id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__hmJbH3FTlyDnGPS2 | the average age of a group of persons going for picnic is 16 years . 12 new persons with an average age of 15 years join the group on the spot due to which their average age becomes 15.5 years . the number of persons initially going for picnic is Choices.
A) 5 B) 10 C) 12 D) 40 E) 50 | <gadget id="calculator">15.5 * 12</gadget>
<output>186</output>
<gadget id="calculator">12 * 15</gadget>
<output>180</output>
<gadget id="calculator">186 - 180</gadget>
<output>6</output>
<gadget id="calculator">16 - 15.5</gadget>
<output>0.5</output>
<gadget id="calculator">6 / 0.5</gadget>
<output>12</output>
<result>C</result> | C | 12 | the average age of a group of persons going for picnic is 16 years . 12 new persons with an average age of 15 years join the group on the spot due to which their average age becomes 15.5 years . the number of persons initially going for picnic is | {
"A": "5",
"B": "10",
"C": "12",
"D": "40",
"E": "50"
} | divide(subtract(multiply(15.5, 12), multiply(12, 15)), subtract(16, 15.5)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n0,n3)|subtract(#0,#1)|divide(#3,#2) | solution let the initial number of persons be x . then 16 x + 12 x 15 = 15.5 ( x + 20 ) = 0.5 x = 6 x = 12 . answer c | general |
math_qa__CTGIeeVEQs6E0e0W | From an island, it is possible to reach the mainland by either Ferry P or Ferry Q. Ferry P travels for 3 hours at 6 kilometers per hour, while Ferry Q takes a route that is three times longer. If Ferry P is slower than Ferry Q by 3 kilometers per hour, how many hours longer is the journey of Ferry Q compared with the journey of Ferry P? Select the correct option: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">3 * 18</gadget>
<output>54</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">54 / 9</gadget>
<output>6</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<result>C</result> | C | 3 | From an island, it is possible to reach the mainland by either Ferry P or Ferry Q. Ferry P travels for 3 hours at 6 kilometers per hour, while Ferry Q takes a route that is three times longer. If Ferry P is slower than Ferry Q by 3 kilometers per hour, how many hours longer is the journey of Ferry Q compared with the journey of Ferry P? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(divide(multiply(const_3, multiply(6, 3)), add(6, 3)), 3) | add(n1,n2)|multiply(n0,n1)|multiply(#1,const_3)|divide(#2,#0)|subtract(#3,n0)| | "the distance traveled by ferry p is 18 km . then the distance traveled by ferry q is 54 km . ferry q travels at a speed of 9 kph . the time of the journey for ferry q is 54 / 9 = 6 hours , which is 3 hours more than ferry p . the answer is c ." | physics |
math_qa__NgTdPmtFSnthixVl | The length of a room is 5 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre. Choose the correct choice
A) 21375 B) 25750 C) 26550 D) 26750 E) 25725 | <gadget id="calculator">5 * 4.75</gadget>
<output>23.75</output>
<gadget id="calculator">900 * 23.75</gadget>
<output>21_375</output>
<result>A</result> | A | 21,375 | The length of a room is 5 m and width is 4.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 900 per sq. metre. | {
"A": "21375",
"B": "25750",
"C": "26550",
"D": "26750",
"E": "25725"
} | multiply(900, multiply(5, 4.75)) | multiply(n0,n1)|multiply(n2,#0)| | "area = 5 × 4.75 sq . metre . cost for 1 sq . metre . = rs . 900 hence total cost = 5 × 4.75 × 900 = 5 × 4275 = rs . 21375 answer is a ." | physics |
math_qa__wH9H460UxGPGliuW | The compound interest earned by Sunil on a certain amount at the end of two years at the rate of5% p.a. was Rs.246. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned. Choose the most appropriate option:
A) rs . 2535
B) rs . 2646
C) rs . 2546
D) rs . 2656
E) rs . 2565 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">(441/400) - 1</gadget>
<output>41/400 = around 0.1025</output>
<gadget id="calculator">246 / (41/400)</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 + 246</gadget>
<output>2_646</output>
<result>B</result> | B | 2,646 | The compound interest earned by Sunil on a certain amount at the end of two years at the rate of5% p.a. was Rs.246. Find the total amount that Sunil got back at the end of two years in the form of principal plus interest earned. | {
"A": "rs . 2535",
"B": "rs . 2646",
"C": "rs . 2546",
"D": "rs . 2656",
"E": "rs . 2565"
} | add(divide(246, subtract(power(add(const_1, divide(5, const_100)), const_2), const_1)), 246) | divide(n0,const_100)|add(#0,const_1)|power(#1,const_2)|subtract(#2,const_1)|divide(n1,#3)|add(n1,#4)| | "let the sum be rs . p p { [ 1 + 5 / 100 ] 2 - 1 } = 246 p ( 5 / 100 ) ( 2 + 5 / 100 ) = 246 [ a 2 - b 2 = ( a - b ) ( a + b ) ] p = 246 / ( 0.05 ) ( 2.05 ) = 2400 . amount = rs . 2646 answer : b" | gain |
math_qa__Fr8osZ7MH3kn0TQU | The ratio of incomes of two person P1 and P2 is 5 : 4 and the ratio of their expenditures is 3 : 2. If at the end of the year, each saves Rs.1800, then what is the income of P1? Choose the correct choice from the following choices:
A) s . 800 B) s . 2400 C) s . 4000 D) s . 3200 E) s . 4500 | <gadget id="calculator">1_800 / 2</gadget>
<output>900</output>
<gadget id="calculator">900 * 3</gadget>
<output>2_700</output>
<gadget id="calculator">2_700 - 1_800</gadget>
<output>900</output>
<gadget id="calculator">900 * 5</gadget>
<output>4_500</output>
<result>E</result> | E | 4,500 | The ratio of incomes of two person P1 and P2 is 5 : 4 and the ratio of their expenditures is 3 : 2. If at the end of the year, each saves Rs.1800, then what is the income of P1? | {
"A": "s . 800",
"B": "s . 2400",
"C": "s . 4000",
"D": "s . 3200",
"E": "s . 4500"
} | multiply(subtract(multiply(divide(1800, 2), 3), 1800), 5) | divide(n6,n1)|multiply(n4,#0)|subtract(#1,n6)|multiply(n2,#2)| | "let the income of p 1 and p 2 be rs . 5 x and rs . 4 x respectively and let their expenditures be rs . 3 y and 2 y respectively . then , 5 x – 3 y = 1800 … ( i ) and 4 x – 2 y = 1800 … … . . ( ii ) on multiplying ( i ) by 2 , ( ii ) by 3 and subtracting , we get : 2 x = 1800 - > x = 900 p 1 ’ s income = rs 5 * 900 = rs . 4500 answer : e" | other |
math_qa__byxzcwpyQ6KAzqOx | The average temperature for Tuesday, Wednesday and Thursday was 45°C. The average temperature for Wednesday, Thursday and Friday was 50°C. If the temperature on Friday be 53°C, what was the Temperature on Tuesday? Options:
A) 39 ° c B) 44 ° c C) 37 ° c D) 42 ° c E) 38 c | <gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">50 * 3</gadget>
<output>150</output>
<gadget id="calculator">150 - 53</gadget>
<output>97</output>
<gadget id="calculator">135 - 97</gadget>
<output>38</output>
<result>E</result> | E | 38 | The average temperature for Tuesday, Wednesday and Thursday was 45°C. The average temperature for Wednesday, Thursday and Friday was 50°C. If the temperature on Friday be 53°C, what was the Temperature on Tuesday? | {
"A": "39 ° c",
"B": "44 ° c",
"C": "37 ° c",
"D": "42 ° c",
"E": "38 c"
} | subtract(multiply(45, const_3), subtract(multiply(50, const_3), 53)) | multiply(n0,const_3)|multiply(n1,const_3)|subtract(#1,n2)|subtract(#0,#2)| | "explanation : t + w + t = 45 × 3 = 135 ° c w + t + f = 50 × 3 = 150 ° c also , temperature on friday = 53 ° c temperature on tuesday = 135 + 53 - 150 = 38 ° c answer : option e" | physics |
math_qa__4IIj219SM9eoKwZh | If (c - a)/(c - b) = 1, then (5b - 2a)/(c - a) = Choose the correct option
A) 0.5
B) 1
C) 1.5
D) 2
E) 6 | <gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<result>E</result> | E | 6 | If (c - a)/(c - b) = 1, then (5b - 2a)/(c - a) = | {
"A": "0.5",
"B": "1",
"C": "1.5",
"D": "2",
"E": "6"
} | multiply(subtract(5, 2), 2) | subtract(n1,n2)|multiply(n2,#0) | let ' s say c = 3 , b = 2 , a = 2 so that our 1 st expression holds true . now , ibsert those numbers in the second expression and we ' ll get 6 answer e ( hopefully ) ) ) | general |
math_qa__zN1C34vNYKSPYsON | In a group of 22 boys, 13 play basketball and 15 play football. 3 of the boys play neither. how many play both ?
Pick:
A) 18
B) 20
C) 21
D) 22
E) 25 | <gadget id="calculator">13 + 15</gadget>
<output>28</output>
<gadget id="calculator">22 - 3</gadget>
<output>19</output>
<gadget id="calculator">19 - 15</gadget>
<output>4</output>
<gadget id="calculator">19 - 13</gadget>
<output>6</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">28 - 10</gadget>
<output>18</output>
<result>A</result> | A | 18 | In a group of 22 boys, 13 play basketball and 15 play football. 3 of the boys play neither. how many play both ? | {
"A": "18",
"B": "20",
"C": "21",
"D": "22",
"E": "25"
} | subtract(add(13, 15), add(subtract(subtract(22, 3), 15), subtract(subtract(22, 3), 13))) | add(n1,n2)|subtract(n0,n3)|subtract(#1,n2)|subtract(#1,n1)|add(#2,#3)|subtract(#0,#4) | 18 boys play something . if b play both , then 13 + 15 - b = 18 answer is a | other |
math_qa__EyFw2ODvdRemWmM1 | A polygon has 44 diagonals, then the number of its sides are Pick one:
A) 11 B) 9 C) 7 D) 5 E) 3 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">44 * 2</gadget>
<output>88</output>
<gadget id="calculator">88 * 4</gadget>
<output>352</output>
<gadget id="calculator">9 + 352</gadget>
<output>361</output>
<gadget id="calculator">361 ** (1/2)</gadget>
<output>19</output>
<gadget id="calculator">19 + 3</gadget>
<output>22</output>
<gadget id="calculator">22 / 2</gadget>
<output>11</output>
<result>A</result> | A | 11 | A polygon has 44 diagonals, then the number of its sides are | {
"A": "11",
"B": "9",
"C": "7",
"D": "5",
"E": "3"
} | divide(add(sqrt(add(power(const_3, const_2), multiply(multiply(44, const_2), const_4))), const_3), const_2) | multiply(n0,const_2)|power(const_3,const_2)|multiply(#0,const_4)|add(#2,#1)|sqrt(#3)|add(#4,const_3)|divide(#5,const_2) | let the number of sides be n . the number of diagonals is given by nc 2 - n therefore , nc 2 - n = 44 , n > 0 n ( n - 1 ) / 2 - n = 44 n 2 - 3 n - 88 = 0 n 2 - 11 n + 8 n - 88 = 0 n ( n - 11 ) + 8 ( n - 11 ) = 0 n = - 8 or n = 11 . answer : a | geometry |
math_qa__fHSyzAumqSbD3xNJ | The cash difference between the selling prices of an article at a profit of 2% and 6% is Rs 3. The ratio of two selling prices is Choose the correct choice from the following options.
A) 51 : 53 B) 52 : 53 C) 53 : 54 D) 54 : 55 E) none of these | <gadget id="calculator">100 + 2</gadget>
<output>102</output>
<gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">102 / 106</gadget>
<output>51/53 = around 0.962264</output>
<result>A</result> | A | 0.962264 | The cash difference between the selling prices of an article at a profit of 2% and 6% is Rs 3. The ratio of two selling prices is | {
"A": "51 : 53",
"B": "52 : 53",
"C": "53 : 54",
"D": "54 : 55",
"E": "none of these"
} | divide(add(const_100, 2), add(const_100, 6)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "explanation : let the cost price of article is rs . x required ratio = ( 102 % of x ) / ( 106 % of x ) = 102 / 106 = 51 / 53 = 51 : 53 . answer : a" | gain |
math_qa__mgu23qmz8mz1DyGo | In a certain village, 200 litres of water are required per household per month. At this rate, if there are 10 households in the village, how long (in months) will 2000 litres of water last? Select: A) 1 B) 20 C) 2 D) 200 E) 2.5 | <gadget id="calculator">200 * 10</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 2_000</gadget>
<output>1</output>
<result>A</result> | A | 1 | In a certain village, 200 litres of water are required per household per month. At this rate, if there are 10 households in the village, how long (in months) will 2000 litres of water last? | {
"A": "1",
"B": "20",
"C": "2",
"D": "200",
"E": "2.5"
} | divide(2000, multiply(200, 10)) | multiply(n0,n1)|divide(n2,#0)| | "i find it much easier to understand with real numbers , so choose ( almost ) any numbers to replace m , n and p : in a certain village , m 200 litres of water are required per household per month . at this rate , if there aren 10 households in the village , how long ( in months ) willp 2000 litres of water last ? water required is 200 * 10 = 2000 ( m * n ) water available is 2000 ( p ) it will last 1 months ( p / m * n ) answer ( a )" | gain |
math_qa__tXZHklQzo3tXYTTq | In a factory, there are 80% technicians and 20% non-technicians. If the 80% of the technicians and 20% of non-technicians are permanent employees, then the percentage of workers who are temporary is? Answers:
A) 62 % B) 68 % C) 52 % D) 22 % E) 42 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">80 * (1/5)</gadget>
<output>16</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 20</gadget>
<output>16</output>
<gadget id="calculator">16 + 16</gadget>
<output>32</output>
<gadget id="calculator">100 - 32</gadget>
<output>68</output>
<result>B</result> | B | 68 | In a factory, there are 80% technicians and 20% non-technicians. If the 80% of the technicians and 20% of non-technicians are permanent employees, then the percentage of workers who are temporary is? | {
"A": "62 %",
"B": "68 %",
"C": "52 %",
"D": "22 %",
"E": "42 %"
} | subtract(const_100, add(multiply(80, divide(20, const_100)), multiply(divide(80, const_100), 20))) | divide(n1,const_100)|divide(n0,const_100)|multiply(n0,#0)|multiply(n1,#1)|add(#2,#3)|subtract(const_100,#4)| | "total = 100 t = 80 nt = 20 80 * ( 20 / 100 ) = 24 80 * ( 20 / 100 ) = 24 16 + 16 = 32 = > 100 - 32 = 68 % answer : b" | gain |
math_qa__r2h7eHvUq3Bul3S9 | What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit? Pick one
A) 10 % B) 30 % C) 20 % D) 70 % E) 45 % | <gadget id="calculator">70 / 10</gadget>
<output>7</output>
<gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">14 / 70</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>C</result> | C | 20 | What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit? | {
"A": "10 %",
"B": "30 %",
"C": "20 %",
"D": "70 %",
"E": "45 %"
} | multiply(divide(multiply(const_2, divide(70, const_10)), 70), const_100) | divide(n1,const_10)|multiply(#0,const_2)|divide(#1,n1)|multiply(#2,const_100) | d 20 % clearly , the numbers which have 1 or 9 in the unit ' s digit , have squares that end in the digit 1 . such numbers from 1 to 70 are 1 , 9 , 11 , 19 , 21 , 29 , 31 , 39 , 41 , 49 , 51 , 59 , 61 , 69 . number of such number = 14 required percentage = ( 14 x 100 / 70 ) % = 20 % . | gain |
math_qa__T7DKlDsoMBzCNKCR | What is the measure of the radius of the circle inscribed in a triangle whose sides measure 8, 15 and 19 units? Choices: A) 2.8 units B) 6 units C) 3 units D) 5 units E) 12 units | <gadget id="calculator">(((8 + 15 + 19) / 2) * ((8 + 15 + 19) / 2 - 8) * ((8 + 15 + 19) / 2 - 15) * ((8 + 15 + 19) / 2 - 19)) ** (1/2)</gadget>
<output>6*sqrt(91) = around 57.236352</output>
<gadget id="calculator">8 + 15 + 19</gadget>
<output>42</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">(6*sqrt(91)) / 21</gadget>
<output>2*sqrt(91)/7 = around 2.725541</output>
<result>A</result> | A | 2.8 | What is the measure of the radius of the circle inscribed in a triangle whose sides measure 8, 15 and 19 units? | {
"A": "2.8 units",
"B": "6 units",
"C": "3 units",
"D": "5 units",
"E": "12 units"
} | divide(triangle_area_three_edges(8, 15, 19), divide(triangle_perimeter(8, 15, 19), const_2)) | triangle_area_three_edges(n0,n1,n2)|triangle_perimeter(n0,n1,n2)|divide(#1,const_2)|divide(#0,#2)| | "sides are 8 , 15 and 19 . . . thus it is right angle triangle since 19 ^ 2 = 8 ^ 2 + 15 ^ 2 therefore , area = 1 / 2 * 15 * 8 = 60 we have to find in - radius therefore , area of triangle = s * r . . . . where s = semi - perimeter and r = in - radius now s = semi - perimeter = 19 + 15 + 8 / 2 = 21 thus , 60 = 21 * r and hence r = in - radius = 2.8 option a" | geometry |
math_qa__WBI10M1bnwM1PsPJ | 12 is what % of 80?
Choose the correct choice from the following.
A) 6 B) 6.67 C) 12 D) 13 E) 15 | <gadget id="calculator">12 / 80</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>E</result> | E | 15 | 12 is what % of 80? | {
"A": "6",
"B": "6.67",
"C": "12",
"D": "13",
"E": "15"
} | multiply(divide(12, 80), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "we assume that 80 is 100 % assume ' x ' is value we looking for here , 80 = 100 % and x % = 12 therefore , 100 / x = 80 / 12 100 / x = 6.6667 x = 15 e" | gain |
math_qa__I58IGE9ig1igFSN0 | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $1.20 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? Select the correct option
A) $ 255 B) $ 275 C) $ 510 D) $ 612 E) $ 2,550 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">3.06 * 1_000_000</gadget>
<output>3_060_000</output>
<gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 * 15</gadget>
<output>6_000</output>
<gadget id="calculator">3_060_000 / 6_000</gadget>
<output>510</output>
<gadget id="calculator">510 * 1.2</gadget>
<output>612</output>
<result>D</result> | D | 612 | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $1.20 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? | {
"A": "$ 255",
"B": "$ 275",
"C": "$ 510",
"D": "$ 612",
"E": "$ 2,550"
} | multiply(divide(multiply(3.06, multiply(const_1000, const_1000)), multiply(multiply(20, 20), 15)), 1.2) | multiply(const_1000,const_1000)|multiply(n0,n0)|multiply(n4,#0)|multiply(n2,#1)|divide(#2,#3)|multiply(n3,#4) | total no . of boxes = 3060000 / ( 20 × 20 × 15 ) = 510 total cost = 510 × $ 1.20 = $ 612 answer d | general |
math_qa__r1APkJslz4BqPVYk | Find L.C.M of 852 and 1491 Choose the correct answer.
A) 5964 B) 5664 C) 4964 D) 4664 E) 5555 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">852 / 2</gadget>
<output>426</output>
<gadget id="calculator">426 / 2</gadget>
<output>213</output>
<gadget id="calculator">213 / 3</gadget>
<output>71</output>
<gadget id="calculator">12 * 71</gadget>
<output>852</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">852 * 7</gadget>
<output>5_964</output>
<result>A</result> | A | 5,964 | Find L.C.M of 852 and 1491 | {
"A": "5964",
"B": "5664",
"C": "4964",
"D": "4664",
"E": "5555"
} | multiply(multiply(multiply(const_3, power(const_2, const_2)), divide(divide(divide(852, const_2), const_2), const_3)), add(const_4, const_3)) | add(const_3,const_4)|divide(n0,const_2)|power(const_2,const_2)|divide(#1,const_2)|multiply(#2,const_3)|divide(#3,const_3)|multiply(#5,#4)|multiply(#0,#6) | 852 ) 1491 ( 1 852 639 ) 852 ( 1 639 213 ) 639 ( 3 639 0 h . c . f of 852 and 1491 is 213 : . l . c . m = 852 * 1491 / 213 = 5964 answer is a . | physics |
math_qa__tPv3BbDGswtqr60L | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 25 hours respectively. The ratio of their speeds is: Choose the correct choice from the following choices.
A) 2 : 3 B) 5 : 3 C) 6 : 7 D) 9 : 16 E) none of these | <gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<result>B</result> | B | 1.666667 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 25 hours respectively. The ratio of their speeds is: | {
"A": "2 : 3",
"B": "5 : 3",
"C": "6 : 7",
"D": "9 : 16",
"E": "none of these"
} | divide(sqrt(25), sqrt(9)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains as a and b . then , ( a ' s speed ) : ( b ' s speed ) = â ˆ š b : â ˆ š a = â ˆ š 25 : â ˆ š 9 = 5 : 3 . answer b" | physics |
math_qa__HuZ2HzvmTV2VT5k0 | What is the remainder when 1274 * 1275 * 1277 *1285 is divided by 12?
Choose the most appropriate option.
A) 0 B) 6 C) 11 D) 9 E) 7 | <gadget id="calculator">1_275 * 1_274</gadget>
<output>1_624_350</output>
<gadget id="calculator">1_624_350 % 1_277</gadget>
<output>6</output>
<result>B</result> | B | 6 | What is the remainder when 1274 * 1275 * 1277 *1285 is divided by 12? | {
"A": "0",
"B": "6",
"C": "11",
"D": "9",
"E": "7"
} | reminder(multiply(1275, 1274), 1277) | multiply(n0,n1)|reminder(#0,n2)| | "1271 * 1275 * 1277 * 1285 = ( 1272 - 2 ) ( 1272 + 3 ) ( 1284 - 7 ) ( 1284 + 1 ) = ( multiple of 12 - 1 ) ( multiple of 12 + 3 ) ( multiple of 12 - 7 ) ( multiple of 12 + 1 ) now , if we expand this expression all terms but the last one will have a multiple of 12 in them , thus will leave no remainder upon division by 12 , the last term will be ( - 2 ) ( 3 ) ( - 7 ) ( 1 ) = 42 . thus the question becomes : what is the remainder upon division of 42 by 12 ? the answer to this question is 6 . answer : b" | general |
math_qa__ZG0gWvOMD0Hv7oNf | How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches? Choose the correct choice from the following answers.
A) 50 % B) 87 % C) 100 % D) 187 % E) 200 % | <gadget id="calculator">11 * 17</gadget>
<output>187</output>
<gadget id="calculator">187 * 2</gadget>
<output>374</output>
<gadget id="calculator">8.5 * 11</gadget>
<output>93.5</output>
<gadget id="calculator">93.5 * 2</gadget>
<output>187</output>
<gadget id="calculator">374 - 187</gadget>
<output>187</output>
<gadget id="calculator">187 / 187</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>C</result> | C | 100 | How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches? | {
"A": "50 %",
"B": "87 %",
"C": "100 %",
"D": "187 %",
"E": "200 %"
} | multiply(divide(subtract(multiply(rectangle_area(11, 17), const_2), multiply(rectangle_area(8.5, 11), const_2)), rectangle_area(11, 17)), const_100) | rectangle_area(n0,n1)|rectangle_area(n0,n2)|multiply(#0,const_2)|multiply(#1,const_2)|subtract(#2,#3)|divide(#4,#0)|multiply(#5,const_100)| | "area of sheet a = 11 * 17 area of sheet b = 11 * 8.5 difference in area = 11 * 8.5 required % = ( 11 * 8.5 ) * 100 / ( 11 * 8.5 ) % = 100 % answer : c" | geometry |
math_qa__ZIuzF9vUdTsXl8Do | Yearly subscription to professional magazines cost a company $940.00. To Make a 35% cut in the magazine budget, how much less must be spent?
Options: A) 654 B) 655 C) 611 D) 657 E) 658 | <gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) * 940</gadget>
<output>611</output>
<result>C</result> | C | 611 | Yearly subscription to professional magazines cost a company $940.00. To Make a 35% cut in the magazine budget, how much less must be spent? | {
"A": "654",
"B": "655",
"C": "611",
"D": "657",
"E": "658"
} | multiply(divide(subtract(const_100, 35), const_100), 940.00) | subtract(const_100,n1)|divide(#0,const_100)|multiply(n0,#1)| | "total cost 940 940 * 35 / 100 = 329 so the cut in amount is 329 the less amount to be spend is 940 - 329 = 611 answer : c" | general |
math_qa__INThWC6e8FtAYox4 | Rates for having a manuscript typed at a certain typing service are $10 per page for the first time a page is typed and $5 per page each time a page is revised. If a certain manuscript has 100 pages, of which 20 were revised only once, 30 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed?
Choose one.
A) $ 1200
B) $ 1500
C) $ 1400
D) $ 1250
E) $ 1350 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">1_000 + 100</gadget>
<output>1_100</output>
<gadget id="calculator">30 * 5</gadget>
<output>150</output>
<gadget id="calculator">150 * 2</gadget>
<output>300</output>
<gadget id="calculator">1_100 + 300</gadget>
<output>1_400</output>
<result>C</result> | C | 1,400 | Rates for having a manuscript typed at a certain typing service are $10 per page for the first time a page is typed and $5 per page each time a page is revised. If a certain manuscript has 100 pages, of which 20 were revised only once, 30 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed? | {
"A": "$ 1200",
"B": "$ 1500",
"C": "$ 1400",
"D": "$ 1250",
"E": "$ 1350"
} | add(add(multiply(100, 10), multiply(20, 5)), multiply(multiply(30, 5), const_2)) | multiply(n0,n2)|multiply(n1,n3)|multiply(n1,n4)|add(#0,#1)|multiply(#2,const_2)|add(#3,#4)| | "50 pages typed 1 x 20 pages typed 2 x ( original + one revision ) 30 pages typed 3 x ( original + two revisions ) 50 ( 10 ) + 20 ( 10 + 5 ) + 30 ( 10 + 5 + 5 ) = 500 + 300 + 600 = 1400 answer - c" | general |
math_qa__IBV4XfUy01WTY5Ii | The average (arithmetic mean) of 20, 40, and 60 is 7 more than the average of 10, 70, and what number? Select: A) 19 B) 25 C) 35 D) 45 E) 55 | <gadget id="calculator">20 + 40</gadget>
<output>60</output>
<gadget id="calculator">60 + 60</gadget>
<output>120</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 10</gadget>
<output>31</output>
<gadget id="calculator">31 + 70</gadget>
<output>101</output>
<gadget id="calculator">120 - 101</gadget>
<output>19</output>
<result>A</result> | A | 19 | The average (arithmetic mean) of 20, 40, and 60 is 7 more than the average of 10, 70, and what number? | {
"A": "19",
"B": "25",
"C": "35",
"D": "45",
"E": "55"
} | subtract(add(add(20, 40), 60), add(add(multiply(7, const_3), 10), 70)) | add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4)| | "a 1 = 120 / 3 = 40 a 2 = a 1 - 7 = 33 sum of second list = 33 * 3 = 99 therefore the number = 99 - 80 = 19 answer : a" | general |
math_qa__HbjsYTuYHhSilksM | There are 2 sections A and B in a class, consisting of 50 and 40 students respectively. If the average weight of section A is 50kg and that of section B is 70kg, Find the average of the whole class? Choose one
A) 50.78 kg
B) 49.32 kg
C) 61.67 kg
D) 58.88 kg
E) 70.89 kg | <gadget id="calculator">50 * 50</gadget>
<output>2_500</output>
<gadget id="calculator">40 * 70</gadget>
<output>2_800</output>
<gadget id="calculator">2_500 + 2_800</gadget>
<output>5_300</output>
<gadget id="calculator">50 + 40</gadget>
<output>90</output>
<gadget id="calculator">5_300 / 90</gadget>
<output>530/9 = around 58.888889</output>
<result>D</result> | D | 58.88 | There are 2 sections A and B in a class, consisting of 50 and 40 students respectively. If the average weight of section A is 50kg and that of section B is 70kg, Find the average of the whole class? | {
"A": "50.78 kg",
"B": "49.32 kg",
"C": "61.67 kg",
"D": "58.88 kg",
"E": "70.89 kg"
} | divide(add(multiply(50, 50), multiply(40, 70)), add(50, 40)) | add(n1,n2)|multiply(n1,n3)|multiply(n2,n4)|add(#1,#2)|divide(#3,#0)| | "total weight of 50 + 40 students = 50 * 50 + 40 * 70 = 2500 + 2800 average weight of the class is = 5300 / 90 = 58.88 kg answer is d" | general |
math_qa__c7tCMWP2I2X6U35X | Dan's age after 20 years will be 7 times his age 4 years ago. What is the present age of Dan? Choose the correct choice from the following options: A) 6 B) 8 C) 10 D) 12 E) 14 | <gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">20 + 28</gadget>
<output>48</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">48 / 6</gadget>
<output>8</output>
<result>B</result> | B | 8 | Dan's age after 20 years will be 7 times his age 4 years ago. What is the present age of Dan? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | divide(add(20, multiply(4, 7)), subtract(7, const_1)) | multiply(n1,n2)|subtract(n1,const_1)|add(n0,#0)|divide(#2,#1)| | "let dan ' s present age be x . x + 20 = 7 ( x - 4 ) 6 x = 48 x = 8 the answer is b ." | general |
math_qa__uz4hazXuotgr40Va | A work as fast as B. If B can complete a work in 12days independently,the number of days in which A and B can together finish the work in? Choose the most appropriate option: A) 2 days B) 3 days C) 4 days D) 5 days E) 6 days | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 * (1/12)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/12) + (1/6)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<result>C</result> | C | 4 | A work as fast as B. If B can complete a work in 12days independently,the number of days in which A and B can together finish the work in? | {
"A": "2 days",
"B": "3 days",
"C": "4 days",
"D": "5 days",
"E": "6 days"
} | inverse(add(inverse(12), multiply(const_2, inverse(12)))) | inverse(n0)|multiply(#0,const_2)|add(#0,#1)|inverse(#2) | ratio of rates of working of a and b = 2 : 1 ratio of times taken = 1 : 2 a ' s 1 day work = 1 / 6 b ' s 1 day work = 1 / 12 a + b 1 day work = 1 / 6 + 1 / 12 = 3 / 12 = 1 / 4 a and b can finish the work in 4 days answer is c | physics |
math_qa__JsNCWM1J5fmxVeB1 | In a group of 6 boys&4 girls a Committee of 4 persons is to be formed. In how many different ways can it be done so that the committee has at least 1girl? Choose the correct answer:
A) 187
B) 190
C) 192
D) 195
E) 213 | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">24 * 720</gadget>
<output>17_280</output>
<gadget id="calculator">3_628_800 / 17_280</gadget>
<output>210</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">720 / 48</gadget>
<output>15</output>
<gadget id="calculator">210 - 15</gadget>
<output>195</output>
<result>D</result> | D | 195 | In a group of 6 boys&4 girls a Committee of 4 persons is to be formed. In how many different ways can it be done so that the committee has at least 1girl? | {
"A": "187",
"B": "190",
"C": "192",
"D": "195",
"E": "213"
} | subtract(divide(factorial(add(6, 4)), multiply(factorial(4), factorial(6))), divide(factorial(6), multiply(factorial(const_2), factorial(4)))) | add(n0,n1)|factorial(n1)|factorial(n0)|factorial(const_2)|factorial(#0)|multiply(#1,#2)|multiply(#3,#1)|divide(#4,#5)|divide(#2,#6)|subtract(#7,#8) | the committee of 4 persons is to be so formed that it has at least 1 woman the different ways that we can choose to form such a committee are : ( i ) lw . 3 m in t 6 x 5 x 4 ' x 6 c 3 = 4 x — — 80 3 x 2 x 1 x 6 c 2 = 42 : : x 26 : : = 90 ( ii ) 2 w . 2 m in ° c 2 ( iii ) 3 w . 1 m in 4 c 3 x 6 c 1 = 4 x 6 = 24 ( iv ) 4 w in 6 c 4 = 1 total no . of different ways in which a committee of 4 persons can be formed so that it has at least one woman . = 80 + 90 + 24 + 1 = 195 d | other |
math_qa__sJkyTQ7EwoiUXPD3 | Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is Pick one.
A) 1.967
B) 1.963
C) 2.388
D) 3.388
E) 2.382 | <gadget id="calculator">3.5 * 2</gadget>
<output>7</output>
<gadget id="calculator">(((7 + 7 + 7) / 2) * ((7 + 7 + 7) / 2 - 7) * ((7 + 7 + 7) / 2 - 7) * ((7 + 7 + 7) / 2 - 7)) ** (1/2)</gadget>
<output>49*sqrt(3)/4 = around 21.217622</output>
<gadget id="calculator">pi * (3.5 ** 2)</gadget>
<output>12.25*pi = around 38.48451</output>
<gadget id="calculator">(12.25*pi) / 2</gadget>
<output>6.125*pi = around 19.242255</output>
<gadget id="calculator">(49*sqrt(3)/4) - (6.125*pi)</gadget>
<output>-6.125*pi + 49*sqrt(3)/4 = around 1.975367</output>
<result>A</result> | A | 1.967 | Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is | {
"A": "1.967",
"B": "1.963",
"C": "2.388",
"D": "3.388",
"E": "2.382"
} | subtract(triangle_area_three_edges(multiply(3.5, const_2), multiply(3.5, const_2), multiply(3.5, const_2)), divide(circle_area(3.5), const_2)) | circle_area(n0)|multiply(n0,const_2)|divide(#0,const_2)|triangle_area_three_edges(#1,#1,#1)|subtract(#3,#2) | explanation : required area = ( area of an equilateral triangle of side 7 cm ) - ( 3 * area of sector with ã = 60 degrees and r = 3.5 cm ) \ inline { \ color { black } ( \ frac { \ sqrt { 3 } } { 4 } \ times 7 \ times 7 ) - ( 3 \ times \ frac { 22 } { 7 } \ times 3.5 \ times 3.5 \ times \ frac { 60 } { 360 } ) } sq cm = \ inline { \ color { black } ( \ frac { \ sqrt { 3 } } { 4 } \ times 49 ) - ( 11 \ times 0.5 \ times 3.5 ) } sq cm = 1.967 sq cm answer : a ) 1.967 | geometry |
math_qa__hg6wjcPlRLatBvrm | 2a
33
+ b9
____
99
If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 3b ? Select:
A) 2
B) 7
C) 9
D) 11
E) 12 | <gadget id="calculator">9 + 2</gadget>
<output>11</output>
<result>D</result> | D | 11 | 2a
33
+ b9
____
99
If a and b represent positive single digits in the correctly worked computation above, what is the value of a + 3b ? | {
"A": "2",
"B": "7",
"C": "9",
"D": "11",
"E": "12"
} | add(9, 2) | add(n0,n2) | adding the digits in unit ' s place , a + 3 + 9 = 19 ( since a and b are positive single digits ) = > a = 7 now adding the digits in ten ' s place , 2 + 3 + b + 1 = 9 ( 1 has been carried over from nit ' s place addition ) = > b = 3 a + 3 b = 2 + 2 * 3 = 11 answer d | physics |
math_qa__iKZ0SNvz7tXDmiCg | A man two flats for $675958 each. On one he gains 11% while on the other he loses 11%. How much does he gain or lose in the whole transaction?
Select:
A) 1.21 %
B) 2.56 %
C) 3.12 %
D) 4.65 %
E) 5.12 % | <gadget id="calculator">100 + 11</gadget>
<output>111</output>
<gadget id="calculator">100 / 111</gadget>
<output>100/111 = around 0.900901</output>
<gadget id="calculator">(100/111) * 675_958</gadget>
<output>67_595_800/111 = around 608_971.171171</output>
<gadget id="calculator">100 - 11</gadget>
<output>89</output>
<gadget id="calculator">100 / 89</gadget>
<output>100/89 = around 1.123596</output>
<gadget id="calculator">(100/89) * 675_958</gadget>
<output>67_595_800/89 = around 759_503.370787</output>
<gadget id="calculator">(67_595_800/111) + (67_595_800/89)</gadget>
<output>13_519_160_000/9_879 = around 1_368_474.541958</output>
<gadget id="calculator">675_958 + 675_958</gadget>
<output>1_351_916</output>
<gadget id="calculator">(13_519_160_000/9_879) - 1_351_916</gadget>
<output>163_581_836/9_879 = around 16_558.541958</output>
<gadget id="calculator">(163_581_836/9_879) / (13_519_160_000/9_879)</gadget>
<output>121/10_000 = around 0.0121</output>
<gadget id="calculator">(121/10_000) * 100</gadget>
<output>121/100 = around 1.21</output>
<result>A</result> | A | 1.21 | A man two flats for $675958 each. On one he gains 11% while on the other he loses 11%. How much does he gain or lose in the whole transaction? | {
"A": "1.21 %",
"B": "2.56 %",
"C": "3.12 %",
"D": "4.65 %",
"E": "5.12 %"
} | multiply(divide(subtract(add(multiply(divide(const_100, add(const_100, 11)), 675958), multiply(divide(const_100, subtract(const_100, 11)), 675958)), add(675958, 675958)), add(multiply(divide(const_100, add(const_100, 11)), 675958), multiply(divide(const_100, subtract(const_100, 11)), 675958))), const_100) | add(n1,const_100)|add(n0,n0)|subtract(const_100,n1)|divide(const_100,#0)|divide(const_100,#2)|multiply(n0,#3)|multiply(n0,#4)|add(#5,#6)|subtract(#7,#1)|divide(#8,#7)|multiply(#9,const_100)| | "in such a case there is always a loss loss % = ( 11 / 10 ) ^ 2 = 23 / 19 = 1.21 % answer is a" | gain |
math_qa__07URJaCaqgkMN4ko | What is the ratio between perimeters of two squares one having 2 times the diagonal then the other? Options
A) 3 : 8 B) 3 : 6 C) 3 : 7 D) 2 : 1 E) 3 : 3 | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">2 / 1</gadget>
<output>2</output>
<result>D</result> | D | 2 | What is the ratio between perimeters of two squares one having 2 times the diagonal then the other? | {
"A": "3 : 8",
"B": "3 : 6",
"C": "3 : 7",
"D": "2 : 1",
"E": "3 : 3"
} | divide(2, divide(2, 2)) | divide(n0,n0)|divide(n0,#0)| | "d = 2 d d = d a √ 2 = 2 d a √ 2 = d a = 2 d / √ 2 a = d / √ 2 = > 2 : 1 answer : d" | geometry |
math_qa__5uUBnYAcrXrAzREP | Richard traveled the entire 60 miles trip. If he did the first 2 miles of at a constant rate 24 miles per hour and the remaining trip of at a constant rate 48 miles per hour, what is the his average speed, in miles per hour? Choose the correct choice: A) 20 mph B) 24 mph C) 30 mph D) 32 mph E) 55 mph | <gadget id="calculator">60 - 2</gadget>
<output>58</output>
<gadget id="calculator">58 / 48</gadget>
<output>29/24 = around 1.208333</output>
<gadget id="calculator">2 / 24</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(29/24) - (1/12)</gadget>
<output>9/8 = around 1.125</output>
<gadget id="calculator">60 / (9/8)</gadget>
<output>160/3 = around 53.333333</output>
<result>E</result> | E | 55 | Richard traveled the entire 60 miles trip. If he did the first 2 miles of at a constant rate 24 miles per hour and the remaining trip of at a constant rate 48 miles per hour, what is the his average speed, in miles per hour? | {
"A": "20 mph",
"B": "24 mph",
"C": "30 mph",
"D": "32 mph",
"E": "55 mph"
} | divide(60, subtract(divide(subtract(60, 2), 48), divide(2, 24))) | divide(n1,n2)|subtract(n0,n1)|divide(#1,n3)|subtract(#2,#0)|divide(n0,#3) | average speed = sum of distance / sum of time . if he travelled the first 2 miles at 24 miles / hr , it would take 0.083 hr . for the remaining trip , if he went at 48 miles / 1 hr , it would take 1 hour . then , the average speed is 60 miles / ( 0.083 + 1 ) hrs = 55 miles / 1 hr . therefore , the answer is e . | physics |
math_qa__WXjRzqDYP0cNzYUE | A man’s current age is (2/5) of the age of his father. After 8 years, he will be (1/2) of the age of his father. What is the age of father at now? Choices
A) 40
B) 45
C) 38
D) 50
E) 39 | <gadget id="calculator">2 / 1</gadget>
<output>2</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">16 - 8</gadget>
<output>8</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 2</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">8 / (1/5)</gadget>
<output>40</output>
<result>A</result> | A | 40 | A man’s current age is (2/5) of the age of his father. After 8 years, he will be (1/2) of the age of his father. What is the age of father at now? | {
"A": "40",
"B": "45",
"C": "38",
"D": "50",
"E": "39"
} | divide(subtract(multiply(8, divide(2, 1)), 8), subtract(const_1, multiply(divide(2, 5), divide(2, 1)))) | divide(n0,n3)|divide(n0,n1)|multiply(n2,#0)|multiply(#1,#0)|subtract(#2,n2)|subtract(const_1,#3)|divide(#4,#5) | a 40 let , father ’ s current age is a years . then , man ’ s current age = [ ( 2 / 5 ) a ] years . therefore , [ ( 2 / 5 ) a + 8 ] = ( 1 / 2 ) ( a + 8 ) 2 ( 2 a + 40 ) = 5 ( a + 8 ) a = 40 | general |
math_qa__Cyg799Q7Sesprk75 | A feed store sells two varieties of birdseed: Brand A, which is 60% millet and 40% sunflower, and Brand B, which is 65% millet and 35% safflower. If a customer purchases a mix of the two types of birdseed that is 50% millet, what percent of the mix is Brand A? Choose the correct choice from the following: A) 40 % B) 60 % C) 50 % D) 45 % E) 55 % | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>B</result> | B | 60 | A feed store sells two varieties of birdseed: Brand A, which is 60% millet and 40% sunflower, and Brand B, which is 65% millet and 35% safflower. If a customer purchases a mix of the two types of birdseed that is 50% millet, what percent of the mix is Brand A? | {
"A": "40 %",
"B": "60 %",
"C": "50 %",
"D": "45 %",
"E": "55 %"
} | multiply(divide(const_3, add(const_3, const_2)), const_100) | add(const_2,const_3)|divide(const_3,#0)|multiply(#1,const_100) | yes there is a simple method : consider the following method brand a : 60 % millet and 40 % sunflower brand b : 65 % millet and 35 % safflower mix : 50 % millet here the weighted average is 50 % , now brand a has 60 % millet , which is 10 % more than the weighted average of mix = + 0.10 a - - - - - - - - - - - - - - - i similarly , brand b has 65 % millet , which is 15 % more than the weighted average of mix = + 0.15 b - - - - - - - - - - - - ii now , both brand a and brand b are combined to give a 50 % mix containing millet , so equate i and ii implies , 0.10 a = 0.15 b therefore a / b = 0.15 / 0.10 = 3 / 2 a : b : ( a + b ) = 3 : 2 : ( 3 + 2 ) = 3 : 2 : 5 we have to find , percent of the mix is brand a i . e . a : ( a + b ) = 3 : 5 = ( 3 / 5 ) * 100 = 60 % here is a pictorial representation : brand a = 60 % - - - - - - - - - - - - - - - - - - - - - - - - 10 % or 0.10 above average , a times - - - - - - - - - - - - - - - - - total above = + 0.10 a - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - average = 50 % or 0.50 brand b = 65 % - - - - - - - - - - - - - - - - - - - - - - - - - - 15 % or 0.15 above average , b times - - - - - - - - - - - - - - - - - total above = + 0.15 b since the amount below the average has to equal the average above the average ; therefore , 0.10 a = 0.15 b a / b = 3 / 2 a : b : total = 3 : 2 : 5 therefore a / total = 3 : 5 = 60 % answer : b | gain |
math_qa__aPUPR6pdIfdFbTiR | The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 40 years, was replaced by a new person. Find the age of the new person?
Choose the correct choice.
A) 18
B) 56
C) 12
D) 17
E) 10 | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<result>E</result> | E | 10 | The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 40 years, was replaced by a new person. Find the age of the new person? | {
"A": "18",
"B": "56",
"C": "12",
"D": "17",
"E": "10"
} | subtract(40, multiply(10, 3)) | multiply(n0,n1)|subtract(n2,#0)| | "initial average age of the 10 persons be p . age of the new person q . sum of the ages of the initial 10 persons = 10 p new average = ( p - 3 ) 10 ( p - 3 ) = 10 p - 40 + q = > q = 10 answer : e" | general |
math_qa__b2FdCYNgWrxGjyU6 | An error 12% in excess is made while measuring the side of a square. Now What is the percentage of error in the calculated area of the square? Answers.
A) 6.64 % B) 16.64 % C) 15.64 % D) 25.44 % E) 10.64 % | <gadget id="calculator">100 + 12</gadget>
<output>112</output>
<gadget id="calculator">112 ** 2</gadget>
<output>12_544</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">12_544 - 10_000</gadget>
<output>2_544</output>
<gadget id="calculator">2_544 * 100</gadget>
<output>254_400</output>
<gadget id="calculator">254_400 / 10_000</gadget>
<output>636/25 = around 25.44</output>
<result>D</result> | D | 25.44 | An error 12% in excess is made while measuring the side of a square. Now What is the percentage of error in the calculated area of the square? | {
"A": "6.64 %",
"B": "16.64 %",
"C": "15.64 %",
"D": "25.44 %",
"E": "10.64 %"
} | divide(multiply(subtract(square_area(add(const_100, 12)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "percentage error in calculated area = ( 12 + 12 + ( 12 ã — 12 ) / 100 ) % = 25.44 % answer : d" | gain |
math_qa__CVNXzHTTGmMedR4E | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 56 ounces of this substance? Choose the correct choice from the following answers:
A) 27
B) 36
C) 42
D) 24
E) 147 | <gadget id="calculator">48 / 112</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 56</gadget>
<output>24</output>
<result>D</result> | D | 24 | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 56 ounces of this substance? | {
"A": "27",
"B": "36",
"C": "42",
"D": "24",
"E": "147"
} | multiply(divide(48, 112), 56) | divide(n0,n1)|multiply(n2,#0)| | "112 ounces of a substance has a volume of 48 cubic inches 56 ounces of a substance has a volume of ( 48 / 112 ) * 56 = 24 cubic inches answer d" | geometry |
math_qa__LRWHhfaevWEq1VhV | 800 is increased by 110%. Find the final number. Choose the correct choice from the following:
A) 1200 B) 1210 C) 1180 D) 1190 E) 1680 | <gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">800 * (11/10)</gadget>
<output>880</output>
<gadget id="calculator">800 + 880</gadget>
<output>1_680</output>
<result>E</result> | E | 1,680 | 800 is increased by 110%. Find the final number. | {
"A": "1200",
"B": "1210",
"C": "1180",
"D": "1190",
"E": "1680"
} | add(800, multiply(800, divide(110, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | explanation final number = initial number + 110 % ( original number ) = 800 + 110 % ( 800 ) = 800 + 880 = 1680 . answer e | gain |
math_qa__FpqHchA8D3rsEGwf | Company KW is being sold, and both Company A and Company B were considering the purchase. The price of Company KW is 40% more than Company A has in assets, and this same price is also 100% more than Company B has in assets. If Companies A and B were to merge and combine their assets, the price of Company KW would be approximately what percent of these combined assets? Choose the correct choice from the following choices.
A) 66 % B) 75 % C) 82 % D) 116 % E) 150 % | <gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">140 / 2</gadget>
<output>70</output>
<gadget id="calculator">100 + 70</gadget>
<output>170</output>
<gadget id="calculator">140 / 170</gadget>
<output>14/17 = around 0.823529</output>
<gadget id="calculator">(14/17) * 100</gadget>
<output>1_400/17 = around 82.352941</output>
<result>C</result> | C | 82 | Company KW is being sold, and both Company A and Company B were considering the purchase. The price of Company KW is 40% more than Company A has in assets, and this same price is also 100% more than Company B has in assets. If Companies A and B were to merge and combine their assets, the price of Company KW would be approximately what percent of these combined assets? | {
"A": "66 %",
"B": "75 %",
"C": "82 %",
"D": "116 %",
"E": "150 %"
} | multiply(divide(add(100, 40), add(100, divide(add(100, 40), const_2))), 100) | add(n0,n1)|divide(#0,const_2)|add(n1,#1)|divide(#0,#2)|multiply(#3,n1)| | "let the price of company a ' s assets be 100 price of assets of kw is 40 % more than company a ' s assets which is 140 price of assets of kw is 100 % more than company b ' s assets which means price of company b ' s assets is half the price of kw = 70 a + b = 170 kw = 140 kw / ( a + b ) * 100 = 140 / 170 * 100 = 82.35 % or 82 % c" | gain |
math_qa__47ZdHcURpgd65P3i | If A:B = 2:3, B:C = 4:5 and C:D = 5:9 then A:D is equal to: Choose the correct choice from the following options
A) 11 : 17 B) 8 : 27 C) 5 : 9 D) 2 : 9 E) none | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 9</gadget>
<output>135</output>
<gadget id="calculator">40 / 135</gadget>
<output>8/27 = around 0.296296</output>
<result>B</result> | B | 0.296296 | If A:B = 2:3, B:C = 4:5 and C:D = 5:9 then A:D is equal to: | {
"A": "11 : 17",
"B": "8 : 27",
"C": "5 : 9",
"D": "2 : 9",
"E": "none"
} | divide(multiply(multiply(2, 4), 5), multiply(multiply(3, 5), 9)) | multiply(n0,n2)|multiply(n1,n3)|multiply(n4,#0)|multiply(n5,#1)|divide(#2,#3)| | "solution : a / d = ( a / b ) * ( b * c ) * ( c / d ) = ( 2 / 3 ) * ( 4 / 5 ) * ( 5 / 9 ) = ( 2 * 4 * 5 ) / ( 3 * 5 * 9 ) = 8 / 27 . answer : option b" | general |
math_qa__Od85V2L5Ax2W8F2l | If an integer n is to be selected at random from 1 to 105, inclusive, what is probability n(n+1) will be divisible by 7? Choose the correct choice from the following choices.
A) 1 / 7 B) 3 / 14 C) 1 / 2 D) 2 / 7 E) 3 / 4 | <gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<result>D</result> | D | 0.285714 | If an integer n is to be selected at random from 1 to 105, inclusive, what is probability n(n+1) will be divisible by 7? | {
"A": "1 / 7",
"B": "3 / 14",
"C": "1 / 2",
"D": "2 / 7",
"E": "3 / 4"
} | divide(const_2, 7) | divide(const_2,n3)| | "for n ( n + 1 ) to be a multiple of 7 , either n or n + 1 has to be a multiple of 7 . thus n must be of the form 7 k or 7 k - 1 . the probability is 2 / 7 . the answer is d ." | general |
math_qa__TIT5qsNRFr6oRFHI | The average height of 35 boys in a class was calculated as 184cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).? Choose the correct answer:
A) 178.27 cm B) 182.29 cm C) 978.29 cm D) 178.89 cm E) 176.29 cm | <gadget id="calculator">35 * 184</gadget>
<output>6_440</output>
<gadget id="calculator">6_440 - 166</gadget>
<output>6_274</output>
<gadget id="calculator">6_274 + 106</gadget>
<output>6_380</output>
<gadget id="calculator">6_380 / 35</gadget>
<output>1_276/7 = around 182.285714</output>
<gadget id="calculator">floor(1_276/7)</gadget>
<output>182</output>
<result>B</result> | B | 182.29 | The average height of 35 boys in a class was calculated as 184cm. It has later found that the height of one of the boys in the class was wrongly written as 166 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).? | {
"A": "178.27 cm",
"B": "182.29 cm",
"C": "978.29 cm",
"D": "178.89 cm",
"E": "176.29 cm"
} | floor(divide(add(subtract(multiply(35, 184), 166), 106), 35)) | multiply(n0,n1)|subtract(#0,n2)|add(n3,#1)|divide(#2,n0)|floor(#3)| | "calculated average height of 35 boys = 184 cm . wrong total height of 35 boys = 184 * 35 cm . this was as a result of an actual height of 106 cm being wrongly written as 166 cm . correct total height of 35 boys = 184 cm - ( 166 cm - 106 cm ) / 35 = 184 cm - 60 / 35 cm = 184 cm - 1.71 cm = 182.29 cm . answer : b" | general |
math_qa__lK7E9pvcrfVGVTEX | All the students of class are told to sit in circle shape. Here the boy at the 7 th position is exactly opposite to 27 th boy. Total number of boys in the class? Pick:
A) 25 B) 40 C) 35 D) 30 E) 28 | <gadget id="calculator">27 - 7</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<result>B</result> | B | 40 | All the students of class are told to sit in circle shape. Here the boy at the 7 th position is exactly opposite to 27 th boy. Total number of boys in the class? | {
"A": "25",
"B": "40",
"C": "35",
"D": "30",
"E": "28"
} | multiply(subtract(27, 7), const_2) | subtract(n1,n0)|multiply(#0,const_2)| | "as half the circle shape consist of 27 - 7 = 20 boys , so total number of boys in full circle = 2 * 20 = 40 answer : b" | general |
math_qa__foIgqxhl2efpLgPB | On my sister's birthday, she was 132 cm in height, having grown 10% since the year before. How tall was she the previous year?
Choices
A) 130 cm B) 126 cm C) 120 cm D) 116 cm E) 112 cm | <gadget id="calculator">132 * 10</gadget>
<output>1_320</output>
<gadget id="calculator">1_320 / 100</gadget>
<output>66/5 = around 13.2</output>
<gadget id="calculator">132 - (66/5)</gadget>
<output>594/5 = around 118.8</output>
<result>C</result> | C | 120 | On my sister's birthday, she was 132 cm in height, having grown 10% since the year before. How tall was she the previous year? | {
"A": "130 cm",
"B": "126 cm",
"C": "120 cm",
"D": "116 cm",
"E": "112 cm"
} | subtract(132, divide(multiply(132, 10), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)| | "let the previous year ' s height be x . 1.1 x = 132 x = 120 the answer is c ." | physics |
math_qa__xoAy9ukFoAIiIViG | A $72.95 lawn chair was sold for $59.95 at a special sale. By approximately what percent was the price decreased? Answers:
A) 18 %
B) 20 %
C) 25 %
D) 60 %
E) 80 % | <gadget id="calculator">72.95 - 59.95</gadget>
<output>13</output>
<gadget id="calculator">13 / 72.95</gadget>
<output>0.178204</output>
<gadget id="calculator">0.178204 * 100</gadget>
<output>17.8204</output>
<result>A</result> | A | 18 | A $72.95 lawn chair was sold for $59.95 at a special sale. By approximately what percent was the price decreased? | {
"A": "18 %",
"B": "20 %",
"C": "25 %",
"D": "60 %",
"E": "80 %"
} | multiply(divide(subtract(72.95, 59.95), 72.95), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100) | listed selling price of chair = 72.95 $ discounted selling price of chair = 59.95 $ discount = 72.95 - 59.95 = 13 $ % decrease in price of chair = ( 13 / 72.95 ) * 100 % = 18 % approx answer a | general |
math_qa__VpC2bYQLO1NcpJ0A | If shares of two persons in profits are Rs.400 and Rs.800 then ratio of their capitals is
Select
A) 3 : 4 B) 2 : 3 C) 4 : 3 D) 1 : 3 E) 1 : 2 | <gadget id="calculator">400 / 800</gadget>
<output>1/2 = around 0.5</output>
<result>E</result> | E | 0.5 | If shares of two persons in profits are Rs.400 and Rs.800 then ratio of their capitals is | {
"A": "3 : 4",
"B": "2 : 3",
"C": "4 : 3",
"D": "1 : 3",
"E": "1 : 2"
} | divide(400, 800) | divide(n0,n1)| | "profit = time * capital so 400 : 800 = 1 : 2 answer : e" | other |
math_qa__Kln7C4O3eWAD7gu8 | If an investor puts $1000 in a savings account that earns 10 percent annual interest compounded semiannually, how much money will be in the account after one year? Choose the correct choice from the following answers
A) $ 1100.25 B) $ 1100.75 C) $ 1101.25 D) $ 1101.75 E) $ 1102.50 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">1_000 * (441/400)</gadget>
<output>2_205/2 = around 1_102.5</output>
<result>E</result> | E | 1,102.5 | If an investor puts $1000 in a savings account that earns 10 percent annual interest compounded semiannually, how much money will be in the account after one year? | {
"A": "$ 1100.25",
"B": "$ 1100.75",
"C": "$ 1101.25",
"D": "$ 1101.75",
"E": "$ 1102.50"
} | multiply(1000, power(add(const_1, divide(divide(10, const_2), const_100)), const_2)) | divide(n1,const_2)|divide(#0,const_100)|add(#1,const_1)|power(#2,const_2)|multiply(n0,#3)| | "1.05 * 1.05 * 1000 = $ 1102.50 the answer is e ." | gain |
math_qa__HVCbTxKIBrFbKMha | At an international conference, “Red” world countries and “Blue” world countries are the only participants. The ratio of “Red” world participants to “Blue” world participants is 7:3. If one-third of “Red” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed?
Options
A) 45 / 21 B) 46 / 2 C) 13 / 30 D) 23 / 6 E) 4 / 6 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">7 * (1/3)</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">3 * (2/3)</gadget>
<output>2</output>
<gadget id="calculator">(7/3) + 2</gadget>
<output>13/3 = around 4.333333</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">(13/3) / 10</gadget>
<output>13/30 = around 0.433333</output>
<result>C</result> | C | 0.433333 | At an international conference, “Red” world countries and “Blue” world countries are the only participants. The ratio of “Red” world participants to “Blue” world participants is 7:3. If one-third of “Red” world participants are left-handed and two-thirds of “Blue” world participants are left-handed, then what is the fraction of the participants who are left-handed? | {
"A": "45 / 21",
"B": "46 / 2",
"C": "13 / 30",
"D": "23 / 6",
"E": "4 / 6"
} | divide(add(multiply(7, const_0_33), multiply(3, divide(const_2, const_3))), add(7, 3)) | add(n0,n1)|divide(const_2,const_3)|multiply(n0,const_0_33)|multiply(n1,#1)|add(#2,#3)|divide(#4,#0)| | "red : blue = 7 : 3 let red = 7 x and blue = 3 x 1 / 3 of red are left handed = > 1 / 3 * 7 x = 7 x / 3 red left handed 2 / 3 of blue are left handed = > 2 / 3 * 3 x = 6 x / 3 blue left handed fraction of participants who are left handed = total left handed / total participants = ( red left handed + blue left handed ) / total participants = ( 7 x / 3 + 6 x / 3 ) / ( 7 x + 3 x ) = 13 / 30 answer : c" | other |
math_qa__RpREAd3HfYqdytoV | If 60% of a number is greater than 30% of 10 by 27, what is the number? Choose one: A) 50 B) 100 C) 30 D) 75 E) 5 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 30</gadget>
<output>3</output>
<gadget id="calculator">27 + 3</gadget>
<output>30</output>
<gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 * (1/2)</gadget>
<output>50</output>
<result>A</result> | A | 50 | If 60% of a number is greater than 30% of 10 by 27, what is the number? | {
"A": "50",
"B": "100",
"C": "30",
"D": "75",
"E": "5"
} | multiply(const_100, divide(add(27, multiply(divide(10, const_100), 30)), 60)) | divide(n2,const_100)|multiply(n1,#0)|add(n3,#1)|divide(#2,n0)|multiply(#3,const_100) | explanation : 60 / 100 * x - 30 / 100 * 10 = 27 60 / 100 * x - 3 = 27 60 / 100 * x = 30 x = 30 * 100 / 60 x = 50 answer : option a | gain |
math_qa__mTReNVlKZHyJDGfV | (0.96)(power 3) - (0.1)(power 3)/ (0.96)(power 2) + 0.096 + (0.1)(power 2) is: Answers.
A) 0.68 B) 0.086 C) 0.86 D) 0.068 E) none of them | <gadget id="calculator">0.96 ** 3</gadget>
<output>0.884736</output>
<gadget id="calculator">0.1 ** 3</gadget>
<output>0.001</output>
<gadget id="calculator">0.884736 - 0.001</gadget>
<output>0.883736</output>
<gadget id="calculator">0.96 ** 2</gadget>
<output>0.9216</output>
<gadget id="calculator">0.9216 + 0.096</gadget>
<output>1.0176</output>
<gadget id="calculator">0.1 ** 2</gadget>
<output>0.01</output>
<gadget id="calculator">1.0176 + 0.01</gadget>
<output>1.0276</output>
<gadget id="calculator">0.883736 / 1.0276</gadget>
<output>0.86</output>
<result>C</result> | C | 0.86 | (0.96)(power 3) - (0.1)(power 3)/ (0.96)(power 2) + 0.096 + (0.1)(power 2) is: | {
"A": "0.68",
"B": "0.086",
"C": "0.86",
"D": "0.068",
"E": "none of them"
} | divide(subtract(power(0.96, 3), power(0.1, 3)), add(add(power(0.96, 2), 0.096), power(0.1, 2))) | power(n0,n1)|power(n2,n1)|power(n0,n5)|power(n2,n5)|add(n6,#2)|subtract(#0,#1)|add(#4,#3)|divide(#5,#6)| | "given expression = ( 0.96 ) ( power 3 ) - ( 0.1 ) ( power 3 ) / ( 0.96 ) ( power 2 ) + ( 0.96 x 0.1 ) + ( 0.1 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 0.96 - 0.1 ) = 0.86 answer is c ." | general |
math_qa__iAGUP1cqYLrNR6V0 | A metal company's old machine makes bolts at a constant rate of 100 bolts per hour. The company's new machine makes bolts at a constant rate of 150 bolts per hour. If both machines start at the same time and continue making bolts simultaneously, how many minutes will it take the two machines to make a total of 450 bolts? Choose the correct choice from the following options
A) 36 B) 72 C) 120 D) 144 E) 108 | <gadget id="calculator">100 / 60</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">150 / 60</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/3) + (5/2)</gadget>
<output>25/6 = around 4.166667</output>
<gadget id="calculator">450 / (25/6)</gadget>
<output>108</output>
<result>E</result> | E | 108 | A metal company's old machine makes bolts at a constant rate of 100 bolts per hour. The company's new machine makes bolts at a constant rate of 150 bolts per hour. If both machines start at the same time and continue making bolts simultaneously, how many minutes will it take the two machines to make a total of 450 bolts? | {
"A": "36",
"B": "72",
"C": "120",
"D": "144",
"E": "108"
} | divide(450, add(divide(100, const_60), divide(150, const_60))) | divide(n0,const_60)|divide(n1,const_60)|add(#0,#1)|divide(n2,#2)| | "old machine 100 bolts in 60 mins so , 5 / 3 bolts in 1 min new machine 150 bolts in 60 mins so , 5 / 2 bolts in 1 min together , 5 / 3 + 5 / 2 = 25 / 6 bolts in 1 min so , for 450 bolts 450 * 6 / 25 = 108 mins ans e" | physics |
math_qa__22atw1YRaKr6ow8j | A man's speed with the current is 21 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is? Choose one
A) 10 B) 20 C) 16 D) 30 E) 40 | <gadget id="calculator">21 - 2.5</gadget>
<output>18.5</output>
<gadget id="calculator">18.5 - 2.5</gadget>
<output>16</output>
<result>C</result> | C | 16 | A man's speed with the current is 21 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is? | {
"A": "10",
"B": "20",
"C": "16",
"D": "30",
"E": "40"
} | subtract(subtract(21, 2.5), 2.5) | subtract(n0,n1)|subtract(#0,n1)| | "man ' s speed with the current = 21 km / hr = > speed of the man + speed of the current = 21 km / hr speed of the current is 2.5 km / hr hence , speed of the man = 21 - 2.5 = 18.5 km / hr man ' s speed against the current = speed of the man - speed of the current = 18.5 - 2.5 = 16 km / hr answer is c ." | gain |
math_qa__wjFO7gCYzOBNqoCf | A train 275 m long, running with a speed of 90 km / hr will pass a tree in Choose the correct choice from the following answers: A) 11 sec B) 15 sec C) 16 sec D) 20 sec E) none | <gadget id="calculator">90 * 1_000</gadget>
<output>90_000</output>
<gadget id="calculator">275 / 90_000</gadget>
<output>11/3_600 = around 0.003056</output>
<gadget id="calculator">(11/3_600) * 3_600</gadget>
<output>11</output>
<result>A</result> | A | 11 | A train 275 m long, running with a speed of 90 km / hr will pass a tree in | {
"A": "11 sec",
"B": "15 sec",
"C": "16 sec",
"D": "20 sec",
"E": "none"
} | multiply(divide(275, multiply(90, const_1000)), const_3600) | multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600)| | "sol . speed = ( 90 x 5 / 18 ) m / sec . = 25 m / sec . time taken = ( 275 x 1 / 25 ) sec = 11 sec answer a" | physics |
math_qa__7RRC8odcewEKVAMa | The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and Danny have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies? Choose the correct option.
A) $ 0.32 B) $ 0.40 C) $ 0.45 D) $ 0.48 E) $ 0.54 | <gadget id="calculator">80 * 0.02</gadget>
<output>1.6</output>
<gadget id="calculator">2 * 1.6</gadget>
<output>3.2</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">160 * (3/4)</gadget>
<output>120</output>
<gadget id="calculator">120 * 0.02</gadget>
<output>2.4</output>
<gadget id="calculator">3.2 - 2.4</gadget>
<output>0.8</output>
<gadget id="calculator">0.8 / 2</gadget>
<output>0.4</output>
<result>B</result> | B | 0.4 | The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and Danny have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies? | {
"A": "$ 0.32",
"B": "$ 0.40",
"C": "$ 0.45",
"D": "$ 0.48",
"E": "$ 0.54"
} | divide(subtract(multiply(const_2, multiply(80, 0.02)), multiply(multiply(160, divide(subtract(100, 25), 100)), 0.02)), const_2) | multiply(n0,n3)|subtract(n2,n1)|divide(#1,n2)|multiply(#0,const_2)|multiply(n4,#2)|multiply(n0,#4)|subtract(#3,#5)|divide(#6,const_2)| | "if steve and danny submit separate orders , each would be smaller than 100 photocopies , so no discount . each would pay ( 80 ) * ( $ 0.02 ) = $ 1.60 , or together , a cost of $ 3.20 - - - that ' s the combined no discount cost . if they submit things together as one big order , they get a discount off of that $ 3.20 price - - - - 25 % or 1 / 4 of that is $ 0.80 , the discount on the combined sale . they each effective save half that amount , or $ 0.40 . answer = ( b ) ." | gain |
math_qa__OM9YVP4Ei1UsG1NV | 28% of employees are women with fair hair. 40% of fair-haired employees are women. What percent of employees have fair hair? Choose the correct choice from the following options.
A) 25 B) 30 C) 50 D) 55 E) 70 | <gadget id="calculator">28 / 40</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 100</gadget>
<output>70</output>
<result>E</result> | E | 70 | 28% of employees are women with fair hair. 40% of fair-haired employees are women. What percent of employees have fair hair? | {
"A": "25",
"B": "30",
"C": "50",
"D": "55",
"E": "70"
} | multiply(divide(28, 40), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "i came up with ( e ) 70 think of 100 people total : from the first fact , 28 of these are women with fair hair . from the second fact , these 20 women make up 40 % of the total fair haired population . we can then make a ratio of 60 : 40 fair haired men to fair haired women . this means that ( 60 / 40 ) * 28 equals the number of fair haired men , which is 42 men with fair hair . add this 42 to the 28 women and get 70 fair haired men and women out of 100 total men and women . 70 % e" | gain |
math_qa__XImlbdHwZdhSLx2B | A jogger running at 9 km/hr along side a railway track is 150 m ahead of the engine of a 100 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? Pick: A) 88 B) 27 C) 36 D) 80 E) 25 | <gadget id="calculator">150 + 100</gadget>
<output>250</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 / 18</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">250 / 10</gadget>
<output>25</output>
<result>E</result> | E | 25 | A jogger running at 9 km/hr along side a railway track is 150 m ahead of the engine of a 100 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? | {
"A": "88",
"B": "27",
"C": "36",
"D": "80",
"E": "25"
} | divide(add(150, 100), multiply(subtract(45, 9), divide(divide(const_10, const_2), divide(subtract(45, 9), const_2)))) | add(n1,n2)|divide(const_10,const_2)|subtract(n3,n0)|divide(#2,const_2)|divide(#1,#3)|multiply(#4,#2)|divide(#0,#5)| | "speed of train relative to jogger = 45 - 9 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . distance to be covered = 150 + 100 = 250 m . time taken = 250 / 10 = 25 sec . answer : e" | general |
math_qa__MmVJuXgZ2UmKaGX8 | A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train? Options:
A) 200 m B) 178 m C) 186 m D) 168 m E) 150 m | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 12</gadget>
<output>200</output>
<result>A</result> | A | 200 | A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train? | {
"A": "200 m",
"B": "178 m",
"C": "186 m",
"D": "168 m",
"E": "150 m"
} | multiply(divide(multiply(60, const_1000), const_3600), 12) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * 5 / 18 = 50 / 3 m / sec length of the train = speed * time = 50 / 3 * 12 = 200 m answer : a" | physics |
math_qa__pAVPLOcu9u1Rwq8O | A, B, C hired a car for Rs. 520 and used it for 7, 8 and 11 hours respectively. Hire charges paid by B were? Pick one:
A) 127 B) 160 C) 287 D) 237 E) 111 | <gadget id="calculator">7 + 8</gadget>
<output>15</output>
<gadget id="calculator">15 + 11</gadget>
<output>26</output>
<gadget id="calculator">8 / 26</gadget>
<output>4/13 = around 0.307692</output>
<gadget id="calculator">520 * (4/13)</gadget>
<output>160</output>
<result>B</result> | B | 160 | A, B, C hired a car for Rs. 520 and used it for 7, 8 and 11 hours respectively. Hire charges paid by B were? | {
"A": "127",
"B": "160",
"C": "287",
"D": "237",
"E": "111"
} | multiply(520, divide(8, add(add(7, 8), 11))) | add(n1,n2)|add(n3,#0)|divide(n2,#1)|multiply(n0,#2) | a : b : c = 7 : 8 : 11 . hire charges paid by b = rs . ( 520 * 8 / 26 ) = rs . 160 . answer : b | physics |
math_qa__bk2fCXh8mKT5wTGN | There are 2 white plates, 6 green plates, 8 red plates, 4 pink plates, and 10 purple plates in the cabinet. What is the least number of plates that you have to pull out to make sure that you will have a matching pair? (Assume that all the plates are identical except for the color) Choose the correct answer.
A) 2 B) 4 C) 12 D) 7 E) 6 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<result>E</result> | E | 6 | There are 2 white plates, 6 green plates, 8 red plates, 4 pink plates, and 10 purple plates in the cabinet. What is the least number of plates that you have to pull out to make sure that you will have a matching pair? (Assume that all the plates are identical except for the color) | {
"A": "2",
"B": "4",
"C": "12",
"D": "7",
"E": "6"
} | add(2, 4) | add(n0,n3) | since there are 5 colors , if you take 5 plates , you could still have 1 plate per color and not have a match . therefore , upon taking the 6 th plate , you will definitely have a match since the 6 th plate will form at least a pair with the 1 st 5 so 5 + 1 = 6 answer is e | general |
math_qa__42tHxAu4sgc1xqZZ | The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is Choose the correct choice from the following choices: A) 1008 B) 1015 C) 1022 D) 1032 E) none | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">144 * 7</gadget>
<output>1_008</output>
<gadget id="calculator">1_008 + 7</gadget>
<output>1_015</output>
<result>B</result> | B | 1,015 | The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is | {
"A": "1008",
"B": "1015",
"C": "1022",
"D": "1032",
"E": "none"
} | add(multiply(multiply(power(const_3, const_2.0), power(const_2.0, const_4)), add(const_3, const_4)), 7) | add(const_3,const_4)|power(const_3,const_2.0)|power(const_2.0,const_4)|multiply(#1,#2)|multiply(#0,#3)|add(#4,n0)| | "solution required numbers = ( l . c . m of 12 , 16,18 , 21,28 ) + 7 ‹ = › 1008 + 7 = 1015 . answer b" | general |
math_qa__ors4LOY17ydeHggK | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 15 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? Choose the correct choice from the following answers.
A) 38 B) 39 C) 40 D) 41 E) 42 | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">100 / 115</gadget>
<output>20/23 = around 0.869565</output>
<gadget id="calculator">(20/23) * 45</gadget>
<output>900/23 = around 39.130435</output>
<result>B</result> | B | 39 | From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 15 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ? | {
"A": "38",
"B": "39",
"C": "40",
"D": "41",
"E": "42"
} | multiply(divide(const_100, add(const_100, 15)), 45) | add(n4,const_100)|divide(const_100,#0)|multiply(n7,#1)| | "soln : - 15 x = 45 - - > 23 / 20 * x = 45 - - > x = 45 * 20 / 23 = 900 / 23 = ~ 39 . answer : b ." | gain |
math_qa__6Fi1y9KA2Y12q9hE | A train 220 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 4 km/hr in the direction opposite to that in which the train is going? Choose the correct choice from the following answers
A) 5 B) 12 C) 7 D) 9 E) 5 | <gadget id="calculator">60 + 4</gadget>
<output>64</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">64 * (5/18)</gadget>
<output>160/9 = around 17.777778</output>
<gadget id="calculator">220 / (160/9)</gadget>
<output>99/8 = around 12.375</output>
<result>B</result> | B | 12 | A train 220 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 4 km/hr in the direction opposite to that in which the train is going? | {
"A": "5",
"B": "12",
"C": "7",
"D": "9",
"E": "5"
} | divide(220, multiply(add(60, 4), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 4 = 64 km / hr . = 64 * 5 / 18 = 160 / 9 m / sec . time taken to pass the men = 220 * 9 / 160 = 12 sec . answer : b" | physics |
math_qa__idpUCwpljQ86TpTC | What is the dividend. divisor 14, the quotient is 12 and the remainder is 8 Choose the correct choice from the following choices
A) 175 B) 176 C) 177 D) 178 E) 179 | <gadget id="calculator">14 * 12</gadget>
<output>168</output>
<gadget id="calculator">168 + 8</gadget>
<output>176</output>
<result>B</result> | B | 176 | What is the dividend. divisor 14, the quotient is 12 and the remainder is 8 | {
"A": "175",
"B": "176",
"C": "177",
"D": "178",
"E": "179"
} | add(multiply(14, 12), 8) | multiply(n0,n1)|add(n2,#0) | b = d * q + r b = 14 * 12 + 8 b = 168 + 8 b = 176 | general |
math_qa__mlhRDK4S7r8VSqAi | Jhon works for 60 days. for the day he is present he is paid 7.00/- and for the day he is
absent he is paid 3.00/- per day. if he is paid 170/-.how many days he is present. Pick:
A) 35 B) 36 C) 37 D) 38 E) 39 | <gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">180 + 170</gadget>
<output>350</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">350 / 10</gadget>
<output>35</output>
<result>A</result> | A | 35 | Jhon works for 60 days. for the day he is present he is paid 7.00/- and for the day he is
absent he is paid 3.00/- per day. if he is paid 170/-.how many days he is present. | {
"A": "35",
"B": "36",
"C": "37",
"D": "38",
"E": "39"
} | divide(add(multiply(3, 60), 170), add(7, 3)) | add(n1,n2)|multiply(n0,n2)|add(n3,#1)|divide(#2,#0) | let no . days be = x and no . days he is absent = 60 - x , so 7 x - 3 ( 60 - x ) = 170 x = 35 answer : a | physics |
math_qa__zPDeLqWbJP6xrtlb | A statue is being carved by a sculptor. The original piece of marble weighed 140 kg. In the first week 60 percent is cut away. In the second week 40 percent of the remainder is cut away. In the third week the statue is completed when 30 percent of the remainder is cut away. What is the weight of the final statue? Answers
A) 24 kg B) 23 kg C) 28 kg D) 25 kg E) 27 kg | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">140 * (2/5)</gadget>
<output>56</output>
<gadget id="calculator">(3/5) * 56</gadget>
<output>168/5 = around 33.6</output>
<gadget id="calculator">(7/10) * (168/5)</gadget>
<output>588/25 = around 23.52</output>
<result>A</result> | A | 24 | A statue is being carved by a sculptor. The original piece of marble weighed 140 kg. In the first week 60 percent is cut away. In the second week 40 percent of the remainder is cut away. In the third week the statue is completed when 30 percent of the remainder is cut away. What is the weight of the final statue? | {
"A": "24 kg",
"B": "23 kg",
"C": "28 kg",
"D": "25 kg",
"E": "27 kg"
} | multiply(subtract(const_1, divide(30, const_100)), multiply(subtract(const_1, divide(40, const_100)), multiply(140, subtract(const_1, divide(60, const_100))))) | divide(n1,const_100)|divide(n2,const_100)|divide(n3,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|subtract(const_1,#2)|multiply(n0,#3)|multiply(#6,#4)|multiply(#7,#5) | a 24 kg 140 ã — 0.4 ã — 0.6 ã — 0.7 = 24 kg . | gain |
math_qa__ZYhQO8h6IY0bglDA | If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 171 games will be played during the tournament. What is the number of participants? Options
A) 15 B) 16 C) 17 D) 18 E) 19 | <gadget id="calculator">171 * 2</gadget>
<output>342</output>
<gadget id="calculator">342 * 4</gadget>
<output>1_368</output>
<gadget id="calculator">1_368 + 1</gadget>
<output>1_369</output>
<gadget id="calculator">1_369 ** (1/2)</gadget>
<output>37</output>
<gadget id="calculator">37 + 1</gadget>
<output>38</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<result>E</result> | E | 19 | If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 171 games will be played during the tournament. What is the number of participants? | {
"A": "15",
"B": "16",
"C": "17",
"D": "18",
"E": "19"
} | divide(add(sqrt(add(multiply(multiply(171, const_2), const_4), const_1)), const_1), const_2) | multiply(n0,const_2)|multiply(#0,const_4)|add(#1,const_1)|sqrt(#2)|add(#3,const_1)|divide(#4,const_2)| | "let n be the number of participants . the number of games is nc 2 = n * ( n - 1 ) / 2 = 171 n * ( n - 1 ) = 342 = 19 * 18 ( trial and error ) the answer is e ." | general |
math_qa__JDzVNszagxwvE4Zy | What is the ratio G of the surface area of a cube to the surface area of a rectangular solid identical to the cube in all ways except that its length has been doubled?
Choose the correct choice from the following options: A) 1 / 4 B) 3 / 8 C) 1 / 2 D) 3 / 5 E) 2 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">6 / 10</gadget>
<output>3/5 = around 0.6</output>
<result>D</result> | D | 0.6 | What is the ratio G of the surface area of a cube to the surface area of a rectangular solid identical to the cube in all ways except that its length has been doubled? | {
"A": "1 / 4",
"B": "3 / 8",
"C": "1 / 2",
"D": "3 / 5",
"E": "2"
} | divide(multiply(const_2, const_3), multiply(add(multiply(multiply(const_1, const_2), const_2), multiply(const_1, const_1)), const_2)) | multiply(const_2,const_3)|multiply(const_1,const_2)|multiply(const_1,const_1)|multiply(#1,const_2)|add(#3,#2)|multiply(#4,const_2)|divide(#0,#5) | one side surface area of a cube = x * x = x ^ 2 total 6 sides = 6 x ^ 2 as for the rectangular , height ( h ) and width ( w ) are same as cube , x . only length = 2 x . l x h = 2 x * x = 2 x ^ 2 - - - - > 4 sides = 2 x ^ 2 * 4 = 8 x ^ 2 w * h = x * x = x ^ 2 - - - - - - > 2 sides = x ^ 2 * 2 = 2 x ^ 2 total 6 sides = 8 x ^ 2 + 2 x ^ 2 = 10 x ^ 2 ratio of cube area to rectangular area g = 6 x ^ 2 / 10 x ^ 2 - - - - > 6 / 10 - - - - > 3 / 5 ( d ) | geometry |
math_qa__nTZCEUJXcsXYgdWL | If the mean of numbers 28, x, 50, 78 and 104 is 62, what is the mean of 48, 62, 98, 124 and x? Choose the correct choice from the following answers
A) 76.5
B) 58
C) 39.8
D) 90.3
E) 66.67 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">62 * 5</gadget>
<output>310</output>
<gadget id="calculator">28 + 50</gadget>
<output>78</output>
<gadget id="calculator">78 + 78</gadget>
<output>156</output>
<gadget id="calculator">156 + 104</gadget>
<output>260</output>
<gadget id="calculator">310 - 260</gadget>
<output>50</output>
<gadget id="calculator">50 + 48</gadget>
<output>98</output>
<gadget id="calculator">98 + 62</gadget>
<output>160</output>
<gadget id="calculator">160 + 98</gadget>
<output>258</output>
<gadget id="calculator">258 + 124</gadget>
<output>382</output>
<gadget id="calculator">382 / 5</gadget>
<output>382/5 = around 76.4</output>
<result>A</result> | A | 76.5 | If the mean of numbers 28, x, 50, 78 and 104 is 62, what is the mean of 48, 62, 98, 124 and x? | {
"A": "76.5",
"B": "58",
"C": "39.8",
"D": "90.3",
"E": "66.67"
} | divide(add(add(add(add(subtract(multiply(62, add(const_4, const_1)), add(add(add(28, 50), 78), 104)), 48), 62), 98), 124), add(const_4, const_1)) | add(const_1,const_4)|add(n0,n1)|add(n2,#1)|multiply(n4,#0)|add(n3,#2)|subtract(#3,#4)|add(n5,#5)|add(n6,#6)|add(n7,#7)|add(n8,#8)|divide(#9,#0)| | "mean = ( sum of all no . in series ) / ( no . in series ) m 1 = 62 = ( x + 28 + 50 + 78 + 104 ) / ( 5 ) 62 x 5 = 260 + x x = 50 therefore mean of 2 nd series m 2 = ( x + 48 + 62 + 98 + 124 ) / 5 m 2 = 76.5 answer = a" | general |
math_qa__EJocc5t4cwprKg9L | John makes $60 a week from his job. He earns a raise andnow makes $68 a week. What is the % increase?
Select the correct option: A) 16.12 % B) 16.66 % C) 16.56 % D) 17.66 % E) 13.33 % | <gadget id="calculator">68 - 60</gadget>
<output>8</output>
<gadget id="calculator">8 / 60</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/15) * 100</gadget>
<output>40/3 = around 13.333333</output>
<result>E</result> | E | 13.33 | John makes $60 a week from his job. He earns a raise andnow makes $68 a week. What is the % increase? | {
"A": "16.12 %",
"B": "16.66 %",
"C": "16.56 %",
"D": "17.66 %",
"E": "13.33 %"
} | multiply(divide(subtract(68, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 8 / 60 ) * 100 = ( 2 / 15 ) * 100 = 13.33 % . e" | gain |
math_qa__kNPhcXpEVlPoF4Kc | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
Pick:
A) rs . 128 B) rs . 129 C) rs . 125 D) rs . 198 E) rs . 120 | <gadget id="calculator">3_750 * 2</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 / 3</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 ** (1/2)</gadget>
<output>50</output>
<gadget id="calculator">3_750 / 50</gadget>
<output>75</output>
<gadget id="calculator">2 * (50 + 75)</gadget>
<output>250</output>
<gadget id="calculator">50 * 250</gadget>
<output>12_500</output>
<gadget id="calculator">12_500 / 100</gadget>
<output>125</output>
<result>C</result> | C | 125 | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is? | {
"A": "rs . 128",
"B": "rs . 129",
"C": "rs . 125",
"D": "rs . 198",
"E": "rs . 120"
} | divide(multiply(50, rectangle_perimeter(sqrt(divide(multiply(3750, 2), 3)), divide(3750, sqrt(divide(multiply(3750, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100) | 3 x * 2 x = 3750 = > x = 25 2 ( 75 + 50 ) = 250 m 250 * 1 / 2 = rs . 125 answer : c | physics |
math_qa__5ub5GwMhaIJfufFQ | A man can row 36 kmph in still water. It takes him thrice as long to row up as to row down the river. Find the rate of the stream? Answers
A) 14 kmph
B) 12 kmph
C) 18 kmph
D) 1 kmph
E) none of these | <gadget id="calculator">36 * 2</gadget>
<output>72</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">72 / 4</gadget>
<output>18</output>
<result>C</result> | C | 18 | A man can row 36 kmph in still water. It takes him thrice as long to row up as to row down the river. Find the rate of the stream? | {
"A": "14 kmph",
"B": "12 kmph",
"C": "18 kmph",
"D": "1 kmph",
"E": "none of these"
} | divide(multiply(36, const_2), add(const_3, const_1)) | add(const_1,const_3)|multiply(n0,const_2)|divide(#1,#0) | explanation : let man ' s rate upsteam be x kmph then his rate of downstream = 3 x kmph rate still water = 1 / 2 ( 3 x + x ) = 2 x 2 x = 36 x = 18 rate of upstream = 18 rate of downstream = 54 rate of stream 1 / 2 ( 54 - 18 ) = 18 kmph answer : option c | gain |
math_qa__AwmnFUrdeLcRchZw | To be considered for “movie of the year,” a film must appear in at least 1/4 of the top-10-movies lists submitted by the Cinematic Academy’s 765 members. What is the smallest number of top-10 lists a film can appear on and still be considered for “movie of the year”?
Choose the most appropriate option.
A) 191
B) 192
C) 193
D) 212
E) 213 | <gadget id="calculator">765 / 4</gadget>
<output>765/4 = around 191.25</output>
<result>B</result> | B | 192 | To be considered for “movie of the year,” a film must appear in at least 1/4 of the top-10-movies lists submitted by the Cinematic Academy’s 765 members. What is the smallest number of top-10 lists a film can appear on and still be considered for “movie of the year”? | {
"A": "191",
"B": "192",
"C": "193",
"D": "212",
"E": "213"
} | divide(765, 4) | divide(n3,n1)| | "total movies submitted are 765 . as per question we need to take 1 / 4 of 765 to be considered for top 10 movies = 191.25 approximate the value we 192 . answer : option b is the correct answer . ." | general |
math_qa__JLdHKQ63hJXqisPv | A box measuring 24 inches long by 40 inches wide by 16 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective?
Choose the most appropriate option: A) 28 B) 30 C) 32 D) 35 E) 37 | <gadget id="calculator">24 * 40</gadget>
<output>960</output>
<gadget id="calculator">960 * 16</gadget>
<output>15_360</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 ** 3</gadget>
<output>512</output>
<gadget id="calculator">15_360 / 512</gadget>
<output>30</output>
<result>B</result> | B | 30 | A box measuring 24 inches long by 40 inches wide by 16 inches deep is to be filled entirely with identical cubes. No space is to be left unfilled. What is the smallest number of cubes that can accomplish this objective? | {
"A": "28",
"B": "30",
"C": "32",
"D": "35",
"E": "37"
} | divide(multiply(multiply(24, 40), 16), volume_cube(divide(16, const_2))) | divide(n2,const_2)|multiply(n0,n1)|multiply(n2,#1)|volume_cube(#0)|divide(#2,#3)| | "least number of cubes will be required when the cubes that could fit in are biggest . 8 is the biggest number that could divide all three , 24 , 40 and 16 . thus side of cube must be 8 , and total number of cubes = 24 / 8 * 40 / 8 * 16 / 8 = 30 ans b" | geometry |
math_qa__FbhMj5h60MIf8jaQ | There are 11 baskets numbered from 1 to 11 and filled with apples. 10 children are asked to pick apples one by one from each basket such that the number of apples picked by each child from each basket is equal to the number marked on the basket. If there were 1000 apples in total and the baskets were filled in such a way that none of the basket became empty in the process, how many apples were left in the end?
Pick:
A) 180 B) 220 C) 260 D) 300 E) 340 | <gadget id="calculator">1 + 11</gadget>
<output>12</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">60 + 5</gadget>
<output>65</output>
<gadget id="calculator">65 + 1</gadget>
<output>66</output>
<gadget id="calculator">66 * 10</gadget>
<output>660</output>
<gadget id="calculator">1_000 - 660</gadget>
<output>340</output>
<result>E</result> | E | 340 | There are 11 baskets numbered from 1 to 11 and filled with apples. 10 children are asked to pick apples one by one from each basket such that the number of apples picked by each child from each basket is equal to the number marked on the basket. If there were 1000 apples in total and the baskets were filled in such a way that none of the basket became empty in the process, how many apples were left in the end? | {
"A": "180",
"B": "220",
"C": "260",
"D": "300",
"E": "340"
} | subtract(1000, multiply(add(add(multiply(add(1, 11), divide(10, const_2)), divide(10, const_2)), const_1), const_10)) | add(n0,n1)|divide(n3,const_2)|multiply(#0,#1)|add(#1,#2)|add(#3,const_1)|multiply(#4,const_10)|subtract(n4,#5) | each child takes a total of 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 = 11 * 12 / 2 = 66 apples . the total number of apples taken by 10 children is 10 * 66 = 660 the number of apples left in the end is 1000 - 660 = 340 apples . the answer is e . | general |
math_qa__4eFs0jmhmXJ4d062 | If A lends Rs.2000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
Select:
A) 90
B) 122.5
C) 132.5
D) 114.5
E) 212.5 | <gadget id="calculator">2_000 * 11.5</gadget>
<output>23_000</output>
<gadget id="calculator">23_000 * 3</gadget>
<output>69_000</output>
<gadget id="calculator">69_000 / 100</gadget>
<output>690</output>
<gadget id="calculator">2_000 * 10</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 * 3</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 100</gadget>
<output>600</output>
<gadget id="calculator">690 - 600</gadget>
<output>90</output>
<result>A</result> | A | 90 | If A lends Rs.2000 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is? | {
"A": "90",
"B": "122.5",
"C": "132.5",
"D": "114.5",
"E": "212.5"
} | subtract(divide(multiply(multiply(2000, 11.5), 3), const_100), divide(multiply(multiply(2000, 10), 3), const_100)) | multiply(n0,n2)|multiply(n0,n1)|multiply(#0,n3)|multiply(n3,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5)| | "( 2000 * 1.5 * 3 ) / 100 = > 90 answer : a" | gain |
math_qa__EcCdV3P2YqQM0Ftm | The time taken by Mr.Dhoni to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 72 kmph, find the speed of the stream? Choose one: A) 24 kmph B) 25 kmph C) 26 kmph D) 30 kmph E) 28 kmph | <gadget id="calculator">72 * 2</gadget>
<output>144</output>
<gadget id="calculator">144 / 3</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>A</result> | A | 24 | The time taken by Mr.Dhoni to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 72 kmph, find the speed of the stream? | {
"A": "24 kmph",
"B": "25 kmph",
"C": "26 kmph",
"D": "30 kmph",
"E": "28 kmph"
} | divide(divide(multiply(72, const_2), const_3), const_2) | multiply(n0,const_2)|divide(#0,const_3)|divide(#1,const_2) | the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 72 / 3 = 24 kmph . answer : a | physics |
math_qa__D6L6iNsUZxlh0Ecu | Increasing the original price of a certain item by 15 percent and then increasing the new price by 15 percent is equivalent to increasing the original price by what percent? Choose the correct choice from the following answers.
A) 31.25 B) 37.5 C) 30.0 D) 32.75 E) 32.25 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) + 1</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(23/20) * (23/20)</gadget>
<output>529/400 = around 1.3225</output>
<gadget id="calculator">(529/400) - 1</gadget>
<output>129/400 = around 0.3225</output>
<gadget id="calculator">(129/400) * 100</gadget>
<output>129/4 = around 32.25</output>
<result>E</result> | E | 32.25 | Increasing the original price of a certain item by 15 percent and then increasing the new price by 15 percent is equivalent to increasing the original price by what percent? | {
"A": "31.25",
"B": "37.5",
"C": "30.0",
"D": "32.75",
"E": "32.25"
} | multiply(subtract(multiply(add(divide(15, const_100), const_1), add(divide(15, const_100), const_1)), const_1), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "we ' re told that the original price of an item is increased by 15 % and then that price is increased by 15 % . . . . if . . . . starting value = $ 100 + 15 % = 100 + . 15 ( 100 ) = 115 + 15 % = 115 + . 15 ( 115 ) = 115 + 17.25 = 132.25 the question asks how the final price relates to the original price . this is essentially about percentage change , which means we should use the percentage change formula : percentage change = ( new - old ) / old = difference / original doing either calculation will yield the same result : 32.25 / 100 = 32.25 % final answer : e" | gain |
math_qa__fdQdoWAhniZ1KOCp | If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability T that N is divisible by 3?
Choose the most appropriate option: A) 1 / 3 B) ¼ C) 9 / 25 D) 5 / 16 E) 0 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">5 / 16</gadget>
<output>5/16 = around 0.3125</output>
<result>D</result> | D | 0.3125 | If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability T that N is divisible by 3? | {
"A": "1 / 3",
"B": "¼",
"C": "9 / 25",
"D": "5 / 16",
"E": "0"
} | divide(add(3, const_2), multiply(const_4, const_4)) | add(n0,const_2)|multiply(const_4,const_4)|divide(#0,#1)| | "prime digits are : 2 , 3 , 5 , 7 total number of 2 digit # s with both digits prime are : 4 * 4 = 16 out of these numbers divisible by 3 = 33 , 27 , 57 , 72 and 75 . i had to find the numbers manually using the 4 numbers above . = > prob = 5 / 16 . ans d . took me 3 : 20 mins ." | general |
math_qa__0Z3PBB2q6uef0Zat | raj invests a part of rs . 12000 in 12 % stock at rs . 120 and the remainder in 15 % stock at rs . 125 . if his total dividend per annum is rs . 1360 , how much does he invest in 12 % stock at rs . 120 ? Choose the correct answer:
A) 3000 B) 4000 C) 5000 D) 5500 E) 6000 | <gadget id="calculator">15 / 125</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) * 12_000</gadget>
<output>1_440</output>
<gadget id="calculator">1_440 - 1_360</gadget>
<output>80</output>
<gadget id="calculator">12 / 120</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(3/25) - (1/10)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">80 / (1/50)</gadget>
<output>4_000</output>
<result>B</result> | B | 4,000 | raj invests a part of rs . 12000 in 12 % stock at rs . 120 and the remainder in 15 % stock at rs . 125 . if his total dividend per annum is rs . 1360 , how much does he invest in 12 % stock at rs . 120 ? | {
"A": "3000",
"B": "4000",
"C": "5000",
"D": "5500",
"E": "6000"
} | divide(subtract(multiply(divide(15, 125), 12000), 1360), subtract(divide(15, 125), divide(12, 120))) | divide(n3,n4)|divide(n1,n2)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n5)|divide(#4,#3) | investment in 12 % stock be x then investment 15 % stock = ( 12000 - x ) 12 / 120 * x + 15 / 125 * ( 12000 - x ) = 1360 x = 4000 answer b | general |
math_qa__8yLgCiR7nsXmAF1L | If 42.24 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ? Options:
A) 6
B) 7
C) 8
D) 9
E) 10 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/4) - (1/100)</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">(6/25) * 50</gadget>
<output>12</output>
<gadget id="calculator">42.24 - (6/25)</gadget>
<output>42</output>
<gadget id="calculator">42 / 14</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<result>B</result> | B | 7 | If 42.24 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of k + m ? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | add(divide(multiply(subtract(const_0_25, divide(const_1, const_100)), 50), divide(subtract(42.24, subtract(const_0_25, divide(const_1, const_100))), 14)), divide(subtract(42.24, subtract(const_0_25, divide(const_1, const_100))), 14)) | divide(const_1,const_100)|subtract(const_0_25,#0)|multiply(n2,#1)|subtract(n0,#1)|divide(#3,n1)|divide(#2,#4)|add(#5,#4) | 42.24 = 14 k + km / 50 . . . we can rewrite the number as follows : 42 + 0.24 = 14 k + km / 50 . . . . . . . . since k is integer , then 42 = 14 k . . . . . . . . . . k = 3 0.24 = km / 50 . . . . . . 24 / 100 = 3 m / 50 . . . . . . m = 4 k + m = 3 + 4 = 7 answer : b | general |
math_qa__dH8uBqeP4bPQqOHP | The reciprocal of the hcf and lcm of two are 1/14 and 1/312 .if one of the number is 24 then other no. is Choose the most appropriate option
A) 126 B) 136 C) 146 D) 156 E) 182 | <gadget id="calculator">14 * 312</gadget>
<output>4_368</output>
<gadget id="calculator">4_368 / 24</gadget>
<output>182</output>
<result>E</result> | E | 182 | The reciprocal of the hcf and lcm of two are 1/14 and 1/312 .if one of the number is 24 then other no. is | {
"A": "126",
"B": "136",
"C": "146",
"D": "156",
"E": "182"
} | divide(multiply(14, 312), 24) | multiply(n1,n3)|divide(#0,n4)| | "reciprocal of the hcf and lcm of two are 1 / 14 and 1 / 312 so , hcf = 14 , lcm = 312 lcm * hcf = product of two numbers = a * b = > b = lcm * hcf / a so , other = 14 * 312 / 24 = 182 answer : e" | physics |
math_qa__FFJLIOFbIAzGJLGb | The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 30 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam. Choose the correct answer.
A) 15 B) 30 C) 35 D) 45 E) 55 | <gadget id="calculator">90 * 5</gadget>
<output>450</output>
<gadget id="calculator">5 * 30</gadget>
<output>150</output>
<gadget id="calculator">450 - 150</gadget>
<output>300</output>
<gadget id="calculator">90 - 80</gadget>
<output>10</output>
<gadget id="calculator">300 / 10</gadget>
<output>30</output>
<result>B</result> | B | 30 | The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 30 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam. | {
"A": "15",
"B": "30",
"C": "35",
"D": "45",
"E": "55"
} | divide(subtract(multiply(90, 5), multiply(5, 30)), subtract(90, 80)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the number of students who wrote the exam be x . total marks of students = 80 x . total marks of ( x - 5 ) students = 90 ( x - 5 ) 80 x - ( 5 * 30 ) = 90 ( x - 5 ) 300 = 10 x = > x = 30 answer : b" | general |
math_qa__BOVoxuqbApIO9uCr | A, B and C have Rs.450 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have? Choose the correct choice from the following options:
A) 100 B) 110 C) 120 D) 130 E) 140 | <gadget id="calculator">200 + 350</gadget>
<output>550</output>
<gadget id="calculator">550 - 450</gadget>
<output>100</output>
<result>A</result> | A | 100 | A, B and C have Rs.450 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have? | {
"A": "100",
"B": "110",
"C": "120",
"D": "130",
"E": "140"
} | subtract(add(200, 350), 450) | add(n1,n2)|subtract(#0,n0)| | "a + b + c = 450 a + c = 200 b + c = 350 - - - - - - - - - - - - - - a + b + 2 c = 550 a + b + c = 450 - - - - - - - - - - - - - - - - c = 100 answer : a" | general |
math_qa__VOlsBcNCLFmRQmYm | One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field?
Select the correct option
A) 110 B) 120 C) 130 D) 140 E) 150 | <gadget id="calculator">17 ** 2</gadget>
<output>289</output>
<gadget id="calculator">15 ** 2</gadget>
<output>225</output>
<gadget id="calculator">289 - 225</gadget>
<output>64</output>
<gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<gadget id="calculator">15 * 8</gadget>
<output>120</output>
<result>B</result> | B | 120 | One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field? | {
"A": "110",
"B": "120",
"C": "130",
"D": "140",
"E": "150"
} | rectangle_area(15, sqrt(subtract(power(17, const_2), power(15, const_2)))) | power(n1,const_2)|power(n0,const_2)|subtract(#0,#1)|sqrt(#2)|rectangle_area(n0,#3)| | "other side = [ ( 17 x 17 ) - ( 15 x 15 ) ] = ( 289 - 225 ) = 8 m area = 15 x 8 = 120 sq . m answer : b" | geometry |
math_qa__aCehASilJq0TWHcr | A and B invests Rs.4000 and Rs.6000 in a business. After 4 months, A withdraws three-fourth of his capital and 4 months later, B withdraws half of his capital. In what ratio should they share the profits at the end of the year? Pick one.
A) 2 : 5 B) 3 : 5 C) 4 : 5 D) 3 : 7 E) 5 : 7 | <gadget id="calculator">4_000 * 4</gadget>
<output>16_000</output>
<gadget id="calculator">6_000 / 3</gadget>
<output>2_000</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">2_000 * 16</gadget>
<output>32_000</output>
<gadget id="calculator">16_000 + 32_000</gadget>
<output>48_000</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">6_000 * 12</gadget>
<output>72_000</output>
<gadget id="calculator">6_000 - 2_000</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 * 12</gadget>
<output>48_000</output>
<gadget id="calculator">72_000 + 48_000</gadget>
<output>120_000</output>
<gadget id="calculator">48_000 / 120_000</gadget>
<output>2/5 = around 0.4</output>
<result>A</result> | A | 0.4 | A and B invests Rs.4000 and Rs.6000 in a business. After 4 months, A withdraws three-fourth of his capital and 4 months later, B withdraws half of his capital. In what ratio should they share the profits at the end of the year? | {
"A": "2 : 5",
"B": "3 : 5",
"C": "4 : 5",
"D": "3 : 7",
"E": "5 : 7"
} | divide(add(multiply(4000, 4), multiply(divide(6000, const_3), multiply(4, 4))), add(multiply(6000, multiply(4, const_3)), multiply(subtract(6000, divide(6000, const_3)), multiply(4, const_3)))) | divide(n1,const_3)|multiply(n0,n2)|multiply(n3,n2)|multiply(n3,const_3)|multiply(#0,#2)|multiply(n1,#3)|subtract(n1,#0)|add(#1,#4)|multiply(#3,#6)|add(#5,#8)|divide(#7,#9)| | "a : b ( 4000 * 4 ) + ( 1000 * 8 ) : ( 6000 * 8 ) + ( 3000 * 4 ) 24000 : 60000 2 : 5 answer : a" | gain |
math_qa__tQ6MnQjfY9ecta7T | A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of : Select the correct option
A) 10 %
B) 10.5 %
C) 11 %
D) 12.5 %
E) none | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">11 / 110</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">100 * (1/10)</gadget>
<output>10</output>
<result>A</result> | A | 10 | A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of : | {
"A": "10 %",
"B": "10.5 %",
"C": "11 %",
"D": "12.5 %",
"E": "none"
} | multiply(const_100, divide(add(multiply(add(const_2, const_3), const_2), 1), add(const_100, 10))) | add(const_2,const_3)|add(n0,const_100)|multiply(#0,const_2)|add(#2,n1)|divide(#3,#1)|multiply(#4,const_100)| | "sol . let c . p . = rs . 100 . then , marked price = rs . 110 , s . p . = rs . 99 . ∴ discount % = [ 11 / 110 * 100 ] % = 10 % answer a" | gain |
math_qa__tG1fc6oPphgyGGnb | A goods train runs at the speed of 72 kmph and crosses a 280 m long platform in 26 seconds. What is the length of the goods train? Choose the correct option: A) 230 m B) 270 m C) 240 m D) 832 m E) 270 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">280 / 20</gadget>
<output>14</output>
<gadget id="calculator">26 - 14</gadget>
<output>12</output>
<gadget id="calculator">12 * 20</gadget>
<output>240</output>
<result>C</result> | C | 240 | A goods train runs at the speed of 72 kmph and crosses a 280 m long platform in 26 seconds. What is the length of the goods train? | {
"A": "230 m",
"B": "270 m",
"C": "240 m",
"D": "832 m",
"E": "270 m"
} | multiply(subtract(26, divide(280, multiply(const_0_2778, 72))), multiply(const_0_2778, 72)) | multiply(n0,const_0_2778)|divide(n1,#0)|subtract(n2,#1)|multiply(#0,#2)| | "speed = ( 72 x 5 / 18 ) m / sec = 20 m / sec . time = 26 sec . let the length of the train be x metres . then , x + 280 / 26 = 20 x + 280 = 520 x = 240 . answer : c" | physics |
math_qa__v0HTJgXL2r3pp68B | Two cars start at the same time from opposite ends of a highway that is 500 miles long. One car is riding at 40 mph and the second car is riding at 60 mph. How long after they begin will they meet? Choose the correct choice from the following options:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">40 + 60</gadget>
<output>100</output>
<gadget id="calculator">500 / 100</gadget>
<output>5</output>
<result>E</result> | E | 5 | Two cars start at the same time from opposite ends of a highway that is 500 miles long. One car is riding at 40 mph and the second car is riding at 60 mph. How long after they begin will they meet? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(500, add(40, 60)) | add(n1,n2)|divide(n0,#0) | as cars are moving in opposite directions their speeds will be added . so their relative speeds : 60 + 40 = 100 mph total distance to be covered = 500 miles . time taken would be : 500 miles / 100 mph = 5 hours e is the answer . | physics |
math_qa__HnrjDMGgQOYH0Kei | The area of circle O is added to its diameter. If the circumference of circle O is then subtracted from this total, the result is 12. What is the radius of circle O?
Choose the correct choice from the following.
A) – 2 / pi B) 2 C) 3 D) 4 E) 6 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>E</result> | E | 6 | The area of circle O is added to its diameter. If the circumference of circle O is then subtracted from this total, the result is 12. What is the radius of circle O? | {
"A": "– 2 / pi",
"B": "2",
"C": "3",
"D": "4",
"E": "6"
} | divide(12, const_2) | divide(n0,const_2) | pi * r ^ 2 + 2 r - 2 * pi * r = 12 simplifying the equation : pi * r ( r - 2 ) + 2 r = 12 without much algebraic : we can test the answers quickly , then 6 is the only possible answer that will eliminate pi from equation . answer is e | geometry |
math_qa__41RuHODaZQTb8C59 | Linda spent 2/3 of her savings on furniture and the rest on a TV. If the TV cost her $250, what were her original savings? Choose the correct choice from the following answers:
A) $ 750
B) $ 350
C) $ 650
D) $ 550
E) $ 850 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">250 / (1/3)</gadget>
<output>750</output>
<result>A</result> | A | 750 | Linda spent 2/3 of her savings on furniture and the rest on a TV. If the TV cost her $250, what were her original savings? | {
"A": "$ 750",
"B": "$ 350",
"C": "$ 650",
"D": "$ 550",
"E": "$ 850"
} | divide(250, subtract(const_1, divide(2, 3))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)| | "if linda spent 2 / 3 of her savings on furniture , the rest 3 / 3 - 2 / 3 = 1 / 3 on a tv but the tv cost her $ 250 . so 1 / 3 of her savings is $ 250 . so her original savings are 3 times $ 250 = $ 750 correct answer a" | general |
math_qa__7UA0RKuchUyuwMqs | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 188 votes. Find the total number of valid votes? Choose the correct answer
A) 430
B) 438
C) 436
D) 470
E) 422 | <gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">188 / (2/5)</gadget>
<output>470</output>
<result>D</result> | D | 470 | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 188 votes. Find the total number of valid votes? | {
"A": "430",
"B": "438",
"C": "436",
"D": "470",
"E": "422"
} | divide(188, divide(subtract(70, subtract(const_100, 70)), const_100)) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)| | "let the total number of valid votes be x . 70 % of x = 70 / 100 * x = 7 x / 10 number of votes secured by the other candidate = x - 7 x / 100 = 3 x / 10 given , 7 x / 10 - 3 x / 10 = 188 = > 4 x / 10 = 188 = > 4 x = 1880 = > x = 470 . answer : d" | gain |
math_qa__RFUXEdDzHTdGBfIc | In a classroom, 12 students brought apples and 8 students brought bananas. If exactly 10 students brought only one of the two types of fruits, how many students brought both types of fruits? Select.
A) 5 B) 6 C) 7 D) 12 E) 14 | <gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<result>A</result> | A | 5 | In a classroom, 12 students brought apples and 8 students brought bananas. If exactly 10 students brought only one of the two types of fruits, how many students brought both types of fruits? | {
"A": "5",
"B": "6",
"C": "7",
"D": "12",
"E": "14"
} | divide(add(12, 8), const_4) | add(n0,n1)|divide(#0,const_4) | say x students brought both fruits . ( 12 - x ) + ( 8 - x ) = 10 - - > x = 5 . answer : a . | other |
math_qa__esJoOj9D2Re32cmd | The average (arithmetic mean) of the even integers from 20 to 60 inclusive is how much greater than the average (arithmetic mean) of the even integers from 10 to 140 inclusive? Choose the correct choice from the following options.
A) 40 B) 15 C) 35 D) 20 E) 25 | <gadget id="calculator">140 + 10</gadget>
<output>150</output>
<gadget id="calculator">150 / 2</gadget>
<output>75</output>
<gadget id="calculator">60 + 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">75 - 40</gadget>
<output>35</output>
<result>C</result> | C | 35 | The average (arithmetic mean) of the even integers from 20 to 60 inclusive is how much greater than the average (arithmetic mean) of the even integers from 10 to 140 inclusive? | {
"A": "40",
"B": "15",
"C": "35",
"D": "20",
"E": "25"
} | subtract(divide(add(140, 10), const_2), divide(add(60, 20), const_2)) | add(n2,n3)|add(n0,n1)|divide(#0,const_2)|divide(#1,const_2)|subtract(#2,#3) | so , according to a mean of a set of even numbers from 20 to 60 = ( 20 + 60 ) / 2 = 40 and mean of a set of even numbers from 10 to 140 = ( 10 + 140 ) / 2 = 75 difference = 75 - 40 = 35 answer : c . | general |
math_qa__oUGcp1YAYpa17NRI | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 26 years. What is Deepak present age.
Choose the correct choice from the following answers:
A) 14 B) 15 C) 20 D) 22 E) 24 | <gadget id="calculator">26 - 6</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<result>B</result> | B | 15 | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 26 years. What is Deepak present age. | {
"A": "14",
"B": "15",
"C": "20",
"D": "22",
"E": "24"
} | divide(multiply(subtract(26, 6), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "explanation : present age is 4 x and 3 x , = > 4 x + 6 = 26 = > x = 5 so deepak age is = 3 ( 5 ) = 15 option b" | other |
math_qa__4n2UMCoPjVxwibk7 | Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 38 miles per hour. How many miles from the station was train A overtaken by train B? Choose the correct answer:
A) 205 B) 245 C) 285 D) 325 E) 365 | <gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">38 - 30</gadget>
<output>8</output>
<gadget id="calculator">60 / 8</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 38</gadget>
<output>285</output>
<result>C</result> | C | 285 | Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 38 miles per hour. How many miles from the station was train A overtaken by train B? | {
"A": "205",
"B": "245",
"C": "285",
"D": "325",
"E": "365"
} | multiply(divide(multiply(30, const_2), subtract(38, 30)), 38) | multiply(n0,const_2)|subtract(n1,n0)|divide(#0,#1)|multiply(n1,#2) | after two hours , train a is ahead by 60 miles . train b can catch up at a rate of 8 miles per hour . the time to catch up is 60 / 8 = 7.5 hours . in 7.5 hours , train a travels another 30 * 7.5 = 225 miles for a total of 285 miles . the answer is c . | physics |
math_qa__iAFjgZXPCJR7cKps | The length of a rectangular floor is more than its breadth by 200%. If Rs. 100 is required to paint the floor at the rate of Rs. 2 per sq m, then what would be the length of the floor? Choose the correct choice from the following answers: A) 12.25 B) 44 C) 18 D) 16 E) 14 | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 3</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) ** (1/2)</gadget>
<output>5*sqrt(6)/3 = around 4.082483</output>
<gadget id="calculator">(5*sqrt(6)/3) * 3</gadget>
<output>5*sqrt(6) = around 12.247449</output>
<result>A</result> | A | 12.25 | The length of a rectangular floor is more than its breadth by 200%. If Rs. 100 is required to paint the floor at the rate of Rs. 2 per sq m, then what would be the length of the floor? | {
"A": "12.25",
"B": "44",
"C": "18",
"D": "16",
"E": "14"
} | multiply(sqrt(divide(divide(100, 2), const_3)), const_3) | divide(n1,n2)|divide(#0,const_3)|sqrt(#1)|multiply(#2,const_3) | let the length and the breadth of the floor be l m and b m respectively . l = b + 200 % of b = l + 2 b = 3 b area of the floor = 100 / 2 = 50 sq m l b = 50 i . e . , l * l / 3 = 150 l 2 = 150 = > l = 12.25 answer : a | gain |
math_qa__MWGrB74Qicv04CUS | Anne bought doughnuts for a class breakfast party. She bought 12 chocolate doughnuts, 12 coconut doughnuts, and 10 jam-filled doughnuts. How many doughnuts did Anne buy in all?
Choose the correct choice from the following
A) 25 B) 34 C) 39 D) 21 E) 11 | <gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">24 + 10</gadget>
<output>34</output>
<result>B</result> | B | 34 | Anne bought doughnuts for a class breakfast party. She bought 12 chocolate doughnuts, 12 coconut doughnuts, and 10 jam-filled doughnuts. How many doughnuts did Anne buy in all? | {
"A": "25",
"B": "34",
"C": "39",
"D": "21",
"E": "11"
} | add(add(12, 12), 10) | add(n0,n1)|add(n2,#0)| | "add the numbers of doughnuts . 12 + 12 + 10 = 34 . answer is b ." | general |
math_qa__8DWiJHqyoUA3N5wD | A bowl was filled with 10 ounces of water, and 0.014 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? Options:
A) 0.004 % B) 0.04 % C) 0.40 % D) 7 % E) 40 % | <gadget id="calculator">50 * 0.014</gadget>
<output>0.7</output>
<gadget id="calculator">0.7 / 10</gadget>
<output>0.07</output>
<gadget id="calculator">0.07 * 100</gadget>
<output>7</output>
<result>D</result> | D | 7 | A bowl was filled with 10 ounces of water, and 0.014 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.004 %",
"B": "0.04 %",
"C": "0.40 %",
"D": "7 %",
"E": "40 %"
} | multiply(divide(multiply(50, 0.014), 10), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "total amount of water evaporated each day during a 50 - day period = . 014 * 50 = . 014 * 100 / 2 = 1.4 / 2 = . 7 percent of the original amount of water evaporated during this period = ( . 7 / 10 ) * 100 % = 7 % answer d" | gain |
math_qa__Fcjf0kTW5RjCra1M | A and B play a game where each is asked to select a number from 1 to 16. If the two numbers match , both of them win a prize. Find the probability that they will not win a prize in a single trial. Choose the correct answer:
A) 15 / 16
B) 1 / 16
C) 7 / 8
D) 9 / 8
E) none of these | <gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">15 / 16</gadget>
<output>15/16 = around 0.9375</output>
<result>A</result> | A | 0.9375 | A and B play a game where each is asked to select a number from 1 to 16. If the two numbers match , both of them win a prize. Find the probability that they will not win a prize in a single trial. | {
"A": "15 / 16",
"B": "1 / 16",
"C": "7 / 8",
"D": "9 / 8",
"E": "none of these"
} | divide(subtract(16, 1), 16) | subtract(n1,n0)|divide(#0,n1) | explanation : a and b win a prize , only if both a and b select the number . so , if a chooses a number , b has to select the same number . hence , it is problem on dependent event . let a select a number . , then p ( a ) = 1 / 16 = probability of a . now , b selects the same number after a has already selected that number . then , p ( b / a ) = 1 / 1 = dependent probability of b given a has occurred . p ( ab ) = probability of winning a prize by both a and b is : - = > p ( a ) x p ( ab ) . = > ( 1 / 16 ) x 1 = 1 / 16 . hence , the probability of not winning a prize is : - = 1 - ( 1 / 16 ) . = 15 / 16 . answer : a | other |
math_qa__LTLC3ldfR7FuJmJc | There are 20 poles with a constant distance between each pole. A car takes 20 second to reach the 12th pole. How much will it take to reach the last pole.
Pick:
A) 34.4543 B) 34.5455 C) 34.45128 D) 34.51288 E) 34.41222 | <gadget id="calculator">20 / 12</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 20</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 34.5455 | There are 20 poles with a constant distance between each pole. A car takes 20 second to reach the 12th pole. How much will it take to reach the last pole. | {
"A": "34.4543",
"B": "34.5455",
"C": "34.45128",
"D": "34.51288",
"E": "34.41222"
} | multiply(divide(20, 12), 20) | divide(n1,n2)|multiply(n0,#0)| | "assuming the car starts at the first pole . to reach the 12 th pole , the car need to travel 11 poles ( the first pole does n ' t count , as the car is already there ) . 11 poles 20 seconds 1 pole ( 20 / 11 ) seconds to reach the last ( 20 th ) pole , the car needs to travel 19 poles . 19 pole 19 x ( 20 / 11 ) seconds = 34.5455 seconds answer : b" | physics |
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