id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__8WIblrJcwBlzvhQ3 | A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his
average after 17th match Pick
A) 36 B) 37 C) 38 D) 39 E) 35 | <gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">87 - 51</gadget>
<output>36</output>
<gadget id="calculator">36 + 3</gadget>
<output>39</output>
<result>D</result> | D | 39 | A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his
average after 17th match | {
"A": "36",
"B": "37",
"C": "38",
"D": "39",
"E": "35"
} | add(subtract(87, multiply(17, 3)), 3) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "explanation : let the average after 17 th match is x then the average before 17 th match is x - 3 so 16 ( x - 3 ) + 87 = 17 x = > x = 87 - 48 = 39 option d" | general |
math_qa__NX3uZlTpWGcfsg1C | Having received his weekly allowance, a student spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $1.20 at the candy store. What is this student’s weekly allowance? Pick
A) $ 3.50 B) $ 4.00 C) $ 4.25 D) $ 4.50 E) $ 5.00 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 * 1.2</gadget>
<output>18</output>
<gadget id="calculator">18 / 4</gadget>
<output>9/2 = around 4.5</output>
<result>D</result> | D | 4.5 | Having received his weekly allowance, a student spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $1.20 at the candy store. What is this student’s weekly allowance? | {
"A": "$ 3.50",
"B": "$ 4.00",
"C": "$ 4.25",
"D": "$ 4.50",
"E": "$ 5.00"
} | divide(multiply(multiply(3, 5), 1.2), const_4) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_4) | let x be the value of the weekly allowance . ( 2 / 3 ) ( 2 / 5 ) x = 120 cents ( 4 / 15 ) x = 120 x = $ 4.50 the answer is d . | general |
math_qa__lkAEXxFAYDsxU2Rm | A man rows his boat 78 km downstream and 50 km upstream, taking 2 hours each time. Find the speed of the stream?
Options:
A) 76 kmph
B) 6 kmph
C) 14 kmph
D) 7 kmph
E) 4 kmph | <gadget id="calculator">78 / 2</gadget>
<output>39</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">39 - 25</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>D</result> | D | 7 | A man rows his boat 78 km downstream and 50 km upstream, taking 2 hours each time. Find the speed of the stream? | {
"A": "76 kmph",
"B": "6 kmph",
"C": "14 kmph",
"D": "7 kmph",
"E": "4 kmph"
} | divide(subtract(divide(78, 2), divide(50, 2)), const_2) | divide(n0,n2)|divide(n1,n2)|subtract(#0,#1)|divide(#2,const_2)| | "speed downstream = d / t = 78 / ( 2 ) = 39 kmph speed upstream = d / t = 50 / ( 2 ) = 25 kmph the speed of the stream = ( 39 - 25 ) / 2 = 7 kmph answer : d" | physics |
math_qa__rKZUezeBoLuw1adL | The difference of two numbers is 1465. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? Choices: A) 270 B) 280 C) 290 D) 300 E) 310 | <gadget id="calculator">1_465 + 15</gadget>
<output>1_480</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_480 / 5</gadget>
<output>296</output>
<result>C</result> | C | 290 | The difference of two numbers is 1465. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? | {
"A": "270",
"B": "280",
"C": "290",
"D": "300",
"E": "310"
} | divide(add(1465, 15), subtract(6, const_1)) | add(n0,n2)|subtract(n1,const_1)|divide(#0,#1)| | "let the smaller number be x . then larger number = ( x + 1465 ) . x + 1465 = 6 x + 15 5 x = 1450 x = 290 smaller number = 290 . c )" | general |
math_qa__crgzX4FQ3MJmOVtA | If it takes a machine 3⁄5 minute to produce one item, how many items will it produce in 2 hours? Pick:
A) 1 ⁄ 3 B) 4 ⁄ 3 C) 80 D) 200 E) 180 | <gadget id="calculator">2 * 60</gadget>
<output>120</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">120 / (3/5)</gadget>
<output>200</output>
<result>D</result> | D | 200 | If it takes a machine 3⁄5 minute to produce one item, how many items will it produce in 2 hours? | {
"A": "1 ⁄ 3",
"B": "4 ⁄ 3",
"C": "80",
"D": "200",
"E": "180"
} | divide(multiply(2, const_60), divide(3, 5)) | divide(n0,n1)|multiply(n2,const_60)|divide(#1,#0)| | "1 item takes 3 / 5 min so it takes 120 min to produce x 3 x / 5 = 120 the x = 200 answer : d" | physics |
math_qa__j7QEQgGJQiIZRKZx | $364 is divided among A, B, and C so that A receives half as much as B, and B receives half as much as C. How much money is C's share? Choose the correct choice from the following choices.
A) $ 200 B) $ 204 C) $ 208 D) $ 212 E) $ 216 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 1</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">364 / (7/2)</gadget>
<output>104</output>
<gadget id="calculator">104 * 2</gadget>
<output>208</output>
<result>C</result> | C | 208 | $364 is divided among A, B, and C so that A receives half as much as B, and B receives half as much as C. How much money is C's share? | {
"A": "$ 200",
"B": "$ 204",
"C": "$ 208",
"D": "$ 212",
"E": "$ 216"
} | multiply(divide(364, add(add(divide(const_1, const_2), const_1), const_2)), const_2) | divide(const_1,const_2)|add(#0,const_1)|add(#1,const_2)|divide(n0,#2)|multiply(#3,const_2)| | "let the shares for a , b , and c be x , 2 x , and 4 x respectively . 7 x = 364 x = 52 4 x = 208 the answer is c ." | general |
math_qa__GcP838v916d2PUdi | The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 20%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount?
Choose the correct choice from the following.
A) 32.5 B) 35 C) 48 D) 65 E) 66.67 | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">75 * (1/5)</gadget>
<output>15</output>
<gadget id="calculator">75 - 15</gadget>
<output>60</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">100 * (2/3)</gadget>
<output>200/3 = around 66.666667</output>
<result>E</result> | E | 66.67 | The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 20%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? | {
"A": "32.5",
"B": "35",
"C": "48",
"D": "65",
"E": "66.67"
} | multiply(const_100, divide(subtract(const_100, subtract(subtract(const_100, 25), multiply(subtract(const_100, 25), divide(20, const_100)))), subtract(subtract(const_100, 25), multiply(subtract(const_100, 25), divide(20, const_100))))) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|subtract(#1,#2)|subtract(const_100,#3)|divide(#4,#3)|multiply(#5,const_100)| | "1 ) let the price of jacket initially be $ 100 . 2 ) then it is decreased by 25 % , therefore bringing down the price to $ 75 . 3 ) again it is further discounted by 20 % , therefore bringing down the price to $ 60 . 4 ) now 60 has to be added byx % in order to equal the original price . 60 + ( x % ) 60 = 100 . solving this eq for x , we get x = 66.67 ans is e ." | gain |
math_qa__gPANw2ORaVjmmAH1 | Two consultants can type up a report in 12.5 hours and edit it in 7.5 hours. If Mary needs 30 hours to type the report and Jim needs 12 hours to edit it alone, how many E hours will it take if Jim types the report and Mary edits it immediately after he is done? Answers: A) 41.4 B) 34.1 C) 13.4 D) 12.4 E) 10.8 | <gadget id="calculator">1 / 12.5</gadget>
<output>0.08</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">0.08 - (1/30)</gadget>
<output>0.046667</output>
<gadget id="calculator">1 / 0.046667</gadget>
<output>21.428418</output>
<gadget id="calculator">1 / 7.5</gadget>
<output>0.133333</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">0.133333 - (1/12)</gadget>
<output>0.05</output>
<gadget id="calculator">1 / 0.05</gadget>
<output>20</output>
<gadget id="calculator">21.428418 + 20</gadget>
<output>41.428418</output>
<result>A</result> | A | 41.4 | Two consultants can type up a report in 12.5 hours and edit it in 7.5 hours. If Mary needs 30 hours to type the report and Jim needs 12 hours to edit it alone, how many E hours will it take if Jim types the report and Mary edits it immediately after he is done? | {
"A": "41.4",
"B": "34.1",
"C": "13.4",
"D": "12.4",
"E": "10.8"
} | add(inverse(subtract(divide(const_1, 12.5), divide(const_1, 30))), inverse(subtract(divide(const_1, 7.5), divide(const_1, 12)))) | divide(const_1,n0)|divide(const_1,n2)|divide(const_1,n1)|divide(const_1,n3)|subtract(#0,#1)|subtract(#2,#3)|inverse(#4)|inverse(#5)|add(#6,#7)| | "break down the problem into two pieces : typing and editing . mary needs 30 hours to type the report - - > mary ' s typing rate = 1 / 30 ( rate reciprocal of time ) ( point 1 in theory below ) ; mary and jim can type up a report in 12.5 and - - > 1 / 30 + 1 / x = 1 / 12.5 = 2 / 25 ( where x is the time needed for jim to type the report alone ) ( point 23 in theory below ) - - > x = 150 / 7 ; jim needs 12 hours to edit the report - - > jim ' s editing rate = 1 / 12 ; mary and jim can edit a report in 7.5 and - - > 1 / y + 1 / 12 = 1 / 7.5 = 2 / 15 ( where y is the time needed for mary to edit the report alone ) - - > y = 20 ; how many e hours will it take if jim types the report and mary edits it immediately after he is done - - > x + y = 150 / 7 + 20 = ~ 41.4 answer : a ." | physics |
math_qa__dHJz0NC5NhKxO4Sq | A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 10%, he is only able to save Rs. 500 per month. What is his monthly salary? Pick one:
A) rs . 4500 B) rs . 4000 C) rs . 4167 D) rs . 4200 E) rs . 3000 | <gadget id="calculator">500 * 100</gadget>
<output>50_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">80 * (1/10)</gadget>
<output>8</output>
<gadget id="calculator">80 + 8</gadget>
<output>88</output>
<gadget id="calculator">100 - 88</gadget>
<output>12</output>
<gadget id="calculator">50_000 / 12</gadget>
<output>12_500/3 = around 4_166.666667</output>
<result>C</result> | C | 4,167 | A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 10%, he is only able to save Rs. 500 per month. What is his monthly salary? | {
"A": "rs . 4500",
"B": "rs . 4000",
"C": "rs . 4167",
"D": "rs . 4200",
"E": "rs . 3000"
} | divide(multiply(500, const_100), subtract(const_100, add(subtract(const_100, 20), multiply(subtract(const_100, 20), divide(10, const_100))))) | divide(n1,const_100)|multiply(n2,const_100)|subtract(const_100,n0)|multiply(#0,#2)|add(#3,#2)|subtract(const_100,#4)|divide(#1,#5) | income = rs . 100 expenditure = rs . 80 savings = rs . 20 present expenditure 80 + 80 * ( 10 / 100 ) = rs . 88 present savings = 100 – 88 = rs . 12 if savings is rs . 12 , salary = rs . 100 if savings is rs . 500 , salary = 100 / 12 * 500 = 4167 answer : c | general |
math_qa__DoWzxbIxdgmpSRoo | What is the minimum value of |x-4| + |x+7| + |x-5| ? Choose one:
A) - 3
B) 3
C) 5
D) - 12
E) 12 | <gadget id="calculator">7 + 5</gadget>
<output>12</output>
<result>E</result> | E | 12 | What is the minimum value of |x-4| + |x+7| + |x-5| ? | {
"A": "- 3",
"B": "3",
"C": "5",
"D": "- 12",
"E": "12"
} | add(7, 5) | add(n1,n2)| | "a can not be the answer as all the three terms are in modulus and hence the answer will be non negative . | x - 4 | > = 0 - - > minimum occurs at x = 4 | x + 7 | > = 0 - - > minimum occurs at x = - 7 | x - 5 | > = 0 - - > minimum occurs at x = 5 x = - 7 - - > result = 11 + 0 + 12 = 23 . also any negative value will push the combined value of | x - 4 | + | x - 5 | to a value > 9 . x = 4 - - > result = 0 + 11 + 1 = 12 x = 5 - - > result = 1 + 12 + 0 = 13 x = 7 - - > result = 3 + 14 + 2 = 19 so minimum value of the expression occurs at x = 4 and the resultant value = 12 answer : e" | general |
math_qa__8rvDUjlA7quXnifO | Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 456? Answers.
A) 18 %
B) 26.57 %
C) 20 %
D) 19 %
E) none of these | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">115 / 100</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">540 * (23/20)</gadget>
<output>621</output>
<gadget id="calculator">621 - 456</gadget>
<output>165</output>
<gadget id="calculator">165 * 100</gadget>
<output>16_500</output>
<gadget id="calculator">16_500 / 621</gadget>
<output>5_500/207 = around 26.570048</output>
<result>B</result> | B | 26.57 | Mahesh marks an article 15% above the cost price of Rs. 540. What must be his discount percentage if he sells it at Rs. 456? | {
"A": "18 %",
"B": "26.57 %",
"C": "20 %",
"D": "19 %",
"E": "none of these"
} | divide(multiply(subtract(multiply(540, divide(add(const_100, 15), const_100)), 456), const_100), multiply(540, divide(add(const_100, 15), const_100))) | add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|subtract(#2,n2)|multiply(#3,const_100)|divide(#4,#2)| | "cp = rs . 540 , mp = 540 + 15 % of 540 = rs . 621 sp = rs . 456 , discount = 621 - 456 = 165 discount % = 165 / 621 * 100 = 26.57 % answer : b" | gain |
math_qa__OV7OgJDluP7aF7HG | kate and danny each have $ 10 . together , they flip a fair coin 5 times . every time the coin lands on heads , kate gives danny $ 1 . every time the coin lands on tails , danny gives kate $ 1 . after the 5 coin flips , what is the probability that kate has more than $ 10 but less than $ 15 ? Choose the correct choice from the following answers:
A) 5 / 16 B) 1 / 2 C) 12 / 30 D) 15 / 32 E) 3 / 8 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(1)</gadget>
<output>1</output>
<gadget id="calculator">24 * 1</gadget>
<output>24</output>
<gadget id="calculator">120 / 24</gadget>
<output>5</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">5 + 10</gadget>
<output>15</output>
<gadget id="calculator">2 ** 5</gadget>
<output>32</output>
<gadget id="calculator">15 / 32</gadget>
<output>15/32 = around 0.46875</output>
<result>D</result> | D | 0.46875 | kate and danny each have $ 10 . together , they flip a fair coin 5 times . every time the coin lands on heads , kate gives danny $ 1 . every time the coin lands on tails , danny gives kate $ 1 . after the 5 coin flips , what is the probability that kate has more than $ 10 but less than $ 15 ? | {
"A": "5 / 16",
"B": "1 / 2",
"C": "12 / 30",
"D": "15 / 32",
"E": "3 / 8"
} | divide(add(divide(factorial(5), multiply(factorial(const_4), factorial(const_1))), divide(factorial(5), multiply(factorial(const_3), factorial(const_2)))), power(const_2, 5)) | factorial(n1)|factorial(const_4)|factorial(const_1)|factorial(const_3)|factorial(const_2)|power(const_2,n1)|multiply(#1,#2)|multiply(#3,#4)|divide(#0,#6)|divide(#0,#7)|add(#8,#9)|divide(#10,#5) | the probability of the coin landing tails up either 3 or 4 times = p ( 3 t ) + p ( 4 t ) binomial distribution formula : nck p ^ k ( 1 - p ) ^ ( n - k ) p ( 3 t ) = 5 c 3 ( 1 / 2 ) ^ 3 ( 1 / 2 ) ^ 2 = 10 ( 1 / 2 ) ^ 5 p ( 4 t ) = 5 c 4 ( 1 / 2 ) ^ 4 ( 1 / 2 ) ^ 1 = 5 ( 1 / 2 ) ^ 5 = > p ( 3 t ) + p ( 4 t ) = 15 / 32 answer : d | general |
math_qa__Oe8EYVZdoKrofQ2U | There are two groups of students in the sixth grade. There are 30 students in group A, and 50 students in group B. If, on a particular day, 20% of the students in group A forget their homework, and 12% of the students in group B forget their homework, then what percentage of the sixth graders forgot their homework? Choose the correct answer.
A) 13 % B) 14 % C) 15 % D) 16 % E) 17 % | <gadget id="calculator">30 * 20</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">50 * 12</gadget>
<output>600</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">30 + 50</gadget>
<output>80</output>
<gadget id="calculator">12 / 80</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>C</result> | C | 15 | There are two groups of students in the sixth grade. There are 30 students in group A, and 50 students in group B. If, on a particular day, 20% of the students in group A forget their homework, and 12% of the students in group B forget their homework, then what percentage of the sixth graders forgot their homework? | {
"A": "13 %",
"B": "14 %",
"C": "15 %",
"D": "16 %",
"E": "17 %"
} | multiply(divide(add(divide(multiply(30, 20), const_100), divide(multiply(50, 12), const_100)), add(30, 50)), const_100) | add(n0,n1)|multiply(n0,n2)|multiply(n1,n3)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100) | total students = 30 + 50 = 80 20 % of 30 = 6 12 & of 50 = 6 total students who forget homework = 6 + 6 = 12 percentage = 1280 ∗ 100 = 15 = 12 / 80 ∗ 100 = 15 ; answer = c = 15 % | gain |
math_qa__Phv0khnp9USPDFFS | Raman mixed 34 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction? Choose the correct choice from the following options
A) 129 B) 287 C) 192 D) 188 E) 112 | <gadget id="calculator">34 * 150</gadget>
<output>5_100</output>
<gadget id="calculator">36 * 125</gadget>
<output>4_500</output>
<gadget id="calculator">5_100 + 4_500</gadget>
<output>9_600</output>
<gadget id="calculator">36 + 34</gadget>
<output>70</output>
<gadget id="calculator">9_600 / 70</gadget>
<output>960/7 = around 137.142857</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(960/7) * (2/5)</gadget>
<output>384/7 = around 54.857143</output>
<gadget id="calculator">(960/7) + (384/7)</gadget>
<output>192</output>
<result>C</result> | C | 192 | Raman mixed 34 kg of butter at Rs. 150 per kg with 36 kg butter at the rate of Rs. 125 per kg. At what price per kg should he sell the mixture to make a profit of 40% in the transaction? | {
"A": "129",
"B": "287",
"C": "192",
"D": "188",
"E": "112"
} | add(divide(add(multiply(34, 150), multiply(36, 125)), add(36, 34)), multiply(divide(add(multiply(34, 150), multiply(36, 125)), add(36, 34)), divide(40, const_100))) | add(n0,n2)|divide(n4,const_100)|multiply(n0,n1)|multiply(n2,n3)|add(#2,#3)|divide(#4,#0)|multiply(#5,#1)|add(#5,#6)| | "explanation : cp per kg of mixture = [ 34 ( 150 ) + 36 ( 125 ) ] / ( 34 + 36 ) = rs . 137.14 sp = cp [ ( 100 + profit % ) / 100 ] = 137.14 * [ ( 100 + 40 ) / 100 ] = rs . 192 . answer : c" | gain |
math_qa__O2i0dnMFSELadkC2 | A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is? Answers:
A) 16 % B) 12 % C) 74 % D) 10 % E) 45 % | <gadget id="calculator">5_000 * 2</gadget>
<output>10_000</output>
<gadget id="calculator">3_000 * 4</gadget>
<output>12_000</output>
<gadget id="calculator">10_000 + 12_000</gadget>
<output>22_000</output>
<gadget id="calculator">2_200 / 22_000</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>D</result> | D | 10 | A lent Rs. 5000 to B for 2 years and Rs. 3000 to C for 4 years on simple interest at the same rate of interest and received Rs. 2200 in all from both of them as interest. The rate of interest per annum is? | {
"A": "16 %",
"B": "12 %",
"C": "74 %",
"D": "10 %",
"E": "45 %"
} | multiply(divide(2200, add(multiply(5000, 2), multiply(3000, 4))), const_100) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)|divide(n4,#2)|multiply(#3,const_100)| | "let the rate be r % p . a . then , ( 5000 * r * 2 ) / 100 + ( 3000 * r * 4 ) / 100 = 2200 100 r + 120 r = 2200 r = 10 % answer : d" | gain |
math_qa__ARlJxhmhedH80Dc3 | when 1 / 10 percent of 7000 is subtracted from 1 / 10 of 7000 , the difference is Choose the correct option.
A) 0 B) 50 C) 450 D) 693 E) 500 | <gadget id="calculator">10 * 7_000</gadget>
<output>70_000</output>
<gadget id="calculator">70_000 / 100</gadget>
<output>700</output>
<result>D</result> | D | 693 | when 1 / 10 percent of 7000 is subtracted from 1 / 10 of 7000 , the difference is | {
"A": "0",
"B": "50",
"C": "450",
"D": "693",
"E": "500"
} | divide(multiply(10, 7000), const_100) | multiply(n1,n2)|divide(#0,const_100) | we can break this problem into two parts : 1 ) what is 1 / 10 percent of 7,000 ? 2 ) what is 1 / 10 of 7,000 ? to calculate 1 / 10 percent of 7,000 we must first remember to divide 1 / 10 by 100 . so we have : ( 1 / 10 ) / ( 100 ) to divide a number by 100 means to multiply it by 1 / 100 , so we have : 1 / 10 x 1 / 100 = 1 / 1,000 thus , 1 / 10 percent of 7,000 = 1 / 1,000 x 7,000 = 7 . now let ' s concentrate on part 2 . we need to calculate 1 / 10 of 7,000 . to do this we simply multiply 1 / 10 by 7,000 . 1 / 10 x 7,000 = 700 the answer to part 1 is 7 , and the answer to part 2 is 700 . their difference is 700 – 7 = 693 . answer d . | general |
math_qa__2Kq3RFwKXv9KvZ2F | A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train? Choose the correct choice from the following options:
A) 288
B) 279
C) 277
D) 272
E) 150 | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 9</gadget>
<output>150</output>
<result>E</result> | E | 150 | A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train? | {
"A": "288",
"B": "279",
"C": "277",
"D": "272",
"E": "150"
} | multiply(divide(multiply(60, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * 5 / 18 = 50 / 3 m / sec length of the train = speed * time = 50 / 3 * 9 = 150 m answer : e" | physics |
math_qa__GfcvKWzpt90bsjEs | Into a bag there are 20 honey and 5 cherry candies. If a boy pick only two candies simultaneous and randomly, what is the probability that he picks one candy of each flavor? Choose the correct choice from the following answers:
A) 2 / 25
B) 1 / 50
C) 1 / 12
D) 1 / 6
E) 1 / 3 | <gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">20 / 25</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">5 / 25</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(4/5) * (1/5)</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 2</gadget>
<output>8/25 = around 0.32</output>
<result>E</result> | E | 0.333333 | Into a bag there are 20 honey and 5 cherry candies. If a boy pick only two candies simultaneous and randomly, what is the probability that he picks one candy of each flavor? | {
"A": "2 / 25",
"B": "1 / 50",
"C": "1 / 12",
"D": "1 / 6",
"E": "1 / 3"
} | multiply(multiply(divide(20, add(20, 5)), divide(5, add(20, 5))), const_2) | add(n0,n1)|divide(n0,#0)|divide(n1,#0)|multiply(#1,#2)|multiply(#3,const_2) | we are told that we have 25 candies , 20 honey and 5 cherry candies . the candies are picked simultaneous and randomly , c 1 and c 2 , in different flavors . there are two acceptable outcomes : 1 ) c 1 is honey and c 2 is cherry ; 2 ) c 1 is cherry and c 2 is honey . let ' s go : 1 ) c 1 = ( 20 / 25 ) ( 5 / 24 ) = 1 / 6 chance of this happening . 2 ) c 2 = ( 5 / 25 ) ( 20 / 24 ) = 1 / 6 chance of this happening . then : ( 1 / 6 ) + ( 1 / 6 ) = 1 / 3 , chance of getting the result that you wanted . answer e . | probability |
math_qa__R8gtHLcVLLSfApVB | A line has a slope of 3/4 and intersects the point (-12, -39). At which point E does this line intersect the x-axis? Pick one
A) ( 400 ) B) ( 300 ) C) ( 040 ) D) ( 4030 ) E) ( 030 ) | <gadget id="calculator">-39</gadget>
<output>-39</output>
<gadget id="calculator">-12</gadget>
<output>-12</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(-12) * (3/4)</gadget>
<output>-9</output>
<gadget id="calculator">(-39) - (-9)</gadget>
<output>-30</output>
<gadget id="calculator">(-30) / (3/4)</gadget>
<output>-40</output>
<gadget id="calculator">-(-40)</gadget>
<output>40</output>
<gadget id="calculator">40 * 10</gadget>
<output>400</output>
<result>A</result> | A | 400 | A line has a slope of 3/4 and intersects the point (-12, -39). At which point E does this line intersect the x-axis? | {
"A": "( 400 )",
"B": "( 300 )",
"C": "( 040 )",
"D": "( 4030 )",
"E": "( 030 )"
} | multiply(negate(divide(subtract(negate(39), multiply(negate(12), divide(3, 4))), divide(3, 4))), const_10) | divide(n0,n1)|negate(n3)|negate(n2)|multiply(#0,#2)|subtract(#1,#3)|divide(#4,#0)|negate(#5)|multiply(#6,const_10) | assume that the equation of the line is y = mx + c , where m and c are the slope and y - intercept . you are also given that the line crosses the point ( - 12 , - 39 ) , this means that this point will also lie on the line above . thus you get - 39 = m * ( - 12 ) + c , with m = 3 / 4 as the slope is given to be 3 / 4 . after substituting the above values , you get c = - 30 . thus the equation of the line is y = 0.75 * x - 30 and the point where it will intersect the x - axis will be with y coordinate = 0 . put y = 0 in the above equation of the line and you will get , x = 40 . thus , the point e of intersection is ( 400 ) . a is the correct answer . | general |
math_qa__c1ymhT7HxhWiFLmK | The salary of a person was reduced by 35%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?
Answers.
A) 50 % B) 32 % C) 25 % D) 54 % E) 29 % | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">100 * (7/20)</gadget>
<output>35</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">35 / 65</gadget>
<output>7/13 = around 0.538462</output>
<gadget id="calculator">(7/13) * 100</gadget>
<output>700/13 = around 53.846154</output>
<result>D</result> | D | 54 | The salary of a person was reduced by 35%. By what percent should his reduced salary be raised so as to bring it at par with his original salary? | {
"A": "50 %",
"B": "32 %",
"C": "25 %",
"D": "54 %",
"E": "29 %"
} | multiply(divide(multiply(const_100, divide(35, const_100)), subtract(const_100, multiply(const_100, divide(35, const_100)))), const_100) | divide(n0,const_100)|multiply(#0,const_100)|subtract(const_100,#1)|divide(#1,#2)|multiply(#3,const_100)| | "let the original salary be $ 100 new salary = $ 65 increase on 65 = 35 increase on 100 = 35 / 65 * 100 = 54 % ( approximately ) answer is d" | gain |
math_qa__m0m6Up6GnMvF1P0A | A, B and C invest in the ratio of 3 : 4: 5. The percentage of return on their investments are in the ratio of 6 : 5 : 4. Find the total earnings, If B earns Rs. 100 more than A : Select the correct option.
A) 2900
B) 7250
C) 2767
D) 1998
E) 2771 | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">18 + 20</gadget>
<output>38</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">38 + 20</gadget>
<output>58</output>
<gadget id="calculator">20 - 18</gadget>
<output>2</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">58 * 50</gadget>
<output>2_900</output>
<result>A</result> | A | 2,900 | A, B and C invest in the ratio of 3 : 4: 5. The percentage of return on their investments are in the ratio of 6 : 5 : 4. Find the total earnings, If B earns Rs. 100 more than A : | {
"A": "2900",
"B": "7250",
"C": "2767",
"D": "1998",
"E": "2771"
} | multiply(add(add(multiply(3, 6), multiply(4, 5)), multiply(5, 4)), divide(100, subtract(multiply(4, 5), multiply(3, 6)))) | multiply(n0,n3)|multiply(n1,n2)|add(#0,#1)|subtract(#1,#0)|add(#2,#1)|divide(n6,#3)|multiply(#4,#5)| | "explanation : a b c investment 3 x 4 x 5 x rate of return 6 y % 5 y % 4 y % return \ inline \ frac { 18 xy } { 100 } \ inline \ frac { 20 xy } { 100 } \ inline \ frac { 20 xy } { 100 } total = ( 18 + 20 + 20 ) = \ inline \ frac { 58 xy } { 100 } b ' s earnings - a ' s earnings = \ inline \ frac { 2 xy } { 100 } = 100 total earning = \ inline \ frac { 58 xy } { 100 } = 2900 answer : a ) rs . 2900" | general |
math_qa__O5XPdIjz4PyreQ7v | A can build a wall in the same time in which B and C together can do it. If A and B together could do it in 25 days and C alone in 35 days, in what time could B alone do it? Choices:
A) 275 days B) 178 days C) 185 days D) 175 days E) 675 days | <gadget id="calculator">25 * 35</gadget>
<output>875</output>
<gadget id="calculator">35 - 25</gadget>
<output>10</output>
<gadget id="calculator">875 / 10</gadget>
<output>175/2 = around 87.5</output>
<gadget id="calculator">(175/2) * 2</gadget>
<output>175</output>
<result>D</result> | D | 175 | A can build a wall in the same time in which B and C together can do it. If A and B together could do it in 25 days and C alone in 35 days, in what time could B alone do it? | {
"A": "275 days",
"B": "178 days",
"C": "185 days",
"D": "175 days",
"E": "675 days"
} | multiply(divide(multiply(25, 35), subtract(35, 25)), const_2) | multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1)|multiply(#2,const_2) | explanation : no explanation is available for this question ! answer : d | physics |
math_qa__nZStXDcOsDf6FSwO | If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be? Choose the correct choice from the following answers
A) 4 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">100 / 25</gadget>
<output>4</output>
<result>A</result> | A | 4 | If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | divide(multiply(add(6, const_4), 10), add(15, 10)) | add(n0,const_4)|add(n2,n6)|multiply(n2,#0)|divide(#2,#1)| | "let 1 men ' s 1 day work = x and 1 boy ' s 1 day work = y . then , 6 x + 8 y = 1 / 10 and 26 x + 48 y = 1 / 2 solving these two equations , we get : x = 1 / 100 and y = 1 / 200 ( 15 men + 20 boys ) ' s 1 day work = ( 15 / 100 + 20 / 200 ) = 1 / 4 15 men and 20 boys can do the work in 4 days . answer : a" | physics |
math_qa__BMWhOjzFerP8qrxw | A man goes downstream at 11 kmph, and upstream8 kmph. The speed of the stream is Choose the correct choice from the following choices.
A) 1.5 kmph B) 4 kmph C) 16 kmph D) 2.5 kmph E) 26 kmph | <gadget id="calculator">11 - 8</gadget>
<output>3</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<result>A</result> | A | 1.5 | A man goes downstream at 11 kmph, and upstream8 kmph. The speed of the stream is | {
"A": "1.5 kmph",
"B": "4 kmph",
"C": "16 kmph",
"D": "2.5 kmph",
"E": "26 kmph"
} | divide(subtract(11, 8), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "speed of the stream = 1 / 2 ( 11 - 8 ) kmph = 1.5 kmph . correct option : a" | physics |
math_qa__EWaTX9idZWobWiCv | In a 1000 m race, A beats B by 70 m and B beats C by 100 m. In the same race, by how many meters does A beat C? Choose the correct choice
A) 145 m B) 176 m C) 168 m D) 163 m E) 218 m | <gadget id="calculator">1_000 - 70</gadget>
<output>930</output>
<gadget id="calculator">1_000 - 100</gadget>
<output>900</output>
<gadget id="calculator">930 * 900</gadget>
<output>837_000</output>
<gadget id="calculator">837_000 / 1_000</gadget>
<output>837</output>
<gadget id="calculator">1_000 - 837</gadget>
<output>163</output>
<result>D</result> | D | 163 | In a 1000 m race, A beats B by 70 m and B beats C by 100 m. In the same race, by how many meters does A beat C? | {
"A": "145 m",
"B": "176 m",
"C": "168 m",
"D": "163 m",
"E": "218 m"
} | subtract(1000, divide(multiply(subtract(1000, 70), subtract(1000, 100)), 1000)) | subtract(n0,n1)|subtract(n0,n2)|multiply(#0,#1)|divide(#2,n0)|subtract(n0,#3) | by the time a covers 1000 m , b covers ( 1000 - 70 ) = 930 m . by the time b covers 1000 m , c covers ( 1000 - 100 ) = 900 m . so , the ratio of speeds of a and c = 1000 / 930 * 1000 / 900 = 1000 / 837 so , by the time a covers 1000 m , c covers 837 m . so in 1000 m race a beats c by 1000 - 837 = 163 m . answer : d | physics |
math_qa__DACteOq6BVSBg50x | What number times (1⁄2)^2 will give the value of 2^3?
Choose the correct choice from the following options.
A) 2 B) 4 C) 8 D) 16 E) 32 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">4 * 8</gadget>
<output>32</output>
<result>E</result> | E | 32 | What number times (1⁄2)^2 will give the value of 2^3? | {
"A": "2",
"B": "4",
"C": "8",
"D": "16",
"E": "32"
} | multiply(power(2, 2), power(2, 3)) | power(n1,n1)|power(n1,n4)|multiply(#0,#1) | x * ( 1 / 2 ) ^ 2 = 2 ^ 3 x = 2 ^ 2 * 2 ^ 3 = 2 ^ 5 = 32 the answer is e . | general |
math_qa__89DVmkMC58CVRbsw | A bowl was filled with 10 ounces of water, and 0.00008 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? Choose the correct choice from the following options
A) 0.004 % B) 0.04 % C) 0.40 % D) 4 % E) 40 % | <gadget id="calculator">50 * 0.00008</gadget>
<output>0.004</output>
<gadget id="calculator">0.004 / 10</gadget>
<output>0.0004</output>
<gadget id="calculator">0.0004 * 100</gadget>
<output>0.04</output>
<result>B</result> | B | 0.04 | A bowl was filled with 10 ounces of water, and 0.00008 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.004 %",
"B": "0.04 %",
"C": "0.40 %",
"D": "4 %",
"E": "40 %"
} | multiply(divide(multiply(50, 0.00008), 10), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "total amount of water evaporated each day during a 50 - day period = . 00008 * 50 = . 00008 * 100 / 2 = . 008 / 2 = . 004 percent of the original amount of water evaporated during this period = ( . 004 / 10 ) * 100 % = 0.04 % answer b" | gain |
math_qa__0y8aT2cSZfaPb27n | A trader sells 30 meters of cloth for Rs. 4500 at the profit of Rs. 10 per metre of cloth. What is the cost price of one metre of cloth?
Pick one.
A) rs . 80 B) rs . 185 C) rs . 140 D) rs . 295 E) none of these | <gadget id="calculator">4_500 / 30</gadget>
<output>150</output>
<gadget id="calculator">150 - 10</gadget>
<output>140</output>
<result>C</result> | C | 140 | A trader sells 30 meters of cloth for Rs. 4500 at the profit of Rs. 10 per metre of cloth. What is the cost price of one metre of cloth? | {
"A": "rs . 80",
"B": "rs . 185",
"C": "rs . 140",
"D": "rs . 295",
"E": "none of these"
} | subtract(divide(4500, 30), 10) | divide(n1,n0)|subtract(#0,n2)| | "sp of 1 m of cloth = 4500 / 30 = rs . 150 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 150 - rs . 10 = rs . 140 . answer : c" | physics |
math_qa__LGAfsEYhDAy5Fs3S | For any even integer P, 300 multiplied by P is square of an integer. What is the least value of P? Answers: A) 3 B) 4 C) 10 D) 12 E) 14 | <gadget id="calculator">300 / 100</gadget>
<output>3</output>
<result>A</result> | A | 3 | For any even integer P, 300 multiplied by P is square of an integer. What is the least value of P? | {
"A": "3",
"B": "4",
"C": "10",
"D": "12",
"E": "14"
} | divide(300, const_100) | divide(n0,const_100) | p ∗ 3 ∗ 10 ^ 2 = s ^ 2 so , s = √ p ∗ 3 ∗ 10 ^ 2 so , if p = 3 we get a perfect square number ! ! hence answer will be ( a ) 3 | geometry |
math_qa__fGJSR59BrMUuagqQ | The average marks of a class of 20 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students? Choose the correct choice from the following choices.
A) 44.28
B) 54.28
C) 34.28
D) 64.28
E) 74.28 | <gadget id="calculator">20 * 40</gadget>
<output>800</output>
<gadget id="calculator">50 * 60</gadget>
<output>3_000</output>
<gadget id="calculator">800 + 3_000</gadget>
<output>3_800</output>
<gadget id="calculator">20 + 50</gadget>
<output>70</output>
<gadget id="calculator">3_800 / 70</gadget>
<output>380/7 = around 54.285714</output>
<result>B</result> | B | 54.28 | The average marks of a class of 20 students is 40 and that of another class of 50 students is 60. Find the average marks of all the students? | {
"A": "44.28",
"B": "54.28",
"C": "34.28",
"D": "64.28",
"E": "74.28"
} | divide(add(multiply(20, 40), multiply(50, 60)), add(20, 50)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "sum of the marks for the class of 20 students = 20 * 40 = 800 sum of the marks for the class of 50 students = 50 * 60 = 3000 sum of the marks for the class of 70 students = 800 + 3000 = 3800 average marks of all the students = 3800 / 70 = 54.28 answer : b" | general |
math_qa__KOz91Dxqb8dXGecP | In shop there are 10 bulbs, a total of 4 are defective. If a customer buys 4 bulbs selected at random from the box, what is the probability that neither bulbs will be defective? Pick: A) 2 / 19 B) 3 / 29 C) 4 / 15 D) 1 / 15 E) 1 / 2 | <gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">6 / 10</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(2/3) - (3/5)</gadget>
<output>1/15 = around 0.066667</output>
<result>D</result> | D | 0.066667 | In shop there are 10 bulbs, a total of 4 are defective. If a customer buys 4 bulbs selected at random from the box, what is the probability that neither bulbs will be defective? | {
"A": "2 / 19",
"B": "3 / 29",
"C": "4 / 15",
"D": "1 / 15",
"E": "1 / 2"
} | subtract(divide(4, subtract(10, 4)), divide(subtract(10, 4), 10)) | subtract(n0,n1)|divide(n1,#0)|divide(#0,n0)|subtract(#1,#2) | first , there are 6 c 4 ways you can select 6 good bulbs from 4 good ones . second , there are 10 c 4 ways you select 4 bulbs from 10 ones in the box . then , the probability that neither bulb will be defective is : 6 c 4 / 10 c 4 = 15 / 210 = 1 / 15 answer is d | general |
math_qa__0wFaV1l5qtTSdVh3 | Employees of a certain company are each to receive a unique 5-digit identification code consisting of the digits 0, 1, 2, 3, and 4 such that no digit is used more than once in any given code. In valid codes, the second digit in the code is exactly twice the first digit. How many valid codes are there? Select the correct option.
A) 10
B) 12
C) 14
D) 16
E) 18 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<result>B</result> | B | 12 | Employees of a certain company are each to receive a unique 5-digit identification code consisting of the digits 0, 1, 2, 3, and 4 such that no digit is used more than once in any given code. In valid codes, the second digit in the code is exactly twice the first digit. How many valid codes are there? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | multiply(multiply(const_2, const_3), 2) | multiply(const_2,const_3)|multiply(n3,#0) | there are 3 ! ways to make codes starting with 12 . there are 3 ! ways to make codes starting with 24 . the number of codes is 2 * 3 ! = 12 . the answer is b . | general |
math_qa__Dxo49SfZFfcdpZ6U | 36 men can complete a piece of work in 18 days. In how many days will 72 men complete the same work ? Choose the correct choice from the following
A) 24 B) 17 C) 18 D) 9 E) 11 | <gadget id="calculator">18 * 36</gadget>
<output>648</output>
<gadget id="calculator">648 / 72</gadget>
<output>9</output>
<result>D</result> | D | 9 | 36 men can complete a piece of work in 18 days. In how many days will 72 men complete the same work ? | {
"A": "24",
"B": "17",
"C": "18",
"D": "9",
"E": "11"
} | divide(multiply(18, 36), 72) | multiply(n0,n1)|divide(#0,n2)| | "explanation : less men , means more days { indirect proportion } let the number of days be x then , 72 : 36 : : 18 : x x = 9 answer : d ) 9 days" | physics |
math_qa__9E5G0XdGGZepwfPM | If p is the product of the integers from 1 to 34, inclusive, what is the greatest integer k for which 3^k is a factor of p? Choose the correct choice from the following answers:
A) 11
B) 13
C) 15
D) 17
E) 19 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<result>C</result> | C | 15 | If p is the product of the integers from 1 to 34, inclusive, what is the greatest integer k for which 3^k is a factor of p? | {
"A": "11",
"B": "13",
"C": "15",
"D": "17",
"E": "19"
} | add(multiply(3, const_4), 3) | multiply(n2,const_4)|add(n2,#0) | 34 ! has 3 , 6 , 9 , . . . . 30 , 33 as factors , which are 11 multiples of 3 . we need to add 4 more to these 11 because of 9 , 18 , and 27 . the greatest integer of k is 15 . the answer is c . | general |
math_qa__t9TcxvY73wK3SoSq | A present value of a machine is $2500. Its value depletiation rate is 5% per annum then find the machine value after 2 years?
Choose the correct choice from the following answers:
A) $ 2100 B) $ 2546 C) $ 2256 D) $ 2451 E) $ 2345 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 - (1/20)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) ** 2</gadget>
<output>361/400 = around 0.9025</output>
<gadget id="calculator">2_500 * (361/400)</gadget>
<output>9_025/4 = around 2_256.25</output>
<result>C</result> | C | 2,256 | A present value of a machine is $2500. Its value depletiation rate is 5% per annum then find the machine value after 2 years? | {
"A": "$ 2100",
"B": "$ 2546",
"C": "$ 2256",
"D": "$ 2451",
"E": "$ 2345"
} | multiply(2500, power(subtract(const_1, divide(5, const_100)), 2)) | divide(n1,const_100)|subtract(const_1,#0)|power(#1,n2)|multiply(n0,#2)| | "p = $ 2500 r = 5 % t = 2 years machine value after 2 years = p [ ( 1 - r / 100 ) ^ t ] = 2500 * 19 / 20 * 19 / 20 = $ 2256 approximately answer is c" | gain |
math_qa__zGkEmtUFFY9zHrsv | The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1280. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ? Choose the correct choice from the following choices.
A) 2480 B) 3490 C) 6785 D) 8255 E) 9255 | <gadget id="calculator">30 + 1</gadget>
<output>31</output>
<gadget id="calculator">30 * 31</gadget>
<output>930</output>
<gadget id="calculator">2 * 30</gadget>
<output>60</output>
<gadget id="calculator">60 + 1</gadget>
<output>61</output>
<gadget id="calculator">930 * 61</gadget>
<output>56_730</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">56_730 / 6</gadget>
<output>9_455</output>
<gadget id="calculator">9_455 - 1_280</gadget>
<output>8_175</output>
<result>D</result> | D | 8,255 | The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1280. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ? | {
"A": "2480",
"B": "3490",
"C": "6785",
"D": "8255",
"E": "9255"
} | subtract(divide(multiply(multiply(30, add(30, 1)), add(multiply(2, 30), 1)), add(3, 3)), 1280) | add(n17,n1)|add(n5,n5)|multiply(n17,n2)|add(#2,n1)|multiply(n17,#0)|multiply(#3,#4)|divide(#5,#1)|subtract(#6,n9)| | "you ' ll never need a formula for the sums of squares on the actual gmat . you do n ' t need to use that formula here , though it ' s not all that straightforward to solve without one . two different approaches : 16 ^ 2 + 17 ^ 2 + 18 ^ 2 + . . . + 30 ^ 2 = ( 15 + 1 ) ^ 2 + ( 15 + 2 ) ^ 2 + ( 15 + 3 ) ^ 2 + . . . + ( 15 + 15 ) ^ 2 now we can expand each square ; they are all in the ( x + y ) ^ 2 = x ^ 2 + 2 xy + y ^ 2 pattern . = ( 15 ^ 2 + 2 * 15 + 1 ^ 2 ) + ( 15 ^ 2 + 4 * 15 + 2 ^ 2 ) + ( 15 ^ 2 + 6 * 15 + 3 ^ 2 ) + . . . + ( 15 ^ 2 + 30 * 15 + 15 ^ 2 ) now we have fifteen 15 ^ 2 terms , so adding these gives 15 * 15 ^ 2 = 15 ^ 3 = 3375 . we also have the entire sum 1 ^ 2 + 2 ^ 2 + . . . + 15 ^ 2 , which we know is equal to 1240 . finally adding the middle terms , we have : 2 * 15 + 4 * 15 + 6 * 15 + . . . + 30 * 15 = 15 ( 2 + 4 + 6 + . . . . + 30 ) = 15 * 2 * ( 1 + 2 + 3 + . . . + 15 ) = 15 * 2 * 8 * 15 = 3600 so the sum must be 3375 + 1240 + 3600 = 8215 alternatively , we can use a different factoring pattern . we want to find the value of 30 ^ 2 + 29 ^ 2 + . . . + 17 ^ 2 + 16 ^ 2 . well if we subtract 15 ^ 2 + 14 ^ 2 + . . . . + 2 ^ 2 + 1 ^ 2 from this , the answer will be 1240 less than what we want to find . so if we can find the value of 30 ^ 2 + 29 ^ 2 + . . . + 17 ^ 2 + 16 ^ 2 - ( 15 ^ 2 + 14 ^ 2 + . . . . + 2 ^ 2 + 1 ^ 2 ) then we can add 1240 to get the answer . now grouping the terms above to get differences of squares , we have = ( 30 ^ 2 - 15 ^ 2 ) + ( 29 ^ 2 - 14 ^ 2 ) + . . . + ( 16 ^ 2 - 1 ^ 2 ) and factoring each of these using x ^ 2 - y ^ 2 = ( x + y ) ( x - y ) , we have = 45 * 15 + 43 * 15 + 41 * 15 + . . . + 17 * 15 = 15 ( 45 + 43 + 41 + . . . + 17 ) in brackets we have an equally spaced sum with fifteen terms , which we can evaluate using the familiar formula . so the above equals 15 * 15 * 62 / 2 = 6975 and adding back the 1280 , we get the answer of 8255 . ( ans d )" | general |
math_qa__6rsmWCIQKLK4dz5h | The diameter of the wheel of a car is 120m. How many revolution/min must the wheel makein order to keep a speed of 60 km/hour approximately? Select: A) 210 B) 245 C) 230 D) 254 E) 265 | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 60</gadget>
<output>1_000</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(22/7) * (6/5)</gadget>
<output>132/35 = around 3.771429</output>
<gadget id="calculator">1_000 / (132/35)</gadget>
<output>8_750/33 = around 265.151515</output>
<result>E</result> | E | 265 | The diameter of the wheel of a car is 120m. How many revolution/min must the wheel makein order to keep a speed of 60 km/hour approximately? | {
"A": "210",
"B": "245",
"C": "230",
"D": "254",
"E": "265"
} | divide(divide(multiply(60, const_1000), const_60), multiply(divide(add(multiply(const_2, const_10), const_2), add(const_4, const_3)), divide(120, const_100))) | add(const_3,const_4)|divide(n0,const_100)|multiply(n1,const_1000)|multiply(const_10,const_2)|add(#3,const_2)|divide(#2,const_60)|divide(#4,#0)|multiply(#6,#1)|divide(#5,#7) | distance to be covered in 1 min . = ( 60 x 1000 ) / ( 60 ) m = 1000 m . circumference of the wheel = ( 2 x ( 22 / 7 ) x 0.60 ) m = 3.77 m . number of revolutions per min . = ( 1000 / 3.77 ) = 265 e | physics |
math_qa__Ecvw7WrjczAK0LQP | Each light bulb at a hotel is either incandescent or fluorescent. At a certain moment, thirty percent of the incandescent bulbs are switched on, and eighty percent of the fluorescent bulbs are switched on. If 70 percent of all the bulbs are switched on at this moment, what percent of the bulbs that are switched on are incandescent? Choose the correct answer: A) 4.5 % B) 8.6 % C) 12.3 % D) 16.7 % E) 20 % | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">8 * 10</gadget>
<output>80</output>
<gadget id="calculator">80 - 70</gadget>
<output>10</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / 5</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(1/2) - (3/10)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 30</gadget>
<output>6</output>
<gadget id="calculator">6 / 70</gadget>
<output>3/35 = around 0.085714</output>
<gadget id="calculator">(3/35) * 100</gadget>
<output>60/7 = around 8.571429</output>
<result>B</result> | B | 8.6 | Each light bulb at a hotel is either incandescent or fluorescent. At a certain moment, thirty percent of the incandescent bulbs are switched on, and eighty percent of the fluorescent bulbs are switched on. If 70 percent of all the bulbs are switched on at this moment, what percent of the bulbs that are switched on are incandescent? | {
"A": "4.5 %",
"B": "8.6 %",
"C": "12.3 %",
"D": "16.7 %",
"E": "20 %"
} | multiply(divide(multiply(subtract(multiply(divide(divide(subtract(multiply(multiply(const_4, const_2), multiply(add(const_4, const_1), const_2)), 70), subtract(70, multiply(const_3, multiply(add(const_4, const_1), const_2)))), add(const_4, const_1)), multiply(add(const_4, const_1), const_2)), divide(multiply(const_3, multiply(add(const_4, const_1), const_2)), const_100)), multiply(const_3, multiply(add(const_4, const_1), const_2))), 70), const_100) | add(const_1,const_4)|multiply(const_2,const_4)|multiply(#0,const_2)|multiply(#2,const_3)|multiply(#1,#2)|divide(#3,const_100)|subtract(#4,n0)|subtract(n0,#3)|divide(#6,#7)|divide(#8,#0)|multiply(#9,#2)|subtract(#10,#5)|multiply(#3,#11)|divide(#12,n0)|multiply(#13,const_100) | let i be the number of incandescent bulbs . let f be the number of fluorescent bulbs . 0.3 i + 0.8 f = 0.7 ( i + f ) 0.1 f = 0.4 i f = 4 i this means that for every 1 incandescent bulb , there are 4 fluorescent bulbs . the percent of bulbs that are switched on which are incandescent is : 0.3 i / ( 0.3 i + 0.8 f ) = 0.3 i / ( 0.3 i + 0.8 * 4 i ) = 0.3 i / 3.5 i = 3 / 35 which is about 8.6 % . the answer is b . | gain |
math_qa__3X6QwsXrtvNpht0m | A chemist mixes one liter of pure water with x liters of a 40% salt solution, and the resulting mixture is a 20% salt solution. What is the value of x? Select
A) 1 / 4 B) 1 / 3 C) 1 / 2 D) 1 E) 3 | <gadget id="calculator">40 - 20</gadget>
<output>20</output>
<gadget id="calculator">20 / 20</gadget>
<output>1</output>
<result>D</result> | D | 1 | A chemist mixes one liter of pure water with x liters of a 40% salt solution, and the resulting mixture is a 20% salt solution. What is the value of x? | {
"A": "1 / 4",
"B": "1 / 3",
"C": "1 / 2",
"D": "1",
"E": "3"
} | divide(20, subtract(40, 20)) | subtract(n0,n1)|divide(n1,#0)| | "concentration of salt in pure solution = 0 concentration of salt in salt solution = 40 % concentration of salt in the mixed solution = 20 % the pure solution and the salt solution is mixed in the ratio of - - > ( 40 - 20 ) / ( 20 - 0 ) = 1 / 1 1 / x = 1 / 1 x = 1 answer : d" | gain |
math_qa__X7knTSl1WqbdZynS | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.5 years. The ration of the number of boys to the number of girls in the class is?
Choose the correct answer.
A) 2 : 6 B) 2 : 3 C) 2 : 5 D) 2 : 1 E) 1 : 2 | <gadget id="calculator">15.8 - 15.5</gadget>
<output>0.3</output>
<gadget id="calculator">16.4 - 15.8</gadget>
<output>0.6</output>
<gadget id="calculator">0.3 / 0.6</gadget>
<output>0.5</output>
<result>E</result> | E | 0.5 | The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.5 years. The ration of the number of boys to the number of girls in the class is? | {
"A": "2 : 6",
"B": "2 : 3",
"C": "2 : 5",
"D": "2 : 1",
"E": "1 : 2"
} | divide(subtract(15.8, 15.5), subtract(16.4, 15.8)) | subtract(n0,n2)|subtract(n1,n0)|divide(#0,#1)| | "let the ratio be k : 1 . then , k * 16.4 + 1 * 15.5 = ( k + 1 ) * 15.8 = ( 16.4 - 15.8 ) k = ( 15.8 - 15.5 ) = k = 0.3 / 0.6 = 1 / 2 required ratio = 1 / 2 : 1 = 1 : 2 . answer : e" | general |
math_qa__gWx6SgPYg9C8BjlK | Consider a right circular cone of base radius 4 and height 10 cm. A cylinder is to be placed inside the cone with one of the flat surface resting on the base of the cone. Find the largest possible total surface area (in sq cm) of the cylinder. Choose the correct option:
A) 100 π / 3 B) 80 π / 3 C) 120 π / 7 D) 130 π / 9 E) 110 π / 7 | <gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) - 1</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(5/2) / (3/2)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 2</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(10/3) ** 2</gadget>
<output>100/9 = around 11.111111</output>
<gadget id="calculator">(100/9) * 3</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">pi * (100/3)</gadget>
<output>100*pi/3 = around 104.719755</output>
<result>A</result> | A | 100 | Consider a right circular cone of base radius 4 and height 10 cm. A cylinder is to be placed inside the cone with one of the flat surface resting on the base of the cone. Find the largest possible total surface area (in sq cm) of the cylinder. | {
"A": "100 π / 3",
"B": "80 π / 3",
"C": "120 π / 7",
"D": "130 π / 9",
"E": "110 π / 7"
} | multiply(const_pi, multiply(power(multiply(divide(divide(10, 4), subtract(divide(10, 4), const_1)), const_2), const_2), const_3)) | divide(n1,n0)|subtract(#0,const_1)|divide(#0,#1)|multiply(#2,const_2)|power(#3,const_2)|multiply(#4,const_3)|multiply(#5,const_pi) | explanation : let the radius of cylinder be r and its height is h . so , the height remained above cylinder is 10 - h also , triangles abc and ade are similar . so ratio of corresponding sides must be equal i . e ab / ad = bc / de . i . e . ( 10 - h ) / 10 = r / 4 . so 40 - 4 h = 10 r ( by cross multiply ) h = ( 40 - 10 r ) / 4 = 10 - 2.5 r now we have total surface area of cyl = 2 * π * r * h + 2 * π * r 2 . putting value of h = 10 - 2.5 r here , we get s = 2 * π * r * ( 10 - 2.5 r ) + 2 * π * r 2 . s = 20 * π * r - 5 * π * r 2 + 2 * π * r 2 . s = 20 * π * r - 3 * π * r . now , we have to maximize s , so differentiate it w . r . t r , we get s = 20 * π - 6 * π * r setting it to zero , we get = > 20 * π - 6 * π * r = 0 = > r = 20 / 6 = 10 / 3 . so , h = 10 - 2.5 r = 10 - 2.5 * 10 / 3 = 5 / 3 so , = > s = 2 * π * r * h + 2 * π * r 2 . = > s = 2 * π * 10 / 3 * 5 / 3 + 2 * π * 100 / 9 . = > s = 2 * π * 50 / 9 + 2 * π * 100 / 9 . = > s = 2 π 150 / 9 . = > s = 100 π / 3 . answer : a | geometry |
math_qa__NyZP3CNYbxHIgCLK | A football field is 10800 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 3600 square yards?
Choose the correct choice: A) 400 B) 600 C) 750 D) 2400 E) 3200 | <gadget id="calculator">1_200 / 10_800</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">3_600 * (1/9)</gadget>
<output>400</output>
<result>A</result> | A | 400 | A football field is 10800 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 3600 square yards? | {
"A": "400",
"B": "600",
"C": "750",
"D": "2400",
"E": "3200"
} | multiply(3600, divide(1200, 10800)) | divide(n1,n0)|multiply(n2,#0)| | "answer a ) 10800 yards need 1200 lbs 1 yard will need 1200 / 10800 = 1 / 9 lbs 3600 yards will need 1 / 9 * 3600 yards = 400 lbs" | geometry |
math_qa__86hQopMEHVnL4IyL | Two same glasses are respectively 1/4th 1/5th full of milk. They are then filled with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is? Choose the correct choice from the following choices:
A) 9 : 39
B) 9 : 31
C) 9 : 36
D) 9 : 32
E) 9 : 34 | <gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 + 1</gadget>
<output>31</output>
<gadget id="calculator">9 / 31</gadget>
<output>9/31 = around 0.290323</output>
<result>B</result> | B | 0.290323 | Two same glasses are respectively 1/4th 1/5th full of milk. They are then filled with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is? | {
"A": "9 : 39",
"B": "9 : 31",
"C": "9 : 36",
"D": "9 : 32",
"E": "9 : 34"
} | divide(add(5, 4), add(multiply(const_3, const_10), 1)) | add(n1,n3)|multiply(const_10,const_3)|add(n0,#1)|divide(#0,#2) | 1 / 4 : 3 / 4 = ( 1 : 3 ) 5 = 5 : 15 1 / 5 : 4 / 5 = ( 1 : 4 ) 4 = 4 : 16 - - - - - - 9 : 31 answer : b | general |
math_qa__uEQdSMMyC6AQywlp | Sales price is $91, gross profit is 160% of cost, what is the value of gross profit? Choose the most appropriate option.
A) 32 B) 33 C) 39 D) 40 E) 56 | <gadget id="calculator">160 / 100</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">1 + (8/5)</gadget>
<output>13/5 = around 2.6</output>
<gadget id="calculator">91 / (13/5)</gadget>
<output>35</output>
<gadget id="calculator">91 - 35</gadget>
<output>56</output>
<result>E</result> | E | 56 | Sales price is $91, gross profit is 160% of cost, what is the value of gross profit? | {
"A": "32",
"B": "33",
"C": "39",
"D": "40",
"E": "56"
} | subtract(91, divide(91, add(const_1, divide(160, const_100)))) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)| | "cost + profit = sales cost + ( 160 / 100 ) cost = 91 cost = 35 profit = 91 - 35 = 56 answer ( e )" | gain |
math_qa__VEGTU4cIzdKUhbVQ | A number exceeds by 25 from its 3/8 part. Then the number is? Choose the correct choice from the following answers:
A) 38 B) 29 C) 27 D) 40 E) 91 | <gadget id="calculator">25 * 8</gadget>
<output>200</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">200 / 5</gadget>
<output>40</output>
<result>D</result> | D | 40 | A number exceeds by 25 from its 3/8 part. Then the number is? | {
"A": "38",
"B": "29",
"C": "27",
"D": "40",
"E": "91"
} | divide(multiply(25, 8), subtract(8, 3)) | multiply(n0,n2)|subtract(n2,n1)|divide(#0,#1)| | "explanation : x â € “ 3 / 8 x = 25 x = 40 answer : d" | general |
math_qa__XiJ0GalzIr7n3RuI | In an IT company, there are a total of 70 employees including 50 programmers. The number of male employees is 80, including 35 male programmers. How many employees must be selected to guaranty that we have 3 programmers of the same sex? Pick
A) 10 B) 25 C) 55 D) 35 E) 65 | <gadget id="calculator">80 - 70</gadget>
<output>10</output>
<gadget id="calculator">50 - 35</gadget>
<output>15</output>
<gadget id="calculator">10 + 15</gadget>
<output>25</output>
<result>B</result> | B | 25 | In an IT company, there are a total of 70 employees including 50 programmers. The number of male employees is 80, including 35 male programmers. How many employees must be selected to guaranty that we have 3 programmers of the same sex? | {
"A": "10",
"B": "25",
"C": "55",
"D": "35",
"E": "65"
} | add(subtract(80, 70), subtract(50, 35)) | subtract(n2,n0)|subtract(n1,n3)|add(#0,#1) | you could pick 70 non - programmers , 2 male programmers , and 2 female programmers , and still not have 3 programmers of the same sex . but if you pick one more person , you must either pick a male or a female programmer , so the answer is 25 . b | general |
math_qa__DX3e4mI0Vqa8bwZv | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 272 runs?
Choose the correct choice from the following answers:
A) 6.25
B) 6.22
C) 6.29
D) 6.39
E) 6.0 | <gadget id="calculator">10 * 3.2</gadget>
<output>32</output>
<gadget id="calculator">272 - 32</gadget>
<output>240</output>
<gadget id="calculator">240 / 40</gadget>
<output>6</output>
<result>E</result> | E | 6 | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 272 runs? | {
"A": "6.25",
"B": "6.22",
"C": "6.29",
"D": "6.39",
"E": "6.0"
} | divide(subtract(272, multiply(10, 3.2)), 40) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "required run rate = [ 272 - ( 3.2 * 10 ) ] / 40 = 240 / 40 = 6.00 answer : e" | gain |
math_qa__69t19jocLO16PdgZ | Sari and Ken climb up a mountain. At night, they camp together. On the day they are supposed to reach the summit, Sari wakes up at 06:00 and starts climbing at a constant pace. Ken starts climbing only at 08:00, when Sari is already 800 meters ahead of him. Nevertheless, Ken climbs at a constant pace of 500 meters per hour, and reaches the summit before Sari. If Sari is 50 meters behind Ken when he reaches the summit, at what time did Ken reach the summit?
Options:
A) 16.3 B) 13 : 30 C) 14 : 00 D) 15 : 00 E) 15 : 30 | <gadget id="calculator">800 + 50</gadget>
<output>850</output>
<gadget id="calculator">800 / 2</gadget>
<output>400</output>
<gadget id="calculator">500 - 400</gadget>
<output>100</output>
<gadget id="calculator">850 / 100</gadget>
<output>17/2 = around 8.5</output>
<gadget id="calculator">(17/2) + 8</gadget>
<output>33/2 = around 16.5</output>
<result>A</result> | A | 16.3 | Sari and Ken climb up a mountain. At night, they camp together. On the day they are supposed to reach the summit, Sari wakes up at 06:00 and starts climbing at a constant pace. Ken starts climbing only at 08:00, when Sari is already 800 meters ahead of him. Nevertheless, Ken climbs at a constant pace of 500 meters per hour, and reaches the summit before Sari. If Sari is 50 meters behind Ken when he reaches the summit, at what time did Ken reach the summit? | {
"A": "16.3",
"B": "13 : 30",
"C": "14 : 00",
"D": "15 : 00",
"E": "15 : 30"
} | add(divide(add(800, 50), subtract(500, divide(800, const_2))), 8) | add(n4,n6)|divide(n4,const_2)|subtract(n5,#1)|divide(#0,#2)|add(n2,#3) | both sari and ken climb in the same direction . speed of sari = 800 / 2 = 400 meters / hr ( since she covers 800 meters in 2 hrs ) speed of ken = 500 meters / hr at 8 : 00 , distance between ken and sari is 800 meters . ken needs to cover this and another 50 meters . time he will take = total distance to be covered / relative speed = ( 800 + 50 ) / ( 500 - 400 ) = 8.5 hrs starting from 8 : 00 , in 8.5 hrs , the time will be 16 : 30 answer ( a ) | physics |
math_qa__1VlbQ0SAr2YdxwKw | Boy sells a book for Rs. 800 he gets a loss of 20 %, To gain 10%, what should be the SP?
Choose the correct choice from the following answers.
A) 1100 B) 450 C) 550 D) 590 E) 600 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">800 / (4/5)</gadget>
<output>1_000</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1_000 * (1/10)</gadget>
<output>100</output>
<gadget id="calculator">1_000 + 100</gadget>
<output>1_100</output>
<result>A</result> | A | 1,100 | Boy sells a book for Rs. 800 he gets a loss of 20 %, To gain 10%, what should be the SP? | {
"A": "1100",
"B": "450",
"C": "550",
"D": "590",
"E": "600"
} | add(divide(800, subtract(const_1, divide(20, const_100))), multiply(divide(800, subtract(const_1, divide(20, const_100))), divide(10, const_100))) | divide(n1,const_100)|divide(n2,const_100)|subtract(const_1,#0)|divide(n0,#2)|multiply(#3,#1)|add(#3,#4) | cost price = 800 / 80 x 100 = 1000 to gain 10 % = 1000 x 10 / 100 = 100 sp = cp + gain = 1000 + 100 = 1100 answer : a | gain |
math_qa__fRRXc2kqTX8R1ts5 | The age of Somu is one-third his father's. 9 years back he was one-fifth of his father's age. What is his persent age ? Choose the correct choice from the following answers.
A) 11 B) 18 C) 14 D) 12 E) 10 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 9</gadget>
<output>45</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>B</result> | B | 18 | The age of Somu is one-third his father's. 9 years back he was one-fifth of his father's age. What is his persent age ? | {
"A": "11",
"B": "18",
"C": "14",
"D": "12",
"E": "10"
} | divide(subtract(multiply(add(const_4, const_1), 9), 9), subtract(add(const_4, const_1), const_3)) | add(const_1,const_4)|multiply(n0,#0)|subtract(#0,const_3)|subtract(#1,n0)|divide(#3,#2) | explanation : let somu ' s age be x and that of his father be 3 x . so , x - 9 = 3 x - 9 / 5 = x = 18 answer : option b | general |
math_qa__rJPb1nAkYDVLyiQ0 | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 11 pencils and 16 charts have been brought to the meeting, how many people are present? Pick
A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">16 + 11</gadget>
<output>27</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">27 / 3</gadget>
<output>9</output>
<result>D</result> | D | 9 | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 11 pencils and 16 charts have been brought to the meeting, how many people are present? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(16, 11), add(2, 1)) | add(n4,n5)|add(n0,n1)|divide(#0,#1)| | "say there are ' a ' associate professors . so we have 2 a pencils and a charts . say there are ' b ' assistant professors . so we have b pencils and 2 b charts . total pencils are 10 so 2 a + b = 11 total charts are 11 so a + 2 b = 16 add both : 3 a + 3 b = 27 so a + b = 9 total number of people = 9 d" | general |
math_qa__lodUPAIrjNHkyZbN | A goods train leaves a station at a certain time and at a fixed speed. After ^hours, an express train leaves the same station and moves in the same direction at a uniform speed of 90 kmph. This train catches up the goods train in 4 hours. Find the speed of the goods train. Pick one:
A) 15 kmph
B) 36 kmph
C) 21 kmph
D) 17 kmph
E) 19 kmph | <gadget id="calculator">90 * 4</gadget>
<output>360</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">360 / 10</gadget>
<output>36</output>
<result>B</result> | B | 36 | A goods train leaves a station at a certain time and at a fixed speed. After ^hours, an express train leaves the same station and moves in the same direction at a uniform speed of 90 kmph. This train catches up the goods train in 4 hours. Find the speed of the goods train. | {
"A": "15 kmph",
"B": "36 kmph",
"C": "21 kmph",
"D": "17 kmph",
"E": "19 kmph"
} | divide(multiply(90, 4), add(4, add(const_3, const_3))) | add(const_3,const_3)|multiply(n0,n1)|add(n1,#0)|divide(#1,#2) | let the speed of the goods train be x kmph . distance covered by goods train in 10 hours = distance covered by express train in 4 hours 10 x = 4 x 90 or x = 36 . so , speed of goods train = 36 kmph . ans : b | physics |
math_qa__suBT1oMDAfMJbTs2 | Rahul can do a work in 3 days while Rajesh can do the same work in 2days. Both of them finish the work together and get $355. What is the share of Rahul? Choose the correct choice from the following choices:
A) $ 50 B) $ 142 C) $ 60 D) $ 100 E) $ 90 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 355</gadget>
<output>142</output>
<result>B</result> | B | 142 | Rahul can do a work in 3 days while Rajesh can do the same work in 2days. Both of them finish the work together and get $355. What is the share of Rahul? | {
"A": "$ 50",
"B": "$ 142",
"C": "$ 60",
"D": "$ 100",
"E": "$ 90"
} | multiply(divide(2, add(3, 2)), 355) | add(n0,n1)|divide(n1,#0)|multiply(n2,#1)| | "rahul ' s wages : rajesh ' s wages = 1 / 3 : 1 / 2 = 2 : 3 rahul ' s share = 355 * 2 / 5 = $ 142 answer is b" | physics |
math_qa__zMvXXOQaskie4XXV | A certain fruit stand sold apples for $0.70 each and cherry for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ? Pick.
A) 12
B) 11
C) 13
D) 14
E) 15 | <gadget id="calculator">0.7 * 10</gadget>
<output>7</output>
<gadget id="calculator">7 + 4</gadget>
<output>11</output>
<result>B</result> | B | 11 | A certain fruit stand sold apples for $0.70 each and cherry for $0.50 each. If a customer purchased both apples and bananas from the stand for a total of $6.30, what total number of apples and bananas did the customer purchase ? | {
"A": "12",
"B": "11",
"C": "13",
"D": "14",
"E": "15"
} | add(multiply(0.7, const_10), const_4) | multiply(n0,const_10)|add(#0,const_4) | some multiple of 7 + some multiple of 5 should yield 63 . to get to a some multiple of 5 , we should ensure that a 3 or 8 ( 5 + 3 ) should be a multiple of 7 . 63 is a direct multiple of 7 , however in this case there wo n ' t be any cherry . hence the next option is to look for a multiple of 7 that has 8 as the unit digit . 28 satisfies this hence no . of apples is 4 and no of bananas is 7 b | other |
math_qa__Aej7EMyoZxH8aIfE | The element being searched for is not found in an array of 100 elements. What is the average number of comparisons needed in a sequential search to determine that the element is not there, if the elements are completely unordered? Choose the correct choice from the following options:
A) 25 B) 50 C) 75 D) 100 E) 125 | <gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">101 * 50</gadget>
<output>5_050</output>
<gadget id="calculator">5_050 / 100</gadget>
<output>101/2 = around 50.5</output>
<gadget id="calculator">floor(101/2)</gadget>
<output>50</output>
<gadget id="calculator">2 * 50</gadget>
<output>100</output>
<result>D</result> | D | 100 | The element being searched for is not found in an array of 100 elements. What is the average number of comparisons needed in a sequential search to determine that the element is not there, if the elements are completely unordered? | {
"A": "25",
"B": "50",
"C": "75",
"D": "100",
"E": "125"
} | multiply(const_2, floor(divide(multiply(add(100, const_1), divide(100, const_2)), 100))) | add(n0,const_1)|divide(n0,const_2)|multiply(#0,#1)|divide(#2,n0)|floor(#3)|multiply(#4,const_2) | let us assume k be the element we need to search then let array be n 1 , n 2 , n 3 . . . . . . . . . . . . . . n 100 now to prove that the element searched is not there in the array we have to compare the element k with every element in the array . so , totally we need 100 comparisons . answer : d | general |
math_qa__PH6brSYvZ0mMFwgS | Two printing presses begin printing currency at the same time and at constant speeds. Press F produces 5-dollar bills at the rate of 1,000 bills per minute. Press T produces 20-dollar bills at the rate of 200 bills per minute. Once the machines have begun printing, how many seconds does it take for Press F to produce 50 dollars more currency than Press T? Pick one.
A) 2
B) 3
C) 4
D) 5
E) 6 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">50 / 1_000</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">60 * (1/20)</gadget>
<output>3</output>
<result>B</result> | B | 3 | Two printing presses begin printing currency at the same time and at constant speeds. Press F produces 5-dollar bills at the rate of 1,000 bills per minute. Press T produces 20-dollar bills at the rate of 200 bills per minute. Once the machines have begun printing, how many seconds does it take for Press F to produce 50 dollars more currency than Press T? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | multiply(const_60, divide(50, multiply(const_100, const_10))) | multiply(const_10,const_100)|divide(n4,#0)|multiply(#1,const_60) | press f produces $ 5 bills @ 1000 per minute ( 60 sec ) so $ 500 in 6 secs press t produces $ 20 bills 200 per minute ( 60 sec ) so $ 400 in 6 secs . . so we can see f produces $ 100 in 6 secs or will print $ 50 in 3 secs . . ans 3 secs . . b | physics |
math_qa__URM8H51JIbl0pjv2 | Last year Sandy saved 6% of her annual salary. This year, she made 10% more money than last year, and she saved 9% of her salary. The amount saved this year was what percent of the amount she saved last year? Choose the correct choice from the following.
A) 140 % B) 152 % C) 165 % D) 176 % E) 190 % | <gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">(9/100) * 110</gadget>
<output>99/10 = around 9.9</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 / 100</gadget>
<output>6</output>
<gadget id="calculator">(99/10) / 6</gadget>
<output>33/20 = around 1.65</output>
<gadget id="calculator">(33/20) * 100</gadget>
<output>165</output>
<result>C</result> | C | 165 | Last year Sandy saved 6% of her annual salary. This year, she made 10% more money than last year, and she saved 9% of her salary. The amount saved this year was what percent of the amount she saved last year? | {
"A": "140 %",
"B": "152 %",
"C": "165 %",
"D": "176 %",
"E": "190 %"
} | multiply(divide(multiply(divide(9, const_100), add(const_100, 10)), divide(multiply(6, const_100), const_100)), const_100) | add(n1,const_100)|divide(n2,const_100)|multiply(n0,const_100)|divide(#2,const_100)|multiply(#0,#1)|divide(#4,#3)|multiply(#5,const_100) | let last year ' s salary be x . last year , sandy save 0.06 x this year , sandy saved 0.09 * 1.1 x = 0.099 x 0.099 x / 0.06 x = 99 / 60 = 1.65 = 165 % the answer is c . | gain |
math_qa__4f41o2ExQ46xOjnY | Rahul can do a work in 3 days while Rajesh can do the same work in 2days. Both of them finish the work together and get $170. What is the share of Rahul?
Pick: A) $ 68 B) $ 40 C) $ 60 D) $ 100 E) $ 90 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 170</gadget>
<output>68</output>
<result>A</result> | A | 68 | Rahul can do a work in 3 days while Rajesh can do the same work in 2days. Both of them finish the work together and get $170. What is the share of Rahul? | {
"A": "$ 68",
"B": "$ 40",
"C": "$ 60",
"D": "$ 100",
"E": "$ 90"
} | multiply(divide(2, add(3, 2)), 170) | add(n0,n1)|divide(n1,#0)|multiply(n2,#1)| | "rahul ' s wages : rajesh ' s wages = 1 / 3 : 1 / 2 = 2 : 3 rahul ' s share = 170 * 2 / 5 = $ 68 answer is a" | physics |
math_qa__nst9H50aQUB4DRNF | The ratio between Sumit's and Prakash's age at present is 2:3. Sumit is 6 years younger than Prakash. The ratio of Sumit's age to Prakash's age after 6 years will be : Choose the correct choice from the following options: A) 1 : 2 B) 2 : 3 C) 3 : 4 D) 3 : 8 E) none | <gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<gadget id="calculator">18 + 6</gadget>
<output>24</output>
<gadget id="calculator">18 / 24</gadget>
<output>3/4 = around 0.75</output>
<result>C</result> | C | 0.75 | The ratio between Sumit's and Prakash's age at present is 2:3. Sumit is 6 years younger than Prakash. The ratio of Sumit's age to Prakash's age after 6 years will be : | {
"A": "1 : 2",
"B": "2 : 3",
"C": "3 : 4",
"D": "3 : 8",
"E": "none"
} | divide(add(multiply(6, const_2), 6), add(add(multiply(6, const_2), 6), 6)) | multiply(n2,const_2)|add(n2,#0)|add(n2,#1)|divide(#1,#2) | explanation : let their ages be 2 x and 3 x years . 3 x - 2 x = 6 or x = 6 sumit ' s age = 12 years , prakash ' s age = 24 years ratio of their ages = 18 : 24 = 3 : 4 . correct option : c | general |
math_qa__LtUtD7Syy0MY2pTG | If a person walks at 12 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is: Choices.
A) 50 km B) 100 km C) 60 km D) 70 km E) 80 km | <gadget id="calculator">12 - 10</gadget>
<output>2</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<result>B</result> | B | 100 | If a person walks at 12 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is: | {
"A": "50 km",
"B": "100 km",
"C": "60 km",
"D": "70 km",
"E": "80 km"
} | multiply(10, divide(20, subtract(12, 10))) | subtract(n0,n1)|divide(n2,#0)|multiply(n1,#1)| | "let the actual distance travelled be x km . x / 10 = ( x + 20 ) / 12 12 x = 10 x + 200 2 x = 200 x = 100 km . answer : b" | general |
math_qa__x957pKLHHCfHrIfw | Cara leaves her home and walks toward Don's house. Two hours later, Don leaves his home and walks toward Cara's house. The distance between their homes is 45 kilometers, Cara's walking speed is 6 km/h, and Don's walking speed is 5 km/h. How many kilometers will Cara walk before she meets Don? Choose the most appropriate option
A) 26 B) 27 C) 28 D) 29 E) 30 | <gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">45 - 12</gadget>
<output>33</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">33 / 11</gadget>
<output>3</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">12 + 18</gadget>
<output>30</output>
<result>E</result> | E | 30 | Cara leaves her home and walks toward Don's house. Two hours later, Don leaves his home and walks toward Cara's house. The distance between their homes is 45 kilometers, Cara's walking speed is 6 km/h, and Don's walking speed is 5 km/h. How many kilometers will Cara walk before she meets Don? | {
"A": "26",
"B": "27",
"C": "28",
"D": "29",
"E": "30"
} | add(multiply(6, const_2), multiply(6, divide(subtract(45, multiply(6, const_2)), add(6, 5)))) | add(n1,n2)|multiply(n1,const_2)|subtract(n0,#1)|divide(#2,#0)|multiply(n1,#3)|add(#1,#4) | cara walks 12 km in the first two hours so there are 33 km remaining . when don starts walking , they complete a total of 11 km per hour . they will meet three hours after don starts walking . since cara walks for 5 hours , she walks 30 km . the answer is e . | physics |
math_qa__v4bKQRWS65VHz4jW | In a garden, there are yellow and green flowers which are straight and curved. If the probability of picking a green flower is 3/4 and picking a straight flower is 1/2, then what is the probability of picking a flower which is yellow and curved Answers.
A) 1 / 8 B) 1 / 6 C) 1 / 4 D) 3 / 4 E) 7 / 8 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) * (1/2)</gadget>
<output>1/8 = around 0.125</output>
<result>A</result> | A | 0.125 | In a garden, there are yellow and green flowers which are straight and curved. If the probability of picking a green flower is 3/4 and picking a straight flower is 1/2, then what is the probability of picking a flower which is yellow and curved | {
"A": "1 / 8",
"B": "1 / 6",
"C": "1 / 4",
"D": "3 / 4",
"E": "7 / 8"
} | multiply(subtract(const_1, divide(3, 4)), divide(1, 2)) | divide(n2,n3)|divide(n0,n1)|subtract(const_1,#1)|multiply(#0,#2) | good question . so we have a garden where all the flowers have two properties : color ( green or yellow ) and shape ( straight or curved ) . we ' re told that 3 / 4 of the garden is green , so , since all the flowers must be either green or yellow , we know that 1 / 4 are yellow . we ' re also told there is an equal probability of straight or curved , 1 / 2 . we want to find out the probability of something being yellow and straight , pr ( yellow and straight ) . so if we recall , the probability of two unique events occurring simultaneously is the product of the two probabilities , pr ( a and b ) = p ( a ) * p ( b ) . so we multiply the two probabilities , pr ( yellow ) * pr ( curved ) = 1 / 4 * 1 / 2 = 1 / 8 , or a . | probability |
math_qa__qjhZH4dOGNTmXnE5 | The speed of a bus increases by 2 km after every one hour. If the distance travelling in the first one hour was 35 km. what was the total distance travelled in 12 hours?
Pick one.
A) 233 B) 552 C) 376 D) 287 E) 166 | <gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">35 + 22</gadget>
<output>57</output>
<gadget id="calculator">35 + 57</gadget>
<output>92</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">92 * 6</gadget>
<output>552</output>
<result>B</result> | B | 552 | The speed of a bus increases by 2 km after every one hour. If the distance travelling in the first one hour was 35 km. what was the total distance travelled in 12 hours? | {
"A": "233",
"B": "552",
"C": "376",
"D": "287",
"E": "166"
} | multiply(add(35, add(35, multiply(subtract(12, const_1), 2))), divide(12, 2)) | divide(n2,n0)|subtract(n2,const_1)|multiply(n0,#1)|add(n1,#2)|add(n1,#3)|multiply(#4,#0) | given that distance travelled in 1 st hour = 35 km and speed of the bus increases by 2 km after every one hour hence distance travelled in 2 nd hour = 37 km hence distance travelled in 3 rd hour = 39 km . . . total distance travelled = [ 35 + 37 + 39 + . . . ( 12 terms ) ] this is an arithmetic progression ( ap ) with first term , a = 35 , number of terms , n = 12 and common difference , d = 2 . the sequence a , ( a + d ) , ( a + 2 d ) , ( a + 3 d ) , ( a + 4 d ) , . . . is called an arithmetic progression ( ap ) where a is the first term and d is the common difference of the ap sum of the first n terms of an arithmetic progression ( ap ) , sn = n 2 [ 2 a + ( n − 1 ) d ] where n = number of terms hence , [ 35 + 37 + 39 + . . . ( 12 terms ) ] = s 12 = 122 [ 2 × 35 + ( 12 − 1 ) 2 ] = 6 [ 70 + 22 ] = 6 × 92 = 552 hence the total distance travelled = 552 km answer : b | physics |
math_qa__hsdsADYyH1cfHiXp | An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ? Pick.
A) rs . 4082.40 B) rs . 1024.21 C) rs . 2810.6 D) rs . 3214 E) none of these | <gadget id="calculator">6 * 1.44</gadget>
<output>8.64</output>
<gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">140 / 100</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">8.64 * (7/5)</gadget>
<output>12.096</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">6 * (5/4)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">12.096 * (15/2)</gadget>
<output>90.72</output>
<gadget id="calculator">90.72 * 45</gadget>
<output>4_082.4</output>
<result>A</result> | A | 4,082.4 | An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq. m ? | {
"A": "rs . 4082.40",
"B": "rs . 1024.21",
"C": "rs . 2810.6",
"D": "rs . 3214",
"E": "none of these"
} | multiply(multiply(multiply(multiply(6, 1.44), divide(add(const_100, 40), const_100)), multiply(6, divide(add(const_100, 25), const_100))), 45) | add(n2,const_100)|add(n3,const_100)|multiply(n0,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(#3,#2)|multiply(n0,#4)|multiply(#5,#6)|multiply(n4,#7) | explanation : length of the first carpet = ( 1.44 ) ( 6 ) = 8.64 cm area of the second carpet = 8.64 ( 1 + 40 / 100 ) 6 ( 1 + 25 / 100 ) = 51.84 ( 1.4 ) ( 5 / 4 ) sq m = ( 12.96 ) ( 7 ) sq m cost of the second carpet = ( 45 ) ( 12.96 x 7 ) = 315 ( 13 - 0.04 ) = 4095 - 12.6 = rs . 4082.40 answer is a | general |
math_qa__TXTVC1xXALi6NLoB | In a office work is distribute between p persons. If 1/7 members are absent then work increased for each person is? Choose the correct choice from the following answers
A) 13.67 % B) 14.67 % C) 15.67 % D) 16.67 % E) 17.67 % | <gadget id="calculator">100 * 7</gadget>
<output>700</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">700 / 6</gadget>
<output>350/3 = around 116.666667</output>
<gadget id="calculator">(350/3) - 100</gadget>
<output>50/3 = around 16.666667</output>
<result>D</result> | D | 16.67 | In a office work is distribute between p persons. If 1/7 members are absent then work increased for each person is? | {
"A": "13.67 %",
"B": "14.67 %",
"C": "15.67 %",
"D": "16.67 %",
"E": "17.67 %"
} | subtract(divide(multiply(const_100, 7), subtract(7, 1)), const_100) | multiply(n1,const_100)|subtract(n1,n0)|divide(#0,#1)|subtract(#2,const_100)| | "let total % of work is 100 % total person = p 1 / 7 person are absent of total person . so absent person is 1 / 7 p ie p / 7 . left person is , p - p / 7 = 6 p / 7 . p person do the work 100 % 1 person do the work 100 * p % 6 p / 7 person do the work ( 100 * p * 7 ) / 6 p % = 116.67 % work increased for each person is = ( 116.67 - 100 ) % = 16.67 % answer : d" | general |
math_qa__CpIlXP4XFCveiMcY | A courtyard is 25 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is?
Choose the correct option
A) 22877
B) 27778
C) 20000
D) 27999
E) 17799 | <gadget id="calculator">25 * 100</gadget>
<output>2_500</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<gadget id="calculator">2_500 * 1_600</gadget>
<output>4_000_000</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">4_000_000 / 200</gadget>
<output>20_000</output>
<result>C</result> | C | 20,000 | A courtyard is 25 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is? | {
"A": "22877",
"B": "27778",
"C": "20000",
"D": "27999",
"E": "17799"
} | divide(multiply(multiply(25, const_100), multiply(16, const_100)), multiply(20, 10)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "number of bricks = courtyard area / 1 brick area = ( 2500 × 1600 / 20 × 10 ) = 20000 answer : c" | physics |
math_qa__vtuC7ch3ajn7aqxj | In a school of 700 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities?
Choices.
A) 173
B) 126
C) 153
D) 143
E) 133 | <gadget id="calculator">44 + 28</gadget>
<output>72</output>
<gadget id="calculator">72 + 10</gadget>
<output>82</output>
<gadget id="calculator">100 - 82</gadget>
<output>18</output>
<gadget id="calculator">700 * 18</gadget>
<output>12_600</output>
<gadget id="calculator">12_600 / 100</gadget>
<output>126</output>
<result>B</result> | B | 126 | In a school of 700 boys, 44% of Muslims, 28% Hindus, 10% Sikhs and the remaining of other communities. How many belonged to the other communities? | {
"A": "173",
"B": "126",
"C": "153",
"D": "143",
"E": "133"
} | divide(multiply(700, subtract(const_100, add(add(44, 28), 10))), const_100) | add(n1,n2)|add(n3,#0)|subtract(const_100,#1)|multiply(n0,#2)|divide(#3,const_100)| | "44 + 28 + 10 = 82 % 100 – 82 = 18 % 700 * 18 / 100 = 126 answer : b" | gain |
math_qa__vIneJGqZGMjWqY18 | The speed of a car is 100 km in the first hour and 80 km in the second hour. What is the average speed of the car? Options.
A) 12 B) 75 C) 88 D) 54 E) 90 | <gadget id="calculator">100 + 80</gadget>
<output>180</output>
<gadget id="calculator">180 / 2</gadget>
<output>90</output>
<result>E</result> | E | 90 | The speed of a car is 100 km in the first hour and 80 km in the second hour. What is the average speed of the car? | {
"A": "12",
"B": "75",
"C": "88",
"D": "54",
"E": "90"
} | divide(add(100, 80), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 100 + 80 ) / 2 = 90 kmph answer : e" | physics |
math_qa__9sKbRuK816bCjslR | The average marks of 10 students in a class is 100. But a student mark is wrongly noted as 60 instead of 10 then find the correct average marks? Choose the correct answer
A) 78 B) 82 C) 95 D) 91 E) 85 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 60</gadget>
<output>940</output>
<gadget id="calculator">940 + 10</gadget>
<output>950</output>
<gadget id="calculator">950 / 10</gadget>
<output>95</output>
<result>C</result> | C | 95 | The average marks of 10 students in a class is 100. But a student mark is wrongly noted as 60 instead of 10 then find the correct average marks? | {
"A": "78",
"B": "82",
"C": "95",
"D": "91",
"E": "85"
} | divide(add(subtract(multiply(100, 10), 60), 10), 10) | multiply(n0,n1)|subtract(#0,n2)|add(n3,#1)|divide(#2,n0)| | "correct avg marks = 100 + ( 10 - 60 ) / 10 avg = 100 - 5 = 95 answer is c" | general |
math_qa__uBFcYoi2w8K6VSAM | there are 300 seniors at morse high school , and 50 % of them have cars . of the remaining grades ( freshmen , sophomores , and juniors ) , only 10 % of them have cars . if 20 % of all the students at morse have cars , how many students are in the 3 lower grades ? Choose the correct choice
A) 600 B) 900 C) 1200 D) 1350 E) 1500 | <gadget id="calculator">300 * 50</gadget>
<output>15_000</output>
<gadget id="calculator">300 * 20</gadget>
<output>6_000</output>
<gadget id="calculator">15_000 - 6_000</gadget>
<output>9_000</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">9_000 / 10</gadget>
<output>900</output>
<result>B</result> | B | 900 | there are 300 seniors at morse high school , and 50 % of them have cars . of the remaining grades ( freshmen , sophomores , and juniors ) , only 10 % of them have cars . if 20 % of all the students at morse have cars , how many students are in the 3 lower grades ? | {
"A": "600",
"B": "900",
"C": "1200",
"D": "1350",
"E": "1500"
} | divide(subtract(multiply(300, 50), multiply(300, 20)), subtract(20, 10)) | multiply(n0,n1)|multiply(n0,n3)|subtract(n3,n2)|subtract(#0,#1)|divide(#3,#2) | let x be the number of students in the lower three grades . 0.1 x + 150 = 0.2 ( x + 300 ) 0.1 x = 900 x = 900 the answer is b . | gain |
math_qa__Alc97Yez4F1tfZsK | Carrie likes to buy t-shirts at the local clothing store. They cost $9.95 each. One day, she bought 20 t-shirts. How much money did she spend?
Choose the correct choice.
A) $ 150 B) $ 248.75 C) $ 199 D) $ 171.6 E) $ 190 | <gadget id="calculator">20 * 9.95</gadget>
<output>199</output>
<gadget id="calculator">floor(199)</gadget>
<output>199</output>
<result>C</result> | C | 199 | Carrie likes to buy t-shirts at the local clothing store. They cost $9.95 each. One day, she bought 20 t-shirts. How much money did she spend? | {
"A": "$ 150",
"B": "$ 248.75",
"C": "$ 199",
"D": "$ 171.6",
"E": "$ 190"
} | floor(multiply(20, 9.95)) | multiply(n0,n1)|floor(#0)| | $ 9.95 * 20 = $ 199 . answer is c . | general |
math_qa__1GwkDsLqJZfF2BnZ | In a mixed college 160 students are there in one class. Out of this 160 students 5/8 students are girls. How many boys are there ? Choose the correct choice from the following options:
A) 40 B) 60 C) 80 D) 120 E) 140 | <gadget id="calculator">160 / 8</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<result>B</result> | B | 60 | In a mixed college 160 students are there in one class. Out of this 160 students 5/8 students are girls. How many boys are there ? | {
"A": "40",
"B": "60",
"C": "80",
"D": "120",
"E": "140"
} | multiply(divide(160, 8), const_3) | divide(n0,n3)|multiply(#0,const_3)| | "total number of students : 160 total girls : 160 * 5 / 8 = 100 total boys : 160 - 100 = 60 answer is b" | general |
math_qa__gG4kOHMF37NEJNTW | If 10 gallons of grape juice are added to 50 gallons of a mixture, which contains 10 percent grape juice then what percent of the resulting mixture is grape juice? Choose the most appropriate option: A) 14 % B) 25 % C) 28 % D) 34 % E) 50 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 50</gadget>
<output>5</output>
<gadget id="calculator">5 + 10</gadget>
<output>15</output>
<gadget id="calculator">50 + 10</gadget>
<output>60</output>
<gadget id="calculator">15 / 60</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | If 10 gallons of grape juice are added to 50 gallons of a mixture, which contains 10 percent grape juice then what percent of the resulting mixture is grape juice? | {
"A": "14 %",
"B": "25 %",
"C": "28 %",
"D": "34 %",
"E": "50 %"
} | multiply(divide(add(multiply(divide(10, const_100), 50), 10), add(50, 10)), const_100) | add(n0,n1)|divide(n2,const_100)|multiply(n1,#1)|add(n0,#2)|divide(#3,#0)|multiply(#4,const_100)| | "official solution : if we start with 40 gallons of a mixture that is 10 % grape juice , then we have : 50 × 0.10 = 5 gallons of grape juice . 50 × 0.90 = 45 gallons of other components . if we add 10 gallons of grape juice , we will end up with 15 gallons of grape juice and 45 gallons of other components , and we will have a total of 60 gallons of the mixture . so 15 / 60 of the new mixture is grape juice . now we convert this to a percent : percent grape juice = 25 / 100 = 25 % . the correct answer is choice ( b )" | general |
math_qa__DShRgKCd2hGpAgFd | An artist who needs to buy only paint and canvas finds that the cost of canvas has decreased by 40 percent and the cost of paint has decreased by 60 percent. If paint previously accounted for 4 times as much of the expense of painting as did canvas, by what percent did the total cost for paint and canvas decrease? Select the correct option
A) 40 % B) 44 % C) 50 % D) 56 % E) 60 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 4</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(8/5) + (3/5)</gadget>
<output>11/5 = around 2.2</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">(11/5) / 5</gadget>
<output>11/25 = around 0.44</output>
<gadget id="calculator">1 - (11/25)</gadget>
<output>14/25 = around 0.56</output>
<gadget id="calculator">(14/25) * 100</gadget>
<output>56</output>
<result>D</result> | D | 56 | An artist who needs to buy only paint and canvas finds that the cost of canvas has decreased by 40 percent and the cost of paint has decreased by 60 percent. If paint previously accounted for 4 times as much of the expense of painting as did canvas, by what percent did the total cost for paint and canvas decrease? | {
"A": "40 %",
"B": "44 %",
"C": "50 %",
"D": "56 %",
"E": "60 %"
} | multiply(subtract(const_1, divide(add(multiply(divide(40, const_100), 4), divide(60, const_100)), add(4, const_1))), const_100) | add(n2,const_1)|divide(n1,const_100)|divide(n0,const_100)|multiply(n2,#2)|add(#1,#3)|divide(#4,#0)|subtract(const_1,#5)|multiply(#6,const_100) | paint : canvas cost is 4 : 1 . so , paint accounts for 80 % of cost and canvas accounts for 20 % . canvas , after decrease by 40 % will be ( 100 - 40 ) % of 20 % = > 60 % of 20 % = > 12 % of original paint , after decrease by 60 % will be ( 100 - 60 ) % of 80 % = > 40 % of 80 % = > 32 % of original new cost as a % of old cost = 32 + 12 = 44 % of original . so , overall cost saving = 100 - 44 = 56 % therefore , ( d ) | general |
math_qa__xUSqv0aTnJGJTknU | A man can row upstream at 55 kmph and downstream at 65 kmph, and then find the speed of the man in still water? Pick one
A) 27 B) 70 C) 60 D) 80 E) 24 | <gadget id="calculator">55 + 65</gadget>
<output>120</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<result>C</result> | C | 60 | A man can row upstream at 55 kmph and downstream at 65 kmph, and then find the speed of the man in still water? | {
"A": "27",
"B": "70",
"C": "60",
"D": "80",
"E": "24"
} | divide(add(55, 65), const_2) | add(n0,n1)|divide(#0,const_2)| | "us = 55 ds = 65 m = ( 55 + 65 ) / 2 = 60 answer : c" | physics |
math_qa__tcRlTH9FUTlrgWoK | A rectangular grassy plot 110 m. by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 60 paise per sq. metre Choose the correct answer.
A) s 510 B) s 780 C) s 880 D) s 480 E) s 980 | <gadget id="calculator">110 * 65</gadget>
<output>7_150</output>
<gadget id="calculator">2.5 * 2</gadget>
<output>5</output>
<gadget id="calculator">110 - 5</gadget>
<output>105</output>
<gadget id="calculator">65 - 5</gadget>
<output>60</output>
<gadget id="calculator">105 * 60</gadget>
<output>6_300</output>
<gadget id="calculator">7_150 - 6_300</gadget>
<output>850</output>
<gadget id="calculator">850 * 60</gadget>
<output>51_000</output>
<gadget id="calculator">51_000 / 100</gadget>
<output>510</output>
<result>A</result> | A | 510 | A rectangular grassy plot 110 m. by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 60 paise per sq. metre | {
"A": "s 510",
"B": "s 780",
"C": "s 880",
"D": "s 480",
"E": "s 980"
} | divide(multiply(subtract(multiply(110, 65), multiply(subtract(110, multiply(2.5, const_2)), subtract(65, multiply(2.5, const_2)))), 60), const_100) | multiply(n0,n1)|multiply(n2,const_2)|subtract(n0,#1)|subtract(n1,#1)|multiply(#2,#3)|subtract(#0,#4)|multiply(n3,#5)|divide(#6,const_100)| | "area of the plot = 110 m * 65 m = 7150 sq . m area of plot excluding gravel = 105 m * 60 m = 6300 sq . m area of gravel = 7150 sq . m - 6300 sq . m = 850 sq . m cost of building it = 850 sq . m * 60 = 51000 p in rs = 51000 / 100 = rs 510 answer : a" | physics |
math_qa__qbRuXbGmVDwssKMo | A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length Choose the correct option:
A) 20 seconds
B) 30 seconds
C) 40 seconds
D) 50 seconds
E) none of these | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">500 / (25/2)</gadget>
<output>40</output>
<result>C</result> | C | 40 | A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length | {
"A": "20 seconds",
"B": "30 seconds",
"C": "40 seconds",
"D": "50 seconds",
"E": "none of these"
} | divide(add(360, 140), divide(multiply(45, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "explanation : speed = 45 km / hr = 45 * ( 5 / 18 ) m / sec = 25 / 2 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 ∗ 2 / 25 = 40 seconds option c" | physics |
math_qa__7zBCDrrv5QiKG9Mw | In some quantity of ghee, 60% is pure ghee and 40% is vanaspati. If 10 kg of pure ghee is added, then the strength of vanaspati ghee becomes 20%. The original quantity was : Choose the correct choice from the following answers
A) 10
B) 27
C) 87
D) 23
E) 93 | <gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">40 - 20</gadget>
<output>20</output>
<gadget id="calculator">200 / 20</gadget>
<output>10</output>
<result>A</result> | A | 10 | In some quantity of ghee, 60% is pure ghee and 40% is vanaspati. If 10 kg of pure ghee is added, then the strength of vanaspati ghee becomes 20%. The original quantity was : | {
"A": "10",
"B": "27",
"C": "87",
"D": "23",
"E": "93"
} | divide(multiply(20, 10), subtract(40, 20)) | multiply(n2,n3)|subtract(n1,n3)|divide(#0,#1)| | "explanation : let the original quantity be x kg . vanaspati ghee in x kg = ( 40 x / 100 ) kg = ( 2 x / 5 ) kg . now , ( 2 x / 5 ) / ( x + 10 ) = 20 / 100 < = > 2 x / ( 5 x + 50 ) = 1 / 5 < = > 5 x = 50 < = > x = 10 . answer : a ) 10 kg" | gain |
math_qa__wwft4jnpUajRN4Qo | If V is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of V?
Choose one.
A) 10
B) 12
C) 14
D) 16
E) 18 | <gadget id="calculator">30 / 3</gadget>
<output>10</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">30 / 9</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">floor(10/3)</gadget>
<output>3</output>
<gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">30 / 27</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">floor(10/9)</gadget>
<output>1</output>
<gadget id="calculator">13 + 1</gadget>
<output>14</output>
<result>C</result> | C | 14 | If V is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of V? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | add(add(divide(30, 3), floor(divide(30, power(3, const_2)))), floor(divide(30, power(3, 3)))) | divide(n1,n2)|power(n2,const_2)|power(n2,n2)|divide(n1,#1)|divide(n1,#2)|floor(#3)|floor(#4)|add(#0,#5)|add(#7,#6) | v = 30 ! 8 v = 30 x 29 x 28 x 27 x 26 x 25 x 24 x 24 x 22 x 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14 x 13 x 12 x 11 x 10 x 09 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 out of these 30 , 27 , 24 , 21 , 18 , 15 , 12 , 09 , 06 , 3 are factors of 3 3 x 10 , 3 x 3 x 3 , 3 x 8 , 3 x 3 x 2 , 3 x 5 , 3 x 4 , 3 x 3 x 3 , 3 x 2 , 3 so we have a total of 14 three ' s . . . therefore the maximum value of k can be 14 ( c ) | general |
math_qa__MUloeAablUrUyxtH | Two cubes have their volumes in the ratio 1 : 27. Find the ratio of their surface areas. Choose the correct choice from the following answers
A) 1 : 9
B) 2 : 9
C) 3 : 9
D) 5 : 9
E) none of them | <gadget id="calculator">1 / 27</gadget>
<output>1/27 = around 0.037037</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/27) ** (1/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) ** 2</gadget>
<output>1/9 = around 0.111111</output>
<result>A</result> | A | 0.111111 | Two cubes have their volumes in the ratio 1 : 27. Find the ratio of their surface areas. | {
"A": "1 : 9",
"B": "2 : 9",
"C": "3 : 9",
"D": "5 : 9",
"E": "none of them"
} | power(power(divide(1, 27), inverse(const_3)), const_2) | divide(n0,n1)|inverse(const_3)|power(#0,#1)|power(#2,const_2) | let their edges be a and b . then , = a ^ 3 / b ^ 3 = 1 / 27 ( or ) ( a / b ) ^ 3 = ( 1 / 3 ) 3 ( or ) ( a / b ) = ( 1 / 3 ) . therefore , ratio of their surface area = 6 a ^ 2 / 6 b ^ 2 = a ^ 2 / b ^ 2 = ( a / b ) ^ 2 = 1 / 9 , i . e . 1 : 9 . answer is a . | geometry |
math_qa__yxvK8z0OJKOxUC5J | One fourth of a solution that was 14% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight? Pick: A) 24 % B) 34 % C) 22 % D) 18 % E) 8.5 % | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">(4/25) * 4</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) * 4</gadget>
<output>14/25 = around 0.56</output>
<gadget id="calculator">(14/25) - (7/50)</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">(16/25) - (21/50)</gadget>
<output>11/50 = around 0.22</output>
<gadget id="calculator">(11/50) * 100</gadget>
<output>22</output>
<result>C</result> | C | 22 | One fourth of a solution that was 14% salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent salt by weight? | {
"A": "24 %",
"B": "34 %",
"C": "22 %",
"D": "18 %",
"E": "8.5 %"
} | multiply(subtract(multiply(divide(16, const_100), const_4), subtract(multiply(divide(14, const_100), const_4), divide(14, const_100))), const_100) | divide(n1,const_100)|divide(n0,const_100)|multiply(#0,const_4)|multiply(#1,const_4)|subtract(#3,#1)|subtract(#2,#4)|multiply(#5,const_100)| | "consider total solution to be 100 liters and in this case you ' ll have : 75 * 0.14 + 25 * x = 100 * 0.16 - - > x = 0.22 . answer : c ." | gain |
math_qa__MP9GNCNUtxewqfRK | For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the mean score E for the exam?
Choose the correct choice from the following answers: A) 74 B) 76 C) 78 D) 80 E) 82 | <gadget id="calculator">58 * 3</gadget>
<output>174</output>
<gadget id="calculator">98 * 2</gadget>
<output>196</output>
<gadget id="calculator">174 + 196</gadget>
<output>370</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">370 / 5</gadget>
<output>74</output>
<result>A</result> | A | 74 | For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the mean score E for the exam? | {
"A": "74",
"B": "76",
"C": "78",
"D": "80",
"E": "82"
} | divide(add(multiply(58, 3), multiply(98, 2)), add(2, 3)) | add(n1,n3)|multiply(n0,n3)|multiply(n1,n2)|add(#1,#2)|divide(#3,#0)| | "a score of 58 was 2 standard deviations below the mean - - > 58 = mean - 2 d a score of 98 was 3 standard deviations above the mean - - > 98 = mean + 3 d solving above for mean e = 74 . answer : a ." | general |
math_qa__QfYTli8LSY3J5lgt | An airplane covers 50 miles in 1/5 hours. How many miles can the airplane cover in 5 hours?
Pick one
A) 800 B) 600 C) 1250 D) 950 E) 1000 | <gadget id="calculator">50 * 5</gadget>
<output>250</output>
<gadget id="calculator">250 * 5</gadget>
<output>1_250</output>
<result>C</result> | C | 1,250 | An airplane covers 50 miles in 1/5 hours. How many miles can the airplane cover in 5 hours? | {
"A": "800",
"B": "600",
"C": "1250",
"D": "950",
"E": "1000"
} | multiply(multiply(50, 5), 5) | multiply(n0,n2)|multiply(n2,#0) | divide 5 by 1 / 5 = 5 ÷ 1 / 5 = 5 / 1 ÷ 1 / 5 = 5 / 1 * 5 / 1 = 25 . then , multiply 50 by 25 to get 1250 in 5 hours , the airplane will cover 1250 miles answer is c . | physics |
math_qa__GzgDcBqJYYXZmUsQ | Evaluate 35 / .07 Choose the correct choice from the following.
A) 400 B) 500 C) 505 D) none of these E) 506 | <gadget id="calculator">7 / 35</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">100 / (1/5)</gadget>
<output>500</output>
<result>B</result> | B | 500 | Evaluate 35 / .07 | {
"A": "400",
"B": "500",
"C": "505",
"D": "none of these",
"E": "506"
} | divide(const_100.0, divide(07, 35)) | divide(n1,const_100)|divide(n0,#0)| | "explanation : 35 / . 07 = 3500 / 7 = 500 option b" | general |
math_qa__CAznTL44da72UneJ | A shopkeeper sold an article offering a discount of 5% and earned a profit of 19.7%. What would have been the percentage of profit earned if no discount was offered?
Pick one.
A) 60 % B) 26 % C) 30 % D) 56 % E) 73 % | <gadget id="calculator">100 + 19.7</gadget>
<output>119.7</output>
<gadget id="calculator">119.7 * 100</gadget>
<output>11_970</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">11_970 / 95</gadget>
<output>126</output>
<gadget id="calculator">126 - 100</gadget>
<output>26</output>
<result>B</result> | B | 26 | A shopkeeper sold an article offering a discount of 5% and earned a profit of 19.7%. What would have been the percentage of profit earned if no discount was offered? | {
"A": "60 %",
"B": "26 %",
"C": "30 %",
"D": "56 %",
"E": "73 %"
} | subtract(divide(multiply(add(const_100, 19.7), const_100), subtract(const_100, 5)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "let c . p . be rs . 100 . then , s . p . = rs . 19.70 let marked price be rs . x . then , 95 / 100 x = 119.70 x = 11970 / 95 = rs . 126 now , s . p . = rs . 126 , c . p . = rs . 100 profit % = 26 % . answer : b" | gain |
math_qa__eTyDCkYKy6xLBmK3 | A candidate who gets 30% of the marks fails by 60 marks. But another candidate who gets 45% marks gets 30 marks more than necessary for passing. Find the number of marks for passing?
Choose one:
A) 100 marks
B) 240 marks
C) 280 marks
D) 371 marks
E) 827 marks | <gadget id="calculator">60 + 30</gadget>
<output>90</output>
<gadget id="calculator">45 / 100</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(9/20) - (3/10)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">90 / (3/20)</gadget>
<output>600</output>
<gadget id="calculator">600 * (3/10)</gadget>
<output>180</output>
<gadget id="calculator">180 + 60</gadget>
<output>240</output>
<result>B</result> | B | 240 | A candidate who gets 30% of the marks fails by 60 marks. But another candidate who gets 45% marks gets 30 marks more than necessary for passing. Find the number of marks for passing? | {
"A": "100 marks",
"B": "240 marks",
"C": "280 marks",
"D": "371 marks",
"E": "827 marks"
} | add(multiply(divide(add(60, 30), subtract(divide(45, const_100), divide(30, const_100))), divide(30, const_100)), 60) | add(n1,n3)|divide(n2,const_100)|divide(n0,const_100)|subtract(#1,#2)|divide(#0,#3)|multiply(#4,#2)|add(n1,#5)| | "30 % - - - - - - - - - - - - 60 45 % - - - - - - - - - - - - 30 - - - - - - - - - - - - - - - - - - - - - - 15 % - - - - - - - - - - - - - 90 30 % - - - - - - - - - - - - - - 180 180 + 60 = 240 marks answer : b" | gain |
math_qa__HFUQMxWKj00qLdzH | The average weight of 20 girls increases by 2 kg when a new girl comes in place of one of them weighing 40 kg. What might be the weight of the new girl? Pick one:
A) 85 kg
B) 90 kg
C) 80 kg
D) 75 kg
E) 70 kg | <gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">40 + 40</gadget>
<output>80</output>
<result>C</result> | C | 80 | The average weight of 20 girls increases by 2 kg when a new girl comes in place of one of them weighing 40 kg. What might be the weight of the new girl? | {
"A": "85 kg",
"B": "90 kg",
"C": "80 kg",
"D": "75 kg",
"E": "70 kg"
} | add(multiply(20, 2), 40) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = 20 x 2 kg = 40 kg . weight of new person = 40 + 40 kg = 80 kg answer : c" | general |
math_qa__oO5PLJBl4mfwOSl2 | In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number T and the smallest possible number of students that could have taken both geometry and biology?
Choose the correct choice
A) 144 B) 119 C) 113 D) 88 E) 31 | <gadget id="calculator">144 + 119</gadget>
<output>263</output>
<gadget id="calculator">263 - 232</gadget>
<output>31</output>
<gadget id="calculator">119 - 31</gadget>
<output>88</output>
<result>D</result> | D | 88 | In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number T and the smallest possible number of students that could have taken both geometry and biology? | {
"A": "144",
"B": "119",
"C": "113",
"D": "88",
"E": "31"
} | subtract(119, subtract(add(144, 119), 232)) | add(n1,n2)|subtract(#0,n0)|subtract(n2,#1)| | "official solution : first of all , notice that since 144 took geometry and 119 took biology , then the number of students who took both geometry and biology can not be greater than 119 . { total } = { geometry } + { biology } - { both } + { neither } ; 232 = 144 + 119 - { both } + { neither } ; { both } = 31 + { neither } . { both } is minimized when { neither } is 0 . in this case { both } = 31 . the greatest possible number t of students that could have taken both geometry and biology , is 119 . thus , the answer is 119 - 31 = 88 . answer : d ." | other |
math_qa__lAHdFgS1OLPW6xSY | A certain fruit stand sold apples for $0.80 each and bananas for $0.70 each. If a customer purchased both apples and bananas from the stand for a total of $6.50, what total number of apples and bananas did the customer purchase? Pick: A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">0.8 * 2</gadget>
<output>1.6</output>
<gadget id="calculator">6.5 - 1.6</gadget>
<output>4.9</output>
<gadget id="calculator">4.9 / 0.7</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>B</result> | B | 9 | A certain fruit stand sold apples for $0.80 each and bananas for $0.70 each. If a customer purchased both apples and bananas from the stand for a total of $6.50, what total number of apples and bananas did the customer purchase? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | add(divide(subtract(6.5, multiply(0.8, const_2)), 0.7), const_2) | multiply(n0,const_2)|subtract(n2,#0)|divide(#1,n1)|add(#2,const_2) | let ' s start with 1 apple for $ 0.80 . let ' s subtract $ 0.80 from $ 6.50 until we get a multiple of $ 0.70 . $ 6.50 , $ 5.70 , $ 4.90 = 7 * $ 0.70 the customer purchased 7 bananas and 2 apples . the answer is b . | other |
math_qa__6smS9Acifn8P8DLL | In how many seconds will a train 180 meters long pass an oak tree, if the speed of the train is 36 km/hr? Choose one:
A) 14 B) 16 C) 18 D) 20 E) 22 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 36</gadget>
<output>10</output>
<gadget id="calculator">180 / 10</gadget>
<output>18</output>
<result>C</result> | C | 18 | In how many seconds will a train 180 meters long pass an oak tree, if the speed of the train is 36 km/hr? | {
"A": "14",
"B": "16",
"C": "18",
"D": "20",
"E": "22"
} | divide(180, multiply(const_0_2778, 36)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 36 * 5 / 18 = 10 m / s time = 180 / 10 = 18 seconds the answer is c ." | physics |
math_qa__pBbgNSBICwzomjYd | What is the perimeter, in meters, of a rectangular garden 24 meters wide that has the same area as a rectangular playground 16 meters long and 12 meters wide? Options
A) 48
B) 56
C) 64
D) 76
E) 192 | <gadget id="calculator">16 * 12</gadget>
<output>192</output>
<gadget id="calculator">192 / 24</gadget>
<output>8</output>
<gadget id="calculator">2 * (8 + 24)</gadget>
<output>64</output>
<result>C</result> | C | 64 | What is the perimeter, in meters, of a rectangular garden 24 meters wide that has the same area as a rectangular playground 16 meters long and 12 meters wide? | {
"A": "48",
"B": "56",
"C": "64",
"D": "76",
"E": "192"
} | rectangle_perimeter(divide(rectangle_area(16, 12), 24), 24) | rectangle_area(n1,n2)|divide(#0,n0)|rectangle_perimeter(n0,#1)| | "say length of garden is l meters . then ( l * 24 ) = 16 * 12 [ given area is same . area = l * b ] therefore l works out to 8 meters . perimeter of garden = 2 * ( 8 + 24 ) = 64 meter . answer is c" | geometry |
math_qa__dnf07ze4bVJ5IPXJ | A can do a work in 12days. When he had worked for 3days, B joinedhim. If they complete the work in 3more days, in how manydays can Balone finish the work?
Choose the correct option.
A) 2 days
B) 4 days
C) 5 days
D) 6 days
E) 9 days | <gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>D</result> | D | 6 | A can do a work in 12days. When he had worked for 3days, B joinedhim. If they complete the work in 3more days, in how manydays can Balone finish the work? | {
"A": "2 days",
"B": "4 days",
"C": "5 days",
"D": "6 days",
"E": "9 days"
} | divide(12, subtract(const_3, const_1)) | subtract(const_3,const_1)|divide(n0,#0) | sax work done by afar 3 days : i j . . remzming war — 1 . work done by ( a + b ) for 1 day : . work done by a for 1 day 6 days d | physics |
math_qa__yE1EgATRANzmd22g | If k is an integer and 0.0010101 x 10^k is greater than 100, what is the least possible value of k? Choose the correct choice from the following answers:
A) 2
B) 3
C) 4
D) 5
E) 6 | <gadget id="calculator">100 / 0.00101</gadget>
<output>99_009.90099</output>
<gadget id="calculator">log(99_009.90099)</gadget>
<output>11.502975</output>
<gadget id="calculator">log(10)</gadget>
<output>log(10) = around 2.302585</output>
<gadget id="calculator">11.502975 / log(10)</gadget>
<output>11.502975/log(10) = around 4.995679</output>
<result>D</result> | D | 5 | If k is an integer and 0.0010101 x 10^k is greater than 100, what is the least possible value of k? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(log(divide(100, 0.0010101)), log(10)) | divide(n2,n0)|log(n1)|log(#0)|divide(#2,#1)| | "0.0010101 * 10 ^ k > 100 we need to move the decimal point to the right 5 places to get 101.01 this is equivalent to multiplying by 10 ^ 5 . the answer is d ." | general |
math_qa__tLdIysHE2PtIiOof | Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy 18 times as heavy as water? Options.
A) 1 : 2 B) 3 : 2 C) 9 : 1 D) 5 : 2 E) 6 : 5 | <gadget id="calculator">18 - 9</gadget>
<output>9</output>
<gadget id="calculator">19 - 18</gadget>
<output>1</output>
<gadget id="calculator">9 / 1</gadget>
<output>9</output>
<result>C</result> | C | 9 | Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy 18 times as heavy as water? | {
"A": "1 : 2",
"B": "3 : 2",
"C": "9 : 1",
"D": "5 : 2",
"E": "6 : 5"
} | divide(subtract(18, 9), subtract(19, 18)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "g = 19 w c = 9 w let 1 gm of gold mixed with x gm of copper to get 1 + x gm of the alloy 1 gm gold + x gm copper = x + 1 gm of alloy 19 w + 9 wx = x + 1 * 18 w 19 + 9 x = 18 ( x + 1 ) x = 1 / 9 ratio of gold with copper = 1 : 1 / 9 = 9 : 1 answer is c" | general |
math_qa__8zv3LYY2qPtUDPp5 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corner, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is Choose the correct choice from the following
A) 6420 B) 8960 C) 5120 D) 4830 E) none | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<gadget id="calculator">36 - 16</gadget>
<output>20</output>
<gadget id="calculator">32 * 20 * 8</gadget>
<output>5_120</output>
<result>C</result> | C | 5,120 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corner, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is | {
"A": "6420",
"B": "8960",
"C": "5120",
"D": "4830",
"E": "none"
} | volume_rectangular_prism(subtract(48, multiply(8, const_2)), subtract(36, multiply(8, const_2)), 8) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "sol . clearly , l = ( 48 - 16 ) m = 32 m , b = ( 36 - 16 ) m = 20 m , h = 8 m . ∴ volume of the box = ( 32 x 20 x 8 ) m 3 = 5120 m 3 answer c" | geometry |
math_qa__AxR6sq9cwGoERbCa | A motorboat can go at 21 kmph and still water. It takes 7 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 3 kmph? Choose the correct choice from the following: A) 65 km B) 85 km C) 55 km D) 72 km E) 40 km | <gadget id="calculator">21 + 3</gadget>
<output>24</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">21 - 3</gadget>
<output>18</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/24) + (1/18)</gadget>
<output>7/72 = around 0.097222</output>
<gadget id="calculator">7 / (7/72)</gadget>
<output>72</output>
<result>D</result> | D | 72 | A motorboat can go at 21 kmph and still water. It takes 7 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 3 kmph? | {
"A": "65 km",
"B": "85 km",
"C": "55 km",
"D": "72 km",
"E": "40 km"
} | divide(7, add(divide(const_1, add(21, 3)), divide(const_1, subtract(21, 3)))) | add(n0,n2)|subtract(n0,n2)|divide(const_1,#0)|divide(const_1,#1)|add(#2,#3)|divide(n1,#4) | let the distance between a and b be x km . total time = x / ( 21 + 3 ) + x / ( 21 - 3 ) = 7 = > x / 24 + x / 18 = 7 = > ( 4 x + 3 x ) / 72 = 7 = > x = 72 km . answer : d | physics |
math_qa__o88I7HLsyxwTB7Cb | The sum of all the digits of the integers from 18 to 21 inclusive is 24 (1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 = 24). What is the sum R of all the digits of the integers from 0 to 99 inclusive? Pick one: A) 450 B) 810 C) 900 D) 1000 E) 1100 | <gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">45 * 20</gadget>
<output>900</output>
<result>C</result> | C | 900 | The sum of all the digits of the integers from 18 to 21 inclusive is 24 (1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 = 24). What is the sum R of all the digits of the integers from 0 to 99 inclusive? | {
"A": "450",
"B": "810",
"C": "900",
"D": "1000",
"E": "1100"
} | multiply(divide(multiply(9, add(9, 1)), 2), multiply(2, const_10)) | add(n6,n3)|multiply(const_10,n7)|multiply(n6,#0)|divide(#2,n7)|multiply(#3,#1)| | "we want the sum of the digits from 0 to 99 , so i approximated : 0 - 9 - > 45 - > ( 9 + 0 ) * 10 / 2 40 - 49 - > 85 ( 13 + 4 ) * 10 / 2 90 - 99 - > 135 ( 18 + 9 ) * 10 / 2 we can see at a glance that theweightgoes up as the numbers go up ( meaning the difference between 85 and 45 is 40 , while 135 - 85 is 50 , this means that the second part of this sequence carries more weight for our result ) , so we know that the final answer has to be more than 850 ( 85 * 10 ) but close to it , and that ' s just r = 900 : the answer is c ." | general |
math_qa__QIRmJJgyE0msxahW | When positive integer X is divided by positive integer Y, the remainder is 9. If X/Y = 96.12, what is the value of Y? Pick.
A) 96 B) 75 C) 48 D) 25 E) 12 | <gadget id="calculator">floor(96.12)</gadget>
<output>96</output>
<gadget id="calculator">96.12 - 96</gadget>
<output>0.12</output>
<gadget id="calculator">9 / 0.12</gadget>
<output>75</output>
<result>B</result> | B | 75 | When positive integer X is divided by positive integer Y, the remainder is 9. If X/Y = 96.12, what is the value of Y? | {
"A": "96",
"B": "75",
"C": "48",
"D": "25",
"E": "12"
} | divide(9, subtract(96.12, floor(96.12))) | floor(n1)|subtract(n1,#0)|divide(n0,#1)| | "x = qy + 9 , where q is the quotient x / y = ( q y + 9 ) / y = q + ( 9 / y ) = 96.12 = 96 + 0.12 = > q = 96 9 / y = 0.12 = > y = 75 answer is b ." | general |
math_qa__6sb7futDoMdNVQCu | The number of students in each section of a school is 24. After admitting new students, three new sections were started. Now, the total number of sections is 16 and there are 21 students in each section. The number of new students admitted is: Choose the correct choice from the following answers.
A) 12 B) 42 C) 24 D) 28 E) 26 | <gadget id="calculator">16 * 21</gadget>
<output>336</output>
<gadget id="calculator">16 - 3</gadget>
<output>13</output>
<gadget id="calculator">24 * 13</gadget>
<output>312</output>
<gadget id="calculator">336 - 312</gadget>
<output>24</output>
<result>C</result> | C | 24 | The number of students in each section of a school is 24. After admitting new students, three new sections were started. Now, the total number of sections is 16 and there are 21 students in each section. The number of new students admitted is: | {
"A": "12",
"B": "42",
"C": "24",
"D": "28",
"E": "26"
} | subtract(multiply(16, 21), multiply(24, subtract(16, const_3))) | multiply(n1,n2)|subtract(n1,const_3)|multiply(n0,#1)|subtract(#0,#2) | original number of sections = 16 - 3 = 13 original number of students = 24 x 13 = 312 present number of students = 21 x 16 = 336 number of new students admitted = 336 - 312 = 24 so the answer is option c ) 24 . | physics |
math_qa__SawtuvUa1hQH0dSH | A man crosses a 600 m long street in 5 minutes. What is his speed in km per hour? Choose the correct answer
A) 7 km / hr
B) 7.2 km / hr
C) 5.2 km / hr
D) 10 km / hr
E) 5 km / hr | <gadget id="calculator">600 / 1_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">5 / 60</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(3/5) / (1/12)</gadget>
<output>36/5 = around 7.2</output>
<result>B</result> | B | 7.2 | A man crosses a 600 m long street in 5 minutes. What is his speed in km per hour? | {
"A": "7 km / hr",
"B": "7.2 km / hr",
"C": "5.2 km / hr",
"D": "10 km / hr",
"E": "5 km / hr"
} | divide(divide(600, const_1000), divide(5, const_60)) | divide(n0,const_1000)|divide(n1,const_60)|divide(#0,#1) | speed = 600 / 5 * 60 = 2 m / sec converting m / sec to km / hr . = 2 * 18 / 5 = 7.2 km / hr answer is b | physics |
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