id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__SAeqNYc1lvP43fT6 | x is the product of each integer from 1 to 50, inclusive and y=100^k, where k is an integer . What is the greatest value of k for which y is a factor of x? Choose the correct option.
A) 0
B) 5
C) 6
D) 10
E) 12 | <gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>C</result> | C | 6 | x is the product of each integer from 1 to 50, inclusive and y=100^k, where k is an integer . What is the greatest value of k for which y is a factor of x? | {
"A": "0",
"B": "5",
"C": "6",
"D": "10",
"E": "12"
} | add(divide(50, const_10), const_1) | divide(n1,const_10)|add(#0,const_1) | x = 1 * 2 * 3 * 4 * 5 * . . . . . . * 49 * 50 = 50 ! y = 100 ^ k 100 = 10 ^ 2 = 2 ^ 2 * 5 ^ 2 on prime factorization of x , power of 5 will always be greater than power of 2 concept : in every factorial value ( x ! ) , on prime factorization , the power of bigger prime number > the power of smaller prime number also , power of any prime number in any factorial can be calculated by following understanding power of prime x in n ! = [ n / x ] + [ n / x ^ 2 ] + [ n / x ^ 3 ] + [ n / x ^ 4 ] + . . . and so on where , [ x ] = greatest integer less than or equal to x and the explanation of terms is as follows [ n / x ] = no . of integers that are multiple of x from 1 to n [ n / x ^ 2 ] = no . of integers that are multiple of x ^ 2 from 1 to n whose first power has been counted in previous step and second is being counted at this step [ n / x ^ 3 ] = no . of integers that are multiple of x ^ 3 from 1 to n whose first two powers have been counted in previous two step and third power is counted at this step and so on . . . . . where [ n / x ] is greatest integer value of ( n / x ) less than or equal to ( n / x ) i . e . [ 100 / 3 ] = [ 33.33 ] = 33 i . e . [ 100 / 9 ] = [ 11.11 ] = 11 etc . power of 5 in x = [ 50 / 5 ] + [ 50 / 5 ^ 2 ] + [ 50 / 5 ^ 3 ] . . . = 10 + 2 + 0 = 12 power of 2 in x = [ 50 / 2 ] + [ 50 / 2 ^ 2 ] + [ 50 / 2 ^ 3 ] . . . = 25 + 12 + 6 + 3 + 1 = 47 i . e . x = 50 ! = 2 ^ 47 * 5 ^ 12 * . . . = 10 ^ 12 * . . . = 100 ^ 6 * . . . i . e . x is divisible by a 6 th power of 100 at the most i . e . y = 100 ^ k = 100 ^ 6 i . e . k = 6 answer : option c | general |
math_qa__2wlH6tJSfwU1RUAc | Dawson and Henry are in a relay race. Dawson runs the first leg of the course in 38 seconds. Henry runs the second leg of the course in 7 seconds. What was the average time they took to run a leg of the course?
Choose the correct option:
A) 20.5 B) 21.5 C) 22.5 D) 23.5 E) 24.5 | <gadget id="calculator">38 + 7</gadget>
<output>45</output>
<gadget id="calculator">45 / 2</gadget>
<output>45/2 = around 22.5</output>
<result>C</result> | C | 22.5 | Dawson and Henry are in a relay race. Dawson runs the first leg of the course in 38 seconds. Henry runs the second leg of the course in 7 seconds. What was the average time they took to run a leg of the course? | {
"A": "20.5",
"B": "21.5",
"C": "22.5",
"D": "23.5",
"E": "24.5"
} | divide(add(38, 7), const_2) | add(n0,n1)|divide(#0,const_2) | ( 38 seconds + 7 seconds ) / 2 = 22.5 seconds correct option is : c | general |
math_qa__OolkX8vzOoM1QIh9 | if 1500 is increased by 20 % , and then reduced by y % , yielding 1080 , what is y ? Select the correct option
A) 20 % B) 40 % C) 60 % D) 80 % E) 100 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">1_500 * (6/5)</gadget>
<output>1_800</output>
<gadget id="calculator">1_080 / 1_800</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>B</result> | B | 40 | if 1500 is increased by 20 % , and then reduced by y % , yielding 1080 , what is y ? | {
"A": "20 %",
"B": "40 %",
"C": "60 %",
"D": "80 %",
"E": "100 %"
} | multiply(subtract(const_1, divide(1080, multiply(1500, divide(add(const_100, 20), const_100)))), const_100) | add(n1,const_100)|divide(#0,const_100)|multiply(n0,#1)|divide(n2,#2)|subtract(const_1,#3)|multiply(#4,const_100) | soln : - 1,500 * 1.2 = 1,800 . 1,800 ( 1 - y / 100 ) = 1,080 - - > ( 1 - y / 100 ) = 0.6 - - > y = 40 % . answer : b | gain |
math_qa__vcF6TfX53CC8oYIw | If A is thrice as fast as B and together can do a work in 24 days. In how many days A alone can do the work? Choose the most appropriate option.
A) 36 B) 42 C) 28 D) 32 E) 45 | <gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">3 / 96</gadget>
<output>1/32 = around 0.03125</output>
<gadget id="calculator">1 / (1/32)</gadget>
<output>32</output>
<result>D</result> | D | 32 | If A is thrice as fast as B and together can do a work in 24 days. In how many days A alone can do the work? | {
"A": "36",
"B": "42",
"C": "28",
"D": "32",
"E": "45"
} | inverse(divide(const_3, multiply(24, const_4))) | multiply(n0,const_4)|divide(const_3,#0)|inverse(#1)| | "a ’ s one day ’ s work = 1 / x b ’ s one day ’ s work = 1 / 3 x a + b ’ s one day ’ s work = 1 / x + 1 / 3 x = 1 / 24 = 3 + 1 / 3 x = 4 / 3 x = 1 / 24 x = 24 * 4 / 3 = 32 answer : d" | physics |
math_qa__Ci6S8B43n6j3SKUy | A train 500 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is? Choose the correct choice from the following options:
A) 32 B) 28 C) 49 D) 64 E) 21 | <gadget id="calculator">500 + 300</gadget>
<output>800</output>
<gadget id="calculator">800 / 1_000</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">45 / 3_600</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">(4/5) / (1/80)</gadget>
<output>64</output>
<result>D</result> | D | 64 | A train 500 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is? | {
"A": "32",
"B": "28",
"C": "49",
"D": "64",
"E": "21"
} | divide(divide(add(500, 300), const_1000), divide(45, const_3600)) | add(n0,n1)|divide(n2,const_3600)|divide(#0,const_1000)|divide(#2,#1)| | "s = ( 500 + 300 ) / 45 = 800 / 45 * 18 / 5 = 64 answer : d" | physics |
math_qa__FNFUqTvbYzFl9goo | A and B invests Rs.3000 and Rs.4000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
Select: A) 9 : 6 B) 9 : 8 C) 9 : 0 D) 9 : 2 E) 9 : 1 | <gadget id="calculator">3_000 * 6</gadget>
<output>18_000</output>
<gadget id="calculator">3_000 * 2</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 * 6</gadget>
<output>36_000</output>
<gadget id="calculator">18_000 + 36_000</gadget>
<output>54_000</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">4_000 * 12</gadget>
<output>48_000</output>
<gadget id="calculator">54_000 / 48_000</gadget>
<output>9/8 = around 1.125</output>
<result>B</result> | B | 1.125 | A and B invests Rs.3000 and Rs.4000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit? | {
"A": "9 : 6",
"B": "9 : 8",
"C": "9 : 0",
"D": "9 : 2",
"E": "9 : 1"
} | divide(add(multiply(3000, 6), multiply(multiply(3000, const_2), 6)), multiply(4000, add(6, 6))) | add(n2,n2)|multiply(n0,n2)|multiply(n0,const_2)|multiply(n2,#2)|multiply(n1,#0)|add(#1,#3)|divide(#5,#4)| | "( 3 * 6 + 6 * 6 ) : ( 4 * 12 ) 54 : 48 = > 9 : 8 answer : b" | gain |
math_qa__Z6GfL3oghIAoK5TU | We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 30, and the difference between the total number of strawberries and the total number of blueberries would increase by 100. Each blue box contains how many blueberries?
Choose the correct answer
A) 35
B) 40
C) 45
D) 50
E) 55 | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 2</gadget>
<output>35</output>
<result>A</result> | A | 35 | We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 30, and the difference between the total number of strawberries and the total number of blueberries would increase by 100. Each blue box contains how many blueberries? | {
"A": "35",
"B": "40",
"C": "45",
"D": "50",
"E": "55"
} | divide(subtract(100, 30), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "let x be the number of blueberries in each blue box . then there are x + 30 strawberries in each red box . x + ( x + 30 ) = 100 x = 35 the answer is a ." | general |
math_qa__KEhxNhgfcFgO2FHH | There are an average of 117 jellybeans in each of 34 bags of various sizes. After adding another bag, the average number of jellybeans per bag increases by 7. How many jellybeans are in the new bag? Choose the correct choice: A) 124 B) 97 C) 117 D) 229 E) 362 | <gadget id="calculator">34 + 1</gadget>
<output>35</output>
<gadget id="calculator">7 * 35</gadget>
<output>245</output>
<gadget id="calculator">117 + 245</gadget>
<output>362</output>
<result>E</result> | E | 362 | There are an average of 117 jellybeans in each of 34 bags of various sizes. After adding another bag, the average number of jellybeans per bag increases by 7. How many jellybeans are in the new bag? | {
"A": "124",
"B": "97",
"C": "117",
"D": "229",
"E": "362"
} | add(117, multiply(7, add(34, const_1))) | add(n1,const_1)|multiply(n2,#0)|add(n0,#1) | total jellybeans in 34 bags = 34 * 117 = 3978 total jellybeans in 35 bags = 35 * 124 = 4340 number of jellybeans in new bag = 3978 - 4340 = 362 jellybeans answer is e | general |
math_qa__rqfoFiHsGk6JXZp7 | A student has to obtain 33% of the total marks to pass. He got 175 marks and failed by 89 marks. The maximum marks are?
Choose the correct choice from the following answers: A) 450 B) 300 C) 800 D) 610 E) 175 | <gadget id="calculator">175 + 89</gadget>
<output>264</output>
<gadget id="calculator">33 / 100</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">264 / (33/100)</gadget>
<output>800</output>
<result>C</result> | C | 800 | A student has to obtain 33% of the total marks to pass. He got 175 marks and failed by 89 marks. The maximum marks are? | {
"A": "450",
"B": "300",
"C": "800",
"D": "610",
"E": "175"
} | divide(add(175, 89), divide(33, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "let the maximum marks be x then , 33 % of x = 175 + 89 33 x / 100 = 264 x = 800 answer is c" | general |
math_qa__gcWRY3y1PnRWrwv5 | a solution of 90 litres contains milk and water in the ratio 7 : x . if 10 litres of water is added to the solution , the ratio becomes 3 : 2 , find the value of x ?
Choose the most appropriate option: A) 2 B) 1.5 C) 3.5 D) 2.5 E) 3 | <gadget id="calculator">90 * 7</gadget>
<output>630</output>
<gadget id="calculator">630 / 10</gadget>
<output>63</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">63 / (3/2)</gadget>
<output>42</output>
<gadget id="calculator">42 - 10</gadget>
<output>32</output>
<gadget id="calculator">90 / 10</gadget>
<output>9</output>
<gadget id="calculator">32 / 9</gadget>
<output>32/9 = around 3.555556</output>
<result>C</result> | C | 3.5 | a solution of 90 litres contains milk and water in the ratio 7 : x . if 10 litres of water is added to the solution , the ratio becomes 3 : 2 , find the value of x ? | {
"A": "2",
"B": "1.5",
"C": "3.5",
"D": "2.5",
"E": "3"
} | divide(subtract(divide(divide(multiply(90, 7), const_10), divide(3, 2)), 10), divide(90, const_10)) | divide(n3,n4)|divide(n0,const_10)|multiply(n0,n1)|divide(#2,const_10)|divide(#3,#0)|subtract(#4,n2)|divide(#5,#1) | exp . total new quantity = original sol + water = 90 + 10 = 100 new ratio = 3 : 2 , new quantity of milk = 3 / 5 * 100 = 60 lit , new quantity of water = 2 / 5 * 100 = 40 lit water present initially = ( 40 - 10 ) = 30 lit ratio = 60 / 30 = 7 / x there for x = 3.5 answer : c | general |
math_qa__DB7bXKxf7nl8pmp8 | A rectangle has a perimeter of 176 inches. The length of the rectangle is 8 inches more than its width. What is the area of the rectangle? Choose one.
A) 1,408 square inches B) 1,920 square inches C) 1,936 square inches D) 2,304 square inches E) none of these | <gadget id="calculator">176 / 2</gadget>
<output>88</output>
<gadget id="calculator">88 - 8</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">40 + 8</gadget>
<output>48</output>
<gadget id="calculator">48 * 40</gadget>
<output>1_920</output>
<result>B</result> | B | 1,920 | A rectangle has a perimeter of 176 inches. The length of the rectangle is 8 inches more than its width. What is the area of the rectangle? | {
"A": "1,408 square inches",
"B": "1,920 square inches",
"C": "1,936 square inches",
"D": "2,304 square inches",
"E": "none of these"
} | rectangle_area(add(divide(subtract(divide(176, const_2), 8), const_2), 8), divide(subtract(divide(176, const_2), 8), const_2)) | divide(n0,const_2)|subtract(#0,n1)|divide(#1,const_2)|add(n1,#2)|rectangle_area(#3,#2) | explanation : we have : ( l - b ) = 8 and 2 ( l + b ) = 176 or ( l + b ) = 88 . solving the two equations , we get : l = 48 and b = 40 . area = ( l x b ) = ( 48 x 40 ) in 2 = 1920 in 2 . correct answer : b | geometry |
math_qa__jTEC83hTjRhbO6qJ | In an election between the two candidates, the candidates who gets 70% of votes polled is winned by 240 vote’s majority. What is the total number of votes polled? Choose the most appropriate option
A) 600
B) 700
C) 800
D) 850
E) none of these | <gadget id="calculator">100 * 240</gadget>
<output>24_000</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">24_000 / 40</gadget>
<output>600</output>
<result>A</result> | A | 600 | In an election between the two candidates, the candidates who gets 70% of votes polled is winned by 240 vote’s majority. What is the total number of votes polled? | {
"A": "600",
"B": "700",
"C": "800",
"D": "850",
"E": "none of these"
} | divide(multiply(const_100, 240), subtract(70, subtract(const_100, 70))) | multiply(n1,const_100)|subtract(const_100,n0)|subtract(n0,#1)|divide(#0,#2)| | "explanation : note : majority ( 40 % ) = difference in votes polled to win ( 70 % ) & defeated candidates ( 30 % ) 40 % = 70 % - 30 % 40 % - - - - - > 280 ( 40 * 6 = 240 ) 100 % - - - - - > 600 ( 100 * 6 = 600 ) answer : option a" | gain |
math_qa__VIREVPOTKuVg7UaB | In covering a distance of 42 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is: Choose the correct choice from the following options:
A) 5 kmph
B) 6 kmph
C) 6.25 kmph
D) 7 kmph
E) 7.8 kmph | <gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">42 - 21</gadget>
<output>21</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">21 / 3</gadget>
<output>7</output>
<result>D</result> | D | 7 | In covering a distance of 42 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is: | {
"A": "5 kmph",
"B": "6 kmph",
"C": "6.25 kmph",
"D": "7 kmph",
"E": "7.8 kmph"
} | divide(subtract(42, divide(42, 2)), add(1, 2)) | add(n1,n2)|divide(n0,n1)|subtract(n0,#1)|divide(#2,#0)| | "let abhay ' s speed be x km / hr . then , 42 / x - 42 / 2 x = 3 6 x = 42 x = 7 km / hr . answer : option d" | physics |
math_qa__AzR8wCE3PSlrXFde | A store sells chairs and tables. If the price of 2 chairs and 1 table is 60% of the price of 1 chair and 2 tables, and the price of 1 table and 1 chair is $96, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.) Choose the correct choice from the following answers.
A) 81 B) 84 C) 85 D) 88 E) 90 | <gadget id="calculator">96 * 2</gadget>
<output>192</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">96 * (3/5)</gadget>
<output>288/5 = around 57.6</output>
<gadget id="calculator">192 - (288/5)</gadget>
<output>672/5 = around 134.4</output>
<gadget id="calculator">(3/5) + 1</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(672/5) / (8/5)</gadget>
<output>84</output>
<result>B</result> | B | 84 | A store sells chairs and tables. If the price of 2 chairs and 1 table is 60% of the price of 1 chair and 2 tables, and the price of 1 table and 1 chair is $96, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.) | {
"A": "81",
"B": "84",
"C": "85",
"D": "88",
"E": "90"
} | divide(subtract(multiply(96, const_2), multiply(96, divide(60, const_100))), add(divide(60, const_100), const_1)) | divide(n2,const_100)|multiply(n7,const_2)|add(#0,const_1)|multiply(n7,#0)|subtract(#1,#3)|divide(#4,#2) | let c = chair ; t = table 2 c + 1 t = 0.6 ( 1 c + 2 t ) or c ( 2 - 0.6 ) = 1.2 t - 1 t or 1.4 c = 0.2 t therefore c = 0.2 / 1.4 t = 1 / 7 t ic + 1 t = 96 or 1 / 7 t + 1 t = 96 therefore t = 96 * 7 / 8 = 84 b | gain |
math_qa__kNjSCxhsFl6ZXOxq | The length of the bridge, which a train 140 meters long and travelling at 45 km/hr can cross in 30 seconds, is?
Select the correct option
A) 328 B) 279 C) 235 D) 288 E) 211 | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 140</gadget>
<output>235</output>
<result>C</result> | C | 235 | The length of the bridge, which a train 140 meters long and travelling at 45 km/hr can cross in 30 seconds, is? | {
"A": "328",
"B": "279",
"C": "235",
"D": "288",
"E": "211"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 140) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | speed = ( 45 * 5 / 18 ) m / sec = ( 25 / 2 ) m / sec . time = 30 sec . let the length of bridge be x meters . then , ( 140 + x ) / 30 = 25 / 2 = = > 2 ( 140 + x ) = 750 = = > x = 235 m . answer : c | physics |
math_qa__WfuidhmnjDTu3ONe | Maths, Physics and chemistry books are stored on a library shelf that can accommodate 25 books. Currently, 20% of the shelf spots remain empty. There are twice as many maths books as physics books and the number of physics books is 4 greater than that of chemistry books. Among all the books, 12 books are soft cover and the remaining are hard-cover. If there are a total of 7 hard-cover books among the maths and physics books. What is the probability T, that a book selected at random is either a hard cover book or a chemistry book? Choose the correct choice: A) 1 / 10 B) 3 / 20 C) 1 / 5 D) 1 / 4 E) 9 / 20 | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">2 + 6</gadget>
<output>8</output>
<gadget id="calculator">8 + 12</gadget>
<output>20</output>
<gadget id="calculator">2 / 20</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">8 / 20</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/10) + (2/5)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/10) * (2/5)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/2) - (1/25)</gadget>
<output>23/50 = around 0.46</output>
<result>E</result> | E | 0.45 | Maths, Physics and chemistry books are stored on a library shelf that can accommodate 25 books. Currently, 20% of the shelf spots remain empty. There are twice as many maths books as physics books and the number of physics books is 4 greater than that of chemistry books. Among all the books, 12 books are soft cover and the remaining are hard-cover. If there are a total of 7 hard-cover books among the maths and physics books. What is the probability T, that a book selected at random is either a hard cover book or a chemistry book? | {
"A": "1 / 10",
"B": "3 / 20",
"C": "1 / 5",
"D": "1 / 4",
"E": "9 / 20"
} | subtract(add(divide(const_2, add(add(const_2, add(const_2, 4)), 12)), divide(add(const_2, add(const_2, 4)), add(add(const_2, add(const_2, 4)), 12))), multiply(divide(const_2, add(add(const_2, add(const_2, 4)), 12)), divide(add(const_2, add(const_2, 4)), add(add(const_2, add(const_2, 4)), 12)))) | add(n2,const_2)|add(#0,const_2)|add(n3,#1)|divide(const_2,#2)|divide(#1,#2)|add(#3,#4)|multiply(#3,#4)|subtract(#5,#6)| | "first phase of this problem requires you to determine how many mathematics and chemistry books are even on the shelf . to do so , you have the equations : m + p + c = 20 ( since 4 / 5 of the 25 spots are full of books ) m = 2 p p = 4 + c from that , you can use substitution to get everything down to one variable . c = p - 4 m = 2 p p = p then ( p - 4 ) + 2 p + p = 20 , so 4 p = 24 and p = 6 . that means that there are 12 math , 6 physics , and 2 chemistry books on the shelf . with those numbers , you also know that there are 8 total hardcovers , 1 of which is chemistry . so if your goal is to get either a hardcover or a chemistry , there are 9 ways towin - either one of the 7 hardcovers that are n ' t chemistry or the two chemistry books . so out of the 20 total , t = 9 provide the desired outcome , making the answer e ." | general |
math_qa__AUpha33Q1kqwTCiF | A man complete a journey in 40 hours. He travels first half of the journey at the rate of 20 km/hr and second half at the rate of 30 km/hr. Find the total journey in km.
Choose the correct answer
A) 960 km B) 224 km C) 230 km D) 232 km E) 234 km | <gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">600 * 40</gadget>
<output>24_000</output>
<gadget id="calculator">20 + 30</gadget>
<output>50</output>
<gadget id="calculator">24_000 / 50</gadget>
<output>480</output>
<gadget id="calculator">2 * 480</gadget>
<output>960</output>
<result>A</result> | A | 960 | A man complete a journey in 40 hours. He travels first half of the journey at the rate of 20 km/hr and second half at the rate of 30 km/hr. Find the total journey in km. | {
"A": "960 km",
"B": "224 km",
"C": "230 km",
"D": "232 km",
"E": "234 km"
} | multiply(const_2, divide(multiply(multiply(20, 30), 40), add(20, 30))) | add(n1,n2)|multiply(n1,n2)|multiply(n0,#1)|divide(#2,#0)|multiply(#3,const_2)| | "0.5 x / 20 + 0.5 x / 30 = 40 - - > x / 20 + x / 30 = 80 - - > 5 x = 60 x 80 - - > x = ( 60 x 80 ) / 5 = 960 km . answer : a" | physics |
math_qa__kELKmPyTYmYbW3LP | A large box contains 19 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box? Choose the correct choice from the following options
A) 475 B) 350 C) 450 D) 550 E) 650 | <gadget id="calculator">19 * 25</gadget>
<output>475</output>
<result>A</result> | A | 475 | A large box contains 19 small boxes and each small box contains 25 chocolate bars. How many chocolate bars are in the large box? | {
"A": "475",
"B": "350",
"C": "450",
"D": "550",
"E": "650"
} | multiply(19, 25) | multiply(n0,n1)| | "the number of chocolate bars is equal to 19 * 25 = 475 correct answer a" | general |
math_qa__dlUepNJcALLyb0yf | In a class of 50 students, 18 take Chorus, 26 take Band, and 2 take both Chorus and Band. How many students in the class are not enrolled in either Chorus or Band? Pick one
A) 8 B) 12 C) 15 D) 16 E) 18 | <gadget id="calculator">18 - 2</gadget>
<output>16</output>
<gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">16 + 24</gadget>
<output>40</output>
<gadget id="calculator">40 + 2</gadget>
<output>42</output>
<gadget id="calculator">50 - 42</gadget>
<output>8</output>
<result>A</result> | A | 8 | In a class of 50 students, 18 take Chorus, 26 take Band, and 2 take both Chorus and Band. How many students in the class are not enrolled in either Chorus or Band? | {
"A": "8",
"B": "12",
"C": "15",
"D": "16",
"E": "18"
} | subtract(50, add(add(subtract(18, 2), subtract(26, 2)), 2)) | subtract(n1,n3)|subtract(n2,n3)|add(#0,#1)|add(n3,#2)|subtract(n0,#3) | 16 + 2 + 24 + x = 50 42 + x = 50 x = 8 students a ) | other |
math_qa__GaSp39N1850VCYj2 | A shopkeeper sold an article offering a discount of 5% and earned a profit of 34.9%. What would have been the percentage of profit earned if no discount had been offered? Choose the correct choice from the following options:
A) 28.5
B) 27.675
C) 30
D) data inadequate
E) 42 | <gadget id="calculator">100 + 34.9</gadget>
<output>134.9</output>
<gadget id="calculator">134.9 * 100</gadget>
<output>13_490</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">13_490 / 95</gadget>
<output>142</output>
<gadget id="calculator">142 - 100</gadget>
<output>42</output>
<result>E</result> | E | 42 | A shopkeeper sold an article offering a discount of 5% and earned a profit of 34.9%. What would have been the percentage of profit earned if no discount had been offered? | {
"A": "28.5",
"B": "27.675",
"C": "30",
"D": "data inadequate",
"E": "42"
} | subtract(divide(multiply(add(const_100, 34.9), const_100), subtract(const_100, 5)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "giving no discount to customer implies selling the product on printed price . suppose the cost price of the article is 100 . then printed price = 100 ã — ( 100 + 34.9 ) / ( 100 â ˆ ’ 5 ) = 142 hence , required % profit = 142 â € “ 100 = 42 % answer e" | gain |
math_qa__etFI7nj9it6xuTCf | How long will a boy take to run round a square field of side 30 meters, if he runs at the rate of 12km/hr? Choose the most appropriate option: A) 52 sec B) 45 sec C) 60 sec D) 25 sec E) 36 sec | <gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">1_000 / 3_600</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">12 * (5/18)</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">120 / (10/3)</gadget>
<output>36</output>
<result>E</result> | E | 36 | How long will a boy take to run round a square field of side 30 meters, if he runs at the rate of 12km/hr? | {
"A": "52 sec",
"B": "45 sec",
"C": "60 sec",
"D": "25 sec",
"E": "36 sec"
} | divide(multiply(30, const_4), multiply(12, divide(const_1000, const_3600))) | divide(const_1000,const_3600)|multiply(n0,const_4)|multiply(n1,#0)|divide(#1,#2)| | "speed = 12 km / hr = 12 * 5 / 18 = 10 / 3 m / sec distance = 30 * 4 = 120 m time taken = 120 * 3 / 10 = 36 sec answer is e" | gain |
math_qa__qYERH9JL5b1r92s8 | The number of timeshare condos available at Sunset Beach is 2/5 the number of timeshare condos available at Playa del Mar. If the total number of timeshare condos available at the two beaches combined is 280, what is the difference between the number of condos available at Sunset Beach and the number of condos available at Playa del Mar?
Select the correct option:
A) 60
B) 90
C) 120
D) 150
E) 240 | <gadget id="calculator">280 * 2</gadget>
<output>560</output>
<gadget id="calculator">560 / 5</gadget>
<output>112</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">112 + 10</gadget>
<output>122</output>
<result>C</result> | C | 120 | The number of timeshare condos available at Sunset Beach is 2/5 the number of timeshare condos available at Playa del Mar. If the total number of timeshare condos available at the two beaches combined is 280, what is the difference between the number of condos available at Sunset Beach and the number of condos available at Playa del Mar? | {
"A": "60",
"B": "90",
"C": "120",
"D": "150",
"E": "240"
} | add(divide(multiply(280, 2), 5), multiply(2, 5)) | multiply(n0,n2)|multiply(n0,n1)|divide(#0,n1)|add(#2,#1)| | "let x be the number of timeshare condos available at playa del mar . then number of timeshare condos available at sunset beach = 3 / 5 x we know , x + 2 / 5 x = 280 hence , x = 200 . so , number of timeshare condos available at playa del mar = 200 the difference between the number of condos available at sunset beach and the number of condos available at playa del mar = x - 2 / 5 x = 2 / 5 x = 3 / 5 ( 200 ) = 120 the correct answer is c" | general |
math_qa__fHg89BjalAr6uG0N | The price of a coat in a certain store is $500. If the price of the coat is to be reduced by $350, by what percent is the price to be reduced? Choose the correct choice from the following answers
A) 70 %
B) 15 %
C) 20 %
D) 25 %
E) 30 % | <gadget id="calculator">350 / 500</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 100</gadget>
<output>70</output>
<result>A</result> | A | 70 | The price of a coat in a certain store is $500. If the price of the coat is to be reduced by $350, by what percent is the price to be reduced? | {
"A": "70 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "30 %"
} | multiply(divide(350, 500), const_100) | divide(n1,n0)|multiply(#0,const_100)| | "price of a coat in a certain store = $ 500 the price of the coat is to be reduced by $ 350 % change = ( final value - initial value ) * 100 / initial value % reduction = ( reduction in price ) * 100 / initial value i . e . % reduction = ( 350 ) * 100 / 500 = 70 % answer : option a" | gain |
math_qa__q4JHg6TNAOWrUkld | Ratio of two numbers x and y is 7:9. If x is increased by 20% and y is increased by 33 then the new ratio becomes 1:5. What is the ratio 2y:(x+4) Choose one:
A) 18 : 11 B) 8 : 1 C) 11 : 18 D) 1 : 8 E) 1 : 1 | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 5</gadget>
<output>6</output>
<gadget id="calculator">9 / 7</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">6 - (9/7)</gadget>
<output>33/7 = around 4.714286</output>
<gadget id="calculator">33 / (33/7)</gadget>
<output>7</output>
<gadget id="calculator">7 * (9/7)</gadget>
<output>9</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">18 / 11</gadget>
<output>18/11 = around 1.636364</output>
<result>A</result> | A | 1.636364 | Ratio of two numbers x and y is 7:9. If x is increased by 20% and y is increased by 33 then the new ratio becomes 1:5. What is the ratio 2y:(x+4) | {
"A": "18 : 11",
"B": "8 : 1",
"C": "11 : 18",
"D": "1 : 8",
"E": "1 : 1"
} | divide(multiply(const_2, multiply(divide(33, subtract(multiply(divide(add(const_100, 20), const_100), 5), divide(9, 7))), divide(9, 7))), add(divide(33, subtract(multiply(divide(add(const_100, 20), const_100), 5), divide(9, 7))), 4)) | add(n2,const_100)|divide(n1,n0)|divide(#0,const_100)|multiply(n5,#2)|subtract(#3,#1)|divide(n3,#4)|add(n7,#5)|multiply(#5,#1)|multiply(#7,const_2)|divide(#8,#6) | let : x = 7 n y = 9 n 8.4 n / ( 9 n + 33 ) = 1 / 5 42 n = 9 n + 33 n = 1 so , x = 7 ; y = 9 2 y / ( x + 4 ) = 18 / 11 answer = a | general |
math_qa__YCT5MCnd5Co2MqyG | Of 70 players on a football team, 52 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? Pick
A) 54 B) 59 C) 63 D) 64 E) 92 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">70 - 52</gadget>
<output>18</output>
<gadget id="calculator">(2/3) * 18</gadget>
<output>12</output>
<gadget id="calculator">12 + 52</gadget>
<output>64</output>
<result>D</result> | D | 64 | Of 70 players on a football team, 52 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? | {
"A": "54",
"B": "59",
"C": "63",
"D": "64",
"E": "92"
} | add(multiply(subtract(const_1, divide(const_1, const_3)), subtract(70, 52)), 52) | divide(const_1,const_3)|subtract(n0,n1)|subtract(const_1,#0)|multiply(#2,#1)|add(n1,#3)| | "total = 70 thrower = 52 rest = 70 - 52 = 18 left handed = 18 / 3 = 6 right handed = 12 if all thrower are right handed then total right handed is 52 + 12 = 64 so d . 64 is the right answer" | general |
math_qa__qNmA7qk51RzQlVos | A man can row upstream at 15 kmph and downstream at 35 kmph, and then find the speed of the man in still water? Choose the correct choice from the following options.
A) 65
B) 86
C) 30
D) 78
E) 25 | <gadget id="calculator">15 + 35</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>E</result> | E | 25 | A man can row upstream at 15 kmph and downstream at 35 kmph, and then find the speed of the man in still water? | {
"A": "65",
"B": "86",
"C": "30",
"D": "78",
"E": "25"
} | divide(add(15, 35), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 15 ds = 35 m = ( 35 + 15 ) / 2 = 25 answer : e" | physics |
math_qa__LgFY38XdZJxeuviN | 39! is divided by 41. Then what is the remainder? Choose the most appropriate option.
A) 1
B) 3
C) 4
D) 6
E) 9 | <gadget id="calculator">factorial(39)</gadget>
<output>20_397_882_081_197_443_358_640_281_739_902_897_356_800_000_000</output>
<gadget id="calculator">20_397_882_081_197_443_358_640_281_739_902_897_356_800_000_000 % 41</gadget>
<output>1</output>
<result>A</result> | A | 1 | 39! is divided by 41. Then what is the remainder? | {
"A": "1",
"B": "3",
"C": "4",
"D": "6",
"E": "9"
} | reminder(factorial(39), 41) | factorial(n0)|reminder(#0,n1)| | "substituting p = 41 in the wilson ' s theorem , we get 40 ! + 141 = 0 40 × 39 ! + 141 = 0 − 1 × 39 ! 41 = − 1 cancelling - 1 on both sides , 39 ! 41 = 1 a" | other |
math_qa__JfTFTE5wCgsPGdrX | If the product of two numbers is 82500 and their H.C.F. is 55, find their L.C.M. Choose the correct choice from the following answers.
A) 2574
B) 2500
C) 1500
D) 1574
E) none of these | <gadget id="calculator">82_500 / 55</gadget>
<output>1_500</output>
<result>C</result> | C | 1,500 | If the product of two numbers is 82500 and their H.C.F. is 55, find their L.C.M. | {
"A": "2574",
"B": "2500",
"C": "1500",
"D": "1574",
"E": "none of these"
} | divide(82500, 55) | divide(n0,n1)| | "explanation : hcf * lcm = 82500 , because we know product of two numbers = product of hcf and lcm lcm = 82500 / 55 = 1500 option c" | physics |
math_qa__5J6iYelcN5N8u4Vh | What is the area of an obtuse angled triangle whose two sides are 8 and 12 and the angle included between the two sides is 150o?
Choose the most appropriate option:
A) 24 sq units B) 48 sq units C) 24 under root 3 D) 48 under root 3 E) such a triangle does not exist | <gadget id="calculator">3 ** (1/2)</gadget>
<output>sqrt(3) = around 1.732051</output>
<gadget id="calculator">(sqrt(3)) / 2</gadget>
<output>sqrt(3)/2 = around 0.866025</output>
<gadget id="calculator">8 * (sqrt(3)/2)</gadget>
<output>4*sqrt(3) = around 6.928203</output>
<gadget id="calculator">(4*sqrt(3)) + 12</gadget>
<output>4*sqrt(3) + 12 = around 18.928203</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">((4*sqrt(3) + 12) * 4) / 2</gadget>
<output>8*sqrt(3) + 24 = around 37.856406</output>
<gadget id="calculator">(4 * (4*sqrt(3))) / 2</gadget>
<output>8*sqrt(3) = around 13.856406</output>
<gadget id="calculator">(8*sqrt(3) + 24) - (8*sqrt(3))</gadget>
<output>24</output>
<result>A</result> | A | 24 | What is the area of an obtuse angled triangle whose two sides are 8 and 12 and the angle included between the two sides is 150o? | {
"A": "24 sq units",
"B": "48 sq units",
"C": "24 under root 3",
"D": "48 under root 3",
"E": "such a triangle does not exist"
} | subtract(triangle_area(add(multiply(8, divide(sqrt(const_3), const_2)), 12), divide(8, const_2)), triangle_area(divide(8, const_2), multiply(8, divide(sqrt(const_3), const_2)))) | divide(n0,const_2)|sqrt(const_3)|divide(#1,const_2)|multiply(n0,#2)|add(n1,#3)|triangle_area(#0,#3)|triangle_area(#4,#0)|subtract(#6,#5) | explanatory answer if two sides of a triangle and the included angle ' y ' is known , then the area of the triangle = 1 / 2 * ( product of sides ) * sin y substituting the values in the formula , we get 1 / 2 * 8 * 12 * sin 150 o = 1 / 2 * 8 * 12 * 1 / 2 . note : sin 150 o = 1 / 2 area = 24 sq units . choice a | geometry |
math_qa__jqsRmzTBSl3Fmtsv | Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 8 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?
Choose one.
A) 8 mph B) 5.25 mph C) 3.5 mph D) 4.5 mph E) 0.5 mph | <gadget id="calculator">1 + 8</gadget>
<output>9</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<result>D</result> | D | 4.5 | Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 8 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her? | {
"A": "8 mph",
"B": "5.25 mph",
"C": "3.5 mph",
"D": "4.5 mph",
"E": "0.5 mph"
} | divide(add(1, 8), const_2) | add(n0,n1)|divide(#0,const_2)| | "( 1 mph + 8 mph ) / 2 = 4.5 mph correct option is : d" | physics |
math_qa__qlqkkdqc90brhJrk | There were totally 100 men.84 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?
Choose the correct choice from the following answers.
A) 11
B) 12
C) 13
D) 14
E) 15 | <gadget id="calculator">100 - 84</gadget>
<output>16</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">16 + 25</gadget>
<output>41</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">41 + 15</gadget>
<output>56</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">56 + 30</gadget>
<output>86</output>
<gadget id="calculator">100 - 86</gadget>
<output>14</output>
<result>D</result> | D | 14 | There were totally 100 men.84 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | subtract(100, add(add(add(subtract(100, 84), subtract(100, 75)), subtract(100, 85)), subtract(100, 70))) | subtract(n0,n1)|subtract(n0,n2)|subtract(n0,n3)|subtract(n0,n4)|add(#0,#1)|add(#4,#2)|add(#5,#3)|subtract(n0,#6)| | "100 - ( 100 - 84 ) - ( 100 - 75 ) - ( 100 - 85 ) - ( 100 - 70 ) = 100 - 16 - 25 - 15 - 30 = 100 - 86 = 14 answer : d" | general |
math_qa__CkQvAoKo4fzaWr5Y | Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 35 km/hr. For how many minutes does the bus stop per hour? Pick one
A) 22
B) 88
C) 24
D) 20
E) 99 | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">35 / 60</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">(7/12) * 60</gadget>
<output>35</output>
<gadget id="calculator">60 - 35</gadget>
<output>25</output>
<result>C</result> | C | 24 | Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 35 km/hr. For how many minutes does the bus stop per hour? | {
"A": "22",
"B": "88",
"C": "24",
"D": "20",
"E": "99"
} | subtract(multiply(const_1, const_60), multiply(divide(35, 60), const_60)) | divide(n1,n0)|multiply(const_1,const_60)|multiply(#0,const_60)|subtract(#1,#2)| | "in 1 hr , the bus covers 60 km without stoppages and 35 km with stoppages . stoppage time = time take to travel ( 60 - 35 ) km i . e 25 km at 60 km / hr . stoppage time = 25 / 60 hrs = 24 min . answer : c" | general |
math_qa__PuLnUFE11DARwKTm | One paper sheet can be used to create 8 paper boats or 6 paper planes. If total exact 80 paper toys are to be made, minimum how many sheets need to be used to make paper boats?
Options:
A) 5
B) 4
C) 3
D) 2
E) 1 | <gadget id="calculator">80 / 8</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<result>E</result> | E | 1 | One paper sheet can be used to create 8 paper boats or 6 paper planes. If total exact 80 paper toys are to be made, minimum how many sheets need to be used to make paper boats? | {
"A": "5",
"B": "4",
"C": "3",
"D": "2",
"E": "1"
} | divide(divide(80, 8), const_10) | divide(n2,n0)|divide(#0,const_10) | let us say x sheets are used to create paper boats and y sheets are used to create paper planes . since total 80 paper toys are to be created , 8 x + 6 y = 80 . = > 8 x = 80 - 6 y = > x = 10 - ( 6 / 8 ) y = > x = 10 - ( 3 / 4 ) y to minimize x , we need to maximize y . and y needs to be multiple of 4 . y = 4 , x = 10 - ( 3 / 4 ) 4 = 7 y = 8 , x = 10 - ( 3 / 4 ) 8 = 4 y = 12 , x = 10 - ( 3 / 4 ) 12 = 1 beyond this , x will become negative for greater values of y . so , minimum 1 sheet is required to be used for creating paper boats . answer : e | general |
math_qa__74K62HrUeUaurrXw | If ABC is a quarter circle and a smaller circle is inscribed in it; if radius of quarter circle is 1.414units. Find the radius of smaller circle Select the correct option: A) 0.586 B) 0.687 C) 0.784 D) 0.874 E) 0.974 | <gadget id="calculator">2 - 1.414</gadget>
<output>0.586</output>
<result>A</result> | A | 0.586 | If ABC is a quarter circle and a smaller circle is inscribed in it; if radius of quarter circle is 1.414units. Find the radius of smaller circle | {
"A": "0.586",
"B": "0.687",
"C": "0.784",
"D": "0.874",
"E": "0.974"
} | subtract(const_2, 1.414) | subtract(const_2,n0) | if r be radius of smaller circle then distance b / n centres = √ 2 * r so , r + r √ 2 = r here , r = 1.414 = √ 2 = > r = ( √ 2 - 1 ) r r = 0 . 586 unit answer : a | geometry |
math_qa__Qb86M8cQ2Mon0cNS | A bag of potatoes weighs 16 kg divided by a quarter of its weight. How much does the bag weigh? Choose the correct choice from the following answers
A) 4 kg B) 8 kg C) 7 kg D) 3 kg E) 9 kg | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | A bag of potatoes weighs 16 kg divided by a quarter of its weight. How much does the bag weigh? | {
"A": "4 kg",
"B": "8 kg",
"C": "7 kg",
"D": "3 kg",
"E": "9 kg"
} | divide(16, const_2) | divide(n0,const_2) | b 8 kg 8 kg : 16 / 2 | general |
math_qa__0ZGIuXGNmG3wOug8 | A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price of the machine?
Choices
A) 81 B) 100 C) 120 D) 135 E) 160 | <gadget id="calculator">90 * 20</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">90 + 18</gadget>
<output>108</output>
<gadget id="calculator">108 * 100</gadget>
<output>10_800</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">10_800 / 90</gadget>
<output>120</output>
<result>C</result> | C | 120 | A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price of the machine? | {
"A": "81",
"B": "100",
"C": "120",
"D": "135",
"E": "160"
} | divide(multiply(add(90, divide(multiply(90, 20), const_100)), const_100), multiply(multiply(const_3, const_3), 10)) | multiply(n0,n2)|multiply(const_3,const_3)|divide(#0,const_100)|multiply(n1,#1)|add(n0,#2)|multiply(#4,const_100)|divide(#5,#3)| | "my solution : wholesale price = 90 retail price , be = x he provides 10 % discount on retail price = x - 10 x / 100 this retail price = 20 % profit on wholesale price x - 10 x / 100 = 90 + 1 / 5 ( 90 ) x = 120 ; answer : c" | gain |
math_qa__Z3G6QNsXYKpOrbwB | What is the least number should be added to 1056, so the sum of the number is completely divisible by 27? Pick one:
A) 21
B) 22
C) 23
D) 24
E) 25 | <gadget id="calculator">1_056 / 27</gadget>
<output>352/9 = around 39.111111</output>
<gadget id="calculator">floor(352/9)</gadget>
<output>39</output>
<gadget id="calculator">39 + 1</gadget>
<output>40</output>
<gadget id="calculator">40 * 27</gadget>
<output>1_080</output>
<gadget id="calculator">1_080 - 1_056</gadget>
<output>24</output>
<result>D</result> | D | 24 | What is the least number should be added to 1056, so the sum of the number is completely divisible by 27? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | subtract(multiply(add(floor(divide(1056, 27)), const_1), 27), 1056) | divide(n0,n1)|floor(#0)|add(#1,const_1)|multiply(n1,#2)|subtract(#3,n0)| | "( 1056 / 27 ) gives remainder 3 24 + 3 = 27 , so we need to add 24 d" | general |
math_qa__XA3RUjJFR972lFD8 | If 30% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? Answers
A) 620 B) 630 C) 616 D) 600 E) 650 | <gadget id="calculator">880 / 100</gadget>
<output>44/5 = around 8.8</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">(44/5) * 70</gadget>
<output>616</output>
<result>C</result> | C | 616 | If 30% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? | {
"A": "620",
"B": "630",
"C": "616",
"D": "600",
"E": "650"
} | multiply(divide(880, const_100), subtract(const_100, 30)) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)| | "we know 37.5 % people study biology , therefore the no of people not studying = 100 - 30 = 70 % > therefore the people not studying biology out of a total 880 people are = 70 % of 880 > ( 70 / 100 ) * 880 = 616 people c" | other |
math_qa__qiQV0VQyHw0gH3JF | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 30% of all the employees are men .What % of all the employee went to the picnic? Choose the correct choice from the following
A) 33 %
B) 34 %
C) 35 %
D) 36 %
E) 37 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/10) * (1/5)</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(7/10) * (2/5)</gadget>
<output>7/25 = around 0.28</output>
<gadget id="calculator">(3/50) + (7/25)</gadget>
<output>17/50 = around 0.34</output>
<gadget id="calculator">(17/50) * 100</gadget>
<output>34</output>
<result>B</result> | B | 34 | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 30% of all the employees are men .What % of all the employee went to the picnic? | {
"A": "33 %",
"B": "34 %",
"C": "35 %",
"D": "36 %",
"E": "37 %"
} | multiply(add(multiply(divide(30, const_100), divide(20, const_100)), multiply(divide(subtract(const_100, 30), const_100), divide(40, const_100))), const_100) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(const_100,n2)|divide(#3,const_100)|multiply(#0,#1)|multiply(#4,#2)|add(#5,#6)|multiply(#7,const_100)| | "total men in company 30 % means total women in company 70 % ( assume total people in company 100 % ) no of men employees attended picnic = 30 x ( 20 / 100 ) = 6 no of women employees attended picnic = 70 x ( 40 / 100 ) = 28 total percentage of employees attended the picnic = 6 + 28 = 34 % answer : b" | gain |
math_qa__lKg5vwFDam91fwGF | 30 is what percent of 100?
Answers:
A) 35 % B) 30 % C) 45 % D) 50 % E) 55 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 100</gadget>
<output>30</output>
<result>B</result> | B | 30 | 30 is what percent of 100? | {
"A": "35 %",
"B": "30 %",
"C": "45 %",
"D": "50 %",
"E": "55 %"
} | multiply(divide(30, 100), const_100) | divide(n0,n1)|multiply(#0,const_100)| | 30 / 100 × 100 = 30 % answer : b | gain |
math_qa__caMULp24z6dCxmhi | A watch was sold at a loss of 12%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? Select.
A) s . 1000 B) s . 875 C) s . 1007 D) s . 1006 E) s . 1002 | <gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">104 - 88</gadget>
<output>16</output>
<gadget id="calculator">14_000 / 16</gadget>
<output>875</output>
<result>B</result> | B | 875 | A watch was sold at a loss of 12%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? | {
"A": "s . 1000",
"B": "s . 875",
"C": "s . 1007",
"D": "s . 1006",
"E": "s . 1002"
} | divide(multiply(140, const_100), subtract(add(const_100, 4), subtract(const_100, 12))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "explanation : 88 % 104 % - - - - - - - - 16 % - - - - 140 100 % - - - - ? = > rs . 875 answer : b" | gain |
math_qa__RojiEMGYkVTv8xud | Ratio between Rahul and Deepak is 4:3, After 10 Years Rahul age will be 26 years. What is Deepak present age
Choose the correct choice:
A) 12 B) 15 C) 20 D) 22 E) 23 | <gadget id="calculator">26 - 10</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 / 4</gadget>
<output>12</output>
<result>A</result> | A | 12 | Ratio between Rahul and Deepak is 4:3, After 10 Years Rahul age will be 26 years. What is Deepak present age | {
"A": "12",
"B": "15",
"C": "20",
"D": "22",
"E": "23"
} | divide(multiply(subtract(26, 10), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "explanation : present age is 4 x and 3 x , = > 4 x + 10 = 26 = > x = 4 so deepak age is = 3 ( 4 ) = 12 answer : option a" | other |
math_qa__F8SL3aXQfxDbkdtr | Worker A takes 8 hours to do a job. Worker B takes 12 hours to do the same job. How long it take both A & B, working together but independently, to do the same job? Choices
A) 40 days B) 24 / 5 days C) 39 / 9 days D) 30 / 9 days E) 60 / 9 days | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/8) + (1/12)</gadget>
<output>5/24 = around 0.208333</output>
<gadget id="calculator">1 / (5/24)</gadget>
<output>24/5 = around 4.8</output>
<result>B</result> | B | 4.8 | Worker A takes 8 hours to do a job. Worker B takes 12 hours to do the same job. How long it take both A & B, working together but independently, to do the same job? | {
"A": "40 days",
"B": "24 / 5 days",
"C": "39 / 9 days",
"D": "30 / 9 days",
"E": "60 / 9 days"
} | divide(const_1, add(divide(const_1, 8), divide(const_1, 12))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "a ' s one hour work = 1 / 8 . b ' s one hour work = 1 / 12 . ( a + b ) ' s one hour work = 1 / 8 + 1 / 12 = 5 / 24 . both a & b can finish the work in 24 / 5 days b" | physics |
math_qa__r6vUGE7PH5wJbIIr | Denominator of a number is 4 less than the numerator. If 6 is added to the numerator, it becomes 3 times the denominator. Find the denominator. Answers: A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>C</result> | C | 5 | Denominator of a number is 4 less than the numerator. If 6 is added to the numerator, it becomes 3 times the denominator. Find the denominator. | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | divide(add(4, 6), subtract(3, const_1)) | add(n0,n1)|subtract(n2,const_1)|divide(#0,#1) | let the numerator be x and denominator be y . then = > x = y + 4 and 6 + x = 3 * y = > 6 + y + 4 = 3 * y = > 2 y = 10 = > y = 5 option c | general |
math_qa__fMeQVChDdosNSQ1X | If m is an integer such that (-2)^2m=2^(3-m) then m=? Select the correct option:
A) 1 B) 2 C) 3 D) 5 E) 6 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 / 3</gadget>
<output>1</output>
<result>A</result> | A | 1 | If m is an integer such that (-2)^2m=2^(3-m) then m=? | {
"A": "1",
"B": "2",
"C": "3",
"D": "5",
"E": "6"
} | divide(3, add(2, const_1)) | add(n0,const_1)|divide(n3,#0)| | "( - 2 ) ^ ( 2 m ) = 4 ^ m and 2 ^ ( 3 - m ) = 4 ^ ( ( 3 - m ) / 2 ) therefore , m = ( 3 - m ) / 2 2 m = 3 - m m = 1 answer a" | general |
math_qa__2cLtqyUbgGhFybYd | A rectangular paper when folded into two congruent parts had a perimeter of 34cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper? Answers
A) 140
B) 388
C) 238
D) 119
E) 112 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">34 - 20</gadget>
<output>14</output>
<gadget id="calculator">14 * 10</gadget>
<output>140</output>
<result>A</result> | A | 140 | A rectangular paper when folded into two congruent parts had a perimeter of 34cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper? | {
"A": "140",
"B": "388",
"C": "238",
"D": "119",
"E": "112"
} | multiply(subtract(34, multiply(const_10, const_2)), const_10) | multiply(const_10,const_2)|subtract(n0,#0)|multiply(#1,const_10) | when folded along the breadth we have 2 ( l / 2 + b ) = 34 or l + 2 b = 34 . . . . . . . . . . . ( 1 ) when folded along the length , we have 2 ( l + b / 2 ) = 38 or 2 l + b = 38 . . . . . ( 2 ) from 1 & 2 we get l = 14 and b = 10 area of the paper = 14 * 10 = 140 sq cmv answer : a | geometry |
math_qa__s7sbWx8aHXCnhp4o | Given a certain number (x), find x given that 5.76 is 12% of 40% of x? Choices
A) 130 B) 120 C) 140 D) 100 E) 300 | <gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">5.76 * 88</gadget>
<output>506.88</output>
<gadget id="calculator">506.88 / 12</gadget>
<output>42.24</output>
<gadget id="calculator">42.24 + 5.76</gadget>
<output>48</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">48 * 60</gadget>
<output>2_880</output>
<gadget id="calculator">2_880 / 40</gadget>
<output>72</output>
<gadget id="calculator">72 + 48</gadget>
<output>120</output>
<result>B</result> | B | 120 | Given a certain number (x), find x given that 5.76 is 12% of 40% of x? | {
"A": "130",
"B": "120",
"C": "140",
"D": "100",
"E": "300"
} | add(divide(multiply(add(divide(multiply(5.76, subtract(const_100, 12)), 12), 5.76), subtract(const_100, 40)), 40), add(divide(multiply(5.76, subtract(const_100, 12)), 12), 5.76)) | subtract(const_100,n1)|subtract(const_100,n2)|multiply(n0,#0)|divide(#2,n1)|add(n0,#3)|multiply(#4,#1)|divide(#5,n2)|add(#4,#6) | using elimination method to pick the correct option it will be discovered that option b i . e 120 is the correct option because 40 % of 120 is 48 and 12 % of 48 is 5.76 . answer : b | gain |
math_qa__Ftw2rZBLnaRzP2jE | A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.12.60 less, he would have gained 30%. Find the cost of the article. Select.
A) 30 B) 40 C) 50 D) 60 E) 70 | <gadget id="calculator">12.6 * 100</gadget>
<output>1_260</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">30 + 100</gadget>
<output>130</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">130 * 80</gadget>
<output>10_400</output>
<gadget id="calculator">10_400 / 100</gadget>
<output>104</output>
<gadget id="calculator">125 - 104</gadget>
<output>21</output>
<gadget id="calculator">1_260 / 21</gadget>
<output>60</output>
<result>D</result> | D | 60 | A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.12.60 less, he would have gained 30%. Find the cost of the article. | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "70"
} | divide(multiply(12.60, const_100), subtract(add(25, const_100), divide(multiply(add(30, const_100), subtract(const_100, 20)), const_100))) | add(n0,const_100)|add(n3,const_100)|multiply(n2,const_100)|subtract(const_100,n1)|multiply(#1,#3)|divide(#4,const_100)|subtract(#0,#5)|divide(#2,#6)| | "let c . p = 100 gain = 25 % s . p = 125 supposed c . p = 80 gain = 30 % s . p = ( 130 * 80 ) / 100 = 104 diff = ( 125 - 104 ) = 21 diff 21 when c . p = 100 then diff 12.60 when c . p = ( 100 * 12.60 ) / 21 = 60 answer : d" | gain |
math_qa__TsIN0GpaBWFWM4ok | A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? Select: A) 230 B) 200 C) 250 D) 300 E) 500 | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 270</gadget>
<output>230</output>
<result>A</result> | A | 230 | A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? | {
"A": "230",
"B": "200",
"C": "250",
"D": "300",
"E": "500"
} | subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 270) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "answer : option a explanation : relative speed = 120 + 80 = 200 km / hr . = 200 * 5 / 18 = 500 / 9 m / sec . let the length of the other train be x m . then , ( x + 270 ) / 9 = 500 / 9 = > x = 230 . answer a" | physics |
math_qa__AmkYVHtsqhSE5qjg | Two numbers are in respectively 20% and 50% more than a third number. The ratio of the two numbers is? Options
A) 2 : 5 B) 1 : 2 C) 4 : 5 D) 3 : 7 E) 5 : 6 | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">120 / 150</gadget>
<output>4/5 = around 0.8</output>
<result>C</result> | C | 0.8 | Two numbers are in respectively 20% and 50% more than a third number. The ratio of the two numbers is? | {
"A": "2 : 5",
"B": "1 : 2",
"C": "4 : 5",
"D": "3 : 7",
"E": "5 : 6"
} | divide(add(const_100, 20), add(const_100, 50)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "let the 3 rd number be x then , first number = 120 % of x = 120 x / 100 = 6 x / 5 second number = 150 % of x = 150 x / 100 = 3 x / 2 ratio of first two numbers = 6 x / 5 : 3 x / 2 = 12 x : 15 x = 4 : 5 answer is c" | other |
math_qa__E8gXk87uZTuvyTSE | A gardener wants to plant trees in his garden in such a way that the number of trees in each row should be the same. If there are 4 rows or 5 rows or 6 rows, then no tree will be left. Find the least number of trees required
Choose the correct choice.
A) 22 B) 60 C) 28 D) 76 E) 21 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<result>B</result> | B | 60 | A gardener wants to plant trees in his garden in such a way that the number of trees in each row should be the same. If there are 4 rows or 5 rows or 6 rows, then no tree will be left. Find the least number of trees required | {
"A": "22",
"B": "60",
"C": "28",
"D": "76",
"E": "21"
} | divide(multiply(multiply(6, 5), 4), const_2) | multiply(n1,n2)|multiply(n0,#0)|divide(#1,const_2) | explanation : the least number of trees that are required = lcm ( 4 , 5 , 6 ) = 60 . answer : b | general |
math_qa__NDN76T5kSPT1Z4gk | a batsman ' s avg in 12 innings is 24.00 . if his avg is to be double of the no of innings ( 15 innings ) , what should he score in the remaining 3 innings ( avg ) ?
Choose the correct choice from the following answers.
A) 143 B) 144 C) 145 D) 146 E) 147 | <gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">15 * 48</gadget>
<output>720</output>
<gadget id="calculator">12 * 24</gadget>
<output>288</output>
<gadget id="calculator">720 - 288</gadget>
<output>432</output>
<gadget id="calculator">432 / 3</gadget>
<output>144</output>
<result>B</result> | B | 144 | a batsman ' s avg in 12 innings is 24.00 . if his avg is to be double of the no of innings ( 15 innings ) , what should he score in the remaining 3 innings ( avg ) ? | {
"A": "143",
"B": "144",
"C": "145",
"D": "146",
"E": "147"
} | divide(subtract(multiply(15, multiply(24, const_2)), multiply(12, 24)), 3) | multiply(n1,const_2)|multiply(n0,n1)|multiply(n2,#0)|subtract(#2,#1)|divide(#3,n3) | let total runs done by a batsman in 12 innings be x therefore , x / 12 = 24 that means x = 12 * 24 = 288 runs for 15 innings , avg was doubled i . e . . 48.00 therefore , ( x + y ) / 15 = 48 where y is the no of runs done in last 3 innings y = 432 therefore average is 432 / 3 = 144 answer : b | general |
math_qa__AKvIdl1etPYVFNEk | In what time will a railway train 80 m long moving at the rate of 40 kmph pass a telegraph post on its way? Choose the correct choice from the following choices.
A) 3
B) 5
C) 4
D) 6.4
E) 7.2 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">40 * (5/18)</gadget>
<output>100/9 = around 11.111111</output>
<gadget id="calculator">80 / (100/9)</gadget>
<output>36/5 = around 7.2</output>
<result>E</result> | E | 7.2 | In what time will a railway train 80 m long moving at the rate of 40 kmph pass a telegraph post on its way? | {
"A": "3",
"B": "5",
"C": "4",
"D": "6.4",
"E": "7.2"
} | divide(80, multiply(40, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 80 / 40 * 18 / 5 = 7.2 sec answer : e" | physics |
math_qa__rxCYELGHxaZxxXWk | The number of people who purchased book A is twice the number of people who purchased book B. The number of people who purchased both books A and B is 500, which is twice the number of people who purchased only book B. What is the number of people Z who purchased only book A? Pick.
A) 250 B) 500 C) 750 D) 1000 E) 1500 | <gadget id="calculator">500 / 2</gadget>
<output>250</output>
<gadget id="calculator">500 + 250</gadget>
<output>750</output>
<gadget id="calculator">750 * 2</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 - 500</gadget>
<output>1_000</output>
<result>D</result> | D | 1,000 | The number of people who purchased book A is twice the number of people who purchased book B. The number of people who purchased both books A and B is 500, which is twice the number of people who purchased only book B. What is the number of people Z who purchased only book A? | {
"A": "250",
"B": "500",
"C": "750",
"D": "1000",
"E": "1500"
} | subtract(multiply(add(500, divide(500, const_2)), const_2), 500) | divide(n0,const_2)|add(n0,#0)|multiply(#1,const_2)|subtract(#2,n0)| | "this is best solved using overlapping sets or a venn diagram . we know that a = 2 b , and that 500 people purchased both a and b . further , those purchasing both was double those purchasing b only . this gives us 250 people purchasing b only . with the 500 that pruchased both , we have a total of 750 that purchased b and this is 1 / 2 of those that purchased a . so , 1500 purchased a . less the 500 that purchased both , z = 1000 purchased a only . ( this is much simpler to solve using the venn diagram ) . correct answer is d . 1000" | other |
math_qa__HcL0GNVamY2jeAC5 | If the sum of two numbers is 20 and the sum of their squares is 200, then the product of the numbers is Choose the correct choice from the following answers: A) 40 B) 44 C) 100 D) 88 E) 48 | <gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">400 - 200</gadget>
<output>200</output>
<gadget id="calculator">200 / 2</gadget>
<output>100</output>
<result>C</result> | C | 100 | If the sum of two numbers is 20 and the sum of their squares is 200, then the product of the numbers is | {
"A": "40",
"B": "44",
"C": "100",
"D": "88",
"E": "48"
} | divide(subtract(power(20, const_2), 200), const_2) | power(n0,const_2)|subtract(#0,n1)|divide(#1,const_2)| | "according to the given conditions x + y = 20 and x ^ 2 + y ^ 2 = 200 now ( x + y ) ^ 2 = x ^ 2 + y ^ 2 + 2 xy so 20 ^ 2 = 200 + 2 xy so xy = 200 / 2 = 100 answer : c" | general |
math_qa__y5a3AFwfY1Jtb3S1 | Bruce purchased 8kg of grapes at the rate of 70 per kg and 8 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper? Choose the correct choice from the following answers:
A) 1040 B) 1050 C) 1000 D) 1065 E) 1075 | <gadget id="calculator">8 * 70</gadget>
<output>560</output>
<gadget id="calculator">8 * 55</gadget>
<output>440</output>
<gadget id="calculator">560 + 440</gadget>
<output>1_000</output>
<result>C</result> | C | 1,000 | Bruce purchased 8kg of grapes at the rate of 70 per kg and 8 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper? | {
"A": "1040",
"B": "1050",
"C": "1000",
"D": "1065",
"E": "1075"
} | add(multiply(8, 70), multiply(8, 55)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "cost of 8 kg grapes = 70 × 8 = 560 . cost of 8 kg of mangoes = 55 × 8 = 440 . total cost he has to pay = 560 + 440 = 1000 c" | gain |
math_qa__9Rztdr29WOeCsB2k | A certain number when divided by 39 leaves a remainder 16, what is the remainder when the same number is divided by 13?
Choose the correct choice from the following answers: A) 7 B) 8 C) 9 D) 6 E) 3 | <gadget id="calculator">16 % 13</gadget>
<output>3</output>
<result>E</result> | E | 3 | A certain number when divided by 39 leaves a remainder 16, what is the remainder when the same number is divided by 13? | {
"A": "7",
"B": "8",
"C": "9",
"D": "6",
"E": "3"
} | reminder(16, 13) | reminder(n1,n2)| | "explanation : 39 + 16 = 55 / 13 = 3 ( remainder ) answer : e" | general |
math_qa__IL2GCKwqeGtPsXdk | A pump can fill a tank with water in 4 hours. Because of a leak, it took 20 hours to fill the tank. The leak can drain all the water of the tank in? Choose the correct choice from the following answers:
A) 1 B) 3 C) 5 D) 4 E) 2 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/4) - (1/20)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / (1/5)</gadget>
<output>5</output>
<result>C</result> | C | 5 | A pump can fill a tank with water in 4 hours. Because of a leak, it took 20 hours to fill the tank. The leak can drain all the water of the tank in? | {
"A": "1",
"B": "3",
"C": "5",
"D": "4",
"E": "2"
} | divide(const_1, subtract(divide(const_1, 4), divide(const_1, 20))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2) | p - - > pump , l - - - > leak pipe - - - - - - - - - - p - - - - - - - - - l - - - - - - - - - - - - ( p - l ) - - time - - - - - - - - - 4 - - - - - - - - - x - - - - - - - - - - - - - 20 * rate - - - - - - - - - 5 - - - - - - - - - x - - - - - - - - - - - - - 1 work - - - - - - - 20 - - - - - - - - - 20 - - - - - - - - - - - 20 time required to empty the tank if leakage present = 20 / ( ( 5 ) - 1 ) = ( 20 ) / ( 4 ) = 5 ans - c | physics |
math_qa__Fy60osQlmRHnAaTZ | Suppose 5 monkeys take 5 minutes to eat 5 bananas. How many monkeys would it take to eat 15 bananas in 15 minutes?
Choose the correct choice from the following answers.
A) 9
B) 10
C) 11
D) 5
E) 13 | <gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<result>D</result> | D | 5 | Suppose 5 monkeys take 5 minutes to eat 5 bananas. How many monkeys would it take to eat 15 bananas in 15 minutes? | {
"A": "9",
"B": "10",
"C": "11",
"D": "5",
"E": "13"
} | divide(15, divide(15, 5)) | divide(n3,n0)|divide(n3,#0)| | "one monkey takes 5 min to eat 1 banana , so in 15 mins 1 monkey will eat 3 bananas , so for 15 bananas in 15 min we need 15 / 3 = 5 monkeys answer : d" | physics |
math_qa__YSo1nYSoctw7QibP | 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 2 men and 2 women will do that task. Options:
A) 3 / 7 B) 3 / 10 C) 3 / 18 D) 3 / 16 E) 3 / 11 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">6 / 14</gadget>
<output>3/7 = around 0.428571</output>
<result>A</result> | A | 0.428571 | 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 2 men and 2 women will do that task. | {
"A": "3 / 7",
"B": "3 / 10",
"C": "3 / 18",
"D": "3 / 16",
"E": "3 / 11"
} | divide(add(multiply(divide(subtract(8, 2), subtract(6, 3)), 2), 2), add(multiply(6, divide(subtract(8, 2), subtract(6, 3))), 2)) | subtract(n1,n3)|subtract(n2,n0)|divide(#0,#1)|multiply(n4,#2)|multiply(n2,#2)|add(n5,#3)|add(n3,#4)|divide(#5,#6)| | "3 m + 8 w = 6 m + 2 w 3 m = 6 w 1 m = 2 w therefore 3 m + 8 w = 14 w 2 m + 2 w = 6 w answer is 6 / 14 = 3 / 7 answer : a" | physics |
math_qa__7ZoX4Tw4pc9Izhka | rahul played weel in this season.his current batting averagge is 52.if he score 78 runs in today match.his batting average will become 54.how many matches had he played in this season. Choose the correct answer:
A) 8 B) 12 C) 9 D) 6 E) 5 | <gadget id="calculator">78 - 54</gadget>
<output>24</output>
<gadget id="calculator">54 - 52</gadget>
<output>2</output>
<gadget id="calculator">24 / 2</gadget>
<output>12</output>
<result>B</result> | B | 12 | rahul played weel in this season.his current batting averagge is 52.if he score 78 runs in today match.his batting average will become 54.how many matches had he played in this season. | {
"A": "8",
"B": "12",
"C": "9",
"D": "6",
"E": "5"
} | divide(subtract(78, 54), subtract(54, 52)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "52 x + 78 = 54 ( x + 1 ) = > 2 x = 24 = > x = 12 answer : b" | general |
math_qa__5d6TFrvwUxvuQM3K | A container holding 12 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 9 ounces of a solution that is 1 part alcohol to 2 parts water. What is the ratio of alcohol to water in the resulting solution? Pick one:
A) 1 : 2 B) 3 : 7 C) 3 : 5 D) 4 : 7 E) 7 : 3 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">12 * (1/3)</gadget>
<output>4</output>
<gadget id="calculator">9 * (1/3)</gadget>
<output>3</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">12 + 9</gadget>
<output>21</output>
<gadget id="calculator">21 - 7</gadget>
<output>14</output>
<gadget id="calculator">7 / 14</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | A container holding 12 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 9 ounces of a solution that is 1 part alcohol to 2 parts water. What is the ratio of alcohol to water in the resulting solution? | {
"A": "1 : 2",
"B": "3 : 7",
"C": "3 : 5",
"D": "4 : 7",
"E": "7 : 3"
} | divide(add(multiply(12, divide(1, add(1, 2))), multiply(9, divide(1, add(1, 2)))), subtract(add(12, 9), add(multiply(12, divide(1, add(1, 2))), multiply(9, divide(1, add(1, 2)))))) | add(n1,n2)|add(n1,n5)|add(n0,n3)|divide(n1,#0)|divide(n1,#1)|multiply(n0,#3)|multiply(n3,#4)|add(#5,#6)|subtract(#2,#7)|divide(#7,#8)| | "container 1 has 12 ounces in the ratio 1 : 2 or , x + 2 x = 12 gives x ( alcohol ) = 4 and remaining water = 8 container 2 has 9 ounces in the ratio 1 : 2 or , x + 2 x = 9 gives x ( alcohol ) = 3 and remaining water = 6 mixing both we have alcohol = 4 + 3 and water = 8 + 6 ratio thus alcohol / water = 7 / 14 = 1 / 2 answer a" | other |
math_qa__11X05difvIFCkAdy | Some of the 50% solution of acid was removed and this was replaced with an equal amount of 20% solution of acid. As a result, a 35% solution of acid was obtained. What fraction of the original solution was replaced?
Choices:
A) 1 / 3 B) 1 / 2 C) 2 / 3 D) 3 / 5 E) 4 / 7 | <gadget id="calculator">50 + 20</gadget>
<output>70</output>
<gadget id="calculator">35 / 70</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | Some of the 50% solution of acid was removed and this was replaced with an equal amount of 20% solution of acid. As a result, a 35% solution of acid was obtained. What fraction of the original solution was replaced? | {
"A": "1 / 3",
"B": "1 / 2",
"C": "2 / 3",
"D": "3 / 5",
"E": "4 / 7"
} | divide(35, add(50, 20)) | add(n0,n1)|divide(n2,#0) | let x be the fraction of the original solution that was replaced . 0.5 * ( 1 - x ) + 0.2 ( x ) = 0.35 0.3 x = 0.15 x = 1 / 2 the answer is b . | gain |
math_qa__yCZK4qJS4Fn4GXhh | The maximum number of students among them 1048 pens and 828 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: Choose the correct answer:
A) 4 B) 8 C) 16 D) 1911 E) none of these | <gadget id="calculator">gcd(1_048, 828)</gadget>
<output>4</output>
<result>A</result> | A | 4 | The maximum number of students among them 1048 pens and 828 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: | {
"A": "4",
"B": "8",
"C": "16",
"D": "1911",
"E": "none of these"
} | gcd(1048, 828) | gcd(n0,n1)| | "explanation : required number of students = h . c . f of 1048 and 828 = 4 . answer : a" | general |
math_qa__O9NlEXxqfyreR69A | Marts income is 40 percent more than Tims income and Tims income is 40 percent less than Juans income. What percentage of Juans income is Marts income Choose the correct choice from the following answers:
A) 124 %
B) 120 %
C) 96 %
D) 80 %
E) 84 % | <gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">100 / 60</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 100</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">140 / (500/3)</gadget>
<output>21/25 = around 0.84</output>
<gadget id="calculator">(21/25) * 100</gadget>
<output>84</output>
<result>E</result> | E | 84 | Marts income is 40 percent more than Tims income and Tims income is 40 percent less than Juans income. What percentage of Juans income is Marts income | {
"A": "124 %",
"B": "120 %",
"C": "96 %",
"D": "80 %",
"E": "84 %"
} | multiply(divide(add(const_100, 40), multiply(divide(const_100, subtract(const_100, 40)), const_100)), const_100) | add(n0,const_100)|subtract(const_100,n1)|divide(const_100,#1)|multiply(#2,const_100)|divide(#0,#3)|multiply(#4,const_100)| | "m = ( 140 / 100 ) t t = ( 60 / 100 ) j = > m = ( 84 / 100 ) j answer e ." | general |
math_qa__8gktDmYsgXnhI8KN | If all the 6 are replaced by 9, then the algebraic sum of all the numbers from 1 to 100(both inclusive) varies by Choose the correct choice: A) 330 B) 340 C) 350 D) 360 E) 370 | <gadget id="calculator">9 - 6</gadget>
<output>3</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 10</gadget>
<output>300</output>
<gadget id="calculator">300 + 30</gadget>
<output>330</output>
<result>A</result> | A | 330 | If all the 6 are replaced by 9, then the algebraic sum of all the numbers from 1 to 100(both inclusive) varies by | {
"A": "330",
"B": "340",
"C": "350",
"D": "360",
"E": "370"
} | add(multiply(multiply(subtract(9, 6), const_10), const_10), multiply(subtract(9, 6), const_10)) | subtract(n1,n0)|multiply(#0,const_10)|multiply(#1,const_10)|add(#2,#1) | 1 11 21 . . . . . . . 91 2 12 22 . . . . . . . . 92 3 13 23 . . . . . . . . 93 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . there are total 20 occurrence of 6 . once place at 6 th row in every column and tens place in 6 th column and diff of 6 and 9 is 3 so 3 * 1 * 10 + 3 * 10 * 10 = 330 answer : a | other |
math_qa__Mvig0jMyReHF2wVp | A gold purification process cycle, is able to remove 1/16 of impurities in gold. If we have a 10 grams of gold ore dust containing 16/24 pure gold. How much impurities would have been removed from that old after 4 cycles of purification using that method? Select the correct option
A) 0.72 B) 0.74 C) 0.76 D) 0.78 E) 0.82 | <gadget id="calculator">24 - 16</gadget>
<output>8</output>
<gadget id="calculator">10 * 8</gadget>
<output>80</output>
<gadget id="calculator">80 / 24</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(10/3) / 16</gadget>
<output>5/24 = around 0.208333</output>
<gadget id="calculator">(10/3) - (5/24)</gadget>
<output>25/8 = around 3.125</output>
<gadget id="calculator">(25/8) / 16</gadget>
<output>25/128 = around 0.195312</output>
<gadget id="calculator">(25/8) - (25/128)</gadget>
<output>375/128 = around 2.929688</output>
<gadget id="calculator">(375/128) / 16</gadget>
<output>375/2_048 = around 0.183105</output>
<gadget id="calculator">(375/128) - (375/2_048)</gadget>
<output>5_625/2_048 = around 2.746582</output>
<gadget id="calculator">(5_625/2_048) / 16</gadget>
<output>5_625/32_768 = around 0.171661</output>
<gadget id="calculator">(5_625/2_048) - (5_625/32_768)</gadget>
<output>84_375/32_768 = around 2.574921</output>
<gadget id="calculator">(10/3) - (84_375/32_768)</gadget>
<output>74_555/98_304 = around 0.758413</output>
<result>C</result> | C | 0.76 | A gold purification process cycle, is able to remove 1/16 of impurities in gold. If we have a 10 grams of gold ore dust containing 16/24 pure gold. How much impurities would have been removed from that old after 4 cycles of purification using that method? | {
"A": "0.72",
"B": "0.74",
"C": "0.76",
"D": "0.78",
"E": "0.82"
} | subtract(divide(multiply(10, subtract(24, 16)), 24), subtract(subtract(subtract(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), divide(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), 16)), divide(subtract(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), divide(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), 16)), 16)), divide(subtract(subtract(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), divide(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), 16)), divide(subtract(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), divide(subtract(divide(multiply(10, subtract(24, 16)), 24), divide(divide(multiply(10, subtract(24, 16)), 24), 16)), 16)), 16)), 16))) | subtract(n4,n1)|multiply(n2,#0)|divide(#1,n4)|divide(#2,n1)|subtract(#2,#3)|divide(#4,n1)|subtract(#4,#5)|divide(#6,n1)|subtract(#6,#7)|divide(#8,n1)|subtract(#8,#9)|subtract(#2,#10) | x is the initial quantity of impurities in that gold . after a cycle of purification the quantity of impurities left would be x 1 = x - 1 / 16 x i . e . x 1 = 15 / 16 x same thing for x 2 , x 3 , x 4 , respectively representing the quantity of impurities left after 2 , 3 , 4 cycles of purification . so we have : x 1 = 15 / 16 x x 2 = 15 / 16 x 1 x 3 = 15 / 16 x 2 x 4 = 15 / 16 x 3 by multiplying both ends of the equations we get : x 1 * x 2 * x 3 * x 4 = ( 15 / 16 ) ^ 4 x * x 1 * x 2 * x 3 simplification leaves us with : x 4 = ( 15 / 16 ) ^ 4 x x 4 is the quantity of impurities left after four cycles . so the cumulative quantity of impurities ( q 4 ) which has been removed after 4 cycles is : q 4 = x - x 4 = x - ( 15 / 16 ) ^ 4 x i . e . q 4 = x ( 1 - ( 15 / 16 ) ^ 4 ) in this case , given x was : x = ( 1 - 16 / 24 ) * 10 g = 3.33 g ( remember we had 16 / 24 pure gold ) so we have q 4 = 3.33 * ( 1 - ( 15 / 16 ) ^ 4 ) = 3.33 * ( 1 - ( 50625 / 65536 ) ) = 3.33 * ( 14911 / 65536 ) = 0.757 rounded gives q 4 = 0.76 answer : c | general |
math_qa__Sziw66VJnlf98Uh9 | If f(x) = 2x^2 + y, and f(2) = 20, what is the value of f(5)? Choices: A) 104 B) 60 C) 62 D) 50 E) 25 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">2 * 25</gadget>
<output>50</output>
<gadget id="calculator">12 + 50</gadget>
<output>62</output>
<result>C</result> | C | 62 | If f(x) = 2x^2 + y, and f(2) = 20, what is the value of f(5)? | {
"A": "104",
"B": "60",
"C": "62",
"D": "50",
"E": "25"
} | add(subtract(20, multiply(power(2, 2), 2)), multiply(2, power(5, 2))) | power(n4,n0)|power(n0,n0)|multiply(n0,#0)|multiply(n0,#1)|subtract(n3,#3)|add(#2,#4)| | "f ( x ) = 2 x ^ 2 + y f ( 2 ) = 20 = > 2 * ( 2 ) ^ 2 + y = 20 = > 8 + y = 20 = > y = 12 f ( 5 ) = 2 * ( 5 ) ^ 2 + 12 = 62 answer c" | general |
math_qa__9J0raRuXel5pxUfh | Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 10 percent was planted with grapes and 80 percent of the cleared land was planted with potato. If the remaining 450 acres of cleared land was planted with tomato, how many acres did the farmer own? Choose the most appropriate option: A) 3500 B) 4500 C) 5500 D) 5250 E) 5000 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 - 80</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(1/10) * (9/10)</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">450 / (9/100)</gadget>
<output>5_000</output>
<result>E</result> | E | 5,000 | Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 10 percent was planted with grapes and 80 percent of the cleared land was planted with potato. If the remaining 450 acres of cleared land was planted with tomato, how many acres did the farmer own? | {
"A": "3500",
"B": "4500",
"C": "5500",
"D": "5250",
"E": "5000"
} | divide(450, multiply(divide(subtract(subtract(const_100, 10), 80), const_100), divide(90, const_100))) | divide(n0,const_100)|subtract(const_100,n1)|subtract(#1,n2)|divide(#2,const_100)|multiply(#3,#0)|divide(n3,#4) | 10 % od 90 % = 9 % , 80 % 0 f 90 % = 72 % so the remaining 90 - 9 - 72 = 9 % = 450 acres or 10 % of 90 % = 9 % - - > 450 / 9 * 100 = 5000 acres answer ( e ) | gain |
math_qa__lvSFu5JgIivibfWg | David obtained 36, 35, 42, 57 and 55 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ? Choose the most appropriate option
A) 75
B) 45
C) 87
D) 165
E) 11 | <gadget id="calculator">36 + 35</gadget>
<output>71</output>
<gadget id="calculator">71 + 42</gadget>
<output>113</output>
<gadget id="calculator">113 + 57</gadget>
<output>170</output>
<gadget id="calculator">170 + 55</gadget>
<output>225</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">225 / 5</gadget>
<output>45</output>
<result>B</result> | B | 45 | David obtained 36, 35, 42, 57 and 55 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ? | {
"A": "75",
"B": "45",
"C": "87",
"D": "165",
"E": "11"
} | divide(add(add(add(add(36, 35), 42), 57), 55), add(const_2, const_3)) | add(n0,n1)|add(const_2,const_3)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "explanation : average = ( 36 + 35 + 42 + 57 + 55 ) / 5 = 225 / 5 = 45 . answer : b" | general |
math_qa__UlBi60OyXIHUvDZm | Find compound interest on $ 16000 at 15% per annum for 2 years 4 months, compounded annually. Answers
A) 6109 B) 6209 C) 6218 D) 6107 E) 6100 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">16_000 * (3/20)</gadget>
<output>2_400</output>
<gadget id="calculator">16_000 + 2_400</gadget>
<output>18_400</output>
<gadget id="calculator">18_400 * (3/20)</gadget>
<output>2_760</output>
<gadget id="calculator">2_400 + 2_760</gadget>
<output>5_160</output>
<gadget id="calculator">18_400 + 2_760</gadget>
<output>21_160</output>
<gadget id="calculator">(3/20) / 3</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">21_160 * (1/20)</gadget>
<output>1_058</output>
<gadget id="calculator">5_160 + 1_058</gadget>
<output>6_218</output>
<result>C</result> | C | 6,218 | Find compound interest on $ 16000 at 15% per annum for 2 years 4 months, compounded annually. | {
"A": "6109",
"B": "6209",
"C": "6218",
"D": "6107",
"E": "6100"
} | add(add(multiply(16000, divide(15, const_100)), multiply(add(16000, multiply(16000, divide(15, const_100))), divide(15, const_100))), multiply(add(add(16000, multiply(16000, divide(15, const_100))), multiply(add(16000, multiply(16000, divide(15, const_100))), divide(15, const_100))), divide(divide(15, const_100), const_3))) | divide(n1,const_100)|divide(#0,const_3)|multiply(n0,#0)|add(n0,#2)|multiply(#3,#0)|add(#2,#4)|add(#3,#4)|multiply(#6,#1)|add(#5,#7)| | "time = 2 years 4 months = 2 ( 4 / 12 ) years = 2 ( 1 / 3 ) years . amount = $ [ 16000 x ( 1 + ( 15 / 100 ) ) 2 x ( 1 + ( ( 1 / 3 ) * 15 ) / 100 ) ] = $ [ 16000 * ( 23 / 20 ) * ( 23 / 20 ) * ( 21 / 20 ) ] = $ 22218 . : . c . i . = rs . ( 22218 - 16000 ) = $ 6218 answer c ." | gain |
math_qa__BQQCMwU5dL6yaXjT | the average score in an examination of 10 students of a class is 60 . if the scores of the top 5 students are not considered , the average score of the remaining students falls by 5 . the pass mark was 40 and the maximum mark was 100 . it is also known that none of the students failed . if each of the top 5 scorers had distinct integral scores , the maximum possible score of the topper is . . . . . .
Answers:
A) 99
B) 100
C) 87
D) 95
E) 90 | <gadget id="calculator">10 * 60</gadget>
<output>600</output>
<gadget id="calculator">60 - 5</gadget>
<output>55</output>
<gadget id="calculator">55 * 5</gadget>
<output>275</output>
<gadget id="calculator">600 - 275</gadget>
<output>325</output>
<gadget id="calculator">325 - 55</gadget>
<output>270</output>
<gadget id="calculator">55 + 1</gadget>
<output>56</output>
<gadget id="calculator">270 - 56</gadget>
<output>214</output>
<gadget id="calculator">55 + 2</gadget>
<output>57</output>
<gadget id="calculator">214 - 57</gadget>
<output>157</output>
<gadget id="calculator">55 + 3</gadget>
<output>58</output>
<gadget id="calculator">157 - 58</gadget>
<output>99</output>
<result>A</result> | A | 99 | the average score in an examination of 10 students of a class is 60 . if the scores of the top 5 students are not considered , the average score of the remaining students falls by 5 . the pass mark was 40 and the maximum mark was 100 . it is also known that none of the students failed . if each of the top 5 scorers had distinct integral scores , the maximum possible score of the topper is . . . . . . | {
"A": "99",
"B": "100",
"C": "87",
"D": "95",
"E": "90"
} | subtract(subtract(subtract(subtract(subtract(multiply(10, 60), multiply(subtract(60, 5), 5)), subtract(60, 5)), add(subtract(60, 5), const_1)), add(subtract(60, 5), const_2)), add(subtract(60, 5), const_3)) | multiply(n0,n1)|subtract(n1,n2)|add(#1,const_1)|add(#1,const_2)|add(#1,const_3)|multiply(n2,#1)|subtract(#0,#5)|subtract(#6,#1)|subtract(#7,#2)|subtract(#8,#3)|subtract(#9,#4) | detailed solution 10 students have scored 600 marks amongst them , and no one is allowed to score lesser than 40 or higher than 100 . the idea now is to maximize what the highest scorer gets . the 5 least scores have an average of 55 , which means that they have scored 55 x 5 = 275 marks amongst them . this leaves 325 marks to be shared amongst the top 5 students . lets call them a , b , c , d and e . now , in order to maximize what the top scorer “ e ” gets , all the others have to get the least possible scores ( and at the same time , they should also get distinct integers . ) the least possible score of the top 5 should be at least equal to the highest of the bottom 5 . now we want to make sure that the highest of the bottom 5 is the least possible . this can be done by making all scores equal to 55 . if some scores are less than 55 , some other scores have to be higher than 55 to compensate and make the average 55 . thus the highest score is the least only when the range is 0 . so now , we have the lowest value that the top 5 can score , which is 55 . the others have to get distinct integer scores , and as few marks as possible , so that “ e ” gets the maximum . so , 55 + 56 + 57 + 58 + e = 325 e = 99 marks . answer choice ( a ) | general |
math_qa__HGiImh5bDslReflz | 5+3+2 = 151022
9+2+4 = 183652
8+6+3 = 482466
5+4+5 = 202541
THEN ;
7+2+5 = ? Choose the most appropriate option
A) 253547 B) 143681 C) 143547 D) 147614 E) 255547 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 * 10</gadget>
<output>140</output>
<gadget id="calculator">140 + 3</gadget>
<output>143</output>
<gadget id="calculator">143 * 1_000</gadget>
<output>143_000</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">143_000 + 500</gadget>
<output>143_500</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">35 + 14</gadget>
<output>49</output>
<gadget id="calculator">49 - 2</gadget>
<output>47</output>
<gadget id="calculator">143_500 + 47</gadget>
<output>143_547</output>
<result>C</result> | C | 143,547 | 5+3+2 = 151022
9+2+4 = 183652
8+6+3 = 482466
5+4+5 = 202541
THEN ;
7+2+5 = ? | {
"A": "253547",
"B": "143681",
"C": "143547",
"D": "147614",
"E": "255547"
} | add(add(multiply(add(multiply(multiply(7, 2), const_10), 3), const_1000), multiply(5, const_100)), subtract(add(multiply(7, 5), multiply(7, 2)), 2)) | multiply(n2,n16)|multiply(n0,const_100)|multiply(n0,n16)|add(#2,#0)|multiply(#0,const_10)|add(n1,#4)|subtract(#3,n2)|multiply(#5,const_1000)|add(#7,#1)|add(#8,#6) | c 143547 | general |
math_qa__r6Whf687eM1pu1Tj | On a map, 1.5 inches represent 24 miles. How many miles approximately is the distance if you measured 45 centimeters assuming that 1-inch is 2.54 centimeters? Choose the correct choice from the following choices: A) 174.2 B) 212 C) 283 D) 296 E) 282.4 | <gadget id="calculator">45 / 2.54</gadget>
<output>17.716535</output>
<gadget id="calculator">24 / 1.5</gadget>
<output>16</output>
<gadget id="calculator">17.716535 * 16</gadget>
<output>283.46456</output>
<result>C</result> | C | 283 | On a map, 1.5 inches represent 24 miles. How many miles approximately is the distance if you measured 45 centimeters assuming that 1-inch is 2.54 centimeters? | {
"A": "174.2",
"B": "212",
"C": "283",
"D": "296",
"E": "282.4"
} | multiply(divide(45, 2.54), divide(24, 1.5)) | divide(n2,n4)|divide(n1,n0)|multiply(#0,#1)| | "1.5 inch = 2.54 * 1.5 cm . so , 2.54 * 1.5 represents 24 miles . so for 45 cm . : 45 / ( 2.54 * 1.5 ) = x / 24 - - - > x = 24 * 45 / ( 3.81 ) = 283 answer will be c ." | physics |
math_qa__C5ccajflCYP0O8uG | A labourer was engaged for 25 days on the condition that for every day, he works, he will be paid Rs. 2 and for every day, he is absent he will be fined 50p. If he receives only Rs. 37•50, find the no. of days he was absent is_____ Answers.
A) 3 days B) 4 days C) 5 days D) 6 days E) 7 days | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">37 + (1/2)</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">50 - (75/2)</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(1/2) + 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(25/2) / (5/2)</gadget>
<output>5</output>
<result>C</result> | C | 5 | A labourer was engaged for 25 days on the condition that for every day, he works, he will be paid Rs. 2 and for every day, he is absent he will be fined 50p. If he receives only Rs. 37•50, find the no. of days he was absent is_____ | {
"A": "3 days",
"B": "4 days",
"C": "5 days",
"D": "6 days",
"E": "7 days"
} | divide(subtract(50, add(37, divide(50, const_100))), add(divide(50, const_100), const_2)) | divide(n2,const_100)|add(n3,#0)|add(#0,const_2)|subtract(n2,#1)|divide(#3,#2) | if a labour worked for 25 days he should get 50 rs . but in this he is getting 13 rs less . if he do n ' t go for work for 1 day he will loose 2.5 rs then no of days ( absent ) = 13 / 2.5 = 5.2 . means he was absent for 5 days answer : c | physics |
math_qa__SdGI3jaLg2zz7gvx | A cycle is bought for Rs.930 and sold for Rs.1210, find the gain percent? Choose the correct choice from the following answers:
A) 70 % B) 30 % C) 40 % D) 50 % E) 80 % | <gadget id="calculator">1_210 - 930</gadget>
<output>280</output>
<gadget id="calculator">280 / 930</gadget>
<output>28/93 = around 0.301075</output>
<gadget id="calculator">(28/93) * 100</gadget>
<output>2_800/93 = around 30.107527</output>
<result>B</result> | B | 30 | A cycle is bought for Rs.930 and sold for Rs.1210, find the gain percent? | {
"A": "70 %",
"B": "30 %",
"C": "40 %",
"D": "50 %",
"E": "80 %"
} | multiply(divide(subtract(1210, 930), 930), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 930 - - - - 280 100 - - - - ? = > 30 % answer : b" | gain |
math_qa__nXCOqx6QiNsUzCgI | Calculate the ratio between x and y if 80% of x equal to 20% of y? Choose the correct answer:
A) 1 : 1
B) 3 : 1
C) 4 : 5
D) 4 : 3
E) 4 : 1 | <gadget id="calculator">80 / 20</gadget>
<output>4</output>
<result>E</result> | E | 4 | Calculate the ratio between x and y if 80% of x equal to 20% of y? | {
"A": "1 : 1",
"B": "3 : 1",
"C": "4 : 5",
"D": "4 : 3",
"E": "4 : 1"
} | divide(80, 20) | divide(n0,n1) | explanation : 80 x = 20 y x : y = 80 : 20 = 4 : 1 answer : e | general |
math_qa__LqYsuisG9yJFsHZG | A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it? Choose the correct choice from the following: A) 76 hrs B) 99 hrs C) 55 hrs D) 90 hrs E) 11 hrs | <gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/9) - (1/10)</gadget>
<output>1/90 = around 0.011111</output>
<gadget id="calculator">1 / (1/90)</gadget>
<output>90</output>
<result>D</result> | D | 90 | A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it? | {
"A": "76 hrs",
"B": "99 hrs",
"C": "55 hrs",
"D": "90 hrs",
"E": "11 hrs"
} | inverse(subtract(divide(const_1, 9), divide(const_1, const_10))) | divide(const_1,n0)|divide(const_1,const_10)|subtract(#0,#1)|inverse(#2)| | "1 / 9 - 1 / x = 1 / 10 = > 90 hrs answer : d" | physics |
math_qa__9c0IvF6rxrodB1lJ | Andrew travelling to 7 cities. Gasoline prices varied from city to city. $1.75, $1.61, $1.79, $2.11, $1.96, $2.09, $1.85. What is the median gasoline price? Choose the correct choice from the following choices: A) $ 1 B) $ 1.85 C) $ 1.92 D) $ 2.13 E) $ 2.15 | <gadget id="calculator">1.75 + 1.61</gadget>
<output>3.36</output>
<gadget id="calculator">3.36 + 1.79</gadget>
<output>5.15</output>
<gadget id="calculator">5.15 + 2.11</gadget>
<output>7.26</output>
<gadget id="calculator">7.26 + 1.96</gadget>
<output>9.22</output>
<gadget id="calculator">9.22 + 2.09</gadget>
<output>11.31</output>
<gadget id="calculator">11.31 + 1.85</gadget>
<output>13.16</output>
<gadget id="calculator">13.16 / 7</gadget>
<output>1.88</output>
<gadget id="calculator">min(1.88, 1.85)</gadget>
<output>1.85</output>
<result>B</result> | B | 1.85 | Andrew travelling to 7 cities. Gasoline prices varied from city to city. $1.75, $1.61, $1.79, $2.11, $1.96, $2.09, $1.85. What is the median gasoline price? | {
"A": "$ 1",
"B": "$ 1.85",
"C": "$ 1.92",
"D": "$ 2.13",
"E": "$ 2.15"
} | min(divide(add(add(add(add(add(add(1.75, 1.61), 1.79), 2.11), 1.96), 2.09), 1.85), 7), 1.85) | add(n1,n2)|add(n3,#0)|add(n4,#1)|add(n5,#2)|add(n6,#3)|add(n7,#4)|divide(#5,n0)|min(n7,#6)| | "ordering the data from least to greatest , we get : $ 1.61 , $ 1.75 , $ 1.79 , $ 1.85 , $ 1.96 , $ 2.09 , $ 2.11 the median gasoline price is $ 1.85 . ( there were 3 states with higher gasoline prices and 3 with lower prices . ) b" | general |
math_qa__7zfY1ch1RxsOxJyk | If 20 men can build a water fountain 56 metres long in 6 days, what length of a similar water fountain can be built by 35 men in 3 days? Options
A) 40 m B) 44 m C) 47 m D) 49 m E) 50 m | <gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">56 / 120</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">35 * 3</gadget>
<output>105</output>
<gadget id="calculator">(7/15) * 105</gadget>
<output>49</output>
<result>D</result> | D | 49 | If 20 men can build a water fountain 56 metres long in 6 days, what length of a similar water fountain can be built by 35 men in 3 days? | {
"A": "40 m",
"B": "44 m",
"C": "47 m",
"D": "49 m",
"E": "50 m"
} | multiply(divide(56, multiply(20, 6)), multiply(35, 3)) | multiply(n0,n2)|multiply(n3,n4)|divide(n1,#0)|multiply(#2,#1) | explanation : let the required length be x metres more men , more length built ( direct proportion ) less days , less length built ( direct proportion ) men 20 : 35 days 6 : 3 : : 56 : x therefore ( 20 x 6 x x ) = ( 35 x 3 x 56 ) x = ( 35 x 3 x 56 ) / 120 = 49 hence , the required length is 49 m . answer : d | physics |
math_qa__RU8N73kkI1M9mkKt | A certain psychologist charges $25 more for the first hour of therapy than for each additional hour. If the total charge to a patient who receives 5 hours of therapy is $250, what is the total charge to a patient who receives only 2 hours of therapy ? Choose the correct choice from the following answers: A) $ 115 B) $ 135 C) $ 150 D) $ 165 E) $ 192 | <gadget id="calculator">250 - 25</gadget>
<output>225</output>
<gadget id="calculator">225 / 5</gadget>
<output>45</output>
<gadget id="calculator">45 * 2</gadget>
<output>90</output>
<gadget id="calculator">90 + 25</gadget>
<output>115</output>
<result>A</result> | A | 115 | A certain psychologist charges $25 more for the first hour of therapy than for each additional hour. If the total charge to a patient who receives 5 hours of therapy is $250, what is the total charge to a patient who receives only 2 hours of therapy ? | {
"A": "$ 115",
"B": "$ 135",
"C": "$ 150",
"D": "$ 165",
"E": "$ 192"
} | add(multiply(divide(subtract(250, 25), 5), 2), 25) | subtract(n2,n0)|divide(#0,n1)|multiply(n3,#1)|add(n0,#2)| | "let the charge for first hour = x + 25 then charge for each additional hour = x x + 25 + 4 x = 250 = > 5 x = 225 = > x = 45 total charge for patient for 3 hours of therapy = x + 25 + x = 2 x + 25 = 115 $ answer a" | general |
math_qa__S3fEIRigObbhWxTO | There are 8 stores in town that had a total of 23 visitors on a particular day. However, only 12 people went shopping that day; some people visited more than one store. If 8 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited? Choose the correct option:
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">23 - 16</gadget>
<output>7</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<result>C</result> | C | 4 | There are 8 stores in town that had a total of 23 visitors on a particular day. However, only 12 people went shopping that day; some people visited more than one store. If 8 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | subtract(subtract(23, multiply(8, const_2)), subtract(subtract(12, 8), const_1)) | multiply(n0,const_2)|subtract(n2,n0)|subtract(n1,#0)|subtract(#1,const_1)|subtract(#2,#3)| | "8 people visited 2 stores each for 16 visits . to maximize the number of stores that one person visited , let ' s assume that 3 people visited 1 store each . the number of remaining visits is 23 - 16 - 3 = 4 , which is the maximum that one person could have visited . the answer is c ." | general |
math_qa__EC5e94DNqOKIYGOC | If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.61 then sum is Choose the correct choice from the following answers.
A) s . 6100 B) s . 5100 C) s . 5800 D) s . 6000 E) s . 6200 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * (1/10)</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">61 / (1/100)</gadget>
<output>6_100</output>
<result>A</result> | A | 6,100 | If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.61 then sum is | {
"A": "s . 6100",
"B": "s . 5100",
"C": "s . 5800",
"D": "s . 6000",
"E": "s . 6200"
} | divide(61, multiply(divide(10, const_100), divide(10, const_100))) | divide(n0,const_100)|multiply(#0,#0)|divide(n2,#1)| | "p ( r / 100 ) ^ 2 = c . i - s . i p ( 10 / 100 ) ^ 2 = 61 6100 answer : a" | gain |
math_qa__ffM148dJ62aAgdSz | according to the directions on a can of frozen orange juice concentrate , 1 can of concentrate is to be mixed with 4 cans of water to make orange juice . how many 12 ounce cans of concentrate are required to prepare 120 6 - ounce servings of orange juice ? Pick.
A) 10 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">720 / 5</gadget>
<output>144</output>
<gadget id="calculator">144 / 12</gadget>
<output>12</output>
<result>B</result> | B | 12 | according to the directions on a can of frozen orange juice concentrate , 1 can of concentrate is to be mixed with 4 cans of water to make orange juice . how many 12 ounce cans of concentrate are required to prepare 120 6 - ounce servings of orange juice ? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(divide(multiply(120, 6), add(4, 1)), 12) | add(n0,n1)|multiply(n3,n4)|divide(#1,#0)|divide(#2,n2) | 1 x 12 ounce can of concentrate + 4 x 12 ounce cans of water = 60 ounces of the mixture . 60 ounces of mixture gives ( 60 / 6 ) = 10 servings . thus 1 x 12 ounce can of concentrate is used to produce 10 servings of the mixture . to make 120 servings of the mixture , we need 120 / 10 = 12 cans of the concentrate . the answer is b . | general |
math_qa__wIDzTggWctHCpnmf | At a certain restaurant, the price of a sandwich is $ 4.00 more than the price of a cup of coffee. If the price of a sandwich and a cup of coffee is $ 7.35, including a sales tax of 5%, what is the price of a cup of coffee, EXCLUDING the sales tax? Choose the most appropriate option: A) $ 1.50 B) $ 3.00 C) $ 4.00 D) $ 5.50 E) $ 7.00 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">7.35 * 5</gadget>
<output>36.75</output>
<gadget id="calculator">36.75 / 10</gadget>
<output>3.675</output>
<gadget id="calculator">3.675 + 3.675</gadget>
<output>7.35</output>
<gadget id="calculator">7.35 - 5</gadget>
<output>2.35</output>
<gadget id="calculator">(1/5) + 2.35</gadget>
<output>2.55</output>
<gadget id="calculator">2.55 - 1</gadget>
<output>1.55</output>
<result>A</result> | A | 1.5 | At a certain restaurant, the price of a sandwich is $ 4.00 more than the price of a cup of coffee. If the price of a sandwich and a cup of coffee is $ 7.35, including a sales tax of 5%, what is the price of a cup of coffee, EXCLUDING the sales tax? | {
"A": "$ 1.50",
"B": "$ 3.00",
"C": "$ 4.00",
"D": "$ 5.50",
"E": "$ 7.00"
} | subtract(add(divide(const_1, 5), subtract(add(divide(multiply(7.35, 5), const_10), divide(multiply(7.35, 5), const_10)), 5)), const_1) | divide(const_1,n2)|multiply(n1,n2)|divide(#1,const_10)|add(#2,#2)|subtract(#3,n2)|add(#0,#4)|subtract(#5,const_1) | let the price of sandwich = s price of coffee = c s = c + 4 = > s - c = 4 - - 1 the price of a sandwich and a cup of coffee is $ 7.35 , including a sales tax of 5 % , 1.05 ( s + c ) = 7.35 = > s + c = 7 - - 2 from equations 1 and 2 , we get s = 5.5 $ c = 1.5 $ answer a | general |
math_qa__Mc6MUpI51G07vLto | What will be the percentage increase in the area of the cube's surface if each of the cube's edges grows by 30%? Answers.
A) 70 % B) 69 % C) 80 % D) 82 % E) 55 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(13/10) ** 2</gadget>
<output>169/100 = around 1.69</output>
<gadget id="calculator">(169/100) - 1</gadget>
<output>69/100 = around 0.69</output>
<gadget id="calculator">(69/100) * 100</gadget>
<output>69</output>
<result>B</result> | B | 69 | What will be the percentage increase in the area of the cube's surface if each of the cube's edges grows by 30%? | {
"A": "70 %",
"B": "69 %",
"C": "80 %",
"D": "82 %",
"E": "55 %"
} | multiply(subtract(power(add(const_1, divide(30, const_100)), const_2), const_1), const_100) | divide(n0,const_100)|add(#0,const_1)|power(#1,const_2)|subtract(#2,const_1)|multiply(#3,const_100) | the question is very easy . my logic is the following : a surface = 6 * a ^ 2 after 30 % increase a surface = 6 * ( ( 1.3 a ) ^ 2 ) = 6 * 1.69 * a ^ 2 the increase in the surface area = ( 6 * 1.69 * a ^ 2 - 6 * a ^ 2 ) / 6 * a ^ 2 = ( 6 * a ^ 2 ( 1.69 - 1 ) ) / ( 6 * a ^ 2 ) = 1.69 - 1 = 0.69 = 69 % answer : b | geometry |
math_qa__0okcfNIFrOj3bCn2 | If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number A of integers that can be negative?
Choose the correct choice
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 + 0</gadget>
<output>5</output>
<result>D</result> | D | 5 | If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number A of integers that can be negative? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | add(divide(const_10, const_2), 0) | divide(const_10,const_2)|add(n0,#0) | minimuum should be 1 maximum should be 4 : 1 out of a or b to make the multiplication negative 3 out of c , d , e or f to make the multiplication negative . negative + negative < 0 answer : c maximum will be 5 . . you dont require both the multiplicatin to be negative for entire equation to be negative . . . any one a or b can be negative to make ab negative and it can still be more ( away from 0 ) than the multiplication of 4 other - ve numbers . . . actually by writing minimum required as 1 out of 6 , you are actually meaning 5 out of 6 also possible as you will see a = 5 or 1 will give you same equation . . ans d | general |
math_qa__ZV2Nd8RBil5OfHpi | if the ratio of two number is 3:4 and LCM of the number is 180 then what is the number. Select the correct option:
A) 15 B) 20 C) 25 D) 30 E) 35 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">180 / 12</gadget>
<output>15</output>
<result>A</result> | A | 15 | if the ratio of two number is 3:4 and LCM of the number is 180 then what is the number. | {
"A": "15",
"B": "20",
"C": "25",
"D": "30",
"E": "35"
} | divide(180, multiply(3, 4)) | multiply(n0,n1)|divide(n2,#0)| | "product of two no = lcm * hcf 3 x * 4 x = 180 * x x = 15 answer : a" | other |
math_qa__3snMEhjq91fgbs6M | Calculate the average marks of a student who obtained 56, 60, 72, 85 and 80 marks (out of 100) in Geography, History and Government, Art, Computer Science and Modern Literature ? Select
A) 71.6 B) 70.6 C) 80.6 D) 60.6 E) 50.6 | <gadget id="calculator">56 + 60</gadget>
<output>116</output>
<gadget id="calculator">72 + 85</gadget>
<output>157</output>
<gadget id="calculator">116 + 157</gadget>
<output>273</output>
<gadget id="calculator">273 + 80</gadget>
<output>353</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">353 / 5</gadget>
<output>353/5 = around 70.6</output>
<result>B</result> | B | 70.6 | Calculate the average marks of a student who obtained 56, 60, 72, 85 and 80 marks (out of 100) in Geography, History and Government, Art, Computer Science and Modern Literature ? | {
"A": "71.6",
"B": "70.6",
"C": "80.6",
"D": "60.6",
"E": "50.6"
} | divide(add(add(add(56, 60), add(72, 85)), 80), add(const_2, const_3)) | add(n0,n1)|add(n2,n3)|add(const_2,const_3)|add(#0,#1)|add(n4,#3)|divide(#4,#2) | explanation : average = ( 56 + 60 + 72 + 85 + 80 ) / 5 = 70.6 . answer : b ) 70.6 | general |
math_qa__t7uUkfpI7MLVjAm1 | Find the 21th term of an arithmetic progression whose first term is 3 and the common difference is 5. Pick:
A) 100 B) 102 C) 103 D) 150 E) 46 | <gadget id="calculator">21 - 1</gadget>
<output>20</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 + 3</gadget>
<output>103</output>
<result>C</result> | C | 103 | Find the 21th term of an arithmetic progression whose first term is 3 and the common difference is 5. | {
"A": "100",
"B": "102",
"C": "103",
"D": "150",
"E": "46"
} | add(multiply(subtract(21, const_1), 5), 3) | subtract(n0,const_1)|multiply(n2,#0)|add(n1,#1)| | "n th term of a . p = a + ( n - 1 ) * d = 3 + ( 21 - 1 ) * 5 , = 3 + 100 = 103 . answer : c" | general |
math_qa__xjwmnII9olenJlNJ | A committee is reviewing a total of 20x black-and-white films and 6y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction W of the selected films are in color? Choose the most appropriate option
A) 1 / 130
B) 1 / 5
C) 3 / 13
D) 10 / 13
E) 30 / 31 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 6</gadget>
<output>31/5 = around 6.2</output>
<gadget id="calculator">6 / (31/5)</gadget>
<output>30/31 = around 0.967742</output>
<result>E</result> | E | 0.967742 | A committee is reviewing a total of 20x black-and-white films and 6y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction W of the selected films are in color? | {
"A": "1 / 130",
"B": "1 / 5",
"C": "3 / 13",
"D": "10 / 13",
"E": "30 / 31"
} | divide(6, add(divide(20, const_100), 6)) | divide(n0,const_100)|add(n1,#0)|divide(n1,#1)| | "it ' s y / xpercentnot y / x . if x = 20 and y = 10 . then : 20 x = 400 black - and - white films ; 6 y = 60 color films . y / x % = 10 / 20 % = 0.5 % of the black - and - white films , so 2 black - and - white films and all 60 color films , thus total of 62 films were selected . color films thus compose w 60 / 62 = 30 / 31 of the selected films . answer : e ." | general |
math_qa__bWmByCYbTdfBp71f | The slant height of a cone is 13 cm and radius of the base is 9 cm, find the curved surface of the cone? Pick one:
A) 367 B) 378 C) 365 D) 26 E) 28 | <gadget id="calculator">pi * 9</gadget>
<output>9*pi = around 28.274334</output>
<gadget id="calculator">(9*pi) * 13</gadget>
<output>117*pi = around 367.56634</output>
<result>A</result> | A | 367 | The slant height of a cone is 13 cm and radius of the base is 9 cm, find the curved surface of the cone? | {
"A": "367",
"B": "378",
"C": "365",
"D": "26",
"E": "28"
} | multiply(multiply(const_pi, 9), 13) | multiply(n1,const_pi)|multiply(n0,#0)| | "π * 13 * 9 = 367 answer : a" | geometry |
math_qa__i0U9jydTxCtHOH0i | A number increased by 20% gives 480. The number is Select: A) 200 B) 400 C) 300 D) 450 E) 500 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">480 / (6/5)</gadget>
<output>400</output>
<result>B</result> | B | 400 | A number increased by 20% gives 480. The number is | {
"A": "200",
"B": "400",
"C": "300",
"D": "450",
"E": "500"
} | divide(480, add(const_1, divide(20, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "formula = total = 100 % , increse = ` ` + ' ' decrease = ` ` - ' ' a number means = 100 % that same number increased by 20 % = 120 % 120 % - - - - - - - > 480 ( 120 × 4 = 480 ) 100 % - - - - - - - > 400 ( 100 × 4 = 400 ) b )" | gain |
math_qa__pd4uqsXMXuE0yIjp | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 400. How much did he have with him in the beginning?
Choose one: A) s 200 B) s 1000 C) s 300 D) s 450 E) s 550 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 5</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/3) - (2/15)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">(8/15) / 4</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(8/15) - (2/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">400 / (2/5)</gadget>
<output>1_000</output>
<result>B</result> | B | 1,000 | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 400. How much did he have with him in the beginning? | {
"A": "s 200",
"B": "s 1000",
"C": "s 300",
"D": "s 450",
"E": "s 550"
} | divide(400, subtract(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), divide(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), 4))) | divide(n0,n1)|subtract(n0,#0)|divide(#1,n3)|subtract(#1,#2)|divide(#3,n5)|subtract(#3,#4)|divide(n6,#5)| | "suppose the amount in the beginning was rs ’ x ’ money spent on clothes = rs 1 x / 3 balance = rs 2 x / 3 money spent on food = 1 / 5 of 2 x / 3 = rs 2 x / 15 balance = 2 x / 3 - 2 x / 15 = rs 8 x / 15 money spent on travel = 1 / 4 of 8 x / 15 = rs 2 x / 15 = 8 x / 15 - 2 x / 15 = 6 x / 15 = rs 2 x / 5 therefore 2 x / 5 = 400 = 1000 answer : b" | general |
math_qa__Iux1QKrxC1XahDn9 | In what time will a train 200 metres long cross an electric pole, if its speed be 124 km/hr? Options.
A) 4.8 sec B) 5.9 sec C) 5.0 sec D) 5.4 sec E) 5.8 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">124 * (5/18)</gadget>
<output>310/9 = around 34.444444</output>
<gadget id="calculator">200 / (310/9)</gadget>
<output>180/31 = around 5.806452</output>
<result>E</result> | E | 5.8 | In what time will a train 200 metres long cross an electric pole, if its speed be 124 km/hr? | {
"A": "4.8 sec",
"B": "5.9 sec",
"C": "5.0 sec",
"D": "5.4 sec",
"E": "5.8 sec"
} | divide(200, multiply(124, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "solution speed = ( 124 x 5 / 18 ) m / sec = 34.44 m / sec time taken = ( 200 / 34.44 ) sec = 5.8 sec . answer e" | physics |
math_qa__XcXun6seujdGpkQX | The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 15 and 16. The larger of the two numbers is: Choose the correct option.
A) 338 B) 278 C) 322 D) 368 E) 121 | <gadget id="calculator">23 * 16</gadget>
<output>368</output>
<result>D</result> | D | 368 | The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 15 and 16. The larger of the two numbers is: | {
"A": "338",
"B": "278",
"C": "322",
"D": "368",
"E": "121"
} | multiply(23, 16) | multiply(n0,n2) | clearly , the numbers are ( 23 * 15 ) and ( 23 * 16 ) . larger number = ( 23 * 16 ) = 368 . answer : d | other |
math_qa__FLqtPX4DPSXNnJLE | A train of 45 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long? Choose the correct option:
A) 6 B) 3 C) 4.2 D) 9 E) 4 | <gadget id="calculator">45 + 1</gadget>
<output>46</output>
<gadget id="calculator">46 * 60</gadget>
<output>2_760</output>
<gadget id="calculator">2_760 / 1_000</gadget>
<output>69/25 = around 2.76</output>
<gadget id="calculator">(69/25) + 1.5</gadget>
<output>4.26</output>
<result>C</result> | C | 4.2 | A train of 45 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long? | {
"A": "6",
"B": "3",
"C": "4.2",
"D": "9",
"E": "4"
} | add(divide(multiply(add(45, const_1), 60), const_1000), 1.5) | add(n0,const_1)|multiply(n1,#0)|divide(#1,const_1000)|add(n4,#2)| | "d = 45 * 60 + 1500 = 4200 m t = 4200 / 60 * 18 / 5 = 252 sec = 4.2 mins answer : c" | physics |
math_qa__a0dzKuAK2ZXQslCy | Mike needs 30% to pass. If he scored 212 marks and falls short by 13 marks, what was the maximum marks he could have got? Answers.
A) 343 B) 377 C) 750 D) 367 E) 232 | <gadget id="calculator">212 + 13</gadget>
<output>225</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">225 / (3/10)</gadget>
<output>750</output>
<result>C</result> | C | 750 | Mike needs 30% to pass. If he scored 212 marks and falls short by 13 marks, what was the maximum marks he could have got? | {
"A": "343",
"B": "377",
"C": "750",
"D": "367",
"E": "232"
} | divide(add(212, 13), divide(30, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "if mike had scored 13 marks more , he could have scored 30 % therefore , mike required 212 + 13 = 225 marks let the maximum marks be m . then 30 % of m = 225 ( 30 / 100 ) × m = 225 m = ( 225 × 100 ) / 30 m = 22500 / 30 m = 750 answer : c" | gain |
math_qa__oPWH3dd6QQyU4R6q | When 100 is divided by positive integer x, the remainder is 4. What is the remainder when 196 is divided by x? Choose the correct answer: A) 2 B) 3 C) 4 D) 6 E) 8 | <gadget id="calculator">196 - 100</gadget>
<output>96</output>
<gadget id="calculator">100 - 96</gadget>
<output>4</output>
<result>C</result> | C | 4 | When 100 is divided by positive integer x, the remainder is 4. What is the remainder when 196 is divided by x? | {
"A": "2",
"B": "3",
"C": "4",
"D": "6",
"E": "8"
} | subtract(100, subtract(196, 100)) | subtract(n2,n0)|subtract(n0,#0)| | "f 100 / x leaves a reminder 4 then ( 100 - 4 ) i . e . 96 is divisible by x so ( 100 + 96 ) / x leaves a reminder rem ( 100 / x ) + rem ( 96 / x ) = > 4 + 0 = 4 answer : c" | general |
math_qa__l6RVNbBIFPoSpxz6 | A fair price shopkeeper takes 10% profit on his goods. He lost 50% goods during theft. His loss percent is: Pick.
A) 72 % B) 45 % C) 32 % D) 12 % E) 22 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 * 50</gadget>
<output>5_500</output>
<gadget id="calculator">5_500 / 100</gadget>
<output>55</output>
<gadget id="calculator">110 - 55</gadget>
<output>55</output>
<gadget id="calculator">100 - 55</gadget>
<output>45</output>
<result>B</result> | B | 45 | A fair price shopkeeper takes 10% profit on his goods. He lost 50% goods during theft. His loss percent is: | {
"A": "72 %",
"B": "45 %",
"C": "32 %",
"D": "12 %",
"E": "22 %"
} | subtract(const_100, subtract(add(const_100, 10), divide(multiply(add(const_100, 10), 50), const_100))) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(const_100,#3)| | "explanation : suppose he has 100 items . let c . p . of each item be re . 1 . total cost = rs . 100 . number of items left after theft = 50 . s . p . of each item = rs . 1.10 total sale = 1.10 * 50 = rs . 55 hence , loss % = 45 / 100 * 100 = 45 % answer : b" | gain |
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