id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__7ynfSfjut4DC2j7a | Stacy and Heather are 5 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?. Choose the correct option:
A) 2.5 mile B) 1.9 mile C) 1.7 mile D) 1.5 mile E) 1.18 mile | <gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">24 * (1/10)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">5 - (12/5)</gadget>
<output>13/5 = around 2.6</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">(13/5) / 11</gadget>
<output>13/55 = around 0.236364</output>
<gadget id="calculator">(13/55) * 5</gadget>
<output>13/11 = around 1.181818</output>
<result>E</result> | E | 1.18 | Stacy and Heather are 5 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?. | {
"A": "2.5 mile",
"B": "1.9 mile",
"C": "1.7 mile",
"D": "1.5 mile",
"E": "1.18 mile"
} | multiply(divide(subtract(5, multiply(24, divide(add(1, 5), const_60))), add(5, add(1, 5))), 5) | add(n1,n2)|add(n2,#0)|divide(#0,const_60)|multiply(n3,#2)|subtract(n0,#3)|divide(#4,#1)|multiply(n2,#5)| | "ss - stacy ' s speed = 6 m / hr sh - heather ' s speed = 5 m / hr in 24 minutes stacy will cover = ( 24 / 60 ) * 6 = 2.4 miles now since both are walking in opposite directions , add their speeds - 6 + 5 = 11 m / hr and distance to cover is 5 - 2.4 = 2.6 time taken = distance / speed = 2.6 / 11 = 0.23 hrs heather will cover = 5 * 0.23 = 1.18 miles . answer e" | physics |
math_qa__uyvOM8yuT3BCw73P | A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 50 miles per hour. The train then travels back to Albany from Syracuse. The total travelling time of the train is 5 hours and 30 minutes. What was the average rate of speed of the train on the return trip to Albany?
Choose the correct choice from the following choices.
A) 31
B) 38.7
C) 35
D) 36
E) 39 | <gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">5 + (1/2)</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">120 / 50</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(11/2) - (12/5)</gadget>
<output>31/10 = around 3.1</output>
<gadget id="calculator">120 / (31/10)</gadget>
<output>1_200/31 = around 38.709677</output>
<result>B</result> | B | 38.7 | A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 50 miles per hour. The train then travels back to Albany from Syracuse. The total travelling time of the train is 5 hours and 30 minutes. What was the average rate of speed of the train on the return trip to Albany? | {
"A": "31",
"B": "38.7",
"C": "35",
"D": "36",
"E": "39"
} | speed(120, subtract(add(5, divide(30, const_60)), divide(120, 50))) | divide(n3,const_60)|divide(n0,n1)|add(n2,#0)|subtract(#2,#1)|speed(n0,#3) | 50 * t = 120 therefore t = 120 / 50 = 2.4 on return speed * ( 5.5 - 2.4 ) = 120 therefore t = 120 / 3.1 = 38.70 b | physics |
math_qa__oNkz02Kci2lsjlX9 | A train crosses a platform of 180 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train? Choose the correct option:
A) 30
B) 887
C) 167
D) 197
E) 161 | <gadget id="calculator">15 / 3</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">250 * 3</gadget>
<output>750</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">180 * 4</gadget>
<output>720</output>
<gadget id="calculator">750 - 720</gadget>
<output>30</output>
<result>A</result> | A | 30 | A train crosses a platform of 180 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train? | {
"A": "30",
"B": "887",
"C": "167",
"D": "197",
"E": "161"
} | subtract(multiply(250, divide(15, divide(15, const_3))), multiply(180, divide(20, divide(15, const_3)))) | divide(n1,const_3)|divide(n1,#0)|divide(n3,#0)|multiply(n2,#1)|multiply(n0,#2)|subtract(#3,#4)| | "length of the train be ‘ x ’ x + 180 / 15 = x + 250 / 20 20 x + 3600 = 15 x + 3750 5 x = 150 x = 30 m answer : a" | physics |
math_qa__UVX3Z1b0fmeKn7XP | What will be the difference between simple interest and compound interest @10% per annum on a sum of Rs. 1000 after 4 years? Pick one:
A) rs . 31 B) rs . 32.10 C) rs . 40.40 D) rs . 64.10 E) none | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 4</gadget>
<output>14_641/10_000 = around 1.4641</output>
<gadget id="calculator">(14_641/10_000) * 1_000</gadget>
<output>14_641/10 = around 1_464.1</output>
<gadget id="calculator">(14_641/10) - 1_000</gadget>
<output>4_641/10 = around 464.1</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 10_000</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 / 100</gadget>
<output>400</output>
<gadget id="calculator">(4_641/10) - 400</gadget>
<output>641/10 = around 64.1</output>
<result>D</result> | D | 64.1 | What will be the difference between simple interest and compound interest @10% per annum on a sum of Rs. 1000 after 4 years? | {
"A": "rs . 31",
"B": "rs . 32.10",
"C": "rs . 40.40",
"D": "rs . 64.10",
"E": "none"
} | subtract(subtract(multiply(power(add(divide(10, const_100), const_1), const_4), 1000), 1000), divide(multiply(4, multiply(10, 1000)), const_100)) | divide(n0,const_100)|multiply(n0,n1)|add(#0,const_1)|multiply(n2,#1)|divide(#3,const_100)|power(#2,const_4)|multiply(n1,#5)|subtract(#6,n1)|subtract(#7,#4) | solution s . i . = rs ( 1000 x 10 x 4 / 100 ) = rs . 400 . c . i . = rs . [ 1000 x ( 1 x 10 / 100 ) 4 - 1000 ] = rs . 464.10 ∴ difference = rs . ( 464.10 - 400 ) = rs . 64.10 answer d | gain |
math_qa__XI3zYWO6tikXQcwh | Two men start together to walk a certain distance, one at 4 kmph and another at 3 kmph.The former arrives half an hour before the latter. Find the distance.
Pick.
A) 6 km
B) 7 km
C) 8 km
D) 9 km
E) none of these | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>A</result> | A | 6 | Two men start together to walk a certain distance, one at 4 kmph and another at 3 kmph.The former arrives half an hour before the latter. Find the distance. | {
"A": "6 km",
"B": "7 km",
"C": "8 km",
"D": "9 km",
"E": "none of these"
} | divide(multiply(3, 4), const_2) | multiply(n0,n1)|divide(#0,const_2) | let the distance be x km . then , x / 3 - x / 4 = 1 / 2 ( 4 x - 3 x ) / 12 = 1 / 2 x = 6 km answer : a | physics |
math_qa__3FeEJNBJ8ZOLHrzH | Cubes with each side one inch long are glued together to form a larger cube. The larger cube's face is painted with red color and the entire assembly is taken apart. 25 small cubes are found with no paints on them . How many of unit cubes have at least one face that is painted red? Pick one
A) 64 B) 72 C) 86 D) 98 E) 100 | <gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 ** 3</gadget>
<output>125</output>
<gadget id="calculator">125 - 25</gadget>
<output>100</output>
<result>E</result> | E | 100 | Cubes with each side one inch long are glued together to form a larger cube. The larger cube's face is painted with red color and the entire assembly is taken apart. 25 small cubes are found with no paints on them . How many of unit cubes have at least one face that is painted red? | {
"A": "64",
"B": "72",
"C": "86",
"D": "98",
"E": "100"
} | subtract(power(add(const_1, add(const_1, const_3)), const_3), 25) | add(const_1,const_3)|add(#0,const_1)|power(#1,const_3)|subtract(#2,n0)| | "use the options . the options which after getting added to 25 shows a cube of a number could be right . here 64 + 25 = 89 72 + 25 = 97 86 + 25 = 111 98 + 25 = 123 100 + 25 = 125 - - - ( 5 * 5 * 5 ) so we have 100 as the answer ! e" | geometry |
math_qa__JXXFXb87szQvOngf | There are 35 kids in a play school. 26 kids play with white color balls and some kids play with yellow color balls and 19 kids play with both color balls. How many kids use yellow color balls?
Choose the correct choice
A) 12
B) 32
C) 5
D) 28
E) 35 | <gadget id="calculator">26 - 19</gadget>
<output>7</output>
<gadget id="calculator">35 - 7</gadget>
<output>28</output>
<result>D</result> | D | 28 | There are 35 kids in a play school. 26 kids play with white color balls and some kids play with yellow color balls and 19 kids play with both color balls. How many kids use yellow color balls? | {
"A": "12",
"B": "32",
"C": "5",
"D": "28",
"E": "35"
} | subtract(35, subtract(26, 19)) | subtract(n1,n2)|subtract(n0,#0) | explanation : n ( aub ) = n ( a ) + n ( b ) - n ( anb ) . . . . ( 1 ) n ( a ) = number of kids playing with white color balls = 26 n ( aub ) = total number of kids in the play school = 35 n ( anb ) = number of kids playing with both white and yellow color balls = 19 we have to find , n ( b ) = number of kids playing with yellow color balls from ( 1 ) , 35 = 26 + n ( b ) - 19 n ( b ) = 35 + 19 - 26 = 28 hence , answer is 28 kids play with yellow color balls . answer : d | other |
math_qa__DF0KPhX0BHCJ59O8 | In the rectangular coordinate system, what is the x-intercept of a line passing through (10, 3) and (−8, −6)? Choose the correct choice from the following options.
A) 4 B) 2 C) 0 D) − 2 E) − 4 | <gadget id="calculator">-6</gadget>
<output>-6</output>
<gadget id="calculator">(-6) - 3</gadget>
<output>-9</output>
<gadget id="calculator">-8</gadget>
<output>-8</output>
<gadget id="calculator">(-8) - 10</gadget>
<output>-18</output>
<gadget id="calculator">(-9) / (-18)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 10</gadget>
<output>5</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">2 / (1/2)</gadget>
<output>4</output>
<result>A</result> | A | 4 | In the rectangular coordinate system, what is the x-intercept of a line passing through (10, 3) and (−8, −6)? | {
"A": "4",
"B": "2",
"C": "0",
"D": "− 2",
"E": "− 4"
} | divide(subtract(multiply(divide(subtract(negate(6), 3), subtract(negate(8), 10)), 10), 3), divide(subtract(negate(6), 3), subtract(negate(8), 10))) | negate(n3)|negate(n2)|subtract(#0,n1)|subtract(#1,n0)|divide(#2,#3)|multiply(n0,#4)|subtract(#5,n1)|divide(#6,#4)| | "slope = rise / run = 9 / 18 = 1 / 2 the equation of the line is y = ( 1 / 2 ) x + b 3 = ( 1 / 2 ) ( 10 ) + b b = - 2 the equation of the line is y = ( 1 / 2 ) x - 2 to find the x - intercept , let y = 0 : 0 = ( 1 / 2 ) x - 2 x = 4 the answer is a ." | general |
math_qa__dR0H4QsSFwVMy1yu | In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 21 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp? Answers:
A) 70 B) 245 C) 150 D) 35 E) 350 | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(7/10) * (1/5)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">21 / (7/50)</gadget>
<output>150</output>
<result>C</result> | C | 150 | In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 21 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp? | {
"A": "70",
"B": "245",
"C": "150",
"D": "35",
"E": "350"
} | divide(21, multiply(divide(subtract(const_100, 30), const_100), divide(20, const_100))) | divide(n0,const_100)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#2,#0)|divide(n2,#3)| | "since 30 % of the boys from school a study science , then 70 % of the boys from school a do not study science and since 20 % of the total number of boys are from school a , then 0.2 * 0.7 = 0.14 , or 14 % of the boys in the camp are from school a and do not study science . we are told that this number equals to 21 , so 0.14 * { total } = 21 - - > { total } = 150 . answer : c ." | gain |
math_qa__eDbeIhCIIKT8ciGv | A train 110 m long is running with a speed of 80 km/hr. In what time will it pass a man who is running at 8 km/hr in the direction opposite to that in which the train is going? Select:
A) 5
B) 6
C) 4.5
D) 8
E) 9 | <gadget id="calculator">80 + 8</gadget>
<output>88</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">88 * (5/18)</gadget>
<output>220/9 = around 24.444444</output>
<gadget id="calculator">110 / (220/9)</gadget>
<output>9/2 = around 4.5</output>
<result>C</result> | C | 4.5 | A train 110 m long is running with a speed of 80 km/hr. In what time will it pass a man who is running at 8 km/hr in the direction opposite to that in which the train is going? | {
"A": "5",
"B": "6",
"C": "4.5",
"D": "8",
"E": "9"
} | divide(110, multiply(add(80, 8), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 80 + 8 = 88 km / hr . = 88 * 5 / 18 = 220 / 9 m / sec . time taken to pass the men = 110 * 9 / 220 = 4.5 sec . answer : option c" | physics |
math_qa__gOzHbOIP3zOFFSpE | Set A contains all the even numbers between 6 and 50 inclusive. Set B contains all the even numbers between 106 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? Select the correct option.
A) 2300 B) 2550 C) 5050 D) 6275 E) 11325 | <gadget id="calculator">106 - 6</gadget>
<output>100</output>
<gadget id="calculator">50 - 6</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<gadget id="calculator">22 + 1</gadget>
<output>23</output>
<gadget id="calculator">100 * 23</gadget>
<output>2_300</output>
<result>A</result> | A | 2,300 | Set A contains all the even numbers between 6 and 50 inclusive. Set B contains all the even numbers between 106 and 150 inclusive. What is the difference between the sum of elements of set B and the sum of the elements of set A? | {
"A": "2300",
"B": "2550",
"C": "5050",
"D": "6275",
"E": "11325"
} | multiply(subtract(106, 6), add(divide(subtract(50, 6), const_2), const_1)) | subtract(n1,n0)|subtract(n2,n0)|divide(#0,const_2)|add(#2,const_1)|multiply(#3,#1)| | "set a contains 6 , 8 , . . . 50 set b contains 102 , 104 , 106 . . . 150 number of terms in each set = 23 difference between corresponding terms in set a and b = 100 difference between sum of set b and set a = 100 * 23 = 2300 answer a" | general |
math_qa__NuXpLk5vXa27XFgI | David completes a piece of work in 5 days, John completes the same work in 9 days. If both of them work together, then the number of days required to complete the work is? Select:
A) 3.2 days B) 8 days C) 10 days D) 12 days E) 14 days | <gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/9) + (1/5)</gadget>
<output>14/45 = around 0.311111</output>
<gadget id="calculator">1 / (14/45)</gadget>
<output>45/14 = around 3.214286</output>
<result>A</result> | A | 3.2 | David completes a piece of work in 5 days, John completes the same work in 9 days. If both of them work together, then the number of days required to complete the work is? | {
"A": "3.2 days",
"B": "8 days",
"C": "10 days",
"D": "12 days",
"E": "14 days"
} | inverse(add(inverse(9), inverse(5))) | inverse(n1)|inverse(n0)|add(#0,#1)|inverse(#2) | ifa can complete a work in x days and b can complete the same work in y days , then , both of them together can complete the work in x y / x + y days . that is , the required no . of days = 5 × 9 / 14 = 3.2 days answer : a | physics |
math_qa__IpxIK7kvmk6djUsF | The citizens of planet nigiet are 8 fingered and have thus developed their decimal system in base 8. A certain street in nigiet contains 1000 buildings numbered 1 to 1000 in base 8. How many 3s are used in numbering these buildings?Express your answer in base 10
Choose the most appropriate option:
A) 192 B) 200 C) 196 D) 198 E) none | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">3 * 64</gadget>
<output>192</output>
<result>A</result> | A | 192 | The citizens of planet nigiet are 8 fingered and have thus developed their decimal system in base 8. A certain street in nigiet contains 1000 buildings numbered 1 to 1000 in base 8. How many 3s are used in numbering these buildings?Express your answer in base 10 | {
"A": "192",
"B": "200",
"C": "196",
"D": "198",
"E": "none"
} | multiply(3, power(8, const_2)) | power(n0,const_2)|multiply(#0,n6)| | "explanation : number 3 in 1 - 100 comes 20 times . 101 - 200 - > 20 times 201 - 300 - > 20 times 301 - 400 - > 120 times 401 - 500 - > 20 times 501 - 600 - > 20 times 601 - 700 - > 20 times 701 - 800 - > 20 times 801 - 900 - > 20 times 901 - 1000 - > 20 times total times : 300 times ( any no . from 1 to 9 except 0 will occur 300 times ) 8 based planet . . then 3 * 8 ( 2 ) + 0 * 8 ( 1 ) + 0 * 8 ( 0 ) = 192 answer : a" | physics |
math_qa__v1bdzmeepSEkJYKw | 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 4 days, working 15 hours a day, the number of men required? Choose the correct choice
A) 15 days B) 12 days C) 16 days D) 18 days E) 20 days | <gadget id="calculator">12 * 10</gadget>
<output>120</output>
<gadget id="calculator">120 * 8</gadget>
<output>960</output>
<gadget id="calculator">4 * 15</gadget>
<output>60</output>
<gadget id="calculator">960 / 60</gadget>
<output>16</output>
<result>C</result> | C | 16 | 12 men work 8 hours per day to complete the work in 10 days. To complete the same work in 4 days, working 15 hours a day, the number of men required? | {
"A": "15 days",
"B": "12 days",
"C": "16 days",
"D": "18 days",
"E": "20 days"
} | divide(multiply(multiply(12, 10), 8), multiply(4, 15)) | multiply(n0,n2)|multiply(n3,n4)|multiply(n1,#0)|divide(#2,#1) | that is , 1 work done = 12 × 8 × 10 then , 12 8 × 10 = ? × 15 × 6 ? ( i . e . no . of men required ) = 12 × 8 × 10 / 15 × 6 = 16 days c ) | physics |
math_qa__rXAjx8CTEsvBEtBS | When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 3. What is the value of 13y – x ? Answers
A) 1 B) 0 C) - 1 D) - 2 E) - 4 | <gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">2 * 11</gadget>
<output>22</output>
<gadget id="calculator">24 - 22</gadget>
<output>2</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">13 * (5/2)</gadget>
<output>65/2 = around 32.5</output>
<gadget id="calculator">11 * (5/2)</gadget>
<output>55/2 = around 27.5</output>
<gadget id="calculator">(55/2) + 4</gadget>
<output>63/2 = around 31.5</output>
<gadget id="calculator">(65/2) - (63/2)</gadget>
<output>1</output>
<result>A</result> | A | 1 | When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 3. What is the value of 13y – x ? | {
"A": "1",
"B": "0",
"C": "- 1",
"D": "- 2",
"E": "- 4"
} | subtract(multiply(13, divide(subtract(multiply(2, 4), 3), subtract(multiply(8, 3), multiply(2, 11)))), add(multiply(11, divide(subtract(multiply(2, 4), 3), subtract(multiply(8, 3), multiply(2, 11)))), 4)) | multiply(n1,n2)|multiply(n3,n4)|multiply(n0,n2)|subtract(#0,n5)|subtract(#1,#2)|divide(#3,#4)|multiply(n6,#5)|multiply(n0,#5)|add(n1,#7)|subtract(#6,#8)| | "( 1 ) x = 11 y + 4 ( 2 ) 2 x = 24 y + 3 let ' s subtract equation ( 1 ) from equation ( 2 ) . 13 y - 1 = x 13 y - x = 1 the answer is a ." | general |
math_qa__oxAqliuQXQA7fbMK | A money lender lent Rs. 800 at 3% per year and Rs. 1400 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years.
Choices.
A) 3.5
B) 3.72
C) 4
D) 4.25
E) 4.5 | <gadget id="calculator">3 * 800</gadget>
<output>2_400</output>
<gadget id="calculator">2_400 / 100</gadget>
<output>24</output>
<gadget id="calculator">1_400 * 5</gadget>
<output>7_000</output>
<gadget id="calculator">7_000 / 100</gadget>
<output>70</output>
<gadget id="calculator">24 + 70</gadget>
<output>94</output>
<gadget id="calculator">350 / 94</gadget>
<output>175/47 = around 3.723404</output>
<result>B</result> | B | 3.72 | A money lender lent Rs. 800 at 3% per year and Rs. 1400 at 5% per year. The amount should be returned to him when the total interest comes to Rs. 350. Find the number of years. | {
"A": "3.5",
"B": "3.72",
"C": "4",
"D": "4.25",
"E": "4.5"
} | divide(350, add(divide(multiply(3, 800), const_100), divide(multiply(1400, 5), const_100))) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|divide(n4,#4)| | ( 800 xtx 3 / 100 ) + ( 1400 xtx 5 / 100 ) = 350 â † ’ t = 3.72 answer b | gain |
math_qa__nZUclvVi7srJGZl7 | If 3x – 5y = 5 and x/x+y=5/7, then what is the value of x – y? Select the correct option:
A) 9 B) 6 C) 4 D) 3 E) none of these | <gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">1 / (5/7)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) - 1</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 5</gadget>
<output>2</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">5 / 1</gadget>
<output>5</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<result>D</result> | D | 3 | If 3x – 5y = 5 and x/x+y=5/7, then what is the value of x – y? | {
"A": "9",
"B": "6",
"C": "4",
"D": "3",
"E": "none of these"
} | subtract(divide(5, subtract(3, multiply(subtract(inverse(divide(5, 7)), const_1), 5))), multiply(subtract(inverse(divide(5, 7)), const_1), divide(5, subtract(3, multiply(subtract(inverse(divide(5, 7)), const_1), 5))))) | divide(n1,n4)|inverse(#0)|subtract(#1,const_1)|multiply(n1,#2)|subtract(n0,#3)|divide(n1,#4)|multiply(#5,#2)|subtract(#5,#6) | 3 x – 5 y = 5 . . . ( i ) and xx + y = 57 xx + y = 57 ⇒ 7 x = 5 x + 5 y ⇒ 2 x = 5 y . . . ( ii ) from ( i ) and ( ii ) , x = 5 and y = 2 ∴ x – y = 3 answer d | general |
math_qa__rEx6QaSPePzRpqYK | John borrowed 3 soccer boots from Jake, and forgot them on the field, if peter came across a total of 15 boots on the field Jake's boots inclusive, and he took 4 boots at random, what is the probability that Jake's boots were not amongst the 4 taken?. Choices
A) 12 / 91 B) 3 / 15 C) 12 / 15 D) 33 / 91 E) 3 / 91 | <gadget id="calculator">15 - 3</gadget>
<output>12</output>
<gadget id="calculator">binomial(12, 4)</gadget>
<output>495</output>
<gadget id="calculator">binomial(15, 4)</gadget>
<output>1_365</output>
<gadget id="calculator">495 / 1_365</gadget>
<output>33/91 = around 0.362637</output>
<result>D</result> | D | 0.362637 | John borrowed 3 soccer boots from Jake, and forgot them on the field, if peter came across a total of 15 boots on the field Jake's boots inclusive, and he took 4 boots at random, what is the probability that Jake's boots were not amongst the 4 taken?. | {
"A": "12 / 91",
"B": "3 / 15",
"C": "12 / 15",
"D": "33 / 91",
"E": "3 / 91"
} | divide(choose(subtract(15, 3), 4), choose(15, 4)) | choose(n1,n2)|subtract(n1,n0)|choose(#1,n2)|divide(#2,#0) | since jake owns 3 of the boots , the subset from which the 4 boots should be chosen are the 12 boots not owned by jake from the universe of 15 . the first boot can be one of the 12 from the 15 with probability 12 / 15 . the second boot can be one of the 11 from the 14 remaining with probability 11 / 14 . the third boot can be one of the 10 from the 13 remaining with probability 10 / 13 . the fourth boot can be one of the 9 from the 12 remaining with probability 9 / 12 . the total probability will be 12 / 15 × 11 / 14 × 10 / 13 × 9 / 12 . on cancellation , this comes to 33 / 91 . thus , the answer is d - 33 / 91 | probability |
math_qa__YzCEUBf4wZzGnF0p | A student needs 30% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 40 marks, find the maximum marks set for the test. Choose one
A) 400 B) 500 C) 600 D) 700 E) 800 | <gadget id="calculator">80 + 40</gadget>
<output>120</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">120 / (3/10)</gadget>
<output>400</output>
<result>A</result> | A | 400 | A student needs 30% of the marks on a test to pass the test. If the student gets 80 marks and fails the test by 40 marks, find the maximum marks set for the test. | {
"A": "400",
"B": "500",
"C": "600",
"D": "700",
"E": "800"
} | divide(add(80, 40), divide(30, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1) | 30 % = 120 marks 1 % = 4 marks 100 % = 400 marks the answer is a . | gain |
math_qa__5McQOGObCvjisWCw | he average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 75 kg. What might be the weight of the new person ? Select.
A) 75 kg B) 95 kg C) 45 kg D) 85 kg E) 25 kg | <gadget id="calculator">2.5 * 8</gadget>
<output>20</output>
<gadget id="calculator">20 + 75</gadget>
<output>95</output>
<result>B</result> | B | 95 | he average weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 75 kg. What might be the weight of the new person ? | {
"A": "75 kg",
"B": "95 kg",
"C": "45 kg",
"D": "85 kg",
"E": "25 kg"
} | add(multiply(2.5, 8), 75) | multiply(n0,n1)|add(n2,#0)| | "explanation : total weight increased = ( 8 x 2.5 ) kg = 20 kg . weight of new person = ( 75 + 20 ) kg = 95 kg . answer : b" | general |
math_qa__SuSUEOmWj3WACkXT | A rectangle A has an area of 30 square centimeters. Square B has a perimeter of 16 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B?
Pick:
A) 9 / 30
B) 14 / 30
C) 4 / 9
D) 3 / 5
E) 6 / 25 | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">30 - 16</gadget>
<output>14</output>
<gadget id="calculator">14 / 30</gadget>
<output>7/15 = around 0.466667</output>
<result>B</result> | B | 0.466667 | A rectangle A has an area of 30 square centimeters. Square B has a perimeter of 16 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B? | {
"A": "9 / 30",
"B": "14 / 30",
"C": "4 / 9",
"D": "3 / 5",
"E": "6 / 25"
} | divide(subtract(30, square_area(square_edge_by_perimeter(16))), 30) | square_edge_by_perimeter(n1)|square_area(#0)|subtract(n0,#1)|divide(#2,n0) | i guess it ' s mean that square b is placed within rectangle a entirely . since , the perimeter of b is 16 , then its side is 16 / 4 = 4 and the area is 4 ^ 2 = 16 ; empty space between the squares is 30 - 16 = 14 square centimeters , so if a random point is in this area then it wo n ' t be within square b : p = favorable / total = 14 / 30 . answer : b . | geometry |
math_qa__olYxRWDT5NZ07ytG | A garden center sells a certain grass seed in 5-pound bags at $13.85 per bag, 10-pound bags at $20.40 per bag, and 25-pound bags $32.25 per bag. If a customer is to buy at least 65 pounds of the grass seed, but no more than 80 pounds, what is the least possible cost of the grass seed that the customer will buy? Pick:
A) $ 94.03
B) $ 96.75
C) $ 98.75
D) $ 102.07
E) $ 105.3 | <gadget id="calculator">2 * 32.25</gadget>
<output>64.5</output>
<gadget id="calculator">1 * 20.4</gadget>
<output>20.4</output>
<gadget id="calculator">64.5 + 20.4</gadget>
<output>84.9</output>
<gadget id="calculator">1 * 13.85</gadget>
<output>13.85</output>
<gadget id="calculator">84.9 + 13.85</gadget>
<output>98.75</output>
<result>C</result> | C | 98.75 | A garden center sells a certain grass seed in 5-pound bags at $13.85 per bag, 10-pound bags at $20.40 per bag, and 25-pound bags $32.25 per bag. If a customer is to buy at least 65 pounds of the grass seed, but no more than 80 pounds, what is the least possible cost of the grass seed that the customer will buy? | {
"A": "$ 94.03",
"B": "$ 96.75",
"C": "$ 98.75",
"D": "$ 102.07",
"E": "$ 105.3"
} | add(add(multiply(const_2, 32.25), multiply(const_1, 20.40)), multiply(const_1, 13.85)) | multiply(n5,const_2)|multiply(n3,const_1)|multiply(n1,const_1)|add(#0,#1)|add(#3,#2)| | "there can be 2 cases 1 ) 25 + 25 + 10 + 5 = $ 98.75 or 2 ) 25 + 25 + 25 = $ 96.75 c" | general |
math_qa__vO4beuB3JwOMXHhd | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 20. Find the sum : Choices:
A) 4500 B) 7500 C) 5000 D) 8000 E) none of these | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">2 * (1/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">20 / (1/400)</gadget>
<output>8_000</output>
<result>D</result> | D | 8,000 | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 20. Find the sum : | {
"A": "4500",
"B": "7500",
"C": "5000",
"D": "8000",
"E": "none of these"
} | divide(20, subtract(power(add(const_1, divide(5, const_100)), 2), add(const_1, multiply(2, divide(5, const_100))))) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|add(#2,const_1)|power(#1,n1)|subtract(#4,#3)|divide(n2,#5)| | "sol . ( d ) let the sum be 100 . therefore , si = 100 × 5 × 2100 = 10100 × 5 × 2100 = 10 and ci = 100 ( 1 + 5100 ) 2 − 100100 ( 1 + 5100 ) 2 − 100 ∴ = 100 × 21 × 2120 × 20 − 100 = 414 = 100 × 21 × 2120 × 20 − 100 = 414 difference of ci and si = 41 ⁄ 4 - 10 = 1 ⁄ 4 if the difference is 1 ⁄ 4 , the sum = 100 = > if the difference is 20 , the sum = 400 × 20 = 8000 answer d" | gain |
math_qa__EFkBvbs9vdehKZnt | If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ?
Select the correct option.
A) rs . 12 B) rs . 16 C) rs . 14 D) rs . 10 E) rs . 18 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 3</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + 3</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(7/2) - (10/3)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 8_400</gadget>
<output>1_400</output>
<gadget id="calculator">1_400 / 100</gadget>
<output>14</output>
<result>C</result> | C | 14 | If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ? | {
"A": "rs . 12",
"B": "rs . 16",
"C": "rs . 14",
"D": "rs . 10",
"E": "rs . 18"
} | divide(multiply(subtract(add(divide(1, 2), 3), add(divide(1, 3), 3)), 8400), const_100) | divide(n1,n2)|divide(n1,n0)|add(n0,#0)|add(n0,#1)|subtract(#2,#3)|multiply(n6,#4)|divide(#5,const_100)| | "required difference = [ 3 ½ % of rs . 8400 ] – [ 3 1 / 3 % of rs . 8400 ] = [ ( 7 / 20 - ( 10 / 3 ) ] % of rs . 8400 = 1 / 6 % of rs . 8400 = rs . [ ( 1 / 6 ) 8 ( 1 / 100 ) * 8400 ] = rs . 14 . answer is c ." | general |
math_qa__Ba77pj1yWN3ZhSRy | Find (7x + 8y ) / (x-2y) if x/2y = 3/2 ?
Choose the correct choice from the following options: A) 24 B) 25 C) 26 D) 27 E) 29 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">21 + 8</gadget>
<output>29</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<gadget id="calculator">29 / 1</gadget>
<output>29</output>
<result>E</result> | E | 29 | Find (7x + 8y ) / (x-2y) if x/2y = 3/2 ? | {
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "29"
} | divide(add(multiply(multiply(divide(3, 2), 2), 7), 8), subtract(multiply(divide(3, 2), 2), 2)) | divide(n4,n2)|multiply(n2,#0)|multiply(n0,#1)|subtract(#1,n2)|add(n1,#2)|divide(#4,#3) | x / 2 y = 3 / 2 = > x = 6 y / 2 = 3 y = > ( 7 x + 8 y ) / ( x - 2 y ) = ( ( 7 * ( 3 y ) ) + 8 y ) / ( 3 y - 2 y ) = > 29 y / y = 29 answer : e | general |
math_qa__7J4wj8Db5YEIArN9 | Kramer can pack 10 boxes of cigarettes per minute. If there are 5 boxes of cigarettes in one case, how many cases can Kramer pack in 2 hours? Choose the correct choice from the following answers:
A) 100 B) 120 C) 240 D) 150 E) 200 | <gadget id="calculator">60 * 2</gadget>
<output>120</output>
<gadget id="calculator">120 * 10</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 5</gadget>
<output>240</output>
<result>C</result> | C | 240 | Kramer can pack 10 boxes of cigarettes per minute. If there are 5 boxes of cigarettes in one case, how many cases can Kramer pack in 2 hours? | {
"A": "100",
"B": "120",
"C": "240",
"D": "150",
"E": "200"
} | divide(multiply(multiply(const_60, 2), 10), 5) | multiply(n2,const_60)|multiply(n0,#0)|divide(#1,n1) | kramer can pack 10 boxes per min . therefore in 2 hrs ( 120 mins ) he can pack 120 * 10 = 1200 boxes . if there are 5 boxes in one case then then the total number of cases packed by kramer = 1200 / 5 = 240 answer is c | physics |
math_qa__97wttkovX2xQwVNW | List D consists of 12 consecutive integers. If -4 is the least integer in list D, what is the range of positive integers in list D? Choose the correct choice from the following.
A) 5 B) 6 C) 7 D) 11 E) 12 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 - 4</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<result>B</result> | B | 6 | List D consists of 12 consecutive integers. If -4 is the least integer in list D, what is the range of positive integers in list D? | {
"A": "5",
"B": "6",
"C": "7",
"D": "11",
"E": "12"
} | subtract(subtract(subtract(12, const_1), 4), const_1) | subtract(n0,const_1)|subtract(#0,n1)|subtract(#1,const_1) | since - 4 is the least integer in list d , then 7 is the largest integer in that list . thus the range of the positive integers in the list is 7 - 1 = 6 . answer : b . | general |
math_qa__X4LCabzBCee6YEKy | The ratio of the volumes of two cubes is 729 : 1000. What is the ratio of their total surface areas? Choose the correct choice from the following answers:
A) 1 : 12
B) 81 : 13
C) 46 : 51
D) 86 : 16
E) 56 : 13 | <gadget id="calculator">729 / 1_000</gadget>
<output>729/1_000 = around 0.729</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(729/1_000) ** (1/3)</gadget>
<output>9/10 = around 0.9</output>
<result>C</result> | C | 0.901961 | The ratio of the volumes of two cubes is 729 : 1000. What is the ratio of their total surface areas? | {
"A": "1 : 12",
"B": "81 : 13",
"C": "46 : 51",
"D": "86 : 16",
"E": "56 : 13"
} | power(divide(729, 1000), divide(const_1, const_3)) | divide(n0,n1)|divide(const_1,const_3)|power(#0,#1)| | "ratio of the sides = ³ √ 729 : ³ √ 1000 = 9 : 10 ratio of surface areas = 92 : 102 = 46 : 51 answer : c" | geometry |
math_qa__aODfseybbHiBVDW8 | The average weight of 9 person's increases by 5.5 kg when a new person comes in place of one of them weighing 86 kg. What might be the weight of the new person? Choose the correct choice from the following
A) 72 kg B) 77.5 kg C) 135.5 kg D) data inadequate E) none of these | <gadget id="calculator">9 * 5.5</gadget>
<output>49.5</output>
<gadget id="calculator">49.5 + 86</gadget>
<output>135.5</output>
<result>C</result> | C | 135.5 | The average weight of 9 person's increases by 5.5 kg when a new person comes in place of one of them weighing 86 kg. What might be the weight of the new person? | {
"A": "72 kg",
"B": "77.5 kg",
"C": "135.5 kg",
"D": "data inadequate",
"E": "none of these"
} | add(multiply(9, 5.5), 86) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 9 x 5.5 ) kg = 49.5 kg . weight of new person = ( 86 + 49.5 ) kg = 135.5 kg . answer : option c" | general |
math_qa__MKIBuhmhZBiUG29f | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 50 more than the correct answer. Find the number. Choose the correct option
A) 96 B) 280 C) 384 D) 400 E) 500 | <gadget id="calculator">50 * 16</gadget>
<output>800</output>
<gadget id="calculator">800 * 6</gadget>
<output>4_800</output>
<gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">80 - 30</gadget>
<output>50</output>
<gadget id="calculator">4_800 / 50</gadget>
<output>96</output>
<result>A</result> | A | 96 | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 50 more than the correct answer. Find the number. | {
"A": "96",
"B": "280",
"C": "384",
"D": "400",
"E": "500"
} | divide(multiply(multiply(50, 16), 6), subtract(multiply(5, 16), multiply(5, 6))) | multiply(n1,n4)|multiply(n0,n1)|multiply(n0,n3)|multiply(n3,#0)|subtract(#1,#2)|divide(#3,#4)| | "explanation : let the number be x . 5 * x / 6 = 5 * x / 16 + 50 25 * x / 48 = 50 x = 96 answer a" | general |
math_qa__FBCqsZdPJwfaC1sd | Two numbers N and 12 have LCM = 42 and GCF = 6. Find N. Choose the correct option
A) 35 B) 56 C) 21 D) 87 E) 24 | <gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">252 / 12</gadget>
<output>21</output>
<result>C</result> | C | 21 | Two numbers N and 12 have LCM = 42 and GCF = 6. Find N. | {
"A": "35",
"B": "56",
"C": "21",
"D": "87",
"E": "24"
} | divide(multiply(42, 6), 12) | multiply(n1,n2)|divide(#0,n0)| | "the product of two integers is equal to the product of their lcm and gcf . hence . 12 * n = 42 * 6 n = 42 * 6 / 12 = 21 correct answer c" | physics |
math_qa__5y4BbDD5LxJnbEh5 | Ajay spends 45% of his monthly income on household items, 25% of his monthly income on buying cloths, 7.5% of his monthly income on medicines and saves the remaining amount which is Rs. 9000. Find his monthly income. Choose the correct choice:
A) rs . 40000
B) rs . 36000
C) rs . 50000
D) rs . 45000
E) none of these | <gadget id="calculator">45 + 25</gadget>
<output>70</output>
<gadget id="calculator">70 + 7.5</gadget>
<output>77.5</output>
<gadget id="calculator">100 - 77.5</gadget>
<output>22.5</output>
<gadget id="calculator">22.5 / 100</gadget>
<output>0.225</output>
<gadget id="calculator">9_000 / 0.225</gadget>
<output>40_000</output>
<result>A</result> | A | 40,000 | Ajay spends 45% of his monthly income on household items, 25% of his monthly income on buying cloths, 7.5% of his monthly income on medicines and saves the remaining amount which is Rs. 9000. Find his monthly income. | {
"A": "rs . 40000",
"B": "rs . 36000",
"C": "rs . 50000",
"D": "rs . 45000",
"E": "none of these"
} | divide(9000, divide(subtract(const_100, add(add(45, 25), 7.5)), const_100)) | add(n0,n1)|add(n2,#0)|subtract(const_100,#1)|divide(#2,const_100)|divide(n3,#3)| | "let the monthly income of ajay be rs . x savings of ajay = x - ( 45 + 25 + 7.5 ) / 100 * x = 22.5 / 100 x 22.5 / 100 x = 9000 x = 40000 . answer : a" | gain |
math_qa__OFDB1mvFpB1Av1MX | The length of the bridge, which a train 145 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Select
A) 200 m B) 230 m C) 245 m D) 250 m E) 270 m | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 145</gadget>
<output>230</output>
<result>B</result> | B | 230 | The length of the bridge, which a train 145 metres long and travelling at 45 km/hr can cross in 30 seconds, is: | {
"A": "200 m",
"B": "230 m",
"C": "245 m",
"D": "250 m",
"E": "270 m"
} | subtract(multiply(divide(multiply(45, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 145) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "let the length of the bridge : l the equation now is l + 145 / 12.5 m / s ( 45 km / hr or 12.5 m / s ) = 30 solving , l = 230 m answer : b" | physics |
math_qa__MZPBM8mm2LIuWJd0 | How many diagonals does a polygon with 19 sides have, if one of its vertices does not connect to any diagonal? Choose the correct choice from the following answers
A) 135 B) 125 C) 120 D) 110 E) 140 | <gadget id="calculator">19 - 1</gadget>
<output>18</output>
<gadget id="calculator">18 - 3</gadget>
<output>15</output>
<gadget id="calculator">18 * 15</gadget>
<output>270</output>
<gadget id="calculator">270 / 2</gadget>
<output>135</output>
<result>A</result> | A | 135 | How many diagonals does a polygon with 19 sides have, if one of its vertices does not connect to any diagonal? | {
"A": "135",
"B": "125",
"C": "120",
"D": "110",
"E": "140"
} | divide(multiply(subtract(19, const_1), subtract(subtract(19, const_1), const_3)), const_2) | subtract(n0,const_1)|subtract(#0,const_3)|multiply(#0,#1)|divide(#2,const_2)| | "if i calculate it using the formulae , # diagonals = n ( n - 3 ) / 2 each vertex sends of n - 3 diagonals n = 19 - 1 then 18 * ( 18 - 3 ) / 2 = 135 correct option : a" | geometry |
math_qa__pNgSo9Jyayf169F1 | Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin? Select the correct option:
A) 22.5 years
B) 24.5 years
C) 12.5 years
D) 28.5 years
E) 29.5 years | <gadget id="calculator">9 - 7</gadget>
<output>2</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) * 7</gadget>
<output>49/2 = around 24.5</output>
<result>B</result> | B | 24.5 | Sachin is younger than Rahul by 7 years. If their ages are in the respective ratio of 7 : 9, how old is Sachin? | {
"A": "22.5 years",
"B": "24.5 years",
"C": "12.5 years",
"D": "28.5 years",
"E": "29.5 years"
} | multiply(divide(7, subtract(9, 7)), 7) | subtract(n2,n1)|divide(n0,#0)|multiply(n1,#1)| | "let rahul ' s age be x years . then , sachin ' s age = ( x - 7 ) years . therefore ( x - 7 ) / x = 7 / 9 9 x - 63 = 7 x 2 x = 63 x = 31.5 hence , sachin ' s age = ( x - 7 ) = 24.5 years . answer : b" | other |
math_qa__8XWBVjGVpsy9fK3a | A train running at the speed of 72 km/hr crosses a pole in 9 sec. What is the length of the train? Choose the correct choice from the following answers
A) 288 B) 279 C) 277 D) 272 E) 180 | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 9</gadget>
<output>180</output>
<result>E</result> | E | 180 | A train running at the speed of 72 km/hr crosses a pole in 9 sec. What is the length of the train? | {
"A": "288",
"B": "279",
"C": "277",
"D": "272",
"E": "180"
} | multiply(divide(multiply(72, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 72 * 5 / 18 = 20 m / sec length of the train = speed * time = 20 * 9 = 180 m answer : e" | physics |
math_qa__QLxyPsm3GlZlRsvY | Find the 12th term of an arithmetic progression whose first term is 2 and the common difference is 8. Choose the correct option: A) 45 B) 38 C) 44 D) 90 E) 96 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 8</gadget>
<output>88</output>
<gadget id="calculator">88 + 2</gadget>
<output>90</output>
<result>D</result> | D | 90 | Find the 12th term of an arithmetic progression whose first term is 2 and the common difference is 8. | {
"A": "45",
"B": "38",
"C": "44",
"D": "90",
"E": "96"
} | add(multiply(subtract(12, const_1), 8), 2) | subtract(n0,const_1)|multiply(n2,#0)|add(n1,#1)| | "n th term of a . p = a + ( n - 1 ) * d = 2 + ( 12 - 1 ) * 8 , = 2 + 88 = 90 . answer : d" | general |
math_qa__BKRbePMf3nNdVLed | United Telephone charges a base rate of $6.00 for service, plus an additional charge of $0.25 per minute. Atlantic Call charges a base rate of $12.00 for service, plus an additional charge of $0.20 per minute. For what number of minutes would the bills for each telephone company be the same?
Choices
A) 20 minutes B) 110 minutes C) 120 minutes D) 140 minutes E) 160 minutes | <gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">0.25 - 0.2</gadget>
<output>0.05</output>
<gadget id="calculator">6 / 0.05</gadget>
<output>120</output>
<result>C</result> | C | 120 | United Telephone charges a base rate of $6.00 for service, plus an additional charge of $0.25 per minute. Atlantic Call charges a base rate of $12.00 for service, plus an additional charge of $0.20 per minute. For what number of minutes would the bills for each telephone company be the same? | {
"A": "20 minutes",
"B": "110 minutes",
"C": "120 minutes",
"D": "140 minutes",
"E": "160 minutes"
} | divide(subtract(12.00, 6.00), subtract(0.25, 0.20)) | subtract(n2,n0)|subtract(n1,n3)|divide(#0,#1)| | "lets take number of minutesx . given that , 6 + 0.25 x = 12 + 0.2 x - > 0.05 x = 2 - > x = 120 minutes ans c" | general |
math_qa__MW2vcHNq8gg3r6qo | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A's share is? Pick:
A) rs . 7500
B) rs . 7200
C) rs . 6000
D) rs . 5750
E) rs . 6750 | <gadget id="calculator">1 * 12</gadget>
<output>12</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">18_000 / 36</gadget>
<output>500</output>
<gadget id="calculator">12 * 500</gadget>
<output>6_000</output>
<result>C</result> | C | 6,000 | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A's share is? | {
"A": "rs . 7500",
"B": "rs . 7200",
"C": "rs . 6000",
"D": "rs . 5750",
"E": "rs . 6750"
} | multiply(multiply(const_1, const_12), divide(18000, add(add(multiply(const_1, const_12), multiply(subtract(const_12, 6), const_2)), multiply(subtract(const_12, 8), const_3)))) | multiply(const_1,const_12)|subtract(const_12,n0)|subtract(const_12,n1)|multiply(#1,const_2)|multiply(#2,const_3)|add(#0,#3)|add(#5,#4)|divide(n2,#6)|multiply(#7,#0)| | "x * 12 : 2 x * 6 : 3 x * 4 1 : 1 : 1 1 / 3 * 18000 = 6000 answer : c" | gain |
math_qa__0hOnhTxMMLrXmyFg | The difference of two numbers is 1365. on dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number? Choose the correct choice from the following options
A) 240 B) 270 C) 295 D) 360 E) 365 | <gadget id="calculator">1_365 + 15</gadget>
<output>1_380</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_380 / 5</gadget>
<output>276</output>
<result>B</result> | B | 270 | The difference of two numbers is 1365. on dividing the larger number by the smaller, we get 6 as quotient and 15 as remainder. What is the smaller number? | {
"A": "240",
"B": "270",
"C": "295",
"D": "360",
"E": "365"
} | divide(add(1365, 15), subtract(6, const_1)) | add(n0,n2)|subtract(n1,const_1)|divide(#0,#1)| | "let the smallest number be x . then larger number = ( x + 1365 ) x + 1365 = 6 x + 15 = 5 x = 1350 x = 270 smaller number = 270 . answer : b" | general |
math_qa__387755QwnHd0V07C | In a 100m race, Sam beats John by 4 seconds. On the contrary, if Sam allowed John to start 24m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race?
Choices.
A) 4 seconds
B) 25 seconds
C) 19 seconds
D) 21 seconds
E) 6.25 seconds | <gadget id="calculator">100 - 24</gadget>
<output>76</output>
<gadget id="calculator">76 / 4</gadget>
<output>19</output>
<result>C</result> | C | 19 | In a 100m race, Sam beats John by 4 seconds. On the contrary, if Sam allowed John to start 24m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race? | {
"A": "4 seconds",
"B": "25 seconds",
"C": "19 seconds",
"D": "21 seconds",
"E": "6.25 seconds"
} | divide(subtract(100, 24), 4) | subtract(n0,n2)|divide(#0,n1)| | "their difference is 4 second but this difference is 0 if john allows sam to start the race from 24 m ahead . that means jhon was 24 m away from finishing line when they started together . so he will cover 24 m in 4 seconds . so his speed = 24 / 4 = 6 metre / second . so time taken = 100 / 4 = 25 seconds . so sam took = 19 seconds . correct answer = c" | physics |
math_qa__1IfLUmmE91yRJNHW | The contents of a certain box consist of 14 apples and 20 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples? Choose the correct choice from the following.
A) 3 B) 6 C) 14 D) 17 E) 20 | <gadget id="calculator">14 + 20</gadget>
<output>34</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">14 / (7/10)</gadget>
<output>20</output>
<gadget id="calculator">34 - 20</gadget>
<output>14</output>
<result>C</result> | C | 14 | The contents of a certain box consist of 14 apples and 20 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples? | {
"A": "3",
"B": "6",
"C": "14",
"D": "17",
"E": "20"
} | subtract(add(14, 20), divide(14, divide(70, const_100))) | add(n0,n1)|divide(n2,const_100)|divide(n0,#1)|subtract(#0,#2) | the objective here is that 70 % of the fruit in the box should be apples . now , there are 14 apples at start and there is no talk of removing any apples , so number of apples should remain 14 and they should constitute 70 % of total fruit , so total fruit = 14 / 0.7 = 20 so we should have 20 - 14 = 6 oranges . right now , there are 20 oranges , so to get to 6 oranges , we should remove 20 - 6 = 14 oranges . answer c | general |
math_qa__2c6JFnUhVxNSoo1S | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.500, what is the reduced price for kg? Choose the correct choice from the following choices: A) 25 B) 60 C) 70 D) 80 E) 20 | <gadget id="calculator">500 * 25</gadget>
<output>12_500</output>
<gadget id="calculator">12_500 / 100</gadget>
<output>125</output>
<gadget id="calculator">125 / 5</gadget>
<output>25</output>
<result>A</result> | A | 25 | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.500, what is the reduced price for kg? | {
"A": "25",
"B": "60",
"C": "70",
"D": "80",
"E": "20"
} | divide(divide(multiply(500, 25), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "a 500 * ( 25 / 100 ) = 125 - - - - 5 ? - - - - 1 = > rs . 25" | gain |
math_qa__haQwNtsdKWl5cLHr | There are two concentric circles with radii 8 and 6. If the radius of the outer circle is increased by 25% and the radius of the inner circle decreased by 50%, by what percent does the area between the circles increase? Choose the correct choice from the following choices:
A) 225
B) 250
C) 275
D) 300
E) 325 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">8 * (5/4)</gadget>
<output>10</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 * (1/2)</gadget>
<output>3</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">100 - 9</gadget>
<output>91</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">64 - 36</gadget>
<output>28</output>
<gadget id="calculator">91 - 28</gadget>
<output>63</output>
<gadget id="calculator">63 / 28</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">(9/4) * 100</gadget>
<output>225</output>
<result>A</result> | A | 225 | There are two concentric circles with radii 8 and 6. If the radius of the outer circle is increased by 25% and the radius of the inner circle decreased by 50%, by what percent does the area between the circles increase? | {
"A": "225",
"B": "250",
"C": "275",
"D": "300",
"E": "325"
} | multiply(divide(subtract(subtract(power(multiply(8, divide(add(const_100, 25), const_100)), const_2), power(multiply(6, divide(subtract(const_100, 50), const_100)), const_2)), subtract(power(8, const_2), power(6, const_2))), subtract(power(8, const_2), power(6, const_2))), const_100) | add(n2,const_100)|power(n0,const_2)|power(n1,const_2)|subtract(const_100,n3)|divide(#0,const_100)|divide(#3,const_100)|subtract(#1,#2)|multiply(n0,#4)|multiply(n1,#5)|power(#7,const_2)|power(#8,const_2)|subtract(#9,#10)|subtract(#11,#6)|divide(#12,#6)|multiply(#13,const_100)| | "the area of a circle is pir ^ 2 , where r is the radius . the area of the big circle is 64 pi . the area of the small circle is 36 pi . the area a 1 between the circles is 28 pi . when the big circle ' s radius increases , the new area is 100 pi . when the small circle ' s radius decreases , the new area is 9 pi . the area a 2 between the circles is 91 pi . the ratio of a 2 / a 1 is 91 / 28 = 3.25 which is an increase of 225 % . the answer is a ." | gain |
math_qa__FG5JV5CAJtOPgM4e | The speed at which a man can row a boat in still water is 15 km/hr. If he rows downstream, where the speed of current is 3 km/hr, how many seconds will he take to cover 100 meters?
Choose the most appropriate option.
A) 14 B) 16 C) 18 D) 20 E) 22 | <gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>D</result> | D | 20 | The speed at which a man can row a boat in still water is 15 km/hr. If he rows downstream, where the speed of current is 3 km/hr, how many seconds will he take to cover 100 meters? | {
"A": "14",
"B": "16",
"C": "18",
"D": "20",
"E": "22"
} | divide(100, multiply(add(15, 3), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1) | the speed of the boat downstream = 15 + 3 = 18 km / hr 18 km / hr * 5 / 18 = 5 m / s the time taken to cover 100 meters = 100 / 5 = 20 seconds . the answer is d . | physics |
math_qa__80r3NcpGtVVJiUey | 3 people decided to put a down payment on a car for 3500 dollars. How much money do they each have to pay, given that that they have to pay the same amount, and they cannot use any bills below $1? Choose the correct choice
A) $ 1166
B) $ 1168
C) $ 1166.6
D) $ 1167
E) none of the above | <gadget id="calculator">3_500 / 3</gadget>
<output>3_500/3 = around 1_166.666667</output>
<result>D</result> | D | 1,167 | 3 people decided to put a down payment on a car for 3500 dollars. How much money do they each have to pay, given that that they have to pay the same amount, and they cannot use any bills below $1? | {
"A": "$ 1166",
"B": "$ 1168",
"C": "$ 1166.6",
"D": "$ 1167",
"E": "none of the above"
} | divide(3500, 3) | divide(n1,n0) | to keep the amount exact when dividing for 3 , we have to work backwards through division . dividing 3500 by 3 will give us 1166.66 then by subtracting . 66 , we get 1166 , and we multiply it by 3 to get 3498 . to get enough for the down payment , we add 3 to 3498 . dividing the result by 3 gives us our answer . correct option : d | general |
math_qa__mT0S9Z829Agb9IRA | A biker covered half the distance between two towns in 2 hr 30 min. After that he increased his speed by 2 km/hr. He covered the second half of the distance in 2 hr 20 min. Find the distance between the two towns and the initial speed of the biker. Choose the correct choice from the following options:
A) 140
B) 120
C) 130
D) 150
E) 160 | <gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 + (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2 + (1/3)</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(7/3) * 2</gadget>
<output>14/3 = around 4.666667</output>
<gadget id="calculator">(5/2) - (7/3)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(14/3) / (1/6)</gadget>
<output>28</output>
<gadget id="calculator">(5/2) * 28</gadget>
<output>70</output>
<gadget id="calculator">2 * 70</gadget>
<output>140</output>
<result>A</result> | A | 140 | A biker covered half the distance between two towns in 2 hr 30 min. After that he increased his speed by 2 km/hr. He covered the second half of the distance in 2 hr 20 min. Find the distance between the two towns and the initial speed of the biker. | {
"A": "140",
"B": "120",
"C": "130",
"D": "150",
"E": "160"
} | multiply(2, multiply(add(2, divide(30, const_60)), divide(multiply(add(2, divide(20, const_60)), 2), subtract(add(2, divide(30, const_60)), add(2, divide(20, const_60)))))) | divide(n1,const_60)|divide(n4,const_60)|add(n0,#0)|add(n0,#1)|multiply(n0,#3)|subtract(#2,#3)|divide(#4,#5)|multiply(#2,#6)|multiply(n0,#7) | let x km / hr be the initial speed of the biker , then his speed during the second part of the trip is x + 2 km / hr . half the distance between two cities equals 23060 ⋅ x km and 22060 ⋅ ( x + 2 ) km . from the equation : 23060 ⋅ x = 22060 ⋅ ( x + 2 ) we get x = 28 km / hr . the intial speed of the biker is 28 km / h . half the distance between the two towns is 2 h 30 min × 28 = 2.5 × 28 = 70 . so the distance is 2 × 70 = 140 km . answer is a . | physics |
math_qa__lwBiWoXPuSZNJJ9X | The diagonal of a square is 40 m. The area of the square is: Choose the most appropriate option: A) 600 B) 900 C) 800 D) 500 E) 400 | <gadget id="calculator">40 ** 2</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 / 2</gadget>
<output>800</output>
<result>C</result> | C | 800 | The diagonal of a square is 40 m. The area of the square is: | {
"A": "600",
"B": "900",
"C": "800",
"D": "500",
"E": "400"
} | divide(power(40, const_2), const_2) | power(n0,const_2)|divide(#0,const_2) | arear = 1 / 2 × ( diagonal ) ( power ) 2 = ( 1 / 2 × 40 × 40 ) m ( power ) 2 = 1600 / 2 = 800 m ( power ) 2 answer is c . | geometry |
math_qa__br3HrUP34OPJDCNM | On dividing 16698 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor? Pick one.
A) 743 B) 154 C) 187 D) 741 E) 785 | <gadget id="calculator">16_698 - 14</gadget>
<output>16_684</output>
<gadget id="calculator">16_684 / 89</gadget>
<output>16_684/89 = around 187.460674</output>
<result>C</result> | C | 187 | On dividing 16698 by a certain number, we get 89 as quotient and 14 as remainder. What is the divisor? | {
"A": "743",
"B": "154",
"C": "187",
"D": "741",
"E": "785"
} | divide(subtract(16698, 14), 89) | subtract(n0,n2)|divide(#0,n1)| | "divisor * quotient + remainder = dividend divisor = ( dividend ) - ( remainder ) / quotient ( 16698 - 14 ) / 89 = 187 answer ( c )" | general |
math_qa__Y90nlQQCBlaoUtQg | A box contains 4 black, 3 red and 6 green marbles. 2 marbles are drawn from the box at random. What is the probability that both the marbles are of the same color? Choose the correct choice from the following:
A) 24 / 78 B) 24 / 709 C) 24 / 76 D) 24 / 71 E) 24 / 72 | <gadget id="calculator">3 + 6</gadget>
<output>9</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">9 + 15</gadget>
<output>24</output>
<gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">13 * 6</gadget>
<output>78</output>
<gadget id="calculator">24 / 78</gadget>
<output>4/13 = around 0.307692</output>
<result>A</result> | A | 0.307692 | A box contains 4 black, 3 red and 6 green marbles. 2 marbles are drawn from the box at random. What is the probability that both the marbles are of the same color? | {
"A": "24 / 78",
"B": "24 / 709",
"C": "24 / 76",
"D": "24 / 71",
"E": "24 / 72"
} | divide(add(add(3, 6), add(const_10, add(3, 2))), multiply(add(const_10, const_3), 6)) | add(n1,n2)|add(n1,n3)|add(const_10,const_3)|add(#1,const_10)|multiply(n2,#2)|add(#0,#3)|divide(#5,#4) | explanation : total marbles in a box = 4 black + 3 red + 6 green marbles = 13 marbles 2 marbles are drawn from 13 marbles at random . therefore , n ( s ) = 13 c 2 = 78 ways let a be the event that 2 marbles drawn at random are of the same color . number of cases favorable to the event a is n ( a ) = 4 c 2 + 3 c 2 + 6 c 2 = 6 + 3 + 15 = 24 therefore , by definition of probability of event a , p ( a ) = n ( a ) / n ( s ) = 24 / 78 answer : a | other |
math_qa__FysAlzpQRjGQ3QiZ | When an amount was distributed among 14 boys, each of them got rs 80 more than the amount received by each boy when the same amount is distributed equally among 18 boys. What was the amount? Choose the correct choice from the following options: A) 5000 B) 5030 C) 5010 D) 5040 E) 5020 | <gadget id="calculator">1 / 14</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/14) - (1/18)</gadget>
<output>1/63 = around 0.015873</output>
<gadget id="calculator">80 / (1/63)</gadget>
<output>5_040</output>
<result>D</result> | D | 5,040 | When an amount was distributed among 14 boys, each of them got rs 80 more than the amount received by each boy when the same amount is distributed equally among 18 boys. What was the amount? | {
"A": "5000",
"B": "5030",
"C": "5010",
"D": "5040",
"E": "5020"
} | divide(80, subtract(divide(const_1, 14), divide(const_1, 18))) | divide(const_1,n0)|divide(const_1,n2)|subtract(#0,#1)|divide(n1,#2) | let the total amount be rs . x the , x / 14 - x / 18 = 80 < = > 2 x / 126 = 80 < = > x / 63 = 63 x 80 = 5040 . hence the total amount is 5040 answer is d . | general |
math_qa__tA0QqeDPEYtvqvES | Sum of the squares of 3 no. is 156 and the sum of their products taken two at a time is 50. Find the sum? Choose the correct choice from the following answers: A) 18 B) 16 C) 19 D) 21 E) 15 | <gadget id="calculator">50 * 2</gadget>
<output>100</output>
<gadget id="calculator">156 + 100</gadget>
<output>256</output>
<gadget id="calculator">256 ** (1/2)</gadget>
<output>16</output>
<result>B</result> | B | 16 | Sum of the squares of 3 no. is 156 and the sum of their products taken two at a time is 50. Find the sum? | {
"A": "18",
"B": "16",
"C": "19",
"D": "21",
"E": "15"
} | sqrt(add(156, multiply(50, const_2))) | multiply(n2,const_2)|add(n1,#0)|sqrt(#1) | ( a + b + c ) 2 = a 2 + b 2 + c 2 + 2 ( ab + bc + ca ) = 156 + 2 * 50 a + b + c = â ˆ š 256 = 16 answer b | general |
math_qa__2SOlEfIVVXKNBUhW | Farm Tax is levied on the 60% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. willam. Mr. willam paid only $ 500 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : Choose one: A) 15.502 % B) 25.7014 % C) 12.502 % D) 21.7014 % E) none | <gadget id="calculator">500 / 3_840</gadget>
<output>25/192 = around 0.130208</output>
<gadget id="calculator">(25/192) * 100</gadget>
<output>625/48 = around 13.020833</output>
<gadget id="calculator">(625/48) * 100</gadget>
<output>15_625/12 = around 1_302.083333</output>
<gadget id="calculator">(15_625/12) / 60</gadget>
<output>3_125/144 = around 21.701389</output>
<result>D</result> | D | 21.7014 | Farm Tax is levied on the 60% of the cultivated Land. The tax department collected total $ 3840 through the farm Tax from the village of Mr. willam. Mr. willam paid only $ 500 as farm tax. The percentage of total land of Mr. willam over the total taxable land of the village is : | {
"A": "15.502 %",
"B": "25.7014 %",
"C": "12.502 %",
"D": "21.7014 %",
"E": "none"
} | divide(multiply(multiply(divide(500, 3840), const_100), const_100), 60) | divide(n2,n1)|multiply(#0,const_100)|multiply(#1,const_100)|divide(#2,n0)| | "only trick n this question is to ignore 60 % information as farm tax is levied uniformly in the village and that includes mr william ' s land . what percentage of tax mr william paid ? this will be equal to the percentage of total cultivated land he holds over the total cultivated land in the village . that leads to ( 500 / 3840 ) x 100 = 13.02083 % in percentage terms . but the question asks ratio between his total land to total cultivated land . hence the answer is 13.02083 % x ( 100 / 60 ) = 21.7014 % and the answer is not there in the options . the correct answer is ( d ) ." | general |
math_qa__MyNaxe7ki0jLWzV7 | A, B and C started a business with capitals of Rs.6000, Rs.8000, and Rs.10000 respectively. At the end of the year, the profit share of B is Rs1000. The difference between the profit shares of A and C is Choose one: A) rs . 400 B) rs . 450 C) rs . 500 D) rs . 550 E) rs . 650 | <gadget id="calculator">10_000 - 6_000</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 / 8_000</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 1_000</gadget>
<output>500</output>
<result>C</result> | C | 500 | A, B and C started a business with capitals of Rs.6000, Rs.8000, and Rs.10000 respectively. At the end of the year, the profit share of B is Rs1000. The difference between the profit shares of A and C is | {
"A": "rs . 400",
"B": "rs . 450",
"C": "rs . 500",
"D": "rs . 550",
"E": "rs . 650"
} | multiply(divide(subtract(10000, 6000), 8000), 1000) | subtract(n2,n0)|divide(#0,n1)|multiply(n3,#1) | ratio of investments of a , b and c is 6000 : 8000 : 10000 = 3 : 4 : 5 . and also given that , profit share of ‘ b ’ is rs . 1000 . now required difference is 5 – 3 = 2 parts . therefore , required difference = 2 / 4 ( 1000 ) = rs . 500 . answer : c | gain |
math_qa__yYslSpmGlYV1roo1 | The length of a rectangle is five times of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 16 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 11 units?
Choose the correct choice from the following choices: A) 180 sq . units B) 11 sq . units C) 110 sq . units D) 140 sq . units E) 220 sq . units | <gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 11</gadget>
<output>220</output>
<result>E</result> | E | 220 | The length of a rectangle is five times of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 16 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 11 units? | {
"A": "180 sq . units",
"B": "11 sq . units",
"C": "110 sq . units",
"D": "140 sq . units",
"E": "220 sq . units"
} | multiply(multiply(sqrt(16), add(const_2, const_3)), 11) | add(const_2,const_3)|sqrt(n0)|multiply(#0,#1)|multiply(n1,#2) | given that the area of the square = 16 sq . units = > side of square = â ˆ š 16 = 4 units the radius of the circle = side of the square = 4 units length of the rectangle = 5 * 4 = 20 units given that breadth = 11 units area of the rectangle = lb = 20 * 11 = 220 sq . units answer : e | geometry |
math_qa__kuKFnLZelSIcLVxE | Second Saturday and every Sunday is a holiday. How many working days will be there in a month of 30 days beginning on a Saturday? Options: A) 24 B) 23 C) 18 D) 21 E) 22 | <gadget id="calculator">30 - 2</gadget>
<output>28</output>
<gadget id="calculator">28 / 4</gadget>
<output>7</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 + 3</gadget>
<output>23</output>
<result>A</result> | A | 24 | Second Saturday and every Sunday is a holiday. How many working days will be there in a month of 30 days beginning on a Saturday? | {
"A": "24",
"B": "23",
"C": "18",
"D": "21",
"E": "22"
} | add(multiply(subtract(divide(subtract(30, const_2), const_4), const_2), const_4), const_3) | subtract(n0,const_2)|divide(#0,const_4)|subtract(#1,const_2)|multiply(#2,const_4)|add(#3,const_3) | explanation : mentioned month begins on a saturday and has 30 days sundays = 2 nd , 9 th , 16 th , 23 rd , 30 th = > total sundays = 5 every second saturday is holiday . 1 second saturday in every month total days in the month = 30 total working days = 30 - ( 5 + 1 ) = 24 . answer : option a | physics |
math_qa__w0woeO7j7wJL7LqR | If 80% of 90 is greater than 70% of a number by 30, what is the number? Choose the correct choice: A) 70 B) 60 C) 10 D) 75 E) 85 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 90</gadget>
<output>72</output>
<gadget id="calculator">72 - 30</gadget>
<output>42</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">42 / (7/10)</gadget>
<output>60</output>
<result>B</result> | B | 60 | If 80% of 90 is greater than 70% of a number by 30, what is the number? | {
"A": "70",
"B": "60",
"C": "10",
"D": "75",
"E": "85"
} | divide(subtract(multiply(divide(80, const_100), 90), 30), divide(70, const_100)) | divide(n0,const_100)|divide(n2,const_100)|multiply(n1,#0)|subtract(#2,n3)|divide(#3,#1)| | "explanation : 80 / 100 * 90 - 70 / 100 * x = 30 72 - 70 / 100 * x = 30 72 - 30 = 70 / 100 * x 42 = 70 / 100 * x 42 * 100 / 70 = x 60 = x answer : option b" | gain |
math_qa__FtRHmL38NnYSEbpg | Find large number from below question The difference of two numbers is 1000. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder Pick
A) 1345 B) 1197 C) 1540 D) 1600 E) 1635 | <gadget id="calculator">1_000 - 15</gadget>
<output>985</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">985 / 5</gadget>
<output>197</output>
<gadget id="calculator">197 * 6</gadget>
<output>1_182</output>
<result>B</result> | B | 1,197 | Find large number from below question The difference of two numbers is 1000. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder | {
"A": "1345",
"B": "1197",
"C": "1540",
"D": "1600",
"E": "1635"
} | multiply(divide(subtract(1000, 15), subtract(6, const_1)), 6) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 1365 ) . x + 1000 = 6 x + 15 5 x = 985 x = 197 large number = 197 + 1365 = 1197 b" | general |
math_qa__D8PlrSHMvA2tVVac | A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be?
Choose one.
A) 7744 B) 8844 C) 5544 D) 4444 E) 3444 | <gadget id="calculator">2 * pi * 56</gadget>
<output>112*pi = around 351.858377</output>
<gadget id="calculator">(112*pi) / 4</gadget>
<output>28*pi = around 87.964594</output>
<gadget id="calculator">(28*pi) ** 2</gadget>
<output>784*pi**2 = around 7_737.76985</output>
<result>A</result> | A | 7,744 | A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be? | {
"A": "7744",
"B": "8844",
"C": "5544",
"D": "4444",
"E": "3444"
} | power(divide(circumface(56), const_4), const_2) | circumface(n0)|divide(#0,const_4)|power(#1,const_2) | length of wire = 2 pier = 2 * ( 22 / 7 ) * 56 = 352 cm side of the square = 352 / 4 = 88 cm area of the square = 88 * 88 = 7744 sq cm answer : a | geometry |
math_qa__MB7RwXuypJ1WPnoi | A rectangular courtyard, the sides of which are in the ratio of 4:3, cost Rs.600 for paving at 50 p per m2; find the length of the diagonal of the courtyard? Choose one
A) 17 m B) 45 m C) 54 m D) 77 m E) 34 m | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">600 / (1/2)</gadget>
<output>1_200</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">1_200 / 12</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 ** 2</gadget>
<output>1_600</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 ** 2</gadget>
<output>900</output>
<gadget id="calculator">1_600 + 900</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 ** (1/2)</gadget>
<output>50</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">50 - 5</gadget>
<output>45</output>
<result>B</result> | B | 45 | A rectangular courtyard, the sides of which are in the ratio of 4:3, cost Rs.600 for paving at 50 p per m2; find the length of the diagonal of the courtyard? | {
"A": "17 m",
"B": "45 m",
"C": "54 m",
"D": "77 m",
"E": "34 m"
} | subtract(sqrt(add(power(multiply(4, sqrt(divide(divide(600, divide(50, const_100)), multiply(4, 3)))), 2), power(multiply(3, sqrt(divide(divide(600, divide(50, const_100)), multiply(4, 3)))), 2))), add(const_2, const_3)) | add(const_2,const_3)|divide(n3,const_100)|multiply(n0,n1)|divide(n2,#1)|divide(#3,#2)|sqrt(#4)|multiply(n0,#5)|multiply(n1,#5)|power(#6,n4)|power(#7,n4)|add(#8,#9)|sqrt(#10)|subtract(#11,#0) | 1 m 2 - - - - 1 / 2 ? - - - - - 600 = > 1200 m 2 4 x * 3 x = 1200 = > x = 10 answer : b | geometry |
math_qa__IO2BRVlqvSDXO8ng | If the area of a circle decreases by 42%, then the radius of a circle decreases by Select.
A) 20 % B) 18 % C) 24 % D) 64 % E) none of these | <gadget id="calculator">100 - 42</gadget>
<output>58</output>
<gadget id="calculator">58 / 100</gadget>
<output>29/50 = around 0.58</output>
<gadget id="calculator">(29/50) ** (1/2)</gadget>
<output>sqrt(58)/10 = around 0.761577</output>
<gadget id="calculator">1 - (sqrt(58)/10)</gadget>
<output>1 - sqrt(58)/10 = around 0.238423</output>
<gadget id="calculator">(1 - sqrt(58)/10) * 100</gadget>
<output>100 - 10*sqrt(58) = around 23.842269</output>
<result>C</result> | C | 24 | If the area of a circle decreases by 42%, then the radius of a circle decreases by | {
"A": "20 %",
"B": "18 %",
"C": "24 %",
"D": "64 %",
"E": "none of these"
} | multiply(subtract(const_1, sqrt(divide(subtract(const_100, 42), const_100))), const_100) | subtract(const_100,n0)|divide(#0,const_100)|sqrt(#1)|subtract(const_1,#2)|multiply(#3,const_100)| | "if area of a circle decreased by x % then the radius of a circle decreases by ( 100 − 10 √ 100 − x ) % = ( 100 − 10 √ 100 − 42 ) % = ( 100 − 10 √ 58 ) % = 100 - 76 = 24 % answer c" | geometry |
math_qa__GXO4bkiY1nICepq3 | A batsman makes a score of 83 runs in the 17th inning and thus increases his averages by 3.Find his average after 17th inning? Choose the correct choice from the following answers.
A) 19 B) 29 C) 35 D) 49 E) 59 | <gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">83 - 51</gadget>
<output>32</output>
<gadget id="calculator">32 + 3</gadget>
<output>35</output>
<result>C</result> | C | 35 | A batsman makes a score of 83 runs in the 17th inning and thus increases his averages by 3.Find his average after 17th inning? | {
"A": "19",
"B": "29",
"C": "35",
"D": "49",
"E": "59"
} | add(subtract(83, multiply(17, 3)), 3) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "let the average after 17 th inning = x then average after 16 th inning = ( x - 3 ) therefore 16 ( x - 3 ) + 83 = 17 x therefore x = 35 answer : c" | general |
math_qa__SCmLFW5zDOjHx4lZ | When x is multiplied by 3, the result is 20 more than the result of subtracting x from 20. What is the value of x?
Select.
A) 10 B) - 2 C) 11 D) 13 E) 22 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">40 / 4</gadget>
<output>10</output>
<result>A</result> | A | 10 | When x is multiplied by 3, the result is 20 more than the result of subtracting x from 20. What is the value of x? | {
"A": "10",
"B": "- 2",
"C": "11",
"D": "13",
"E": "22"
} | divide(add(20, 20), add(3, const_1)) | add(n1,n2)|add(const_1,n0)|divide(#0,#1)| | "the equation that can be formed is : 3 x - 20 = 20 - x or , 4 x = 40 or , x = 10 . answer : a" | general |
math_qa__ANAYBVlqH2QSHGpf | Solution for 2.75+.003+.158 Pick one
A) 2.91
B) 2.911
C) 2.938
D) 2.986
E) 2.999 | <gadget id="calculator">3 / 1_000</gadget>
<output>3/1_000 = around 0.003</output>
<gadget id="calculator">2.75 + (3/1_000)</gadget>
<output>2.753</output>
<gadget id="calculator">158 / 1_000</gadget>
<output>79/500 = around 0.158</output>
<gadget id="calculator">2.753 + (79/500)</gadget>
<output>2.911</output>
<result>B</result> | B | 2.911 | Solution for 2.75+.003+.158 | {
"A": "2.91",
"B": "2.911",
"C": "2.938",
"D": "2.986",
"E": "2.999"
} | add(add(2.75, divide(003, const_1000)), divide(158, const_1000)) | divide(n1,const_1000)|divide(n2,const_1000)|add(n0,#0)|add(#2,#1)| | "2.75 + . 003 + . 158 = 0 0 = 0 - 2.75 - 0.003 - 0.158 0 = - 2.911 answer : b" | general |
math_qa__uBEk3bJdurLrNz81 | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 238, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala? Choose the correct choice from the following.
A) 22 B) 33 C) 55 D) 42 E) 88 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/10) + (3/4)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">238 / (17/20)</gadget>
<output>280</output>
<gadget id="calculator">280 - 238</gadget>
<output>42</output>
<result>D</result> | D | 42 | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 238, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala? | {
"A": "22",
"B": "33",
"C": "55",
"D": "42",
"E": "88"
} | subtract(divide(238, add(divide(10, const_100), divide(3, 4))), 238) | divide(n0,const_100)|divide(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,n1)| | "let f = pure fuji , g = pure gala and c - cross pollinated . c = 10 % of x where x is total trees . c = . 1 x also 3 x / 4 = f and c + f = 238 = > . 1 x + 3 / 4 x = 238 = > x = 280 280 - 238 = pure gala = 42 . answer d" | general |
math_qa__KcUN0U0lOPvzTzMd | The purchase price of an article is $48. In order to include 25% of cost for overhead and to provide $12 of net profit, the markup should be Pick one
A) 50 % B) 25 % C) 35 % D) 40 % E) 45 % | <gadget id="calculator">12 / 48</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">25 + 25</gadget>
<output>50</output>
<result>A</result> | A | 50 | The purchase price of an article is $48. In order to include 25% of cost for overhead and to provide $12 of net profit, the markup should be | {
"A": "50 %",
"B": "25 %",
"C": "35 %",
"D": "40 %",
"E": "45 %"
} | add(multiply(divide(12, 48), const_100), 25) | divide(n2,n0)|multiply(#0,const_100)|add(n1,#1) | cost price of article = 48 $ % of overhead cost = 25 net profit = 12 $ we need to calculate % markup net profit as % of cost price = ( 12 / 48 ) * 100 = 25 % total markup should be = 25 + 25 = 50 % answer a | gain |
math_qa__mG1s1259MUexAHXL | What should be the least number to be added to the 51234 number to make it divisible by 9? Choose the correct answer:
A) 6
B) 4
C) 3
D) 5
E) 2 | <gadget id="calculator">51_234 % 9</gadget>
<output>6</output>
<gadget id="calculator">9 - 6</gadget>
<output>3</output>
<result>C</result> | C | 3 | What should be the least number to be added to the 51234 number to make it divisible by 9? | {
"A": "6",
"B": "4",
"C": "3",
"D": "5",
"E": "2"
} | subtract(9, reminder(51234, 9)) | reminder(n0,n1)|subtract(n1,#0)| | "the least number to be added to the numbers to make them divisible by 9 is equal to the difference of the least multiple of 9 greater than the sum of the digits and sum of the digits . sum of digits = 15 . nearest multiple of 9 greater than sum of digits = 18 . hence 3 has to be added . answer : c" | general |
math_qa__npRtQwAQjAHZ1DmU | 8 k 8 + k 88 - - - - - - - - 16 t 6 if k and t represent non - zero digits within the integers above , what is t ? Choose the correct option:
A) 6 B) 7 C) 8 D) 9 E) 17 | <gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">16 - 9</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<result>A</result> | A | 6 | 8 k 8 + k 88 - - - - - - - - 16 t 6 if k and t represent non - zero digits within the integers above , what is t ? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "17"
} | subtract(subtract(16, add(8, const_1)), const_1) | add(n0,const_1)|subtract(n3,#0)|subtract(#1,const_1) | 8 k 8 k 88 - - - - - - - - 16 t 6 trial and error or just plug - in method might be the shortest way to solve this problem . though you can narrow down the possible values of k to just two : 7 and 8 - - > 8 * * + 7 * * = 16 * * or 8 * * + 8 * * = 16 * * ( k can not be less than 7 or 9 , as the result wo n ' t be 16 * * ) . after that it ' s easy to get that k = 7 and t = 6 . answer : a . | general |
math_qa__ORdSTDc5qdKP1yFR | The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet? Choose the correct choice from the following choices.
A) 08 a . m .
B) 09 a . m .
C) 12 a . m .
D) 10 a . m .
E) 07 a . m . | <gadget id="calculator">20 + 25</gadget>
<output>45</output>
<gadget id="calculator">110 / 45</gadget>
<output>22/9 = around 2.444444</output>
<gadget id="calculator">8 + (22/9)</gadget>
<output>94/9 = around 10.444444</output>
<result>D</result> | D | 10 | The distance between Delhi and Mathura is 110 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet? | {
"A": "08 a . m .",
"B": "09 a . m .",
"C": "12 a . m .",
"D": "10 a . m .",
"E": "07 a . m ."
} | add(8, divide(110, add(20, 25))) | add(n1,n3)|divide(n0,#0)|add(n4,#1)| | "d 10 a . m . d = 110 – 20 = 90 rs = 20 + 25 = 45 t = 90 / 45 = 2 hours 8 a . m . + 2 = 10 a . m ." | physics |
math_qa__6IL5cLgh77zpP2Gl | Shopkeeper rise price by 31% and gives successive discount of 10% and 15%. What is overall % gain or loss?
Choose one:
A) 0.215 % B) 1.215 % C) 3.215 % D) 6.215 % E) 7.215 % | <gadget id="calculator">100 + 31</gadget>
<output>131</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">131 * (9/10)</gadget>
<output>1_179/10 = around 117.9</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(1_179/10) * (17/20)</gadget>
<output>20_043/200 = around 100.215</output>
<gadget id="calculator">(20_043/200) - 100</gadget>
<output>43/200 = around 0.215</output>
<result>A</result> | A | 0.215 | Shopkeeper rise price by 31% and gives successive discount of 10% and 15%. What is overall % gain or loss? | {
"A": "0.215 %",
"B": "1.215 %",
"C": "3.215 %",
"D": "6.215 %",
"E": "7.215 %"
} | subtract(multiply(multiply(add(const_100, 31), divide(subtract(const_100, 10), const_100)), divide(subtract(const_100, 15), const_100)), const_100) | add(n0,const_100)|subtract(const_100,n2)|subtract(const_100,n1)|divide(#1,const_100)|divide(#2,const_100)|multiply(#0,#4)|multiply(#3,#5)|subtract(#6,const_100)| | "let d initial price be 100 31 % rise now price = 131 / 100 * 100 = 131 10 % discount then price = 131 * 90 / 100 = 117.9 15 % discount then price = 117.9 * 85 / 100 = 100.215 so gain = 100.215 - 100 = 0.215 gain % = gain * 100 / cp = = > 0.215 * 100 / 100 = 0.215 % answer : a" | gain |
math_qa__NujX9zo7tFxoAhL9 | The probability that a computer company will get a computer hardware contract is 4/5 and the probability that it will not get a software contract is 3/5. If the probability of getting at least one contract is 9/10, what is the probability that it will get both the contracts? Choose the correct option.
A) 1 / 8 B) 2 / 9 C) 3 / 10 D) 4 / 11 E) 5 / 12 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/5) + (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(4/5) - (1/2)</gadget>
<output>3/10 = around 0.3</output>
<result>C</result> | C | 0.3 | The probability that a computer company will get a computer hardware contract is 4/5 and the probability that it will not get a software contract is 3/5. If the probability of getting at least one contract is 9/10, what is the probability that it will get both the contracts? | {
"A": "1 / 8",
"B": "2 / 9",
"C": "3 / 10",
"D": "4 / 11",
"E": "5 / 12"
} | subtract(add(divide(const_3.0, 5), subtract(const_1, divide(4, 5))), divide(5, 10)) | divide(n2,n1)|divide(n0,n3)|divide(n3,n5)|subtract(const_1,#1)|add(#0,#3)|subtract(#4,#2)| | "let , a ≡ event of getting hardware contract b ≡ event of getting software contract ab ≡ event of getting both hardware and software contract . p ( a ) = 4 / 5 , p ( ~ b ) = 5 / 9 = > p ( b ) = 1 - ( 3 / 5 ) = 2 / 5 . a and b are not mutually exclusive events but independent events . so , p ( at least one of a and b ) = p ( a ) + p ( b ) - p ( ab ) . = > 9 / 10 = ( 4 / 5 ) + ( 2 / 5 ) - p ( ab ) . = > p ( ab ) = 3 / 10 . hence , the required probability is 3 / 10 . the answer is c ." | other |
math_qa__phlsEDfs9l70QZNB | The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 4 years ? Choose the correct choice from the following answers
A) 3277 B) 2977 C) 12656 D) 6077 E) 17112 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 10_000</gadget>
<output>40_000</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 4</gadget>
<output>81/256 = around 0.316406</output>
<gadget id="calculator">40_000 * (81/256)</gadget>
<output>50_625/4 = around 12_656.25</output>
<result>C</result> | C | 12,656 | The value of a scooter depreciates in such a way that its value of the end of each year is 3/4 of its value of the beginning of the same year. If the initial value of the scooter is Rs.40,000, what is the value at the end of 4 years ? | {
"A": "3277",
"B": "2977",
"C": "12656",
"D": "6077",
"E": "17112"
} | multiply(multiply(4, multiply(const_100, const_100)), power(divide(3, 4), 4)) | divide(n0,n1)|multiply(const_100,const_100)|multiply(n1,#1)|power(#0,n3)|multiply(#2,#3)| | "explanation : 40,000 * ( 3 / 4 ) ^ 4 answer : c" | general |
math_qa__kbXkIyXonsUbX6aT | The simple interest on a sum of money will be Rs.400 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? Select the correct option: A) 800 B) 3799 C) 1200 D) 2693 E) 1732 | <gadget id="calculator">400 / 10</gadget>
<output>40</output>
<gadget id="calculator">40 * 5</gadget>
<output>200</output>
<gadget id="calculator">200 * 3</gadget>
<output>600</output>
<gadget id="calculator">600 + 200</gadget>
<output>800</output>
<result>A</result> | A | 800 | The simple interest on a sum of money will be Rs.400 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? | {
"A": "800",
"B": "3799",
"C": "1200",
"D": "2693",
"E": "1732"
} | add(multiply(multiply(divide(400, 10), 5), const_3), multiply(divide(400, 10), 5)) | divide(n0,n1)|multiply(n2,#0)|multiply(#1,const_3)|add(#2,#1)| | "p - - - 10 - - - - 400 p - - - 5 - - - - - 200 3 p - - - 5 - - - - - 600 - - - - - - = > 800 answer : a" | general |
math_qa__GE4ZUG7nwKXgLrhx | The banker’s gain on a sum due 3 years hence at 10% per annum is Rs. 120. The banker’s discount is
Choices.
A) rs . 960 B) rs . 840 C) rs . 520 D) rs . 760 E) none | <gadget id="calculator">120 * 100</gadget>
<output>12_000</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">12_000 / 30</gadget>
<output>400</output>
<gadget id="calculator">400 + 120</gadget>
<output>520</output>
<result>C</result> | C | 520 | The banker’s gain on a sum due 3 years hence at 10% per annum is Rs. 120. The banker’s discount is | {
"A": "rs . 960",
"B": "rs . 840",
"C": "rs . 520",
"D": "rs . 760",
"E": "none"
} | add(divide(multiply(120, const_100), multiply(3, 10)), 120) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "solution t . d = ( b . g x 100 / r x t ) = rs . ( 120 x 100 / 10 x 3 ) = rs . 400 . b . d = rs ( 400 + 120 ) = rs . 520 . answer c" | gain |
math_qa__lOg21jYcDV3lYHzR | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $0.90 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? Answers:
A) $ 255
B) $ 275
C) $ 459
D) $ 1,250
E) $ 2,550 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">3.06 * 1_000_000</gadget>
<output>3_060_000</output>
<gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">400 * 15</gadget>
<output>6_000</output>
<gadget id="calculator">3_060_000 / 6_000</gadget>
<output>510</output>
<gadget id="calculator">510 * 0.9</gadget>
<output>459</output>
<result>C</result> | C | 459 | When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $0.90 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes? | {
"A": "$ 255",
"B": "$ 275",
"C": "$ 459",
"D": "$ 1,250",
"E": "$ 2,550"
} | multiply(divide(multiply(3.06, multiply(const_1000, const_1000)), multiply(multiply(20, 20), 15)), 0.90) | multiply(const_1000,const_1000)|multiply(n0,n0)|multiply(n4,#0)|multiply(n2,#1)|divide(#2,#3)|multiply(n3,#4)| | "total no . of boxes = 3060000 / ( 20 × 20 × 15 ) = 510 total cost = 510 × $ 0.9 = $ 459 answer c" | general |
math_qa__AZ1j9Va4SdIlZXYX | For any number y, y* is defined as the greatest positive even integer less than or equal to y. What is the value of 5.0– 5.0*? Pick one: A) 0.2 B) 1.2 C) 1.8 D) 2.2 E) 1.0 | <gadget id="calculator">floor(5)</gadget>
<output>5</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">5 - 4</gadget>
<output>1</output>
<result>E</result> | E | 1 | For any number y, y* is defined as the greatest positive even integer less than or equal to y. What is the value of 5.0– 5.0*? | {
"A": "0.2",
"B": "1.2",
"C": "1.8",
"D": "2.2",
"E": "1.0"
} | subtract(5.0, subtract(floor(5.0), const_1)) | floor(n0)|subtract(#0,const_1)|subtract(n0,#1)| | "since y * is defined as the greatest positive even integer less than or equal to y , then 5.0 * = 4 ( the greatest positive even integer less than or equal to 5.0 is 4 ) . hence , 5.0 – 5.0 * = 5.0 - 4 = 1.0 answer : e ." | general |
math_qa__D9TUaVZl5MIruvOe | The salary of a person was reduced by 10%. By what percent should his
reduced salary be raised so as to bring it at par with his original salary? Pick one.
A) 10 % B) 11 1 / 9 % C) 13 2 / 7 % D) 15 3 / 11 % E) 12 1 / 3 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">100 * (1/10)</gadget>
<output>10</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">10 / 90</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/9) * 100</gadget>
<output>100/9 = around 11.111111</output>
<result>B</result> | B | 11 | The salary of a person was reduced by 10%. By what percent should his
reduced salary be raised so as to bring it at par with his original salary? | {
"A": "10 %",
"B": "11 1 / 9 %",
"C": "13 2 / 7 %",
"D": "15 3 / 11 %",
"E": "12 1 / 3 %"
} | multiply(divide(multiply(const_100, divide(10, const_100)), subtract(const_100, multiply(const_100, divide(10, const_100)))), const_100) | divide(n0,const_100)|multiply(#0,const_100)|subtract(const_100,#1)|divide(#1,#2)|multiply(#3,const_100)| | "let the original salary be $ 100 new salary = $ 90 increase on 90 = 10 increase on 100 = 10 / 90 * 100 = 11 1 / 9 % answer is b" | gain |
math_qa__QHbFxbMtdoSnDEPP | If the average (arithmetic mean) of 102 consecutive odd integers is 414, then the least of these integers is Choose the correct choice:
A) 160
B) 289
C) 250
D) 313
E) 525 | <gadget id="calculator">414 - 102</gadget>
<output>312</output>
<gadget id="calculator">312 + 1</gadget>
<output>313</output>
<result>D</result> | D | 313 | If the average (arithmetic mean) of 102 consecutive odd integers is 414, then the least of these integers is | {
"A": "160",
"B": "289",
"C": "250",
"D": "313",
"E": "525"
} | add(subtract(414, 102), const_1) | subtract(n1,n0)|add(#0,const_1)| | "a very helpful rule to know in arithmetic is the rule that in evenly spaced sets , average = median . because the average will equal the median in these sets , then we quickly know that the median of this set of consecutive odd integer numbers is 414 . there are 102 numbers in the set , and in a set with an even number of terms the median is just the average of the two most median terms ( here the 51 st and 52 nd numbers in the set ) . this means that numbers 51 and 52 in this set are 413 and 415 . because we know that number 51 is 413 , we know that the smallest number is 50 odd numbers below this , which means that it is 50 * 2 = 100 below this ( every odd number is every other number ) . therefore 413 - 100 = 313 , answer choice d" | general |
math_qa__EkqOJx6az3E5x6kt | 10 play kabadi, 40 play kho kho only, 5 play both gmaes. Then how many in total? Choose one:
A) 30
B) 35
C) 38
D) 40
E) 50 | <gadget id="calculator">40 + 5</gadget>
<output>45</output>
<gadget id="calculator">10 + 45</gadget>
<output>55</output>
<gadget id="calculator">55 - 5</gadget>
<output>50</output>
<result>E</result> | E | 50 | 10 play kabadi, 40 play kho kho only, 5 play both gmaes. Then how many in total? | {
"A": "30",
"B": "35",
"C": "38",
"D": "40",
"E": "50"
} | subtract(add(10, add(40, 5)), 5) | add(n1,n2)|add(n0,#0)|subtract(#1,n2)| | "10 play kabadi = > n ( a ) = 10 , 5 play both gmaes . = > n ( anb ) = 5 40 play kho kho only , = > n ( b ) = n ( b only ) + n ( anb ) = 40 + 5 = 45 total = > n ( aub ) = n ( a ) + n ( b ) - n ( anb ) = 10 + 45 - 5 = 50 answer : e" | general |
math_qa__Ll4DOYUxvuNxVwYg | 1+2=10
2+3=26
3+4=50 then
4+5=? Select
A) 80 B) 81 C) 82 D) 83 E) 84 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 ** 2</gadget>
<output>81</output>
<gadget id="calculator">81 + 1</gadget>
<output>82</output>
<result>C</result> | C | 82 | 1+2=10
2+3=26
3+4=50 then
4+5=? | {
"A": "80",
"B": "81",
"C": "82",
"D": "83",
"E": "84"
} | add(power(add(4, 5), const_2), const_1) | add(n7,n10)|power(#0,const_2)|add(#1,const_1) | 1 + 2 = 10 . . . . . ( 1 + 2 ) ^ 2 + 1 = 10 2 + 3 = 26 . . . . . . . ( 2 + 3 ) ^ 2 + 1 = 26 3 + 4 = 50 then . . . ( 3 + 4 ) ^ 2 + 1 = 50 4 + 5 = 82 . . . . . . . . ( 4 + 5 ) ^ 2 + 1 = 82 answer : c | general |
math_qa__T5tpQZstv9hwVyaE | In the list 3, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode? Choose the correct choice.
A) 2 / 9 B) 1 / 3 C) 2 / 5 D) 2 / 3 E) 7 / 9 | <gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<result>A</result> | A | 0.222222 | In the list 3, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode? | {
"A": "2 / 9",
"B": "1 / 3",
"C": "2 / 5",
"D": "2 / 3",
"E": "7 / 9"
} | divide(const_2, add(5, 4)) | add(n1,n2)|divide(const_2,#0) | highest frequent term in the set is 5 ( with frequency 4 ) hence mode = 5 two terms ( 3 , 4 ) out of a total of 9 terms are less than mode of the set . fraction of set that are less than mode of set = 2 / 9 answer : option a | general |
math_qa__RkDc1mhfIt0brw89 | John makes $60 a week from his job. He earns a raise andnow makes $84 a week. What is the % increase? Choose one.
A) 16.12 % B) 16.66 % C) 16.56 % D) 40 % E) 18.1 % | <gadget id="calculator">84 - 60</gadget>
<output>24</output>
<gadget id="calculator">24 / 60</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>D</result> | D | 40 | John makes $60 a week from his job. He earns a raise andnow makes $84 a week. What is the % increase? | {
"A": "16.12 %",
"B": "16.66 %",
"C": "16.56 %",
"D": "40 %",
"E": "18.1 %"
} | multiply(divide(subtract(84, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 24 / 60 ) * 100 = ( 4 / 10 ) * 100 = 40 % . d" | gain |
math_qa__Qqbi6gJMCBfwtKtM | 56 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is : Choose the correct choice from the following options:
A) 33.0
B) 37.66
C) 32.1
D) 31.23
E) 19 | <gadget id="calculator">56 * 10</gadget>
<output>560</output>
<gadget id="calculator">780 - 560</gadget>
<output>220</output>
<gadget id="calculator">22 - 10</gadget>
<output>12</output>
<gadget id="calculator">220 / 12</gadget>
<output>55/3 = around 18.333333</output>
<gadget id="calculator">56 - (55/3)</gadget>
<output>113/3 = around 37.666667</output>
<result>B</result> | B | 37.66 | 56 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is : | {
"A": "33.0",
"B": "37.66",
"C": "32.1",
"D": "31.23",
"E": "19"
} | subtract(56, divide(subtract(780, multiply(56, 10)), subtract(22, 10))) | multiply(n0,n1)|subtract(n2,n1)|subtract(n3,#0)|divide(#2,#1)|subtract(n0,#3) | explanation : let the two parts be ( 56 - x ) and x . then , 10 ( 56 - x ) + 22 x = 780 = > 12 x = 220 = > x = 20 . bigger part = ( 56 - x ) = 37.66 . answer : b ) 37.66 | general |
math_qa__Nfvqg1l87GlENdJ4 | Find the value for x from below equation: x/2=-2? Select: A) - 6 B) 1 C) - 2 D) - 3 E) - 4 | <gadget id="calculator">2 - 4</gadget>
<output>-2</output>
<gadget id="calculator">(-2) * 2</gadget>
<output>-4</output>
<result>E</result> | E | -4 | Find the value for x from below equation: x/2=-2? | {
"A": "- 6",
"B": "1",
"C": "- 2",
"D": "- 3",
"E": "- 4"
} | multiply(subtract(2, const_4), 2) | subtract(n1,const_4)|multiply(#0,n0)| | "1 . multiply both sides by 2 : x * 2 / 2 = - 2 / 2 simplify both sides : x = - 4 e" | general |
math_qa__6WI1r7vvDqmKBimt | A man sold 18 toys for Rs. 18900, gaining thereby the cost price of 3 toy find the cost price of a toy Choose the correct choice from the following answers.
A) s . 600 B) s . 800 C) s . 500 D) s . 900 E) s . 990 | <gadget id="calculator">18 + 3</gadget>
<output>21</output>
<gadget id="calculator">18_900 / 21</gadget>
<output>900</output>
<result>D</result> | D | 900 | A man sold 18 toys for Rs. 18900, gaining thereby the cost price of 3 toy find the cost price of a toy | {
"A": "s . 600",
"B": "s . 800",
"C": "s . 500",
"D": "s . 900",
"E": "s . 990"
} | divide(18900, add(18, 3)) | add(n0,n2)|divide(n1,#0)| | "let the cost of one toy = x . then , cost of 18 toys = 18 x . gain = 3 x . sp of 18 toys = rs . 18900 . gain = sp â € “ cp 3 x = 18900 â € “ 18 x 21 x = 18900 x = rs . 900 . answer : option d" | gain |
math_qa__Qu8QF6dL9f7G0s86 | If it is assumed that 62 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed? Choose the correct choice from the following.
A) 400 B) 420 C) 480 D) 483.8 E) 600 | <gadget id="calculator">62 / 100</gadget>
<output>31/50 = around 0.62</output>
<gadget id="calculator">300 / (31/50)</gadget>
<output>15_000/31 = around 483.870968</output>
<result>D</result> | D | 483.8 | If it is assumed that 62 percent of those who receive a questionnaire by mail will respond and 300 responses are needed, what is the minimum number of questionnaires that should be mailed? | {
"A": "400",
"B": "420",
"C": "480",
"D": "483.8",
"E": "600"
} | divide(300, divide(62, const_100)) | divide(n0,const_100)|divide(n1,#0)| | "minimum no of mail to be sent for getting 300 responses at 62 % = 300 / 0.62 = 483.8 option d" | gain |
math_qa__N9njrsxIBYpAm8ZF | What is the lowest positive integer that is divisible by 1 through 2, inclusive? Choose the correct choice from the following options
A) 2 B) 4 C) 8 D) 6 E) 1 | <gadget id="calculator">lcm(1, 2)</gadget>
<output>2</output>
<result>A</result> | A | 2 | What is the lowest positive integer that is divisible by 1 through 2, inclusive? | {
"A": "2",
"B": "4",
"C": "8",
"D": "6",
"E": "1"
} | lcm(1, 2) | lcm(n0,n1) | the integer should be divisible by : 1 and 2 . the least common multiple of these integers is lcm = 1 * 2 = 2 answer : a | general |
math_qa__evABuY43KV1gdJFz | The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 12%. Options:
A) 37.5 % B) 38.5 % C) 42 % D) 27.5 % E) none | <gadget id="calculator">100 - 12</gadget>
<output>88</output>
<gadget id="calculator">88 / 64</gadget>
<output>11/8 = around 1.375</output>
<gadget id="calculator">(11/8) - 1</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 100</gadget>
<output>75/2 = around 37.5</output>
<result>A</result> | A | 37.5 | The cost price of an article is 64% of the marked price. Calculate the gain percent after allowing a discount of 12%. | {
"A": "37.5 %",
"B": "38.5 %",
"C": "42 %",
"D": "27.5 %",
"E": "none"
} | multiply(subtract(divide(subtract(const_100, 12), 64), const_1), const_100) | subtract(const_100,n1)|divide(#0,n0)|subtract(#1,const_1)|multiply(#2,const_100)| | "sol . let marked price = rs . 100 . then , c . p . = rs . 64 . s . p = rs . 88 . ∴ gain % = [ 24 / 64 * 100 ] % = 37.5 % . answer a" | gain |
math_qa__tiE5wokN4vvzRAOt | Two vessels having volumes in the ratio 3:5 are filled with water and milk solutions. The ratio of milk and water in the two vessels are 1:2 and 3:2 respectively. If the contents of both the vessel are empties into a larger vessel, find the ratio of milk and water in the larger vessel. Choose the correct answer
A) 99 : 61
B) 1 : 1
C) 61 : 160
D) 61 : 99
E) 99 : 160 | <gadget id="calculator">1 ** 3</gadget>
<output>1</output>
<result>B</result> | B | 1 | Two vessels having volumes in the ratio 3:5 are filled with water and milk solutions. The ratio of milk and water in the two vessels are 1:2 and 3:2 respectively. If the contents of both the vessel are empties into a larger vessel, find the ratio of milk and water in the larger vessel. | {
"A": "99 : 61",
"B": "1 : 1",
"C": "61 : 160",
"D": "61 : 99",
"E": "99 : 160"
} | power(1, 3) | power(n2,n0) | vessel a = 300 gallons - - > milk = 100 , water = 200 ; vessel b = 500 gallons - - > milk = 300 , water = 200 ; vessel a + b = 800 gallons - - > milk = 400 , water 400 . the ratio = 400 / 400 - - > 1 : 1 answer : b | other |
math_qa__z9CFazCGC70IE7eS | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 30% profit? Select
A) 220 B) 230 C) 960 D) 832 E) 400 | <gadget id="calculator">832 - 448</gadget>
<output>384</output>
<gadget id="calculator">384 / 2</gadget>
<output>192</output>
<gadget id="calculator">832 - 192</gadget>
<output>640</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">640 * (13/10)</gadget>
<output>832</output>
<result>D</result> | D | 832 | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 30% profit? | {
"A": "220",
"B": "230",
"C": "960",
"D": "832",
"E": "400"
} | multiply(subtract(832, divide(subtract(832, 448), const_2)), add(const_1, divide(30, const_100))) | divide(n2,const_100)|subtract(n0,n1)|add(#0,const_1)|divide(#1,const_2)|subtract(n0,#3)|multiply(#2,#4)| | "c . p . = rs . x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 130 % of rs . 640 = 130 / 100 * 640 = rs . 832 . d" | gain |
math_qa__ux19qYAxXnCPe8of | Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 1250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period. Options: A) 513 B) 512 C) 517 D) 519 E) 521 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) ** 4</gadget>
<output>625/256 = around 2.441406</output>
<gadget id="calculator">1_250 / (625/256)</gadget>
<output>512</output>
<result>B</result> | B | 512 | Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 1250 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period. | {
"A": "513",
"B": "512",
"C": "517",
"D": "519",
"E": "521"
} | divide(1250, power(add(divide(1, 4), 1), 4)) | divide(n1,n0)|add(n1,#0)|power(#1,n0)|divide(n3,#2) | trees increase by 1 / 4 the number of trees in preceding year . hence , correct answer must be divisible by 4 . based on divisibility rules , if last 2 digits are divisible by 4 then the number is divisible by 4 . thus , we can eliminate a , c , d , e the answer to be b again , trees increase by 1 / 4 the number of trees in preceding year . hence , the number of trees increase by 5 / 4 times the number of trees the preceding year . if x = initial number of trees = 512 year 1 = 5 / 4 x year 2 = ( 5 / 4 ) ( 5 / 4 ) x year 3 = ( 5 / 4 ) ( 5 / 4 ) ( 5 / 4 ) x year 4 = ( 5 / 4 ) ( 5 / 4 ) ( 5 / 4 ) ( 5 / 4 ) x only for answer d : ( 5 / 4 ) ( 5 / 4 ) ( 5 / 4 ) ( 5 / 4 ) 512 = 1250 hence , correct answer = b | general |
math_qa__a9QeQKzMzfFV8JRx | A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 6 kilometers per hour. It returns by the same route at an average speed of 5 kilometers per hour. What is the average speed for the round-trip in kilometers per hour? Choose the correct option
A) 5.5
B) 7.1
C) 7.2
D) 7.0
E) 8.0 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">60 / 11</gadget>
<output>60/11 = around 5.454545</output>
<result>A</result> | A | 5.5 | A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 6 kilometers per hour. It returns by the same route at an average speed of 5 kilometers per hour. What is the average speed for the round-trip in kilometers per hour? | {
"A": "5.5",
"B": "7.1",
"C": "7.2",
"D": "7.0",
"E": "8.0"
} | divide(multiply(multiply(6, 5), const_2), add(6, 5)) | add(n0,n1)|multiply(n0,n1)|multiply(#1,const_2)|divide(#2,#0)| | "pick a number which is lcm of 5 and 6 = 30 . upstream time = 30 / 6 = 5 hrs downstream time = 30 / 5 = 6 hrs total time = 11 hrs total distance = 60 average speed = 60 / 11 = 5.5 km / hr" | physics |
math_qa__KG4v5lwCbWgGPzna | A cistern is normally filled in 10 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in? Pick:
A) 33 B) 88 C) 60 D) 99 E) 11 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/10) - (1/12)</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">1 / (1/60)</gadget>
<output>60</output>
<result>C</result> | C | 60 | A cistern is normally filled in 10 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in? | {
"A": "33",
"B": "88",
"C": "60",
"D": "99",
"E": "11"
} | inverse(subtract(divide(const_1, 10), divide(const_1, add(10, const_2)))) | add(n0,const_2)|divide(const_1,n0)|divide(const_1,#0)|subtract(#1,#2)|inverse(#3)| | "1 / 10 - 1 / x = 1 / 12 x = 60 answer : c" | physics |
math_qa__RWJcha8dcPGX7FIr | 6% of customers that enter a store on any given day must not pay tax. If 1000 people shop every day, how many people pay taxes in the store every week Choose the correct choice.
A) 6500
B) 6580
C) 7200
D) 7120
E) 6800 | <gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">1_000 * (3/50)</gadget>
<output>60</output>
<gadget id="calculator">1_000 - 60</gadget>
<output>940</output>
<gadget id="calculator">7 * 940</gadget>
<output>6_580</output>
<result>B</result> | B | 6,580 | 6% of customers that enter a store on any given day must not pay tax. If 1000 people shop every day, how many people pay taxes in the store every week | {
"A": "6500",
"B": "6580",
"C": "7200",
"D": "7120",
"E": "6800"
} | multiply(add(6, const_1), subtract(1000, multiply(1000, divide(6, const_100)))) | add(n0,const_1)|divide(n0,const_100)|multiply(n1,#1)|subtract(n1,#2)|multiply(#0,#3) | 6 % of customers do not pay taxes . 6 / 100 * 1000 customers do not pay taxes . 6 / 100 * 1000 = 60 therefore 1000 - 60 customers do pay taxes . 1000 - 60 = 940 940 * 7 days per week = 6580 b ) | gain |
math_qa__P7AisJ2bcAq1gMkd | A Raz's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996? Choose one:
A) 1 : 2 B) 4 : 5 C) 1 : 1 D) 3 : 2 E) 5 : 3 | <gadget id="calculator">100 + 7</gadget>
<output>107</output>
<gadget id="calculator">107 / 100</gadget>
<output>107/100 = around 1.07</output>
<gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">101 / 100</gadget>
<output>101/100 = around 1.01</output>
<gadget id="calculator">(107/100) - (101/100)</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">100 - 11</gadget>
<output>89</output>
<gadget id="calculator">89 / 100</gadget>
<output>89/100 = around 0.89</output>
<gadget id="calculator">(101/100) - (89/100)</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/50) / (3/25)</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | A Raz's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996? | {
"A": "1 : 2",
"B": "4 : 5",
"C": "1 : 1",
"D": "3 : 2",
"E": "5 : 3"
} | divide(subtract(divide(add(const_100, 7), const_100), divide(add(const_100, 1), const_100)), subtract(divide(add(const_100, 1), const_100), divide(subtract(const_100, 11), const_100))) | add(n3,const_100)|add(n6,const_100)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|divide(#2,const_100)|subtract(#3,#4)|subtract(#4,#5)|divide(#6,#7) | a raz ' s company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996 . 1996 - x - - - - - y - - - - - - - x + y 1997 - x 1 - - - - y 1 - - x 1 + y 1 x 1 = a * x . . . . . ( p ) y 1 = 1.07 * y . . . ( q ) x 1 + y 1 / x + y = 1.01 solve using p and q and find x / y | other |
math_qa__wa75Vu6HbAtzB2Au | 45 x ? = 60% of 900
Choose the correct choice from the following answers:
A) 16.2 B) 12 C) 5 D) 500 E) none | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 900</gadget>
<output>540</output>
<gadget id="calculator">540 / 45</gadget>
<output>12</output>
<result>B</result> | B | 12 | 45 x ? = 60% of 900 | {
"A": "16.2",
"B": "12",
"C": "5",
"D": "500",
"E": "none"
} | divide(multiply(divide(60, const_100), 900), 45) | divide(n1,const_100)|multiply(n2,#0)|divide(#1,n0)| | "answer let 45 x a = ( 60 x 900 ) / 100 ∴ a = ( 60 x 9 ) / 45 = 12 correct option : b" | general |
math_qa__uxzpnwYDhx5QPyLe | Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 6, while all other numbers remain the same, what is the new average of Set S?
Choose the correct choice from the following choices:
A) 6.6 B) 6.7 C) 6.8 D) 6.85 E) 6.9 | <gadget id="calculator">10 * 6.2</gadget>
<output>62</output>
<gadget id="calculator">62 + 6</gadget>
<output>68</output>
<gadget id="calculator">68 / 10</gadget>
<output>34/5 = around 6.8</output>
<result>C</result> | C | 6.8 | Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 6, while all other numbers remain the same, what is the new average of Set S? | {
"A": "6.6",
"B": "6.7",
"C": "6.8",
"D": "6.85",
"E": "6.9"
} | divide(add(multiply(10, 6.2), 6), 10) | multiply(n0,n1)|add(n2,#0)|divide(#1,n0)| | "old set s - total is avg * no of elements = 6.2 * 10 = 62 if one number is increased by 6 then total increased to 62 + 6 = 68 new avg - 68 / 10 = 6.8 . hence answer is c ." | general |
math_qa__ZCe4FkCDe6zWHADQ | What is the greatest 6-digit number when divided by 8 , 9, and 10 leaves a remainder of 6, 7, and 8 respectively? Choose the correct option
A) 456780 B) 678918 C) 997479 D) 997916 E) 997920 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">1_000_000 - 1</gadget>
<output>999_999</output>
<gadget id="calculator">lcm(8, 9)</gadget>
<output>72</output>
<gadget id="calculator">lcm(10, 9)</gadget>
<output>90</output>
<gadget id="calculator">lcm(72, 90)</gadget>
<output>360</output>
<gadget id="calculator">360 * 90</gadget>
<output>32_400</output>
<gadget id="calculator">32_400 * 10</gadget>
<output>324_000</output>
<gadget id="calculator">999_999 - 324_000</gadget>
<output>675_999</output>
<result>B</result> | B | 678,918 | What is the greatest 6-digit number when divided by 8 , 9, and 10 leaves a remainder of 6, 7, and 8 respectively? | {
"A": "456780",
"B": "678918",
"C": "997479",
"D": "997916",
"E": "997920"
} | subtract(subtract(multiply(const_1000, const_1000), const_1), multiply(multiply(lcm(lcm(8, 9), lcm(10, 9)), lcm(10, 9)), 10)) | lcm(n1,n2)|lcm(n2,n3)|multiply(const_1000,const_1000)|lcm(#0,#1)|subtract(#2,const_1)|multiply(#3,#1)|multiply(n3,#5)|subtract(#4,#6) | when you divide a positive integer by 10 , the remainder will just be the units digit . we know the remainder is 8 when we divide by 10 , so b is the only possible answer . | general |
math_qa__mDGfw1QiW6B9fuFz | A thief is spotted by a policeman from a distance of 160 meters. When the policeman starts the chase, the thief also starts running. If the speed of the thief be 8km/hr and that of the policeman 10 km/hr, how far the thief will have run before he is overtaken? Choices
A) 350 m
B) 240 m
C) 440 m
D) 640 m
E) none of them | <gadget id="calculator">160 * 8</gadget>
<output>1_280</output>
<gadget id="calculator">10 - 8</gadget>
<output>2</output>
<gadget id="calculator">1_280 / 2</gadget>
<output>640</output>
<result>D</result> | D | 640 | A thief is spotted by a policeman from a distance of 160 meters. When the policeman starts the chase, the thief also starts running. If the speed of the thief be 8km/hr and that of the policeman 10 km/hr, how far the thief will have run before he is overtaken? | {
"A": "350 m",
"B": "240 m",
"C": "440 m",
"D": "640 m",
"E": "none of them"
} | divide(multiply(160, 8), subtract(10, 8)) | multiply(n0,n1)|subtract(n2,n1)|divide(#0,#1)| | "relative speed of the policeman = ( 10 - 8 ) km / hr = 2 km / hr . time taken by police man to cover ( 160 m / 1000 ) x 1 / 2 hr = 2 / 25 hr . in 2 / 25 hr / s , the thief covers a distance of 8 x 2 / 25 km = 16 / 25 km = 640 m answer is d ." | physics |
math_qa__tXiF69lrglDmRjFK | The average of runs of a cricket player of 20 innings was 36. How many runs must he make in his next innings so as to increase his average of runs by 4 ? Choose the correct choice from the following options
A) 96 B) 106 C) 122 D) 116 E) 120 | <gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">4 + 36</gadget>
<output>40</output>
<gadget id="calculator">21 * 40</gadget>
<output>840</output>
<gadget id="calculator">20 * 36</gadget>
<output>720</output>
<gadget id="calculator">840 - 720</gadget>
<output>120</output>
<result>E</result> | E | 120 | The average of runs of a cricket player of 20 innings was 36. How many runs must he make in his next innings so as to increase his average of runs by 4 ? | {
"A": "96",
"B": "106",
"C": "122",
"D": "116",
"E": "120"
} | subtract(multiply(add(20, const_1), add(4, 36)), multiply(20, 36)) | add(n0,const_1)|add(n1,n2)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "average = total runs / no . of innings = 36 so , total = average x no . of innings = 36 * 20 = 720 now increase in avg = 4 runs . so , new avg = 36 + 4 = 40 runs total runs = new avg x new no . of innings = 40 * 21 = 840 runs made in the 11 th inning = 840 - 720 = 120 answer : e" | general |
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