id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__sWJTiefyrcN0deYO | If f(x)=1/x and x is a natural number, what CANNOT be the answer for f(f(x))?
Select the correct option.
A) 1 / 7 B) 3 C) 12 / 3 D) 6 / 6 E) 1 | <gadget id="calculator">1 * 1</gadget>
<output>1</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<result>A</result> | A | 0.142857 | If f(x)=1/x and x is a natural number, what CANNOT be the answer for f(f(x))? | {
"A": "1 / 7",
"B": "3",
"C": "12 / 3",
"D": "6 / 6",
"E": "1"
} | divide(multiply(1, const_1), subtract(multiply(const_2, const_4), 1)) | multiply(n0,const_1)|multiply(const_2,const_4)|subtract(#1,n0)|divide(#0,#2) | answer a is impossible because the invers of 1 / x is x , and the only way to have something other than a natural number is to input something other than a natural number . with the specification that only natural numbers may be used 1 / 7 is not a possibility for f ( f ( x ) ) | general |
math_qa__4rGYBR09q3KG1Nbr | if 28 less than 5 times a certain number is 232 . what is the number ? Choose the correct option
A) 32 B) 42 C) 52 D) 62 E) 72 | <gadget id="calculator">5 * 28</gadget>
<output>140</output>
<gadget id="calculator">140 + 232</gadget>
<output>372</output>
<gadget id="calculator">372 - 140</gadget>
<output>232</output>
<gadget id="calculator">232 - 140</gadget>
<output>92</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">92 - 40</gadget>
<output>52</output>
<result>C</result> | C | 52 | if 28 less than 5 times a certain number is 232 . what is the number ? | {
"A": "32",
"B": "42",
"C": "52",
"D": "62",
"E": "72"
} | subtract(subtract(subtract(add(multiply(5, 28), 232), multiply(5, 28)), multiply(5, 28)), multiply(const_4, const_10)) | multiply(n0,n1)|multiply(const_10,const_4)|add(n2,#0)|subtract(#2,#0)|subtract(#3,#0)|subtract(#4,#1) | 5 x − 28 subtraction is built backwards , multiply the unknown by 5 5 x − 28 = 232 is translates to equals + 28 + 28 add 28 to both sides 5 x = 260 the variable ismultiplied by 5 5 5 divide both sides by 5 x = 52 the number is 52 . correct answer c | general |
math_qa__glgWewR8O7V2m5eo | A rope of which a calf is tied is increased from 10 m to 23 m, how much additional grassy ground shall it graze?
Choose the correct choice from the following:
A) 1217 B) 1348.2 C) 1210 D) 1212 E) 1312 | <gadget id="calculator">23 ** 2</gadget>
<output>529</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">529 - 100</gadget>
<output>429</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">429 * (22/7)</gadget>
<output>9_438/7 = around 1_348.285714</output>
<result>B</result> | B | 1,348.2 | A rope of which a calf is tied is increased from 10 m to 23 m, how much additional grassy ground shall it graze? | {
"A": "1217",
"B": "1348.2",
"C": "1210",
"D": "1212",
"E": "1312"
} | multiply(subtract(power(23, const_2), power(const_10, const_2)), divide(add(multiply(const_10, const_2), const_2), add(const_4, const_3))) | add(const_3,const_4)|multiply(const_10,const_2)|power(n1,const_2)|power(const_10,const_2)|add(#1,const_2)|subtract(#2,#3)|divide(#4,#0)|multiply(#6,#5) | π ( 232 – 102 ) = 1348.2 answer : b | general |
math_qa__zxRUv12zOokVMnU6 | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets into it. The mass of the man is :
Choose one.
A) 50 kg B) 60 kg C) 70 kg D) 80 kg E) none of these | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">6 * (1/100)</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 1_000</gadget>
<output>60</output>
<result>B</result> | B | 60 | A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets into it. The mass of the man is : | {
"A": "50 kg",
"B": "60 kg",
"C": "70 kg",
"D": "80 kg",
"E": "none of these"
} | multiply(multiply(multiply(3, 2), divide(1, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000) | explanation : in this type of question , first we will calculate the volume of water displaces then will multiply with the density of water . volume of water displaced = 3 * 2 * 0.01 = 0.06 m cube mass of man = volume of water displaced * density of water = 0.06 * 1000 = 60 kg option b | physics |
math_qa__PxqfRkhzcRHuBZTg | Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 6 meters, and the interior of tank B has a height of 6 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B?
Pick one:
A) 60 % B) 80 % C) 100 % D) 120 % E) 125 % | <gadget id="calculator">6 / 10</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) ** 2</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">10 / 6</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(9/25) * (5/3)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>A</result> | A | 60 | Tanks A and B are each in the shape of a right circular cylinder. The interior of tank A has a height of 10 meters and a circumference of 6 meters, and the interior of tank B has a height of 6 meters and a circumference of 10 meters. The capacity of tank A is what percent of the capacity of tank B? | {
"A": "60 %",
"B": "80 %",
"C": "100 %",
"D": "120 %",
"E": "125 %"
} | multiply(multiply(power(divide(6, 10), const_2), divide(10, 6)), const_100) | divide(n0,n2)|divide(n1,n3)|power(#1,const_2)|multiply(#0,#2)|multiply(#3,const_100)| | "the radius of tank a is 6 / ( 2 * pi ) . the capacity of tank a is 10 * pi * 36 / ( 4 * pi ^ 2 ) = 180 / ( 2 * pi ) the radius of tank b is 10 / ( 2 * pi ) . the capacity of tank b is 6 * pi * 100 / ( 4 * pi ^ 2 ) = 300 / ( 2 * pi ) tank a / tank b = 180 / 300 = 6 / 10 = 60 % the answer is a ." | physics |
math_qa__ZKq3vveyUE2SBewi | The tax on a commodity is diminished by 30% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it? Choose the correct choice from the following answers
A) 12 % B) 14 % C) 16 % D) 20 % E) 23 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">110 * 70</gadget>
<output>7_700</output>
<gadget id="calculator">7_700 / 100</gadget>
<output>77</output>
<gadget id="calculator">100 - 77</gadget>
<output>23</output>
<result>E</result> | E | 23 | The tax on a commodity is diminished by 30% but its consumption is increased by 10%. Find the decrease percent in the revenue derived from it? | {
"A": "12 %",
"B": "14 %",
"C": "16 %",
"D": "20 %",
"E": "23 %"
} | subtract(const_100, divide(multiply(add(const_100, 10), subtract(const_100, 30)), const_100)) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(const_100,#3)| | "explanation : 100 * 100 = 10000 70 * 110 = 7700 10000 - - - - - - - 2300 100 - - - - - - - ? = 23 % e )" | general |
math_qa__mTeSdxOhw9qQWoDL | A jogger running at 9 kmph along side a railway track is 270 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Options: A) 3.6 sec B) 18 sec C) 36 sec D) 39 sec E) none of these | <gadget id="calculator">270 + 120</gadget>
<output>390</output>
<gadget id="calculator">390 / 1_000</gadget>
<output>39/100 = around 0.39</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">(39/100) / 36</gadget>
<output>13/1_200 = around 0.010833</output>
<gadget id="calculator">(13/1_200) * 60</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) * 60</gadget>
<output>39</output>
<result>D</result> | D | 39 | A jogger running at 9 kmph along side a railway track is 270 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger? | {
"A": "3.6 sec",
"B": "18 sec",
"C": "36 sec",
"D": "39 sec",
"E": "none of these"
} | multiply(multiply(divide(divide(add(270, 120), const_1000), subtract(45, 9)), const_60), const_60) | add(n1,n2)|subtract(n3,n0)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_60)|multiply(#4,const_60)| | "speed of train relative to jogger = ( 45 – 9 ) km / h = 36 km / h = ( 36 × 5 ⁄ 18 ) m / sec = 10 m / sec distance to be covered = ( 270 + 120 ) m = 390 m . ∴ time taken = ( 390 ⁄ 10 ) sec = 39 sec . answer d" | physics |
math_qa__daDTg2VFfCtncAu4 | Some consecutive natural numbers, starting with 1, are written on the board. Now, one of the numbers was erased and the average of the remaining numbers is 800/39. Find the number which was erased. Choose one
A) 20
B) 87
C) 266
D) 288
E) 11 | <gadget id="calculator">39 + 1</gadget>
<output>40</output>
<gadget id="calculator">40 + 1</gadget>
<output>41</output>
<gadget id="calculator">40 * 41</gadget>
<output>1_640</output>
<gadget id="calculator">1_640 / 2</gadget>
<output>820</output>
<gadget id="calculator">820 - 800</gadget>
<output>20</output>
<result>A</result> | A | 20 | Some consecutive natural numbers, starting with 1, are written on the board. Now, one of the numbers was erased and the average of the remaining numbers is 800/39. Find the number which was erased. | {
"A": "20",
"B": "87",
"C": "266",
"D": "288",
"E": "11"
} | subtract(divide(multiply(add(39, const_1), add(add(39, const_1), const_1)), const_2), 800) | add(n2,const_1)|add(#0,const_1)|multiply(#0,#1)|divide(#2,const_2)|subtract(#3,n1) | we know that average of n consecutive numbes average = n × ( n + 1 ) 2 n = ( n + 1 ) 2 n × ( n + 1 ) 2 n = ( n + 1 ) 2 if the given n is sufficiently large , the average does not change much even though we exclude one or two numbers from it . so the approximate number of observations is almost double to the average ( remember : the average of consecutive numbers almost lies in the middle ) the approximate average is 800 / 39 = approx 20 . so the initial numbers may be nearer to 40 . in this question it is actually 40 as from the denominator of the new average 800 / 39 . the initial numbers are 40 . sum of 40 consecutive numbers = 40 × ( 40 + 1 ) 2 = 82040 × ( 40 + 1 ) 2 = 820 sum of 39 numbers = average x numbenumber of observations = 80039 × 3980039 × 39 = 800 so the number excluded = 820 - 800 = 20 answer : a | general |
math_qa__E3McaiL97u3Lj254 | Find the area of the quadrilateral of one of its diagonals is 10 cm and its off sets 7 cm and 3 cm? Options.
A) 50 cm 2 B) 100 cm 2 C) 150 cm 2 D) 200 cm 2 E) 250 cm 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + 7</gadget>
<output>10</output>
<gadget id="calculator">(1/2) * 10</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<result>A</result> | A | 50 | Find the area of the quadrilateral of one of its diagonals is 10 cm and its off sets 7 cm and 3 cm? | {
"A": "50 cm 2",
"B": "100 cm 2",
"C": "150 cm 2",
"D": "200 cm 2",
"E": "250 cm 2"
} | multiply(multiply(divide(const_1, const_2), add(3, 7)), 10) | add(n1,n2)|divide(const_1,const_2)|multiply(#0,#1)|multiply(n0,#2)| | "1 / 2 * 10 ( 7 + 3 ) = 50 cm 2 answer : a" | geometry |
math_qa__eeaulWtDtGcQMzl5 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 15 inches by 24 inches and Jordan's rectangle is 8 inches long, how wide is Jordan's rectangle, in inches? Choose the correct choice from the following options
A) 30 B) 35 C) 40 D) 45 E) 50 | <gadget id="calculator">15 * 24</gadget>
<output>360</output>
<gadget id="calculator">360 / 8</gadget>
<output>45</output>
<result>D</result> | D | 45 | Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 15 inches by 24 inches and Jordan's rectangle is 8 inches long, how wide is Jordan's rectangle, in inches? | {
"A": "30",
"B": "35",
"C": "40",
"D": "45",
"E": "50"
} | divide(rectangle_area(15, 24), 8) | rectangle_area(n0,n1)|divide(#0,n2)| | "area of first rectangle is 15 * 24 = 360 hence area of second would be 8 x = 360 x x = 45 answer is d" | geometry |
math_qa__KHnWBZXMrSTzvDUf | What is the smallest number which when increased by 3 is divisible by 18, 70, 25 and 21?
Choose the correct answer
A) 2327 B) 2757 C) 3147 D) 3587 E) 3997 | <gadget id="calculator">lcm(18, 70)</gadget>
<output>630</output>
<gadget id="calculator">lcm(25, 21)</gadget>
<output>525</output>
<gadget id="calculator">lcm(630, 525)</gadget>
<output>3_150</output>
<gadget id="calculator">3_150 + 3</gadget>
<output>3_153</output>
<result>C</result> | C | 3,147 | What is the smallest number which when increased by 3 is divisible by 18, 70, 25 and 21? | {
"A": "2327",
"B": "2757",
"C": "3147",
"D": "3587",
"E": "3997"
} | add(lcm(lcm(18, 70), lcm(25, 21)), 3) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "when increased by 3 , the number must include at least 2 * 3 ^ 2 * 5 ^ 2 * 7 = 3150 the answer is c ." | general |
math_qa__MOKV3dqf00hbS5by | In a survey of parents, exactly 7/8 of the mothers and 3/4 of the fathers held full-time jobs. If 60 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs? Choose the correct choice from the following answers
A) 25.5 % B) 21.5 % C) 17.5 % D) 13.5 % E) 9.5 % | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 40</gadget>
<output>30</output>
<gadget id="calculator">40 - 30</gadget>
<output>10</output>
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>
<gadget id="calculator">(7/8) * 60</gadget>
<output>105/2 = around 52.5</output>
<gadget id="calculator">60 - (105/2)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">10 + (15/2)</gadget>
<output>35/2 = around 17.5</output>
<result>C</result> | C | 17.5 | In a survey of parents, exactly 7/8 of the mothers and 3/4 of the fathers held full-time jobs. If 60 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs? | {
"A": "25.5 %",
"B": "21.5 %",
"C": "17.5 %",
"D": "13.5 %",
"E": "9.5 %"
} | add(subtract(subtract(const_100, 60), multiply(divide(3, 4), subtract(const_100, 60))), subtract(60, multiply(divide(7, 8), 60))) | divide(n2,n3)|divide(n0,n1)|subtract(const_100,n4)|multiply(#0,#2)|multiply(n4,#1)|subtract(#2,#3)|subtract(n4,#4)|add(#5,#6)| | "fathers without full - time jobs are 1 / 4 * 2 / 5 = 2 / 20 of all the parents surveyed . mothers without full - time jobs are 1 / 8 * 3 / 5 = 3 / 40 of all the parents surveyed . the percent of parents without full - time jobs is 2 / 20 + 3 / 40 = 7 / 40 = 17.5 % the answer is c ." | general |
math_qa__OkDvAKL1c6X8eZHP | A truck covers a distance of 296 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 6.5 km more than that travelled by the truck ? Pick one
A) 6 hours
B) 5 hours
C) 5.5 hours
D) 8 hours
E) none | <gadget id="calculator">296 + 6.5</gadget>
<output>302.5</output>
<gadget id="calculator">296 / 8</gadget>
<output>37</output>
<gadget id="calculator">37 + 18</gadget>
<output>55</output>
<gadget id="calculator">302.5 / 55</gadget>
<output>5.5</output>
<result>C</result> | C | 5.5 | A truck covers a distance of 296 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 6.5 km more than that travelled by the truck ? | {
"A": "6 hours",
"B": "5 hours",
"C": "5.5 hours",
"D": "8 hours",
"E": "none"
} | divide(add(296, 6.5), add(divide(296, 8), 18)) | add(n0,n3)|divide(n0,n1)|add(n2,#1)|divide(#0,#2) | explanation : speed of the truck = distance / time = 296 / 8 = 37 kmph now , speed of car = ( speed of truck + 18 ) kmph = ( 37 + 18 ) = 55 kmph distance travelled by car = 296 + 6.5 = 302.5 km time taken by car = distance / speed = 302.5 / 55 = 5.5 hours . answer – c | physics |
math_qa__tLlpFCHadTFqySCT | A candidate got 10% of the votes polled and he lost to his rival by 16000 votes. How many votes were cast? Choices
A) 7500 B) 20000 C) 2775 D) 5496 E) 6851 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) - (1/10)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">16_000 / (4/5)</gadget>
<output>20_000</output>
<result>B</result> | B | 20,000 | A candidate got 10% of the votes polled and he lost to his rival by 16000 votes. How many votes were cast? | {
"A": "7500",
"B": "20000",
"C": "2775",
"D": "5496",
"E": "6851"
} | divide(16000, subtract(subtract(const_1, divide(10, const_100)), divide(10, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "10 % - - - - - - - - - - - l 90 % - - - - - - - - - - - w - - - - - - - - - - - - - - - - - - 80 % - - - - - - - - - - 16000 100 % - - - - - - - - - ? = > 20000 answer : b" | gain |
math_qa__W1xldW69rijQvSnL | The length of a rectangle is 2 cm more than the width of the rectangle. The perimeter of the rectangle is 20 cm. Find the length and the width of the rectangle.
Choose the correct answer:
A) l = 2 , w = 9
B) l = 5 , w = 8
C) l = 6 , w = 4
D) l = 1 , w = 7
E) l = 2 , w = 3 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<result>C</result> | C | 6 | The length of a rectangle is 2 cm more than the width of the rectangle. The perimeter of the rectangle is 20 cm. Find the length and the width of the rectangle. | {
"A": "l = 2 , w = 9",
"B": "l = 5 , w = 8",
"C": "l = 6 , w = 4",
"D": "l = 1 , w = 7",
"E": "l = 2 , w = 3"
} | add(divide(subtract(divide(20, const_2), 2), const_2), 2) | divide(n1,const_2)|subtract(#0,n0)|divide(#1,const_2)|add(n0,#2) | let length l = x , width w = x − 2 and perimeter = p ∴ p = 2 l + 2 w = 2 x + 2 ( x − 2 ) 20 = 2 x + 2 x − 4 4 x = 24 x = 6 l = 6 cm and w = l − 2 = 4 cm answer is c . | geometry |
math_qa__R7mLDh8De7qCwEzW | a certain sum becomes 4 times itself at simple interest in 8 years . in how many years does it become 10 times itself ?
Choose the correct choice
A) 24 B) 55 C) 77 D) 99 E) 01 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">9 / 3</gadget>
<output>3</output>
<gadget id="calculator">3 * 8</gadget>
<output>24</output>
<result>A</result> | A | 24 | a certain sum becomes 4 times itself at simple interest in 8 years . in how many years does it become 10 times itself ? | {
"A": "24",
"B": "55",
"C": "77",
"D": "99",
"E": "01"
} | multiply(divide(subtract(10, const_1), subtract(4, const_1)), 8) | subtract(n2,const_1)|subtract(n0,const_1)|divide(#0,#1)|multiply(n1,#2) | let the sum be rs . x , then it becomes rs . 4 x in eight years rs . 3 x is the interest on x for eight years . r = ( 100 * 3 x ) / ( x * 8 ) = 300 / 8 % if the sum becomes ten times itself , then interest is 9 x . the required time period = ( 100 * 9 x ) / ( x * 300 / 8 ) = ( 100 * 9 x * 8 ) / ( x * 300 ) = 24 years . answer : a | general |
math_qa__X6rffk5wvg0dc8kQ | Product of two natural numbers is 5. Then, the sum of reciprocals of their squares is Select the correct option: A) 290 / 289 B) 26 / 25 C) 290 / 90 D) 290 / 19 E) none of these | <gadget id="calculator">1 / 1</gadget>
<output>1</output>
<gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) ** 2</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<result>B</result> | B | 1.04 | Product of two natural numbers is 5. Then, the sum of reciprocals of their squares is | {
"A": "290 / 289",
"B": "26 / 25",
"C": "290 / 90",
"D": "290 / 19",
"E": "none of these"
} | add(power(divide(const_1, const_1), const_2), power(divide(const_1, 5), const_2)) | divide(const_1,const_1)|divide(const_1,n0)|power(#0,const_2)|power(#1,const_2)|add(#2,#3)| | "explanation : if the numbers are a , b , then ab = 5 , as 17 is a prime number , so a = 1 , b = 5 . 1 / a 2 + 1 / b 2 = 1 / 1 ( 2 ) + 1 / 5 ( 2 ) = 26 / 25 option b" | general |
math_qa__dSt1gLMnRr7h9lFA | Jar A has 26% more marbles than Jar B . What percent of marbles from Jar A need to be moved into Jar B so that both jars have equal marbles?
Select the correct option:
A) 7.6 % B) 8.3 % C) 9.6 % D) 10.3 % E) 11.5 % | <gadget id="calculator">26 / 2</gadget>
<output>13</output>
<gadget id="calculator">26 + 100</gadget>
<output>126</output>
<gadget id="calculator">13 / 126</gadget>
<output>13/126 = around 0.103175</output>
<gadget id="calculator">(13/126) * 100</gadget>
<output>650/63 = around 10.31746</output>
<result>D</result> | D | 10.3 | Jar A has 26% more marbles than Jar B . What percent of marbles from Jar A need to be moved into Jar B so that both jars have equal marbles? | {
"A": "7.6 %",
"B": "8.3 %",
"C": "9.6 %",
"D": "10.3 %",
"E": "11.5 %"
} | multiply(divide(divide(26, const_2), add(26, const_100)), const_100) | add(n0,const_100)|divide(n0,const_2)|divide(#1,#0)|multiply(#2,const_100)| | "an easy way to solve this question is by number plugging . assume there are 100 marbles in jar b then in jar a there will be 126 marbles . now , for both jars to have equal marbles we should move 13 marbles from a to b , which is 13 / 126 = ~ 10.3 % of a . answer : d ." | gain |
math_qa__C6gMnjNmgfn5WoZT | The average weight of 5 students decreases by 4 kg when one of them weighing 92 kg is replaced by a new student. The weight of the student is Pick one: A) 62 kg B) 60 kg C) 70 kg D) 72 kg E) none of these | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">92 - 20</gadget>
<output>72</output>
<result>D</result> | D | 72 | The average weight of 5 students decreases by 4 kg when one of them weighing 92 kg is replaced by a new student. The weight of the student is | {
"A": "62 kg",
"B": "60 kg",
"C": "70 kg",
"D": "72 kg",
"E": "none of these"
} | subtract(92, multiply(5, 4)) | multiply(n0,n1)|subtract(n2,#0)| | "explanation : let the weight of student be x kg . given , difference in average weight = 4 kg = > ( 92 - x ) / 5 = 4 = > x = 72 answer : d" | general |
math_qa__5wFYHjf9HPaqXomZ | Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 25 grades are D's. What is the number of students in the course? Choose the correct answer.
A) 80
B) 110
C) 160
D) 500
E) 400 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/5) + (1/4)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(9/20) + (1/2)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1 - (19/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">25 / (1/20)</gadget>
<output>500</output>
<result>D</result> | D | 500 | Of the final grades received by the students in a certain math course, 1/5 are A's, 1/4 are B's, 1/2 are C's, and the remaining 25 grades are D's. What is the number of students in the course? | {
"A": "80",
"B": "110",
"C": "160",
"D": "500",
"E": "400"
} | divide(25, subtract(1, add(add(divide(1, 5), divide(1, 4)), divide(1, 2)))) | divide(n0,n1)|divide(n0,n3)|divide(n0,n5)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5)| | "we start by creating a variable for the total number of students in the math course . we can say : t = total number of students in the math course next , we can use variable t in an equation that we translate from the given information . we are given that , of the final grades received by the students in a certain math course , 1 / 5 are a ' s , 1 / 4 are b ' s , 1 / 2 are c ' s , and the remaining 25 grades are d ' s . since this represents all the grades in the class , it represents all the students in the class . thus we know : # a ’ s + # b ’ s + # c ’ s + # d ’ s = total number of students in the class 1 / 5 ( t ) + ¼ ( t ) + ½ ( t ) + 25 = t we can multiply the entire equation by 20 to cancel out the denominators of the fractions and we have : 4 t + 5 t + 10 t + 500 = 20 t 19 t + 500 = 20 t 500 = t there are a total of 500 students in the math class . answer is d ." | general |
math_qa__jXInmw0n1IgBGvuN | The difference between simple and compound interest on Rs. 1400 for one year at 10% per annum reckoned half-yearly is? Pick one: A) 8.25 B) 3.5 C) 9.0 D) 3.15 E) 2.0 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">(1/400) * 1_400</gadget>
<output>7/2 = around 3.5</output>
<result>B</result> | B | 3.5 | The difference between simple and compound interest on Rs. 1400 for one year at 10% per annum reckoned half-yearly is? | {
"A": "8.25",
"B": "3.5",
"C": "9.0",
"D": "3.15",
"E": "2.0"
} | multiply(subtract(power(add(divide(divide(10, const_2), const_100), const_1), const_2), add(divide(10, const_100), const_1)), 1400) | divide(n1,const_2)|divide(n1,const_100)|add(#1,const_1)|divide(#0,const_100)|add(#3,const_1)|power(#4,const_2)|subtract(#5,#2)|multiply(n0,#6)| | "s . i . = ( 1400 * 10 * 1 ) / 100 = rs . 140 c . i . = [ 1400 * ( 1 + 5 / 100 ) 2 - 1400 ] = rs . 143.5 difference = ( 143.5 - 140 ) = rs . 3.50 answer : b" | gain |
math_qa__Iu7RGWW7cR2VWmnG | If a * b * c =(√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 2. Options
A) 8
B) 5
C) 11
D) 3
E) 4 | <gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">8 * 18</gadget>
<output>144</output>
<gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>E</result> | E | 4 | If a * b * c =(√(a + 2)(b + 3)) / (c + 1), find the value of 6 * 15 * 2. | {
"A": "8",
"B": "5",
"C": "11",
"D": "3",
"E": "4"
} | divide(sqrt(multiply(add(6, 2), add(15, 3))), add(2, 1)) | add(n0,n3)|add(n1,n4)|add(n2,n5)|multiply(#0,#1)|sqrt(#3)|divide(#4,#2)| | "6 * 15 * 2 = ( √ ( 6 + 2 ) ( 15 + 3 ) ) / ( 2 + 1 ) = ( √ 8 * 18 ) / 3 = ( √ 144 ) / 3 = 12 / 3 = 4 . answer is e" | general |
math_qa__xOIPT36mJz6FZ8Uu | A train 500 m long, running with a speed of 180 km/hr will pass a tree in?
Choose the correct choice from the following
A) 17 sec B) 16 sec C) 18 sec D) 10 sec E) 12 sec | <gadget id="calculator">180 * 1_000</gadget>
<output>180_000</output>
<gadget id="calculator">500 / 180_000</gadget>
<output>1/360 = around 0.002778</output>
<gadget id="calculator">(1/360) * 3_600</gadget>
<output>10</output>
<result>D</result> | D | 10 | A train 500 m long, running with a speed of 180 km/hr will pass a tree in? | {
"A": "17 sec",
"B": "16 sec",
"C": "18 sec",
"D": "10 sec",
"E": "12 sec"
} | multiply(divide(500, multiply(180, const_1000)), const_3600) | multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600) | speed = 180 * 5 / 18 = 50 m / sec time taken = 500 * 1 / 50 = 10 sec answer : d | physics |
math_qa__UsVqGYP1472sYMtH | 33 1/3% OF 330? Choose one:
A) 80 B) 90 C) 110 D) 120 E) 130 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">33 + (1/3)</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 330</gadget>
<output>11_000</output>
<gadget id="calculator">11_000 / 100</gadget>
<output>110</output>
<result>C</result> | C | 110 | 33 1/3% OF 330? | {
"A": "80",
"B": "90",
"C": "110",
"D": "120",
"E": "130"
} | divide(multiply(add(33, divide(1, 3)), 330), const_100) | divide(n1,n2)|add(n0,#0)|multiply(n3,#1)|divide(#2,const_100)| | "33 1 / 3 % = 1 / 3 1 / 3 × 330 = 110 c )" | gain |
math_qa__M6j27mTOp5jIFMEx | The Malibu Country Club needs to drain its pool for refinishing. The hose they use to drain it can remove 60 cubic feet of water per minute. If the pool is 40 feet wide by 150 feet long by 10 feet deep and is currently at 80% capacity, how long will it take to drain the pool? Choose the correct choice from the following answers: A) 1000 B) 800 C) 600 D) 700 E) 500 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">40 * 150</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 * 10</gadget>
<output>60_000</output>
<gadget id="calculator">(4/5) * 60_000</gadget>
<output>48_000</output>
<gadget id="calculator">48_000 / 60</gadget>
<output>800</output>
<result>B</result> | B | 800 | The Malibu Country Club needs to drain its pool for refinishing. The hose they use to drain it can remove 60 cubic feet of water per minute. If the pool is 40 feet wide by 150 feet long by 10 feet deep and is currently at 80% capacity, how long will it take to drain the pool? | {
"A": "1000",
"B": "800",
"C": "600",
"D": "700",
"E": "500"
} | divide(multiply(divide(80, const_100), multiply(multiply(40, 150), 10)), 60) | divide(n4,const_100)|multiply(n1,n2)|multiply(n3,#1)|multiply(#0,#2)|divide(#3,n0)| | "volume of pool = 40 * 150 * 10 cu . ft , 80 % full = 40 * 150 * 10 * 0.8 cu . ft water is available to drain . draining capacity = 60 cu . ft / min therefore time taken = 40 * 150 * 10 * 0.8 / 60 min = 800 min b" | gain |
math_qa__VFfzHDOjPaGjSy9W | You collect pens. Suppose you start out with 7. Mike gives you another 22 pens. Since her father makes pens, Cindy decides to double your pens. Since you're nice, you give Sharon 19 pens. How many pens do you have at the end?
Choose the correct choice:
A) 39
B) 40
C) 41
D) 42
E) 43 | <gadget id="calculator">22 + 7</gadget>
<output>29</output>
<gadget id="calculator">29 * 2</gadget>
<output>58</output>
<gadget id="calculator">58 - 19</gadget>
<output>39</output>
<result>A</result> | A | 39 | You collect pens. Suppose you start out with 7. Mike gives you another 22 pens. Since her father makes pens, Cindy decides to double your pens. Since you're nice, you give Sharon 19 pens. How many pens do you have at the end? | {
"A": "39",
"B": "40",
"C": "41",
"D": "42",
"E": "43"
} | subtract(multiply(add(22, 7), const_2), 19) | add(n0,n1)|multiply(#0,const_2)|subtract(#1,n2)| | "solution start with 7 pens . mike gives you 22 pens : 7 + 22 = 29 pens . cindy doubles the number of pens you have : 29 × 2 = 58 pens . sharon takes 19 pens from you : 58 - 19 = 39 pens . so you have 39 at the end . correct answer : a" | general |
math_qa__WUwmVlLmy6qEmb8j | The difference between simple and compound interest on Rs. 1300 for one year at 10% per annum reckoned half-yearly is? Choose the correct option
A) 8.0 B) 3.25 C) 9.15 D) 3.13 E) 2.0 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">(1/400) * 1_300</gadget>
<output>13/4 = around 3.25</output>
<result>B</result> | B | 3.25 | The difference between simple and compound interest on Rs. 1300 for one year at 10% per annum reckoned half-yearly is? | {
"A": "8.0",
"B": "3.25",
"C": "9.15",
"D": "3.13",
"E": "2.0"
} | multiply(subtract(power(add(divide(divide(10, const_2), const_100), const_1), const_2), add(divide(10, const_100), const_1)), 1300) | divide(n1,const_2)|divide(n1,const_100)|add(#1,const_1)|divide(#0,const_100)|add(#3,const_1)|power(#4,const_2)|subtract(#5,#2)|multiply(n0,#6) | s . i . = ( 1300 * 10 * 1 ) / 100 = rs . 130 c . i . = [ 1300 * ( 1 + 5 / 100 ) 2 - 1300 ] = rs . 133.25 difference = ( 133.25 - 130 ) = rs . 3.25 answer : b | gain |
math_qa__4CmQ2ZEIAqKCG5jV | Ravi and Kavi start a business by investing ₹ 3000 and ₹ 72000, respectively. Find the ratio of their profits at the end of year.
Pick one: A) 2 : 24 B) 5 : 24 C) 7 : 24 D) 1 : 24 E) 3 : 24 | <gadget id="calculator">3_000 / 72_000</gadget>
<output>1/24 = around 0.041667</output>
<result>D</result> | D | 0.041667 | Ravi and Kavi start a business by investing ₹ 3000 and ₹ 72000, respectively. Find the ratio of their profits at the end of year. | {
"A": "2 : 24",
"B": "5 : 24",
"C": "7 : 24",
"D": "1 : 24",
"E": "3 : 24"
} | divide(3000, 72000) | divide(n0,n1) | ratio of profit = ratio of investments = 3000 : 72000 = 1 : 24 answer : d | gain |
math_qa__1Jy5KkOskUFSVlCd | In August,a cricket team that played 120 matches won 30% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average? Options:
A) 40 B) 55 C) 68 D) 80 E) 98 | <gadget id="calculator">52 / 100</gadget>
<output>13/25 = around 0.52</output>
<gadget id="calculator">(13/25) * 120</gadget>
<output>312/5 = around 62.4</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 120</gadget>
<output>36</output>
<gadget id="calculator">(312/5) - 36</gadget>
<output>132/5 = around 26.4</output>
<gadget id="calculator">1 - (13/25)</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">(132/5) / (12/25)</gadget>
<output>55</output>
<result>B</result> | B | 55 | In August,a cricket team that played 120 matches won 30% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average? | {
"A": "40",
"B": "55",
"C": "68",
"D": "80",
"E": "98"
} | divide(subtract(multiply(divide(52, const_100), 120), multiply(divide(30, const_100), 120)), subtract(const_1, divide(52, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|multiply(n0,#1)|subtract(const_1,#0)|subtract(#2,#3)|divide(#5,#4)| | "let the no of matches played more = x so , ( 120 + x ) * 52 / 100 = 36 + x by solving we get x = 55 answer : b" | general |
math_qa__09ZsK7x9ElDwkM5B | Jim’s Taxi Service charges an initial fee of $2.05 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?
Pick: A) $ 5.20 B) $ 4.45 C) $ 4.80 D) $ 5.05 E) $ 5.40 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3.6 / (2/5)</gadget>
<output>9</output>
<gadget id="calculator">0.35 * 9</gadget>
<output>3.15</output>
<gadget id="calculator">2.05 + 3.15</gadget>
<output>5.2</output>
<result>A</result> | A | 5.2 | Jim’s Taxi Service charges an initial fee of $2.05 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? | {
"A": "$ 5.20",
"B": "$ 4.45",
"C": "$ 4.80",
"D": "$ 5.05",
"E": "$ 5.40"
} | add(2.05, multiply(0.35, divide(3.6, divide(2, 5)))) | divide(n2,n3)|divide(n4,#0)|multiply(n1,#1)|add(n0,#2) | let the fixed charge of jim ’ s taxi service = 2.05 $ and charge per 2 / 5 mile ( . 4 mile ) = . 35 $ total charge for a trip of 3.6 miles = 2.05 + ( 3.6 / . 4 ) * . 35 = 2.05 + 9 * . 35 = 5.2 $ answer a | general |
math_qa__aJUdVihFdjUYLmAV | If a = 105 and a^3 = 21 × 25 × 45 × w, what is the value of w? Choose the most appropriate option.
A) 35 B) 42 C) 45 D) 49 E) 54 | <gadget id="calculator">105 ** 3</gadget>
<output>1_157_625</output>
<gadget id="calculator">21 * 25</gadget>
<output>525</output>
<gadget id="calculator">525 * 45</gadget>
<output>23_625</output>
<gadget id="calculator">1_157_625 / 23_625</gadget>
<output>49</output>
<result>D</result> | D | 49 | If a = 105 and a^3 = 21 × 25 × 45 × w, what is the value of w? | {
"A": "35",
"B": "42",
"C": "45",
"D": "49",
"E": "54"
} | divide(power(105, 3), multiply(multiply(21, 25), 45)) | multiply(n2,n3)|power(n0,n1)|multiply(n4,#0)|divide(#1,#2)| | "a = 105 = 3 * 5 * 7 a ^ 3 = 21 × 25 × 45 × w = > a ^ 3 = ( 7 * 3 ) x ( 5 * 5 ) x ( 3 ^ 2 * 5 ) x w = > a ^ 3 = 3 ^ 3 * 5 ^ 3 * 7 x w = > ( 3 * 5 * 7 ) ^ 3 = 3 ^ 3 * 5 ^ 3 * 7 x w w = 7 ^ 2 = 49 answer d" | general |
math_qa__vMtC7eUAOw4xK3J4 | A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 40 miles per gallon, and from Town B to Town C, the car averaged 50 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C?
Choose the correct choice from the following.
A) 42.85
B) 40
C) 35
D) 41
E) 39 | <gadget id="calculator">50 * 10</gadget>
<output>500</output>
<gadget id="calculator">500 / 2</gadget>
<output>250</output>
<gadget id="calculator">500 + 250</gadget>
<output>750</output>
<gadget id="calculator">500 / 40</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">250 / 50</gadget>
<output>5</output>
<gadget id="calculator">(25/2) + 5</gadget>
<output>35/2 = around 17.5</output>
<gadget id="calculator">750 / (35/2)</gadget>
<output>300/7 = around 42.857143</output>
<result>A</result> | A | 42.85 | A certain car traveled twice as many miles from Town A to Town B as it did from Town B to Town C. From Town A to Town B, the car averaged 40 miles per gallon, and from Town B to Town C, the car averaged 50 miles per gallon. What is the average miles per gallon that the car achieved on its trip from Town A through Town B to Town C? | {
"A": "42.85",
"B": "40",
"C": "35",
"D": "41",
"E": "39"
} | divide(add(multiply(50, const_10), divide(multiply(50, const_10), const_2)), add(divide(multiply(50, const_10), 40), divide(divide(multiply(50, const_10), const_2), 50))) | multiply(n1,const_10)|divide(#0,const_2)|divide(#0,n0)|add(#1,#0)|divide(#1,n1)|add(#2,#4)|divide(#3,#5)| | "step 1 ) took lcm of 40 and 50 . . came as 200 . step 2 ) 200 distance between b to c . . . do 200 / 50 hence 4 gallons used step 3 ) twice distance . . hence 200 * 2 = 400 . . . do as above . . 400 / 40 = 10 gallons used step 4 ) total gallons . . 4 + 10 = 14 gallons step ) total miles = 200 + 400 = 600 miles hence . . average of whole journey = 600 / 14 which comes to 42.85 answer : a" | general |
math_qa__wsEBdjey8UWUFEnI | A car averages 45 mph for the first 4 hours of a trip and averages 75 mph for each additional hour. The average speed for the entire trip was 65 mph. How many hours long is the trip?
Choose the correct option:
A) 12 B) 11 C) 10 D) 9 E) 8 | <gadget id="calculator">65 * 4</gadget>
<output>260</output>
<gadget id="calculator">45 * 4</gadget>
<output>180</output>
<gadget id="calculator">260 - 180</gadget>
<output>80</output>
<gadget id="calculator">75 - 65</gadget>
<output>10</output>
<gadget id="calculator">80 / 10</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<result>A</result> | A | 12 | A car averages 45 mph for the first 4 hours of a trip and averages 75 mph for each additional hour. The average speed for the entire trip was 65 mph. How many hours long is the trip? | {
"A": "12",
"B": "11",
"C": "10",
"D": "9",
"E": "8"
} | add(divide(subtract(multiply(65, 4), multiply(45, 4)), subtract(75, 65)), 4) | multiply(n3,n1)|multiply(n0,n1)|subtract(n2,n3)|subtract(#0,#1)|divide(#3,#2)|add(n1,#4)| | "let the time for which car averages 75 mph = t 65 * ( t + 4 ) = 45 * 4 + 75 t = > 10 t = 80 = > t = 8 total duration of the trip = 8 + 4 = 12 answer a" | general |
math_qa__ayqrVL434jqk1lOF | The cricket team of 11members is 25yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ? Answers: A) 21 B) 22 C) 23 D) 25 E) 28 | <gadget id="calculator">25 + 3</gadget>
<output>28</output>
<gadget id="calculator">28 + 25</gadget>
<output>53</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">53 - 9</gadget>
<output>44</output>
<gadget id="calculator">11 - 9</gadget>
<output>2</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<result>B</result> | B | 22 | The cricket team of 11members is 25yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ? | {
"A": "21",
"B": "22",
"C": "23",
"D": "25",
"E": "28"
} | divide(subtract(add(add(25, const_3), 25), subtract(11, 2)), subtract(11, subtract(11, 2))) | add(n1,const_3)|subtract(n0,n3)|add(n1,#0)|subtract(n0,#1)|subtract(#2,#1)|divide(#4,#3) | let the average age of the whole team be x years . 11 x - ( 25 + 28 ) = 9 ( x - 1 ) = > 11 x - 9 x = 44 = > 2 x = 44 = > x = 22 . so , average age of the team is 22 years . b | general |
math_qa__ElE1TM3KwsQcxM6t | The speed of a boat in still water is 24 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 15 minutes is
Select the correct option.
A) 1.6 km
B) 2 km
C) 3.6 km
D) 6.75 km
E) none of these | <gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">24 + 3</gadget>
<output>27</output>
<gadget id="calculator">(1/4) * 27</gadget>
<output>27/4 = around 6.75</output>
<result>D</result> | D | 6.75 | The speed of a boat in still water is 24 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 15 minutes is | {
"A": "1.6 km",
"B": "2 km",
"C": "3.6 km",
"D": "6.75 km",
"E": "none of these"
} | multiply(divide(15, const_60), add(24, 3)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstreams = ( 24 + 3 ) kmph = 27 kmph . distance travelled = ( 27 x 15 / 60 ) km = 6.75 km option d" | physics |
math_qa__fL36tSR1a3oGFDQD | louie takes out a 3 - month loan of $ 2000 . the lender charges him 10 % interest per month compounded monthly . the terms of the loan state that louie must repay the loan in 3 equal monthly payments . to the nearest dollar , how much does louie have to pay each month ? Select:
A) 333 B) 383 C) 402 D) 433 E) 804 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">2_000 * (11/10)</gadget>
<output>2_200</output>
<gadget id="calculator">2_200 * (11/10)</gadget>
<output>2_420</output>
<gadget id="calculator">2_420 / 3</gadget>
<output>2_420/3 = around 806.666667</output>
<result>E</result> | E | 804 | louie takes out a 3 - month loan of $ 2000 . the lender charges him 10 % interest per month compounded monthly . the terms of the loan state that louie must repay the loan in 3 equal monthly payments . to the nearest dollar , how much does louie have to pay each month ? | {
"A": "333",
"B": "383",
"C": "402",
"D": "433",
"E": "804"
} | divide(multiply(multiply(2000, add(const_1, divide(const_1, const_10))), add(const_1, divide(const_1, const_10))), 3) | divide(const_1,const_10)|add(#0,const_1)|multiply(n1,#1)|multiply(#1,#2)|divide(#3,n0) | here ' s the calculation for that case , assume monthly payment is x . after 1 st month : ( 2000 ) ( 1.1 ) - x = 2200 - x after 2 nd month : ( 2200 - x ) ( 1.1 ) - x = 2420 - 2.21 x after 3 rd month : ( 2420 - 2.21 x ) ( 1.1 ) - x = 2662 - 3.31 x now , the amount after the last payment in 3 rd month must bring the total to 0 . hence : 2662 - 3.31 x = 0 x = 2662 / 3.31 = 804 answer e | general |
math_qa__4byT6GRf2xsOY55r | Some of 50%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 45%. What fraction of the original paint was replaced? Choose the correct answer:
A) 1 / 30 B) 1 / 5 C) 2 / 3 D) 3 / 4 E) 4 / 5 | <gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(9/20) - (1/2)</gadget>
<output>-1/20 = around -0.05</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) - (1/2)</gadget>
<output>-1/4 = around -0.25</output>
<gadget id="calculator">(-1/20) / (-1/4)</gadget>
<output>1/5 = around 0.2</output>
<result>B</result> | B | 0.2 | Some of 50%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 45%. What fraction of the original paint was replaced? | {
"A": "1 / 30",
"B": "1 / 5",
"C": "2 / 3",
"D": "3 / 4",
"E": "4 / 5"
} | divide(subtract(divide(45, const_100), divide(50, const_100)), subtract(divide(25, const_100), divide(50, const_100))) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(#2,#1)|divide(#3,#4)| | "45 % is 20 % - points above 25 % and 5 % - points below 50 % . thus the ratio of 25 % - solution to 50 % - solution is 1 : 4 . 1 / 5 of the original paint was replaced . the answer is b ." | gain |
math_qa__p5gh7PhO20tLFwzf | If a certain toy store's revenue in November was 3/5 of its revenue in December and its revenue in January was 1/3 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
Choose the correct answer:
A) 5 / 2 B) 7 / 2 C) 10 / 3 D) 15 / 4 E) 25 / 3 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(3/5) * (1/3)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/5) + (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) / 2</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 / (2/5)</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | If a certain toy store's revenue in November was 3/5 of its revenue in December and its revenue in January was 1/3 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January? | {
"A": "5 / 2",
"B": "7 / 2",
"C": "10 / 3",
"D": "15 / 4",
"E": "25 / 3"
} | divide(1, divide(add(divide(3, 5), multiply(divide(3, 5), divide(1, 3))), const_2)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)|add(#0,#2)|divide(#3,const_2)|divide(n2,#4)| | "n = 3 d / 5 j = n / 3 = d / 5 the average of november and january is ( n + j ) / 2 = 4 d / 5 / 2 = 2 d / 5 d is 5 / 2 times the average of november and january . the answer is a ." | general |
math_qa__sOwqqcopp0M2eWhF | The jogging track in a sports complex is 528 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? Choose the correct choice from the following answers
A) 5.29 min B) 3.84 min C) 5.08 min D) 9.28 min E) 5.988 min | <gadget id="calculator">528 / 1_000</gadget>
<output>66/125 = around 0.528</output>
<gadget id="calculator">4.5 + 3.75</gadget>
<output>8.25</output>
<gadget id="calculator">(66/125) / 8.25</gadget>
<output>0.064</output>
<gadget id="calculator">0.064 * 60</gadget>
<output>3.84</output>
<result>B</result> | B | 3.84 | The jogging track in a sports complex is 528 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? | {
"A": "5.29 min",
"B": "3.84 min",
"C": "5.08 min",
"D": "9.28 min",
"E": "5.988 min"
} | multiply(divide(divide(528, const_1000), add(4.5, 3.75)), const_60) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_60)| | "clearly , the two will meet when they are 528 m apart . to be ( 4.5 + 3.75 ) = 8.25 km apart , they take 1 hour . to be 528 m apart , they take ( 100 / 825 * 528 / 1000 ) hrs = ( 528 / 8250 * 60 ) min = 3.84 min . answer : b" | general |
math_qa__sXQD1z7cAjt9sOXI | If 45% of z is 72% of y and y is 75% of x, what percent of x is z?
Options.
A) 200 B) 120 C) 100 D) 65 E) 50 | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">72 / 100</gadget>
<output>18/25 = around 0.72</output>
<gadget id="calculator">(9/20) / (18/25)</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">(3/4) / (5/8)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 100</gadget>
<output>120</output>
<result>B</result> | B | 120 | If 45% of z is 72% of y and y is 75% of x, what percent of x is z? | {
"A": "200",
"B": "120",
"C": "100",
"D": "65",
"E": "50"
} | multiply(divide(divide(75, const_100), divide(divide(45, const_100), divide(72, const_100))), const_100) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|divide(#1,#2)|divide(#0,#3)|multiply(#4,const_100)| | "( 45 / 100 ) z = ( 72 / 100 ) y and y = ( 75 / 100 ) x i . e . y = ( 3 / 4 ) x i . e . ( 45 / 100 ) z = ( 72 / 100 ) * ( 3 / 4 ) x i . e . z = ( 72 * 3 ) x / ( 45 * 4 ) i . e . z = ( 1.2 ) x = ( 120 / 100 ) x i . e . z is 120 % of x answer : option b" | gain |
math_qa__MenSRahvBipHX5m3 | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 420 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? Choose the correct choice from the following choices:
A) 600 B) 620 C) 500 D) 520 E) 840 | <gadget id="calculator">420 * 2</gadget>
<output>840</output>
<result>E</result> | E | 840 | On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 420 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school? | {
"A": "600",
"B": "620",
"C": "500",
"D": "520",
"E": "840"
} | multiply(420, const_2) | multiply(n0,const_2)| | "let the number of children in the school be x . since each child gets 2 bananas , total number of bananas = 2 x . 2 x / ( x - 420 ) = 2 + 2 ( extra ) = > 2 x - 840 = x = > x = 840 . answer : e" | general |
math_qa__kWyngAo8LuIIoRna | Two trains 111 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? Choose the most appropriate option:
A) 4.85 B) 7.85 C) 6.85 D) 5.85 E) 6.15 | <gadget id="calculator">111 + 165</gadget>
<output>276</output>
<gadget id="calculator">80 + 65</gadget>
<output>145</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">145 * (5/18)</gadget>
<output>725/18 = around 40.277778</output>
<gadget id="calculator">276 / (725/18)</gadget>
<output>4_968/725 = around 6.852414</output>
<result>C</result> | C | 6.85 | Two trains 111 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? | {
"A": "4.85",
"B": "7.85",
"C": "6.85",
"D": "5.85",
"E": "6.15"
} | divide(add(111, 165), multiply(add(80, 65), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2) | t = ( 111 + 165 ) / ( 80 + 65 ) * 18 / 5 t = 6.85 answer : c | physics |
math_qa__z9QckizBg0Gdm06w | Working alone, Mary can pave a driveway in 5 hours and Hillary can pave the same driveway in 2 hours. When they work together, Mary thrives on teamwork so her rate increases by 33.33%, but Hillary becomes distracted and her rate decreases by 50%. If they both work together, how many hours will it take to pave the driveway? Choose the correct option.
A) 2 hours B) 4 hours C) 5 hours D) 6 hours E) 7 hours | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">33.33 / 100</gadget>
<output>0.3333</output>
<gadget id="calculator">0.3333 + 1</gadget>
<output>1.3333</output>
<gadget id="calculator">(1/5) * 1.3333</gadget>
<output>0.26666</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * (1/2)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">0.26666 + (1/4)</gadget>
<output>0.51666</output>
<gadget id="calculator">1 / 0.51666</gadget>
<output>1.935509</output>
<result>A</result> | A | 2 | Working alone, Mary can pave a driveway in 5 hours and Hillary can pave the same driveway in 2 hours. When they work together, Mary thrives on teamwork so her rate increases by 33.33%, but Hillary becomes distracted and her rate decreases by 50%. If they both work together, how many hours will it take to pave the driveway? | {
"A": "2 hours",
"B": "4 hours",
"C": "5 hours",
"D": "6 hours",
"E": "7 hours"
} | inverse(add(multiply(divide(const_1, 5), add(divide(33.33, const_100), const_1)), multiply(divide(const_1, 2), divide(50, const_100)))) | divide(n2,const_100)|divide(const_1,n0)|divide(const_1,n1)|divide(n3,const_100)|add(#0,const_1)|multiply(#2,#3)|multiply(#4,#1)|add(#6,#5)|inverse(#7)| | "initial working rates : mary = 1 / 5 per hour hillary = 1 / 2 per hour rate when working together : mary = 1 / 5 + ( 1 / 3 * 1 / 5 ) = 1 / 4 per hour hillary = 1 / 2 - ( 1 / 2 * 1 / 2 ) = 1 / 4 per hour together they work 1 / 4 + 1 / 4 = 1 / 2 per hour so they will need 2 hours to complete the driveway . the correct answer is a ." | gain |
math_qa__H04yZlQ7a3wRqqD1 | Some of 50%-intensity red paint is replaced with 20% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced? Options
A) 1 / 30 B) 1 / 5 C) 2 / 3 D) 3 / 4 E) 4 / 5 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/10) - (1/2)</gadget>
<output>-1/5 = around -0.2</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) - (1/2)</gadget>
<output>-3/10 = around -0.3</output>
<gadget id="calculator">(-1/5) / (-3/10)</gadget>
<output>2/3 = around 0.666667</output>
<result>C</result> | C | 0.666667 | Some of 50%-intensity red paint is replaced with 20% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced? | {
"A": "1 / 30",
"B": "1 / 5",
"C": "2 / 3",
"D": "3 / 4",
"E": "4 / 5"
} | divide(subtract(divide(30, const_100), divide(50, const_100)), subtract(divide(20, const_100), divide(50, const_100))) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(#2,#1)|divide(#3,#4) | 30 % is 10 % - points above 20 % and 20 % - points below 50 % . thus the ratio of 25 % - solution to 50 % - solution is 2 : 1 . 2 / 3 of the original paint was replaced . the answer is c . | gain |
math_qa__exLd65vjcxdIvMOM | Two women started running simultaneously around a circular track of length 1800 m from the same point at speeds of 10 km/hr and 20 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions? Choose the correct choice from the following choices
A) 72 B) 74 C) 76 D) 78 E) 80 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">10 * (5/18)</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">20 * (5/18)</gadget>
<output>50/9 = around 5.555556</output>
<gadget id="calculator">(25/9) + (50/9)</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">1_800 / (25/3)</gadget>
<output>216</output>
<gadget id="calculator">216 / 3</gadget>
<output>72</output>
<result>A</result> | A | 72 | Two women started running simultaneously around a circular track of length 1800 m from the same point at speeds of 10 km/hr and 20 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions? | {
"A": "72",
"B": "74",
"C": "76",
"D": "78",
"E": "80"
} | divide(divide(1800, add(multiply(10, const_0_2778), multiply(20, const_0_2778))), const_3) | multiply(n1,const_0_2778)|multiply(n2,const_0_2778)|add(#0,#1)|divide(n0,#2)|divide(#3,const_3) | time taken to meet for the first time anywhere on the track = length of the track / relative speed = 1800 / ( 30 + 60 ) 5 / 18 = 1800 * 18 / 90 * 5 = 72 seconds . answer : a | physics |
math_qa__6f8sGgScnBWWpt0R | The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 20 runs. Find his average in all the 30 matches? Choose the most appropriate option: A) 31 B) 46 C) 88 D) 33.33 E) 12 | <gadget id="calculator">40 * 20</gadget>
<output>800</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">800 + 200</gadget>
<output>1_000</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">1_000 / 30</gadget>
<output>100/3 = around 33.333333</output>
<result>D</result> | D | 33.33 | The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 20 runs. Find his average in all the 30 matches? | {
"A": "31",
"B": "46",
"C": "88",
"D": "33.33",
"E": "12"
} | divide(add(multiply(40, 20), multiply(20, 10)), add(20, 10)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "total score of the batsman in 20 matches = 800 . total score of the batsman in the next 10 matches = 200 . total score of the batsman in the 30 matches = 1000 . average score of the batsman = 1000 / 30 = 33.33 answer : d" | general |
math_qa__UxDhQUsI2BiG7Cmi | A goods train runs at the speed of 72 kmph and crosses a 240 m long platform in 26 seconds. What is the length of the goods train? Pick.
A) 230 m B) 270 m C) 643 m D) 280 m E) 270 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">240 / 20</gadget>
<output>12</output>
<gadget id="calculator">26 - 12</gadget>
<output>14</output>
<gadget id="calculator">14 * 20</gadget>
<output>280</output>
<result>D</result> | D | 280 | A goods train runs at the speed of 72 kmph and crosses a 240 m long platform in 26 seconds. What is the length of the goods train? | {
"A": "230 m",
"B": "270 m",
"C": "643 m",
"D": "280 m",
"E": "270 m"
} | multiply(subtract(26, divide(240, multiply(const_0_2778, 72))), multiply(const_0_2778, 72)) | multiply(n0,const_0_2778)|divide(n1,#0)|subtract(n2,#1)|multiply(#0,#2)| | "speed = ( 72 x 5 / 18 ) m / sec = 20 m / sec . time = 26 sec . let the length of the train be x metres . then , x + 240 / 26 = 20 x + 240 = 520 x = 280 . answer : d" | physics |
math_qa__SMs4rek4D5N1Trau | How much time will a train of length 300 m moving at a speed of 72 kmph take to cross another train of length 500 m, moving at 36 kmph in the same direction? Choose the correct choice from the following answers:
A) 50
B) 80
C) 88
D) 76
E) 12 | <gadget id="calculator">300 + 500</gadget>
<output>800</output>
<gadget id="calculator">72 - 36</gadget>
<output>36</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">800 / 10</gadget>
<output>80</output>
<result>B</result> | B | 80 | How much time will a train of length 300 m moving at a speed of 72 kmph take to cross another train of length 500 m, moving at 36 kmph in the same direction? | {
"A": "50",
"B": "80",
"C": "88",
"D": "76",
"E": "12"
} | divide(add(300, 500), multiply(subtract(72, 36), const_0_2778)) | add(n0,n2)|subtract(n1,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "the distance to be covered = sum of their lengths = 300 + 500 = 800 m . relative speed = 72 - 36 = 36 kmph = 36 * 5 / 18 = 10 mps . time required = d / s = 800 / 10 = 80 sec . answer : b" | physics |
math_qa__vk3eIHUU7mSRCdPY | A certain number when divided by 39 leaves a remainder 17, what is the remainder when the same number is divided by 13? Select the correct option:
A) 7 B) 8 C) 9 D) 6 E) 4 | <gadget id="calculator">17 % 13</gadget>
<output>4</output>
<result>E</result> | E | 4 | A certain number when divided by 39 leaves a remainder 17, what is the remainder when the same number is divided by 13? | {
"A": "7",
"B": "8",
"C": "9",
"D": "6",
"E": "4"
} | reminder(17, 13) | reminder(n1,n2)| | "explanation : 39 + 17 = 56 / 13 = 4 ( remainder ) answer : e" | general |
math_qa__NcObEwd5w42hrx2B | X, Y and Z, each working alone can complete a job in 2, 4 and 6 days respectively. If all three of them work together to complete a job and earn $2000, what will be Z's share of the earnings? Options
A) $ 1080.90 B) $ 1000.90 C) $ 1070.90 D) $ 1050.90 E) $ 1090.90 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) + (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(3/4) + (1/6)</gadget>
<output>11/12 = around 0.916667</output>
<gadget id="calculator">2_000 / (11/12)</gadget>
<output>24_000/11 = around 2_181.818182</output>
<gadget id="calculator">(24_000/11) * (1/2)</gadget>
<output>12_000/11 = around 1_090.909091</output>
<result>E</result> | E | 1,090.9 | X, Y and Z, each working alone can complete a job in 2, 4 and 6 days respectively. If all three of them work together to complete a job and earn $2000, what will be Z's share of the earnings? | {
"A": "$ 1080.90",
"B": "$ 1000.90",
"C": "$ 1070.90",
"D": "$ 1050.90",
"E": "$ 1090.90"
} | multiply(divide(2000, add(add(inverse(2), inverse(4)), inverse(6))), inverse(2)) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|divide(n3,#4)|multiply(#5,#0) | the dollars earned will be in the same ratio as amount of work done 1 day work of z is 1 / 6 ( or 2 / 12 ) 1 day work of the combined workforce is ( 1 / 2 + 1 / 4 + 1 / 6 ) = 11 / 12 z ' s contribution is 2 / 9 of the combined effort translating effort to $ = 6 / 11 * 2000 = $ 1090.90 hence : e | physics |
math_qa__ZwrChkrRktQCZ8QB | The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: Select:
A) 504
B) 536
C) 544
D) 548
E) 568 | <gadget id="calculator">54 * 10</gadget>
<output>540</output>
<result>D</result> | D | 548 | The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: | {
"A": "504",
"B": "536",
"C": "544",
"D": "548",
"E": "568"
} | multiply(54, const_10) | multiply(n3,const_10)| | "required number = ( l . c . m . of 12 , 15 , 20 , 54 ) + 8 = 540 + 8 = 548 . answer : option d" | general |
math_qa__ifGpUwQUu0CJQFfU | Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 30 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? Choose the correct choice from the following answers:
A) 15 seconds B) 18 seconds C) 25 seconds D) 30 seconds E) 45 seconds | <gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 30 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? | {
"A": "15 seconds",
"B": "18 seconds",
"C": "25 seconds",
"D": "30 seconds",
"E": "45 seconds"
} | divide(30, subtract(5, 3)) | subtract(n1,n2)|divide(n0,#0)| | "used pluging in method say t is the time for cristina to catch up with nicky , the equation will be as under : for nicky = n = 3 * t + 30 for cristina = c = 5 * t @ t = 15 , n = 75 c = 75 right answer ans : a" | physics |
math_qa__HyNOQ8pCSmEKgIuV | How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6.6 m x 22.5 cm? Choose the correct choice from the following answers.
A) 6400 B) 6410 C) 6440 D) 6500 E) 7040 | <gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">6.6 * 100</gadget>
<output>660</output>
<gadget id="calculator">800 * 660</gadget>
<output>528_000</output>
<gadget id="calculator">528_000 * 22.5</gadget>
<output>11_880_000</output>
<gadget id="calculator">25 * 11.25</gadget>
<output>281.25</output>
<gadget id="calculator">281.25 * 6</gadget>
<output>1_687.5</output>
<gadget id="calculator">11_880_000 / 1_687.5</gadget>
<output>7_040</output>
<result>E</result> | E | 7,040 | How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6.6 m x 22.5 cm? | {
"A": "6400",
"B": "6410",
"C": "6440",
"D": "6500",
"E": "7040"
} | divide(multiply(multiply(multiply(8, const_100), multiply(6.6, const_100)), 22.5), multiply(multiply(25, 11.25), 6)) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(n2,#2)|multiply(n5,#3)|divide(#5,#4) | number of bricks = volume of wall / volume of bricks = 800 x 660 x 22.5 / 25 x 11.25 x 6 = = 7040 answer : e | physics |
math_qa__iTreE0EzOEvdTIuB | The total number of students in Grades 1 and 2 is 30 more than the total number of students in grades 2 and 5. How much lesser is the number of students in Grade 5 as compared to Grade 1? Choose the correct answer
A) 20 B) 30 C) 10 D) 40 E) 15 | <gadget id="calculator">30 + 5</gadget>
<output>35</output>
<gadget id="calculator">35 + 2</gadget>
<output>37</output>
<gadget id="calculator">37 + 2</gadget>
<output>39</output>
<gadget id="calculator">39 + 2</gadget>
<output>41</output>
<gadget id="calculator">41 + 3</gadget>
<output>44</output>
<gadget id="calculator">44 + 4</gadget>
<output>48</output>
<gadget id="calculator">48 + 12</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>B</result> | B | 30 | The total number of students in Grades 1 and 2 is 30 more than the total number of students in grades 2 and 5. How much lesser is the number of students in Grade 5 as compared to Grade 1? | {
"A": "20",
"B": "30",
"C": "10",
"D": "40",
"E": "15"
} | divide(add(add(add(add(add(add(add(30, 5), 2), 2), 2), const_3), const_4), const_12), 2) | add(n2,n4)|add(n1,#0)|add(n1,#1)|add(n1,#2)|add(#3,const_3)|add(#4,const_4)|add(#5,const_12)|divide(#6,n1) | ( grade 1 + grade 2 ) - ( grade 2 + grade 5 ) = 30 grade 1 - grade 5 = 30 answer : b | general |
math_qa__BharGWizO3phfCWV | A football player scores 5 goals in his fifth match thus increasing his average goals score by 0.2. The total number of goals in his 5 matches would be Choose the correct choice from the following answers.
A) 14 B) 16 C) 18 D) 10 E) 21 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 0.2</gadget>
<output>4</output>
<gadget id="calculator">20 - 4</gadget>
<output>16</output>
<gadget id="calculator">16 + 5</gadget>
<output>21</output>
<result>E</result> | E | 21 | A football player scores 5 goals in his fifth match thus increasing his average goals score by 0.2. The total number of goals in his 5 matches would be | {
"A": "14",
"B": "16",
"C": "18",
"D": "10",
"E": "21"
} | add(subtract(multiply(const_4, 5), multiply(multiply(const_4, 5), 0.2)), 5) | multiply(n0,const_4)|multiply(n2,const_4)|multiply(n1,#1)|subtract(#0,#2)|add(n0,#3)| | "while this question can be solved with a rather straight - forward algebra approach ( as the other posters have noted ) , it can also be solved by testing the answers . one of those numbers must be the total number of goals . . . from a tactical standpoint , it ' s best to test either answer b or answer d , so if the answer is not correct , then you would have a gauge for whether you should gohigherorlowerwith your next test . here , i ' ll start with answer e = 21 goals if . . . . total goals = 21 goals 5 th game = 5 goals 1 st 4 games = 16 goals avg . for 1 st 4 games = 16 / 4 = 4 goal / game avg . for all 5 games = 21 / 5 = 4.2 goals / game this is an exact match for what we ' re told in the prompt , so answer e must be the answer ." | general |
math_qa__yhcSiViqXuiwP0BB | A jeep takes 4 hours to cover a distance of 620 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Choose the correct choice from the following:
A) 148 kmph B) 152 kmph C) 106 kmph D) 103 kmph E) 165 kmph | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 4</gadget>
<output>6</output>
<gadget id="calculator">620 / 6</gadget>
<output>310/3 = around 103.333333</output>
<result>D</result> | D | 103 | A jeep takes 4 hours to cover a distance of 620 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "148 kmph",
"B": "152 kmph",
"C": "106 kmph",
"D": "103 kmph",
"E": "165 kmph"
} | divide(620, multiply(divide(3, 2), 4)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "time = 4 distance = 620 3 / 2 of 4 hours = 4 * 3 / 2 = 6 hours required speed = 620 / 6 = 103 kmph d )" | physics |
math_qa__5pMXqz3rv99roJFT | The mean of 50 observations was 36. It was found later that an observation 60 was wrongly taken as 23. The corrected new mean is? Choose the correct choice from the following options: A) 36.7 B) 36.1 C) 36.5 D) 36.9 E) 36.3 | <gadget id="calculator">36 * 50</gadget>
<output>1_800</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 23</gadget>
<output>25</output>
<gadget id="calculator">1_800 + 25</gadget>
<output>1_825</output>
<gadget id="calculator">1_825 / 50</gadget>
<output>73/2 = around 36.5</output>
<result>A</result> | A | 36.7 | The mean of 50 observations was 36. It was found later that an observation 60 was wrongly taken as 23. The corrected new mean is? | {
"A": "36.7",
"B": "36.1",
"C": "36.5",
"D": "36.9",
"E": "36.3"
} | divide(add(multiply(36, 50), subtract(subtract(50, const_2), 23)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "correct sum = ( 36 * 50 + 60 - 23 ) = 1837 . correct mean = 1837 / 50 = 36.7 answer : a" | general |
math_qa__AdoSa6MMJCzyowGT | In a party every person shakes hands with every other person. If there were a total of 105 handshakes in the party then what is the number of persons present in the party ? Pick.
A) 15
B) 16
C) 17
D) 18
E) 19 | <gadget id="calculator">105 * 2</gadget>
<output>210</output>
<gadget id="calculator">210 * 4</gadget>
<output>840</output>
<gadget id="calculator">840 + 1</gadget>
<output>841</output>
<gadget id="calculator">841 ** (1/2)</gadget>
<output>29</output>
<gadget id="calculator">29 + 1</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<result>A</result> | A | 15 | In a party every person shakes hands with every other person. If there were a total of 105 handshakes in the party then what is the number of persons present in the party ? | {
"A": "15",
"B": "16",
"C": "17",
"D": "18",
"E": "19"
} | divide(add(sqrt(add(multiply(multiply(105, const_2), const_4), const_1)), const_1), const_2) | multiply(n0,const_2)|multiply(#0,const_4)|add(#1,const_1)|sqrt(#2)|add(#3,const_1)|divide(#4,const_2)| | "explanation : let the number of persons be n â ˆ ´ total handshakes = nc 2 = 105 n ( n - 1 ) / 2 = 105 â ˆ ´ n = 15 answer : a" | general |
math_qa__f3WZr5DT8cQ83hVs | At a certain organisation, the number of male members went up by 12% in the year 2001 from year 2000, and the number of females members went down by 4% in the same time period. If the total membership at the organisation went up by 1.2% from the year 2000 to 2001, what was the ratio of male members to female members in the year 2000? Choose the correct choice from the following answers
A) 1 : 2 B) 1 : 3 C) 2 : 3 D) 3 : 2 E) 2 : 1 | <gadget id="calculator">1.2 / 100</gadget>
<output>0.012</output>
<gadget id="calculator">1 + 0.012</gadget>
<output>1.012</output>
<gadget id="calculator">1.012 * 1_000</gadget>
<output>1_012</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 - (1/25)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">(24/25) * 1_000</gadget>
<output>960</output>
<gadget id="calculator">1_012 - 960</gadget>
<output>52</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">(28/25) * 1_000</gadget>
<output>1_120</output>
<gadget id="calculator">1_120 - 1_012</gadget>
<output>108</output>
<gadget id="calculator">52 / 108</gadget>
<output>13/27 = around 0.481481</output>
<result>A</result> | A | 0.5 | At a certain organisation, the number of male members went up by 12% in the year 2001 from year 2000, and the number of females members went down by 4% in the same time period. If the total membership at the organisation went up by 1.2% from the year 2000 to 2001, what was the ratio of male members to female members in the year 2000? | {
"A": "1 : 2",
"B": "1 : 3",
"C": "2 : 3",
"D": "3 : 2",
"E": "2 : 1"
} | divide(subtract(multiply(add(const_1, divide(1.2, const_100)), const_1000), multiply(subtract(const_1, divide(4, const_100)), const_1000)), subtract(multiply(add(const_1, divide(12, const_100)), const_1000), multiply(add(const_1, divide(1.2, const_100)), const_1000))) | divide(n4,const_100)|divide(n3,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#2,const_1)|subtract(const_1,#1)|multiply(#3,const_1000)|multiply(#5,const_1000)|multiply(#4,const_1000)|subtract(#6,#7)|subtract(#8,#6)|divide(#9,#10)| | "men increase by 12 % = = > 1.12 m = males in 2001 women decrease by 4 % = = > 0.96 f = women in 2001 total employees increase by 1.2 % = = > 1.012 * ( m + f ) = total number of employees in 2001 obviously ( males in 2001 ) + ( females in 2001 ) = total number of employees in 2001 1.12 m + 0.96 f = 1.012 * ( m + f ) 1.12 m + 0.96 f = 1.012 m + 1.012 f 1.12 m - 1.012 m = 1.012 f - 0.96 f 0.108 m = 0.052 f m / f = ( 0.052 ) / ( 0.108 ) = 52 / 108 = 1 / 2 answer = ( a )" | other |
math_qa__AMoPw72FXqFeNF1O | There are 7 players in a bowling team with an average weight of 76 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight? Options: A) 78 kg . B) 70 kg . C) 75 kg . D) 70 kg . E) 72 kg . | <gadget id="calculator">7 * 76</gadget>
<output>532</output>
<gadget id="calculator">110 + 60</gadget>
<output>170</output>
<gadget id="calculator">532 + 170</gadget>
<output>702</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">702 / 9</gadget>
<output>78</output>
<result>A</result> | A | 78 | There are 7 players in a bowling team with an average weight of 76 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight? | {
"A": "78 kg .",
"B": "70 kg .",
"C": "75 kg .",
"D": "70 kg .",
"E": "72 kg ."
} | divide(add(multiply(7, 76), add(110, 60)), add(7, const_2)) | add(n2,n3)|add(n0,const_2)|multiply(n0,n1)|add(#0,#2)|divide(#3,#1)| | "the new average will be = ( 76 * 7 + 110 + 60 ) / 9 = 78 kgs a is the answer" | general |
math_qa__r9221b9pRQAF4QfB | Ratio between Rahul and Deepak is 4:3, After 2 Years Rahul age will be 26 years. What is Deepak present age. Choose the correct choice:
A) 14
B) 18
C) 20
D) 22
E) 24 | <gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">24 * 3</gadget>
<output>72</output>
<gadget id="calculator">72 / 4</gadget>
<output>18</output>
<result>B</result> | B | 18 | Ratio between Rahul and Deepak is 4:3, After 2 Years Rahul age will be 26 years. What is Deepak present age. | {
"A": "14",
"B": "18",
"C": "20",
"D": "22",
"E": "24"
} | divide(multiply(subtract(26, 2), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "explanation : present age is 4 x and 3 x , = > 4 x + 2 = 26 = > x = 6 so deepak age is = 3 ( 6 ) = 18 option b" | other |
math_qa__rYB35aLxYqqFLcWq | A train crosses a platform of 130 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?
Choose one
A) 150 B) 887 C) 167 D) 197 E) 230 | <gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">250 * 3</gadget>
<output>750</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">130 * 4</gadget>
<output>520</output>
<gadget id="calculator">750 - 520</gadget>
<output>230</output>
<result>E</result> | E | 230 | A train crosses a platform of 130 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train? | {
"A": "150",
"B": "887",
"C": "167",
"D": "197",
"E": "230"
} | subtract(multiply(250, divide(15, divide(15, const_3))), multiply(130, divide(20, divide(15, const_3)))) | divide(n1,const_3)|divide(n1,#0)|divide(n3,#0)|multiply(n2,#1)|multiply(n0,#2)|subtract(#3,#4)| | "length of the train be ‘ x ’ x + 130 / 15 = x + 250 / 20 20 x + 2600 = 15 x + 3750 5 x = 1150 x = 230 m answer : e" | physics |
math_qa__CCJkXCpLqC6kJoNH | After decreasing 50% in the price of an article costs Rs.620. Find the actual cost of an article? Choose the correct option
A) 1400
B) 1240
C) 1200
D) 1100
E) 1500 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">620 / (1/2)</gadget>
<output>1_240</output>
<result>B</result> | B | 1,240 | After decreasing 50% in the price of an article costs Rs.620. Find the actual cost of an article? | {
"A": "1400",
"B": "1240",
"C": "1200",
"D": "1100",
"E": "1500"
} | divide(620, subtract(const_1, divide(50, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "cp * ( 50 / 100 ) = 620 cp = 12.4 * 100 = > cp = 1240 answer : b" | gain |
math_qa__veawTMudX7iaf3kc | A cube has a volume of 27 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is? Pick.
A) 216 B) 48 C) 64 D) 80 E) 100 | <gadget id="calculator">27 ** (1/3)</gadget>
<output>3</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 ** 3</gadget>
<output>216</output>
<result>A</result> | A | 216 | A cube has a volume of 27 cubic feet. If a similar cube is twice as long, twice as wide, and twice as high, then the volume, in cubic feet of such cube is? | {
"A": "216",
"B": "48",
"C": "64",
"D": "80",
"E": "100"
} | volume_cube(multiply(const_2, cube_edge_by_volume(27))) | cube_edge_by_volume(n0)|multiply(#0,const_2)|volume_cube(#1)| | "volume = 27 = side ^ 3 i . e . side of cube = 3 new cube has dimensions 6 , 6 , and 6 as all sides are twice of teh side of first cube volume = 6 * 6 * 6 = 216 square feet answer : option a" | geometry |
math_qa__yWubhlPYPXL8rI5N | If the compound interest on a certain sum of money for 7 years at 10% per annum be Rs. 993, what would be the simple interest? Options.
A) rs . 880
B) rs . 890
C) rs . 895
D) rs . 2100
E) none | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * 10</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 * 7</gadget>
<output>210_000</output>
<gadget id="calculator">210_000 / 100</gadget>
<output>2_100</output>
<result>D</result> | D | 2,100 | If the compound interest on a certain sum of money for 7 years at 10% per annum be Rs. 993, what would be the simple interest? | {
"A": "rs . 880",
"B": "rs . 890",
"C": "rs . 895",
"D": "rs . 2100",
"E": "none"
} | divide(multiply(multiply(multiply(multiply(const_3.0, const_100), 10), 10), 7), const_100) | multiply(const_3.0,const_100)|multiply(n1,#0)|multiply(n1,#1)|multiply(n0,#2)|divide(#3,const_100)| | "let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 7 yrs = ( 3000 x 10 x 7 ) / 100 = 2100 / - answer : d ." | gain |
math_qa__kuACh6MAE7e8SKr5 | In the Hillside summer camp there are 50 children. 85% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen? Choose the correct choice from the following answers: A) 20 . B) 45 . C) 50 . D) 30 . E) 25 . | <gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) * 50</gadget>
<output>95/2 = around 47.5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 50</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(95/2) + (5/2)</gadget>
<output>50</output>
<result>C</result> | C | 50 | In the Hillside summer camp there are 50 children. 85% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 5% of the total number of children in the camp. How many more boys must she bring to make that happen? | {
"A": "20 .",
"B": "45 .",
"C": "50 .",
"D": "30 .",
"E": "25 ."
} | add(multiply(divide(subtract(const_100, 5), const_100), 50), multiply(divide(5, const_100), 50)) | divide(n2,const_100)|subtract(const_100,n2)|divide(#1,const_100)|multiply(n0,#0)|multiply(n0,#2)|add(#4,#3) | given there are 50 students , 84 % of 50 = 42 boys and remaining 8 girls . now here 84 % are boys and 16 % are girls . now question is asking about how many boys do we need to add , to make the girls percentage to 5 or 8 % . . if we add 50 to existing 45 then the count will be 92 and the girls number will be 8 as it . now boys are 92 % and girls are 8 % . ( out of 100 students = 92 boys + 8 girls ) . imo option c is correct . | general |
math_qa__fLYoWuWFgVEjXhdK | A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many acres Q were used for corn? Pick.
A) 188 B) 258 C) 376 D) 470 E) 517 | <gadget id="calculator">1_000 * 1</gadget>
<output>1_000</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">30 + 4</gadget>
<output>34</output>
<gadget id="calculator">1_000 + 34</gadget>
<output>1_034</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">1_034 / 11</gadget>
<output>94</output>
<gadget id="calculator">94 * 4</gadget>
<output>376</output>
<result>C</result> | C | 376 | A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many acres Q were used for corn? | {
"A": "188",
"B": "258",
"C": "376",
"D": "470",
"E": "517"
} | multiply(divide(add(multiply(const_1000, const_1), add(multiply(const_10, const_3), 4)), add(add(5, 2), 4)), 4) | add(n1,n2)|multiply(const_10,const_3)|multiply(const_1,const_1000)|add(n3,#1)|add(n3,#0)|add(#3,#2)|divide(#5,#4)|multiply(n3,#6) | consider 5 x acres of land used for bean consider 2 x acres of land used for wheat consider 4 x acres of land used for corn total given is 1034 acres 11 x = 1034 x = 94 land used for corn q = 4 * 94 = 376 correct option - c | other |
math_qa__mLURYIghQv3HvNG3 | A sum fetched a total simple interest of $4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? Select
A) $ 8829
B) $ 2840
C) $ 6578
D) $ 7782
E) $ 8925 | <gadget id="calculator">4_016.25 * 100</gadget>
<output>401_625</output>
<gadget id="calculator">401_625 / 9</gadget>
<output>44_625</output>
<gadget id="calculator">44_625 / 5</gadget>
<output>8_925</output>
<result>E</result> | E | 8,925 | A sum fetched a total simple interest of $4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? | {
"A": "$ 8829",
"B": "$ 2840",
"C": "$ 6578",
"D": "$ 7782",
"E": "$ 8925"
} | divide(divide(multiply(4016.25, const_100), 9), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "e 8925 principal = $ 100 x 4016.25 / 9 x 5 = $ 401625 / 45 = $ 8925 ." | gain |
math_qa__MynvXXl29G2Cab3t | A train running at 1/2 of its own speed reached a place in 8 hours. How much time could be saved if the train would have run at its own speed? Choose the correct choice from the following answers.
A) 8 hrs B) 10 hrs C) 4 hrs D) 15 hrs E) 6 hrs | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 8</gadget>
<output>4</output>
<result>C</result> | C | 4 | A train running at 1/2 of its own speed reached a place in 8 hours. How much time could be saved if the train would have run at its own speed? | {
"A": "8 hrs",
"B": "10 hrs",
"C": "4 hrs",
"D": "15 hrs",
"E": "6 hrs"
} | multiply(divide(1, 2), 8) | divide(n0,n1)|multiply(n2,#0) | time taken if run its own speed = 1 / 2 * 8 = 4 hrs time saved = 8 - 4 = 4 hrs answer : c | physics |
math_qa__O3iukzZqrd4MO3yB | The ratio 6 : 5 expressed as a percent equals Options.
A) 12.5 %
B) 40 %
C) 120 %
D) 125 %
E) none | <gadget id="calculator">6 / 5</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 100</gadget>
<output>120</output>
<result>C</result> | C | 120 | The ratio 6 : 5 expressed as a percent equals | {
"A": "12.5 %",
"B": "40 %",
"C": "120 %",
"D": "125 %",
"E": "none"
} | multiply(divide(6, 5), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "solution 6 : 5 = 6 / 5 = ( 6 / 5 x 100 ) % . = 120 % . answer c" | general |
math_qa__2G1no9PY8Bexwr20 | Find the area of a parallelogram with base 20 cm and height 16 cm? Choose the correct choice from the following choices
A) 198 cm 2 B) 320 cm 2 C) 279 cm 2 D) 128 cm 2 E) 297 cm 2 | <gadget id="calculator">20 * 16</gadget>
<output>320</output>
<result>B</result> | B | 320 | Find the area of a parallelogram with base 20 cm and height 16 cm? | {
"A": "198 cm 2",
"B": "320 cm 2",
"C": "279 cm 2",
"D": "128 cm 2",
"E": "297 cm 2"
} | multiply(20, 16) | multiply(n0,n1)| | "area of a parallelogram = base * height = 20 * 16 = 320 cm 2 answer : b" | geometry |
math_qa__c5T4nNJG9FYlWZmj | A part of certain sum of money is invested at 10% per annum and the rest at 16% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is? Choose one: A) 8 : 5 B) 4 : 9 C) 4 : 3 D) 4 : 1 E) 4 : 2 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 10</gadget>
<output>8/5 = around 1.6</output>
<result>A</result> | A | 1.6 | A part of certain sum of money is invested at 10% per annum and the rest at 16% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is? | {
"A": "8 : 5",
"B": "4 : 9",
"C": "4 : 3",
"D": "4 : 1",
"E": "4 : 2"
} | multiply(divide(16, const_100), 10) | divide(n1,const_100)|multiply(n0,#0) | 16 : 10 = 8 : 5 answer : a | gain |
math_qa__hxoD8FBnSHehMFlg | The unit digit in the product (624 * 708 * 913 * 463) is:
Select
A) 2 B) 5 C) 6 D) 8 E) 10 | <gadget id="calculator">624 * 708</gadget>
<output>441_792</output>
<gadget id="calculator">441_792 * 913</gadget>
<output>403_356_096</output>
<gadget id="calculator">403_356_096 * 463</gadget>
<output>186_753_872_448</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">186_753_872_448 - 8</gadget>
<output>186_753_872_440</output>
<gadget id="calculator">186_753_872_448 - 186_753_872_440</gadget>
<output>8</output>
<result>D</result> | D | 8 | The unit digit in the product (624 * 708 * 913 * 463) is: | {
"A": "2",
"B": "5",
"C": "6",
"D": "8",
"E": "10"
} | subtract(multiply(multiply(multiply(624, 708), 913), 463), subtract(multiply(multiply(multiply(624, 708), 913), 463), add(const_4, const_4))) | add(const_4,const_4)|multiply(n0,n1)|multiply(n2,#1)|multiply(n3,#2)|subtract(#3,#0)|subtract(#3,#4)| | "explanation : unit digit in the given product = unit digit in ( 4 * 8 * 3 * 3 ) = 8 answer : d" | general |
math_qa__ojJIw7Z94IeZfzt6 | In the faculty of Reverse-Engineering, 226 second year students study numeric methods, 450 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total?
Pick one
A) 515 . B) 678 . C) 618 . D) 644 . E) 666 . | <gadget id="calculator">226 + 450</gadget>
<output>676</output>
<result>B</result> | B | 678 | In the faculty of Reverse-Engineering, 226 second year students study numeric methods, 450 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 80% of the total? | {
"A": "515 .",
"B": "678 .",
"C": "618 .",
"D": "644 .",
"E": "666 ."
} | add(226, 450) | add(n0,n1)| | "answer is b : 678 solution : total number of students studying both are 450 + 226 - 134 = 542 ( subtracting the 134 since they were included in the both the other numbers already ) . so 80 % of total is 542 , so 100 % is approx . 678 ." | general |
math_qa__8Up7fKWgnYO5ZuaZ | The volume of the sphere Q is (37/64)% less than the volume of sphere P and the volume of sphere R is (19/27)% less than that of sphere Q. By what is the surface area of sphere R less than the surface area of sphere P? Pick one:
A) 77.77 % B) 75 % C) 67.5 % D) 87.5 % E) none of these | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<gadget id="calculator">64 / 4</gadget>
<output>16</output>
<gadget id="calculator">16 - 4</gadget>
<output>12</output>
<gadget id="calculator">12 / 16</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<result>B</result> | B | 75 | The volume of the sphere Q is (37/64)% less than the volume of sphere P and the volume of sphere R is (19/27)% less than that of sphere Q. By what is the surface area of sphere R less than the surface area of sphere P? | {
"A": "77.77 %",
"B": "75 %",
"C": "67.5 %",
"D": "87.5 %",
"E": "none of these"
} | multiply(divide(subtract(divide(64, power(64, divide(const_1, const_3))), power(64, divide(const_1, const_3))), divide(64, power(64, divide(const_1, const_3)))), const_100) | divide(const_1,const_3)|power(n1,#0)|divide(n1,#1)|subtract(#2,#1)|divide(#3,#2)|multiply(#4,const_100) | explanation : let the volume of sphere p be 64 parts . therefore volume of sphere q = > 64 − ( 37 / 64 ) % of 64 . = > 64 − 37 = 27 parts . the volume of r is : - = > 27 − ( 19 / 27 ) × 27 . = > 27 − 19 = 8 parts . volume ratio : = > p : q : r = 64 : 27 : 8 . radius ratio : = > p : q : r = 4 : 3 : 2 . the surface area will be 16 : 9 : 5 . surface area of r is less than the surface area of sphere p . = > 16 k − 4 k = 12 k . now , = > ( 12 k / 16 k ) × 100 . = > 75 % . hence , the surface area of sphere r is less than the surface area of sphere p by 75 % . answer : b | geometry |
math_qa__pdppkfGYAzV2giFk | What is the radius of a circle that has a circumference of 3.14 meters? Choose the correct choice from the following options.
A) 2.5 B) 2 C) 1.5 D) 1 E) 0.5 | <gadget id="calculator">2 * pi</gadget>
<output>2*pi = around 6.283185</output>
<gadget id="calculator">3.14 / (2*pi)</gadget>
<output>1.57/pi = around 0.499747</output>
<result>E</result> | E | 0.5 | What is the radius of a circle that has a circumference of 3.14 meters? | {
"A": "2.5",
"B": "2",
"C": "1.5",
"D": "1",
"E": "0.5"
} | divide(3.14, multiply(const_2, const_pi)) | multiply(const_2,const_pi)|divide(n0,#0) | circumference of a circle = 2 π r . given , circumference = 3.14 meters . therefore , 2 π r = circumference of a circle or , 2 π r = 3.14 . or , 2 ? 3.14 r = 3.14 , [ putting the value of pi ( π ) = 3.14 ] . or , 6.28 r = 3.14 . or , r = 3.14 / 6.28 . or , r = 0.5 . answer : 0.5 meter . correct answer e | physics |
math_qa__7xsc5Sqw5jpfJ1CW | The difference between a two-digit number and the number obtained by interchanging the digit is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1:2? Choose the correct choice from the following options.
A) 8 B) 15 C) 14 D) 12 E) 10 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">21 - 10</gadget>
<output>11</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">36 / 9</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 + 8</gadget>
<output>12</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<result>A</result> | A | 8 | The difference between a two-digit number and the number obtained by interchanging the digit is 36. What is the difference between the sum and the difference of the digits of the number if the ratio between the digits of the number is 1:2? | {
"A": "8",
"B": "15",
"C": "14",
"D": "12",
"E": "10"
} | subtract(add(divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)), multiply(divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)), 2)), subtract(multiply(divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)), 2), divide(36, subtract(subtract(add(multiply(2, const_10), 1), const_10), 2)))) | multiply(n2,const_10)|add(n1,#0)|subtract(#1,const_10)|subtract(#2,n2)|divide(n0,#3)|multiply(n2,#4)|add(#4,#5)|subtract(#5,#4)|subtract(#6,#7) | since the number is greater than the number obtained on reversing the digits , so the ten ' s digit is greater than the unit ' s digit . let the ten ' s and unit ' s digits be 2 x and x respectively . then , ( 10 * 2 x + x ) - ( 10 x + 2 x ) = 36 9 x = 36 x = 4 required difference = ( 2 x + x ) - ( 2 x - x ) = 2 x = 8 . answer a | general |
math_qa__XcYGdoum25YaDAQt | A pharmaceutical company received $3 million in royalties on the first $20 million in sales of and then $9 million in royalties on the next $108 million in sales. By approximately what percentage did the ratio of royalties to sales decrease from the first $20 million in sales to the next $108 million in sales? Select the correct option: A) 8 % B) 15 % C) 45 % D) 52 % E) 56 % | <gadget id="calculator">3 / 20</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>B</result> | B | 15 | A pharmaceutical company received $3 million in royalties on the first $20 million in sales of and then $9 million in royalties on the next $108 million in sales. By approximately what percentage did the ratio of royalties to sales decrease from the first $20 million in sales to the next $108 million in sales? | {
"A": "8 %",
"B": "15 %",
"C": "45 %",
"D": "52 %",
"E": "56 %"
} | multiply(divide(3, 20), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "first ratio = 3 / 20 = 15 % second ratio = ( 3 + 12 ) / ( 9 + 108 ) = 15 / 117 = 12,8 % decrease = 2,2 % 2,2 % / 15 % = 15 % approximately . answer : b" | general |
math_qa__kHccwNXpvMBqhmyK | An internet recently hired 8 new network,in addvertisement 20 network already employed.All new network cam from university A.In addition 75%of computer addvertisement came from same university A.what fraction of original 20 network addvertisement came from same univerity A? pls help to solve Choose the correct choice from the following options: A) 13 / 20 B) 15 / 20 C) 14 / 20 D) 12 / 20 E) 11 / 20 | <gadget id="calculator">8 + 20</gadget>
<output>28</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">28 * (3/4)</gadget>
<output>21</output>
<gadget id="calculator">21 - 8</gadget>
<output>13</output>
<gadget id="calculator">13 / 20</gadget>
<output>13/20 = around 0.65</output>
<result>A</result> | A | 0.65 | An internet recently hired 8 new network,in addvertisement 20 network already employed.All new network cam from university A.In addition 75%of computer addvertisement came from same university A.what fraction of original 20 network addvertisement came from same univerity A? pls help to solve | {
"A": "13 / 20",
"B": "15 / 20",
"C": "14 / 20",
"D": "12 / 20",
"E": "11 / 20"
} | divide(subtract(multiply(add(8, 20), divide(75, const_100)), 8), 20) | add(n0,n1)|divide(n2,const_100)|multiply(#0,#1)|subtract(#2,n0)|divide(#3,n1) | new networks = 8 already employed networks = 20 total networks = 28 computer advt . from uni . a = 28 * ( 75 / 100 ) = 21 out 28 networks 21 came from uni . a among these 21 we know 8 are newly hired so 21 - 8 = 13 networks among previously employed networks came from uni . a answer is : 13 / 20 answer : a | gain |
math_qa__MkgixbzddrACdUWW | Dividing by 3⁄9 and then multiplying by 5⁄6 is the same as dividing by what number? Choose one
A) 31 ⁄ 5
B) 16 ⁄ 5
C) 20 ⁄ 9
D) 5 / 2
E) 5 ⁄ 16 | <gadget id="calculator">9 / 3</gadget>
<output>3</output>
<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">3 * (5/6)</gadget>
<output>5/2 = around 2.5</output>
<result>D</result> | D | 2.5 | Dividing by 3⁄9 and then multiplying by 5⁄6 is the same as dividing by what number? | {
"A": "31 ⁄ 5",
"B": "16 ⁄ 5",
"C": "20 ⁄ 9",
"D": "5 / 2",
"E": "5 ⁄ 16"
} | multiply(divide(9, 3), divide(5, 6)) | divide(n1,n0)|divide(n2,n3)|multiply(#0,#1)| | "say x / 3 / 9 * 5 / 6 = x * 9 / 3 * 5 / 6 = x * 5 / 2 d" | general |
math_qa__9tu9RnnrPNRIEaqh | If it takes a machine 1⁄3 minute to produce one item, how many items will it produce in 2 hours? Choose one: A) 1 ⁄ 3 B) 4 ⁄ 3 C) 80 D) 120 E) 360 | <gadget id="calculator">2 * 60</gadget>
<output>120</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">120 / (1/3)</gadget>
<output>360</output>
<result>E</result> | E | 360 | If it takes a machine 1⁄3 minute to produce one item, how many items will it produce in 2 hours? | {
"A": "1 ⁄ 3",
"B": "4 ⁄ 3",
"C": "80",
"D": "120",
"E": "360"
} | divide(multiply(2, const_60), divide(1, 3)) | divide(n0,n1)|multiply(n2,const_60)|divide(#1,#0)| | "1 item takes 1 / 3 min so it takes 120 min to produce x x / 3 = 120 the x = 360 answer : e" | physics |
math_qa__R3vsDaCSHQXNh9Iu | A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many S apples did each person get before 45 people joined the feast?
Choose the correct choice from the following answers
A) 20 . B) 21 . C) 22 . D) 23 . E) 24 . | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">1_430 / 22</gadget>
<output>65</output>
<gadget id="calculator">65 + 45</gadget>
<output>110</output>
<gadget id="calculator">1_430 / 110</gadget>
<output>13</output>
<gadget id="calculator">13 + 9</gadget>
<output>22</output>
<result>C</result> | C | 22 | A basket of 1430 apples is divided equally among a group of apple lovers. If 45 people join the group, each apple lover would receive 9 apples less. How many S apples did each person get before 45 people joined the feast? | {
"A": "20 .",
"B": "21 .",
"C": "22 .",
"D": "23 .",
"E": "24 ."
} | add(divide(1430, add(divide(1430, add(add(const_10, const_10), const_2)), 45)), 9) | add(const_10,const_10)|add(#0,const_2)|divide(n0,#1)|add(n1,#2)|divide(n0,#3)|add(n2,#4)| | "before solving it algebraically , let us prime factorize 1430 = 2 * 5 * 11 * 13 . since number of apples per person * total persons s = 1430 , the answer should be a factor of 1430 . only c is . and that ' s your answer . c" | general |
math_qa__kiGdeAyNzZvkNBnH | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 7700. What is the share of B ?
Pick.
A) 1100 B) 800 C) 1400 D) 1200 E) none of them | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 3</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 3</gadget>
<output>11</output>
<gadget id="calculator">2 / 11</gadget>
<output>2/11 = around 0.181818</output>
<gadget id="calculator">7_700 * (2/11)</gadget>
<output>1_400</output>
<result>C</result> | C | 1,400 | A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 7700. What is the share of B ? | {
"A": "1100",
"B": "800",
"C": "1400",
"D": "1200",
"E": "none of them"
} | multiply(7700, divide(const_2, add(add(multiply(const_2, 3), multiply(divide(const_2, 3), 3)), 3))) | divide(const_2,n0)|multiply(const_2,n0)|multiply(#0,n0)|add(#1,#2)|add(#3,n0)|divide(const_2,#4)|multiply(n1,#5)| | "let c ' s capital = rs . x . then , b ' s capital = rs . ( 2 / 3 ) x a ’ s capital = rs . ( 3 x ( 2 / 3 ) . x ) = rs . 2 x . ratio of their capitals = 2 x : ( 2 / 3 ) x : x = 6 : 2 : 3 . hence , b ' s share = rs . ( 7700 x ( 2 / 11 ) ) = rs . 1400 . answer is c" | gain |
math_qa__TMmWNBR14X5uEvUe | sobha ' s father was 38 years of age when she was born while her mother was 36 years old when her brother 4 years younger to her was born . what is the difference between the ages of her parents ? Select the correct option:
A) 4 B) 6 C) 8 D) 10 E) 2 | <gadget id="calculator">38 + 4</gadget>
<output>42</output>
<gadget id="calculator">42 - 36</gadget>
<output>6</output>
<result>B</result> | B | 6 | sobha ' s father was 38 years of age when she was born while her mother was 36 years old when her brother 4 years younger to her was born . what is the difference between the ages of her parents ? | {
"A": "4",
"B": "6",
"C": "8",
"D": "10",
"E": "2"
} | subtract(add(38, 4), 36) | add(n0,n2)|subtract(#0,n1) | age of sobha ' s father when sobha was born = 38 age of sobha ' s mother when sobha was born = 36 − 4 = 32 required difference of age = 38 − 32 = 6 answer is b . | general |
math_qa__52hatI4SVROMVylk | If the average (arithmetic mean) of (2a+16) and (3a-8) is 74, what is the value of a? Answers.
A) 25 B) 30 C) 28 D) 36 E) 42 | <gadget id="calculator">74 * 2</gadget>
<output>148</output>
<gadget id="calculator">16 - 8</gadget>
<output>8</output>
<gadget id="calculator">148 - 8</gadget>
<output>140</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">140 / 5</gadget>
<output>28</output>
<result>C</result> | C | 28 | If the average (arithmetic mean) of (2a+16) and (3a-8) is 74, what is the value of a? | {
"A": "25",
"B": "30",
"C": "28",
"D": "36",
"E": "42"
} | divide(subtract(multiply(74, 2), subtract(16, 8)), add(2, 3)) | add(n0,n2)|multiply(n0,n4)|subtract(n1,n3)|subtract(#1,#2)|divide(#3,#0)| | "( ( 2 a + 16 ) + ( 3 a - 8 ) ) / 2 = ( 5 a + 8 ) / 2 = 74 a = 28 the answer is c ." | general |
math_qa__ulVTjB0GfSY8cJLW | The ratio of the arithmetic mean of two numbers to one of the numbers is 5:7. What is the ratio of the smaller number to the larger number? Choose the most appropriate option
A) 2 : 3
B) 2 : 5
C) 3 : 7
D) 4 : 9
E) 5 : 6 | <gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(5/7) - (1/2)</gadget>
<output>3/14 = around 0.214286</output>
<gadget id="calculator">(3/14) * 2</gadget>
<output>3/7 = around 0.428571</output>
<result>C</result> | C | 0.428571 | The ratio of the arithmetic mean of two numbers to one of the numbers is 5:7. What is the ratio of the smaller number to the larger number? | {
"A": "2 : 3",
"B": "2 : 5",
"C": "3 : 7",
"D": "4 : 9",
"E": "5 : 6"
} | multiply(subtract(divide(5, 7), divide(const_1, const_2)), const_2) | divide(n0,n1)|divide(const_1,const_2)|subtract(#0,#1)|multiply(#2,const_2)| | "for two numbers , the arithmetic mean is the middle of the two numbers . the ratio of the mean to the larger number is 5 : 7 , thus the smaller number must have a ratio of 3 . the ratio of the smaller number to the larger number is 3 : 7 . the answer is c ." | other |
math_qa__Hduf4lotHjbj1TKF | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 182 votes. Find the total number of valid votes? Choose the correct choice from the following choices:
A) 455 B) 570 C) 480 D) 520 E) 550 | <gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">182 / (2/5)</gadget>
<output>455</output>
<result>A</result> | A | 455 | In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 182 votes. Find the total number of valid votes? | {
"A": "455",
"B": "570",
"C": "480",
"D": "520",
"E": "550"
} | divide(182, divide(subtract(70, subtract(const_100, 70)), const_100)) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)| | "let the total number of valid votes be x . 70 % of x = 70 / 100 * x = 7 x / 10 number of votes secured by the other candidate = x - 7 x / 100 = 3 x / 10 given , 7 x / 10 - 3 x / 10 = 182 = > 4 x / 10 = 182 = > 4 x = 1820 = > x = 455 . answer : a" | gain |
math_qa__r79YZFZEV1tV8Dnu | Find the number which is nearest to 457 and is exactly divisible by 11. Pick:
A) 450 B) 451 C) 460 D) 462 E) none | <gadget id="calculator">457 % 11</gadget>
<output>6</output>
<gadget id="calculator">11 - 6</gadget>
<output>5</output>
<gadget id="calculator">457 + 5</gadget>
<output>462</output>
<result>D</result> | D | 462 | Find the number which is nearest to 457 and is exactly divisible by 11. | {
"A": "450",
"B": "451",
"C": "460",
"D": "462",
"E": "none"
} | add(457, subtract(11, reminder(457, 11))) | reminder(n0,n1)|subtract(n1,#0)|add(n0,#1)| | "solution on dividing 457 by 11 , remainder is 6 . required number is either 451 or 462 nearest to 456 is = 462 . answer d" | general |
math_qa__zLB4s1Ky3PV8IHuS | A cycle is bought for Rs.450 and sold for Rs.520, find the gain percent? Choose the correct choice from the following answers.
A) 18 B) 14 C) 20 D) 15 E) 15.55 | <gadget id="calculator">520 - 450</gadget>
<output>70</output>
<gadget id="calculator">70 / 450</gadget>
<output>7/45 = around 0.155556</output>
<gadget id="calculator">(7/45) * 100</gadget>
<output>140/9 = around 15.555556</output>
<result>E</result> | E | 15.55 | A cycle is bought for Rs.450 and sold for Rs.520, find the gain percent? | {
"A": "18",
"B": "14",
"C": "20",
"D": "15",
"E": "15.55"
} | multiply(divide(subtract(520, 450), 450), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "450 - - - - 70 100 - - - - ? = > 15.55 % answer : e" | gain |
math_qa__3C4juFxbvB7hcGKC | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration R of the acid in the mixture? Choose one.
A) 1 / 2
B) 1 / 3
C) 1 / 4
D) 1 / 6
E) 1 / 5 | <gadget id="calculator">150 * 30</gadget>
<output>4_500</output>
<gadget id="calculator">4_500 / 100</gadget>
<output>45</output>
<gadget id="calculator">400 * 12</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">45 + 48</gadget>
<output>93</output>
<gadget id="calculator">150 + 400</gadget>
<output>550</output>
<gadget id="calculator">93 / 550</gadget>
<output>93/550 = around 0.169091</output>
<result>D</result> | D | 0.166667 | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration R of the acid in the mixture? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 6",
"E": "1 / 5"
} | divide(add(divide(multiply(150, 30), const_100), divide(multiply(400, 12), const_100)), add(150, 400)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)| | "do not need any computation 30 % - - - - - - - - - - - 21 % - - - - - - - - - 12 % if volume of both sol . were equal the concentration r would be 21 % = 1 / 5 , but 12 % is more than 3 times only possibility is 1 / 6 d" | general |
math_qa__lcrWqszlbnPcFcpw | 12.1212+17.0005 - 9.1103 = ? Choose the correct choice from the following answers:
A) 20.0015 B) 20.0105 C) 20.0115 D) 20.0114 E) none | <gadget id="calculator">12.1212 + 17.0005</gadget>
<output>29.1217</output>
<gadget id="calculator">29.1217 - 9.1103</gadget>
<output>20.0114</output>
<result>D</result> | D | 20.0114 | 12.1212+17.0005 - 9.1103 = ? | {
"A": "20.0015",
"B": "20.0105",
"C": "20.0115",
"D": "20.0114",
"E": "none"
} | subtract(add(12.1212, 17.0005), 9.1103) | add(n0,n1)|subtract(#0,n2) | solution given expression = ( 12.1212 + 17.0005 ) - 9.1103 = ( 29.1217 - 9.1103 ) = 20.0114 . answer d | general |
math_qa__9U75WlNDWTZTic5W | A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 104. What was the number he chose? Choose the correct choice from the following answers: A) 123 B) 121 C) 277 D) 267 E) 120 | <gadget id="calculator">104 + 138</gadget>
<output>242</output>
<gadget id="calculator">242 / 2</gadget>
<output>121</output>
<result>B</result> | B | 121 | A student chose a number, multiplied it by 2, then subtracted 138 from the result and got 104. What was the number he chose? | {
"A": "123",
"B": "121",
"C": "277",
"D": "267",
"E": "120"
} | divide(add(104, 138), 2) | add(n1,n2)|divide(#0,n0)| | "let xx be the number he chose , then 2 â ‹ … x â ˆ ’ 138 = 104 2 â ‹ … x â ˆ ’ 138 = 104 x = 121 answer : b" | general |
math_qa__72xGvEd2a9H2urbj | John want to buy a $100 Trouser at the store, but he think it’s too expensive. Finally, it goes on sale for $75. What is the percent decrease?
Choose the correct choice from the following choices.
A) 20 % B) 30 % C) 40 % D) 25 % E) 60 % | <gadget id="calculator">100 - 75</gadget>
<output>25</output>
<result>D</result> | D | 25 | John want to buy a $100 Trouser at the store, but he think it’s too expensive. Finally, it goes on sale for $75. What is the percent decrease? | {
"A": "20 %",
"B": "30 %",
"C": "40 %",
"D": "25 %",
"E": "60 %"
} | subtract(100, 75) | subtract(n0,n1)| | "the is always the difference between our starting and ending points . in this case , it â € ™ s 100 â € “ 75 = 25 . the â € œ original â € is our starting point ; in this case , it â € ™ s 100 . ( 25 / 100 ) * 100 = ( 0.25 ) * 100 = 25 % . d" | general |
math_qa__GxYghUfUCOmizlL6 | What is the remainder when (55)(57) is divided by 8?
Pick one.
A) 1 B) 2 C) 4 D) 5 E) 7 | <gadget id="calculator">57 * 55</gadget>
<output>3_135</output>
<gadget id="calculator">3_135 % 8</gadget>
<output>7</output>
<result>E</result> | E | 7 | What is the remainder when (55)(57) is divided by 8? | {
"A": "1",
"B": "2",
"C": "4",
"D": "5",
"E": "7"
} | reminder(multiply(57, 55), 8) | multiply(n0,n1)|reminder(#0,n2) | ( 55 ) ( 57 ) = ( 56 - 1 ) ( 56 + 1 ) = 56 ^ 2 - 1 which is 1 less than a multiple of 8 . then the remainder will be 7 . the answer is e . | general |
math_qa__Vz7uSlfOevhkPHk2 | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.25 as old as Robert? Choose the correct option: A) 1960 B) 1965 C) 1970 D) 2050 E) 2060 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">1.25 + 7</gadget>
<output>8.25</output>
<gadget id="calculator">1_950 + 8.25</gadget>
<output>1_958.25</output>
<result>E</result> | E | 2,060 | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.25 as old as Robert? | {
"A": "1960",
"B": "1965",
"C": "1970",
"D": "2050",
"E": "2060"
} | add(1950, add(1.25, add(const_4, const_3))) | add(const_3,const_4)|add(n4,#0)|add(n0,#1) | in 1950 : ri = 4 ro - - - - - - - - - - - - - - eq 1 in 1955 : ri + 5 = 3 ( ro + 5 ) - - - - - - - - - eq 2 thus in 1950 , solving eq 1 and eq 2 ro = 10 , ri = 40 now for each year we can calculate : 1960 : ri = 50 , ro = 20 1965 : ri = 55 , ro = 25 2060 : ri = 120 , ro = 150 thus ans : e | general |
math_qa__WWdVZkCnaTnMG15i | A dog is tied to a tree by a long nylon cord. If the dog runs from the due North side of the tree to the due South side of the tree with the cord extended to its full length at all items, and the dog ran approximately 30 feet, what was the approximate length of the nylon cord Q, in feet? Options
A) 30 B) 25 C) 15 D) 10 E) 5 | <gadget id="calculator">30 / 3</gadget>
<output>10</output>
<result>D</result> | D | 10 | A dog is tied to a tree by a long nylon cord. If the dog runs from the due North side of the tree to the due South side of the tree with the cord extended to its full length at all items, and the dog ran approximately 30 feet, what was the approximate length of the nylon cord Q, in feet? | {
"A": "30",
"B": "25",
"C": "15",
"D": "10",
"E": "5"
} | divide(30, const_3) | divide(n0,const_3) | because the cord was extended to its full length at all items , the dog ran along a semi - circular path , from north to south . the circumference of a full circle is 2 * pi * r , but since we only care about the length of half the circle , the semi - circle path is pi * r . q = pi * r = 30 . round pi = 3 , then r = 10 . chord is about 10 feet long . d | general |
math_qa__qKWp1E4YRGouOOvM | A person crosses a 300 m long street in 4 minutes. What is his speed in km per hour? Answers:
A) 1.6 B) 4.5 C) 8.2 D) 6.5 E) 2.9 | <gadget id="calculator">300 / 1_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">4 * 60</gadget>
<output>240</output>
<gadget id="calculator">240 / 3_600</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(3/10) / (1/15)</gadget>
<output>9/2 = around 4.5</output>
<result>B</result> | B | 4.5 | A person crosses a 300 m long street in 4 minutes. What is his speed in km per hour? | {
"A": "1.6",
"B": "4.5",
"C": "8.2",
"D": "6.5",
"E": "2.9"
} | divide(divide(300, const_1000), divide(multiply(4, const_60), const_3600)) | divide(n0,const_1000)|multiply(n1,const_60)|divide(#1,const_3600)|divide(#0,#2)| | "distance = 300 meter time = 4 minutes = 4 x 60 seconds = 240 seconds speed = distance / time = 300 / 240 = 1.25 m / s = 1.25 ã — 18 / 5 km / hr = 4.5 km / hr answer : b" | physics |
math_qa__4aeFMFbiDgo7af28 | Jerry and Michelle play a card game. In the beginning of the game they have an equal number of cards. Each player, at her turn, gives the other a third of her cards. Michelle plays first, giving Jerry a third of her cards. Jerry plays next, and Michelle follows. Then the game ends. Jerry ended up with 28 more cards than Michelle. How many cards did each player have originally? Choose the most appropriate option:
A) 51 B) 52 C) 53 D) 54 E) 56 | <gadget id="calculator">28 * 3</gadget>
<output>84</output>
<gadget id="calculator">84 - 28</gadget>
<output>56</output>
<result>D</result> | D | 54 | Jerry and Michelle play a card game. In the beginning of the game they have an equal number of cards. Each player, at her turn, gives the other a third of her cards. Michelle plays first, giving Jerry a third of her cards. Jerry plays next, and Michelle follows. Then the game ends. Jerry ended up with 28 more cards than Michelle. How many cards did each player have originally? | {
"A": "51",
"B": "52",
"C": "53",
"D": "54",
"E": "56"
} | subtract(multiply(28, const_3), 28) | multiply(n0,const_3)|subtract(#0,n0)| | "gamemichelle jerry initially 54 54 assume after game 1 36 72 after game 2 60 48 after game 3 40 68 now merry has 28 cards more than michelle . this option gives us exactly what number of cards they had initially . so the answer is d" | general |
math_qa__1NXohAjAuvlTWlR2 | If Albert’s monthly earnings rise by 26%, he would earn $693. If, instead, his earnings rise by only 20%, how much (in $) would he earn this month?
Answers: A) 643 B) 652 C) 660 D) 690 E) 693 | <gadget id="calculator">26 / 100</gadget>
<output>13/50 = around 0.26</output>
<gadget id="calculator">1 + (13/50)</gadget>
<output>63/50 = around 1.26</output>
<gadget id="calculator">693 / (63/50)</gadget>
<output>550</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">550 * (6/5)</gadget>
<output>660</output>
<result>C</result> | C | 660 | If Albert’s monthly earnings rise by 26%, he would earn $693. If, instead, his earnings rise by only 20%, how much (in $) would he earn this month? | {
"A": "643",
"B": "652",
"C": "660",
"D": "690",
"E": "693"
} | multiply(divide(693, add(const_1, divide(26, const_100))), add(const_1, divide(20, const_100))) | divide(n2,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|divide(n1,#3)|multiply(#2,#4) | = 693 / 1.26 ∗ 1.2 = 660 = 660 answer is c | gain |
math_qa__UD6nqL2N49YATNdv | What is the normal price of an article sold at $36 after two successive discounts of 10% and 20%? Select the correct option.
A) $ 45 B) $ 48 C) $ 50 D) $ 54 E) $ 56 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(9/10) * (4/5)</gadget>
<output>18/25 = around 0.72</output>
<gadget id="calculator">36 / (18/25)</gadget>
<output>50</output>
<result>C</result> | C | 50 | What is the normal price of an article sold at $36 after two successive discounts of 10% and 20%? | {
"A": "$ 45",
"B": "$ 48",
"C": "$ 50",
"D": "$ 54",
"E": "$ 56"
} | divide(36, multiply(divide(subtract(const_100, 10), const_100), divide(subtract(const_100, 20), const_100))) | subtract(const_100,n1)|subtract(const_100,n2)|divide(#0,const_100)|divide(#1,const_100)|multiply(#2,#3)|divide(n0,#4)| | "0.8 * 0.9 * cost price = $ 36 cost price = $ 50 the answer is c ." | gain |
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