id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__7GlVb5Lt4rkvuMnd | Find the cost of fencing around a circular field of diameter 30 m at the rate of Rs.5 a meter?
Choose the correct choice from the following options.
A) 288 B) 132 C) 772 D) 592 E) 471.25 | <gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">2 * pi * 15</gadget>
<output>30*pi = around 94.24778</output>
<gadget id="calculator">(30*pi) * 5</gadget>
<output>150*pi = around 471.238898</output>
<result>E</result> | E | 471.25 | Find the cost of fencing around a circular field of diameter 30 m at the rate of Rs.5 a meter? | {
"A": "288",
"B": "132",
"C": "772",
"D": "592",
"E": "471.25"
} | multiply(circumface(divide(30, const_2)), 5) | divide(n0,const_2)|circumface(#0)|multiply(n1,#1)| | "2 * 22 / 7 * 15 = 94.25 94.25 * 5 = rs . 471.25 answer : e" | physics |
math_qa__WSJ2GGIcbafsVzRh | If x#y is defined to equal x^2/y for all x and y, then (-1#2)#-3 =
Answers:
A) 1 / 12
B) 1 / 3
C) 1 / 2
D) - 1 / 12
E) - 4 / 3 | <gadget id="calculator">-1</gadget>
<output>-1</output>
<gadget id="calculator">(-1) ** 2</gadget>
<output>1</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">-3</gadget>
<output>-3</output>
<gadget id="calculator">(1/4) / (-3)</gadget>
<output>-1/12 = around -0.083333</output>
<result>D</result> | D | -0.083333 | If x#y is defined to equal x^2/y for all x and y, then (-1#2)#-3 = | {
"A": "1 / 12",
"B": "1 / 3",
"C": "1 / 2",
"D": "- 1 / 12",
"E": "- 4 / 3"
} | divide(power(divide(power(negate(const_1), 2), 2), 2), negate(3)) | negate(const_1)|negate(n3)|power(#0,n0)|divide(#2,n0)|power(#3,n0)|divide(#4,#1) | ( - 1 ) ^ 2 / 2 = 1 / 2 ( - 1 / 2 ) ^ 2 / - 3 = - 1 / 12 so d is my answer | general |
math_qa__sNlSBMk53ptMK4Mf | 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 15 persons, working 6 hours a day, complete the work? Pick
A) 10
B) 13
C) 14
D) 26
E) 16 | <gadget id="calculator">39 * 12</gadget>
<output>468</output>
<gadget id="calculator">468 * 5</gadget>
<output>2_340</output>
<gadget id="calculator">15 * 6</gadget>
<output>90</output>
<gadget id="calculator">2_340 / 90</gadget>
<output>26</output>
<result>D</result> | D | 26 | 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 15 persons, working 6 hours a day, complete the work? | {
"A": "10",
"B": "13",
"C": "14",
"D": "26",
"E": "16"
} | divide(multiply(multiply(39, 12), 5), multiply(15, 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1)| | "let the required number of days be x . less persons , more days ( indirect proportion ) more working hours per day , less days ( indirect proportion ) persons 15 : 39 : : 12 : x working hours / day 6 : 5 15 x 6 x x = 39 x 5 x 12 x = ( 39 x 5 x 12 ) / ( 15 x 6 ) x = 26 . answer : d" | physics |
math_qa__EbypimdmDIpoc42S | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4.5 liters per minute. When the tank is full in inlet is opened and due to the leak the tank is empties in 8 hours. The capacity of the tank is? Choose the correct answer:
A) 5729
B) 5760
C) 2889
D) 6480
E) 2799 | <gadget id="calculator">8 * 60</gadget>
<output>480</output>
<gadget id="calculator">4.5 * 480</gadget>
<output>2_160</output>
<gadget id="calculator">6 * 60</gadget>
<output>360</output>
<gadget id="calculator">480 / 360</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) - 1</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2_160 / (1/3)</gadget>
<output>6_480</output>
<result>D</result> | D | 6,480 | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 4.5 liters per minute. When the tank is full in inlet is opened and due to the leak the tank is empties in 8 hours. The capacity of the tank is? | {
"A": "5729",
"B": "5760",
"C": "2889",
"D": "6480",
"E": "2799"
} | divide(multiply(4.5, multiply(8, const_60)), subtract(divide(multiply(8, const_60), multiply(6, const_60)), const_1)) | multiply(n2,const_60)|multiply(n0,const_60)|divide(#0,#1)|multiply(n1,#0)|subtract(#2,const_1)|divide(#3,#4)| | "1 / x - 1 / 6 = - 1 / 8 x = 24 hrs 24 * 60 * 4.5 = 6480 . answer : d" | physics |
math_qa__Unwp4vYlmTMORsWm | Last year Sandy saved 6% of her annual salary. This year, she made 10% more money than last year, and she saved 8% of her salary. The amount saved this year was what percent of the amount she saved last year? Choices: A) 132 % B) 147 % C) 158 % D) 176 % E) 188 % | <gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">(2/25) * 110</gadget>
<output>44/5 = around 8.8</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">(44/5) / 6</gadget>
<output>22/15 = around 1.466667</output>
<gadget id="calculator">(22/15) * 100</gadget>
<output>440/3 = around 146.666667</output>
<result>B</result> | B | 147 | Last year Sandy saved 6% of her annual salary. This year, she made 10% more money than last year, and she saved 8% of her salary. The amount saved this year was what percent of the amount she saved last year? | {
"A": "132 %",
"B": "147 %",
"C": "158 %",
"D": "176 %",
"E": "188 %"
} | multiply(divide(multiply(divide(8, const_100), add(const_100, 10)), divide(multiply(6, const_100), const_100)), const_100) | add(n1,const_100)|divide(n2,const_100)|multiply(n0,const_100)|divide(#2,const_100)|multiply(#0,#1)|divide(#4,#3)|multiply(#5,const_100)| | "let last year ' s salary be x . last year , sandy save 0.06 x this year , sandy saved 0.08 * 1.1 x = 0.088 x 0.088 x / 0.06 x = 88 / 60 = 1.47 = 147 % the answer is b ." | gain |
math_qa__QroNF2uDMlmDrv5d | The length of a rectangle is twice its breadth. If its length is decreased by 10 cm and breadth is increased by 10 cm, the area of the rectangle is increased by 75 sq.cm. What is the length of the rectangle? Choose the correct choice from the following answers.
A) 25 cm
B) 35 cm
C) 30 cm
D) 45 cm
E) 55 cm | <gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 35 | The length of a rectangle is twice its breadth. If its length is decreased by 10 cm and breadth is increased by 10 cm, the area of the rectangle is increased by 75 sq.cm. What is the length of the rectangle? | {
"A": "25 cm",
"B": "35 cm",
"C": "30 cm",
"D": "45 cm",
"E": "55 cm"
} | divide(const_100, const_3) | divide(const_100,const_3)| | "let breadth = x cm then , length = 2 x cm area = x × 2 x = 2 x ^ 2 sq . cm . new length = ( 2 x − 10 ) cm new breadth = ( x + 10 ) cm new area = ( 2 x − 10 ) ( x + 10 ) sq . cm . given that , new area = initial area + 75 sq . cm . ⇒ ( 2 x − 10 ) ( x + 10 ) = 2 x ^ 2 + 75 ⇒ 2 x ^ 2 + 20 x − 10 x − 100 = 2 x ^ 2 + 75 ⇒ 10 x − 100 = 75 ⇒ 10 x = 75 + 100 = 175 ⇒ x = 175 / 10 = 17.5 cm length = 2 x = 2 × 17.5 = 35 cm answer : b" | geometry |
math_qa__u3SNXNYZCzeVCmBW | 7 years ago, Paula was 3 times as old as Karl. In 2 years, Paula will be twice as old as Karl. What is the sum of their ages now?
Choose the correct choice from the following.
A) 26 B) 32 C) 38 D) 44 E) 50 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">2 - 4</gadget>
<output>-2</output>
<gadget id="calculator">-(-2)</gadget>
<output>2</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 - 7</gadget>
<output>14</output>
<gadget id="calculator">2 + 14</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 - 14</gadget>
<output>34</output>
<gadget id="calculator">34 + 16</gadget>
<output>50</output>
<result>E</result> | E | 50 | 7 years ago, Paula was 3 times as old as Karl. In 2 years, Paula will be twice as old as Karl. What is the sum of their ages now? | {
"A": "26",
"B": "32",
"C": "38",
"D": "44",
"E": "50"
} | add(subtract(multiply(add(negate(subtract(2, multiply(2, const_2))), subtract(multiply(7, 3), 7)), 3), subtract(multiply(7, 3), 7)), add(negate(subtract(2, multiply(2, const_2))), subtract(multiply(7, 3), 7))) | multiply(n2,const_2)|multiply(n0,n1)|subtract(n2,#0)|subtract(#1,n0)|negate(#2)|add(#4,#3)|multiply(#5,n1)|subtract(#6,#3)|add(#5,#7)| | "p - 7 = 3 ( k - 7 ) and so p = 3 k - 14 p + 2 = 2 ( k + 2 ) ( 3 k - 14 ) + 2 = 2 k + 4 k = 16 p = 34 p + k = 50 the answer is e ." | general |
math_qa__ezmFr5U4dIGqVbl3 | A dress on sale in a shop is marked at $D. During the discount sale its price is reduced by 65%. Staff are allowed a further 60% reduction on the discounted price. If a staff member buys the dress what will she have to pay in terms of D ? Choose the correct choice from the following options.
A) 0.15 d B) 0.16 d C) 0.65 d D) 0.14 d E) 0.05 d | <gadget id="calculator">100 - 65</gadget>
<output>35</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(7/20) * (3/5)</gadget>
<output>21/100 = around 0.21</output>
<gadget id="calculator">(7/20) - (21/100)</gadget>
<output>7/50 = around 0.14</output>
<result>D</result> | D | 0.14 | A dress on sale in a shop is marked at $D. During the discount sale its price is reduced by 65%. Staff are allowed a further 60% reduction on the discounted price. If a staff member buys the dress what will she have to pay in terms of D ? | {
"A": "0.15 d",
"B": "0.16 d",
"C": "0.65 d",
"D": "0.14 d",
"E": "0.05 d"
} | subtract(divide(subtract(const_100, 65), const_100), multiply(divide(subtract(const_100, 65), const_100), divide(60, const_100))) | divide(n1,const_100)|subtract(const_100,n0)|divide(#1,const_100)|multiply(#2,#0)|subtract(#2,#3)| | "effective discount = a + b + ab / 100 = - 65 - 60 + ( - 65 ) ( - 60 ) / 100 = - 86 sale price = d * ( 1 - 86 / 100 ) sale price = . 14 * d answer ( d )" | gain |
math_qa__dPOirz7QXwAeuZlU | If a truck is traveling at a constant rate of 54 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters) Choose the correct choice from the following choices
A) 18 B) 24 C) 30 D) 36 E) 40 | <gadget id="calculator">600 / 1_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / 54</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">(1/90) * 3_600</gadget>
<output>40</output>
<result>E</result> | E | 40 | If a truck is traveling at a constant rate of 54 kilometers per hour, how many seconds will it take the truck to travel a distance of 600 meters? (1 kilometer = 1000 meters) | {
"A": "18",
"B": "24",
"C": "30",
"D": "36",
"E": "40"
} | multiply(divide(divide(600, 1000), 54), const_3600) | divide(n1,n3)|divide(#0,n0)|multiply(#1,const_3600)| | "speed = 54 km / hr = > 54,000 m / hr in one minute = > 54000 / 60 = 900 meters in one sec = > 900 / 60 = 15 meters time = total distance need to be covered / avg . speed = > 600 / 15 = 40 and hence the answer : e" | physics |
math_qa__OyiCNoUmGunAUUzj | The ratio 2:10 expressed as percent equals to Choose one.
A) 50 % B) 30 % C) 25 % D) 20 % E) 90 % | <gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>D</result> | D | 20 | The ratio 2:10 expressed as percent equals to | {
"A": "50 %",
"B": "30 %",
"C": "25 %",
"D": "20 %",
"E": "90 %"
} | multiply(divide(2, 10), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "explanation : actually it means 2 is what percent of 10 , which can be calculated as , ( 2 / 10 ) * 100 = 2 * 10 = 20 answer : option d" | general |
math_qa__U3rXnUhxxsTpafSI | A watch was sold at a loss of 21%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? Answers.
A) 560 B) 882 C) 799 D) 778 E) 901 | <gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 21</gadget>
<output>79</output>
<gadget id="calculator">104 - 79</gadget>
<output>25</output>
<gadget id="calculator">14_000 / 25</gadget>
<output>560</output>
<result>A</result> | A | 560 | A watch was sold at a loss of 21%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? | {
"A": "560",
"B": "882",
"C": "799",
"D": "778",
"E": "901"
} | divide(multiply(140, const_100), subtract(add(const_100, 4), subtract(const_100, 21))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "79 % 104 % - - - - - - - - 25 % - - - - 140 100 % - - - - ? = > rs . 560 answer : a" | gain |
math_qa__6T9fmjKCxMa5a0nz | At a certain restaurant, the ratio of the number of cooks to the number of waiters is 3 to 8. When 12 more waiters are hired, the ratio of the number of cooks to the number of waiters changes to 1 to 4. How many cooks does the restaurant have? Pick one:
A) 4 B) 6 C) 9 D) 12 E) 15 | <gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<result>C</result> | C | 9 | At a certain restaurant, the ratio of the number of cooks to the number of waiters is 3 to 8. When 12 more waiters are hired, the ratio of the number of cooks to the number of waiters changes to 1 to 4. How many cooks does the restaurant have? | {
"A": "4",
"B": "6",
"C": "9",
"D": "12",
"E": "15"
} | multiply(divide(12, 4), divide(12, 4)) | divide(n2,n4)|multiply(#0,#0) | originally there were 3 k cooks and 8 k waiters . the new ratio is 1 : 4 which equals 3 : 12 . 12 k = 8 k + 12 k = 3 there are 9 cooks . the answer is c . | other |
math_qa__kyvc8QHaY1ACUJiU | A bag contains 5 green balls and 8 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour?
Options:
A) 3 / 7
B) 6 / 11
C) 12 / 21
D) 19 / 39
E) 29 / 49 | <gadget id="calculator">5 + 8</gadget>
<output>13</output>
<gadget id="calculator">8 / 13</gadget>
<output>8/13 = around 0.615385</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">13 - 1</gadget>
<output>12</output>
<gadget id="calculator">7 / 12</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(8/13) * (7/12)</gadget>
<output>14/39 = around 0.358974</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">5 / 13</gadget>
<output>5/13 = around 0.384615</output>
<gadget id="calculator">(1/3) * (5/13)</gadget>
<output>5/39 = around 0.128205</output>
<gadget id="calculator">(14/39) + (5/39)</gadget>
<output>19/39 = around 0.487179</output>
<result>D</result> | D | 0.487179 | A bag contains 5 green balls and 8 white balls. If two balls are drawn simultaneously, what is the probability that both balls are the same colour? | {
"A": "3 / 7",
"B": "6 / 11",
"C": "12 / 21",
"D": "19 / 39",
"E": "29 / 49"
} | add(multiply(divide(8, add(5, 8)), divide(subtract(8, const_1), subtract(add(5, 8), const_1))), multiply(divide(subtract(5, const_1), subtract(add(5, 8), const_1)), divide(5, add(5, 8)))) | add(n0,n1)|subtract(n1,const_1)|subtract(n0,const_1)|divide(n1,#0)|divide(n0,#0)|subtract(#0,const_1)|divide(#1,#5)|divide(#2,#5)|multiply(#3,#6)|multiply(#7,#4)|add(#8,#9)| | "the total number of ways to draw two balls is 13 c 2 = 78 the number of ways to draw two green balls is 5 c 2 = 10 the number of ways to draw two white balls is 8 c 2 = 28 p ( two balls of the same colour ) = 38 / 78 = 19 / 39 the answer is d ." | other |
math_qa__53j0QuahyjlK92Q9 | If 60% of 3/5 of a number is 36, then the number is?
Choose the most appropriate option: A) 80 B) 100 C) 75 D) 90 E) none of these | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">36 / (9/25)</gadget>
<output>100</output>
<result>B</result> | B | 100 | If 60% of 3/5 of a number is 36, then the number is? | {
"A": "80",
"B": "100",
"C": "75",
"D": "90",
"E": "none of these"
} | divide(36, multiply(divide(60, const_100), divide(3, 5))) | divide(n0,const_100)|divide(n1,n2)|multiply(#0,#1)|divide(n3,#2)| | "let the number be x . then 60 % of 3 / 5 of x = 36 60 / 100 * 3 / 5 * x = 36 x = ( 36 * 25 / 9 ) = 100 required number = 100 . correct option : b" | gain |
math_qa__TedY7QUYBqacG6rq | A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is? Choose the correct choice
A) 16 % B) 15 % C) 12 % D) 22 % E) 19 % | <gadget id="calculator">12_005 - 9_800</gadget>
<output>2_205</output>
<gadget id="calculator">9_800 * 8</gadget>
<output>78_400</output>
<gadget id="calculator">5 * 12_005</gadget>
<output>60_025</output>
<gadget id="calculator">78_400 - 60_025</gadget>
<output>18_375</output>
<gadget id="calculator">2_205 / 18_375</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) * 100</gadget>
<output>12</output>
<result>C</result> | C | 12 | A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is? | {
"A": "16 %",
"B": "15 %",
"C": "12 %",
"D": "22 %",
"E": "19 %"
} | multiply(divide(subtract(12005, 9800), subtract(multiply(9800, 8), multiply(5, 12005))), const_100) | multiply(n0,n3)|multiply(n1,n2)|subtract(n2,n0)|subtract(#0,#1)|divide(#2,#3)|multiply(#4,const_100)| | "s . i . for 3 years = ( 12005 - 9800 ) = rs . 2205 s . i . for 5 years = rs . 2205 / 3 * 5 = rs . 3675 . principal = ( 9800 - 3675 ) = rs . 6125 hence , rate = ( 100 * 3675 ) / ( 6125 * 5 ) = 12 % answer : c" | gain |
math_qa__fmzl9BwJbzEIF7Gl | In a college, 1 percent of students hate math, 2 percent of students hate English, 1 percent hate French and 4 percent hate German.
Can you find out the percentage of students who hate all 4 subjects ? Choose one:
A) 8 % B) 5 % C) 7 % D) 12 % E) 19 % | <gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>A</result> | A | 8 | In a college, 1 percent of students hate math, 2 percent of students hate English, 1 percent hate French and 4 percent hate German.
Can you find out the percentage of students who hate all 4 subjects ? | {
"A": "8 %",
"B": "5 %",
"C": "7 %",
"D": "12 %",
"E": "19 %"
} | multiply(4, multiply(1, 2)) | multiply(n0,n1)|multiply(n3,#0) | a 8 % of student hate all four subjects . | gain |
math_qa__fFKn6yMLZWL09iE5 | Amit and Ananthu can do a work in 15 days and 30 days respectively. Amit started the work and left after 3 days. Ananthu took over and completed the work. In how many days was the total work completed? Choose one:
A) 28 days
B) 20 days
C) 23 days
D) 25 days
E) 27 days | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) * 3</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(4/5) / (1/30)</gadget>
<output>24</output>
<gadget id="calculator">24 + 3</gadget>
<output>27</output>
<result>E</result> | E | 27 | Amit and Ananthu can do a work in 15 days and 30 days respectively. Amit started the work and left after 3 days. Ananthu took over and completed the work. In how many days was the total work completed? | {
"A": "28 days",
"B": "20 days",
"C": "23 days",
"D": "25 days",
"E": "27 days"
} | add(divide(subtract(const_1, multiply(inverse(15), 3)), inverse(30)), 3) | inverse(n0)|inverse(n1)|multiply(#0,n2)|subtract(const_1,#2)|divide(#3,#1)|add(#4,n2)| | "amit ’ s one day ’ s work = 1 / 15 amit ’ s 3 day ’ s work = 1 / 15 * 3 = 1 / 5 work left = 1 - 1 / 5 = 4 / 5 ananthu ’ s one day ’ s work = 1 / 30 ananthu can do work in = 4 / 5 * 30 = 24 days so total days = 24 + 3 = 27 days answer : e" | physics |
math_qa__lHYvu3ll9JtgQvJ6 | If a - b = 3 and a(power 2) + b(power 2) = 39, find the value of ab. Select the correct option:
A) 15 B) 8 C) 4 D) 10 E) 3 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">39 - 9</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | If a - b = 3 and a(power 2) + b(power 2) = 39, find the value of ab. | {
"A": "15",
"B": "8",
"C": "4",
"D": "10",
"E": "3"
} | divide(subtract(39, power(3, 2)), 2) | power(n0,n1)|subtract(n3,#0)|divide(#1,n1)| | "2 ab = ( a ( power 2 ) + b ( power 2 ) - ( a - b ) ( power 2 ) = 39 - 9 = 30 ab = 15 . answer is a ." | general |
math_qa__F6G479bHxVspLdKn | A cylinder of height h is 2/3 of water. When all of the water is poured into an empty cylinder whose radius is 25 percent larger than that of the original cylinder, the new cylinder is 3/5 full. The height of the new cylinder is what percent of h? Choose one:
A) 25 %
B) 50 %
C) 60 %
D) 80 %
E) 90 % | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(3/5) / (2/3)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 100</gadget>
<output>90</output>
<result>E</result> | E | 90 | A cylinder of height h is 2/3 of water. When all of the water is poured into an empty cylinder whose radius is 25 percent larger than that of the original cylinder, the new cylinder is 3/5 full. The height of the new cylinder is what percent of h? | {
"A": "25 %",
"B": "50 %",
"C": "60 %",
"D": "80 %",
"E": "90 %"
} | multiply(divide(divide(3, 5), divide(2, 3)), const_100) | divide(n3,n4)|divide(n0,n1)|divide(#0,#1)|multiply(#2,const_100)| | "basically we can disregard the radius is 25 % information , as we are only asked about the height of the original and the new cylinder . this is becausethe new cylinder is 3 / 5 fullmeans the same as that it ' s height is 3 / 5 . original cylinder 2 / 3 new cylinder 3 / 5 so 3 / 5 / 2 / 3 = 3 / 5 * 3 / 2 = 0.90 or 90 % . answer e" | gain |
math_qa__XkoCv53dStdG61U5 | Express a speed of 108 kmph in meters per second?
Choose one
A) 30 mps B) 76 mps C) 26 mps D) 97 mps E) 16 mps | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 108</gadget>
<output>30</output>
<result>A</result> | A | 30 | Express a speed of 108 kmph in meters per second? | {
"A": "30 mps",
"B": "76 mps",
"C": "26 mps",
"D": "97 mps",
"E": "16 mps"
} | multiply(const_0_2778, 108) | multiply(n0,const_0_2778)| | "108 * 5 / 18 = 30 mps answer : a" | physics |
math_qa__IhH8tLXv5tPMFvF4 | The ratio of the two natural numbers is 6 : 5. If a certain number is subtracted to both the numbers, the ratio becomes 5 : 4. If the larger number exceeds the smaller number by 5, find the number subtracted? Options.
A) 8 B) 5 C) 15 D) 22 E) 6 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 5</gadget>
<output>125</output>
<gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">125 - 120</gadget>
<output>5</output>
<result>B</result> | B | 5 | The ratio of the two natural numbers is 6 : 5. If a certain number is subtracted to both the numbers, the ratio becomes 5 : 4. If the larger number exceeds the smaller number by 5, find the number subtracted? | {
"A": "8",
"B": "5",
"C": "15",
"D": "22",
"E": "6"
} | subtract(multiply(multiply(5, 5), 5), multiply(add(multiply(5, 5), 5), 4)) | multiply(n1,n1)|add(n1,#0)|multiply(n1,#0)|multiply(n3,#1)|subtract(#2,#3) | let the two numbers be 6 x and 5 x . let the numbers subtracted to both so that their ratio becomes 5 : 4 be k . ( 6 x - k ) / ( 5 x - k ) = 5 / 4 = > 24 x - 4 k = 25 x - 5 k = > k = x . 6 x - 5 x = 5 = > x = 5 k = x = 5 . answer : b | other |
math_qa__XppV8EGWNOSRPYQZ | 200 is what percent of 50?
Choose the correct choice from the following options.
A) 0.2 %
B) 2 %
C) 5 %
D) 20 %
E) 400 % | <gadget id="calculator">200 / 50</gadget>
<output>4</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<result>E</result> | E | 400 | 200 is what percent of 50? | {
"A": "0.2 %",
"B": "2 %",
"C": "5 %",
"D": "20 %",
"E": "400 %"
} | multiply(divide(200, 50), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "200 = x * 50 / 100 x = 400 % ans ; e" | gain |
math_qa__LoQLWvpEvEzgRGl7 | A big container is 30% full with water. If 54 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container? Answers
A) 36 liters B) 40 liters C) 45 liters D) 54 liters E) 120 liters | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/4) - (3/10)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">54 / (9/20)</gadget>
<output>120</output>
<result>E</result> | E | 120 | A big container is 30% full with water. If 54 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container? | {
"A": "36 liters",
"B": "40 liters",
"C": "45 liters",
"D": "54 liters",
"E": "120 liters"
} | divide(54, subtract(divide(3, 4), divide(30, const_100))) | divide(n2,n3)|divide(n0,const_100)|subtract(#0,#1)|divide(n1,#2)| | "a big container is 30 % full with water and after 54 liters of water is added , the container becomes 75 % full . hence these 54 liters account for 45 % of the container , which means that the capacity of it is 54 / 0.45 = 120 liters . or : if the capacity of the container is x liters then : 0.3 x + 54 = 0.75 x - - > x = 120 liters . answer : e" | general |
math_qa__V9goDLIHLaTNDuPn | At what rate percent per annum will the simple interest on a sum of money be 6/5 of the amount in 10 years? Select:
A) 4 %
B) 7 %
C) 9 %
D) 3 %
E) 12 % | <gadget id="calculator">6 / 5</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 100</gadget>
<output>120</output>
<gadget id="calculator">120 / 10</gadget>
<output>12</output>
<result>E</result> | E | 12 | At what rate percent per annum will the simple interest on a sum of money be 6/5 of the amount in 10 years? | {
"A": "4 %",
"B": "7 %",
"C": "9 %",
"D": "3 %",
"E": "12 %"
} | divide(multiply(divide(6, 5), const_100), 10) | divide(n0,n1)|multiply(#0,const_100)|divide(#1,n2)| | "let sum = x . then , s . i . = 6 x / 5 , time = 10 years . rate = ( 100 * 6 x ) / ( x * 5 * 10 ) = 12 % answer : e" | gain |
math_qa__tbayAgxGOQvA6iAg | If x is real, find the maximum value of the expression -2x^2 + 5x + 7. Choose the correct choice from the following options.
A) 6.125
B) 8.125
C) 10.125
D) 12.125
E) 14.125 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">5 * (4/5)</gadget>
<output>4</output>
<gadget id="calculator">4 + 7</gadget>
<output>11</output>
<gadget id="calculator">(4/5) ** 2</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">2 * (16/25)</gadget>
<output>32/25 = around 1.28</output>
<gadget id="calculator">11 - (32/25)</gadget>
<output>243/25 = around 9.72</output>
<result>C</result> | C | 10.125 | If x is real, find the maximum value of the expression -2x^2 + 5x + 7. | {
"A": "6.125",
"B": "8.125",
"C": "10.125",
"D": "12.125",
"E": "14.125"
} | subtract(add(multiply(5, divide(multiply(2, 2), 5)), 7), multiply(2, power(divide(multiply(2, 2), 5), 2))) | multiply(n0,n0)|divide(#0,n2)|multiply(n2,#1)|power(#1,n0)|add(n3,#2)|multiply(n0,#3)|subtract(#4,#5) | this is an equation of a downward facing parabola . the maximum value is the top point of the parabola . - 2 x ^ 2 + 5 x + 7 = ( - 2 x + 7 ) ( x + 1 ) the roots are 7 / 2 and - 1 . the maximum value must be when x is halfway between these two points . x = 1.25 the maximum value is - 2 ( 1.25 ) ^ 2 + 5 ( 1.25 ) + 7 = 10.125 the answer is c . | general |
math_qa__oCJlkVuZnHA3NOMd | The perimeter of one face of a cube is 40 cm. Its volume will be:
Answers:
A) 125 cm 3 B) 400 cm 3 C) 250 cm 3 D) 1000 cm 3 E) none of these | <gadget id="calculator">40 / 4</gadget>
<output>10</output>
<gadget id="calculator">10 ** 3</gadget>
<output>1_000</output>
<result>D</result> | D | 1,000 | The perimeter of one face of a cube is 40 cm. Its volume will be: | {
"A": "125 cm 3",
"B": "400 cm 3",
"C": "250 cm 3",
"D": "1000 cm 3",
"E": "none of these"
} | volume_cube(square_edge_by_perimeter(40)) | square_edge_by_perimeter(n0)|volume_cube(#0)| | "explanation : edge of cude = 40 / 4 = 10 cm volume = a * a * a = 10 * 10 * 10 = 1000 cm cube option d" | geometry |
math_qa__Eh8tS7SpZiKpcRgs | A starts business with Rs.3500 and after 10 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the Capital ? Choices: A) 24887 B) 20778 C) 23788 D) 31500 E) 2811 | <gadget id="calculator">3_500 * 12</gadget>
<output>42_000</output>
<gadget id="calculator">42_000 * 3</gadget>
<output>126_000</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">126_000 / 4</gadget>
<output>31_500</output>
<result>D</result> | D | 31,500 | A starts business with Rs.3500 and after 10 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the Capital ? | {
"A": "24887",
"B": "20778",
"C": "23788",
"D": "31500",
"E": "2811"
} | divide(multiply(multiply(3500, const_12), 3), multiply(subtract(const_12, 10), 2)) | multiply(n0,const_12)|subtract(const_12,n1)|multiply(n3,#0)|multiply(n2,#1)|divide(#2,#3)| | "explanation : a invested rs . 3500 for 12 months . let b joined with investment x . and he invested for 12 - 10 = 2 months . so there profit ratio = ( 3500 ã — 12 ) : ( 2 x ) = 2 : 3 â ‡ ’ x = 31500 answer : d" | other |
math_qa__UoyJzDU8pfvNDRwN | If the personal income tax rate is lowered from 45% to 30%, what is the differential savings for a tax payer having an annual income before tax to the tune of $48000? Choose the correct choice from the following answers.
A) $ 3500 B) $ 5000 C) $ 3150 D) $ 7200 E) $ 10000 | <gadget id="calculator">48_000 / 100</gadget>
<output>480</output>
<gadget id="calculator">45 - 30</gadget>
<output>15</output>
<gadget id="calculator">480 * 15</gadget>
<output>7_200</output>
<result>D</result> | D | 7,200 | If the personal income tax rate is lowered from 45% to 30%, what is the differential savings for a tax payer having an annual income before tax to the tune of $48000? | {
"A": "$ 3500",
"B": "$ 5000",
"C": "$ 3150",
"D": "$ 7200",
"E": "$ 10000"
} | multiply(divide(48000, const_100), subtract(45, 30)) | divide(n2,const_100)|subtract(n0,n1)|multiply(#0,#1) | saving = ( 45 - 30 ) % of 48000 = 7200 . answer : d | gain |
math_qa__3GzABPU06iXGuwIh | A trader sells 45 meters of cloth for Rs. 4500 at the profit of Rs. 12 per metre of cloth. What is the cost price of one metre of cloth? Answers
A) rs . 80 B) rs . 85 C) rs . 88 D) rs . 100 E) none of these | <gadget id="calculator">4_500 / 45</gadget>
<output>100</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<result>C</result> | C | 88 | A trader sells 45 meters of cloth for Rs. 4500 at the profit of Rs. 12 per metre of cloth. What is the cost price of one metre of cloth? | {
"A": "rs . 80",
"B": "rs . 85",
"C": "rs . 88",
"D": "rs . 100",
"E": "none of these"
} | subtract(divide(4500, 45), 12) | divide(n1,n0)|subtract(#0,n2) | sp of 1 m of cloth = 4500 / 45 = rs . 100 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 100 - rs . 12 = rs . 88 . answer : c | physics |
math_qa__u8tbhKI0tYg12lLp | How much is 80% of 60 is greater than 4/5 of 25? Answers.
A) 15 B) 28 C) 16 D) 12 E) 73 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">60 * (4/5)</gadget>
<output>48</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 25</gadget>
<output>20</output>
<gadget id="calculator">48 - 20</gadget>
<output>28</output>
<result>B</result> | B | 28 | How much is 80% of 60 is greater than 4/5 of 25? | {
"A": "15",
"B": "28",
"C": "16",
"D": "12",
"E": "73"
} | subtract(multiply(60, divide(80, const_100)), multiply(divide(4, 5), 25)) | divide(n0,const_100)|divide(n2,n3)|multiply(n1,#0)|multiply(n4,#1)|subtract(#2,#3)| | "( 80 / 100 ) * 60 â € “ ( 4 / 5 ) * 25 48 - 20 = 28 answer : b" | general |
math_qa__Oeb0pLetrAvGCUQa | A 6 litre sol is 30% alcohol .How many litres of pure alcohol must be added to produce a sol that is 50% alcohol ?
Select: A) a . 0.6 B) b . 1 C) c . 2.1 D) d . 3 E) e . 2.4 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 6</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">2 * (9/5)</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">6 - (18/5)</gadget>
<output>12/5 = around 2.4</output>
<result>E</result> | E | 2.4 | A 6 litre sol is 30% alcohol .How many litres of pure alcohol must be added to produce a sol that is 50% alcohol ? | {
"A": "a . 0.6",
"B": "b . 1",
"C": "c . 2.1",
"D": "d . 3",
"E": "e . 2.4"
} | subtract(6, multiply(const_2, multiply(divide(30, const_100), 6))) | divide(n1,const_100)|multiply(n0,#0)|multiply(#1,const_2)|subtract(n0,#2) | 30 % of 6 = 1.8 50 % of 6 = 3 shortage is 1.2 so we need to have 1.2 / 50 % to get 50 % alcohol content . = 2.4 e | gain |
math_qa__mNX6Zm3HqQoji3Fy | can you find a 7 digit number which describes itself . the first digit is the number of zeros in the number . the second digit is the number of ones in the number , etc . for example , in the number 21200 , there are 2 zeros , 1 one , 2 twos , 0 threes and 0 fours . Choose the correct answer:
A) 4211000
B) 1211000
C) 5211000
D) 2211000
E) 3211000 | <gadget id="calculator">21_200 * 10</gadget>
<output>212_000</output>
<gadget id="calculator">212_000 * 3</gadget>
<output>636_000</output>
<gadget id="calculator">636_000 / 2</gadget>
<output>318_000</output>
<gadget id="calculator">318_000 * 1_000</gadget>
<output>318_000_000</output>
<gadget id="calculator">318_000_000 / 10</gadget>
<output>31_800_000</output>
<gadget id="calculator">31_800_000 / 10</gadget>
<output>3_180_000</output>
<gadget id="calculator">3_180_000 + 21_200</gadget>
<output>3_201_200</output>
<gadget id="calculator">3_201_200 + 21_200</gadget>
<output>3_222_400</output>
<gadget id="calculator">3_222_400 - 1_000</gadget>
<output>3_221_400</output>
<gadget id="calculator">3_221_400 - 1_000</gadget>
<output>3_220_400</output>
<gadget id="calculator">3_220_400 - 3_600</gadget>
<output>3_216_800</output>
<gadget id="calculator">3_216_800 - 3_600</gadget>
<output>3_213_200</output>
<gadget id="calculator">3_213_200 - 1_000</gadget>
<output>3_212_200</output>
<gadget id="calculator">3_212_200 - 1_000</gadget>
<output>3_211_200</output>
<gadget id="calculator">3_211_200 - 100</gadget>
<output>3_211_100</output>
<gadget id="calculator">3_211_100 - 100</gadget>
<output>3_211_000</output>
<result>E</result> | E | 3,211,000 | can you find a 7 digit number which describes itself . the first digit is the number of zeros in the number . the second digit is the number of ones in the number , etc . for example , in the number 21200 , there are 2 zeros , 1 one , 2 twos , 0 threes and 0 fours . | {
"A": "4211000",
"B": "1211000",
"C": "5211000",
"D": "2211000",
"E": "3211000"
} | subtract(subtract(subtract(subtract(subtract(subtract(subtract(subtract(add(add(divide(divide(multiply(divide(multiply(multiply(21200, const_10), const_3), 2), const_1000), const_10), const_10), 21200), 21200), const_1000), const_1000), const_3600), const_3600), const_1000), const_1000), const_100), const_100) | multiply(n1,const_10)|multiply(#0,const_3)|divide(#1,n2)|multiply(#2,const_1000)|divide(#3,const_10)|divide(#4,const_10)|add(n1,#5)|add(n1,#6)|subtract(#7,const_1000)|subtract(#8,const_1000)|subtract(#9,const_3600)|subtract(#10,const_3600)|subtract(#11,const_1000)|subtract(#12,const_1000)|subtract(#13,const_100)|subtract(#14,const_100) | e 3211000 | physics |
math_qa__xZgVVDHu3iovz6Ji | A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is Choose the correct answer:
A) 8.5 km / hr B) 9 km / hr C) 10 km / hr D) 12.5 km / hr E) none | <gadget id="calculator">15 - 2.5</gadget>
<output>12.5</output>
<gadget id="calculator">12.5 - 2.5</gadget>
<output>10</output>
<result>C</result> | C | 10 | A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is | {
"A": "8.5 km / hr",
"B": "9 km / hr",
"C": "10 km / hr",
"D": "12.5 km / hr",
"E": "none"
} | subtract(subtract(15, 2.5), 2.5) | subtract(n0,n1)|subtract(#0,n1) | sol . man ' s rate in still in water = ( 15 - 2.5 ) km / hr = 12.5 km / hr . man ' s rate against the current = ( 12.5 - 2.5 ) km / hr = 10 km / hr . answer c | gain |
math_qa__pWm803rMhZ1x6TH9 | In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
Choose the correct option.
A) 2.5 sec B) 2.8 sec C) 8.5 sec D) 2.2 sec E) 4.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">100 / 40</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.5 sec",
"B": "2.8 sec",
"C": "8.5 sec",
"D": "2.2 sec",
"E": "4.5 sec"
} | divide(100, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 100 / 40 = 2.5 sec . answer : a" | physics |
math_qa__Kw1PrRVXRQ1VHVLf | If R is a positive integer, and R/15 = 8.2, what is the remainder when R is divided by 15?
Choose the correct choice from the following answers
A) a . 1 B) b . 2 C) c . 3 D) d . 4 E) e . 8 | <gadget id="calculator">8.2 * 15</gadget>
<output>123</output>
<gadget id="calculator">123 % 15</gadget>
<output>3</output>
<result>C</result> | C | 3 | If R is a positive integer, and R/15 = 8.2, what is the remainder when R is divided by 15? | {
"A": "a . 1",
"B": "b . 2",
"C": "c . 3",
"D": "d . 4",
"E": "e . 8"
} | reminder(multiply(8.2, 15), 15) | multiply(n0,n1)|reminder(#0,n0) | if r were a multiple of 15 , the quotient r / 15 would be an integer . the fact that it ' s a decimal tells us that 15 goes into r eight whole times and some decimal part of a time . this decimal part , 0.2 is the remainder divided by the divisor . let b be the remainder . b / 15 = 0.2 = 1 / 5 b = ( 15 ) * ( 1 / 5 ) = 3 answer = ( c ) | general |
math_qa__ZN7tNteUnhroi9sd | Working alone, printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 15, 12, and 18 hours, respectively. What is the ratio of the time it takes printer X to do the job, working alone at its rate, to the time it takes printers Y and Z to do the job, working together at their individual rates? Select the correct option
A) 4 / 15 B) 1 / 2 C) 15 / 22 D) 25 / 12 E) 11 / 4 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/12) + (1/18)</gadget>
<output>5/36 = around 0.138889</output>
<gadget id="calculator">1 / (5/36)</gadget>
<output>36/5 = around 7.2</output>
<gadget id="calculator">15 / (36/5)</gadget>
<output>25/12 = around 2.083333</output>
<result>D</result> | D | 2.083333 | Working alone, printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 15, 12, and 18 hours, respectively. What is the ratio of the time it takes printer X to do the job, working alone at its rate, to the time it takes printers Y and Z to do the job, working together at their individual rates? | {
"A": "4 / 15",
"B": "1 / 2",
"C": "15 / 22",
"D": "25 / 12",
"E": "11 / 4"
} | divide(15, divide(const_1, add(divide(const_1, 12), divide(const_1, 18)))) | divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|divide(const_1,#2)|divide(n0,#3)| | "the time it takes printer x is 15 hours . the combined rate of y and z is 1 / 12 + 1 / 18 = 5 / 36 the time it takes y and z is 36 / 5 the ratio of times is 15 / ( 36 / 5 ) = 5 * 15 / 36 = 25 / 12 the answer is d ." | general |
math_qa__re22P4wd9RFRYrZx | what is the 20 - fifth decimal to the right in the fraction 10 / 11 ? Pick one.
A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">10 / 11</gadget>
<output>10/11 = around 0.909091</output>
<gadget id="calculator">(10/11) * 10</gadget>
<output>100/11 = around 9.090909</output>
<gadget id="calculator">floor(100/11)</gadget>
<output>9</output>
<result>E</result> | E | 9 | what is the 20 - fifth decimal to the right in the fraction 10 / 11 ? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | floor(multiply(divide(10, 11), const_10)) | divide(n1,n2)|multiply(#0,const_10)|floor(#1) | 10 / 11 = 0.9090909090 . . . the odd - numbered decimal places are 9 . the answer is e . | general |
math_qa__uBAvc2XZVxX2wENm | One cutting machine cuts 100 metal bars in 30 minutes.Another machine does the same job in 30 seconds.What time will it take if both machines are put on the same work ? Choose the correct choice from the following answers.
A) 25.0 seconds
B) 29.5 seconds
C) 30.0 seconds
D) 30.5 seconds
E) 30.7 seconds | <gadget id="calculator">30 * 60</gadget>
<output>1_800</output>
<gadget id="calculator">1 / 1_800</gadget>
<output>1/1_800 = around 0.000556</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/1_800) + (1/30)</gadget>
<output>61/1_800 = around 0.033889</output>
<gadget id="calculator">1 / (61/1_800)</gadget>
<output>1_800/61 = around 29.508197</output>
<result>B</result> | B | 29.5 | One cutting machine cuts 100 metal bars in 30 minutes.Another machine does the same job in 30 seconds.What time will it take if both machines are put on the same work ? | {
"A": "25.0 seconds",
"B": "29.5 seconds",
"C": "30.0 seconds",
"D": "30.5 seconds",
"E": "30.7 seconds"
} | divide(const_1, add(divide(const_1, multiply(30, const_60)), divide(const_1, 30))) | divide(const_1,n1)|multiply(n1,const_60)|divide(const_1,#1)|add(#2,#0)|divide(const_1,#3) | by guess it is clear that the time taken will be less than 30 seconds and very near to it . therefore , answer 29.5 seconds will be correct . answer - b | physics |
math_qa__VJF9gyRZbbUlb2uC | the sum of 5th and 21th term of A.P. is equal to the sum of 8th , 15th and 13 th term . find the term which is 0
Choose the correct choice
A) 11 B) 10 C) 12 D) 13 E) 14 | <gadget id="calculator">8 + 15</gadget>
<output>23</output>
<gadget id="calculator">23 + 13</gadget>
<output>36</output>
<gadget id="calculator">5 + 21</gadget>
<output>26</output>
<gadget id="calculator">36 - 26</gadget>
<output>10</output>
<result>B</result> | B | 10 | the sum of 5th and 21th term of A.P. is equal to the sum of 8th , 15th and 13 th term . find the term which is 0 | {
"A": "11",
"B": "10",
"C": "12",
"D": "13",
"E": "14"
} | subtract(add(add(8, 15), 13), add(5, 21)) | add(n2,n3)|add(n0,n1)|add(n4,#0)|subtract(#2,#1)| | "t 5 + t 21 = t 8 + t 15 + t 13 = > a + 4 d + a + 20 d = a + 7 d + a + 14 d + a + 12 d = > a + 9 d = 0 = > t 10 = 0 i . e . 10 th term is zero . answer : b" | general |
math_qa__CvEbvc9FHnkUeES8 | in 5 football games thus far this season , barry has run for 98 , 107 , 85 , 89 , and 91 yards . at a minimum , how many yards n will he need to gain this sunday if he wants to keep his season average above 100 yards ? Choose the most appropriate option:
A) 101 B) 116 C) 130 D) n = 131 E) n = 141 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">98 + 107</gadget>
<output>205</output>
<gadget id="calculator">205 + 85</gadget>
<output>290</output>
<gadget id="calculator">290 + 89</gadget>
<output>379</output>
<gadget id="calculator">379 + 91</gadget>
<output>470</output>
<gadget id="calculator">600 - 470</gadget>
<output>130</output>
<result>D</result> | D | 131 | in 5 football games thus far this season , barry has run for 98 , 107 , 85 , 89 , and 91 yards . at a minimum , how many yards n will he need to gain this sunday if he wants to keep his season average above 100 yards ? | {
"A": "101",
"B": "116",
"C": "130",
"D": "n = 131",
"E": "n = 141"
} | subtract(multiply(add(5, const_1), 100), add(add(add(add(98, 107), 85), 89), 91)) | add(n0,const_1)|add(n1,n2)|add(n3,#1)|multiply(n6,#0)|add(n4,#2)|add(n5,#4)|subtract(#3,#5) | sorry the answer n = 131 is d . | general |
math_qa__0Q8JDxFjFp5u5IZH | ab + cd = jjj , where ab and cd are two - digit numbers and jjj is a 3 digit number ; a , b , c , and d are distinct positive integers . in the addition problem above , what is the value of c ? Choose the correct choice from the following answers
A) 1 B) 3 C) 7 D) 9 E) can not be determined | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<result>D</result> | D | 9 | ab + cd = jjj , where ab and cd are two - digit numbers and jjj is a 3 digit number ; a , b , c , and d are distinct positive integers . in the addition problem above , what is the value of c ? | {
"A": "1",
"B": "3",
"C": "7",
"D": "9",
"E": "can not be determined"
} | multiply(3, 3) | multiply(n0,n0) | ab and cd are two digit integers , their sum can give us only one three digit integer of a kind of jjj it ' s 111 . so , a = 1 . 1 b + cd = 111 now , c can not be less than 9 , because no to digit integer with first digit 1 ( mean that it ' s < 20 ) can be added to two digit integer less than 90 to have the sum 111 ( if cd < 90 meaning c < 9 cd + 1 b < 111 ) - - > c = 9 answer : d . | general |
math_qa__9zfpwRRGdHdwqr8W | 8 friends went to a hotel and decided to pay the bill amount equally. But 7 of them could pay Rs. 80 each as a result 8th has to pay Rs. 70 extra than his share. Find the amount paid by him. Choose the correct choice from the following answers:
A) 140
B) 121
C) 110
D) 160
E) none | <gadget id="calculator">80 * 7</gadget>
<output>560</output>
<gadget id="calculator">560 + 70</gadget>
<output>630</output>
<gadget id="calculator">630 / 7</gadget>
<output>90</output>
<gadget id="calculator">70 + 90</gadget>
<output>160</output>
<result>D</result> | D | 160 | 8 friends went to a hotel and decided to pay the bill amount equally. But 7 of them could pay Rs. 80 each as a result 8th has to pay Rs. 70 extra than his share. Find the amount paid by him. | {
"A": "140",
"B": "121",
"C": "110",
"D": "160",
"E": "none"
} | add(70, divide(add(multiply(80, 7), 70), 7)) | multiply(n1,n2)|add(n4,#0)|divide(#1,n1)|add(n4,#2)| | "explanation : average amount paid by 7 persons = rs . 80 increase in average due to rs . 70 paid extra by the 8 th men = rs . 70 / 7 = rs . 10 therefore , average expenditure of 8 friends = rs . 80 + rs . 10 = rs . 90 therefore , amount paid by the 11 th men = rs . 90 + rs . 70 = rs . 160 correct option : d" | general |
math_qa__zI2pX05jqNBkTpSh | If 4 men can colour 48 m long cloth in 2 days, then 8 men can colour 36 m long cloth in Choose the most appropriate option
A) 0.75 day B) 2 days C) 1.2 days D) 4 days E) 5 days | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">36 / 48</gadget>
<output>3/4 = around 0.75</output>
<result>A</result> | A | 0.75 | If 4 men can colour 48 m long cloth in 2 days, then 8 men can colour 36 m long cloth in | {
"A": "0.75 day",
"B": "2 days",
"C": "1.2 days",
"D": "4 days",
"E": "5 days"
} | divide(36, multiply(divide(48, multiply(4, 2)), 8)) | multiply(n0,n2)|divide(n1,#0)|multiply(n3,#1)|divide(n4,#2)| | "the length of cloth painted by one man in one day = 48 / 4 × 2 = 6 m no . of days required to paint 36 m cloth by 6 men = 36 / 6 × 8 = 0.75 day . a" | physics |
math_qa__X8tOapKQG4eFG7VR | A person lent a certain sum of money at 6% per annum at simple interest and in 8 years the interest amounted to $572 less than the sum lent. What was the sum lent? Choose the correct choice from the following answers: A) 1000 B) 1100 C) 1200 D) 1300 E) 1400 | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">48 / 100</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">1 - (12/25)</gadget>
<output>13/25 = around 0.52</output>
<gadget id="calculator">572 / (13/25)</gadget>
<output>1_100</output>
<result>B</result> | B | 1,100 | A person lent a certain sum of money at 6% per annum at simple interest and in 8 years the interest amounted to $572 less than the sum lent. What was the sum lent? | {
"A": "1000",
"B": "1100",
"C": "1200",
"D": "1300",
"E": "1400"
} | divide(572, subtract(const_1, divide(multiply(6, 8), const_100))) | multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)| | "p - 572 = ( p * 6 * 8 ) / 100 p = 1100 the answer is b ." | gain |
math_qa__nyth16e0adnWEa6I | Walking at 3/4 of her normal speed, a worker is 12 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is Pick: A) 36 B) 48 C) 60 D) 62 E) 66 | <gadget id="calculator">3 * 12</gadget>
<output>36</output>
<result>A</result> | A | 36 | Walking at 3/4 of her normal speed, a worker is 12 minutes later than usual in reaching her office. The usual time (in minutes) taken by her to cover the distance between her home and her office is | {
"A": "36",
"B": "48",
"C": "60",
"D": "62",
"E": "66"
} | multiply(3, 12) | multiply(n0,n2) | let v be her normal speed and let t be her normal time . d = ( 3 / 4 ) v * ( t + 12 ) since the distance is the same we can equate this to a regular day which is d = v * t v * t = ( 3 / 4 ) v * ( t + 12 ) t / 4 = 9 t = 36 the answer is a . | physics |
math_qa__sYOfi5aSca9Dkics | If a:b = 4:1, then find (a - 3b)/(2a - b)?
Options
A) 6 / 7 B) 1 / 7 C) 5 / 7 D) 3 / 2 E) 4 / 7 | <gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<result>B</result> | B | 0.142857 | If a:b = 4:1, then find (a - 3b)/(2a - b)? | {
"A": "6 / 7",
"B": "1 / 7",
"C": "5 / 7",
"D": "3 / 2",
"E": "4 / 7"
} | divide(subtract(4, 3), subtract(multiply(2, 4), 1)) | multiply(n0,n3)|subtract(n0,n2)|subtract(#0,n1)|divide(#1,#2) | answer : option b a / b = 4 / 1 = > a = 4 b ( a - 3 b ) / ( 2 a - b ) = ( 4 b - 3 b ) / ( 8 b - b ) = b / 7 b = > 1 / 7 | general |
math_qa__yDb35nz6ceVHa1Qz | log3 N+log12 N what is 3 digit number N that will be whole number Select the correct option
A) 6291 B) 7292 C) 1728 D) 1929 E) 1727 | <gadget id="calculator">12 ** 3</gadget>
<output>1_728</output>
<result>C</result> | C | 1,728 | log3 N+log12 N what is 3 digit number N that will be whole number | {
"A": "6291",
"B": "7292",
"C": "1728",
"D": "1929",
"E": "1727"
} | power(12, 3) | power(n1,n0)| | "no of values n can take is 1 12 ^ 3 = 1728 answer : c" | other |
math_qa__j9x5JRCISB1oVGWh | The average weight of A,B,C is 45 Kg. The avgwgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B. Select
A) 23 B) 43 C) 21 D) 31 E) 43 | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">43 * 2</gadget>
<output>86</output>
<gadget id="calculator">80 + 86</gadget>
<output>166</output>
<gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">166 - 135</gadget>
<output>31</output>
<result>D</result> | D | 31 | The average weight of A,B,C is 45 Kg. The avgwgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B. | {
"A": "23",
"B": "43",
"C": "21",
"D": "31",
"E": "43"
} | subtract(add(multiply(40, const_2), multiply(43, const_2)), multiply(45, const_3)) | multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2) | sol . let a , b , c represent their individual wgts . then , a + b + c = ( 45 * 3 ) kg = 135 kg a + b = ( 40 * 2 ) kg = 80 kg & b + c = ( 43 * 2 ) kg = 86 kg b = ( a + b ) + ( b + c ) - ( a + b + c ) = ( 80 + 86 - 135 ) kg = 31 kg . answer d | general |
math_qa__OKuegMJo589pTJNj | The price of a shirt is increased by 15% and then reduced by 15%. The final price of the shirt is? Choose the correct choice from the following answers:
A) $ 97.75 B) $ 90 C) $ 91.56 D) $ 95.62 E) $ 93.45 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(17/20) * (23/20)</gadget>
<output>391/400 = around 0.9775</output>
<gadget id="calculator">(391/400) * 100</gadget>
<output>391/4 = around 97.75</output>
<result>A</result> | A | 97.75 | The price of a shirt is increased by 15% and then reduced by 15%. The final price of the shirt is? | {
"A": "$ 97.75",
"B": "$ 90",
"C": "$ 91.56",
"D": "$ 95.62",
"E": "$ 93.45"
} | multiply(multiply(subtract(const_1, divide(15, const_100)), add(const_1, divide(15, const_100))), const_100) | divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#0)|multiply(#1,#2)|multiply(#3,const_100) | let the original price be $ 100 new final price = 85 % of ( 115 % of $ 100 ) = 85 / 100 * 115 / 100 * 100 = $ 97.75 answer is a | gain |
math_qa__PklL2eiL3mlOdBC8 | If two integers x,y (x>y) are selected from -3 to 4 (inclusive), how many cases are there? Choose the correct choice from the following choices:
A) 20 B) 22 C) 24 D) 26 E) 28 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">7 + 6</gadget>
<output>13</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">13 + 5</gadget>
<output>18</output>
<gadget id="calculator">18 + 4</gadget>
<output>22</output>
<gadget id="calculator">22 + 3</gadget>
<output>25</output>
<gadget id="calculator">25 + 2</gadget>
<output>27</output>
<gadget id="calculator">27 + 1</gadget>
<output>28</output>
<result>E</result> | E | 28 | If two integers x,y (x>y) are selected from -3 to 4 (inclusive), how many cases are there? | {
"A": "20",
"B": "22",
"C": "24",
"D": "26",
"E": "28"
} | add(add(add(add(add(add(add(4, 3), add(4, const_2)), add(4, const_1)), const_4), const_3), const_2), const_1) | add(n0,n1)|add(n1,const_2)|add(n1,const_1)|add(#0,#1)|add(#3,#2)|add(#4,const_4)|add(#5,const_3)|add(#6,const_2)|add(#7,const_1) | there are 8 integers from - 3 to 4 inclusive . 8 c 2 = 28 . the answer is e . | general |
math_qa__6yctQfyrDFQDzvNr | In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:
Choose the correct choice from the following:
A) 10
B) 12
C) 30
D) 40
E) 20 | <gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">45 - 36</gadget>
<output>9</output>
<gadget id="calculator">(20/9) * 9</gadget>
<output>20</output>
<result>E</result> | E | 20 | In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by: | {
"A": "10",
"B": "12",
"C": "30",
"D": "40",
"E": "20"
} | multiply(divide(100, 45), subtract(45, 36)) | divide(n0,n2)|subtract(n2,n1)|multiply(#0,#1) | dist = ( 100 / 45 * 9 ) = 20 m answer e | physics |
math_qa__XaAOXyWpdWa61kU7 | The citizens of planet nigiet are 5 fingered and have thus developed their decimal system in base 8. A certain street in nigiet contains 1000 (in base 5) buildings numbered 1 to 1000. How many 3s are used in numbering these buildings? Express result in terms of base 10. Choose the correct choice from the following
A) 54
B) 64
C) 75
D) 85
E) 100 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">3 * 25</gadget>
<output>75</output>
<result>C</result> | C | 75 | The citizens of planet nigiet are 5 fingered and have thus developed their decimal system in base 8. A certain street in nigiet contains 1000 (in base 5) buildings numbered 1 to 1000. How many 3s are used in numbering these buildings? Express result in terms of base 10. | {
"A": "54",
"B": "64",
"C": "75",
"D": "85",
"E": "100"
} | multiply(const_3, power(5, const_2)) | power(n0,const_2)|multiply(#0,const_3) | no of 3 s b / w 1 - 99 is 20,100 - 199 is 20 and so on . so leavn d range b / w 300 - 399 total no of 3 s is ( 9 * 20 = ) 180 . no of 3 s b / w 300 - 399 is ( 20 + 100 = ) 120 . total no of 3 s b / w 1 - 1000 = 120 + 180 = 300 in base 10 300 = 3 * 5 ^ 2 = 75 . answer : c | physics |
math_qa__DrBbjVWVMTaWrXsf | Of the people who responded to a market survey, 150 preferred Brand X and the rest preferred Brand Y. If the respondents indicated a preference for Brand X over Brand Y by ratio of 5 to 1, how many people responded to the survey? Choose the correct choice from the following choices: A) 80 B) 180 C) 240 D) 360 E) 480 | <gadget id="calculator">150 / 5</gadget>
<output>30</output>
<gadget id="calculator">30 + 150</gadget>
<output>180</output>
<result>B</result> | B | 180 | Of the people who responded to a market survey, 150 preferred Brand X and the rest preferred Brand Y. If the respondents indicated a preference for Brand X over Brand Y by ratio of 5 to 1, how many people responded to the survey? | {
"A": "80",
"B": "180",
"C": "240",
"D": "360",
"E": "480"
} | add(divide(150, 5), 150) | divide(n0,n1)|add(n0,#0) | ratio = 5 : 1 = > 5 x respondents preferred brand x and x preferred brand y since , no . of respondents who preferred brand x = 150 = > 5 x = 150 = > x = 30 hence total no . of respondents = 150 + 30 = 180 hence b is the answer . | other |
math_qa__iT0sgTDfWCixNkBa | The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 9 and 10. The larger of the two numbers is: Choose one: A) 276 B) 299 C) 230 D) 345 E) 395 | <gadget id="calculator">23 * 10</gadget>
<output>230</output>
<result>C</result> | C | 230 | The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 9 and 10. The larger of the two numbers is: | {
"A": "276",
"B": "299",
"C": "230",
"D": "345",
"E": "395"
} | multiply(23, 10) | multiply(n0,n2)| | "clearly , the numbers are ( 23 x 9 ) and ( 23 x 10 ) . larger number = ( 23 x 10 ) = 230 . answer : option c" | other |
math_qa__whPB3XhBnM4HOC6k | A semicircle has a radius of 11. What is the approximate perimeter of the semicircle?
Choose the most appropriate option: A) 45 B) 51 C) 57 D) 63 E) 69 | <gadget id="calculator">2 * pi * 11</gadget>
<output>22*pi = around 69.115038</output>
<gadget id="calculator">(22*pi) / 2</gadget>
<output>11*pi = around 34.557519</output>
<gadget id="calculator">2 * 11</gadget>
<output>22</output>
<gadget id="calculator">(11*pi) + 22</gadget>
<output>22 + 11*pi = around 56.557519</output>
<result>C</result> | C | 57 | A semicircle has a radius of 11. What is the approximate perimeter of the semicircle? | {
"A": "45",
"B": "51",
"C": "57",
"D": "63",
"E": "69"
} | add(divide(circumface(11), const_2), multiply(const_2, 11)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1) | the perimeter of a circle is 2 * pi * r . the perimeter of a semicircle is 2 * pi * r / 2 + 2 r = pi * r + 2 r the perimeter is pi * 11 + 2 * 11 which is about 57 . the answer is c . | geometry |
math_qa__zWahinFc0GTGQVd9 | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 37 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake?
Choose the correct choice from the following answers:
A) 36
B) 2 ^ 4 * 3
C) 24
D) 38
E) 47 | <gadget id="calculator">37 - 1</gadget>
<output>36</output>
<result>A</result> | A | 36 | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 37 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? | {
"A": "36",
"B": "2 ^ 4 * 3",
"C": "24",
"D": "38",
"E": "47"
} | subtract(37, const_1) | subtract(n0,const_1)| | "working backward from the day it ' s covered : day 37 : fully covered day 36 : half covered so 36 days answer : a" | physics |
math_qa__VyGlbevn0Cuf7Vjt | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 64 hours and 25 hours respectively. The ratio of their speeds is? Choose the correct choice:
A) 4 : 9
B) 4 : 3
C) 4 : 5
D) 5 : 8
E) 4 : 2 | <gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<result>D</result> | D | 0.625 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 64 hours and 25 hours respectively. The ratio of their speeds is? | {
"A": "4 : 9",
"B": "4 : 3",
"C": "4 : 5",
"D": "5 : 8",
"E": "4 : 2"
} | divide(sqrt(25), sqrt(64)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains a and b . then , ( a ' s speed ) : ( b ' s speed ) = √ b : √ a = √ 25 : √ 64 = 5 : 8 answer : d" | physics |
math_qa__z0m8FCcb8VQ1u6Pw | 20 is added to a certain number, the sum is multiplied by 2, the product is divided by 2 and 2 is subtracted from the quotient. The remainder left is half of 88. What is the number?
Options:
A) 21 B) 20 C) 26 D) 30 E) 45 | <gadget id="calculator">88 / 2</gadget>
<output>44</output>
<gadget id="calculator">44 + 2</gadget>
<output>46</output>
<gadget id="calculator">46 * 2</gadget>
<output>92</output>
<gadget id="calculator">92 / 2</gadget>
<output>46</output>
<gadget id="calculator">46 - 20</gadget>
<output>26</output>
<result>C</result> | C | 26 | 20 is added to a certain number, the sum is multiplied by 2, the product is divided by 2 and 2 is subtracted from the quotient. The remainder left is half of 88. What is the number? | {
"A": "21",
"B": "20",
"C": "26",
"D": "30",
"E": "45"
} | subtract(divide(multiply(add(divide(88, const_2), 2), 2), 2), 20) | divide(n4,const_2)|add(n2,#0)|multiply(n2,#1)|divide(#2,n1)|subtract(#3,n0)| | "let number is x . when 20 added to it , = ( x + 20 ) 2 multiplied to sum , = 2 * ( x + 20 ) now , = [ { 2 * ( x + 20 ) } / 2 ] and , = [ { 2 * ( x + 20 ) } / 2 ] - 2 according to question , [ { 2 * ( x + 20 ) } / 2 ] - 2 = half of 88 [ ( 2 x + 40 ) / 2 ) = 44 + 2 2 x + 40 = 46 * 2 x + 20 = 46 x = 46 - 20 x = 26 so , required number is : 26 . answer : c" | general |
math_qa__KbdC9emqLGpcszTW | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction E of the total distance did he cover while the sun was shining on him?
Select.
A) 1 / 4
B) 4 / 5
C) 1 / 5
D) 1 / 6
E) 1 / 7 | <gadget id="calculator">lcm(2, 3)</gadget>
<output>6</output>
<gadget id="calculator">6 / 2.8</gadget>
<output>2.142857</output>
<gadget id="calculator">2.142857 - 2</gadget>
<output>0.142857</output>
<result>E</result> | E | 0.142857 | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction E of the total distance did he cover while the sun was shining on him? | {
"A": "1 / 4",
"B": "4 / 5",
"C": "1 / 5",
"D": "1 / 6",
"E": "1 / 7"
} | subtract(divide(lcm(const_2, const_3), 2.8), const_2) | lcm(const_2,const_3)|divide(#0,n1)|subtract(#1,const_2)| | if s is an integer and we know that the average speed is 2.8 , s must be = 2 . that meanss + 1 = 3 . this implies that the ratio of time for s = 2 is 1 / 4 of the total time . the formula for distance / rate is d = rt . . . so the distance travelled when s = 2 is 2 t . the distance travelled for s + 1 = 3 is 3 * 4 t or 12 t . therefore , total distance covered while the sun was shining over him is e = 2 / 14 = 1 / 7 . answer : e | general |
math_qa__DP9942ltRmiofkg5 | A shopkeeper sold an article at $100 with 40% profit. Then find its cost price? Choose the correct option
A) $ 120 B) $ 100 C) $ 91 D) $ 71 E) $ 69 | <gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">100 / 140</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">100 * (5/7)</gadget>
<output>500/7 = around 71.428571</output>
<result>D</result> | D | 71 | A shopkeeper sold an article at $100 with 40% profit. Then find its cost price? | {
"A": "$ 120",
"B": "$ 100",
"C": "$ 91",
"D": "$ 71",
"E": "$ 69"
} | multiply(100, divide(const_100, add(const_100, 40))) | add(n1,const_100)|divide(const_100,#0)|multiply(n0,#1) | cost price = selling price * 100 / ( 100 + profit ) c . p . = 100 * 100 / 140 = $ 71 ( approximately ) answer is d | gain |
math_qa__YvYjAHcO2qIFQAEu | A plant manager must assign 12 new workers to one of five shifts. She needs a first, second, and third shift, and two alternate shifts. Each of the shifts will receive 2 new workers. How many different ways can she assign the new workers? Choose one
A) 23760
B) 47520
C) 33000
D) 48600
E) 54000 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">720 / 2</gadget>
<output>360</output>
<gadget id="calculator">factorial(12)</gadget>
<output>479_001_600</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">3_628_800 * 2</gadget>
<output>7_257_600</output>
<gadget id="calculator">479_001_600 / 7_257_600</gadget>
<output>66</output>
<gadget id="calculator">360 * 66</gadget>
<output>23_760</output>
<result>A</result> | A | 23,760 | A plant manager must assign 12 new workers to one of five shifts. She needs a first, second, and third shift, and two alternate shifts. Each of the shifts will receive 2 new workers. How many different ways can she assign the new workers? | {
"A": "23760",
"B": "47520",
"C": "33000",
"D": "48600",
"E": "54000"
} | multiply(divide(factorial(divide(12, 2)), const_2), divide(factorial(12), multiply(factorial(subtract(12, 2)), factorial(2)))) | divide(n0,n1)|factorial(n0)|factorial(n1)|subtract(n0,n1)|factorial(#0)|factorial(#3)|divide(#4,const_2)|multiply(#5,#2)|divide(#1,#7)|multiply(#6,#8)| | "whatever : my take selecting team of 2 out of 12 to assign to the shifts = 12 c 2 = 66 ways . now 2 out of 12 means total of 6 group possible . so putting them in shifts = counting methode : first , second , third , alt , alt = 6 * 5 * 4 * 3 * 2 * 1 = 720 here alt and alt are the same : so 720 / 2 = 360 ways . total ways of selecting = ( selecting 2 out of 12 ) * arranging those teams in shifts = 66 * 360 = 23760 ans : a" | physics |
math_qa__VHeTvqZ4W6LizOlO | Instead of multiplying a number by 5, the number is divided by 10. What is the percentage of error obtained ? Pick one.
A) 96 % B) 98 % C) 95 % D) 97 % E) 96 % | <gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 100</gadget>
<output>2</output>
<gadget id="calculator">100 - 2</gadget>
<output>98</output>
<result>B</result> | B | 98 | Instead of multiplying a number by 5, the number is divided by 10. What is the percentage of error obtained ? | {
"A": "96 %",
"B": "98 %",
"C": "95 %",
"D": "97 %",
"E": "96 %"
} | subtract(const_100, multiply(divide(divide(10, 10), multiply(5, 10)), const_100)) | divide(n1,n1)|multiply(n0,n1)|divide(#0,#1)|multiply(#2,const_100)|subtract(const_100,#3)| | "let the number be x the right number is 5 x the wrong number is x / 10 error is ( 5 x - x / 10 ) = 49 x / 10 percentage of error is ( ( 49 x / 10 ) / 5 x ) * 100 = 98 % answer : b" | general |
math_qa__Se34PgL5suRZHbAe | A car going at 30 miles per hour set out on an 80-mile trip at 9:00 A.M. Exactly 10 minutes later, a second car left from the same place and followed the same route. How fast, in miles per hour, was the second car going if it caught up with the first car at 10:30 A.M.? Choices: A) 45 B) 50 C) 53 D) 55 E) 60 | <gadget id="calculator">10 - 9</gadget>
<output>1</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">30 - 10</gadget>
<output>20</output>
<gadget id="calculator">60 + 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 60</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">80 / (4/3)</gadget>
<output>60</output>
<result>E</result> | E | 60 | A car going at 30 miles per hour set out on an 80-mile trip at 9:00 A.M. Exactly 10 minutes later, a second car left from the same place and followed the same route. How fast, in miles per hour, was the second car going if it caught up with the first car at 10:30 A.M.? | {
"A": "45",
"B": "50",
"C": "53",
"D": "55",
"E": "60"
} | divide(80, divide(add(multiply(subtract(10, 9), const_60), subtract(30, 10)), const_60)) | subtract(n4,n2)|subtract(n0,n4)|multiply(#0,const_60)|add(#2,#1)|divide(#3,const_60)|divide(n1,#4) | let car a = car that starts at 9 am car b = car that starts at 9 : 10 am time for which car a travels at speed of 30 m per hour = 1.5 hours distance travelled by car a = 30 * 1.5 = 45 miles since car b catches up car a at 10 : 30 , time = 80 mins = 4 / 3 hour speed of car b = 45 / ( 4 / 3 ) = 60 miles per hour answer e | physics |
math_qa__xCMTUZ9cq6JoWP08 | If 325/999=0.125, what is the 81st digit to the right of the decimal point in the decimal equivalent of the fraction?
Options
A) 3
B) 3.5
C) 4
D) 4.5
E) 5 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<result>E</result> | E | 5 | If 325/999=0.125, what is the 81st digit to the right of the decimal point in the decimal equivalent of the fraction? | {
"A": "3",
"B": "3.5",
"C": "4",
"D": "4.5",
"E": "5"
} | add(const_2, const_3) | add(const_2,const_3)| | "0 . [ u ] 325 [ / u = 0.325325325 . . . . . every 3 rd digit is 5 and every multiple of 3 will be the digit 5 . since 81 is multiple of 3 , the 81 st digit is 5 . answer e" | general |
math_qa__d2d1UGROx8RKTmBy | Pipe P can fill a tank in 2 hours, pipe Q in 4 hours and pipe R in 12 hours. If all the pipes are open, in how many hours will the tank be filled? Select the correct option: A) 2 hours B) 1.2 hours C) 3 hours D) 1.5 hours E) 2.5 hours | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) + (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/12) + (3/4)</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 / (5/6)</gadget>
<output>6/5 = around 1.2</output>
<result>B</result> | B | 1.2 | Pipe P can fill a tank in 2 hours, pipe Q in 4 hours and pipe R in 12 hours. If all the pipes are open, in how many hours will the tank be filled? | {
"A": "2 hours",
"B": "1.2 hours",
"C": "3 hours",
"D": "1.5 hours",
"E": "2.5 hours"
} | inverse(add(divide(const_1, 12), add(divide(const_1, 2), divide(const_1, 4)))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|inverse(#4)| | "explanation : part filled by ( p + q + r ) in 1 hour = ( 1 / 2 + 1 / 4 + 1 / 12 ) = 5 / 6 all the three pipes together will fill the tank = 6 / 5 = 1.2 hours answer b" | physics |
math_qa__jC1ehaGqZz70A2nI | 300 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees Choose the correct choice from the following options.
A) 10
B) 12
C) 14
D) 16
E) 18 | <gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">300 / 25</gadget>
<output>12</output>
<result>B</result> | B | 12 | 300 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(300, add(subtract(26, 2), const_1)) | subtract(n1,n2)|add(#0,const_1)|divide(n0,#1) | 26 trees have 25 gaps between them , required distance ( 300 / 25 ) = 12 b | physics |
math_qa__kwMHrJGYA17HMbtl | In a 100m race, Sam beats John by 6 seconds. On the contrary, if Sam allowed John to start 36m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race? Choose the correct choice from the following choices:
A) 10.66 seconds B) 25 seconds C) 29 seconds D) 21 seconds E) 6.25 seconds | <gadget id="calculator">100 - 36</gadget>
<output>64</output>
<gadget id="calculator">64 / 6</gadget>
<output>32/3 = around 10.666667</output>
<result>A</result> | A | 10.66 | In a 100m race, Sam beats John by 6 seconds. On the contrary, if Sam allowed John to start 36m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race? | {
"A": "10.66 seconds",
"B": "25 seconds",
"C": "29 seconds",
"D": "21 seconds",
"E": "6.25 seconds"
} | divide(subtract(100, 36), 6) | subtract(n0,n2)|divide(#0,n1)| | "their difference is 6 second but this difference is 0 if john allows sam to start the race from 36 m ahead . that means jhon was 36 m away from finishing line when they started together . so he will cover 36 m in 6 seconds . so his speed = 36 / 6 = 6 metre / second . so time taken = 100 / 6 = 16.66 seconds . so sam took = 10.66 seconds . correct answer = a" | physics |
math_qa__1TfdG2VzmXncPqhn | A bag contains 3 red, 5 yellow and 4 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls? Options.
A) 9 / 16 B) 7 / 18 C) 12 / 55 D) 14 / 67 E) 19 / 87 | <gadget id="calculator">binomial(4, 2)</gadget>
<output>6</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">binomial(8, 1)</gadget>
<output>8</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">binomial(12, 3)</gadget>
<output>220</output>
<gadget id="calculator">48 / 220</gadget>
<output>12/55 = around 0.218182</output>
<result>C</result> | C | 0.218182 | A bag contains 3 red, 5 yellow and 4 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls? | {
"A": "9 / 16",
"B": "7 / 18",
"C": "12 / 55",
"D": "14 / 67",
"E": "19 / 87"
} | divide(multiply(choose(4, const_2), choose(add(3, 5), const_1)), choose(add(add(3, 5), 4), 3)) | add(n0,n1)|choose(n2,const_2)|add(n2,#0)|choose(#0,const_1)|choose(#2,n0)|multiply(#1,#3)|divide(#5,#4) | total number of balls = 3 + 5 + 4 = 12 n ( s ) = 12 c 3 = 12 * 11 * 10 / 3 * 2 = 220 n ( e ) = 4 c 2 * 8 c 1 = 6 * 8 = 48 probability = 48 / 220 = 12 / 55 answer is c | probability |
math_qa__vdDDSQGQw9XMldPv | Debanshu normally drives to work in 45 minutes at an average speed of 40 miles per hour. This week, however, she plans to bike to work along a route that decreases the total distance she usually travels when driving by 20% . If Debanshu averages between 12 and 16 miles per hour when biking, how many minutes earlier will she need to leave in the morning in order to ensure she arrives at work at the same time as when she drives? Choices
A) 135 B) 105 C) 95 D) 75 E) 45 | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">45 / 60</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 40</gadget>
<output>30</output>
<gadget id="calculator">(4/5) * 30</gadget>
<output>24</output>
<gadget id="calculator">24 / 12</gadget>
<output>2</output>
<gadget id="calculator">2 - (3/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 60</gadget>
<output>75</output>
<result>D</result> | D | 75 | Debanshu normally drives to work in 45 minutes at an average speed of 40 miles per hour. This week, however, she plans to bike to work along a route that decreases the total distance she usually travels when driving by 20% . If Debanshu averages between 12 and 16 miles per hour when biking, how many minutes earlier will she need to leave in the morning in order to ensure she arrives at work at the same time as when she drives? | {
"A": "135",
"B": "105",
"C": "95",
"D": "75",
"E": "45"
} | multiply(subtract(divide(multiply(divide(subtract(const_100, 20), const_100), multiply(divide(45, const_60), 40)), 12), divide(45, const_60)), const_60) | divide(n0,const_60)|subtract(const_100,n2)|divide(#1,const_100)|multiply(n1,#0)|multiply(#2,#3)|divide(#4,n3)|subtract(#5,#0)|multiply(#6,const_60) | debanshu normally drives to work in 45 minutes at an average speed of 40 miles per hour . use formula d = rt car : t 1 : 45 min r 1 : 40 mph d 1 : [ ( 40 * 45 ) / 60 ] = 30 miles bike : t 1 : ? r 2 : 12 - 16 mph d 2 : 08 * d 1 = 24 miles t 1 : [ ( 24 * 60 ) / 12 ] = 120 min ( only 12 mph speed yields an answer given in the choices ) therefore , deb has to leave 120 min - 45 min = 75 min early answer : d | physics |
math_qa__D04YiuwxfjgHtEaV | At the end of year X, automobile installment credit accounted for 36% of all outstanding consumer installment credit. At that time automobile finance companies extended $75 billion of credit, or 1/2 of the automobile installment credit. How many billion dollars of consumer installment credit was outstanding at that time? Choose the most appropriate option.
A) 412.16 B) 150 C) 400 D) 416.67 E) 420.34 | <gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">36 / 100</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">150 / (9/25)</gadget>
<output>1_250/3 = around 416.666667</output>
<result>D</result> | D | 416.67 | At the end of year X, automobile installment credit accounted for 36% of all outstanding consumer installment credit. At that time automobile finance companies extended $75 billion of credit, or 1/2 of the automobile installment credit. How many billion dollars of consumer installment credit was outstanding at that time? | {
"A": "412.16",
"B": "150",
"C": "400",
"D": "416.67",
"E": "420.34"
} | divide(multiply(75, 2), divide(36, const_100)) | divide(n0,const_100)|multiply(n1,n3)|divide(#1,#0)| | "system of equations a = ( 36 / 100 ) c ( 1 / 2 ) a = 75 - - > a = 150 substitution 150 = ( 36 / 100 ) c c = ( 100 / 36 ) 150 calculate 150 / 36 * 100 the correct answer is d - the correct answer will be slightly smaller than 513 . therefore , the correct answer is 475 ." | general |
math_qa__9TvtCsO21mDndycu | Three table runners have a combined area of 204 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner? Choose the correct answer.
A) 18 square inches B) 20 square inches C) 24 square inches D) 28 square inches E) 30 square inches | <gadget id="calculator">204 - 24</gadget>
<output>180</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">175 * (4/5)</gadget>
<output>140</output>
<gadget id="calculator">180 - 140</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>B</result> | B | 20 | Three table runners have a combined area of 204 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner? | {
"A": "18 square inches",
"B": "20 square inches",
"C": "24 square inches",
"D": "28 square inches",
"E": "30 square inches"
} | divide(subtract(subtract(204, 24), multiply(175, divide(80, const_100))), const_2) | divide(n1,const_100)|subtract(n0,n3)|multiply(n2,#0)|subtract(#1,#2)|divide(#3,const_2)| | "total = a + b + c - ( sum of exactly 2 - group overlaps ) - 2 * ( all three ) + neither 80 % * 175 = 204 - 24 - 2 * ( all three ) + 0 2 * ( all three ) = 204 - 24 - 140 all three = 20 answer : b" | geometry |
math_qa__b2L61D6xRhYy9ch7 | Nr Books bought Nr of People
6 3
7 1
8 5
9 2
What is the median of books bought per person? Choose the correct choice from the following answers: A) 2 B) 4 C) 6 D) 8 E) 18 | <gadget id="calculator">8 * 1</gadget>
<output>8</output>
<result>D</result> | D | 8 | Nr Books bought Nr of People
6 3
7 1
8 5
9 2
What is the median of books bought per person? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "18"
} | multiply(8, const_1) | multiply(n4,const_1) | 6 , 6,6 , 7,8 , 8,8 , 8,8 , 9,9 so you will observer that the median of the list is 8 . ans d | general |
math_qa__K3q6qgKHErTGaPsh | A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 55 meters, what is the height of the building (in meters)? Choose the correct choice from the following options
A) 20 B) 22 C) 24 D) 26 E) 28 | <gadget id="calculator">18 / 45</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">55 * (2/5)</gadget>
<output>22</output>
<result>B</result> | B | 22 | A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 55 meters, what is the height of the building (in meters)? | {
"A": "20",
"B": "22",
"C": "24",
"D": "26",
"E": "28"
} | multiply(55, divide(18, 45)) | divide(n0,n1)|multiply(n2,#0)| | "the height : length ratio will be equal in both cases . 18 / 45 = x / 55 x = 22 the answer is b ." | physics |
math_qa__yHXPiy1ERBvACjuj | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 49 hours respectively. The ratio of their speeds is:
Choose the most appropriate option
A) 2 : 3 B) 4 : 3 C) 6 : 7 D) 7 : 2 E) none of these | <gadget id="calculator">49 ** (1/2)</gadget>
<output>7</output>
<gadget id="calculator">4 ** (1/2)</gadget>
<output>2</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<result>D</result> | D | 3.5 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 4 hours and 49 hours respectively. The ratio of their speeds is: | {
"A": "2 : 3",
"B": "4 : 3",
"C": "6 : 7",
"D": "7 : 2",
"E": "none of these"
} | divide(sqrt(49), sqrt(4)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains as a and b . then , ( a ' s speed ) : ( b ' s speed ) = â ˆ š b : â ˆ š a = â ˆ š 49 : â ˆ š 4 = 7 : 2 . answer d" | physics |
math_qa__pqL4DMUItuu6Oxoy | Find 62976 ÷ ? = 123
Choose one.
A) 412 B) 502 C) 512 D) 522 E) none | <gadget id="calculator">62_976 / 123</gadget>
<output>512</output>
<result>C</result> | C | 512 | Find 62976 ÷ ? = 123 | {
"A": "412",
"B": "502",
"C": "512",
"D": "522",
"E": "none"
} | divide(62976, 123) | divide(n0,n1)| | "answer let 62976 / n = 123 then n = 62976 / 123 = 512 . option : c" | general |
math_qa__XanB9TT9vO22AmkR | X alone can do a piece of work in 15 days and Y alone can do it in 10 days. X and Y undertook to do it for Rs. 720. With the help of Z they finished it in 5 days. How much is paid to Z?
Choose the correct choice from the following choices:
A) rs . 360
B) rs . 120
C) rs . 240
D) rs . 300
E) none | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/5) - (1/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) - (1/15)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/30) / (1/5)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 720</gadget>
<output>120</output>
<result>B</result> | B | 120 | X alone can do a piece of work in 15 days and Y alone can do it in 10 days. X and Y undertook to do it for Rs. 720. With the help of Z they finished it in 5 days. How much is paid to Z? | {
"A": "rs . 360",
"B": "rs . 120",
"C": "rs . 240",
"D": "rs . 300",
"E": "none"
} | multiply(divide(subtract(subtract(divide(const_1, 5), divide(const_1, 10)), divide(const_1, 15)), divide(const_1, 5)), 720) | divide(const_1,n3)|divide(const_1,n1)|divide(const_1,n0)|subtract(#0,#1)|subtract(#3,#2)|divide(#4,#0)|multiply(n2,#5) | solution : in one day x can finish 1 / 15 th of the work . in one day y can finish 1 / 10 th of the work . let us say that in one day z can finish 1 / zth of the work . when all the three work together in one day they can finish 1 / 15 + 1 / 10 + 1 / z = 1 / 5 th of the work . therefore , 1 / z = 1 / 30 . ratio of their efficiencies = 1 / 15 : 1 / 10 : 1 / 30 = 2 : 3 : 1 . therefore z receives 1 / 6 th of the total money . according to their efficiencies money is divided as 240 : 360 : 120 . hence , the share of z = rs . 120 . answer b | physics |
math_qa__syYNfRdrGiaM8xHD | The weights of one liter vegetable ghee packet of two brands ‘A’ and ‘B’ are 950 gm and 850 gm respectively. If they are mixed in the ratio of 3 : 2 by volumes to form a mixture of 4 liters, what is the weight (in kg) of the mixture?
Choose one
A) 3.64
B) 1.75
C) 3.52
D) 2.72
E) none of these | <gadget id="calculator">3 * 950</gadget>
<output>2_850</output>
<gadget id="calculator">2 * 850</gadget>
<output>1_700</output>
<gadget id="calculator">2_850 + 1_700</gadget>
<output>4_550</output>
<gadget id="calculator">4 * 4_550</gadget>
<output>18_200</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">18_200 / 5</gadget>
<output>3_640</output>
<gadget id="calculator">3_640 / 1_000</gadget>
<output>91/25 = around 3.64</output>
<result>A</result> | A | 3.64 | The weights of one liter vegetable ghee packet of two brands ‘A’ and ‘B’ are 950 gm and 850 gm respectively. If they are mixed in the ratio of 3 : 2 by volumes to form a mixture of 4 liters, what is the weight (in kg) of the mixture? | {
"A": "3.64",
"B": "1.75",
"C": "3.52",
"D": "2.72",
"E": "none of these"
} | divide(divide(multiply(4, add(multiply(3, 950), multiply(2, 850))), add(3, 2)), const_1000) | add(n2,n3)|multiply(n0,n2)|multiply(n1,n3)|add(#1,#2)|multiply(n4,#3)|divide(#4,#0)|divide(#5,const_1000)| | "here ' s how i did it . my notes from reading the problem were : 1 l a = 950 gm 1 l b = 850 gm we are mixing five parts ( 3 parts a plus 2 parts b , 5 parts total ) to get 4 l , so 5 x = 4 - - - > x = 4 / 5 . each part is 4 / 5 of a liter . so if we have 3 parts a , we have 950 * 3 * ( 4 / 5 ) = 2280 if we have 2 parts b , we have 850 * 2 * ( 4 / 5 ) = 1360 2280 + 1360 = 3640 solving for units gives us 3.64 so the answer is a" | other |
math_qa__jbfjRFMuqJj9BBe3 | A,B,C can complete a piece of work in 24,6,12 days. Working together, they complete the same work in how many days? Choose one
A) 2 B) 4 / 5 C) 7 / 9 D) 10 E) 24 / 7 | <gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/24) + (1/6)</gadget>
<output>5/24 = around 0.208333</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(5/24) + (1/12)</gadget>
<output>7/24 = around 0.291667</output>
<gadget id="calculator">1 / (7/24)</gadget>
<output>24/7 = around 3.428571</output>
<result>E</result> | E | 3.428571 | A,B,C can complete a piece of work in 24,6,12 days. Working together, they complete the same work in how many days? | {
"A": "2",
"B": "4 / 5",
"C": "7 / 9",
"D": "10",
"E": "24 / 7"
} | divide(const_1, add(add(divide(const_1, 24), divide(const_1, add(const_4, const_2))), divide(const_1, multiply(const_2, add(const_4, const_2))))) | add(const_2,const_4)|divide(const_1,n0)|divide(const_1,#0)|multiply(#0,const_2)|add(#1,#2)|divide(const_1,#3)|add(#4,#5)|divide(const_1,#6)| | "a + b + c 1 day work = 1 / 24 + 1 / 6 + 1 / 12 = 7 / 24 a , b , c together will complete the job in 24 / 7 days answer is e" | physics |
math_qa__6GD2GMrB2KS8ObcU | A caterer ordered 200 ice-cream bars and 200 sundaes. If the total price was $200.00 and the price of each ice-cream bar was $0.40, what was the price of each sundae? Pick one
A) $ 0.60 B) $ 0.80 C) $ 1.00 D) $ 1.20 E) $ 1.60 | <gadget id="calculator">200 * 0.4</gadget>
<output>80</output>
<gadget id="calculator">200 - 80</gadget>
<output>120</output>
<gadget id="calculator">120 / 200</gadget>
<output>3/5 = around 0.6</output>
<result>A</result> | A | 0.6 | A caterer ordered 200 ice-cream bars and 200 sundaes. If the total price was $200.00 and the price of each ice-cream bar was $0.40, what was the price of each sundae? | {
"A": "$ 0.60",
"B": "$ 0.80",
"C": "$ 1.00",
"D": "$ 1.20",
"E": "$ 1.60"
} | divide(subtract(200.00, multiply(200, 0.40)), 200) | multiply(n0,n3)|subtract(n2,#0)|divide(#1,n1)| | "let price of a sundae = s price of ice cream bar = . 4 $ 200 * . 4 + 200 * s = 200 = > 200 * s = 200 = > s = 0.6 answer a" | general |
math_qa__ZbUinhbMyDzJ1NjP | What is the least value of k. So that 123k578 is divisible by 11. Choose the correct answer
A) 8 B) 7 C) 5 D) 6 E) 4 | <gadget id="calculator">lcm(123, 578)</gadget>
<output>71_094</output>
<gadget id="calculator">71_094 / 578</gadget>
<output>123</output>
<gadget id="calculator">123 / 4</gadget>
<output>123/4 = around 30.75</output>
<gadget id="calculator">(123/4) / 4</gadget>
<output>123/16 = around 7.6875</output>
<result>A</result> | A | 8 | What is the least value of k. So that 123k578 is divisible by 11. | {
"A": "8",
"B": "7",
"C": "5",
"D": "6",
"E": "4"
} | divide(divide(divide(lcm(123, 578), 578), const_4), const_4) | lcm(n0,n1)|divide(#0,n1)|divide(#1,const_4)|divide(#2,const_4) | explanation : the difference of the sum of the digits at odd place and the sum of the digits at even place of the number , is either 0 or a number divisible by 11 . ( 1 + 3 + 5 + 8 ) - ( 2 + k + 7 ) = 17 - 9 - k = 8 - k therefore if k = 8 , then the value become zero . k = 8 is the least value so that 123 k 578 is divisible by 11 . answer : option a | general |
math_qa__fhNaH7yk5bmZCEcr | Local kennel has cats and dogs in the ratio of 3:4. If there are 8 fewer cats than dogs, how many dogs are in the kennel? Choose the correct choice from the following answers
A) 28 B) 26 C) 24 D) 32 E) 30 | <gadget id="calculator">8 * 4</gadget>
<output>32</output>
<result>D</result> | D | 32 | Local kennel has cats and dogs in the ratio of 3:4. If there are 8 fewer cats than dogs, how many dogs are in the kennel? | {
"A": "28",
"B": "26",
"C": "24",
"D": "32",
"E": "30"
} | multiply(8, 4) | multiply(n1,n2)| | "lets work with the data given to us . we know that there ratio of cats to dogs is 3 : 4 or cats 3 dogs 4 we can write number of cats as 3 x and number of dogs as 4 x and we know that 4 x - 3 x = 8 ( therefore x = 8 ) then # of dogs = 4 x 8 = 32 answer is d" | other |
math_qa__dgZSbvmAPAx5dCZO | The ratio of ducks and frogs in a pond is 37 : 39 respectively. The average number of ducks and frogs in the pond is 142. What is the number of frogs in the pond ? Choices: A) 148 B) 152 C) 156 D) 145 E) none | <gadget id="calculator">37 + 39</gadget>
<output>76</output>
<gadget id="calculator">76 + 2</gadget>
<output>78</output>
<gadget id="calculator">78 / 2</gadget>
<output>39</output>
<gadget id="calculator">142 / 39</gadget>
<output>142/39 = around 3.641026</output>
<gadget id="calculator">39 * (142/39)</gadget>
<output>142</output>
<result>D</result> | D | 145 | The ratio of ducks and frogs in a pond is 37 : 39 respectively. The average number of ducks and frogs in the pond is 142. What is the number of frogs in the pond ? | {
"A": "148",
"B": "152",
"C": "156",
"D": "145",
"E": "none"
} | multiply(39, divide(142, divide(add(add(37, 39), const_2), const_2))) | add(n0,n1)|add(#0,const_2)|divide(#1,const_2)|divide(n2,#2)|multiply(n1,#3)| | "solution : ratio of ducks and frogs in pond , = 37 : 39 . average of ducks and frogs in pond , = 142 . so , total number of ducks and frogs in the pond , = 2 * 142 = 284 . therefore , number of frogs , = ( 284 * 39 ) / 76 = 145 . answer : option d" | general |
math_qa__QDlqRaSw0komi94N | John had a stock of 1400 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold? Select the correct option.
A) 50.4 % B) 71.3 % C) 66.5 % D) 34.9 % E) 43.5 % | <gadget id="calculator">75 + 50</gadget>
<output>125</output>
<gadget id="calculator">64 + 78</gadget>
<output>142</output>
<gadget id="calculator">125 + 142</gadget>
<output>267</output>
<gadget id="calculator">267 + 135</gadget>
<output>402</output>
<gadget id="calculator">1_400 - 402</gadget>
<output>998</output>
<gadget id="calculator">998 / 1_400</gadget>
<output>499/700 = around 0.712857</output>
<gadget id="calculator">(499/700) * 100</gadget>
<output>499/7 = around 71.285714</output>
<result>B</result> | B | 71.3 | John had a stock of 1400 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold? | {
"A": "50.4 %",
"B": "71.3 %",
"C": "66.5 %",
"D": "34.9 %",
"E": "43.5 %"
} | multiply(divide(subtract(1400, add(add(add(75, 50), add(64, 78)), 135)), 1400), const_100) | add(n1,n2)|add(n3,n4)|add(#0,#1)|add(n5,#2)|subtract(n0,#3)|divide(#4,n0)|multiply(#5,const_100)| | "let n be the total number of books sold . hence n = 75 + 50 + 64 + 78 + 135 = 402 let m be the books not sold m = 1400 - n = 1400 - 402 = 998 percentage books not sold / total number of books = 998 / 1400 = 0.713 = 71.3 % correct answer b" | gain |
math_qa__XF0ZqnIBXagUykyK | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.1 years, The ratio of the number of boys to the number of girls in the class is
Choose the most appropriate option:
A) 7 : 6 B) 2 : 3 C) 9 : 3 D) 6 : 3 E) 2 : 5 | <gadget id="calculator">15.8 - 15.1</gadget>
<output>0.7</output>
<gadget id="calculator">16.4 - 15.8</gadget>
<output>0.6</output>
<gadget id="calculator">0.7 / 0.6</gadget>
<output>1.166667</output>
<result>A</result> | A | 1.166667 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.1 years, The ratio of the number of boys to the number of girls in the class is | {
"A": "7 : 6",
"B": "2 : 3",
"C": "9 : 3",
"D": "6 : 3",
"E": "2 : 5"
} | divide(subtract(15.8, 15.1), subtract(16.4, 15.8)) | subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1) | explanation : let the ratio be k : 1 . then , k * 16.4 + 1 * 15.1 = ( k + 1 ) * 15.8 < = > ( 16.4 - 15.8 ) k = ( 15.8 - 15.1 ) < = > k = 0.7 / 0.6 = 7 / 6 . required ratio = 7 / 6 : 1 = 7 : 6 . answer : a | general |
math_qa__6D7gkKc5DS2ur5de | A man purchased 4 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? Choose one: A) 300 B) 350 C) 450 D) 470 E) 500 | <gadget id="calculator">10 * 150</gadget>
<output>1_500</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">400 + 750</gadget>
<output>1_150</output>
<gadget id="calculator">1_500 - 1_150</gadget>
<output>350</output>
<result>B</result> | B | 350 | A man purchased 4 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? | {
"A": "300",
"B": "350",
"C": "450",
"D": "470",
"E": "500"
} | subtract(multiply(const_10, 150), add(multiply(4, 100), multiply(5, 150))) | multiply(n3,const_10)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(#0,#3)| | "explanation : 10 * 150 = 1500 4 * 100 + 5 * 150 = 1150 1500 – 1150 = 350 b" | general |
math_qa__BWogFD9SBfCAYgv0 | Of 70 players on a football team, 31 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? Choose the correct answer
A) 57 B) 59 C) 63 D) 71 E) 92 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">70 - 31</gadget>
<output>39</output>
<gadget id="calculator">(2/3) * 39</gadget>
<output>26</output>
<gadget id="calculator">26 + 31</gadget>
<output>57</output>
<result>A</result> | A | 57 | Of 70 players on a football team, 31 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? | {
"A": "57",
"B": "59",
"C": "63",
"D": "71",
"E": "92"
} | add(multiply(subtract(const_1, divide(const_1, const_3)), subtract(70, 31)), 31) | divide(const_1,const_3)|subtract(n0,n1)|subtract(const_1,#0)|multiply(#2,#1)|add(n1,#3)| | "total = 70 thrower = 31 rest = 70 - 31 = 39 left handed = 39 / 3 = 13 right handed = 26 if all thrower are right handed then total right handed is 31 + 26 = 57 so a . 57 is the right answer" | general |
math_qa__dqxkhZtOz91EqqwS | Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 9, what is the measure of side XY? Choose the most appropriate option: A) 4 B) 4 √ 2 C) 8 D) 6 E) can not be determined from the information provided | <gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">3 * (sqrt(2))</gadget>
<output>3*sqrt(2) = around 4.242641</output>
<gadget id="calculator">(3*sqrt(2)) ** 2</gadget>
<output>18</output>
<gadget id="calculator">18 + 18</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<result>D</result> | D | 6 | Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 9, what is the measure of side XY? | {
"A": "4",
"B": "4 √ 2",
"C": "8",
"D": "6",
"E": "can not be determined from the information provided"
} | sqrt(add(power(multiply(sqrt(9), sqrt(const_2)), const_2), power(multiply(sqrt(9), sqrt(const_2)), const_2))) | sqrt(n0)|sqrt(const_2)|multiply(#0,#1)|power(#2,const_2)|add(#3,#3)|sqrt(#4)| | "ans d . . 6 . . xy being larger means it is the hyp . . area = ( 1 / 2 ) * ( yz ) ^ 2 = 9 or yz = 3 * \ sqrt { 2 } . . therefore hyp = xy = 6" | geometry |
math_qa__JVNQSZ9PPCvfH7gr | yesterday ' s closing prices of 1980 different stocks listed on a certain stock exchange were all different from today ' s closing prices . the number of stocks that closed at a higher price today than yesterday was 20 percent greater than the number that closed at a lower price . how many of the stocks closed at a higher price today than yesterday ?
Choices: A) 484 B) 1080 C) 1,100 D) 1,320 E) 1,694 | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) + 1</gadget>
<output>11/5 = around 2.2</output>
<gadget id="calculator">1_980 / (11/5)</gadget>
<output>900</output>
<gadget id="calculator">1_980 - 900</gadget>
<output>1_080</output>
<result>B</result> | B | 1,080 | yesterday ' s closing prices of 1980 different stocks listed on a certain stock exchange were all different from today ' s closing prices . the number of stocks that closed at a higher price today than yesterday was 20 percent greater than the number that closed at a lower price . how many of the stocks closed at a higher price today than yesterday ? | {
"A": "484",
"B": "1080",
"C": "1,100",
"D": "1,320",
"E": "1,694"
} | subtract(1980, divide(1980, add(divide(add(const_100, 20), const_100), const_1))) | add(n1,const_100)|divide(#0,const_100)|add(#1,const_1)|divide(n0,#2)|subtract(n0,#3) | lets consider the below - the number of stocks that closed at a higher price = h the number of stocks that closed at a lower price = l we understand from first statement - > h + l = 1980 - - - - ( 1 ) we understand from second statement - > h = ( 120 / 100 ) l = > h = 1.2 l - - - - ( 2 ) solve eq ( 1 ) ( 2 ) to get h = 1080 . b is my answer . | gain |
math_qa__9blRindpKtikxqSD | A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge (in metres) is?
Select the correct option
A) 2267 B) 1162 C) 2276 D) 1250 E) 1262 | <gadget id="calculator">5 * 1_000</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 / 60</gadget>
<output>250/3 = around 83.333333</output>
<gadget id="calculator">(250/3) * 15</gadget>
<output>1_250</output>
<result>D</result> | D | 1,250 | A man walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge (in metres) is? | {
"A": "2267",
"B": "1162",
"C": "2276",
"D": "1250",
"E": "1262"
} | multiply(divide(multiply(5, const_1000), const_60), 15) | multiply(n0,const_1000)|divide(#0,const_60)|multiply(n1,#1)| | "explanation : speed = ( 5 x 5 / 18 ) m / sec = 25 / 18 m / sec . distance covered in 15 minutes = ( 25 / 18 x 15 x 60 ) m = 1250 m . answer : d" | physics |
math_qa__eBIGZy9axhAYiKQE | A 75m long train is running at 54 km/hr. In how much time will it cross an electric pole? Choose the correct answer: A) 5 B) 10 C) 15 D) 20 E) 25 | <gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 3_600</gadget>
<output>15</output>
<gadget id="calculator">75 / 15</gadget>
<output>5</output>
<result>A</result> | A | 5 | A 75m long train is running at 54 km/hr. In how much time will it cross an electric pole? | {
"A": "5",
"B": "10",
"C": "15",
"D": "20",
"E": "25"
} | divide(75, divide(multiply(54, const_1000), const_3600)) | multiply(n1,const_1000)|divide(#0,const_3600)|divide(n0,#1) | speed of the train = ( 54 * 5 / 18 ) m / sec = 15 m / sec . length of the train = ( speed x time ) time = ( length of the train / speed ) = ( 75 / 15 ) = 5 sec answer : a | general |
math_qa__kNsO4jffO1nRYKoX | What is the least number that should be added to 1077, so the sum of the number is divisible by 23? Choose the correct answer
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">1_077 / 23</gadget>
<output>1_077/23 = around 46.826087</output>
<gadget id="calculator">floor(1_077/23)</gadget>
<output>46</output>
<gadget id="calculator">1 + 46</gadget>
<output>47</output>
<gadget id="calculator">47 - (1_077/23)</gadget>
<output>4/23 = around 0.173913</output>
<gadget id="calculator">(4/23) * 23</gadget>
<output>4</output>
<result>D</result> | D | 4 | What is the least number that should be added to 1077, so the sum of the number is divisible by 23? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | multiply(subtract(add(const_1, floor(divide(1077, 23))), divide(1077, 23)), 23) | divide(n0,n1)|floor(#0)|add(#1,const_1)|subtract(#2,#0)|multiply(n1,#3)| | "( 1077 / 23 ) gives a remainder 19 so we need to add 4 . the answer is d ." | general |
math_qa__FXoHvz8rAQjoA73Q | How many pieces of 0.63 meteres can be cut from a rod 32.5 meteres long
Select.
A) 30
B) 40
C) 51
D) 60
E) 70 | <gadget id="calculator">32.5 / 0.63</gadget>
<output>51.587302</output>
<result>C</result> | C | 51 | How many pieces of 0.63 meteres can be cut from a rod 32.5 meteres long | {
"A": "30",
"B": "40",
"C": "51",
"D": "60",
"E": "70"
} | divide(32.5, 0.63) | divide(n1,n0)| | "explanation : we need so simple divide 32.5 / 0.63 , = ( 3250 / 63 ) = 51 option c" | physics |
math_qa__o9TKJUqgiMlj5mAs | How many terminating zeroes Q does 200! have? Choose the correct choice from the following options.
A) 40 B) 48 C) 49 D) 55 E) 64 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">200 / 25</gadget>
<output>8</output>
<gadget id="calculator">40 + 8</gadget>
<output>48</output>
<result>C</result> | C | 49 | How many terminating zeroes Q does 200! have? | {
"A": "40",
"B": "48",
"C": "49",
"D": "55",
"E": "64"
} | add(divide(200, add(const_4, const_1)), divide(200, multiply(add(const_4, const_1), add(const_4, const_1)))) | add(const_1,const_4)|divide(n0,#0)|multiply(#0,#0)|divide(n0,#2)|add(#1,#3)| | you have 40 multiples of 5 , 8 of 25 and 1 of 125 . this will give 49 zeros . c | other |
math_qa__JFxHmb3SsedUmC0C | Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy 17 times as heavy as water? Choose one
A) 1 : 2 B) 3 : 2 C) 4 : 1 D) 5 : 2 E) 6 : 5 | <gadget id="calculator">17 - 9</gadget>
<output>8</output>
<gadget id="calculator">19 - 17</gadget>
<output>2</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>C</result> | C | 4 | Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy 17 times as heavy as water? | {
"A": "1 : 2",
"B": "3 : 2",
"C": "4 : 1",
"D": "5 : 2",
"E": "6 : 5"
} | divide(subtract(17, 9), subtract(19, 17)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "g = 19 w c = 9 w let 1 gm of gold mixed with x gm of copper to get 1 + x gm of the alloy 1 gm gold + x gm copper = x + 1 gm of alloy 19 w + 9 wx = x + 1 * 17 w 19 + 9 x = 17 ( x + 1 ) x = 1 / 4 ratio of gold with copper = 1 : 1 / 4 = 4 : 1 answer is c" | general |
math_qa__Z3af8dWEE64tH7ZT | A man bought an article and sold it at a gain of 5 %. If he had bought it at 5% less and sold it for Re 2 less, he would have made a profit of 10%. The C.P. of the article was Choose the correct choice
A) 344 B) 218 C) 400 D) 388 E) 211 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">200 * 2</gadget>
<output>400</output>
<result>C</result> | C | 400 | A man bought an article and sold it at a gain of 5 %. If he had bought it at 5% less and sold it for Re 2 less, he would have made a profit of 10%. The C.P. of the article was | {
"A": "344",
"B": "218",
"C": "400",
"D": "388",
"E": "211"
} | multiply(multiply(multiply(5, const_4.0), 10), 2) | multiply(n0,const_4.0)|multiply(n3,#0)|multiply(n2,#1)| | "explanation : let original cost price is x its selling price = ( 105 / 100 ) * x = 21 x / 20 new cost price = ( 95 / 100 ) * x = 19 x / 20 new selling price = ( 110 / 100 ) * ( 19 x / 20 ) = 209 x / 200 [ ( 21 x / 20 ) - ( 209 x / 200 ) ] = 2 = > x = 400 answer : c ) rs 400" | gain |
math_qa__tz56RFMGN2nNBvAu | Two trains of equal are running on parallel lines in the same direction at 47 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is? Choose the correct choice from the following choices: A) 50 B) 88 C) 66 D) 55 E) 22 | <gadget id="calculator">47 - 36</gadget>
<output>11</output>
<gadget id="calculator">11 * 1_000</gadget>
<output>11_000</output>
<gadget id="calculator">11_000 / 3_600</gadget>
<output>55/18 = around 3.055556</output>
<gadget id="calculator">36 * (55/18)</gadget>
<output>110</output>
<gadget id="calculator">110 / 2</gadget>
<output>55</output>
<result>D</result> | D | 55 | Two trains of equal are running on parallel lines in the same direction at 47 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is? | {
"A": "50",
"B": "88",
"C": "66",
"D": "55",
"E": "22"
} | divide(multiply(36, divide(multiply(subtract(47, 36), const_1000), const_3600)), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "let the length of each train be x m . then , distance covered = 2 x m . relative speed = 47 - 36 = 11 km / hr . = 11 * 5 / 18 = 55 / 18 m / sec . 2 x / 36 = 55 / 18 = > x = 55 . answer : d" | general |
math_qa__QZ67OJbFXTJ5Nipo | A confectioner decides to sell all of his pastry due to the coming holiday. His pastry goods are equally divided among a group of 30 regular customers. If only 49 customers come to the bakery, each one will receive 6 less pastry goods. How much pastry does the confectioner needs to sell? Choose the correct answer
A) 450 . B) 412 . C) 432 . D) 502 . E) 522 . | <gadget id="calculator">49 * 6</gadget>
<output>294</output>
<gadget id="calculator">49 - 30</gadget>
<output>19</output>
<gadget id="calculator">294 / 19</gadget>
<output>294/19 = around 15.473684</output>
<gadget id="calculator">(294/19) * 30</gadget>
<output>8_820/19 = around 464.210526</output>
<result>A</result> | A | 450 | A confectioner decides to sell all of his pastry due to the coming holiday. His pastry goods are equally divided among a group of 30 regular customers. If only 49 customers come to the bakery, each one will receive 6 less pastry goods. How much pastry does the confectioner needs to sell? | {
"A": "450 .",
"B": "412 .",
"C": "432 .",
"D": "502 .",
"E": "522 ."
} | multiply(divide(multiply(49, 6), subtract(49, 30)), 30) | multiply(n1,n2)|subtract(n1,n0)|divide(#0,#1)|multiply(n0,#2) | pastry is divided in 30 customers equally . so , total number of pastry must be a multiple of 30 only option a satisfies the condition , and hence is the answer | general |
math_qa__pKoZVFKCD4vd05Wr | The average weight of 8 person's increases by 6 kg when a new person comes in place of one of them weighing 45 kg. What is the weight of the new person?
Pick one:
A) 90 B) 93 C) 56 D) 80.5 E) 78 | <gadget id="calculator">8 * 6</gadget>
<output>48</output>
<gadget id="calculator">48 + 45</gadget>
<output>93</output>
<result>B</result> | B | 93 | The average weight of 8 person's increases by 6 kg when a new person comes in place of one of them weighing 45 kg. What is the weight of the new person? | {
"A": "90",
"B": "93",
"C": "56",
"D": "80.5",
"E": "78"
} | add(multiply(8, 6), 45) | multiply(n0,n1)|add(n2,#0)| | "total increase in weight = 8 × 6 = 48 if x is the weight of the new person , total increase in weight = x − 45 = > 48 = x - 45 = > x = 48 + 45 = 93 answer : b" | general |
math_qa__rWWSGkelTfCjsUVu | How many digits 2^300 has? Choose one
A) 31
B) 35
C) 50
D) 91
E) 101 | <gadget id="calculator">log(2)</gadget>
<output>log(2) = around 0.693147</output>
<gadget id="calculator">log(10)</gadget>
<output>log(10) = around 2.302585</output>
<gadget id="calculator">log(2) / log(10)</gadget>
<output>log(2)/log(10) = around 0.30103</output>
<gadget id="calculator">(log(2)/log(10)) * 300</gadget>
<output>300*log(2)/log(10) = around 90.308999</output>
<gadget id="calculator">1 + (300*log(2)/log(10))</gadget>
<output>1 + 300*log(2)/log(10) = around 91.308999</output>
<gadget id="calculator">floor(1 + 300*log(2)/log(10))</gadget>
<output>91</output>
<result>D</result> | D | 91 | How many digits 2^300 has? | {
"A": "31",
"B": "35",
"C": "50",
"D": "91",
"E": "101"
} | floor(add(const_1, multiply(divide(log(2), log(const_10)), 300))) | log(n0)|log(const_10)|divide(#0,#1)|multiply(n1,#2)|add(#3,const_1)|floor(#4) | 2 ^ 10 = 1.024 * 10 ^ 3 = > 2 ^ 100 = ( 1.024 ) ^ 10 * 10 ^ 90 therefore 91 digits would be my best guess d | general |
math_qa__AlqOnyDHeKeTti94 | After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets ? Choices
A) 328
B) 348
C) 358
D) 362
E) data inadequate | <gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">28 * 12</gadget>
<output>336</output>
<gadget id="calculator">336 + 22</gadget>
<output>358</output>
<result>C</result> | C | 358 | After distributing the sweets equally among 25 children, 8 sweets remain. Had the number of children been 28, 22 sweets would have been left after equal distribution. What was the total number of sweets ? | {
"A": "328",
"B": "348",
"C": "358",
"D": "362",
"E": "data inadequate"
} | add(multiply(28, divide(subtract(25, const_1), const_2)), 22) | subtract(n0,const_1)|divide(#0,const_2)|multiply(n2,#1)|add(n3,#2) | explanation : let the total number of sweets be ( 25 x + 8 ) . then , ( 25 x + 8 ) - 22 is divisible by 28 ( 25 x - 14 ) is divisible by 28 28 x - ( 3 x + 14 ) is divisible by 28 ( 3 x + 14 ) is divisible by 28 x = 14 . therefore total number of sweets = ( 25 x 14 + 8 ) = 358 . answer : c | general |
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