id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__fsd7B7TGKJolbN5N | Find the least number which when divided by 38 and 3 leaves a remainder of 1 in each case. Choose the correct choice:
A) 107
B) 109
C) 111
D) 113
E) 115 | <gadget id="calculator">lcm(38, 3)</gadget>
<output>114</output>
<gadget id="calculator">1 + 114</gadget>
<output>115</output>
<result>E</result> | E | 115 | Find the least number which when divided by 38 and 3 leaves a remainder of 1 in each case. | {
"A": "107",
"B": "109",
"C": "111",
"D": "113",
"E": "115"
} | add(1, lcm(38, 3)) | lcm(n0,n1)|add(n2,#0)| | "the least number which when divided by different divisors leaving the same remainder in each case = lcm ( different divisors ) + remainder left in each case . hence the required least number = lcm ( 38 , 3 ) + 1 = 115 . answer : e" | general |
math_qa__gbu838JBmuREvG3w | In a certain supermarket, a triangular display of cans is arranged in 10 rows, numbered 1 through 10 from top to bottom. Each successively numbered row contains 3 more cans than the row immediately above it. If there are fewer than 150 cans in the entire display, how many cans are in the seventh row? Pick: A) 13 B) 15 C) 17 D) 19 E) 21 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">3 * 9</gadget>
<output>27</output>
<gadget id="calculator">27 / 2</gadget>
<output>27/2 = around 13.5</output>
<gadget id="calculator">(27/2) * 10</gadget>
<output>135</output>
<gadget id="calculator">150 - 135</gadget>
<output>15</output>
<gadget id="calculator">15 / 10</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">floor(3/2)</gadget>
<output>1</output>
<gadget id="calculator">18 + 1</gadget>
<output>19</output>
<result>D</result> | D | 19 | In a certain supermarket, a triangular display of cans is arranged in 10 rows, numbered 1 through 10 from top to bottom. Each successively numbered row contains 3 more cans than the row immediately above it. If there are fewer than 150 cans in the entire display, how many cans are in the seventh row? | {
"A": "13",
"B": "15",
"C": "17",
"D": "19",
"E": "21"
} | add(multiply(add(3, 3), 3), floor(divide(subtract(150, multiply(divide(multiply(3, subtract(10, 1)), const_2), 10)), 10))) | add(n3,n3)|subtract(n0,n1)|multiply(n3,#1)|multiply(n3,#0)|divide(#2,const_2)|multiply(n0,#4)|subtract(n4,#5)|divide(#6,n0)|floor(#7)|add(#8,#3) | let x be the number of cans in row 1 . the total number of cans is x + ( x + 3 ) + . . . + ( x + 27 ) = 10 x + 3 ( 1 + 2 + . . . + 9 ) = 10 x + 3 ( 9 ) ( 10 ) / 2 = 10 x + 135 since the total is less than 150 , x must equal 1 . the number of cans in the 7 th row is 1 + 3 ( 6 ) = 19 the answer is d . | general |
math_qa__okUHLCr0Hf2me5FL | Q' = 3Q - 3, what is the value of (5')' ? Choose the correct choice from the following answers: A) 96 B) 108 C) 120 D) 132 E) 144 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 - 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36 - 3</gadget>
<output>33</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">33 * 4</gadget>
<output>132</output>
<result>D</result> | D | 132 | Q' = 3Q - 3, what is the value of (5')' ? | {
"A": "96",
"B": "108",
"C": "120",
"D": "132",
"E": "144"
} | multiply(subtract(multiply(subtract(multiply(3, 5), 3), 3), 3), subtract(5, const_1)) | multiply(n0,n2)|subtract(n2,const_1)|subtract(#0,n0)|multiply(n0,#2)|subtract(#3,n0)|multiply(#4,#1)| | "( 5 ' ) ' = ( 3 * 5 - 3 ) ' = 12 ' = 12 * 12 - 12 = 132 answer d" | general |
math_qa__yEZBc4tFHbc6O6Sm | The L.C.M of two numbers is 2310 and their H.C.F is 30. If one number is 210 the Other is Choices.
A) 330
B) 300
C) 270
D) 250
E) 350 | <gadget id="calculator">30 * 2_310</gadget>
<output>69_300</output>
<gadget id="calculator">69_300 / 210</gadget>
<output>330</output>
<result>A</result> | A | 330 | The L.C.M of two numbers is 2310 and their H.C.F is 30. If one number is 210 the Other is | {
"A": "330",
"B": "300",
"C": "270",
"D": "250",
"E": "350"
} | divide(multiply(30, 2310), 210) | multiply(n0,n1)|divide(#0,n2)| | "the other number = l . c . m * h . c . f / given number = 2310 * 30 / 210 = 330 answer is a ." | physics |
math_qa__YBsIILToOSe3vBl0 | The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: Select the correct option:
A) 1439 B) 1440 C) 1459 D) 1449 E) 1500 | <gadget id="calculator">lcm(12, 18)</gadget>
<output>36</output>
<gadget id="calculator">lcm(24, 32)</gadget>
<output>96</output>
<gadget id="calculator">lcm(36, 96)</gadget>
<output>288</output>
<gadget id="calculator">lcm(288, 40)</gadget>
<output>1_440</output>
<gadget id="calculator">1_440 + 1</gadget>
<output>1_441</output>
<result>A</result> | A | 1,439 | The smallest number when increased by " 1 " is exactly divisible by 12, 18, 24, 32 and 40 is: | {
"A": "1439",
"B": "1440",
"C": "1459",
"D": "1449",
"E": "1500"
} | add(lcm(lcm(lcm(12, 18), lcm(24, 32)), 40), 1) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|lcm(n5,#2)|add(n0,#3) | lcm = 1440 1440 - 1 = 1439 answer : a | general |
math_qa__yk2KjVbhwM3qmrvV | Of the 720 students at a certain university, 25 percent are seniors. If x seniors were to graduate early and leave the university and no additional students entered or left the university, what value of x would reduce the number of seniors at the university to 20 percent?
Choose the most appropriate option.
A) 30 B) 36 C) 42 D) 45 E) 48 | <gadget id="calculator">720 / 25</gadget>
<output>144/5 = around 28.8</output>
<gadget id="calculator">(144/5) * 2</gadget>
<output>288/5 = around 57.6</output>
<gadget id="calculator">(288/5) - 4</gadget>
<output>268/5 = around 53.6</output>
<gadget id="calculator">(268/5) - 10</gadget>
<output>218/5 = around 43.6</output>
<result>D</result> | D | 45 | Of the 720 students at a certain university, 25 percent are seniors. If x seniors were to graduate early and leave the university and no additional students entered or left the university, what value of x would reduce the number of seniors at the university to 20 percent? | {
"A": "30",
"B": "36",
"C": "42",
"D": "45",
"E": "48"
} | subtract(subtract(multiply(divide(720, 25), const_2), const_4), const_10) | divide(n0,n1)|multiply(#0,const_2)|subtract(#1,const_4)|subtract(#2,const_10) | sol : 180 - x = 20 % of ( 720 - x ) 4 x = 180 x = 45 answer : d | general |
math_qa__QGyS0aOsoPEs9WQ7 | From given equation find the value of x: 2x² + 9x − 5
Choose the most appropriate option.
A) 1 / 2
B) 1
C) 3
D) 4
E) 5 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | From given equation find the value of x: 2x² + 9x − 5 | {
"A": "1 / 2",
"B": "1",
"C": "3",
"D": "4",
"E": "5"
} | divide(const_1, 2) | divide(const_1,n0) | that quadratic is factored as follows : 2 x ² + 9 x − 5 = ( 2 x − 1 ) ( x + 5 ) . lesson 17 . now , it is easy to see that the second factor will be 0 when x = − 5 . as for the value of x that will make 2 x − 1 = 0 , we must solve that little equation . ( lesson 9 . ) we have : 2 x = 1 x = 1 2 the solutions are : x = 1 / 2 or − 5 a | general |
math_qa__iuVAfSWOv76pABqN | A can do a job in 15days and B in 20days. If they work on it together for 3 days, then the fraction of the work that is left is? Choose the correct choice:
A) 2 / 15
B) 8 / 15
C) 13 / 20
D) 1 / 12
E) 6 / 13 | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/15) + (1/20)</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">3 * (7/60)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">1 - (7/20)</gadget>
<output>13/20 = around 0.65</output>
<result>C</result> | C | 0.65 | A can do a job in 15days and B in 20days. If they work on it together for 3 days, then the fraction of the work that is left is? | {
"A": "2 / 15",
"B": "8 / 15",
"C": "13 / 20",
"D": "1 / 12",
"E": "6 / 13"
} | subtract(const_1, multiply(3, add(divide(const_1, 15), divide(const_1, 20)))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3) | a ' s 1 day work = 1 / 15 b ' s 1 day work = 1 / 20 a + b 1 day work = 1 / 15 + 1 / 20 = 7 / 60 a + b 3 days work = 7 / 60 * 3 = 7 / 20 remaining work = 1 - 7 / 20 = 13 / 20 answer is c | physics |
math_qa__uEiVsZ0XK1T2660G | How many positive integers between 100 and 500 are there such that they are multiples of 19? Choose one:
A) 10 B) 15 C) 21 D) 18 E) 19 | <gadget id="calculator">500 - 100</gadget>
<output>400</output>
<gadget id="calculator">400 / 19</gadget>
<output>400/19 = around 21.052632</output>
<result>C</result> | C | 21 | How many positive integers between 100 and 500 are there such that they are multiples of 19? | {
"A": "10",
"B": "15",
"C": "21",
"D": "18",
"E": "19"
} | divide(subtract(500, 100), 19) | subtract(n1,n0)|divide(#0,n2) | multiples of 19 = 114 , 133,152 , - - - - - , 494 number of multiples of 19 = > 494 - 114 / 19 + 1 = 21 answer is c | general |
math_qa__uVPynDiMdjDqhpMI | P says to Q "I am thrice as old as you were when i was as old as you are". If the sum of their present age is 100 years, then the present age of Q? Choose the correct choice:
A) 35.5
B) 36.5
C) 37.5
D) 38.5
E) 39.5 | <gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">300 / 8</gadget>
<output>75/2 = around 37.5</output>
<result>C</result> | C | 37.5 | P says to Q "I am thrice as old as you were when i was as old as you are". If the sum of their present age is 100 years, then the present age of Q? | {
"A": "35.5",
"B": "36.5",
"C": "37.5",
"D": "38.5",
"E": "39.5"
} | divide(multiply(100, const_3), subtract(multiply(const_3, const_3), const_1)) | multiply(n0,const_3)|multiply(const_3,const_3)|subtract(#1,const_1)|divide(#0,#2) | let the present age of q be x the age of q years back ( to be defined ) is x / 3 as the age of p will be x by then . years passed = x - x / 3 = 2 x / 3 ( subtracting age of q ) so p acurrent age is x + 2 x / 3 and q current age is x adding them to 100 we get x = 37.5 answer : c | general |
math_qa__nSKeAilNCnBM9R7B | In February Wilson’s earnings were 40 percent of his family’s total income. In March Wilson earned 25 percent less than in February. If the rest of his family’s income was the same in both months, then, in March, Wilson’s earnings were approximately what percent W of his family’s total income? Choose the correct option.
A) 15 %
B) 17 %
C) 24 %
D) 30 %
E) 33 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * (2/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(2/5) - (1/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(3/10) / (9/10)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33 | In February Wilson’s earnings were 40 percent of his family’s total income. In March Wilson earned 25 percent less than in February. If the rest of his family’s income was the same in both months, then, in March, Wilson’s earnings were approximately what percent W of his family’s total income? | {
"A": "15 %",
"B": "17 %",
"C": "24 %",
"D": "30 %",
"E": "33 %"
} | multiply(divide(subtract(divide(40, const_100), multiply(divide(25, const_100), divide(40, const_100))), subtract(const_1, multiply(divide(25, const_100), divide(40, const_100)))), const_100) | divide(n0,const_100)|divide(n1,const_100)|multiply(#1,#0)|subtract(#0,#2)|subtract(const_1,#2)|divide(#3,#4)|multiply(#5,const_100)| | "lets suppose the total family income in feb = 100 x wilson ' s earning in feb = 40 % of 100 x = 40 x earnings of remaining family in feb = 100 x - 40 x = 60 x wilson ' s earning in march = 75 % of wilson ' s feb earnings = 75 % of 40 x = 30 x earnings of remaining family in march = earnings of remaining family in feb = 60 x thus wilson ' s earning as % of total family income in march w = 30 x / ( 30 + 60 ) x = 30 x / 90 x = 33.33 % thus answer is e" | general |
math_qa__f3tvDG88OLXCXYY2 | A committee is reviewing a total of 20x black-and-white films and 6y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction R of the selected films are in color?
Choose the most appropriate option:
A) 1 / 130
B) 1 / 5
C) 3 / 13
D) 10 / 13
E) 30 / 31 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 6</gadget>
<output>31/5 = around 6.2</output>
<gadget id="calculator">6 / (31/5)</gadget>
<output>30/31 = around 0.967742</output>
<result>E</result> | E | 0.967742 | A committee is reviewing a total of 20x black-and-white films and 6y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction R of the selected films are in color? | {
"A": "1 / 130",
"B": "1 / 5",
"C": "3 / 13",
"D": "10 / 13",
"E": "30 / 31"
} | divide(6, add(divide(20, const_100), 6)) | divide(n0,const_100)|add(n1,#0)|divide(n1,#1)| | "it ' s y / xpercentnot y / x . if x = 20 and y = 10 . then : 20 x = 400 black - and - white films ; 6 y = 60 color films . y / x % = 10 / 20 % = 0.5 % of the black - and - white films , so 2 black - and - white films and all 60 color films , thus total of 62 films were selected . color films thus compose r = 60 / 62 = 30 / 31 of the selected films . answer : e ." | general |
math_qa__7I9LLbCgRGyIjdRj | In 110 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by: Choose one: A) 20 m B) 25 m C) 22 m D) 9 m E) 12 m | <gadget id="calculator">110 / 45</gadget>
<output>22/9 = around 2.444444</output>
<gadget id="calculator">45 - 36</gadget>
<output>9</output>
<gadget id="calculator">(22/9) * 9</gadget>
<output>22</output>
<result>C</result> | C | 22 | In 110 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by: | {
"A": "20 m",
"B": "25 m",
"C": "22 m",
"D": "9 m",
"E": "12 m"
} | multiply(divide(110, 45), subtract(45, 36)) | divide(n0,n2)|subtract(n2,n1)|multiply(#0,#1)| | "distance covered by b in 9 sec . = 110 / 45 x 9 m = 22 m . a beats b by 20 metres . answer : option c" | physics |
math_qa__oGbfJkMv9xx2ZPTG | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 16.9 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? Pick one:
A) 13.0
B) 13.3
C) 13.6
D) 13.9
E) 14.2 | <gadget id="calculator">16.9 / 10</gadget>
<output>1.69</output>
<gadget id="calculator">1.69 ** (1/2)</gadget>
<output>1.3</output>
<gadget id="calculator">1.3 * 10</gadget>
<output>13</output>
<result>A</result> | A | 13 | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 16.9 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? | {
"A": "13.0",
"B": "13.3",
"C": "13.6",
"D": "13.9",
"E": "14.2"
} | multiply(sqrt(divide(16.9, 10.0)), 10.0) | divide(n5,n2)|sqrt(#0)|multiply(#1,n2)| | "let x be the factor by which the bacteria increases every three hours . at 4 : 00 pm , the amount of bacteria was 10 x and at 7 : 00 pm it was 10 x ^ 2 . 10 x ^ 2 = 16.9 x ^ 2 = 1.69 x = 1.3 at 4 : 00 pm , the amount of bacteria was 10 ( 1.3 ) = 13 grams . the answer is a ." | general |
math_qa__y0GP1hzuhDz9iAul | A certain tax rate is $65 per $100.00. What is the rate, expressed as a percent? Choose the most appropriate option: A) 82 % B) 6.5 % C) 0.82 % D) 65 % E) 0.0065 % | <gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) * 100</gadget>
<output>65</output>
<result>D</result> | D | 65 | A certain tax rate is $65 per $100.00. What is the rate, expressed as a percent? | {
"A": "82 %",
"B": "6.5 %",
"C": "0.82 %",
"D": "65 %",
"E": "0.0065 %"
} | multiply(divide(65, 100), const_100) | divide(n0,n1)|multiply(#0,const_100) | here in question it is asking $ 65 is what percent of $ 100 . suppose $ 65 is x % of 100 means 100 * ( x / 100 ) = 65 hence x = 65 so answer is d | gain |
math_qa__NWOsPesiFVAnqido | What is the sum of the multiples of 4 between 53 and 145 inclusive?
Select the correct option
A) 2000
B) 2200
C) 2300
D) 2450
E) 2500 | <gadget id="calculator">145 - 3</gadget>
<output>142</output>
<gadget id="calculator">53 + 2</gadget>
<output>55</output>
<gadget id="calculator">142 + 55</gadget>
<output>197</output>
<gadget id="calculator">197 / 2</gadget>
<output>197/2 = around 98.5</output>
<gadget id="calculator">142 - 55</gadget>
<output>87</output>
<gadget id="calculator">87 / 4</gadget>
<output>87/4 = around 21.75</output>
<gadget id="calculator">(87/4) + 1</gadget>
<output>91/4 = around 22.75</output>
<gadget id="calculator">(197/2) * (91/4)</gadget>
<output>17_927/8 = around 2_240.875</output>
<result>C</result> | C | 2,300 | What is the sum of the multiples of 4 between 53 and 145 inclusive? | {
"A": "2000",
"B": "2200",
"C": "2300",
"D": "2450",
"E": "2500"
} | multiply(divide(add(subtract(145, const_3), add(53, const_2)), const_2), add(divide(subtract(subtract(145, const_3), add(53, const_2)), 4), const_1)) | add(n1,const_2)|subtract(n2,const_3)|add(#0,#1)|subtract(#1,#0)|divide(#3,n0)|divide(#2,const_2)|add(#4,const_1)|multiply(#6,#5)| | "the fastest way in an ap is to find the average and multiply with total integers . . between 53 and 145 , the smallest multiple of 4 is 56 and largest = 144 . . average = ( 56 + 144 ) / 2 = 100 . . total numbers = ( 144 - 56 ) / 4 + 1 = 22 + 1 = 23 . . sum = 23 * 100 = 2300 ans c" | general |
math_qa__ennhoyj8BqYfRuiM | The simple Interest on a certain sum of money at the rate of 4% p.a. for 5 years is Rs. 1680. At what rate of interest the same amount of interest can be received on the same sum after 4 years ? Select the correct option
A) 5 % B) 6 % C) 7 % D) 8 % E) 9 % | <gadget id="calculator">1_680 / 4</gadget>
<output>420</output>
<gadget id="calculator">1_680 / 5</gadget>
<output>336</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">336 / (1/25)</gadget>
<output>8_400</output>
<gadget id="calculator">420 / 8_400</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<result>A</result> | A | 5 | The simple Interest on a certain sum of money at the rate of 4% p.a. for 5 years is Rs. 1680. At what rate of interest the same amount of interest can be received on the same sum after 4 years ? | {
"A": "5 %",
"B": "6 %",
"C": "7 %",
"D": "8 %",
"E": "9 %"
} | multiply(divide(divide(1680, 4), divide(divide(1680, 5), divide(4, const_100))), const_100) | divide(n2,n0)|divide(n2,n1)|divide(n0,const_100)|divide(#1,#2)|divide(#0,#3)|multiply(#4,const_100) | s . i . = 1680 , r = 4 % t = 5 years principal = ( 100 * 1680 ) / ( 5 * 4 ) = 8400 so p = 8400 rate = ( 100 * 1680 ) / ( 8400 * 4 ) = 5 % answer : a | gain |
math_qa__rCd3Bg7bLR3PLY9X | The edge of a cube is 6a cm. Find its surface?
Options:
A) 216 a 2
B) 24 a 4
C) 24 a 1
D) 24 a 2
E) 24 a 7 | <gadget id="calculator">6 * (6 ** 2)</gadget>
<output>216</output>
<result>A</result> | A | 216 | The edge of a cube is 6a cm. Find its surface? | {
"A": "216 a 2",
"B": "24 a 4",
"C": "24 a 1",
"D": "24 a 2",
"E": "24 a 7"
} | surface_cube(6) | surface_cube(n0)| | "6 a 2 = 6 * 6 a * 6 a = 216 a 2 answer : a" | geometry |
math_qa__TCMVZO1X3E1BI8SB | If (1/2)^25 (1/81)^k = 1/18^25, then k =
Options
A) 8 B) 12.5 C) 16 D) 24 E) 36 | <gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 4</gadget>
<output>25/2 = around 12.5</output>
<result>B</result> | B | 12.5 | If (1/2)^25 (1/81)^k = 1/18^25, then k = | {
"A": "8",
"B": "12.5",
"C": "16",
"D": "24",
"E": "36"
} | divide(multiply(25, 2), const_4) | multiply(n1,n2)|divide(#0,const_4)| | "i ' m going to focus on denominator only . . ( 2 ^ 25 ) . ( ( 3 ^ 4 ) ^ k = 18 ^ 25 ( 2 ^ 25 ) . ( ( 3 ^ 4 k ) = ( 2 . 3 ^ 2 ) ^ 25 ( 2 ^ 25 ) . ( ( 3 ^ 4 k ) = ( 2 ^ 25 ) . ( 3 ^ 2 ) ^ 25 hence 4 k = 50 k = 12,5 answer b i hope it ' s quite clear" | general |
math_qa__aMckMLumKF3tlD8S | 180 metres long yard, 11 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees Choose the correct option
A) 18 B) 12 C) 14 D) 16 E) 17 | <gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">180 / 10</gadget>
<output>18</output>
<result>A</result> | A | 18 | 180 metres long yard, 11 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees | {
"A": "18",
"B": "12",
"C": "14",
"D": "16",
"E": "17"
} | divide(180, add(subtract(11, 2), const_1)) | subtract(n1,n2)|add(#0,const_1)|divide(n0,#1)| | "11 trees have 10 gaps between them , required distance ( 180 / 10 ) = 18 a" | physics |
math_qa__pqckKyb0ab3TRb0P | If it is assumed that 70 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed? Select.
A) 400
B) 428.5
C) 480
D) 500
E) 600 | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">300 / (7/10)</gadget>
<output>3_000/7 = around 428.571429</output>
<result>B</result> | B | 428.5 | If it is assumed that 70 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed? | {
"A": "400",
"B": "428.5",
"C": "480",
"D": "500",
"E": "600"
} | divide(300, divide(70, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "minimum no of mail to be sent for getting 300 responses at 70 % = 300 / 0.7 = 428.5 option b" | gain |
math_qa__V6OM7zPDCuQ9IaJC | The difference between a positive proper fraction and its reciprocal is 9/20. The fraction is?
Select.
A) 4 / 5 B) 4 / 7 C) 5 D) 5 / 7 E) none | <gadget id="calculator">9 - 4</gadget>
<output>5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<result>A</result> | A | 0.8 | The difference between a positive proper fraction and its reciprocal is 9/20. The fraction is? | {
"A": "4 / 5",
"B": "4 / 7",
"C": "5",
"D": "5 / 7",
"E": "none"
} | divide(const_4, subtract(9, const_4)) | subtract(n0,const_4)|divide(const_4,#0)| | "let the required fraction be x . then 1 - x = 9 x 20 1 - x 2 = 9 x 20 20 - 20 x 2 = 9 x 20 x 2 + 9 x - 20 = 0 20 x 2 + 25 x - 16 x - 20 = 0 5 x ( 4 x + 5 ) - 4 ( 4 x + 5 ) = 0 ( 4 x + 5 ) ( 5 x - 4 ) = 0 x = 4 / 5 option a" | general |
math_qa__ETNuh9BIfTK8miUH | A man can swim in still water at 1.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is? Pick one:
A) 1.7 B) 0.5 C) 1.1 D) 1.5 E) 1.9 | <gadget id="calculator">1.5 / 3</gadget>
<output>0.5</output>
<result>B</result> | B | 0.5 | A man can swim in still water at 1.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is? | {
"A": "1.7",
"B": "0.5",
"C": "1.1",
"D": "1.5",
"E": "1.9"
} | divide(1.5, const_3) | divide(n0,const_3)| | "m = 1.5 s = x ds = 1.5 + x us = 1.5 + x 1.5 + x = ( 1.5 - x ) 2 1.5 + x = 3 - 2 x 3 x = 1.5 x = 0.5 answer : b" | general |
math_qa__kYgjidMmj0dCKnpk | A car is purchased on hire-purchase. The cash price is $25 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly installments. Interest is charged at 12% p.a. What is the monthly installment? Select.
A) $ 500 B) $ 504 C) $ 505 D) $ 560 E) $ 600 | <gadget id="calculator">25 * 1_000</gadget>
<output>25_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">25_000 * (9/10)</gadget>
<output>22_500</output>
<gadget id="calculator">22_500 / 60</gadget>
<output>375</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) / 12</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 22_500</gadget>
<output>225</output>
<gadget id="calculator">375 + 225</gadget>
<output>600</output>
<result>E</result> | E | 600 | A car is purchased on hire-purchase. The cash price is $25 000 and the terms are a deposit of 10% of the price, then the balance to be paid off over 60 equal monthly installments. Interest is charged at 12% p.a. What is the monthly installment? | {
"A": "$ 500",
"B": "$ 504",
"C": "$ 505",
"D": "$ 560",
"E": "$ 600"
} | add(divide(multiply(multiply(25, const_1000), subtract(const_1, divide(10, const_100))), 60), multiply(divide(divide(12, const_100), 12), multiply(multiply(25, const_1000), subtract(const_1, divide(10, const_100))))) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_1000)|divide(#1,n4)|subtract(const_1,#0)|multiply(#2,#4)|divide(#5,n3)|multiply(#3,#5)|add(#6,#7)| | "explanation : cash price = $ 25 000 deposit = 10 % ã — $ 25 000 = $ 2500 loan amount = $ 25000 â ˆ ’ $ 2500 number of payments = 60 = $ 22500 i = p * r * t / 100 i = 13500 total amount = 22500 + 13500 = $ 36000 regular payment = total amount / number of payments = 600 answer : e" | gain |
math_qa__PdzLs26VziedA1Nj | A jar contains 5 black and 2 white balls. If you pick two balls at the same time, what's the probability that one ball is black and one is white? Choose the correct choice from the following options:
A) 2 / 7
B) 5 / 21
C) 4 / 21
D) 3 / 7
E) 1 / 2 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(5/7) * (1/3)</gadget>
<output>5/21 = around 0.238095</output>
<result>B</result> | B | 0.238095 | A jar contains 5 black and 2 white balls. If you pick two balls at the same time, what's the probability that one ball is black and one is white? | {
"A": "2 / 7",
"B": "5 / 21",
"C": "4 / 21",
"D": "3 / 7",
"E": "1 / 2"
} | multiply(divide(5, add(5, 2)), divide(2, subtract(add(5, 2), const_1))) | add(n0,n1)|divide(n0,#0)|subtract(#0,const_1)|divide(n1,#2)|multiply(#1,#3) | p ( 1 st black , 2 nd white ) = 5 / 7 * 2 / 6 = 10 / 42 ; p ( 1 st white , 2 nd black ) = 2 / 7 * 5 / 6 = 10 / 42 . p = 10 / 42 + 10 / 42 = 20 / 84 = 10 / 42 = 5 / 21 answer : b . | probability |
math_qa__72LKMJkHQzYVsIH3 | There are 2 more women than there are men on a local co-ed softball team. If there are a total of 16 players on the team, what is the ratio of men to women? Choose the correct choice from the following
A) 10 / 16 B) 6 / 16 C) 4 / 16 D) 7 / 9 E) 4 / 10 | <gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>
<result>D</result> | D | 0.777778 | There are 2 more women than there are men on a local co-ed softball team. If there are a total of 16 players on the team, what is the ratio of men to women? | {
"A": "10 / 16",
"B": "6 / 16",
"C": "4 / 16",
"D": "7 / 9",
"E": "4 / 10"
} | divide(divide(subtract(16, 2), add(const_1, const_1)), add(divide(subtract(16, 2), add(const_1, const_1)), 2)) | add(const_1,const_1)|subtract(n1,n0)|divide(#1,#0)|add(n0,#2)|divide(#2,#3)| | "w = m + 2 w + m = 16 m + 2 + m = 16 2 m = 14 m = 7 w = 9 ratio : 7 : 9 ans : d" | general |
math_qa__lQrpevdi3SO49f9Q | The regular price per can of a certain brand of soda is $0.40. If the regular price per can is discounted 15 percent when the soda is purchased in 24-can cases, what is the price of 100 cans of this brand of soda purchased in 24-can cases? Options:
A) $ 16.32 B) $ 18.00 C) $ 21.60 D) $ 34 E) $ 28.80 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">0.4 * 100</gadget>
<output>40</output>
<gadget id="calculator">(17/20) * 40</gadget>
<output>34</output>
<result>D</result> | D | 34 | The regular price per can of a certain brand of soda is $0.40. If the regular price per can is discounted 15 percent when the soda is purchased in 24-can cases, what is the price of 100 cans of this brand of soda purchased in 24-can cases? | {
"A": "$ 16.32",
"B": "$ 18.00",
"C": "$ 21.60",
"D": "$ 34",
"E": "$ 28.80"
} | multiply(divide(subtract(const_100, 15), const_100), multiply(0.40, 100)) | multiply(n0,n3)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#2,#0)| | "the discounted price of one can of soda is ( 0.85 ) ( $ 0.40 ) , or $ 0.34 . therefore , the price of 72 cans of soda at the discounted price would be ( 100 ) ( $ 0.34 ) = 34 answer : d ." | gain |
math_qa__FqADvZdHlkxrWD3T | A lady has fine gloves and hats in her closet- 18 blue, 32 red, and 25 yellow. The lights are out and it is totally dark. In spite of the darkness, she can make out the difference between a hat and a glove. She takes out an item out of the closet only if she is sure that if it is a glove. How many gloves must she take out to make sure she has a pair of each color?
Pick.
A) 50 B) 8 C) 60 D) 42 E) 32 | <gadget id="calculator">25 + 32</gadget>
<output>57</output>
<gadget id="calculator">57 + 2</gadget>
<output>59</output>
<result>C</result> | C | 60 | A lady has fine gloves and hats in her closet- 18 blue, 32 red, and 25 yellow. The lights are out and it is totally dark. In spite of the darkness, she can make out the difference between a hat and a glove. She takes out an item out of the closet only if she is sure that if it is a glove. How many gloves must she take out to make sure she has a pair of each color? | {
"A": "50",
"B": "8",
"C": "60",
"D": "42",
"E": "32"
} | add(add(25, 32), const_2) | add(n1,n2)|add(#0,const_2) | in the first case the lady takes up 32 red colour then he takes up 24 y ( cause he should take up pair ) then he takes up 1 y + 1 blue then 2 blue ( cause to make sure he has a pair of each color in hand ) 32 + 24 + 2 + 2 = 60 answer : c | general |
math_qa__aJAuEvEirl4LJOqM | In a 2000 census, 51.27% of the population are male, and 48.73% are female. What is the ratio of men to every 100 women? Choose the correct choice:
A) 110 : 100 B) 105 : 100 C) 95 : 100 D) 85 : 100 E) 120 : 100 | <gadget id="calculator">51.27 / 48.73</gadget>
<output>1.052124</output>
<result>B</result> | B | 1.05 | In a 2000 census, 51.27% of the population are male, and 48.73% are female. What is the ratio of men to every 100 women? | {
"A": "110 : 100",
"B": "105 : 100",
"C": "95 : 100",
"D": "85 : 100",
"E": "120 : 100"
} | divide(51.27, 48.73) | divide(n1,n2) | the ratio of a to b , where a = the percent of males , and b = the percent of females . a = 51.27 b = 48.73 a : b = 51.27 : 48.73 so , 100 ( 5,127 / 4,873 ) : 100 giving a male to female ratio of 105.20 men for every 100 women . answer is b | other |
math_qa__KQ4EtY7TJ0cgl97q | The radius of a semi circle is 14 cm then its perimeter is?
Choose the correct choice from the following answers:
A) 32.8 B) 32.4 C) 72 D) 32.2 E) 32.9 | <gadget id="calculator">2 * pi * 14</gadget>
<output>28*pi = around 87.964594</output>
<gadget id="calculator">(28*pi) / 2</gadget>
<output>14*pi = around 43.982297</output>
<gadget id="calculator">14 * 2</gadget>
<output>28</output>
<gadget id="calculator">(14*pi) + 28</gadget>
<output>28 + 14*pi = around 71.982297</output>
<result>C</result> | C | 72 | The radius of a semi circle is 14 cm then its perimeter is? | {
"A": "32.8",
"B": "32.4",
"C": "72",
"D": "32.2",
"E": "32.9"
} | add(divide(circumface(14), const_2), multiply(14, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "diameter = 28 cm 1 / 2 * 22 / 7 * 28 + 28 = 72 answer : c" | physics |
math_qa__2sjJYIm4aYD8duKj | A large field of 900 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares? Choose the correct option:
A) 435 hectares . B) 425 hectares . C) 445 hectares . D) 415 hectares . E) 405 hectares . | <gadget id="calculator">900 / 2</gadget>
<output>450</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">450 * (1/5)</gadget>
<output>90</output>
<gadget id="calculator">900 - 90</gadget>
<output>810</output>
<gadget id="calculator">810 / 2</gadget>
<output>405</output>
<result>E</result> | E | 405 | A large field of 900 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares? | {
"A": "435 hectares .",
"B": "425 hectares .",
"C": "445 hectares .",
"D": "415 hectares .",
"E": "405 hectares ."
} | divide(subtract(900, multiply(divide(900, const_2), divide(const_1, add(const_1, const_4)))), const_2) | add(const_1,const_4)|divide(n0,const_2)|divide(const_1,#0)|multiply(#1,#2)|subtract(n0,#3)|divide(#4,const_2)| | "let the areas of the parts be x hectares and ( 900 - x ) hectares . difference of the areas of the two parts = x - ( 900 - x ) = 2 x - 900 one - fifth of the average of the two areas = 1 / 5 [ x + ( 900 − x ) ] / 2 = 1 / 5 × ( 900 / 2 ) = 450 / 5 = 90 given that difference of the areas of the two parts = one - fifth of the average of the two areas = > 2 x - 900 = 90 = > 2 x = 990 ⇒ x = 990 / 2 = 495 hence , area of smaller part = ( 900 - x ) = ( 900 – 495 ) = 405 hectares . answer is e ." | general |
math_qa__n4xNW1yzPGrjQ5zB | 15 men work 8 hours per day to complete the work in 10 days. To complete the same work in 8 days, working 15 hours a day, the number of men required? Choose the correct choice from the following answers:
A) 10 days B) 11 days C) 9 days D) 8 days E) 12 days | <gadget id="calculator">15 * 10</gadget>
<output>150</output>
<gadget id="calculator">150 * 8</gadget>
<output>1_200</output>
<gadget id="calculator">8 * 15</gadget>
<output>120</output>
<gadget id="calculator">1_200 / 120</gadget>
<output>10</output>
<result>A</result> | A | 10 | 15 men work 8 hours per day to complete the work in 10 days. To complete the same work in 8 days, working 15 hours a day, the number of men required? | {
"A": "10 days",
"B": "11 days",
"C": "9 days",
"D": "8 days",
"E": "12 days"
} | divide(multiply(multiply(15, 10), 8), multiply(8, 15)) | multiply(n0,n2)|multiply(n3,n4)|multiply(n1,#0)|divide(#2,#1)| | "that is , 1 work done = 15 × 8 × 10 then , 12 8 × 10 = ? × 15 × 8 ? ( i . e . no . of men required ) = 15 × 8 × 10 / 15 × 8 = 10 days a )" | physics |
math_qa__0k1SBRLuRHngWt0W | A factory produces 4560 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? Choose the correct choice from the following choices
A) 1140 toys B) 2375 toys C) 3375 toys D) 4375 toys E) 5375 toys | <gadget id="calculator">4_560 / 4</gadget>
<output>1_140</output>
<result>A</result> | A | 1,140 | A factory produces 4560 toys per week. If the workers at this factory work 4 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? | {
"A": "1140 toys",
"B": "2375 toys",
"C": "3375 toys",
"D": "4375 toys",
"E": "5375 toys"
} | divide(4560, 4) | divide(n0,n1)| | "to find the number of toys produced every day , we divide the total number of toys produced in one week ( of 4 days ) by 4 . 4560 / 4 = 1140 toys correct answer a" | physics |
math_qa__L0cOm5sizhfi63EW | A batsman makes a score of 82 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning? Choose the correct choice
A) 25
B) 31
C) 27
D) 29
E) 34 | <gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">82 - 51</gadget>
<output>31</output>
<gadget id="calculator">31 + 3</gadget>
<output>34</output>
<result>E</result> | E | 34 | A batsman makes a score of 82 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning? | {
"A": "25",
"B": "31",
"C": "27",
"D": "29",
"E": "34"
} | add(subtract(82, multiply(17, 3)), 3) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "let the average after 17 innings = x total runs scored in 17 innings = 17 x average after 16 innings = ( x - 3 ) total runs scored in 16 innings = 16 ( x - 3 ) total runs scored in 16 innings + 82 = total runs scored in 17 innings = > 16 ( x - 3 ) + 82 = 17 x = > 16 x - 48 + 82 = 17 x = > x = 34 answer is e ." | general |
math_qa__hxSo9dqjz9qDAMJk | The length of a rectangle is reduced by 30%. By what % would the width have to be increased to maintain the original area? Pick one.
A) 42.8 % B) 20 % C) 25 % D) 30 % E) 35 % | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 - (7/10)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) / (7/10)</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 100</gadget>
<output>300/7 = around 42.857143</output>
<result>A</result> | A | 42.8 | The length of a rectangle is reduced by 30%. By what % would the width have to be increased to maintain the original area? | {
"A": "42.8 %",
"B": "20 %",
"C": "25 %",
"D": "30 %",
"E": "35 %"
} | multiply(divide(subtract(const_1, divide(subtract(const_100, 30), const_100)), divide(subtract(const_100, 30), const_100)), const_100) | subtract(const_100,n0)|divide(#0,const_100)|subtract(const_1,#1)|divide(#2,#1)|multiply(#3,const_100)| | "sol . required change = ( 30 * 100 ) / ( 100 - 30 ) = 42.8 % a" | geometry |
math_qa__Z0HNNLPUdwTu1yU0 | What is the remainder if 7^4 is divided by 100? Choose the correct choice
A) 5
B) 4
C) 1
D) 2
E) 10 | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">50 - 49</gadget>
<output>1</output>
<result>C</result> | C | 1 | What is the remainder if 7^4 is divided by 100? | {
"A": "5",
"B": "4",
"C": "1",
"D": "2",
"E": "10"
} | subtract(divide(100, const_2), multiply(7, 7)) | divide(n2,const_2)|multiply(n0,n0)|subtract(#0,#1)| | "7 * 7 * 7 * 7 / 100 = 2401 / 100 = 24 reminder 1 answer : c" | general |
math_qa__GDiYRVOiUK0zULBb | Find value of X: (422+404)^2−(4×422×404)=X. Choose the correct choice from the following answers:
A) 234 B) 267 C) 324 D) 356 E) 577 | <gadget id="calculator">422 + 404</gadget>
<output>826</output>
<gadget id="calculator">826 ** 2</gadget>
<output>682_276</output>
<gadget id="calculator">4 * 422</gadget>
<output>1_688</output>
<gadget id="calculator">1_688 * 404</gadget>
<output>681_952</output>
<gadget id="calculator">682_276 - 681_952</gadget>
<output>324</output>
<result>C</result> | C | 324 | Find value of X: (422+404)^2−(4×422×404)=X. | {
"A": "234",
"B": "267",
"C": "324",
"D": "356",
"E": "577"
} | subtract(power(add(422, 404), const_2), multiply(multiply(4, 422), 404)) | add(n0,n1)|multiply(n0,n3)|multiply(n1,#1)|power(#0,const_2)|subtract(#3,#2) | given equation is in the form ( a + b ) 2 − 4 ab where a = 422 and b = 404 hence answer = ( a + b ) 2 − 4 ab = ( a − b ) 2 = ( 422 − 404 ) 2 = 182 = 324 c | general |
math_qa__3ZniycoayNc1MvMp | After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6400. Find the actual price of the good. Choose the correct choice from the following: A) s . 6000 B) s . 9000 C) s . 10800 D) s . 9357 E) s . 9980 | <gadget id="calculator">6_400 * 100</gadget>
<output>640_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 * 10</gadget>
<output>800</output>
<gadget id="calculator">800 / 100</gadget>
<output>8</output>
<gadget id="calculator">80 - 8</gadget>
<output>72</output>
<gadget id="calculator">72 * 5</gadget>
<output>360</output>
<gadget id="calculator">360 / 100</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">72 - (18/5)</gadget>
<output>342/5 = around 68.4</output>
<gadget id="calculator">640_000 / (342/5)</gadget>
<output>1_600_000/171 = around 9_356.725146</output>
<result>D</result> | D | 9,357 | After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6400. Find the actual price of the good. | {
"A": "s . 6000",
"B": "s . 9000",
"C": "s . 10800",
"D": "s . 9357",
"E": "s . 9980"
} | divide(multiply(6400, const_100), subtract(subtract(subtract(const_100, 20), divide(multiply(subtract(const_100, 20), 10), const_100)), divide(multiply(subtract(subtract(const_100, 20), divide(multiply(subtract(const_100, 20), 10), const_100)), 5), const_100))) | multiply(n3,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,const_100)|subtract(#1,#3)|multiply(n2,#4)|divide(#5,const_100)|subtract(#4,#6)|divide(#0,#7)| | "let actual price was 100 . after three successive discount this will become , 100 = = 20 % discount = > 80 = = 10 % discount = > 72 = = 5 % discount = 68.4 now compare , 68.4 = 6400 1 = 6400 / 68.4 100 = ( 6400 * 100 ) / 68.4 = rs . 9357 . answer : option d" | gain |
math_qa__ZjU3BJ7ngu7fcRDl | X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.14080 ?
Choose the correct choice
A) 3200 B) 4000 C) 3250 D) 3825 E) 4096 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">48_000 * 8</gadget>
<output>384_000</output>
<gadget id="calculator">36_000 * 12</gadget>
<output>432_000</output>
<gadget id="calculator">42_000 * 12</gadget>
<output>504_000</output>
<gadget id="calculator">432_000 + 504_000</gadget>
<output>936_000</output>
<gadget id="calculator">936_000 + 384_000</gadget>
<output>1_320_000</output>
<gadget id="calculator">14_080 / 1_320_000</gadget>
<output>4/375 = around 0.010667</output>
<gadget id="calculator">384_000 * (4/375)</gadget>
<output>4_096</output>
<result>E</result> | E | 4,096 | X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.14080 ? | {
"A": "3200",
"B": "4000",
"C": "3250",
"D": "3825",
"E": "4096"
} | multiply(multiply(48000, subtract(multiply(const_3, 4), 4)), divide(14080, add(add(multiply(36000, multiply(const_3, 4)), multiply(42000, multiply(const_3, 4))), multiply(48000, subtract(multiply(const_3, 4), 4))))) | multiply(const_3,n2)|multiply(n0,#0)|multiply(n1,#0)|subtract(#0,n2)|add(#1,#2)|multiply(n3,#3)|add(#4,#5)|divide(n4,#6)|multiply(#7,#5)| | "ratio of investment , as investments is for different time . investment x number of units of time . ratio of investments x : y : z = 36000 : 42000 : 48000 = > 6 : 7 : 8 . x = 6 x 12 months = 72 , y = 7 x 12 = 84 , z = 8 x 8 = 64 = > 18 : 21 : 16 . ratio of investments = > x : y : z = 18 : 21 : 16 . investment ratio = profit sharing ratio . z = 14080 ã — 16 / 55 = rs . 4096 . share of z in the profit is rs . 4096 . option e" | gain |
math_qa__mHgBvn4kFF1xfh7i | 6) A marketing firm determined that , of 160 households surveyed, 80 used neither Brand A nor Brand B soap.60 used only Brand A soap and for every household that used both brands of soap, 3 used only brand B soap.how many of the 200 household surveyed used both brands of soap? Choose the correct choice from the following answers.
A) 15 B) 20 C) 30 D) 40 E) 5 | <gadget id="calculator">160 - 80</gadget>
<output>80</output>
<gadget id="calculator">80 - 60</gadget>
<output>20</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<result>E</result> | E | 5 | 6) A marketing firm determined that , of 160 households surveyed, 80 used neither Brand A nor Brand B soap.60 used only Brand A soap and for every household that used both brands of soap, 3 used only brand B soap.how many of the 200 household surveyed used both brands of soap? | {
"A": "15",
"B": "20",
"C": "30",
"D": "40",
"E": "5"
} | divide(subtract(subtract(160, 80), 60), const_4) | subtract(n1,n2)|subtract(#0,n3)|divide(#1,const_4)| | "80 = at least one of soap a or b both brands = x brand b = 3 x = > 60 + x + 3 x = 120 = > 4 x = 20 = > x = 5 answer - e" | other |
math_qa__SwB9YZAweZ1Hf1nv | Every disk in a bag is either blue, yellow or green. The ratio of blue disks to yellow disks to green disks in this bag is 3 : 7 : 8. If the total number of disks in the bag is 54, how many more green disks than blue disks are in the bag? Choose the correct choice from the following options
A) 15 B) 25 C) 30 D) 35 E) 40 | <gadget id="calculator">3 + 7</gadget>
<output>10</output>
<gadget id="calculator">10 + 8</gadget>
<output>18</output>
<gadget id="calculator">54 / 18</gadget>
<output>3</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<result>A</result> | A | 15 | Every disk in a bag is either blue, yellow or green. The ratio of blue disks to yellow disks to green disks in this bag is 3 : 7 : 8. If the total number of disks in the bag is 54, how many more green disks than blue disks are in the bag? | {
"A": "15",
"B": "25",
"C": "30",
"D": "35",
"E": "40"
} | multiply(divide(54, add(add(3, 7), 8)), subtract(8, 3)) | add(n0,n1)|subtract(n2,n0)|add(n2,#0)|divide(n3,#2)|multiply(#3,#1)| | "let b : y : g = 3 x : 7 x : 8 x . 3 x + 7 x + 8 x = 18 x = 54 - - > x = 3 . g - b = 8 x - 3 x = 5 x = 15 . the answer is a ." | general |
math_qa__07QgLRDHEAxGFzxn | among 250 viewers interviewed who watch at least one of the 3 tv channels namely a , bc . 116 watch a , 127 watch c , while 107 watch b . if 90 watch exactly two channels . how many watch exactly one channel ? Answers:
A) 155 B) 160 C) 175 D) 190 E) 195 | <gadget id="calculator">250 - 90</gadget>
<output>160</output>
<gadget id="calculator">116 + 127</gadget>
<output>243</output>
<gadget id="calculator">243 + 107</gadget>
<output>350</output>
<gadget id="calculator">350 - 90</gadget>
<output>260</output>
<gadget id="calculator">260 - 250</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">160 - 5</gadget>
<output>155</output>
<result>A</result> | A | 155 | among 250 viewers interviewed who watch at least one of the 3 tv channels namely a , bc . 116 watch a , 127 watch c , while 107 watch b . if 90 watch exactly two channels . how many watch exactly one channel ? | {
"A": "155",
"B": "160",
"C": "175",
"D": "190",
"E": "195"
} | subtract(subtract(250, 90), divide(subtract(subtract(add(add(116, 127), 107), 90), 250), const_2)) | add(n2,n3)|subtract(n0,n5)|add(n4,#0)|subtract(#2,n5)|subtract(#3,n0)|divide(#4,const_2)|subtract(#1,#5) | 250 = n ( exactly 1 channel ) + n ( exactly 2 channels ) + n ( exactly 3 channels ) 250 = n ( exactly 1 channel ) + 90 + n ( exactly 3 channels ) let ' s find the value of n ( exactly 3 channels ) = x 250 = n ( a ) + n ( b ) + n ( c ) - n ( a and b ) - n ( b and c ) - n ( c and a ) + n ( a and b and c ) note that each of n ( a and b ) is the sum of ' number of people watching exactly two channels a and b ' and ' number of people watching all three channels ' . 250 = 116 + 127 + 107 - n ( exactly 2 channels ) - 3 x + x 250 = 116 + 127 + 107 - 90 - 2 x x = 25 250 = n ( exactly 1 channel ) + 90 + 25 n ( exactly 1 channel ) = 155 answer ( a ) | general |
math_qa__m06WmZzuwSCZhdNm | Some of 50%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced? Select the correct option:
A) 1 / 30
B) 1 / 5
C) 2 / 3
D) 3 / 4
E) 4 / 5 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/10) - (1/2)</gadget>
<output>-1/5 = around -0.2</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) - (1/2)</gadget>
<output>-1/4 = around -0.25</output>
<gadget id="calculator">(-1/5) / (-1/4)</gadget>
<output>4/5 = around 0.8</output>
<result>E</result> | E | 0.8 | Some of 50%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced? | {
"A": "1 / 30",
"B": "1 / 5",
"C": "2 / 3",
"D": "3 / 4",
"E": "4 / 5"
} | divide(subtract(divide(30, const_100), divide(50, const_100)), subtract(divide(25, const_100), divide(50, const_100))) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(#2,#1)|divide(#3,#4)| | "let total paint = 1 let amount replaced = x 50 ( 1 - x ) + 25 x = 30 x = 4 / 5 answer : e" | gain |
math_qa__i1kF3voWlDYJ84U8 | 9 spheres of the same size are made from melting a solid cylinder of 8 cm diameter and 48 cm height. What is the diameter of each sphere? Pick:
A) 4 cm
B) 6 cm
C) 8 cm
D) 10 cm
E) 12 cm | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">pi * (4 ** 2) * 48</gadget>
<output>768*pi = around 2_412.743158</output>
<gadget id="calculator">(768*pi) / pi</gadget>
<output>768</output>
<gadget id="calculator">768 * 3</gadget>
<output>2_304</output>
<gadget id="calculator">2_304 / 4</gadget>
<output>576</output>
<gadget id="calculator">576 / 9</gadget>
<output>64</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>C</result> | C | 8 | 9 spheres of the same size are made from melting a solid cylinder of 8 cm diameter and 48 cm height. What is the diameter of each sphere? | {
"A": "4 cm",
"B": "6 cm",
"C": "8 cm",
"D": "10 cm",
"E": "12 cm"
} | multiply(divide(divide(divide(divide(multiply(divide(volume_cylinder(divide(8, const_2), 48), const_pi), const_3), const_4), 9), const_4), const_4), const_2) | divide(n1,const_2)|volume_cylinder(#0,n2)|divide(#1,const_pi)|multiply(#2,const_3)|divide(#3,const_4)|divide(#4,n0)|divide(#5,const_4)|divide(#6,const_4)|multiply(#7,const_2)| | "volume of cylinder = pi * r ^ 2 * h volume of a sphere = 4 * pi * r ^ 3 / 3 9 * 4 * pi * r ^ 3 / 3 = pi * r ^ 2 * h r ^ 3 = r ^ 2 * h / 12 = 64 cm ^ 3 r = 4 cm d = 8 cm the answer is c ." | physics |
math_qa__FXgm6za8UcImXvaF | Working simultaneously and independently at an identical constant rate, 6 machines of a certain type can produce a total of x units of product P in 5 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 4x units of product P in 10 days?
Choose one
A) 9 B) 10 C) 12 D) 14 E) 18 | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">24 * (1/2)</gadget>
<output>12</output>
<result>C</result> | C | 12 | Working simultaneously and independently at an identical constant rate, 6 machines of a certain type can produce a total of x units of product P in 5 days. How many of these machines, working simultaneously and independently at this constant rate, can produce a total of 4x units of product P in 10 days? | {
"A": "9",
"B": "10",
"C": "12",
"D": "14",
"E": "18"
} | multiply(multiply(6, 4), divide(5, 10)) | divide(n1,n3)|multiply(n0,n2)|multiply(#0,#1)| | "the rate of 6 machines is rate = job / time = x / 5 units per day - - > the rate of 1 machine 1 / 6 * ( x / 5 ) = x / 30 units per day ; now , again as { time } * { combined rate } = { job done } then 10 * ( m * x / 30 ) = 4 x - - > m = 12 . answer : c ." | general |
math_qa__zetJAYwFouKtnddD | A boat goes 100 km downstream in 4 hours, and 75 Km upstream in 15 hours. The speed of the stream is? Choose the correct choice from the following choices
A) 10
B) 20
C) 25
D) 35
E) 15 | <gadget id="calculator">100 / 4</gadget>
<output>25</output>
<gadget id="calculator">75 / 15</gadget>
<output>5</output>
<gadget id="calculator">25 - 5</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>A</result> | A | 10 | A boat goes 100 km downstream in 4 hours, and 75 Km upstream in 15 hours. The speed of the stream is? | {
"A": "10",
"B": "20",
"C": "25",
"D": "35",
"E": "15"
} | divide(subtract(divide(100, 4), divide(75, 15)), const_2) | divide(n0,n1)|divide(n2,n3)|subtract(#0,#1)|divide(#2,const_2)| | "100 - - - 10 ds = 25 ? - - - - 1 75 - - - - 15 us = 5 ? - - - - - 1 s = ( 25 - 5 ) / 2 = 10 kmph . answer : a" | physics |
math_qa__1llhaLpQR3xLwS8S | Along a road lie an odd number of stones placed at intervals of 10m. These stones have to be assembled around the middle stone. A person can carry only one stone at a time. A man carried out the job starting with the stone in the middle, carrying stones in succession, thereby covering a distance of 4.8 km. Then the number of stones is Choose the correct choice from the following answers:
A) 35 B) 15 C) 29 D) 31 E) 29 | <gadget id="calculator">4.8 * 1_000</gadget>
<output>4_800</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">4_800 / 40</gadget>
<output>120</output>
<gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">240 / 16</gadget>
<output>15</output>
<gadget id="calculator">15 * 2</gadget>
<output>30</output>
<gadget id="calculator">30 + 1</gadget>
<output>31</output>
<result>D</result> | D | 31 | Along a road lie an odd number of stones placed at intervals of 10m. These stones have to be assembled around the middle stone. A person can carry only one stone at a time. A man carried out the job starting with the stone in the middle, carrying stones in succession, thereby covering a distance of 4.8 km. Then the number of stones is | {
"A": "35",
"B": "15",
"C": "29",
"D": "31",
"E": "29"
} | add(multiply(divide(multiply(divide(multiply(4.8, const_1000), multiply(multiply(const_2, const_2), 10)), const_2), multiply(const_4, const_4)), const_2), const_1) | multiply(n1,const_1000)|multiply(const_2,const_2)|multiply(const_4,const_4)|multiply(n0,#1)|divide(#0,#3)|multiply(#4,const_2)|divide(#5,#2)|multiply(#6,const_2)|add(#7,const_1) | explanation : if he travels 10 m for the first stone he has to travel that dist back as well . . . so he travels 2 * 10 m dist for the first stone and so on . = > 2400 = 2 * ( 10 + 20 + 30 . . . . 10 n ) using formula for ap = > 2400 = 2 * n / 2 * ( 2 * 10 + ( n - 1 ) * 10 ) . = > 2400 = 10 n 2 + 10 n . on solving this , we get n = 15 as the positive root , so total numer of stones on both sides = 30 . and including the one which he was at = 31 . answer : d | physics |
math_qa__N6TTwDWCcgnAjECq | The contents of two vessels containing copper and tin in the ratio 2:3 and 5:7 are mixed in the ratio 3:5. The resulting mixture will have copper and tin in the ratio? Choose the correct choice from the following answers: A) 210 : 283 B) 312 : 433 C) 178 : 213 D) 197 : 283 E) 145 : 256 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">6 + 25</gadget>
<output>31</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">9 + 35</gadget>
<output>44</output>
<gadget id="calculator">31 / 44</gadget>
<output>31/44 = around 0.704545</output>
<result>D</result> | D | 0.696113 | The contents of two vessels containing copper and tin in the ratio 2:3 and 5:7 are mixed in the ratio 3:5. The resulting mixture will have copper and tin in the ratio? | {
"A": "210 : 283",
"B": "312 : 433",
"C": "178 : 213",
"D": "197 : 283",
"E": "145 : 256"
} | divide(add(multiply(2, 3), multiply(5, 5)), add(multiply(3, 3), multiply(7, 5))) | multiply(n0,n1)|multiply(n2,n2)|multiply(n1,n1)|multiply(n2,n3)|add(#0,#1)|add(#2,#3)|divide(#4,#5) | the ratio of copper and tin the new vessel = ( 2 / 5 * 3 / 8 + 5 / 12 * 5 / 8 ) : ( 3 / 5 * 3 / 8 + 7 / 12 * 5 / 8 ) = 197 / 480 : 283 / 480 = 197 : 283 answer is d | other |
math_qa__BmAyXgxyKtgi0HYA | A and B together can do a work In 8 days. A alone can do it in 12 days. What time B will take to do the work alone? Choose the correct choice from the following options.
A) 6 days B) 8 days C) 12 days D) 24 days E) 25 days | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/8) - (1/12)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">24 + (2/5)</gadget>
<output>122/5 = around 24.4</output>
<result>D</result> | D | 24 | A and B together can do a work In 8 days. A alone can do it in 12 days. What time B will take to do the work alone? | {
"A": "6 days",
"B": "8 days",
"C": "12 days",
"D": "24 days",
"E": "25 days"
} | add(inverse(subtract(divide(const_1, 8), divide(const_1, 12))), divide(const_2, add(const_2, const_3))) | add(const_2,const_3)|divide(const_1,n0)|divide(const_1,n1)|divide(const_2,#0)|subtract(#1,#2)|inverse(#4)|add(#3,#5)| | "explanation : a and b 1 day ' s work = 1 / 8 a alone can do 1 day ' s work = 1 / 12 what time b will take to do the work alone ? b = ( a + b ) - a = ( 1 / 8 ) - ( 1 / 12 ) = 24 days answer : option d" | physics |
math_qa__PPyUpwSIlJ0njfvs | What is the minimum percentage increase in the mean of set S {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes? Choose the correct choice from the following answers
A) 25 % B) 50 % C) 75 % D) 100 % E) 200 % | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 / 2</gadget>
<output>100</output>
<result>D</result> | D | 100 | What is the minimum percentage increase in the mean of set S {-4, -1, 0, 6, 9} if its two smallest elements are replaced with two different primes? | {
"A": "25 %",
"B": "50 %",
"C": "75 %",
"D": "100 %",
"E": "200 %"
} | divide(multiply(const_2, const_100), const_2) | multiply(const_100,const_2)|divide(#0,const_2) | mean of s is ( - 4 - 1 + 0 + 6 + 9 ) / 5 = 2 ; in order the increase to be minimal we should replace two smallest elements of s , which are - 4 and - 1 , with two smallest primes , which are 2 and 3 . hence our new set will be { 2 , 3 , 0 , 6 , 9 } - - > new mean is ( 2 + 3 + 0 + 6 + 9 ) / 5 = 4 . percent increase = ( 4 - 2 ) / 2 * 100 = 100 % . answer : d . | general |
math_qa__74zoD5BvyBdYqpYY | In a renowned city, the average birth rate is 6 people every two seconds and the death rate is 3 people every two seconds. Estimate the size of the population net increase that occurs in one day.
Choices:
A) 129,500
B) 129,600
C) 129,700
D) 129,800
E) 129,900 | <gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">3 * 3_600</gadget>
<output>10_800</output>
<gadget id="calculator">10_800 * 12</gadget>
<output>129_600</output>
<result>B</result> | B | 129,600 | In a renowned city, the average birth rate is 6 people every two seconds and the death rate is 3 people every two seconds. Estimate the size of the population net increase that occurs in one day. | {
"A": "129,500",
"B": "129,600",
"C": "129,700",
"D": "129,800",
"E": "129,900"
} | multiply(multiply(subtract(6, 3), const_3600), const_12) | subtract(n0,n1)|multiply(#0,const_3600)|multiply(#1,const_12)| | "this question can be modified so that the birth rate is given every m seconds and the death rate is given every n seconds . for this particular question : increase in the population every 2 seconds = 6 - 3 = 3 people . total 2 second interval in a day = 24 * 60 * 60 / 2 = 43,200 population increase = 43,200 * 3 = 129,600 . hence b ." | general |
math_qa__jJ8kmmvBAzQOUoYz | How many times in a day, are the hands of a clock in straight line but opposite in direction? Choose the correct answer:
A) 21
B) 22
C) 17
D) 26
E) 25 | <gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">48 - 4</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<result>B</result> | B | 22 | How many times in a day, are the hands of a clock in straight line but opposite in direction? | {
"A": "21",
"B": "22",
"C": "17",
"D": "26",
"E": "25"
} | divide(subtract(multiply(const_2, multiply(const_2, const_12)), const_4), const_2) | multiply(const_12,const_2)|multiply(#0,const_2)|subtract(#1,const_4)|divide(#2,const_2) | b 22 the hands of a clock point in opposite directions ( in the same straight line ) 11 times in every 12 hours . ( because between 5 and 7 they point in opposite directions at 6 o ' clcok only ) . so , in a day , the hands point in the opposite directions 22 times . | physics |
math_qa__EvGlOy9F8f1fONJY | add 11% of 36 and 12% of 64. Pick one:
A) 9.5
B) 10.5
C) 11.5
D) 12
E) 15 | <gadget id="calculator">11 * 36</gadget>
<output>396</output>
<gadget id="calculator">396 / 100</gadget>
<output>99/25 = around 3.96</output>
<gadget id="calculator">12 * 64</gadget>
<output>768</output>
<gadget id="calculator">768 / 100</gadget>
<output>192/25 = around 7.68</output>
<gadget id="calculator">(99/25) + (192/25)</gadget>
<output>291/25 = around 11.64</output>
<result>C</result> | C | 11.5 | add 11% of 36 and 12% of 64. | {
"A": "9.5",
"B": "10.5",
"C": "11.5",
"D": "12",
"E": "15"
} | add(divide(multiply(11, 36), const_100), divide(multiply(12, 64), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)| | "11 % of 36 + 12 % of 64 36 * 11 / 100 + 64 * 12 / 100 3.9 + 7.6 = 11.5 answer c" | gain |
math_qa__vF9iBHGKTk92NpGA | If the cost price of 55 articles is equal to the selling price of 50 articles, then what is the percent profit? Choices.
A) 5 %
B) 10 %
C) 15 %
D) 20 %
E) 25 % | <gadget id="calculator">100 * 50</gadget>
<output>5_000</output>
<gadget id="calculator">5_000 / 55</gadget>
<output>1_000/11 = around 90.909091</output>
<gadget id="calculator">100 - (1_000/11)</gadget>
<output>100/11 = around 9.090909</output>
<gadget id="calculator">(100/11) / (1_000/11)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">100 * (1/10)</gadget>
<output>10</output>
<result>B</result> | B | 10 | If the cost price of 55 articles is equal to the selling price of 50 articles, then what is the percent profit? | {
"A": "5 %",
"B": "10 %",
"C": "15 %",
"D": "20 %",
"E": "25 %"
} | multiply(const_100, divide(subtract(const_100, divide(multiply(const_100, 50), 55)), divide(multiply(const_100, 50), 55))) | multiply(n1,const_100)|divide(#0,n0)|subtract(const_100,#1)|divide(#2,#1)|multiply(#3,const_100)| | "let x be the cost price of one article . let y be the selling price of one article . 50 y = 55 x y = 1.1 x the answer is b ." | gain |
math_qa__maOoNbP74rq44t4L | In a certain quiz that consists of 8 questions, each question after the first is worth 4 points more than the preceding question. If the 10 questions on the quiz are worth a total of 360 points, how many points is the third question worth?
Choose the correct choice from the following
A) 39 B) 40 C) 44 D) 48 E) 52 | <gadget id="calculator">360 / 10</gadget>
<output>36</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">36 + 3</gadget>
<output>39</output>
<result>A</result> | A | 39 | In a certain quiz that consists of 8 questions, each question after the first is worth 4 points more than the preceding question. If the 10 questions on the quiz are worth a total of 360 points, how many points is the third question worth? | {
"A": "39",
"B": "40",
"C": "44",
"D": "48",
"E": "52"
} | add(divide(360, 10), subtract(subtract(8, 4), const_1)) | divide(n3,n2)|subtract(n0,n1)|subtract(#1,const_1)|add(#0,#2) | x x + 4 x + 8 x + 12 x + 16 x + 20 x + 24 x + 28 8 x + 112 = 360 8 x = 248 x = 31 3 rd question = 31 + 8 = 31 + 8 = 39 answer a | general |
math_qa__pE62ITyRvTLRidPY | Line L passes through the points (-2,0) and (0,a). Line LL passes through the points (4,0) and (6,2). What value of a makes the two lines parallel?
Options
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">2 - 0</gadget>
<output>2</output>
<result>B</result> | B | 2 | Line L passes through the points (-2,0) and (0,a). Line LL passes through the points (4,0) and (6,2). What value of a makes the two lines parallel? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(const_2, 0) | subtract(const_2,n1) | find slopes first slope of l = ( a - 0 ) / ( 0 - ( - 2 ) ) = a / 2 slope of ll = ( 2 - 0 ) / ( 6 - 4 ) = 1 for l and ll to be parallel , their slopes must be equal a / 2 = 1 , a = 2 correct answer b | geometry |
math_qa__LjZ1AFM0g00hP32P | A certain school implemented a reading program for its students, with the goal of getting each student to read 6 books per month year-round. If the school has c classes made up of s students in each class, how many books will the entire student body read in one year? Choose the correct option.
A) 20 cs B) cs / 2 C) 72 cs D) ( 2 cs ) / 12 E) ( 24 c ) / s | <gadget id="calculator">6 * 12</gadget>
<output>72</output>
<result>C</result> | C | 72 | A certain school implemented a reading program for its students, with the goal of getting each student to read 6 books per month year-round. If the school has c classes made up of s students in each class, how many books will the entire student body read in one year? | {
"A": "20 cs",
"B": "cs / 2",
"C": "72 cs",
"D": "( 2 cs ) / 12",
"E": "( 24 c ) / s"
} | multiply(6, const_12) | multiply(n0,const_12)| | "ans : c solution : simple multiplication s students , c classes , 6 books / month = 72 books a year total number of books = 72 cs" | general |
math_qa__GFunUzJNZsWpiEmi | Debony normally drives to work in 45 minutes at an average speed of 40 miles per hour. This week, however, she plans to bike to work along a route that decreases the total distance she usually travels when driving by 20% . If Debony averages between 12 and 16 miles per hour when biking, how many minutes earlier will she need to leave in the morning in order to ensure she arrives at work at the same time as when she drives? Choose the correct choice from the following:
A) 135
B) 105
C) 95
D) 75
E) 45 | <gadget id="calculator">40 * 45</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 60</gadget>
<output>30</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">30 * 80</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 / 100</gadget>
<output>24</output>
<gadget id="calculator">24 * 60</gadget>
<output>1_440</output>
<gadget id="calculator">1_440 / 12</gadget>
<output>120</output>
<gadget id="calculator">120 - 45</gadget>
<output>75</output>
<result>D</result> | D | 75 | Debony normally drives to work in 45 minutes at an average speed of 40 miles per hour. This week, however, she plans to bike to work along a route that decreases the total distance she usually travels when driving by 20% . If Debony averages between 12 and 16 miles per hour when biking, how many minutes earlier will she need to leave in the morning in order to ensure she arrives at work at the same time as when she drives? | {
"A": "135",
"B": "105",
"C": "95",
"D": "75",
"E": "45"
} | subtract(divide(multiply(divide(multiply(divide(multiply(40, 45), const_60), multiply(40, const_2)), const_100), const_60), 12), 45) | multiply(n0,n1)|multiply(n1,const_2)|divide(#0,const_60)|multiply(#2,#1)|divide(#3,const_100)|multiply(#4,const_60)|divide(#5,n3)|subtract(#6,n0) | debony normally drives to work in 45 minutes at an average speed of 40 miles per hour . use formula d = rt car : t 1 : 45 min r 1 : 40 mph d 1 : [ ( 40 * 45 ) / 60 ] = 30 miles bike : t 1 : ? r 2 : 12 - 16 mph d 2 : 08 * d 1 = 24 miles t 1 : [ ( 24 * 60 ) / 12 ] = 120 min ( only 12 mph speed yields an answer given in the choices ) therefore , deb has to leave 120 min - 45 min = 75 min early answer : d | physics |
math_qa__Jwo5606HNQ0CSgOJ | If the average (arithmetic mean) of a and b is 40 and the average of b and c is 60, what is the value of c − a? Select the correct option
A) 25 B) 40 C) 90 D) 140 E) it can not be determined from the information given . | <gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">120 - 80</gadget>
<output>40</output>
<result>B</result> | B | 40 | If the average (arithmetic mean) of a and b is 40 and the average of b and c is 60, what is the value of c − a? | {
"A": "25",
"B": "40",
"C": "90",
"D": "140",
"E": "it can not be determined from the information given ."
} | subtract(multiply(60, const_2), multiply(40, const_2)) | multiply(n1,const_2)|multiply(n0,const_2)|subtract(#0,#1)| | "- ( a + b = 80 ) b + c = 120 c - a = 40 b . 40" | general |
math_qa__zbenGeyVjDtey5bN | A 6-liter solution is 25% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol? Select the correct option.
A) 2.1 B) 2.4 C) 2.7 D) 3.0 E) 3.3 | <gadget id="calculator">6 * 25</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 2</gadget>
<output>3</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<result>D</result> | D | 3 | A 6-liter solution is 25% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol? | {
"A": "2.1",
"B": "2.4",
"C": "2.7",
"D": "3.0",
"E": "3.3"
} | subtract(6, multiply(divide(multiply(6, 25), const_100), const_2)) | multiply(n0,n1)|divide(#0,const_100)|multiply(#1,const_2)|subtract(n0,#2)| | "let x be the amount of pure alcohol required . 0.25 ( 6 ) + x = 0.5 ( x + 6 ) 0.5 x = 3 - 1.5 x = 3 liters the answer is d ." | general |
math_qa__wuVp8b35aV0UViq4 | A container holding 9 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 8 ounces of a solution that is 1 part alcohol to 3 parts water. What is the ratio of alcohol to water in the resulting solution? Choose one: A) 2 : 5 B) 3 : 7 C) 3 : 5 D) 5 : 12 E) 7 : 3 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">9 * (1/3)</gadget>
<output>3</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">8 * (1/4)</gadget>
<output>2</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">9 + 8</gadget>
<output>17</output>
<gadget id="calculator">17 - 5</gadget>
<output>12</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<result>D</result> | D | 0.416667 | A container holding 9 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 8 ounces of a solution that is 1 part alcohol to 3 parts water. What is the ratio of alcohol to water in the resulting solution? | {
"A": "2 : 5",
"B": "3 : 7",
"C": "3 : 5",
"D": "5 : 12",
"E": "7 : 3"
} | divide(add(multiply(9, divide(1, add(1, 2))), multiply(8, divide(1, add(1, 3)))), subtract(add(9, 8), add(multiply(9, divide(1, add(1, 2))), multiply(8, divide(1, add(1, 3)))))) | add(n1,n2)|add(n1,n5)|add(n0,n3)|divide(n1,#0)|divide(n1,#1)|multiply(n0,#3)|multiply(n3,#4)|add(#5,#6)|subtract(#2,#7)|divide(#7,#8)| | "container 1 has 9 ounces in the ratio 1 : 2 or , x + 2 x = 9 gives x ( alcohol ) = 3 and remaining water = 6 container 2 has 8 ounces in the ratio 1 : 3 or , x + 3 x = 8 gives x ( alcohol ) = 2 and remaining water = 6 mixing both we have alcohol = 3 + 2 and water = 6 + 6 ratio thus alcohol / water = 5 / 12 answer d" | other |
math_qa__Gg1Z8kE0EfczVD7G | If the ratio of apples to bananas is 3 to 2 and the ratio of bananas to cucumbers is 1 to 3, what is the ratio of apples to cucumbers?
Choose the correct choice from the following
A) 2 : 3 B) 1 : 2 C) 3 : 5 D) 2 : 5 E) 5 : 6 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) / 3</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | If the ratio of apples to bananas is 3 to 2 and the ratio of bananas to cucumbers is 1 to 3, what is the ratio of apples to cucumbers? | {
"A": "2 : 3",
"B": "1 : 2",
"C": "3 : 5",
"D": "2 : 5",
"E": "5 : 6"
} | divide(divide(3, 2), 3) | divide(n0,n1)|divide(#0,n3)| | "the ratio of bananas to cucumbers is 1 to 3 which equals 2 to 6 . the ratio of apples to bananas to cucumbers is 3 to 2 to 6 . the ratio of apples to cucumbers is 3 to 6 which equals 1 : 2 . the answer is b ." | other |
math_qa__nNDy5u9L2KJW96UP | A candidate appearing for an examination has to secure 42% marks to pass paper I. But he secured only 60 marks and failed by 20 marks. What is the maximum mark for paper I? Choose the correct choice from the following answers.
A) 110 B) 120 C) 130 D) 140 E) 190 | <gadget id="calculator">60 + 20</gadget>
<output>80</output>
<gadget id="calculator">42 / 100</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">80 / (21/50)</gadget>
<output>4_000/21 = around 190.47619</output>
<result>E</result> | E | 190 | A candidate appearing for an examination has to secure 42% marks to pass paper I. But he secured only 60 marks and failed by 20 marks. What is the maximum mark for paper I? | {
"A": "110",
"B": "120",
"C": "130",
"D": "140",
"E": "190"
} | divide(add(60, 20), divide(42, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "he secured 60 marks nd fail by 20 marks so total marks for pass the examinatn = 80 let toal marks x x * 42 / 100 = 80 x = 190 answer : e" | gain |
math_qa__NSUtMjivJmbzo4cw | The sum of the first 50 positive even integers is 2550. What is the sum of even integers from 102 to 200 inclusive? Choices: A) 5100 B) 7550 C) 10100 D) 15500 E) 20100 | <gadget id="calculator">200 + 102</gadget>
<output>302</output>
<gadget id="calculator">302 / 2</gadget>
<output>151</output>
<gadget id="calculator">200 - 102</gadget>
<output>98</output>
<gadget id="calculator">98 / 2</gadget>
<output>49</output>
<gadget id="calculator">49 + 1</gadget>
<output>50</output>
<gadget id="calculator">151 * 50</gadget>
<output>7_550</output>
<result>B</result> | B | 7,550 | The sum of the first 50 positive even integers is 2550. What is the sum of even integers from 102 to 200 inclusive? | {
"A": "5100",
"B": "7550",
"C": "10100",
"D": "15500",
"E": "20100"
} | multiply(divide(add(200, 102), const_2), add(divide(subtract(200, 102), const_2), const_1)) | add(n2,n3)|subtract(n3,n2)|divide(#1,const_2)|divide(#0,const_2)|add(#2,const_1)|multiply(#4,#3) | first 50 even integers : 2 4 6 8 < . . . > integers from 102 to 200 102 104 106 108 < . . . > we notice that each integer from the second set is 100 more than the respective integer in the first set . since we have 50 even integers from 102 to 200 , then : 2550 + ( 100 * 50 ) = 7550 ; answer : b | general |
math_qa__si51SoicMnzNM2Mf | Ratio between Rahul and Deepak is 4:3, After 22 Years Rahul age will be 26 years. What is Deepak present age Choose the correct choice from the following answers: A) 10 B) 3 C) 5 D) 7 E) 8 | <gadget id="calculator">26 - 22</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 / 4</gadget>
<output>3</output>
<result>B</result> | B | 3 | Ratio between Rahul and Deepak is 4:3, After 22 Years Rahul age will be 26 years. What is Deepak present age | {
"A": "10",
"B": "3",
"C": "5",
"D": "7",
"E": "8"
} | divide(multiply(subtract(26, 22), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "explanation : present age is 4 x and 3 x , = > 4 x + 22 = 26 = > x = 1 so deepak age is = 3 ( 1 ) = 3 answer : option b" | other |
math_qa__hYmEjsWNXulYzKJd | which of the options is a two - digit number , which has a unit ' s digit that exceeds its 10 ' s digit by 4 and the product of the given number and the sum of its digits is equal to 208 . Choose the correct choice
A) 15 B) 37 C) 55 D) 26 E) 73 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">208 / 8</gadget>
<output>26</output>
<result>D</result> | D | 26 | which of the options is a two - digit number , which has a unit ' s digit that exceeds its 10 ' s digit by 4 and the product of the given number and the sum of its digits is equal to 208 . | {
"A": "15",
"B": "37",
"C": "55",
"D": "26",
"E": "73"
} | divide(208, multiply(4, const_2)) | multiply(n1,const_2)|divide(n2,#0) | using the elimination method the option that fits this description is 26 6 - 2 = 4 ( unit ' s digit that exceeds its ten ' s digit by 3 ) 26 * 8 = 208 ( the product of the given number and the sum of its digits is equal to 175 ) answer : d | general |
math_qa__PeMmTTxNJwAZCrl1 | The HCF and LCM of two numbers m and n are respectively 5 and 210. If m + n = 75, then 1/m + 1/n is equal to Choose the most appropriate option
A) 1 / 14 B) 3 / 35 C) 5 / 37 D) 2 / 35 E) none | <gadget id="calculator">5 * 210</gadget>
<output>1_050</output>
<gadget id="calculator">75 / 1_050</gadget>
<output>1/14 = around 0.071429</output>
<result>A</result> | A | 0.071429 | The HCF and LCM of two numbers m and n are respectively 5 and 210. If m + n = 75, then 1/m + 1/n is equal to | {
"A": "1 / 14",
"B": "3 / 35",
"C": "5 / 37",
"D": "2 / 35",
"E": "none"
} | divide(75, multiply(5, 210)) | multiply(n0,n1)|divide(n2,#0)| | "answer we have , m x n = 5 x 210 = 1050 â ˆ ´ 1 / m + 1 / n = ( m + n ) / mn = 75 / 1050 = 1 / 14 correct option : a" | general |
math_qa__4Y8Hly34PLJryPbO | Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 1/4 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what capacity? Choose the correct choice.
A) 1 / 2 B) 2 / 3 C) 3 / 4 D) 5 / 6 E) 7 / 8 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 12</gadget>
<output>3</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 * (1/2)</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | Drum X is 1/2 full of oil and drum Y, which has twice the capacity of drum X, is 1/4 full of oil. If all of the oil in drum X is poured into drum Y, then drum Y will be filled to what capacity? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "3 / 4",
"D": "5 / 6",
"E": "7 / 8"
} | divide(add(multiply(divide(1, 4), const_12), multiply(divide(const_12, const_2), divide(1, 2))), const_12) | divide(n0,n3)|divide(const_12,const_2)|divide(n0,n1)|multiply(#0,const_12)|multiply(#1,#2)|add(#3,#4)|divide(#5,const_12) | ( 1 / 2 ) x = ( 1 / 4 ) y ( 1 / 4 ) y + ( 1 / 4 ) y = ( 1 / 2 ) y the answer is a . | general |
math_qa__CCTJZcNfsU6Hjppz | The ratio of three numbers is 1:2:3 and the sum of their squares is 2744. The sum of the numbers is? Choose the most appropriate option: A) 10 B) 12 C) 15 D) 14 E) 9 | <gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">9 + 5</gadget>
<output>14</output>
<gadget id="calculator">2_744 / 14</gadget>
<output>196</output>
<gadget id="calculator">196 ** (1/2)</gadget>
<output>14</output>
<result>D</result> | D | 14 | The ratio of three numbers is 1:2:3 and the sum of their squares is 2744. The sum of the numbers is? | {
"A": "10",
"B": "12",
"C": "15",
"D": "14",
"E": "9"
} | sqrt(divide(2744, add(power(3, 2), add(power(1, 2), power(2, 2))))) | power(n0,n1)|power(n1,n1)|power(n2,n1)|add(#0,#1)|add(#3,#2)|divide(n3,#4)|sqrt(#5)| | "let the numbers be x , 2 x , 3 x then , x ^ 2 + 4 x ^ 2 + 9 x ^ 2 = 2744 14 x ^ 2 = 2744 x ^ 2 = 196 x = 14 answer is d" | other |
math_qa__cXbJGHfekd3wUdbX | 0.6 of a number is equal to 0.08 of another number. The ratio of the numbers will be Choose the correct choice from the following: A) 3 : 4 B) 4 : 3 C) 2 : 15 D) 2 : 9 E) 3 : 8 | <gadget id="calculator">0.08 / 0.6</gadget>
<output>0.133333</output>
<result>C</result> | C | 0.133333 | 0.6 of a number is equal to 0.08 of another number. The ratio of the numbers will be | {
"A": "3 : 4",
"B": "4 : 3",
"C": "2 : 15",
"D": "2 : 9",
"E": "3 : 8"
} | divide(0.08, 0.6) | divide(n1,n0) | let the numbers be x and y 0.6 x = 0.08 y = > x / y = 0.08 / 0.6 = 2 : 15 answer c . | other |
math_qa__Cr716u6Gy1lbN1Am | If a coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 6 times, what is the probability that it will land heads up on all 6 flips?
Choose the most appropriate option:
A) 1 / 6 B) 1 / 8 C) 1 / 32 D) 1 / 2 E) 1 / 64 | <gadget id="calculator">2 ** 6</gadget>
<output>64</output>
<gadget id="calculator">1 / 64</gadget>
<output>1/64 = around 0.015625</output>
<result>E</result> | E | 0.015625 | If a coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 6 times, what is the probability that it will land heads up on all 6 flips? | {
"A": "1 / 6",
"B": "1 / 8",
"C": "1 / 32",
"D": "1 / 2",
"E": "1 / 64"
} | divide(1, power(2, 6)) | power(n1,n2)|divide(n0,#0)| | ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) = 1 / 64 answer : e | probability |
math_qa__ZJrCQ61Gd7DNnyDn | The perimeter of one face a of cube is 20 cm. Its volume must be
Select:
A) 125 cm 3 B) 400 cm 3 C) 1000 cm 3 D) 8000 cm 3 E) none | <gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<result>A</result> | A | 125 | The perimeter of one face a of cube is 20 cm. Its volume must be | {
"A": "125 cm 3",
"B": "400 cm 3",
"C": "1000 cm 3",
"D": "8000 cm 3",
"E": "none"
} | volume_cube(square_edge_by_perimeter(20)) | square_edge_by_perimeter(n0)|volume_cube(#0) | solution edge of the cube = ( 20 / 4 ) cm ‹ = › 5 cm . volume = ( 5 × 5 × 5 ) cm 3 ‹ = › 125 cm 3 . answer a | geometry |
math_qa__abYNERiEqrriarEJ | The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 8400 for a computer table, then what was the cost price of the computer table? Choose the correct choice from the following answers:
A) rs . 6725 B) rs . 6727 C) rs . 6908 D) rs . 6725 E) rs . 7000 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">8_400 / (6/5)</gadget>
<output>7_000</output>
<result>E</result> | E | 7,000 | The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 8400 for a computer table, then what was the cost price of the computer table? | {
"A": "rs . 6725",
"B": "rs . 6727",
"C": "rs . 6908",
"D": "rs . 6725",
"E": "rs . 7000"
} | divide(8400, add(const_1, divide(20, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "cp = sp * ( 100 / ( 100 + profit % ) ) = 8400 ( 100 / 120 ) = rs . 7000 . answer : e" | gain |
math_qa__yWrjxe6pLLnPA2rg | The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 30% profit? Choose the correct choice from the following options:
A) $ 480 B) $ 450 C) $ 960 D) $ 832 E) $ 660 | <gadget id="calculator">832 + 448</gadget>
<output>1_280</output>
<gadget id="calculator">1_280 / 2</gadget>
<output>640</output>
<gadget id="calculator">640 * 30</gadget>
<output>19_200</output>
<gadget id="calculator">19_200 / 100</gadget>
<output>192</output>
<gadget id="calculator">192 + 640</gadget>
<output>832</output>
<result>D</result> | D | 832 | The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 30% profit? | {
"A": "$ 480",
"B": "$ 450",
"C": "$ 960",
"D": "$ 832",
"E": "$ 660"
} | add(divide(multiply(divide(add(832, 448), const_2), 30), const_100), divide(add(832, 448), const_2)) | add(n0,n1)|divide(#0,const_2)|multiply(n2,#1)|divide(#2,const_100)|add(#3,#1)| | "let c . p . = $ x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 130 % of $ 640 = $ 832 . d" | gain |
math_qa__YFLdatPcuFBpueJF | A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 18 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix?
Options
A) 1 / 10 B) 3 / 10 C) 1 / 2 D) 7 / 25 E) 9 / 10 | <gadget id="calculator">50 + 40</gadget>
<output>90</output>
<gadget id="calculator">90 - 18</gadget>
<output>72</output>
<gadget id="calculator">100 - 72</gadget>
<output>28</output>
<gadget id="calculator">28 / 100</gadget>
<output>7/25 = around 0.28</output>
<result>D</result> | D | 0.28 | A certain manufacturer of cake, muffin, and bread mixes has 100 buyers, of whom 50 purchases cake mix, 40 purchase muffin mix, and 18 purchase both cake mix and muffin mix. If a buyer is to be selected at random from the 100 buyers, what is the probability that the buyer selected will be one who purchases neither cake mix nor muffin mix? | {
"A": "1 / 10",
"B": "3 / 10",
"C": "1 / 2",
"D": "7 / 25",
"E": "9 / 10"
} | divide(subtract(100, subtract(add(50, 40), 18)), 100) | add(n1,n2)|subtract(#0,n3)|subtract(n0,#1)|divide(#2,n0)| | "c + m + b - cm - mb - cb - 2 cmb = 100 c - cake buyers , m - muffin and b - bread buyers . cm , mb , cb and cmb are intersecting regions . the question asks for people who have bought only bread mixes = b - cb - mb - 2 cmb has to be found out . 50 + 40 + b - cb - mb - 18 - 2 cmb = 100 b - cb - mb - 2 cmb = 28 hence the probability = 28 / 100 = 7 / 25 . d" | other |
math_qa__9ZFn2Mn8LB02GJYK | If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 5 m of the same rod? Answers.
A) 22.8 kg B) 25.6 kg C) 19 kg D) 26.5 kg E) none of these | <gadget id="calculator">5 * 42.75</gadget>
<output>213.75</output>
<gadget id="calculator">213.75 / 11.25</gadget>
<output>19</output>
<result>C</result> | C | 19 | If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 5 m of the same rod? | {
"A": "22.8 kg",
"B": "25.6 kg",
"C": "19 kg",
"D": "26.5 kg",
"E": "none of these"
} | divide(multiply(5, 42.75), 11.25) | multiply(n1,n2)|divide(#0,n0)| | "explanation : let the required weight be x kg . then , less length , less weight ( direct proportion ) = > 11.25 : 5 : : 42.75 : x = > 11.25 x x = 5 x 42.75 = > x = ( 5 x 42.75 ) / 11.25 = > x = 19 answer : c" | physics |
math_qa__jAHLzRUnTFlZHp6d | The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field ? Options: A) 20 B) 27 C) 26 D) 188 E) 11 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">460 / (23/20)</gadget>
<output>400</output>
<gadget id="calculator">400 ** (1/2)</gadget>
<output>20</output>
<result>A</result> | A | 20 | The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field ? | {
"A": "20",
"B": "27",
"C": "26",
"D": "188",
"E": "11"
} | sqrt(divide(460, add(const_1, divide(15, const_100)))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|sqrt(#2) | explanation : let breadth = x meters . then , length = meters given that , = > x = 20 breadth = 20 answer : a ) 20 m | geometry |
math_qa__cb9oEYJcXrFKOlqB | Find the compound interest on $100000 in 2years at 4% per annum, the interest being compounded half-yearly? Choose the correct choice
A) $ 645.56 B) $ 824.32 C) $ 954.26 D) $ 745.69 E) $ 8243.21 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) / 2</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) + 1</gadget>
<output>51/50 = around 1.02</output>
<gadget id="calculator">(51/50) ** 4</gadget>
<output>6_765_201/6_250_000 = around 1.082432</output>
<gadget id="calculator">(6_765_201/6_250_000) * 100_000</gadget>
<output>13_530_402/125 = around 108_243.216</output>
<gadget id="calculator">(13_530_402/125) - 100_000</gadget>
<output>1_030_402/125 = around 8_243.216</output>
<result>E</result> | E | 8,243.21 | Find the compound interest on $100000 in 2years at 4% per annum, the interest being compounded half-yearly? | {
"A": "$ 645.56",
"B": "$ 824.32",
"C": "$ 954.26",
"D": "$ 745.69",
"E": "$ 8243.21"
} | subtract(multiply(power(add(divide(divide(4, const_100), 2), const_1), 4), 100000), 100000) | divide(n2,const_100)|divide(#0,n1)|add(#1,const_1)|power(#2,n2)|multiply(n0,#3)|subtract(#4,n0)| | "principle = $ 10000 rate = 2 % half yearly = 4 half years amount = 100000 * ( 1 + 2 / 100 ) ^ 4 = 100000 * 51 / 50 * 51 / 50 * 51 / 50 * 51 / 50 = $ 108243.21 c . i . = 108243.21 - 100000 = $ 8243.21 answer is e" | gain |
math_qa__ueGy57oGlopc8ND1 | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.135. How much was lent at 5%?
Options: A) 2333 B) 2777 C) 2688 D) 1500 E) 2871 | <gadget id="calculator">6 * 2_500</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<gadget id="calculator">135 - 150</gadget>
<output>-15</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(1/20) - (3/50)</gadget>
<output>-1/100 = around -0.01</output>
<gadget id="calculator">(-15) / (-1/100)</gadget>
<output>1_500</output>
<result>D</result> | D | 1,500 | Rs.2500 is divided into two parts such that if one part be put out at 5% simple interest and the other at 6%, the yearly annual income may be Rs.135. How much was lent at 5%? | {
"A": "2333",
"B": "2777",
"C": "2688",
"D": "1500",
"E": "2871"
} | divide(subtract(135, divide(multiply(6, 2500), const_100)), subtract(divide(5, const_100), divide(6, const_100))) | divide(n1,const_100)|divide(n2,const_100)|multiply(n0,n2)|divide(#2,const_100)|subtract(#0,#1)|subtract(n3,#3)|divide(#5,#4)| | "( x * 5 * 1 ) / 100 + [ ( 2500 - x ) * 6 * 1 ] / 100 = 135 x = 1500 answer : d" | gain |
math_qa__JjJYCcVoWNwHqvC8 | (0.66)(power 3) - (0.1)(power 3)/ (0.66)(power 2) + 0.066 + (0.1)(power 2) is:
Choices.
A) 0.86 B) 0.56 C) 0.96 D) 0.69 E) 0.76 | <gadget id="calculator">0.66 ** 3</gadget>
<output>0.287496</output>
<gadget id="calculator">0.1 ** 3</gadget>
<output>0.001</output>
<gadget id="calculator">0.287496 - 0.001</gadget>
<output>0.286496</output>
<gadget id="calculator">0.66 ** 2</gadget>
<output>0.4356</output>
<gadget id="calculator">0.4356 + 0.066</gadget>
<output>0.5016</output>
<gadget id="calculator">0.1 ** 2</gadget>
<output>0.01</output>
<gadget id="calculator">0.5016 + 0.01</gadget>
<output>0.5116</output>
<gadget id="calculator">0.286496 / 0.5116</gadget>
<output>0.56</output>
<result>B</result> | B | 0.56 | (0.66)(power 3) - (0.1)(power 3)/ (0.66)(power 2) + 0.066 + (0.1)(power 2) is: | {
"A": "0.86",
"B": "0.56",
"C": "0.96",
"D": "0.69",
"E": "0.76"
} | divide(subtract(power(0.66, 3), power(0.1, 3)), add(add(power(0.66, 2), 0.066), power(0.1, 2))) | power(n0,n1)|power(n2,n1)|power(n0,n5)|power(n2,n5)|add(n6,#2)|subtract(#0,#1)|add(#4,#3)|divide(#5,#6)| | "given expression = ( 0.66 ) ( power 3 ) - ( 0.1 ) ( power 3 ) / ( 0.66 ) ( power 2 ) + ( 0.66 x 0.1 ) + ( 0.1 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 0.66 - 0.1 ) = 0.56 answer is b" | general |
math_qa__N3DKS92VxPjbfr6b | A trader cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 10% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 50% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage. Choose the correct choice from the following
A) 80 % B) 65 % C) 28.33 % D) 19.109 % E) 50 % | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">150 / 100</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">(3/2) * 110</gadget>
<output>165</output>
<gadget id="calculator">165 - 100</gadget>
<output>65</output>
<result>B</result> | B | 65 | A trader cheats both his supplier and customer by using faulty weights. When he buys from the supplier, he takes 10% more than the indicated weight. When he sells to his customer, he gives the customer a weight such that 50% of that is added to the weight, the weight claimed by the trader is obtained. If he charges the cost price of the weight that he claims, find his profit percentage. | {
"A": "80 %",
"B": "65 %",
"C": "28.33 %",
"D": "19.109 %",
"E": "50 %"
} | subtract(multiply(divide(add(const_100, 50), const_100), add(const_100, 10)), const_100) | add(n0,const_100)|add(n1,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100)| | "anyways , one can infer that he ' steals ' 10 % from suppliers and then charges 50 % extra to customers so basically 1.1 * 1.5 = 1.65 given that 1 is start point , we get 65 % more hence answer is b" | gain |
math_qa__inGywuUCSZ3n0VtF | When the no.7y86038 is exactly divisible by 11, then the smallest whole no.in place of y?
Select:
A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">7 + 8</gadget>
<output>15</output>
<gadget id="calculator">15 + 8</gadget>
<output>23</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">23 - 9</gadget>
<output>14</output>
<gadget id="calculator">14 - 11</gadget>
<output>3</output>
<result>B</result> | B | 3 | When the no.7y86038 is exactly divisible by 11, then the smallest whole no.in place of y? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | subtract(subtract(add(add(7, multiply(const_2, const_4)), multiply(const_2, const_4)), add(multiply(const_2, const_3), const_3)), 11) | multiply(const_2,const_4)|multiply(const_2,const_3)|add(n0,#0)|add(#1,const_3)|add(#2,#0)|subtract(#4,#3)|subtract(#5,n2) | the given number = 7 y 86038 sum of the odd places = 8 + 0 + 8 + 7 = 23 sum of the even places = 3 + 6 + y ( sum of the odd places ) - ( sum of even places ) = number ( exactly divisible by 11 ) 23 - ( 9 + y ) = divisible by 11 14 � y = divisible by 11 . y must be 3 , to make given number divisible by 11 . b | general |
math_qa__irABcKBmTUAqAPjv | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 12 inches long, how wide is Jordan's rectangle, in inches? Choose one.
A) 25 B) 23 C) 22 D) 20 E) 10 | <gadget id="calculator">5 * 24</gadget>
<output>120</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<result>E</result> | E | 10 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 12 inches long, how wide is Jordan's rectangle, in inches? | {
"A": "25",
"B": "23",
"C": "22",
"D": "20",
"E": "10"
} | divide(rectangle_area(5, 24), 12) | rectangle_area(n0,n1)|divide(#0,n2)| | "area of carol ' s rectangle = 24 * 5 = 120 let width of jordan ' s rectangle = w since , the areas are equal 12 w = 120 = > w = 10 answer e" | geometry |
math_qa__L8trWk2lAK258gRi | A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? Options:
A) 80 feet B) 85 feet C) 83 feet D) 88 feet E) 90 feet | <gadget id="calculator">680 / 20</gadget>
<output>34</output>
<gadget id="calculator">2 * (20 + 34)</gadget>
<output>108</output>
<gadget id="calculator">108 - 20</gadget>
<output>88</output>
<result>D</result> | D | 88 | A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? | {
"A": "80 feet",
"B": "85 feet",
"C": "83 feet",
"D": "88 feet",
"E": "90 feet"
} | subtract(rectangle_perimeter(20, divide(680, 20)), 20) | divide(n1,n0)|rectangle_perimeter(n0,#0)|subtract(#1,n0) | given that area of the field = 680 sq . feet = > lb = 680 sq . feet length ( l ) = 20 feet = > 20 × b = 680 = > b = 680 / 20 = 34 feet required length of the fencing = l + 2 b = 20 + ( 2 × 34 ) = 88 feet answer is d . | geometry |
math_qa__POulpZcmltBoVEeW | 10 men working 12 hours daily finish a work in 24 days. In how many days will they finish 1/4th of the work working 8 hours daily? Pick:
A) 9 days B) 10 days C) 11 days D) 12 days E) 18 days | <gadget id="calculator">12 * 24</gadget>
<output>288</output>
<gadget id="calculator">288 / 4</gadget>
<output>72</output>
<gadget id="calculator">72 / 8</gadget>
<output>9</output>
<result>A</result> | A | 9 | 10 men working 12 hours daily finish a work in 24 days. In how many days will they finish 1/4th of the work working 8 hours daily? | {
"A": "9 days",
"B": "10 days",
"C": "11 days",
"D": "12 days",
"E": "18 days"
} | divide(divide(multiply(12, 24), 4), 8) | multiply(n1,n2)|divide(#0,n4)|divide(#1,n5) | the number of days needed to finish 1 / 4 of the work = 1 / 4 * 12 / 8 * 24 = 9 days . answer : a | physics |
math_qa__1XzICnRHgFJvqcTr | 65% of x = 20% of 747.50. Find the value of x?
Choose the correct option.
A) 100 B) 230 C) 150 D) 180 E) 199 | <gadget id="calculator">747.5 / 100</gadget>
<output>7.475</output>
<gadget id="calculator">7.475 * 20</gadget>
<output>149.5</output>
<gadget id="calculator">149.5 * 100</gadget>
<output>14_950</output>
<gadget id="calculator">14_950 / 65</gadget>
<output>230</output>
<result>B</result> | B | 230 | 65% of x = 20% of 747.50. Find the value of x? | {
"A": "100",
"B": "230",
"C": "150",
"D": "180",
"E": "199"
} | divide(multiply(multiply(divide(747.50, const_100), 20), const_100), 65) | divide(n2,const_100)|multiply(n1,#0)|multiply(#1,const_100)|divide(#2,n0)| | "65 % of x = 20 % of 747.50 then , 65 / 100 * x = 20 / 100 * 7475 / 10 x = 230 answer is b" | general |
math_qa__iKDIdFVoCNLgzpH6 | A certain car can travel 40 kilometers on a liter of fuel. If the fuel tank’s contents decrease by 3.9 gallons over a period of 5.7 hours as the car moves at a constant speed, how fast is the car moving, in miles per hour? (1 gallon = 3.8 liters; 1 mile = 1.6 kilometers) Choose one
A) 52 B) 65 C) 78 D) 91 E) 104 | <gadget id="calculator">40 * 3.8</gadget>
<output>152</output>
<gadget id="calculator">152 / 1.6</gadget>
<output>95</output>
<gadget id="calculator">95 * 3.9</gadget>
<output>370.5</output>
<gadget id="calculator">370.5 / 5.7</gadget>
<output>65</output>
<result>B</result> | B | 65 | A certain car can travel 40 kilometers on a liter of fuel. If the fuel tank’s contents decrease by 3.9 gallons over a period of 5.7 hours as the car moves at a constant speed, how fast is the car moving, in miles per hour? (1 gallon = 3.8 liters; 1 mile = 1.6 kilometers) | {
"A": "52",
"B": "65",
"C": "78",
"D": "91",
"E": "104"
} | divide(multiply(divide(multiply(40, 3.8), 1.6), 3.9), 5.7) | multiply(n0,n4)|divide(#0,n6)|multiply(n1,#1)|divide(#2,n2)| | "fuel used 3.9 gallons ; convert to liters - - > 3.9 x 3.8 liters time = 5.7 hours 1 mile = 1.6 kilometers ; convert to miles - - > 1 km = 1 / 1.6 mile speed ( km / hour ) = d / t = 40 ( km * ) x 3.9 x 3.8 / 5.7 replace ( km * ) to miles ; multiply by 1 / 1.6 mile speed ( miles / hour ) = 40 x 3.9 x 3.8 / 5.7 x 1.6 = 78 miles / hour ans : c ps : i felt the factors were easy to cancel out , so did n ' t require much rounding off = 40 x 3.9 x 3.8 / 5.7 x 1.6 = 65 b" | physics |
math_qa__5wZLVVKZw44zX9ei | Each side of a rectangle is increased by 100% .By what percentage does the area increase? Pick
A) 300 % B) 400 % C) 500 % D) 200 % E) 600 % | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<result>A</result> | A | 300 | Each side of a rectangle is increased by 100% .By what percentage does the area increase? | {
"A": "300 %",
"B": "400 %",
"C": "500 %",
"D": "200 %",
"E": "600 %"
} | multiply(subtract(multiply(const_2, const_2), const_1), 100) | multiply(const_2,const_2)|subtract(#0,const_1)|multiply(n0,#1) | original area = a * b where a and b are sides after increase in side increase in area will be = ( ( ( 2 a * 2 b ) - ( a * b ) ) * 100 ) / ( a * b ) = 300 % answer : a | geometry |
math_qa__EA70on1VxQLsEkiE | The average monthly salary of 20 employees in an organisation is Rs. 1300. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?
Choose the correct answer:
A) 3600 B) 3890 C) 88798 D) 3400 E) 2891 | <gadget id="calculator">1_300 + 100</gadget>
<output>1_400</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">1_400 * 21</gadget>
<output>29_400</output>
<gadget id="calculator">1_300 * 20</gadget>
<output>26_000</output>
<gadget id="calculator">29_400 - 26_000</gadget>
<output>3_400</output>
<result>D</result> | D | 3,400 | The average monthly salary of 20 employees in an organisation is Rs. 1300. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ? | {
"A": "3600",
"B": "3890",
"C": "88798",
"D": "3400",
"E": "2891"
} | subtract(multiply(add(1300, 100), add(20, const_1)), multiply(1300, 20)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : manager ' s monthly salary rs . ( 1400 * 21 - 1300 * 20 ) = rs . 3400 . answer : d" | general |
math_qa__KBdFTXKsHFYlgW94 | Seller selling an apple for Rs.19, a Seller loses 1/6th of what it costs him. The CP of the apple is? Choose the correct choice from the following options.
A) 10
B) 12
C) 20
D) 18
E) 21 | <gadget id="calculator">19 + 1</gadget>
<output>20</output>
<result>C</result> | C | 20 | Seller selling an apple for Rs.19, a Seller loses 1/6th of what it costs him. The CP of the apple is? | {
"A": "10",
"B": "12",
"C": "20",
"D": "18",
"E": "21"
} | add(19, 1) | add(n0,n1) | sp = 19 loss = cp 20 loss = cp − sp = cp − 19 ⇒ cp 20 = cp − 19 ⇒ 19 cp 20 = 19 ⇒ cp 20 = 1 ⇒ cp = 20 c | general |
math_qa__BHVbdJF6WMk41Kv7 | If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/3 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? Choose the correct choice from the following choices.
A) 5 / 3
B) 5 / 4
C) 10 / 3
D) 15 / 4
E) 15 / 2 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(2/5) * (1/3)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/5) + (2/15)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">(8/15) / 2</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">1 / (4/15)</gadget>
<output>15/4 = around 3.75</output>
<result>D</result> | D | 3.75 | If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/3 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? | {
"A": "5 / 3",
"B": "5 / 4",
"C": "10 / 3",
"D": "15 / 4",
"E": "15 / 2"
} | divide(1, divide(add(divide(2, 5), multiply(divide(2, 5), divide(1, 3))), const_2)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)|add(#0,#2)|divide(#3,const_2)|divide(n2,#4)| | "n = 2 d / 5 j = n / 3 = 2 d / 15 the average of november and january is ( n + j ) / 2 = 8 d / 15 / 2 = 4 d / 15 d is 15 / 4 times the average of november and january . the answer is d ." | general |
math_qa__6Q8NQB30hgSDk9V3 | A man bring 2 cats to his home to eliminate all the mice. They do a half of the work in 5 days, then the man brings 3 more cats. If they hunt at the same rate, how many days will take to hunt all the mice, since the first day?
Choose the correct choice from the following answers
A) 7 days
B) 8 days
C) 9 days
D) 10 days
E) 11 days | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 5</gadget>
<output>2</output>
<gadget id="calculator">2 + 5</gadget>
<output>7</output>
<result>A</result> | A | 7 | A man bring 2 cats to his home to eliminate all the mice. They do a half of the work in 5 days, then the man brings 3 more cats. If they hunt at the same rate, how many days will take to hunt all the mice, since the first day? | {
"A": "7 days",
"B": "8 days",
"C": "9 days",
"D": "10 days",
"E": "11 days"
} | add(multiply(divide(2, 5), 5), 5) | divide(n0,n1)|multiply(n1,#0)|add(n1,#1) | we have that : 2 cats - - - - - 5 days , ( 2 + 3 ) c - - - - - x d , that is : ( x d / 2 c ) = ( 5 d / 5 p ) , then : x d = ( 5 d / 5 c ) 2 c = 2 d . is to say , the 5 cats hunt the same quantity in 2 days ; as it is only 1 / 2 of the work , all the mice would be hunt in : m = 5 d + 2 d = 7 days . answer a . | physics |
math_qa__XzFQzU7YtWjNwsY8 | A sum of money lent out at S.I. amounts to Rs. 720 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is?
Choose the correct choice from the following choices.
A) 600 B) 288 C) 2768 D) 287 E) 191 | <gadget id="calculator">1_020 - 720</gadget>
<output>300</output>
<gadget id="calculator">300 / 5</gadget>
<output>60</output>
<gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">720 - 120</gadget>
<output>600</output>
<result>A</result> | A | 600 | A sum of money lent out at S.I. amounts to Rs. 720 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is? | {
"A": "600",
"B": "288",
"C": "2768",
"D": "287",
"E": "191"
} | subtract(720, multiply(divide(subtract(1020, 720), 5), 2)) | subtract(n2,n0)|divide(#0,n3)|multiply(n1,#1)|subtract(n0,#2)| | "s . i for 5 years = ( 1020 - 720 ) = rs . 300 . s . i . for 2 years = 300 / 5 * 2 = rs . 120 . principal = ( 720 - 120 ) = rs . 600 . answer : a" | general |
math_qa__e1Iy0DqgtBlMqpPe | There are 15 members in a family. it takes 180 days for a women to complete the work, however man completes in 120 days. They take 17days to complete the work if men work on alternate days and women work every third day. if all of them started together on the 1st day, then how many women are there in the family Choose the correct option
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">180 / 15</gadget>
<output>12</output>
<gadget id="calculator">15 - 12</gadget>
<output>3</output>
<result>C</result> | C | 3 | There are 15 members in a family. it takes 180 days for a women to complete the work, however man completes in 120 days. They take 17days to complete the work if men work on alternate days and women work every third day. if all of them started together on the 1st day, then how many women are there in the family | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(15, divide(180, 15)) | divide(n1,n0)|subtract(n0,#0) | let the number of men be m and so the number of women = 15 - m out of 17 days , men and women work together on 1,4 , 7,10 , 13,16 th days ( total of 6 days ) from the start . men work on alternate days , that is 1 , 3,5 , 7,9 , 11,13 , 15,17 th days ( total of 9 days ) . let the total work be 360 units ( lcm of 180 and 120 ) . 1 man does 360 / 120 = 3 units per day 1 woman does 360 / 180 = 2 units per day based on above facts , total work by men + women in these 17 days = 360 units m * 9 * 3 + ( 15 - m ) * 6 * 2 = 360 , 27 m + 180 - 12 m = 360 , solving m = 12 . num of men = 12 and number of women = 15 - 12 = 3 answer : c | physics |
math_qa__5RkyHreOqAbe9U3F | How many integers between 1000 and 10000 have
no digits other than 4, 5 or 6? Pick
A) 91 B) 51 C) 81 D) 71 E) 61 | <gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 9</gadget>
<output>81</output>
<result>C</result> | C | 81 | How many integers between 1000 and 10000 have
no digits other than 4, 5 or 6? | {
"A": "91",
"B": "51",
"C": "81",
"D": "71",
"E": "61"
} | multiply(multiply(subtract(4, const_1), subtract(4, const_1)), multiply(subtract(4, const_1), subtract(4, const_1))) | subtract(n2,const_1)|multiply(#0,#0)|multiply(#1,#1) | any number between 1000 and 10000 is of 4 digits . the unit ’ s place can be filled up by 45 or 6 , that is , in 3 ways . similarly , the ten ’ s place can be filled up by 4 or 5 or 6 , that is in 3 ways . the hundred ’ s place can be filled up by 4 , 5 or 6 , that is in 3 ways and the thousand ’ s place can . be filled up by 4 or 5 or 6 , that is , in 3 ways . hence the required numbers = 3 x 3 x 3 x 3 = 81 answer : c | general |
math_qa__etl7IAja41OGJkYr | John completes a piece of work in 8 days, Rose completes the same work in 16 days. If both of them work together, then the number of days required to complete the work is?
Choose the correct answer:
A) 6 days
B) 5.33 days
C) 10 days
D) 12 days
E) 14 days | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">(1/8) + (1/16)</gadget>
<output>3/16 = around 0.1875</output>
<gadget id="calculator">1 / (3/16)</gadget>
<output>16/3 = around 5.333333</output>
<result>B</result> | B | 5.33 | John completes a piece of work in 8 days, Rose completes the same work in 16 days. If both of them work together, then the number of days required to complete the work is? | {
"A": "6 days",
"B": "5.33 days",
"C": "10 days",
"D": "12 days",
"E": "14 days"
} | divide(const_1, add(divide(const_1, 8), divide(const_1, 16))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2) | if a can complete a work in x days and b can complete the same work in y days , then , both of them together can complete the work in x y / x + y days . that is , the required no . of days = 8 × 16 / 24 = 5.33 days answer : b | physics |
math_qa__koqlkHZBrr8TiOy0 | What is the area of a triangle with the following vertices L(2, 3), M(5, 1), and N(3, 5) ? Choose the correct answer:
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">1 - 3</gadget>
<output>-2</output>
<gadget id="calculator">(-2) ** 2</gadget>
<output>4</output>
<gadget id="calculator">9 + 4</gadget>
<output>13</output>
<gadget id="calculator">13 ** (1/2)</gadget>
<output>sqrt(13) = around 3.605551</output>
<gadget id="calculator">2 - 3</gadget>
<output>-1</output>
<gadget id="calculator">(-1) ** 2</gadget>
<output>1</output>
<gadget id="calculator">3 - 5</gadget>
<output>-2</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 ** (1/2)</gadget>
<output>sqrt(5) = around 2.236068</output>
<gadget id="calculator">1 - 5</gadget>
<output>-4</output>
<gadget id="calculator">(-4) ** 2</gadget>
<output>16</output>
<gadget id="calculator">16 + 4</gadget>
<output>20</output>
<gadget id="calculator">20 ** (1/2)</gadget>
<output>2*sqrt(5) = around 4.472136</output>
<gadget id="calculator">((((sqrt(13)) + (sqrt(5)) + (2*sqrt(5))) / 2) * (((sqrt(13)) + (sqrt(5)) + (2*sqrt(5))) / 2 - (sqrt(13))) * (((sqrt(13)) + (sqrt(5)) + (2*sqrt(5))) / 2 - (sqrt(5))) * (((sqrt(13)) + (sqrt(5)) + (2*sqrt(5))) / 2 - (2*sqrt(5)))) ** (1/2)</gadget>
<output>sqrt(-sqrt(13)/2 + 3*sqrt(5)/2)*sqrt(sqrt(13)/2 + 3*sqrt(5)/2)*sqrt(-sqrt(5)/2 + sqrt(13)/2)*sqrt(sqrt(5)/2 + sqrt(13)/2) = around 4</output>
<result>B</result> | B | 4 | What is the area of a triangle with the following vertices L(2, 3), M(5, 1), and N(3, 5) ? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | triangle_area_three_edges(sqrt(add(power(subtract(5, 2), const_2), power(subtract(1, 3), const_2))), sqrt(add(power(subtract(2, 3), const_2), power(subtract(3, 5), const_2))), sqrt(add(power(subtract(1, 5), const_2), power(subtract(3, 5), const_2)))) | subtract(n2,n0)|subtract(n3,n1)|subtract(n0,n1)|subtract(n1,n2)|subtract(n3,n2)|power(#0,const_2)|power(#1,const_2)|power(#2,const_2)|power(#3,const_2)|power(#4,const_2)|add(#5,#6)|add(#7,#8)|add(#9,#8)|sqrt(#10)|sqrt(#11)|sqrt(#12)|triangle_area_three_edges(#13,#14,#15) | there is a direct formula to calculate the are of a triangle based on coordinates of its vertices and one could use it to solve this problem . though if you make a diagram minimum simple calculations will be needed : answer : b . | geometry |
math_qa__NRfNOfKG9cLDlzkL | How long does a train 140 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length? Pick.
A) 13.6 sec
B) 12.1 sec
C) 17.9 sec
D) 16.8 sec
E) 14.9 sec | <gadget id="calculator">140 + 132</gadget>
<output>272</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">272 / 20</gadget>
<output>68/5 = around 13.6</output>
<result>A</result> | A | 13.6 | How long does a train 140 m long running at the speed of 72 km/hr takes to cross a bridge 132 m length? | {
"A": "13.6 sec",
"B": "12.1 sec",
"C": "17.9 sec",
"D": "16.8 sec",
"E": "14.9 sec"
} | divide(add(140, 132), multiply(72, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1)| | "speed = 72 * 5 / 18 = 20 m / sec total distance covered = 140 + 132 = 272 m . required time = 272 / 20 = 13.6 sec . answer : a" | physics |
math_qa__wh2rdKt68jpqSeqc | In Kaya's teacher's desk there are 10 pink highlighters, 15 yellow highlighters, and 8 blue highlighters. How many highlighters are there in all? Select the correct option.
A) 11
B) 22
C) 77
D) 33
E) 88 | <gadget id="calculator">10 + 15</gadget>
<output>25</output>
<gadget id="calculator">25 + 8</gadget>
<output>33</output>
<result>D</result> | D | 33 | In Kaya's teacher's desk there are 10 pink highlighters, 15 yellow highlighters, and 8 blue highlighters. How many highlighters are there in all? | {
"A": "11",
"B": "22",
"C": "77",
"D": "33",
"E": "88"
} | add(add(10, 15), 8) | add(n0,n1)|add(n2,#0)| | "add the numbers of highlighters . 10 + 15 + 8 = 33 . answer is d ." | general |
math_qa__nn3MNd29MSEsMQhG | Income and expenditure of a person are in the ratio 9 : 8. If the income of the person is Rs. 18000, then find his savings? Choose the correct choice:
A) rs . 3600
B) rs . 3603
C) rs . 2000
D) rs . 3632
E) rs . 3602 | <gadget id="calculator">8 / 9</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(8/9) * 18_000</gadget>
<output>16_000</output>
<gadget id="calculator">18_000 - 16_000</gadget>
<output>2_000</output>
<result>C</result> | C | 2,000 | Income and expenditure of a person are in the ratio 9 : 8. If the income of the person is Rs. 18000, then find his savings? | {
"A": "rs . 3600",
"B": "rs . 3603",
"C": "rs . 2000",
"D": "rs . 3632",
"E": "rs . 3602"
} | subtract(18000, multiply(divide(8, 9), 18000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 9 x and rs . 8 x respectively . income , 9 x = 18000 = > x = 2000 savings = income - expenditure = 9 x - 8 x = x so , savings = rs . 2000 answer : c" | other |
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