id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__kW8fFaWKZ2eJ9akN | A man buys a cycle for Rs.1200 and sells it at a loss of 15%. What is the selling price of the cycle? Choose the correct choice from the following answers.
A) s . 1020
B) s . 1160
C) s . 1190
D) s . 1202
E) s . 1256 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 * 1_200</gadget>
<output>102_000</output>
<gadget id="calculator">102_000 / 100</gadget>
<output>1_020</output>
<result>A</result> | A | 1,020 | A man buys a cycle for Rs.1200 and sells it at a loss of 15%. What is the selling price of the cycle? | {
"A": "s . 1020",
"B": "s . 1160",
"C": "s . 1190",
"D": "s . 1202",
"E": "s . 1256"
} | divide(multiply(subtract(const_100, 15), 1200), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "s . p . = 85 % of rs . 1200 = rs . 85 / 100 x 1200 = rs . 1020 answer : a" | gain |
math_qa__YcClIU5krBvpHezx | A wheel rotates 20 times every minute and moves 35 cm during each rotation. How many metres does the wheel move in one hour?
Pick
A) 6 metre B) 120 metre C) 220 metre D) 1200 metre E) 420 metre | <gadget id="calculator">20 * 60</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 * 35</gadget>
<output>42_000</output>
<gadget id="calculator">42_000 / 100</gadget>
<output>420</output>
<result>E</result> | E | 420 | A wheel rotates 20 times every minute and moves 35 cm during each rotation. How many metres does the wheel move in one hour? | {
"A": "6 metre",
"B": "120 metre",
"C": "220 metre",
"D": "1200 metre",
"E": "420 metre"
} | divide(multiply(multiply(20, const_60), 35), const_100) | multiply(n0,const_60)|multiply(n1,#0)|divide(#1,const_100) | number of times wheel moves in 1 hour = 20 * 60 = 1200 : . distance moves = ( 1200 * 35 ) cms = 42000 cms in metres = 420 metre answer : e | physics |
math_qa__6OEq4n2YcrDHqh4X | A certain roller coaster has 2 cars, and a passenger is equally likely to ride in any 1 of the 2 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 2 times, what is the probability that the passenger will ride in each of the 2 cars? Options:
A) 0 B) 1 / 2 C) 2 / 9 D) 1 / 3 E) 1 | <gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">2 * (1/4)</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | A certain roller coaster has 2 cars, and a passenger is equally likely to ride in any 1 of the 2 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 2 times, what is the probability that the passenger will ride in each of the 2 cars? | {
"A": "0",
"B": "1 / 2",
"C": "2 / 9",
"D": "1 / 3",
"E": "1"
} | multiply(factorial(2), power(divide(1, 2), 2)) | divide(n1,n0)|factorial(n0)|power(#0,n0)|multiply(#1,#2)| | "if he is to ride 2 times and since he can choose any of the 2 cars each time , total number of ways is = 2 * 2 = 4 now the number of ways if he is to choose a different car each time is = 2 * 1 = 2 so the probability is = 2 / 4 = 1 / 2 answer : b" | general |
math_qa__qwhIl32cjrKlyxqd | A man invested Rs. 4455 in Rs. 10 shares quoted at Rs. 8.25. If the rate of dividend be 12%, his annual income is: Choose one.
A) rs . 207.40 B) rs . 534.60 C) rs . 648 D) rs . 655.60 E) rs . 685.60 | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">4_455 / 8.25</gadget>
<output>540</output>
<gadget id="calculator">540 * 10</gadget>
<output>5_400</output>
<gadget id="calculator">(3/25) * 5_400</gadget>
<output>648</output>
<result>C</result> | C | 648 | A man invested Rs. 4455 in Rs. 10 shares quoted at Rs. 8.25. If the rate of dividend be 12%, his annual income is: | {
"A": "rs . 207.40",
"B": "rs . 534.60",
"C": "rs . 648",
"D": "rs . 655.60",
"E": "rs . 685.60"
} | multiply(divide(12, const_100), multiply(divide(4455, 8.25), 10)) | divide(n3,const_100)|divide(n0,n2)|multiply(n1,#1)|multiply(#0,#2) | solution numbers of shares = ( 4455 / 825 ) = 540 face value = rs . ( 540 x 10 ) = rs . 5400 annual income = rs . ( 12 / 10 x 5400 ) = rs . 648 . answer c | gain |
math_qa__c3TXYMfDQCDhVKqB | Mike drives his new Corvette from San Francisco to Las Vegas, a journey of 640 miles. He drives the first half of the trip at an average rate of 80 miles per hour, but has to slow down for the second half of his journey. If the second half of the trip takes him 200 percent longer than the first half, what is his average rate W in miles per hour for the entire trip? Options:
A) w = 26.7
B) w = 30.0
C) w = 40.0
D) w = 53.3
E) 60.0 | <gadget id="calculator">640 / 2</gadget>
<output>320</output>
<gadget id="calculator">320 / 80</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">640 / 16</gadget>
<output>40</output>
<result>C</result> | C | 40 | Mike drives his new Corvette from San Francisco to Las Vegas, a journey of 640 miles. He drives the first half of the trip at an average rate of 80 miles per hour, but has to slow down for the second half of his journey. If the second half of the trip takes him 200 percent longer than the first half, what is his average rate W in miles per hour for the entire trip? | {
"A": "w = 26.7",
"B": "w = 30.0",
"C": "w = 40.0",
"D": "w = 53.3",
"E": "60.0"
} | divide(640, add(add(multiply(divide(divide(640, const_2), 80), const_2), divide(divide(640, const_2), 80)), divide(divide(640, const_2), 80))) | divide(n0,const_2)|divide(#0,n1)|multiply(#1,const_2)|add(#1,#2)|add(#3,#1)|divide(n0,#4)| | "veritas prepofficial solution correct answer : c using the formula : time = distance / rate , we find that mike takes 4 hours to cover the first 320 miles of his trip . since the 2 nd 320 miles take 200 % longer than the first , it takes mike 8 hours longer , or 12 hours . ( note : 200 % longer than the first half is not 200 % of the first half . ) the overall time is 4 hours + 12 hours or 16 hours . since the definition of average rate = total distance traveled / total time of travel , mike ' s average rate = 640 / 16 or 40 miles per hour . answer choice c is correct ." | physics |
math_qa__ldp0SR7zwBPGwq8Z | The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 10%. if in july , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ? Choose the correct choice.
A) 45 B) 40 C) 35 D) 47.61 E) 30 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(9/10) * (6/5)</gadget>
<output>27/25 = around 1.08</output>
<gadget id="calculator">50 / (27/25)</gadget>
<output>1_250/27 = around 46.296296</output>
<result>D</result> | D | 47.61 | The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 10%. if in july , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ? | {
"A": "45",
"B": "40",
"C": "35",
"D": "47.61",
"E": "30"
} | divide(50, multiply(subtract(const_1, divide(10, const_100)), add(divide(20, const_100), const_1))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|divide(n2,#4) | let the price of tea and coffee be x per kg in june . price of tea in july = 1.2 x price of coffee in july = 0.9 x . in july the price of 1 / 2 kg ( 500 gm ) of tea and 1 / 2 kg ( 500 gm ) of coffee ( equal quantities ) = 50 1.2 x ( 1 / 2 ) + 0.9 x ( 1 / 2 ) = 50 = > x = 47.61 d | general |
math_qa__H1WeaLYulE9PgFbg | A man can swim in still water at 7.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is? Choose the correct choice from the following choices.
A) 3
B) 2.5
C) 2.25
D) 1.5
E) 4 | <gadget id="calculator">7.5 / 3</gadget>
<output>2.5</output>
<result>B</result> | B | 2.5 | A man can swim in still water at 7.5 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is? | {
"A": "3",
"B": "2.5",
"C": "2.25",
"D": "1.5",
"E": "4"
} | divide(7.5, const_3) | divide(n0,const_3)| | "m = 7.5 s = x ds = 7.5 + x us = 7.5 - x 7.5 + x = ( 7.5 - x ) 2 7.5 + x = 15 - 2 x 3 x = 7.5 x = 2.5 answer : b" | general |
math_qa__H2u8KAEJvX2pj4c2 | In a Express Train passengers traveling in A.C. Sleeper Class, First Class and Sleeper Class are in the ratio 1:2:3, and fare to each class in the ratio 5:4:2. If the income from this train is Rs. 57000, the income of A.C. Sleeper Class is
Select: A) rs . 8000 B) rs . 12000 C) rs . 15000 D) rs . 6000 E) none | <gadget id="calculator">57_000 / 4</gadget>
<output>14_250</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 10</gadget>
<output>150</output>
<gadget id="calculator">14_250 + 150</gadget>
<output>14_400</output>
<result>C</result> | C | 15,000 | In a Express Train passengers traveling in A.C. Sleeper Class, First Class and Sleeper Class are in the ratio 1:2:3, and fare to each class in the ratio 5:4:2. If the income from this train is Rs. 57000, the income of A.C. Sleeper Class is | {
"A": "rs . 8000",
"B": "rs . 12000",
"C": "rs . 15000",
"D": "rs . 6000",
"E": "none"
} | add(divide(57000, 4), multiply(multiply(3, 5), const_10)) | divide(n6,n4)|multiply(n2,n3)|multiply(#1,const_10)|add(#0,#2) | income is divided in the ratio 1 × 5 : 2 × 4 : 3 × 2 = 5 : 8 : 6 . now 5 x + 8 x + 6 x = 19 x = 57000 . ∴ x = 3000 . therefore income from a . c . sleeper class = 30005 = 15000 . answer : c . | other |
math_qa__clYUQfvQvZPao5U0 | How many positive factors do 150 and 90 have in common?
Select the correct option:
A) 8
B) 12
C) 16
D) 18
E) 24 | <gadget id="calculator">90 - 10</gadget>
<output>80</output>
<gadget id="calculator">80 / 10</gadget>
<output>8</output>
<result>A</result> | A | 8 | How many positive factors do 150 and 90 have in common? | {
"A": "8",
"B": "12",
"C": "16",
"D": "18",
"E": "24"
} | divide(subtract(90, const_10), const_10) | subtract(n1,const_10)|divide(#0,const_10) | the number of common factors will be same as number of factors of the highest common factor ( hcf ) hcf of 150 and 90 is 30 number of factors of 30 = 8 answer : a | other |
math_qa__mV9azmciTSBsxXxI | Mona and Sona go around a circular track of length 400 m on a bike at speeds of 18 kmph and 36 kmph. After how much time will they meet for the first time at the starting point? Pick:
A) 120 B) 80 C) 60 D) 136 E) 150 | <gadget id="calculator">36 - 18</gadget>
<output>18</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">400 / 5</gadget>
<output>80</output>
<result>B</result> | B | 80 | Mona and Sona go around a circular track of length 400 m on a bike at speeds of 18 kmph and 36 kmph. After how much time will they meet for the first time at the starting point? | {
"A": "120",
"B": "80",
"C": "60",
"D": "136",
"E": "150"
} | divide(400, multiply(subtract(36, 18), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1) | time taken to meet for the first time at the starting point = lcm { length of the track / speed of mona , length of the track / speed of sona } = lcm { 400 / ( 18 * 5 / 18 ) , 400 / ( 36 * 5 / 18 ) } = lcm ( 80 , 40 ) = 80 sec . answer : b | physics |
math_qa__4ES9ZvhKHZXncphQ | A cube of edge 10cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 20cm * 15cm , find the rise in water level? Pick.
A) 6 cm B) 8.25 cm C) 11.25 cm D) 15.12 cm E) 3.33 cm | <gadget id="calculator">10 ** 3</gadget>
<output>1_000</output>
<gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">1_000 / 300</gadget>
<output>10/3 = around 3.333333</output>
<result>E</result> | E | 3.33 | A cube of edge 10cm is immersed completely in a rectangular vessel containing water. If the dimensions of the base of vessel are 20cm * 15cm , find the rise in water level? | {
"A": "6 cm",
"B": "8.25 cm",
"C": "11.25 cm",
"D": "15.12 cm",
"E": "3.33 cm"
} | divide(volume_cube(10), multiply(20, 15)) | multiply(n1,n2)|volume_cube(n0)|divide(#1,#0) | increase in volume = volume of the cube = 10 * 10 * 10 cm ^ 3 rise in water level = volume / area = 10 * 10 * 10 / 20 * 15 = 3.33 cm answer is e | geometry |
math_qa__XqBZ7P0Trqb1R0Ff | A bag marked at $200 is sold for $120. The rate of discount is? Choose the correct option.
A) 10 % B) 25 % C) 20 % D) 50 % E) 40 % | <gadget id="calculator">200 - 120</gadget>
<output>80</output>
<gadget id="calculator">80 / 200</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>E</result> | E | 40 | A bag marked at $200 is sold for $120. The rate of discount is? | {
"A": "10 %",
"B": "25 %",
"C": "20 %",
"D": "50 %",
"E": "40 %"
} | multiply(divide(subtract(200, 120), 200), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "rate of discount = 80 / 200 * 100 = 40 % answer is e" | gain |
math_qa__senMfs5Q4ZSP1AZi | The sale price of a trolley bag including the sale tax is Rs. 1120. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is: Choose the correct answer: A) rs 1000 B) rs 1515 C) rs 800 D) rs 900 E) none of these | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1_120 * (3/25)</gadget>
<output>672/5 = around 134.4</output>
<gadget id="calculator">1_120 - (672/5)</gadget>
<output>4_928/5 = around 985.6</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(4_928/5) / (5/4)</gadget>
<output>19_712/25 = around 788.48</output>
<result>C</result> | C | 800 | The sale price of a trolley bag including the sale tax is Rs. 1120. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is: | {
"A": "rs 1000",
"B": "rs 1515",
"C": "rs 800",
"D": "rs 900",
"E": "none of these"
} | divide(subtract(1120, multiply(1120, divide(12, const_100))), add(divide(25, const_100), const_1)) | divide(n1,const_100)|divide(n2,const_100)|add(#1,const_1)|multiply(n0,#0)|subtract(n0,#3)|divide(#4,#2)| | "explanation : 112 % of s . p . = 1120 s . p . = rs . ( 1120 x 100 / 112 ) = rs . 1000 . c . p . = rs ( 100 / 125 x 1000 ) = rs 800 . answer : c" | gain |
math_qa__RFgyYrB4NYcWsb0L | Little John had $10.10. He spent $3.25 on sweets and gave to his two friends $2.20 each. How much money was left? Pick.
A) $ 2.45 B) $ 2.54 C) $ 2.35 D) $ 2.48 E) $ 2.49 | <gadget id="calculator">2.2 + 2.2</gadget>
<output>4.4</output>
<gadget id="calculator">3.25 + 4.4</gadget>
<output>7.65</output>
<gadget id="calculator">10.1 - 7.65</gadget>
<output>2.45</output>
<result>A</result> | A | 2.45 | Little John had $10.10. He spent $3.25 on sweets and gave to his two friends $2.20 each. How much money was left? | {
"A": "$ 2.45",
"B": "$ 2.54",
"C": "$ 2.35",
"D": "$ 2.48",
"E": "$ 2.49"
} | subtract(10.10, add(3.25, add(2.20, 2.20))) | add(n2,n2)|add(n1,#0)|subtract(n0,#1)| | "john spent and gave to his two friends a total of 3.25 + 2.20 + 2.20 = $ 7.65 money left 10.10 - 7.65 = $ 2.45 answer : a" | general |
math_qa__YKS5Dudv033vTXHn | The size of a television screen is given as the length of the screen's diagonal. If the screens were flat, then the area of a square 22-inch screen would be how many square inches greater than the area of a square 20-inch screen? Select the correct option
A) 2 B) 4 C) 16 D) 42 E) 40 | <gadget id="calculator">22 ** 2</gadget>
<output>484</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">484 - 400</gadget>
<output>84</output>
<gadget id="calculator">84 / 2</gadget>
<output>42</output>
<result>D</result> | D | 42 | The size of a television screen is given as the length of the screen's diagonal. If the screens were flat, then the area of a square 22-inch screen would be how many square inches greater than the area of a square 20-inch screen? | {
"A": "2",
"B": "4",
"C": "16",
"D": "42",
"E": "40"
} | divide(subtract(power(22, const_2), power(20, const_2)), const_2) | power(n0,const_2)|power(n1,const_2)|subtract(#0,#1)|divide(#2,const_2)| | "pythogoras will help here ! let the sides be x and diagonal be d then d ^ 2 = 2 x ^ 2 and area = x ^ 2 now plug in the given diagonal values to find x values and then subtract the areas ans will be 22 ^ 2 / 2 - 20 ^ 2 / 2 = 84 / 2 = 42 ans d ." | geometry |
math_qa__5K3mb7bchu6FOUNX | If a and b are the roots of the equation x2 - 5x + 5 = 0, then the value of a2 + b2 is:
Options
A) 36
B) 24
C) 15
D) 6
E) 5 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">5 ** (1/2)</gadget>
<output>sqrt(5) = around 2.236068</output>
<gadget id="calculator">5 - (sqrt(5))</gadget>
<output>5 - sqrt(5) = around 2.763932</output>
<gadget id="calculator">(5 - sqrt(5)) / 2</gadget>
<output>5/2 - sqrt(5)/2 = around 1.381966</output>
<gadget id="calculator">(5/2 - sqrt(5)/2) ** 2</gadget>
<output>(5/2 - sqrt(5)/2)**2 = around 1.90983</output>
<gadget id="calculator">5 + (sqrt(5))</gadget>
<output>sqrt(5) + 5 = around 7.236068</output>
<gadget id="calculator">(sqrt(5) + 5) / 2</gadget>
<output>sqrt(5)/2 + 5/2 = around 3.618034</output>
<gadget id="calculator">(sqrt(5)/2 + 5/2) ** 2</gadget>
<output>(sqrt(5)/2 + 5/2)**2 = around 13.09017</output>
<gadget id="calculator">((5/2 - sqrt(5)/2)**2) + ((sqrt(5)/2 + 5/2)**2)</gadget>
<output>(5/2 - sqrt(5)/2)**2 + (sqrt(5)/2 + 5/2)**2 = around 15</output>
<result>C</result> | C | 15 | If a and b are the roots of the equation x2 - 5x + 5 = 0, then the value of a2 + b2 is: | {
"A": "36",
"B": "24",
"C": "15",
"D": "6",
"E": "5"
} | add(power(divide(subtract(5, sqrt(subtract(power(5, 2), multiply(const_4, 5)))), 2), 2), power(divide(add(5, sqrt(subtract(power(5, 2), multiply(const_4, 5)))), 2), 2)) | multiply(n1,const_4)|power(n1,n0)|subtract(#1,#0)|sqrt(#2)|add(n1,#3)|subtract(n1,#3)|divide(#5,n0)|divide(#4,n0)|power(#6,n0)|power(#7,n0)|add(#8,#9)| | "sol . ( b ) the sum of roots = a + b = 5 product of roots = ab = 5 now , a 2 + b 2 = ( a + b ) 2 - 2 ab = 25 - 10 = 15 answer c" | general |
math_qa__4vCqeKahMZ95M5zK | Two cars A and B are running towards each other from different places 88 km apart. If the ratio of the speeds of the cars A and B is 5 : 6 and the speed of the car B is 90 km per hour then after how long will the two meet each other? Choose the correct option: A) 2263 minutes B) 24 minutes C) 32 minutes D) 36 minutes E) none of these | <gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">90 * (5/6)</gadget>
<output>75</output>
<gadget id="calculator">75 + 90</gadget>
<output>165</output>
<gadget id="calculator">88 / 165</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">(8/15) * 60</gadget>
<output>32</output>
<result>C</result> | C | 32 | Two cars A and B are running towards each other from different places 88 km apart. If the ratio of the speeds of the cars A and B is 5 : 6 and the speed of the car B is 90 km per hour then after how long will the two meet each other? | {
"A": "2263 minutes",
"B": "24 minutes",
"C": "32 minutes",
"D": "36 minutes",
"E": "none of these"
} | multiply(divide(88, add(multiply(90, divide(5, 6)), 90)), const_60) | divide(n1,n2)|multiply(n3,#0)|add(n3,#1)|divide(n0,#2)|multiply(#3,const_60) | speed of the car a = 5 ⁄ 6 × 90 = 75 km / hr \ reqd time = 88 / 90 + 75 × 60 = 32 minutes answer c | physics |
math_qa__AUfFXcT94Wk4aeP3 | Find the angle between the hour hand and the minute hand of a clock when
3.25. Choose the correct choice from the following choices.
A) 47.5 B) 46.5 C) 45.5 D) 48.5 E) 44.5 | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">3.25 - 3</gadget>
<output>0.25</output>
<gadget id="calculator">0.25 * 100</gadget>
<output>25</output>
<gadget id="calculator">30 * 25</gadget>
<output>750</output>
<gadget id="calculator">750 / 60</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">60 - (25/2)</gadget>
<output>95/2 = around 47.5</output>
<result>A</result> | A | 47.5 | Find the angle between the hour hand and the minute hand of a clock when
3.25. | {
"A": "47.5",
"B": "46.5",
"C": "45.5",
"D": "48.5",
"E": "44.5"
} | subtract(const_60, divide(multiply(divide(const_60, const_2), multiply(subtract(3.25, const_3), const_100)), const_60)) | divide(const_60,const_2)|subtract(n0,const_3)|multiply(#1,const_100)|multiply(#0,#2)|divide(#3,const_60)|subtract(const_60,#4) | angle = 30 ( hours ) - ( 11 / 2 ) ( minutes ) = 30 * 3 - ( 5.5 * 25 ) ( hour = 3 and minutes = 25 ) = 90 - 137.5 = 47.5 answer : a | physics |
math_qa__lMTpVeAEvPmiJ87i | a chocolate manufacturer produces 400 units of a certain model each month at a cost to the manufacturer of £ 40 per unit and all of the produced units are sold each month . what is the minimum selling price per unit that will ensure that the monthly profit ( revenue from sales minus production costs ) on the sales of these units will be at least £ 40000 ? Choose the correct choice from the following answers
A) 123 B) 213 C) 440 D) 550 E) 540 | <gadget id="calculator">400 + 40</gadget>
<output>440</output>
<result>C</result> | C | 440 | a chocolate manufacturer produces 400 units of a certain model each month at a cost to the manufacturer of £ 40 per unit and all of the produced units are sold each month . what is the minimum selling price per unit that will ensure that the monthly profit ( revenue from sales minus production costs ) on the sales of these units will be at least £ 40000 ? | {
"A": "123",
"B": "213",
"C": "440",
"D": "550",
"E": "540"
} | add(400, 40) | add(n0,n1) | 400 ( x - 40 ) ≥ 40000 x - 40 ≥ 400 x ≥ 440 answer : option c | general |
math_qa__rDmhrVTc6dwZYlio | 1,000^2 + 1,001^2 +1,002^2 + 1,003^2 + 1,004^2 + 1,005^2+ 1,006^2 = Choose the correct choice from the following:
A) 6 , 030,053
B) 6 , 030,054
C) 6 , 030,055
D) 6 , 042,091
E) 6 , 030,057 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<result>D</result> | D | 6 | 1,000^2 + 1,001^2 +1,002^2 + 1,003^2 + 1,004^2 + 1,005^2+ 1,006^2 = | {
"A": "6 , 030,053",
"B": "6 , 030,054",
"C": "6 , 030,055",
"D": "6 , 042,091",
"E": "6 , 030,057"
} | multiply(2, const_3) | multiply(n1,const_3)| | "interesting problem . i think key is to notice that all the given answer choices differs in last two digits . therefore , our entire focus should be to figure out how the given terms contribute to last two digits of total . 1000 ^ 2 - > 00 1001 ^ 1 - > 01 . . . 1006 ^ 2 - > 36 total - > * 91 answer d ." | general |
math_qa__AIX77XGuaIx3Hzaz | (112 x 54) = ? Pick:
A) 67000 B) 70000 C) 76500 D) 77200 E) 85200 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 ** 4</gadget>
<output>625</output>
<gadget id="calculator">112 * 625</gadget>
<output>70_000</output>
<result>B</result> | B | 70,000 | (112 x 54) = ? | {
"A": "67000",
"B": "70000",
"C": "76500",
"D": "77200",
"E": "85200"
} | multiply(112, power(add(const_4, const_1), const_4)) | add(const_1,const_4)|power(#0,const_4)|multiply(n0,#1) | explanation : ( 112 x 54 ) = 112 x ( 10 / 2 ) 4 = 112 x 10 4 / 2 4 = 1120000 / 16 = 70000 answer is b | general |
math_qa__7gzWZhHBpIpO8oPq | The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles.
Answers
A) 3312
B) 2888
C) 4312
D) 2881
E) 1221 | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">352 / (2*pi)</gadget>
<output>176/pi = around 56.02254</output>
<gadget id="calculator">pi * ((176/pi) ** 2)</gadget>
<output>30976/pi = around 9_859.967034</output>
<gadget id="calculator">264 / (2*pi)</gadget>
<output>132/pi = around 42.016905</output>
<gadget id="calculator">pi * ((132/pi) ** 2)</gadget>
<output>17424/pi = around 5_546.231457</output>
<gadget id="calculator">(30976/pi) - (17424/pi)</gadget>
<output>13552/pi = around 4_313.735578</output>
<result>C</result> | C | 4,312 | The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles. | {
"A": "3312",
"B": "2888",
"C": "4312",
"D": "2881",
"E": "1221"
} | subtract(circle_area(divide(352, multiply(const_2, const_pi))), circle_area(divide(264, multiply(const_2, const_pi)))) | multiply(const_2,const_pi)|divide(n1,#0)|divide(n0,#0)|circle_area(#1)|circle_area(#2)|subtract(#3,#4)| | "let the radii of the smaller and the larger circles be s m and l m respectively . 2 ∏ s = 264 and 2 ∏ l = 352 s = 264 / 2 ∏ and l = 352 / 2 ∏ difference between the areas = ∏ l 2 - ∏ s 2 = ∏ { 1762 / ∏ 2 - 1322 / ∏ 2 } = 1762 / ∏ - 1322 / ∏ = ( 176 - 132 ) ( 176 + 132 ) / ∏ = ( 44 ) ( 308 ) / ( 22 / 7 ) = ( 2 ) ( 308 ) ( 7 ) = 4312 sq m answer : c" | geometry |
math_qa__hUgW8mxMDx7NDEU2 | Find avrg speed if a man travels at speed of 15km/hr up and 28km/hr dawn at an altitude of 230m. Answers.
A) 25.8 B) 19.5 C) 18.0 D) 12.2 E) 29.8 | <gadget id="calculator">2 * 15</gadget>
<output>30</output>
<gadget id="calculator">30 * 28</gadget>
<output>840</output>
<gadget id="calculator">15 + 28</gadget>
<output>43</output>
<gadget id="calculator">840 / 43</gadget>
<output>840/43 = around 19.534884</output>
<result>B</result> | B | 19.5 | Find avrg speed if a man travels at speed of 15km/hr up and 28km/hr dawn at an altitude of 230m. | {
"A": "25.8",
"B": "19.5",
"C": "18.0",
"D": "12.2",
"E": "29.8"
} | divide(multiply(multiply(const_2, 15), 28), add(15, 28)) | add(n0,n1)|multiply(n0,const_2)|multiply(n1,#1)|divide(#2,#0)| | "avg speed = 2 * x * y / ( x + y ) = 2 * 15 * 28 / ( 15 + 28 ) = 19.5 answer : b" | physics |
math_qa__Va289eNnoHUKmJVQ | An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.21168/- in 3 years at the same rate of interest. Find the rate percentage? Choose one: A) 5 % B) 7 % C) 9 % D) 11 % E) 20 % | <gadget id="calculator">21_168 - 17_640</gadget>
<output>3_528</output>
<gadget id="calculator">3_528 / 17_640</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>E</result> | E | 20 | An amount at compound interest sums to Rs.17640/- in 2 years and to Rs.21168/- in 3 years at the same rate of interest. Find the rate percentage? | {
"A": "5 %",
"B": "7 %",
"C": "9 %",
"D": "11 %",
"E": "20 %"
} | multiply(divide(subtract(21168, 17640), 17640), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : the difference of two successive amounts must be the simple interest in 1 year on the lower amount of money . s . i = 21168 / - - 17640 / - = rs . 3528 / - rate of interest = ( 3528 / 17640 ) × ( 100 / 1 ) = > 20 % answer : option e" | general |
math_qa__Yuolb5yr1DKc6VRs | In the above number, A and B represent the tens and units digits, respectively. If the above number is divisible by 25, what is the greatest possible value of B x A? Choose the correct choice from the following: A) 0 B) 15 C) 20 D) 25 E) 35 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<result>E</result> | E | 35 | In the above number, A and B represent the tens and units digits, respectively. If the above number is divisible by 25, what is the greatest possible value of B x A? | {
"A": "0",
"B": "15",
"C": "20",
"D": "25",
"E": "35"
} | multiply(add(const_3, const_4), add(const_2, const_3)) | add(const_3,const_4)|add(const_2,const_3)|multiply(#0,#1) | i also was confused when i was looking forabove number : d as far as i understood , 25 is a factor of ab . in other words , the values of b ( units digits can be 5 or 0 . better to have option for 5 in this case to havebigger result ) . now let ' s try 25 x 1 ( a = 2 , b = 5 respectively we have = 10 ) . but we do n ' t have this number in answer choices , move on . ( avoid even multiples of 2,4 , 6,8 etc ( we will have 0 in units thus making our result 0 ) 25 x 3 = 75 ( a = 7 b = 5 respectively . hey ! that ' s 35 . this is the greatest possible value of b x a imo e . | general |
math_qa__ocqTMO0yd8KUGVic | A train 100 meters long completely crosses a 300 meters long bridge in 24 seconds. What is the speed of the train is? Pick:
A) 60 kmph B) 76 kmph C) 34 kmph D) 43 kmph E) 40 kmph | <gadget id="calculator">100 + 300</gadget>
<output>400</output>
<gadget id="calculator">400 / 1_000</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">24 / 3_600</gadget>
<output>1/150 = around 0.006667</output>
<gadget id="calculator">(2/5) / (1/150)</gadget>
<output>60</output>
<result>A</result> | A | 60 | A train 100 meters long completely crosses a 300 meters long bridge in 24 seconds. What is the speed of the train is? | {
"A": "60 kmph",
"B": "76 kmph",
"C": "34 kmph",
"D": "43 kmph",
"E": "40 kmph"
} | divide(divide(add(100, 300), const_1000), divide(24, const_3600)) | add(n0,n1)|divide(n2,const_3600)|divide(#0,const_1000)|divide(#2,#1)| | "s = ( 100 + 300 ) / 24 = 400 / 24 * 18 / 5 = 60 answer : a" | physics |
math_qa__F0Nfs0k1gsiZpgeG | (0.15)(power 3) - (0.06)(power 3)/ (0.15)(power 2) + 0.009 + (0.06)(power 2) is: Choose the correct choice from the following options:
A) 0.09 B) 0.08 C) 0.1 D) 0.07 E) none of them | <gadget id="calculator">0.15 ** 3</gadget>
<output>0.003375</output>
<gadget id="calculator">0.06 ** 3</gadget>
<output>0.000216</output>
<gadget id="calculator">0.003375 - 0.000216</gadget>
<output>0.003159</output>
<gadget id="calculator">0.15 ** 2</gadget>
<output>0.0225</output>
<gadget id="calculator">0.0225 + 0.009</gadget>
<output>0.0315</output>
<gadget id="calculator">0.06 ** 2</gadget>
<output>0.0036</output>
<gadget id="calculator">0.0315 + 0.0036</gadget>
<output>0.0351</output>
<gadget id="calculator">0.003159 / 0.0351</gadget>
<output>0.09</output>
<result>A</result> | A | 0.09 | (0.15)(power 3) - (0.06)(power 3)/ (0.15)(power 2) + 0.009 + (0.06)(power 2) is: | {
"A": "0.09",
"B": "0.08",
"C": "0.1",
"D": "0.07",
"E": "none of them"
} | divide(subtract(power(0.15, 3), power(0.06, 3)), add(add(power(0.15, 2), 0.009), power(0.06, 2))) | power(n0,n1)|power(n2,n1)|power(n0,n5)|power(n2,n5)|add(n6,#2)|subtract(#0,#1)|add(#4,#3)|divide(#5,#6)| | "given expression = ( 0.15 ) ( power 3 ) - ( 0.06 ) ( power 3 ) / ( 0.15 ) ( power 2 ) + ( 0.15 x 0.06 ) + ( 0.06 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 0.15 - 0.06 ) = 0.09 answer is a ." | general |
math_qa__wY8R6dwU9WFe9Usd | If the remainder is 8 when positive integer n is divided by 12, what is the remainder when n is divided by 6? Answers:
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">12 / 6</gadget>
<output>2</output>
<result>C</result> | C | 2 | If the remainder is 8 when positive integer n is divided by 12, what is the remainder when n is divided by 6? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | divide(12, 6) | divide(n1,n2)| | "assume x is quotient here , n = 12 x + 8 - - - - - - - - - - ( 1 ) and n = 6 x + ? we can also write equation ( 1 ) as : n = ( 12 x + 6 ) + 2 . ie 6 ( 2 x + 1 ) + 2 ie the first term is perfectly divisible by 6 . so , the remainder left is 2 . so , answer ( c ) is right choice ." | general |
math_qa__EI7As4b5DjhZJSl2 | If 9 men do a work in 80 days, in how many days will 20 men do it? Pick one: A) 18 days B) 36 days C) 42 days D) 48 days E) 44 days | <gadget id="calculator">9 * 80</gadget>
<output>720</output>
<gadget id="calculator">720 / 20</gadget>
<output>36</output>
<result>B</result> | B | 36 | If 9 men do a work in 80 days, in how many days will 20 men do it? | {
"A": "18 days",
"B": "36 days",
"C": "42 days",
"D": "48 days",
"E": "44 days"
} | divide(multiply(9, 80), 20) | multiply(n0,n1)|divide(#0,n2)| | "9 * 80 = 20 * x x = 36 days answer : b" | physics |
math_qa__vFAxTIT7LX2TY12K | What is the rate percent when the simple interest on Rs.2000 amount to Rs.500 in 2 Years?
Choose the correct option
A) 5 % B) 6 % C) 12.5 % D) 95 % E) 1 % | <gadget id="calculator">100 * 500</gadget>
<output>50_000</output>
<gadget id="calculator">2_000 * 2</gadget>
<output>4_000</output>
<gadget id="calculator">50_000 / 4_000</gadget>
<output>25/2 = around 12.5</output>
<result>C</result> | C | 12.5 | What is the rate percent when the simple interest on Rs.2000 amount to Rs.500 in 2 Years? | {
"A": "5 %",
"B": "6 %",
"C": "12.5 %",
"D": "95 %",
"E": "1 %"
} | divide(multiply(const_100, 500), multiply(2000, 2)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "interest for 2 yrs = 500 interest for 1 yr = 250 interest rate = 250 / 2000 x 100 = 12.5 % answer : c" | gain |
math_qa__3RBj7B8b8J36vNkl | x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to: Choose the correct choice from the following options:
A) 1 / 2 B) 1 / 3 C) 1 / 5 D) 1 / 9 E) 1 / 3 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">1 * 4</gadget>
<output>4</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">4 / 36</gadget>
<output>1/9 = around 0.111111</output>
<result>D</result> | D | 0.111111 | x varies inversely as square of y. Given that y = 2 for x = 1. The value of x for y = 6 will be equal to: | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 5",
"D": "1 / 9",
"E": "1 / 3"
} | divide(multiply(1, power(2, const_2)), power(6, const_2)) | power(n0,const_2)|power(n2,const_2)|multiply(n1,#0)|divide(#2,#1)| | "given x = k / y 2 , where k is a constant . now , y = 2 and x = 1 gives k = 4 . x = 4 / y 2 = > x = 4 / 62 , when y = 6 = > x = 4 / 36 = 1 / 9 . answer : d" | general |
math_qa__UqErXAT4Yjal77YT | In the first 10 overs of a cricket game, the run rate was only 4.6. What should be the run rate in the remaining 40 overs to reach the target of 282 runs? Options:
A) 4.25 B) 5.9 C) 6.25 D) 7 E) 7.5 | <gadget id="calculator">10 * 4.6</gadget>
<output>46</output>
<gadget id="calculator">282 - 46</gadget>
<output>236</output>
<gadget id="calculator">236 / 40</gadget>
<output>59/10 = around 5.9</output>
<result>B</result> | B | 5.9 | In the first 10 overs of a cricket game, the run rate was only 4.6. What should be the run rate in the remaining 40 overs to reach the target of 282 runs? | {
"A": "4.25",
"B": "5.9",
"C": "6.25",
"D": "7",
"E": "7.5"
} | divide(subtract(282, multiply(10, 4.6)), 40) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "required run rate = 282 - ( 4.6 x 10 ) = 236 236 / 40 = 5.9 b )" | gain |
math_qa__RoeVGmkhyPA9Ewld | Calculate the dividend from Moses's stock, if he invested Rs. 3000 at 72 to obtain an income of Rs. 210. Choose the correct choice from the following options: A) 3 B) 9 C) 3 D) 4 E) 5.04 | <gadget id="calculator">210 * 72</gadget>
<output>15_120</output>
<gadget id="calculator">15_120 / 3_000</gadget>
<output>126/25 = around 5.04</output>
<result>E</result> | E | 5.04 | Calculate the dividend from Moses's stock, if he invested Rs. 3000 at 72 to obtain an income of Rs. 210. | {
"A": "3",
"B": "9",
"C": "3",
"D": "4",
"E": "5.04"
} | divide(multiply(210, 72), 3000) | multiply(n1,n2)|divide(#0,n0) | by investing rs . 3000 , income = rs . 210 by investing rs . 72 , income = 210 ã — 72 / 3000 = 5.04 ie , dividend = 5.04 % answer is e . | gain |
math_qa__2ULmIuUjIyznQY9m | Perimeter of the back wheel = 9 feet, front wheel = 7 feet on a certain distance, the front wheel gets 10 revolutions more than the back wheel .What is the distance? Answers: A) 315 B) 325 C) 335 D) 345 E) 305 | <gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">9 - 7</gadget>
<output>2</output>
<gadget id="calculator">70 / 2</gadget>
<output>35</output>
<gadget id="calculator">9 * 35</gadget>
<output>315</output>
<result>A</result> | A | 315 | Perimeter of the back wheel = 9 feet, front wheel = 7 feet on a certain distance, the front wheel gets 10 revolutions more than the back wheel .What is the distance? | {
"A": "315",
"B": "325",
"C": "335",
"D": "345",
"E": "305"
} | multiply(9, divide(multiply(10, 7), subtract(9, 7))) | multiply(n1,n2)|subtract(n0,n1)|divide(#0,#1)|multiply(n0,#2) | for 1 revolution : front wheel goes 7 ft . and back wheel goes 9 feet . let distance is x feet . x / 7 = ( x / 9 ) + 10 or , 2 x / 63 = 10 or , x = ( 10 * 63 ) / 2 therefore , x = 315 answer : a | physics |
math_qa__CLINjoXrEFRdjy8I | How many positive integers less than 9,000 are there in which the sum of the digits equals 5? Select the correct option: A) 56 B) 57 C) 58 D) 59 E) 60 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<result>A</result> | A | 56 | How many positive integers less than 9,000 are there in which the sum of the digits equals 5? | {
"A": "56",
"B": "57",
"C": "58",
"D": "59",
"E": "60"
} | divide(factorial(subtract(add(const_4, 5), const_1)), multiply(factorial(5), factorial(subtract(const_4, const_1)))) | add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6)| | "basically , the question asks how many 4 digit numbers ( including those in the form 0 xxx , 00 xx , and 000 x ) have digits which add up to 5 . think about the question this way : we know that there is a total of 5 to be spread among the 4 digits , we just have to determine the number of ways it can be spread . let x represent a sum of 1 , and | represent a seperator between two digits . as a result , we will have 5 x ' s ( digits add up to the 5 ) , and 3 | ' s ( 3 digit seperators ) . so , for example : xx | x | x | x = 2111 | | xxx | xx = 0032 etc . there are 8 c 3 ways to determine where to place the separators . hence , the answer is 8 c 3 = 56 . a" | general |
math_qa__s8ZxzRSKCmL6HLT0 | A certain airline's fleet consisted of 110 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet? Options:
A) 15
B) 16
C) 17
D) 18
E) 19 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">110 / 7</gadget>
<output>110/7 = around 15.714286</output>
<result>B</result> | B | 16 | A certain airline's fleet consisted of 110 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet? | {
"A": "15",
"B": "16",
"C": "17",
"D": "18",
"E": "19"
} | divide(110, add(const_3, const_4)) | add(const_3,const_4)|divide(n0,#0) | let x be the number of years . 4 x > 110 - 3 x 7 x > 110 x > 15 + 5 / 7 the answer is b . | gain |
math_qa__ijxTZznejSfsb7tI | Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? Options
A) rs . 200
B) rs . 250
C) rs . 300
D) rs . 350
E) rs . 370 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">550 * 10</gadget>
<output>5_500</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">5_500 / 22</gadget>
<output>250</output>
<result>B</result> | B | 250 | Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "rs . 200",
"B": "rs . 250",
"C": "rs . 300",
"D": "rs . 350",
"E": "rs . 370"
} | divide(multiply(550, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 550 but x = 120 % of y = 120 y / 100 = 12 y / 10 ∴ 12 y / 10 + y = 550 ⇒ y [ 12 / 10 + 1 ] = 550 ⇒ 22 y / 10 = 550 ⇒ 22 y = 5500 ⇒ y = 5500 / 22 = 500 / 2 = rs . 250 b )" | general |
math_qa__RvSlFENJ0ddEcLp7 | Set A contains all the even numbers between 32 and 80 inclusive. Set B contains all the even numbers between 62 and 110 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? Choose one.
A) 450 B) 550 C) 650 D) 750 E) 850 | <gadget id="calculator">62 - 32</gadget>
<output>30</output>
<gadget id="calculator">80 - 32</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">30 * 25</gadget>
<output>750</output>
<result>D</result> | D | 750 | Set A contains all the even numbers between 32 and 80 inclusive. Set B contains all the even numbers between 62 and 110 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? | {
"A": "450",
"B": "550",
"C": "650",
"D": "750",
"E": "850"
} | multiply(subtract(62, 32), add(divide(subtract(80, 32), const_2), const_1)) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,const_2)|add(#2,const_1)|multiply(#3,#1)| | "each term in set b is 30 more than the corresponding term in set a . the difference of the sums = 25 * 30 = 750 . the answer is d ." | general |
math_qa__FR2sZvCL52aNPixb | P and Q invested in a business. The profit earned was divided in the ratio 3 : 5. If P invested Rs 12000, the amount invested by Q is
Answers.
A) 30000 B) 50000 C) 40000 D) 20000 E) 60000 | <gadget id="calculator">12_000 / 2</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 * 5</gadget>
<output>30_000</output>
<result>A</result> | A | 30,000 | P and Q invested in a business. The profit earned was divided in the ratio 3 : 5. If P invested Rs 12000, the amount invested by Q is | {
"A": "30000",
"B": "50000",
"C": "40000",
"D": "20000",
"E": "60000"
} | multiply(divide(12000, const_2.0), 5) | divide(n2,const_2.0)|multiply(n1,#0)| | "let the amount invested by q = q 12000 : q = 3 : 5 ⇒ 12000 × 5 = 3 q ⇒ q = ( 12000 × 5 ) / 3 = 30000 answer is a" | gain |
math_qa__s4gnMLRMTVn5sVEM | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 300 more than the correct answer. Find the number. Choose the correct choice
A) 125
B) 280
C) 384
D) 400
E) 576 | <gadget id="calculator">300 * 16</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 * 6</gadget>
<output>28_800</output>
<gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">80 - 30</gadget>
<output>50</output>
<gadget id="calculator">28_800 / 50</gadget>
<output>576</output>
<result>E</result> | E | 576 | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 300 more than the correct answer. Find the number. | {
"A": "125",
"B": "280",
"C": "384",
"D": "400",
"E": "576"
} | divide(multiply(multiply(300, 16), 6), subtract(multiply(5, 16), multiply(5, 6))) | multiply(n1,n4)|multiply(n0,n1)|multiply(n0,n3)|multiply(n3,#0)|subtract(#1,#2)|divide(#3,#4) | explanation : let the number be x . 5 * x / 6 = 5 * x / 16 + 300 25 * x / 48 = 300 x = 576 answer e | general |
math_qa__oUp4tH3BXKVSrnvA | Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?
Choose the correct choice from the following:
A) 10 % B) 33.33 % C) 40 % D) 50 % E) 66.66 % | <gadget id="calculator">30 - 25</gadget>
<output>5</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(2/5) - (1/4)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">5 / (3/20)</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 33.33 | Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ? | {
"A": "10 %",
"B": "33.33 %",
"C": "40 %",
"D": "50 %",
"E": "66.66 %"
} | divide(subtract(30, 25), subtract(divide(40, const_100), divide(25, const_100))) | divide(n0,const_100)|divide(n2,const_100)|subtract(n4,n2)|subtract(#0,#1)|divide(#2,#3)| | "qnty . ( cheaper ) / qty . ( dearer ) = ( dearer - mean ) / ( mean - cheaper ) thus qy / qx = ( 40 - 30 ) / ( 30 - 25 ) = 2 therefore qy = 2 qx and qy + qx = 100 % ( total ) . hence qx = 33.33 % answer : b" | gain |
math_qa__VgX97wg86QPkd79n | A computer factory produces 5376 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month? Choose the correct choice from the following answers: A) 2.25 . B) 3.125 . C) 4.5 . D) 4.00 . E) 6.25 . | <gadget id="calculator">5_376 / 28</gadget>
<output>192</output>
<gadget id="calculator">28 - 4</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">192 / 48</gadget>
<output>4</output>
<result>D</result> | D | 4 | A computer factory produces 5376 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month? | {
"A": "2.25 .",
"B": "3.125 .",
"C": "4.5 .",
"D": "4.00 .",
"E": "6.25 ."
} | divide(divide(5376, 28), multiply(subtract(28, const_4), const_2)) | divide(n0,n2)|subtract(n2,const_4)|multiply(#1,const_2)|divide(#0,#2)| | "number of hours in 28 days = 28 * 24 number of 30 mins in 28 days = 28 * 24 * 2 number of computers built every 30 mins = 5376 / ( 28 * 24 * 2 ) = 4.00 answer d" | physics |
math_qa__AIl4rQAX07niOv6Q | If a cost college Rs0.70 a companyto produce a program for yhe home coming football game.if Rs 15000 was received for addvertisement in the pgm ,how many copies rs 0.50 a copy must be sold to make a profit of Rs 8000 Answers:
A) 15000
B) 25000
C) 45000
D) 32000
E) 35000 | <gadget id="calculator">15_000 - 8_000</gadget>
<output>7_000</output>
<gadget id="calculator">0.7 - 0.5</gadget>
<output>0.2</output>
<gadget id="calculator">7_000 / 0.2</gadget>
<output>35_000</output>
<result>E</result> | E | 35,000 | If a cost college Rs0.70 a companyto produce a program for yhe home coming football game.if Rs 15000 was received for addvertisement in the pgm ,how many copies rs 0.50 a copy must be sold to make a profit of Rs 8000 | {
"A": "15000",
"B": "25000",
"C": "45000",
"D": "32000",
"E": "35000"
} | divide(subtract(15000, 8000), subtract(0.7, 0.5)) | subtract(n1,n3)|subtract(n0,n2)|divide(#0,#1) | let no . of pages be x while selling with 0.70 paise / page total cost = 0.70 * x while selling with 0.50 paise / page toatal cost = 0.50 * x now according to question - ( 0.70 x - 0.50 x ) + 8000 = 15000 therefore , x = 35000 copies must be sold answer : e | gain |
math_qa__Zl7HWkpo1Xxfj8BH | If a trader sold two cars each at Rs. 325475 and gains 14% on the first and loses 14% on the second, then his profit or loss percent on the whole is? Choose the correct option: A) 1.44 % B) 1.74 % C) 1.84 % D) 1.96 % E) 1.24 % | <gadget id="calculator">14 * 14</gadget>
<output>196</output>
<gadget id="calculator">196 / 100</gadget>
<output>49/25 = around 1.96</output>
<result>D</result> | D | 1.96 | If a trader sold two cars each at Rs. 325475 and gains 14% on the first and loses 14% on the second, then his profit or loss percent on the whole is? | {
"A": "1.44 %",
"B": "1.74 %",
"C": "1.84 %",
"D": "1.96 %",
"E": "1.24 %"
} | divide(multiply(14, 14), const_100) | multiply(n1,n1)|divide(#0,const_100)| | "sp of each car is rs . 325475 , he gains 14 % on first car and losses 14 % on second car . in this case , there will be loss and percentage of loss is given by = [ ( profit % ) ( loss % ) ] / 100 = ( 14 ) ( 14 ) / 100 % = 1.96 % answer : d" | gain |
math_qa__xhIzJgcHwTMRKJOY | If the wheel is 28 cm then the number of revolutions to cover a distance of 1056 cm is?
Pick: A) 3 B) 5 C) 26 D) 12 E) 6 | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">1 * 10</gadget>
<output>10</output>
<gadget id="calculator">300 + 10</gadget>
<output>310</output>
<gadget id="calculator">310 + 4</gadget>
<output>314</output>
<gadget id="calculator">314 / 100</gadget>
<output>157/50 = around 3.14</output>
<gadget id="calculator">2 * (157/50)</gadget>
<output>157/25 = around 6.28</output>
<gadget id="calculator">(157/25) * 28</gadget>
<output>4_396/25 = around 175.84</output>
<gadget id="calculator">1_056 / (4_396/25)</gadget>
<output>6_600/1_099 = around 6.00546</output>
<result>E</result> | E | 6 | If the wheel is 28 cm then the number of revolutions to cover a distance of 1056 cm is? | {
"A": "3",
"B": "5",
"C": "26",
"D": "12",
"E": "6"
} | divide(1056, multiply(multiply(const_2, divide(add(add(multiply(const_3, const_100), multiply(const_1, const_10)), const_4), const_100)), 28)) | multiply(const_100,const_3)|multiply(const_1,const_10)|add(#0,#1)|add(#2,const_4)|divide(#3,const_100)|multiply(#4,const_2)|multiply(n0,#5)|divide(n1,#6)| | "2 * 22 / 7 * 28 * x = 1056 = > x = 6 answer : e" | physics |
math_qa__l1YW4OzgJD9ClyjQ | How much more would Rs.30000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly? Select the correct option: A) 482 B) 725 C) 992 D) 837 E) 723 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 2</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 4</gadget>
<output>14_641/10_000 = around 1.4641</output>
<gadget id="calculator">(14_641/10_000) * 30_000</gadget>
<output>43_923</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) ** 2</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(36/25) * 30_000</gadget>
<output>43_200</output>
<gadget id="calculator">43_923 - 43_200</gadget>
<output>723</output>
<result>E</result> | E | 723 | How much more would Rs.30000 fetch, after two years, if it is put at 20% p.a. compound interest payable half yearly than if is put at 20% p.a. compound interest payable yearly? | {
"A": "482",
"B": "725",
"C": "992",
"D": "837",
"E": "723"
} | subtract(multiply(power(add(const_1, divide(divide(20, const_100), const_2)), const_4), 30000), multiply(power(add(divide(20, const_100), const_1), const_2), 30000)) | divide(n1,const_100)|add(#0,const_1)|divide(#0,const_2)|add(#2,const_1)|power(#1,const_2)|multiply(n0,#4)|power(#3,const_4)|multiply(n0,#6)|subtract(#7,#5) | 30000 ( 11 / 10 ) 4 - 30000 ( 6 / 5 ) 2 = 723 answer : e | gain |
math_qa__W211bR58fEOozM5A | A survey was sent to 70 customers, 7 of whom responded. Then the survey was redesigned and sent to another 63 customers, 9 of whom responded. By approximately what percent did the response rate increase from the original survey to the redesigned survey? Choices.
A) 2 %
B) 6 %
C) 4 %
D) 28 %
E) 63 % | <gadget id="calculator">9 / 63</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">7 / 70</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/7) - (1/10)</gadget>
<output>3/70 = around 0.042857</output>
<gadget id="calculator">(3/70) * 100</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<result>C</result> | C | 4 | A survey was sent to 70 customers, 7 of whom responded. Then the survey was redesigned and sent to another 63 customers, 9 of whom responded. By approximately what percent did the response rate increase from the original survey to the redesigned survey? | {
"A": "2 %",
"B": "6 %",
"C": "4 %",
"D": "28 %",
"E": "63 %"
} | floor(multiply(subtract(divide(9, 63), divide(7, 70)), const_100)) | divide(n3,n2)|divide(n1,n0)|subtract(#0,#1)|multiply(#2,const_100)|floor(#3) | case 1 : ( 7 / 70 ) = x / 100 x = 10 % case 2 : ( 9 / 63 ) = y / 100 y = 14 % so percent increase is = ( y - x ) = ( 14 - 10 ) % = 4 % answer is c | gain |
math_qa__O9ATSvY6lgl3uNw9 | A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 20 balls per box. If 104 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed?
Select
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">25 - 20</gadget>
<output>5</output>
<result>E</result> | E | 5 | A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 20 balls per box. If 104 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(25, 20) | subtract(n0,n1) | we have to work with multiples of 20 and 25 . first , we must know the limits of this multiples , so : 105 / 25 = 4 . . . . so the max is 4 105 / 20 = 5 . . . so the max is 5 105 - 100 = 5 answer : e | general |
math_qa__dqobrQOjAYQHN63a | How many seconds will a train 250 meters long take to cross a platform 200 meters long if the speed of the train is 90 kmph? Pick: A) 18 sec B) 15 sec C) 21 sec D) 16 sec E) 20 sec | <gadget id="calculator">200 + 250</gadget>
<output>450</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">90 * (5/18)</gadget>
<output>25</output>
<gadget id="calculator">450 / 25</gadget>
<output>18</output>
<result>A</result> | A | 18 | How many seconds will a train 250 meters long take to cross a platform 200 meters long if the speed of the train is 90 kmph? | {
"A": "18 sec",
"B": "15 sec",
"C": "21 sec",
"D": "16 sec",
"E": "20 sec"
} | divide(add(200, 250), multiply(90, const_0_2778)) | add(n0,n1)|multiply(n2,const_0_2778)|divide(#0,#1)| | "d = 250 + 200 = 450 s = 90 * 5 / 18 = 25 mps t = 450 / 25 = 18 sec a ) 18 sec" | physics |
math_qa__cwUq88Fq9FfD45J4 | If x/y = 7/3, then (x + y)/(x - y) = ?
Options
A) 5 B) 5 / 2 C) - 1 / 6 D) - 1 / 5 E) - 5 | <gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">7 - 3</gadget>
<output>4</output>
<gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<result>B</result> | B | 2.5 | If x/y = 7/3, then (x + y)/(x - y) = ? | {
"A": "5",
"B": "5 / 2",
"C": "- 1 / 6",
"D": "- 1 / 5",
"E": "- 5"
} | divide(add(7, 3), subtract(7, 3)) | add(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "any x and y satisfying x / y = 7 / 3 should give the same value for ( x + y ) / ( x - y ) . say x = 7 and y = 3 , then ( x + y ) / ( x - y ) = ( 7 + 3 ) / ( 7 - 3 ) = 5 / 2 . answer : b ." | general |
math_qa__9FqScfVrGX4JEKhp | Working at their respective constant rates, machine A makes 100 copies in 10 minutes and machine B makes 150 copies in 15 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? Options.
A) 250 B) 600 C) 675 D) 700 E) 750 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<result>B</result> | B | 600 | Working at their respective constant rates, machine A makes 100 copies in 10 minutes and machine B makes 150 copies in 15 minutes. If these machines work simultaneously at their respective rates for 30 minutes, what is the total number of copies that they will produce? | {
"A": "250",
"B": "600",
"C": "675",
"D": "700",
"E": "750"
} | multiply(add(divide(100, 10), divide(150, 15)), 30) | divide(n0,n1)|divide(n2,n3)|add(#0,#1)|multiply(n4,#2)| | "machine a can produce 100 * 30 / 10 = 300 copies and , machine b can produce 150 * 30 / 15 = 300 copies total producing 600 copies . b is the answer" | physics |
math_qa__bGlTOSwxUHmGGqaP | The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 360. The banker's discount is: Choose the correct choice.
A) rs . 1360 B) rs . 1000 C) rs . 360 D) rs . 640 E) none of these | <gadget id="calculator">360 * 100</gadget>
<output>36_000</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36_000 / 36</gadget>
<output>1_000</output>
<gadget id="calculator">360 + 1_000</gadget>
<output>1_360</output>
<result>A</result> | A | 1,360 | The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 360. The banker's discount is: | {
"A": "rs . 1360",
"B": "rs . 1000",
"C": "rs . 360",
"D": "rs . 640",
"E": "none of these"
} | add(360, divide(multiply(360, const_100), multiply(12, 3))) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "explanation : bg = rs . 360 t = 3 years r = 12 % td = ( bg × 100 ) / tr = ( 360 × 100 ) / ( 3 × 12 ) = rs . 1000 bg = bd – td = > bd = bg + td = 360 + 1000 = rs . 1360 answer : option a" | gain |
math_qa__GxgJG8hnKLmYKEpo | Calculate the sum of first 19 natural numbers.
Select:
A) 190 B) 120 C) 150 D) 199 E) 110 | <gadget id="calculator">19 + 1</gadget>
<output>20</output>
<gadget id="calculator">19 / 2</gadget>
<output>19/2 = around 9.5</output>
<gadget id="calculator">20 * (19/2)</gadget>
<output>190</output>
<result>A</result> | A | 190 | Calculate the sum of first 19 natural numbers. | {
"A": "190",
"B": "120",
"C": "150",
"D": "199",
"E": "110"
} | multiply(add(19, const_1), divide(19, const_2)) | add(n0,const_1)|divide(n0,const_2)|multiply(#0,#1) | solution we know that ( 1 + 2 + 3 + . . . . . + 19 ) = n ( n + 1 ) / 2 therefore ( 1 + 2 + 3 + . . . . + 19 ) = ( 19 × 20 / 2 ) = 190 . answer a | general |
math_qa__xZ3ddP6vuf2fN4d6 | A is twice as good a workman as B and they took 5 days together to do the work B alone can do it in? Pick
A) 15 days B) 88 days C) 21 days D) 11 days E) 13 days | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 / 2</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | A is twice as good a workman as B and they took 5 days together to do the work B alone can do it in? | {
"A": "15 days",
"B": "88 days",
"C": "21 days",
"D": "11 days",
"E": "13 days"
} | multiply(divide(multiply(5, add(const_2, const_1)), const_2), const_2) | add(const_1,const_2)|multiply(n0,#0)|divide(#1,const_2)|multiply(#2,const_2)| | "wc = 2 : 1 2 x + x = 1 / 5 x = 1 / 15 = > 15 days answer : a" | physics |
math_qa__4Ze1sIRqMbCdsYHP | Carl is facing very difficult financial times and can only pay the interest on a $10,000 loan he has taken. The bank charges him a quarterly compound rate of 5%. What is the approximate interest he pays annually? Choose the correct choice from the following options: A) $ 1200 B) $ 2000 C) $ 2150 D) $ 2500 E) $ 12000 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 4</gadget>
<output>194_481/160_000 = around 1.215506</output>
<gadget id="calculator">10_000 * (194_481/160_000)</gadget>
<output>194_481/16 = around 12_155.0625</output>
<gadget id="calculator">(194_481/16) - 10_000</gadget>
<output>34_481/16 = around 2_155.0625</output>
<result>C</result> | C | 2,150 | Carl is facing very difficult financial times and can only pay the interest on a $10,000 loan he has taken. The bank charges him a quarterly compound rate of 5%. What is the approximate interest he pays annually? | {
"A": "$ 1200",
"B": "$ 2000",
"C": "$ 2150",
"D": "$ 2500",
"E": "$ 12000"
} | subtract(multiply(multiply(const_100, const_100), power(add(const_1, divide(5, const_100)), const_4)), multiply(const_100, const_100)) | divide(n1,const_100)|multiply(const_100,const_100)|add(#0,const_1)|power(#2,const_4)|multiply(#1,#3)|subtract(#4,#1) | since the options did not make sense with 5 % annual rate of interest , it is apparent that the intent was a 5 % quarterly rate . so the bank charges 5 % every quarter and compounds it in the next quarter . had it been a simple quarterly rate , we would have just found 4 * 5 % of 10,000 = $ 2000 as our answer . but since , the interest is compounded , it will be a bit more than $ 2000 . option ( c ) looks correct . answer : c | gain |
math_qa__UPe4oZW1OXFaZ07p | In measuring the sides of a rectangle, one side is taken 6% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements. Choose the most appropriate option
A) 3.5 %
B) 2.4 %
C) 3 %
D) 5 %
E) 0.7 % | <gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<result>E</result> | E | 0.7 | In measuring the sides of a rectangle, one side is taken 6% in excess and other 5% in deficit. Find the error percentage in the area calculated from these measurements. | {
"A": "3.5 %",
"B": "2.4 %",
"C": "3 %",
"D": "5 %",
"E": "0.7 %"
} | subtract(subtract(6, 5), divide(multiply(6, 5), const_100)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,const_100)|subtract(#1,#2)| | "say both sides of the rectangle are equal to 100 ( so consider that we have a square ) . in this case the area is 100 * 100 = 10,000 . now , the area obtained with wrong measurements would be 106 * 95 = 10,070 , which is 0.7 % greater than the actual area . answer : e ." | geometry |
math_qa__3gbuCa1ifUIYWw6x | In a division, divident is 689, divisior is 36 and quotient is 19. Find the remainder. Choose the correct option
A) 4 B) 3 C) 2 D) 5 E) 6 | <gadget id="calculator">689 % 36</gadget>
<output>5</output>
<result>D</result> | D | 5 | In a division, divident is 689, divisior is 36 and quotient is 19. Find the remainder. | {
"A": "4",
"B": "3",
"C": "2",
"D": "5",
"E": "6"
} | reminder(689, 36) | reminder(n0,n1) | explanation : 689 = 36 x 19 + r 689 = 684 + r r = 689 - 684 = 5 answer : option d | general |
math_qa__4BGat3W9Vy4hNSrF | The product of two numbers is 120 and the sum of their squares is 289. The sum of the number is
Options:
A) 20
B) 23
C) 27
D) 150
E) 255 | <gadget id="calculator">2 * 120</gadget>
<output>240</output>
<gadget id="calculator">289 - 240</gadget>
<output>49</output>
<gadget id="calculator">49 ** (1/2)</gadget>
<output>7</output>
<gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">4 * 120</gadget>
<output>480</output>
<gadget id="calculator">49 + 480</gadget>
<output>529</output>
<gadget id="calculator">529 ** (1/2)</gadget>
<output>23</output>
<result>B</result> | B | 23 | The product of two numbers is 120 and the sum of their squares is 289. The sum of the number is | {
"A": "20",
"B": "23",
"C": "27",
"D": "150",
"E": "255"
} | sqrt(add(power(sqrt(subtract(289, multiply(const_2, 120))), const_2), multiply(const_4, 120))) | multiply(n0,const_4)|multiply(n0,const_2)|subtract(n1,#1)|sqrt(#2)|power(#3,const_2)|add(#0,#4)|sqrt(#5)| | "explanation : we know ( x + y ) 2 = x 2 + y 2 + 2 xy = > ( x + y ) 2 = 289 + 2 ( 120 ) = > ( x + y ) = 529 − − − √ = 23 option b" | general |
math_qa__WmQfYo1nzFugRj4Q | A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 8 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B? Choose the correct choice from the following options
A) 2 B) 9 C) 6 D) 21 E) 30 | <gadget id="calculator">0.06 * 8</gadget>
<output>0.48</output>
<gadget id="calculator">0.6 - 0.48</gadget>
<output>0.12</output>
<gadget id="calculator">0.08 - 0.06</gadget>
<output>0.02</output>
<gadget id="calculator">0.12 / 0.02</gadget>
<output>6</output>
<result>C</result> | C | 6 | A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 8 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B? | {
"A": "2",
"B": "9",
"C": "6",
"D": "21",
"E": "30"
} | divide(subtract(0.6, multiply(0.06, 8)), subtract(0.08, 0.06)) | multiply(n1,n2)|subtract(n3,n2)|subtract(n0,#0)|divide(#2,#1) | let the duration , in minutes , for which the company charges the same under plan a and plan b be t minutes . then under plan a the cost would be $ 0.6 + 0.06 ( t - 8 ) and under plan b the cost would be $ 0.08 t . we want these amount to be equal : 0.6 + 0.06 ( t - 8 ) = 0.08 t - - > 60 + 6 ( t - 8 ) = 8 t - - > t = 6 . answer : c . | other |
math_qa__sI21ZBlWaUmD1SAR | What is the dividend. divisor 18, the quotient is 9 and the remainder is 3 Answers.
A) 145 B) 148 C) 165 D) 153 E) 158 | <gadget id="calculator">18 * 9</gadget>
<output>162</output>
<gadget id="calculator">162 + 3</gadget>
<output>165</output>
<result>C</result> | C | 165 | What is the dividend. divisor 18, the quotient is 9 and the remainder is 3 | {
"A": "145",
"B": "148",
"C": "165",
"D": "153",
"E": "158"
} | add(multiply(18, 9), 3) | multiply(n0,n1)|add(n2,#0)| | "d = d * q + r d = 18 * 9 + 3 d = 162 + 3 d = 165 answer : c" | general |
math_qa__5HsESvi9zkf2684S | The R train leaves station A moving at a constant speed, and passes by stations B and C, in this order. It takes the R train 7 hours to reach station B, and 5 additional hours to reach station C. The distance between stations A and B is m kilometers longer than the distance between stations B and C. What is the distance between stations A and C in terms of m? Choose the correct choice from the following:
A) 1.8 m
B) 6 m
C) 7 m
D) 9 m
E) 12 m | <gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>B</result> | B | 6 | The R train leaves station A moving at a constant speed, and passes by stations B and C, in this order. It takes the R train 7 hours to reach station B, and 5 additional hours to reach station C. The distance between stations A and B is m kilometers longer than the distance between stations B and C. What is the distance between stations A and C in terms of m? | {
"A": "1.8 m",
"B": "6 m",
"C": "7 m",
"D": "9 m",
"E": "12 m"
} | divide(add(7, 5), const_2) | add(n0,n1)|divide(#0,const_2) | the reason it is failing for you is that you chose incorrect numbers . if the question says r it took 7 hrs to reach from a to b and 5 hrs to reach from b to c at a constant speed . it shows that distance ab and bc should be in ratio of 7 / 5 . if you take such numbers you can solve problem . ab = 7 , bc = 5 therefore ab - bc = 2 but from question , ab - bc = m = > m = 2 now total distance = ab + bc = 12 substitute 12 to get answer in terms of m total distance = 12 = 6 m ans b | physics |
math_qa__tn3AyRNpKg5mAff9 | A shirt goes on sale for 50% of its original price. One week later, the sale price is marked down 10%. The final price is what percent of the original price? Select the correct option: A) 72 % B) 70 % C) 52 % D) 50 % E) 45 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 10</gadget>
<output>5</output>
<gadget id="calculator">50 - 5</gadget>
<output>45</output>
<result>E</result> | E | 45 | A shirt goes on sale for 50% of its original price. One week later, the sale price is marked down 10%. The final price is what percent of the original price? | {
"A": "72 %",
"B": "70 %",
"C": "52 %",
"D": "50 %",
"E": "45 %"
} | subtract(50, multiply(divide(50, const_100), 10)) | divide(n0,const_100)|multiply(n1,#0)|subtract(n0,#1)| | "just assume original price is 100 . sale price = 50 then it is marked down by 10 % = 50 - 5 = 45 . hence it is 45 % od the original price . hence answer is e ." | gain |
math_qa__PURp7hVV72P75J3m | Each child has 2 pencils and 13 Skittles. If there are 8 children, how many pencils are there in total? Choose the correct choice from the following:
A) 16 B) 12 C) 18 D) 22 E) 08 | <gadget id="calculator">2 * 8</gadget>
<output>16</output>
<result>A</result> | A | 16 | Each child has 2 pencils and 13 Skittles. If there are 8 children, how many pencils are there in total? | {
"A": "16",
"B": "12",
"C": "18",
"D": "22",
"E": "08"
} | multiply(2, 8) | multiply(n0,n2)| | 2 * 8 = 16 . answer is a . | general |
math_qa__x1UUHxCnURS8DzHa | In what time will a railway train 56 m long moving at the rate of 39 kmph pass a telegraph post on its way? Answers:
A) 3 sec B) 4 sec C) 5 sec D) 6 sec E) 7 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">39 * (5/18)</gadget>
<output>65/6 = around 10.833333</output>
<gadget id="calculator">56 / (65/6)</gadget>
<output>336/65 = around 5.169231</output>
<result>C</result> | C | 5 | In what time will a railway train 56 m long moving at the rate of 39 kmph pass a telegraph post on its way? | {
"A": "3 sec",
"B": "4 sec",
"C": "5 sec",
"D": "6 sec",
"E": "7 sec"
} | divide(56, multiply(39, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 56 / 39 * 18 / 5 = 5 sec answer : c" | physics |
math_qa__To5PiQB2yaFIpgkM | Sachin is younger than Rahul by 9 years. If the ratio of their ages is 7:9, find the age of Sachin Options
A) 31.5
B) 24.5
C) 24.3
D) 24.9
E) 24.1 | <gadget id="calculator">9 - 7</gadget>
<output>2</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) * 7</gadget>
<output>63/2 = around 31.5</output>
<result>A</result> | A | 31.5 | Sachin is younger than Rahul by 9 years. If the ratio of their ages is 7:9, find the age of Sachin | {
"A": "31.5",
"B": "24.5",
"C": "24.3",
"D": "24.9",
"E": "24.1"
} | multiply(divide(9, subtract(9, 7)), 7) | subtract(n2,n1)|divide(n0,#0)|multiply(n1,#1)| | "if rahul age is x , then sachin age is x - 9 , so ( x - 9 ) / x = 7 / 9 = > 9 x - 81 = 7 x = > 2 x = 81 = > x = 40.5 so sachin age is 40.5 - 9 = 31.5 answer : a" | other |
math_qa__JOTJklrKxNu2w4xo | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 245, then how much amount should C pay as his share of rent?
Choose the correct choice from the following.
A) 35
B) 45
C) 25
D) 63
E) 55 | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">70 + 60</gadget>
<output>130</output>
<gadget id="calculator">130 + 45</gadget>
<output>175</output>
<gadget id="calculator">45 / 175</gadget>
<output>9/35 = around 0.257143</output>
<gadget id="calculator">245 * (9/35)</gadget>
<output>63</output>
<result>D</result> | D | 63 | A, B and C rent a pasture. If A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing and the rent of the pasture is Rs. 245, then how much amount should C pay as his share of rent? | {
"A": "35",
"B": "45",
"C": "25",
"D": "63",
"E": "55"
} | multiply(245, divide(multiply(15, 3), add(add(multiply(10, 7), multiply(12, 5)), multiply(15, 3)))) | multiply(n4,n5)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|add(#3,#0)|divide(#0,#4)|multiply(n6,#5)| | "a : b : c = 10 × 7 : 12 × 5 : 15 × 3 = 2 × 7 : 12 × 1 : 3 × 3 = 14 : 12 : 9 amount that c should pay = 245 × 9 / 35 = 7 × 9 = 63 answer is d" | general |
math_qa__EWQZZeWsOf2MQHLV | If 5 machines can produce 20 units in 10 hours, how long would it take 10 to produce 60 units? Answers:
A) 9 B) 10 C) 15 D) 25 E) 30 | <gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 20</gadget>
<output>4</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<result>C</result> | C | 15 | If 5 machines can produce 20 units in 10 hours, how long would it take 10 to produce 60 units? | {
"A": "9",
"B": "10",
"C": "15",
"D": "25",
"E": "30"
} | divide(60, multiply(divide(divide(10, 10), 5), 20)) | divide(n3,n2)|divide(#0,n0)|multiply(n1,#1)|divide(n4,#2)| | "5 machines would produce 60 units in 30 hours . increasing the amount of machines by 2 would mean dividing 30 hours by 2 . 30 / 2 = 15 answer : c" | physics |
math_qa__mYhVrEY3oeMutzUY | A and B started a business jointly A's investment was thrice the investment of B and the period of his investment was two times the period of investment of B. If B received Rs. 4000 as profit, then their total profit is ? Pick one
A) 28029
B) 28000
C) 28001
D) 28012
E) 28129 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 * 4_000</gadget>
<output>28_000</output>
<result>B</result> | B | 28,000 | A and B started a business jointly A's investment was thrice the investment of B and the period of his investment was two times the period of investment of B. If B received Rs. 4000 as profit, then their total profit is ? | {
"A": "28029",
"B": "28000",
"C": "28001",
"D": "28012",
"E": "28129"
} | multiply(add(multiply(const_2, const_3), const_1), 4000) | multiply(const_2,const_3)|add(#0,const_1)|multiply(n0,#1) | suppose b invested rs . x for y months . then , a invested rs . 3 x for 2 y months . so , a : b = ( 3 x * 2 y ) : ( x * y ) = 6 xy : xy = 6 : 1 . b ' s profit : total profit = 1 : 7 . let the total profit be rs . x then , 1 / 7 = 4000 / x or x = 28000 . answer : b | general |
math_qa__AEzSfaURzteRF7Tj | In a class of 40 students, 10 did not opt for math. 15 did not opt for science and 2 did not opt for either. How many students of the class opted for both math and science?
Select: A) 13 B) 15 C) 7 D) 17 E) 18 | <gadget id="calculator">40 - 10</gadget>
<output>30</output>
<gadget id="calculator">40 - 15</gadget>
<output>25</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<gadget id="calculator">30 - 23</gadget>
<output>7</output>
<result>C</result> | C | 7 | In a class of 40 students, 10 did not opt for math. 15 did not opt for science and 2 did not opt for either. How many students of the class opted for both math and science? | {
"A": "13",
"B": "15",
"C": "7",
"D": "17",
"E": "18"
} | subtract(subtract(40, 10), subtract(subtract(40, 15), 2)) | subtract(n0,n1)|subtract(n0,n2)|subtract(#1,n3)|subtract(#0,#2) | 40 students total 10 did not opt for math 15 did not opt for science 2 did not opt for either total of 30 students in math and 13 did not opt for sci but did for math 30 - 13 = 7 7 students of the class opted for both math and science answer : c . 7 | other |
math_qa__f4eM0irkoDZgmkBe | A car traveled 462 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 15 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city? Choose the correct choice from the following answers:
A) 14 B) 16 C) 21 D) 22 E) 40 | <gadget id="calculator">462 - 336</gadget>
<output>126</output>
<gadget id="calculator">126 / 15</gadget>
<output>42/5 = around 8.4</output>
<gadget id="calculator">336 / (42/5)</gadget>
<output>40</output>
<result>E</result> | E | 40 | A car traveled 462 miles per tankful of gasoline on the highway and 336 miles per tankful of gasoline in the city. If the car traveled 15 fewer miles per gallon in the city than on the highway, how many miles per gallon did the car travel in the city? | {
"A": "14",
"B": "16",
"C": "21",
"D": "22",
"E": "40"
} | divide(336, divide(subtract(462, 336), 15)) | subtract(n0,n1)|divide(#0,n2)|divide(n1,#1)| | "i treat such problems as work ones . work = rate * time mileage ( m ) = rate ( mpg ) * gallons ( g ) x gallons is a full tank { 462 = rx { 336 = ( r - 15 ) x solve for r , r = 55 55 - 15 = 40 mpg e" | physics |
math_qa__sYHmQ8b1ladCbc72 | Sahil purchased a machine at Rs 14000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it. Choose the correct option:
A) rs . 22000 B) rs . 24000 C) rs . 26000 D) rs . 30000 E) none of these | <gadget id="calculator">14_000 + 5_000</gadget>
<output>19_000</output>
<gadget id="calculator">19_000 + 1_000</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 100</gadget>
<output>200</output>
<gadget id="calculator">200 * 50</gadget>
<output>10_000</output>
<gadget id="calculator">20_000 + 10_000</gadget>
<output>30_000</output>
<result>D</result> | D | 30,000 | Sahil purchased a machine at Rs 14000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it. | {
"A": "rs . 22000",
"B": "rs . 24000",
"C": "rs . 26000",
"D": "rs . 30000",
"E": "none of these"
} | add(add(add(14000, 5000), 1000), multiply(divide(add(add(14000, 5000), 1000), const_100), 50)) | add(n0,n1)|add(n2,#0)|divide(#1,const_100)|multiply(n3,#2)|add(#1,#3)| | "explanation : question seems a bit tricky , but it is very simple . just calculate all cost price , then get 150 % of cp . c . p . = 14000 + 5000 + 1000 = 20000 150 % of 20000 = 150 / 100 * 20000 = 30000 option d" | gain |
math_qa__fyINNSXCNWSbRM1s | The salary of a person was reduced by 50%. By what percent should his reduced salary be raised so as to bring it at par with his original salary? Answers:
A) 20 %
B) 25 %
C) 50 %
D) 75 %
E) 100 % | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 * (1/2)</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>E</result> | E | 100 | The salary of a person was reduced by 50%. By what percent should his reduced salary be raised so as to bring it at par with his original salary? | {
"A": "20 %",
"B": "25 %",
"C": "50 %",
"D": "75 %",
"E": "100 %"
} | multiply(divide(multiply(const_100, divide(50, const_100)), subtract(const_100, multiply(const_100, divide(50, const_100)))), const_100) | divide(n0,const_100)|multiply(#0,const_100)|subtract(const_100,#1)|divide(#1,#2)|multiply(#3,const_100)| | "let the original salary be $ 100 new salary = $ 50 increase on 50 = 50 increase on 100 = 50 / 50 * 100 = 100 % ( approximately ) answer is e" | gain |
math_qa__ZDpxcwpiO1zZKws8 | There are 25 stations between Hyderabad and Bangalore. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station? Select the correct option: A) 156 B) 167 C) 157 D) 352 E) 702 | <gadget id="calculator">25 + 1</gadget>
<output>26</output>
<gadget id="calculator">26 + 1</gadget>
<output>27</output>
<gadget id="calculator">26 * 27</gadget>
<output>702</output>
<result>E</result> | E | 702 | There are 25 stations between Hyderabad and Bangalore. How many second class tickets have to be printed, so that a passenger can travel from any station to any other station? | {
"A": "156",
"B": "167",
"C": "157",
"D": "352",
"E": "702"
} | multiply(add(25, const_1), add(add(25, const_1), const_1)) | add(n0,const_1)|add(#0,const_1)|multiply(#0,#1)| | "the total number of stations = 27 from 27 stations we have to choose any two stations and the direction of travel ( i . e . , hyderabad to bangalore is different from bangalore to hyderabad ) in ² ⁰ p ₂ ways . ² ⁰ p ₂ = 27 * 26 = 702 . answer : e" | physics |
math_qa__tDRhO0JFsaijxH3X | If in a cricket one day match, there were no wide balls, no wides, no extras and no overthrows.
What is the maximum number of runs that a batsman can score in 35 overs in an ideal case scenario?
Choices.
A) 1158 B) 1651 C) 1653 D) 1654 E) none | <gadget id="calculator">35 - 2</gadget>
<output>33</output>
<gadget id="calculator">35 * 33</gadget>
<output>1_155</output>
<result>A</result> | A | 1,158 | If in a cricket one day match, there were no wide balls, no wides, no extras and no overthrows.
What is the maximum number of runs that a batsman can score in 35 overs in an ideal case scenario? | {
"A": "1158",
"B": "1651",
"C": "1653",
"D": "1654",
"E": "none"
} | multiply(35, subtract(35, const_2)) | subtract(n0,const_2)|multiply(n0,#0) | solution : 1158 explanation : for an ideal case , the batsman will hit a six on each ball . but if he hits six on the last ball of the over , the strike will change in the next over . thus , the best he can do in the last ball is run 3 runs so that he retains the strike even in the next over . thus the total runs that he can score in each over : 6 * 5 + 3 = 33 but this will have to go like it only till the 34 th over . in the 35 th over , he can hit a six in the last ball as well as that will be the last ball of his destination . thus runs for the 35 th over will be 6 * 6 = 36 . hence the maximum runs = 33 * 34 + 36 = 1158 answer a | physics |
math_qa__X4czXDNFv9uQcAc6 | There is a total of 90 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/3 and the probability that it will be green is 1/5. What is the probability that the marble will be either red or blue?
Choose the most appropriate option.
A) 1 / 3
B) 3 / 5
C) 7 / 15
D) 11 / 30
E) 17 / 30 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/3) + (1/5)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">1 - (8/15)</gadget>
<output>7/15 = around 0.466667</output>
<result>C</result> | C | 0.466667 | There is a total of 90 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/3 and the probability that it will be green is 1/5. What is the probability that the marble will be either red or blue? | {
"A": "1 / 3",
"B": "3 / 5",
"C": "7 / 15",
"D": "11 / 30",
"E": "17 / 30"
} | subtract(1, add(divide(1, 3), divide(1, 5))) | divide(n1,n2)|divide(n3,n4)|add(#0,#1)|subtract(n1,#2)| | "p ( red or blue ) = 1 - p ( white ) - p ( green ) = 15 / 15 - 5 / 15 - 3 / 15 = 7 / 15 the answer is c ." | general |
math_qa__r9SlPvxxEugIp2q6 | A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail Choose the correct choice:
A) 2 / 4 B) 1 / 3 C) 2 / 3 D) 3 / 6 E) 1 / 4 | <gadget id="calculator">2 / 8</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">6 / 8</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/4) / (3/4)</gadget>
<output>1/3 = around 0.333333</output>
<result>B</result> | B | 0.333333 | A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail | {
"A": "2 / 4",
"B": "1 / 3",
"C": "2 / 3",
"D": "3 / 6",
"E": "1 / 4"
} | divide(divide(const_2, 8), divide(const_6, 8)) | divide(const_2,n0)|divide(const_6,n0)|divide(#0,#1) | sample space s = { hh , ht , t 1 , t 2 , t 3 , t 4 , t 5 , t 6 } let a be the event that the die shows a number greater than 4 and b be the event that the first throw of the coin results in a tail then , a = { t 5 , t 6 } b = { t 1 , t 2 , t 3 , t 4 , t 5 , t 6 } required probability = ( 2 / 8 ) / ( 6 / 8 ) = 1 / 3 answer : b | probability |
math_qa__GId8kgKoADQYRoOE | John purchased a grinder and a mobile for Rs. 15000 &Rs. 10000 respectively. He sold the grinder at a loss of 4% and the mobile phone at a profit of 10%. Overall how much he make a profit. Choices: A) s . 400 B) s . 120 C) s . 420 D) s . 450 E) s . 290 | <gadget id="calculator">10_000 / 100</gadget>
<output>100</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<gadget id="calculator">4 * 150</gadget>
<output>600</output>
<gadget id="calculator">1_000 - 600</gadget>
<output>400</output>
<result>A</result> | A | 400 | John purchased a grinder and a mobile for Rs. 15000 &Rs. 10000 respectively. He sold the grinder at a loss of 4% and the mobile phone at a profit of 10%. Overall how much he make a profit. | {
"A": "s . 400",
"B": "s . 120",
"C": "s . 420",
"D": "s . 450",
"E": "s . 290"
} | subtract(multiply(10, divide(10000, const_100)), multiply(4, divide(15000, const_100))) | divide(n1,const_100)|divide(n0,const_100)|multiply(n3,#0)|multiply(n2,#1)|subtract(#2,#3)| | "let the sp of the refrigerator and the mobile phone be rs . r and rs . m respectively . r = 15000 ( 1 - 4 / 100 ) = 15000 - 600 m = 10000 ( 1 + 10 / 100 ) = 10000 + 1000 total sp - total cp = r + m - ( 15000 + 10000 ) = - 600 + 1000 = rs . 400 as this is positive , an overall profit of rs . 400 was made . a" | gain |
math_qa__1m5RjysusjLvIqmd | A boat crossed a lake from North to East at the speed of 10 km/h, entered a river and covered twice as much distance going upstream at 9 km/h. It then turned around and stopped at the south shore of the lake. If it averaged 3.8 km/h that day, what was its approximate downstream speed? Choose the correct choice from the following choices.
A) 4 B) 5 C) 6 D) 7 E) 11 | <gadget id="calculator">10 - 9</gadget>
<output>1</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<result>E</result> | E | 11 | A boat crossed a lake from North to East at the speed of 10 km/h, entered a river and covered twice as much distance going upstream at 9 km/h. It then turned around and stopped at the south shore of the lake. If it averaged 3.8 km/h that day, what was its approximate downstream speed? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "11"
} | add(10, subtract(10, 9)) | subtract(n0,n1)|add(n0,#0) | one way of solving this is : speed of boat on still water ( lake ) = 10 kmph speed upstream = 9 kmph = speed in still water - speed of river = > speed of river = 1 kmph = > speed downstream = speed in still water + speed of river = 10 + 1 = 11 kmph ans is e | general |
math_qa__wuXCTNDeHbHooUoD | A 180m long train is running at 72 kmph.If it crossed the platform in 20 sec.then find the platform length? Choose the correct choice:
A) 220 m B) 110 m C) 230 m D) 100 m E) 90 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 - 180</gadget>
<output>220</output>
<result>A</result> | A | 220 | A 180m long train is running at 72 kmph.If it crossed the platform in 20 sec.then find the platform length? | {
"A": "220 m",
"B": "110 m",
"C": "230 m",
"D": "100 m",
"E": "90 m"
} | subtract(multiply(20, multiply(72, const_0_2778)), 180) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0) | length = speed * time length = 72 km / hr * time length = [ 72 * ( 5 / 18 ) ] * 20 { ( ie ) ( x ) km / hr ) } = x * ( 5 / 18 ) = 20 * 20 length = 400 m length of platform = length - length of the train length of platform = 400 - 180 length of platform = 220 m option a | physics |
math_qa__ygCOKLR43j1yeDq5 | Two cars start at the same time from opposite ends of a highway that is 333 miles long. One car is riding at 54 mph and the second car is riding at 57 mph. How long after they begin will they meet?
Answers:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">54 + 57</gadget>
<output>111</output>
<gadget id="calculator">333 / 111</gadget>
<output>3</output>
<result>C</result> | C | 3 | Two cars start at the same time from opposite ends of a highway that is 333 miles long. One car is riding at 54 mph and the second car is riding at 57 mph. How long after they begin will they meet? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(333, add(54, 57)) | add(n1,n2)|divide(n0,#0)| | "as cars are moving in opposite directions their speeds will be added . so their relative speeds : 57 + 54 = 111 mph total distance to be covered = 333 miles . time taken would be : 333 miles / 111 mph = 3 hours c is the answer ." | physics |
math_qa__SLrDrqFewqQjbEfV | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 6500, brokerage being 1/4%, is: Select the correct option
A) 90.03 B) 114 C) 114.75 D) 124 E) 124.75 | <gadget id="calculator">6_500 / 756</gadget>
<output>1_625/189 = around 8.597884</output>
<gadget id="calculator">(1_625/189) * 10.5</gadget>
<output>90.277778</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">90.277778 - (1/4)</gadget>
<output>90.027778</output>
<result>A</result> | A | 90.03 | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 6500, brokerage being 1/4%, is: | {
"A": "90.03",
"B": "114",
"C": "114.75",
"D": "124",
"E": "124.75"
} | subtract(multiply(divide(6500, 756), 10.5), divide(1, 4)) | divide(n2,n1)|divide(n3,n4)|multiply(n0,#0)|subtract(#2,#1)| | "face value = rs . 6500 . dividend = 10.5 % . annual income = rs . 756 . brokerage per rs . 100 = rs . 0.25 . dividend is always paid on the face value of a share . face value * dividend / ( market value + brokerage per rs . 100 ) = annual income . = 6500 * 10.5 / 756 = market value of rs . 100 stock + brokerage per rs . 100 . = market value of rs . 100 stock + brokerage per rs . 100 = rs . 90.27 . = market value of rs . 100 stock = rs . 90.27 - re . 0.25 . = market value of rs . 100 stock = rs . 90.03 . answer : a" | gain |
math_qa__3la00pwaQ1ruz3WA | A factory produces 5500 toys per week. If the workers at this factory work 5 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? Choose the correct choice from the following options:
A) 1100 toys
B) 5487 toys
C) 6113 toys
D) 2354 toys
E) 1375 toys | <gadget id="calculator">5_500 / 5</gadget>
<output>1_100</output>
<result>A</result> | A | 1,100 | A factory produces 5500 toys per week. If the workers at this factory work 5 days a week and if these workers make the same number of toys everyday, how many toys are produced each day? | {
"A": "1100 toys",
"B": "5487 toys",
"C": "6113 toys",
"D": "2354 toys",
"E": "1375 toys"
} | divide(5500, 5) | divide(n0,n1)| | "to find the number of toys produced every day , we divide the total number of toys produced in one week ( of 5 days ) by 5 . 5500 / 5 = 1100 toys correct answer a" | physics |
math_qa__HDdlpu4L1vAmVoxH | How many litres of pure acid are there in 8 litres of a 20% solution Choose the correct choice from the following
A) 1.5 B) 1.6 C) 1.7 D) 1.8 E) 1.9 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 8</gadget>
<output>8/5 = around 1.6</output>
<result>B</result> | B | 1.6 | How many litres of pure acid are there in 8 litres of a 20% solution | {
"A": "1.5",
"B": "1.6",
"C": "1.7",
"D": "1.8",
"E": "1.9"
} | multiply(divide(20, const_100), 8) | divide(n1,const_100)|multiply(n0,#0)| | "explanation : question of this type looks a bit typical , but it is too simple , as below . . . it will be 8 * 20 / 100 = 1.6 answer : option b" | gain |
math_qa__tn7nnpTHZSAaPgg3 | The avg weight of A,B & C is 50 kg. If D joins the group, the avg weight of the group becomes 53 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 51 kg. What is the weight of A?
Select the correct option:
A) 56 B) 65 C) 73 D) 89 E) 90 | <gadget id="calculator">53 * 4</gadget>
<output>212</output>
<gadget id="calculator">51 * 4</gadget>
<output>204</output>
<gadget id="calculator">50 * 3</gadget>
<output>150</output>
<gadget id="calculator">212 - 150</gadget>
<output>62</output>
<gadget id="calculator">3 + 62</gadget>
<output>65</output>
<gadget id="calculator">204 - 65</gadget>
<output>139</output>
<gadget id="calculator">212 - 139</gadget>
<output>73</output>
<result>C</result> | C | 73 | The avg weight of A,B & C is 50 kg. If D joins the group, the avg weight of the group becomes 53 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 51 kg. What is the weight of A? | {
"A": "56",
"B": "65",
"C": "73",
"D": "89",
"E": "90"
} | subtract(multiply(53, const_4), subtract(multiply(51, const_4), add(3, subtract(multiply(53, const_4), multiply(50, 3))))) | multiply(n1,const_4)|multiply(n3,const_4)|multiply(n0,n2)|subtract(#0,#2)|add(n2,#3)|subtract(#1,#4)|subtract(#0,#5)| | "a + b + c = 3 * 50 = 150 a + b + c + d = 4 * 53 = 212 - - - - ( i ) so , d = 62 & e = 62 + 3 = 65 b + c + d + e = 51 * 4 = 204 - - - ( ii ) from eq . ( i ) & ( ii ) a - e = 212 – 204 = 8 a = e + 8 = 65 + 8 = 73 answer : c" | general |
math_qa__F9n8CRJxLKdiMfiw | In an election between two candidates, the winner has a margin of 20% of the votes polled. If 3000 people change their mind and vote for the loser, the loser would have won by a margin of 20% of the votes polled. Find the total number of votes polled in the election? Select:
A) 15000
B) 20000
C) 30000
D) 60000
E) 45000 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">3_000 / (1/5)</gadget>
<output>15_000</output>
<result>A</result> | A | 15,000 | In an election between two candidates, the winner has a margin of 20% of the votes polled. If 3000 people change their mind and vote for the loser, the loser would have won by a margin of 20% of the votes polled. Find the total number of votes polled in the election? | {
"A": "15000",
"B": "20000",
"C": "30000",
"D": "60000",
"E": "45000"
} | divide(3000, divide(20, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "winner - looser 60 % - 40 % if 3000 people change their mind and vote for the loser : winner - looser 40 % - 60 % thus 3,000 people compose 20 % of all voters , which means that the total number of votes is 15,000 . answer : a" | gain |
math_qa__XmX6klfSBiHrayt2 | P, Q and R have $5000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? Choose the correct choice from the following options:
A) 2400 B) 2403 C) 3998 D) 2539 E) 2000 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">5_000 * 4</gadget>
<output>20_000</output>
<gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) * 3</gadget>
<output>4</output>
<gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">20_000 / 10</gadget>
<output>2_000</output>
<result>E</result> | E | 2,000 | P, Q and R have $5000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? | {
"A": "2400",
"B": "2403",
"C": "3998",
"D": "2539",
"E": "2000"
} | divide(multiply(5000, multiply(const_2, const_2)), add(add(multiply(divide(multiply(const_2, const_2), const_3), const_3), multiply(const_1, const_3)), multiply(const_1, const_3))) | multiply(const_2,const_2)|multiply(const_1,const_3)|divide(#0,const_3)|multiply(n0,#0)|multiply(#2,const_3)|add(#4,#1)|add(#5,#1)|divide(#3,#6)| | "e 2000 let the amount with r be $ r r = 2 / 3 ( total amount with p and q ) r = 2 / 3 ( 5000 - r ) = > 3 r = 10000 - 2 r = > 5 r = 10000 = > r = 2000 ." | general |
math_qa__3XSZ5Svhk0Jz2axL | A $500 investment and a $1,500 investment have a combined yearly return of 16 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? Choose the correct choice from the following answers:
A) 9 %
B) 10 %
C) 105 / 8 %
D) 11 %
E) 19 % | <gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<gadget id="calculator">500 + 1_500</gadget>
<output>2_000</output>
<gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">2_000 * (4/25)</gadget>
<output>320</output>
<gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">500 * (7/100)</gadget>
<output>35</output>
<gadget id="calculator">320 - 35</gadget>
<output>285</output>
<gadget id="calculator">285 / 1_500</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">(19/100) * 100</gadget>
<output>19</output>
<result>E</result> | E | 19 | A $500 investment and a $1,500 investment have a combined yearly return of 16 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? | {
"A": "9 %",
"B": "10 %",
"C": "105 / 8 %",
"D": "11 %",
"E": "19 %"
} | multiply(divide(subtract(multiply(add(500, multiply(const_3, 500)), divide(16, const_100)), multiply(500, divide(7, const_100))), multiply(const_3, 500)), const_100) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_3)|add(n0,#2)|multiply(n0,#1)|multiply(#3,#0)|subtract(#5,#4)|divide(#6,#2)|multiply(#7,const_100)| | "the equation we can form the question : return on total investment = sum of individual investments ( 500 + 1500 ) ( 16 ) = ( 500 â ˆ — 7 ) + ( 1500 x ) , where x is the return on investment of 1500 . solving the equation , we get x = 19 % ( option e ) answer : e" | gain |
math_qa__BxHLVja6B7LQP2QO | An investment yields an interest payment of $216 each month. If the simple annual interest rate is 9%, what is the amount of the investment? Choose the correct choice
A) $ 28,300 B) $ 30,400 C) $ 28,800 D) $ 32,500 E) $ 35,100 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">216 / (3/4)</gadget>
<output>288</output>
<gadget id="calculator">288 * 100</gadget>
<output>28_800</output>
<result>C</result> | C | 28,800 | An investment yields an interest payment of $216 each month. If the simple annual interest rate is 9%, what is the amount of the investment? | {
"A": "$ 28,300",
"B": "$ 30,400",
"C": "$ 28,800",
"D": "$ 32,500",
"E": "$ 35,100"
} | multiply(divide(216, divide(9, multiply(const_3, const_4))), const_100) | multiply(const_3,const_4)|divide(n1,#0)|divide(n0,#1)|multiply(#2,const_100)| | "let the principal amount = p simple annual interest = 9 % simple monthly interest = ( 9 / 12 ) = ( 3 / 4 ) % ( 3 / 4 ) * ( p / 100 ) = 216 = > p = ( 216 * 4 * 10 ^ 2 ) / 3 = 72 * 4 * 10 ^ 2 = 288 * 10 ^ 2 = 28800 answer c" | gain |
math_qa__ElYaPMg0o1LinWhc | you have a 6 - sided cube and 6 cans of paint , each a different color . you may not mix colors of paint . how many distinct ways can you paint the cube using a different color for each side ? ( if you can reorient a cube to look like another cube , then the two cubes are not distinct . )
Choose the correct choice from the following answers:
A) 24 B) 30 C) 48 D) 60 E) 120 | <gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>B</result> | B | 30 | you have a 6 - sided cube and 6 cans of paint , each a different color . you may not mix colors of paint . how many distinct ways can you paint the cube using a different color for each side ? ( if you can reorient a cube to look like another cube , then the two cubes are not distinct . ) | {
"A": "24",
"B": "30",
"C": "48",
"D": "60",
"E": "120"
} | multiply(factorial(divide(6, const_2)), subtract(6, const_1)) | divide(n0,const_2)|subtract(n0,const_1)|factorial(#0)|multiply(#2,#1) | paint one of the faces red and make it the top face . 5 options for the bottom face . now , four side faces can be painted in ( 4 - 1 ) ! = 3 ! = 6 ways ( circular arrangements of 4 colors ) . total = 5 * 6 = 30 . answer : b . | general |
math_qa__TgHy4KqS9Kj7rSE6 | One night 18 percent of the female officers on a police force were on duty. If 144 police officers were on duty that night and half of these were female officers, how many female officers were on the police force? Select.
A) 300
B) 400
C) 500
D) 600
E) 700 | <gadget id="calculator">144 / 2</gadget>
<output>72</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">72 / (9/50)</gadget>
<output>400</output>
<result>B</result> | B | 400 | One night 18 percent of the female officers on a police force were on duty. If 144 police officers were on duty that night and half of these were female officers, how many female officers were on the police force? | {
"A": "300",
"B": "400",
"C": "500",
"D": "600",
"E": "700"
} | divide(divide(144, const_2), divide(18, const_100)) | divide(n1,const_2)|divide(n0,const_100)|divide(#0,#1)| | "let x be the number of female police officers on the police force . the number of female police officers on duty was 72 . 0.18 x = 72 x = 400 the answer is b ." | gain |
math_qa__rdOLme4rA9p1xlMg | A shirt goes on sale for 70% of its original price. One week later, the sale price is marked down 10%. The final price is what percent of the original price?
Choose the most appropriate option
A) 63 % B) 70 % C) 62 % D) 50 % E) 28 % | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 10</gadget>
<output>7</output>
<gadget id="calculator">70 - 7</gadget>
<output>63</output>
<result>A</result> | A | 63 | A shirt goes on sale for 70% of its original price. One week later, the sale price is marked down 10%. The final price is what percent of the original price? | {
"A": "63 %",
"B": "70 %",
"C": "62 %",
"D": "50 %",
"E": "28 %"
} | subtract(70, multiply(divide(70, const_100), 10)) | divide(n0,const_100)|multiply(n1,#0)|subtract(n0,#1) | just assume original price is 100 . sale price = 70 then it is marked down by 10 % = 70 - 7 = 63 . hence it is 63 % od the original price . hence answer is a . | gain |
math_qa__YY1tGW1oRzDJntS1 | A 250 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? Choose the correct choice from the following answers:
A) 250 B) 245 C) 240 D) 235 E) 230 | <gadget id="calculator">120 + 80</gadget>
<output>200</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">200 * (5/18)</gadget>
<output>500/9 = around 55.555556</output>
<gadget id="calculator">(500/9) * 9</gadget>
<output>500</output>
<gadget id="calculator">500 - 250</gadget>
<output>250</output>
<result>A</result> | A | 250 | A 250 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? | {
"A": "250",
"B": "245",
"C": "240",
"D": "235",
"E": "230"
} | subtract(multiply(multiply(add(120, 80), const_0_2778), 9), 250) | add(n1,n2)|multiply(#0,const_0_2778)|multiply(n3,#1)|subtract(#2,n0)| | "relative speed = 120 + 80 = 200 km / hr . = 200 * 5 / 18 = 500 / 9 m / sec . let the length of the other train be x m . then , ( x + 250 ) / 9 = 500 / 9 = > x = 250 . answer : option a" | physics |
math_qa__TPCuccxa4NmEHnkg | 3 candidates in an election and received 2500, 5000 and 15000 votes respectively. What % of the total votes did the winningcandidate got in that election? Choose the correct choice from the following
A) 45 %
B) 50 %
C) 57 %
D) 66.6 %
E) 65.6 % | <gadget id="calculator">2_500 + 5_000</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 + 15_000</gadget>
<output>22_500</output>
<gadget id="calculator">15_000 / 22_500</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>D</result> | D | 66.6 | 3 candidates in an election and received 2500, 5000 and 15000 votes respectively. What % of the total votes did the winningcandidate got in that election? | {
"A": "45 %",
"B": "50 %",
"C": "57 %",
"D": "66.6 %",
"E": "65.6 %"
} | multiply(divide(15000, add(add(2500, 5000), 15000)), const_100) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(#2,const_100)| | "total number of votes polled = ( 2500 + 5000 + 15000 ) = 22500 so , required percentage = 11628 / 20400 * 100 = 66.6 % d" | gain |
math_qa__qBPzwgxYHUbeENzH | Laura took out a charge account at the General Store and agreed to pay 4% simple annual interest. If she charges $35 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? Choose the correct option.
A) $ 36.4 B) $ 37.10 C) $ 37.16 D) $ 38.10 E) $ 38.80 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 35</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) + 35</gadget>
<output>182/5 = around 36.4</output>
<result>A</result> | A | 36.4 | Laura took out a charge account at the General Store and agreed to pay 4% simple annual interest. If she charges $35 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? | {
"A": "$ 36.4",
"B": "$ 37.10",
"C": "$ 37.16",
"D": "$ 38.10",
"E": "$ 38.80"
} | add(multiply(divide(4, const_100), 35), 35) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)| | "principal that is amount taken by laura at year beginning = 35 $ rate of interest = 4 % interest = ( 4 / 100 ) * 35 = 1.4 $ total amount that laura owes a year later = 35 + 1.4 = 36.4 $ answer a" | general |
math_qa__bFjHTXXZHktTkYhB | A boat running up stram takes 6 hours to cover a certain distance, while it takes 10 hours to cover the same distance running down stream. what is the ratio between the speed of the boat and the speed of water current respectively?
Choose the correct choice from the following answers.
A) 2 : 3 B) 5 : 6 C) 4 : 1 D) 7 : 1 E) 8 : 1 | <gadget id="calculator">10 - 6</gadget>
<output>4</output>
<result>C</result> | C | 4 | A boat running up stram takes 6 hours to cover a certain distance, while it takes 10 hours to cover the same distance running down stream. what is the ratio between the speed of the boat and the speed of water current respectively? | {
"A": "2 : 3",
"B": "5 : 6",
"C": "4 : 1",
"D": "7 : 1",
"E": "8 : 1"
} | subtract(10, 6) | subtract(n1,n0) | explanation : let speed of boat is x km / h and speed stream is y km / hr 6 ( x + y ) = 10 ( x - y ) 6 x + 6 y = 10 x - 10 y 16 y = 4 x 4 y = x x / y = 4 / 1 4 : 1 answer : option c | physics |
math_qa__PCsu9KdrY81mw7Ox | How many of the integers between 10 and 40 are even ? Select.
A) 21 B) 20 C) 15 D) 10 E) 9 | <gadget id="calculator">40 - 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>C</result> | C | 15 | How many of the integers between 10 and 40 are even ? | {
"A": "21",
"B": "20",
"C": "15",
"D": "10",
"E": "9"
} | divide(subtract(40, 10), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "number start between 10 to 40 is 30 numbers half of them is even . . which is 15 answer : c" | general |
math_qa__9OdD4pcoxI2OSIAs | In a class of 35 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 10 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed? Choose the correct choice from the following choices.
A) 3 B) 5 C) 8 D) 13 E) 15 | <gadget id="calculator">35 * 2</gadget>
<output>70</output>
<gadget id="calculator">12 * 1</gadget>
<output>12</output>
<gadget id="calculator">12 + 10</gadget>
<output>22</output>
<gadget id="calculator">22 + 2</gadget>
<output>24</output>
<gadget id="calculator">35 - 24</gadget>
<output>11</output>
<gadget id="calculator">11 - 1</gadget>
<output>10</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">12 + 20</gadget>
<output>32</output>
<gadget id="calculator">30 + 32</gadget>
<output>62</output>
<gadget id="calculator">70 - 62</gadget>
<output>8</output>
<result>C</result> | C | 8 | In a class of 35 students, 2 students did not borrow any books from the library, 12 students each borrowed 1 book, 10 students each borrowed 2 books, and the rest borrowed at least 3 books. If the average number of books per student was 2, what is the maximum number of books any single student could have borrowed? | {
"A": "3",
"B": "5",
"C": "8",
"D": "13",
"E": "15"
} | subtract(multiply(35, 2), add(multiply(subtract(subtract(35, add(add(multiply(12, 1), 10), 2)), 1), 3), add(multiply(12, 1), multiply(10, 2)))) | multiply(n0,n1)|multiply(n2,n3)|multiply(n1,n4)|add(#1,#2)|add(n4,#1)|add(n1,#4)|subtract(n0,#5)|subtract(#6,n3)|multiply(n6,#7)|add(#3,#8)|subtract(#0,#9)| | "total # of students = 35 avg # of books per student = 2 total # of books = 35 * 2 = 70 # of student borrowed at least 3 books = 35 - 2 - 12 - 10 = 11 # of books borrowed by above 11 students = 70 - ( 12 * 1 ) + ( 10 * 2 ) = 38 considering that 10 out of above 11 students borrowed only 3 books , # of books borrowed = 10 * 3 = 30 so maximum # of books borrowed by any single student = 38 - 30 = 8 option c" | general |
math_qa__r4Vm4YsvTLnhH8DR | Find avrg speed if a man travels at speed of 24km/hr up and 36km/hr dawn at an altitude of 200m. Choose the correct choice from the following answers.
A) 25.8 B) 26.8 C) 27.8 D) 28.8 E) 29.8 | <gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">48 * 36</gadget>
<output>1_728</output>
<gadget id="calculator">24 + 36</gadget>
<output>60</output>
<gadget id="calculator">1_728 / 60</gadget>
<output>144/5 = around 28.8</output>
<result>D</result> | D | 28.8 | Find avrg speed if a man travels at speed of 24km/hr up and 36km/hr dawn at an altitude of 200m. | {
"A": "25.8",
"B": "26.8",
"C": "27.8",
"D": "28.8",
"E": "29.8"
} | divide(multiply(multiply(const_2, 24), 36), add(24, 36)) | add(n0,n1)|multiply(n0,const_2)|multiply(n1,#1)|divide(#2,#0) | avg speed = 2 * x * y / ( x + y ) = 2 * 24 * 36 / ( 24 + 36 ) = 28.8 answer : d | physics |
math_qa__gixrWZFcLmygiClO | A watch was sold at a loss of 36%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?
Choose the correct choice from the following options.
A) 350 B) 288 C) 799 D) 778 E) 901 | <gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 36</gadget>
<output>64</output>
<gadget id="calculator">104 - 64</gadget>
<output>40</output>
<gadget id="calculator">14_000 / 40</gadget>
<output>350</output>
<result>A</result> | A | 350 | A watch was sold at a loss of 36%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? | {
"A": "350",
"B": "288",
"C": "799",
"D": "778",
"E": "901"
} | divide(multiply(140, const_100), subtract(add(const_100, 4), subtract(const_100, 36))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "64 % 104 % - - - - - - - - 40 % - - - - 140 100 % - - - - ? = > rs . 350 answer : a" | gain |
math_qa__HUF7IuYx4trx1w7x | What is the probability that Jamie and Tom will get selected for a job they both applied for in a company, given that their chances of getting selected is 2/3 and 5/7 respectively? Pick:
A) 13 / 25 B) 2 / 5 C) 9 / 20 D) 11 / 20 E) 10 / 21 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">(2/3) * (5/7)</gadget>
<output>10/21 = around 0.47619</output>
<result>E</result> | E | 0.47619 | What is the probability that Jamie and Tom will get selected for a job they both applied for in a company, given that their chances of getting selected is 2/3 and 5/7 respectively? | {
"A": "13 / 25",
"B": "2 / 5",
"C": "9 / 20",
"D": "11 / 20",
"E": "10 / 21"
} | multiply(divide(2, 3), divide(5, 7)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1) | explanation : p ( jamie ) = 2 / 3 p ( tom ) = 5 / 7 e = { jamie and tom both get selected } p ( e ) = p ( jamie ) * p ( tom ) = 2 / 3 * 5 / 7 = 10 / 21 answer : e | probability |
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