id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__3CBuDYuKXxMTAK2U | By investing Rs. 1800 in 9% stock, Syam earns Rs. 120. The stock is then quoted at Options
A) rs . 135 B) rs . 96 C) rs . 85 D) rs . 122 E) rs . 142 | <gadget id="calculator">1_800 / 120</gadget>
<output>15</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">15 * (9/100)</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">(27/20) * 100</gadget>
<output>135</output>
<result>A</result> | A | 135 | By investing Rs. 1800 in 9% stock, Syam earns Rs. 120. The stock is then quoted at | {
"A": "rs . 135",
"B": "rs . 96",
"C": "rs . 85",
"D": "rs . 122",
"E": "rs . 142"
} | multiply(multiply(divide(1800, 120), divide(9, const_100)), const_100) | divide(n0,n2)|divide(n1,const_100)|multiply(#0,#1)|multiply(#2,const_100)| | "explanation : assume that face value = rs . 100 . dividend per share = rs . 9 ( as it is a 9 % stock ) by investing rs . 1800 , he earns rs . 120 investment needed to earn rs . 9 = 1800 × 9 / 120 = rs . 135 ie , stock is then quoted ( then market value ) = rs . 135 answer : option a" | gain |
math_qa__n8Ke3GsevO7SP1Br | The rowing athletes in a rowing conference voted for coach of the year. Each rower who voted chose exactly 3 coaches to vote for among the 36 coaches in the conference. If each of the 36 coaches received exactly 5 votes (a 36 way tie), how many rowers voted for coach of the year? Choose one:
A) 60 B) 70 C) 75 D) 84 E) 90 | <gadget id="calculator">36 * 5</gadget>
<output>180</output>
<gadget id="calculator">180 / 3</gadget>
<output>60</output>
<result>A</result> | A | 60 | The rowing athletes in a rowing conference voted for coach of the year. Each rower who voted chose exactly 3 coaches to vote for among the 36 coaches in the conference. If each of the 36 coaches received exactly 5 votes (a 36 way tie), how many rowers voted for coach of the year? | {
"A": "60",
"B": "70",
"C": "75",
"D": "84",
"E": "90"
} | divide(multiply(36, 5), 3) | multiply(n1,n3)|divide(#0,n0) | there were 36 * 5 = 180 total votes made . if each voter picked 3 coaches , there were 180 / 3 = 60 voters . a | general |
math_qa__m8ZGJVqD5s8jyvGn | I. x + 2y + 3z = 2
II. x + y - z = 0
III. 2x + 2y - z = 1
What is the value of y in the system above? Choose the correct answer: A) - 2 B) - 1 C) 0 D) 1 E) 2 | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">2 - 4</gadget>
<output>-2</output>
<result>A</result> | A | -2 | I. x + 2y + 3z = 2
II. x + y - z = 0
III. 2x + 2y - z = 1
What is the value of y in the system above? | {
"A": "- 2",
"B": "- 1",
"C": "0",
"D": "1",
"E": "2"
} | subtract(2, add(3, 1)) | add(n1,n6)|subtract(n0,#0) | 1 . from the given system of equations i can make equation ii . to be x + y = z 2 . now put that in iii . : 2 x + 2 y - ( x + y ) = 1 = 2 x + 2 y - x - y = 1 = x + y = 1 that gives usz = 1 ! 3 . put z = 1 in i . and solve : x + 2 y + 3 = 2 ; calculate minus 3 = x + 2 y = - 1 ; calculate minus x = 2 y = - 1 - x ; 4 . now put 2 y = - 1 - x in iii . and solve : 2 x + ( - 1 - x ) - 1 = 1 = x - 2 = 1 ; calculate plus 2 that gives usx = 3 5 . now solve for y with x = 3 and z = 1 : x + y = 1 = 3 + y = 1 ; calculate minus 3 that gives y = - 2 , and hence answer ( a ) - 2 | general |
math_qa__uYpL1v3fIvsrigaI | If grapes are 90% water and raisins are 15% water, then how many kilograms did a quantity of raisins, which currently weighs 12 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.)
Select the correct option: A) 96 B) 98 C) 100 D) 102 E) 104 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(17/20) * 12</gadget>
<output>51/5 = around 10.2</output>
<gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(51/5) / (1/10)</gadget>
<output>102</output>
<result>D</result> | D | 102 | If grapes are 90% water and raisins are 15% water, then how many kilograms did a quantity of raisins, which currently weighs 12 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.) | {
"A": "96",
"B": "98",
"C": "100",
"D": "102",
"E": "104"
} | divide(multiply(divide(subtract(const_100, 15), const_100), 12), divide(subtract(const_100, 90), const_100)) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,const_100)|multiply(n2,#2)|divide(#4,#3)| | "let x be the original weight of the grapes . the weight of the grape pulp was 0.1 x . since the grape pulp is 85 % of the raisins , 0.1 x = 0.85 ( 12 kg ) . then x = 8.5 * 12 = 102 kg . the answer is d ." | general |
math_qa__rla6QE3nQ0rNhPB2 | A car travels uphill at 30 km/hr and downhill at 50 km/hr. It goes 100 km uphill and 50 km downhill. Find the average speed of the car? Choose the correct answer
A) 32 kmph B) 33 kmph C) 34 kmph D) 35 kmph E) 36 kmph | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">100 / 30</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">(10/3) + 1</gadget>
<output>13/3 = around 4.333333</output>
<gadget id="calculator">150 / (13/3)</gadget>
<output>450/13 = around 34.615385</output>
<result>D</result> | D | 35 | A car travels uphill at 30 km/hr and downhill at 50 km/hr. It goes 100 km uphill and 50 km downhill. Find the average speed of the car? | {
"A": "32 kmph",
"B": "33 kmph",
"C": "34 kmph",
"D": "35 kmph",
"E": "36 kmph"
} | divide(add(100, 50), add(divide(100, 30), divide(50, 50))) | add(n2,n3)|divide(n2,n0)|divide(n3,n1)|add(#1,#2)|divide(#0,#3)| | "avg speed = total distance / total time . total distance traveled = 100 + 50 = 150 km ; time taken for uphill journey = 100 / 30 = 10 / 3 ; time taken for down hill journey = 50 / 50 = 5 / 5 ; avg speed = 150 / ( 10 / 3 + 5 / 5 ) = 35 kmph answer : d" | general |
math_qa__u1OjEwqFRUPtAQMe | The Speed of a boat in still water is 25 kmph. If it can travel 10 km upstream in 1 hr, What time it would take to travel the same distance downstream? Choose the correct choice from the following:
A) 26 minutes B) 23 minutes C) 15 minutes D) 19 minutes E) 28 minutes | <gadget id="calculator">25 - 10</gadget>
<output>15</output>
<result>C</result> | C | 15 | The Speed of a boat in still water is 25 kmph. If it can travel 10 km upstream in 1 hr, What time it would take to travel the same distance downstream? | {
"A": "26 minutes",
"B": "23 minutes",
"C": "15 minutes",
"D": "19 minutes",
"E": "28 minutes"
} | subtract(25, 10) | subtract(n0,n1) | speed of boat in still water = 25 km / hr speed upstream = 10 ⁄ 1 = 10 km / hr speed of the stream = ( 25 - 10 ) = 15 km / hr speed downstream = ( 25 + 15 ) = 40 km / hr time taken to travel 10 km downstream = 10 / 40 hours = ( 10 × 60 ) / 40 = 15 minutes answer is c | physics |
math_qa__Hx0Wjr2wMj3A9Eqh | Seller selling an apple for Rs.17, a Seller loses 1/6th of what it costs him. The CP of the apple is?
Pick.
A) 10
B) 12
C) 18
D) 19
E) 20 | <gadget id="calculator">17 + 1</gadget>
<output>18</output>
<result>C</result> | C | 18 | Seller selling an apple for Rs.17, a Seller loses 1/6th of what it costs him. The CP of the apple is? | {
"A": "10",
"B": "12",
"C": "18",
"D": "19",
"E": "20"
} | add(17, 1) | add(n0,n1)| | "sp = 17 loss = cp 18 loss = cp − sp = cp − 17 ⇒ cp 18 = cp − 17 ⇒ 17 cp 18 = 17 ⇒ cp 18 = 1 ⇒ cp = 18 c" | general |
math_qa__9BcFjyKSs5K2iJna | There are two positive numbers in the ratio 7:11. If the larger number exceeds the smaller by 16, then find the smaller number? Choose the correct choice from the following answers.
A) 25 B) 26 C) 30 D) 24 E) 28 | <gadget id="calculator">16 * 7</gadget>
<output>112</output>
<gadget id="calculator">112 / 4</gadget>
<output>28</output>
<result>E</result> | E | 28 | There are two positive numbers in the ratio 7:11. If the larger number exceeds the smaller by 16, then find the smaller number? | {
"A": "25",
"B": "26",
"C": "30",
"D": "24",
"E": "28"
} | divide(multiply(16, 7), const_4) | multiply(n0,n2)|divide(#0,const_4) | let the two positive numbers be 7 x and 11 x respectively . 11 x - 7 x = 16 4 x = 16 = > x = 4 = > smaller number = 7 x = 28 . answer : e | other |
math_qa__vgBObZfFFyQ4z9Lq | what is rate of interest if principal.amount be 400,simple interest 120 and time 2year.
Choose the correct choice from the following answers
A) 10
B) 12.5
C) 25
D) 12
E) 15 | <gadget id="calculator">400 * 2</gadget>
<output>800</output>
<gadget id="calculator">120 / 800</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>E</result> | E | 15 | what is rate of interest if principal.amount be 400,simple interest 120 and time 2year. | {
"A": "10",
"B": "12.5",
"C": "25",
"D": "12",
"E": "15"
} | multiply(divide(120, multiply(400, 2)), const_100) | multiply(n0,n2)|divide(n1,#0)|multiply(#1,const_100)| | "s . i = ( p * r * t ) / 100 120 = 800 r / 100 r = 120 / 8 = 15 % answer e" | gain |
math_qa__SnnBvPEDmZblAQv2 | A BOWLER CAN TAKE MAX. 3WICKETS IN A OVER.IF HE BOWLS 6OVERS IN AN INNINGS, HOW MANY MAXIMUM WICKETS CAN HE TAKE?
Select the correct option:
A) 8
B) 9
C) 11
D) 7
E) 10 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">12 - 2</gadget>
<output>10</output>
<result>E</result> | E | 10 | A BOWLER CAN TAKE MAX. 3WICKETS IN A OVER.IF HE BOWLS 6OVERS IN AN INNINGS, HOW MANY MAXIMUM WICKETS CAN HE TAKE? | {
"A": "8",
"B": "9",
"C": "11",
"D": "7",
"E": "10"
} | subtract(subtract(multiply(6, 3), 6), const_2) | multiply(n0,n1)|subtract(#0,n1)|subtract(#1,const_2) | 10 because after 10 wickets , the innings is complete . answer : e | general |
math_qa__M2ciyXootmYdJ9h6 | If the personal income tax rate is lowered from 42% to 32%, what is the differential savings for a tax payer having an annual income before tax to the tune of $42400? Pick.
A) $ 3500
B) $ 5000
C) $ 4240
D) $ 7000
E) $ 10000 | <gadget id="calculator">42_400 / 100</gadget>
<output>424</output>
<gadget id="calculator">42 - 32</gadget>
<output>10</output>
<gadget id="calculator">424 * 10</gadget>
<output>4_240</output>
<result>C</result> | C | 4,240 | If the personal income tax rate is lowered from 42% to 32%, what is the differential savings for a tax payer having an annual income before tax to the tune of $42400? | {
"A": "$ 3500",
"B": "$ 5000",
"C": "$ 4240",
"D": "$ 7000",
"E": "$ 10000"
} | multiply(divide(42400, const_100), subtract(42, 32)) | divide(n2,const_100)|subtract(n0,n1)|multiply(#0,#1)| | "saving = ( 42 - 32 ) % of 42400 = 4240 . answer : c" | gain |
math_qa__IvOFSmetVPmXIkhr | (5568 / 87)1/3 + (72 x 2)1/2 = (?)1/2 ? Choose the correct choice
A) 256
B) 4
C) √ 2
D) 16
E) none | <gadget id="calculator">5_568 / 87</gadget>
<output>64</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">64 ** (1/3)</gadget>
<output>4</output>
<gadget id="calculator">72 * 2</gadget>
<output>144</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">144 ** (1/2)</gadget>
<output>12</output>
<gadget id="calculator">4 + 12</gadget>
<output>16</output>
<gadget id="calculator">16 ** 2</gadget>
<output>256</output>
<result>A</result> | A | 256 | (5568 / 87)1/3 + (72 x 2)1/2 = (?)1/2 ? | {
"A": "256",
"B": "4",
"C": "√ 2",
"D": "16",
"E": "none"
} | power(add(power(divide(5568, 87), divide(1, 3)), power(multiply(72, 2), divide(1, 2))), 2) | divide(n0,n1)|divide(n2,n3)|divide(n2,n5)|multiply(n4,n5)|power(#0,#1)|power(#3,#2)|add(#4,#5)|power(#6,n5) | answer ? ) 1 / 2 = ( 5568 / 87 ) 1 / 3 + ( 72 x 2 ) 1 / 2 = ( 64 ) 1 / 3 + ( 144 ) 1 / 2 ∴ ? = ( 4 + 12 ) 2 = 256 correct option : a | general |
math_qa__cAsGodp4o0Dc5v7u | At the end of the first quarter, the share price of a certain mutual fund was 20 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 50 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? Choose the correct answer:
A) 20 %
B) 25 %
C) 30 %
D) 33 %
E) 40 % | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">150 / 120</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) - 1</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | At the end of the first quarter, the share price of a certain mutual fund was 20 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 50 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "33 %",
"E": "40 %"
} | multiply(subtract(divide(add(const_100, 50), add(const_100, 20)), const_1), const_100) | add(n1,const_100)|add(n0,const_100)|divide(#0,#1)|subtract(#2,const_1)|multiply(#3,const_100) | say price at the beginning of year = 100 end of 1 st quarter = 100 + 20 = 120 end of 2 nd quarter = 100 + 50 = 150 percentage increase between 1 st & 2 nd quarter = 150 − 120 / 120 ∗ 100 = 25 answer = b | gain |
math_qa__Cvnw8C0p3HoxkLo7 | Find the 25% of Rs. 800. Choose the correct answer:
A) s . 50
B) s . 200
C) s . 100
D) s . 80
E) s . 60 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">800 * (1/4)</gadget>
<output>200</output>
<result>B</result> | B | 200 | Find the 25% of Rs. 800. | {
"A": "s . 50",
"B": "s . 200",
"C": "s . 100",
"D": "s . 80",
"E": "s . 60"
} | multiply(800, divide(25, const_100)) | divide(n0,const_100)|multiply(n1,#0)| | "explanation : 25 % of 800 = > 25 / 100 * 800 = rs . 200 answer : b" | gain |
math_qa__pGze61CCjimRZ5A7 | A crate measures 5 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? Options:
A) 2
B) 4
C) 5
D) 8
E) 12 | <gadget id="calculator">8 * 12</gadget>
<output>96</output>
<gadget id="calculator">96 * 5</gadget>
<output>480</output>
<gadget id="calculator">480 / 12</gadget>
<output>40</output>
<gadget id="calculator">40 / 8</gadget>
<output>5</output>
<result>C</result> | C | 5 | A crate measures 5 feet by 8 feet by 12 feet on the inside. A stone pillar in the shape of a right circular cylinder must fit into the crate for shipping so that it rests upright when the crate sits on at least one of its six sides. What is the radius, in feet, of the pillar with the largest volume that could still fit in the crate? | {
"A": "2",
"B": "4",
"C": "5",
"D": "8",
"E": "12"
} | divide(divide(multiply(multiply(8, 12), 5), 12), 8) | multiply(n1,n2)|multiply(n0,#0)|divide(#1,n2)|divide(#2,n1)| | "we can find the radius of all the three cases of cylinders . the only crux to find the answer faster is that : voulme is pi * r ^ 2 * h . the volume is a function of r ^ 2 . so r has to be the highest to find the largest volume . so r = 5 for the surface 8 * 12 face . volume = 125 pi answer c" | geometry |
math_qa__MfmhMOBqYBhLRmqb | What is the minimum number of square tiles required to tile a floor of length 5 metres 78 cm and width 3 metres 74 cm?
Choose the correct choice from the following options
A) 187
B) 180
C) 190
D) 195
E) 197 | <gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">500 + 78</gadget>
<output>578</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 + 2</gadget>
<output>34</output>
<gadget id="calculator">578 / 34</gadget>
<output>17</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">300 + 74</gadget>
<output>374</output>
<gadget id="calculator">374 / 34</gadget>
<output>11</output>
<gadget id="calculator">17 * 11</gadget>
<output>187</output>
<result>A</result> | A | 187 | What is the minimum number of square tiles required to tile a floor of length 5 metres 78 cm and width 3 metres 74 cm? | {
"A": "187",
"B": "180",
"C": "190",
"D": "195",
"E": "197"
} | multiply(divide(add(multiply(const_100, 5), 78), add(multiply(multiply(const_4, const_4), const_2), const_2)), divide(add(multiply(const_100, 3), 74), add(multiply(multiply(const_4, const_4), const_2), const_2))) | multiply(n0,const_100)|multiply(const_4,const_4)|multiply(n2,const_100)|add(n1,#0)|add(n3,#2)|multiply(#1,const_2)|add(#5,const_2)|divide(#3,#6)|divide(#4,#6)|multiply(#7,#8) | length = width = = > square = 5 m 78 cm and 3 m 74 5 m 78 cm = 578 cm and 3 m 74 cm = 374 cm hcf of 578 and 374 = 34 square is 34 = 578 * 374 / 34 * 34 = = 17 * 11 = 187 answer a | physics |
math_qa__xpcRTO08YDCqN6u0 | Three rugs have a combined area of 204 square meters. By overlapping the rugs to cover floor area of 140 square meters, the area that is covered by exactly two layers of rug is 24 square meters. What is the area that is covered with three layers of rug ? Choose the correct choice from the following choices:
A) 18 square meters B) 20 square meters C) 24 square meters D) 28 square meters E) 30 square meters | <gadget id="calculator">204 - 140</gadget>
<output>64</output>
<gadget id="calculator">64 - 24</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>B</result> | B | 20 | Three rugs have a combined area of 204 square meters. By overlapping the rugs to cover floor area of 140 square meters, the area that is covered by exactly two layers of rug is 24 square meters. What is the area that is covered with three layers of rug ? | {
"A": "18 square meters",
"B": "20 square meters",
"C": "24 square meters",
"D": "28 square meters",
"E": "30 square meters"
} | divide(subtract(subtract(204, 140), 24), const_2) | subtract(n0,n1)|subtract(#0,n2)|divide(#1,const_2)| | "total = rug 1 + rug 2 + rug 3 - { overlap of exactly 2 rugs } - 2 * { overlap of exactly 3 rugs } 140 = 204 - 24 - 2 * { overlap of exactly 2 rugs } - - > { overlap of exactly 3 rugs } = 20 . answer : b ." | geometry |
math_qa__mR2u8Nfy9wuf9Snd | In a group of 100 cars, 37 cars do not have air conditioning. If at least 41 cars have racing stripes, what is the greatest number of cars that could have air conditioning but not racing stripes? Select the correct option:
A) 45 B) 47 C) 59 D) 51 E) 53 | <gadget id="calculator">100 - 41</gadget>
<output>59</output>
<result>C</result> | C | 59 | In a group of 100 cars, 37 cars do not have air conditioning. If at least 41 cars have racing stripes, what is the greatest number of cars that could have air conditioning but not racing stripes? | {
"A": "45",
"B": "47",
"C": "59",
"D": "51",
"E": "53"
} | subtract(100, 41) | subtract(n0,n2)| | "lets assume ac = 63 ( includesonly ac carsandcars with ac and racing stripes ) lets assume rs ( racing stripes ) > = 41 ( includescars with ac and racing stripesandonly racing stripes ) . now since we want to maximize ( only ac ) we have to see to it thatcars with ac and racing stripesis minimal ( assume 0 ) but since rs > = 41 . . we have to assign atleast 4 tocars with ac and racing stripes . hence ac = 63 - 4 = 59 . the answer is" | other |
math_qa__9LLidNIHXOuLRJEQ | A man goes downstream at 12 kmph, and upstream8 kmph. The speed of the stream is Choose the correct option: A) 2 kmph B) 4 kmph C) 16 kmph D) 2.5 kmph E) 26 kmph | <gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<result>A</result> | A | 2 | A man goes downstream at 12 kmph, and upstream8 kmph. The speed of the stream is | {
"A": "2 kmph",
"B": "4 kmph",
"C": "16 kmph",
"D": "2.5 kmph",
"E": "26 kmph"
} | divide(subtract(12, 8), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "speed of the stream = 1 / 2 ( 12 - 8 ) kmph = 2 kmph . correct option a" | physics |
math_qa__dvybQa4UhwoPGSfc | Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 18 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately. Choose the correct choice from the following options:
A) 25 days
B) 100 days
C) 120 days
D) 110 days
E) 90 days | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 18</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/20) - (1/100)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 / (1/25)</gadget>
<output>25</output>
<result>A</result> | A | 25 | Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 18 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately. | {
"A": "25 days",
"B": "100 days",
"C": "120 days",
"D": "110 days",
"E": "90 days"
} | inverse(subtract(inverse(20), inverse(multiply(inverse(subtract(const_1, multiply(inverse(20), 18))), 10)))) | inverse(n0)|multiply(n1,#0)|subtract(const_1,#1)|inverse(#2)|multiply(n2,#3)|inverse(#4)|subtract(#0,#5)|inverse(#6)| | "rate of both = 1 / 20 together they do = 1 / 20 * 18 = 9 / 10 left work = 1 - 9 / 10 = 1 / 10 adam completes 1 / 10 work in 10 day so he took 10 * 10 = 100 days to complete the left work alone . thus the rate of adam is 1 / 100 rate of micheal = 1 / 20 - 1 / 100 = 1 / 25 thus micheal takes 25 days to complete the whole work . ans . a ." | physics |
math_qa__zRcoLGz2UFbhydIx | A batsman in his 12th innings makes a score of 115 and thereby increases his average by 3 runs. What is his average after the 12th innings if he had never been ‘not out’?
Choose the correct answer.
A) 42 B) 43 C) 44 D) 82 E) 46 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">115 - 36</gadget>
<output>79</output>
<gadget id="calculator">79 + 3</gadget>
<output>82</output>
<result>D</result> | D | 82 | A batsman in his 12th innings makes a score of 115 and thereby increases his average by 3 runs. What is his average after the 12th innings if he had never been ‘not out’? | {
"A": "42",
"B": "43",
"C": "44",
"D": "82",
"E": "46"
} | add(subtract(115, multiply(12, 3)), 3) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "let ‘ x ’ be the average score after 12 th innings ⇒ 12 x = 11 × ( x – 4 ) + 115 ∴ x = 82 answer d" | general |
math_qa__IHaeKEOlLuRUWrNx | The ratio 3 : 5 expressed as a percent equals Choose the most appropriate option
A) 60 %
B) 40 %
C) 80 %
D) 125 %
E) none | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>A</result> | A | 60 | The ratio 3 : 5 expressed as a percent equals | {
"A": "60 %",
"B": "40 %",
"C": "80 %",
"D": "125 %",
"E": "none"
} | multiply(divide(3, 5), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "solution 3 : 5 = 3 / 5 = ( 3 / 5 x 100 ) % . = 60 % . answer a" | general |
math_qa__B319dy8Iz6Z3khDL | When positive integer N is divided by positive integer J, the remainder is 28. If N/J = 142.07, what is value of J? Choices.
A) 300 B) 375 C) 400 D) 460 E) 500 | <gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 + 2</gadget>
<output>42</output>
<gadget id="calculator">100 + 42</gadget>
<output>142</output>
<gadget id="calculator">142.07 - 142</gadget>
<output>0.07</output>
<gadget id="calculator">28 / 0.07</gadget>
<output>400</output>
<result>C</result> | C | 400 | When positive integer N is divided by positive integer J, the remainder is 28. If N/J = 142.07, what is value of J? | {
"A": "300",
"B": "375",
"C": "400",
"D": "460",
"E": "500"
} | divide(28, subtract(142.07, add(const_100, add(multiply(const_4, const_10), const_2)))) | multiply(const_10,const_4)|add(#0,const_2)|add(#1,const_100)|subtract(n1,#2)|divide(n0,#3) | when a number is divided by another number , we can represent it as : dividend = quotient * divisor + remainder so , dividend / divisor = quotient + remainder / divisor given that n / j = 142.07 here 142 is the quotient . given that remainder = 28 so , 142.07 = 142 + 28 / j so , j = 400 answer - c | general |
math_qa__njfhkDOzhIGCwy4H | Find the annual dividend received by Nishita from 1200 preferred shares and 3000 common shares both of par value Rs. 50 each if the dividend paid on preferred shares is 10% and semi-annual dividend of 3½ % is declared on common shares.
Choose the correct choice from the following answers
A) 16000 B) 16500 C) 17000 D) 17500 E) 18000 | <gadget id="calculator">1_200 * 50</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 * 10</gadget>
<output>600_000</output>
<gadget id="calculator">600_000 / 100</gadget>
<output>6_000</output>
<gadget id="calculator">3_000 * 50</gadget>
<output>150_000</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 3</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">150_000 * (7/2)</gadget>
<output>525_000</output>
<gadget id="calculator">525_000 / 100</gadget>
<output>5_250</output>
<gadget id="calculator">6_000 + 5_250</gadget>
<output>11_250</output>
<gadget id="calculator">11_250 + 5_250</gadget>
<output>16_500</output>
<result>B</result> | B | 16,500 | Find the annual dividend received by Nishita from 1200 preferred shares and 3000 common shares both of par value Rs. 50 each if the dividend paid on preferred shares is 10% and semi-annual dividend of 3½ % is declared on common shares. | {
"A": "16000",
"B": "16500",
"C": "17000",
"D": "17500",
"E": "18000"
} | add(add(divide(multiply(multiply(1200, 50), 10), const_100), divide(multiply(multiply(3000, 50), add(divide(const_1, const_2), 3)), const_100)), divide(multiply(multiply(3000, 50), add(divide(const_1, const_2), 3)), const_100)) | divide(const_1,const_2)|multiply(n0,n2)|multiply(n1,n2)|add(n4,#0)|multiply(n3,#1)|divide(#4,const_100)|multiply(#3,#2)|divide(#6,const_100)|add(#5,#7)|add(#8,#7) | total number of preferred shares = 1200 face value = rs . 50 dividend paid on preferred shares is 10 % dividend per share = 50 × 10 / 100 = rs . 5 total dividend = 1200 × 5 = 6000 total number of common shares = 3000 face value = rs . 50 semi - annual dividend of 3 ½ % is declared on common shares . semi - annual dividend per share = 50 × 7 / 2 × 100 = rs . 74 total semi - annual dividend = 7 / 4 × 3000 = rs . 5250 annual dividend = rs . 5250 × 2 = rs . 10500 total dividend on all all shares ( preferred and common ) = 6000 + 10500 = rs . 16500 answer is b . | general |
math_qa__GpqREpNXnQ0g6lpG | Length of a rectangular plot is 32 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? Choose one.
A) 56 m B) 66 m C) 76 m D) 86 m E) 96 m | <gadget id="calculator">5_300 / 26.5</gadget>
<output>200</output>
<gadget id="calculator">2 * 32</gadget>
<output>64</output>
<gadget id="calculator">200 + 64</gadget>
<output>264</output>
<gadget id="calculator">264 / 4</gadget>
<output>66</output>
<result>B</result> | B | 66 | Length of a rectangular plot is 32 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? | {
"A": "56 m",
"B": "66 m",
"C": "76 m",
"D": "86 m",
"E": "96 m"
} | divide(add(divide(5300, 26.50), multiply(const_2, 32)), const_4) | divide(n2,n1)|multiply(n0,const_2)|add(#0,#1)|divide(#2,const_4)| | "let breadth = x metres . then , length = ( x + 32 ) metres . perimeter = 5300 m = 200 m . 26.50 2 [ ( x + 32 ) + x ] = 200 2 x + 32 = 100 2 x = 68 x = 34 . hence , length = x + 32 = 66 m b" | physics |
math_qa__uq6A0IxcerCdO6Pd | The distance from City A to City B is 120 miles. While driving from City A to City B, Bob drives at a constant speed of 40 miles per hour. Alice leaves City A 30 minutes after Bob. What is the minimum constant speed in miles per hour that Alice must exceed in order to arrive in City B before Bob? Choose one
A) 45 B) 48 C) 50 D) 52 E) 54 | <gadget id="calculator">120 / 40</gadget>
<output>3</output>
<gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 - (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">120 / (5/2)</gadget>
<output>48</output>
<result>B</result> | B | 48 | The distance from City A to City B is 120 miles. While driving from City A to City B, Bob drives at a constant speed of 40 miles per hour. Alice leaves City A 30 minutes after Bob. What is the minimum constant speed in miles per hour that Alice must exceed in order to arrive in City B before Bob? | {
"A": "45",
"B": "48",
"C": "50",
"D": "52",
"E": "54"
} | divide(120, subtract(divide(120, 40), divide(30, const_60))) | divide(n0,n1)|divide(n2,const_60)|subtract(#0,#1)|divide(n0,#2) | the time it takes bob to drive to city b is 120 / 40 = 3 hours . alice needs to take less than 2.5 hours for the trip . alice needs to exceed a constant speed of 120 / 2.5 = 48 miles per hour . the answer is b . | physics |
math_qa__MBvYW7lW5Bo682IS | Solve: 12.05*5.4+0.6 Choose the correct choice from the following choices.
A) 108.45
B) 110.45
C) 106.45
D) 109.45
E) none of them | <gadget id="calculator">5.4 / 0.6</gadget>
<output>9</output>
<gadget id="calculator">12.05 * 9</gadget>
<output>108.45</output>
<result>A</result> | A | 108.45 | Solve: 12.05*5.4+0.6 | {
"A": "108.45",
"B": "110.45",
"C": "106.45",
"D": "109.45",
"E": "none of them"
} | multiply(12.05, divide(5.4, 0.6)) | divide(n1,n2)|multiply(n0,#0) | = 12.05 * ( 5.4 / 0.6 ) = ( 12.05 * 9 ) = 108.45 answer is a . | general |
math_qa__NDSov6CY08gg6E5V | An investment yields an interest payment of $225 each month. If the simple annual interest rate is 9%, what is the amount of the investment? Choose the correct choice:
A) $ 30,000 B) $ 30,400 C) $ 31,300 D) $ 32,500 E) $ 35,100 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">225 / (3/4)</gadget>
<output>300</output>
<gadget id="calculator">300 * 100</gadget>
<output>30_000</output>
<result>A</result> | A | 30,000 | An investment yields an interest payment of $225 each month. If the simple annual interest rate is 9%, what is the amount of the investment? | {
"A": "$ 30,000",
"B": "$ 30,400",
"C": "$ 31,300",
"D": "$ 32,500",
"E": "$ 35,100"
} | multiply(divide(225, divide(9, multiply(const_3, const_4))), const_100) | multiply(const_3,const_4)|divide(n1,#0)|divide(n0,#1)|multiply(#2,const_100)| | "let the principal amount = p simple annual interest = 9 % simple monthly interest = ( 9 / 12 ) = ( 3 / 4 ) % ( 3 / 4 ) * ( p / 100 ) = 225 = > p = ( 225 * 4 * 10 ^ 2 ) / 3 = 75 * 4 * 10 ^ 2 = 300 * 10 ^ 2 = 30000 answer a" | gain |
math_qa__otjny66DPsvYjAPe | List I: { y, 2, 4, 7, 10, 11}
List II: {3, 3, 4, 6, 7, 10}
If the median Q of List I is equal to the sum of the median of list II and the mode of list II, then y equals Options
A) 5 B) 7 C) 8 D) q = 9 E) 10 | <gadget id="calculator">6 + 3</gadget>
<output>9</output>
<result>D</result> | D | 9 | List I: { y, 2, 4, 7, 10, 11}
List II: {3, 3, 4, 6, 7, 10}
If the median Q of List I is equal to the sum of the median of list II and the mode of list II, then y equals | {
"A": "5",
"B": "7",
"C": "8",
"D": "q = 9",
"E": "10"
} | add(6, 3) | add(n5,n8) | mode of list ii = 3 median q of list ii = 4 + 6 / 2 = 5 sum of mode + mean = 3 + 5 = 8 now to make 8 as the median we need to find a value of y such that if the no . of terms in list 1 are odd then y = 8 else if even then 7 + y / 2 = 8 here its even so 7 + y / 2 = 8 from this y = 9 ( d ) | general |
math_qa__U2ItuxQ8uoI4LlIs | In a college the ratio of the numbers of boys to the girls is 8:5. If there are 135 girls, the total number of students in the college is? Choose the correct choice from the following answers:
A) 562 B) 351 C) 452 D) 416 E) 512 | <gadget id="calculator">8 / 5</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">(8/5) * 135</gadget>
<output>216</output>
<gadget id="calculator">216 + 135</gadget>
<output>351</output>
<result>B</result> | B | 351 | In a college the ratio of the numbers of boys to the girls is 8:5. If there are 135 girls, the total number of students in the college is? | {
"A": "562",
"B": "351",
"C": "452",
"D": "416",
"E": "512"
} | add(multiply(divide(8, 5), 135), 135) | divide(n0,n1)|multiply(n2,#0)|add(n2,#1)| | "let the number of boys and girls be 8 x and 5 x then , 5 x = 135 x = 27 total number of students = 13 x = 13 * 27 = 351 answer is b" | other |
math_qa__jGDgpGjsa9T4RJAx | An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 18 as commission, the cloth sold through him on that day is worth Select.
A) 333
B) 500
C) 887
D) 720
E) 132 | <gadget id="calculator">2.5 / 100</gadget>
<output>0.025</output>
<gadget id="calculator">18 / 0.025</gadget>
<output>720</output>
<result>D</result> | D | 720 | An agent, gets a commission of 2.5% on the sales of cloth. If on a certain day, he gets Rs. 18 as commission, the cloth sold through him on that day is worth | {
"A": "333",
"B": "500",
"C": "887",
"D": "720",
"E": "132"
} | divide(18, divide(2.5, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "explanation : let the total sale be rs . x . then , 2.5 % . of x = 18 < = > ( 25 / 10 * 1 / 100 * x ) = 18 < = > x = 720 . answer : d" | gain |
math_qa__Iz4Xkt4h1gF3oJ8Q | If 45-[28-{37-(15-*)}]= 58, then * is equal to: Choose the correct choice from the following options: A) - 29 B) - 19 C) 19 D) 29 E) 39 | <gadget id="calculator">28 - 37</gadget>
<output>-9</output>
<gadget id="calculator">(-9) + 15</gadget>
<output>6</output>
<gadget id="calculator">45 - 6</gadget>
<output>39</output>
<gadget id="calculator">58 - 39</gadget>
<output>19</output>
<result>C</result> | C | 19 | If 45-[28-{37-(15-*)}]= 58, then * is equal to: | {
"A": "- 29",
"B": "- 19",
"C": "19",
"D": "29",
"E": "39"
} | subtract(58, subtract(45, add(subtract(28, 37), 15))) | subtract(n1,n2)|add(n3,#0)|subtract(n0,#1)|subtract(n4,#2)| | "45 - [ 28 - { 37 - ( 15 - * ) } ] = 58 = > 45 - [ 28 - { 37 - 15 + * } ] = 58 45 - [ 28 - 37 + 15 - * ] = 58 = > 45 [ 43 - 37 - * ] = 58 45 - [ 6 - * ] = 58 = > 45 - 6 + * = 58 39 + * = 58 = > * = 58 - 39 = 19 answer : c" | general |
math_qa__f8alQr6Vpoh6L7Mr | If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is?
Choose the correct choice from the following answers:
A) 17
B) 19
C) 17
D) 12
E) 91 | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">1 * 10</gadget>
<output>10</output>
<gadget id="calculator">300 + 10</gadget>
<output>310</output>
<gadget id="calculator">310 + 4</gadget>
<output>314</output>
<gadget id="calculator">314 / 100</gadget>
<output>157/50 = around 3.14</output>
<gadget id="calculator">2 * (157/50)</gadget>
<output>157/25 = around 6.28</output>
<gadget id="calculator">(157/25) * 14</gadget>
<output>2_198/25 = around 87.92</output>
<gadget id="calculator">1_056 / (2_198/25)</gadget>
<output>13_200/1_099 = around 12.010919</output>
<result>D</result> | D | 12 | If the wheel is 14 cm then the number of revolutions to cover a distance of 1056 cm is? | {
"A": "17",
"B": "19",
"C": "17",
"D": "12",
"E": "91"
} | divide(1056, multiply(multiply(const_2, divide(add(add(multiply(const_3, const_100), multiply(const_1, const_10)), const_4), const_100)), 14)) | multiply(const_100,const_3)|multiply(const_1,const_10)|add(#0,#1)|add(#2,const_4)|divide(#3,const_100)|multiply(#4,const_2)|multiply(n0,#5)|divide(n1,#6)| | "2 * 22 / 7 * 14 * x = 1056 = > x = 12 answer : d" | physics |
math_qa__q1UkCwJbOAVblFhG | A man walked a certain distance south and then the same distance plus 7km due west.He is now 13km from his starting point.What are the distances south and west that he walked? Choose the most appropriate option.
A) 512 B) 612 C) 712 D) 513 E) 613 | <gadget id="calculator">13 * 7</gadget>
<output>91</output>
<gadget id="calculator">91 * 3</gadget>
<output>273</output>
<gadget id="calculator">273 * 2</gadget>
<output>546</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">546 - 40</gadget>
<output>506</output>
<result>A</result> | A | 512 | A man walked a certain distance south and then the same distance plus 7km due west.He is now 13km from his starting point.What are the distances south and west that he walked? | {
"A": "512",
"B": "612",
"C": "712",
"D": "513",
"E": "613"
} | subtract(multiply(multiply(multiply(13, 7), const_3), const_2), multiply(const_10, const_4)) | multiply(n0,n1)|multiply(const_10,const_4)|multiply(#0,const_3)|multiply(#2,const_2)|subtract(#3,#1) | if a man walked distance ( in km ) ' x ' towards south & then ' x + 7 ' towards west . distance from starting point = hypotenuse of a right triangle with sides x & ( x + 7 ) so 13 ^ 2 = x ^ 2 + ( x + 7 ) ^ 2 x ^ 2 + 7 x - 60 = 0 or ( x + 12 ) ( x - 5 ) = 0 , so x = 5 distance towards west = x + 7 = 5 + 7 = 12 km . answer : a | physics |
math_qa__Iw7VPTM6tfdEtZ9y | Out of 40 applicants to a law school, 15 majored in political science, 20 had a grade point average higher than 3.0, and 10 did not major in political science and had a GPA equal to or lower than 3.0. How many R applicants majored in political science and had a GPA higher than 3.0?
Pick:
A) 5
B) 10
C) 15
D) 25
E) 35 | <gadget id="calculator">10 + 15</gadget>
<output>25</output>
<gadget id="calculator">40 - 25</gadget>
<output>15</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<result>A</result> | A | 5 | Out of 40 applicants to a law school, 15 majored in political science, 20 had a grade point average higher than 3.0, and 10 did not major in political science and had a GPA equal to or lower than 3.0. How many R applicants majored in political science and had a GPA higher than 3.0? | {
"A": "5",
"B": "10",
"C": "15",
"D": "25",
"E": "35"
} | subtract(20, subtract(40, add(10, 15))) | add(n1,n4)|subtract(n0,#0)|subtract(n2,#1)| | "total applicants = 40 political science = 15 and non political science = 40 - 15 = 25 gpa > 3.0 = 20 and gpa < = 3.0 = 20 10 non political science students had gpa < = 3.0 - - > 15 non political science students had gpa > 3.0 gpa > 3.0 in political science = total - ( gpa > 3.0 in non political science ) r = 20 - 15 = 5 answer : a" | general |
math_qa__VOJvwv8VgUrkWcWx | A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 12 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton? Choose the correct choice from the following answers:
A) 210 B) 150 C) 280 D) 300 E) 420 | <gadget id="calculator">25 * 42</gadget>
<output>1_050</output>
<gadget id="calculator">1_050 * 60</gadget>
<output>63_000</output>
<gadget id="calculator">7 * 12</gadget>
<output>84</output>
<gadget id="calculator">84 * 5</gadget>
<output>420</output>
<gadget id="calculator">63_000 / 420</gadget>
<output>150</output>
<result>B</result> | B | 150 | A grocer is storing soap boxes in cartons that measure 25 inches by 42 inches by 60 inches. If the measurement of each soap box is 7 inches by 12 inches by 5 inches, then what is the maximum number of soap boxes that can be placed in each carton? | {
"A": "210",
"B": "150",
"C": "280",
"D": "300",
"E": "420"
} | divide(multiply(multiply(25, 42), 60), multiply(multiply(7, 12), 5)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|multiply(n5,#1)|divide(#2,#3)| | "however the process of dividing the volume of box by the volume of a soap seems flawed but it does work in this case due to the numbers dimensions of the box = 25 * 42 * 60 dimensions of the soap = 5 * 12 * 7 placing the 7 inch side along 42 inch side we get 6 soaps in a line and in a similar way 5 along 25 and 6 along 60 we get = 5 x 6 x 5 = 150 so the question is why this particular arrangement , in order to maximize number of soaps we need to minimize the space wasted and this is the only config where we dont waste any space so we can expect the maximum number the answer is ( b )" | general |
math_qa__lhEIrOhOufQ5NVw4 | If 25% of x is 15 less than 15% of 1600, then x is? Select the correct option: A) 872 B) 738 C) 900 D) 840 E) 83 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1_600 * (3/20)</gadget>
<output>240</output>
<gadget id="calculator">240 - 15</gadget>
<output>225</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">225 / (1/4)</gadget>
<output>900</output>
<result>C</result> | C | 900 | If 25% of x is 15 less than 15% of 1600, then x is? | {
"A": "872",
"B": "738",
"C": "900",
"D": "840",
"E": "83"
} | divide(subtract(multiply(1600, divide(15, const_100)), 15), divide(25, const_100)) | divide(n2,const_100)|divide(n0,const_100)|multiply(n3,#0)|subtract(#2,n1)|divide(#3,#1)| | "25 % of x = x / 4 ; 15 % of 1600 = 15 / 100 * 1600 = 240 given that , x / 4 = 240 - 15 = > x / 4 = 225 = > x = 900 . answer : c" | general |
math_qa__f8rt7RuMnUj7E6En | 30 ladies and 60 gentlemen are present at a party. There are 23 couples among them. If a lady and a gentleman is selected at random, what is the probability that they will be a couple?
Choose the correct choice from the following options:
A) 1 / 200 B) 1 / 100 C) 1 / 50 D) 1 / 40 E) 23 / 1800 | <gadget id="calculator">30 * 60</gadget>
<output>1_800</output>
<gadget id="calculator">23 / 1_800</gadget>
<output>23/1_800 = around 0.012778</output>
<result>E</result> | E | 0.012778 | 30 ladies and 60 gentlemen are present at a party. There are 23 couples among them. If a lady and a gentleman is selected at random, what is the probability that they will be a couple? | {
"A": "1 / 200",
"B": "1 / 100",
"C": "1 / 50",
"D": "1 / 40",
"E": "23 / 1800"
} | divide(23, multiply(30, 60)) | multiply(n0,n1)|divide(n2,#0) | in how many ways we can select a woman and a man from 30 women and 60 men ? in 30 * 60 = 1800 ways . we have a total of 23 couples so , the probability of selecting a couple is 23 / 1800 = 23 / 1800 . ans - e | probability |
math_qa__1q0nxbmRXx4F1Z6Y | In a class, 30% of the students speaks truth, 20% speaks lie and 10% speaks both. If a student is selected at random, what is the probability that he has speak truth or lie? Options.
A) 1 / 4 B) 2 / 3 C) 3 / 5 D) 2 / 5 E) 2 / 7 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/10) + (1/5)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/10) + (1/2)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<result>D</result> | D | 0.4 | In a class, 30% of the students speaks truth, 20% speaks lie and 10% speaks both. If a student is selected at random, what is the probability that he has speak truth or lie? | {
"A": "1 / 4",
"B": "2 / 3",
"C": "3 / 5",
"D": "2 / 5",
"E": "2 / 7"
} | subtract(const_1, add(divide(10, multiply(multiply(const_5, const_5), const_4)), add(divide(30, multiply(multiply(const_5, const_5), const_4)), divide(20, multiply(multiply(const_5, const_5), const_4))))) | multiply(const_5,const_5)|multiply(#0,const_4)|divide(n0,#1)|divide(n1,#1)|divide(n2,#1)|add(#2,#3)|add(#5,#4)|subtract(const_1,#6) | d ) 2 / 5 | other |
math_qa__L8iH8TwFF2Izj8Yd | The milk level in a rectangular box measuring 50 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons) Choose the correct option.
A) 100
B) 250
C) 750
D) 4687.5
E) 5635.5 | <gadget id="calculator">50 * 25</gadget>
<output>1_250</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1_250 * (1/2)</gadget>
<output>625</output>
<gadget id="calculator">625 * 7.5</gadget>
<output>4_687.5</output>
<result>D</result> | D | 4,687.5 | The milk level in a rectangular box measuring 50 feet by 25 feet is to be lowered by 6 inches. How many gallons of milk must be removed? (1 cu ft = 7.5 gallons) | {
"A": "100",
"B": "250",
"C": "750",
"D": "4687.5",
"E": "5635.5"
} | multiply(multiply(multiply(50, 25), divide(1, const_2)), 7.5) | divide(n3,const_2)|multiply(n0,n1)|multiply(#0,#1)|multiply(n4,#2)| | "6 inches = 1 / 2 feet ( there are 12 inches in a foot . ) , so 50 * 25 * 1 / 2 = 625 feet ^ 3 of milk must be removed , which equals to 625 * 7.5 = 4687.5 gallons . answer : d ." | general |
math_qa__oml9IgRgIRHVovkN | In the new budget , the price of kerosene oil rose by 25%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase ? Choose the correct option.
A) 10 B) 20 C) 30 D) 40 E) none of them | <gadget id="calculator">25 - 4</gadget>
<output>21</output>
<gadget id="calculator">21 - 1</gadget>
<output>20</output>
<result>B</result> | B | 20 | In the new budget , the price of kerosene oil rose by 25%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase ? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "none of them"
} | subtract(subtract(25, const_4), const_1) | subtract(n0,const_4)|subtract(#0,const_1) | reduction in consumption = [ ( ( r / ( 100 + r ) ) * 100 ] % = [ ( 25 / 125 ) * 100 ] % = 20 % . answer is b . | general |
math_qa__tsO3B9FtkI9pLTvj | The LCM of two numbers is 2310 and HCF is 26. If one of the numbers is 210. Then what is the other number ?
Pick:
A) 715 B) 825 C) 286 D) 582 E) 465 | <gadget id="calculator">2_310 * 26</gadget>
<output>60_060</output>
<gadget id="calculator">60_060 / 210</gadget>
<output>286</output>
<result>C</result> | C | 286 | The LCM of two numbers is 2310 and HCF is 26. If one of the numbers is 210. Then what is the other number ? | {
"A": "715",
"B": "825",
"C": "286",
"D": "582",
"E": "465"
} | divide(multiply(2310, 26), 210) | multiply(n0,n1)|divide(#0,n2)| | "first number * second number = lcm * hcf other number = 2310 * 26 / 210 = 11 * 26 = 286 answer : c" | physics |
math_qa__JdF8ZsOW6Ow8t1QF | Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer) Choose the correct answer: A) 3337 B) 2782 C) 2788 D) 4266 E) 2321 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">14 * 1_000</gadget>
<output>14_000</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">14_000 + 800</gadget>
<output>14_800</output>
<gadget id="calculator">13.5 / 100</gadget>
<output>0.135</output>
<gadget id="calculator">1 + 0.135</gadget>
<output>1.135</output>
<gadget id="calculator">1.135 ** 2</gadget>
<output>1.288225</output>
<gadget id="calculator">1.288225 - 1</gadget>
<output>0.288225</output>
<gadget id="calculator">14_800 * 0.288225</gadget>
<output>4_265.73</output>
<result>D</result> | D | 4,266 | Find the compound interest accrued on an amount of Rs.14,800 at 13.5% p.a at the end of two years. (Round off your answer to nearest integer) | {
"A": "3337",
"B": "2782",
"C": "2788",
"D": "4266",
"E": "2321"
} | multiply(add(multiply(multiply(add(const_3, const_4), const_2), multiply(const_100, multiply(add(const_2, const_3), const_2))), multiply(subtract(multiply(add(const_2, const_3), const_2), const_2), const_100)), subtract(power(add(const_1, divide(13.5, const_100)), const_2), const_1)) | add(const_3,const_4)|add(const_2,const_3)|divide(n1,const_100)|add(#2,const_1)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(#5,const_100)|power(#3,const_2)|subtract(#5,const_2)|multiply(#4,#6)|multiply(#8,const_100)|subtract(#7,const_1)|add(#9,#10)|multiply(#12,#11) | ci = 14800 { [ 1 + 13.5 / 100 ] 2 - 1 } = 14800 { [ 1 + 27 / 200 ] 2 - 1 = 14800 { 2 + 27 / 200 } { 27 / 200 } = ( 74 ) [ 2 + 27 / 200 ] ( 27 ) = 1998 [ 2 + 27 / 200 ] = 3996 + 269.73 = rs . 4266 answer : d | gain |
math_qa__oYdux4iWPwCwRrra | if all of the telephone extensions in a certain company must be even numbers , and if each of the extensions uses all 4 of the digits 1 , 2 , 3 , and 8 , what is the greatest number of 4 - digit extensions that the company can have ? Pick one:
A) 4 B) 6 C) 12 D) 16 E) 24 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>C</result> | C | 12 | if all of the telephone extensions in a certain company must be even numbers , and if each of the extensions uses all 4 of the digits 1 , 2 , 3 , and 8 , what is the greatest number of 4 - digit extensions that the company can have ? | {
"A": "4",
"B": "6",
"C": "12",
"D": "16",
"E": "24"
} | multiply(4, const_3) | multiply(n0,const_3) | since the phone number must be even , the unit ' s digit can be either 2 or 8 . when the unit ' s digit is 2 - - > number of possibilities is 3 ! = 6 when the unit ' s digit is 8 - - > number of possibilities is 3 ! = 6 largest number of extensions = 6 + 6 = 12 answer : c | general |
math_qa__cnjsoKrEnCVxaL4E | the first half of the 20th century, the population of a particular country increased by 200 percent. In the second half of the century, the population increased by 300 percent. What was the percent increase for the 20th century as a whole? Pick.
A) 500 % B) 600 % C) 800 % D) 1100 % E) 1200 % | <gadget id="calculator">300 / 100</gadget>
<output>3</output>
<gadget id="calculator">100 * 3</gadget>
<output>300</output>
<gadget id="calculator">300 * 3</gadget>
<output>900</output>
<gadget id="calculator">900 + 300</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 - 100</gadget>
<output>1_100</output>
<result>D</result> | D | 1,100 | the first half of the 20th century, the population of a particular country increased by 200 percent. In the second half of the century, the population increased by 300 percent. What was the percent increase for the 20th century as a whole? | {
"A": "500 %",
"B": "600 %",
"C": "800 %",
"D": "1100 %",
"E": "1200 %"
} | subtract(add(multiply(multiply(const_100, divide(300, const_100)), divide(300, const_100)), multiply(const_100, divide(300, const_100))), const_100) | divide(n2,const_100)|multiply(#0,const_100)|multiply(#0,#1)|add(#2,#1)|subtract(#3,const_100) | say initially population was 100 . what is 200 % of 100 ? it is 200 / 100 * 100 = 200 . an increase of 200 % means the new population became 100 + 200 = 300 what is 300 % of 300 ? it is 300 / 100 * 300 = 900 an increase of 300 % means the new population now is 300 + 900 = 1200 so from 100 , the population increased to 1200 i . e . an increase of 1100 . 1100 is what percent of 100 ? 1100 = x / 100 * 100 i . e . it is 1100 % d | gain |
math_qa__NRaZx0ieR1qQQPSJ | At a certain restaurant, the average (arithmetic mean) number of customers served for the past x days was 60. If the restaurant serves 120 customers today, raising the average to 70 customers per day, what is the value of x? Select: A) 2 B) 5 C) 9 D) 15 E) 30 | <gadget id="calculator">120 - 70</gadget>
<output>50</output>
<gadget id="calculator">70 - 60</gadget>
<output>10</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">120 - 100</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">5 - (1/5)</gadget>
<output>24/5 = around 4.8</output>
<result>B</result> | B | 5 | At a certain restaurant, the average (arithmetic mean) number of customers served for the past x days was 60. If the restaurant serves 120 customers today, raising the average to 70 customers per day, what is the value of x? | {
"A": "2",
"B": "5",
"C": "9",
"D": "15",
"E": "30"
} | subtract(divide(subtract(120, 70), subtract(70, 60)), divide(subtract(120, const_100), const_100)) | subtract(n1,n2)|subtract(n2,n0)|subtract(n1,const_100)|divide(#0,#1)|divide(#2,const_100)|subtract(#3,#4)| | "withoutusing the formula , we can see that today the restaurant served 50 customers above the average . the total amount above the average must equal total amount below the average . this additional 50 customers must offset the “ deficit ” below the average of 70 created on the x days the restaurant served only 60 customers per day . 50 / 10 = 5 days . choice ( a ) . withthe formula , we can set up the following : 70 = ( 60 x + 120 ) / ( x + 1 ) 70 x + 70 = 60 x + 120 10 x = 50 x = 5 answer choice ( b )" | general |
math_qa__LJHwJXv4duRxXD78 | 100 students appeared in 2 tests.60 students passed 1st test. 40 students passed in the 2nd test. 20 students passed in both 1 and 2 tests. what is the probability of the students who failed in both tests? Options
A) 10 % B) 15 % C) 20 % D) 25 % E) 30 % | <gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<result>C</result> | C | 20 | 100 students appeared in 2 tests.60 students passed 1st test. 40 students passed in the 2nd test. 20 students passed in both 1 and 2 tests. what is the probability of the students who failed in both tests? | {
"A": "10 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "30 %"
} | subtract(const_100, subtract(add(60, 40), 20)) | add(n2,n4)|subtract(#0,n6)|subtract(const_100,#1) | 20 student passed both two test 40 student passed only 1 st test 20 student passed only 2 nd test so 100 - ( 20 + 40 + 20 ) = 20 student failed in both sub so ans is 20 % answer : c | other |
math_qa__uSQ0ojrO6IKL1Vp5 | There has been successive increases of 30% and then 20% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change? Choices:
A) 20 % B) 24 % C) 28 % D) 32 % E) 36 % | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 * 20</gadget>
<output>2_600</output>
<gadget id="calculator">2_600 / 100</gadget>
<output>26</output>
<gadget id="calculator">130 + 26</gadget>
<output>156</output>
<gadget id="calculator">100 / 156</gadget>
<output>25/39 = around 0.641026</output>
<gadget id="calculator">1 - (25/39)</gadget>
<output>14/39 = around 0.358974</output>
<gadget id="calculator">(14/39) * 100</gadget>
<output>1_400/39 = around 35.897436</output>
<result>E</result> | E | 36 | There has been successive increases of 30% and then 20% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change? | {
"A": "20 %",
"B": "24 %",
"C": "28 %",
"D": "32 %",
"E": "36 %"
} | multiply(subtract(const_1, divide(const_100, add(add(const_100, 30), divide(multiply(add(const_100, 30), 20), const_100)))), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|add(#0,#2)|divide(const_100,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "let p be the original price per unit of gas . let x be the original gas consumption . let y be the reduced gas consumption . y * 1.2 * 1.3 * p = x * p y = x / ( 1.2 * 1.3 ) which is about 0.64 x which is a decrease of about 36 % . the answer is e ." | general |
math_qa__IKluck9Xo4dLdEzf | A train speeds past a pole in 50 seconds and a platform 500 m long in 100 seconds. Its length is: Select the correct option:
A) 550 m .
B) 300 m .
C) 600 m .
D) 400 m .
E) 500 m . | <gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">500 * 1</gadget>
<output>500</output>
<result>E</result> | E | 500 | A train speeds past a pole in 50 seconds and a platform 500 m long in 100 seconds. Its length is: | {
"A": "550 m .",
"B": "300 m .",
"C": "600 m .",
"D": "400 m .",
"E": "500 m ."
} | multiply(500, subtract(const_2, const_1)) | subtract(const_2,const_1)|multiply(n1,#0)| | "let the length of the train be x meters and its speed be y m / sec . they , x / y = 50 = > y = x / 50 x + 500 / 100 = x / 50 x = 500 m . answer : option e" | physics |
math_qa__pPYVcAxOqp5QGyEz | If m is an integer such that (-2)^2m=2^(24-m) then m=? Choose the correct choice from the following options:
A) 7
B) 8
C) 9
D) 10
E) 11 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<result>B</result> | B | 8 | If m is an integer such that (-2)^2m=2^(24-m) then m=? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | divide(24, add(2, const_1)) | add(n0,const_1)|divide(n3,#0)| | "2 m = 24 - m 3 m = 24 m = 8 the answer is b ." | general |
math_qa__H8Yys68P1Ok7ArHu | A seller of used cars has 16 cars to sell and each of his clients selected 2 cars that he liked most. If each car was selected exactly thrice, how many clients visited the garage? Select.
A) 8 B) 10 C) 12 D) 14 E) 24 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<result>E</result> | E | 24 | A seller of used cars has 16 cars to sell and each of his clients selected 2 cars that he liked most. If each car was selected exactly thrice, how many clients visited the garage? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "24"
} | multiply(divide(16, 2), const_3) | divide(n0,n1)|multiply(#0,const_3) | ifno caris selected more than once then the number of clients = 16 / 2 = 8 but since every car is being selected three times so no . of clients must be thrice as well = 8 * 3 = 24 answer : option e | general |
math_qa__WnChyegpvOgnf2DW | The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is? Choose the correct choice from the following.
A) 30 / 7 B) 30 / 9 C) 30 / 2 D) 30 / 3 E) 30 / 6 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<result>A</result> | A | 4.285714 | The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is? | {
"A": "30 / 7",
"B": "30 / 9",
"C": "30 / 2",
"D": "30 / 3",
"E": "30 / 6"
} | divide(multiply(6, 5), 7) | multiply(n0,n2)|divide(#0,n1)| | "required fraction = l . c . m of 6 / 7 , 5 / 14 , 10 / 21 = ( l . c . m of 6 , 5 , 10 ) / ( h . c . f of 7 , 14 , 21 ) = 30 / 7 answer : a" | general |
math_qa__rmT5jizsGuEF0LSC | A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 40% lemonade syrup? Choose the correct choice from the following options.
A) 1.5 B) 1.75 C) 2.14 D) 2.34 E) 2.64 | <gadget id="calculator">8 + 7</gadget>
<output>15</output>
<gadget id="calculator">7 / 15</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(7/15) - (2/5)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/15) / (7/15)</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">(1/7) * 15</gadget>
<output>15/7 = around 2.142857</output>
<result>C</result> | C | 2.14 | A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 40% lemonade syrup? | {
"A": "1.5",
"B": "1.75",
"C": "2.14",
"D": "2.34",
"E": "2.64"
} | multiply(divide(subtract(divide(7, add(8, 7)), divide(const_2, add(const_2, const_3))), divide(7, add(8, 7))), add(8, 7)) | add(n0,n1)|add(const_2,const_3)|divide(n1,#0)|divide(const_2,#1)|subtract(#2,#3)|divide(#4,#2)|multiply(#0,#5)| | "let the total solution is 150 l with 80 l water & 70 l syrup . to make 40 % syrup solution , the result solution must have 90 l syrup and 60 l syrup . therefore we are taking 10 l of syrup from initial solution and replacing with water . using urinary method : 70 l syrup in 150 l solution 10 l syrup in 21.4 l solution we started by multiplying 10 now to get to the result we need to divide by 10 = > amount of solution to be replaced with water = ( 21.4 / 10 ) = 2.14 . correct option : c" | gain |
math_qa__47UUvFoVK9CGXcq3 | The length of a rectangular floor is more than its breadth by 200%. If Rs. 640 is required to paint the floor at the rate of Rs. 5 per sq m, then what would be the length of the floor? Select the correct option
A) 19.6 m . B) 20.0 m . C) 19.3 m . D) 18.5 m . E) 18.9 m . | <gadget id="calculator">640 / 5</gadget>
<output>128</output>
<gadget id="calculator">128 / 3</gadget>
<output>128/3 = around 42.666667</output>
<gadget id="calculator">(128/3) ** (1/2)</gadget>
<output>8*sqrt(6)/3 = around 6.531973</output>
<gadget id="calculator">(8*sqrt(6)/3) * 3</gadget>
<output>8*sqrt(6) = around 19.595918</output>
<result>A</result> | A | 19.6 | The length of a rectangular floor is more than its breadth by 200%. If Rs. 640 is required to paint the floor at the rate of Rs. 5 per sq m, then what would be the length of the floor? | {
"A": "19.6 m .",
"B": "20.0 m .",
"C": "19.3 m .",
"D": "18.5 m .",
"E": "18.9 m ."
} | multiply(sqrt(divide(divide(640, 5), const_3)), const_3) | divide(n1,n2)|divide(#0,const_3)|sqrt(#1)|multiply(#2,const_3)| | "let the length and the breadth of the floor be l m and b m respectively . l = b + 200 % of b = l + 3 b = 3 b area of the floor = 640 / 5 = 128 sq m l b = 128 i . e . , l * l / 3 = 128 l 2 = 384 = > l = 19.6 m . answer : a" | gain |
math_qa__Z8vUzkiOmEbiLB3m | A reduction of 15% in the price of wheat enables a house wife to obtain 3 kgs more for Rs.500, what is the reduced price for kg? Choose the correct choice:
A) rs . 10
B) rs . 15
C) rs . 20
D) rs . 25
E) rs . 30 | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(17/20) * 500</gadget>
<output>425</output>
<gadget id="calculator">500 - 425</gadget>
<output>75</output>
<gadget id="calculator">75 / 3</gadget>
<output>25</output>
<result>D</result> | D | 25 | A reduction of 15% in the price of wheat enables a house wife to obtain 3 kgs more for Rs.500, what is the reduced price for kg? | {
"A": "rs . 10",
"B": "rs . 15",
"C": "rs . 20",
"D": "rs . 25",
"E": "rs . 30"
} | divide(subtract(500, multiply(divide(subtract(const_100, 15), const_100), 500)), 3) | subtract(const_100,n0)|divide(#0,const_100)|multiply(n2,#1)|subtract(n2,#2)|divide(#3,n1) | explanation : 500 * ( 15 / 100 ) = 75 - - - - 3 ? - - - - 1 = > rs . 25 answer : d | gain |
math_qa__TrNPC9iZKW24vo1O | The ration of the father’s age to his son’s age is 7:3.The product of their ages is 756.The ratio of their ages after 6 years will be : Choices.
A) 5 : 2 B) 2 : 1 C) 11 : 7 D) 13 : 9 E) none of these | <gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">756 / 21</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 + 6</gadget>
<output>48</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">18 + 6</gadget>
<output>24</output>
<gadget id="calculator">48 / 24</gadget>
<output>2</output>
<result>B</result> | B | 2 | The ration of the father’s age to his son’s age is 7:3.The product of their ages is 756.The ratio of their ages after 6 years will be : | {
"A": "5 : 2",
"B": "2 : 1",
"C": "11 : 7",
"D": "13 : 9",
"E": "none of these"
} | divide(add(multiply(7, sqrt(divide(756, multiply(7, 3)))), 6), add(multiply(3, sqrt(divide(756, multiply(7, 3)))), 6)) | multiply(n0,n1)|divide(n2,#0)|sqrt(#1)|multiply(n0,#2)|multiply(n1,#2)|add(n3,#3)|add(n3,#4)|divide(#5,#6) | solution let the present ages of the father and son be 7 x and 3 x years respectively . then , 7 x 3 x = 756 ⇔ 21 x 2 = 756 ⇔ x 2 = 36 ⇔ x = 6 . ∴ required ratio = ( 7 x + 6 ) : ( 3 x + 6 ) = 48 : 24 = 2 : 1 . answer b | general |
math_qa__lrGtIEaNhlTlaIf6 | At a certain university, 68% of the professors are women, and 70% of the professors are tenured. If 90% of the professors are women, tenured, or both, then what percent of the men are tenured?
Choices
A) 25 B) 37.5 C) 55 D) 62.5 E) 75 | <gadget id="calculator">100 - 68</gadget>
<output>32</output>
<gadget id="calculator">90 - 68</gadget>
<output>22</output>
<gadget id="calculator">32 + 22</gadget>
<output>54</output>
<result>C</result> | C | 55 | At a certain university, 68% of the professors are women, and 70% of the professors are tenured. If 90% of the professors are women, tenured, or both, then what percent of the men are tenured? | {
"A": "25",
"B": "37.5",
"C": "55",
"D": "62.5",
"E": "75"
} | add(subtract(const_100, 68), subtract(90, 68)) | subtract(const_100,n0)|subtract(n2,n0)|add(#0,#1) | total women = 68 % total men = 40 % total tenured = 70 % ( both men and women ) therefore , women tenured + women professors + men tenured = 90 % men tenured = 22 % but question wants to know the percent of men that are tenured 22 % / 40 % = 55 % c | gain |
math_qa__tVKXHexlqWD2b7PB | How many times are the hands of a clock at right angles in a day? Choose the correct option.
A) 42 B) 44 C) 49 D) 41 E) 47 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">22 * 2</gadget>
<output>44</output>
<result>B</result> | B | 44 | How many times are the hands of a clock at right angles in a day? | {
"A": "42",
"B": "44",
"C": "49",
"D": "41",
"E": "47"
} | multiply(multiply(subtract(const_12, const_1), const_2), const_2) | subtract(const_12,const_1)|multiply(#0,const_2)|multiply(#1,const_2) | in 12 hours , they are at right angles 22 times . = = > in 24 hours , they are at right angles 44 times . answer is b . | physics |
math_qa__zeus5e1qNUHOA4Fm | A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work. Choose one.
A) 27 days B) 54 days C) 56 days D) 68 days E) none of these | <gadget id="calculator">18 * 3</gadget>
<output>54</output>
<result>B</result> | B | 54 | A is twice as good as workman as B and together they finish a piece of work in 18 days. In how many days will B alone finish the work. | {
"A": "27 days",
"B": "54 days",
"C": "56 days",
"D": "68 days",
"E": "none of these"
} | multiply(18, const_3) | multiply(n0,const_3) | explanation : as per question , a do twice the work as done by b . so a : b = 2 : 1 also ( a + b ) one day work = 1 / 18 to get days in which b will finish the work , lets calculate work done by b in 1 day = = ( 118 ∗ 13 ) = 154 [ please note we multiplied by 1 / 3 as per b share and total of ra ɵ o is 1 / 3 ] so b will finish the work in 54 days answer : b | physics |
math_qa__MDLOgRw8BPReUcCC | In the xy-coordinate system, what is the slope of the line that goes through the origin and is equidistant from the two points P = (4, 6) and Q = (6, 2)? Options: A) 0.8 B) 1.0 C) 1.2 D) 1.4 E) 1.6 | <gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<result>A</result> | A | 0.8 | In the xy-coordinate system, what is the slope of the line that goes through the origin and is equidistant from the two points P = (4, 6) and Q = (6, 2)? | {
"A": "0.8",
"B": "1.0",
"C": "1.2",
"D": "1.4",
"E": "1.6"
} | divide(divide(add(6, 2), const_2), divide(add(4, 6), const_2)) | add(n1,n3)|add(n0,n1)|divide(#0,const_2)|divide(#1,const_2)|divide(#2,#3) | first , get the middle coordinate between ( 46 ) and ( 62 ) . x = 4 + ( 6 - 4 ) / 2 = 5 y = 2 + ( 6 - 2 ) / 2 = 4 second , get the slope of ( 54 ) and ( 00 ) . m = 4 - 0 / 5 - 0 = 4 / 5 = 0.8 answer : a | general |
math_qa__ID1ZGdvKI9M2tJZ8 | The youngest of 4 children has siblings who are 3, 5, and 8 years older than she is. If the average (arithmetic mean) age of the 4 siblings is 21, what is the age of the youngest sibling? Choose one:
A) 17
B) 18
C) 19
D) 21
E) 22 | <gadget id="calculator">4 * 21</gadget>
<output>84</output>
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 + 8</gadget>
<output>17</output>
<gadget id="calculator">84 - 17</gadget>
<output>67</output>
<gadget id="calculator">67 / 4</gadget>
<output>67/4 = around 16.75</output>
<result>A</result> | A | 17 | The youngest of 4 children has siblings who are 3, 5, and 8 years older than she is. If the average (arithmetic mean) age of the 4 siblings is 21, what is the age of the youngest sibling? | {
"A": "17",
"B": "18",
"C": "19",
"D": "21",
"E": "22"
} | divide(subtract(multiply(4, 21), add(add(4, 5), 8)), 4) | add(n0,n2)|multiply(n0,n5)|add(n3,#0)|subtract(#1,#2)|divide(#3,n0)| | "total age of the 4 sibling is 21 x 4 = 84 years . . we already have the total age of all the children is 4 y + 16 so , 4 y + 16 = 84 or , 4 y = 68 or , y = 17 so , age of the youngest child is 17 years . answer : a" | general |
math_qa__TX9PpZWMuuKzEJrV | The speed of a boat in still water is 36 kmph. What is the speed of the stream if the boat can cover 80 km downstream or 40 km upstream in the same time? Pick
A) 10 kmph
B) 14 kmph
C) 12 kmph
D) 16 kmph
E) 15 kmph | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">36 / 3</gadget>
<output>12</output>
<result>C</result> | C | 12 | The speed of a boat in still water is 36 kmph. What is the speed of the stream if the boat can cover 80 km downstream or 40 km upstream in the same time? | {
"A": "10 kmph",
"B": "14 kmph",
"C": "12 kmph",
"D": "16 kmph",
"E": "15 kmph"
} | divide(36, add(const_1, const_2)) | add(const_1,const_2)|divide(n0,#0)| | "x = the speed of the stream ( 36 + x ) / ( 36 - x ) = 2 / 1 36 + x = 72 - 2 x 3 x = 36 x = 12 km / hour if the speed of the stream is 12 km / hour , then the ' downstream ' speed of the boat is 36 + 12 = 48 km / hour and the ' upstream ' speed of the boat is 36 - 12 = 24 km / hour . in that way , if the boat traveled for 2 hours , it would travel 2 x 48 = 96 km downstream and 2 x 24 = 48 km / hour upstream . answer : c" | physics |
math_qa__ZxUoBfRgTjO1eIY8 | A man buys a cycle for Rs. 1800 and sells it at a loss of 10%. What is the selling price of the cycle? Choose the correct choice
A) 1410 B) 1620 C) 1430 D) 1440 E) 1540 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 * 1_800</gadget>
<output>162_000</output>
<gadget id="calculator">162_000 / 100</gadget>
<output>1_620</output>
<result>B</result> | B | 1,620 | A man buys a cycle for Rs. 1800 and sells it at a loss of 10%. What is the selling price of the cycle? | {
"A": "1410",
"B": "1620",
"C": "1430",
"D": "1440",
"E": "1540"
} | divide(multiply(subtract(const_100, 10), 1800), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "s . p . = 90 % of rs . 1800 = 90 / 100 x 1800 = rs . 1620 answer : b" | gain |
math_qa__qP9syjsMNyLNgTcC | If n divided by 11 has a remainder of 1, what is the remainder when 5 times n is divided by 11? Choose the correct choice from the following answers:
A) 1 B) 2 C) 3 D) 9 E) 5 | <gadget id="calculator">5 * 1</gadget>
<output>5</output>
<result>E</result> | E | 5 | If n divided by 11 has a remainder of 1, what is the remainder when 5 times n is divided by 11? | {
"A": "1",
"B": "2",
"C": "3",
"D": "9",
"E": "5"
} | multiply(5, 1) | multiply(n1,n2)| | "as per question = > n = 11 p + 1 for some integer p hence 5 n = > 55 q + 5 = > remainder = > 5 for some integer q hence e" | general |
math_qa__1OgvQP1zZNf091X5 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 47, then how old is B? Choices:
A) 17 years
B) 19 years
C) 18 years
D) 10 years
E) 12 years | <gadget id="calculator">47 - 2</gadget>
<output>45</output>
<gadget id="calculator">45 * 2</gadget>
<output>90</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">90 / 5</gadget>
<output>18</output>
<result>C</result> | C | 18 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 47, then how old is B? | {
"A": "17 years",
"B": "19 years",
"C": "18 years",
"D": "10 years",
"E": "12 years"
} | divide(multiply(subtract(47, const_2), const_2), add(const_4, const_1)) | add(const_1,const_4)|subtract(n0,const_2)|multiply(#1,const_2)|divide(#2,#0)| | "let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 47 5 x = 45 = > x = 9 hence , b ' s age = 2 x = 18 years . answer : c" | general |
math_qa__sPfJSDA1dDJjeRHr | Find the value of 658217 x 99999 = m? Choose the correct choice from the following options:
A) 65842158943 B) 65839570421 C) 65821141683 D) 66821785904 E) 65821041783 | <gadget id="calculator">99_999 - 4</gadget>
<output>99_995</output>
<gadget id="calculator">99_995 * 658_217</gadget>
<output>65_818_408_915</output>
<result>E</result> | E | 65,821,041,783 | Find the value of 658217 x 99999 = m? | {
"A": "65842158943",
"B": "65839570421",
"C": "65821141683",
"D": "66821785904",
"E": "65821041783"
} | multiply(subtract(99999, const_4), 658217) | subtract(n1,const_4)|multiply(#0,n0)| | "658217 x 99999 = 658217 x ( 100000 - 1 ) = 658217 x 100000 - 658217 x 1 = 65821700000 - 658217 = 65821041783 e" | general |
math_qa__89qS5VlFZIpbCWot | A girl was asked to multiply a certain number by 43. She multiplied it by 34 and got his answer less than the correct one by 1251. Find the number to be multiplied. Choose the correct choice from the following choices
A) 130 B) 132 C) 134 D) 136 E) 139 | <gadget id="calculator">43 - 34</gadget>
<output>9</output>
<gadget id="calculator">1_251 / 9</gadget>
<output>139</output>
<result>E</result> | E | 139 | A girl was asked to multiply a certain number by 43. She multiplied it by 34 and got his answer less than the correct one by 1251. Find the number to be multiplied. | {
"A": "130",
"B": "132",
"C": "134",
"D": "136",
"E": "139"
} | divide(1251, subtract(43, 34)) | subtract(n0,n1)|divide(n2,#0)| | "let the required number be x . then , 43 x – 34 x = 1251 or 9 x = 1251 or x = 139 . required number = 139 . answer : e" | general |
math_qa__1ONpPo73qBanm17s | 10 years ago , the age of peter was one - third the age of jacob at that time . the present age of jacob is 12 years more than the present age of peter . find the present age of peter ?
Choices:
A) 15 B) 11 C) 18 D) 16 E) 20 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">10 + 6</gadget>
<output>16</output>
<result>D</result> | D | 16 | 10 years ago , the age of peter was one - third the age of jacob at that time . the present age of jacob is 12 years more than the present age of peter . find the present age of peter ? | {
"A": "15",
"B": "11",
"C": "18",
"D": "16",
"E": "20"
} | add(10, divide(12, const_2)) | divide(n1,const_2)|add(n0,#0) | d 16 let the present ages of peter and jacob be ' a ' and ' b ' respectively . a - 10 = 1 / 3 ( b - 10 ) - - - ( 1 ) b = a + 12 substituting b = a + 12 in first equation , a - 10 = 1 / 3 ( a + 2 ) = > 3 a - 30 = a + 2 = > 2 a = 32 = > a = 16 . | general |
math_qa__mPZ1pwPc2gD8Hwrg | At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $8 on candy, how much did John spend at the supermarket? Choose the correct choice from the following: A) $ 60 B) $ 80 C) $ 90 D) $ 120 E) $ 180 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/10) + (1/3)</gadget>
<output>13/30 = around 0.433333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(13/30) + (1/2)</gadget>
<output>14/15 = around 0.933333</output>
<gadget id="calculator">1 - (14/15)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">8 / (1/15)</gadget>
<output>120</output>
<result>D</result> | D | 120 | At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $8 on candy, how much did John spend at the supermarket? | {
"A": "$ 60",
"B": "$ 80",
"C": "$ 90",
"D": "$ 120",
"E": "$ 180"
} | divide(8, subtract(1, add(add(divide(1, 10), divide(1, 3)), divide(1, 2)))) | divide(n0,n5)|divide(n0,n3)|divide(n0,n1)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5) | let ' s let t = total number of dollars spent at the supermarket . with this variable we can set up an equation and determine t . we are given that john spent 1 / 2 of his money on fresh fruits and vegetables , or ( 1 / 2 ) t , 1 / 3 on meat products , or ( 1 / 3 ) t , and 1 / 10 on bakery products , or ( 1 / 10 ) t . we are also given that he spent the remaining $ 8 on candy . since we know where all his money was allocated , we can sum these values together and set the sum to t . so we have : ( 1 / 2 ) t + ( 1 / 3 ) t + ( 1 / 10 ) t + 8 = t to get rid of the fractions we can multiply the entire equation by 30 , and we obtain : 15 t + 10 t + 3 t + 240 = 30 t 28 t + 240 = 30 t 240 = 2 t t = 120 john spent $ 90 at the supermarket . answer : d | general |
math_qa__sk1spOaNKEoqyKaO | Tough and Tricky questions: Exponents.
If 5^(x+1)*4^(y-1) = 25^x*64^y, then x + y = Answers.
A) 3 / 2 B) - 1 / 2 C) - 1 D) 1 / 2 E) 2 / 3 | <gadget id="calculator">gcd(64, 25)</gadget>
<output>1</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<result>D</result> | D | 0.5 | Tough and Tricky questions: Exponents.
If 5^(x+1)*4^(y-1) = 25^x*64^y, then x + y = | {
"A": "3 / 2",
"B": "- 1 / 2",
"C": "- 1",
"D": "1 / 2",
"E": "2 / 3"
} | divide(gcd(64, 25), const_2) | gcd(n4,n5)|divide(#0,const_2) | here is my solution . 5 ^ ( x + 1 ) * 4 ^ ( y - 1 ) = 25 ^ x * 64 ^ y here rhs 25 ^ x * 64 ^ y = 5 ^ ( 2 x ) * 4 ^ ( 3 y ) equating powers on both sides - - > x + 1 = 2 x , thus x = 1 and 2 y - 1 = 3 y giving y = - 1 / 2 so , x + y = 1 / 2 option : d | general |
math_qa__6M69KLVkJdtzbqPl | What is the remainder of E=3^19 when divided by 10? Choose the correct answer: A) 0 B) 1 C) 5 D) 7 E) 9 | <gadget id="calculator">19 % 4</gadget>
<output>3</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 % 10</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the remainder of E=3^19 when divided by 10? | {
"A": "0",
"B": "1",
"C": "5",
"D": "7",
"E": "9"
} | reminder(power(3, reminder(19, const_4)), const_10) | reminder(n1,const_4)|power(n0,#0)|reminder(#1,const_10) | i looked for patterns : ^ 2 - units digit 9 ^ 3 - units digit 7 ^ 4 - units digit 1 ^ 5 - units digit 3 hence , we can see that when raised to a power which is multiple of 4 , the units digit is 1 , and when to an even power not multiple of 4 , the units digit is 9 and we can then see : ^ 16 - units digit 1 , or ^ 18 - units digit 9 and ^ 19 - units digit 7 therefore , e = when divided by 10 , the remainder must be 7 . d | general |
math_qa__w75v8DjonKoEEnfq | what no should be subtracted from 92555 to make it a perfect square ? Choose one: A) 128 B) 158 C) 178 D) 139 E) 140 | <gadget id="calculator">92_555 ** (1/2)</gadget>
<output>sqrt(92555) = around 304.228533</output>
<gadget id="calculator">floor(sqrt(92555))</gadget>
<output>304</output>
<gadget id="calculator">304 * 304</gadget>
<output>92_416</output>
<gadget id="calculator">92_555 - 92_416</gadget>
<output>139</output>
<result>D</result> | D | 139 | what no should be subtracted from 92555 to make it a perfect square ? | {
"A": "128",
"B": "158",
"C": "178",
"D": "139",
"E": "140"
} | subtract(92555, multiply(floor(sqrt(92555)), floor(sqrt(92555)))) | sqrt(n0)|floor(#0)|multiply(#1,#1)|subtract(n0,#2) | root 92555 = 304.228 and 304 ^ 2 = 92416 92555 - 92416 = 139 should be subtracted from 92555 to make it a perfect square answer : d | geometry |
math_qa__IZdIpyJfEHKJz9p5 | A hall is 6 meters long and 6 meters wide. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, what is the volume of the hall (in cubic meters)? Choose the correct choice from the following answers: A) 96 B) 100 C) 104 D) 108 E) 112 | <gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">36 * 2</gadget>
<output>72</output>
<gadget id="calculator">2 * (6 + 6)</gadget>
<output>24</output>
<gadget id="calculator">72 / 24</gadget>
<output>3</output>
<gadget id="calculator">6 * 6 * 3</gadget>
<output>108</output>
<result>D</result> | D | 108 | A hall is 6 meters long and 6 meters wide. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, what is the volume of the hall (in cubic meters)? | {
"A": "96",
"B": "100",
"C": "104",
"D": "108",
"E": "112"
} | volume_rectangular_prism(6, 6, divide(multiply(rectangle_area(6, 6), const_2), rectangle_perimeter(6, 6))) | rectangle_area(n0,n1)|rectangle_perimeter(n0,n1)|multiply(#0,const_2)|divide(#2,#1)|volume_rectangular_prism(n0,n1,#3)| | "2 hl + 2 hw = 2 lw h = lw / ( l + w ) volume = lwh = ( lw ) ^ 2 / ( l + w ) = 108 the answer is d ." | geometry |
math_qa__L3qkCLYJw1WsYXpV | The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.6. The true discount is Choose the most appropriate option: A) rs . 72 B) rs . 36 C) rs . 54 D) rs . 50 E) none | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">6 / (3/25)</gadget>
<output>50</output>
<result>D</result> | D | 50 | The banker's gain on a bill due due 1 year hence at 12% per annum is Rs.6. The true discount is | {
"A": "rs . 72",
"B": "rs . 36",
"C": "rs . 54",
"D": "rs . 50",
"E": "none"
} | divide(6, divide(12, const_100)) | divide(n1,const_100)|divide(n2,#0)| | "solution t . d = [ b . g x 100 / r x t ] = rs . ( 6 x 100 / 12 x 1 ) = rs . 50 . answer d" | gain |
math_qa__SKplce9vSBfPJlw4 | A line has a slope of 3/4 and intersects the point Q (-12, -39). At which point does this line intersect the x-axis? Pick one.
A) ( 40,0 ) B) ( 30,0 ) C) ( 0,40 ) D) ( 40,30 ) E) ( 0,30 ) | <gadget id="calculator">-39</gadget>
<output>-39</output>
<gadget id="calculator">-12</gadget>
<output>-12</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(-12) * (3/4)</gadget>
<output>-9</output>
<gadget id="calculator">(-39) - (-9)</gadget>
<output>-30</output>
<gadget id="calculator">(-30) / (3/4)</gadget>
<output>-40</output>
<gadget id="calculator">-(-40)</gadget>
<output>40</output>
<gadget id="calculator">40 * 10</gadget>
<output>400</output>
<result>A</result> | A | 400 | A line has a slope of 3/4 and intersects the point Q (-12, -39). At which point does this line intersect the x-axis? | {
"A": "( 40,0 )",
"B": "( 30,0 )",
"C": "( 0,40 )",
"D": "( 40,30 )",
"E": "( 0,30 )"
} | multiply(negate(divide(subtract(negate(39), multiply(negate(12), divide(3, 4))), divide(3, 4))), const_10) | divide(n0,n1)|negate(n3)|negate(n2)|multiply(#0,#2)|subtract(#1,#3)|divide(#4,#0)|negate(#5)|multiply(#6,const_10)| | "assume that the equation of the line is y = mx + c , where m and c are the slope and y - intercept . you are also given that the line crosses the point ( - 12 , - 39 ) , this means that this point will also lie on the line above . thus you get - 39 = m * ( - 12 ) + c , with m = 3 / 4 as the slope is given to be 3 / 4 . after substituting the above values , you get c = - 30 . thus the equation of the line is y = 0.75 * x - 30 and the point where it will intersect the x - axis will be with y coordinate = 0 . put y = 0 in the above equation of the line and you will get , x = 40 . thus , the point q of intersection is ( 40,0 ) . a is the correct answer ." | general |
math_qa__VBZ5x9gj9DEzDQ4I | A student took 6 courses last year and received an average (arithmetic mean) grade of 100 points. The year before, the student took 5 courses and received an average grade of 80 points. To the nearest tenth of a point, what was the student’s average grade for the entire two-year period? Pick one: A) 79 B) 89 C) 95 D) 90.91 E) 97.2 | <gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">5 * 80</gadget>
<output>400</output>
<gadget id="calculator">600 + 400</gadget>
<output>1_000</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">1_000 / 11</gadget>
<output>1_000/11 = around 90.909091</output>
<gadget id="calculator">floor(1_000/11)</gadget>
<output>90</output>
<result>D</result> | D | 90.91 | A student took 6 courses last year and received an average (arithmetic mean) grade of 100 points. The year before, the student took 5 courses and received an average grade of 80 points. To the nearest tenth of a point, what was the student’s average grade for the entire two-year period? | {
"A": "79",
"B": "89",
"C": "95",
"D": "90.91",
"E": "97.2"
} | floor(divide(add(multiply(6, 100), multiply(5, 80)), add(6, 5))) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)|floor(#4) | let the 6 courses that were taken last year be a 1 , a 2 , a 3 , a 4 , a 5 , a 6 a 1 + a 2 + a 3 + a 4 + a 5 + a 6 = 100 * 6 = 600 the year before , the 5 courses be b 1 , b 2 , b 3 , b 4 , b 5 b 1 + b 2 + b 3 + b 4 + b 5 = 80 * 5 = 400 student ' s average = ( 600 + 400 ) / 11 = 90.91 answer d | general |
math_qa__xmhZjWuIlxlSgdPF | A motorcyclist started riding at highway marker A, drove 120 miles to highway marker B, and then, without pausing, continued to highway marker C, where she stopped. The average speed of the motorcyclist, over the course of the entire trip, was 50 miles per hour. If the ride from marker A to marker B lasted 3 times as many hours as the rest of the ride, and the distance from marker B to marker C was half of the distance from marker A to marker B, what was the average speed, in miles per hour, of the motorcyclist while driving from marker B to marker C?
Choose the correct choice from the following options:
A) 40 B) 45 C) 50 D) 54 E) 60 | <gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">60 + 120</gadget>
<output>180</output>
<gadget id="calculator">180 / 50</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">(18/5) / 4</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 60</gadget>
<output>54</output>
<result>D</result> | D | 54 | A motorcyclist started riding at highway marker A, drove 120 miles to highway marker B, and then, without pausing, continued to highway marker C, where she stopped. The average speed of the motorcyclist, over the course of the entire trip, was 50 miles per hour. If the ride from marker A to marker B lasted 3 times as many hours as the rest of the ride, and the distance from marker B to marker C was half of the distance from marker A to marker B, what was the average speed, in miles per hour, of the motorcyclist while driving from marker B to marker C? | {
"A": "40",
"B": "45",
"C": "50",
"D": "54",
"E": "60"
} | multiply(divide(divide(add(divide(120, const_2), 120), 50), const_4), divide(120, const_2)) | divide(n0,const_2)|add(n0,#0)|divide(#1,n1)|divide(#2,const_4)|multiply(#3,#0)| | "a - b = 120 miles b - c = 60 miles avg speed = 50 miles time taken for a - b 3 t and b - c be t avg speed = ( 120 + 60 ) / total time 50 = 180 / 4 t t = 54 b - c = 54 mph answer d" | physics |
math_qa__Gmc9z9NEO5v8gOE3 | A 14% stock yielding 10% is quoted at :
Pick.
A) 83.33 B) 110 C) 112 D) 140 E) 160 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">10 * 14</gadget>
<output>140</output>
<result>D</result> | D | 140 | A 14% stock yielding 10% is quoted at : | {
"A": "83.33",
"B": "110",
"C": "112",
"D": "140",
"E": "160"
} | multiply(divide(const_100, 10), 14) | divide(const_100,n1)|multiply(n0,#0)| | "solution to earn rs . 10 , money invested = rs . 100 . to earn rs . 14 , money invested = rs . ( 100 / 10 x 14 ) = rs . 140 . â ˆ ´ market value of rs . 100 stock = rs . 140 answer d" | gain |
math_qa__bwm3RteZqAYUeGnF | A 25% stock yielding 20% is quoted at: Choose the correct option:
A) s . 83.33 B) s . 110 C) s . 112 D) s . 125 E) s . 140 | <gadget id="calculator">100 / 20</gadget>
<output>5</output>
<gadget id="calculator">5 * 25</gadget>
<output>125</output>
<result>D</result> | D | 125 | A 25% stock yielding 20% is quoted at: | {
"A": "s . 83.33",
"B": "s . 110",
"C": "s . 112",
"D": "s . 125",
"E": "s . 140"
} | multiply(divide(const_100, 20), 25) | divide(const_100,n1)|multiply(n0,#0)| | "income of rs 20 on investment of rs 100 income of rs 25 on investment of ? = ( 25 * 100 ) / 20 = 125 answer : d" | gain |
math_qa__vJNqiVSE39HHcT3r | the average of 11 numbers is 9.9 . if the average of the first 6 numbers is 10.5 and that of the last 6 numbers is 11.4 , then the middle number is Choose the correct option
A) 71.5 B) 11.5 C) 81.5 D) 11.5 E) 22.5 | <gadget id="calculator">10.5 * 6</gadget>
<output>63</output>
<gadget id="calculator">11.4 * 6</gadget>
<output>68.4</output>
<gadget id="calculator">63 + 68.4</gadget>
<output>131.4</output>
<gadget id="calculator">9.9 * 11</gadget>
<output>108.9</output>
<gadget id="calculator">131.4 - 108.9</gadget>
<output>22.5</output>
<result>E</result> | E | 22.5 | the average of 11 numbers is 9.9 . if the average of the first 6 numbers is 10.5 and that of the last 6 numbers is 11.4 , then the middle number is | {
"A": "71.5",
"B": "11.5",
"C": "81.5",
"D": "11.5",
"E": "22.5"
} | subtract(add(multiply(10.5, 6), multiply(11.4, 6)), multiply(9.9, 11)) | multiply(n2,n3)|multiply(n2,n5)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2) | explanation : middle numbers = [ ( 10.5 x 6 + 11.4 x 6 ) - 9.9 x 11 ] = 22.5 . answer : e | general |
math_qa__W5gmN1FQSoH7tx0R | In how many ways can an answer key for a quiz be written if the quiz contains 3 true-false questions followed by 3 multiple-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same? Choose the correct option.
A) 164
B) 224
C) 280
D) 384
E) 476 | <gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 - 3</gadget>
<output>24</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">24 * 16</gadget>
<output>384</output>
<result>D</result> | D | 384 | In how many ways can an answer key for a quiz be written if the quiz contains 3 true-false questions followed by 3 multiple-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same? | {
"A": "164",
"B": "224",
"C": "280",
"D": "384",
"E": "476"
} | multiply(subtract(power(3, 3), 3), multiply(4, 4)) | multiply(n2,n2)|power(n1,n0)|subtract(#1,n1)|multiply(#0,#2)| | "there are 2 ^ 3 = 8 possibilities for the true - false answers . however we need to remove two cases for ttt and fff . there are 4 * 4 * 4 = 64 possibilities for the multiple choice questions . the total number of possibilities is 6 * 64 = 384 . the answer is d ." | general |
math_qa__6y6lSZPPjpLrqPQm | If 2^5, 3^3, and 12^2 are all factors of the product of 936 and w where w is a positive integer, what is the smallest possible value of w?
Answers.
A) 26 B) 39 C) 42 D) 144 E) 156 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">12 * 6</gadget>
<output>72</output>
<gadget id="calculator">72 * 2</gadget>
<output>144</output>
<result>D</result> | D | 144 | If 2^5, 3^3, and 12^2 are all factors of the product of 936 and w where w is a positive integer, what is the smallest possible value of w? | {
"A": "26",
"B": "39",
"C": "42",
"D": "144",
"E": "156"
} | multiply(multiply(multiply(power(2, 2), 3), divide(12, 2)), 2) | divide(n4,n0)|power(n0,n0)|multiply(n2,#1)|multiply(#0,#2)|multiply(n0,#3)| | "here 156 has three two ' s two three ' s and one 13 rest of them must be in w so w = 12 * 3 * 4 = 144 smash d" | general |
math_qa__PkOPhKzHrjtK7WEv | the ratio of 3 numbers is 5 : 1 : 4 and their sum is 1000 . the last number of the 3 numbers is ? Pick one:
A) 24
B) 26
C) 27
D) 400
E) 30 | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(5/4) + (1/4)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">1_000 / (5/2)</gadget>
<output>400</output>
<result>D</result> | D | 400 | the ratio of 3 numbers is 5 : 1 : 4 and their sum is 1000 . the last number of the 3 numbers is ? | {
"A": "24",
"B": "26",
"C": "27",
"D": "400",
"E": "30"
} | divide(1000, add(add(divide(5, 4), divide(1, 4)), 1)) | divide(n1,n3)|divide(n2,n3)|add(#0,#1)|add(n2,#2)|divide(n4,#3) | 5 : 1 : 4 total parts = 10 10 parts - - > 1000 1 part - - - - > 100 the last number of the three numbers is = 4 * 100 = 400 answer : d | other |
math_qa__VhLR8ui4uYqpNbiw | When average age of 21 members are 0, how many members greater than 0?
Options:
A) 17
B) 20
C) 21
D) 24
E) 25 | <gadget id="calculator">21 - 1</gadget>
<output>20</output>
<result>B</result> | B | 20 | When average age of 21 members are 0, how many members greater than 0? | {
"A": "17",
"B": "20",
"C": "21",
"D": "24",
"E": "25"
} | subtract(21, const_1) | subtract(n0,const_1)| | "average of 21 numbers = 0 . sum of 21 numbers ( 0 x 21 ) = 0 . it is quite possible that 20 of these numbers may be positive and if their sum is a then 21 st number is ( - a ) answer is 20 ( b )" | general |
math_qa__varFNs4MbJ72XCMw | The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/72 of the area of the field. What is the length of the field? Choose the correct choice from the following answers: A) 73 B) 32 C) 34 D) 43 E) 96 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 * 72</gadget>
<output>4_608</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4_608 / (1/2)</gadget>
<output>9_216</output>
<gadget id="calculator">9_216 ** (1/2)</gadget>
<output>96</output>
<result>E</result> | E | 96 | The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/72 of the area of the field. What is the length of the field? | {
"A": "73",
"B": "32",
"C": "34",
"D": "43",
"E": "96"
} | sqrt(divide(multiply(square_area(8), 72), inverse(const_2))) | inverse(const_2)|square_area(n0)|multiply(n2,#1)|divide(#2,#0)|sqrt(#3)| | "explanation : a / 72 = 8 * 8 = > a = 8 * 8 * 72 x * 2 x = 8 * 8 * 72 x = 48 = > 2 x = 96 answer : option e" | geometry |
math_qa__FslL3FyKCo6yTbXs | How many times digit 6 is used while writing numbers from 80 to 1000? Choose one: A) 648 B) 300 C) 252 D) 225 E) 26 | <gadget id="calculator">1_000 - 80</gadget>
<output>920</output>
<gadget id="calculator">920 / 10</gadget>
<output>92</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 11</gadget>
<output>121</output>
<gadget id="calculator">92 + 121</gadget>
<output>213</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">213 + 12</gadget>
<output>225</output>
<result>D</result> | D | 225 | How many times digit 6 is used while writing numbers from 80 to 1000? | {
"A": "648",
"B": "300",
"C": "252",
"D": "225",
"E": "26"
} | add(add(divide(subtract(1000, 80), const_10), multiply(add(const_10, const_1), add(const_10, const_1))), multiply(6, const_2)) | add(const_1,const_10)|multiply(n0,const_2)|subtract(n2,n1)|divide(#2,const_10)|multiply(#0,#0)|add(#3,#4)|add(#5,#1) | there are 100 numbers which begin with 600 next , in every 10 numbers such as 100 to 110 , 110 to 120 , 120 to 130 6 comes at least once . number of such intervals = end limit - first no . / interval . our range of numbers is 100 - 1000 1000 - 100 = 900 / 10 = 90 number of 10 s interval in this is 90 . so 90 ' 6 s ' so far we have calculated 190 . the total now comes to 280 . the nearest to which is 225 . hence d . | general |
math_qa__tc9wb7wga06qW4OU | If m = ||n – 3| – 2|, for how many values of n is m = 5? Choose the correct choice from the following:
A) 5 B) 4 C) 2 D) 3 E) 1 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 - 5</gadget>
<output>2</output>
<result>C</result> | C | 2 | If m = ||n – 3| – 2|, for how many values of n is m = 5? | {
"A": "5",
"B": "4",
"C": "2",
"D": "3",
"E": "1"
} | subtract(add(5, 2), 5) | add(n1,n2)|subtract(#0,n2) | m = | | n – 3 | – 2 | can be 4 only and only when n - 3 = + / - 7 . so there are 2 values of n answer : c | physics |
math_qa__WL7YVXLB3tmXCZBJ | The average of 30 results is 20 and the average of other 20 results is 30 . what is the average of all the results?
Choose the correct option
A) 24
B) 25
C) 48
D) 50
E) none | <gadget id="calculator">30 * 20</gadget>
<output>600</output>
<gadget id="calculator">20 * 30</gadget>
<output>600</output>
<gadget id="calculator">600 + 600</gadget>
<output>1_200</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">1_200 / 50</gadget>
<output>24</output>
<result>A</result> | A | 24 | The average of 30 results is 20 and the average of other 20 results is 30 . what is the average of all the results? | {
"A": "24",
"B": "25",
"C": "48",
"D": "50",
"E": "none"
} | divide(add(multiply(30, 20), multiply(20, 30)), add(30, 20)) | add(n0,n1)|multiply(n0,n1)|add(#1,#1)|divide(#2,#0)| | "answer sum of 50 result = sum of 30 result + sum of 20 result . = 30 x 20 + 20 x 30 = 1200 correct option : a" | general |
math_qa__9VJZbYdqp51dPvbm | When an amount was distributed among 14 boys, each of them got $80 more than the amount received by each boy when the same amount is distributed equally among 18 boys. What was the amount? Choose the correct choice from the following.
A) 5050 B) 5020 C) 5040 D) 5030 E) 5075 | <gadget id="calculator">1 / 14</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/14) - (1/18)</gadget>
<output>1/63 = around 0.015873</output>
<gadget id="calculator">80 / (1/63)</gadget>
<output>5_040</output>
<result>C</result> | C | 5,040 | When an amount was distributed among 14 boys, each of them got $80 more than the amount received by each boy when the same amount is distributed equally among 18 boys. What was the amount? | {
"A": "5050",
"B": "5020",
"C": "5040",
"D": "5030",
"E": "5075"
} | divide(80, subtract(divide(const_1, 14), divide(const_1, 18))) | divide(const_1,n0)|divide(const_1,n2)|subtract(#0,#1)|divide(n1,#2)| | "let the total amount be rs . x the , x / 14 - x / 18 = 80 = = > 2 x / 126 = 80 = = > x / 63 = 63 x 80 = 5040 . hence the total amount is 5040 . answer c ." | general |
math_qa__LYA423KdlacEimTn | A baseball card decreased in value 50% in its first year and 10% in its second year. What was the total percent decrease of the card's value over the two years? Choose the correct answer:
A) 28 % B) 55 % C) 32 % D) 36 % E) 72 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(9/10) * (1/2)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) * 100</gadget>
<output>45</output>
<gadget id="calculator">100 - 45</gadget>
<output>55</output>
<result>B</result> | B | 55 | A baseball card decreased in value 50% in its first year and 10% in its second year. What was the total percent decrease of the card's value over the two years? | {
"A": "28 %",
"B": "55 %",
"C": "32 %",
"D": "36 %",
"E": "72 %"
} | subtract(const_100, multiply(multiply(subtract(const_1, divide(10, const_100)), subtract(const_1, divide(50, const_100))), const_100)) | divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(const_100,#5)| | "let the initial value of baseball card = 100 after first year , value of baseball card = ( 1 - 50 / 100 ) * 100 = 50 after second year , value of baseball card = ( 1 - 10 / 100 ) * 50 = 45 total percent decrease of the card ' s value over the two years = ( 100 - 45 ) / 100 * 100 % = 55 % answer b" | gain |
math_qa__SFsb7pVJKu73pxef | 2 ^ 35 ^ 26 ^ 1 find largest value ? Answers: A) 2 B) 3 C) 1 D) 10 E) 25 | <gadget id="calculator">26 - 1</gadget>
<output>25</output>
<result>E</result> | E | 25 | 2 ^ 35 ^ 26 ^ 1 find largest value ? | {
"A": "2",
"B": "3",
"C": "1",
"D": "10",
"E": "25"
} | subtract(26, 1) | subtract(n2,n3) | explanation : 2 ^ 3 = 2 * 2 * 2 = 8 5 ^ 2 = 5 * 5 = 25 6 ^ 1 = 6 * 1 = 6 hence 5 ^ 2 is the largest one answer : e | general |
math_qa__Hs2H2VaJlvsZD3J3 | At a small company, 64 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married? Choose the most appropriate option
A) 5 / 16 B) 3 / 4 C) 9 / 20 D) 7 / 10 E) 5 / 7 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">64 / 100</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">1 - (16/25)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(9/25) * (1/3)</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/5) - (3/25)</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">(12/25) / (16/25)</gadget>
<output>3/4 = around 0.75</output>
<result>B</result> | B | 0.75 | At a small company, 64 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married? | {
"A": "5 / 16",
"B": "3 / 4",
"C": "9 / 20",
"D": "7 / 10",
"E": "5 / 7"
} | divide(subtract(divide(60, const_100), multiply(subtract(const_1, divide(64, const_100)), subtract(const_1, divide(2, 3)))), divide(64, const_100)) | divide(n1,const_100)|divide(n0,const_100)|divide(n2,n3)|subtract(const_1,#1)|subtract(const_1,#2)|multiply(#3,#4)|subtract(#0,#5)|divide(#6,#1)| | "lets take total employees are 100 . given that , total women = 64 and total married = 60 . total men = 100 - 64 = 36 and single men = 2 / 3 * 36 = 24 . married men = total men - single men = 36 - 24 = 12 . married women = total married - married men = 60 - 12 = 48 . fraction of women are married = married women / total women = 48 / 64 = 3 / 4 . ans b" | gain |
math_qa__Mw7pRUe9My1UHi6e | If annual decrease in the population of a town is 10% and the present number of people is 500 what will the population be in 1 year? Choose the correct option: A) 450 B) 310 C) 250 D) 410 E) 390 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) ** 1</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 500</gadget>
<output>450</output>
<result>A</result> | A | 450 | If annual decrease in the population of a town is 10% and the present number of people is 500 what will the population be in 1 year? | {
"A": "450",
"B": "310",
"C": "250",
"D": "410",
"E": "390"
} | multiply(power(divide(subtract(const_100, 10), const_100), 1), 500) | subtract(const_100,n0)|divide(#0,const_100)|power(#1,n2)|multiply(n1,#2)| | "population in 1 year = 500 ( 1 - 10 / 100 ) = 500 * 90 / 100 = 450 answer is a" | gain |
math_qa__hsWFs7COjuXZA8eJ | The sum of two numbers is 56, and one of them is 12 more than the other. What are the two numbers? Choose the correct choice from the following answers:
A) 36 - 48 B) 22 - 34 C) 60 - 24 D) 42 - 42 E) 21 - 63 | <gadget id="calculator">56 - 12</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<result>B</result> | B | 22 | The sum of two numbers is 56, and one of them is 12 more than the other. What are the two numbers? | {
"A": "36 - 48",
"B": "22 - 34",
"C": "60 - 24",
"D": "42 - 42",
"E": "21 - 63"
} | divide(subtract(56, 12), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "in this problem , we are asked to find two numbers . therefore , we must let x be one of them . let x , then , be the first number . we are told that the other number is 12 more , x + 12 . the problem states that their sum is 56 : word problem = 56 the line over x + 12 is a grouping symbol called a vinculum . it saves us writing parentheses . we have : 2 x = 56 â ˆ ’ 12 = 44 . x = 44 / 2 = 22 . this is the first number . therefore the other number is x + 12 = 22 + 12 = 34 . the sum of 22 + 34 is 56 . b" | general |
math_qa__DJlOW4FHrcKfmwVl | A horse is tethered to one corner of a rectangular grassy field 46 m by 20 m with a rope 17 m long. Over how much area of the field can it graze?
Choose one: A) 154 cm 2 B) 308 m 2 C) 227 m 2 D) 407 m 2 E) none of these | <gadget id="calculator">17 ** 2</gadget>
<output>289</output>
<gadget id="calculator">289 * pi</gadget>
<output>289*pi = around 907.920277</output>
<gadget id="calculator">(289*pi) / 4</gadget>
<output>289*pi/4 = around 226.980069</output>
<result>C</result> | C | 227 | A horse is tethered to one corner of a rectangular grassy field 46 m by 20 m with a rope 17 m long. Over how much area of the field can it graze? | {
"A": "154 cm 2",
"B": "308 m 2",
"C": "227 m 2",
"D": "407 m 2",
"E": "none of these"
} | divide(multiply(power(17, const_2), const_pi), const_4) | power(n2,const_2)|multiply(#0,const_pi)|divide(#1,const_4)| | "area of the shaded portion = 1 ⁄ 4 × π × ( 17 ) 2 = 227 m 2 answer c" | geometry |
math_qa__t2vS3EXEQfT7vNiN | A person incurs 5% loss by selling a watch for $1140 . At
what price should the watch be sold to earn 5% profit?
Choose the correct answer: A) $ 1260 B) $ 1150 C) $ 1542 D) $ 1000 E) $ 1292 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 - (1/20)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1_140 / (19/20)</gadget>
<output>1_200</output>
<result>A</result> | A | 1,260 | A person incurs 5% loss by selling a watch for $1140 . At
what price should the watch be sold to earn 5% profit? | {
"A": "$ 1260",
"B": "$ 1150",
"C": "$ 1542",
"D": "$ 1000",
"E": "$ 1292"
} | divide(1140, subtract(const_1, divide(5, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1) | let the new selling price be $ x ( 100 - loss % ) : ( 1 st s . p . ) = ( 100 + gain % ) : ( 2 nd s . p . ) ( 100 - 5 ) / 1140 = ( 100 + 5 ) / x x = 105 * 1140 / 95 = 1260 answer is a | gain |
math_qa__d3rDLEoUUnFFi4Px | Find the area of a parallelogram with base 32 cm and height 22 cm?
Answers:
A) 281 B) 284 C) 704 D) 640 E) 920 | <gadget id="calculator">32 * 22</gadget>
<output>704</output>
<result>C</result> | C | 704 | Find the area of a parallelogram with base 32 cm and height 22 cm? | {
"A": "281",
"B": "284",
"C": "704",
"D": "640",
"E": "920"
} | multiply(32, 22) | multiply(n0,n1)| | "area of a parallelogram = base * height = 32 * 22 = 704 cm 2 answer : c" | geometry |
math_qa__UpwoZHn594FttcHa | Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 350 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 4 of the days were hot, then what was the price of 1 cup on a hot day? Choose the correct answer.
A) $ 1.50 B) $ 1.88 C) $ 2.09 D) $ 2.50 E) $ 3.25 | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">32 * (3/4)</gadget>
<output>24</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">24 * 10</gadget>
<output>240</output>
<gadget id="calculator">240 + 350</gadget>
<output>590</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">6 * 32</gadget>
<output>192</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 32</gadget>
<output>160</output>
<gadget id="calculator">192 + 160</gadget>
<output>352</output>
<gadget id="calculator">590 / 352</gadget>
<output>295/176 = around 1.676136</output>
<gadget id="calculator">(295/176) * (5/4)</gadget>
<output>1_475/704 = around 2.09517</output>
<result>C</result> | C | 2.09 | Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 350 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 4 of the days were hot, then what was the price of 1 cup on a hot day? | {
"A": "$ 1.50",
"B": "$ 1.88",
"C": "$ 2.09",
"D": "$ 2.50",
"E": "$ 3.25"
} | multiply(divide(add(multiply(multiply(32, divide(75, const_100)), multiply(add(const_4, 1), const_2)), 350), add(multiply(subtract(multiply(add(const_4, 1), const_2), 4), 32), multiply(multiply(divide(add(const_100, 25), const_100), 4), 32))), divide(add(const_100, 25), const_100)) | add(n5,const_4)|add(n1,const_100)|divide(n2,const_100)|divide(#1,const_100)|multiply(n3,#2)|multiply(#0,const_2)|multiply(#4,#5)|multiply(n4,#3)|subtract(#5,n4)|add(n0,#6)|multiply(n3,#8)|multiply(n3,#7)|add(#10,#11)|divide(#9,#12)|multiply(#13,#3)| | "6 regular days - - > sales = 6 * 32 * x = 192 x ; 4 hot days - - > sales = 4 * 32 * ( 1.25 x ) = 160 x ; total sales = 192 x + 160 x = 352 x . total cost = 10 * 32 * 0.75 = 240 . profit = 352 x - 240 = 350 - - > x = 1.676 . 1.25 x = ~ 2.09 . answer : c ." | gain |
math_qa__mQlADcBwhFTeSh3U | If
1 = 6
2 = 12
3 = 18
4 = 24
5 = 30
6 = 36
Then 12 = ?
Hint: Its a logic Riddle not a mathematical riddle Answers: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">min(12, 2)</gadget>
<output>2</output>
<result>B</result> | B | 2 | If
1 = 6
2 = 12
3 = 18
4 = 24
5 = 30
6 = 36
Then 12 = ?
Hint: Its a logic Riddle not a mathematical riddle | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | min(12, 2) | min(n2,n3) | b 2 as stated 2 = 12 = > 12 = 2 answer is b | other |
math_qa__rZHcSTXVDFENDYXx | 217 + 2.017 + 0.217 + 2.0017 = ? Choose the most appropriate option:
A) 229.3657
B) 229.7563
C) 229.6357
D) 229.5637
E) 221.2357 | <gadget id="calculator">217 + 2.017</gadget>
<output>219.017</output>
<gadget id="calculator">219.017 + 0.217</gadget>
<output>219.234</output>
<gadget id="calculator">219.234 + 2.0017</gadget>
<output>221.2357</output>
<result>E</result> | E | 221.2357 | 217 + 2.017 + 0.217 + 2.0017 = ? | {
"A": "229.3657",
"B": "229.7563",
"C": "229.6357",
"D": "229.5637",
"E": "221.2357"
} | add(add(add(217, 2.017), 0.217), 2.0017) | add(n0,n1)|add(n2,#0)|add(n3,#1) | 217 2.017 0.217 + 2.0017 - - - - - - - - 221.2357 - - - - - - - - - answer is e . | general |
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