id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__eomDGl6MCSDfrGMq | The standard deviation of a normal distribution of data is 2, and 3 standard deviations below the mean is greater than 44. What is a possible value for the mean of the distribution?
Choose the correct choice from the following answers:
A) 46
B) 47
C) 48
D) 49
E) 51 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">44 + 6</gadget>
<output>50</output>
<gadget id="calculator">50 + 1</gadget>
<output>51</output>
<result>E</result> | E | 51 | The standard deviation of a normal distribution of data is 2, and 3 standard deviations below the mean is greater than 44. What is a possible value for the mean of the distribution? | {
"A": "46",
"B": "47",
"C": "48",
"D": "49",
"E": "51"
} | add(add(44, multiply(3, 2)), const_1) | multiply(n0,n1)|add(n2,#0)|add(#1,const_1)| | "the standard deviation ( { sd } ) = 2 ; 3 standard deviations below the mean is greater than 44 : { mean } - 3 * { sd } > 44 ; { mean } - 6 > 44 ; { mean } > 50 . answer : e ." | general |
math_qa__NziAdYV6O1hpkxwj | the set x = { 78 , 910 } . the set y = { 23 , 45 } . we will randomly choose one element x from set x and one element y from set y . what is the probability that x / y will be an integer ? Select
A) 7 / 16 B) 5 / 16 C) 3 / 16 D) 7 / 8 E) 5 / 8 | <gadget id="calculator">78 / 23</gadget>
<output>78/23 = around 3.391304</output>
<gadget id="calculator">floor(78/23)</gadget>
<output>3</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">910 / 45</gadget>
<output>182/9 = around 20.222222</output>
<gadget id="calculator">floor(182/9)</gadget>
<output>20</output>
<gadget id="calculator">20 - 3</gadget>
<output>17</output>
<gadget id="calculator">17 - 1</gadget>
<output>16</output>
<gadget id="calculator">5 / 16</gadget>
<output>5/16 = around 0.3125</output>
<result>B</result> | B | 0.3125 | the set x = { 78 , 910 } . the set y = { 23 , 45 } . we will randomly choose one element x from set x and one element y from set y . what is the probability that x / y will be an integer ? | {
"A": "7 / 16",
"B": "5 / 16",
"C": "3 / 16",
"D": "7 / 8",
"E": "5 / 8"
} | divide(add(floor(divide(78, 23)), const_2), subtract(subtract(floor(divide(910, 45)), floor(divide(78, 23))), const_1)) | divide(n0,n2)|divide(n1,n3)|floor(#0)|floor(#1)|add(#2,const_2)|subtract(#3,#2)|subtract(#5,const_1)|divide(#4,#6) | the total number of x and y pairs is 4 * 4 = 16 . there are five pairs such that x / y is an integer . the probability that x / y is an integer is 5 / 16 . the answer is b . | general |
math_qa__wycAG9UaIp9ShRJd | Two vessels contains equal number of mixtures milk and water in the ratio 4:2 and 5:1. Both the mixtures are now mixed thoroughly. Find the ratio of milk to water in the new mixture so obtained? Choose the correct choice from the following answers:
A) 3 : 1 B) 9 : 13 C) 5 : 11 D) 11 : 3 E) 15 : 4 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 / 6</gadget>
<output>1</output>
<gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">2 * 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">9 / 3</gadget>
<output>3</output>
<result>A</result> | A | 3 | Two vessels contains equal number of mixtures milk and water in the ratio 4:2 and 5:1. Both the mixtures are now mixed thoroughly. Find the ratio of milk to water in the new mixture so obtained? | {
"A": "3 : 1",
"B": "9 : 13",
"C": "5 : 11",
"D": "11 : 3",
"E": "15 : 4"
} | divide(add(multiply(4, divide(add(5, 1), add(4, 2))), 5), add(multiply(2, divide(add(5, 1), add(4, 2))), 1)) | add(n2,n3)|add(n0,n1)|divide(#0,#1)|multiply(n0,#2)|multiply(n1,#2)|add(n2,#3)|add(n3,#4)|divide(#5,#6)| | "the ratio of milk and water in the new vessel is = ( 4 / 6 + 5 / 6 ) : ( 2 / 6 + 1 / 6 ) = 9 / 6 : 3 / 6 = 3 : 1 answer is a" | other |
math_qa__xbnanpKmpPfEAuKz | In what time will a train 90 m long cross an electric pole, it its speed be 72 km/hr? Pick:
A) 1.5
B) 2.5
C) 3.5
D) 4.5
E) 5.5 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">90 / 20</gadget>
<output>9/2 = around 4.5</output>
<result>D</result> | D | 4.5 | In what time will a train 90 m long cross an electric pole, it its speed be 72 km/hr? | {
"A": "1.5",
"B": "2.5",
"C": "3.5",
"D": "4.5",
"E": "5.5"
} | divide(90, multiply(72, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 72 * 5 / 18 = 20 m / sec time taken = 90 / 20 = 4.5 sec . answer : d" | physics |
math_qa__2hJpsu0Lc5Obgd1m | A can give B 200 meters start and C 400 meters start in a kilometer race. How much start can B give C in a kilometer race? Pick
A) 111.12 B) 250 C) 111.64 D) 111.11 E) 101.12 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 400</gadget>
<output>600</output>
<gadget id="calculator">1_000 * 600</gadget>
<output>600_000</output>
<gadget id="calculator">1_000 - 200</gadget>
<output>800</output>
<gadget id="calculator">600_000 / 800</gadget>
<output>750</output>
<gadget id="calculator">1_000 - 750</gadget>
<output>250</output>
<result>B</result> | B | 250 | A can give B 200 meters start and C 400 meters start in a kilometer race. How much start can B give C in a kilometer race? | {
"A": "111.12",
"B": "250",
"C": "111.64",
"D": "111.11",
"E": "101.12"
} | subtract(multiply(const_100, const_10), divide(multiply(multiply(const_100, const_10), subtract(multiply(const_100, const_10), 400)), subtract(multiply(const_100, const_10), 200))) | multiply(const_10,const_100)|subtract(#0,n1)|subtract(#0,n0)|multiply(#0,#1)|divide(#3,#2)|subtract(#0,#4)| | "a runs 1000 m while b runs 800 m and c runs 600 m . the number of meters that c runs when b runs 1000 m , = ( 1000 * 600 ) / 800 = 750 m . b can give c = 1000 - 750 = 250 m . answer : b" | physics |
math_qa__XtZgntUicensZgGb | A reduction of 40% in the price of bananas would enable a man to obtain 65 more for Rs.40, what is reduced price per dozen? Select the correct option: A) 1.95 B) 2.95 C) 4.95 D) 3.95 E) 5.95 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">40 * (2/5)</gadget>
<output>16</output>
<gadget id="calculator">16 / 65</gadget>
<output>16/65 = around 0.246154</output>
<gadget id="calculator">12 * (16/65)</gadget>
<output>192/65 = around 2.953846</output>
<result>B</result> | B | 2.95 | A reduction of 40% in the price of bananas would enable a man to obtain 65 more for Rs.40, what is reduced price per dozen? | {
"A": "1.95",
"B": "2.95",
"C": "4.95",
"D": "3.95",
"E": "5.95"
} | multiply(const_12, divide(multiply(40, divide(40, const_100)), 65)) | divide(n0,const_100)|multiply(n0,#0)|divide(#1,n1)|multiply(#2,const_12)| | "40 * ( 40 / 100 ) = 16 - - - 65 ? - - - 12 = > rs . 2.95 answer : b" | gain |
math_qa__UrNDCZruEna8ACVk | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 115 units raises the average to 55 units per day, what is the value of n? Select:
A) 8 B) 10 C) 12 D) 14 E) 16 | <gadget id="calculator">115 - 50</gadget>
<output>65</output>
<gadget id="calculator">55 - 50</gadget>
<output>5</output>
<gadget id="calculator">65 / 5</gadget>
<output>13</output>
<gadget id="calculator">13 - 1</gadget>
<output>12</output>
<result>C</result> | C | 12 | For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 115 units raises the average to 55 units per day, what is the value of n? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "16"
} | subtract(divide(subtract(115, 50), subtract(55, 50)), const_1) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,#1)|subtract(#2,const_1) | the daily production was raised by 5 units for n days , which has a weighting of 5 n . 5 n = 115 - 55 = 60 n = 12 the answer is c . | general |
math_qa__I9kX8X32T21OLIwv | Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 41 kmph. For how many minutes does the bus stop per hour? Choices: A) 7 min B) 8 min C) 14.4 min D) 10 min E) 11 min | <gadget id="calculator">54 - 41</gadget>
<output>13</output>
<gadget id="calculator">13 / 54</gadget>
<output>13/54 = around 0.240741</output>
<gadget id="calculator">60 * (13/54)</gadget>
<output>130/9 = around 14.444444</output>
<result>C</result> | C | 14.4 | Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 41 kmph. For how many minutes does the bus stop per hour? | {
"A": "7 min",
"B": "8 min",
"C": "14.4 min",
"D": "10 min",
"E": "11 min"
} | multiply(const_60, divide(subtract(54, 41), 54)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60) | due to stoppages , it covers 13 km less . time taken to cover 13 km = ( 13 / 54 ) x 60 = 14.4 min answer : c | physics |
math_qa__cZhDlGi3BLDdFbLL | a train length 100 m going with speed 10m/sec another train 150m long going with speed 15m/sec.the distance between two train is 50m.then how much time second train will take to cross the first train? Options
A) 60 sec B) 40 sec C) 30 sec D) 45 sec E) 1 min 10 sec | <gadget id="calculator">100 + 150</gadget>
<output>250</output>
<gadget id="calculator">250 + 50</gadget>
<output>300</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">300 / 5</gadget>
<output>60</output>
<result>A</result> | A | 60 | a train length 100 m going with speed 10m/sec another train 150m long going with speed 15m/sec.the distance between two train is 50m.then how much time second train will take to cross the first train? | {
"A": "60 sec",
"B": "40 sec",
"C": "30 sec",
"D": "45 sec",
"E": "1 min 10 sec"
} | divide(add(add(100, 150), 50), subtract(15, 10)) | add(n0,n2)|subtract(n3,n1)|add(n4,#0)|divide(#2,#1) | net speed = 15 - 10 = 5 m / sec net distance = 100 + 150 + 50 = 300 total time = 300 / 5 = 60 sec answer a | physics |
math_qa__ZXPQIEXdWlRCdQhs | One copy machine can make 15 copies a minute, and a second copy machine makes 10 copies a minute. If the two copiers work together, how long would it take them to make 1,000 copies?
Choose one:
A) 20 minutes
B) 30 minutes
C) 40 minutes
D) 50 minutes
E) 60 minutes | <gadget id="calculator">10 ** 3</gadget>
<output>1_000</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">1_000 / 25</gadget>
<output>40</output>
<result>C</result> | C | 40 | One copy machine can make 15 copies a minute, and a second copy machine makes 10 copies a minute. If the two copiers work together, how long would it take them to make 1,000 copies? | {
"A": "20 minutes",
"B": "30 minutes",
"C": "40 minutes",
"D": "50 minutes",
"E": "60 minutes"
} | divide(power(10, const_3), add(15, 10)) | add(n0,n1)|power(n1,const_3)|divide(#1,#0) | total work done by both machines in a minute = 15 + 10 = 25 copies total number of copies required = 1000 time = 1000 / 25 = 40 mins answer c | physics |
math_qa__TNWSvvCHIE54xuZk | A and B start walking towards each other at 6pm at speed of 6kmph and 4kmph. They were initially 50km apart. At what time do they meet? Choose the correct choice from the following choices
A) 8 pm
B) 6 pm
C) 11 pm
D) 10 pm
E) 5 pm | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">50 / 10</gadget>
<output>5</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<result>C</result> | C | 11 | A and B start walking towards each other at 6pm at speed of 6kmph and 4kmph. They were initially 50km apart. At what time do they meet? | {
"A": "8 pm",
"B": "6 pm",
"C": "11 pm",
"D": "10 pm",
"E": "5 pm"
} | add(6, divide(50, add(6, 4))) | add(n1,n2)|divide(n3,#0)|add(n0,#1)| | "time of meeting = distance / relative speed = 50 / 4 + 6 = 50 / 10 = 5 hrs after 6 pm = 11 pm answer is c" | physics |
math_qa__XmXswcEQ00ONHwNa | Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 10 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X? Pick.
A) 34
B) 35
C) 36
D) 37 1 / 25
E) 40 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">10 * (3/10)</gadget>
<output>3</output>
<gadget id="calculator">2 * (3/10)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">3 + (3/5)</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">10 * (7/10)</gadget>
<output>7</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">2 * (7/10)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">5 + (7/5)</gadget>
<output>32/5 = around 6.4</output>
<gadget id="calculator">(18/5) + (32/5)</gadget>
<output>10</output>
<gadget id="calculator">(18/5) / 10</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">100 * (9/25)</gadget>
<output>36</output>
<result>C</result> | C | 36 | Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 10 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X? | {
"A": "34",
"B": "35",
"C": "36",
"D": "37 1 / 25",
"E": "40"
} | multiply(const_100, divide(add(multiply(10, divide(30, const_100)), multiply(2, divide(30, const_100))), add(add(multiply(10, divide(30, const_100)), multiply(2, divide(30, const_100))), add(subtract(multiply(10, divide(70, const_100)), 2), multiply(2, divide(70, const_100)))))) | divide(n0,const_100)|divide(n1,const_100)|multiply(n3,#0)|multiply(n2,#0)|multiply(n2,#1)|multiply(n3,#1)|add(#2,#3)|subtract(#5,n2)|add(#4,#7)|add(#6,#8)|divide(#6,#9)|multiply(#10,const_100)| | "in 8 kilograms of solution y there are 0.3 * 10 = 3 kilograms of solution x ; after 2 kilograms of water are replaced by 2 kilograms of solution y , to the existing 2.4 kilograms of solution x , 0.3 * 2 = 0.6 kilograms of solution x are added , so in the new solution of 8 kilograms there are 3 + 0.6 = 3.6 kilograms of solution x , which is 3.6 / 10 * 100 = 36 % of this new solution . answer : c ." | gain |
math_qa__Kf31SE9w6dVM6N2n | Water is poured into a tank so that the tank is being filled at the rate of 4 cubic feet per hour. If the empty rectangular tank is 6 feet long, 4 feet wide, and 3 feet deep, approximately how many hours does it take to fill the tank? Choose the correct choice: A) 16 B) 18 C) 20 D) 22 E) 24 | <gadget id="calculator">6 * 4 * 3</gadget>
<output>72</output>
<gadget id="calculator">72 / 4</gadget>
<output>18</output>
<result>B</result> | B | 18 | Water is poured into a tank so that the tank is being filled at the rate of 4 cubic feet per hour. If the empty rectangular tank is 6 feet long, 4 feet wide, and 3 feet deep, approximately how many hours does it take to fill the tank? | {
"A": "16",
"B": "18",
"C": "20",
"D": "22",
"E": "24"
} | divide(volume_rectangular_prism(6, 4, 3), 4) | volume_rectangular_prism(n3,n1,n2)|divide(#0,n0)| | "the volume the tank is : length * width * depth = 6 * 4 * 3 = 72 cubic feet . 72 cubic feet / 4 cubic feet per hour = 18 hours . it will take 18 hours to fill the tank . the answer is b ." | physics |
math_qa__5PWsSxM7bqDq1bQg | two pipes a and b can separately fill a cistern in 60 min and 75 min respectively . there is a third pipe in the bottom of the cistern to empty it . if all the 3 pipes are simultaneously opened , then the cistern is full in 50 min . in how much time , the third pipe alone can empty the cistern ?
Options: A) 197 min B) 100 min C) 177 min D) 176 min E) 186 min | <gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">1 / 75</gadget>
<output>1/75 = around 0.013333</output>
<gadget id="calculator">(1/60) + (1/75)</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(3/100) - (1/50)</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">1 / (1/100)</gadget>
<output>100</output>
<result>B</result> | B | 100 | two pipes a and b can separately fill a cistern in 60 min and 75 min respectively . there is a third pipe in the bottom of the cistern to empty it . if all the 3 pipes are simultaneously opened , then the cistern is full in 50 min . in how much time , the third pipe alone can empty the cistern ? | {
"A": "197 min",
"B": "100 min",
"C": "177 min",
"D": "176 min",
"E": "186 min"
} | inverse(subtract(add(divide(const_1, 60), divide(const_1, 75)), divide(const_1, 50))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n3)|add(#0,#1)|subtract(#3,#2)|inverse(#4) | work done by the third pipe in 1 min = 1 / 50 - ( 1 / 60 + 1 / 75 ) = - 1 / 100 . [ - ve sign means emptying ] the third pipe alone can empty the cistern in 100 min . answer : b | gain |
math_qa__9LcogqERQf5tIzr9 | A trader sells 92 meters of cloth for Rs. 9890 at the profit of Rs. 24 per metre of cloth. What is the cost price of one metre of cloth? Pick
A) 22 B) 89.5 C) 76.9 D) 83.5 E) 11 | <gadget id="calculator">9_890 / 92</gadget>
<output>215/2 = around 107.5</output>
<gadget id="calculator">(215/2) - 24</gadget>
<output>167/2 = around 83.5</output>
<result>D</result> | D | 83.5 | A trader sells 92 meters of cloth for Rs. 9890 at the profit of Rs. 24 per metre of cloth. What is the cost price of one metre of cloth? | {
"A": "22",
"B": "89.5",
"C": "76.9",
"D": "83.5",
"E": "11"
} | subtract(divide(9890, 92), 24) | divide(n1,n0)|subtract(#0,n2)| | "sp of 1 m of cloth = 9890 / 92 = rs . 107.5 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 107.5 - rs . 24 = rs . 83.5 answer : d" | physics |
math_qa__hJkPzWlNvtN33E00 | The ratio of numbers is 3:4 and their H.C.F is 3. Their L.C.M is:
Options.
A) 12 B) 16 C) 36 D) 48 E) 98 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">lcm(9, 12)</gadget>
<output>36</output>
<result>C</result> | C | 36 | The ratio of numbers is 3:4 and their H.C.F is 3. Their L.C.M is: | {
"A": "12",
"B": "16",
"C": "36",
"D": "48",
"E": "98"
} | lcm(multiply(3, 3), multiply(4, 3)) | multiply(n0,n2)|multiply(n1,n2)|lcm(#0,#1)| | "let the numbers be 3 x and 4 x . then their h . c . f = x . so , x = 3 . so , the numbers are 9 and 12 . l . c . m of 9 and 12 = 36 . answer : c" | other |
math_qa__YZcau2jhoIGw6AkN | The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 65 kg. What is the correct weight? Pick
A) 67.4 kg B) 57.75 kg C) 58.85 kg D) 49.4 kg E) none of these | <gadget id="calculator">58.4 * 20</gadget>
<output>1_168</output>
<gadget id="calculator">65 - 56</gadget>
<output>9</output>
<gadget id="calculator">1_168 + 9</gadget>
<output>1_177</output>
<gadget id="calculator">1_177 / 20</gadget>
<output>1_177/20 = around 58.85</output>
<result>C</result> | C | 58.85 | The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 65 kg. What is the correct weight? | {
"A": "67.4 kg",
"B": "57.75 kg",
"C": "58.85 kg",
"D": "49.4 kg",
"E": "none of these"
} | divide(add(multiply(58.4, 20), subtract(65, 56)), 20) | multiply(n0,n1)|subtract(n3,n2)|add(#0,#1)|divide(#2,n0)| | "actual total weight is ( 20 ã — 58.4 - 56 + 65 ) = 1177 kgs actual average weight is 1177 / 20 = 58.85 kgs answer is c" | general |
math_qa__172l8MFdfgVE98iP | The sale price sarees listed for Rs.400 after successive discount is 30% and 20% is? Answers: A) 297 B) 879 C) 342 D) 762 E) 224 | <gadget id="calculator">400 * 30</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 100</gadget>
<output>120</output>
<gadget id="calculator">400 - 120</gadget>
<output>280</output>
<gadget id="calculator">280 * 20</gadget>
<output>5_600</output>
<gadget id="calculator">5_600 / 100</gadget>
<output>56</output>
<gadget id="calculator">280 - 56</gadget>
<output>224</output>
<result>E</result> | E | 224 | The sale price sarees listed for Rs.400 after successive discount is 30% and 20% is? | {
"A": "297",
"B": "879",
"C": "342",
"D": "762",
"E": "224"
} | subtract(subtract(400, divide(multiply(400, 30), const_100)), divide(multiply(subtract(400, divide(multiply(400, 30), const_100)), 20), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "400 * ( 70 / 100 ) * ( 80 / 100 ) = 224 answer : e" | gain |
math_qa__GIJSJ2QnVwKDZ9ID | A runs 1 ¾ times as fast as B. if A gives B a start of 84 m, bow far must winning post be so that A and B might reach it at the same time?
Pick.
A) 196 m
B) 194 m
C) 186 m
D) 296 m
E) 106 m | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(7/3) * 84</gadget>
<output>196</output>
<result>A</result> | A | 196 | A runs 1 ¾ times as fast as B. if A gives B a start of 84 m, bow far must winning post be so that A and B might reach it at the same time? | {
"A": "196 m",
"B": "194 m",
"C": "186 m",
"D": "296 m",
"E": "106 m"
} | multiply(divide(add(const_4, const_3), const_3), 84) | add(const_3,const_4)|divide(#0,const_3)|multiply(n1,#1) | . ratio of the rates of a and b = 7 / 4 : 1 = 7 : 4 . so , in a race of 7 m , a gains 3 m over b . : . 3 m are gained by a in a race of 7 m . : . 84 m are gained by a in a race of ( 7 / 3 x 84 ) m = 196 m . : . winning post must be 196 m away from the starting point . answer is a . | physics |
math_qa__szvT9y7THLEPh0yE | A box contains 13 apples, 12 of which are red. An apple is drawn from the box and its color is noted before it is eaten. This is done a total of n times, and the probability that a red apple is drawn each time is less than 0.5. What is the smallest possible value of n?
Choose the correct choice from the following choices.
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">0.5 * 12</gadget>
<output>6</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<result>E</result> | E | 7 | A box contains 13 apples, 12 of which are red. An apple is drawn from the box and its color is noted before it is eaten. This is done a total of n times, and the probability that a red apple is drawn each time is less than 0.5. What is the smallest possible value of n? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | add(multiply(0.5, 12), const_1) | multiply(n2,n1)|add(#0,const_1)| | "p ( choosing a red apple 7 times in a row ) = 12 / 13 * 11 / 12 * 10 / 11 * 9 / 10 * 8 / 9 * 7 / 8 * 6 / 7 = 6 / 13 < 0.5 the answer is e ." | general |
math_qa__z0rx04r99VQJW3UX | A = {2, 3, 5, 7, 11}
B = {2, 4, 6, 19}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained?
Choose the correct choice from the following answers.
A) 15 B) 16 C) 19 D) 24 E) 36 | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<result>D</result> | D | 24 | A = {2, 3, 5, 7, 11}
B = {2, 4, 6, 19}
Two integers will be randomly selected from sets A and B, one integer from set A and one from set B, and then multiplied together. How many different products can be obtained? | {
"A": "15",
"B": "16",
"C": "19",
"D": "24",
"E": "36"
} | multiply(6, 4) | multiply(n6,n7) | step 1 : find out the number of products you get . 5 distinct numbers in set a and 4 distinct in set b so number of products = 5 * 4 = 20 step 2 : remove the products that appear more than once . notice that 5 , 7 , 11 and 13 are primes and none of their multiples are in either set . so ignore them . we just need to focus on 2 and 3 of set a and 2 , 4 and 6 of set b . 2 , 3 2 , 4 , 6 the only product repeated when you take a number from each set is 12 . ( 3 * 4 and 2 * 6 ) rest all are distinct . answer = 20 - 1 = 24 note here that the second step will involve manual calculation since it will depend on the specific numbers you have in the two sets . d | general |
math_qa__LGtsXdPqeTXDq5mH | If one-seventh of a number exceeds its eleventh part by 100 then the number is… Choose the correct choice from the following options.
A) 770 B) 870 C) 1825 D) 1925 E) 925 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">100 * 11</gadget>
<output>1_100</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">1_100 * 7</gadget>
<output>7_700</output>
<gadget id="calculator">11 - 7</gadget>
<output>4</output>
<gadget id="calculator">7_700 / 4</gadget>
<output>1_925</output>
<result>D</result> | D | 1,925 | If one-seventh of a number exceeds its eleventh part by 100 then the number is… | {
"A": "770",
"B": "870",
"C": "1825",
"D": "1925",
"E": "925"
} | divide(multiply(multiply(100, add(const_10, const_1)), add(const_3, const_4)), subtract(add(const_10, const_1), add(const_3, const_4))) | add(const_3,const_4)|add(const_1,const_10)|multiply(n0,#1)|subtract(#1,#0)|multiply(#0,#2)|divide(#4,#3) | let no be : x 1 / 7 x - 1 / 11 x = 100 4 x / 77 = 100 x = 7700 / 4 = 1925 answer : d | general |
math_qa__AWLu7pDEEBEkDOZx | A regular 10 sided area is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ? Choose the correct choice from the following answers: A) 48 degrees B) 54 degrees C) 72 degrees D) 84 degrees E) 72 degrees | <gadget id="calculator">360 / 10</gadget>
<output>36</output>
<gadget id="calculator">180 - 36</gadget>
<output>144</output>
<gadget id="calculator">144 / 2</gadget>
<output>72</output>
<result>E</result> | E | 72 | A regular 10 sided area is inscribed in a circle. If A and B are adjacent vertices of the pentagon and O is the center of the circle, what is the value of ∠OAB ? | {
"A": "48 degrees",
"B": "54 degrees",
"C": "72 degrees",
"D": "84 degrees",
"E": "72 degrees"
} | divide(subtract(const_180, divide(const_360, 10)), const_2) | divide(const_360,n0)|subtract(const_180,#0)|divide(#1,const_2) | its a regular 10 sided so divide the globe by 10 . = 360 / 10 = 36 36 would be the angle at o . angles at a and b are equivalent , so 36 + 2 x = 180 2 x = 144 x = 72 angles oab and oba will be 72 degrees each . e | geometry |
math_qa__SzTQV0bx5thg8oxv | List I: 3, 4, 8, 19
List II: x, 3, 4, 8, 19 Choose the correct choice from the following answers: A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<result>A</result> | A | 6 | List I: 3, 4, 8, 19
List II: x, 3, 4, 8, 19 | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | multiply(subtract(const_3, const_1), 3) | subtract(const_3,const_1)|multiply(n0,#0) | we start by calculating the median of the numbers of list i : 3 , 4 , 8 , 19 . we see that the numbers in the list are in order already and , since we have an even number of numbers , the median is the average of the two middle numbers . median = ( 4 + 8 ) / 2 median = 12 / 2 median = 6 the median of list i is 6 . looking at list ii : x , 3 , 4 , 8 , 19 , we see that we have an odd number of terms . thus , when the list is ordered from least to greatest the median must be the middle term . since the medians of the two lists must be equal , we know that the median of list ii must be 6 and therefore x is 6 . the answer is a . | general |
math_qa__AxV2DSDXDj9iFNsW | There are 4 more women than there are men on a local co-ed softball team. If there are a total of 20 players on the team, what is the ratio of men to women?
Choose the correct choice from the following choices:
A) 8 / 12 B) 6 / 16 C) 4 / 16 D) 6 / 10 E) 4 / 10 | <gadget id="calculator">20 - 4</gadget>
<output>16</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | There are 4 more women than there are men on a local co-ed softball team. If there are a total of 20 players on the team, what is the ratio of men to women? | {
"A": "8 / 12",
"B": "6 / 16",
"C": "4 / 16",
"D": "6 / 10",
"E": "4 / 10"
} | divide(divide(subtract(20, 4), add(const_1, const_1)), add(divide(subtract(20, 4), add(const_1, const_1)), 4)) | add(const_1,const_1)|subtract(n1,n0)|divide(#1,#0)|add(n0,#2)|divide(#2,#3)| | "w = m + 4 w + m = 20 m + 4 + m = 20 2 m = 16 m = 8 w = 12 ratio : 8 : 12 ans : a" | general |
math_qa__rgYTORTzzQ9eE7E6 | A man can row his boat with the stream at 20 km/h and against the stream in 4 km/h. The man's rate is?
Answers
A) 1 kmph B) 7 kmph C) 98 kmph D) 6 kmph E) 8 kmph | <gadget id="calculator">20 - 4</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>E</result> | E | 8 | A man can row his boat with the stream at 20 km/h and against the stream in 4 km/h. The man's rate is? | {
"A": "1 kmph",
"B": "7 kmph",
"C": "98 kmph",
"D": "6 kmph",
"E": "8 kmph"
} | divide(subtract(20, 4), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 20 us = 4 s = ? s = ( 20 - 4 ) / 2 = 8 kmph answer : e" | gain |
math_qa__DrJ5DloSrABek8sZ | 6 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? Select the correct option: A) 19 B) 20 C) 30 D) 33 E) 34 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>C</result> | C | 30 | 6 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played? | {
"A": "19",
"B": "20",
"C": "30",
"D": "33",
"E": "34"
} | multiply(6, subtract(6, const_1)) | subtract(n0,const_1)|multiply(n0,#0)| | "though 2 * ( 6 c 2 ) is the correct approcah to do this , but for people like me who find perm , comb n prob a nightmare , an easy approach can be used . the first guy has to play 2 matches with the rest of 5 , so he ' ll play 10 matches . similarly , second guy has to play with the rest of 4 as his 2 games with the first guy are already played . so he plays 8 matches . this continues like this and the total matches are 10 + 8 + 6 . . . + 2 10 + 8 + . . . + 2 = 2 ( 5 + 4 + . . . + 1 ) = 2 ( ( 5 * 6 ) / 2 ) = 5 * 6 = 30 . answer : c" | general |
math_qa__jmRayoJIkwJJlLRD | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 51 kmph, find the speed of the stream? Choose the correct answer:
A) 12 kmph B) 13 kmph C) 14 kmph D) 15 kmph E) 17 kmph | <gadget id="calculator">51 * 2</gadget>
<output>102</output>
<gadget id="calculator">102 / 3</gadget>
<output>34</output>
<gadget id="calculator">51 - 34</gadget>
<output>17</output>
<result>E</result> | E | 17 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 51 kmph, find the speed of the stream? | {
"A": "12 kmph",
"B": "13 kmph",
"C": "14 kmph",
"D": "15 kmph",
"E": "17 kmph"
} | subtract(51, divide(multiply(51, const_2), const_3)) | multiply(n0,const_2)|divide(#0,const_3)|subtract(n0,#1)| | "the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 51 / 3 = 17 kmph answer : e" | physics |
math_qa__JjqrlblRJBso89xK | the average ( arithmetic man ) of 3 integers a , b , and c is exactly 4 times the median . if a < b < c and a = 0 , what is the value of c / b ?
Choose the correct choice from the following answers
A) 2 B) 3 C) 4 D) 11 E) can not be determined from the information given . | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<result>D</result> | D | 11 | the average ( arithmetic man ) of 3 integers a , b , and c is exactly 4 times the median . if a < b < c and a = 0 , what is the value of c / b ? | {
"A": "2",
"B": "3",
"C": "4",
"D": "11",
"E": "can not be determined from the information given ."
} | subtract(multiply(4, 3), const_1) | multiply(n0,n1)|subtract(#0,const_1) | the average of three integers a , b , and c is exactly twice the median - - > ( a + b + c ) / 3 = 4 b - - > since a = 0 , then ( 0 + b + c ) / 3 = 4 b - - > c = 11 b - - > c / b = 11 . answer : d . | general |
math_qa__CrYQQTOIlUEWEyPI | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.75 times as old as Robert? Pick: A) 1960 B) 1965 C) 1970 D) 1975 E) 1980 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">1.75 + 7</gadget>
<output>8.75</output>
<gadget id="calculator">1_950 + 8.75</gadget>
<output>1_958.75</output>
<result>E</result> | E | 1,980 | In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.75 times as old as Robert? | {
"A": "1960",
"B": "1965",
"C": "1970",
"D": "1975",
"E": "1980"
} | add(1950, add(1.75, add(4, 3))) | add(n3,n1)|add(n4,#0)|add(n0,#1)| | "in 1950 : ri = 4 ro - - - - - - - - - - - - - - eq 1 in 1955 : ri + 5 = 3 ( ro + 5 ) - - - - - - - - - eq 2 thus in 1950 , solving eq 1 and eq 2 ro = 10 , ri = 40 now for each year we can calculate : 1960 : ri = 50 , ro = 20 1965 : ri = 55 , ro = 25 1980 : ri = 40 , ro = 70 thus 8 ans : e" | general |
math_qa__Gp3A5fMJu0KI4v27 | Raman's salary was decreased by 50% and subsequently increased by 50%. How much percent does he loss Choose the correct choice from the following choices
A) 75 B) 65 C) 45 D) 25 E) 35 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">50 * 150</gadget>
<output>7_500</output>
<gadget id="calculator">10_000 - 7_500</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 / 100</gadget>
<output>25</output>
<result>D</result> | D | 25 | Raman's salary was decreased by 50% and subsequently increased by 50%. How much percent does he loss | {
"A": "75",
"B": "65",
"C": "45",
"D": "25",
"E": "35"
} | divide(subtract(multiply(const_100, const_100), multiply(subtract(const_100, 50), add(const_100, 50))), const_100) | add(n0,const_100)|multiply(const_100,const_100)|subtract(const_100,n0)|multiply(#0,#2)|subtract(#1,#3)|divide(#4,const_100)| | "explanation : let the origianl salary = rs . 100 it will be 150 % of ( 50 % of 100 ) = ( 150 / 100 ) * ( 50 / 100 ) * 100 = 75 so new salary is 75 , it means his loss is 25 % answer : option d" | gain |
math_qa__DIu4TOLAoSP3RdaR | A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 930gm. for a kg.His gain is …%. Choose the correct option
A) 5.26 %
B) 5.36 %
C) 4.26 %
D) 6.26 %
E) 7.53 % | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">930 / 1_000</gadget>
<output>93/100 = around 0.93</output>
<gadget id="calculator">1 / (93/100)</gadget>
<output>100/93 = around 1.075269</output>
<gadget id="calculator">(100/93) - 1</gadget>
<output>7/93 = around 0.075269</output>
<gadget id="calculator">(7/93) * 100</gadget>
<output>700/93 = around 7.526882</output>
<result>E</result> | E | 7.53 | A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 930gm. for a kg.His gain is …%. | {
"A": "5.26 %",
"B": "5.36 %",
"C": "4.26 %",
"D": "6.26 %",
"E": "7.53 %"
} | multiply(subtract(inverse(divide(930, multiply(multiply(add(const_4, const_1), const_2), const_100))), const_1), const_100) | add(const_1,const_4)|multiply(#0,const_2)|multiply(#1,const_100)|divide(n0,#2)|inverse(#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "his percentage gain is 100 * 7 / 930 as he is gaining 70 units for his purchase of 930 units . so 7.53 % . answer : e" | gain |
math_qa__187CMAk0RscN7c66 | A 6-liter solution is 30% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol? Options:
A) 1.8 B) 2.1 C) 2.4 D) 2.7 E) 3.0 | <gadget id="calculator">6 * 30</gadget>
<output>180</output>
<gadget id="calculator">180 / 100</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 2</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">6 - (18/5)</gadget>
<output>12/5 = around 2.4</output>
<result>C</result> | C | 2.4 | A 6-liter solution is 30% alcohol. How many liters of pure alcohol must be added to produce a solution that is 50% alcohol? | {
"A": "1.8",
"B": "2.1",
"C": "2.4",
"D": "2.7",
"E": "3.0"
} | subtract(6, multiply(divide(multiply(6, 30), const_100), const_2)) | multiply(n0,n1)|divide(#0,const_100)|multiply(#1,const_2)|subtract(n0,#2)| | "let x be the amount of pure alcohol required . 0.3 ( 6 ) + x = 0.5 ( x + 6 ) 0.5 x = 3 - 1.8 x = 2.4 liters the answer is c ." | general |
math_qa__vM3DOU0fA4u47ptM | If you add all the numbers on your mobile phone , what is the answer? Answers.
A) 45 B) 50 C) 55 D) 100 E) 60 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">1 + 9</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 9</gadget>
<output>45</output>
<result>A</result> | A | 45 | If you add all the numbers on your mobile phone , what is the answer? | {
"A": "45",
"B": "50",
"C": "55",
"D": "100",
"E": "60"
} | multiply(divide(add(const_1, subtract(const_10, const_1)), const_2), subtract(const_10, const_1)) | subtract(const_10,const_1)|add(#0,const_1)|divide(#1,const_2)|multiply(#2,#0) | 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 are in your mobile phone . therefore 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45 answer is a | general |
math_qa__zTiqEXDT9UXo1rac | If $650 is deposited into a savings account at an annual interest rate of 5% that compounds monthly, what is the value of the investment after 7 years? Choose the correct choice from the following choices
A) $ 750.00
B) $ 823.50
C) $ 973.25
D) $ 921.75
E) $ 110.00 | <gadget id="calculator">650 * 5</gadget>
<output>3_250</output>
<gadget id="calculator">3_250 / 100</gadget>
<output>65/2 = around 32.5</output>
<gadget id="calculator">650 + (65/2)</gadget>
<output>1_365/2 = around 682.5</output>
<gadget id="calculator">5 * (1_365/2)</gadget>
<output>6_825/2 = around 3_412.5</output>
<gadget id="calculator">(6_825/2) / 100</gadget>
<output>273/8 = around 34.125</output>
<gadget id="calculator">(1_365/2) + (273/8)</gadget>
<output>5_733/8 = around 716.625</output>
<gadget id="calculator">5 * (5_733/8)</gadget>
<output>28_665/8 = around 3_583.125</output>
<gadget id="calculator">(28_665/8) / 100</gadget>
<output>5_733/160 = around 35.83125</output>
<gadget id="calculator">(5_733/160) + (5_733/8)</gadget>
<output>120_393/160 = around 752.45625</output>
<gadget id="calculator">(120_393/160) * 5</gadget>
<output>120_393/32 = around 3_762.28125</output>
<gadget id="calculator">(120_393/32) / 100</gadget>
<output>120_393/3_200 = around 37.622813</output>
<gadget id="calculator">(120_393/3_200) + (120_393/160)</gadget>
<output>2_528_253/3_200 = around 790.079062</output>
<gadget id="calculator">(2_528_253/3_200) * 5</gadget>
<output>2_528_253/640 = around 3_950.395312</output>
<gadget id="calculator">(2_528_253/640) / 100</gadget>
<output>2_528_253/64_000 = around 39.503953</output>
<gadget id="calculator">(2_528_253/64_000) + (2_528_253/3_200)</gadget>
<output>53_093_313/64_000 = around 829.583016</output>
<gadget id="calculator">(53_093_313/64_000) * 5</gadget>
<output>53_093_313/12_800 = around 4_147.915078</output>
<gadget id="calculator">(53_093_313/12_800) / 100</gadget>
<output>53_093_313/1_280_000 = around 41.479151</output>
<gadget id="calculator">(53_093_313/1_280_000) + (53_093_313/64_000)</gadget>
<output>1_114_959_573/1_280_000 = around 871.062166</output>
<gadget id="calculator">(1_114_959_573/1_280_000) * 5</gadget>
<output>1_114_959_573/256_000 = around 4_355.310832</output>
<gadget id="calculator">(1_114_959_573/256_000) / 100</gadget>
<output>1_114_959_573/25_600_000 = around 43.553108</output>
<gadget id="calculator">(1_114_959_573/25_600_000) + (1_114_959_573/1_280_000)</gadget>
<output>23_414_151_033/25_600_000 = around 914.615275</output>
<result>D</result> | D | 921.75 | If $650 is deposited into a savings account at an annual interest rate of 5% that compounds monthly, what is the value of the investment after 7 years? | {
"A": "$ 750.00",
"B": "$ 823.50",
"C": "$ 973.25",
"D": "$ 921.75",
"E": "$ 110.00"
} | add(divide(multiply(add(divide(multiply(add(divide(multiply(add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100)))), 5), const_100), add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))))), 5), const_100), add(divide(multiply(add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100)))), 5), const_100), add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100)))))), 5), const_100), add(divide(multiply(add(divide(multiply(add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100)))), 5), const_100), add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))))), 5), const_100), add(divide(multiply(add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100)))), 5), const_100), add(divide(multiply(add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), 5), const_100), add(divide(multiply(5, add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))), const_100), add(add(650, divide(multiply(650, 5), const_100)), divide(multiply(5, add(650, divide(multiply(650, 5), const_100))), const_100))))))) | multiply(n0,n1)|divide(#0,const_100)|add(n0,#1)|multiply(n1,#2)|divide(#3,const_100)|add(#2,#4)|multiply(n1,#5)|divide(#6,const_100)|add(#5,#7)|multiply(n1,#8)|divide(#9,const_100)|add(#8,#10)|multiply(n1,#11)|divide(#12,const_100)|add(#11,#13)|multiply(n1,#14)|divide(#15,const_100)|add(#14,#16)|multiply(n1,#17)|divide(#18,const_100)|add(#17,#19) | using ci formula : a = p ( 1 + r / n ) ^ n * t a = 650 ( 1 + 5 / 7 ) ^ 5 * 7 a = 921.75 option : d | gain |
math_qa__gGtWn6qjlPPqJAAq | In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 15% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy? Choose the correct choice from the following choices:
A) 22 %
B) 23 %
C) 24 %
D) 26 %
E) 34 % | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">22 / (17/20)</gadget>
<output>440/17 = around 25.882353</output>
<result>D</result> | D | 26 | In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 15% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy? | {
"A": "22 %",
"B": "23 %",
"C": "24 %",
"D": "26 %",
"E": "34 %"
} | divide(22, divide(subtract(const_100, 15), const_100)) | subtract(const_100,n1)|divide(#0,const_100)|divide(n0,#1) | since 15 % of the customers who sample the candyare notcaught , then 88 % of the customers who sample the candyarecaught : { % of customers who sample candy } * 0.85 = 0.22 ; { % of customers who sample candy } = 0.259 answer : d . | gain |
math_qa__ocwHIInmvaTsKDlz | The jogging track in a sports complex is 561 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? Choose the correct answer:
A) 5.29 min B) 5.28 min C) 4.08 min D) 9.28 min E) 5.988 min | <gadget id="calculator">561 / 1_000</gadget>
<output>561/1_000 = around 0.561</output>
<gadget id="calculator">4.5 + 3.75</gadget>
<output>8.25</output>
<gadget id="calculator">(561/1_000) / 8.25</gadget>
<output>0.068</output>
<gadget id="calculator">0.068 * 60</gadget>
<output>4.08</output>
<result>C</result> | C | 4.08 | The jogging track in a sports complex is 561 m in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in? | {
"A": "5.29 min",
"B": "5.28 min",
"C": "4.08 min",
"D": "9.28 min",
"E": "5.988 min"
} | multiply(divide(divide(561, const_1000), add(4.5, 3.75)), const_60) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_60) | clearly , the two will meet when they are 561 m apart . to be ( 4.5 + 3.75 ) = 8.25 km apart , they take 1 hour . to be 561 m apart , they take ( 100 / 825 * 561 / 1000 ) hrs = ( 561 / 8250 * 60 ) min = 4.08 min . answer : c | general |
math_qa__6Q5AXlnX5fJCP2eJ | At a small company, 76 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married?
Choose the correct option.
A) 13 / 19
B) 1 / 3
C) 9 / 20
D) 7 / 10
E) 5 / 7 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">76 / 100</gadget>
<output>19/25 = around 0.76</output>
<gadget id="calculator">1 - (19/25)</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(6/25) * (1/3)</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(3/5) - (2/25)</gadget>
<output>13/25 = around 0.52</output>
<gadget id="calculator">(13/25) / (19/25)</gadget>
<output>13/19 = around 0.684211</output>
<result>A</result> | A | 0.684211 | At a small company, 76 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married? | {
"A": "13 / 19",
"B": "1 / 3",
"C": "9 / 20",
"D": "7 / 10",
"E": "5 / 7"
} | divide(subtract(divide(60, const_100), multiply(subtract(const_1, divide(76, const_100)), subtract(const_1, divide(2, 3)))), divide(76, const_100)) | divide(n1,const_100)|divide(n0,const_100)|divide(n2,n3)|subtract(const_1,#1)|subtract(const_1,#2)|multiply(#3,#4)|subtract(#0,#5)|divide(#6,#1)| | "lets take total employees are 100 . given that , total women = 76 and total married = 60 . total men = 100 - 76 = 24 and single men = 2 / 3 * 24 = 16 . married men = total men - single men = 24 - 16 = 8 . married women = total married - married men = 60 - 8 = 52 . fraction of women are married = married women / total women = 52 / 76 = 13 / 19 . ans a" | gain |
math_qa__HtKzWRBGS7gWAn0I | A store reported total sales of $385 million for February of this year. If the total sales for the same month last year was $340 million, approximately what was the percent increase in sales? Choose the correct choice from the following answers: A) 2 % B) 17 % C) 20 % D) 65 % E) 13 % | <gadget id="calculator">385 - 340</gadget>
<output>45</output>
<gadget id="calculator">45 / 340</gadget>
<output>9/68 = around 0.132353</output>
<gadget id="calculator">(9/68) * 100</gadget>
<output>225/17 = around 13.235294</output>
<result>E</result> | E | 13 | A store reported total sales of $385 million for February of this year. If the total sales for the same month last year was $340 million, approximately what was the percent increase in sales? | {
"A": "2 %",
"B": "17 %",
"C": "20 %",
"D": "65 %",
"E": "13 %"
} | multiply(divide(subtract(385, 340), 340), const_100) | subtract(n0,n1)|divide(#0,n1)|multiply(#1,const_100)| | "new value – old value ) / old value x 100 we are given : february sales this year = 385 million february sales last year = 340 million we need to determine the percent increase between sales from last year to sales this year . thus , the new value = 385 million and the old value = 340 million . let ’ s plug them into our percent change formula . ( new value – old value ) / old value x 100 [ ( 385 – 340 ) / 340 ] x 100 65 / 340 x 100 ≈ 13 % . the answer is e ." | general |
math_qa__aAFbeDuovzhn02Gw | Each of the dogs in a certain kennel is a single color. Each of the dogs in the kennel either has long fur or does not. Of the 45 dogs in the kennel, 36 have long fur, 27 are brown, and 8 are neither long-furred nor brown. How many long-furred dogs are brown?
Choose the correct choice from the following options
A) 26 B) 19 C) 11 D) 8 E) 6 | <gadget id="calculator">36 + 27</gadget>
<output>63</output>
<gadget id="calculator">45 - 8</gadget>
<output>37</output>
<gadget id="calculator">63 - 37</gadget>
<output>26</output>
<result>A</result> | A | 26 | Each of the dogs in a certain kennel is a single color. Each of the dogs in the kennel either has long fur or does not. Of the 45 dogs in the kennel, 36 have long fur, 27 are brown, and 8 are neither long-furred nor brown. How many long-furred dogs are brown? | {
"A": "26",
"B": "19",
"C": "11",
"D": "8",
"E": "6"
} | subtract(add(36, 27), subtract(45, 8)) | add(n1,n2)|subtract(n0,n3)|subtract(#0,#1)| | "no of dogs = 45 long fur = 36 brown = 27 neither long fur nor brown = 8 therefore , either long fur or brown = 45 - 8 = 37 37 = 36 + 27 - both both = 26 answer a" | other |
math_qa__W8FUnxZt2hGiAK2u | A certain protective additive increases from 20 days to 25 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive? Choose the correct choice from the following answers
A) 25 %
B) 33 1 / 3 %
C) 50 %
D) 66 2 / 3 %
E) 75 % | <gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">5 / 20</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>A</result> | A | 25 | A certain protective additive increases from 20 days to 25 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive? | {
"A": "25 %",
"B": "33 1 / 3 %",
"C": "50 %",
"D": "66 2 / 3 %",
"E": "75 %"
} | multiply(divide(subtract(25, 20), 20), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "general formula for percent increase or decrease , ( percent change ) : percent = change / original ∗ 100 so , the time between maintenance checks increased by 25 − 20 / 20 ∗ 100 = 25 answer : a ." | general |
math_qa__Zd6iMRA3Qx33s3Yx | A $500 investment and a $1,500 investment have a combined yearly return of 13 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? Pick one:
A) 9 % B) 15 % C) 105 / 8 % D) 11 % E) 12 % | <gadget id="calculator">3 * 500</gadget>
<output>1_500</output>
<gadget id="calculator">500 + 1_500</gadget>
<output>2_000</output>
<gadget id="calculator">13 / 100</gadget>
<output>13/100 = around 0.13</output>
<gadget id="calculator">2_000 * (13/100)</gadget>
<output>260</output>
<gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">500 * (7/100)</gadget>
<output>35</output>
<gadget id="calculator">260 - 35</gadget>
<output>225</output>
<gadget id="calculator">225 / 1_500</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>B</result> | B | 15 | A $500 investment and a $1,500 investment have a combined yearly return of 13 percent of the total of the two investments. If the $500 investment has a yearly return of 7 percent, what percent yearly return does the $1,500 investment have? | {
"A": "9 %",
"B": "15 %",
"C": "105 / 8 %",
"D": "11 %",
"E": "12 %"
} | multiply(divide(subtract(multiply(add(500, multiply(const_3, 500)), divide(13, const_100)), multiply(500, divide(7, const_100))), multiply(const_3, 500)), const_100) | divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_3)|add(n0,#2)|multiply(n0,#1)|multiply(#3,#0)|subtract(#5,#4)|divide(#6,#2)|multiply(#7,const_100)| | "the equation we can form the question : return on total investment = sum of individual investments ( 500 + 1500 ) ( 13 ) = ( 500 â ˆ — 7 ) + ( 1500 x ) , where x is the return on investment of 1500 . solving the equation , we get x = 15 % ( option b ) answer : b" | gain |
math_qa__t6E3dvXGo3MPkNym | The monthly rent of a shop of dimension 20feet × 15feet is Rs.3600. What is the annual rent per square foot of the shop?
Choices:
A) 43
B) 144
C) 68
D) 87
E) 92 | <gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">3_600 / 300</gadget>
<output>12</output>
<gadget id="calculator">12 * 12</gadget>
<output>144</output>
<result>B</result> | B | 144 | The monthly rent of a shop of dimension 20feet × 15feet is Rs.3600. What is the annual rent per square foot of the shop? | {
"A": "43",
"B": "144",
"C": "68",
"D": "87",
"E": "92"
} | multiply(add(const_10, const_2), divide(3600, rectangle_area(20, 15))) | add(const_10,const_2)|rectangle_area(n0,n1)|divide(n2,#1)|multiply(#0,#2)| | "sol . monthly rent per square feet = 3600 / ( 20 * 15 ) = 12 & annual rent per square feet = 12 * 12 = 144 answer : b" | geometry |
math_qa__P06RK0liBVG0JBiS | Liam is pulled over for speeding just as he is arriving at work.He explains to the police officer that he could not afford to be late today, and has arrived at work only four minutes before he is to start. The officer explains that if Liam had driven 5mph slower for his whole commute, he would have arrived at work exactly on time. If Liam's commute is 40 miles long,how fast was he actually driving?(Assume that Liam drove at a constant speed for the duration of his commute.) Choose the correct answer:
A) 50 mph B) 45 mph C) 48 mph D) 52 mph E) 60 mph | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<result>E</result> | E | 60 | Liam is pulled over for speeding just as he is arriving at work.He explains to the police officer that he could not afford to be late today, and has arrived at work only four minutes before he is to start. The officer explains that if Liam had driven 5mph slower for his whole commute, he would have arrived at work exactly on time. If Liam's commute is 40 miles long,how fast was he actually driving?(Assume that Liam drove at a constant speed for the duration of his commute.) | {
"A": "50 mph",
"B": "45 mph",
"C": "48 mph",
"D": "52 mph",
"E": "60 mph"
} | add(40, multiply(5, const_4)) | multiply(n0,const_4)|add(n1,#0) | let t be the number of hours he would need to reach office on time . when he is driving with over speed , he reached office 4 min earlier ! so the equation for this is s ( t - 4 / 60 ) = 40 where s is the speed and 30 is the distance . if he decreases his speed by 5 mph then he would have reached his office on time : ( s - 5 ) t = 40 if you solve above equations , you will arrive at t = 2 / 3 hr and s = 60 mph therefore answer is e | physics |
math_qa__iFLr6ExJUSO35egv | An article costing rs.160 is sold at 20% discount on a mark-up price. What is the selling price after
discount? Select the correct option
A) 106 B) 116 C) 128 D) 136 E) 146 | <gadget id="calculator">160 * 20</gadget>
<output>3_200</output>
<gadget id="calculator">3_200 / 100</gadget>
<output>32</output>
<gadget id="calculator">160 - 32</gadget>
<output>128</output>
<result>C</result> | C | 128 | An article costing rs.160 is sold at 20% discount on a mark-up price. What is the selling price after
discount? | {
"A": "106",
"B": "116",
"C": "128",
"D": "136",
"E": "146"
} | subtract(160, divide(multiply(160, 20), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1) | 160 * 80 / 100 = 128 answer : c | gain |
math_qa__44ZhWAzKY32B78E1 | 75% of x is greater than 1/3rd of x by 110.what is x? Choose the most appropriate option:
A) 160 B) 264 C) 360 D) 354 E) 400 | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(3/4) - (1/3)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">110 / (5/12)</gadget>
<output>264</output>
<result>B</result> | B | 264 | 75% of x is greater than 1/3rd of x by 110.what is x? | {
"A": "160",
"B": "264",
"C": "360",
"D": "354",
"E": "400"
} | divide(110, subtract(divide(75, const_100), divide(1, 3))) | divide(n0,const_100)|divide(n1,n2)|subtract(#0,#1)|divide(n3,#2) | 75 x / 100 - x / 3 = 110 5 x / 12 = 110 x = 264 answer : b | general |
math_qa__l0cPaXjKiGwzrxt1 | There are 8 stores in town that had a total of 21 visitors on a particular day. However, only 12 people went shopping that day; some people visited more than one store. If 8 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited? Choose the correct option
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">21 - 16</gadget>
<output>5</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<result>A</result> | A | 2 | There are 8 stores in town that had a total of 21 visitors on a particular day. However, only 12 people went shopping that day; some people visited more than one store. If 8 people visited exactly two stores each, and everyone visited at least one store, what is the largest number of stores anyone could have visited? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | subtract(subtract(21, multiply(8, const_2)), subtract(subtract(12, 8), const_1)) | multiply(n0,const_2)|subtract(n2,n0)|subtract(n1,#0)|subtract(#1,const_1)|subtract(#2,#3)| | "8 people visited 2 stores each for 16 visits . to maximize the number of stores that one person visited , let ' s assume that 3 people visited 1 store each . the number of remaining visits is 21 - 16 - 3 = 2 , which is the maximum that one person could have visited . the answer is a ." | general |
math_qa__4HJKrOgJAeHDmhyv | Indu gave Bindu Rs.2500 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest?
Choose the correct choice from the following answers.
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 + (1/25)</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">2_500 * (676/625)</gadget>
<output>2_704</output>
<gadget id="calculator">2_704 - 2_500</gadget>
<output>204</output>
<gadget id="calculator">2_500 * (1/25)</gadget>
<output>100</output>
<gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">204 - 200</gadget>
<output>4</output>
<result>D</result> | D | 4 | Indu gave Bindu Rs.2500 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(subtract(multiply(2500, power(add(const_1, divide(4, const_100)), 2)), 2500), multiply(multiply(2500, divide(4, const_100)), 2)) | divide(n2,const_100)|add(#0,const_1)|multiply(n0,#0)|multiply(n1,#2)|power(#1,n1)|multiply(n0,#4)|subtract(#5,n0)|subtract(#6,#3)| | "2500 = d ( 100 / 4 ) 2 d = 4 answer : d" | gain |
math_qa__gum3oRA5XMykzeqM | 7 people average age is 30. youngest person age is 7. find average of the people when youngest was born.
Choose the correct choice from the following options:
A) 23 B) 24 C) 25 D) 26 E) 27 | <gadget id="calculator">30 * 7</gadget>
<output>210</output>
<gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">210 - 49</gadget>
<output>161</output>
<gadget id="calculator">161 / 7</gadget>
<output>23</output>
<result>A</result> | A | 23 | 7 people average age is 30. youngest person age is 7. find average of the people when youngest was born. | {
"A": "23",
"B": "24",
"C": "25",
"D": "26",
"E": "27"
} | divide(subtract(multiply(30, 7), multiply(7, 7)), 7) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n0)| | "average age of people = 30 so have total age = 210 before 7 years we have to deduct each person age by seven years 210 - 49 = 161 so average age would be 161 / 7 = 23 answer : a" | general |
math_qa__z4ZhEJ05HDns3iam | How many pounds of salt at 50 cents/lb must be mixed with 40 lbs of salt that costs 35 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb? Choose the most appropriate option.
A) 20 B) 15 C) 40 D) 50 E) 25 | <gadget id="calculator">48 * 40</gadget>
<output>1_920</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">35 * 40</gadget>
<output>1_400</output>
<gadget id="calculator">(6/5) * 1_400</gadget>
<output>1_680</output>
<gadget id="calculator">1_920 - 1_680</gadget>
<output>240</output>
<gadget id="calculator">50 * (6/5)</gadget>
<output>60</output>
<gadget id="calculator">60 - 48</gadget>
<output>12</output>
<gadget id="calculator">240 / 12</gadget>
<output>20</output>
<result>A</result> | A | 20 | How many pounds of salt at 50 cents/lb must be mixed with 40 lbs of salt that costs 35 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb? | {
"A": "20",
"B": "15",
"C": "40",
"D": "50",
"E": "25"
} | divide(subtract(multiply(48, 40), multiply(divide(add(const_100, 20), const_100), multiply(35, 40))), subtract(multiply(50, divide(add(const_100, 20), const_100)), 48)) | add(n3,const_100)|multiply(n1,n4)|multiply(n1,n2)|divide(#0,const_100)|multiply(#3,#2)|multiply(n0,#3)|subtract(#1,#4)|subtract(#5,n4)|divide(#6,#7)| | "selling price is 48 cents / lb for a 20 % profit , cost price should be 40 cents / lb ( cp * 6 / 5 = 48 ) basically , you need to mix 35 cents / lb ( salt 1 ) with 50 cents / lb ( salt 2 ) to get a mixture costing 40 cents / lb ( salt avg ) weight of salt 1 / weight of salt 2 = ( salt 2 - salt avg ) / ( salt avg - salt 1 ) = ( 50 - 40 ) / ( 40 - 35 ) = 2 / 1 we know that weight of salt 1 is 40 lbs . weight of salt 2 must be 20 lbs . answer ( a )" | gain |
math_qa__cT3v7AkmTm4SjNjX | Along a yard 273 metres long, 14 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees Choose the correct choice from the following
A) 18 B) 19 C) 10 D) 21 E) 12 | <gadget id="calculator">14 - 1</gadget>
<output>13</output>
<gadget id="calculator">273 / 13</gadget>
<output>21</output>
<result>D</result> | D | 21 | Along a yard 273 metres long, 14 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between two consecutive trees | {
"A": "18",
"B": "19",
"C": "10",
"D": "21",
"E": "12"
} | divide(273, subtract(14, const_1)) | subtract(n1,const_1)|divide(n0,#0)| | "explanation : 14 trees have 13 gaps between them , required distance ( 273 / 13 ) = 21 option d" | physics |
math_qa__Bvyl4EFrwwlSD0mW | A sum of money deposited at C.I. amounts to Rs.2442 in 2 years and to Rs.2926 in 3 years. Find the rate percent?
Choose the correct choice from the following options.
A) 11 B) 20 C) 28 D) 24 E) 82 | <gadget id="calculator">2_926 - 2_442</gadget>
<output>484</output>
<gadget id="calculator">484 / 2_442</gadget>
<output>22/111 = around 0.198198</output>
<gadget id="calculator">(22/111) * 100</gadget>
<output>2_200/111 = around 19.81982</output>
<result>B</result> | B | 20 | A sum of money deposited at C.I. amounts to Rs.2442 in 2 years and to Rs.2926 in 3 years. Find the rate percent? | {
"A": "11",
"B": "20",
"C": "28",
"D": "24",
"E": "82"
} | multiply(divide(subtract(2926, 2442), 2442), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "explanation : 2420 - - - 484 100 - - - ? = > 20 % answer : option b" | gain |
math_qa__KXUlQTThhEZczdcI | A ratio between two numbers is 8:9 and their L.C.M. is 432. The first number is Answers:
A) 60 B) 45 C) 50 D) 48 E) none | <gadget id="calculator">8 * 9</gadget>
<output>72</output>
<gadget id="calculator">432 / 72</gadget>
<output>6</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<result>D</result> | D | 48 | A ratio between two numbers is 8:9 and their L.C.M. is 432. The first number is | {
"A": "60",
"B": "45",
"C": "50",
"D": "48",
"E": "none"
} | multiply(divide(432, multiply(8, 9)), 8) | multiply(n0,n1)|divide(n2,#0)|multiply(n0,#1) | sol . let the required numbers be 8 x and 9 x . then , their l . c . m . is 72 x . ∴ 72 x = 432 ⇔ x = 6 . hence , the first number is 48 . answer d | other |
math_qa__peXe9YqMFzV71qbN | jim needs $ 1000 to buy a new flat - screen tv . since he has only $ 7 , he borrows the remaining balance from his sister mary . the loan will be repaid in 3 annual installments at an interest rate of 10 % , compounded annually . the formula for calculating the monthly payment p is p = ( l x c x r ) / ( c – 1 ) where l = amount of the loan , r = annual interest rate , and c = compounding factor = ( 1 + r ) ^ n where n = number of annual payments . how much does jim have to pay mary at the end of each of the next 3 years ( rounded to the nearest penny ) ? Choose the correct choice from the following answers.
A) $ 357.67 B) $ 375.85 C) $ 387.40 D) $ 399.30 E) $ 433.33 | <gadget id="calculator">1_000 - 7</gadget>
<output>993</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">993 * (1/10)</gadget>
<output>993/10 = around 99.3</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 3</gadget>
<output>1_331/1_000 = around 1.331</output>
<gadget id="calculator">(993/10) * (1_331/1_000)</gadget>
<output>1_321_683/10_000 = around 132.1683</output>
<gadget id="calculator">(1_331/1_000) - 1</gadget>
<output>331/1_000 = around 0.331</output>
<gadget id="calculator">(1_321_683/10_000) / (331/1_000)</gadget>
<output>3_993/10 = around 399.3</output>
<result>D</result> | D | 399.3 | jim needs $ 1000 to buy a new flat - screen tv . since he has only $ 7 , he borrows the remaining balance from his sister mary . the loan will be repaid in 3 annual installments at an interest rate of 10 % , compounded annually . the formula for calculating the monthly payment p is p = ( l x c x r ) / ( c – 1 ) where l = amount of the loan , r = annual interest rate , and c = compounding factor = ( 1 + r ) ^ n where n = number of annual payments . how much does jim have to pay mary at the end of each of the next 3 years ( rounded to the nearest penny ) ? | {
"A": "$ 357.67",
"B": "$ 375.85",
"C": "$ 387.40",
"D": "$ 399.30",
"E": "$ 433.33"
} | divide(multiply(multiply(subtract(1000, 7), divide(10, const_100)), power(add(1, divide(10, const_100)), 3)), subtract(power(add(1, divide(10, const_100)), 3), const_1)) | divide(n3,const_100)|subtract(n0,n1)|add(n4,#0)|multiply(#0,#1)|power(#2,n2)|multiply(#3,#4)|subtract(#4,const_1)|divide(#5,#6) | l = 993 r = 0.1 c = 1.1 ^ 3 = 1.331 insert all of these in the formula and we get p = 993 * 1.331 * 0.1 / 0.331 in order to resolve above without a calc , we need to find the approx value of 0.1331 / 0.331 ~ 0.4 ~ ~ 993 * 0.4 ~ 397 answer d | general |
math_qa__YwxN1sqU2DgGPhCY | A circular well with a diameter of 2 metres , is dug to a depth of 14 metres. What is the volume of the earth dug out?
Select: A) 32 m 3 B) 36 m 3 C) 40 m 3 D) 44 m 3 E) none | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">pi * (1 ** 2) * 14</gadget>
<output>14*pi = around 43.982297</output>
<result>D</result> | D | 44 | A circular well with a diameter of 2 metres , is dug to a depth of 14 metres. What is the volume of the earth dug out? | {
"A": "32 m 3",
"B": "36 m 3",
"C": "40 m 3",
"D": "44 m 3",
"E": "none"
} | volume_cylinder(divide(2, 2), 14) | divide(n0,n0)|volume_cylinder(#0,n1)| | "sol . volume = π r 2 h = ( 22 / 7 x 1 x 1 x 14 ) m 3 = 44 m 3 . answer d" | geometry |
math_qa__3yMCt4ZuK4mYgJj9 | A searchlight on top of the watchtower makes 4 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds?
Choose the correct choice from the following options:
A) 5 / 6 B) 4 / 5 C) 3 / 4 D) 2 / 3 E) 1 / 2 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">5 / 15</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<result>D</result> | D | 0.666667 | A searchlight on top of the watchtower makes 4 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 5 seconds? | {
"A": "5 / 6",
"B": "4 / 5",
"C": "3 / 4",
"D": "2 / 3",
"E": "1 / 2"
} | subtract(const_1, divide(5, multiply(5, const_3))) | multiply(n1,const_3)|divide(n1,#0)|subtract(const_1,#1) | the searchlight completes one revolution every 15 seconds . the probability that the man ' s area will be lit up is 5 / 15 = 1 / 3 . the probability that he will stay in the dark is 1 - 1 / 3 = 2 / 3 the answer is d . | physics |
math_qa__OnaDlenFgubzq3vn | How many integers are between 7 and 120/9, inclusive? Choose the most appropriate option
A) 5 B) 6 C) 7 D) 9 E) 10 | <gadget id="calculator">120 / 9</gadget>
<output>40/3 = around 13.333333</output>
<gadget id="calculator">(40/3) - 7</gadget>
<output>19/3 = around 6.333333</output>
<gadget id="calculator">(19/3) + 1</gadget>
<output>22/3 = around 7.333333</output>
<result>C</result> | C | 7 | How many integers are between 7 and 120/9, inclusive? | {
"A": "5",
"B": "6",
"C": "7",
"D": "9",
"E": "10"
} | add(subtract(divide(120, 9), 7), const_1) | divide(n1,n2)|subtract(#0,n0)|add(#1,const_1)| | "120 / 9 = 13 . xx we are not concerned about the exact value of 120 / 9 as we just need the integers . the different integers between 7 and 120 / 9 would be 7 , 8 , 9 , 10 , 11 , 12,13 total number of integers = 7 option c" | general |
math_qa__Zbr2jsVQHHyTHSZv | The two lines y=x and x=-5 intersect on the coordinate plane. What is the value of the area of the figure formed by the intersecting lines and the x-axis? Choose the most appropriate option.
A) 7.5
B) 10
C) 12.5
D) 15
E) 17.5 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 2</gadget>
<output>25/2 = around 12.5</output>
<result>C</result> | C | 12.5 | The two lines y=x and x=-5 intersect on the coordinate plane. What is the value of the area of the figure formed by the intersecting lines and the x-axis? | {
"A": "7.5",
"B": "10",
"C": "12.5",
"D": "15",
"E": "17.5"
} | divide(multiply(5, 5), const_2) | multiply(n0,n0)|divide(#0,const_2)| | "the point of intersection is ( - 5 , - 5 ) . the triangle has a base of length 5 and a height of 5 . area = ( 1 / 2 ) * base * height = ( 1 / 2 ) * 5 * 5 = 12.5 the answer is c ." | general |
math_qa__vLhBobiMX6pwgXvX | In a 100-mile trip, the first 30 miles were completed at 60 mph. If the average speed for the whole trip was 40 mph, what was the average speed in the last 70 miles? Choices: A) 30 mph B) 32 mph C) 35 mph D) 37 mph E) 38 mph | <gadget id="calculator">100 / 40</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(5/2) - (1/2)</gadget>
<output>2</output>
<gadget id="calculator">70 / 2</gadget>
<output>35</output>
<result>C</result> | C | 35 | In a 100-mile trip, the first 30 miles were completed at 60 mph. If the average speed for the whole trip was 40 mph, what was the average speed in the last 70 miles? | {
"A": "30 mph",
"B": "32 mph",
"C": "35 mph",
"D": "37 mph",
"E": "38 mph"
} | divide(70, subtract(divide(100, 40), divide(30, 60))) | divide(n0,n3)|divide(n1,n2)|subtract(#0,#1)|divide(n4,#2) | the time to complete the first 30 miles was ( 30 miles / 60 mph ) = ( 1 / 2 ) hours . the time to complete the whole trip was ( 100 miles / 40 mph ) = ( 5 / 2 ) hours . the time to complete the last 70 miles was ( 5 / 2 ) - ( 1 / 2 ) = ( 2 ) hours . the average speed in the last 70 miles was ( 70 miles / 2 hours ) = 35 mph . the answer is c . | general |
math_qa__cusOdObXjkMK2CQn | Diana took out a charge account at the General Store and agreed to pay 6% simple annual interest. If she charges $60 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? Choose the correct choice
A) $ 62.40
B) $ 62.80
C) $ 63.20
D) $ 63.60
E) $ 64.00 | <gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 60</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">60 + (18/5)</gadget>
<output>318/5 = around 63.6</output>
<result>D</result> | D | 63.6 | Diana took out a charge account at the General Store and agreed to pay 6% simple annual interest. If she charges $60 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? | {
"A": "$ 62.40",
"B": "$ 62.80",
"C": "$ 63.20",
"D": "$ 63.60",
"E": "$ 64.00"
} | add(60, multiply(divide(6, const_100), 60)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)| | "1.06 * $ 60 = $ 63.60 the answer is d ." | general |
math_qa__QB7GmvbXCo9PR9r9 | The manager of a produce market purchased a quantity of tomatoes for $0.80 per pound. Due to improper handling, 10 percent of the tomatoes, by weight, were ruined and discarded. At what price per pound should the manager sell the remaining tomatoes if she wishes to make a profit on the sale of the tomatoes equal to 10 percent of the cost of the tomatoes. Choose the correct choice from the following
A) $ 0.94 B) $ 0.96 C) $ 0.98 D) $ 1.00 E) $ 1.20 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">0.8 / (9/10)</gadget>
<output>0.888889</output>
<gadget id="calculator">(11/10) * 0.888889</gadget>
<output>0.977778</output>
<result>C</result> | C | 0.98 | The manager of a produce market purchased a quantity of tomatoes for $0.80 per pound. Due to improper handling, 10 percent of the tomatoes, by weight, were ruined and discarded. At what price per pound should the manager sell the remaining tomatoes if she wishes to make a profit on the sale of the tomatoes equal to 10 percent of the cost of the tomatoes. | {
"A": "$ 0.94",
"B": "$ 0.96",
"C": "$ 0.98",
"D": "$ 1.00",
"E": "$ 1.20"
} | multiply(add(const_1, divide(10, const_100)), divide(0.80, divide(subtract(const_100, 10), const_100))) | divide(n2,const_100)|subtract(const_100,n1)|add(#0,const_1)|divide(#1,const_100)|divide(n0,#3)|multiply(#2,#4)| | "assume the manager bought 100 tomatoes . cost price = 80 given : 10 % are damaged - - > available tomatoes to sell = 90 90 * x - 80 = 0.1 * 80 90 x - 80 = 8 90 x = 88 x = 88 / 90 = 44 / 45 = 0.977 x is slightly under 0.977 = 0.98 answer : c" | gain |
math_qa__T5WHdJy9ZUhZnPH4 | A rectangle having length 140 cm and width 40 cm. If the length of the rectangle is increased by thirty percent then how much percent the breadth should be decreased so as to maintain the same area. Choices: A) 17.64 % B) 33.33 % C) 40 % D) 75 % E) none of these | <gadget id="calculator">140 * 40</gadget>
<output>5_600</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 140</gadget>
<output>4_200</output>
<gadget id="calculator">4_200 / 100</gadget>
<output>42</output>
<gadget id="calculator">140 + 42</gadget>
<output>182</output>
<gadget id="calculator">5_600 / 182</gadget>
<output>400/13 = around 30.769231</output>
<gadget id="calculator">(400/13) / 40</gadget>
<output>10/13 = around 0.769231</output>
<gadget id="calculator">1 + (10/13)</gadget>
<output>23/13 = around 1.769231</output>
<gadget id="calculator">(23/13) * 10</gadget>
<output>230/13 = around 17.692308</output>
<result>A</result> | A | 17.64 | A rectangle having length 140 cm and width 40 cm. If the length of the rectangle is increased by thirty percent then how much percent the breadth should be decreased so as to maintain the same area. | {
"A": "17.64 %",
"B": "33.33 %",
"C": "40 %",
"D": "75 %",
"E": "none of these"
} | multiply(add(const_1, divide(divide(multiply(140, 40), add(140, divide(multiply(multiply(const_3, const_10), 140), const_100))), 40)), const_10) | multiply(n0,n1)|multiply(const_10,const_3)|multiply(n0,#1)|divide(#2,const_100)|add(n0,#3)|divide(#0,#4)|divide(#5,n1)|add(#6,const_1)|multiply(#7,const_10) | explanation : solution : ( 30 / ( 140 + 30 ) * 100 ) % = 17.64 % answer : a | geometry |
math_qa__RfSuMqF2jB28OnWn | Which number can we add to 722425 to get a number exactly divisible by 456?
Pick
A) 312 B) 335 C) 347 D) 361 E) 383 | <gadget id="calculator">722_425 % 456</gadget>
<output>121</output>
<gadget id="calculator">456 - 121</gadget>
<output>335</output>
<result>B</result> | B | 335 | Which number can we add to 722425 to get a number exactly divisible by 456? | {
"A": "312",
"B": "335",
"C": "347",
"D": "361",
"E": "383"
} | subtract(456, reminder(722425, 456)) | reminder(n0,n1)|subtract(n1,#0)| | "722425 / 456 = 1584 with a remainder of 121 . we need to add 456 - 121 = 335 the answer is b ." | general |
math_qa__vuvnscRUS4EOTHVu | A man is walking at the rate of 8 km/hr crosses a bridge in 15 minutes. The length of the bridge is
Select the correct option
A) 1000 meters B) 1050 meters C) 1200 meters D) 2000 meters E) none of these | <gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">8 * (1/4)</gadget>
<output>2</output>
<gadget id="calculator">2 * 1_000</gadget>
<output>2_000</output>
<result>D</result> | D | 2,000 | A man is walking at the rate of 8 km/hr crosses a bridge in 15 minutes. The length of the bridge is | {
"A": "1000 meters",
"B": "1050 meters",
"C": "1200 meters",
"D": "2000 meters",
"E": "none of these"
} | multiply(multiply(8, divide(15, const_60)), const_1000) | divide(n1,const_60)|multiply(n0,#0)|multiply(#1,const_1000) | explanation : we need to get the answer in meters . so we will first of change distance from km / hour to meter / sec by multiplying it with 5 / 18 and also change 15 minutes to seconds by multiplying it with 60 . speed = 8 â ˆ — 5 / 18 = 20 / 9 m / sec time = 15 â ˆ — 60 seconds = 900 seconds distance = time â ˆ — speed / distance = 20 / 9 â ˆ — 900 = 2000 meter option d | gain |
math_qa__sALAW1fECkm8GRA7 | A certain company reported that the revenue on sales increased 15 % from 2000 to 2003, and increased 30 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005? Select: A) 50 % B) 40 % C) 35 % D) 32 % E) 13 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(13/10) - (23/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) / (23/20)</gadget>
<output>3/23 = around 0.130435</output>
<gadget id="calculator">(3/23) * 100</gadget>
<output>300/23 = around 13.043478</output>
<result>E</result> | E | 13 | A certain company reported that the revenue on sales increased 15 % from 2000 to 2003, and increased 30 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005? | {
"A": "50 %",
"B": "40 %",
"C": "35 %",
"D": "32 %",
"E": "13 %"
} | multiply(divide(subtract(add(const_1, divide(30, const_100)), add(const_1, divide(15, const_100))), add(const_1, divide(15, const_100))), const_100) | divide(n3,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(#2,#3)|divide(#4,#3)|multiply(#5,const_100)| | "assume the revenue in 2000 to be 100 . then in 2003 it would be 115 and and in 2005 130 , so from 2003 to 2005 it increased by ( 130 - 115 ) / 115 = 15 / 115 = 13 % . answer : e ." | gain |
math_qa__wqmDR3b7zL6RfI40 | P and Q invested in a business. The profit earned was divided in the ratio 2 : 3. If P invested Rs 40000, the amount invested by Q is Options:
A) 30000 B) 50000 C) 40000 D) 20000 E) 60000 | <gadget id="calculator">40_000 / 2</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 * 3</gadget>
<output>60_000</output>
<result>E</result> | E | 60,000 | P and Q invested in a business. The profit earned was divided in the ratio 2 : 3. If P invested Rs 40000, the amount invested by Q is | {
"A": "30000",
"B": "50000",
"C": "40000",
"D": "20000",
"E": "60000"
} | multiply(divide(40000, 2), 3) | divide(n2,n0)|multiply(n1,#0) | let the amount invested by q = q 40000 : q = 2 : 3 ⇒ 40000 × 3 = 2 q ⇒ q = ( 40000 × 3 ) / 2 = 60000 answer is e . | gain |
math_qa__NT4ZIrLhns0vcaxT | If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $65. If $2,000 is the total amount invested, how much is invested at 8 percent?
Choose the correct choice from the following choices.
A) $ 550
B) $ 650
C) $ 750
D) $ 850
E) $ 950 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 2</gadget>
<output>2_000</output>
<gadget id="calculator">10 * 8</gadget>
<output>80</output>
<gadget id="calculator">80 * 2</gadget>
<output>160</output>
<gadget id="calculator">160 + 65</gadget>
<output>225</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(1/10) + (2/25)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">225 / (9/50)</gadget>
<output>1_250</output>
<gadget id="calculator">2_000 - 1_250</gadget>
<output>750</output>
<result>C</result> | C | 750 | If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $65. If $2,000 is the total amount invested, how much is invested at 8 percent? | {
"A": "$ 550",
"B": "$ 650",
"C": "$ 750",
"D": "$ 850",
"E": "$ 950"
} | subtract(multiply(multiply(const_100, 10), const_2), divide(add(multiply(multiply(10, 8), const_2), 65), add(divide(10, const_100), divide(8, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|multiply(n0,const_100)|multiply(n0,n1)|add(#0,#1)|multiply(#2,const_2)|multiply(#3,const_2)|add(n4,#6)|divide(#7,#4)|subtract(#5,#8)| | "0.1 x = 0.08 ( 2000 - x ) + 65 0.18 x = 225 x = 1250 then the amount invested at 8 % is $ 2000 - $ 1250 = $ 750 the answer is c ." | general |
math_qa__tDbo4Fnp3kwvBUj1 | Ramu bought an old car for Rs. 36000. He spent Rs. 15000 on repairs and sold it for Rs. 62900. What is his profit percent? Answers:
A) 16 % B) 17 % C) 18 % D) 58 % E) 23 % | <gadget id="calculator">36_000 + 15_000</gadget>
<output>51_000</output>
<gadget id="calculator">62_900 - 51_000</gadget>
<output>11_900</output>
<gadget id="calculator">11_900 / 51_000</gadget>
<output>7/30 = around 0.233333</output>
<gadget id="calculator">(7/30) * 100</gadget>
<output>70/3 = around 23.333333</output>
<result>E</result> | E | 23 | Ramu bought an old car for Rs. 36000. He spent Rs. 15000 on repairs and sold it for Rs. 62900. What is his profit percent? | {
"A": "16 %",
"B": "17 %",
"C": "18 %",
"D": "58 %",
"E": "23 %"
} | multiply(divide(subtract(62900, add(36000, 15000)), add(36000, 15000)), const_100) | add(n0,n1)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100) | total cp = rs . 36000 + rs . 15000 = rs . 51000 and sp = rs . 62900 profit ( % ) = ( 62900 - 51000 ) / 51000 * 100 = 23 % answer : e | gain |
math_qa__6qJx2PR4eOt3U0sW | A goods train runs at a speed of 72 kmph and crosses a 270 m long platform in 26 seconds.What is the length of the goods train? Choose the correct answer
A) 230 m B) 250 m C) 260 m D) 270 m E) 240 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 270</gadget>
<output>250</output>
<result>B</result> | B | 250 | A goods train runs at a speed of 72 kmph and crosses a 270 m long platform in 26 seconds.What is the length of the goods train? | {
"A": "230 m",
"B": "250 m",
"C": "260 m",
"D": "270 m",
"E": "240 m"
} | subtract(multiply(multiply(72, const_0_2778), 26), 270) | multiply(n0,const_0_2778)|multiply(n2,#0)|subtract(#1,n1)| | "s = 270 + x / t 72 * 5 / 18 = 270 + x / 26 x = 250 answer : b" | physics |
math_qa__cEZsDNsP3t55MuTS | Ron cycles his way up on a hill side and back. He takes the exact same route both ways. On the trip out he cycles an average speed of 5 miles per hour. On the trip back, downhill cycling at an average speed of 100 miles per hour, he is quick to return back. What is his approximate average speed for the round trip in miles per hour? Options:
A) 8 B) 9.52 C) 10 D) 11.7 E) 20 | <gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<gadget id="calculator">200 / 100</gadget>
<output>2</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 + 200</gadget>
<output>400</output>
<gadget id="calculator">2 + 40</gadget>
<output>42</output>
<gadget id="calculator">400 / 42</gadget>
<output>200/21 = around 9.52381</output>
<result>B</result> | B | 9.52 | Ron cycles his way up on a hill side and back. He takes the exact same route both ways. On the trip out he cycles an average speed of 5 miles per hour. On the trip back, downhill cycling at an average speed of 100 miles per hour, he is quick to return back. What is his approximate average speed for the round trip in miles per hour? | {
"A": "8",
"B": "9.52",
"C": "10",
"D": "11.7",
"E": "20"
} | divide(add(multiply(divide(multiply(100, const_2), 5), 5), multiply(divide(multiply(100, const_2), 100), 100)), add(divide(multiply(100, const_2), 100), divide(multiply(100, const_2), 5))) | multiply(n1,const_2)|divide(#0,n0)|divide(#0,n1)|add(#2,#1)|multiply(n0,#1)|multiply(n1,#2)|add(#4,#5)|divide(#6,#3) | average speed = total distance / total time here distance to hill top and back is same as he takes the same route . d = 5 t 1 and d = 100 t 2 therefore , t 1 = d / 5 and t 2 = d / 100 t 1 + t 2 = 21 d / 100 therefore , average speed = 2 d / 21 d / 100 = 2 d * 100 / 21 d answer is 9.52 since , the options are far away we need not solve till the decimal points so correct answer is option b | physics |
math_qa__eeOr8MYSQlTv2EgS | Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability Q that Jane will be on the same committee as Albert? Pick.
A) 12 % B) 20 % C) 33 % D) 40 % E) 50 % | <gadget id="calculator">binomial(4, 1)</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">binomial(6, 3)</gadget>
<output>20</output>
<gadget id="calculator">8 / 20</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 4</gadget>
<output>100</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>D</result> | D | 40 | Two MBA admissions committees are to be formed randomly from 6 second year MBAs with 3 members each. What is the probability Q that Jane will be on the same committee as Albert? | {
"A": "12 %",
"B": "20 %",
"C": "33 %",
"D": "40 %",
"E": "50 %"
} | multiply(divide(multiply(choose(const_4, const_1), const_2), choose(6, 3)), multiply(multiply(const_5, const_5), const_4)) | choose(const_4,const_1)|choose(n0,n1)|multiply(const_5,const_5)|multiply(#0,const_2)|multiply(#2,const_4)|divide(#3,#1)|multiply(#5,#4)| | "total number of ways to choose 3 member committee - 6 c 3 = ( 6 ! / 3 ! 3 ! ) = 20 no . of ways albert n jane are in same committee : - ( 4 c 1 * 2 ) = 8 probability q = ( 8 / 20 ) * 100 = 40 % . + 1 for me . . : d" | probability |
math_qa__0FxFE0CBkdo0ZHy8 | How many 3 digit positive integers Q exist that when divided by 7 leave a remainder of 5? Options:
A) 128 B) 142 C) 143 D) 141 E) 129 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 1</gadget>
<output>999</output>
<gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">14 * 7</gadget>
<output>98</output>
<gadget id="calculator">98 + 5</gadget>
<output>103</output>
<gadget id="calculator">999 - 103</gadget>
<output>896</output>
<gadget id="calculator">896 / 7</gadget>
<output>128</output>
<result>E</result> | E | 129 | How many 3 digit positive integers Q exist that when divided by 7 leave a remainder of 5? | {
"A": "128",
"B": "142",
"C": "143",
"D": "141",
"E": "129"
} | divide(subtract(subtract(multiply(const_100, const_10), const_1), add(multiply(add(const_10, const_4), 7), 5)), 7) | add(const_10,const_4)|multiply(const_10,const_100)|multiply(n1,#0)|subtract(#1,const_1)|add(n2,#2)|subtract(#3,#4)|divide(#5,n1) | minimum three digit number is 100 and maximum three digit number is 999 . the first three digit number that leaves remainder 5 when divided by 7 is 103 . 14 * 7 = 98 + 5 = 103 the second three digit number that leaves remainder 5 when divided by 7 is 110 . 15 * 7 = 105 + 5 = 110 the third three digit number that leaves remainder 5 when divided by 7 is 117 and so on the last three digit number that leaves remainder 5 when divided by 7 is 999 142 * 7 = 994 + 5 = 999 therefore , we identify the sequence 103 , 110,117 . . . . . 999 use the formula of last term last term = first term + ( n - 1 ) * common difference you will get the answer 129 that is definitely e . | general |
math_qa__nUehNv7iYwRBOtt4 | alice , benjamin , and carol each try independently to win a carnival game . if their individual probabilities for success are 1 / 5 , 3 / 8 , and 2 / 7 , respectively , what is the probability that exactly two of the 3 players will win but one will lose ? Answers:
A) 3 / 140 B) 1 / 28 C) 3 / 56 D) 3 / 35 E) 7 / 40 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(4/5) * (3/8)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(3/10) * (2/7)</gadget>
<output>3/35 = around 0.085714</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">(1/5) * (5/8)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * (2/7)</gadget>
<output>1/28 = around 0.035714</output>
<gadget id="calculator">(3/35) + (1/28)</gadget>
<output>17/140 = around 0.121429</output>
<gadget id="calculator">(1/5) * (3/8)</gadget>
<output>3/40 = around 0.075</output>
<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">(3/40) * (5/7)</gadget>
<output>3/56 = around 0.053571</output>
<gadget id="calculator">(17/140) + (3/56)</gadget>
<output>7/40 = around 0.175</output>
<result>E</result> | E | 0.175 | alice , benjamin , and carol each try independently to win a carnival game . if their individual probabilities for success are 1 / 5 , 3 / 8 , and 2 / 7 , respectively , what is the probability that exactly two of the 3 players will win but one will lose ? | {
"A": "3 / 140",
"B": "1 / 28",
"C": "3 / 56",
"D": "3 / 35",
"E": "7 / 40"
} | add(add(multiply(multiply(divide(const_4, 5), divide(3, 8)), divide(2, 7)), multiply(multiply(divide(1, 5), divide(5, 8)), divide(2, 7))), multiply(multiply(divide(1, 5), divide(3, 8)), divide(5, 7))) | divide(n4,n5)|divide(const_4,n1)|divide(n2,n3)|divide(n0,n1)|divide(n1,n3)|divide(n1,n5)|multiply(#1,#2)|multiply(#3,#4)|multiply(#3,#2)|multiply(#0,#6)|multiply(#0,#7)|multiply(#5,#8)|add(#9,#10)|add(#12,#11) | p = p ( a wins , b wins , c loses ) + p ( a wins , b loses , c wins ) + p ( a loses , b wins , c wins ) = 1 / 5 * 3 / 8 * 5 / 7 + 1 / 5 * 5 / 8 * 2 / 7 + 4 / 5 * 3 / 8 * 2 / 7 = 7 / 40 . answer : e . | general |
math_qa__m0JfGcZpdvrn5c9m | A person takes 10 minutes more to cover a certain distance by decreasing his speed by 20%. What is the time taken to cover the distance at his original speed?
Select the correct option
A) 50 minutes
B) 20 minutes
C) 40 minutes
D) 60 minutes
E) 80 minutes | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<result>C</result> | C | 40 | A person takes 10 minutes more to cover a certain distance by decreasing his speed by 20%. What is the time taken to cover the distance at his original speed? | {
"A": "50 minutes",
"B": "20 minutes",
"C": "40 minutes",
"D": "60 minutes",
"E": "80 minutes"
} | multiply(10, divide(subtract(const_100, 20), 20)) | subtract(const_100,n1)|divide(#0,n1)|multiply(n0,#1) | let the distance and original speed be d km and k kmph respectively . d / 0.8 k - d / k = 10 / 60 = > 5 d / 4 k - d / k = 1 / 6 = > ( 5 d - 4 d ) / 4 k = 1 / 6 = > d = 4 / 6 k = 2 / 3 k time taken to cover the distance at original speed = d / k = 2 / 3 hours = 40 minutes . answer : c | physics |
math_qa__ZTJYEqWEZkWmVdKR | Victor gets 92 % marks in examinations. If these are 184 marks, find the maximum marks. Choose the correct choice from the following answers.
A) 334 B) 500 C) 200 D) 288 E) 271 | <gadget id="calculator">92 / 100</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">184 / (23/25)</gadget>
<output>200</output>
<result>C</result> | C | 200 | Victor gets 92 % marks in examinations. If these are 184 marks, find the maximum marks. | {
"A": "334",
"B": "500",
"C": "200",
"D": "288",
"E": "271"
} | divide(184, divide(92, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "let the maximum marks be m then 92 % of m = 184 ⇒ 92 / 100 × m = 184 ⇒ m = ( 184 × 100 ) / 92 ⇒ m = 18400 / 92 ⇒ m = 200 therefore , maximum marks in the examinations are 200 . answer : c" | gain |
math_qa__A07T1zXqfL6BauRf | By selling 8 pencils for a rupee a man loses 60%. How many for a rupee should he sell in order to gain 60%? Choices.
A) 8 B) 9 C) 2 D) 6 E) 4 | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">160 * (1/40)</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 8</gadget>
<output>2</output>
<result>C</result> | C | 2 | By selling 8 pencils for a rupee a man loses 60%. How many for a rupee should he sell in order to gain 60%? | {
"A": "8",
"B": "9",
"C": "2",
"D": "6",
"E": "4"
} | multiply(divide(const_1, multiply(add(const_100, 60), divide(const_1, subtract(const_100, 60)))), 8) | add(n2,const_100)|subtract(const_100,n1)|divide(const_1,#1)|multiply(#0,#2)|divide(const_1,#3)|multiply(n0,#4)| | "40 % - - - 8 160 % - - - ? 40 / 160 * 12 = 2 answer : c" | gain |
math_qa__effNDCzn0qjO6KZ5 | For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 1000, what is the maximum possible sum of the length of x and the length of y?
Choose the correct choice from the following answers
A) 5 B) 6 C) 15 D) 16 E) 18 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">7 + 9</gadget>
<output>16</output>
<result>D</result> | D | 16 | For any integer k > 1, the term “length of an integer” refers to the number of positive prime factors, not necessarily distinct, whose product is equal to k. For example, if k = 24, the length of k is equal to 4, since 24 = 2 × 2 × 2 × 3. If x and y are positive integers such that x > 1, y > 1, and x + 3y < 1000, what is the maximum possible sum of the length of x and the length of y? | {
"A": "5",
"B": "6",
"C": "15",
"D": "16",
"E": "18"
} | add(add(4, 3), add(add(4, 4), 1)) | add(n2,n7)|add(n2,n2)|add(n0,#1)|add(#0,#2) | basically the length of an integer is the sum of the powers of its prime factors . for example the length of 24 is 4 because 24 = 2 ^ 3 * 3 ^ 1 - - > 3 + 1 = 4 . given : x + 3 y < 1,000 . now , to maximize the length of x or y ( to maximize the sum of the powers of their primes ) we should minimize their prime bases . minimum prime base is 2 : so if x = 2 ^ 9 = 512 then its length is 9 - - > 512 + 3 y < 1,000 - - > y < 162.7 - - > maximum length of y can be 7 as 2 ^ 7 = 128 - - > 9 + 7 = 16 . answer : d . | general |
math_qa__XUaJgeYx4mQ2Z3f2 | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total T of the book? Choose the most appropriate option: A) 3003 B) 3027 C) 3024 D) 3021 E) 3018 | <gadget id="calculator">3_000 + 3</gadget>
<output>3_003</output>
<result>A</result> | A | 3,003 | There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total T of the book? | {
"A": "3003",
"B": "3027",
"C": "3024",
"D": "3021",
"E": "3018"
} | add(3000, 3) | add(n0,n5)| | "first , you have to find the common ratio for all 3 books . you have : p : c : b 3 : 2 - - > multiply by 2 ( gives you row 3 ) 4 : 6 6 : 4 : 3 hence : p : c : b : t ( total ) t 6 : 4 : 3 : 13 - - - - > this means , the total number must be a multiple of 13 . answer a is correct since 299 is divisible by 13 , hence is 2990 and so is 3003 ( 2990 + 13 ) ." | other |
math_qa__8EF6zdDcI0F0204q | A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? Choices:
A) 3.6 sec B) 18 sec C) 36 sec D) 72 sec E) none | <gadget id="calculator">240 + 120</gadget>
<output>360</output>
<gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">(9/25) / 36</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 60</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 60</gadget>
<output>36</output>
<result>C</result> | C | 36 | A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? | {
"A": "3.6 sec",
"B": "18 sec",
"C": "36 sec",
"D": "72 sec",
"E": "none"
} | multiply(multiply(divide(divide(add(240, 120), const_1000), subtract(45, 9)), const_60), const_60) | add(n1,n2)|subtract(n3,n0)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_60)|multiply(#4,const_60) | category formulae examples directions : problems based on trains . 11 . a train 280 m long , running with a speed of 63 km / hr will pass a tree in a . 15 sec . b . 16 sec . c . 18 sec . d . 20 sec . solution speed = ( 63 x 5 / 18 ) m / sec = 35 / 2 msec time taken = ( 280 x 2 / 35 ) m / sec = 16 sec . 12 . a train running at the speed of 60 km / hr crosses a pole in 9 seconds . what is ihe length of the train ? a . 120 metres b . 180 metres c . 324 metres d . none of these solution 13 . a jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction . in how much time will the train pass the jogger ? a . 3.6 sec b . 18 sec c . 36 sec d . 72 sec solution speed of train relative to jogger = ( 45 - 9 ) km / hr = 36 km / hr = ( 36 x 5 / 18 ) m / sec = 10 m / sec distance covered = ( 240 + 120 ) m = 360 m time taken = ( 360 / 10 ) sec = 36 sec . answer c | physics |
math_qa__bGwFMw0XbrYjl2IH | Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 100 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?
Choose the correct choice from the following answers:
A) 280 B) 400 C) 540 D) 500 E) 840 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">100 / (2/5)</gadget>
<output>250</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">250 / (3/4)</gadget>
<output>1_000/3 = around 333.333333</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(1_000/3) / (2/3)</gadget>
<output>500</output>
<result>D</result> | D | 500 | Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 100 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond? | {
"A": "280",
"B": "400",
"C": "540",
"D": "500",
"E": "840"
} | divide(divide(divide(100, subtract(const_1, divide(3, 5))), divide(3, 4)), divide(2, 3)) | divide(n1,n5)|divide(n1,n3)|divide(n0,n1)|subtract(const_1,#0)|divide(n6,#3)|divide(#4,#1)|divide(#5,#2)| | "of the goose eggs laid at a certain pond , 2 / 3 hatched and 3 / 4 of the geese that hatched from those eggs survived the first month : 2 / 3 * 3 / 4 = 1 / 2 survived the first month . of the geese that survived the first month , 3 / 5 did not survive the first year : ( 1 - 3 / 5 ) * 1 / 2 = 1 / 5 survived the first year . 100 geese survived the first year : 1 / 5 * ( total ) = 100 - - > ( total ) = 500 . answer : d ." | general |
math_qa__ZcG9hHw5CecTlMZ2 | A shopkeeper sold an article for Rs 2524.36. Approximately what was his profit percent if the cost price of the article was Rs 2400 Choose the correct choice from the following.
A) 4 % B) 5 % C) 6 % D) 7 % E) 8 % | <gadget id="calculator">2_524.36 - 2_400</gadget>
<output>124.36</output>
<gadget id="calculator">124.36 / 2_400</gadget>
<output>0.051817</output>
<gadget id="calculator">100 * 0.051817</gadget>
<output>5.1817</output>
<gadget id="calculator">floor(5.1817)</gadget>
<output>5</output>
<result>B</result> | B | 5 | A shopkeeper sold an article for Rs 2524.36. Approximately what was his profit percent if the cost price of the article was Rs 2400 | {
"A": "4 %",
"B": "5 %",
"C": "6 %",
"D": "7 %",
"E": "8 %"
} | floor(multiply(const_100, divide(subtract(2524.36, 2400), 2400))) | subtract(n0,n1)|divide(#0,n1)|multiply(#1,const_100)|floor(#2)| | "explanation : gain % = ( 125.36 * 100 / 2400 ) = 5.2 % = 5 % approx option b" | gain |
math_qa__kIMdb8S8kyHtw7vm | At a particular graduation party with 300 guests, 70% of the guests brought gifts, and 40% of the female guests brought gifts. If 30 males did not bring gifts to the party, how many females did bring gifts? Answers
A) 18 B) 28 C) 40 D) 68 E) 70 | <gadget id="calculator">70 * 300</gadget>
<output>21_000</output>
<gadget id="calculator">21_000 / 100</gadget>
<output>210</output>
<gadget id="calculator">300 - 210</gadget>
<output>90</output>
<gadget id="calculator">90 - 30</gadget>
<output>60</output>
<gadget id="calculator">60 * 100</gadget>
<output>6_000</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">6_000 / 60</gadget>
<output>100</output>
<gadget id="calculator">100 * 40</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 100</gadget>
<output>40</output>
<result>C</result> | C | 40 | At a particular graduation party with 300 guests, 70% of the guests brought gifts, and 40% of the female guests brought gifts. If 30 males did not bring gifts to the party, how many females did bring gifts? | {
"A": "18",
"B": "28",
"C": "40",
"D": "68",
"E": "70"
} | divide(multiply(divide(multiply(subtract(subtract(300, divide(multiply(70, 300), const_100)), 30), const_100), subtract(const_100, 40)), 40), const_100) | multiply(n0,n1)|subtract(const_100,n2)|divide(#0,const_100)|subtract(n0,#2)|subtract(#3,n3)|multiply(#4,const_100)|divide(#5,#1)|multiply(n2,#6)|divide(#7,const_100)| | "the correct method total = 300 . . 70 % of 300 = 210 got gifts . . 90 did not get gift , out of which 30 are males , so remaining 90 - 30 = 60 are females . . but 40 % females brought gift , so 60 % did not get it . . so 60 % = 60 , 100 % = 60 * 100 / 60 = 100 . ans 40 % of 100 = 40 c" | gain |
math_qa__WopGM22mRYvCj34J | a cave is going to explode . a family is trapped inside that cave . the only way to get outside is a narrow tunnel . but the tunnel is weak and thus only two people can go at one time . also , everybody is afraid of going alone . the father takes one minute to go through till the end , the mother takes two , the son takes 4 and the daughter takes 5 . the cave and tunnel will explode in 12 minutes . can they make it to the other end in that time frame ? ps : keep in mind that when two people are moving , the total time taken will be as per the slower one .
Choose one
A) 10 minutes B) 12 minutes C) 18 minutes D) 19 minutes E) 16 minutes | <gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 - 3</gadget>
<output>12</output>
<result>B</result> | B | 12 | a cave is going to explode . a family is trapped inside that cave . the only way to get outside is a narrow tunnel . but the tunnel is weak and thus only two people can go at one time . also , everybody is afraid of going alone . the father takes one minute to go through till the end , the mother takes two , the son takes 4 and the daughter takes 5 . the cave and tunnel will explode in 12 minutes . can they make it to the other end in that time frame ? ps : keep in mind that when two people are moving , the total time taken will be as per the slower one . | {
"A": "10 minutes",
"B": "12 minutes",
"C": "18 minutes",
"D": "19 minutes",
"E": "16 minutes"
} | subtract(multiply(divide(12, 4), 5), const_3) | divide(n2,n0)|multiply(n1,#0)|subtract(#1,const_3) | b 12 minutes explanation : yes , surely they can all make it out of the cave . first , father and mother will go . time taken = 2 minutes . father comes back . time taken = 2 + 1 = 3 minutes . both children go . time taken = 3 + 5 = 8 minutes . mother comes back . time taken = 8 + 2 = 10 minutes . mother and father go . time taken = 10 + 2 = 12 minutes . thus in 12 minutes , all of them will be out of the cave through the tunnel . | general |
math_qa__BMCIJGcESrhPPCZi | A bag contains 10 balls numbered from 0 to 9. the balls are such that the person picking a ball out of the bag is equally likely to pick anyone of them. A person picked a ball and replaced it in the bag after noting its number. He repeated this process 2 more times. What is the probability that the ball picked first is numbered higher than the ball picked second and the ball picked second is numbered higher than the ball picked third? Choose the correct option:
A) 72 / 100
B) 3 / 25
C) 4 / 5
D) 1 / 6
E) 1 / 9 | <gadget id="calculator">10 * 9</gadget>
<output>90</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">90 * 8</gadget>
<output>720</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">720 / 6</gadget>
<output>120</output>
<gadget id="calculator">10 ** 3</gadget>
<output>1_000</output>
<gadget id="calculator">120 / 1_000</gadget>
<output>3/25 = around 0.12</output>
<result>B</result> | B | 0.12 | A bag contains 10 balls numbered from 0 to 9. the balls are such that the person picking a ball out of the bag is equally likely to pick anyone of them. A person picked a ball and replaced it in the bag after noting its number. He repeated this process 2 more times. What is the probability that the ball picked first is numbered higher than the ball picked second and the ball picked second is numbered higher than the ball picked third? | {
"A": "72 / 100",
"B": "3 / 25",
"C": "4 / 5",
"D": "1 / 6",
"E": "1 / 9"
} | divide(divide(multiply(multiply(10, 9), add(const_4, const_4)), add(const_4, const_2)), power(const_10, const_3)) | add(const_4,const_4)|add(const_2,const_4)|multiply(n0,n2)|power(const_10,const_3)|multiply(#0,#2)|divide(#4,#1)|divide(#5,#3) | explanation : let , the number of the ball picked first = a , second = b and third = c and these three numbers a , b and c are distinct . three distinct ball can be picked in ( 10 × 9 × 8 ) ways . the order of a , b and c can be as follows : - ( i ) a > b > c . ( ii ) a > c > b . ( iii ) b > c > a . ( iv ) b > a > c . ( v ) c > a > b . ( vi ) c > b > a . they will occur equal number of times . so , the number of ways in which ( a > b > c ) are : - = > 1 / 6 x 10 x 9 x 8 . = > 120 . hence , the required probability is : - = > 120 / ( 10 x 10 x 10 ) . = > 3 / 25 . answer : b | general |
math_qa__5dz0nRtVB331WQdw | What sum of money will produce Rs.70 as simple interest in 3 years at 3 1/2 percent? Choose the correct choice
A) 263 B) 500 C) 367 D) 368 E) 666.7 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">3 * (7/2)</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">(21/2) / 100</gadget>
<output>21/200 = around 0.105</output>
<gadget id="calculator">70 / (21/200)</gadget>
<output>2_000/3 = around 666.666667</output>
<result>E</result> | E | 666.7 | What sum of money will produce Rs.70 as simple interest in 3 years at 3 1/2 percent? | {
"A": "263",
"B": "500",
"C": "367",
"D": "368",
"E": "666.7"
} | divide(70, divide(multiply(3, add(3, divide(1, 2))), const_100)) | divide(n3,n4)|add(n2,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(n0,#3)| | "70 = ( p * 3 * 7 / 2 ) / 100 p = 666.7 answer : e" | gain |
math_qa__fBqgAxDoWwcib0CE | a person x working alone can complete a work in 5 days . a person y completes the same amount of work in 20 days , and a person z when working alone can complete the same amount of work in 30 days . all 3 people work together for 2 days but then x and y leave . how many more days does z need to complete the work after x and y leave ? Choose the correct choice from the following choices:
A) 13 B) 14 C) 15 D) 16 E) 17 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/5) + (1/20)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/4) + (1/30)</gadget>
<output>17/60 = around 0.283333</output>
<gadget id="calculator">(17/60) * 2</gadget>
<output>17/30 = around 0.566667</output>
<gadget id="calculator">1 - (17/30)</gadget>
<output>13/30 = around 0.433333</output>
<gadget id="calculator">(13/30) / (1/30)</gadget>
<output>13</output>
<result>A</result> | A | 13 | a person x working alone can complete a work in 5 days . a person y completes the same amount of work in 20 days , and a person z when working alone can complete the same amount of work in 30 days . all 3 people work together for 2 days but then x and y leave . how many more days does z need to complete the work after x and y leave ? | {
"A": "13",
"B": "14",
"C": "15",
"D": "16",
"E": "17"
} | divide(subtract(const_1, multiply(add(add(divide(const_1, 5), divide(const_1, 20)), divide(const_1, 30)), 2)), divide(const_1, 30)) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|multiply(n4,#4)|subtract(const_1,#5)|divide(#6,#2) | the fraction of work completed in two days is 2 / 5 + 2 / 20 + 2 / 30 = 17 / 30 the fraction of work remaining is 1 - 17 / 30 = 13 / 30 the number of days required for z is 13 days . the answer is a . | physics |
math_qa__Tea0nlVVtqh4I41O | In what time will a train 200 meters long completely pass an electric pole, if it travels at a speed of 80kmph. Choose the correct option:
A) 7 B) 9 C) 5 D) 10 E) 3 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">80 * (5/18)</gadget>
<output>200/9 = around 22.222222</output>
<gadget id="calculator">200 / (200/9)</gadget>
<output>9</output>
<result>B</result> | B | 9 | In what time will a train 200 meters long completely pass an electric pole, if it travels at a speed of 80kmph. | {
"A": "7",
"B": "9",
"C": "5",
"D": "10",
"E": "3"
} | divide(200, multiply(80, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0) | sol . speed = [ 80 x 5 / 18 ] m / sec = 22.2 m / sec . time taken = ( 200 / 22.2 ) sec = 9 sec . answer b | physics |
math_qa__iHzrGPUMOeU39Ckk | A company organzied a help desk.there have been done 24 hrs work on software,17 hrs on help user nd 40% on other services.find the total no. of hrs have been worked on that day?
Choose the correct choice from the following answers: A) 68 B) 69 C) 70 D) 67 E) 76 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">24 + 17</gadget>
<output>41</output>
<gadget id="calculator">5 * 41</gadget>
<output>205</output>
<gadget id="calculator">205 / 3</gadget>
<output>205/3 = around 68.333333</output>
<result>A</result> | A | 68 | A company organzied a help desk.there have been done 24 hrs work on software,17 hrs on help user nd 40% on other services.find the total no. of hrs have been worked on that day? | {
"A": "68",
"B": "69",
"C": "70",
"D": "67",
"E": "76"
} | divide(multiply(add(const_1, const_4), add(24, 17)), const_3) | add(const_1,const_4)|add(n0,n1)|multiply(#0,#1)|divide(#2,const_3) | let total no of hrs = x they have done 24 + 17 = 41 40 % of x is 40 / 100 = 2 / 5 x = 41 + 2 x / 5 x = 68.3 answer : a | physics |
math_qa__MCNBUK0u3RWMCOIo | The true discount on a bill of Rs. 2360 is Rs. 360. What is the banker's discount? Choose the most appropriate option
A) rs . 432 B) rs . 425 C) rs . 412 D) rs . 442 E) none of these | <gadget id="calculator">2_360 - 360</gadget>
<output>2_000</output>
<gadget id="calculator">360 / 2_000</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) * 2_360</gadget>
<output>2_124/5 = around 424.8</output>
<result>B</result> | B | 425 | The true discount on a bill of Rs. 2360 is Rs. 360. What is the banker's discount? | {
"A": "rs . 432",
"B": "rs . 425",
"C": "rs . 412",
"D": "rs . 442",
"E": "none of these"
} | multiply(divide(360, subtract(2360, 360)), 2360) | subtract(n0,n1)|divide(n1,#0)|multiply(n0,#1)| | "explanation : f = rs . 2360 td = rs . 360 pw = f - td = 2360 - 360 = rs . 2000 true discount is the simple interest on the present value for unexpired time = > simple interest on rs . 2000 for unexpired time = rs . 360 banker ' s discount is the simple interest on the face value of the bill for unexpired time = simple interest on rs . 2360 for unexpired time = 360 / 2000 × 2360 = 0.18 × 2160 = rs . 425 answer : option b" | gain |
math_qa__ZlZw0FXetW26FY6e | 15 litres of mixture contains 20% alcohol and the rest water. If 2litres of water be mixed with it, the percentage of alcohol in the new mixture would be? Choose the correct choice from the following options:
A) 16.67 % B) 23 % C) 18.3 % D) 17.64 % E) 21.23 % | <gadget id="calculator">15 + 2</gadget>
<output>17</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 15</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">17 - 14</gadget>
<output>3</output>
<gadget id="calculator">3 / 17</gadget>
<output>3/17 = around 0.176471</output>
<gadget id="calculator">(3/17) * 100</gadget>
<output>300/17 = around 17.647059</output>
<result>D</result> | D | 17.64 | 15 litres of mixture contains 20% alcohol and the rest water. If 2litres of water be mixed with it, the percentage of alcohol in the new mixture would be? | {
"A": "16.67 %",
"B": "23 %",
"C": "18.3 %",
"D": "17.64 %",
"E": "21.23 %"
} | multiply(divide(subtract(add(15, 2), add(multiply(divide(subtract(const_100, 20), const_100), 15), 2)), add(15, 2)), const_100) | add(n0,n2)|subtract(const_100,n1)|divide(#1,const_100)|multiply(n0,#2)|add(n2,#3)|subtract(#0,#4)|divide(#5,#0)|multiply(#6,const_100)| | "alcohol in the 15 litres of mix . = 20 % of 15 litres = ( 20 * 15 / 100 ) = 3 litres water in it = 15 - 3 = 12 litres new quantity of mix . = 15 + 2 = 17 litres quantity of alcohol in it = 3 litres percentage of alcohol in new mix . = 3 * 100 / 17 = 17.64 % answer is d" | gain |
math_qa__M0fFV4uZuRXPW98X | Two pipes P and Q can fill a cistern in 10 and 15 minutes respectively. Both are opened together, but at the end of 2 minutes the first is turned off. How many more minutes will it take for the cistern to fill after the first pipe is turned off? Choose one: A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) + (1/15)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 2</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 15</gadget>
<output>10</output>
<result>E</result> | E | 10 | Two pipes P and Q can fill a cistern in 10 and 15 minutes respectively. Both are opened together, but at the end of 2 minutes the first is turned off. How many more minutes will it take for the cistern to fill after the first pipe is turned off? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | multiply(subtract(const_1, multiply(add(divide(const_1, 10), divide(const_1, 15)), 2)), 15) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(#2,n2)|subtract(const_1,#3)|multiply(n1,#4)| | "let x be the total time it takes for the cistern to fill . 2 / 10 + x / 15 = 1 x / 15 = 4 / 5 x = 12 after the first pipe is turned off , it takes 10 more minutes to fill the cistern . the answer is e ." | physics |
math_qa__CC0bAWsSHh92h11I | There are 16 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season? Answers.
A) 750
B) 900
C) 1050
D) 1200
E) 1350 | <gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">16 * 15</gadget>
<output>240</output>
<gadget id="calculator">240 * 10</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 / 2</gadget>
<output>1_200</output>
<result>D</result> | D | 1,200 | There are 16 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season? | {
"A": "750",
"B": "900",
"C": "1050",
"D": "1200",
"E": "1350"
} | divide(multiply(multiply(16, subtract(16, const_1)), 10), const_2) | subtract(n0,const_1)|multiply(n0,#0)|multiply(n1,#1)|divide(#2,const_2) | the number of ways to choose two teams is 16 c 2 = 16 * 15 / 2 = 120 the total number of games in the season is 10 * 120 = 1200 . the answer is d . | general |
math_qa__bHNdVAMFebdwpbPR | In an examination, the percentage of students qualified to the number of students appeared from school A is 70%. In school B, the number of students appeared is 20% more than the students appeared from school A and the number of students qualified from school B is 50% more than the students qualified from school A. What is the percentage of students qualified to the number of students appeared from school B? Options
A) 30 % B) 70 % C) 80 % D) 87.5 % E) none | <gadget id="calculator">70 - 20</gadget>
<output>50</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">50 - (1/2)</gadget>
<output>99/2 = around 49.5</output>
<gadget id="calculator">(99/2) - 12</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">50 + (75/2)</gadget>
<output>175/2 = around 87.5</output>
<result>D</result> | D | 87.5 | In an examination, the percentage of students qualified to the number of students appeared from school A is 70%. In school B, the number of students appeared is 20% more than the students appeared from school A and the number of students qualified from school B is 50% more than the students qualified from school A. What is the percentage of students qualified to the number of students appeared from school B? | {
"A": "30 %",
"B": "70 %",
"C": "80 %",
"D": "87.5 %",
"E": "none"
} | add(subtract(70, 20), subtract(subtract(50, multiply(const_0_25, const_2)), const_12)) | multiply(const_0_25,const_2)|subtract(n0,n1)|subtract(n2,#0)|subtract(#2,const_12)|add(#1,#3) | solution let number of students appeared from school a = 100 . then , number of students qualified from school a = 70 . number of students appeared from school b = 120 . number of students qualified from school b = [ 150 / 100 x 70 ] = 105 . required percentage = [ 105 / 120 x 100 ] % = 87.5 % answer d | general |
math_qa__MecEvsJxwR5WK4S8 | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 130 m long? Pick.
A) 39.2 sec
B) 35 sec
C) 44 sec
D) 40 sec
E) none of these | <gadget id="calculator">130 / 1_000</gadget>
<output>13/100 = around 0.13</output>
<gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(13/100) + (9/25)</gadget>
<output>49/100 = around 0.49</output>
<gadget id="calculator">(49/100) / 45</gadget>
<output>49/4_500 = around 0.010889</output>
<gadget id="calculator">(49/4_500) * 3_600</gadget>
<output>196/5 = around 39.2</output>
<result>A</result> | A | 39.2 | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 130 m long? | {
"A": "39.2 sec",
"B": "35 sec",
"C": "44 sec",
"D": "40 sec",
"E": "none of these"
} | multiply(divide(add(divide(130, const_1000), divide(360, const_1000)), 45), const_3600) | divide(n2,const_1000)|divide(n0,const_1000)|add(#0,#1)|divide(#2,n1)|multiply(#3,const_3600)| | "speed = 45 km / hr = 45 ã — ( 5 / 18 ) m / s = 150 / 12 = 50 / 4 = 25 / 2 m / s total distance = length of the train + length of the platform = 360 + 130 = 490 meter time taken to cross the platform = 490 / ( 25 / 2 ) = 490 ã — 2 / 25 = 39.2 seconds answer : a" | physics |
math_qa__RudpUKe8HqVrT39O | Two trains are traveling from point A to point B such that the speed of first train is 65 kmph and the speed of 2 train is 29 kmph. Where is the distance b/w A and B such that the slower train reached 5 hrs late compared to the faster?
Choose the most appropriate option:
A) 3 B) 65 C) 9 D) 5 E) 31 | <gadget id="calculator">29 * 5</gadget>
<output>145</output>
<gadget id="calculator">65 - 29</gadget>
<output>36</output>
<gadget id="calculator">145 / 36</gadget>
<output>145/36 = around 4.027778</output>
<gadget id="calculator">65 * (145/36)</gadget>
<output>9_425/36 = around 261.805556</output>
<gadget id="calculator">(9_425/36) / (145/36)</gadget>
<output>65</output>
<result>B</result> | B | 65 | Two trains are traveling from point A to point B such that the speed of first train is 65 kmph and the speed of 2 train is 29 kmph. Where is the distance b/w A and B such that the slower train reached 5 hrs late compared to the faster? | {
"A": "3",
"B": "65",
"C": "9",
"D": "5",
"E": "31"
} | speed(multiply(65, divide(multiply(29, 5), subtract(65, 29))), divide(multiply(29, 5), subtract(65, 29))) | multiply(n2,n3)|subtract(n0,n2)|divide(#0,#1)|multiply(n0,#2)|speed(#3,#2) | answer : b | physics |
math_qa__bS8ceKEXwww53xD4 | If G is to be chosen at random from the set {5,8,7,1} and K is to be chosen at random from the set {14,8,3}, what is the probability that GK will be even? Choose the correct choice from the following answers.
A) 1
B) 5
C) 8
D) 4
E) 3 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 / 12</gadget>
<output>1</output>
<result>A</result> | A | 1 | If G is to be chosen at random from the set {5,8,7,1} and K is to be chosen at random from the set {14,8,3}, what is the probability that GK will be even? | {
"A": "1",
"B": "5",
"C": "8",
"D": "4",
"E": "3"
} | divide(multiply(const_4, const_3), multiply(const_4, const_3)) | multiply(const_3,const_4)|divide(#0,#0) | method - 1 gk will be even when 1 ) g is even and k is odd , probability of g even is ( 1 / 4 ) and probability of k odd is ( 1 / 3 ) , so probability of case ( 1 ) = ( 1 / 4 ) * ( 1 / 3 ) = ( 1 / 12 ) 2 ) g is odd and k is even , probability of g odd is ( 3 / 4 ) and probability of k even is ( 2 / 3 ) , so probability of case ( 2 ) = ( 3 / 4 ) * ( 2 / 3 ) = ( 6 / 12 ) 3 ) g is even and k is even , probability of g even is ( 1 / 4 ) and probability of k even is ( 2 / 3 ) , so probability of case ( 1 ) = ( 1 / 4 ) * ( 2 / 3 ) = ( 2 / 12 ) total favorable probability = ( 1 / 12 ) + ( 6 / 12 ) + ( 2 / 12 ) = ( 12 / 12 ) = 1 answer : option a | probability |
math_qa__WOEfXLXW9jvqNtcC | The cost of painting the whole surface area of a cube at the rate of 13 paise per Sq.cm is Rs. 343.98. Then the volume of the cube is Choose the most appropriate option
A) 8500 cm 3 B) 9000 cm 3 C) 9250 cm 3 D) 9261 cm 3 E) none | <gadget id="calculator">13 / 100</gadget>
<output>13/100 = around 0.13</output>
<gadget id="calculator">343.98 / (13/100)</gadget>
<output>2_646</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">2_646 / 6</gadget>
<output>441</output>
<gadget id="calculator">441 ** (1/2)</gadget>
<output>21</output>
<gadget id="calculator">21 ** 3</gadget>
<output>9_261</output>
<result>D</result> | D | 9,261 | The cost of painting the whole surface area of a cube at the rate of 13 paise per Sq.cm is Rs. 343.98. Then the volume of the cube is | {
"A": "8500 cm 3",
"B": "9000 cm 3",
"C": "9250 cm 3",
"D": "9261 cm 3",
"E": "none"
} | volume_cube(sqrt(divide(divide(343.98, divide(13, const_100)), multiply(const_2, const_3)))) | divide(n0,const_100)|multiply(const_2,const_3)|divide(n1,#0)|divide(#2,#1)|sqrt(#3)|volume_cube(#4) | solution surface area = ( 34398 / 13 ) ‹ = › 2646 cm 3 ‹ = › 6 a 2 = 2646 ‹ = › a 2 = 441 ‹ = › a = 21 . so , volume = ( 21 x 21 x 21 ) cm 3 = 9261 cm 3 . answer d | geometry |
math_qa__CSUvT9LUtdCRou9m | A man can row 8 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man? Choose the correct choice from the following:
A) 7.82 km
B) 6 km
C) 5.76 km
D) 5.66 km
E) 10 km | <gadget id="calculator">8 + 1.2</gadget>
<output>9.2</output>
<gadget id="calculator">8 - 1.2</gadget>
<output>6.8</output>
<gadget id="calculator">9.2 * 6.8</gadget>
<output>62.56</output>
<gadget id="calculator">9.2 + 6.8</gadget>
<output>16</output>
<gadget id="calculator">62.56 / 16</gadget>
<output>3.91</output>
<gadget id="calculator">3.91 * 2</gadget>
<output>7.82</output>
<result>A</result> | A | 7.82 | A man can row 8 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man? | {
"A": "7.82 km",
"B": "6 km",
"C": "5.76 km",
"D": "5.66 km",
"E": "10 km"
} | multiply(divide(multiply(add(8, 1.2), subtract(8, 1.2)), add(add(8, 1.2), subtract(8, 1.2))), const_2) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|multiply(#0,#1)|divide(#3,#2)|multiply(#4,const_2)| | "m = 8 s = 1.2 ds = 9.2 us = 6.8 x / 9.2 + x / 6.8 = 1 x = 3.91 d = 3.91 * 2 = 7.82 answer : a" | physics |
math_qa__Jn1oOlxCOEWIwqzi | If 45-[28-{37-(15-*)}]= 56, then * is equal to: Choose the correct choice from the following options.
A) - 29 B) - 19 C) 17 D) 29 E) 39 | <gadget id="calculator">28 - 37</gadget>
<output>-9</output>
<gadget id="calculator">(-9) + 15</gadget>
<output>6</output>
<gadget id="calculator">45 - 6</gadget>
<output>39</output>
<gadget id="calculator">56 - 39</gadget>
<output>17</output>
<result>C</result> | C | 17 | If 45-[28-{37-(15-*)}]= 56, then * is equal to: | {
"A": "- 29",
"B": "- 19",
"C": "17",
"D": "29",
"E": "39"
} | subtract(56, subtract(45, add(subtract(28, 37), 15))) | subtract(n1,n2)|add(n3,#0)|subtract(n0,#1)|subtract(n4,#2)| | "45 - [ 28 - { 37 - ( 15 - * ) } ] = 56 = > 45 - [ 28 - { 37 - 15 + * } ] = 56 45 - [ 28 - 37 + 15 - * ] = 56 = > 45 [ 43 - 37 - * ] = 56 45 - [ 6 - * ] = 56 = > 45 - 6 + * = 56 39 + * = 56 = > * = 56 - 39 = 17 answer : c" | general |
math_qa__0IZrJ6TV68jeznMH | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration W of the acid in the mixture?
Choose the correct choice from the following:
A) 1 / 2 B) 1 / 3 C) 1 / 4 D) 1 / 6 E) 1 / 5 | <gadget id="calculator">150 * 30</gadget>
<output>4_500</output>
<gadget id="calculator">4_500 / 100</gadget>
<output>45</output>
<gadget id="calculator">400 * 12</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 / 100</gadget>
<output>48</output>
<gadget id="calculator">45 + 48</gadget>
<output>93</output>
<gadget id="calculator">150 + 400</gadget>
<output>550</output>
<gadget id="calculator">93 / 550</gadget>
<output>93/550 = around 0.169091</output>
<result>D</result> | D | 0.166667 | 150 ml of 30% sulphuric acid was added to approximate 400 ml of 12% sulphuric acid solution. Find the approximate concentration W of the acid in the mixture? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 6",
"E": "1 / 5"
} | divide(add(divide(multiply(150, 30), const_100), divide(multiply(400, 12), const_100)), add(150, 400)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)| | "do not need any computation 30 % - - - - - - - - - - - 21 % - - - - - - - - - 12 % if volume of both sol . were equal the concentration w would be 21 % = 1 / 5 , but 12 % is more than 3 times only possibility is 1 / 6 d" | general |
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