id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__I2KBeUQmvgM5KP37 | When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land once on heads and twice tails? Choose one:
A) 1 / 3
B) 1 / 6
C) 1 / 4
D) 1 / 8
E) 1 / 5 | <gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<result>D</result> | D | 0.125 | When tossed, a certain coin has equal probability of landing on either side. If the coin is tossed 3 times, what is the probability that it will land once on heads and twice tails? | {
"A": "1 / 3",
"B": "1 / 6",
"C": "1 / 4",
"D": "1 / 8",
"E": "1 / 5"
} | divide(const_1, power(const_2, 3)) | power(const_2,n0)|divide(const_1,#0)| | "must be once on heads and twice on tails 1 / 2 * 1 / 2 * 1 / 2 = 1 / 8 answer : d" | general |
math_qa__SaIkvKeiQSApjS5y | If a man lost 4% by selling oranges at the rate of 36 a rupee at how many a rupee must he sell them to gain 44%?
Choose the correct option
A) 1 B) 8 C) 9 D) 24 E) 3 | <gadget id="calculator">100 - 4</gadget>
<output>96</output>
<gadget id="calculator">96 * 36</gadget>
<output>3_456</output>
<gadget id="calculator">100 + 44</gadget>
<output>144</output>
<gadget id="calculator">3_456 / 144</gadget>
<output>24</output>
<result>D</result> | D | 24 | If a man lost 4% by selling oranges at the rate of 36 a rupee at how many a rupee must he sell them to gain 44%? | {
"A": "1",
"B": "8",
"C": "9",
"D": "24",
"E": "3"
} | divide(multiply(subtract(const_100, 4), 36), add(const_100, 44)) | add(n2,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,#0)| | "96 % - - - - 36 144 % - - - - ? 96 / 144 * 36 = 24 answer : d" | gain |
math_qa__BPEHp1GDJzbsAfz6 | The Fisherman sale, all of the prices of the fishes sold were different. If the price of a radio sold at the fisherman sale was both the 4th highest price and the 13th lowest price among the prices of the fishes sold, how many fishes were sold at the fisherman sale?
Choose the correct choice from the following answers
A) 13 B) 14 C) 15 D) 41 E) 16 | <gadget id="calculator">4 + 13</gadget>
<output>17</output>
<gadget id="calculator">17 - 1</gadget>
<output>16</output>
<result>E</result> | E | 16 | The Fisherman sale, all of the prices of the fishes sold were different. If the price of a radio sold at the fisherman sale was both the 4th highest price and the 13th lowest price among the prices of the fishes sold, how many fishes were sold at the fisherman sale? | {
"A": "13",
"B": "14",
"C": "15",
"D": "41",
"E": "16"
} | subtract(add(4, 13), const_1) | add(n0,n1)|subtract(#0,const_1) | 3 + 12 + 1 = 16 answer : e | other |
math_qa__RKR2R1nuwaounp1X | In a school of 600 students, 45% wear blue shirts, 23% wear red shirts, 15% wear green shirts, and the remaining students wear other colors. How many students wear other colors (not blue, not red, not green)? Choose the correct choice from the following answers: A) 102 B) 112 C) 122 D) 132 E) 142 | <gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">(9/20) * 600</gadget>
<output>270</output>
<gadget id="calculator">23 / 100</gadget>
<output>23/100 = around 0.23</output>
<gadget id="calculator">(23/100) * 600</gadget>
<output>138</output>
<gadget id="calculator">270 + 138</gadget>
<output>408</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 600</gadget>
<output>90</output>
<gadget id="calculator">408 + 90</gadget>
<output>498</output>
<gadget id="calculator">600 - 498</gadget>
<output>102</output>
<result>A</result> | A | 102 | In a school of 600 students, 45% wear blue shirts, 23% wear red shirts, 15% wear green shirts, and the remaining students wear other colors. How many students wear other colors (not blue, not red, not green)? | {
"A": "102",
"B": "112",
"C": "122",
"D": "132",
"E": "142"
} | subtract(600, add(add(multiply(divide(45, const_100), 600), multiply(divide(23, const_100), 600)), multiply(divide(15, const_100), 600))) | divide(n1,const_100)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n0,#1)|multiply(n0,#2)|add(#3,#4)|add(#6,#5)|subtract(n0,#7)| | "45 + 23 + 15 = 83 % 100 – 83 = 17 % 600 * 17 / 100 = 102 the answer is a ." | gain |
math_qa__IT3RAL3hERaE18aw | The average of the marks of 10 students in a class is 80. If the marks of each student are doubled, find the new average? Choose one
A) 80 B) 120 C) 160 D) 270 E) 110 | <gadget id="calculator">80 * 2</gadget>
<output>160</output>
<result>C</result> | C | 160 | The average of the marks of 10 students in a class is 80. If the marks of each student are doubled, find the new average? | {
"A": "80",
"B": "120",
"C": "160",
"D": "270",
"E": "110"
} | multiply(80, const_2) | multiply(n1,const_2)| | "sum of the marks for the 10 students = 10 * 80 = 800 . the marks of each student are doubled , the sum also will be doubled . the new sum = 800 * 2 = 1600 . so , the new average = 1600 / 10 = 160 . answer : c" | general |
math_qa__kQ27vKIliiOigqFd | The area of a sector of a circle of radius 5 cm formed by an arc of length 5.5 cm is? Pick: A) 13.78 B) 13.67 C) 13.75 D) 13.98 E) 13.28 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 * 5.5</gadget>
<output>27.5</output>
<gadget id="calculator">(1/2) * 27.5</gadget>
<output>13.75</output>
<result>C</result> | C | 13.75 | The area of a sector of a circle of radius 5 cm formed by an arc of length 5.5 cm is? | {
"A": "13.78",
"B": "13.67",
"C": "13.75",
"D": "13.98",
"E": "13.28"
} | multiply(divide(const_1, const_2), multiply(5, 5.5)) | divide(const_1,const_2)|multiply(n0,n1)|multiply(#0,#1)| | "( 5 * 5.5 ) / 2 = 13.75 answer : c" | physics |
math_qa__djxZk3JqEcvZMdcH | There were totally 100 men.83 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married? Choose the correct answer: A) 11 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">100 - 83</gadget>
<output>17</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">17 + 25</gadget>
<output>42</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">42 + 15</gadget>
<output>57</output>
<gadget id="calculator">100 - 70</gadget>
<output>30</output>
<gadget id="calculator">57 + 30</gadget>
<output>87</output>
<gadget id="calculator">100 - 87</gadget>
<output>13</output>
<result>C</result> | C | 13 | There were totally 100 men.83 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | subtract(100, add(add(add(subtract(100, 83), subtract(100, 75)), subtract(100, 85)), subtract(100, 70))) | subtract(n0,n1)|subtract(n0,n2)|subtract(n0,n3)|subtract(n0,n4)|add(#0,#1)|add(#4,#2)|add(#5,#3)|subtract(n0,#6) | 100 - ( 100 - 83 ) - ( 100 - 75 ) - ( 100 - 85 ) - ( 100 - 70 ) = 100 - 17 - 25 - 15 - 30 = 100 - 87 = 13 answer : c | general |
math_qa__nDhw2P6qYrzk24Wg | A 450 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? Select.
A) 600
B) 525
C) 360
D) 370
E) 380 | <gadget id="calculator">450 / 18</gadget>
<output>25</output>
<gadget id="calculator">25 * 39</gadget>
<output>975</output>
<gadget id="calculator">975 - 450</gadget>
<output>525</output>
<result>B</result> | B | 525 | A 450 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec. What is the length of the platform? | {
"A": "600",
"B": "525",
"C": "360",
"D": "370",
"E": "380"
} | subtract(multiply(speed(450, 18), 39), 450) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 450 / 18 = 25 m / sec . let the length of the platform be x meters . then , ( x + 450 ) / 39 = 25 = > x = 975 m . l = 975 - 450 = 525 answer : option b" | physics |
math_qa__BirxnjXX7AtyccDB | If an integer n is to be chosen at random from the integers 1 to 94, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8? Choose the correct answer
A) 1 / 4
B) 3 / 8
C) 1 / 2
D) 5 / 8
E) 59 / 94 | <gadget id="calculator">94 / 2</gadget>
<output>47</output>
<gadget id="calculator">94 / 8</gadget>
<output>47/4 = around 11.75</output>
<gadget id="calculator">47 + (47/4)</gadget>
<output>235/4 = around 58.75</output>
<gadget id="calculator">(235/4) / 94</gadget>
<output>5/8 = around 0.625</output>
<result>E</result> | E | 0.62766 | If an integer n is to be chosen at random from the integers 1 to 94, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8? | {
"A": "1 / 4",
"B": "3 / 8",
"C": "1 / 2",
"D": "5 / 8",
"E": "59 / 94"
} | divide(add(divide(94, 2), divide(94, 8)), 94) | divide(n1,n3)|divide(n1,n4)|add(#0,#1)|divide(#2,n1)| | "n ( n + 1 ) ( n + 2 ) will be divisible by 8 when n is a multiple of 2 or when ( n + 1 ) is a multiple of 8 . thus when n is even , this whole expression will be divisible by 8 . from 1 to 96 , there are 47 even integers . now when ( n + 1 ) is multiple by 8 , we have 12 such values for ( n + 1 ) probability that n ( n + 1 ) ( n + 2 ) will be divisible by 8 = ( 47 + 12 ) / 94 = 59 / 94 = 5 / 8 ans is e" | general |
math_qa__IIQMbO0SW1T2Zi6j | What is x if x + 2y = 10 and y = 1? Choose the correct choice:
A) 10 B) 8 C) 6 D) 4 E) 2 | <gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | What is x if x + 2y = 10 and y = 1? | {
"A": "10",
"B": "8",
"C": "6",
"D": "4",
"E": "2"
} | subtract(10, multiply(2, 1)) | multiply(n0,n2)|subtract(n1,#0) | x = 10 - 2 y x = 10 - 2 . x = 8 answer : b | general |
math_qa__JIIOLhkfwrWRV7mD | What is the median of a set of consecutive integers if the sum of nth number from the beginning and nth number from the end is 50? Choose the correct choice from the following answers
A) 10 B) 25 C) 50 D) 75 E) 100 | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>B</result> | B | 25 | What is the median of a set of consecutive integers if the sum of nth number from the beginning and nth number from the end is 50? | {
"A": "10",
"B": "25",
"C": "50",
"D": "75",
"E": "100"
} | divide(50, const_2) | divide(n0,const_2)| | "surprisingly no one answered this easy one . property of a set of consecutive integerz . mean = median = ( first element + last element ) / 2 = ( second element + last but one element ) / 2 = ( third element + third last element ) / 2 etc . etc . so mean = median = 50 / 2 = 25 answer is b" | general |
math_qa__5dJL9YZRkNV7qwxy | A number is selected at random from the first 40 natural numbers. What is the probability that the number is a multiple of either 2 or 21?
Answers.
A) 21 / 40 B) 2 / 5 C) 7 / 15 D) 4 / 15 E) 11 / 30 | <gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">floor(20)</gadget>
<output>20</output>
<gadget id="calculator">40 / 21</gadget>
<output>40/21 = around 1.904762</output>
<gadget id="calculator">20 + (40/21)</gadget>
<output>460/21 = around 21.904762</output>
<gadget id="calculator">(460/21) / 40</gadget>
<output>23/42 = around 0.547619</output>
<result>A</result> | A | 0.525 | A number is selected at random from the first 40 natural numbers. What is the probability that the number is a multiple of either 2 or 21? | {
"A": "21 / 40",
"B": "2 / 5",
"C": "7 / 15",
"D": "4 / 15",
"E": "11 / 30"
} | divide(add(floor(divide(40, 2)), divide(40, 21)), 40) | divide(n0,n2)|divide(n0,n1)|floor(#1)|add(#0,#2)|divide(#3,n0)| | "number of multiples of 2 from 1 through 40 = 40 / 2 = 20 number of multiples of 21 from 1 through 40 = 40 / 21 = 1 number of multiples of 2 and 21 both from 1 through 40 = number of multiples of 21 * 2 ( = 42 ) = 0 total favourable cases = 20 + 1 - 0 = 21 probability = 21 / 40 answer : option a" | probability |
math_qa__Fsfh0ofJXRFOdw1G | If a, b, c and d are positive integers less than 4, and 4^a+3^b+2^c+1^d=78 then what is the value of b/c?
Pick one: A) 3 B) 2 C) 1 D) 1 / 2 E) 1 / 3 | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<result>C</result> | C | 1 | If a, b, c and d are positive integers less than 4, and 4^a+3^b+2^c+1^d=78 then what is the value of b/c? | {
"A": "3",
"B": "2",
"C": "1",
"D": "1 / 2",
"E": "1 / 3"
} | divide(2, 2) | divide(n3,n3) | since a , b and c are positive integers less than 4 we have the following possibilities : 4 ^ a = 416 , or 64 3 ^ b = 39 , or 27 2 ^ c = 24 , or 8 trial and error gives us quite quick the solution of 4 ^ a = 64 3 ^ b = 9 2 ^ c = 4 64 + 9 + 4 = 77 i . e . c = 2 and b = 2 - - - - > b / c = 1 / 1 = 1 the correct answer is c | general |
math_qa__AVJL0tPwO7aW1zks | On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? Choose the correct choice from the following answers.
A) 28 B) 27 C) 11 D) 15 E) 19 | <gadget id="calculator">112 - 32</gadget>
<output>80</output>
<gadget id="calculator">80 * 6</gadget>
<output>480</output>
<gadget id="calculator">480 / 32</gadget>
<output>15</output>
<result>D</result> | D | 15 | On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ? | {
"A": "28",
"B": "27",
"C": "11",
"D": "15",
"E": "19"
} | divide(multiply(subtract(112, 32), 6), 32) | subtract(n0,n1)|multiply(n2,#0)|divide(#1,n1) | explanation : let ' k ' be the total number of sweets . given total number of students = 112 if sweets are distributed among 112 children , let number of sweets each student gets = ' l ' = > k / 112 = l . . . . ( 1 ) but on that day students absent = 32 = > remaining = 112 - 32 = 80 then , each student gets ' 6 ' sweets extra . = > k / 80 = l + 6 . . . . ( 2 ) from ( 1 ) k = 112 l substitute in ( 2 ) , we get 112 l = 80 l + 480 32 l = 480 l = 15 therefore , 15 sweets were each student originally supposed to get . answer : d | general |
math_qa__JCbi7jL3zMIal6d2 | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 16. Find the sum : Answers: A) 4500 B) 7500 C) 5000 D) 6400 E) none of these | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">2 * (1/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">16 / (1/400)</gadget>
<output>6_400</output>
<result>D</result> | D | 6,400 | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 16. Find the sum : | {
"A": "4500",
"B": "7500",
"C": "5000",
"D": "6400",
"E": "none of these"
} | divide(16, subtract(power(add(const_1, divide(5, const_100)), 2), add(const_1, multiply(2, divide(5, const_100))))) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|add(#2,const_1)|power(#1,n1)|subtract(#4,#3)|divide(n2,#5)| | "sol . ( d ) let the sum be 100 . therefore , si = 100 × 5 × 2 / 100 = 10 and ci = 100 ( 1 + 5 / 100 ) 2 − 100 ∴ = 100 × 21 × 21 / 20 × 20 − 100 = 41 / 4 difference of ci and si = 41 ⁄ 4 - 10 = 1 ⁄ 4 if the difference is 1 ⁄ 4 , the sum = 100 = > if the difference is 16 , the sum = 400 × 16 = 6400 answer d" | gain |
math_qa__EF3c4i3LcO7o4F3c | there are two numbers . if 50 % of the first number is added to the second number , then the second number increases to its 5 - fourth . find the ratio of the first number to the second number ? Choose the most appropriate option: A) 1 / 2 B) 5 / 8 C) 6 D) 6 / 7 E) 7 | <gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) - 1</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) / (1/2)</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | there are two numbers . if 50 % of the first number is added to the second number , then the second number increases to its 5 - fourth . find the ratio of the first number to the second number ? | {
"A": "1 / 2",
"B": "5 / 8",
"C": "6",
"D": "6 / 7",
"E": "7"
} | divide(subtract(divide(5, const_4), const_1), divide(50, const_100)) | divide(n1,const_4)|divide(n0,const_100)|subtract(#0,const_1)|divide(#2,#1) | let the two numbers be x and y . 50 / 100 * x + y = 5 / 4 y = > 1 / 2 x = 1 / 4 y = > x / y = 1 / 2 a ) | general |
math_qa__ENghrQYh7aHvtBWK | If you wish to live to be 100 years old (hypothetically), you must consume 500 calories less than your Average Daily Allowance for your age. If you are in your 60's, and your Average Daily allowance is 2000 calories per day, how many calories are you allowed in a week?
Choose the correct option: A) 7000 B) 10500 C) 14000 D) 12000 E) 3500 | <gadget id="calculator">2_000 - 500</gadget>
<output>1_500</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">1_500 * 7</gadget>
<output>10_500</output>
<result>B</result> | B | 10,500 | If you wish to live to be 100 years old (hypothetically), you must consume 500 calories less than your Average Daily Allowance for your age. If you are in your 60's, and your Average Daily allowance is 2000 calories per day, how many calories are you allowed in a week? | {
"A": "7000",
"B": "10500",
"C": "14000",
"D": "12000",
"E": "3500"
} | multiply(subtract(2000, 500), add(const_4, const_3)) | add(const_3,const_4)|subtract(n3,n1)|multiply(#0,#1) | to determine the amount of calories allowed per day , you need to subtract 500 from 2000 , for a total of 1500 to determine the amount of calories allowed per week , you need to multiply the daily amount allowed ( 1500 ) by the number of days in a week ( 7 ) for a total of 10500 the correct answer is b | general |
math_qa__FHzt1TpSGWe7j2vA | 250 metres long yard, 51 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees Choose the correct choice from the following answers: A) 10 B) 12 C) 14 D) 16 E) 5 | <gadget id="calculator">51 - 2</gadget>
<output>49</output>
<gadget id="calculator">49 + 1</gadget>
<output>50</output>
<gadget id="calculator">250 / 50</gadget>
<output>5</output>
<result>E</result> | E | 5 | 250 metres long yard, 51 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "5"
} | divide(250, add(subtract(51, 2), const_1)) | subtract(n1,n2)|add(#0,const_1)|divide(n0,#1)| | "51 trees have 50 gaps between them , required distance ( 250 / 50 ) = 15 e" | physics |
math_qa__sMLEqu8hdaLJdzYt | A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2783 in 3 years. Find the rate percent? Answers:
A) 15
B) 10
C) 28
D) 24
E) 82 | <gadget id="calculator">2_783 - 2_420</gadget>
<output>363</output>
<gadget id="calculator">363 / 2_420</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>A</result> | A | 15 | A sum of money deposited at C.I. amounts to Rs.2420 in 2 years and to Rs.2783 in 3 years. Find the rate percent? | {
"A": "15",
"B": "10",
"C": "28",
"D": "24",
"E": "82"
} | multiply(divide(subtract(2783, 2420), 2420), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 2420 - - - 363 100 - - - ? = > 15 % answer : option a" | gain |
math_qa__ZTcezsiJTJc6u9de | If an integer n is to be selected at random from 1 to 100, inclusive, what is probability n(n+1) will be divisible by 16? Pick.
A) 1 / 4 B) 1 / 8 C) 1 / 2 D) 2 / 3 E) 3 / 4 | <gadget id="calculator">2 / 16</gadget>
<output>1/8 = around 0.125</output>
<result>B</result> | B | 0.125 | If an integer n is to be selected at random from 1 to 100, inclusive, what is probability n(n+1) will be divisible by 16? | {
"A": "1 / 4",
"B": "1 / 8",
"C": "1 / 2",
"D": "2 / 3",
"E": "3 / 4"
} | divide(const_2, 16) | divide(const_2,n3)| | "because n ( n + 1 ) is always an even product of even * odd or odd * even factors , there is a probability of 1 that that it will be divisible by 2 , and , thus , a probability of 1 / 2 that it will be divisible by 4 and , thus , a probability of 1 / 4 that it will be divisible by 8 and , thus , a probability of 1 / 8 that it will be divisible by 16 1 * 1 / 8 = 1 / 8 answer : b" | general |
math_qa__Kckaj5C1CBUQYmsu | how many zeros are there in 50! Select the correct option:
A) 10
B) 11
C) 12
D) 13
E) 14 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">50 / 5</gadget>
<output>10</output>
<gadget id="calculator">50 - 5</gadget>
<output>45</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">45 / 25</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">10 + (9/5)</gadget>
<output>59/5 = around 11.8</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">45 / 125</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(59/5) + (9/25)</gadget>
<output>304/25 = around 12.16</output>
<result>C</result> | C | 12 | how many zeros are there in 50! | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | add(add(divide(50, add(const_4, const_1)), divide(subtract(50, add(const_4, const_1)), power(add(const_4, const_1), const_2))), divide(subtract(50, add(const_4, const_1)), power(add(const_4, const_1), const_3))) | add(const_1,const_4)|divide(n0,#0)|power(#0,const_2)|power(#0,const_3)|subtract(n0,#0)|divide(#4,#2)|divide(#4,#3)|add(#1,#5)|add(#7,#6)| | "to find the number of trailing zeroes in 50 ! factorial we must find the number of integral values in : 50 / 5 + 50 / 5 ^ 2 + 50 / 5 ^ 3 + . . . . . . . . . = 10 + 2 + 0 + 0 . . . . = 12 answer : c" | other |
math_qa__37zk2couJdkw6nx9 | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 450 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)
Choose the most appropriate option:
A) 8 / 3
B) 2 / 1
C) 8 / 5
D) 5 / 8
E) 5 / 3 | <gadget id="calculator">450 / 3</gadget>
<output>150</output>
<gadget id="calculator">300 / 4</gadget>
<output>75</output>
<gadget id="calculator">150 / 75</gadget>
<output>2</output>
<result>B</result> | B | 2 | Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 450 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy) | {
"A": "8 / 3",
"B": "2 / 1",
"C": "8 / 5",
"D": "5 / 8",
"E": "5 / 3"
} | divide(divide(450, 3), divide(300, 4)) | divide(n2,n0)|divide(n3,n1)|divide(#0,#1)| | "distance traveled by eddy = 600 km time taken by eddy = 3 hours average speed of eddy = 450 / 3 = 150 km / hour distance traveled by freddy = 300 km time taken by freddy = 4 hours average speed of freddy = 300 / 4 = 75 km / hour ratio of average speed of eddy to freddy = 150 / 75 = 2 / 1 answer b" | physics |
math_qa__MwaX0TC18rEMGsCQ | Pipe X that can fill a tank in an hour and pipe Y that can fill the tank in half an hour are opened simultaneously when the tank is empty. Pipe Y is shut 15 minutes before the tank overflows. When will the tank overflow?
Choices.
A) 35 mins B) 30 mins C) 40 mins D) 32 mins E) 36 mins | <gadget id="calculator">60 * 1</gadget>
<output>60</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">(3/4) / 3</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + (1/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<result>B</result> | B | 30 | Pipe X that can fill a tank in an hour and pipe Y that can fill the tank in half an hour are opened simultaneously when the tank is empty. Pipe Y is shut 15 minutes before the tank overflows. When will the tank overflow? | {
"A": "35 mins",
"B": "30 mins",
"C": "40 mins",
"D": "32 mins",
"E": "36 mins"
} | multiply(add(divide(subtract(const_1, divide(15, multiply(const_60, const_1))), add(const_1, const_2)), divide(15, multiply(const_60, const_1))), const_60) | add(const_1,const_2)|multiply(const_1,const_60)|divide(n0,#1)|subtract(const_1,#2)|divide(#3,#0)|add(#4,#2)|multiply(#5,const_60) | the last 15 minutes only pipe x was open . since it needs 1 hour to fill the tank , then in 15 minutes it fills 1 / 4 th of the tank , thus 3 / 4 of the tank is filled with both pipes open . the combined rate of two pipes is 1 + 2 = 3 tanks / hour , therefore to fill 3 / 4 th of the tank they need ( time ) = ( work ) / ( rate ) = ( 3 / 4 ) / 3 = 1 / 4 hours = 15 minutes . total time = 15 + 15 = 30 minutes . answer : b | physics |
math_qa__kp4zneOF5qHka58z | A and B can complete a work in 15days and 10day. They started doing the work together but after 2days B had to leave and A alone completed the remaining work. The whole work was completed in?
Choose the correct choice from the following answers
A) 10 days B) 12 days C) 15 days D) 8 days E) 16 days | <gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/15) + (1/10)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 2</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 15</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<result>B</result> | B | 12 | A and B can complete a work in 15days and 10day. They started doing the work together but after 2days B had to leave and A alone completed the remaining work. The whole work was completed in? | {
"A": "10 days",
"B": "12 days",
"C": "15 days",
"D": "8 days",
"E": "16 days"
} | add(multiply(subtract(const_1, multiply(add(divide(const_1, 15), divide(const_1, 10)), 2)), 15), 2) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)|multiply(n0,#4)|add(n2,#5)| | "a + b 1 day work = 1 / 15 + 1 / 10 = 1 / 6 work done by a and b in 2 days = 1 / 6 * 2 = 1 / 3 remaining work = 1 - 1 / 3 = 2 / 3 now 1 / 15 work is done by a in 1 day 2 / 3 work will be done by a in 15 * 2 / 3 = 10 days total time taken = 10 + 2 = 12 days answer is b" | physics |
math_qa__kHvWgttaYKXuYg9T | The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 6000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation?
Choose the correct choice:
A) 500 B) 1,600 / 3 C) 1,000 D) 1,500 E) 2,500 | <gadget id="calculator">6_000 / 2</gadget>
<output>3_000</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3_000 * (1/2)</gadget>
<output>1_500</output>
<result>D</result> | D | 1,500 | The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 6000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation? | {
"A": "500",
"B": "1,600 / 3",
"C": "1,000",
"D": "1,500",
"E": "2,500"
} | multiply(divide(6000, 2), divide(const_1, 2)) | divide(n8,n3)|divide(const_1,n3)|multiply(#0,#1)| | "x 13 : ( t , d , s ) y 14 : ( t , 3 d , s + 6000 mi / hour ) z 15 : ( t + 2 seconds , s , 5 d ) d = ? distance = speed * time x 13 : d = s * t x 14 : 3 d = ( s + 6000 ) * t = = = > 3 d = ts + 6000 t z 15 : 5 d = s * ( t + 2 t ) = = = > 5 d = st + 2 st = = = > 5 d - 2 st = st 3 d = 5 d - 2 st + 6000 t - 2 d = - 2 st + 6000 t 2 d = 2 st - 6000 t d = st - 3000 t x 13 : d = s * t st - 3000 t = s * t s - 3000 = s - 1500 = s i got to this point and could n ' t go any further . this seems like a problem where i can set up individual d = r * t formulas and solve but it appears that ' s not the case . for future reference how would i know not to waste my time setting up this problem in the aforementioned way ? thanks ! ! ! the distance of z 15 is equal to five times the distance of x 13 ( we established that x 13 is the baseline and thus , it ' s measurements are d , s , t ) s ( t + 2 ) = 5 ( s * t ) what clues would i have to know to set up the equation in this fashion ? is it because i am better off setting two identical distances together ? st + 2 s = 5 st t + 2 = 5 t 2 = 4 t t = 1 / 2 we are looking for distance ( d = s * t ) so we need to solve for speed now that we have time . speed y 14 - speed x 13 speed = d / t 3 d / t - d / t = 6000 ( remember , t is the same because both asteroids were observed for the same amount of time ) 2 d = 6000 2 = 3000 d = s * t d = 3000 * ( 1 / 2 ) d = 1500 answer : d" | physics |
math_qa__BnxmNLhIsw9DaHVM | The roof of an apartment building is rectangular and its length is 3 times longer than its width. If the area of the roof is 768 feet squared, what is the difference between the length and the width of the roof?
Choices
A) 32 . B) 40 . C) 42 . D) 44 . E) 46 . | <gadget id="calculator">768 / 3</gadget>
<output>256</output>
<gadget id="calculator">256 ** (1/2)</gadget>
<output>16</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<result>A</result> | A | 32 | The roof of an apartment building is rectangular and its length is 3 times longer than its width. If the area of the roof is 768 feet squared, what is the difference between the length and the width of the roof? | {
"A": "32 .",
"B": "40 .",
"C": "42 .",
"D": "44 .",
"E": "46 ."
} | subtract(multiply(sqrt(divide(768, 3)), 3), sqrt(divide(768, 3))) | divide(n1,n0)|sqrt(#0)|multiply(#1,n0)|subtract(#2,#1)| | "answer is a : 42 let w be the width , so length is 3 w . therefore : w * 4 w = 768 , solving for , w = 16 , so 3 w - w = 2 w = 2 * 16 = 32" | geometry |
math_qa__WAld0CO9SKx14FoU | A certain fraction is equivalent to 2/5. If the numerator of the fraction is increased by 3 and the denominator is doubled, the new fraction is equivalent to 1/3. What is the sum of the numerator and denominator of the original fraction? Choose the correct answer:
A) 21 / 4
B) 35
C) 28
D) 26
E) 21 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) * 3</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) + 3</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">(21/2) / 2</gadget>
<output>21/4 = around 5.25</output>
<result>A</result> | A | 5.25 | A certain fraction is equivalent to 2/5. If the numerator of the fraction is increased by 3 and the denominator is doubled, the new fraction is equivalent to 1/3. What is the sum of the numerator and denominator of the original fraction? | {
"A": "21 / 4",
"B": "35",
"C": "28",
"D": "26",
"E": "21"
} | divide(add(multiply(divide(5, 2), 3), 3), 2) | divide(n1,n0)|multiply(n2,#0)|add(n2,#1)|divide(#2,n0) | x / y = 2 / 5 - > 1 ( x + 3 ) / 2 y = 1 / 3 - > 2 divide 1 by 2 : = > 2 x / ( x + 3 ) = 6 / 5 = > 10 x = 6 x + 18 = > x = 3 / 2 = > y = 5 / 2 * 3 / 2 = 15 / 4 so x + y = 21 / 4 the answer is a | general |
math_qa__iDRsmMdCZAqLA657 | In what time will a train 95 m long cross an electric pole, it its speed be 214 km/hr? Answers: A) 1.6 sec B) 2.9 sec C) 2.7 sec D) 8.7 sec E) 8.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">214 * (5/18)</gadget>
<output>535/9 = around 59.444444</output>
<gadget id="calculator">95 / (535/9)</gadget>
<output>171/107 = around 1.598131</output>
<result>A</result> | A | 1.6 | In what time will a train 95 m long cross an electric pole, it its speed be 214 km/hr? | {
"A": "1.6 sec",
"B": "2.9 sec",
"C": "2.7 sec",
"D": "8.7 sec",
"E": "8.5 sec"
} | divide(95, multiply(214, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 214 * 5 / 18 = 59 m / sec time taken = 95 / 59 = 1.6 sec . answer : a" | physics |
math_qa__Oj7MeiKcqmaQY5hl | Q-2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? Pick.
A) 9
B) 10
C) 11
D) 12
E) 14 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 + 3</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<result>E</result> | E | 14 | Q-2: How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "14"
} | add(add(add(add(add(2, 1), 2), 3), 4), 2) | add(n0,n1)|add(n0,#0)|add(n3,#1)|add(n4,#2)|add(n0,#3) | concept : a number will be divisible by 3 if sum of all the digits of the number is divisible by 3 here the possible sum of the two distinct digits can be 3 , 6 , 9 and 12 only in order to satisfy the given condition if sum of digits = 3 , no . = 12 , 21 - - - 2 cases if sum of digits = 6 , no . = 15 , 24 , 42 , 51 - - - 4 cases if sum of digits = 9 , no . = 27 , 36 , 45 , 54 , 63 , 72 - - - 6 cases if sum of digits = 12 , no . = 57 , 75 - - - 2 cases total cases = 2 + 4 + 6 + 2 = 14 cases answer : option e | general |
math_qa__qHtji0FCQgPCiOhl | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 65 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? Pick: A) 15 B) 20 C) 40 D) 47 E) 49 | <gadget id="calculator">72 / 60</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 35</gadget>
<output>42</output>
<gadget id="calculator">65 - 35</gadget>
<output>30</output>
<gadget id="calculator">42 / 30</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">35 * (7/5)</gadget>
<output>49</output>
<result>E</result> | E | 49 | Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 65 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? | {
"A": "15",
"B": "20",
"C": "40",
"D": "47",
"E": "49"
} | multiply(35, divide(multiply(divide(72, const_60), 35), subtract(65, 35))) | divide(n1,const_60)|subtract(n2,n0)|multiply(n0,#0)|divide(#2,#1)|multiply(n0,#3)| | "car y began travelling after 72 minutes or 1.2 hours . let t be the time for which car y travelled before it stopped . both cars stop when they have travelled the same distance . so , 35 ( t + 1.2 ) = 65 t t = 1.4 distance traveled by car x from the time car y began traveling until both cars stopped is 35 x 1.4 = 49 miles answer : - e" | physics |
math_qa__RpWVumGY9QjPsqBE | The L.C.M. of two numbers is 42. The numbers are in the ratio 2 : 3. Then sum of the number is: Answers.
A) 28 B) 32 C) 35 D) 53 E) 54 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">42 / 6</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">21 + 14</gadget>
<output>35</output>
<result>C</result> | C | 35 | The L.C.M. of two numbers is 42. The numbers are in the ratio 2 : 3. Then sum of the number is: | {
"A": "28",
"B": "32",
"C": "35",
"D": "53",
"E": "54"
} | add(multiply(divide(42, multiply(2, 3)), 3), multiply(divide(42, multiply(2, 3)), 2)) | multiply(n1,n2)|divide(n0,#0)|multiply(n2,#1)|multiply(n1,#1)|add(#2,#3) | let the numbers be 2 x and 3 x . then , their l . c . m . = 6 x . so , 6 x = 42 or x = 7 . the numbers are 14 and 21 . hence , required sum = ( 14 + 21 ) = 35 . answer : option c | other |
math_qa__DKE5idGpyqPgUt0f | A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.150. Find the unknown rate of two towels? Choose the correct choice from the following choices.
A) 400 B) 450 C) 500 D) 550 E) 600 | <gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 150</gadget>
<output>1_500</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">1_500 - 750</gadget>
<output>750</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">750 - 300</gadget>
<output>450</output>
<result>B</result> | B | 450 | A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.150. Find the unknown rate of two towels? | {
"A": "400",
"B": "450",
"C": "500",
"D": "550",
"E": "600"
} | subtract(subtract(multiply(add(add(3, 5), const_2), 150), multiply(5, 150)), multiply(3, 100)) | add(n0,n2)|multiply(n2,n3)|multiply(n0,n1)|add(#0,const_2)|multiply(n4,#3)|subtract(#4,#1)|subtract(#5,#2)| | "10 * 150 = 1500 3 * 100 + 5 * 150 = 1050 1500 – 1050 = 450 b" | general |
math_qa__Et9daa3bAIj4M2yi | A present value of a machine is $400. Its value depletiation rate is 25% per annum then find the machine value after 2 years? Select:
A) $ 125
B) $ 100
C) $ 200
D) $ 215
E) $ 225 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 2</gadget>
<output>9/16 = around 0.5625</output>
<gadget id="calculator">400 * (9/16)</gadget>
<output>225</output>
<result>E</result> | E | 225 | A present value of a machine is $400. Its value depletiation rate is 25% per annum then find the machine value after 2 years? | {
"A": "$ 125",
"B": "$ 100",
"C": "$ 200",
"D": "$ 215",
"E": "$ 225"
} | multiply(400, power(subtract(const_1, divide(25, const_100)), 2)) | divide(n1,const_100)|subtract(const_1,#0)|power(#1,n2)|multiply(n0,#2)| | "p = $ 400 r = 25 % t = 2 years machine value after 2 years = p [ ( 1 - r / 100 ) ^ t ] = 400 * 3 / 4 * 3 / 4 = $ 225 approximately answer is e" | gain |
math_qa__jCvbjbGt9i6KKhJ7 | A merchant purchased a jacket for $60 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 20 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale? Choose the correct choice from the following.
A) $ 0 B) $ 3 C) $ 4 D) $ 12 E) $ 15 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">60 / (4/5)</gadget>
<output>75</output>
<gadget id="calculator">75 * (4/5)</gadget>
<output>60</output>
<gadget id="calculator">60 - 60</gadget>
<output>0</output>
<result>A</result> | A | 0 | A merchant purchased a jacket for $60 and then determined a selling price that equalled the purchase price of the jacket plus a markup that was 20 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale? | {
"A": "$ 0",
"B": "$ 3",
"C": "$ 4",
"D": "$ 12",
"E": "$ 15"
} | subtract(multiply(divide(60, subtract(const_1, divide(20, const_100))), subtract(const_1, divide(20, const_100))), 60) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_1,#0)|subtract(const_1,#1)|divide(n0,#2)|multiply(#4,#3)|subtract(#5,n0)| | "actual cost = $ 60 sp = actual cost + mark up = actual cost + 20 % sp = 60 * 100 / 80 on sale sp = 80 / 100 ( 60 * 100 / 80 ) = 60 gross profit = $ 0 answer is a" | gain |
math_qa__m92sBtJCPZDFOigl | A store’s selling price of $2240 for a certain computer would yield a profit of 40 percent of the store’s cost for the computer. What selling price would yield a profit of 50 percent of the computer’s cost? Choose the correct choice from the following choices: A) $ 2400 B) $ 2464 C) $ 2650 D) $ 2732 E) $ 2800 | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">150 / 140</gadget>
<output>15/14 = around 1.071429</output>
<gadget id="calculator">2_240 * (15/14)</gadget>
<output>2_400</output>
<result>A</result> | A | 2,400 | A store’s selling price of $2240 for a certain computer would yield a profit of 40 percent of the store’s cost for the computer. What selling price would yield a profit of 50 percent of the computer’s cost? | {
"A": "$ 2400",
"B": "$ 2464",
"C": "$ 2650",
"D": "$ 2732",
"E": "$ 2800"
} | multiply(2240, divide(add(const_100, 50), add(const_100, 40))) | add(n2,const_100)|add(n1,const_100)|divide(#0,#1)|multiply(n0,#2)| | "2240 = x * 1.4 = x * ( 7 / 5 ) . therefore , x = 2240 * 5 / 7 . 2240 is easily divided by 7 to be 320 , which is then easily multiplied by 5 to give x = 1600 . to get 50 % profit , you need 1600 * 1.5 = 2400 . answer : a" | gain |
math_qa__jLl1NYOloBqTgyqM | Two interconnected, circular gears travel at the same circumferential rate. If Gear A has a diameter of 80 centimeters and Gear B has a diameter of 50 centimeters, what is the ratio of the number of revolutions that Gear A makes per minute to the number of revolutions that Gear B makes per minute? Choose one:
A) 8 : 5 B) 9 : 25 C) 5 : 8 D) 25 : 9 E) can not be determined from the information provided | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">2 * pi * 25</gadget>
<output>50*pi = around 157.079633</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<gadget id="calculator">2 * pi * 40</gadget>
<output>80*pi = around 251.327412</output>
<gadget id="calculator">(50*pi) / (80*pi)</gadget>
<output>5/8 = around 0.625</output>
<result>C</result> | C | 0.625 | Two interconnected, circular gears travel at the same circumferential rate. If Gear A has a diameter of 80 centimeters and Gear B has a diameter of 50 centimeters, what is the ratio of the number of revolutions that Gear A makes per minute to the number of revolutions that Gear B makes per minute? | {
"A": "8 : 5",
"B": "9 : 25",
"C": "5 : 8",
"D": "25 : 9",
"E": "can not be determined from the information provided"
} | divide(circumface(divide(50, const_2)), circumface(divide(80, const_2))) | divide(n1,const_2)|divide(n0,const_2)|circumface(#0)|circumface(#1)|divide(#2,#3) | same circumferential rate means that a point on both the gears would take same time to come back to the same position again . hence in other words , time taken by the point to cover the circumference of gear a = time take by point to cover the circumference of gear b time a = 2 * pi * 25 / speed a time b = 2 * pi * 40 / speed b since the times are same , 50 pi / speed a = 80 pi / speed b speeda / speed b = 50 pi / 80 pi = 5 / 8 correct option : c | physics |
math_qa__7ydO3u64zIsStHzK | Tough and Tricky questions: Distance/Rate.
On a reconnaissance mission, a state-of-the-art nuclear powered submarine traveled 300 miles to reposition itself in the proximity of an aircraft carrier. This journey would have taken 1 hour less if the submarine had traveled 10 miles per hour faster. What was the average speed, in miles per hour, for the actual journey?
Choices.
A) 20 B) 40 C) 60 D) 80 E) 50 | <gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * 4</gadget>
<output>12_000</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">12_000 + 100</gadget>
<output>12_100</output>
<gadget id="calculator">12_100 ** (1/2)</gadget>
<output>110</output>
<gadget id="calculator">110 - 10</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>E</result> | E | 50 | Tough and Tricky questions: Distance/Rate.
On a reconnaissance mission, a state-of-the-art nuclear powered submarine traveled 300 miles to reposition itself in the proximity of an aircraft carrier. This journey would have taken 1 hour less if the submarine had traveled 10 miles per hour faster. What was the average speed, in miles per hour, for the actual journey? | {
"A": "20",
"B": "40",
"C": "60",
"D": "80",
"E": "50"
} | divide(subtract(sqrt(add(multiply(multiply(300, 10), const_4), power(10, const_2))), 10), const_2) | multiply(n0,n2)|power(n2,const_2)|multiply(#0,const_4)|add(#2,#1)|sqrt(#3)|subtract(#4,n2)|divide(#5,const_2) | say , if speed is 60 , 300 / 50 = 6 hrs and 300 / 60 = 5 hrs ( a reduction of 1 hr - > correct answer ) answer ( e ) | general |
math_qa__oi3TXAZnv4TytJgy | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.12000. A's share is? Select:
A) 2500 B) 3500 C) 4500 D) 2800 E) 4000 | <gadget id="calculator">1 * 12</gadget>
<output>12</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">12_000 / 36</gadget>
<output>1_000/3 = around 333.333333</output>
<gadget id="calculator">12 * (1_000/3)</gadget>
<output>4_000</output>
<result>E</result> | E | 4,000 | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.12000. A's share is? | {
"A": "2500",
"B": "3500",
"C": "4500",
"D": "2800",
"E": "4000"
} | multiply(multiply(const_1, const_12), divide(12000, add(add(multiply(const_1, const_12), multiply(subtract(const_12, 6), const_2)), multiply(subtract(const_12, 8), const_3)))) | multiply(const_1,const_12)|subtract(const_12,n0)|subtract(const_12,n1)|multiply(#1,const_2)|multiply(#2,const_3)|add(#0,#3)|add(#5,#4)|divide(n2,#6)|multiply(#7,#0)| | "x * 12 : 2 x * 6 : 3 x * 4 1 : 1 : 1 1 / 3 * 12000 = 4000 answer : e" | gain |
math_qa__fVinPdlfd88xpeGX | One computer can upload 100 megabytes worth of data in 3 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 30 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data? Options: A) 6 B) 10 C) 9 D) 11 E) 13 | <gadget id="calculator">1_300 / 30</gadget>
<output>130/3 = around 43.333333</output>
<gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(130/3) - (100/3)</gadget>
<output>10</output>
<result>B</result> | B | 10 | One computer can upload 100 megabytes worth of data in 3 seconds. Two computers, including this one, working together, can upload 1300 megabytes worth of data in 30 seconds. How long would it take for the second computer, working on its own, to upload 100 megabytes of data? | {
"A": "6",
"B": "10",
"C": "9",
"D": "11",
"E": "13"
} | subtract(divide(1300, 30), divide(100, 3)) | divide(n2,n3)|divide(n0,n1)|subtract(#0,#1) | since the first computer can upload 100 megabytes worth of data in 3 seconds then in 3 * 10 = 30 seconds it can upload 10 * 100 = 1000 megabytes worth of data , hence the second computer in 30 seconds uploads 1300 - 1000 = 300 megabytes worth of data . the second computer can upload 100 megabytes of data in 10 seconds . answer : b . | physics |
math_qa__jLj6iPjTWnspkosN | Two trains 130 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Choose the correct choice: A) 10.9 B) 10.7 C) 10.3 D) 10.44 E) 10.8 | <gadget id="calculator">130 + 160</gadget>
<output>290</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">290 / (250/9)</gadget>
<output>261/25 = around 10.44</output>
<result>D</result> | D | 10.44 | Two trains 130 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.9",
"B": "10.7",
"C": "10.3",
"D": "10.44",
"E": "10.8"
} | divide(add(130, 160), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 130 + 160 = 290 m . required time = 290 * 9 / 250 = 261 / 25 = 10.44 sec . ' answer : d" | physics |
math_qa__roimGnTbwrA1F1ti | In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number W of employees who take the subway to work? Answers:
A) 12 B) 13 C) 14 D) 15 E) 16 | <gadget id="calculator">48 * 3</gadget>
<output>144</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">144 / 12</gadget>
<output>12</output>
<gadget id="calculator">48 - 12</gadget>
<output>36</output>
<gadget id="calculator">36 / 12</gadget>
<output>3</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<result>D</result> | D | 15 | In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number W of employees who take the subway to work? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | add(divide(multiply(48, 3), multiply(3, 4)), divide(subtract(48, multiply(3, 4)), divide(multiply(48, 3), multiply(3, 4)))) | multiply(n0,n2)|multiply(n2,n4)|divide(#0,#1)|subtract(n0,#1)|divide(#3,#2)|add(#2,#4) | p / 3 + f / 4 = p / 3 + ( 48 - p ) / 4 = 12 + p / 2 p / 3 + f / 3 = ( p + f ) / 3 = 48 / 3 = 16 p / 4 + f / 4 = 12 p / 3 + f / 3 > p / 3 + f / 4 > p / 4 + f / 4 - - > 16 > 12 + p / 12 > 12 greatest possible w : 12 + p / 12 = 15 - - > p = 36 ( integer - - > good ) 15 or d is the answer | general |
math_qa__VI2WuWzjL9kDHXoY | If Sharon's weekly salary increased by 16 percent, she would earn $406 per week. If instead, her weekly salary were to increase by 10 percent, how much would she earn per week? Answers.
A) $ 374 B) $ 382 C) $ 385 D) $ 392 E) $ 399 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">1 + (4/25)</gadget>
<output>29/25 = around 1.16</output>
<gadget id="calculator">406 / (29/25)</gadget>
<output>350</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 350</gadget>
<output>35</output>
<gadget id="calculator">350 + 35</gadget>
<output>385</output>
<result>C</result> | C | 385 | If Sharon's weekly salary increased by 16 percent, she would earn $406 per week. If instead, her weekly salary were to increase by 10 percent, how much would she earn per week? | {
"A": "$ 374",
"B": "$ 382",
"C": "$ 385",
"D": "$ 392",
"E": "$ 399"
} | add(divide(406, add(const_1, divide(16, const_100))), multiply(divide(10, const_100), divide(406, add(const_1, divide(16, const_100))))) | divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|divide(n1,#2)|multiply(#1,#3)|add(#3,#4)| | "soln : - ( 406 / 116 ) 110 = 385 in this case long division does not take much time . ( 406 / 116 ) = 3.5 35 * 11 = 385 ( 350 + 35 ) answer : c" | general |
math_qa__2TKSdSF1lawUzBBh | What is the average of first 21 multiples of 6 ? Choose the correct answer
A) 66 B) 77 C) 79 D) 81 E) 82 | <gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">21 * 22</gadget>
<output>462</output>
<gadget id="calculator">462 / 2</gadget>
<output>231</output>
<gadget id="calculator">231 / 21</gadget>
<output>11</output>
<gadget id="calculator">11 * 6</gadget>
<output>66</output>
<result>A</result> | A | 66 | What is the average of first 21 multiples of 6 ? | {
"A": "66",
"B": "77",
"C": "79",
"D": "81",
"E": "82"
} | multiply(divide(divide(multiply(21, add(21, const_1)), const_2), 21), 6) | add(n0,const_1)|multiply(n0,#0)|divide(#1,const_2)|divide(#2,n0)|multiply(n1,#3)| | "required average = 6 ( 1 + 2 + . . . . + 21 ) / 21 ( 6 / 21 ) x ( ( 21 x 22 ) / 2 ) ( because sum of first 21 natural numbers ) = 66 a" | general |
math_qa__1zrCxFCdhuu2yb2X | A contractor undertook to do a piece of work in 8 days. He employed certain number of laboures but 3 of them were absent from the very first day and the rest could finish the work in only 14 days. Find the number of men originally employed ? Choose the correct choice from the following options: A) 6 B) 7.5 C) 5 D) 6 E) 7 | <gadget id="calculator">14 * 3</gadget>
<output>42</output>
<gadget id="calculator">14 - 8</gadget>
<output>6</output>
<gadget id="calculator">42 / 6</gadget>
<output>7</output>
<result>E</result> | E | 7 | A contractor undertook to do a piece of work in 8 days. He employed certain number of laboures but 3 of them were absent from the very first day and the rest could finish the work in only 14 days. Find the number of men originally employed ? | {
"A": "6",
"B": "7.5",
"C": "5",
"D": "6",
"E": "7"
} | divide(multiply(14, 3), subtract(14, 8)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "let the number of men originally employed be x . 8 x = 14 ( x â € “ 3 ) or x = 7 answer e" | physics |
math_qa__WULG3ohRXg5iRkU7 | What is the sum of two consecutive even numbers, the difference of whose squares is 84? Pick.
A) 42 B) 84 C) 48 D) 24 E) 43 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">84 - 4</gadget>
<output>80</output>
<gadget id="calculator">80 / 4</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">20 + 22</gadget>
<output>42</output>
<result>A</result> | A | 42 | What is the sum of two consecutive even numbers, the difference of whose squares is 84? | {
"A": "42",
"B": "84",
"C": "48",
"D": "24",
"E": "43"
} | add(divide(subtract(84, multiply(const_2, const_2)), multiply(const_2, const_2)), add(divide(subtract(84, multiply(const_2, const_2)), multiply(const_2, const_2)), const_2)) | multiply(const_2,const_2)|subtract(n0,#0)|divide(#1,#0)|add(#2,const_2)|add(#3,#2) | let the numbers be x and x + 2 . then , ( x + 2 ) 2 - x 2 = 84 4 x + 4 = 84 4 x = 80 x = 20 . the required sum = x + ( x + 2 ) = 2 x + 2 = 42 . answer a 42 | general |
math_qa__M6SdLDburYVYXg2f | If x > 0, x/5 + x/25 is what percent of x?
Pick.
A) 6 % B) 24 % C) 37 1 / 2 % D) 60 % E) 75 % | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/5) + (1/25)</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">(6/25) * 100</gadget>
<output>24</output>
<result>B</result> | B | 24 | If x > 0, x/5 + x/25 is what percent of x? | {
"A": "6 %",
"B": "24 %",
"C": "37 1 / 2 %",
"D": "60 %",
"E": "75 %"
} | multiply(add(divide(const_1, 5), divide(const_1, 25)), const_100) | divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|multiply(#2,const_100)| | "just plug and chug . since the question asks for percents , pick 100 . ( but any number will do . ) 100 / 5 + 100 / 25 = 20 + 4 = 24 24 is 24 % of 100 = b" | general |
math_qa__p0KArTn3oP9Ovr9Y | Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $102 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary? Choose the correct choice from the following answers: A) $ 3400 B) $ 3200 C) $ 6000 D) $ 6400 E) $ 9600 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">50 + 35</gadget>
<output>85</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">102 / 15</gadget>
<output>34/5 = around 6.8</output>
<gadget id="calculator">500 * (34/5)</gadget>
<output>3_400</output>
<result>A</result> | A | 3,400 | Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $102 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary? | {
"A": "$ 3400",
"B": "$ 3200",
"C": "$ 6000",
"D": "$ 6400",
"E": "$ 9600"
} | multiply(multiply(const_100, add(const_3, const_2)), divide(102, subtract(const_100, add(add(30, 20), 35)))) | add(n0,n1)|add(const_2,const_3)|add(n2,#0)|multiply(#1,const_100)|subtract(const_100,#2)|divide(n3,#4)|multiply(#5,#3)| | "let x be the monthly salary 15 % of 1 / 5 * x = 102 x = 3400 answer a" | gain |
math_qa__W3Stg30kie6hU976 | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2017) = ? Pick one:
A) 2018 B) 2088 C) 270 D) 1881 E) 1781 | <gadget id="calculator">1 + 2_017</gadget>
<output>2_018</output>
<result>A</result> | A | 2,018 | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2017) = ? | {
"A": "2018",
"B": "2088",
"C": "270",
"D": "1881",
"E": "1781"
} | add(1, 2017) | add(n3,n4)| | "f ( f ( 0 ) ) + f ( 0 ) = 2 ( 0 ) + 3 ⇒ ⇒ f ( 1 ) = 3 - 1 = 2 , f ( 1 ) = 2 f ( f ( 1 ) ) + f ( 1 ) = 2 ( 1 ) + 3 ⇒ ⇒ f ( 2 ) = 5 - 2 = 3 , f ( 2 ) = 3 f ( f ( 2 ) ) + f ( 2 ) = 2 ( 2 ) + 3 ⇒ ⇒ f ( 3 ) = 7 - 3 = 4 , f ( 3 ) = 4 . . . . . . . . . . . . . . f ( 2017 ) = 2018 ans : a" | general |
math_qa__V7sFAjzBIWoBwgp1 | The H.C.F. of two numbers is 32 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: Choose the correct choice from the following choices.
A) 448
B) 299
C) 421
D) 460
E) 365 | <gadget id="calculator">32 * 14</gadget>
<output>448</output>
<result>A</result> | A | 448 | The H.C.F. of two numbers is 32 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: | {
"A": "448",
"B": "299",
"C": "421",
"D": "460",
"E": "365"
} | multiply(32, 14) | multiply(n0,n2)| | "clearly , the numbers are ( 32 x 13 ) and ( 32 x 14 ) . larger number = ( 32 x 14 ) = 448 . answer : option a" | other |
math_qa__uF0cStvhQ2Q5nomC | A solution is 90% glycerin. If there are 4 gallons of the solution, how much water, in gallons must be addded to make a 75% glycerin solution
Answers: A) 1.8 B) 1.4 C) 1.2 D) 1.0 E) 0.8 | <gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * 4</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(18/5) / (3/4)</gadget>
<output>24/5 = around 4.8</output>
<gadget id="calculator">(24/5) - 4</gadget>
<output>4/5 = around 0.8</output>
<result>E</result> | E | 0.8 | A solution is 90% glycerin. If there are 4 gallons of the solution, how much water, in gallons must be addded to make a 75% glycerin solution | {
"A": "1.8",
"B": "1.4",
"C": "1.2",
"D": "1.0",
"E": "0.8"
} | subtract(divide(multiply(divide(90, const_100), 4), divide(75, const_100)), 4) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|divide(#2,#1)|subtract(#3,n1) | in 4 gallons of the solution there are 0.9 ∗ 4 = 3.80 gallons of glycerin . we want to add ww gallons of water to 4 gallons of solution so that these 3.6 gallons of glycerin to be 75 % of new solution : 0.9 ∗ 4 = 0.75 ( 4 + w ) - - > w = 0.8 answer : e . | general |
math_qa__4WKiF3M1vGCfLuIT | Of the 120 passengers on Flight 750, 30% are female. 10% of the passengers sit in first class, and the rest of the passengers sit in coach class. If 1/3 of the passengers in first class are male, how many females are there in coach class? Choose the correct choice from the following options: A) 44 B) 28 C) 50 D) 52 E) 56 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">120 * (3/10)</gadget>
<output>36</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">120 * (1/10)</gadget>
<output>12</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">36 - 8</gadget>
<output>28</output>
<result>B</result> | B | 28 | Of the 120 passengers on Flight 750, 30% are female. 10% of the passengers sit in first class, and the rest of the passengers sit in coach class. If 1/3 of the passengers in first class are male, how many females are there in coach class? | {
"A": "44",
"B": "28",
"C": "50",
"D": "52",
"E": "56"
} | subtract(multiply(120, divide(30, const_100)), subtract(multiply(120, divide(10, const_100)), divide(multiply(120, divide(10, const_100)), 3))) | divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n0,#1)|divide(#3,n5)|subtract(#3,#4)|subtract(#2,#5)| | "number of passengers on flight = 120 number of female passengers = . 3 * 120 = 36 number of passengers in first class = ( 10 / 100 ) * 120 = 12 number of passengers in coach class = ( 90 / 100 ) * 120 = 108 number of male passengers in first class = 1 / 3 * 12 = 4 number of female passengers in first class = 12 - 4 = 8 number of female passengers in coach class = 36 - 8 = 28 answer b" | gain |
math_qa__b2rgrnfcv4ipGx81 | 1240 men have provisions for 12 days. If 300 more men join them, for how many days will the provisions last now? Choose the correct choice: A) 12.9 B) 12.0 C) 9.7 D) 8.6 E) 12.1 | <gadget id="calculator">12 * 1_240</gadget>
<output>14_880</output>
<gadget id="calculator">1_240 + 300</gadget>
<output>1_540</output>
<gadget id="calculator">14_880 / 1_540</gadget>
<output>744/77 = around 9.662338</output>
<result>C</result> | C | 9.7 | 1240 men have provisions for 12 days. If 300 more men join them, for how many days will the provisions last now? | {
"A": "12.9",
"B": "12.0",
"C": "9.7",
"D": "8.6",
"E": "12.1"
} | divide(multiply(12, 1240), add(1240, 300)) | add(n0,n2)|multiply(n0,n1)|divide(#1,#0)| | "1240 * 12 = 1540 * x x = 9.7 answer : c" | physics |
math_qa__CeMxVbqQUa2zyAml | On a certain transatlantic crossing, 15 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets? Pick one:
A) 37.5 %
B) 40 %
C) 50 %
D) 60 %
E) 66.6 % | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">15 / (2/5)</gadget>
<output>75/2 = around 37.5</output>
<result>A</result> | A | 37.5 | On a certain transatlantic crossing, 15 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets? | {
"A": "37.5 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "66.6 %"
} | divide(15, divide(subtract(const_100, 60), const_100)) | subtract(const_100,n1)|divide(#0,const_100)|divide(n0,#1) | 0.15 p = rt + c 0.6 ( rt ) = no c = > 0.40 ( rt ) had c 0.15 p = 0.40 ( rt ) rt / p = 37.5 % answer - a | gain |
math_qa__IrbphdAiVD6ctT12 | In how many seconds will a train 150 meters long pass an oak tree, if the speed of the train is 36 km/hr? Choose the correct choice from the following answers: A) 11 B) 13 C) 15 D) 17 E) 19 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 36</gadget>
<output>10</output>
<gadget id="calculator">150 / 10</gadget>
<output>15</output>
<result>C</result> | C | 15 | In how many seconds will a train 150 meters long pass an oak tree, if the speed of the train is 36 km/hr? | {
"A": "11",
"B": "13",
"C": "15",
"D": "17",
"E": "19"
} | divide(150, multiply(const_0_2778, 36)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 36 * 5 / 18 = 10 m / s time = 150 / 10 = 15 seconds the answer is c ." | physics |
math_qa__lQ4ypPwpHGud29H4 | Two numbers N and 16 have LCM = 48 and GCF = 4. Find N. Choose the most appropriate option.
A) 35 B) 56 C) 76 D) 87 E) 12 | <gadget id="calculator">48 * 4</gadget>
<output>192</output>
<gadget id="calculator">192 / 16</gadget>
<output>12</output>
<result>E</result> | E | 12 | Two numbers N and 16 have LCM = 48 and GCF = 4. Find N. | {
"A": "35",
"B": "56",
"C": "76",
"D": "87",
"E": "12"
} | divide(multiply(48, 4), 16) | multiply(n1,n2)|divide(#0,n0)| | "the product of two integers is equal to the product of their lcm and gcf . hence . 16 * n = 48 * 4 n = 48 * 4 / 16 = 12 correct answer e" | physics |
math_qa__thTPRuDc16KvbGDX | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.65000? Pick one
A) 81000 B) 81007 C) 81008 D) 81066 E) 82265.6 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 65_000</gadget>
<output>8_125</output>
<gadget id="calculator">65_000 + 8_125</gadget>
<output>73_125</output>
<gadget id="calculator">(1/8) * 73_125</gadget>
<output>73_125/8 = around 9_140.625</output>
<gadget id="calculator">73_125 + (73_125/8)</gadget>
<output>658_125/8 = around 82_265.625</output>
<result>E</result> | E | 82,265.6 | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.65000? | {
"A": "81000",
"B": "81007",
"C": "81008",
"D": "81066",
"E": "82265.6"
} | add(add(65000, multiply(divide(1, 8), 65000)), multiply(divide(1, 8), add(65000, multiply(divide(1, 8), 65000)))) | divide(n0,n1)|multiply(n2,#0)|add(n2,#1)|multiply(#2,#0)|add(#2,#3)| | "65000 * 9 / 8 * 9 / 8 = 82265.6 answer : e" | general |
math_qa__RH0wEssY4EyLFeWo | A track covers a distance of 550 metres in 1 minute whereas a bus covers a distance of 33 kms in 45 minute. The ratio of their speeds is: Choose the correct choice from the following:
A) 4 : 3 B) 3 : 5 C) 3 : 4 D) 50 : 3 E) none | <gadget id="calculator">550 / 60</gadget>
<output>55/6 = around 9.166667</output>
<gadget id="calculator">33 * 1_000</gadget>
<output>33_000</output>
<gadget id="calculator">45 * 60</gadget>
<output>2_700</output>
<gadget id="calculator">33_000 / 2_700</gadget>
<output>110/9 = around 12.222222</output>
<gadget id="calculator">(55/6) / (110/9)</gadget>
<output>3/4 = around 0.75</output>
<result>C</result> | C | 0.75 | A track covers a distance of 550 metres in 1 minute whereas a bus covers a distance of 33 kms in 45 minute. The ratio of their speeds is: | {
"A": "4 : 3",
"B": "3 : 5",
"C": "3 : 4",
"D": "50 : 3",
"E": "none"
} | divide(divide(550, const_60), divide(multiply(33, const_1000), multiply(45, const_60))) | divide(n0,const_60)|multiply(n2,const_1000)|multiply(n3,const_60)|divide(#1,#2)|divide(#0,#3) | solution : speed of track = 550 per minute . speed of bus = 33 kms / 45 = 33000 / 45 = 733.33 m / minute ratio of their speeds = 550 / 733.33 = 3 : 4 . answer : option c | physics |
math_qa__ma0o4CG1iz9ajnNv | The length of rectangle is thrice its breadth and its perimeter is 64 m, find the area of the rectangle? Choose the correct choice from the following options: A) 432 sq m B) 192 sq m C) 452 sq m D) 428 sq m E) 528 sq m | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">64 / 8</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 * 8</gadget>
<output>192</output>
<result>B</result> | B | 192 | The length of rectangle is thrice its breadth and its perimeter is 64 m, find the area of the rectangle? | {
"A": "432 sq m",
"B": "192 sq m",
"C": "452 sq m",
"D": "428 sq m",
"E": "528 sq m"
} | multiply(multiply(divide(64, add(multiply(const_3, const_2), multiply(const_1, const_2))), const_3), divide(64, add(multiply(const_3, const_2), multiply(const_1, const_2)))) | multiply(const_2,const_3)|multiply(const_1,const_2)|add(#0,#1)|divide(n0,#2)|multiply(#3,const_3)|multiply(#3,#4)| | "2 ( 3 x + x ) = 64 l = 24 b = 8 lb = 24 * 8 = 192 answer : b" | geometry |
math_qa__eObeP0qUTdV84g9Y | The instructions state that Cheryl needs 3/8 square yards of one type of material and 1/3 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 15/40 square yards left that she did not use. What is the total amount of square yards of material Cheryl used?
Choose the correct choice from the following choices
A) 1 / 12 B) 1 / 9 C) 2 / 3 D) 1 / 3 E) 2 1 / 9 | <gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(3/8) + (1/3)</gadget>
<output>17/24 = around 0.708333</output>
<gadget id="calculator">15 / 40</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(17/24) - (3/8)</gadget>
<output>1/3 = around 0.333333</output>
<result>D</result> | D | 0.333333 | The instructions state that Cheryl needs 3/8 square yards of one type of material and 1/3 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 15/40 square yards left that she did not use. What is the total amount of square yards of material Cheryl used? | {
"A": "1 / 12",
"B": "1 / 9",
"C": "2 / 3",
"D": "1 / 3",
"E": "2 1 / 9"
} | subtract(add(divide(3, 8), divide(1, 3)), divide(15, 40)) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|add(#0,#1)|subtract(#3,#2)| | "total bought = 3 / 8 + 1 / 3 left part 15 / 40 - - - > 3 / 8 so used part 3 / 8 + 1 / 3 - 3 / 8 = 1 / 3 ans d" | general |
math_qa__PGbRMB3ZcKSzmoal | Running at the same rate, 8 identical machines can produce 560 paperclips a minute. At this rate, how many paperclips could 10 machines produce in 6 minutes? Choose the correct choice from the following answers
A) 1344 B) 4200 C) 8400 D) 50400 E) 67200 | <gadget id="calculator">10 / 8</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">560 * (5/4)</gadget>
<output>700</output>
<gadget id="calculator">700 * 6</gadget>
<output>4_200</output>
<result>B</result> | B | 4,200 | Running at the same rate, 8 identical machines can produce 560 paperclips a minute. At this rate, how many paperclips could 10 machines produce in 6 minutes? | {
"A": "1344",
"B": "4200",
"C": "8400",
"D": "50400",
"E": "67200"
} | multiply(multiply(560, divide(10, 8)), 6) | divide(n2,n0)|multiply(n1,#0)|multiply(n3,#1) | 8 machines produce 560 in 1 min 8 machines produce 560 * 6 in 6 min 10 machine produce 560 * 6 * ( 10 / 8 ) in 6 minutes 560 * 6 * 10 / 8 = 4200 answer is b . | gain |
math_qa__m64c4XpH7NlepAc9 | Speed of a boat in standing water is 16 kmph and the speed of the stream is 2 kmph. A man rows to a place at a distance of 7020 km and comes back to the starting point. The total time taken by him is: Choose one.
A) 914.2 hours B) 900 hours C) 915 hours D) 891.4 hours E) 915 hours | <gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">7_020 / 18</gadget>
<output>390</output>
<gadget id="calculator">16 - 2</gadget>
<output>14</output>
<gadget id="calculator">7_020 / 14</gadget>
<output>3_510/7 = around 501.428571</output>
<gadget id="calculator">390 + (3_510/7)</gadget>
<output>6_240/7 = around 891.428571</output>
<result>D</result> | D | 891.4 | Speed of a boat in standing water is 16 kmph and the speed of the stream is 2 kmph. A man rows to a place at a distance of 7020 km and comes back to the starting point. The total time taken by him is: | {
"A": "914.2 hours",
"B": "900 hours",
"C": "915 hours",
"D": "891.4 hours",
"E": "915 hours"
} | add(divide(7020, add(16, 2)), divide(7020, subtract(16, 2))) | add(n0,n1)|subtract(n0,n1)|divide(n2,#0)|divide(n2,#1)|add(#2,#3)| | "explanation : speed downstream = ( 16 + 2 ) = 18 kmph speed upstream = ( 16 - 2 ) = 14 kmph total time taken = 7020 / 18 + 7020 / 14 = 390 + 501.4 = 891.4 hours answer : option d" | physics |
math_qa__dOejC0lU8nhxXEpU | At 6'o clock clock ticks 6 times. The time between first and last ticks was 30sec. How much time it takes at 8'o clock. Pick.
A) 54 sec B) 48 sec C) 42 sec D) 70 sec E) 60 sec | <gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<result>C</result> | C | 42 | At 6'o clock clock ticks 6 times. The time between first and last ticks was 30sec. How much time it takes at 8'o clock. | {
"A": "54 sec",
"B": "48 sec",
"C": "42 sec",
"D": "70 sec",
"E": "60 sec"
} | multiply(subtract(8, const_1), divide(30, subtract(6, const_1))) | subtract(n0,const_1)|subtract(n3,const_1)|divide(n2,#0)|multiply(#2,#1) | at 6 ' 0 clock , clock ticks 6 times . so , there must be 5 intervals between clock ticks . time between first and last ticks = 30 sec so , 1 interval = 30 / 5 = 6 sec so 6 ' o clock 5 * 6 = 30 sec 7 ' o clock 6 * 6 = 36 sec 8 ' o clock 7 * 6 = 42 sec so , 42 sec at 8 ' o clock . answer : c | general |
math_qa__AVzmRktZ2m51viLx | 9 fencers participate in a fencing championship . assuming all competitors have an equal chance of winning , how many possibilities are there with respect to how a first - place and second - place medal can be awarded ? Choose the correct choice from the following:
A) 72 B) 75 C) 81 D) 84 E) 88 | <gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">factorial(7)</gadget>
<output>5_040</output>
<gadget id="calculator">362_880 / 5_040</gadget>
<output>72</output>
<result>A</result> | A | 72 | 9 fencers participate in a fencing championship . assuming all competitors have an equal chance of winning , how many possibilities are there with respect to how a first - place and second - place medal can be awarded ? | {
"A": "72",
"B": "75",
"C": "81",
"D": "84",
"E": "88"
} | divide(factorial(9), factorial(subtract(9, const_2))) | factorial(n0)|subtract(n0,const_2)|factorial(#1)|divide(#0,#2) | 9 * 8 = 72 the answer is a . | general |
math_qa__FyuAT20B2p3LzgAt | In a factory, an average of 70 TV's are produced per day for the fist 25days of the months. A few workers fell ill for the next 5days reducing the daily avg for the month to 68 sets/day . The average production per day for day last 5days is ? Pick
A) 20
B) 36
C) 48
D) 50
E) 58 | <gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 68</gadget>
<output>2_040</output>
<gadget id="calculator">25 * 70</gadget>
<output>1_750</output>
<gadget id="calculator">2_040 - 1_750</gadget>
<output>290</output>
<gadget id="calculator">290 / 5</gadget>
<output>58</output>
<result>E</result> | E | 58 | In a factory, an average of 70 TV's are produced per day for the fist 25days of the months. A few workers fell ill for the next 5days reducing the daily avg for the month to 68 sets/day . The average production per day for day last 5days is ? | {
"A": "20",
"B": "36",
"C": "48",
"D": "50",
"E": "58"
} | divide(subtract(multiply(add(25, 5), 68), multiply(25, 70)), 5) | add(n1,n2)|multiply(n0,n1)|multiply(n3,#0)|subtract(#2,#1)|divide(#3,n2)| | "production during these 5 days = total production in a month - production in first 25 days . = 30 x 68 - 25 x 70 = 290 ∴ average for last 5 days = 290 / 5 = 58 e" | general |
math_qa__BdMv5ZPOZILEOzH2 | Alex has 4 pens worth of {22, 25, 30, 40}, what is the total mean and median of the worth of pens ? Choose the correct choice from the following options:
A) 3.42 B) 6.16 C) 8.32 D) 2.0 E) 1.75 | <gadget id="calculator">22 + 25</gadget>
<output>47</output>
<gadget id="calculator">47 + 30</gadget>
<output>77</output>
<gadget id="calculator">77 + 40</gadget>
<output>117</output>
<gadget id="calculator">117 / 4</gadget>
<output>117/4 = around 29.25</output>
<gadget id="calculator">25 + 30</gadget>
<output>55</output>
<gadget id="calculator">55 / 2</gadget>
<output>55/2 = around 27.5</output>
<gadget id="calculator">(117/4) - (55/2)</gadget>
<output>7/4 = around 1.75</output>
<result>E</result> | E | 1.75 | Alex has 4 pens worth of {22, 25, 30, 40}, what is the total mean and median of the worth of pens ? | {
"A": "3.42",
"B": "6.16",
"C": "8.32",
"D": "2.0",
"E": "1.75"
} | subtract(divide(add(add(add(22, 25), 30), 40), 4), divide(add(25, 30), const_2)) | add(n1,n2)|add(n2,n3)|add(n3,#0)|divide(#1,const_2)|add(n4,#2)|divide(#4,n0)|subtract(#5,#3) | this is a good question to understand the difference between mean and median . mean : average of all the numbers . ( sum of all the elements divided by the number of elements ) median : arrange the elements of the set in increasing order . if the number of terms is odd , the middle term is the median . if the number of terms is even , the average of middle two terms is the median coming to this question , mean = ( 22 + 25 + 30 + 40 ) / 4 = 29.25 median = ( 25 + 30 ) / 2 = 27.5 total = 1.75 option e | general |
math_qa__fTtzCyafbcfFpgZD | There were 35 students in a hostel. Due to the admission of 7 new students, ;he expenses of the mess were increased by Rs. 42 per day while the average expenditure per head diminished by Rs 1. What was the original expenditure of the mess? Choose the correct choice from the following:
A) 320 B) 120 C) 400 D) 420 E) 514 | <gadget id="calculator">42 + 42</gadget>
<output>84</output>
<gadget id="calculator">42 - 35</gadget>
<output>7</output>
<gadget id="calculator">84 / 7</gadget>
<output>12</output>
<gadget id="calculator">12 * 35</gadget>
<output>420</output>
<gadget id="calculator">42 - 12</gadget>
<output>30</output>
<gadget id="calculator">30 - 12</gadget>
<output>18</output>
<gadget id="calculator">18 + 2</gadget>
<output>20</output>
<gadget id="calculator">420 - 20</gadget>
<output>400</output>
<result>D</result> | D | 420 | There were 35 students in a hostel. Due to the admission of 7 new students, ;he expenses of the mess were increased by Rs. 42 per day while the average expenditure per head diminished by Rs 1. What was the original expenditure of the mess? | {
"A": "320",
"B": "120",
"C": "400",
"D": "420",
"E": "514"
} | subtract(multiply(divide(add(42, 42), subtract(42, 35)), 35), add(subtract(subtract(42, divide(add(42, 42), subtract(42, 35))), divide(add(42, 42), subtract(42, 35))), const_2)) | add(n2,n2)|subtract(n2,n0)|divide(#0,#1)|multiply(n0,#2)|subtract(n2,#2)|subtract(#4,#2)|add(#5,const_2)|subtract(#3,#6)| | "sol . let the original average expenditure be rs . x . then , 42 ( x - 1 ) - 35 x = 42 7 x = 84 x = 12 . original expenditure = rs . ( 35 x 12 ) = rs . 420 . . answer d" | general |
math_qa__MY4EBbuFiuTLEY28 | If $100 invested at a certain rate of simple interest amounts to $140 at the end of 3 years,How much will $150 amount to at the same rate of interest in 6 years? Options.
A) $ 190 B) $ 180 C) $ 200 D) $ 240 E) $ 270 | <gadget id="calculator">150 * 6</gadget>
<output>900</output>
<gadget id="calculator">140 - 100</gadget>
<output>40</output>
<gadget id="calculator">40 * 100</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 100</gadget>
<output>40</output>
<gadget id="calculator">40 / 3</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">900 * (40/3)</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 100</gadget>
<output>120</output>
<gadget id="calculator">150 + 120</gadget>
<output>270</output>
<result>E</result> | E | 270 | If $100 invested at a certain rate of simple interest amounts to $140 at the end of 3 years,How much will $150 amount to at the same rate of interest in 6 years? | {
"A": "$ 190",
"B": "$ 180",
"C": "$ 200",
"D": "$ 240",
"E": "$ 270"
} | add(150, divide(multiply(multiply(150, 6), divide(divide(multiply(subtract(140, 100), const_100), 100), 3)), 100)) | multiply(n3,n4)|subtract(n1,n0)|multiply(#1,const_100)|divide(#2,n0)|divide(#3,n2)|multiply(#4,#0)|divide(#5,n0)|add(n3,#6) | 100 amounts to 140 in 3 years . i . e ( principal + interest ) on 120 in 3 years = 140 100 + 100 * ( r / 100 ) * ( 3 ) = 140 = > r = 40 / 3 150 in 6 years = principal + interest = 150 + 150 * ( r / 100 ) * ( 6 ) = 270 answer is e . | gain |
math_qa__H38DDH9wpCpFODHI | The owner of a furniture shop charges his customer 100% more than the cost price. If a customer paid Rs. 1000 for a computer table, then what was the cost price of the computer table? Answers
A) 800 B) 650 C) 500 D) 600 E) 250 | <gadget id="calculator">100 / 100</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">1_000 / 2</gadget>
<output>500</output>
<result>C</result> | C | 500 | The owner of a furniture shop charges his customer 100% more than the cost price. If a customer paid Rs. 1000 for a computer table, then what was the cost price of the computer table? | {
"A": "800",
"B": "650",
"C": "500",
"D": "600",
"E": "250"
} | divide(1000, add(const_1, divide(100, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "cp = sp * ( 100 / ( 100 + profit % ) ) = 1000 ( 100 / 200 ) = rs . 500 . answer : c" | gain |
math_qa__W4kDtcJggtm4hPbO | if a father said to his elder son , ` ` i was as old as you are at the present at the time of your birth ' ' . if the father ' s age is 25 years now , what was the son ' s age 4 years back ? Choose the correct answer: A) 7.5 B) 8.5 C) 9 D) 9.5 E) 10 | <gadget id="calculator">25 / 2</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) - 4</gadget>
<output>17/2 = around 8.5</output>
<result>B</result> | B | 8.5 | if a father said to his elder son , ` ` i was as old as you are at the present at the time of your birth ' ' . if the father ' s age is 25 years now , what was the son ' s age 4 years back ? | {
"A": "7.5",
"B": "8.5",
"C": "9",
"D": "9.5",
"E": "10"
} | subtract(divide(25, const_2), 4) | divide(n0,const_2)|subtract(#0,n1) | let son ' s present age be a years . then , ( 25 − a ) = a ⇒ 2 a = 25 ⇒ a = 25 / 2 = 12.5 son ' s age 4 years back = 12.5 - 4 = 8.5 answer : b | general |
math_qa__T0BqS3c6uFCRCX0L | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 13% microphotonics; 24% home electronics; 15% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? Answers
A) 8 ° B) 40 ° C) 18 ° D) 36 ° E) 52 ° | <gadget id="calculator">13 + 24</gadget>
<output>37</output>
<gadget id="calculator">37 + 15</gadget>
<output>52</output>
<gadget id="calculator">52 + 29</gadget>
<output>81</output>
<gadget id="calculator">81 + 8</gadget>
<output>89</output>
<gadget id="calculator">100 - 89</gadget>
<output>11</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">11 * 360</gadget>
<output>3_960</output>
<gadget id="calculator">3_960 / 100</gadget>
<output>198/5 = around 39.6</output>
<result>B</result> | B | 40 | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 13% microphotonics; 24% home electronics; 15% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? | {
"A": "8 °",
"B": "40 °",
"C": "18 °",
"D": "36 °",
"E": "52 °"
} | divide(multiply(subtract(const_100, add(add(add(add(13, 24), 15), 29), 8)), divide(const_3600, const_10)), const_100) | add(n0,n1)|divide(const_3600,const_10)|add(n2,#0)|add(n3,#2)|add(n4,#3)|subtract(const_100,#4)|multiply(#1,#5)|divide(#6,const_100)| | "here all percentage when summed we need to get 100 % . as per data 13 + 24 + 15 + 29 + 8 = 89 % . so remaining 11 % is the balance for the astrophysics . since this is a circle all percentage must be equal to 360 degrees . 100 % - - - - 360 degrees then 11 % will be 40 degrees . . imo option b ." | gain |
math_qa__kjmSvYTUJV5ayXFc | Jim’s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.25 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? Choose the correct choice from the following answers.
A) $ 3.15
B) $ 4.5
C) $ 4.80
D) $ 5.05
E) $ 5.40 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3.6 / (2/5)</gadget>
<output>9</output>
<gadget id="calculator">0.25 * 9</gadget>
<output>2.25</output>
<gadget id="calculator">2.25 + 2.25</gadget>
<output>4.5</output>
<result>B</result> | B | 4.5 | Jim’s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.25 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles? | {
"A": "$ 3.15",
"B": "$ 4.5",
"C": "$ 4.80",
"D": "$ 5.05",
"E": "$ 5.40"
} | add(2.25, multiply(0.25, divide(3.6, divide(2, 5)))) | divide(n2,n3)|divide(n4,#0)|multiply(n1,#1)|add(n0,#2)| | "let the fixed charge of jim ’ s taxi service = 2.25 $ and charge per 2 / 5 mile ( . 4 mile ) = . 25 $ total charge for a trip of 3.6 miles = 2.25 + ( 3.6 / . 4 ) * . 25 = 2.25 + 9 * . 25 = 4.5 $ answer b" | general |
math_qa__pDIVrTRbGGvh6W0C | Payal finished 2/3 of a book. She calculated that she finished 20 more pages than she has yet to read. How long is her book? Choose the correct choice from the following choices
A) 60
B) 150
C) 130
D) 90
E) 210 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 2</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">20 / (1/3)</gadget>
<output>60</output>
<result>A</result> | A | 60 | Payal finished 2/3 of a book. She calculated that she finished 20 more pages than she has yet to read. How long is her book? | {
"A": "60",
"B": "150",
"C": "130",
"D": "90",
"E": "210"
} | divide(20, divide(divide(2, 3), const_2)) | divide(n0,n1)|divide(#0,const_2)|divide(n2,#1) | let x be the total number of pages in the book , then she finished 2 / 3 * x pages . then she has x − 2 / 3 * x = 1 / 3 * x pages left . 2 / 3 * x − 1 / 3 * x = 20 1 / 3 * x = 20 x = 60 so the book is 270 pages long . answer is a . | general |
math_qa__EVRyH8MYgE05Nawg | The surface of a cube is 384sq cm. Find its volume?
Choose the correct choice from the following answers:
A) 8 cc B) 9 cc C) 512 cc D) 4 cc E) 6 cc | <gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">384 / 6</gadget>
<output>64</output>
<gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<gadget id="calculator">8 ** 3</gadget>
<output>512</output>
<result>C</result> | C | 512 | The surface of a cube is 384sq cm. Find its volume? | {
"A": "8 cc",
"B": "9 cc",
"C": "512 cc",
"D": "4 cc",
"E": "6 cc"
} | volume_cube(sqrt(divide(384, add(const_2, const_4)))) | add(const_2,const_4)|divide(n0,#0)|sqrt(#1)|volume_cube(#2)| | "6 a 2 = 384 = 6 * 64 a = 8 = > a 3 = 512 cc answer : c" | geometry |
math_qa__oLgyuT8GuaINVJus | The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 4 cm, the area of the rectangle is increased by 75 sq. cm. Find the length of the rectangle.
Choose the correct choice from the following choices
A) 20 cm B) 25 cm C) 26 cm D) 100 / 3 cm E) 23 cm | <gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<result>D</result> | D | 33.333333 | The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 4 cm, the area of the rectangle is increased by 75 sq. cm. Find the length of the rectangle. | {
"A": "20 cm",
"B": "25 cm",
"C": "26 cm",
"D": "100 / 3 cm",
"E": "23 cm"
} | divide(const_100, const_3) | divide(const_100,const_3) | explanation : let breadth = x . then , length = 2 x . then , ( 2 x - 5 ) ( x + 4 ) - 2 x * x = 75 = > 3 x - 25 = 75 = > x = 100 / 3 . length of the rectangle = 100 / 3 cm . answer : option d | geometry |
math_qa__EiUNBQZ7yAj56ajc | There is a 1 km long wire placed on some number of poles which are in equal distance. If the number of poles is reduced by 1 then the distance of wire between each poles
increases 1(2/3).How many poles are there initially.
Select
A) 24
B) 25
C) 26
D) 27
E) 28 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">(2/3) * 2</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) * 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 12</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 2</gadget>
<output>26</output>
<result>C</result> | C | 26 | There is a 1 km long wire placed on some number of poles which are in equal distance. If the number of poles is reduced by 1 then the distance of wire between each poles
increases 1(2/3).How many poles are there initially. | {
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "28"
} | add(divide(multiply(multiply(multiply(divide(2, 3), add(1, 1)), 3), const_12), 2), 2) | add(n0,n0)|divide(n3,n4)|multiply(#0,#1)|multiply(n4,#2)|multiply(#3,const_12)|divide(#4,n3)|add(n3,#5) | 26 answer : c | general |
math_qa__e7ZXgv2PIXdAUasN | By investing Rs. 1620 in 8% stock,Michael earns Rs. 135.The stock is then quoted at : Choose the correct option: A) rs . 80 B) rs . 96 C) rs . 106 D) rs . 108 E) rs . 118 | <gadget id="calculator">1_620 / 135</gadget>
<output>12</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">12 * (2/25)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">(24/25) * 100</gadget>
<output>96</output>
<result>B</result> | B | 96 | By investing Rs. 1620 in 8% stock,Michael earns Rs. 135.The stock is then quoted at : | {
"A": "rs . 80",
"B": "rs . 96",
"C": "rs . 106",
"D": "rs . 108",
"E": "rs . 118"
} | multiply(multiply(divide(1620, 135), divide(8, const_100)), const_100) | divide(n0,n2)|divide(n1,const_100)|multiply(#0,#1)|multiply(#2,const_100) | michel earns rs 135 by investing rs 1620 to earn rs 8 how much he have to invest ? = ( 8 * 1620 ) / 135 = rs 96 answer : b | gain |
math_qa__gWrDZZnWV1xHubq5 | The initial price of an article is Rs.2000 which increases 30% increse in its price in the first year,a 20% decrease in the second year and a 10% increase in the next year. What is the final price of the article ? Select the correct option:
A) rs . 1748 B) rs . 1948 C) rs . 1848 D) rs . 2048 E) rs . 2148 | <gadget id="calculator">2_000 * 20</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 / 100</gadget>
<output>400</output>
<gadget id="calculator">2_000 - 400</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 * 10</gadget>
<output>16_000</output>
<gadget id="calculator">16_000 / 100</gadget>
<output>160</output>
<gadget id="calculator">1_600 + 160</gadget>
<output>1_760</output>
<result>C</result> | C | 1,848 | The initial price of an article is Rs.2000 which increases 30% increse in its price in the first year,a 20% decrease in the second year and a 10% increase in the next year. What is the final price of the article ? | {
"A": "rs . 1748",
"B": "rs . 1948",
"C": "rs . 1848",
"D": "rs . 2048",
"E": "rs . 2148"
} | add(subtract(2000, divide(multiply(2000, 20), const_100)), divide(multiply(subtract(2000, divide(multiply(2000, 20), const_100)), 10), const_100)) | multiply(n0,n2)|divide(#0,const_100)|subtract(n0,#1)|multiply(n3,#2)|divide(#3,const_100)|add(#4,#2) | the initial price of the article , four years age is rs . 2000 in the 1 st year , price of the article = 2000 + 600 = rs . 2600 . in the 2 nd year , price = 2600 - 20 % of 2600 = 2200 - 520 = rs . 1680 . in the 3 rd year , price = 1680 + 10 % of 1680 = 1680 + 168 = rs . 1848 . required price = rs . 1848 answer : c | general |
math_qa__YSMi6RsV7HlK6EZI | At what rate percent on simple interest will Rs.750 amount to Rs.900 in 16 years? Choose the most appropriate option: A) 6.25 % B) 1.25 % C) 4 % D) 5 % E) 3.25 % | <gadget id="calculator">900 - 750</gadget>
<output>150</output>
<gadget id="calculator">150 / 750</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) / 16</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">(1/80) * 100</gadget>
<output>5/4 = around 1.25</output>
<result>B</result> | B | 1.25 | At what rate percent on simple interest will Rs.750 amount to Rs.900 in 16 years? | {
"A": "6.25 %",
"B": "1.25 %",
"C": "4 %",
"D": "5 %",
"E": "3.25 %"
} | multiply(divide(divide(subtract(900, 750), 750), 16), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "150 = ( 750 * 16 * r ) / 100 r = 1.25 % answer : b" | gain |
math_qa__PryWE2Zp1ugmJL4K | If there are only 2 wheelers and 4 wheelers parked in a school located at the heart of the city, find the number of 4 wheelers parked there if the total number of wheels is 58? Choose one
A) 11 B) 12 C) 13 D) 14 E) 15 | <gadget id="calculator">58 - 2</gadget>
<output>56</output>
<gadget id="calculator">56 / 4</gadget>
<output>14</output>
<result>D</result> | D | 14 | If there are only 2 wheelers and 4 wheelers parked in a school located at the heart of the city, find the number of 4 wheelers parked there if the total number of wheels is 58? | {
"A": "11",
"B": "12",
"C": "13",
"D": "14",
"E": "15"
} | divide(subtract(58, 2), 4) | subtract(n3,n0)|divide(#0,n1)| | "four wheeler = 14 * 4 = 56 ( max ) 2 wheel = 1 so no of 4 wheeler = 14 answer : d" | general |
math_qa__S1zRBJfuWSiGIANa | If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land Tails up exactly once in 3 consecutive flips ? Pick one: A) 0.125 B) 0.375 C) 0.325 D) 0.5 E) 0.666 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 3</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3</gadget>
<output>3/8 = around 0.375</output>
<result>B</result> | B | 0.375 | If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land Tails up exactly once in 3 consecutive flips ? | {
"A": "0.125",
"B": "0.375",
"C": "0.325",
"D": "0.5",
"E": "0.666"
} | multiply(power(divide(const_1, const_2), const_3), 3) | divide(const_1,const_2)|power(#0,const_3)|multiply(n0,#1) | total number of ways in which h or t can appear in 3 tosses of coin is = 2 * 2 * 2 = 8 ways for 2 t and 1 th thus probability is = p ( htt ) + p ( tth ) + p ( tht ) = 1 / 8 + 1 / 8 + 1 / 8 = 3 / 8 = . 375 answer : b | probability |
math_qa__ee97TNQEiK8opwnh | if the ratio of two number is 5:7 and LCM of the number is 320 then what is the number. Choose the correct choice:
A) 15 B) 9 C) 10 D) 11 E) 35 | <gadget id="calculator">5 * 7</gadget>
<output>35</output>
<gadget id="calculator">320 / 35</gadget>
<output>64/7 = around 9.142857</output>
<result>B</result> | B | 9 | if the ratio of two number is 5:7 and LCM of the number is 320 then what is the number. | {
"A": "15",
"B": "9",
"C": "10",
"D": "11",
"E": "35"
} | divide(320, multiply(5, 7)) | multiply(n0,n1)|divide(n2,#0)| | "product of two no = lcm * hcf 5 x * 7 x = 320 * x x = 9 answer : b" | other |
math_qa__faIQOWw90Dc2wP38 | Find the principle on a certain sum of money at 5% per annum for 3 1/5 years if the amount being Rs.2030? Select
A) rs . 2000 B) rs . 1750 C) rs . 2010 D) rs . 2005 E) none of these | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 5</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">(18/5) * 5</gadget>
<output>18</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) + 1</gadget>
<output>59/50 = around 1.18</output>
<gadget id="calculator">2_030 / (59/50)</gadget>
<output>101_500/59 = around 1_720.338983</output>
<result>B</result> | B | 1,750 | Find the principle on a certain sum of money at 5% per annum for 3 1/5 years if the amount being Rs.2030? | {
"A": "rs . 2000",
"B": "rs . 1750",
"C": "rs . 2010",
"D": "rs . 2005",
"E": "none of these"
} | divide(2030, add(divide(multiply(divide(add(multiply(3, 5), 3), 5), 5), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "explanation : 2030 = p [ 1 + ( 5 * 16 / 5 ) / 100 ] p = 1750 answer : option b" | general |
math_qa__43djQcYDj07dbypj | Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 7000 envelopes. Choose the correct choice from the following answers:
A) 2
B) 3
C) 4
D) 5
E) 60 / 7 | <gadget id="calculator">6_000 / 2.5</gadget>
<output>2_400</output>
<gadget id="calculator">3_000 / 1</gadget>
<output>3_000</output>
<gadget id="calculator">6_000 / 3</gadget>
<output>2_000</output>
<gadget id="calculator">3_000 - 2_000</gadget>
<output>1_000</output>
<gadget id="calculator">2_400 - 1_000</gadget>
<output>1_400</output>
<gadget id="calculator">7_000 / 1_400</gadget>
<output>5</output>
<result>D</result> | D | 5 | Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 7000 envelopes. | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "60 / 7"
} | divide(7000, subtract(divide(6000, 2.5), subtract(divide(3000, 1), divide(6000, 3)))) | divide(n0,n2)|divide(n3,n4)|divide(n0,n1)|subtract(#1,#2)|subtract(#0,#3)|divide(n5,#4)| | "you can either take the amount of work done as the same as karishma has done or take the work done by each in the same time . i will do the latter 1 . work done in 1 hr by a is 2000 envelopes 2 . work done in 1 hr by a and c is 3000 envelopes 3 . so work done in 1 hr by c is 1000 envelopes 4 . work done in 1 hr by b and c is 2400 envelopes 5 . so work done in 1 hr by b is 1400 envelopes 6 . so to process 7000 envelopes b will take 7000 / 1400 hrs = 5 hrs so the answer is choice d" | physics |
math_qa__6gP3KDt1nRzzFnMw | ABCD IS A square AEGF IS A rectangle..such that the rectangle shares 25% of the area of the suare ALSO AE lies ON THE LINE AB and AG lies on segment of AD.if the square shares half the area of the rectangle what is the ratio AE:AG? Select the correct option: A) 1 : 4 B) 8 : 1 C) 4 : 1 D) 3 : 1 E) 1 : 3 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / (1/4)</gadget>
<output>4</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4 / (1/2)</gadget>
<output>8</output>
<result>B</result> | B | 8 | ABCD IS A square AEGF IS A rectangle..such that the rectangle shares 25% of the area of the suare ALSO AE lies ON THE LINE AB and AG lies on segment of AD.if the square shares half the area of the rectangle what is the ratio AE:AG? | {
"A": "1 : 4",
"B": "8 : 1",
"C": "4 : 1",
"D": "3 : 1",
"E": "1 : 3"
} | divide(divide(const_1, divide(25, const_100)), divide(const_1, const_2)) | divide(n0,const_100)|divide(const_1,const_2)|divide(const_1,#0)|divide(#2,#1) | a - - - - - - - - - - - - b - - - - - - - - e | | 50 % | g - - - - - - - - - - - - | - - - - - - - - f | | | 75 % | d - - - - - - - - - - - c remaining square 75 % and remaining rectangle 50 % rectangle share 25 % area of square so , ab x ag = ( ad x ab ) / 4 ad = 4 ag - - - - - - - - - - - - - - - - - - ( 1 ) square share half the area of rectangle so , ag x ab = ( ae x ag ) / 2 ab = ae / 2 - - - - - - - - - - - - - - - - - - ( 2 ) in square all sides are equal i . e . ab = bc = cd = ad so , equation ( 1 ) and ( 2 ) both are equal ae / 2 = 4 ag ae / ag = 8 ae : ag = 8 : 1 answer : b | geometry |
math_qa__Tl0IrqoloYbiqDRK | 2 cow’s and 10 goats are brought for Rs.1500. If the average price of a goat be Rs.70. What is the average price of a cow.
Choose the correct choice.
A) 420 B) 400 C) 430 D) 410 E) 450 | <gadget id="calculator">10 * 70</gadget>
<output>700</output>
<gadget id="calculator">1_500 - 700</gadget>
<output>800</output>
<gadget id="calculator">800 / 2</gadget>
<output>400</output>
<result>B</result> | B | 400 | 2 cow’s and 10 goats are brought for Rs.1500. If the average price of a goat be Rs.70. What is the average price of a cow. | {
"A": "420",
"B": "400",
"C": "430",
"D": "410",
"E": "450"
} | divide(subtract(1500, multiply(10, 70)), 2) | multiply(n1,n3)|subtract(n2,#0)|divide(#1,n0)| | "explanation : average price of a goat = rs . 70 total price of 8 goats = 10 * 70 = rs . 700 but total price of 2 cows and 8 goats = rs . 1500 total price of 2 cows is = 1500 - 700 = 800 average price of a cow = 800 / 2 = rs . 400 answer : b" | general |
math_qa__9llD1gQWFcPbuCjg | If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value F of z - x? Choose one: A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>D</result> | D | 9 | If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value F of z - x? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | add(add(5, const_2), const_2) | add(n0,const_2)|add(#0,const_2)| | "x < y < z to find the least possible value for z - x ; we need to find the values for z and x that can be closest to each other . if x is some even number , then what could be minimum possible odd z . if x is some even number y - x > 5 ; y > x + 5 ; minimum value for y = x + 5 + 2 = x + 7 [ note : x + 5 is as even + odd = odd and nearest odd greater than x + 5 is x + 5 + 2 ] minimum value for z = y + 2 = x + 7 + 2 = x + 9 [ note : z = y + 2 because both z and y are odd . difference between two odd numbers is 2 ] f = z - x = x + 9 - x = 9 ans : d" | general |
math_qa__DHDcVzvPoCgdhiMD | In the set of positive integers from 1 to 60, what is the sum of all the odd multiples of 5? Pick one.
A) 180 B) 185 C) 190 D) 160 E) 165 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">60 * 15</gadget>
<output>900</output>
<gadget id="calculator">900 / 5</gadget>
<output>180</output>
<result>A</result> | A | 180 | In the set of positive integers from 1 to 60, what is the sum of all the odd multiples of 5? | {
"A": "180",
"B": "185",
"C": "190",
"D": "160",
"E": "165"
} | divide(multiply(60, multiply(const_3, 5)), 5) | multiply(n2,const_3)|multiply(n1,#0)|divide(#1,n2) | 1 - 60 5 - 15 - 25 - 35 - 45 are valid multiples of 5 . add them 5 + 15 + 25 + 35 + 45 + 55 = 180 a | general |
math_qa__JsgXAuVInAe2zJN0 | A train is 360 meter long is running at a speed of 54 km/hour. In what time will it pass a bridge of 140 meter length?
Choose the most appropriate option
A) 65 seconds B) 33.33 seconds C) 40 seconds D) 97 seconds E) 26 seconds | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 3_600</gadget>
<output>15</output>
<gadget id="calculator">500 / 15</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 33.33 | A train is 360 meter long is running at a speed of 54 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "65 seconds",
"B": "33.33 seconds",
"C": "40 seconds",
"D": "97 seconds",
"E": "26 seconds"
} | divide(add(360, 140), divide(multiply(54, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 54 km / hr = 54 * ( 5 / 18 ) m / sec = 15 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 * ( 1 / 15 ) = 33.33 seconds answer : b" | physics |
math_qa__K8TEbYzRu58RVTjt | The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 15000, then find the annual income of A? Pick: A) 187888 B) 276889 C) 267777 D) 504000 E) 297112 | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 + (3/25)</gadget>
<output>28/25 = around 1.12</output>
<gadget id="calculator">15_000 * (28/25)</gadget>
<output>16_800</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">16_800 * (5/2)</gadget>
<output>42_000</output>
<gadget id="calculator">42_000 * 12</gadget>
<output>504_000</output>
<result>D</result> | D | 504,000 | The monthly incomes of A and B are in the ratio 5 : 2. B's monthly income is 12% more than C's monthly income. If C's monthly income is Rs. 15000, then find the annual income of A? | {
"A": "187888",
"B": "276889",
"C": "267777",
"D": "504000",
"E": "297112"
} | multiply(multiply(multiply(15000, add(const_1, divide(12, const_100))), divide(5, 2)), 12) | divide(n0,n1)|divide(n2,const_100)|add(#1,const_1)|multiply(n3,#2)|multiply(#0,#3)|multiply(n2,#4)| | "b ' s monthly income = 15000 * 112 / 100 = rs . 16800 b ' s monthly income = 2 parts - - - - > rs . 16800 a ' s monthly income = 5 parts = 5 / 2 * 16800 = rs . 42000 a ' s annual income = rs . 42000 * 12 = rs . 504000 answer : d" | other |
math_qa__g8ON1W62x7C4mXGb | If an article is sold at 18% profit instead of 9% profit, then the profit would be $72 more. What is the cost price?
Answers: A) $ 500 B) $ 600 C) $ 700 D) $ 800 E) $ 900 | <gadget id="calculator">72 / 9</gadget>
<output>8</output>
<gadget id="calculator">8 * 100</gadget>
<output>800</output>
<result>D</result> | D | 800 | If an article is sold at 18% profit instead of 9% profit, then the profit would be $72 more. What is the cost price? | {
"A": "$ 500",
"B": "$ 600",
"C": "$ 700",
"D": "$ 800",
"E": "$ 900"
} | multiply(divide(72, 9), const_100) | divide(n2,n1)|multiply(#0,const_100)| | "9 % * cost price = $ 72 1 % * cost price = $ 72 / 9 = $ 8 the cost price is $ 800 . the answer is d ." | gain |
math_qa__DZ6qlQ3gXWbPjC3T | A train 1500 m long can cross an electric pole in 50 sec and then find the speed of the train? Choose the correct option: A) 106 B) 107 C) 108 D) 109 E) 110 | <gadget id="calculator">1_500 / 1_000</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">50 / 3_600</gadget>
<output>1/72 = around 0.013889</output>
<gadget id="calculator">(3/2) / (1/72)</gadget>
<output>108</output>
<result>C</result> | C | 108 | A train 1500 m long can cross an electric pole in 50 sec and then find the speed of the train? | {
"A": "106",
"B": "107",
"C": "108",
"D": "109",
"E": "110"
} | divide(divide(1500, const_1000), divide(50, const_3600)) | divide(n0,const_1000)|divide(n1,const_3600)|divide(#0,#1)| | "length = speed * time speed = l / t s = 1500 / 50 s = 30 m / sec speed = 30 * 18 / 5 ( to convert m / sec in to kmph multiply by 18 / 5 ) speed = 108 kmph answer : c" | physics |
math_qa__i4hYCMHbKEs5oy62 | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 35% of all the employees are men .What % of all the employee went to the picnic? Select: A) 33 % B) 34 % C) 35 % D) 36 % E) 37 % | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(7/20) * (1/5)</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">65 / 100</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(13/20) * (2/5)</gadget>
<output>13/50 = around 0.26</output>
<gadget id="calculator">(7/100) + (13/50)</gadget>
<output>33/100 = around 0.33</output>
<gadget id="calculator">(33/100) * 100</gadget>
<output>33</output>
<result>A</result> | A | 33 | In a certain company 20% of the men and 40% of the women attended the annual company picnic.If 35% of all the employees are men .What % of all the employee went to the picnic? | {
"A": "33 %",
"B": "34 %",
"C": "35 %",
"D": "36 %",
"E": "37 %"
} | multiply(add(multiply(divide(35, const_100), divide(20, const_100)), multiply(divide(subtract(const_100, 35), const_100), divide(40, const_100))), const_100) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(const_100,n2)|divide(#3,const_100)|multiply(#0,#1)|multiply(#4,#2)|add(#5,#6)|multiply(#7,const_100) | total men in company 35 % means total women in company 65 % ( assume total people in company 100 % ) no of men emplyess attended picnic = 35 x ( 20 / 100 ) = 7 no of women empolyees attened picnin = 65 x ( 40 / 100 ) = 26 total percentage of empolyess attened the picnic = 7 + 26 = 33 % answer : a | gain |
math_qa__K8xDqlQJA6vI1ikw | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 60 sq. feet, how many feet of fencing will be required? Choose the correct choice from the following choices.
A) 34 B) 40 C) 68 D) 88 E) 26 | <gadget id="calculator">60 / 20</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 20</gadget>
<output>26</output>
<result>E</result> | E | 26 | A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 60 sq. feet, how many feet of fencing will be required? | {
"A": "34",
"B": "40",
"C": "68",
"D": "88",
"E": "26"
} | add(multiply(divide(60, 20), const_2), 20) | divide(n1,n0)|multiply(#0,const_2)|add(n0,#1)| | "we have : l = 20 ft and lb = 60 sq . ft . so , b = 3 ft . length of fencing = ( l + 2 b ) = ( 20 + 6 ) ft = 26 ft . answer : e" | geometry |
math_qa__XHgaykLC0OGAdZwT | If an integer w is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that w(w + 1)(w + 2) will be divisible by 8? Choose the most appropriate option.
A) 1 / 4
B) 3 / 8
C) 1 / 2
D) 5 / 8
E) 3 / 4 | <gadget id="calculator">96 / 8</gadget>
<output>12</output>
<gadget id="calculator">96 / 2</gadget>
<output>48</output>
<gadget id="calculator">12 + 48</gadget>
<output>60</output>
<gadget id="calculator">60 / 96</gadget>
<output>5/8 = around 0.625</output>
<result>D</result> | D | 0.625 | If an integer w is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that w(w + 1)(w + 2) will be divisible by 8? | {
"A": "1 / 4",
"B": "3 / 8",
"C": "1 / 2",
"D": "5 / 8",
"E": "3 / 4"
} | divide(add(divide(96, 8), divide(96, 2)), 96) | divide(n1,n4)|divide(n1,n3)|add(#0,#1)|divide(#2,n1) | for w total numbers 8 * 12 there are 12 numbers divisible by 8 - > 3 * 12 ( if 8 is an example - ( 6 , 78 ) , ( 7 , 89 ) , ( 8 , 910 ) ) and 12 numbers divisible by 4 but not divisible by 8 - > 2 * 12 ( if 4 is an example ( 2 , 34 ) and ( 4 , 56 ) ) the answer 5 / 8 - > d | general |
math_qa__doknH6DnUOqEAJOs | Tickets numbered from 1 to 24 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3?
Choose one
A) 1 / 3 B) 2 / 5 C) 3 / 10 D) 3 / 7 E) 1 / 7 | <gadget id="calculator">24 / 3</gadget>
<output>8</output>
<gadget id="calculator">8 / 24</gadget>
<output>1/3 = around 0.333333</output>
<result>A</result> | A | 0.333333 | Tickets numbered from 1 to 24 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3? | {
"A": "1 / 3",
"B": "2 / 5",
"C": "3 / 10",
"D": "3 / 7",
"E": "1 / 7"
} | divide(divide(24, 3), 24) | divide(n1,n2)|divide(#0,n1) | here , s = [ 1 , 2 , 3 , 4 , … . , 19 , 20 , 21 , 22 , 23 , 24 ] let e = event of getting a multiple of 3 = [ 3 , 6 , 9 , 12 , 15 , 18 , 21 , 24 ] p ( e ) = n ( e ) / n ( s ) = 8 / 24 = 1 / 3 the answer is a . | general |
math_qa__VKhQreKOgkvCu0V7 | A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 14 adults have their meal, find the total number of children that can be catered with the remaining food.
Answers.
A) 33 B) 54 C) 18 D) 17 E) 72 | <gadget id="calculator">70 - 14</gadget>
<output>56</output>
<gadget id="calculator">90 / 70</gadget>
<output>9/7 = around 1.285714</output>
<gadget id="calculator">56 * (9/7)</gadget>
<output>72</output>
<result>E</result> | E | 72 | A group of 55 adults and 70 children go for trekking. If there is meal for either 70 adults or 90 children and if 14 adults have their meal, find the total number of children that can be catered with the remaining food. | {
"A": "33",
"B": "54",
"C": "18",
"D": "17",
"E": "72"
} | multiply(subtract(70, 14), divide(90, 70)) | divide(n3,n1)|subtract(n1,n4)|multiply(#0,#1)| | "explanation : as there is meal for 70 adults and 14 have their meal , the meal left can be catered to 56 adults . now , 70 adults = 90 children 7 adults = 9 children therefore , 56 adults = 72 children hence , the meal can be catered to 72 children . answer : e" | general |
math_qa__2SKkasTk8np94Muh | Robert's salary was decreased by 60% and subsequently increased by 60%. how much percentage does he lose? Options:
A) 10 % B) 20 % C) 25 % D) 36 % E) 50 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">40 * 160</gadget>
<output>6_400</output>
<gadget id="calculator">10_000 - 6_400</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 10_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 100</gadget>
<output>36</output>
<result>D</result> | D | 36 | Robert's salary was decreased by 60% and subsequently increased by 60%. how much percentage does he lose? | {
"A": "10 %",
"B": "20 %",
"C": "25 %",
"D": "36 %",
"E": "50 %"
} | multiply(divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 60), add(const_100, 60))), multiply(const_100, const_100)), const_100) | add(n0,const_100)|multiply(const_100,const_100)|subtract(const_100,n0)|multiply(#0,#2)|subtract(#1,#3)|divide(#4,#1)|multiply(#5,const_100) | let original salary be $ 100 salary after decreasing 60 % = 100 - 100 x 60 / 100 = $ 40 salary after increasing 60 % on $ 40 = 40 + 40 x 60 / 100 = $ 64 percentage of loss = 100 - 64 = 36 % answer : d | general |
math_qa__IzUXSqeAU9AZlp8t | A candidate got 34% of the votes polled and he lost to his rival by 640 votes. How many votes were cast? Choices: A) 2000 B) 2400 C) 2800 D) 3200 E) 3600 | <gadget id="calculator">34 / 100</gadget>
<output>17/50 = around 0.34</output>
<gadget id="calculator">1 - (17/50)</gadget>
<output>33/50 = around 0.66</output>
<gadget id="calculator">(33/50) - (17/50)</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">640 / (8/25)</gadget>
<output>2_000</output>
<result>A</result> | A | 2,000 | A candidate got 34% of the votes polled and he lost to his rival by 640 votes. How many votes were cast? | {
"A": "2000",
"B": "2400",
"C": "2800",
"D": "3200",
"E": "3600"
} | divide(640, subtract(subtract(const_1, divide(34, const_100)), divide(34, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "let x be the total number of votes . 0.34 x + 640 = 0.66 x 0.32 x = 640 x = 640 / 0.32 = 2000 the answer is a ." | gain |
math_qa__Si0wrJaarIAHUeov | If x ¤ y = (x + y)^2 - (x - y)^2. Then √11 ¤ √11 = Choices:
A) 44 B) 5 C) 10 D) 15 E) 20 | <gadget id="calculator">11 ** (1/2)</gadget>
<output>sqrt(11) = around 3.316625</output>
<gadget id="calculator">(sqrt(11)) + (sqrt(11))</gadget>
<output>2*sqrt(11) = around 6.63325</output>
<gadget id="calculator">(2*sqrt(11)) ** 2</gadget>
<output>44</output>
<result>A</result> | A | 44 | If x ¤ y = (x + y)^2 - (x - y)^2. Then √11 ¤ √11 = | {
"A": "44",
"B": "5",
"C": "10",
"D": "15",
"E": "20"
} | power(add(sqrt(11), sqrt(11)), const_2) | sqrt(n2)|add(#0,#0)|power(#1,const_2) | x = √ 11 and y also = √ 11 applying the function ( √ 11 + √ 11 ) ^ 2 - ( √ 11 - √ 11 ) ^ 2 = ( 2 √ 11 ) ^ 2 - 0 = 4 x 11 = 44 . note : alternative approach is the entire function is represented as x ^ 2 - y ^ 2 = ( x + y ) ( x - y ) which can be simplified as ( x + y + x - y ) ( x + y - ( x - y ) ) = ( 2 x ) ( 2 y ) = 4 xy . substituting x = √ 11 and y = √ 11 you get the answer 44 . answer a | general |
math_qa__76RjIGLouNrs3Hrc | Of the people who responded to a market survey, 200 preferred Brand X and the rest preferred Brand Y. If the respondents indicated a preference for Brand X over Brand Y by ratio of 4 to 1, how many people responded to the survey?
Select.
A) 80 B) 160 C) 250 D) 350 E) 480 | <gadget id="calculator">200 / 4</gadget>
<output>50</output>
<gadget id="calculator">50 + 200</gadget>
<output>250</output>
<result>C</result> | C | 250 | Of the people who responded to a market survey, 200 preferred Brand X and the rest preferred Brand Y. If the respondents indicated a preference for Brand X over Brand Y by ratio of 4 to 1, how many people responded to the survey? | {
"A": "80",
"B": "160",
"C": "250",
"D": "350",
"E": "480"
} | add(divide(200, 4), 200) | divide(n0,n1)|add(n0,#0)| | "ratio = 4 : 1 = > 4 x respondents preferred brand x and x preferred brand y since , no . of respondents who preferred brand x = 200 = > 4 x = 200 = > x = 50 hence total no . of respondents = 200 + 50 = 250 hence c is the answer ." | other |
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