id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__BjY9EMEn5S89KkMK | If x + (1/x) = 5, what is the value of R=x^2 + (1/x)^2? Choose the correct answer.
A) r = 21 B) r = 22 C) r = 23 D) 24 E) 27 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<result>C</result> | C | 23 | If x + (1/x) = 5, what is the value of R=x^2 + (1/x)^2? | {
"A": "r = 21",
"B": "r = 22",
"C": "r = 23",
"D": "24",
"E": "27"
} | subtract(power(5, 2), 2) | power(n1,n2)|subtract(#0,n2)| | "squaring on both sides , x ^ 2 + ( 1 / x ) ^ 2 + 2 ( x ) ( 1 / x ) = 5 ^ 2 x ^ 2 + ( 1 / x ) ^ 2 = 23 answer : c" | general |
math_qa__qpM00OQWkkohn17N | The average of marks obtained by 120 boys was 39. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is? Choose one:
A) 100 B) 110 C) 120 D) 130 E) 140 | <gadget id="calculator">39 * 120</gadget>
<output>4_680</output>
<gadget id="calculator">120 * 15</gadget>
<output>1_800</output>
<gadget id="calculator">4_680 - 1_800</gadget>
<output>2_880</output>
<gadget id="calculator">39 - 15</gadget>
<output>24</output>
<gadget id="calculator">2_880 / 24</gadget>
<output>120</output>
<result>C</result> | C | 120 | The average of marks obtained by 120 boys was 39. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is? | {
"A": "100",
"B": "110",
"C": "120",
"D": "130",
"E": "140"
} | divide(subtract(multiply(39, 120), multiply(120, 15)), subtract(39, 15)) | multiply(n0,n1)|multiply(n0,n3)|subtract(n2,n3)|subtract(#0,#1)|divide(#3,#2)| | "let the number of boys who passed = x . then , 39 x x + 15 x ( 120 - x ) = 120 x 39 24 x = 4680 - 1800 = > x = 2880 / 24 x = 120 . hence , the number of boys passed = 120 . answer : c" | general |
math_qa__qUbXrb2vq1R0SHX6 | The area of a circular place is 17.56 hectares. Find the cost of fencing it at the rate of Rs. 3/meter approximately.
Select:
A) rs . 4233 B) rs . 4350 C) rs . 4457 D) rs . 4670 E) rs . 4756 | <gadget id="calculator">1_000 * 10</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 * 17.56</gadget>
<output>175_600</output>
<gadget id="calculator">175_600 / pi</gadget>
<output>175600/pi = around 55_895.216014</output>
<gadget id="calculator">(175600/pi) ** (1/2)</gadget>
<output>20*sqrt(439)/sqrt(pi) = around 236.421691</output>
<gadget id="calculator">2 * pi * (20*sqrt(439)/sqrt(pi))</gadget>
<output>40*sqrt(439)*sqrt(pi) = around 1_485.481296</output>
<gadget id="calculator">(40*sqrt(439)*sqrt(pi)) * 3</gadget>
<output>120*sqrt(439)*sqrt(pi) = around 4_456.443887</output>
<result>C</result> | C | 4,457 | The area of a circular place is 17.56 hectares. Find the cost of fencing it at the rate of Rs. 3/meter approximately. | {
"A": "rs . 4233",
"B": "rs . 4350",
"C": "rs . 4457",
"D": "rs . 4670",
"E": "rs . 4756"
} | multiply(circumface(sqrt(divide(multiply(multiply(const_1000, const_10), 17.56), const_pi))), const_3) | multiply(const_10,const_1000)|multiply(n0,#0)|divide(#1,const_pi)|sqrt(#2)|circumface(#3)|multiply(#4,const_3) | area = ( 17.56 x 10000 ) m 2 = 175600 m 2 . π r 2 = 175600 ⇔ ( r ) 2 = ( 175600 x ( 7 / 22 ) ) ⇔ r = 236.37 m . circumference = 2 π r = ( 2 x ( 22 / 7 ) x 236.37 ) m = 1485.78 m . cost of fencing = rs . ( 1485.78 x 3 ) = rs . 4457 . c | geometry |
math_qa__vyME8XZerMqGUOQS | The length of a rectangle is halved, while its breadth is tripled. Wa tis the % changein area? Select
A) 40 %
B) 45 %
C) 50 %
D) 60 %
E) 67 % | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 * (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) / 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | The length of a rectangle is halved, while its breadth is tripled. Wa tis the % changein area? | {
"A": "40 %",
"B": "45 %",
"C": "50 %",
"D": "60 %",
"E": "67 %"
} | multiply(divide(subtract(multiply(const_3, divide(const_1, const_2)), const_1), const_1), const_100) | divide(const_1,const_2)|multiply(#0,const_3)|subtract(#1,const_1)|divide(#2,const_1)|multiply(#3,const_100)| | "let original length = x and original breadth = y . original area = xy . new length = x . 2 new breadth = 3 y . new area = x x 3 y = 3 xy . 2 2 increase % = 1 xy x 1 x 100 % = 50 % . 2 xy c" | geometry |
math_qa__I7cqArk975fnP7xr | 10 men and 15 women together can complete a work in 5 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work? Select the correct option
A) 127 days B) 150 days C) 177 days D) 187 days E) 225 days | <gadget id="calculator">1 * 100</gadget>
<output>100</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">15 * 5</gadget>
<output>75</output>
<gadget id="calculator">2 * 75</gadget>
<output>150</output>
<result>B</result> | B | 150 | 10 men and 15 women together can complete a work in 5 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work? | {
"A": "127 days",
"B": "150 days",
"C": "177 days",
"D": "187 days",
"E": "225 days"
} | multiply(divide(multiply(const_1, 100), subtract(multiply(const_1, 100), multiply(10, 5))), multiply(15, 5)) | multiply(n3,const_1)|multiply(n0,n2)|multiply(n1,n2)|subtract(#0,#1)|divide(#0,#3)|multiply(#4,#2)| | "1 man ' s 1 day work = 1 / 100 ( 10 men + 15 women ) ' s 1 day work = 1 / 5 15 women ' s 1 day work = ( 1 / 5 - 10 / 100 ) = 1 / 10 1 woman ' s 1 day work = 1 / 150 1 woman alone can complete the work in 150 days . answer : b" | physics |
math_qa__W1QKkHLIyKx9NOVm | On selling 20 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is: Choose the correct option.
A) s . 48 B) s . 50 C) s . 55 D) s . 60 E) s . 70 | <gadget id="calculator">20 - 5</gadget>
<output>15</output>
<gadget id="calculator">720 / 15</gadget>
<output>48</output>
<result>A</result> | A | 48 | On selling 20 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is: | {
"A": "s . 48",
"B": "s . 50",
"C": "s . 55",
"D": "s . 60",
"E": "s . 70"
} | divide(720, subtract(20, 5)) | subtract(n0,n2)|divide(n1,#0)| | "( c . p . of 20 balls ) - ( s . p . of 20 balls ) = ( c . p . of 5 balls ) c . p . of 15 balls = s . p . of 20 balls = rs . 720 . c . p . of 1 ball = rs . 720 / 15 = rs . 48 . answer : option a" | gain |
math_qa__bPPahzchWrjckhSn | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.54000 after completion of one year. What will be Jose's share of profit? Choose the correct choice: A) 20000 B) 24000 C) 34000 D) 35000 E) 30000 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">30_000 * 12</gadget>
<output>360_000</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">45_000 * 10</gadget>
<output>450_000</output>
<gadget id="calculator">450_000 + 360_000</gadget>
<output>810_000</output>
<gadget id="calculator">360_000 / 810_000</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">1 - (4/9)</gadget>
<output>5/9 = around 0.555556</output>
<gadget id="calculator">54_000 * (5/9)</gadget>
<output>30_000</output>
<result>E</result> | E | 30,000 | Tom opened a shop investing Rs.30000. Jose joined him 2 months later, investing Rs.45000. They earned a profit of Rs.54000 after completion of one year. What will be Jose's share of profit? | {
"A": "20000",
"B": "24000",
"C": "34000",
"D": "35000",
"E": "30000"
} | multiply(54000, subtract(const_1, divide(multiply(30000, multiply(const_2, multiply(const_2, const_3))), add(multiply(45000, subtract(multiply(const_2, multiply(const_2, const_3)), 2)), multiply(30000, multiply(const_2, multiply(const_2, const_3))))))) | multiply(const_2,const_3)|multiply(#0,const_2)|multiply(n0,#1)|subtract(#1,n1)|multiply(n2,#3)|add(#4,#2)|divide(#2,#5)|subtract(const_1,#6)|multiply(n3,#7) | sol = ~ s - so anju ’ s share = [ 5 / 9 ] x 54000 = 30000 e | gain |
math_qa__OCXsdlSkC7uaIODP | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000? Choose the correct choice from the following choices.
A) 81000 B) 22887 C) 26877 D) 26771 E) 17121 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 64_000</gadget>
<output>8_000</output>
<gadget id="calculator">64_000 + 8_000</gadget>
<output>72_000</output>
<gadget id="calculator">(1/8) * 72_000</gadget>
<output>9_000</output>
<gadget id="calculator">72_000 + 9_000</gadget>
<output>81_000</output>
<result>A</result> | A | 81,000 | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000? | {
"A": "81000",
"B": "22887",
"C": "26877",
"D": "26771",
"E": "17121"
} | add(add(64000, multiply(divide(1, 8), 64000)), multiply(divide(1, 8), add(64000, multiply(divide(1, 8), 64000)))) | divide(n0,n1)|multiply(n2,#0)|add(n2,#1)|multiply(#2,#0)|add(#2,#3) | 64000 * 9 / 8 * 9 / 8 = 81000 answer : a | general |
math_qa__mfGW7HX2sAN9wbop | Victor gets 95 % marks in examinations. If these are 285 marks, find the maximum marks. Choices: A) 334 B) 500 C) 376 D) 288 E) 300 | <gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">285 / (19/20)</gadget>
<output>300</output>
<result>E</result> | E | 300 | Victor gets 95 % marks in examinations. If these are 285 marks, find the maximum marks. | {
"A": "334",
"B": "500",
"C": "376",
"D": "288",
"E": "300"
} | divide(285, divide(95, const_100)) | divide(n0,const_100)|divide(n1,#0) | let the maximum marks be m then 95 % of m = 285 ⇒ 95 / 100 × m = 285 ⇒ m = ( 285 × 100 ) / 95 ⇒ m = 28500 / 95 ⇒ m = 300 therefore , maximum marks in the examinations are 300 . answer : e | gain |
math_qa__3qZQhY1Etrbrfzql | Last month, John rejected 0.5% of the products that he inspected and Jane rejected 0.9 percent of the products that she inspected. If total of 0.75 percent of the products produced last month were rejected, what fraction of the products did Jane inspect? Answers:
A) 1 / 6
B) 1 / 2
C) 5 / 8
D) 5 / 6
E) 15 / 16 | <gadget id="calculator">0.75 - 0.5</gadget>
<output>0.25</output>
<gadget id="calculator">0.9 - 0.5</gadget>
<output>0.4</output>
<gadget id="calculator">0.25 / 0.4</gadget>
<output>0.625</output>
<result>C</result> | C | 0.625 | Last month, John rejected 0.5% of the products that he inspected and Jane rejected 0.9 percent of the products that she inspected. If total of 0.75 percent of the products produced last month were rejected, what fraction of the products did Jane inspect? | {
"A": "1 / 6",
"B": "1 / 2",
"C": "5 / 8",
"D": "5 / 6",
"E": "15 / 16"
} | divide(subtract(0.75, 0.5), subtract(0.9, 0.5)) | subtract(n2,n0)|subtract(n1,n0)|divide(#0,#1)| | "x - fraction of products jane inspected ( 1 - x ) - fraction of products john inspected 0.9 ( x ) + 0.5 ( 1 - x ) = 0.75 0.4 x = 0.75 - 0.5 x = 0.25 / 0.4 x = 5 / 8 therefore the answer is c : 5 / 8 ." | gain |
math_qa__oB8cC0vl1diDOJBc | Find the circumference and area of radius 7 cm. Choose the correct choice from the following answers
A) 151 cm ²
B) 152 cm ²
C) 154 cm ²
D) 155 cm ²
E) 157 cm ² | <gadget id="calculator">pi * (7 ** 2)</gadget>
<output>49*pi = around 153.93804</output>
<result>C</result> | C | 154 | Find the circumference and area of radius 7 cm. | {
"A": "151 cm ²",
"B": "152 cm ²",
"C": "154 cm ²",
"D": "155 cm ²",
"E": "157 cm ²"
} | circle_area(7) | circle_area(n0)| | "circumference of circle = 2 π r = 2 × 22 / 7 × 7 = 44 cm area of circle = π r ² = 22 / 7 × 7 × 7 cm ² = 154 cm ² answer : c" | geometry |
math_qa__KU6M56RMWDyrAgEA | A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $375 and $150 per unit, respectively. What is the fewest number of computer printers that the company can purchase? Choose the most appropriate option:
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">lcm(375, 150)</gadget>
<output>750</output>
<gadget id="calculator">750 / 375</gadget>
<output>2</output>
<gadget id="calculator">750 / 150</gadget>
<output>5</output>
<gadget id="calculator">2 + 5</gadget>
<output>7</output>
<result>E</result> | E | 7 | A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $375 and $150 per unit, respectively. What is the fewest number of computer printers that the company can purchase? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | add(divide(lcm(375, 150), 375), divide(lcm(375, 150), 150)) | lcm(n0,n1)|divide(#0,n0)|divide(#0,n1)|add(#1,#2) | the smallest amount that the company can spend is the lcm of 375 and 150 , which is 750 for each , which is total 1500 . the number of 1 st type of computers which costing $ 375 = 750 / 375 = 2 . the number of 2 nd type of computers which costing $ 150 = 750 / 150 = 5 . total = 2 + 5 = 7 answer is e . | general |
math_qa__siJvFNYCceEe4Qoa | A grocer is storing soap boxes in cartons that measure 30 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton? Select.
A) 360 B) 252 C) 280 D) 300 E) 420 | <gadget id="calculator">30 * 42</gadget>
<output>1_260</output>
<gadget id="calculator">1_260 * 60</gadget>
<output>75_600</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 * 5</gadget>
<output>210</output>
<gadget id="calculator">75_600 / 210</gadget>
<output>360</output>
<result>A</result> | A | 360 | A grocer is storing soap boxes in cartons that measure 30 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 6 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton? | {
"A": "360",
"B": "252",
"C": "280",
"D": "300",
"E": "420"
} | divide(multiply(multiply(30, 42), 60), multiply(multiply(7, 6), 5)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|multiply(n5,#1)|divide(#2,#3)| | "however the process of dividing the volume of box by the volume of a soap seems flawed but it does work in this case due to the numbers dimensions of the box = 30 * 42 * 60 dimensions of the soap = 5 * 6 * 7 we get = 6 x 6 x 10 = 360 so the question is why this particular arrangement , in order to maximize number of soaps we need to minimize the space wasted and this is the only config where we dont waste any space so we can expect the maximum number the answer is ( a )" | general |
math_qa__wMr6IkzVntOGCvjo | If (A-B-C+D = 13) and (A+B-C-D = 5), what is the value of (B-D)^2? Choose the correct choice from the following answers
A) 4 . B) 8 . C) 12 . D) 16 E) 64 | <gadget id="calculator">13 + 5</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">5 - 9</gadget>
<output>-4</output>
<gadget id="calculator">(-4) ** 2</gadget>
<output>16</output>
<result>D</result> | D | 16 | If (A-B-C+D = 13) and (A+B-C-D = 5), what is the value of (B-D)^2? | {
"A": "4 .",
"B": "8 .",
"C": "12 .",
"D": "16",
"E": "64"
} | power(subtract(5, divide(add(13, 5), const_2)), const_2) | add(n0,n1)|divide(#0,const_2)|subtract(n1,#1)|power(#2,const_2) | a - b - c + d = 13 - - equation 1 a + b - c - d = 5 - - equation 2 adding 1 and 2 , we get 2 a - 2 c = 18 = > a - c = 9 - - equation 3 using equation 3 in 2 , we get b - d = 5 - 9 = - 4 = > ( b - d ) ^ 2 = 16 answer d | general |
math_qa__UJ0oFFpDBu6Omp8b | A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3 , then the weight of the pipe is
Choose the correct choice from the following
A) 3.6 kg B) 3.696 kg C) 36 kg D) 36.9 kg E) none of these | <gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">pi * (4 ** 2) * 21</gadget>
<output>336*pi = around 1_055.575132</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">pi * (3 ** 2) * 21</gadget>
<output>189*pi = around 593.761012</output>
<gadget id="calculator">(336*pi) - (189*pi)</gadget>
<output>147*pi = around 461.81412</output>
<gadget id="calculator">(147*pi) * 8</gadget>
<output>1176*pi = around 3_694.512961</output>
<gadget id="calculator">(1176*pi) / 1_000</gadget>
<output>147*pi/125 = around 3.694513</output>
<result>B</result> | B | 3.696 | A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3 , then the weight of the pipe is | {
"A": "3.6 kg",
"B": "3.696 kg",
"C": "36 kg",
"D": "36.9 kg",
"E": "none of these"
} | divide(multiply(subtract(volume_cylinder(divide(8, const_2), 21), volume_cylinder(subtract(divide(8, const_2), 1), 21)), 8), const_1000) | divide(n1,const_2)|subtract(#0,n2)|volume_cylinder(#0,n0)|volume_cylinder(#1,n0)|subtract(#2,#3)|multiply(n1,#4)|divide(#5,const_1000)| | "explanation : external radius = 4 cm , internal radius = 3 cm . volume of iron = [ ( 22 / 7 ) × ( 42 - 32 ) × 21 ] cm 3 = 462 cm 3 weight of iron = ( 462 x 8 ) gm = 3696 gm = 3.696 kg answer : b" | physics |
math_qa__yqzdDFBOHxdlAY0R | Find the value of 3 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)] Choose the correct choice from the following choices
A) 800 B) 500 C) 900 D) 1600 E) 2400 | <gadget id="calculator">3.6 * 0.48</gadget>
<output>1.728</output>
<gadget id="calculator">1.728 * 2.5</gadget>
<output>4.32</output>
<gadget id="calculator">0.12 * 0.09</gadget>
<output>0.0108</output>
<gadget id="calculator">0.0108 * 0.5</gadget>
<output>0.0054</output>
<gadget id="calculator">4.32 / 0.0054</gadget>
<output>800</output>
<gadget id="calculator">800 * 3</gadget>
<output>2_400</output>
<result>E</result> | E | 2,400 | Find the value of 3 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)] | {
"A": "800",
"B": "500",
"C": "900",
"D": "1600",
"E": "2400"
} | multiply(divide(multiply(multiply(3.6, 0.48), 2.50), multiply(multiply(0.12, 0.09), 0.5)), 3) | multiply(n1,n2)|multiply(n4,n5)|multiply(n3,#0)|multiply(n6,#1)|divide(#2,#3)|multiply(n0,#4)| | "answer 3 x [ ( 3.6 x 0.48 x 2.50 ) / ( 0.12 x 0.09 x 0.5 ) ] = 3 x [ ( 36 x 48 x 250 ) / ( 12 x 9 x 5 ) ] = 3 x 4 x 4 x 50 = 2400 correct option : e" | general |
math_qa__aUnYSapQGZWULxPw | Sara bought both German chocolate and Swiss chocolate for some cakes she was baking. The Swiss chocolate cost $3.5 per pound, and German chocolate cost $2.8 per pound. if the total the she spent on chocolate was $28 and both types of chocolate were purchased in whole number of pounds, how many total pounds of chocolate she purchased? Select the correct option:
A) 9 B) 8 C) 10 D) 12 E) 15 | <gadget id="calculator">3.5 + 2.8</gadget>
<output>6.3</output>
<gadget id="calculator">6.3 / 2</gadget>
<output>3.15</output>
<gadget id="calculator">28 / 3.15</gadget>
<output>8.888889</output>
<result>A</result> | A | 9 | Sara bought both German chocolate and Swiss chocolate for some cakes she was baking. The Swiss chocolate cost $3.5 per pound, and German chocolate cost $2.8 per pound. if the total the she spent on chocolate was $28 and both types of chocolate were purchased in whole number of pounds, how many total pounds of chocolate she purchased? | {
"A": "9",
"B": "8",
"C": "10",
"D": "12",
"E": "15"
} | divide(28, divide(add(3.5, 2.8), const_2)) | add(n0,n1)|divide(#0,const_2)|divide(n2,#1)| | "if there were all the expensive ones , 3.5 . . . . there would be 28 / 3.5 or 8 of them but since 2.8 $ ones are also there , answer has to be > 8 . . if all were 2.8 $ ones , there will be 28 / 2.8 or 10 . . . so only 9 is left answer a . ." | other |
math_qa__OuqwA0zW5C6NiLl2 | The length of the bridge, which a train 110 metres long and travelling at 45 km/hr can cross in 30 seconds, is? Choose the correct choice from the following answers.
A) 10 m
B) 16 m
C) 245 m
D) 265 m
E) 27 m | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 110</gadget>
<output>265</output>
<result>D</result> | D | 265 | The length of the bridge, which a train 110 metres long and travelling at 45 km/hr can cross in 30 seconds, is? | {
"A": "10 m",
"B": "16 m",
"C": "245 m",
"D": "265 m",
"E": "27 m"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 110) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "speed = [ 45 x 5 / 18 ] m / sec = [ 25 / 2 ] m / sec time = 30 sec let the length of bridge be x metres . then , ( 130 + x ) / 30 = 25 / 2 = > 2 ( 110 + x ) = 750 = > x = 265 m . answer : d" | physics |
math_qa__qrRuaA5YWiyO8zgE | If 16 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days? Select:
A) 127
B) 225
C) 287
D) 450
E) 281 | <gadget id="calculator">36 * 30</gadget>
<output>1_080</output>
<gadget id="calculator">16 * 24</gadget>
<output>384</output>
<gadget id="calculator">384 / 80</gadget>
<output>24/5 = around 4.8</output>
<gadget id="calculator">1_080 / (24/5)</gadget>
<output>225</output>
<result>B</result> | B | 225 | If 16 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days? | {
"A": "127",
"B": "225",
"C": "287",
"D": "450",
"E": "281"
} | divide(multiply(36, 30), divide(multiply(16, 24), 80)) | multiply(n3,n4)|multiply(n0,n2)|divide(#1,n1)|divide(#0,#2)| | "explanation : let the required no of hectares be x . then men - - - hectares - - - days 16 - - - - - - - - - 80 - - - - - - - - - 24 36 - - - - - - - - - x - - - - - - - - - 30 more men , more hectares ( direct proportion ) more days , more hectares ( direct proportion ) x = 36 / 16 * 30 / 24 * 80 x = 225 answer : b" | physics |
math_qa__NDd6nytknAJRnRMI | a shop sells 1 chocolate at the rate rupee 1 each . you can exchange 3 warppers for one chocolate . if you have rs . 15 , what is the maximum number of chocolates you can get ? Choose the correct choice from the following choices
A) 21 B) 22 C) 23 D) 24 E) 25 | <gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">7 + 15</gadget>
<output>22</output>
<result>B</result> | B | 22 | a shop sells 1 chocolate at the rate rupee 1 each . you can exchange 3 warppers for one chocolate . if you have rs . 15 , what is the maximum number of chocolates you can get ? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | add(add(add(divide(15, 3), 1), 1), 15) | divide(n3,n2)|add(n0,#0)|add(n0,#1)|add(n3,#2) | rs . 15 = 15 chocolates 15 wrappers = 5 chocolates 5 wrappers = 1 chocolate ( u have 2 wrappers with you . . ) count this wrapper with already existing wrappers = 15 + 5 + 1 + 1 = 22 chocolates . . answer : b | gain |
math_qa__YW1z2wKUlLRveeEr | jim is now twice as old as fred , who is 9 years older than sam . 6 years ago , jim was 5 times as old as sam . how old is jim now ? Choose the correct option:
A) 42
B) 46
C) 50
D) 54
E) 58 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 - 6</gadget>
<output>24</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">24 + 18</gadget>
<output>42</output>
<gadget id="calculator">9 - 6</gadget>
<output>3</output>
<gadget id="calculator">42 / 3</gadget>
<output>14</output>
<gadget id="calculator">14 + 9</gadget>
<output>23</output>
<gadget id="calculator">23 * 2</gadget>
<output>46</output>
<result>B</result> | B | 46 | jim is now twice as old as fred , who is 9 years older than sam . 6 years ago , jim was 5 times as old as sam . how old is jim now ? | {
"A": "42",
"B": "46",
"C": "50",
"D": "54",
"E": "58"
} | multiply(add(divide(add(subtract(multiply(6, 5), 6), multiply(9, const_2)), subtract(9, 6)), 9), const_2) | multiply(n0,const_2)|multiply(n1,n2)|subtract(n0,n1)|subtract(#1,n1)|add(#0,#3)|divide(#4,#2)|add(n0,#5)|multiply(#6,const_2) | j = 2 f = 2 ( s + 9 ) = 2 s + 18 j - 6 = 5 * ( s - 6 ) ( 2 s + 18 ) - 6 = 5 s - 30 s = 14 and so j = 46 the answer is b . | general |
math_qa__1lkTnCJLsi896Qiy | A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.204 less than the sum lent. What was the sum lent?
Pick one
A) 228 B) 278 C) 300 D) 500 E) 821 | <gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">1 - (8/25)</gadget>
<output>17/25 = around 0.68</output>
<gadget id="calculator">204 / (17/25)</gadget>
<output>300</output>
<result>C</result> | C | 300 | A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.204 less than the sum lent. What was the sum lent? | {
"A": "228",
"B": "278",
"C": "300",
"D": "500",
"E": "821"
} | divide(204, subtract(const_1, divide(multiply(4, 8), const_100))) | multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2) | p - 204 = ( p * 4 * 8 ) / 100 p = 300 answer : c | gain |
math_qa__wCHgV3dTx6yhwf1d | The credit card and a global payment processing companies have been suffering losses for some time now. A well known company recently announced its quarterly results. According to the results, the revenue fell to $42.0 billion from $69.0 billion, a year ago. By what percent did the revenue fall? Choose the correct choice from the following answers: A) 20.8 B) 30.4 C) 31.8 D) 39.1 E) 33.8 | <gadget id="calculator">69 - 42</gadget>
<output>27</output>
<gadget id="calculator">27 / 69</gadget>
<output>9/23 = around 0.391304</output>
<gadget id="calculator">(9/23) * 100</gadget>
<output>900/23 = around 39.130435</output>
<result>D</result> | D | 39.1 | The credit card and a global payment processing companies have been suffering losses for some time now. A well known company recently announced its quarterly results. According to the results, the revenue fell to $42.0 billion from $69.0 billion, a year ago. By what percent did the revenue fall? | {
"A": "20.8",
"B": "30.4",
"C": "31.8",
"D": "39.1",
"E": "33.8"
} | multiply(divide(subtract(69.0, 42.0), 69.0), const_100) | subtract(n1,n0)|divide(#0,n1)|multiply(#1,const_100)| | "$ 69 - $ 42 = 27 $ ( 27 / 69 ) * 100 = 39.13 % answer : d" | gain |
math_qa__L71myrU3MfR0pDi4 | The price of a bushel of corn is currently $3.20, and the price of a peck of wheat is $10.80. The price of corn is increasing at a constant rate of 5x cents per day while the price of wheat is decreasing at a constant rate of x(2^1/2) - x cents per day. What is the approximate price when a bushel of corn costs the same amount as a peck of wheat? Choose the correct choice from the following: A) $ 4.50 B) $ 10.2 C) $ 5.30 D) $ 5.50 E) $ 5.60 | <gadget id="calculator">10.8 - 3.2</gadget>
<output>7.6</output>
<gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">(sqrt(2)) - 1</gadget>
<output>-1 + sqrt(2) = around 0.414214</output>
<gadget id="calculator">5 + (-1 + sqrt(2))</gadget>
<output>sqrt(2) + 4 = around 5.414214</output>
<gadget id="calculator">7.6 / (sqrt(2) + 4)</gadget>
<output>7.6/(sqrt(2) + 4) = around 1.403713</output>
<gadget id="calculator">(7.6/(sqrt(2) + 4)) * 5</gadget>
<output>38.0/(sqrt(2) + 4) = around 7.018563</output>
<gadget id="calculator">3.2 + (38.0/(sqrt(2) + 4))</gadget>
<output>3.2 + 38.0/(sqrt(2) + 4) = around 10.218563</output>
<result>B</result> | B | 10.2 | The price of a bushel of corn is currently $3.20, and the price of a peck of wheat is $10.80. The price of corn is increasing at a constant rate of 5x cents per day while the price of wheat is decreasing at a constant rate of x(2^1/2) - x cents per day. What is the approximate price when a bushel of corn costs the same amount as a peck of wheat? | {
"A": "$ 4.50",
"B": "$ 10.2",
"C": "$ 5.30",
"D": "$ 5.50",
"E": "$ 5.60"
} | add(3.2, multiply(divide(subtract(10.8, 3.2), add(5, subtract(sqrt(const_2), 1))), 5)) | sqrt(const_2)|subtract(n1,n0)|subtract(#0,n4)|add(n2,#2)|divide(#1,#3)|multiply(n2,#4)|add(n0,#5) | i tried using time / rate approach : - initial price difference = 10.80 - 3.20 = 7.60 price of corn increasing by 5 x price of wheat decreasing by x ( 1.4 ) - x = . 4 x since both the quantities are moving towards reducing the price gap hence : - relative increase = 5 x + . 4 x let t be the time by which gap is filled so , 7.6 = t ( 5.4 x ) - > t = ( 7.6 ) / 5.4 x final price = 3.20 + 5 x * t - > 3.20 + 5 * 7.6 / 5.4 = 10.2 answer b . | general |
math_qa__GC1YGab5HBT1pigA | How many positive integers E between 200 and 300 (both inclusive) are not divisible by 2, 3 or 5? Choose the correct choice
A) 3
B) 16
C) 75
D) 24
E) 26 | <gadget id="calculator">300 - 200</gadget>
<output>100</output>
<gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 + 1</gadget>
<output>51</output>
<gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) + 1</gadget>
<output>103/3 = around 34.333333</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 + 2</gadget>
<output>17</output>
<gadget id="calculator">(103/3) - 17</gadget>
<output>52/3 = around 17.333333</output>
<gadget id="calculator">floor(52/3)</gadget>
<output>17</output>
<gadget id="calculator">17 + 1</gadget>
<output>18</output>
<gadget id="calculator">51 + 18</gadget>
<output>69</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">21 - 15</gadget>
<output>6</output>
<gadget id="calculator">69 + 6</gadget>
<output>75</output>
<gadget id="calculator">101 - 75</gadget>
<output>26</output>
<result>E</result> | E | 26 | How many positive integers E between 200 and 300 (both inclusive) are not divisible by 2, 3 or 5? | {
"A": "3",
"B": "16",
"C": "75",
"D": "24",
"E": "26"
} | subtract(add(subtract(300, 200), const_1), add(add(add(divide(subtract(300, 200), 2), const_1), add(floor(subtract(add(divide(subtract(300, 200), 3), const_1), add(multiply(5, 3), 2))), const_1)), subtract(add(divide(subtract(300, 200), 5), const_1), multiply(5, 3)))) | multiply(n3,n4)|subtract(n1,n0)|add(#1,const_1)|add(n2,#0)|divide(#1,n2)|divide(#1,n3)|divide(#1,n4)|add(#4,const_1)|add(#5,const_1)|add(#6,const_1)|subtract(#8,#3)|subtract(#9,#0)|floor(#10)|add(#12,const_1)|add(#7,#13)|add(#14,#11)|subtract(#2,#15) | 1 ) i figured there are 101 integers ( 300 - 200 + 1 = 101 ) . since the set begins with an even and ends with an even , there are 51 evens . 2 ) question says integers are not divisible by 2 , leaving all of the odds ( 101 - 51 = 50 integers ) . 3 ) question says integers are not divisible by 5 , removing all the integers ending in 5 ( already took out those ending in 0 ) . take out 10 integers ( 2 ? 5 , ? = 0 to 9 ) , leaving us with 40 integers . 4 ) now the painstaking part . we have to remove the remaining numbers that are multiples of 3 . those are 201 , 207 , 213 , 219 , 231 , 237 , 243 , 249 , 261 , 267 , 273 , 279 , 291 , and 297 . . . a total of 14 numbers . 26 numbers left ! 6 ) answer choice e . | other |
math_qa__d43MASDagKF0iR2e | The HCF of two numbers is 23 and the other two factors of their LCM are 13 and 14. What is the largest number?
Choose the correct answer.
A) 280
B) 284
C) 292
D) 320
E) 322 | <gadget id="calculator">23 * 14</gadget>
<output>322</output>
<result>E</result> | E | 322 | The HCF of two numbers is 23 and the other two factors of their LCM are 13 and 14. What is the largest number? | {
"A": "280",
"B": "284",
"C": "292",
"D": "320",
"E": "322"
} | multiply(23, 14) | multiply(n0,n2) | hcf of the two numbers = 23 since hcf will be always a factor of lcm , 23 is a factor of the lcm . given that other two factors in the lcm are 13 and 14 . hence factors of the lcm are 23 , 13 , 14 so , numbers can be taken as ( 23 × 13 ) and ( 23 × 14 ) = 299 and 322 hence , largest number = 322 e ) | other |
math_qa__yQlxbEVIBvodxRqF | In a throw of dice what is the probability of geƫng number greater than 2
Choose the correct choice from the following options: A) 1 / 2 B) 2 / 3 C) 1 / 5 D) 1 / 6 E) none of these | <gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<result>B</result> | B | 0.666667 | In a throw of dice what is the probability of geƫng number greater than 2 | {
"A": "1 / 2",
"B": "2 / 3",
"C": "1 / 5",
"D": "1 / 6",
"E": "none of these"
} | divide(subtract(const_6, 2), const_6) | subtract(const_6,n0)|divide(#0,const_6) | explanation : number greater than 2 is 3 , 4 , 5 & 6 , so only 4 number total cases of dice = [ 1,2 , 3,4 , 5,6 ] so probability = 4 / 6 = 2 / 3 answer : b | probability |
math_qa__CZM0OnkL6W0XIq6B | A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 50 percent greater than the wholesale price. If the retailer decreases the retail price by 30 percent this will have the same effect as increasing the wholesale price by what percent? Choose the most appropriate option.
A) 15
B) 20
C) 10
D) 5
E) 8 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(3/2) * (7/10)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) - 1</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<result>D</result> | D | 5 | A retailer purchases shirts from a wholesaler and then sells the shirts in her store at a retail price that is 50 percent greater than the wholesale price. If the retailer decreases the retail price by 30 percent this will have the same effect as increasing the wholesale price by what percent? | {
"A": "15",
"B": "20",
"C": "10",
"D": "5",
"E": "8"
} | multiply(subtract(multiply(add(const_1, divide(50, const_100)), subtract(const_1, divide(30, const_100))), const_1), const_100) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100) | answer : d = 5 . assume rs . 100 to be the price at which the retailer buys from wholesaler . 50 % increase makes retail price = 150 . now 30 % decrease - > ( 1 - 30 / 100 ) * 150 = 105 . now compared to the wholesale price of 100 , 5 % increase is what will have the same effect as increasing the wholesale price . | gain |
math_qa__OY3VYhsI3xgkbyvj | On dividing 172 by a number, the quotient is 10 and the remainder is 2. Find the divisor. Answers.
A) 9 B) 11 C) 13 D) 15 E) 17 | <gadget id="calculator">172 / 10</gadget>
<output>86/5 = around 17.2</output>
<gadget id="calculator">floor(86/5)</gadget>
<output>17</output>
<result>E</result> | E | 17 | On dividing 172 by a number, the quotient is 10 and the remainder is 2. Find the divisor. | {
"A": "9",
"B": "11",
"C": "13",
"D": "15",
"E": "17"
} | floor(divide(172, 10)) | divide(n0,n1)|floor(#0)| | "d = ( d - r ) / q = ( 172 - 2 ) / 10 = 170 / 10 = 17 e" | general |
math_qa__Ap2BlkJNAf51pNUP | In what time a sum of money double itself at 4% per annum simple interest?
Pick one: A) 25 % B) 33 1 / 3 % C) 83 1 / 3 % D) 33 4 / 3 % E) 73 1 / 3 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">10_000 / 400</gadget>
<output>25</output>
<result>A</result> | A | 25 | In what time a sum of money double itself at 4% per annum simple interest? | {
"A": "25 %",
"B": "33 1 / 3 %",
"C": "83 1 / 3 %",
"D": "33 4 / 3 %",
"E": "73 1 / 3 %"
} | divide(multiply(const_100, const_100), multiply(4, const_100)) | multiply(const_100,const_100)|multiply(n0,const_100)|divide(#0,#1)| | "p = ( p * 4 * r ) / 100 r = 25 % answer : a" | gain |
math_qa__Om019estrkzKun5e | A big container is 35% full with water. If 48 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters? Choose the correct answer:
A) 80
B) 90
C) 100
D) 110
E) 120 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(3/4) - (7/20)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">48 / (2/5)</gadget>
<output>120</output>
<result>E</result> | E | 120 | A big container is 35% full with water. If 48 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters? | {
"A": "80",
"B": "90",
"C": "100",
"D": "110",
"E": "120"
} | divide(48, subtract(divide(3, 4), divide(35, const_100))) | divide(n2,n3)|divide(n0,const_100)|subtract(#0,#1)|divide(n1,#2)| | "48 liters is 40 % of the capacity c . 48 = 0.4 c c = 48 / 0.4 = 120 liters . the answer is e ." | general |
math_qa__mNFU8cg4VwJ3L1aW | In a box, there are 8 orange, 7 black and 6 white balls. If one ball is picked up randomly. What is the probability that it is neither orange nor white? Pick.
A) 2 / 3 B) 3 / 4 C) 7 / 19 D) 8 / 21 E) 10 / 21 | <gadget id="calculator">8 + 7</gadget>
<output>15</output>
<gadget id="calculator">15 + 6</gadget>
<output>21</output>
<gadget id="calculator">8 / 21</gadget>
<output>8/21 = around 0.380952</output>
<result>D</result> | D | 0.380952 | In a box, there are 8 orange, 7 black and 6 white balls. If one ball is picked up randomly. What is the probability that it is neither orange nor white? | {
"A": "2 / 3",
"B": "3 / 4",
"C": "7 / 19",
"D": "8 / 21",
"E": "10 / 21"
} | divide(8, add(add(8, 7), 6)) | add(n0,n1)|add(n2,#0)|divide(n0,#1) | total balls are 21 and neither black nor white . so favor case will be only 8 c 1 and total case 21 c 1 probability will be 8 c 1 / 21 c 1 = 8 / 21 answer : d | general |
math_qa__T8DKyH9ON9YXoLt9 | Suraj has a certain average of runs for 12 innings. In the 13th innings he scores 96 runs thereby increasing his average by 5 runs. What is his average after the 13th innings? Choose the correct choice from the following answers.
A) 48 B) 64 C) 36 D) 72 E) 27 | <gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">96 - 60</gadget>
<output>36</output>
<gadget id="calculator">13 - 12</gadget>
<output>1</output>
<gadget id="calculator">36 / 1</gadget>
<output>36</output>
<result>C</result> | C | 36 | Suraj has a certain average of runs for 12 innings. In the 13th innings he scores 96 runs thereby increasing his average by 5 runs. What is his average after the 13th innings? | {
"A": "48",
"B": "64",
"C": "36",
"D": "72",
"E": "27"
} | divide(subtract(96, multiply(12, 5)), subtract(13, 12)) | multiply(n0,n3)|subtract(n1,n0)|subtract(n2,#0)|divide(#2,#1)| | "to improve his average by 5 runs per innings he has to contribute 12 x 5 = 60 runs for the previous 12 innings . thus , the average after the 13 th innings = 96 - 60 = 36 . answer : c" | general |
math_qa__brhRg7mZc6K0n9Zz | Total number of boys and girls in a school is 150. If the number of boys is x, then girls become x% of the total number of students. The number of boys is Choose the correct option:
A) 50 B) 60 C) 70 D) 80 E) 90 | <gadget id="calculator">150 * 100</gadget>
<output>15_000</output>
<gadget id="calculator">150 + 100</gadget>
<output>250</output>
<gadget id="calculator">15_000 / 250</gadget>
<output>60</output>
<result>B</result> | B | 60 | Total number of boys and girls in a school is 150. If the number of boys is x, then girls become x% of the total number of students. The number of boys is | {
"A": "50",
"B": "60",
"C": "70",
"D": "80",
"E": "90"
} | divide(multiply(150, const_100), add(150, const_100)) | add(n0,const_100)|multiply(n0,const_100)|divide(#1,#0) | explanation : clearly , x % of 150 = 150 - x [ as x is number of boys ] = > x + x / 100 ∗ 150 = 150 = > 5 / 2 x = 150 = > x = 60 option b | general |
math_qa__gmd93GoQugm3tBcG | $20000 will become $60000 at 20% P.A. find the time? Choose the correct choice from the following choices
A) 2 years
B) 5 years
C) 7 years
D) 8 years
E) 10 years | <gadget id="calculator">60_000 - 20_000</gadget>
<output>40_000</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">20_000 * (1/5)</gadget>
<output>4_000</output>
<gadget id="calculator">40_000 / 4_000</gadget>
<output>10</output>
<result>E</result> | E | 10 | $20000 will become $60000 at 20% P.A. find the time? | {
"A": "2 years",
"B": "5 years",
"C": "7 years",
"D": "8 years",
"E": "10 years"
} | divide(subtract(60000, 20000), multiply(20000, divide(20, const_100))) | divide(n2,const_100)|subtract(n1,n0)|multiply(n0,#0)|divide(#1,#2)| | "si = simple interest = a - p = 60000 - 20000 = $ 40000 r = 100 si / pt = 100 * 40000 / 20000 * 20 = 10 years answer is e" | gain |
math_qa__fzi0CaT5tTXXz797 | A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 6:2. The ratio of economy cars to sport utility vehicles is 5:3. What is the ratio of luxury cars to sport utility vehicles? Choose the correct choice from the following options
A) 9 : 8 B) 8 : 9 C) 6 : 2 D) 2 : 3 E) 1 : 2 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">12 / 9</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">12 / 8</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(4/3) / (3/2)</gadget>
<output>8/9 = around 0.888889</output>
<result>B</result> | B | 0.888889 | A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 6:2. The ratio of economy cars to sport utility vehicles is 5:3. What is the ratio of luxury cars to sport utility vehicles? | {
"A": "9 : 8",
"B": "8 : 9",
"C": "6 : 2",
"D": "2 : 3",
"E": "1 : 2"
} | divide(divide(multiply(const_4, 3), multiply(3, 3)), divide(multiply(3, const_4), multiply(2, const_4))) | multiply(n3,const_4)|multiply(n3,n3)|multiply(n1,const_4)|divide(#0,#1)|divide(#0,#2)|divide(#3,#4) | the ratio of economy to luxury cars is 6 : 2 - - > e : l = 6 : 2 = 30 : 10 . the ratio of economy cars to sport utility vehicles is 5 : 3 - - > e : s = 5 : 3 = 30 : 18 . thus , l : s = 10 : 18 = 5 : 6 . answer : b . | other |
math_qa__sl03oiaiXliHMBWg | The average (arithmetic mean) of 20, 40, and 60 is 5 more than the average of 10, 80, and what number?
Choose the correct choice from the following answers:
A) 35
B) 30
C) 25
D) 20
E) 15 | <gadget id="calculator">20 + 40</gadget>
<output>60</output>
<gadget id="calculator">60 + 60</gadget>
<output>120</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 80</gadget>
<output>105</output>
<gadget id="calculator">120 - 105</gadget>
<output>15</output>
<result>E</result> | E | 15 | The average (arithmetic mean) of 20, 40, and 60 is 5 more than the average of 10, 80, and what number? | {
"A": "35",
"B": "30",
"C": "25",
"D": "20",
"E": "15"
} | subtract(add(add(20, 40), 60), add(add(multiply(5, const_3), 10), 80)) | add(n0,n1)|multiply(n3,const_3)|add(n2,#0)|add(n4,#1)|add(n5,#3)|subtract(#2,#4) | a 1 = 120 / 3 = 40 a 2 = a 1 - 5 = 35 sum of second list = 35 * 3 = 105 therefore the number = 105 - 90 = 15 e | general |
math_qa__PJnGvP2jUheo1f8M | If a = 105 and a^3= 21 * 49 * 45 * b, what is the value of b? Choices:
A) 25 B) 42 C) 45 D) 49 E) 54 | <gadget id="calculator">105 ** 3</gadget>
<output>1_157_625</output>
<gadget id="calculator">21 * 49</gadget>
<output>1_029</output>
<gadget id="calculator">1_029 * 45</gadget>
<output>46_305</output>
<gadget id="calculator">1_157_625 / 46_305</gadget>
<output>25</output>
<result>A</result> | A | 25 | If a = 105 and a^3= 21 * 49 * 45 * b, what is the value of b? | {
"A": "25",
"B": "42",
"C": "45",
"D": "49",
"E": "54"
} | divide(power(105, 3), multiply(multiply(21, 49), 45)) | multiply(n2,n3)|power(n0,n1)|multiply(n4,#0)|divide(#1,#2)| | "first step will be to break down all the numbers into their prime factors . 105 = 3 * 5 * 7 21 = 7 * 3 49 = 7 * 7 45 = 3 * 3 * 5 so , ( 105 ) ^ 3 = 3 * 7 * 7 * 7 * 3 * 3 * 5 * b therefore ( 3 * 5 * 7 ) ^ 3 = 3 ^ 3 * 5 * 7 ^ 3 * b therefore , b = 3 ^ 3 * 5 ^ 3 * 7 ^ 3 / 3 ^ 3 * 5 * 7 ^ 3 b = 5 ^ 2 = 25 correct answer a ." | general |
math_qa__SRqb8jwIlNJtznLm | James took a 3-hour bike ride. In the second hour he traveled 30 miles, which was 20 percent farther than he traveled the first hour. If he traveled 25 percent farther in the third hour than he did in the second hour, how many miles did jose travel during the entire ride? Pick one:
A) 54.0
B) 54.9
C) 92.5
D) 57.0
E) 63.0 | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 30</gadget>
<output>24</output>
<gadget id="calculator">24 + 30</gadget>
<output>54</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 30</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">54 + (75/2)</gadget>
<output>183/2 = around 91.5</output>
<result>C</result> | C | 92.5 | James took a 3-hour bike ride. In the second hour he traveled 30 miles, which was 20 percent farther than he traveled the first hour. If he traveled 25 percent farther in the third hour than he did in the second hour, how many miles did jose travel during the entire ride? | {
"A": "54.0",
"B": "54.9",
"C": "92.5",
"D": "57.0",
"E": "63.0"
} | add(add(multiply(divide(subtract(const_100, 20), const_100), 30), 30), multiply(divide(add(const_100, 25), const_100), 30)) | add(n3,const_100)|subtract(const_100,n2)|divide(#1,const_100)|divide(#0,const_100)|multiply(n1,#2)|multiply(n1,#3)|add(n1,#4)|add(#6,#5) | let the distance travelled in the first hour be x . thus , 1.2 x = 30 , x = 25 . now , the distance travelled in the 3 rd hour = 30 + 1 / 4 â ˆ — 30 = 37.5 the only option ending with a 0.5 in the decimal place is c . answer : c | physics |
math_qa__w6i48SALw6XmtOIS | A number x is multiplied by 5, and this product is then divided by 3. If the positive square root of the result of these two operations equals x, what is the value of x if x≠0 ?
Choose the correct choice from the following answers:
A) 25 / 9 B) 9 / 5 C) 5 / 3 D) 3 / 5 E) 9 / 25 | <gadget id="calculator">5 / 3</gadget>
<output>5/3 = around 1.666667</output>
<result>C</result> | C | 1.666667 | A number x is multiplied by 5, and this product is then divided by 3. If the positive square root of the result of these two operations equals x, what is the value of x if x≠0 ? | {
"A": "25 / 9",
"B": "9 / 5",
"C": "5 / 3",
"D": "3 / 5",
"E": "9 / 25"
} | divide(5, 3) | divide(n0,n1)| | "sqrt ( 5 x / 3 ) to be perfect square x has to 5 / 3 ans : c" | general |
math_qa__W09fiOkr9j6kFpxx | What amount does an investor receive if the investor invests $4000 at 10% p.a. compound interest for two years, compounding done annually?
Choices:
A) $ 4720 B) $ 4840 C) $ 4920 D) $ 5080 E) $ 5160 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">4_000 * (121/100)</gadget>
<output>4_840</output>
<result>B</result> | B | 4,840 | What amount does an investor receive if the investor invests $4000 at 10% p.a. compound interest for two years, compounding done annually? | {
"A": "$ 4720",
"B": "$ 4840",
"C": "$ 4920",
"D": "$ 5080",
"E": "$ 5160"
} | multiply(4000, power(add(const_1, divide(10, const_100)), const_2)) | divide(n1,const_100)|add(#0,const_1)|power(#1,const_2)|multiply(n0,#2)| | "a = ( 1 + r / 100 ) ^ n * p ( 1.1 ) ^ 2 * 5000 = 1.21 * 5000 = 4840 the answer is b ." | gain |
math_qa__mLtgA7Zupp0br48Q | The school soccer team looks at their record and finds that they win, lose, and tie games in a ratio of 4:3:1. How many games did they play if they lost 9 games? Choose the correct choice.
A) 3 B) 9 C) 12 D) 18 E) 24 | <gadget id="calculator">9 / 3</gadget>
<output>3</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">3 * 8</gadget>
<output>24</output>
<result>E</result> | E | 24 | The school soccer team looks at their record and finds that they win, lose, and tie games in a ratio of 4:3:1. How many games did they play if they lost 9 games? | {
"A": "3",
"B": "9",
"C": "12",
"D": "18",
"E": "24"
} | multiply(divide(9, 3), add(add(4, 3), 1)) | add(n0,n1)|divide(n3,n1)|add(n2,#0)|multiply(#2,#1) | the ratio is 4 wins : 3 losses : 1 tie . think of ratio as ` ` parts . ' ' divide 9 ( total losses ) by 3 ( ratio losses ) to find 1 ` ` part ' ' of the ratio . 9 / 3 = 3 this means the team tied 3 games . multiply 3 ( 1 ` ` part ' ' of ratio ) by 4 ( ratio wins ) to find total wins . 3 * 4 = 12 . this mean the team won 12 games . add up wins , losses , and ties . 12 + 9 + 3 = 24 the answer is e | other |
math_qa__U1GCsl7hMZS5GTbb | If 9 gallons of gasoline are added to a tank that is already filled to 3/4 of its capacity, the tank is then filled to 9/10 of its capacity. How many gallons does the tank hold? Choices.
A) 20 B) 24 C) 36 D) 40 E) 54 | <gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(9/10) - (3/4)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">9 / (3/20)</gadget>
<output>60</output>
<gadget id="calculator">60 * (3/4)</gadget>
<output>45</output>
<gadget id="calculator">45 + 9</gadget>
<output>54</output>
<result>E</result> | E | 54 | If 9 gallons of gasoline are added to a tank that is already filled to 3/4 of its capacity, the tank is then filled to 9/10 of its capacity. How many gallons does the tank hold? | {
"A": "20",
"B": "24",
"C": "36",
"D": "40",
"E": "54"
} | add(multiply(divide(9, subtract(divide(9, 10), divide(3, 4))), divide(3, 4)), 9) | divide(n3,n4)|divide(n1,n2)|subtract(#0,#1)|divide(n0,#2)|multiply(#3,#1)|add(n0,#4)| | "let the capacity of the tank = c ( 3 / 4 ) c + 9 = ( 9 / 10 ) c = > ( 9 / 10 ) c - ( 3 / 4 ) c = 9 = > ( 3 / 20 ) c = 9 = > c = ( 9 * 20 ) / 3 = 60 number of gallons of gasoline that the tank currently holds = 3 / 4 * c + 9 = 45 + 9 = 54 answer e" | general |
math_qa__OqxFGweReKTEgqNA | What is the remainder when 121212.......(300) digits is divided by 99.
Choose the correct choice from the following choices: A) 18 B) 36 C) 72 D) 0 E) 1 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">99 / 11</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<result>A</result> | A | 18 | What is the remainder when 121212.......(300) digits is divided by 99. | {
"A": "18",
"B": "36",
"C": "72",
"D": "0",
"E": "1"
} | multiply(divide(99, add(const_10, const_1)), const_2) | add(const_1,const_10)|divide(n2,#0)|multiply(#1,const_2) | 12 / 99 = 12 1212 / 99 = 24 121212 / 99 = 36 . . . 121212 . . . ( 300 ) / 99 = ( 12 * 300 ) % 99 = 36 if they say 300 digits then ( 12 * 150 ) % 99 = 18 answer : a | general |
math_qa__NPSOj6fEcTIgOqUy | Walking 9/8 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school?
Answers
A) 22 B) 99 C) 27 D) 36 E) 20 | <gadget id="calculator">4 * 9</gadget>
<output>36</output>
<result>D</result> | D | 36 | Walking 9/8 of his usual rate, a boy reaches his school 4 min early. Find his usual time to reach the school? | {
"A": "22",
"B": "99",
"C": "27",
"D": "36",
"E": "20"
} | multiply(4, 9) | multiply(n0,n2)| | "speed ratio = 1 : 9 / 8 = 8 : 9 time ratio = 9 : 8 1 - - - - - - - - 9 4 - - - - - - - - - ? 36 m . answer : d" | gain |
math_qa__cbjb1zqHoOWOSvNh | A batsman scored 1 runs in his 18th innings and that makes his average 18. Find his average upto
the 17th innings? Choose the correct answer:
A) 19 B) 20 C) 21 D) 22 E) 23 | <gadget id="calculator">18 * 18</gadget>
<output>324</output>
<gadget id="calculator">324 - 1</gadget>
<output>323</output>
<gadget id="calculator">323 / 17</gadget>
<output>19</output>
<result>A</result> | A | 19 | A batsman scored 1 runs in his 18th innings and that makes his average 18. Find his average upto
the 17th innings? | {
"A": "19",
"B": "20",
"C": "21",
"D": "22",
"E": "23"
} | divide(subtract(multiply(18, 18), 1), 17) | multiply(n1,n1)|subtract(#0,n0)|divide(#1,n3) | avg = sum of the value / no . of the value 18 = ( sum of the first 17 innings score + 1 ) / 18 ( 18 * 18 - 1 ) = sum of the first 17 innings score sum of the first 17 innings score = 323 ave upto 17 innings = 323 / 17 = 19 answer : a | general |
math_qa__qbFoVmsRsaS53Sy6 | If Jack walked 9 miles in 1 hour and 15 minutes, what was his rate of walking in miles per hour?
Pick.
A) 4
B) 4.5
C) 6
D) 6.25
E) 7.2 | <gadget id="calculator">9 * 60</gadget>
<output>540</output>
<gadget id="calculator">15 + 60</gadget>
<output>75</output>
<gadget id="calculator">540 / 75</gadget>
<output>36/5 = around 7.2</output>
<result>E</result> | E | 7.2 | If Jack walked 9 miles in 1 hour and 15 minutes, what was his rate of walking in miles per hour? | {
"A": "4",
"B": "4.5",
"C": "6",
"D": "6.25",
"E": "7.2"
} | divide(multiply(9, const_60), add(15, const_60)) | add(n2,const_60)|multiply(n0,const_60)|divide(#1,#0)| | "distance walked in 1 hour and 15 mins = 9 miles speed per hour = distance / time = 9 / ( 5 / 4 ) = 7.2 miles per hour answer e" | physics |
math_qa__GzsLVktX9GTF6x0T | A student chose a number, multiplied it by 2, then subtracted 148 from the result and got 110. What was the number he chose? Choose the correct choice from the following:
A) 90 B) 129 C) 120 D) 160 E) 200 | <gadget id="calculator">110 + 148</gadget>
<output>258</output>
<gadget id="calculator">258 / 2</gadget>
<output>129</output>
<result>B</result> | B | 129 | A student chose a number, multiplied it by 2, then subtracted 148 from the result and got 110. What was the number he chose? | {
"A": "90",
"B": "129",
"C": "120",
"D": "160",
"E": "200"
} | divide(add(110, 148), 2) | add(n1,n2)|divide(#0,n0)| | "solution : let x be the number he chose , then 2 * x * 148 = 110 2 x = 258 x = 129 correct answer b" | general |
math_qa__j5VEMVBzdR0oGQuS | A crate measures 3 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? Pick.
A) 27 B) 3 C) 6 D) 8 E) 12 | <gadget id="calculator">8 * 12</gadget>
<output>96</output>
<gadget id="calculator">96 * 3</gadget>
<output>288</output>
<gadget id="calculator">288 / 12</gadget>
<output>24</output>
<gadget id="calculator">24 / 8</gadget>
<output>3</output>
<result>B</result> | B | 3 | A crate measures 3 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? | {
"A": "27",
"B": "3",
"C": "6",
"D": "8",
"E": "12"
} | divide(divide(multiply(multiply(8, 12), 3), 12), 8) | multiply(n1,n2)|multiply(n0,#0)|divide(#1,n2)|divide(#2,n1)| | "we can find the radius of all the three cases of cylinders . the only crux to find the answer faster is that : voulme is pi * r ^ 2 * h . the volume is a function of r ^ 2 . so r has to be the highest to find the largest volume . so r = 3 for the surface 8 * 12 face . volume = 27 pi answer b" | geometry |
math_qa__ta6cfUOfUBoBzqF8 | A train 225 m long running at 90 kmph crosses a platform in 25 sec. What is the length of the platform? Choose the correct choice from the following choices.
A) 271 B) 266 C) 400 D) 277 E) 232 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">90 * (5/18)</gadget>
<output>25</output>
<gadget id="calculator">25 * 25</gadget>
<output>625</output>
<gadget id="calculator">625 - 225</gadget>
<output>400</output>
<result>C</result> | C | 400 | A train 225 m long running at 90 kmph crosses a platform in 25 sec. What is the length of the platform? | {
"A": "271",
"B": "266",
"C": "400",
"D": "277",
"E": "232"
} | subtract(multiply(25, multiply(90, const_0_2778)), 225) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)| | "length of the platform = 90 * 5 / 18 * 25 = 625 – 225 = 400 answer : c" | physics |
math_qa__Y4Lt1kjmsxXpcniK | In an election only two candidates contested 20% of the voters did not vote and 120 votes were declared as invalid. The winner got 200 votes more than his opponent thus he secured 41% votes of the total voters on the voter list. Percentage votes of the defeated candidate out of the total votes casted is: Pick.
A) 22
B) 389
C) 38
D) 45
E) 01 | <gadget id="calculator">10 + 20</gadget>
<output>30</output>
<gadget id="calculator">41 / 100</gadget>
<output>41/100 = around 0.41</output>
<gadget id="calculator">(41/100) * 1_000</gadget>
<output>410</output>
<gadget id="calculator">30 + 410</gadget>
<output>440</output>
<gadget id="calculator">440 + 1_000</gadget>
<output>1_440</output>
<gadget id="calculator">200 + 120</gadget>
<output>320</output>
<gadget id="calculator">320 * 10</gadget>
<output>3_200</output>
<gadget id="calculator">1_440 / 3_200</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) * 100</gadget>
<output>45</output>
<result>D</result> | D | 45 | In an election only two candidates contested 20% of the voters did not vote and 120 votes were declared as invalid. The winner got 200 votes more than his opponent thus he secured 41% votes of the total voters on the voter list. Percentage votes of the defeated candidate out of the total votes casted is: | {
"A": "22",
"B": "389",
"C": "38",
"D": "45",
"E": "01"
} | multiply(divide(add(add(add(const_10, 20), multiply(divide(41, const_100), const_1000)), const_1000), multiply(add(200, 120), const_10)), const_100) | add(n0,const_10)|add(n1,n2)|divide(n3,const_100)|multiply(#2,const_1000)|multiply(#1,const_10)|add(#0,#3)|add(#5,const_1000)|divide(#6,#4)|multiply(#7,const_100) | let there be x voters and k votes goes to loser then 0.8 x - 120 = k + ( k + 200 ) k + 200 = 0.41 x \ inline \ rightarrow k = 1440 and ( k + 200 ) = 1640 therefore \ inline \ frac { 1440 } { 3200 } \ times 100 = 45 % answer : d ) 45 % | general |
math_qa__cAkuNI94T0qeCEnK | A 600 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? Choose one: A) 800 B) 700 C) 360 D) 370 E) 380 | <gadget id="calculator">600 / 18</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 39</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 - 600</gadget>
<output>700</output>
<result>B</result> | B | 700 | A 600 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "800",
"B": "700",
"C": "360",
"D": "370",
"E": "380"
} | subtract(multiply(speed(600, 18), 39), 600) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 600 / 18 = 100 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 100 / 3 = > x = 1300 m . l = 1300 - 600 = 700 m answer : option b" | physics |
math_qa__soioxJDyzkuMOSRG | Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many R kilometers per hour did Tammy walk on the second day? Choices.
A) 3 B) 3.5 C) 4 D) 4.5 E) 6 | <gadget id="calculator">14 + 2</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">52 - 3</gadget>
<output>49</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">49 / 14</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(7/2) + (1/2)</gadget>
<output>4</output>
<result>C</result> | C | 4 | Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day, she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many R kilometers per hour did Tammy walk on the second day? | {
"A": "3",
"B": "3.5",
"C": "4",
"D": "4.5",
"E": "6"
} | add(divide(subtract(52, divide(subtract(divide(add(14, 2), 2), 2), 2)), add(subtract(divide(add(14, 2), 2), 2), divide(add(14, 2), 2))), divide(const_1, 2)) | add(n0,n1)|divide(const_1,n1)|divide(#0,n1)|subtract(#2,n1)|add(#2,#3)|divide(#3,n1)|subtract(n2,#5)|divide(#6,#4)|add(#7,#1)| | "ans : c total time = 14 hrs let time traveled during 1 st day = x let time traveled during 2 nd day = x - 2 total time = 14 x + x - 2 = 14 x = 8 speed * time = distance s * 8 + ( s + 0.5 ) ( 8 - 2 ) = 52 solving s = 4.5 now speed for 2 nd day is 0.5 less than the 1 st day which is 4.5 thus speed for 2 nd day = 4 its simple algebra for s * 8 + ( s + 0.5 ) ( 8 - 2 ) = 52 but for some reason im getting 3.5 and not 4.5 . 8 s + 6 s + 3 = 52 14 s = 49 s = 3.5" | physics |
math_qa__abFxDEvig6wIbhzd | howmany 3 digit numbers are there tens digit place is more than hundreds digit place and units place less than hundreds digit place? Choose the correct choice from the following choices.
A) 80 B) 100 C) 110 D) 120 E) 140 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 4</gadget>
<output>120</output>
<result>D</result> | D | 120 | howmany 3 digit numbers are there tens digit place is more than hundreds digit place and units place less than hundreds digit place? | {
"A": "80",
"B": "100",
"C": "110",
"D": "120",
"E": "140"
} | multiply(multiply(3, const_10), const_4) | multiply(n0,const_10)|multiply(#0,const_4) | we have numbers { 01 , 23 , 45 , 67 , 89 } now we would decide the cases on behalf of value of hundred place digit . and accordingly choose unit ' s digit and ten ' s digit . value of hundred place digit must be choosen in such a manner that there should exist a greater digit for ten ' s place and a smaller digit for unit place . thus we can have values of hundred ' s digit from 12 , 34 , 56 , 78 only now starting from hundred ' s digit = 8 : hundred ' s digit possible values for ten ' s digit possible values for unit digit total ways 8 9 01 , 23 , 45 , 67 1 * 1 * 8 = 8 7 89 0 , 12 , 34 , 56 1 * 2 * 7 = 14 6 7 , 89 01 , 23 , 45 1 * 3 * 6 = 18 5 67 , 89 0 , 12 , 34 1 * 4 * 5 = 20 4 5 , 67 , 89 01 , 23 1 * 5 * 4 = 20 3 45 , 67 , 89 0 . 1.2 1 * 6 * 3 = 18 2 3 , 45 , 67 , 89 01 1 * 7 * 2 = 14 1 23 , 45 , 67 , 89 0 1 * 8 * 1 = 8 so , total no of cases = 8 + 14 + 18 + 20 + 20 + 18 + 14 + 8 = 120 hence total no of possible 3 digit numbers = 120 answer : d | general |
math_qa__myQNKmHuiZMIJlNc | What is the total surface area in square meters of a rectangular solid whose length is 6 meters, width is 5 meters, and depth is 2 meters? Choose the correct choice from the following answers:
A) 100 m 2 B) 104 m 2 C) 106 m 2 D) 108 m 2 E) 160 m 2 | <gadget id="calculator">2 * (5 * 6 + 6 * 2 + 5 * 2)</gadget>
<output>104</output>
<result>B</result> | B | 104 | What is the total surface area in square meters of a rectangular solid whose length is 6 meters, width is 5 meters, and depth is 2 meters? | {
"A": "100 m 2",
"B": "104 m 2",
"C": "106 m 2",
"D": "108 m 2",
"E": "160 m 2"
} | surface_rectangular_prism(5, 6, 2) | surface_rectangular_prism(n0,n1,n2) | surface area of a cuboid = 2 ( lb + bh + lh ) = 2 ( 6 * 5 + 5 * 2 + 6 * 2 ) = 2 ( 30 + 10 + 12 ) = 2 * 52 = 104 m 2 answer : b | geometry |
math_qa__W9kT9pnd8pvIEt3r | Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs. Choose the correct choice from the following answers:
A) 70 B) 76 C) 78 D) 80 E) 88 | <gadget id="calculator">32 + 4</gadget>
<output>36</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">36 * 11</gadget>
<output>396</output>
<gadget id="calculator">10 * 32</gadget>
<output>320</output>
<gadget id="calculator">396 - 320</gadget>
<output>76</output>
<result>B</result> | B | 76 | Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs. | {
"A": "70",
"B": "76",
"C": "78",
"D": "80",
"E": "88"
} | subtract(multiply(add(32, 4), add(10, const_1)), multiply(10, 32)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : average after 11 innings should be 36 so , required score = ( 11 * 36 ) - ( 10 * 32 ) = 396 - 320 = 76 answer : option b" | general |
math_qa__w5aFGLXGIKRnhF7j | A particular library has 300 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 244 books in the special collection at that time, how many books of the special collection were loaned out during that month? Choose the correct option.
A) 120
B) 140
C) 160
D) 180
E) 200 | <gadget id="calculator">300 - 244</gadget>
<output>56</output>
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">1 - (13/20)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">56 / (7/20)</gadget>
<output>160</output>
<result>C</result> | C | 160 | A particular library has 300 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 244 books in the special collection at that time, how many books of the special collection were loaned out during that month? | {
"A": "120",
"B": "140",
"C": "160",
"D": "180",
"E": "200"
} | divide(subtract(300, 244), subtract(const_1, divide(65, const_100))) | divide(n1,const_100)|subtract(n0,n2)|subtract(const_1,#0)|divide(#1,#2)| | "the total number of books is 300 . let x be the number of books which were loaned out . 65 % of books that were loaned out are returned . 35 % of books that were loaned out are not returned . now , there are 244 books , thus the number of un - returned books is 300 - 244 = 56 books . 0.35 x = 56 x = 160 the answer is c ." | gain |
math_qa__UzUM786hiC1BUCvT | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 58 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? Choices.
A) 57 B) 2 ^ 4 * 3 C) 24 D) 38 E) 47 | <gadget id="calculator">58 - 1</gadget>
<output>57</output>
<result>A</result> | A | 57 | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 58 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? | {
"A": "57",
"B": "2 ^ 4 * 3",
"C": "24",
"D": "38",
"E": "47"
} | subtract(58, const_1) | subtract(n0,const_1)| | "so 57 days answer a = 57" | physics |
math_qa__ous6LBmRj4imfals | What is the value of n if the sum of the consecutive odd intergers E from 1 to n equals 169? Choices: A) 47 B) 25 C) 37 D) 33 E) 29 | <gadget id="calculator">169 ** (1/2)</gadget>
<output>13</output>
<gadget id="calculator">13 * 2</gadget>
<output>26</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<result>B</result> | B | 25 | What is the value of n if the sum of the consecutive odd intergers E from 1 to n equals 169? | {
"A": "47",
"B": "25",
"C": "37",
"D": "33",
"E": "29"
} | add(subtract(multiply(sqrt(169), const_2), multiply(const_2, 1)), 1) | multiply(n0,const_2)|sqrt(n1)|multiply(#1,const_2)|subtract(#2,#0)|add(n0,#3)| | "before you tackle this question you must first understand that the question is comprised of two key parts , 1 st is finding out how manytermsis in that sequence and 2 nd whatactual number valuethat term is . in an arithmetic progression , in this case consecutive odd integers 1 , 3 , 5 , . . . . , there are two set of rules . rule # 1 ( arithmetic sequence ) : xn = a + d ( n - 1 ) identifies what the actual # in the sequence would be . each number in the sequence has a term such as 1 ( is the first term ) , 3 ( is the second term ) and so on . so if i were to ask you to find out what the 10 th term is of that sequence you would use that formula to find that value . a = 1 ( first term ) d = 2 ( the common difference ) remember in the sequence 1 , 3 , 5 , 7 the common difference is always 2 * on a side note we use n - 1 because we do n ' t have d in the first term , therefore if we were solving for the first term we would get 0 as n - 1 and 0 times d would give us 0 , leaving only the first term . this works regardless what your first term is in any sequence . but remember the question askswhat is thevalueof n if the sum of the consecutive odd integers from 1 to n equals 169 ? which means we first need a consecutive sequence that sums up to 169 and than find what the value of the n is , in this case it would be the last number in that sequence . in order to find that we first need to knowhow many terms ( how many of the n there is ) in order to be able to plug n in this formula given we know what the sum is . for that to happen we need to use rule # 2 . rule # 2 ( summing an arithmetic series ) : 169 = n / 2 ( 2 a + ( n - 1 ) d ) . given the question gives us what the sum is ( 169 in this case ) we would simply use this formula to solve for n . once we solve for n ( 13 in this case ) we can simply plug n into the first formula ( rule 1 ) and find the value . it feels very confusing and difficult at first , but once you identify the steps all you need to do is plug and play . we have the sum ( 169 ) of a sequence , the number of terms in that sequence is ( unknown ) . rule # 2 tells us how many numbers there are in that sequence and rule # 1 gives us what that last term is ." | general |
math_qa__Q0B2ByPyOcLFJGUH | The average of first thirteen prime numbers which are odd is? Options: A) 20.15 B) 21.15 C) 22.15 D) 23.15 E) 24.15 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">8 + 7</gadget>
<output>15</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">15 + 11</gadget>
<output>26</output>
<gadget id="calculator">11 + 2</gadget>
<output>13</output>
<gadget id="calculator">26 + 13</gadget>
<output>39</output>
<gadget id="calculator">13 + 4</gadget>
<output>17</output>
<gadget id="calculator">39 + 17</gadget>
<output>56</output>
<gadget id="calculator">17 + 2</gadget>
<output>19</output>
<gadget id="calculator">56 + 19</gadget>
<output>75</output>
<gadget id="calculator">19 + 4</gadget>
<output>23</output>
<gadget id="calculator">75 + 23</gadget>
<output>98</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">23 + 6</gadget>
<output>29</output>
<gadget id="calculator">98 + 29</gadget>
<output>127</output>
<gadget id="calculator">29 + 2</gadget>
<output>31</output>
<gadget id="calculator">127 + 31</gadget>
<output>158</output>
<gadget id="calculator">31 + 6</gadget>
<output>37</output>
<gadget id="calculator">158 + 37</gadget>
<output>195</output>
<gadget id="calculator">37 + 4</gadget>
<output>41</output>
<gadget id="calculator">195 + 41</gadget>
<output>236</output>
<gadget id="calculator">41 + 2</gadget>
<output>43</output>
<gadget id="calculator">236 + 43</gadget>
<output>279</output>
<gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">279 / 13</gadget>
<output>279/13 = around 21.461538</output>
<result>B</result> | B | 21.15 | The average of first thirteen prime numbers which are odd is? | {
"A": "20.15",
"B": "21.15",
"C": "22.15",
"D": "23.15",
"E": "24.15"
} | divide(add(add(add(add(add(add(add(add(add(add(add(add(const_3, add(const_4, const_1)), add(add(const_4, const_1), const_2)), add(add(add(const_4, const_1), const_2), const_4)), add(add(add(add(const_4, const_1), const_2), const_4), const_2)), add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4)), add(add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4), const_2)), add(add(add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4), const_2), const_4)), add(add(add(add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4), const_2), const_4), multiply(const_3, const_2))), add(add(add(add(add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4), const_2), const_4), multiply(const_3, const_2)), const_2)), add(add(add(add(add(add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4), const_2), const_4), multiply(const_3, const_2)), const_2), multiply(const_3, const_2))), add(add(add(add(add(add(add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4), const_2), const_4), multiply(const_3, const_2)), const_2), multiply(const_3, const_2)), const_4)), add(add(add(add(add(add(add(add(add(add(add(add(const_4, const_1), const_2), const_4), const_2), const_4), const_2), const_4), multiply(const_3, const_2)), const_2), multiply(const_3, const_2)), const_4), const_2)), add(const_10, const_3)) | add(const_1,const_4)|add(const_10,const_3)|multiply(const_2,const_3)|add(#0,const_3)|add(#0,const_2)|add(#3,#4)|add(#4,const_4)|add(#5,#6)|add(#6,const_2)|add(#7,#8)|add(#8,const_4)|add(#9,#10)|add(#10,const_2)|add(#11,#12)|add(#12,const_4)|add(#13,#14)|add(#14,#2)|add(#15,#16)|add(#16,const_2)|add(#17,#18)|add(#18,#2)|add(#19,#20)|add(#20,const_4)|add(#21,#22)|add(#22,const_2)|add(#23,#24)|divide(#25,#1) | explanation : sum of first 13 prime no . which are odd = 275 average = 275 / 13 = 21.15 answer : b | general |
math_qa__Na8g6RzDqD4y5qfK | Population is 24000. Population increases by 10% every year, then the population after 3 years is? Pick one.
A) 26630 B) 26640 C) 36644 D) 31944 E) 26844 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">24_000 * (13/10)</gadget>
<output>31_200</output>
<result>D</result> | D | 31,944 | Population is 24000. Population increases by 10% every year, then the population after 3 years is? | {
"A": "26630",
"B": "26640",
"C": "36644",
"D": "31944",
"E": "26844"
} | multiply(24000, add(const_1, divide(multiply(3, 10), const_100))) | multiply(n1,n2)|divide(#0,const_100)|add(#1,const_1)|multiply(n0,#2)| | "population after 1 st year = 24000 * 10 / 100 = 2400 = = = > 24000 + 2400 = 26400 population after 2 nd year = 26400 * 10 / 100 = 2640 = = = > 26400 + 2640 = 29040 population after 3 rd year = 29040 * 10 / 100 = 2904 = = = > 29040 + 2904 = 31944 answer : d" | gain |
math_qa__rhN9VlwrtGzrnD3B | A man purchased 3 blankets @ Rs.100 each, 2 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? Choose the correct choice from the following answers.
A) 278 B) 900 C) 278 D) 450 E) 772 | <gadget id="calculator">10 * 150</gadget>
<output>1_500</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">2 * 150</gadget>
<output>300</output>
<gadget id="calculator">300 + 300</gadget>
<output>600</output>
<gadget id="calculator">1_500 - 600</gadget>
<output>900</output>
<result>B</result> | B | 900 | A man purchased 3 blankets @ Rs.100 each, 2 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? | {
"A": "278",
"B": "900",
"C": "278",
"D": "450",
"E": "772"
} | subtract(multiply(const_10, 150), add(multiply(3, 100), multiply(2, 150))) | multiply(n3,const_10)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(#0,#3)| | "10 * 150 = 1500 3 * 100 + 2 * 150 = 600 1500 – 600 = 900 answer : b" | general |
math_qa__VbKXTBUk6D3Gvnbc | Find the least number which when divided by 34 and 5 leaves a remainder of 4 in each case. Choose the correct option: A) 170 B) 172 C) 174 D) 176 E) 178 | <gadget id="calculator">lcm(34, 5)</gadget>
<output>170</output>
<gadget id="calculator">4 + 170</gadget>
<output>174</output>
<result>C</result> | C | 174 | Find the least number which when divided by 34 and 5 leaves a remainder of 4 in each case. | {
"A": "170",
"B": "172",
"C": "174",
"D": "176",
"E": "178"
} | add(4, lcm(34, 5)) | lcm(n0,n1)|add(n2,#0)| | "the least number which when divided by different divisors leaving the same remainder in each case = lcm ( different divisors ) + remainder left in each case . hence the required least number = lcm ( 31 , 5 ) + 4 = 174 . answer : c" | general |
math_qa__AC1RA1NWKwwzIE7U | Two trains 120 m and 150 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? Choose the correct choice from the following options:
A) 10.9 sec
B) 14.8 sec
C) 10.6 sec
D) 10.8 sec
E) 9.27 sec | <gadget id="calculator">120 + 150</gadget>
<output>270</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">270 / (250/9)</gadget>
<output>243/25 = around 9.72</output>
<result>E</result> | E | 9.27 | Two trains 120 m and 150 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.9 sec",
"B": "14.8 sec",
"C": "10.6 sec",
"D": "10.8 sec",
"E": "9.27 sec"
} | divide(add(120, 150), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 120 + 150 = 270 m . required time = 270 * 9 / 250 = 9.27 = 9.27 sec . answer : e" | physics |
math_qa__go3nK7hRn2CQRzSP | 18 beavers, working together in a constant pace, can build a dam in 12 hours. How many hours will it take 12 beavers that work at the same pace, to build the same dam? Choose the correct choice:
A) 2 .
B) 4 .
C) 5 .
D) 6
E) 18 . | <gadget id="calculator">12 * 18</gadget>
<output>216</output>
<gadget id="calculator">216 / 12</gadget>
<output>18</output>
<result>E</result> | E | 18 | 18 beavers, working together in a constant pace, can build a dam in 12 hours. How many hours will it take 12 beavers that work at the same pace, to build the same dam? | {
"A": "2 .",
"B": "4 .",
"C": "5 .",
"D": "6",
"E": "18 ."
} | divide(multiply(12, 18), 12) | multiply(n0,n1)|divide(#0,n2)| | "total work = 18 * 12 = 216 beaver hours 12 beaver * x = 216 beaver hours x = 216 / 12 = 18 answer : e" | physics |
math_qa__umamqwQqjzabYLV7 | A batsman makes a score of 87 runs in the 17th inning and thus increases his avg by 3. Find his average after 17th inning.
Choices.
A) 12 B) 39 C) 43 D) 52 E) 34 | <gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">87 - 51</gadget>
<output>36</output>
<gadget id="calculator">36 + 3</gadget>
<output>39</output>
<result>B</result> | B | 39 | A batsman makes a score of 87 runs in the 17th inning and thus increases his avg by 3. Find his average after 17th inning. | {
"A": "12",
"B": "39",
"C": "43",
"D": "52",
"E": "34"
} | add(subtract(87, multiply(17, 3)), 3) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "let the average after 17 th inning = x . then , average after 16 th inning = ( x - 3 ) . : . 16 ( x - 3 ) + 87 = 17 x or x = ( 87 - 48 ) = 39 . ans : b" | general |
math_qa__Ezd4DZONnGlpdt1U | A company produces 120000 bottles of water everyday. If a case can hold 12 bottles of water .How many cases are required by the company to hold its one day production Choose the correct option:
A) 2000 B) 4500 C) 5000 D) 8000 E) 10000 | <gadget id="calculator">120_000 / 12</gadget>
<output>10_000</output>
<result>E</result> | E | 10,000 | A company produces 120000 bottles of water everyday. If a case can hold 12 bottles of water .How many cases are required by the company to hold its one day production | {
"A": "2000",
"B": "4500",
"C": "5000",
"D": "8000",
"E": "10000"
} | divide(120000, 12) | divide(n0,n1) | number of bottles that can be held in a case = 12 number of cases required to hold 120000 bottles = 120000 / 12 = 10000 cases . so the answer is e = 10000 | physics |
math_qa__aH3y0tFNeG3ymWN4 | At a garage sale, all of the items were sold at different prices. If the price of a radio sold at the garage sale was both the 15th highest price and the 22nd lowest price among the prices of the items sold, how many items were sold at the garage sale? Select the correct option: A) 34 B) 35 C) 36 D) 37 E) 38 | <gadget id="calculator">22 + 15</gadget>
<output>37</output>
<gadget id="calculator">37 - 1</gadget>
<output>36</output>
<result>C</result> | C | 36 | At a garage sale, all of the items were sold at different prices. If the price of a radio sold at the garage sale was both the 15th highest price and the 22nd lowest price among the prices of the items sold, how many items were sold at the garage sale? | {
"A": "34",
"B": "35",
"C": "36",
"D": "37",
"E": "38"
} | subtract(add(22, 15), const_1) | add(n0,n1)|subtract(#0,const_1)| | "there were 14 items sold at a higher price than the radio and 21 items sold at a lower price than the radio . including the radio , there were 14 + 21 + 1 = 36 items sold . the answer is c ." | other |
math_qa__OwJNaU0FfcMMyQQ3 | The cash difference between the selling prices of an book at a profit of 4% and 6% is $3. The ratio of the two selling prices is:
Answers: A) 50 : 53 B) 58 : 53 C) 52 : 53 D) 42 : 36 E) 38 : 53 | <gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 + 6</gadget>
<output>106</output>
<gadget id="calculator">104 / 106</gadget>
<output>52/53 = around 0.981132</output>
<result>C</result> | C | 0.981132 | The cash difference between the selling prices of an book at a profit of 4% and 6% is $3. The ratio of the two selling prices is: | {
"A": "50 : 53",
"B": "58 : 53",
"C": "52 : 53",
"D": "42 : 36",
"E": "38 : 53"
} | divide(add(const_100, 4), add(const_100, 6)) | add(n0,const_100)|add(n1,const_100)|divide(#0,#1)| | "c 52 : 53 let c . p . of the book be $ x . then , required ratio = 104 % of x / 106 % of x = 104 / 106 = 52 / 53 = 52 : 53" | gain |
math_qa__ZFvkdNCNg2nYKrAq | In Town X, 120 percent of the population are employed, and 80 percent of the population are employed males. What percent of the employed people in Town X are females? Choose the correct choice from the following answers:
A) 16 % B) 25 % C) 33 % D) 40 % E) 52 % | <gadget id="calculator">120 - 80</gadget>
<output>40</output>
<gadget id="calculator">40 / 120</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>C</result> | C | 33 | In Town X, 120 percent of the population are employed, and 80 percent of the population are employed males. What percent of the employed people in Town X are females? | {
"A": "16 %",
"B": "25 %",
"C": "33 %",
"D": "40 %",
"E": "52 %"
} | multiply(divide(subtract(120, 80), 120), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "total employed people 12 % , out of which 80 are employed males , hence 40 % are employed females . ( employed females ) / ( total employed people ) = 40 / 120 = 1 / 3 = 33 % answer : c ." | gain |
math_qa__14pcNigHXSMBsPQh | If an average hard drive had a capacity of 0.1 TB in 2000, and average hard drive capacities double every 5 years, what will be the average hard drive capacity in 2050? Choose the correct answer:
A) 256
B) 512
C) 768
D) 1024
E) 1536 | <gadget id="calculator">0.1 * 2</gadget>
<output>0.2</output>
<gadget id="calculator">0.2 * 2</gadget>
<output>0.4</output>
<gadget id="calculator">0.4 * 2</gadget>
<output>0.8</output>
<gadget id="calculator">0.8 * 2</gadget>
<output>1.6</output>
<gadget id="calculator">1.6 * 2</gadget>
<output>3.2</output>
<gadget id="calculator">3.2 * 2</gadget>
<output>6.4</output>
<gadget id="calculator">6.4 * 2</gadget>
<output>12.8</output>
<gadget id="calculator">12.8 * 2</gadget>
<output>25.6</output>
<gadget id="calculator">25.6 * 2</gadget>
<output>51.2</output>
<gadget id="calculator">51.2 * 2</gadget>
<output>102.4</output>
<gadget id="calculator">102.4 + 0.1</gadget>
<output>102.5</output>
<gadget id="calculator">102.5 * 10</gadget>
<output>1_025</output>
<result>D</result> | D | 1,024 | If an average hard drive had a capacity of 0.1 TB in 2000, and average hard drive capacities double every 5 years, what will be the average hard drive capacity in 2050? | {
"A": "256",
"B": "512",
"C": "768",
"D": "1024",
"E": "1536"
} | multiply(add(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(0.1, const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), 0.1), const_10) | multiply(n0,const_2)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(#2,const_2)|multiply(#3,const_2)|multiply(#4,const_2)|multiply(#5,const_2)|multiply(#6,const_2)|multiply(#7,const_2)|multiply(#8,const_2)|add(n0,#9)|multiply(#10,const_10)| | "0.1 * 2 ^ 10 = 0.1 * 1024 = 102.4 the answer is d ." | general |
math_qa__u98IxI6jyJw4Dkid | (x + 3) is a factor in x^2 - mx - 15. What is the value of m? Choose the correct choice from the following options: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<result>B</result> | B | 2 | (x + 3) is a factor in x^2 - mx - 15. What is the value of m? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(divide(15, 3), 3) | divide(n2,n0)|subtract(#0,n0)| | "i solved the second degree equation and found it like this : x ^ 2 - mx - 15 = 0 ( x - 5 ) ( x + 3 ) = 0 x = 5 or x = - 3 substituting both values for x in the equation we find : x ^ 2 - mx - 15 = > ( - 3 ) ^ 2 - m ( - 3 ) = 15 = > 9 + 3 m = 15 = > 3 m = 15 - 9 = 6 = > m = 2 and with 5 , using a similar process we end up with : ( 5 ) ^ 2 - m ( 5 ) = 15 - 5 m = 15 - 25 = - 10 m = 2 ao , ans b" | general |
math_qa__KfYgmtzpC1SUs2dO | A small water pump would take 3 hours to fill an empty tank. A larger pump would take 1/4 hour to fill the same tank. How many hours would it take both pumps, working at their respective constant rates, to fill the empty tank if they began pumping at the same time? Choices:
A) 3 / 13 B) 1 / 5 C) 1 / 10 D) 1 / 3 E) 1 / 7 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + 4</gadget>
<output>13/3 = around 4.333333</output>
<gadget id="calculator">1 / (13/3)</gadget>
<output>3/13 = around 0.230769</output>
<result>A</result> | A | 0.230769 | A small water pump would take 3 hours to fill an empty tank. A larger pump would take 1/4 hour to fill the same tank. How many hours would it take both pumps, working at their respective constant rates, to fill the empty tank if they began pumping at the same time? | {
"A": "3 / 13",
"B": "1 / 5",
"C": "1 / 10",
"D": "1 / 3",
"E": "1 / 7"
} | inverse(add(inverse(3), 4)) | inverse(n0)|add(n2,#0)|inverse(#1) | rate of the small pump is 1 / 3 tank / hour rate of the larger pump is 1 / ( 1 / 4 ) or 4 tank / hour ; combined rate of the two pumps is 1 / 3 + 4 = 13 / 3 tank / hour , together they will fill the empty tank in 1 / ( 13 / 3 ) = 3 / 13 hours ( time = job / rate ) . answer : a | physics |
math_qa__kAPCfR95OgoS8ceY | By approximately what percent is x greater than 4/7 if (1/7)(x) = 1?
Choose the correct choice from the following answers:
A) 1125 % B) 956 % C) 417 % D) 3788 % E) 219 % | <gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">7 - (4/7)</gadget>
<output>45/7 = around 6.428571</output>
<gadget id="calculator">(45/7) / (4/7)</gadget>
<output>45/4 = around 11.25</output>
<gadget id="calculator">(45/4) * 100</gadget>
<output>1_125</output>
<result>A</result> | A | 1,125 | By approximately what percent is x greater than 4/7 if (1/7)(x) = 1? | {
"A": "1125 %",
"B": "956 %",
"C": "417 %",
"D": "3788 %",
"E": "219 %"
} | multiply(divide(subtract(7, divide(4, 7)), divide(4, 7)), const_100) | divide(n0,n1)|subtract(n1,#0)|divide(#1,#0)|multiply(#2,const_100) | what percent is x greater than 4 / 7 if ( 1 / 7 ) ( x ) = 1 ? = > x = 7 % change = [ ( 7 - 4 / 7 ) / ( 4 / 7 ) ] * 100 = ( 49 / 4 - 1 ) * 100 = 45 * 25 = 1125 % ans , a | general |
math_qa__iWgt1fz5WTmLvL0G | How many multiples of 5 are there between 10 and 89, 10 and 89 inclusive? Choose the correct choice from the following options: A) 17 B) 16 C) 18 D) 19 E) 20 | <gadget id="calculator">89 - 10</gadget>
<output>79</output>
<gadget id="calculator">79 / 5</gadget>
<output>79/5 = around 15.8</output>
<gadget id="calculator">(79/5) + 1</gadget>
<output>84/5 = around 16.8</output>
<result>B</result> | B | 16 | How many multiples of 5 are there between 10 and 89, 10 and 89 inclusive? | {
"A": "17",
"B": "16",
"C": "18",
"D": "19",
"E": "20"
} | add(divide(subtract(89, 10), 5), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "5 multiples are . . . 10,15 , 20,25 , 30,35 , 40,45 , 50,55 , 60,65 , 70,75 , 80,85 , . . . , . . . , the answer is = 16 answer is b" | general |
math_qa__wnaEXRKqJPHFhGDV | A worker can load one truck in 5 hours. A second worker can load the same truck in 8 hours. If both workers load one truck simultaneously while maintaining their constant rates, approximately how long, in hours, will it take them to fill one truck?
Choose the correct option:
A) 2.5
B) 2.7
C) 2.9
D) 3.1
E) 3.3 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/5) + (1/8)</gadget>
<output>13/40 = around 0.325</output>
<gadget id="calculator">1 / (13/40)</gadget>
<output>40/13 = around 3.076923</output>
<result>D</result> | D | 3.1 | A worker can load one truck in 5 hours. A second worker can load the same truck in 8 hours. If both workers load one truck simultaneously while maintaining their constant rates, approximately how long, in hours, will it take them to fill one truck? | {
"A": "2.5",
"B": "2.7",
"C": "2.9",
"D": "3.1",
"E": "3.3"
} | inverse(add(divide(const_1, 5), divide(const_1, 8))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)| | "the workers fill the truck at a rate of 1 / 5 + 1 / 8 = 13 / 40 of the truck per hour . then the time to fill one truck is 40 / 13 which is about 3.1 hours . the answer is d ." | physics |
math_qa__Ypuc5Jjp0cZTHKw3 | If 4a = 5b and ab ≠0, what is the ratio of a/5 to b/4? Choose the correct choice from the following answers
A) 125 / 64 B) 25 / 16 C) 1 D) 4 / 5 E) 64 / 125 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 / 20</gadget>
<output>1</output>
<result>C</result> | C | 1 | If 4a = 5b and ab ≠0, what is the ratio of a/5 to b/4? | {
"A": "125 / 64",
"B": "25 / 16",
"C": "1",
"D": "4 / 5",
"E": "64 / 125"
} | divide(multiply(4, 5), multiply(5, 4)) | multiply(n0,n1)|divide(#0,#0) | a nice fast approach is the first find a pair of numbers that satisfy the given equation : 4 a = 5 b here ' s one pair : a = 5 and b = 4 what is the ratio of a / 5 to b / 4 ? in other words , what is the value of ( a / 5 ) / ( b / 4 ) ? plug in values to get : ( a / 5 ) / ( b / 4 ) = ( 5 / 5 ) / ( 4 / 4 ) = 1 / 1 = 1 c | general |
math_qa__U3JQDhhNuo1cUyrK | What number is that, to which if 1, 5, and 13, be severally added, the first sum shall be to the second, as the second to the third? Choose the correct choice from the following options
A) 1
B) 2
C) 3
D) 4
E) 5 | <gadget id="calculator">13 + 5</gadget>
<output>18</output>
<gadget id="calculator">18 + 1</gadget>
<output>19</output>
<gadget id="calculator">19 + 1</gadget>
<output>20</output>
<gadget id="calculator">13 - 5</gadget>
<output>8</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">12 / 4</gadget>
<output>3</output>
<result>C</result> | C | 3 | What number is that, to which if 1, 5, and 13, be severally added, the first sum shall be to the second, as the second to the third? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(subtract(add(add(add(13, 5), 1), 1), subtract(13, 5)), subtract(5, 1)) | add(n1,n2)|subtract(n2,n1)|subtract(n1,n0)|add(n0,#0)|add(n0,#3)|subtract(#4,#1)|divide(#5,#2) | solution let x = the number required . by the conditions , x + 1 : x + 5 = a + 5 : x + 13 subtracting terms , ( art . 385,2 . ) x + 1 : 4 = x + 5 : 8 therefore 8 x + 8 = 4 x + 20 . and x = 3 . answer c | general |
math_qa__lVCYtWcWPdIWLdOV | The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 40 per cent. The two reductions together are equal to a single reduction of Choose the correct choice from the following
A) 45 % B) 55 % C) 35 % D) 32.5 % E) 30 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">(3/5) * 75</gadget>
<output>45</output>
<gadget id="calculator">100 - 45</gadget>
<output>55</output>
<result>B</result> | B | 55 | The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 40 per cent. The two reductions together are equal to a single reduction of | {
"A": "45 %",
"B": "55 %",
"C": "35 %",
"D": "32.5 %",
"E": "30 %"
} | subtract(const_100, multiply(divide(subtract(const_100, 40), const_100), subtract(const_100, 25))) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|multiply(#2,#1)|subtract(const_100,#3)| | "price = p initially price reduced by 25 % which means new price is 3 / 4 p now on this new price further 40 percent is reduced which means the new price is merely 60 percent of 3 / 4 p = = > ( 3 / 4 ) x ( 3 / 5 ) p = 9 / 20 p is the new price after both deduction which is 45 percent of the original value p . this implies this entire series of deduction is worth having discounted 55 % of p . so answer is b = 55 %" | general |
math_qa__cJrinRrnU2qKXKzf | 1000 boys have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now? Choose the most appropriate option:
A) 12
B) 12.5
C) 13
D) 13.5
E) 14 | <gadget id="calculator">1_000 * 15</gadget>
<output>15_000</output>
<gadget id="calculator">1_000 + 200</gadget>
<output>1_200</output>
<gadget id="calculator">15_000 / 1_200</gadget>
<output>25/2 = around 12.5</output>
<result>B</result> | B | 12.5 | 1000 boys have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now? | {
"A": "12",
"B": "12.5",
"C": "13",
"D": "13.5",
"E": "14"
} | divide(multiply(1000, 15), add(1000, 200)) | add(n0,n2)|multiply(n0,n1)|divide(#1,#0) | explanation : 1000 * 15 = 1200 * x x = 12.5 b | physics |
math_qa__UqEEkir2HkTvhamm | in a certain neighborhood , there are half as many beige houses as white houses , and 6 times as many white houses as brown houses . what is the ratio of the number of brown houses to the number of beige houses ? Options:
A) 1 : 3
B) 1 : 9
C) 2 : 5
D) 5 : 3
E) 6 : 1 | <gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<result>A</result> | A | 0.333333 | in a certain neighborhood , there are half as many beige houses as white houses , and 6 times as many white houses as brown houses . what is the ratio of the number of brown houses to the number of beige houses ? | {
"A": "1 : 3",
"B": "1 : 9",
"C": "2 : 5",
"D": "5 : 3",
"E": "6 : 1"
} | divide(const_2, 6) | divide(const_2,n0) | the ratio of beige : white : brown = 3 : 6 : 1 the answer is a . | other |
math_qa__J6uyxp6B2rayGq5L | A man buy a book in Rs50 & sale it Rs50. What is the rate of profit ??? Choose the correct choice from the following answers.
A) 10 %
B) 0 %
C) 30 %
D) 25 %
E) 28 % | <gadget id="calculator">50 - 50</gadget>
<output>0</output>
<gadget id="calculator">0 / 50</gadget>
<output>0</output>
<gadget id="calculator">0 * 100</gadget>
<output>0</output>
<result>B</result> | B | 0 | A man buy a book in Rs50 & sale it Rs50. What is the rate of profit ??? | {
"A": "10 %",
"B": "0 %",
"C": "30 %",
"D": "25 %",
"E": "28 %"
} | multiply(divide(subtract(50, 50), 50), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "cp = 50 sp = 50 profit = 50 - 50 = 0 % = 0 / 50 * 100 = 0 % answer : b" | gain |
math_qa__hQkCxAeoqFSZPOFX | Certain stocks in January were 40% less than they were in February and 15% greater than they were in March. What was the percentage decrease in the stocks from February to March? Options
A) 50.81 % B) 15.11 % C) 20.7 % D) 48.8 % E) 40 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">100 / (3/5)</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">100 / (23/20)</gadget>
<output>2_000/23 = around 86.956522</output>
<gadget id="calculator">(500/3) - (2_000/23)</gadget>
<output>5_500/69 = around 79.710145</output>
<gadget id="calculator">(5_500/69) / (500/3)</gadget>
<output>11/23 = around 0.478261</output>
<gadget id="calculator">(11/23) * 100</gadget>
<output>1_100/23 = around 47.826087</output>
<result>D</result> | D | 48.8 | Certain stocks in January were 40% less than they were in February and 15% greater than they were in March. What was the percentage decrease in the stocks from February to March? | {
"A": "50.81 %",
"B": "15.11 %",
"C": "20.7 %",
"D": "48.8 %",
"E": "40 %"
} | multiply(divide(subtract(divide(const_100, divide(subtract(const_100, 40), const_100)), divide(const_100, divide(add(const_100, 15), const_100))), divide(const_100, divide(subtract(const_100, 40), const_100))), const_100) | add(n1,const_100)|subtract(const_100,n0)|divide(#1,const_100)|divide(#0,const_100)|divide(const_100,#2)|divide(const_100,#3)|subtract(#4,#5)|divide(#6,#4)|multiply(#7,const_100)| | "let stocks value in feb = 100 = > in jan = 60 and march = 60 * 100 / 115 = 51.2 % thus , percent decrease in stocks from feb to march = 100 - 51.2 = 48.8 % hence answer is d" | general |
math_qa__K1il2PTkwJOFFJvw | The length of the bridge, which a train 150 metres long and travelling at 45 km/hr can cross in 30 seconds, is: Answers:
A) 200 m B) 225 m C) 245 m D) 250 m E) 270 m | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 150</gadget>
<output>225</output>
<result>B</result> | B | 225 | The length of the bridge, which a train 150 metres long and travelling at 45 km/hr can cross in 30 seconds, is: | {
"A": "200 m",
"B": "225 m",
"C": "245 m",
"D": "250 m",
"E": "270 m"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 150) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "let the length of the bridge : l the equation now is l + 150 / 12.5 m / s ( 45 km / hr or 12.5 m / s ) = 30 solving , l = 225 m answer : b" | physics |
math_qa__XY1G0ZKJmROv10Tc | Fresh grapes contain 85% water by weight and raisins obtained by drying fresh grapes contain 25% water by weight. How many kgs of fresh grapes are needed to get 20kgs of raisins? Pick one
A) 75 kgs B) 64 kgs C) 100 kgs D) 65 kgs E) 70 kgs | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">20 * 75</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 100</gadget>
<output>15</output>
<gadget id="calculator">15 + 85</gadget>
<output>100</output>
<result>C</result> | C | 100 | Fresh grapes contain 85% water by weight and raisins obtained by drying fresh grapes contain 25% water by weight. How many kgs of fresh grapes are needed to get 20kgs of raisins? | {
"A": "75 kgs",
"B": "64 kgs",
"C": "100 kgs",
"D": "65 kgs",
"E": "70 kgs"
} | add(divide(multiply(20, subtract(const_100, 25)), const_100), 85) | subtract(const_100,n1)|multiply(n2,#0)|divide(#1,const_100)|add(n0,#2) | the weight of non - water in 20 kg of dried grapes ( which is 100 - 25 = 75 % of whole weight ) will be the same as the weight of non - water in x kg of fresh grapes ( which is 100 - 85 = 15 % of whole weight ) , so 20 * 0.75 = x * 0.15 - - > x = 100 . answer : c | gain |
math_qa__dkYroreBSjfvg34E | Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 45 people bought tickets to the concert, what was the total revenue from ticket sales? Answers:
A) $ 600
B) $ 760
C) $ 850
D) $ 980
E) $ 1,140 | <gadget id="calculator">45 - 20</gadget>
<output>25</output>
<gadget id="calculator">25 - 10</gadget>
<output>15</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 10</gadget>
<output>6</output>
<gadget id="calculator">15 + 6</gadget>
<output>21</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(17/20) * 20</gadget>
<output>17</output>
<gadget id="calculator">21 + 17</gadget>
<output>38</output>
<gadget id="calculator">38 * 20</gadget>
<output>760</output>
<result>B</result> | B | 760 | Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 45 people bought tickets to the concert, what was the total revenue from ticket sales? | {
"A": "$ 600",
"B": "$ 760",
"C": "$ 850",
"D": "$ 980",
"E": "$ 1,140"
} | multiply(add(add(subtract(subtract(45, 20), 10), multiply(subtract(const_1, divide(40, const_100)), 10)), multiply(subtract(const_1, divide(15, const_100)), 20)), 20) | divide(n2,const_100)|divide(n4,const_100)|subtract(n5,n0)|subtract(const_1,#0)|subtract(#2,n1)|subtract(const_1,#1)|multiply(n1,#3)|multiply(n0,#5)|add(#6,#4)|add(#8,#7)|multiply(n0,#9) | price of 1 ticket = 20 $ revenue generated from sales of first 10 tickets = 10 * ( 60 / 100 * 20 ) = 10 * 12 = 120 revenue generated from sales of next 20 tickets = 20 * ( 85 / 100 * 20 ) = 20 * 17 = 340 revenue generated from sales of last 15 tickets = 20 * 15 = 300 revenue generated from sales of 45 tickets = 120 + 340 + 300 = 760 $ answer b | gain |
math_qa__MIrSfjD4liB4upAL | A car averages 35 miles per hour for the first 4 hours of a trip and averages 44 miles per hour for each additional hour of travel time. If the average speed for the entire trip is 38 miles per hour, how many hours long is the trip? Choose the correct answer.
A) 6 B) 8 C) 10 D) 12 E) 14 | <gadget id="calculator">38 * 4</gadget>
<output>152</output>
<gadget id="calculator">35 * 4</gadget>
<output>140</output>
<gadget id="calculator">152 - 140</gadget>
<output>12</output>
<gadget id="calculator">44 - 38</gadget>
<output>6</output>
<gadget id="calculator">12 / 6</gadget>
<output>2</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<result>A</result> | A | 6 | A car averages 35 miles per hour for the first 4 hours of a trip and averages 44 miles per hour for each additional hour of travel time. If the average speed for the entire trip is 38 miles per hour, how many hours long is the trip? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "14"
} | add(divide(subtract(multiply(38, 4), multiply(35, 4)), subtract(44, 38)), 4) | multiply(n1,n3)|multiply(n0,n1)|subtract(n2,n3)|subtract(#0,#1)|divide(#3,#2)|add(n1,#4)| | "let t be the total time of the trip . 35 * 4 + 44 ( t - 4 ) = 38 t 6 t = 176 - 140 t = 6 the answer is a ." | physics |
math_qa__F9NOFlAi8fwB9gv5 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? Choose the correct choice from the following options.
A) 288 B) 350 C) 889 D) 276 E) 234 | <gadget id="calculator">300 / 18</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 39</gadget>
<output>650</output>
<gadget id="calculator">650 - 300</gadget>
<output>350</output>
<result>B</result> | B | 350 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "288",
"B": "350",
"C": "889",
"D": "276",
"E": "234"
} | subtract(multiply(speed(300, 18), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 18 = 50 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 50 / 3 3 x + 900 = 1950 = > x = 350 m . answer : b" | physics |
math_qa__RzzlNRZxG32QlINU | How many seconds will a 220 metre long train take to cross a man running with a speed of 8 km/hr in the direction of the moving train if the speed of the train is 80 km/hr?
Choose one:
A) 25 B) 30 C) 40 D) 11 E) 60 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">80 - 8</gadget>
<output>72</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">220 / 20</gadget>
<output>11</output>
<result>D</result> | D | 11 | How many seconds will a 220 metre long train take to cross a man running with a speed of 8 km/hr in the direction of the moving train if the speed of the train is 80 km/hr? | {
"A": "25",
"B": "30",
"C": "40",
"D": "11",
"E": "60"
} | divide(220, multiply(const_0_2778, subtract(80, 8))) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "explanation : speed of train relatively to man = ( 80 - 8 ) km / hr = 72 km / hr = ( 72 x 5 / 18 ) m / sec = 20 m / sec time taken to pass the man = ( 220 / 20 ) sec = 11 sec . answer : d" | physics |
math_qa__49qggGgATr8Djlv1 | Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes? Choose the correct choice:
A) 18 B) 27 C) 98 D) 27 E) 21 | <gadget id="calculator">30 / 16</gadget>
<output>15/8 = around 1.875</output>
<gadget id="calculator">(15/8) - 1</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(7/8) * 24</gadget>
<output>21</output>
<result>E</result> | E | 21 | Pipe A can fill a tank in 16 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes? | {
"A": "18",
"B": "27",
"C": "98",
"D": "27",
"E": "21"
} | multiply(subtract(divide(30, 16), const_1), 24) | divide(n2,n0)|subtract(#0,const_1)|multiply(n1,#1)| | "let the pipe b be closed after x minutes . 30 / 16 - x / 24 = 1 = > x / 24 = 30 / 16 - 1 = 14 / 16 = > x = 14 / 16 * 24 = 21 . answer : e" | physics |
math_qa__GnJSqDIraxxGMiBE | What is the units digit of (147^25)^50 ? Choose the correct choice
A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>E</result> | E | 9 | What is the units digit of (147^25)^50 ? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | add(add(const_4, const_3), const_2) | add(const_3,const_4)|add(#0,const_2) | the units digit of the exponents of 7 repeat in a cycle of four , which is { 7,9 , 3,1 } . the number 25 has the form 4 n + 1 so the units digit is 7 inside the bracket . the exponent 50 has the form 4 n + 2 , so the units digit is 9 . the answer is e . | general |
math_qa__Ws0sqWnuh1PFyle0 | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $9 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 33 percent, what is the discount rate on Pony jeans? Choose the correct option.
A) 9 % B) 10 % C) 11 % D) 12 % E) 65 % | <gadget id="calculator">33 / 100</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">(33/100) * 36</gadget>
<output>297/25 = around 11.88</output>
<gadget id="calculator">9 - (297/25)</gadget>
<output>-72/25 = around -2.88</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 - 36</gadget>
<output>9</output>
<gadget id="calculator">(-72/25) / 9</gadget>
<output>-8/25 = around -0.32</output>
<gadget id="calculator">(33/100) - (-8/25)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) * 100</gadget>
<output>65</output>
<result>E</result> | E | 65 | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $9 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discounts rates is 33 percent, what is the discount rate on Pony jeans? | {
"A": "9 %",
"B": "10 %",
"C": "11 %",
"D": "12 %",
"E": "65 %"
} | multiply(subtract(divide(33, const_100), divide(subtract(9, multiply(divide(33, const_100), multiply(18, 2))), subtract(multiply(15, 3), multiply(18, 2)))), const_100) | divide(n6,const_100)|multiply(n1,n5)|multiply(n0,n4)|multiply(#0,#1)|subtract(#2,#1)|subtract(n2,#3)|divide(#5,#4)|subtract(#0,#6)|multiply(#7,const_100)| | "x discount on pony jeans , ( 0.33 - x ) discount on fox jeans . set the equation : 3 * 15 ( 0.33 - x ) + 2 * 18 x = 9 - - > x = 0.65 = 65 % answer : e ." | gain |
math_qa__AhSW7OgtQj2AkUG5 | A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
Choose the correct choice:
A) 2.5 min
B) 3 min
C) 3.2 min
D) 3.5 min
E) 4 min | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(1/4) + (7/2)</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">(15/4) / 75</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 60</gadget>
<output>3</output>
<result>B</result> | B | 3 | A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? | {
"A": "2.5 min",
"B": "3 min",
"C": "3.2 min",
"D": "3.5 min",
"E": "4 min"
} | multiply(divide(add(divide(1, 4), divide(add(const_3, const_4), 2)), 75), const_60) | add(const_3,const_4)|divide(n3,n4)|divide(#0,n2)|add(#1,#2)|divide(#3,n0)|multiply(#4,const_60) | total distance = ( 7 / 2 + 1 / 4 ) miles = 15 / 4 miles time taken = 15 / 4 * 75 hrs = 1 / 20 hrs = 3 min answer b | physics |
math_qa__zrucHsuGWCyCpZ7C | A watch was sold at a loss of 16%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? Options:
A) 700 B) 882 C) 799 D) 778 E) 901 | <gadget id="calculator">140 * 100</gadget>
<output>14_000</output>
<gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<gadget id="calculator">104 - 84</gadget>
<output>20</output>
<gadget id="calculator">14_000 / 20</gadget>
<output>700</output>
<result>A</result> | A | 700 | A watch was sold at a loss of 16%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price? | {
"A": "700",
"B": "882",
"C": "799",
"D": "778",
"E": "901"
} | divide(multiply(140, const_100), subtract(add(const_100, 4), subtract(const_100, 16))) | add(const_100,n2)|multiply(n1,const_100)|subtract(const_100,n0)|subtract(#0,#2)|divide(#1,#3)| | "84 % 104 % - - - - - - - - 20 % - - - - 140 100 % - - - - ? = > rs . 700 answer : a" | gain |
math_qa__ZjW0Cw4DqGHeYIth | Robin's average (arithmetic mean) test score on 9 tests is 82. What must be Robin's score on a 10th test for his average score on the 10 tests to be 83? Choose the correct choice from the following choices.
A) 92
B) 82
C) 72
D) 62
E) 52 | <gadget id="calculator">10 * 83</gadget>
<output>830</output>
<gadget id="calculator">9 * 82</gadget>
<output>738</output>
<gadget id="calculator">830 - 738</gadget>
<output>92</output>
<result>A</result> | A | 92 | Robin's average (arithmetic mean) test score on 9 tests is 82. What must be Robin's score on a 10th test for his average score on the 10 tests to be 83? | {
"A": "92",
"B": "82",
"C": "72",
"D": "62",
"E": "52"
} | subtract(multiply(10, 83), multiply(9, 82)) | multiply(n2,n4)|multiply(n0,n1)|subtract(#0,#1) | ( 9 * 82 + x ) / 10 = 83 x = ( 10 * 83 ) - ( 9 * 82 ) x = 830 - 738 total score required 830 - 738 = 92 correct answer is a | general |
math_qa__mLMHFNzMPpIe7a5A | A goods train runs at the speed of 72 km/hr and crosses a 210 m long platform in 26 sec. What is the length of the goods train? Choose the correct option: A) 382 B) 782 C) 278 D) 310 E) 881 | <gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 210</gadget>
<output>310</output>
<result>D</result> | D | 310 | A goods train runs at the speed of 72 km/hr and crosses a 210 m long platform in 26 sec. What is the length of the goods train? | {
"A": "382",
"B": "782",
"C": "278",
"D": "310",
"E": "881"
} | subtract(multiply(multiply(divide(72, const_3600), const_1000), 26), 210) | divide(n0,const_3600)|multiply(#0,const_1000)|multiply(n2,#1)|subtract(#2,n1)| | "speed = 72 * 5 / 18 = 20 m / sec . time = 26 sec . let the length of the train be x meters . then , ( x + 210 ) / 26 = 20 x = 310 m . answer : d" | physics |
math_qa__t7DT59JH5fKO2wRX | Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $220, what were her original savings? Choose the correct choice from the following choices
A) $ 900 B) $ 880 C) $ 1000 D) $ 700 E) $ 1500 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">220 / (1/4)</gadget>
<output>880</output>
<result>B</result> | B | 880 | Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $220, what were her original savings? | {
"A": "$ 900",
"B": "$ 880",
"C": "$ 1000",
"D": "$ 700",
"E": "$ 1500"
} | divide(220, subtract(const_1, divide(3, 4))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1)| | "if linda spent 3 / 4 of her savings on furnitute , the rest 4 / 4 - 3 / 4 = 1 / 4 on a tv but the tv cost her $ 220 . so 1 / 4 of her savings is $ 220 . so her original savings are 4 times $ 220 = $ 880 correct answer b" | general |
math_qa__I9viYN0HmO2FABdO | I have only 1$ and 2$ note. I want to give 95$ to John. How many maximum number of 2$ note I need?
Select the correct option.
A) 39 B) 95 C) 47 D) 55 E) 76 | <gadget id="calculator">95 / 2</gadget>
<output>95/2 = around 47.5</output>
<result>C</result> | C | 47 | I have only 1$ and 2$ note. I want to give 95$ to John. How many maximum number of 2$ note I need? | {
"A": "39",
"B": "95",
"C": "47",
"D": "55",
"E": "76"
} | divide(95, 2) | divide(n2,n1) | check whether 95 is divisible by 2 then that is maximum no of 2 $ note else check next maximum term before 95 so 94 / 2 = 47 ans is c | general |
math_qa__ICw6JTeRG9MqNvwo | If 10,000 microns = 1 decimeter, and 10,000,000,000 angstroms = 1 decimeter, how many angstroms equal 1 micron?
Pick:
A) 0.01
B) 1 , 000,000
C) 0.001
D) 1,000
E) 1.0 e - 05 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">1 / 10_000</gadget>
<output>1/10_000 = around 0.0001</output>
<gadget id="calculator">(1/10_000) * 10_000</gadget>
<output>1</output>
<result>B</result> | B | 1 | If 10,000 microns = 1 decimeter, and 10,000,000,000 angstroms = 1 decimeter, how many angstroms equal 1 micron? | {
"A": "0.01",
"B": "1 , 000,000",
"C": "0.001",
"D": "1,000",
"E": "1.0 e - 05"
} | multiply(divide(1, multiply(const_100, const_100)), multiply(const_100, const_100)) | multiply(const_100,const_100)|divide(n1,#0)|multiply(#1,#0) | given that 10,000 microns = 1 decimeter = 10,000 , 000,000 angstroms so , 1 micron = 10,000 , 000,000 / 10,000 = 1 , 000,000 answer : b | general |
math_qa__MS37kqXPCMI3SiF7 | Salad dressing P is made up of 30% vinegar and 70% oil, and salad dressing Q contains 10% vinegar and 90% oil. If the two dressings are combined to produce a salad dressing that is 12% vinegar, dressing P comprises what percentage of the new dressing? Choose one: A) 50 % B) 40 % C) 30 % D) 20 % E) 10 % | <gadget id="calculator">30 - 10</gadget>
<output>20</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>E</result> | E | 10 | Salad dressing P is made up of 30% vinegar and 70% oil, and salad dressing Q contains 10% vinegar and 90% oil. If the two dressings are combined to produce a salad dressing that is 12% vinegar, dressing P comprises what percentage of the new dressing? | {
"A": "50 %",
"B": "40 %",
"C": "30 %",
"D": "20 %",
"E": "10 %"
} | divide(subtract(30, 10), subtract(12, 10)) | subtract(n0,n2)|subtract(n4,n2)|divide(#0,#1) | let x be the percentage of dressing p in the new dressing . 0.3 x + 0.1 ( 1 - x ) = 0.12 0.2 x = 0.02 x = 0.1 = 10 % the answer is e . | gain |
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