), 15), add(15, 5)), const_100) | add(n0,n2)|divide(n1,const_100)|multiply(n0,#1)|divide(#2,#0)|multiply(#3,const_100) | initially the mixture contains 20 % of 15 = 15 * ( 20 / 100 ) = 3 lts of alcohol after mixing another 5 lts of water . . . the total liquid is 20 lts . . so alcohol percentage = ( 3 / 20 ) * 100 = 15 % answer : b | general |
math_qa__FyFE4oFpQvxjidKm | By how much does the larger root of the equation 2c^2+5c = 12 exceed the smaller root? Choose the correct choice from the following choices:
A) 5 / 2 B) 10 / 3 C) 7 / 2 D) 14 / 3 E) 11 / 2 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">25 + 96</gadget>
<output>121</output>
<gadget id="calculator">121 ** (1/2)</gadget>
<output>11</output>
<gadget... | E | 5.5 | By how much does the larger root of the equation 2c^2+5c = 12 exceed the smaller root? | {
"A": "5 / 2",
"B": "10 / 3",
"C": "7 / 2",
"D": "14 / 3",
"E": "11 / 2"
} | subtract(divide(add(5, sqrt(add(power(5, 2), multiply(multiply(2, 12), const_4)))), multiply(2, 2)), divide(subtract(5, sqrt(add(power(5, 2), multiply(multiply(2, 12), const_4)))), multiply(2, 2))) | multiply(n0,n3)|multiply(n0,n0)|power(n2,n0)|multiply(#0,const_4)|add(#3,#2)|sqrt(#4)|add(n2,#5)|subtract(n2,#5)|divide(#6,#1)|divide(#7,#1)|subtract(#8,#9)| | "for 2 c ^ 2 + 5 c = 12 roots are [ - 5 + sqrt ( 25 + 96 ) ] / 4 or [ - 5 - sqrt ( 25 + 96 ) ] / 4 = 1.5 or - 4 hence larger root 1.5 is 1.5 - ( - 4 ) = 5.5 = 11 / 2 greater than smaller root ( - 4 ) . hence option ( e ) ." | general |
math_qa__ty6Zsk7CXNtXqmqV | At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 20 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank? Select the correct option: A) 3 / 25 B) 11 / 36 C) 5 / 12 D)... | <gadget id="calculator">50 * 5</gadget>
<output>250</output>
<gadget id="calculator">250 / 30</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">(25/3) / 20</gadget>
<output>5/12 = around 0.416667</output>
<result>C</result> | C | 0.416667 | At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 20 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank? | {
"A": "3 / 25",
"B": "11 / 36",
"C": "5 / 12",
"D": "2 / 3",
"E": "25 / 36"
} | divide(divide(multiply(50, 5), 30), 20) | multiply(n0,n4)|divide(#0,n2)|divide(#1,n3)| | "gas used = ( 5 hours ) * ( 50 miles / hour ) * ( 1 gallon / 30 miles ) = 8 + 1 / 3 gallons portion used = ( 8 + 1 / 3 ) / 20 = 5 / 12 ans c" | physics |
math_qa__HdT0ijfCbNtV07Hf | A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $10 more than that received by B, find the total amount shared by A, B and C. Options:
A) $ 260 B) $ 360 C) $ 160 D) $ 460 E) $ 5... | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">60 + 20</gadget>
<output>80</output>
<gadget id="calculator">80 + 10</gadget>
<output>90</output>
<gadget id="c... | B | 360 | A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $10 more than that received by B, find the total amount shared by A, B and C. | {
"A": "$ 260",
"B": "$ 360",
"C": "$ 160",
"D": "$ 460",
"E": "$ 560"
} | add(add(add(multiply(multiply(const_3, 10), const_2), multiply(const_2, 10)), add(add(multiply(multiply(const_3, 10), const_2), multiply(const_2, 10)), 10)), subtract(multiply(add(add(multiply(multiply(const_3, 10), const_2), multiply(const_2, 10)), 10), const_3), add(multiply(multiply(const_3, 10), const_2), multiply(... | multiply(n0,const_3)|multiply(n0,const_2)|multiply(#0,const_2)|add(#2,#1)|add(n0,#3)|add(#3,#4)|multiply(#4,const_3)|subtract(#6,#3)|add(#5,#7)| | "a = 1 / 3 ( b + c ) = > c = 3 a - b - - - ( 1 ) b = 2 / 7 ( a + c ) = > c = 3.5 b - a - - ( b ) a - b = $ 10 a = 10 + b ( 1 ) = = = > c = 30 + 3 b - b = 2 b + 30 = = > 2 b - c = - 30 - - - ( 3 ) ( 2 ) = = = > c = 3.5 b - b - 10 = 2.5 b - 10 = = > 2.5 b - c = 10 - - - ( 4 ) from ( 4 ) and ( 3 ) 0.5 b = 40 b = $ 80 a = ... | general |
math_qa__T6KGjB5NMWY6zdsG | In a can, there is a mixture of milk and water in the ratio 5:3. If the can is filled with an additional 20 liters of milk, the can would be full and the ratio of milk and water would become 3:1. Find the capacity of the can?
Choose the correct choice from the following answers.
A) 52
B) 56
C) 60
D) 64
E) 68 | <gadget id="calculator">1 * 20</gadget>
<output>20</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">1 * 5</gadget>
<output>5</output>
<gadget id="calculator">9 - 5</gadget>
<output>4</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator... | C | 60 | In a can, there is a mixture of milk and water in the ratio 5:3. If the can is filled with an additional 20 liters of milk, the can would be full and the ratio of milk and water would become 3:1. Find the capacity of the can? | {
"A": "52",
"B": "56",
"C": "60",
"D": "64",
"E": "68"
} | add(add(multiply(divide(multiply(1, 20), subtract(multiply(3, 3), multiply(1, 5))), 5), 20), multiply(divide(multiply(1, 20), subtract(multiply(3, 3), multiply(1, 5))), 3)) | multiply(n2,n4)|multiply(n1,n3)|multiply(n0,n4)|subtract(#1,#2)|divide(#0,#3)|multiply(n0,#4)|multiply(n1,#4)|add(n2,#5)|add(#7,#6)| | "let c be the capacity of the can . ( 5 / 8 ) * ( c - 20 ) + 20 = ( 3 / 4 ) * c 5 c - 100 + 160 = 6 c c = 60 the answer is c ." | general |
math_qa__YD9hExCYgc9GyyF9 | When the price of a radio was reduced by 20%, its sale increased by 80%. What was the net effect on the sale? Choose the most appropriate option.
A) 44 % increase B) 44 % decrease C) 66 % increase D) 75 % increase E) none of these | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 / 100</gadget>
<output>4</output>
<gadget id="calculator">40 + 4</gadget>
<output>44</output>
<result>A</result> | A | 44 | When the price of a radio was reduced by 20%, its sale increased by 80%. What was the net effect on the sale? | {
"A": "44 % increase",
"B": "44 % decrease",
"C": "66 % increase",
"D": "75 % increase",
"E": "none of these"
} | add(add(20, 20), divide(multiply(20, 20), const_100)) | add(n0,n0)|multiply(n0,n0)|divide(#1,const_100)|add(#0,#2) | let the original price be x and sale be of y units . then , the revenue collected initially = x × y now , new price = 0.8 x , new sale = 1.8 y then , new revenue collected = 1.44 xy % increase in revenue = 0.44 xy / xy × 100 = 44 % increase answer a | gain |
math_qa__487mEw7gQnSkPEQ3 | Two trains of length 100 m and 200 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? Choose the correct choice from the following choices:
A) 18 sec
B) 15 sec
C) 21 sec
D) 20 sec
E) 19 sec | <gadget id="calculator">100 + 200</gadget>
<output>300</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">300 / 20</gadget>
<ou... | B | 15 | Two trains of length 100 m and 200 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "18 sec",
"B": "15 sec",
"C": "21 sec",
"D": "20 sec",
"E": "19 sec"
} | divide(add(100, 200), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 100 + 200 = 300 m . the time required = d / s = 300 / 20 = 15 sec . answer : b" | physics |
math_qa__tMbBGpM7TOYhbt5d | The greatest number that exactly divided 105, 1001 and 2436 is : Select the correct option
A) 3 B) 7 C) 11 D) 21 E) 24 | <gadget id="calculator">105 / 3</gadget>
<output>35</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">35 / 5</gadget>
<output>7</output>
<result>B</result> | B | 7 | The greatest number that exactly divided 105, 1001 and 2436 is : | {
"A": "3",
"B": "7",
"C": "11",
"D": "21",
"E": "24"
} | divide(divide(105, const_3), add(const_1, const_4)) | add(const_1,const_4)|divide(n0,const_3)|divide(#1,#0) | solution h . c . f . of 2436 and 1001 is 7 . also , h . c . f . of 105 and 7 is 7 . ∴ h . c . f . of 105 , 1001 and 2436 is 7 . answer b | general |
math_qa__WJGbLtZTBSqw3xha | A, B, C subscribe Rs. 50,000 for a business. If A subscribes Rs. 4000 more than B and B Rs. 5000 more than C, out of a total profit of Rs. 37,000, what will be the amount A receives? Select
A) 14700 B) 14500 C) 14900 D) 14300 E) 15540 | <gadget id="calculator">5_000 * 10</gadget>
<output>50_000</output>
<gadget id="calculator">4_000 + 5_000</gadget>
<output>9_000</output>
<gadget id="calculator">9_000 + 5_000</gadget>
<output>14_000</output>
<gadget id="calculator">50_000 - 14_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3... | E | 15,540 | A, B, C subscribe Rs. 50,000 for a business. If A subscribes Rs. 4000 more than B and B Rs. 5000 more than C, out of a total profit of Rs. 37,000, what will be the amount A receives? | {
"A": "14700",
"B": "14500",
"C": "14900",
"D": "14300",
"E": "15540"
} | multiply(add(divide(subtract(multiply(5000, const_10), add(add(4000, 5000), 5000)), const_3), add(4000, 5000)), divide(multiply(multiply(const_3, const_12), const_1000), multiply(5000, const_10))) | add(n1,n2)|multiply(n2,const_10)|multiply(const_12,const_3)|add(n2,#0)|multiply(#2,const_1000)|divide(#4,#1)|subtract(#1,#3)|divide(#6,const_3)|add(#0,#7)|multiply(#8,#5)| | "total amount invested = 50000 assume that investment of c = x . then investment of b = 5000 + x , investment of a = 4000 + 5000 + x = 9000 + x x + 5000 + x + 9000 + x = 50000 ⇒ 3 x + 14000 = 50000 ⇒ 3 x = 50000 – 14000 = 36000 ⇒ x = 36000 / 3 = 12000 investment of c = x = 12000 investment of b = 5000 + x = 17000 inves... | general |
math_qa__G0HSEXa5QhblPlrg | Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.? Choose the most appropriate option
A) 277 B) 209 C) 121 D) 200 E) 128 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 - (1/25)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">15_000 * (24/25)</gadget>
<output>14_400</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget... | D | 200 | Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a.? | {
"A": "277",
"B": "209",
"C": "121",
"D": "200",
"E": "128"
} | subtract(add(multiply(15000, subtract(const_1, divide(4, const_100))), multiply(8000, add(const_1, divide(10, const_100)))), add(15000, 8000)) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|add(#2,const_1)|subtract(const_1,#1)|multiply(n0,#4)|multiply(n1,#3)|add(#5,#6)|subtract(#7,#0)| | "let the sp of the refrigerator and the mobile phone be rs . r and rs . m respectively . r = 15000 ( 1 - 4 / 100 ) = 15000 - 600 m = 8000 ( 1 + 10 / 100 ) = 8000 + 800 total sp - total cp = r + m - ( 15000 + 8000 ) = - 600 + 800 = rs . 200 as this is positive , an overall profit of rs . 200 was made . answer : d" | gain |
math_qa__b9PXv0mf6UzL79cr | Alfred buys an old scooter for $4700 and spends $800 on its repairs. If he sells the scooter for $6000, his gain percent is? Options
A) 9.1 % B) 6.23 % C) 7 % D) 8.12 % E) 10 % | <gadget id="calculator">4_700 + 800</gadget>
<output>5_500</output>
<gadget id="calculator">6_000 - 5_500</gadget>
<output>500</output>
<gadget id="calculator">500 / 5_500</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/11) * 100</gadget>
<output>100/11 = around 9.090909</output>
<result... | A | 9.1 | Alfred buys an old scooter for $4700 and spends $800 on its repairs. If he sells the scooter for $6000, his gain percent is? | {
"A": "9.1 %",
"B": "6.23 %",
"C": "7 %",
"D": "8.12 %",
"E": "10 %"
} | multiply(divide(subtract(6000, add(4700, 800)), add(4700, 800)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "c . p . = 4700 + 800 = $ 5500 s . p . = $ 6000 gain = 6000 - 5500 = $ 500 gain % = 500 / 5500 * 100 = 9.1 % answer is a" | gain |
math_qa__C6kIai1pkgejTfk3 | A train 180 m long is running with a speed of 55 km/hr. In what time will it pass a man who is running at 7km/hr in the direction opposite to that in which the train is going? Select the correct option.
A) 5.5 B) 10.45 C) 7 D) 8 E) 9.5 | <gadget id="calculator">55 + 7</gadget>
<output>62</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">62 * (5/18)</gadget>
<output>155/9 = around 17.222222</output>
<gadget id="calculator">180 / (155/9)</gadget>
<output>324/31 = around 10.451613</output>... | B | 10.45 | A train 180 m long is running with a speed of 55 km/hr. In what time will it pass a man who is running at 7km/hr in the direction opposite to that in which the train is going? | {
"A": "5.5",
"B": "10.45",
"C": "7",
"D": "8",
"E": "9.5"
} | divide(180, multiply(add(55, 7), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 55 + 7 = 62 km / hr . = 62 * 5 / 18 = 155 / 9 m / sec . time taken to pass the men = 180 * 9 / 155 = 10.45 sec . answer : option b" | physics |
math_qa__gtsIsXrjs1xKCEVL | There is 60% increase in an amount in 6years at SI. What will be the CI of Rs. 13,000 after 3 years at the same rate? Choose the correct choice from the following answers: A) 2372 B) 2572 C) 4303 D) 2343 E) 3972 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">60 / 6</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 3</gadget>
<output>3_000</output>
<gadget id="calculator">10_000 + 3_000</gadget>
<output>13... | C | 4,303 | There is 60% increase in an amount in 6years at SI. What will be the CI of Rs. 13,000 after 3 years at the same rate? | {
"A": "2372",
"B": "2572",
"C": "4303",
"D": "2343",
"E": "3972"
} | subtract(multiply(add(multiply(const_100, const_100), multiply(multiply(const_100, divide(60, 6)), const_3)), multiply(multiply(add(const_1, divide(divide(60, 6), const_100)), add(const_1, divide(divide(60, 6), const_100))), add(const_1, divide(divide(60, 6), const_100)))), add(multiply(const_100, const_100), multiply(... | divide(n0,n1)|multiply(const_100,const_100)|divide(#0,const_100)|multiply(#0,const_100)|add(#2,const_1)|multiply(#3,const_3)|add(#1,#5)|multiply(#4,#4)|multiply(#4,#7)|multiply(#6,#8)|subtract(#9,#6) | let p = rs . 100 . then , s . i . rs . 60 and t = 6 years . r = 100 x 60 = 10 % p . a . 100 x 6 now , p = rs . 13000 . t = 3 years and r = 10 % p . a . c . i . = rs . 13000 x 1 + 10 3 - 1 100 = rs . 13000 x 331 1000 = 4303 . c | gain |
math_qa__iVvSQmvhNAOT5zmX | Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $396 per week. How much does she earn in dollars per hour?
Choices
A) 11
B) 10
C) 9
D) 8
E) 7 | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">396 / 36</gadget>
<output>11</output>
<result>A</result> | A | 11 | Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $396 per week. How much does she earn in dollars per hour? | {
"A": "11",
"B": "10",
"C": "9",
"D": "8",
"E": "7"
} | divide(396, add(multiply(8, const_3), multiply(6, const_2))) | multiply(n0,const_3)|multiply(n1,const_2)|add(#0,#1)|divide(n2,#2)| | "let sheila earn x dollars per hour so , on monday , wednesday and friday , she earns 8 x each and , on tuesday and thursday , she earns 6 x each in total , over the week she should earn , 3 ( 8 x ) + 2 ( 6 x ) = 36 x she earns $ 396 per week 36 x = 396 x = 11 correct option : a" | physics |
math_qa__TVuK68L4njsCE4gD | 36 men can complete a piece of work in 18 days. In how many days will 54 men complete the same work ? Choose the correct choice from the following choices
A) 24
B) 77
C) 88
D) 29
E) 12 | <gadget id="calculator">18 * 36</gadget>
<output>648</output>
<gadget id="calculator">648 / 54</gadget>
<output>12</output>
<result>E</result> | E | 12 | 36 men can complete a piece of work in 18 days. In how many days will 54 men complete the same work ? | {
"A": "24",
"B": "77",
"C": "88",
"D": "29",
"E": "12"
} | divide(multiply(18, 36), 54) | multiply(n0,n1)|divide(#0,n2)| | "explanation : less men , means more days { indirect proportion } let the number of days be x then , 54 : 36 : : 18 : x x = 12 answer : e ) 12 days" | physics |
math_qa__DDE4ozY3CZcZ0soV | Ramu bought an old car for Rs. 34000. He spent Rs. 12000 on repairs and sold it for Rs. 65000. What is his profit percent? Options
A) 16 % B) 17 % C) 18 % D) 41 % E) 13 % | <gadget id="calculator">34_000 + 12_000</gadget>
<output>46_000</output>
<gadget id="calculator">65_000 - 46_000</gadget>
<output>19_000</output>
<gadget id="calculator">19_000 / 46_000</gadget>
<output>19/46 = around 0.413043</output>
<gadget id="calculator">(19/46) * 100</gadget>
<output>950/23 = around 41.304348<... | D | 41 | Ramu bought an old car for Rs. 34000. He spent Rs. 12000 on repairs and sold it for Rs. 65000. What is his profit percent? | {
"A": "16 %",
"B": "17 %",
"C": "18 %",
"D": "41 %",
"E": "13 %"
} | multiply(divide(subtract(65000, add(34000, 12000)), add(34000, 12000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "total cp = rs . 34000 + rs . 12000 = rs . 46000 and sp = rs . 65000 profit ( % ) = ( 65000 - 46000 ) / 46000 * 100 = 41 % answer : d" | gain |
math_qa__50fvexjctgogdt60 | John took a bus from home to market, that travels at 50 kmph. While walking back at 5 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 35 kmph. Find the average speed. Choose the correct choice: A) 8.5 kmph B) 16.0 kmph C) 22.5 kmph D) 18.6 kmph E) none of the... | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">35 / 2</gadget>
<output>35/2 = around 17.5</output>
<gadget id="calculator">(1/4) + (35/2)</gadget>
<output>71/4 = around 17.75</output>
<result>D</result> | D | 18.6 | John took a bus from home to market, that travels at 50 kmph. While walking back at 5 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 35 kmph. Find the average speed. | {
"A": "8.5 kmph",
"B": "16.0 kmph",
"C": "22.5 kmph",
"D": "18.6 kmph",
"E": "none of these"
} | add(const_0_25, divide(35, const_2)) | divide(n2,const_2)|add(#0,const_0_25) | let the distance be 2 x ( one way ) time taken by bus = 2 x / 50 , by walking = x / 5 , by cycling = x / 35 hours : . average speed = total distance / total time = 5 x / x / 25 + x / 5 + x / 35 = 5 * 60 / 2.4 + 12 + 1.7 = 18.6 answer : d | physics |
math_qa__DW4AOAcUpzBYljav | Working at a constant rate, P can finish a job in 3 hours. Q, also working at a constant rate, can finish the same job in 9 hours. If they work together for 2 hours, how many more minutes will it take P to finish the job, working alone at his constant rate? Choose the correct choice from the following options: A) 20 ... | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/3) + (1/9)</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(4/9) * 2</gadget>
<output>8/9 = around 0.888889</o... | A | 20 | Working at a constant rate, P can finish a job in 3 hours. Q, also working at a constant rate, can finish the same job in 9 hours. If they work together for 2 hours, how many more minutes will it take P to finish the job, working alone at his constant rate? | {
"A": "20",
"B": "30",
"C": "40",
"D": "50",
"E": "60"
} | multiply(divide(subtract(const_1, multiply(add(inverse(3), inverse(9)), 2)), inverse(3)), const_60) | inverse(n0)|inverse(n1)|add(#0,#1)|multiply(#2,n2)|subtract(const_1,#3)|divide(#4,#0)|multiply(#5,const_60)| | "each hour they complete 1 / 3 + 1 / 9 = 4 / 9 of the job . in 2 hours , they complete 2 ( 4 / 9 ) = 8 / 9 of the job . the time for p to finish is ( 1 / 9 ) / ( 1 / 3 ) = ( 1 / 3 ) hour = 20 minutes the answer is a ." | physics |
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