id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__F7MH9cnA9fti9Rsq | If a certain number is divided by 9, the quotient, dividend, and divisor, added together, will amount to 69. What is the number?
Choose the correct choice from the following answers
A) 18 B) 28 C) 48 D) 38 E) 54 | <gadget id="calculator">69 - 9</gadget>
<output>60</output>
<gadget id="calculator">60 * 9</gadget>
<output>540</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">540 / 10</gadget>
<output>54</output>
<result>E</result> | E | 54 | If a certain number is divided by 9, the quotient, dividend, and divisor, added together, will amount to 69. What is the number? | {
"A": "18",
"B": "28",
"C": "48",
"D": "38",
"E": "54"
} | divide(multiply(subtract(69, 9), 9), add(9, const_1)) | add(n0,const_1)|subtract(n1,n0)|multiply(n0,#1)|divide(#2,#0) | let x = the number sought . then x / 9 + x + 9 = 69 . and x = 54 . e | general |
math_qa__fScoP1XqI4X217MH | If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre? Pick one
A) rs . 49.17 B) rs . 51.03 C) rs . 54.17 D) rs . 55.33 E) none of the above | <gadget id="calculator">10 * 50</gadget>
<output>500</output>
<gadget id="calculator">5 * 66</gadget>
<output>330</output>
<gadget id="calculator">500 + 330</gadget>
<output>830</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">830 / 15</gadget>
<output>166/3 = around 55.333333</output>
<result>D</result> | D | 55.33 | If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre? | {
"A": "rs . 49.17",
"B": "rs . 51.03",
"C": "rs . 54.17",
"D": "rs . 55.33",
"E": "none of the above"
} | divide(add(multiply(10, 50), multiply(5, 66)), add(10, 5)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "50 * 10 = 500 66 * 5 = 330 830 / 15 = 55.33 answer : d" | gain |
math_qa__OvHnG5q2KV3FLAVV | If the price of a book is first decreased by 25% and then increased by 20%, then the decrease in the price will be? Select the correct option: A) 20 % B) 10 % C) 25 % D) 18 % E) 30 % | <gadget id="calculator">100 * 25</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">100 * 20</gadget>
<output>2_000</output>
<gadget id="calculator">2_000 / 100</gadget>
<output>20</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(3/4) * (6/5)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 100</gadget>
<output>90</output>
<gadget id="calculator">100 - 90</gadget>
<output>10</output>
<result>B</result> | B | 10 | If the price of a book is first decreased by 25% and then increased by 20%, then the decrease in the price will be? | {
"A": "20 %",
"B": "10 %",
"C": "25 %",
"D": "18 %",
"E": "30 %"
} | subtract(const_100, multiply(multiply(divide(subtract(const_100, divide(multiply(const_100, 25), const_100)), const_100), divide(add(const_100, divide(multiply(const_100, 20), const_100)), const_100)), const_100)) | multiply(n0,const_100)|multiply(n1,const_100)|divide(#0,const_100)|divide(#1,const_100)|add(#3,const_100)|subtract(const_100,#2)|divide(#5,const_100)|divide(#4,const_100)|multiply(#6,#7)|multiply(#8,const_100)|subtract(const_100,#9)| | "let the original price be $ 100 new final price = 120 % of ( 75 % of $ 100 ) = 120 / 100 * 75 / 100 * 100 = $ 90 decrease is 10 % answer is b" | general |
math_qa__ojwLHBEdJsgC6CA9 | The average weight of 8 people increases by 2.5 kg when a new person comes in place of one of them weighing 35 kg. What is the weight of the new person? Choose the correct choice from the following answers: A) 75 kg B) 85 kg C) 95 kg D) 65 kg E) 55 kg | <gadget id="calculator">2.5 * 8</gadget>
<output>20</output>
<gadget id="calculator">20 + 35</gadget>
<output>55</output>
<result>E</result> | E | 55 | The average weight of 8 people increases by 2.5 kg when a new person comes in place of one of them weighing 35 kg. What is the weight of the new person? | {
"A": "75 kg",
"B": "85 kg",
"C": "95 kg",
"D": "65 kg",
"E": "55 kg"
} | add(multiply(2.5, 8), 35) | multiply(n0,n1)|add(n2,#0)| | "the total weight increase = ( 8 x 2.5 ) kg = 20 kg weight of new person = ( 35 + 20 ) kg = 55 kg the answer is e ." | general |
math_qa__OGOrW45IzzoL7LS2 | From an island, it is possible to reach the mainland by either Ferry P or Ferry Q. Ferry P travels for 2 hours at 8 kilometers per hour, while Ferry Q takes a route that is three times longer. If Ferry P is slower than Ferry Q by 4 kilometers per hour, how many hours longer is the journey of Ferry Q compared with the journey of Ferry P?
Choose the correct answer:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">3 * 16</gadget>
<output>48</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">48 / 12</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<result>B</result> | B | 2 | From an island, it is possible to reach the mainland by either Ferry P or Ferry Q. Ferry P travels for 2 hours at 8 kilometers per hour, while Ferry Q takes a route that is three times longer. If Ferry P is slower than Ferry Q by 4 kilometers per hour, how many hours longer is the journey of Ferry Q compared with the journey of Ferry P? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(divide(multiply(const_3, multiply(8, 2)), add(8, 4)), 2) | add(n1,n2)|multiply(n0,n1)|multiply(#1,const_3)|divide(#2,#0)|subtract(#3,n0) | the distance traveled by ferry p is 16 km . then the distance traveled by ferry q is 48 km . ferry q travels at a speed of 12 kph . the time of the journey for ferry q is 48 / 12 = 4 hours , which is 2 hours more than ferry p . the answer is b . | physics |
math_qa__kz2vCiXdkm1bKY0T | A car takes 6 hours to cover a distance of 324 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Answers: A) 50 kmph B) 60 kmph C) 65 kmph D) 36 kmph E) none | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">324 / 9</gadget>
<output>36</output>
<result>D</result> | D | 36 | A car takes 6 hours to cover a distance of 324 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "50 kmph",
"B": "60 kmph",
"C": "65 kmph",
"D": "36 kmph",
"E": "none"
} | divide(324, divide(multiply(6, 3), 2)) | multiply(n0,n2)|divide(#0,n3)|divide(n1,#1)| | "time = 6 distence = 324 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 324 / 9 = 36 kmph d )" | physics |
math_qa__uJji14eftkGL2Qz3 | In a renowned city, the average birth rate is 4 people every two seconds and the death rate is 2 people every two seconds. Estimate the size of the population net increase that occurs in one day. Choose the correct choice from the following answers:
A) 86,400 B) 172,800 C) 468,830 D) 338,200 E) 259,200 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">2 * 3_600</gadget>
<output>7_200</output>
<gadget id="calculator">7_200 * 12</gadget>
<output>86_400</output>
<result>A</result> | A | 86,400 | In a renowned city, the average birth rate is 4 people every two seconds and the death rate is 2 people every two seconds. Estimate the size of the population net increase that occurs in one day. | {
"A": "86,400",
"B": "172,800",
"C": "468,830",
"D": "338,200",
"E": "259,200"
} | multiply(multiply(subtract(4, 2), const_3600), const_12) | subtract(n0,n1)|multiply(#0,const_3600)|multiply(#1,const_12)| | "every 2 seconds , 2 persons are added ( 4 - 2 ) . every second 1 person are added . in a day 24 hrs = 24 * 60 minutes = 24 * 60 * 60 = 86400 seconds . 86400 * 1 = 86400 option a" | general |
math_qa__IW6R8IJVOeeloJt3 | Steve traveled the first 5 hours of his journey at 40 mph and the last 3 hours of his journey at 80 mph. What is his average speed of travel for the entire journey?
Choose the most appropriate option
A) 53.33 mph B) 88 mph C) 60 mph D) 64 mph E) 66.67 mph | <gadget id="calculator">80 * 3</gadget>
<output>240</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<gadget id="calculator">240 + 200</gadget>
<output>440</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">440 / 8</gadget>
<output>55</output>
<gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(100/3) - (1/3)</gadget>
<output>33</output>
<gadget id="calculator">55 + 33</gadget>
<output>88</output>
<result>B</result> | B | 88 | Steve traveled the first 5 hours of his journey at 40 mph and the last 3 hours of his journey at 80 mph. What is his average speed of travel for the entire journey? | {
"A": "53.33 mph",
"B": "88 mph",
"C": "60 mph",
"D": "64 mph",
"E": "66.67 mph"
} | add(divide(add(multiply(80, 3), multiply(40, 5)), add(3, 5)), subtract(divide(const_100, const_3), const_0_33)) | add(n0,n2)|divide(const_100,const_3)|multiply(n2,n3)|multiply(n0,n1)|add(#2,#3)|subtract(#1,const_0_33)|divide(#4,#0)|add(#6,#5) | average speed = total distance / total time = ( 40 * 5 + 80 * 3 ) / ( 5 + 3 ) = 440 / 5 = 88 answer : b | physics |
math_qa__tnEDiEboY7YAy92n | If circles x and y have the same area and circle x has a circumference of 20π, half of the radius of circle y is: Pick:
A) 16 B) 5 C) 4 D) 2 E) 1 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>B</result> | B | 5 | If circles x and y have the same area and circle x has a circumference of 20π, half of the radius of circle y is: | {
"A": "16",
"B": "5",
"C": "4",
"D": "2",
"E": "1"
} | divide(divide(20, const_2), const_2) | divide(n0,const_2)|divide(#0,const_2)| | "x b é radius of circle x ý b é radius of circle y given : pi * x ^ 2 = pi * ý ^ 2 also , 2 * pi * x = 20 * pi x = 10 thus ý = 10 y / 2 = 5 ans : b" | geometry |
math_qa__QoOmAjNcajmlW4gd | What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23? Select the correct option:
A) 20 B) 23 C) 25 D) 27 E) 28 | <gadget id="calculator">1_056 % 23</gadget>
<output>21</output>
<gadget id="calculator">23 - 21</gadget>
<output>2</output>
<gadget id="calculator">23 - 3</gadget>
<output>20</output>
<gadget id="calculator">2 + 20</gadget>
<output>22</output>
<result>B</result> | B | 23 | What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23? | {
"A": "20",
"B": "23",
"C": "25",
"D": "27",
"E": "28"
} | add(subtract(23, reminder(1056, 23)), subtract(23, const_3)) | reminder(n0,n1)|subtract(n1,const_3)|subtract(n1,#0)|add(#2,#1) | ( 1056 / 23 ) gives remainder 21 21 + 2 = 23 , so we need to add 2 b | general |
math_qa__yfuSJW8MwiSYH8wX | Tanks C and B are each in the shape of a right circular cylinder. The interior of tank C has a height of 10 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank C is what percent of the capacity of tank B? Choose the correct choice from the following: A) 75 % B) 80 % C) 100 % D) 120 % E) 125 % | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">pi * (4 ** 2) * 10</gadget>
<output>160*pi = around 502.654825</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">pi * (5 ** 2) * 8</gadget>
<output>200*pi = around 628.318531</output>
<gadget id="calculator">(160*pi) / (200*pi)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 100</gadget>
<output>80</output>
<result>B</result> | B | 80 | Tanks C and B are each in the shape of a right circular cylinder. The interior of tank C has a height of 10 meters and a circumference of 8 meters, and the interior of tank B has a height of 8 meters and a circumference of 10 meters. The capacity of tank C is what percent of the capacity of tank B? | {
"A": "75 %",
"B": "80 %",
"C": "100 %",
"D": "120 %",
"E": "125 %"
} | multiply(divide(volume_cylinder(divide(8, const_2), 10), volume_cylinder(divide(10, const_2), 8)), const_100) | divide(n1,const_2)|divide(n0,const_2)|volume_cylinder(#0,n0)|volume_cylinder(#1,n1)|divide(#2,#3)|multiply(#4,const_100) | b . for c , r = 8 / 2 pi . its capacity = ( 4 pi ) ^ 2 * 10 = 160 pi for b , r = 10 / pi . its capacity = ( 5 pi ) ^ 2 * 8 = 200 pi c / b = 160 pi / 200 pi = 0.8 | physics |
math_qa__SDd8fg2NUxMkyiHu | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 22, the how old is B?
Choose the correct choice from the following answers:
A) 7
B) 9
C) 8
D) 11
E) 10 | <gadget id="calculator">22 - 2</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<result>C</result> | C | 8 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 22, the how old is B? | {
"A": "7",
"B": "9",
"C": "8",
"D": "11",
"E": "10"
} | divide(multiply(subtract(22, const_2), const_2), add(const_4, const_1)) | add(const_1,const_4)|subtract(n0,const_2)|multiply(#1,const_2)|divide(#2,#0)| | "explanation : let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 22 ⇒ 5 x = 20 ⇒ x = 4 . hence , b ' s age = 2 x = 8 years . answer : c" | general |
math_qa__CMIAse7lM0e5ORou | In the fifth grade at Parkway elementary school there are 420 students. 312 students are boys and 250 students are playing soccer. 78% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer?
Choose the correct choice from the following choices.
A) 69 . B) 73 . C) 53 D) 91 E) 108 | <gadget id="calculator">420 - 312</gadget>
<output>108</output>
<gadget id="calculator">250 * 78</gadget>
<output>19_500</output>
<gadget id="calculator">19_500 / 100</gadget>
<output>195</output>
<gadget id="calculator">250 - 195</gadget>
<output>55</output>
<gadget id="calculator">108 - 55</gadget>
<output>53</output>
<result>C</result> | C | 53 | In the fifth grade at Parkway elementary school there are 420 students. 312 students are boys and 250 students are playing soccer. 78% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer? | {
"A": "69 .",
"B": "73 .",
"C": "53",
"D": "91",
"E": "108"
} | subtract(subtract(420, 312), subtract(250, divide(multiply(250, 78), const_100))) | multiply(n2,n3)|subtract(n0,n1)|divide(#0,const_100)|subtract(n2,#2)|subtract(#1,#3)| | "total students = 420 boys = 312 , girls = 108 total playing soccer = 250 78 % of 250 = 195 are boys who play soccer . girls who play soccer = 55 . total girls who do not play soccer = 108 - 55 = 53 . correct option : c" | gain |
math_qa__D5DoifFKO545SYAe | The price of 3 pants and 6 t-shirts is Rs. 1500. With the same money one can buy 1 pant and 12 t-shirts. If one wants to buy 8 t-shirts, how much shall she have to pay ? Choose the correct option.
A) 700 B) 300 C) 250 D) 550 E) 800 | <gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 6</gadget>
<output>15</output>
<gadget id="calculator">1_500 / 15</gadget>
<output>100</output>
<gadget id="calculator">100 * 8</gadget>
<output>800</output>
<result>E</result> | E | 800 | The price of 3 pants and 6 t-shirts is Rs. 1500. With the same money one can buy 1 pant and 12 t-shirts. If one wants to buy 8 t-shirts, how much shall she have to pay ? | {
"A": "700",
"B": "300",
"C": "250",
"D": "550",
"E": "800"
} | multiply(divide(1500, add(multiply(divide(subtract(12, 6), subtract(3, 1)), 3), 6)), 8) | subtract(n4,n1)|subtract(n0,n3)|divide(#0,#1)|multiply(n0,#2)|add(n1,#3)|divide(n2,#4)|multiply(n5,#5) | let the price of a pant and a t - shirt be rs . x and rs . y respectively . then , 3 x + 6 y = 1500 . . . . ( i ) and x + 12 y = 1500 . . . . ( ii ) divide equation ( i ) by 3 , we get the below equation . = x + 2 y = 500 . - - - ( iii ) now subtract ( iii ) from ( ii ) x + 12 y = 1500 ( - ) x + 2 y = 500 - - - - - - - - - - - - - - - - 10 y = 1000 - - - - - - - - - - - - - - - - cost of 8 t - shirts = 8 * 100 = 800 answer : e | general |
math_qa__cpCksEKfP28hlkTm | Rs.770 were divided among A,B,C in such a way that A had Rs.40 more than B and C had Rs 30 more than A . How much was B’s share?
Choose the correct choice from the following answers
A) rs . 260 B) rs . 270 C) rs . 280 D) rs . 290 E) rs . 300 | <gadget id="calculator">40 + 40</gadget>
<output>80</output>
<gadget id="calculator">80 + 30</gadget>
<output>110</output>
<gadget id="calculator">770 - 110</gadget>
<output>660</output>
<gadget id="calculator">660 / 3</gadget>
<output>220</output>
<gadget id="calculator">220 + 30</gadget>
<output>250</output>
<gadget id="calculator">250 + 40</gadget>
<output>290</output>
<result>D</result> | D | 290 | Rs.770 were divided among A,B,C in such a way that A had Rs.40 more than B and C had Rs 30 more than A . How much was B’s share? | {
"A": "rs . 260",
"B": "rs . 270",
"C": "rs . 280",
"D": "rs . 290",
"E": "rs . 300"
} | add(add(divide(subtract(770, add(add(40, 40), 30)), const_3), 30), 40) | add(n1,n1)|add(n2,#0)|subtract(n0,#1)|divide(#2,const_3)|add(n2,#3)|add(n1,#4) | let b gets rs x . then we can say a gets rs ( x + 40 ) and c gets rs ( x + 70 ) . x + 40 + x + x + 70 = 770 3 x = 660 x = 220 . b â € ™ s share = rs ( 220 + 70 ) = rs . 290 d | general |
math_qa__S0Rqv30RL9Fioji6 | What is the greatest of 3 consecutive integers whose sum is 39? Options
A) 14 B) 15 C) 16 D) 17 E) 18 | <gadget id="calculator">39 - 3</gadget>
<output>36</output>
<gadget id="calculator">36 / 3</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<result>A</result> | A | 14 | What is the greatest of 3 consecutive integers whose sum is 39? | {
"A": "14",
"B": "15",
"C": "16",
"D": "17",
"E": "18"
} | add(divide(subtract(39, 3), 3), const_2) | subtract(n1,n0)|divide(#0,n0)|add(#1,const_2)| | "39 / 3 = 13 the three numbers are 12 , 13 , and 14 . the answer is a ." | physics |
math_qa__1TpgEPtuhICIlEjp | Pipe A can fill a tank in 10 hr, pipe B in 20hr and pipe C in 40hr. If all the pipes are open in how many hours will tank be filled? Choose the correct choice from the following: A) 1 hr B) 30 min C) 15 min D) 17 min E) 10 min | <gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">10 / 20</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(3/2) + (1/4)</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">(7/4) * 10</gadget>
<output>35/2 = around 17.5</output>
<result>D</result> | D | 17 | Pipe A can fill a tank in 10 hr, pipe B in 20hr and pipe C in 40hr. If all the pipes are open in how many hours will tank be filled? | {
"A": "1 hr",
"B": "30 min",
"C": "15 min",
"D": "17 min",
"E": "10 min"
} | multiply(add(add(divide(10, 10), divide(10, 20)), divide(10, 40)), 10) | divide(n0,n0)|divide(n0,n1)|divide(n0,n2)|add(#0,#1)|add(#3,#2)|multiply(n0,#4) | part filled by ( a + b + c ) in 1 hour = 1 / 10 + 1 / 20 + 1 / 40 = 7 / 40 all the 3 pipes together will fill the tank in 17 min approximately answer is d | physics |
math_qa__01o1LXceQ08T070p | A 40 kg metal bar made of alloy of tin and silver lost 4 kg of its weight in the water. 10 kg of tin loses 1.375 kg in the water; 5 kg of silver loses 0.375 kg. What is the ratio of tin to silver in the bar? Choose the correct choice from the following answers
A) 1 / 4 B) 2 / 5 C) 1 / 2 D) 3 / 5 E) 2 / 3 | <gadget id="calculator">0.375 / 5</gadget>
<output>0.075</output>
<gadget id="calculator">0.075 * 40</gadget>
<output>3</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">1.375 / 10</gadget>
<output>0.1375</output>
<gadget id="calculator">0.1375 - 0.075</gadget>
<output>0.0625</output>
<gadget id="calculator">1 / 0.0625</gadget>
<output>16</output>
<gadget id="calculator">40 - 16</gadget>
<output>24</output>
<gadget id="calculator">16 / 24</gadget>
<output>2/3 = around 0.666667</output>
<result>E</result> | E | 0.666667 | A 40 kg metal bar made of alloy of tin and silver lost 4 kg of its weight in the water. 10 kg of tin loses 1.375 kg in the water; 5 kg of silver loses 0.375 kg. What is the ratio of tin to silver in the bar? | {
"A": "1 / 4",
"B": "2 / 5",
"C": "1 / 2",
"D": "3 / 5",
"E": "2 / 3"
} | divide(divide(subtract(4, multiply(divide(0.375, 5), 40)), subtract(divide(1.375, 10), divide(0.375, 5))), subtract(40, divide(subtract(4, multiply(divide(0.375, 5), 40)), subtract(divide(1.375, 10), divide(0.375, 5))))) | divide(n5,n4)|divide(n3,n2)|multiply(n0,#0)|subtract(#1,#0)|subtract(n1,#2)|divide(#4,#3)|subtract(n0,#5)|divide(#5,#6) | you can simply use this formula to avoid confusion : w 1 / w 2 = ( a 2 - aavg ) / ( avg - a 1 ) here is how you will find the values of a 1 an a 2 . we have an overall loss ( average loss ) . the average loss is 4 kg when 40 kg alloy is immersed . this is a loss of ( 4 / 40 ) * 100 = 10 % . this is aavg the loss of tin is 1.375 kg for every 10 kg . this means it loses ( 1.375 / 10 ) * 100 = 13.75 % of its weight in water . this is a 1 . the loss of silver is . 375 kg for every 5 kg . this means it loses ( . 375 / 5 ) * 100 = 7.5 % of its weight in water . this is a 2 . weight of tin / weight of silver = ( silver ' s loss - avg loss ) / ( avg loss - tin ' s loss ) x / y = ( 7.5 - 10 ) / ( 10 - 13.75 ) = 2 / 3 e | other |
math_qa__ntOBt6tvLZxgxvUv | In a sports club with 28 members, 17 play badminton and 19 play tennis and 2 do not play either. How many members play both badminton and tennis? Choose the correct choice from the following answers
A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">17 + 19</gadget>
<output>36</output>
<gadget id="calculator">36 + 2</gadget>
<output>38</output>
<gadget id="calculator">38 - 28</gadget>
<output>10</output>
<result>D</result> | D | 10 | In a sports club with 28 members, 17 play badminton and 19 play tennis and 2 do not play either. How many members play both badminton and tennis? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | subtract(add(add(17, 19), 2), 28) | add(n1,n2)|add(n3,#0)|subtract(#1,n0)| | "let x play both badminton and tennis so 17 - x play only badminton and 19 - x play only tennis . 2 play none and there are total 30 students . hence , ( 17 - x ) + ( 19 - x ) + x + 2 = 28 38 - 2 x + x = 28 38 - x = 28 x = 10 so 8 members play both badminton and tennis . d" | other |
math_qa__brS0XnaRcMKAPzNO | Village X has a population of 74000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal? Options: A) 15 B) 16 C) 11 D) 18 E) 13 | <gadget id="calculator">74_000 - 42_000</gadget>
<output>32_000</output>
<gadget id="calculator">800 + 1_200</gadget>
<output>2_000</output>
<gadget id="calculator">32_000 / 2_000</gadget>
<output>16</output>
<result>B</result> | B | 16 | Village X has a population of 74000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal? | {
"A": "15",
"B": "16",
"C": "11",
"D": "18",
"E": "13"
} | divide(subtract(74000, 42000), add(800, 1200)) | add(n1,n3)|subtract(n0,n2)|divide(#1,#0)| | "let the population of two villages be equal after p years then , 74000 - 1200 p = 42000 + 800 p 2000 p = 32000 p = 16 answer is b ." | general |
math_qa__fhOdOYpHcFDZVWQQ | The radius of a semi circle is 6.5 cm then its perimeter is? Choose the correct choice from the following choices.
A) 32.7 B) 32.4 C) 33.4 D) 32.8 E) 32.1 | <gadget id="calculator">2 * pi * 6.5</gadget>
<output>13.0*pi = around 40.840704</output>
<gadget id="calculator">(13.0*pi) / 2</gadget>
<output>6.5*pi = around 20.420352</output>
<gadget id="calculator">6.5 * 2</gadget>
<output>13</output>
<gadget id="calculator">(6.5*pi) + 13</gadget>
<output>13 + 6.5*pi = around 33.420352</output>
<result>C</result> | C | 33.4 | The radius of a semi circle is 6.5 cm then its perimeter is? | {
"A": "32.7",
"B": "32.4",
"C": "33.4",
"D": "32.8",
"E": "32.1"
} | add(divide(circumface(6.5), const_2), multiply(6.5, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "36 / 7 r = 6.5 = 33.4 answer : c" | physics |
math_qa__Fxei4tAW0jmuc0r9 | A number x is 3 times another number y. The percentage that y is less than x is Pick:
A) 12.5 %
B) 66.6 %
C) 80 %
D) 11 %
E) 1 % | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>B</result> | B | 66.6 | A number x is 3 times another number y. The percentage that y is less than x is | {
"A": "12.5 %",
"B": "66.6 %",
"C": "80 %",
"D": "11 %",
"E": "1 %"
} | multiply(divide(subtract(3, const_1), 3), const_100) | subtract(n0,const_1)|divide(#0,n0)|multiply(#1,const_100)| | "say y = 1 and x = 3 . then y = 1 is less than x = 3 by ( 3 - 1 ) / 3 * 100 = 2 / 3 * 100 = 66.6 % . answer : b ." | general |
math_qa__voiUw7DolndxSkJn | If a car had traveled 20 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 60 km, at what speed did it travel? Options.
A) 35 kmh
B) 40 kmh
C) 50 kmh
D) 60 kmh
E) 65 kmh | <gadget id="calculator">60 * 20</gadget>
<output>1_200</output>
<gadget id="calculator">2 * 1_200</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 * 4</gadget>
<output>9_600</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">9_600 + 400</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 ** (1/2)</gadget>
<output>100</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>B</result> | B | 40 | If a car had traveled 20 kmh faster than it actually did, the trip would have lasted 30 minutes less. If the car went exactly 60 km, at what speed did it travel? | {
"A": "35 kmh",
"B": "40 kmh",
"C": "50 kmh",
"D": "60 kmh",
"E": "65 kmh"
} | divide(subtract(sqrt(add(multiply(multiply(const_2, multiply(60, 20)), const_4), power(20, const_2))), 20), const_2) | multiply(n0,n2)|power(n0,const_2)|multiply(#0,const_2)|multiply(#2,const_4)|add(#3,#1)|sqrt(#4)|subtract(#5,n0)|divide(#6,const_2)| | "time = distance / speed difference in time = 1 / 2 hrs 60 / x - 60 / ( x + 20 ) = 1 / 2 substitute the value of x from the options . - - > x = 40 - - > 60 / 40 - 60 / 60 = 3 / 2 - 1 = 1 / 2 answer : b" | physics |
math_qa__cu9rasLfwpsz4TZN | A student has to obtain 33% of the total marks to pass. He got 59 marks and failed by 40 marks. The maximum marks are? Select the correct option:
A) 450 B) 300 C) 500 D) 610 E) 175 | <gadget id="calculator">59 + 40</gadget>
<output>99</output>
<gadget id="calculator">33 / 100</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">99 / (33/100)</gadget>
<output>300</output>
<result>B</result> | B | 300 | A student has to obtain 33% of the total marks to pass. He got 59 marks and failed by 40 marks. The maximum marks are? | {
"A": "450",
"B": "300",
"C": "500",
"D": "610",
"E": "175"
} | divide(add(59, 40), divide(33, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "let the maximum marks be x then , 33 % of x = 59 + 40 33 x / 100 = 99 x = 300 answer is b" | general |
math_qa__KG9mytpWEgiFJ52e | The amount of principal Rs.8000 at compound interest at the ratio of 5% p.a. for 4 years is
Choose the correct choice from the following answers:
A) s . 9621
B) s . 6921
C) s . 9724
D) s . 6261
E) s . 6361 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 4</gadget>
<output>194_481/160_000 = around 1.215506</output>
<gadget id="calculator">8_000 * (194_481/160_000)</gadget>
<output>194_481/20 = around 9_724.05</output>
<result>C</result> | C | 9,724 | The amount of principal Rs.8000 at compound interest at the ratio of 5% p.a. for 4 years is | {
"A": "s . 9621",
"B": "s . 6921",
"C": "s . 9724",
"D": "s . 6261",
"E": "s . 6361"
} | multiply(8000, power(add(const_1, divide(5, const_100)), 4)) | divide(n1,const_100)|add(#0,const_1)|power(#1,n2)|multiply(n0,#2)| | "c . i = p ( 1 + r / 100 ) ^ n = 8000 ( 1 + 5 / 100 ) ^ 4 = rs 9724 answer : c" | gain |
math_qa__7WxWcw30Khludu7F | There are 6 working days in a regular week and for each day, the working hours are 10. A man earns Rs. 2.10 per hour for regular work and Rs. 4.20 per hour for overtime. If he earns Rs.525 in 4 weeks, how many hours did he work? Choose the correct choice from the following options: A) 225 B) 235 C) 215 D) 255 E) 245 | <gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">24 * 10</gadget>
<output>240</output>
<gadget id="calculator">240 * 2.1</gadget>
<output>504</output>
<gadget id="calculator">525 - 504</gadget>
<output>21</output>
<gadget id="calculator">21 / 4.2</gadget>
<output>5</output>
<gadget id="calculator">240 + 5</gadget>
<output>245</output>
<result>E</result> | E | 245 | There are 6 working days in a regular week and for each day, the working hours are 10. A man earns Rs. 2.10 per hour for regular work and Rs. 4.20 per hour for overtime. If he earns Rs.525 in 4 weeks, how many hours did he work? | {
"A": "225",
"B": "235",
"C": "215",
"D": "255",
"E": "245"
} | add(multiply(multiply(4, 6), 10), divide(subtract(525, multiply(multiply(multiply(4, 6), 10), 2.1)), 4.2)) | multiply(n0,n5)|multiply(n1,#0)|multiply(n2,#1)|subtract(n4,#2)|divide(#3,n3)|add(#4,#1) | egular working hours in 4 weeks = ( 4 × 6 × 10 ) = 240 hours amount earned by working in these regular working hours = 240 × 2.10 = rs . 504 additional amount he earned = 525 - 504 = rs . 21 hours he worked overtime = 21 / 4.2 = 210 / 42 = 5 hours total hours he worked = 240 + 5 = 245 hours answer is e . | physics |
math_qa__rpq68scKaqVzXL7w | If the price of gasoline increases by 25% and a driver intends to spend only 5% more on gasoline, by how much percent should the driver reduce the quantity of gasoline that he buys? Choose the correct answer:
A) 20 %
B) 16 %
C) 15 %
D) 12 %
E) 10 % | <gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">5 + 100</gadget>
<output>105</output>
<gadget id="calculator">125 - 105</gadget>
<output>20</output>
<gadget id="calculator">20 / 125</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 100</gadget>
<output>16</output>
<result>B</result> | B | 16 | If the price of gasoline increases by 25% and a driver intends to spend only 5% more on gasoline, by how much percent should the driver reduce the quantity of gasoline that he buys? | {
"A": "20 %",
"B": "16 %",
"C": "15 %",
"D": "12 %",
"E": "10 %"
} | multiply(divide(subtract(add(25, const_100), add(5, const_100)), add(25, const_100)), const_100) | add(n0,const_100)|add(n1,const_100)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100)| | "let x be the amount of gasoline the driver buys originally . let y be the new amount of gasoline the driver should buy . let p be the original price per liter . ( 1.25 * p ) y = 1.05 ( p * x ) y = ( 1.05 / 1.25 ) x = 0.84 x which is a reduction of 16 % . the answer is b ." | general |
math_qa__kExyMlDtejlEI2nM | The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 9 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each? Choose the correct choice from the following:
A) 4000 B) 345 C) 5673 D) 6530 E) 8154 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">15 + 25</gadget>
<output>40</output>
<gadget id="calculator">24 * 40</gadget>
<output>960</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">960 - 18</gadget>
<output>942</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">942 - 36</gadget>
<output>906</output>
<gadget id="calculator">906 * 9</gadget>
<output>8_154</output>
<result>E</result> | E | 8,154 | The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 9 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each? | {
"A": "4000",
"B": "345",
"C": "5673",
"D": "6530",
"E": "8154"
} | multiply(subtract(subtract(multiply(multiply(const_2, 12), add(15, 25)), multiply(6, 3)), multiply(3, multiply(4, 3))), 9) | add(n0,n1)|multiply(n2,const_2)|multiply(n4,n5)|multiply(n5,n6)|multiply(#0,#1)|multiply(n5,#3)|subtract(#4,#2)|subtract(#6,#5)|multiply(n3,#7)| | "area of the four walls = 2 h ( l + b ) since there are doors and windows , area of the walls = 2 * 12 ( 15 + 25 ) - ( 6 * 3 ) - 3 ( 4 * 3 ) = 906 sq . ft . total cost = 906 * 9 = rs . 8154 answer : option e" | geometry |
math_qa__SvsTY5ksCWRMKCD0 | There are 24 stations between Ernakulam and Chennai. How many second class tickets have to be printed, so that a passenger can travel from one station to any other station?
Choose the correct choice:
A) 800 B) 820 C) 650 D) 870 E) 900 | <gadget id="calculator">24 + 2</gadget>
<output>26</output>
<gadget id="calculator">26 - 1</gadget>
<output>25</output>
<gadget id="calculator">26 * 25</gadget>
<output>650</output>
<result>C</result> | C | 650 | There are 24 stations between Ernakulam and Chennai. How many second class tickets have to be printed, so that a passenger can travel from one station to any other station? | {
"A": "800",
"B": "820",
"C": "650",
"D": "870",
"E": "900"
} | multiply(add(24, const_2), subtract(add(24, const_2), const_1)) | add(n0,const_2)|subtract(#0,const_1)|multiply(#0,#1)| | "the total number of stations = 26 from 26 stations we have to choose any two stations and the direction of travel ( ernakulam to chennai is different from chennai to ernakulam ) in 26 p 2 ways . 26 p 2 = 26 * 25 = 650 answer : c" | physics |
math_qa__etdJidGXfUjBVnap | X does a work in 30 days. Y does the same work in 45 days. In how many days they together will do the same work? Choose the correct option.
A) 18 B) 12 C) 20 D) 30 E) 15 | <gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / 45</gadget>
<output>1/45 = around 0.022222</output>
<gadget id="calculator">(1/30) + (1/45)</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">1 / (1/18)</gadget>
<output>18</output>
<result>A</result> | A | 18 | X does a work in 30 days. Y does the same work in 45 days. In how many days they together will do the same work? | {
"A": "18",
"B": "12",
"C": "20",
"D": "30",
"E": "15"
} | inverse(add(divide(const_1, 30), divide(const_1, 45))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)| | "x ' s 1 day ' s work = 1 / 30 y ' s 1 day ' s work = 1 / 45 ( x + y ) ' s 1 day ' s work = ( 1 / 30 + 1 / 45 ) = 1 / 18 both together will finish the work in 18 days . correct option is a" | physics |
math_qa__Enh4niovhnGiohFh | How many pieces of 0.42 meteres can be cut from a rod 36.5 meteres long Select the correct option:
A) 30
B) 40
C) 86
D) 89
E) 95 | <gadget id="calculator">36.5 / 0.42</gadget>
<output>86.904762</output>
<result>C</result> | C | 86 | How many pieces of 0.42 meteres can be cut from a rod 36.5 meteres long | {
"A": "30",
"B": "40",
"C": "86",
"D": "89",
"E": "95"
} | divide(36.5, 0.42) | divide(n1,n0)| | "explanation : we need so simple divide 36.5 / 0.42 , = ( 3650 / 42 ) = 86 option c" | physics |
math_qa__GSQCvg7FZ3wsVmFv | If the cost price is 94% of sp then what is the profit % Answers.
A) 5.07 %
B) 6 %
C) 5.7 %
D) 6.50 %
E) 6.25 % | <gadget id="calculator">100 - 94</gadget>
<output>6</output>
<gadget id="calculator">6 / 94</gadget>
<output>3/47 = around 0.06383</output>
<gadget id="calculator">(3/47) * 100</gadget>
<output>300/47 = around 6.382979</output>
<result>E</result> | E | 6.25 | If the cost price is 94% of sp then what is the profit % | {
"A": "5.07 %",
"B": "6 %",
"C": "5.7 %",
"D": "6.50 %",
"E": "6.25 %"
} | multiply(divide(subtract(const_100, 94), 94), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "sol . sp = rs 100 : then cp = rs 94 : profit = rs 6 . profit = { ( 6 / 94 ) * 100 } % = 6.25 % answer is e ." | gain |
math_qa__J9rJoNPAMDWAUinl | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 5 feet and a height of 10 feet, how far did the oil level drop in the stationary tank?
Select: A) 2.5 ft B) 1 ft C) 0.5 ft D) 0.25 ft E) 0.025 ft | <gadget id="calculator">pi * (5 ** 2) * 10</gadget>
<output>250*pi = around 785.398163</output>
<gadget id="calculator">pi * (100 ** 2)</gadget>
<output>10000*pi = around 31_415.926536</output>
<gadget id="calculator">(250*pi) / (10000*pi)</gadget>
<output>1/40 = around 0.025</output>
<result>E</result> | E | 0.025 | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 5 feet and a height of 10 feet, how far did the oil level drop in the stationary tank? | {
"A": "2.5 ft",
"B": "1 ft",
"C": "0.5 ft",
"D": "0.25 ft",
"E": "0.025 ft"
} | divide(volume_cylinder(5, 10), circle_area(100)) | circle_area(n0)|volume_cylinder(n2,n3)|divide(#1,#0) | in order to fill up the tank , same volume is shifted from one tank to the other . pi r 1 ^ 2 h 1 = pi r 2 ^ 2 h 2 5 * 5 * 10 = 100 * 100 * h 2 h 2 = . 025 ft e is the answer | geometry |
math_qa__ylOHk1ficv2APEQB | A person saved $10 in buying an item on sale. If he spent $100 for the item, approximately how much percent he saved in the transaction? Pick one
A) 8 % B) 10 % C) 2 % D) 5 % E) 6 % | <gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">10 / 110</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/11) * 100</gadget>
<output>100/11 = around 9.090909</output>
<gadget id="calculator">floor(100/11)</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<result>B</result> | B | 10 | A person saved $10 in buying an item on sale. If he spent $100 for the item, approximately how much percent he saved in the transaction? | {
"A": "8 %",
"B": "10 %",
"C": "2 %",
"D": "5 %",
"E": "6 %"
} | add(floor(multiply(divide(10, add(10, 100)), const_100)), const_1) | add(n0,n1)|divide(n0,#0)|multiply(#1,const_100)|floor(#2)|add(#3,const_1) | actual price = 100 + 10 = $ 110 saving = 10 / 110 * 100 = 100 / 11 = 10 % approximately answer is b | general |
math_qa__NWCocE53CZFqdJop | Two family reunions are happening at the same hotel, the Oates reunion and the Yellow reunion. All 100 guests at the hotel attend at least one of the reunions. If 42 people attend the Oates reunion and 65 people attend the Yellow reunion, how many people attend both reunions? Choose the most appropriate option:
A) 2 B) 7 C) 10 D) 16 E) 22 | <gadget id="calculator">42 + 65</gadget>
<output>107</output>
<gadget id="calculator">107 - 100</gadget>
<output>7</output>
<result>B</result> | B | 7 | Two family reunions are happening at the same hotel, the Oates reunion and the Yellow reunion. All 100 guests at the hotel attend at least one of the reunions. If 42 people attend the Oates reunion and 65 people attend the Yellow reunion, how many people attend both reunions? | {
"A": "2",
"B": "7",
"C": "10",
"D": "16",
"E": "22"
} | subtract(add(42, 65), 100) | add(n1,n2)|subtract(#0,n0) | no of people in oates reunion = 42 no of people in yellow reunion = 65 attending both = x all guests attend at least one . therefore , 100 = 42 + 65 - ( both ) both = 7 answer b | other |
math_qa__xu6ZSLHFZwRcjQUC | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? Choose the correct choice from the following:
A) 140 B) 146 C) 152 D) 162 E) 170 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">200 * (9/10)</gadget>
<output>180</output>
<gadget id="calculator">180 * (9/10)</gadget>
<output>162</output>
<gadget id="calculator">162 * (9/10)</gadget>
<output>729/5 = around 145.8</output>
<result>B</result> | B | 146 | In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? | {
"A": "140",
"B": "146",
"C": "152",
"D": "162",
"E": "170"
} | multiply(multiply(multiply(200, subtract(1, divide(1, 10))), subtract(1, divide(1, 10))), subtract(1, divide(1, 10))) | divide(n1,n2)|subtract(n1,#0)|multiply(n3,#1)|multiply(#2,#1)|multiply(#3,#1)| | "number of newborns that can die in first month = 1 / 10 * 200 = 20 survived = 180 number of newborns that can die in second month = 1 / 10 * 180 = 18 survived = 162 number of newborns that can die in third month = 1 / 10 * 162 = 16 survived = 146 answer : b" | probability |
math_qa__HsbjeyZlluT2kpXU | The surface of a cube is 150sq cm. Find its volume?
Answers: A) 8 cc B) 9 cc C) 125 cc D) 4 cc E) 6 cc | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">150 / 6</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<result>C</result> | C | 125 | The surface of a cube is 150sq cm. Find its volume? | {
"A": "8 cc",
"B": "9 cc",
"C": "125 cc",
"D": "4 cc",
"E": "6 cc"
} | volume_cube(sqrt(divide(150, add(const_2, const_4)))) | add(const_2,const_4)|divide(n0,#0)|sqrt(#1)|volume_cube(#2)| | "6 a 2 = 150 = 6 * 25 a = 5 = > a 3 = 125 cc answer : c" | geometry |
math_qa__79Ao27omNh6BaZrD | A diagonal of a polygon is an segment between two non-adjacent vertices of the polygon. How many diagonals does a regular 40-sided polygon have? Choose the correct answer: A) 875 B) 740 C) 1425 D) 2025 E) 2500 | <gadget id="calculator">40 - 3</gadget>
<output>37</output>
<gadget id="calculator">37 * 40</gadget>
<output>1_480</output>
<gadget id="calculator">1_480 / 2</gadget>
<output>740</output>
<result>B</result> | B | 740 | A diagonal of a polygon is an segment between two non-adjacent vertices of the polygon. How many diagonals does a regular 40-sided polygon have? | {
"A": "875",
"B": "740",
"C": "1425",
"D": "2025",
"E": "2500"
} | divide(multiply(subtract(40, const_3), 40), const_2) | subtract(n0,const_3)|multiply(n0,#0)|divide(#1,const_2)| | "there ' s a direct formula for this . number of diagonals in a regular polygon = [ n * ( n - 3 ) ] / 2 , n = number of sides of the regular polygon . here , n = 40 . plugging it in , we get 740 diagonals ! answer ( b ) ." | geometry |
math_qa__WBoGhpFmPIOnn6SZ | In covering a distance of 24 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is: Options: A) 4 kmph B) 6 kmph C) 6.25 kmph D) 7.5 kmph E) 7.8 kmph | <gadget id="calculator">24 / 2</gadget>
<output>12</output>
<gadget id="calculator">24 - 12</gadget>
<output>12</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>A</result> | A | 4 | In covering a distance of 24 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is: | {
"A": "4 kmph",
"B": "6 kmph",
"C": "6.25 kmph",
"D": "7.5 kmph",
"E": "7.8 kmph"
} | divide(subtract(24, divide(24, 2)), add(1, 2)) | add(n1,n2)|divide(n0,n1)|subtract(n0,#1)|divide(#2,#0)| | "let abhay ' s speed be x km / hr . then , 24 / x - 24 / 2 x = 3 6 x = 24 x = 4 km / hr . answer : option a" | physics |
math_qa__NKlBvFOkPEGFlPO1 | 20 workers can finish a work in 30 days. After how many days should 5 workers leave the job so the work is completed in 35 days? Choose the correct answer:
A) 7 B) 6 C) 15 D) 4 E) 3 | <gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 35</gadget>
<output>525</output>
<gadget id="calculator">600 - 525</gadget>
<output>75</output>
<gadget id="calculator">75 / 5</gadget>
<output>15</output>
<result>C</result> | C | 15 | 20 workers can finish a work in 30 days. After how many days should 5 workers leave the job so the work is completed in 35 days? | {
"A": "7",
"B": "6",
"C": "15",
"D": "4",
"E": "3"
} | divide(subtract(multiply(20, 30), multiply(subtract(20, 5), 35)), 5) | multiply(n0,n1)|subtract(n0,n2)|multiply(n3,#1)|subtract(#0,#2)|divide(#3,n2) | work done by 15 workers in 35 days = 15 * 35 = 525 men days . now , work remaining = 600 – 525 = 75 men days and we have 5 workers . so 5 workers will work for 75 / 5 = 15 days . answer : c | physics |
math_qa__iYIvC4SeloV2sLcO | A glass was filled with 10 ounces of water, and 0.02 ounce of the water evaporated each day during a 30-day period. What percent of the original amount of water evaporated during this period? Options: A) 0.006 % B) 0.06 % C) 6 % D) 2 % E) 60 % | <gadget id="calculator">0.02 * 30</gadget>
<output>0.6</output>
<gadget id="calculator">0.6 / 10</gadget>
<output>0.06</output>
<gadget id="calculator">0.06 * 100</gadget>
<output>6</output>
<result>C</result> | C | 6 | A glass was filled with 10 ounces of water, and 0.02 ounce of the water evaporated each day during a 30-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.006 %",
"B": "0.06 %",
"C": "6 %",
"D": "2 %",
"E": "60 %"
} | multiply(divide(multiply(0.02, 30), 10), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "in 30 days 30 * 0.02 = 0.6 ounces of water evaporated , which is 0.6 / 10 â ˆ — 100 = 6 of the original amount of water . answer : c ." | gain |
math_qa__8SBYkK8SNKjugpvO | roy is now 8 years older than julia and half of that amount older than kelly . if in 2 years , roy will be 3 times as old as julia , then in 2 years what would be roy ’ s age multiplied by kelly ’ s age ? Choose the most appropriate option.
A) 72 B) 84 C) 88 D) 96 E) 108 | <gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">2 + 10</gadget>
<output>12</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">12 * 8</gadget>
<output>96</output>
<result>D</result> | D | 96 | roy is now 8 years older than julia and half of that amount older than kelly . if in 2 years , roy will be 3 times as old as julia , then in 2 years what would be roy ’ s age multiplied by kelly ’ s age ? | {
"A": "72",
"B": "84",
"C": "88",
"D": "96",
"E": "108"
} | multiply(add(divide(subtract(add(8, 2), multiply(3, 2)), subtract(3, const_1)), add(8, 2)), subtract(add(divide(subtract(add(8, 2), multiply(3, 2)), subtract(3, const_1)), add(8, 2)), divide(8, const_2))) | add(n0,n1)|divide(n0,const_2)|multiply(n1,n2)|subtract(n2,const_1)|subtract(#0,#2)|divide(#4,#3)|add(#0,#5)|subtract(#6,#1)|multiply(#6,#7) | r = j + 8 = k + 4 r + 2 = 3 ( j + 2 ) ( j + 8 ) + 2 = 3 j + 6 j = 2 r = 10 k = 6 in 2 years ( r + 2 ) ( k + 2 ) = 12 * 8 = 96 the answer is d . | general |
math_qa__QYVEDCo9ldP4Xy7r | A mixture of 120 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture? Select: A) 2 liters B) 3 liters C) 8 liters D) 5 liters E) 7 liters | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 120</gadget>
<output>30</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 120</gadget>
<output>24</output>
<gadget id="calculator">30 - 24</gadget>
<output>6</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">6 / (3/4)</gadget>
<output>8</output>
<result>C</result> | C | 8 | A mixture of 120 liters of wine and water contains 20% water. How much more water should be added so that water becomes 25% of the new mixture? | {
"A": "2 liters",
"B": "3 liters",
"C": "8 liters",
"D": "5 liters",
"E": "7 liters"
} | divide(subtract(multiply(divide(25, const_100), 120), multiply(divide(20, const_100), 120)), subtract(const_1, divide(25, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(const_1,#0)|subtract(#2,#3)|divide(#5,#4) | number of liters of water in 120 liters of the mixture = 20 % of 120 = 20 / 100 * 120 = 24 liters . p liters of water added to the mixture to make water 25 % of the new mixture . total amount of water becomes ( 24 + p ) and total volume of mixture is ( 120 + p ) . ( 24 + p ) = 25 / 100 * ( 120 + p ) 96 + 4 p = 120 + p p = 8 liters . answer : c | general |
math_qa__tLUfAecDVITn7H0s | 5 friends visited a fruit stall, and everyone decided to contribute equally to the total bill of $100. If one of the friends had a coupon for 6% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay? Choose the correct choice from the following answers.
A) 18 B) 18.8 C) 19 D) 17.8 E) 17.9 | <gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">100 - 6</gadget>
<output>94</output>
<gadget id="calculator">94 / 5</gadget>
<output>94/5 = around 18.8</output>
<result>B</result> | B | 18.8 | 5 friends visited a fruit stall, and everyone decided to contribute equally to the total bill of $100. If one of the friends had a coupon for 6% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay? | {
"A": "18",
"B": "18.8",
"C": "19",
"D": "17.8",
"E": "17.9"
} | divide(subtract(100, divide(multiply(6, 100), const_100)), 5) | multiply(n1,n2)|divide(#0,const_100)|subtract(n1,#1)|divide(#2,n0) | at the non - discounted price , each friend would pay $ 20 , as $ 100 divided by 5 friends is $ 20 per friend . but if the bill is 6 % off , then each friend would pay 6 % less . 6 % of $ 20 is $ 1.2 , so each friend saves $ 1.2 and pays the remaining 18.8 correct option : option b | general |
math_qa__oLEpIJjSFEceBANY | A certain country is divided into 5 provinces. Each province consists entirely of Progressives and Traditionalists. If each province contains the same number of Traditionalists and the number of Traditionalists in any given province is 1/15 the total number of Progressives in the entire country, what fraction of the country is Traditionalist? Choose the correct option
A) 1 / 5
B) 1 / 3
C) 1 / 2
D) 2 / 3
E) 3 / 4 | <gadget id="calculator">5 / 15</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + 1</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(1/3) / (4/3)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<result>E</result> | E | 0.75 | A certain country is divided into 5 provinces. Each province consists entirely of Progressives and Traditionalists. If each province contains the same number of Traditionalists and the number of Traditionalists in any given province is 1/15 the total number of Progressives in the entire country, what fraction of the country is Traditionalist? | {
"A": "1 / 5",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "3 / 4"
} | subtract(1, divide(divide(5, 15), add(divide(5, 15), 1))) | divide(n0,n2)|add(n1,#0)|divide(#0,#1)|subtract(n1,#2)| | "let p be the number of progressives in the country as a whole . in each province , the number of traditionalists is p / 15 the total number of traditionalists is 5 p / 15 = p / 3 . the total population is p + p / 3 = 4 p / 3 p / ( 4 p / 3 ) = 3 / 4 the answer is e ." | general |
math_qa__U2gksBytvjaORYws | An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.22050/- in 3 years at the same rate of interest. Find the rate percentage? Select the correct option:
A) 5 %
B) 7 %
C) 9 %
D) 11 %
E) 25 % | <gadget id="calculator">22_050 - 17_640</gadget>
<output>4_410</output>
<gadget id="calculator">4_410 / 17_640</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>E</result> | E | 25 | An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.22050/- in 3 years at the same rate of interest. Find the rate percentage? | {
"A": "5 %",
"B": "7 %",
"C": "9 %",
"D": "11 %",
"E": "25 %"
} | multiply(divide(subtract(22050, 17640), 17640), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : the difference of two successive amounts must be the simple interest in 1 year on the lower amount of money . s . i = 22050 / - - 17640 / - = rs . 4410 / - rate of interest = ( 4410 / 17640 ) × ( 100 / 1 ) = > 25 % answer : option e" | general |
math_qa__Cx69HnF27uQ2FBGi | Which number can we add to 859722 to get a number exactly divisible by 456? Choose the correct choice
A) 294 B) 306 C) 318 D) 338 E) 362 | <gadget id="calculator">859_722 % 456</gadget>
<output>162</output>
<gadget id="calculator">456 - 162</gadget>
<output>294</output>
<result>A</result> | A | 294 | Which number can we add to 859722 to get a number exactly divisible by 456? | {
"A": "294",
"B": "306",
"C": "318",
"D": "338",
"E": "362"
} | subtract(456, reminder(859722, 456)) | reminder(n0,n1)|subtract(n1,#0)| | "859722 / 456 = 1885 with a remainder of 162 . we need to add 456 - 162 = 294 the answer is a ." | general |
math_qa__JLmd5LK0piVMp5Ys | Walking with 4/5 of my usual speed, I miss the bus by 3 minutes. What is my usual time? Select.
A) 16 min B) 26 min C) 34 min D) 20 min E) 12 min | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">3 / (5/4)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 5</gadget>
<output>12</output>
<result>E</result> | E | 12 | Walking with 4/5 of my usual speed, I miss the bus by 3 minutes. What is my usual time? | {
"A": "16 min",
"B": "26 min",
"C": "34 min",
"D": "20 min",
"E": "12 min"
} | multiply(divide(3, divide(5, 4)), 5) | divide(n1,n0)|divide(n2,#0)|multiply(n1,#1) | speed ratio = 1 : 4 / 5 = 5 : 4 time ratio = 4 : 51 - - - - - - - - 3 4 - - - - - - - - - ? è 12 answer : e | physics |
math_qa__YZFz3AwOu73VZ3lP | In the Hillside summer camp there are 100 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen?
Select the correct option:
A) 150 . B) 145 . C) 100 . D) 30 . E) 25 . | <gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) * 100</gadget>
<output>95</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<gadget id="calculator">95 + 5</gadget>
<output>100</output>
<result>C</result> | C | 100 | In the Hillside summer camp there are 100 children. 90% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen? | {
"A": "150 .",
"B": "145 .",
"C": "100 .",
"D": "30 .",
"E": "25 ."
} | add(multiply(divide(subtract(const_100, 5), const_100), 100), multiply(divide(5, const_100), 100)) | divide(n2,const_100)|subtract(const_100,n2)|divide(#1,const_100)|multiply(n0,#0)|multiply(n0,#2)|add(#4,#3)| | "given there are 100 students , 90 % of 50 = 90 boys and remaining 10 girls . now here 90 % are boys and 10 % are girls . now question is asking about how many boys do we need to add , to make the girls percentage to 5 or 5 % . . if we add 1000 to existing 90 then the count will be 190 and the girls number will be 10 as it . now boys are 95 % and girls are 5 % . ( out of 200 students = 190 boys + 10 girls ) . imo option c is correct ." | general |
math_qa__p93uQnprVDUxEB86 | 10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is ? Answers
A) 1 B) 7 C) 3 D) 9 E) 2 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">24 * 6</gadget>
<output>144</output>
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">96 + 40</gadget>
<output>136</output>
<gadget id="calculator">144 - 136</gadget>
<output>8</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>C</result> | C | 3 | 10 years ago, the average age of a family of 4 members was 24 years. Two children having been born (with age diference of 2 years), the present average age of the family is the same. The present age of the youngest child is ? | {
"A": "1",
"B": "7",
"C": "3",
"D": "9",
"E": "2"
} | divide(subtract(subtract(multiply(24, add(4, 2)), add(multiply(24, 4), multiply(10, 4))), 2), const_2) | add(n1,n3)|multiply(n1,n2)|multiply(n0,n1)|add(#1,#2)|multiply(n2,#0)|subtract(#4,#3)|subtract(#5,n3)|divide(#6,const_2) | total age of 4 members , 10 years ago = ( 24 x 4 ) years = 96 years . total age of 4 members now = [ 96 + ( 10 x 4 ) ] years = 136 years . total age of 6 members now = ( 24 x 6 ) years = 144 years . sum of the ages of 2 children = ( 144 - 136 ) years = 8 years . let the age of the younger child be years . then , age of the elder child = years . so , age of younger child = 3 years . answer : c | general |
math_qa__m9uGYkEKNuACsvHs | A certain quantity of 70% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced?
Options:
A) 1 / 4 B) 1 / 3 C) 1 / 2 D) 2 / 3 E) 7 / 9 | <gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">70 - 35</gadget>
<output>35</output>
<gadget id="calculator">10 / 35</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(2/7) + 1</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">1 / (9/7)</gadget>
<output>7/9 = around 0.777778</output>
<result>E</result> | E | 0.777778 | A certain quantity of 70% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced? | {
"A": "1 / 4",
"B": "1 / 3",
"C": "1 / 2",
"D": "2 / 3",
"E": "7 / 9"
} | inverse(add(divide(subtract(35, 25), subtract(70, 35)), const_1)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)|add(#2,const_1)|inverse(#3) | let ' s say that the total original mixture a is 100 ml the original mixture a thus has 70 ml of alcohol out of 100 ml of solution you want to replace some of that original mixture a with another mixture b that contains 25 ml of alcohol per 100 ml . thus , the difference between 70 ml and 25 ml is 45 ml per 100 ml of mixture . this means that every time you replace 100 ml of the original mixture a by 100 ml of mixture b , the original alcohol concentration will decrease by 45 % . the question says that the new mixture , let ' s call it c , must be 35 % alcohol , a decrease of only 35 % . therefore , 35 out of 45 is 7 / 9 and e is the answer . | other |
math_qa__24wcoFVk5gldNfa8 | f1(x)f1(x) = 2x - 1 and fn(x)=f1(fn−1(x))fn(x)=f1(fn−1(x)) for n ≥≥ 2. Find f5(2)
Choices.
A) 7 B) 6 C) 78 D) 9 E) 1 | <gadget id="calculator">2 + 5</gadget>
<output>7</output>
<result>A</result> | A | 7 | f1(x)f1(x) = 2x - 1 and fn(x)=f1(fn−1(x))fn(x)=f1(fn−1(x)) for n ≥≥ 2. Find f5(2) | {
"A": "7",
"B": "6",
"C": "78",
"D": "9",
"E": "1"
} | add(2, 5) | add(n2,n9) | answer : a | general |
math_qa__TJ9OI8dfD5BH7iu7 | Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 22 boys and 38 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?
Choose the correct choice from the following options.
A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">22 - 6</gadget>
<output>16</output>
<gadget id="calculator">16 - 6</gadget>
<output>10</output>
<result>E</result> | E | 10 | Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 22 boys and 38 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | subtract(subtract(22, subtract(10, 4)), 6) | subtract(n2,n7)|subtract(n4,#0)|subtract(#1,n6)| | "venn diagrams are useful for multiple values of a single variable e . g . state of mind - happy / sad / neither . when you have two or more variables such as here where you have gender - boy / girl too , it becomes unwieldy . in this case , either use the table or logic . table method is shown above ; here is how you will use logic : there are 6 happy boys . there are 4 sad girls but total 10 sad children . so rest 6 sad children must be sad boys . we have 6 happy boys and 6 sad boys . total we have 22 boys . so 22 - 6 - 6 = 10 boys must be neither happy nor sad . answer ( e )" | other |
math_qa__YWIwdHaQk0ZREtoc | Find the distance covered by a man walking for 42 min at a speed of 10km/hr? Choose the most appropriate option:
A) 7 km B) 3 km C) 4 km D) 5 km E) 6 km | <gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 60</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">42 * (500/3)</gadget>
<output>7_000</output>
<gadget id="calculator">7_000 / 1_000</gadget>
<output>7</output>
<result>A</result> | A | 7 | Find the distance covered by a man walking for 42 min at a speed of 10km/hr? | {
"A": "7 km",
"B": "3 km",
"C": "4 km",
"D": "5 km",
"E": "6 km"
} | divide(multiply(42, divide(multiply(10, const_1000), const_60)), const_1000) | multiply(n1,const_1000)|divide(#0,const_60)|multiply(n0,#1)|divide(#2,const_1000)| | "distance = 10 * 42 / 60 = 7 km answer is a" | physics |
math_qa__xDmMsc2oTvU5UTdc | The output of a factory was increased by 15% to keep up with rising demand. To handle the holiday rush, this new output was increased by 20%. By approximately what percent would the output now have to be decreased in order to restore the original output? Pick one: A) 20 % B) 27 % C) 30 % D) 32 % E) 79 % | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">115 * (1/5)</gadget>
<output>23</output>
<gadget id="calculator">115 + 23</gadget>
<output>138</output>
<gadget id="calculator">138 - 100</gadget>
<output>38</output>
<gadget id="calculator">38 * 100</gadget>
<output>3_800</output>
<gadget id="calculator">3_800 / 138</gadget>
<output>1_900/69 = around 27.536232</output>
<result>B</result> | B | 27 | The output of a factory was increased by 15% to keep up with rising demand. To handle the holiday rush, this new output was increased by 20%. By approximately what percent would the output now have to be decreased in order to restore the original output? | {
"A": "20 %",
"B": "27 %",
"C": "30 %",
"D": "32 %",
"E": "79 %"
} | divide(multiply(subtract(add(add(const_100, 15), multiply(add(const_100, 15), divide(20, const_100))), const_100), const_100), add(add(const_100, 15), multiply(add(const_100, 15), divide(20, const_100)))) | add(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|add(#0,#2)|subtract(#3,const_100)|multiply(#4,const_100)|divide(#5,#3) | the original output increases by 15 % and then 20 % . total % change = a + b + ab / 100 total % change = 15 + 20 + 15 * 20 / 100 = 38 % now , you want to change it to 0 , so , 0 = 38 + x + 38 x / 100 x = - 38 ( 100 ) / 138 = 27 % approximately answer is b | general |
math_qa__UI8XG7TRrq22MJ9x | In a sample of associates at a law firm, 30 percent are second-year associates, and 60 percent are not first-year associates. What percentage of the associates at the law firm have been there for more than two years? Choose the correct option: A) 10 B) 20 C) 30 % D) 40 E) 50 | <gadget id="calculator">60 - 30</gadget>
<output>30</output>
<result>C</result> | C | 30 | In a sample of associates at a law firm, 30 percent are second-year associates, and 60 percent are not first-year associates. What percentage of the associates at the law firm have been there for more than two years? | {
"A": "10",
"B": "20",
"C": "30 %",
"D": "40",
"E": "50"
} | subtract(60, 30) | subtract(n1,n0) | let the sample be 100 . given 60 % are not first year i . e . there could be second year ( x ) and more than 2 years ( y ) possibility . 60 % = ( x ) + y given 30 % = second year ( x ) club both , we get y = 30 % . answer : option c is correct answer . | general |
math_qa__94HsBGaOmZAeKfBM | In a company of 160 employees, 90 are females. A total of 80 employees have advanced degrees and the rest have a college degree only. If 40 employees are males with college degree only, how many employees are females with advanced degrees? Choose the correct choice.
A) 40 B) 45 C) 50 D) 55 E) 60 | <gadget id="calculator">160 - 90</gadget>
<output>70</output>
<gadget id="calculator">70 - 40</gadget>
<output>30</output>
<gadget id="calculator">80 - 30</gadget>
<output>50</output>
<result>C</result> | C | 50 | In a company of 160 employees, 90 are females. A total of 80 employees have advanced degrees and the rest have a college degree only. If 40 employees are males with college degree only, how many employees are females with advanced degrees? | {
"A": "40",
"B": "45",
"C": "50",
"D": "55",
"E": "60"
} | subtract(80, subtract(subtract(160, 90), 40)) | subtract(n0,n1)|subtract(#0,n3)|subtract(n2,#1)| | "the number of males is 160 - 90 = 70 . the number of males with advanced degrees is 70 - 40 = 30 . the number of females with advanced degrees is 80 - 30 = 50 . the answer is c ." | geometry |
math_qa__8asLW5UoKegXJ8Ut | The average (arithmetic mean) of 20, 40, and 60 is 5 more than the average of 10, 50, and what number? Select the correct option: A) 40 B) 45 C) 55 D) 45 E) 50 | <gadget id="calculator">20 + 40</gadget>
<output>60</output>
<gadget id="calculator">60 + 60</gadget>
<output>120</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 50</gadget>
<output>75</output>
<gadget id="calculator">120 - 75</gadget>
<output>45</output>
<result>D</result> | D | 45 | The average (arithmetic mean) of 20, 40, and 60 is 5 more than the average of 10, 50, and what number? | {
"A": "40",
"B": "45",
"C": "55",
"D": "45",
"E": "50"
} | subtract(add(add(20, 40), 60), add(add(multiply(5, const_3), 10), 50)) | add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4)| | "a 1 = 120 / 3 = 40 a 2 = a 1 - 5 = 35 sum of second list = 35 * 3 = 105 therefore the number = 105 - 60 = 45 d" | general |
math_qa__ycVFzBjRoZRDIk7q | An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 49 times the difference between the two numbers. How many coins did the old man have? Select: A) 24 B) 26 C) 30 D) 49 E) 40 | <gadget id="calculator">floor(49)</gadget>
<output>49</output>
<result>D</result> | D | 49 | An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 49 times the difference between the two numbers. How many coins did the old man have? | {
"A": "24",
"B": "26",
"C": "30",
"D": "49",
"E": "40"
} | floor(49) | floor(n0)| | "let the number of coins one son got be x and the number of coins another got be y . total = x + y . x ^ 2 - y ^ 2 = 49 ( x - y ) - - > x + y = 49 . answer : d ." | general |
math_qa__fe3QvewhBWfNMzNL | How many times will the digit 4 be written when listing the integers from 1 to 1000? Choose the correct answer:
A) 512 B) 300 C) 294 D) 264 E) 385 | <gadget id="calculator">1 * 10</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<result>B</result> | B | 300 | How many times will the digit 4 be written when listing the integers from 1 to 1000? | {
"A": "512",
"B": "300",
"C": "294",
"D": "264",
"E": "385"
} | multiply(multiply(multiply(1, const_10), const_10), const_3) | multiply(n1,const_10)|multiply(#0,const_10)|multiply(#1,const_3)| | "many approaches are possible . for example : consider numbers from 0 to 999 written as follows : 1 . 000 2 . 001 3 . 002 4 . 003 . . . . . . . . . 1000 . 999 we have 1000 numbers . we used 3 digits per number , hence used total of 3 * 1000 = 3000 digits . now , why should any digit have preferences over another ? we used each of 10 digits equal # of times , thus we used each digit ( including 4 ) 3000 / 10 = 300 times . answer : b ." | general |
math_qa__5jOpOSBex9bQUw7i | Jonathan can type a 20 page document in 50 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document? Choose the correct choice from the following answers:
A) 5 minutes B) 11 minutes C) 15 minutes D) 18 minutes E) 20 minutes | <gadget id="calculator">20 / 24</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">20 / 50</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">20 / 30</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/5) + (2/3)</gadget>
<output>16/15 = around 1.066667</output>
<gadget id="calculator">(5/6) + (16/15)</gadget>
<output>19/10 = around 1.9</output>
<gadget id="calculator">20 / (19/10)</gadget>
<output>200/19 = around 10.526316</output>
<result>B</result> | B | 11 | Jonathan can type a 20 page document in 50 minutes, Susan can type it in 30 minutes, and Jack can type it in 24 minutes. Working together, how much time will it take them to type the same document? | {
"A": "5 minutes",
"B": "11 minutes",
"C": "15 minutes",
"D": "18 minutes",
"E": "20 minutes"
} | divide(20, add(divide(20, 24), add(divide(20, 50), divide(20, 30)))) | divide(n0,n1)|divide(n0,n2)|divide(n0,n3)|add(#0,#1)|add(#3,#2)|divide(n0,#4) | you may set up common equation like this : job / a + job / b + job / c = job / x memorize this universal formula , you will need it definitely for gmat . and find x from this equation in this specific case , the equation will look like this : 20 / 50 + 20 / 30 + 20 / 24 = 20 / x if you solve this equation , you get the same answer b ( 11 ) | physics |
math_qa__FMQ7Vv6sovlzNxs7 | In a certain village, 150 litres of water are required per household per month. At this rate, if there are 10 households in the village, how long (in months) will 6000 litres of water last? Select.
A) 8
B) 10
C) 6
D) 2
E) 4 | <gadget id="calculator">150 * 10</gadget>
<output>1_500</output>
<gadget id="calculator">6_000 / 1_500</gadget>
<output>4</output>
<result>E</result> | E | 4 | In a certain village, 150 litres of water are required per household per month. At this rate, if there are 10 households in the village, how long (in months) will 6000 litres of water last? | {
"A": "8",
"B": "10",
"C": "6",
"D": "2",
"E": "4"
} | divide(6000, multiply(150, 10)) | multiply(n0,n1)|divide(n2,#0)| | "i find it much easier to understand with real numbers , so choose ( almost ) any numbers to replace m , n and p : in a certain village , m 150 litres of water are required per household per month . at this rate , if there aren 10 households in the village , how long ( in months ) willp 2000 litres of water last ? water required is 150 * 10 = 1500 ( m * n ) water available is 6000 ( p ) it will last 4 months ( p / m * n ) ans : e" | gain |
math_qa__avMfs98nYSHX7f2X | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 24 more photos than Claire. How many photos has Claire taken? Choose one.
A) 6 B) 8 C) 10 D) 12 E) 14 | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>D</result> | D | 12 | Lisa and Robert have taken the same number of photos on their school trip. Lisa has taken 3 times as many photos as Claire and Robert has taken 24 more photos than Claire. How many photos has Claire taken? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | divide(24, subtract(3, const_1)) | subtract(n0,const_1)|divide(n1,#0) | l = r l = 3 c r = c + 24 3 c = c + 24 c = 12 the answer is d . | general |
math_qa__hstBdX3aK2c8xq7J | 42 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
Choose one: A) 10 B) 16 C) 13 D) 14 E) 19 | <gadget id="calculator">42 * 12</gadget>
<output>504</output>
<gadget id="calculator">504 * 5</gadget>
<output>2_520</output>
<gadget id="calculator">30 * 6</gadget>
<output>180</output>
<gadget id="calculator">2_520 / 180</gadget>
<output>14</output>
<result>D</result> | D | 14 | 42 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work? | {
"A": "10",
"B": "16",
"C": "13",
"D": "14",
"E": "19"
} | divide(multiply(multiply(42, 12), 5), multiply(30, 6)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1)| | "let the required number of days be x . less persons , more days ( indirect proportion ) more working hours per day , less days ( indirect proportion ) persons 30 : 42 : : 12 : x working hours / day 6 : 5 30 x 6 x x = 42 x 5 x 12 x = ( 42 x 5 x 12 ) / ( 30 x 6 ) x = 14 answer d" | physics |
math_qa__r4vH7T5tNIUakO0Z | For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 30 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated? Choose one:
A) 27 % B) 26 % C) 29 % D) 30 % E) 60 % | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 300</gadget>
<output>75</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 200</gadget>
<output>60</output>
<gadget id="calculator">75 + 60</gadget>
<output>135</output>
<gadget id="calculator">300 + 200</gadget>
<output>500</output>
<gadget id="calculator">135 / 500</gadget>
<output>27/100 = around 0.27</output>
<gadget id="calculator">(27/100) * 100</gadget>
<output>27</output>
<result>A</result> | A | 27 | For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 30 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated? | {
"A": "27 %",
"B": "26 %",
"C": "29 %",
"D": "30 %",
"E": "60 %"
} | multiply(divide(add(multiply(divide(25, const_100), 300), multiply(divide(30, const_100), 200)), add(300, 200)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100)| | "in the first plot 25 % of 300 seeds germinated , so 0.25 x 300 = 75 seeds germinated . in the second plot , 30 % of 200 seeds germinated , so 0.30 x 200 = 60 seeds germinated . since 75 + 60 = 135 seeds germinated out of a total of 300 + 200 = 500 seeds , the percent of seeds that germinated is ( 135 / 500 ) x 100 % , or 27 % . answer : a ." | general |
math_qa__8mNrUbCw2nv5mDMm | if x:y = 1:4, then find the value of
(7x+3y):(2x+y)
Choose the correct choice from the following choices: A) 14 : 5 B) 15 : 5 C) 16 : 5 D) 19 : 6 E) none of these | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 7</gadget>
<output>19</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">19 / 6</gadget>
<output>19/6 = around 3.166667</output>
<result>D</result> | D | 3.166667 | if x:y = 1:4, then find the value of
(7x+3y):(2x+y) | {
"A": "14 : 5",
"B": "15 : 5",
"C": "16 : 5",
"D": "19 : 6",
"E": "none of these"
} | divide(add(multiply(3, 4), 7), add(2, 4)) | add(n1,n4)|multiply(n1,n3)|add(n2,#1)|divide(#2,#0) | explanation : let x = 1 k and y = 4 k , so = 7 ( k ) + 3 ( 4 k ) / 2 ( k ) + 1 ( 4 k ) = 19 k / 6 k = 19 : 6 option d | general |
math_qa__UgYZ4FYSIq627gL8 | John want to buy a $100 Trouser at the store, but he think it’s too expensive. Finally, it goes on sale for $55. What is the percent decrease? Choose the correct option:
A) 20 % B) 30 % C) 40 % D) 50 % E) 45 % | <gadget id="calculator">100 - 55</gadget>
<output>45</output>
<result>E</result> | E | 45 | John want to buy a $100 Trouser at the store, but he think it’s too expensive. Finally, it goes on sale for $55. What is the percent decrease? | {
"A": "20 %",
"B": "30 %",
"C": "40 %",
"D": "50 %",
"E": "45 %"
} | subtract(100, 55) | subtract(n0,n1)| | "the is always the difference between our starting and ending points . in this case , it â € ™ s 100 â € “ 55 = 45 . the â € œ original â € is our starting point ; in this case , it â € ™ s 100 . ( 45 / 100 ) * 100 = ( 0.45 ) * 100 = 45 % . e" | general |
math_qa__iEsP3nmqs9rBskOP | In a garden, 26 trees are planted at equal distances along a yard 800 metres long, one tree being at each end of the yard. What is the distance between two consecutive trees? Choose the correct option
A) 10 B) 8 C) 32 D) 14 E) 16 | <gadget id="calculator">26 - 1</gadget>
<output>25</output>
<gadget id="calculator">800 / 25</gadget>
<output>32</output>
<result>C</result> | C | 32 | In a garden, 26 trees are planted at equal distances along a yard 800 metres long, one tree being at each end of the yard. What is the distance between two consecutive trees? | {
"A": "10",
"B": "8",
"C": "32",
"D": "14",
"E": "16"
} | divide(800, subtract(26, const_1)) | subtract(n0,const_1)|divide(n1,#0)| | "26 trees have 25 gaps between them . length of each gap = 800 / 25 = 32 i . e . , distance between two consecutive trees = 32 answer is c ." | physics |
math_qa__c4CdvtZ4g14md28D | The average age of A, B and C is 28 years. If the average age of A and C is 29 years, what is the age of B in years ? Choose the correct choice from the following answers: A) 19 B) 26 C) 20 D) 32 E) 21 | <gadget id="calculator">28 * 3</gadget>
<output>84</output>
<gadget id="calculator">29 * 2</gadget>
<output>58</output>
<gadget id="calculator">84 - 58</gadget>
<output>26</output>
<result>B</result> | B | 26 | The average age of A, B and C is 28 years. If the average age of A and C is 29 years, what is the age of B in years ? | {
"A": "19",
"B": "26",
"C": "20",
"D": "32",
"E": "21"
} | subtract(multiply(28, const_3), multiply(29, const_2)) | multiply(n0,const_3)|multiply(n1,const_2)|subtract(#0,#1)| | "age of b = age of ( a + b + c ) â € “ age of ( a + c ) = 28 ã — 3 â € “ 29 ã — 2 = 84 â € “ 58 = 26 years b" | general |
math_qa__BjoFtIVgPAwPLj49 | A reduction of 30% in the price of oil enables a house wife to obtain 3kgs more for Rs.700, what is the reduced price for kg? Pick one.
A) 70
B) 50
C) 60
D) 80
E) 65 | <gadget id="calculator">700 * 30</gadget>
<output>21_000</output>
<gadget id="calculator">21_000 / 100</gadget>
<output>210</output>
<gadget id="calculator">210 / 3</gadget>
<output>70</output>
<result>A</result> | A | 70 | A reduction of 30% in the price of oil enables a house wife to obtain 3kgs more for Rs.700, what is the reduced price for kg? | {
"A": "70",
"B": "50",
"C": "60",
"D": "80",
"E": "65"
} | divide(divide(multiply(700, 30), const_100), 3) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "700 * ( 30 / 100 ) = 210 - - - - 3 ? - - - - 1 = > rs . 70 answer : a" | gain |
math_qa__RytvFVGnPKQh5FH2 | A multiple choice test consists of 4 questions, and each question has 5 answer choices. In how many F ways can the test be completed if every question is unanswered? Choose the most appropriate option.
A) 24 B) 120 C) 625 D) 720 E) 1024 | <gadget id="calculator">5 ** 4</gadget>
<output>625</output>
<result>C</result> | C | 625 | A multiple choice test consists of 4 questions, and each question has 5 answer choices. In how many F ways can the test be completed if every question is unanswered? | {
"A": "24",
"B": "120",
"C": "625",
"D": "720",
"E": "1024"
} | power(5, 4) | power(n1,n0)| | "5 choices for each of the 4 questions , thus total f of 5 * 5 * 5 * 5 = 5 ^ 4 = 625 ways to answer all of them . answer : c ." | general |
math_qa__jbRqr3Xtg0aleEVQ | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 8 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? Choose the correct choice from the following answers.
A) 17 : 7
B) 18 : 8
C) 19 : 9
D) 19 : 5
E) 19 : 4 | <gadget id="calculator">62.5 * 8</gadget>
<output>500</output>
<gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">87.5 * 4</gadget>
<output>350</output>
<gadget id="calculator">350 / 100</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">5 + (7/2)</gadget>
<output>17/2 = around 8.5</output>
<gadget id="calculator">8 - 5</gadget>
<output>3</output>
<gadget id="calculator">4 - (7/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(17/2) / (7/2)</gadget>
<output>17/7 = around 2.428571</output>
<result>A</result> | A | 2.428571 | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 8 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? | {
"A": "17 : 7",
"B": "18 : 8",
"C": "19 : 9",
"D": "19 : 5",
"E": "19 : 4"
} | divide(add(divide(multiply(62.5, 8), const_100), divide(multiply(87.5, 4), const_100)), add(subtract(8, divide(multiply(62.5, 8), const_100)), subtract(4, divide(multiply(87.5, 4), const_100)))) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|subtract(n2,#2)|subtract(n3,#3)|add(#5,#6)|divide(#4,#7)| | "quantity of alcohol in vessel p = 62.5 / 100 * 8 = 5 litres quantity of alcohol in vessel q = 87.5 / 100 * 4 = 7 / 2 litres quantity of alcohol in the mixture formed = 5 + 7 / 2 = 17 / 2 = 8.5 litres as 12 litres of mixture is formed , ratio of alcohol and water in the mixture formed = 8.5 : 3.5 = 17 : 7 . answer : a" | other |
math_qa__SlP6iDeGlFxGWjTf | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 34 years. What is Deepak present age? Pick one:
A) 22 B) 15 C) 77 D) 21 E) 182 | <gadget id="calculator">34 - 6</gadget>
<output>28</output>
<gadget id="calculator">28 * 3</gadget>
<output>84</output>
<gadget id="calculator">84 / 4</gadget>
<output>21</output>
<result>D</result> | D | 21 | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 34 years. What is Deepak present age? | {
"A": "22",
"B": "15",
"C": "77",
"D": "21",
"E": "182"
} | divide(multiply(subtract(34, 6), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "present age is 4 x and 3 x , = > 4 x + 6 = 34 = > x = 7 so deepak age is = 3 ( 7 ) = 21 answer : d" | other |
math_qa__nDhLiPoRbvyE7cvw | A retailer bought a machine at a wholesale price of $99 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price of the machine? Options:
A) 81
B) 100
C) 120
D) 132
E) 160 | <gadget id="calculator">99 * 20</gadget>
<output>1_980</output>
<gadget id="calculator">1_980 / 100</gadget>
<output>99/5 = around 19.8</output>
<gadget id="calculator">99 + (99/5)</gadget>
<output>594/5 = around 118.8</output>
<gadget id="calculator">(594/5) * 100</gadget>
<output>11_880</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">11_880 / 90</gadget>
<output>132</output>
<result>D</result> | D | 132 | A retailer bought a machine at a wholesale price of $99 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price of the machine? | {
"A": "81",
"B": "100",
"C": "120",
"D": "132",
"E": "160"
} | divide(multiply(add(99, divide(multiply(99, 20), const_100)), const_100), multiply(multiply(const_3, const_3), 10)) | multiply(n0,n2)|multiply(const_3,const_3)|divide(#0,const_100)|multiply(n1,#1)|add(n0,#2)|multiply(#4,const_100)|divide(#5,#3)| | "my solution : wholesale price = 99 retail price , be = x he provides 10 % discount on retail price = x - 10 x / 100 this retail price = 20 % profit on wholesale price x - 10 x / 100 = 99 + 1 / 5 ( 99 ) x = 132 ; answer : d" | gain |
math_qa__Fjeu00k8ESgM7nBu | A store reported total sales of $480 million for February of this year. If the total sales for the same month last year was $320 million, approximately what was the percent increase in sales? Choose the correct choice from the following.
A) 2 % B) 17 % C) 50 % D) 65 % E) 83 % | <gadget id="calculator">480 - 320</gadget>
<output>160</output>
<gadget id="calculator">160 / 320</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | A store reported total sales of $480 million for February of this year. If the total sales for the same month last year was $320 million, approximately what was the percent increase in sales? | {
"A": "2 %",
"B": "17 %",
"C": "50 %",
"D": "65 %",
"E": "83 %"
} | multiply(divide(subtract(480, 320), 320), const_100) | subtract(n0,n1)|divide(#0,n1)|multiply(#1,const_100)| | "new value – old value ) / old value x 100 we are given : february sales this year = 480 million february sales last year = 320 million we need to determine the percent increase between sales from last year to sales this year . thus , the new value = 480 million and the old value = 320 million . let ’ s plug them into our percent change formula . ( new value – old value ) / old value x 100 [ ( 480 – 320 ) / 320 ] x 100 = 50 % . the answer is c ." | general |
math_qa__LKeu2bU5aZwULKqJ | A cricket bat is sold for $850, making a profit of $215. The profit percentage would be Pick
A) 24 % B) 25 % C) 34 % D) 36 % E) 40 % | <gadget id="calculator">850 - 215</gadget>
<output>635</output>
<gadget id="calculator">215 / 635</gadget>
<output>43/127 = around 0.338583</output>
<gadget id="calculator">(43/127) * 100</gadget>
<output>4_300/127 = around 33.858268</output>
<result>C</result> | C | 34 | A cricket bat is sold for $850, making a profit of $215. The profit percentage would be | {
"A": "24 %",
"B": "25 %",
"C": "34 %",
"D": "36 %",
"E": "40 %"
} | multiply(divide(215, subtract(850, 215)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100)| | "215 / ( 850 - 215 ) = 215 / 635 = 43 / 127 = 34 % . answer : c ." | gain |
math_qa__X7COGr6VEH4hHt5T | Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 35% profit?
Choose the correct choice from the following options: A) 16.39 B) 16.33 C) 16.35 D) 17.01 E) 16.32 | <gadget id="calculator">30 * 11.5</gadget>
<output>345</output>
<gadget id="calculator">20 * 14.25</gadget>
<output>285</output>
<gadget id="calculator">345 + 285</gadget>
<output>630</output>
<gadget id="calculator">630 / 100</gadget>
<output>63/10 = around 6.3</output>
<gadget id="calculator">(63/10) * 35</gadget>
<output>441/2 = around 220.5</output>
<gadget id="calculator">630 + (441/2)</gadget>
<output>1_701/2 = around 850.5</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">(1_701/2) / 50</gadget>
<output>1_701/100 = around 17.01</output>
<result>D</result> | D | 17.01 | Arun purchased 30 kg of wheat at the rate of Rs. 11.50 per kg and 20 kg of wheat at the rate of 14.25 per kg. He mixed the two and sold the mixture. Approximately what price per kg should be sell the mixture to make 35% profit? | {
"A": "16.39",
"B": "16.33",
"C": "16.35",
"D": "17.01",
"E": "16.32"
} | divide(add(add(multiply(30, 11.5), multiply(20, 14.25)), multiply(divide(add(multiply(30, 11.5), multiply(20, 14.25)), const_100), 35)), add(30, 20)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,const_100)|multiply(n4,#4)|add(#3,#5)|divide(#6,#0) | c . p . of 50 kg wheat = ( 30 * 11.50 + 20 * 14.25 ) = rs . 630 . s . p . of 50 kg wheat = 135 % of rs . 630 = 135 / 100 * 630 = rs . 850.50 . s . p . per kg = 850.50 / 50 = rs . 16.38 = 16.30 . answer : d | gain |
math_qa__5yKiOriwWeyDm9E8 | How many times are the hands of a clock at right angle in 2 days? Choose the correct choice from the following answers:
A) 80 B) 82 C) 84 D) 86 E) 88 | <gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">48 - 4</gadget>
<output>44</output>
<gadget id="calculator">48 * 44</gadget>
<output>2_112</output>
<gadget id="calculator">2_112 / 24</gadget>
<output>88</output>
<result>E</result> | E | 88 | How many times are the hands of a clock at right angle in 2 days? | {
"A": "80",
"B": "82",
"C": "84",
"D": "86",
"E": "88"
} | divide(multiply(multiply(multiply(const_12, const_2), 2), subtract(multiply(const_12, const_4), const_4)), multiply(const_12, const_2)) | multiply(const_12,const_2)|multiply(const_12,const_4)|multiply(n0,#0)|subtract(#1,const_4)|multiply(#2,#3)|divide(#4,#0)| | "in 1 day , they are at right angles 44 times . in 2 days , they are at right angles 88 times . answer : option e" | physics |
math_qa__jpQP1xZvSHtvfNJ4 | A cyclist rides a bicycle 8 km at an average speed of 10 km/hr and again travels 10 km at an average speed of 8 km/hr. What is the average speed for the entire trip?
Choices
A) 9.28
B) 8.48
C) 8.78
D) 8.98
E) 9.18 | <gadget id="calculator">8 + 10</gadget>
<output>18</output>
<gadget id="calculator">8 / 10</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">10 / 8</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(4/5) + (5/4)</gadget>
<output>41/20 = around 2.05</output>
<gadget id="calculator">18 / (41/20)</gadget>
<output>360/41 = around 8.780488</output>
<result>C</result> | C | 8.78 | A cyclist rides a bicycle 8 km at an average speed of 10 km/hr and again travels 10 km at an average speed of 8 km/hr. What is the average speed for the entire trip? | {
"A": "9.28",
"B": "8.48",
"C": "8.78",
"D": "8.98",
"E": "9.18"
} | divide(add(8, 10), add(divide(8, 10), divide(10, 8))) | add(n0,n1)|divide(n0,n1)|divide(n1,n0)|add(#1,#2)|divide(#0,#3)| | "distance = 18 km time = 8 / 10 + 10 / 8 = ( 64 + 100 ) / 80 = 164 / 80 = 41 / 20 hours average speed = ( 18 * 20 ) / 41 = 8.78 km / h the answer is c ." | general |
math_qa__pYHzun9r14yiACQh | Find the value of 72516 x 9999 = m? Choose the correct choice from the following options.
A) 456578972 B) 436567874 C) 725087484 D) 725117481 E) 357889964 | <gadget id="calculator">9_999 - 4</gadget>
<output>9_995</output>
<gadget id="calculator">9_995 * 72_516</gadget>
<output>724_797_420</output>
<result>C</result> | C | 725,087,484 | Find the value of 72516 x 9999 = m? | {
"A": "456578972",
"B": "436567874",
"C": "725087484",
"D": "725117481",
"E": "357889964"
} | multiply(subtract(9999, const_4), 72516) | subtract(n1,const_4)|multiply(#0,n0)| | "72516 x 9999 = 72516 x ( 10000 - 1 ) = 72516 x 10000 - 72516 x 1 = 725160000 - 72516 = 725087484 c" | general |
math_qa__s5pr8ZoAnYFhHnHb | What is the tens digit of 7^1001? Choose the correct choice from the following answers: A) 0 B) 0 C) 2 D) 3 E) 4 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">1_001 % 5</gadget>
<output>1</output>
<gadget id="calculator">7 ** 1</gadget>
<output>7</output>
<gadget id="calculator">7 % 100</gadget>
<output>7</output>
<gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">floor(7/10)</gadget>
<output>0</output>
<result>B</result> | B | 0 | What is the tens digit of 7^1001? | {
"A": "0",
"B": "0",
"C": "2",
"D": "3",
"E": "4"
} | floor(divide(reminder(power(7, reminder(1001, add(const_4, const_1))), const_100), const_10)) | add(const_1,const_4)|reminder(n1,#0)|power(n0,#1)|reminder(#2,const_100)|divide(#3,const_10)|floor(#4)| | "7 ^ 1 = 7 7 ^ 2 = 49 7 ^ 3 = 343 7 ^ 4 = 2401 7 ^ 5 = 16807 7 ^ 6 = 117649 we should see this as pattern recognition . we have a cycle of 4 . ( we can multiply the last 2 digits only as we care about ten ' s digit ) 0 , 4 , 4 , 0 . 1001 = 4 * 250 + 1 the ten ' s digit will be 1 . answer b" | general |
math_qa__Q7XvFtztkcdPZ9uS | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3872. What is the difference between Rohan’s and Sudhir’s share in the profit?
Choose the correct option.
A) s . 345 B) s . 350 C) s . 352 D) s . 362 E) s . 368 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">12_000 * (3/4)</gadget>
<output>9_000</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">9_000 * (2/3)</gadget>
<output>6_000</output>
<gadget id="calculator">9_000 - 6_000</gadget>
<output>3_000</output>
<gadget id="calculator">18_000 + 9_000</gadget>
<output>27_000</output>
<gadget id="calculator">27_000 + 6_000</gadget>
<output>33_000</output>
<gadget id="calculator">3_872 / 33_000</gadget>
<output>44/375 = around 0.117333</output>
<gadget id="calculator">3_000 * (44/375)</gadget>
<output>352</output>
<result>C</result> | C | 352 | Suresh started a business, investing Rs.18000. After 3 months and 4 months respectively, Rohan and Sudhir joined him with capitals of 12000 and 9000. At the end of the year the total profit was Rs.3872. What is the difference between Rohan’s and Sudhir’s share in the profit? | {
"A": "s . 345",
"B": "s . 350",
"C": "s . 352",
"D": "s . 362",
"E": "s . 368"
} | multiply(subtract(multiply(12000, divide(subtract(multiply(3, 4), 3), multiply(3, 4))), multiply(9000, divide(subtract(multiply(3, 4), 4), multiply(3, 4)))), divide(3872, add(add(18000, multiply(12000, divide(subtract(multiply(3, 4), 3), multiply(3, 4)))), multiply(9000, divide(subtract(multiply(3, 4), 4), multiply(3, 4)))))) | multiply(n1,n2)|subtract(#0,n1)|subtract(#0,n2)|divide(#1,#0)|divide(#2,#0)|multiply(n3,#3)|multiply(n4,#4)|add(n0,#5)|subtract(#5,#6)|add(#7,#6)|divide(n5,#9)|multiply(#10,#8)| | "suresh : rohan : sudhir ratio of their investments = 18000 × 12 : 12000 × 9 : 9000 × 8 = 6 : 3 : 2 the difference between rohan ’ s and sudhir ’ s share = 1 share : . i . e . = rs . 3872 × 1 / 11 = rs . 352 . c" | gain |
math_qa__LJ5UdDGuZl1edN1W | In a certain alphabet, 20 letters contain a dot and a straight line. 36 letters contain a straight line but do not contain a dot. If that alphabet has 60 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line? Answers:
A) 4 B) 3 C) 14 D) 20 E) 28 | <gadget id="calculator">20 + 36</gadget>
<output>56</output>
<gadget id="calculator">60 - 56</gadget>
<output>4</output>
<result>A</result> | A | 4 | In a certain alphabet, 20 letters contain a dot and a straight line. 36 letters contain a straight line but do not contain a dot. If that alphabet has 60 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line? | {
"A": "4",
"B": "3",
"C": "14",
"D": "20",
"E": "28"
} | subtract(60, add(20, 36)) | add(n0,n1)|subtract(n2,#0)| | "we are told that all of the letters contain either a dot or a straight line or both , which implies that there are no letters without a dot and a line ( no line / no dot box = 0 ) . first we find the total # of letters with lines : 20 + 36 = 56 ; next , we find the total # of letters without line : 60 - 56 = 4 ; finally , we find the # of letters that contain a dot but do not contain a straight line : 4 - 0 = 4 ." | other |
math_qa__gK0QPw3iio4RkdtR | A meal cost $ 35.50 adn there was no tax. If the tip was more than 15 pc but less than 25pc of the price, then the total amount paid should be:
Select the correct option: A) 41 - 44 B) 39 - 41 C) 38 - 40 D) 37 - 39 E) 36 - 37 | <gadget id="calculator">35.5 * 15</gadget>
<output>532.5</output>
<gadget id="calculator">532.5 / 100</gadget>
<output>5.325</output>
<gadget id="calculator">5.325 + 35.5</gadget>
<output>40.825</output>
<result>A</result> | A | 41 | A meal cost $ 35.50 adn there was no tax. If the tip was more than 15 pc but less than 25pc of the price, then the total amount paid should be: | {
"A": "41 - 44",
"B": "39 - 41",
"C": "38 - 40",
"D": "37 - 39",
"E": "36 - 37"
} | add(divide(multiply(35.50, 15), const_100), 35.50) | multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)| | "15 % ( 35.5 ) = 5.325 25 % ( 35.5 ) = 8.875 total amount could have been 35.5 + 5.325 and 35.5 + 8.875 = > could have been between 40.825 and 44.375 = > approximately between 41 and 44 answer is a ." | general |
math_qa__0hXKuHjrhJF5mojI | The sum of the even numbers between 1 and n is 95*96, where n is an odd number, then n=?
Select
A) 167 B) 175 C) 183 D) 191 E) 199 | <gadget id="calculator">95 * 2</gadget>
<output>190</output>
<gadget id="calculator">190 + 1</gadget>
<output>191</output>
<result>D</result> | D | 191 | The sum of the even numbers between 1 and n is 95*96, where n is an odd number, then n=? | {
"A": "167",
"B": "175",
"C": "183",
"D": "191",
"E": "199"
} | add(multiply(95, const_2), 1) | multiply(n1,const_2)|add(#0,n0)| | "let n - 1 = 2 a . 2 + 4 + . . . + 2 a = 2 * ( 1 + 2 + . . . + a ) = 2 * ( a ) ( a + 1 ) / 2 = ( a ) ( a + 1 ) = 95 * 96 then a = 95 and n = 191 . the answer is d ." | general |
math_qa__KYTjeqUosVVqyF0h | The present ratio of students to teachers at a certain school is 50 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1. What is the present number of teachers? Choose the correct choice from the following answers.
A) 3 B) 8 C) 10 D) 12 E) 15 | <gadget id="calculator">50 + 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 25</gadget>
<output>3</output>
<result>A</result> | A | 3 | The present ratio of students to teachers at a certain school is 50 to 1. If the student enrollment were to increase by 50 students and the number of teachers were to increase by 5, the ratio of students to teachers would then be 25 to 1. What is the present number of teachers? | {
"A": "3",
"B": "8",
"C": "10",
"D": "12",
"E": "15"
} | divide(add(50, 25), 25) | add(n0,n4)|divide(#0,n4) | we are given that the ratio of students to teacher is 50 to 1 . we can rewrite this using variable multipliers . students : teachers = 50 x : x we are next given that student enrollment increases by 50 and the number of teachers increases by 5 . with this change the new ratio becomes 25 to 1 . we can put all this into an equation : students / teachers 25 / 1 = ( 30 x + 50 ) / ( x + 5 ) if we cross multiply we have : 25 ( x + 5 ) = 50 x + 50 25 x + 125 = 50 x + 50 3 = x since x is the present number of teachers , currently there are 3 teachers . answer a . | other |
math_qa__2A1olfRl3LaplFvO | julie decided to save a certain amount of her monthly salary each month and her salary was unchanged from month to month . if julie ' s savings by the end of the year from these monthly savings were 4 times the amount she spent per month , what should be the fraction of her salary that she spent each month ? Choose the correct choice from the following options
A) 5 / 3 B) 3 / 9 C) 3 / 2 D) 3 / 5 E) 3 / 4 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<result>E</result> | E | 0.75 | julie decided to save a certain amount of her monthly salary each month and her salary was unchanged from month to month . if julie ' s savings by the end of the year from these monthly savings were 4 times the amount she spent per month , what should be the fraction of her salary that she spent each month ? | {
"A": "5 / 3",
"B": "3 / 9",
"C": "3 / 2",
"D": "3 / 5",
"E": "3 / 4"
} | divide(const_3, 4) | divide(const_3,n0) | let julie ' s monthly savings = s julie ' s monthly pay = p julie ' s monthly expenditure = p - s julie ' s savings by the end of the year from these monthly savings were four times the amount she spent per month 12 s = 4 * ( p - s ) = > 3 s = p - s = > p = 4 s julie ' s monthly expenditure = p - s = 4 s - s = 3 s fraction of her salary that julie spent each month = 3 s / 4 s = p - s / p = 3 / 4 . answer is e | general |
math_qa__ATJ75lgjAzxAb368 | Calculate the amount that an investor needs to be invest to earn $441 in interest in 12 months if the investor plans to invest x dollars in a savings account that pays interest at an annual rate of 7% compounded semi-annually? Select: A) 6209 B) 6200 C) 6799 D) 6199 E) 6685 | <gadget id="calculator">100 * 441</gadget>
<output>44_100</output>
<gadget id="calculator">44_100 / 7</gadget>
<output>6_300</output>
<result>B</result> | B | 6,200 | Calculate the amount that an investor needs to be invest to earn $441 in interest in 12 months if the investor plans to invest x dollars in a savings account that pays interest at an annual rate of 7% compounded semi-annually? | {
"A": "6209",
"B": "6200",
"C": "6799",
"D": "6199",
"E": "6685"
} | divide(multiply(const_100, 441), 7) | multiply(n0,const_100)|divide(#0,n2) | the approach is substitution , our interest requirement is $ 441 after 12 months , 2 compounding period . calculate the compound interest on each option and find out the one that yields $ 441 in 12 months 6200 yielded $ 441 using the formula a = p ( 1 + r / n ) nt hence answer is b | gain |
math_qa__MC6Mq23E3Mxzx1GE | How many positive integers less than 6,000 are there in which the sum of the digits equals 5?
Choose the correct choice.
A) 65
B) 62
C) 61
D) 56
E) 58 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<result>D</result> | D | 56 | How many positive integers less than 6,000 are there in which the sum of the digits equals 5? | {
"A": "65",
"B": "62",
"C": "61",
"D": "56",
"E": "58"
} | divide(factorial(subtract(add(const_4, 5), const_1)), multiply(factorial(5), factorial(subtract(const_4, const_1)))) | add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6)| | "basically , the question asks how many 4 digit numbers ( including those in the form 0 xxx , 00 xx , and 000 x ) have digits which add up to 5 . think about the question this way : we know that there is a total of 5 to be spread among the 4 digits , we just have to determine the number of ways it can be spread . let x represent a sum of 1 , and | represent a seperator between two digits . as a result , we will have 5 x ' s ( digits add up to the 5 ) , and 3 | ' s ( 3 digit seperators ) . so , for example : xx | x | x | x = 2111 | | xxx | xx = 0032 etc . there are 8 c 3 ways to determine where to place the separators . hence , the answer is 8 c 3 = 56 . d" | general |
math_qa__nha5vfDVpblNucQt | the average ( arithmetic mean ) of 8 numbers is 8 . if 4 is added from each of 5 of the numbers , what is the new average ? Options
A) 4.5 B) 8.9 C) 10.5 D) 4.5 E) 5.6 | <gadget id="calculator">8 * 8</gadget>
<output>64</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">64 + 20</gadget>
<output>84</output>
<gadget id="calculator">84 / 8</gadget>
<output>21/2 = around 10.5</output>
<result>C</result> | C | 10.5 | the average ( arithmetic mean ) of 8 numbers is 8 . if 4 is added from each of 5 of the numbers , what is the new average ? | {
"A": "4.5",
"B": "8.9",
"C": "10.5",
"D": "4.5",
"E": "5.6"
} | divide(add(multiply(8, 8), multiply(5, 4)), 8) | multiply(n0,n0)|multiply(n2,n3)|add(#0,#1)|divide(#2,n0) | sum of 8 numbers = 8 * 8 = 64 if 4 is added from each of five of the numbers , we added 4 * 5 = 20 from the total sum sum of 8 number after adding 4 from each of five of the numbers = 64 + 20 = 84 new average = 84 / 8 = 10.5 answer c | general |
math_qa__SOAyAODGHILtKjXU | List K consists of 10 consecutive integers. If -3 is the least integer in list K, what is the range of the positive integers in list K? Choose the correct choice from the following options:
A) 5
B) 6
C) 7
D) 11
E) 12 | <gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<result>A</result> | A | 5 | List K consists of 10 consecutive integers. If -3 is the least integer in list K, what is the range of the positive integers in list K? | {
"A": "5",
"B": "6",
"C": "7",
"D": "11",
"E": "12"
} | subtract(subtract(subtract(10, 3), const_1), const_1) | subtract(n0,n1)|subtract(#0,const_1)|subtract(#1,const_1)| | "answer = a = 5 if least = - 3 , then largest = 6 range = 6 - 1 = 5" | general |
math_qa__brSUvx3mUJ6XcyqZ | A shopkeeper has 280 kg of apples. He sells 40% of these at 20% profit and remaining 60% at 30% profit. Find his % profit on total. Choices:
A) 24 % B) 25 % C) 26 % D) 28 % E) 35 % | <gadget id="calculator">280 * 40</gadget>
<output>11_200</output>
<gadget id="calculator">11_200 / 100</gadget>
<output>112</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">112 * (6/5)</gadget>
<output>672/5 = around 134.4</output>
<gadget id="calculator">280 * 60</gadget>
<output>16_800</output>
<gadget id="calculator">16_800 / 100</gadget>
<output>168</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">168 * (13/10)</gadget>
<output>1_092/5 = around 218.4</output>
<gadget id="calculator">(672/5) + (1_092/5)</gadget>
<output>1_764/5 = around 352.8</output>
<gadget id="calculator">(1_764/5) - 280</gadget>
<output>364/5 = around 72.8</output>
<gadget id="calculator">(364/5) * 100</gadget>
<output>7_280</output>
<gadget id="calculator">7_280 / 280</gadget>
<output>26</output>
<result>C</result> | C | 26 | A shopkeeper has 280 kg of apples. He sells 40% of these at 20% profit and remaining 60% at 30% profit. Find his % profit on total. | {
"A": "24 %",
"B": "25 %",
"C": "26 %",
"D": "28 %",
"E": "35 %"
} | divide(multiply(subtract(add(multiply(divide(multiply(280, 40), const_100), divide(add(const_100, 20), const_100)), multiply(divide(multiply(280, 60), const_100), divide(add(const_100, 30), const_100))), 280), const_100), 280) | add(n2,const_100)|add(n4,const_100)|multiply(n0,n1)|multiply(n0,n3)|divide(#2,const_100)|divide(#0,const_100)|divide(#3,const_100)|divide(#1,const_100)|multiply(#4,#5)|multiply(#6,#7)|add(#8,#9)|subtract(#10,n0)|multiply(#11,const_100)|divide(#12,n0)| | "total number of apples = 280 let the cost price be x selling price at 20 % profit = 1.2 x selling price at 30 % profit = 1.3 x profit % = ( ( sp - cp ) / cp ) * 100 profit % = ( ( 2 / 5 ) * 280 * 1.2 x + ( 3 / 5 ) * 280 * 1.3 x - 280 x ) / 280 x * 100 = ( 1 / 5 * ( 2.4 + 3.9 ) - 1 ) * 100 = ( 6.3 - 5 ) * 20 = 26 % answer : c" | gain |
math_qa__nMPVJApZ8yD20yph | We run a business that rents out canoes and kayaks. A canoe rental costs $14 per day, and a kayak rental costs $15 dollars per day. One day, our business rents out 3 canoes for every 2 kayaks and receives a total of $288 in revenue. How many more canoes than kayaks were rented out? Select the correct option:
A) 3
B) 4
C) 5
D) 6
E) 7 | <gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">3 * 14</gadget>
<output>42</output>
<gadget id="calculator">2 * 15</gadget>
<output>30</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">288 / 72</gadget>
<output>4</output>
<gadget id="calculator">1 * 4</gadget>
<output>4</output>
<result>B</result> | B | 4 | We run a business that rents out canoes and kayaks. A canoe rental costs $14 per day, and a kayak rental costs $15 dollars per day. One day, our business rents out 3 canoes for every 2 kayaks and receives a total of $288 in revenue. How many more canoes than kayaks were rented out? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | multiply(subtract(3, 2), divide(288, add(multiply(3, 14), multiply(2, 15)))) | multiply(n0,n2)|multiply(n1,n3)|subtract(n2,n3)|add(#0,#1)|divide(n4,#3)|multiply(#4,#2) | let x be the number of canoes . then 2 x / 3 is the number of kayaks . 14 x + ( 2 x / 3 ) * 15 = 288 14 x + 10 x = 288 24 x = 288 x = 12 ( canoes ) 2 x / 3 = 8 ( kayaks ) there were 12 - 8 = 4 more canoes rented out . the answer is b . | general |
math_qa__Z3mGwa0Bjd5Y4ttk | Positive integers from 1 to 45, inclusive are placed in 5 groups of 9 each. What is the highest possible average of the medians of these 5 groups? Choose the correct choice from the following choices.
A) 25 B) 31 C) 15 D) 26 E) 23 | <gadget id="calculator">45 - 5</gadget>
<output>40</output>
<gadget id="calculator">40 - 10</gadget>
<output>30</output>
<result>B</result> | B | 31 | Positive integers from 1 to 45, inclusive are placed in 5 groups of 9 each. What is the highest possible average of the medians of these 5 groups? | {
"A": "25",
"B": "31",
"C": "15",
"D": "26",
"E": "23"
} | subtract(subtract(45, 5), const_10) | subtract(n1,n2)|subtract(#0,const_10) | answer we need to maximize the median in each group in order to maximize the average of all the medians . the highest possible median is 41 as there should be 4 numbers higher than the median in a group of 9 . so , if we have a group that has a , b , c , d , 41 , 42 , 43 , 44 , 45 , the median will be 41 . in this set , it is essential not to expend any more high values on a , b , c , or d as these do not affect the median . the median of a group that comprises 1 , 2 , 3 , 4 , 41 , 42 , 43 , 44 , 45 will be 41 . the next group can be 5 , 6 , 7 , 8 , 36 , 37 , 38 , 39 , 40 . the median will be 36 . extrapolating the findings in the two sets listed above , to maximize medians in all the 5 groups , the medians of the 5 groups will have to be 21 , 26 , 31 , 36 and 41 . the average of the highest possible medians will be the average of these 5 numbers = 31 . answer b | general |
math_qa__uoDi3OBzVUsy97UQ | For each of her sales, a saleswoman receives a commission equal to 20 percent of the first $500 of the total amount of the sale, plus 40 percent of the total amount in excess of $500. If the total amount of one of her sales was $800, the saleswoman’s commission was approximately what percent of the total amount of the sale?
Options:
A) 22 % B) 24 % C) 25 % D) 27 % E) 28 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 500</gadget>
<output>100</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">800 - 500</gadget>
<output>300</output>
<gadget id="calculator">(2/5) * 300</gadget>
<output>120</output>
<gadget id="calculator">100 + 120</gadget>
<output>220</output>
<gadget id="calculator">220 / 800</gadget>
<output>11/40 = around 0.275</output>
<gadget id="calculator">(11/40) * 100</gadget>
<output>55/2 = around 27.5</output>
<result>E</result> | E | 28 | For each of her sales, a saleswoman receives a commission equal to 20 percent of the first $500 of the total amount of the sale, plus 40 percent of the total amount in excess of $500. If the total amount of one of her sales was $800, the saleswoman’s commission was approximately what percent of the total amount of the sale? | {
"A": "22 %",
"B": "24 %",
"C": "25 %",
"D": "27 %",
"E": "28 %"
} | multiply(divide(add(multiply(divide(20, const_100), 500), multiply(divide(40, const_100), subtract(800, 500))), 800), const_100) | divide(n0,const_100)|divide(n2,const_100)|subtract(n4,n1)|multiply(n1,#0)|multiply(#1,#2)|add(#3,#4)|divide(#5,n4)|multiply(#6,const_100)| | "total sales = 800 comission = ( 20 / 100 ) * 500 + ( 40 / 100 ) * 300 = 100 + 120 = 220 % comission = ( 220 / 800 ) * 100 = 27.5 ~ 28 % answer is e" | general |
math_qa__e022AuCisVBSgsIC | A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its ave66rage daily production for that year? Choose the correct choice from the following answers:
A) 180 B) 185 C) 190 D) 195 E) 200 | <gadget id="calculator">5_000 * 2</gadget>
<output>10_000</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 100</gadget>
<output>1_100</output>
<gadget id="calculator">10_000 + 1_100</gadget>
<output>11_100</output>
<gadget id="calculator">11_100 * 12</gadget>
<output>133_200</output>
<gadget id="calculator">133_200 / 2</gadget>
<output>66_600</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">300 + 60</gadget>
<output>360</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">360 + 5</gadget>
<output>365</output>
<gadget id="calculator">66_600 / 365</gadget>
<output>13_320/73 = around 182.465753</output>
<result>B</result> | B | 185 | A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its ave66rage daily production for that year? | {
"A": "180",
"B": "185",
"C": "190",
"D": "195",
"E": "200"
} | divide(divide(multiply(add(multiply(5000, const_2), multiply(subtract(const_12, const_1), 100)), const_12), const_2), add(add(multiply(const_3, 100), multiply(multiply(const_2, const_3), const_10)), add(const_2, const_3))) | add(const_2,const_3)|multiply(n0,const_2)|multiply(n1,const_3)|multiply(const_2,const_3)|subtract(const_12,const_1)|multiply(n1,#4)|multiply(#3,const_10)|add(#1,#5)|add(#2,#6)|add(#8,#0)|multiply(#7,const_12)|divide(#10,const_2)|divide(#11,#9)| | "total production of salt by the company in that year = 5000 + 5100 + 5200 + . . . . + 6100 = 66600 . average monthly production of salt for that year = 66600 / 365 = 185 answer : b" | general |
math_qa__CTLJXfDtct85pfE5 | The average weight of 9 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?
Choices
A) 85.5
B) 86.5
C) 87.5
D) 88.5
E) 89.5 | <gadget id="calculator">9 * 2.5</gadget>
<output>22.5</output>
<gadget id="calculator">22.5 + 65</gadget>
<output>87.5</output>
<result>C</result> | C | 87.5 | The average weight of 9 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person? | {
"A": "85.5",
"B": "86.5",
"C": "87.5",
"D": "88.5",
"E": "89.5"
} | add(multiply(9, 2.5), 65) | multiply(n0,n1)|add(n2,#0)| | "total increase in weight = 9 × 2.5 = 22.5 if x is the weight of the new person , total increase in weight = x − 65 = > 22.5 = x - 65 = > x = 22.5 + 65 = 87.5 answer : c" | general |
math_qa__dHvBiEF7tVB66MLV | A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked at 5 miles per hour for 3 hours. How many miles in total did she walk? Choose the correct choice from the following answers
A) 53 B) 44 C) 58 D) 60 E) 62 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">18 + 20</gadget>
<output>38</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">38 + 15</gadget>
<output>53</output>
<result>A</result> | A | 53 | A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked at 5 miles per hour for 3 hours. How many miles in total did she walk? | {
"A": "53",
"B": "44",
"C": "58",
"D": "60",
"E": "62"
} | add(add(18, multiply(5, const_4)), multiply(5, 3)) | multiply(n3,const_4)|multiply(n3,n4)|add(n1,#0)|add(#2,#1)| | "first day - 18 miles with 3 miles per hours then total - 6 hours for that day second day - 4 miles per hour and 5 hours - 20 miles third day - 5 miles per hour and 3 hours - 15 miles total 18 + 20 + 15 = 53 answer : option a ." | physics |
math_qa__17k61ZaaLeIUfmHo | A can do a job in 15days and B in 20days. If they work on it together for 5 days, then the fraction of the work that is left is? Pick one
A) 2 / 15 B) 8 / 15 C) 3 / 11 D) 5 / 12 E) 6 / 13 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/15) + (1/20)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">5 * (7/60)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">1 - (7/12)</gadget>
<output>5/12 = around 0.416667</output>
<result>D</result> | D | 0.416667 | A can do a job in 15days and B in 20days. If they work on it together for 5 days, then the fraction of the work that is left is? | {
"A": "2 / 15",
"B": "8 / 15",
"C": "3 / 11",
"D": "5 / 12",
"E": "6 / 13"
} | subtract(const_1, multiply(5, add(divide(const_1, 15), divide(const_1, 20)))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)| | "a ' s 1 day work = 1 / 15 b ' s 1 day work = 1 / 20 a + b 1 day work = 1 / 15 + 1 / 20 = 7 / 60 a + b 5 days work = 7 / 60 * 5 = 7 / 12 remaining work = 1 - 7 / 12 = 5 / 12 answer is d" | physics |
math_qa__IWv3PvbYSeDvT4y1 | How many zeros are the end of 380! ? Choose the correct answer:
A) 90
B) 91
C) 94
D) none
E) 95 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">380 / 5</gadget>
<output>76</output>
<gadget id="calculator">380 - 5</gadget>
<output>375</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">375 / 25</gadget>
<output>15</output>
<gadget id="calculator">76 + 15</gadget>
<output>91</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">375 / 125</gadget>
<output>3</output>
<gadget id="calculator">91 + 3</gadget>
<output>94</output>
<result>C</result> | C | 94 | How many zeros are the end of 380! ? | {
"A": "90",
"B": "91",
"C": "94",
"D": "none",
"E": "95"
} | add(add(divide(380, add(const_4, const_1)), divide(subtract(380, add(const_4, const_1)), power(add(const_4, const_1), const_2))), divide(subtract(380, add(const_4, const_1)), power(add(const_4, const_1), const_3))) | add(const_1,const_4)|divide(n0,#0)|power(#0,const_2)|power(#0,const_3)|subtract(n0,#0)|divide(#4,#2)|divide(#4,#3)|add(#1,#5)|add(#7,#6) | 380 ! has 380 / 5 + 380 / 5 ^ 2 + 380 / 5 ^ 3 = 76 + 15 + 3 = 94 trailing zeros ( take only the quotient into account ) . answer : c . | other |
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